output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
int main() {
int a[1000];
int b, i, j, c, m, m1, k;
scanf("%d", &b);
for (i = 0; i < b; i++) {
scanf("%d", &c);
for (j = 0; j < c; j++) {
scanf("%d", &a[j]);
}
m = abs(a[0] - a[1]);
for (j = 0; j < c - 1; j++) {
for (k = j + 1; k < c; k++) {
m1 = ... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> v(n);
for (int i = 0; i < n; i++) {
cin >> v[i];
}
sort(v.begin(), v.end());
int mx = v[1] - v[0];
for (int i = 0; i < n - 1; i++) {
mx = min(mx, v[i +... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t-- > 0) {
int len;
cin >> len;
int ar[len];
int min = INT_MAX;
for (int i = 0; i < len; i++) cin >> ar[i];
sort(ar, ar + len);
for (int i = 0; i < len - 1; i++) {
if (ar[i + 1] - ar[i] < min) min ... | ### Prompt
Generate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int diff(int arr[], int n) {
sort(arr, arr + n);
int diff = INT_MAX;
for (int i = 0; i < n - 1; i++)
if (arr[i + 1] - arr[i] < diff) diff = arr[i + 1] - arr[i];
return diff;
}
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n... | ### Prompt
Generate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int, int>;
using vi = vector<int>;
using vl = vector<ll>;
using vvi = vector<vector<int>>;
using vp = vector<pii>;
using vs = vector<string>;
using qi = queue<int>;
using qp = queue<pii>;
using pqi = priority_queue<int>;
using pqim = p... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
vector<int> arr;
cin >> n;
while (n--) {
int input;
cin >> input;
arr.push_back(input);
}
sort(arr.begin(), arr.end());
int max = arr[arr.size() - 1];
for (int i = 0; ... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int T, n, ar[100];
cin >> T;
while (T--) {
int flag = 0;
cin >> n;
for (int i = 0; i < n; i++) cin >> ar[i];
sort(ar, ar + n);
flag = ar[1] - ar[0];
for (int i = 1; i < n - 1; i++) {
if (flag > ar[i + 1] - ar[i]) {
fl... | ### Prompt
In CPP, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 10;
int inf = 0x3f3f3f3f;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int m = inf;
for (int i = 0; i < n - 1; i++) {
m = min(m,... | ### Prompt
In cpp, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
long long n;
cin >> n;
int ar[n];
for (int i = 0; i < n; i++) cin >> ar[i];
sort(ar, ar + n);
int best = 100000;
for (int i = 0; i < n - 1; i++) {
best = min(best, abs(ar[i] - ar[i + 1]));
... | ### Prompt
Generate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int s[55];
for (int i = 0; i < n; i++) {
cin >> s[i];
}
sort(s, s + n, greater<int>());
int min = INT_MAX;
for (int i = 0; i < n - 1; i++) {
int temp = s[i] - s[i ... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int t;
int a[1001];
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cin >> t;
while (t--) {
int n;
int ans = 1e8;
cin >> n;
memset(a, 0, sizeof(a));
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
for (int i ... | ### Prompt
Generate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int arvore[100006];
int n;
long long binpow(long long a, long long b) {
long long res = 1;
while (b > 0) {
if (b & 1) res = res * a;
a = a * a;
b >>= 1;
}
return res;
}
int soma(int x) {
int s = 0;
while (x > 0) {
s += arvore[x];
x -= (x & -x... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
for (int k = 0; k < n; k++) {
int s, m = 1000;
cin >> s;
int a[s];
for (int i = 0; i < s; i++) {
cin >> a[i];
}
sort(a, a + s);
for (int i = 0; i < s - 1; i++) {
m = min(m, (a[i + 1] - a[i]));
}... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
void err(istream_iterator<string> it) {}
template <typename T, typename... Args>
void err(istream_iterator<string> it, T a, Args... args) {
cerr << *it << " = " << a << '\n';
err(++it, args...);
}
long long powMod(long long x, long long y) {
long long p = 1;
while (... | ### Prompt
Please create a solution in cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, i, min, b;
scanf("%d", &t);
while (t) {
scanf("%d", &n);
int a[n];
for (i = 0; i < n; i++) scanf("%d", &a[i]);
sort(a, a + n);
min = 1001;
for (i = 0; i < n - 1; i++) {
b = a[i + 1] - a[i];
if (b < min) min = ... | ### Prompt
Generate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int m = a[1] - a[0];
for (int i = n - 1; i >= 2; i--) {
int k = a[i] - a[i - 1];
if (k... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
void FAST() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
int Rselect(vector<int>&, int, int, int);
int partition(vector<int>&, int, int);
template <typename T>
ostream& operator<<(ostream& stream, const vector<T>& vec) {
for (auto& i : vec) {
stream << ... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
T fact(T n) {
return (n == 1 || n == 0) ? 1 : n * fact(n - 1);
}
bool sortbysec(const pair<int, int> &a, const pair<int, int> &b) {
return (a.second < b.second);
}
int power(int x, unsigned int y) {
int res = 1;
while (y > 0) {
if (y & 1) r... | ### Prompt
Please create a solution in cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
long long n, i;
cin >> n;
vector<long long> vec(n);
for (i = 0; i < n; i++) {
cin >> vec[i];
}
sort(vec.begin(), vec.end());
long long ans = INT_MAX;
for (i = 1; i < n; i++) {
ans = min(ans, vec[i] - vec[i - 1]);
}
cout << ans << '... | ### Prompt
Generate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
vector<int> v;
int main() {
int t;
cin >> t;
while (t--) {
int ans = 1e9;
v.clear();
int n;
cin >> n;
for (int i = 0; i < n; i++) {
int x;
cin >> x;
v.push_back(x);
}
sort(v.begin(), v.end());
for (int i = 1; i < v.siz... | ### Prompt
Create a solution in cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int i, j, count1 = 0, count2 = 0;
void A(void);
void B(void);
void C(void);
void D(void);
void E(void);
void F(void);
int main(void) { B(); }
void B() {
int l, t, n, minv, d;
cin >> t;
for (l = 0; l < t; l++) {
cin >> n;
vector<int> vec(n);
for (i = 0; i <... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
void c_p_c() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
bool isPrime(long long n) {
if (n <= 1) return false;
if (n <= 3) return true;
if (n % 2 == 0 || n % 3 == 0) return false;
for (long long i = 5; i * i <= n; i += 6) {
if (n % i == 0 ||... | ### Prompt
Create a solution in CPP for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n], i, j;
for (i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int min = abs(a[0] - a[1]), x;
for (i = 0; i < n - 1; i++) {
x = abs(a[i] - a[i + 1]);
... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a, b;
cin >> a;
for (b = 0; b <= a - 1; b++) {
int n, i, j, x, min;
min = 1000;
cin >> n;
int s[n];
for (i = 0; i <= n - 1; i++) {
cin >> s[i];
}
for (i = 0; i <= n - 1; i++) {
for (j = i + 1; j < n; j++) {
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int mini = INT_MAX;
int k = 0;
for (int i = 0; i < n ... | ### Prompt
Create a solution in Cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int arr[n], counter = 1000;
for (int i = 0; i < n; i++) cin >> arr[i];
sort(arr, arr + n);
for (int i = 1; i < n; i++)
counter = min(counter, abs(arr[i] - arr[i - 1]));
cout... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, a[50], aux = 0;
cin >> t;
while (t--) {
cin >> n;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
for (int i = 0; i < n - 1; i++) {
for (int j = 0; j < n - i - 1; j++) {
if (a[j] > a[j + 1]) {
aux = a[j... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long t, n;
cin >> t;
while (t--) {
cin >> n;
int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int ans = a[1] - a[0];
for (int i = 2; i < n; i++)
if (a[i] - a[i - 1] < ans) ans = a[i] - a[i - 1];
cout << ... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int min(int a, int b) {
if (a <= b) {
return a;
}
return b;
}
int max(int a, int b) {
if (a <= b) {
return b;
}
return a;
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(NULL);
cout.tie(NULL);
int t;
cin >> t;
while (t) {
int n, i;
... | ### Prompt
Your task is to create a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int t;
cin >> t;
while (t--) {
long long int n;
cin >> n;
long long int arr[n];
for (long long int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n);
long long int a = 1e9;
for (long long int i = 0; i... | ### Prompt
Please create a solution in cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int ara[n];
for (int i = 0; i < n; i++) {
cin >> ara[i];
}
int min = ara[0], c;
for (int i = 0; i < n - 1; i++) {
for (int j = i + 1; j < n; j++) {
if (ara[j] ... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int n;
int col[5005];
vector<int> adj[5005];
bool vis[5005];
void solve() {
int n;
cin >> n;
vector<int> a(n);
for (int i = 0; i < n; i++) cin >> a[i];
sort(a.begin(), a.end());
int mn = 1000000000;
for (int i = 1; i < n; i++) {
mn = min(mn, a[i] - a[i - 1... | ### Prompt
Generate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int t;
cin >> t;
while (t--) {
long long int n, x;
cin >> n;
vector<long long int> a;
a.clear();
for (int i = 0; i < n; i++) {
cin >> x;
a.push_back(x);
}
sort(a.begin(), a.end());
long long int mx = 1... | ### Prompt
Please create a solution in cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int tests;
cin >> tests;
for (int test = 0; test < tests; ++test) {
int n;
cin >> n;
vector<int> a(n);
for (int i = 0; i < n; ++i) {
cin >> a[i];
}
sort(a.begin(), a.end());
int minn = 2000;
for (int i = 0; i < n - 1;... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
std::vector<int> v(n);
for (int i = 0; i < n; i++) {
cin >> v[i];
}
int min = 100000;
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
if (abs(v... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int test;
cin >> test;
for (int tt = 0; tt < test; tt++) {
int n;
cin >> n;
vector<int> a(n);
for (int &x : a) {
cin >> x;
}
sort(a.begin(), a.end());
int result = a[n - 1] - a[0];
for (int i = 0; i < n - 1; i++) {
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int tc, n;
int minDiff;
cin >> tc;
while (tc--) {
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) cin >> arr[i];
sort(arr, arr + n);
minDiff = 100000;
for (int i = 0; i < n - 1; i++)
minDiff = min(minDiff, abs(arr[i] - ar... | ### Prompt
In CPP, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, test;
scanf("%d", &test);
for (t = 0; t < test; t++) {
int i, j, n, m, result, arr[50];
scanf("%d", &n);
for (m = 0; m < n; m++) {
scanf("%d", &arr[m]);
}
sort(arr, arr + n);
i = INT_MAX;
for (m = 0; m < n - 1; m++... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long t, i;
cin >> t;
while (t--) {
long long n, m = 100000, k, j;
cin >> n;
long long a[n + 5];
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
for (i = 1; i < n; i++) {
k = a[i] - a[i - 1];
m = min(k, m);
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n;
cin >> n;
int mas[n];
for (int i = 0; i < n; i++) cin >> mas[i];
sort(mas, mas + n);
int min = 999999;
int a = 0, b = 0;
for (int i = 0; i < n - 1; i++) {
if (mas[i + 1] - mas[i] < min) {
min = mas[i + 1] - mas[i];
a = m... | ### Prompt
Please create a solution in CPP to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, mini, i;
cin >> t;
while (t) {
mini = INT_MAX;
cin >> n;
int a[n];
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
for (i = 0; i < n - 1; i++) {
mini = min(mini, (a[i + 1] - a[i]));
}
cout << mini << en... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
#pragma GCC optimize("O0")
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#pragma GCC optimize("-ffloat-store")
using namespace std;
long long n, m, a, b, c, k, temp, x, y;
const int MAXN = 100000 + 11;
inline void read(vector<long lo... | ### Prompt
Generate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
scanf("%d", &t);
int n;
int i;
for (i = 0; i < t; i++) {
scanf("%d", &n);
int arr[n];
int min = 1005;
for (int j = 0; j < n; j++) {
scanf("%d", &arr[j]);
}
sort(arr, arr + n);
for (int k = 0; k < n - 1; k++) {
... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main(void) {
int t, n;
cin >> t;
while (t--) {
cin >> n;
vector<int> v(n);
map<int, int> mp;
bool flag = false;
for (auto &x : v) {
cin >> x;
mp[x]++;
if (mp[x] >= 2) {
flag = true;
}
}
if (flag) {
... | ### Prompt
Generate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main(void) {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> s(n);
for (int i = 0; i < n; i++) cin >> s[i];
sort(s.begin(), s.end());
int mi = INT_MAX;
f... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int n;
int a[55];
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t;
cin >> t;
while (t--) {
cin >> n;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int result = INT_MAX;
for (int i = 0; i < n - 1; i++... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
void getans() {
int x = INT_MAX, n;
cin >> n;
vector<int> v(n);
for (int i = 0; i < n; i++) cin >> v[i];
sort(v.begin(), v.end());
for (int i = 1; i < n; i++) {
x = min(v[i] - v[i - 1], x);
}
cout << x << endl;
}
int main() {
std::ios::sync_with_stdio(... | ### Prompt
Create a solution in CPP for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, dif = 1001;
cin >> n;
vector<int> s(n);
for (int i = 0; i < n; i++) cin >> s[i];
sort(s.begin(), s.end());
for (int i = 0; i < n - 1; i++) dif = min(dif, s[i + 1] - s[i]);
cout << dif << en... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
scanf("%d", &t);
while (t--) {
int n;
scanf("%d", &n);
vector<int> nums(n);
for (auto &x : nums) {
scanf("%d", &x);
}
sort(nums.begin(), nums.end());
int result = 0x3f3f3f3f;
for (int i = 1; i < n; i++) {
... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int x[53];
int main(int argc, char** argv) {
int t, n, min;
cin >> t;
for (int i = 0; i < t; i++) {
cin >> n;
for (int j = 0; j < n; j++) {
cin >> x[j];
}
sort(x, x + n);
min = x[1] - x[0];
for (int j = 0; j < n - 1; j++) {
if (x[j ... | ### Prompt
In CPP, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
long long t;
cin >> t;
while (t--) {
long long n;
cin >> n;
long long arr[n];
for (long long i = 0; i < n; ++i) {
cin >> arr[i];
}
sort(arr, arr + n);
long ... | ### Prompt
Create a solution in CPP for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
;
int t;
cin >> t;
while (t--) {
int n, flag = 0;
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) cin >> arr[i];
sort(arr, arr + n);
int min = arr[1] - arr[... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
const int MOD = (int)1e9 + 7;
const int MAX = 1e6;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t;
cin >> t;
while (t--) {
int n, ans = INT_MAX;
cin >> n;
int arr[n + 5];
for (int i = 0; i < n; i++) cin >> arr[i];
sort(a... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
void test() {
int mi = INT_MAX;
int s;
cin >> s;
vector<int> v(s);
while (s) cin >> v.at(v.size() - s--);
sort(v.begin(), v.end());
for (int i = 0; i < v.size() - 1; ++i) {
mi = min(abs(v.at(i) - v.at(i + 1)), mi);
}
cout << mi << endl;
}
int main() {
... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int T;
cin >> T;
while (T--) {
int n;
cin >> n;
set<int> st;
int t;
for (int i = 0; i < n; i++) {
cin >> t;
st.insert(t);
}
if (st.size() < n)
cout << 0 << "\n";
else {
vector<int> s;
for (auto... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int, int>;
const int N = 1e5 + 5;
const int MOD = 1e9 + 7;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
std::vector<int> v(n);
for (int i = 0; i < n; ++i) scanf("%d", &v[i]);
sort(v.begin(), v.... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
const unsigned int MOD = 1e9 + 7;
vector<bool> prime(1000001, true);
void seive(int n) {
for (int i = 2; i * i <= n; i++) {
if (prime[i] == true) {
for (int p = i * i; p <= n; p += i) {
prime[p] = false;
}
}
}
}
void solve() {
int N;
cin ... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const long long inf = 1e9;
ll n, m, k;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t;
cin >> t;
while (t--) {
cin >> n;
vector<int> v(n);
for (auto &x : v) cin >> x;
sort(v.begin(), v.end());
int a... | ### Prompt
Generate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
for (int a = 0; a < t; a++) {
int n;
cin >> n;
int arr[n];
int diff = INT_MAX;
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n);
for (int x = 1; x < n; x++) {
if (arr[x] - arr[x... | ### Prompt
Please create a solution in cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long t;
cin >> t;
while (t--) {
long long n;
cin >> n;
long long a[n];
for (long long i = 0; i < n; ++i) {
cin >> a[i];
}
long long minDiff = 0;
sort(a, a + n)... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long t;
cin >> t;
while (t--) {
long long n;
cin >> n;
long long a[n + 1];
for (long long i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
long long diff = INT_MAX;
for (long long i = 0; i < n - 1; i++) {
diff = min(a... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int no;
cin >> no;
while (no--) {
int size;
cin >> size;
int arr[size];
int i = 0;
while (i < size) {
cin >> arr[i++];
}
sort(arr, arr + size);
int least = arr[size - 1] - arr[size - 2], temp;
for (i = 0; i < size... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, t;
cin >> t;
for (int i = 0; i < t; i++) {
cin >> n;
int a[50];
for (int i = 0; i < n; i++) cin >> a[i];
int res = 1000;
for (int i = 0; i < n - 1; i++)
for (int j = i + 1; j < n; j++)
if (abs(a[i] - a[j]) < res) r... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
#pragma GCC optimize("-O3")
const long double PI = 3.141592653589793;
bool isPowerOfTwo(int x) { return x && (!(x & (x - 1))); }
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
long long int t = 0;
cin >> t;
while (t--) {
long long int n, i, p... | ### Prompt
Please create a solution in CPP to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t, n;
cin >> t;
while (t--) {
cin >> n;
int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int lowdif = INT_MAX;
for (int i = 1; i < n; i++) {
i... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, a[100];
cin >> t;
while (t--) {
cin >> n;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
vector<int> v;
int dif = 0;
for (int i = 1; i < n; i++) {
dif = a[i] - a[i - 1];
v.push_back(dif... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
bool com(long long a, long long b) { return a < b; }
int main() {
long long t;
cin >> t;
while (t--) {
long long n, d, ans = 1000;
cin >> n;
long long a[n];
for (long long i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
for (long long i = 1; i ... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
#pragma GCC optimize("O3")
using namespace std;
using ll = long long;
using P = pair<ll, ll>;
template <class T>
using V = vector<T>;
const ll inf = (1e18);
const ll mod = 1000000007;
ll GCD(ll a, ll b) { return b ? GCD(b, a % b) : a; }
ll LCM(ll c, ll d) { return c / GCD(c, d) * d; }
struct __... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> v(n);
for (int i = 0; i < n; i++) {
cin >> v[i];
}
sort(v.begin(), v.end());
int result = v[n - 1] - v[0];
for (int i = 0; i < n; i++) {
for (int j = i... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
signed main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
long long t;
cin >> t;
for (long long curT = 0; curT < t; ++curT) {
long long n;
cin >> n;
vector<long long> in(n);
for (long long i = 0; i < n; ++i) {
cin >> in[i];
}
sort... | ### Prompt
Generate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int arr[n];
for (int i = 0; i < n; ++i) cin >> arr[i];
sort(arr, arr + n);
int mini = INT_MAX, diff = 0;
for... | ### Prompt
In CPP, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, i, j, x, y, ans, k;
int ar[100];
scanf("%d", &t);
while (t--) {
scanf("%d", &n);
ans = 99999999;
for (i = 1; i <= n; i++) {
scanf("%d", &ar[i]);
}
sort(ar + 1, ar + n + 1);
for (i = 1; i < n; i++) {
ans = mi... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
int tc, n, a[1000];
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
;
cin >> tc;
while (tc--) {
cin >> n;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int ans = 1e7;
for (int i = 0; i < n; i++) {
int t = 0;
f... | ### Prompt
Construct a cpp code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
long long t, n, a[100];
int main() {
cin >> t;
while (t--) {
cin >> n;
for (int i = 0; i < n; ++i) cin >> a[i];
sort(a, a + n);
long long ans = 1e9;
for (int i = 1; i < n; ++i) {
ans = min(a[i] - a[i - 1], ans);
}
cout << ans << endl;
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n;
cin >> n;
vector<int> athletes(n);
for (auto &athlete : athletes) cin >> athlete;
sort(athletes.begin(), athletes.end());
int diff = INT_MAX;
for (int i = 1; i < n; ++i) {
diff = min(diff, athletes[i] - athletes[i - 1]);
}
cout <<... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
scanf("%d", &t);
while (t--) {
int n;
scanf("%d", &n);
vector<int> nums(n);
for (int i = 0; i < n; i++) {
scanf("%d", &nums[i]);
}
sort(nums.begin(), nums.end());
int result = 0x3f3f3f3f;
for (int i = 1; i < n;... | ### Prompt
Construct a cpp code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> strength(n, 0);
for (int i = 0; i < n; i++) {
cin >> strength[i];
}
sort(strength.begin(), strength.end());
int mindeff = 10001;
for (int i = 0; i < n - 1; i... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n;
cin >> t;
while (t--) {
cin >> n;
vector<int> a(n);
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a.begin(), a.end());
int ans = INT_MAX;
for (int i = 1; i < n; i++) {
ans = min(ans, a[i] - a[i - 1]);
... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int tc;
scanf("%lld", &tc);
while (tc--) {
long long int n;
scanf("%lld", &n);
vector<long long int> v;
for (long long int i = 0; i < n; i++) {
long long int a;
scanf("%lld", &a);
v.push_back(a);
}
sort(... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
for (int i = 0; i < t; i++) {
int n;
cin >> n;
int arr[n];
for (int j = 0; j < n; j++) {
cin >> arr[j];
}
sort(arr, arr + n);
int minn = 1000;
for (int j = 0; j < n - 1; j++) {
if (minn > (arr[j... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, d = 1001;
cin >> n;
int s[n];
for (int i = 0; i < n; i++) {
cin >> s[i];
}
sort(s, s + n);
int result = s[n - 1] - s[0];
for (int i = 0; i < n; i++) {
for (int j = i + 1; j ... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n;
cin >> t;
while (t--) {
cin >> n;
int arr[n];
map<int, int> maps;
for (int i = 0; i < n; i++) {
cin >> arr[i];
maps[arr[i]]++;
}
int flag = 0;
for (auto i : maps) {
if (i.second > 1) {
cout <... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int i = 0, j = 0;
long long gcd(long long a, long long b) {
if (b == 0) return a;
return gcd(b, a % b);
}
bool isPowerOfTwo(long long n) { return n && (!(n & (n - 1))); }
bool is_numeric(char c) { return c >= 'a' and c <= 'z'; }
string decToBinary(int n) {
string bina... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
int main() {
int t;
scanf("%d", &t);
int n;
for (int i = 0; i < t; i++) {
scanf("%d", &n);
int a[n];
for (int j = 0; j < n; j++) {
scanf("%d", &a[j]);
}
int min = 10000;
for (int j = 0; j < n; j++) {
for (int k = 0; k < n; k++) {
int temp;
... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int mn = 1001;
int vl1 = 0;
int vl2 = 0;
for ... | ### Prompt
Create a solution in CPP for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
int powerMod(int x, unsigned int y, int MOD) {
int res = 1;
x = x % MOD;
if (x == 0) return 0;
while (y > 0) {
if (y & 1) res = (res * x) % MOD;
y = y >> 1;
x = (x * x) % MOD;
}
return res;
}
int main() {
int t;
cin >> t;... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
void input(int &x) {
bool neg = false;
register int c;
x = 0;
c = getchar();
if (c == '-') {
neg = true;
c = getchar();
}
for (; (c > 47 && c < 58); c = getchar()) x = (x << 1) + (x << 3) + c - 48;
if (neg) x *= -1;
}
int main() {
ios_base::sync_wi... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
const int MAX = 50;
void Get_Array(int n, int a[]) {
for (int i = 0; i < n; i++) {
cin >> a[i];
}
}
void Print_Array(int n, int a[]) {
for (int i = 0; i < n; i++) {
cout << i << "---->" << a[i] << endl;
}
}
void MG(int k, int m, int v[], int u[], int s[]) {
... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int long long n, a[60], mx = 2000;
scanf("%lld", &n);
for (int i = 0; i < n; i++) {
scanf("%lld", &a[i]);
}
sort(a, a + n);
for (int i = 1; i < n; i++) {
mx = min(mx, abs(a[i - 1] - a[i]))... | ### Prompt
Generate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
long long ar[n], ans = 1000000, a, b;
for (int i = 0; i < n; i++) {
cin >> ar[i];
}
sort(ar, ar + n);
for (int i = 0; i < n - 1; i++) {
a = ar[i + 1] - ar[i];
an... | ### Prompt
Create a solution in cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
long long n, a[51];
bool cmp(long long x, long long y) { return x < y; }
void A() {
long long ans = 1000000000;
scanf("%lld", &n);
for (long long i = 1; i <= n; i++) scanf("%lld", &a[i]);
sort(a + 1, a + n + 1, cmp);
for (long long i = 1; i < n; i++) ans = min(ans... | ### Prompt
Generate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int T;
int answer = 0;
vector<int> v;
int main(void) {
ios::sync_with_stdio(0);
cin.tie(nullptr);
cout.tie(nullptr);
cin >> T;
while (T--) {
v.clear();
int n;
cin >> n;
v.resize(n);
for (int i = 0; i < n; ++i) {
cin >> v[i];
}
sor... | ### Prompt
Generate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int honest_coach(vector<int> arr, int n) {
sort(arr.begin(), arr.end());
int result = INT_MAX;
for (int i = 0; i < arr.size() - 1; i++) {
result = min(result, abs(arr[i] - arr[i + 1]));
}
return result;
}
int main() {
int T;
cin >> T;
while (T--) {
i... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
const int mod = 998244353;
vector<long long> p;
int ho, mi, se, ho1, mi1, cnt;
void fix_time() {
if (se > 59) mi += se / 60, se = se % 60;
if (se < 0) se += 60, mi--;
if (mi > 59) ho += mi / 60, mi = mi % 60;
if (mi < 0) mi += 60, ho--;
if (ho < 0) ho += 24;
if ... | ### Prompt
Generate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
struct compare {
bool operator()(pair<long long int, long long int> a,
pair<long long int, long long int> b) {
if ((a.second - a.first) > (b.second - b.first))
return false;
else if ((a.second - a.first) == (b.second - b.first)) {
if ... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, a, b;
cin >> n;
while (n--) {
cin >> a;
vector<int> vect;
int mini(1001);
while (a--) {
cin >> b;
vect.push_back(b);
}
sort(vect.begin(), vect.end());
for (int i(0); i < vect.size() - 1; i++) {
if (abs(... | ### Prompt
Generate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int n, m;
int read() {
int s = 0, f = 1;
char ch = getchar();
while (ch < '0' || ch > '9') {
if (ch == '-') f = -1;
ch = getchar();
}
while (ch >= '0' && ch <= '9') {
s = s * 10 + ch - '0';
ch = getchar();
}
return s * f;
}
int s[101010];
int m... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int abs(int a, int b) {
if (a < b) {
return b - a;
} else {
return a - b;
}
}
int main() {
int t;
int arr[100];
cin >> t;
for (int i = 0; i < t; i++) {
int n;
cin >> n;
for (int j = 0; j < n; j++) {
cin >> arr[j];
}
int min_va... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
const int mod = 998244353;
long long t, n, a[55], b;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> t;
while (t--) {
cin >> n;
for (int i = 1; i <= n; i++) cin >> a[i];
long long ans = 1e9;
sort(a + 1, a + 1 + n);
for (in... | ### Prompt
Generate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int m = a[1] - a[0];
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
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