output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n;
while (cin >> n) {
int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int ans = a[1] - a[0];
for (int i = 2; i < n; i++) {
int t = a[i] - a[i - 1];
ans = min(ans, t);
}
cout << ans << "\n";
... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
template <typename A>
ostream &operator<<(ostream &cout, vector<A> const &v);
template <typename A, typename B>
ostream &operator<<(ostream &cout, pair<A, B> const &p) {
return cout << "(" << p.first << ", " << p.second << ")";
}
template <typename A>
ostream &operator<<(... | ### Prompt
Please create a solution in cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t;
cin >> t;
while (t--) {
vector<int> ath;
int a;
cin >> a;
for (int i = 0; i < a; i++) {
int g;
cin >> g;
ath.emplace_back(g);
}
sort(ath.begin(), ath.... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int cases;
cin >> cases;
for (int i = 0; i < cases; i++) {
vector<int> v;
int len;
cin >> len;
for (int j = 0; j < len; j++) {
int inp;
cin >> inp;
v.push_back(inp);
}
sort(v.begin(), v.end());
int min = 2000;... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
long long t;
cin >> t;
while (t--) {
long long n;
cin >> n;
vector<long long> v(n);
for (long long i = 0; i < n; i++) cin >> v[i];
sort(v.begin(), v.end());
long long ans = INT_MAX;
for (long long i = 0; i < (n - 1); i++) a... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0);
srand(time(NULL));
long long int t, i, j;
cin >> t;
while (t--) {
long long int n;
cin >> n;
long long int a[n];
long long int ans = LONG_LONG_MAX;
for (i = 0; i < n; i++) ... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
long long int n;
cin >> n;
int arr[n];
vector<long long int> v;
for (int i = 0; i < n; i++) cin >> arr[i];
sort(arr, arr + n);
for (int i = 0; i < n - 1; i++) {
int x = arr[i] - arr[i + 1];
... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
const double PI = acos(-1);
const long long int MOD = 1000000007;
int main() {
int t;
scanf("%d", &t);
while (t--) {
int n;
scanf("%d", &n);
vector<int> v(n);
for (int i = int(0); i <= int(n - 1); i++) scanf("%d", &v[i]);
sort(v.begin(), v.end());
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
const long long N = 1e6 + 1;
set<long long> o;
map<long long, long long> mp, pm;
map<char, long long> hs;
vector<long long> v, vc, oreder1, inoreder, posoreder, ve, vv, vd;
deque<char> p, pe;
deque<string> ts, ss, stoi, rs;
deque<double> sd, ds;
string g, s, w, h, s1;
char ... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
long long exp(long long x, long long y, long long p) {
long long res = 1;
while (y) {
if (y % 2) res = (res * x % p) % p;
x = (x * x) % p;
y /= 2;
}
return res;
}
long long exp(long long x, long long y) {
long long res = 1;
while (y) {
if (y % 2)... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int t;
cin >> t;
while (t--) {
long long int n;
cin >> n;
vector<int> a(n);
for (int i = 0; i < n; i++) {
cin >> a[i];
}
int ans = INT_MAX;
sort(a.begin(), a.end());
for (int i = 0; i < n - 1; i++) {
a... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
void codeforces() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
int32_t main() {
codeforces();
long long t;
cin >> t;
while (t--) {
long long n;
cin >> n;
vector<long long> a(n);
long long d = INT_MAX;
for (long long i = 0; i <... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long t;
cin >> t;
while (t--) {
long long n;
cin >> n;
long long a[n];
for (long long i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
long long m = a[1] - a[0];
for (long long i = 0; i < n - 1; i++) {
i... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
const int M = 1e5 + 7;
int a[55];
int main() {
ios_base::sync_with_stdio(false), cin.tie(0);
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int mn = 1 << 29;
for (int i = 1; i < n; i++... | ### Prompt
Create a solution in cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
}
int min = INT_MAX;
for (int i = 0; i < n - 1; i++) {
for (int j = i + 1; j < n; j++)
if (abs(a[i] - a[j]... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
inline char nc() {
static char buf[100000], *p1 = buf, *p2 = buf;
return p1 == p2 && (p2 = (p1 = buf) + fread(buf, 1, 100000, stdin), p1 == p2)
? EOF
: *p1++;
}
inline int read() {
static char c = nc();
int x = 0, f = 1;
for (; c > '9' ||... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
long long int t;
cin >> t;
while (t--) {
long long n;
cin >> n;
long long a[n], i, ans = 999999999;
for (int i = (0); i < (n); i++) cin >> (a)[i];
;
sort(a, a + n);
fo... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
const long long MOD = 1000000007;
const long long INF = 1e15;
using Graph = vector<vector<long long>>;
signed main() {
long long T;
cin >> T;
for (long long t = 0; t < T; t++) {
long long N;
cin >> N;
vector<long long> A(N);
for (long long i = 0; i < N... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
vector<int> v;
while (t--) {
vector<int> v;
int n, m = 0;
cin >> n;
for (int i = 0; i < n; i++) {
int c;
cin >> c;
v.push_back(c);
}
sort(v.begin(), v.end());
for (int i = 0; i < v.size() - ... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int t, n, a[1001], ans = 10000;
int main() {
cin >> t;
while (t--) {
cin >> n;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
for (int i = 0; i < n - 1; i++) {
ans = min(ans, (a[i + 1] - a[i]));
}
cout << ans << endl... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> s(n);
for (int i = 0; i < n; i++) {
cin >> s[i];
}
sort(s.begin(), s.end());
int ans = INT_MAX;
for (int i = 0; i < n - 1; i++) {
ans = min(s[i + 1] - ... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n;
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) cin >> arr[i];
int mi = INT_MAX;
for (int i = 0; i < n - 1; i++) {
for (int j = i + 1; j < n; j++) {
mi = min(mi, abs(arr[i] - arr[j]));
}
}
cout << mi;
cout << endl;
;... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1000000007;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
long long t, n, i, j, m, k, a, b, c = 0;
cin >> t;
while (t--) {
cin >> n;
long long ar[n];
for (long long i = 0; i < n; i++) cin >> ar[i];
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
while (n--) {
bool digits[1005] = {false};
int numbers;
cin >> numbers;
int dataset[numbers], done = 0;
for (int i = 0; i < numbers; i++) {
cin >> dataset[i];
if (digits[dataset[i]]) done = 1;
digits[... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
vector<int> v;
int n, k, a, c, flag = 0, x, tlag = 0, dis, q, firstone, y, len, z, vagfol,
i, sum = 0, ans, total, coun = 0;
cin >> n;
string str;
for (int i = 0; i < n; i++) {
c... | ### Prompt
Generate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int t, n;
vector<long long> s;
long long min_;
int main() {
cin >> t;
for (int z = 0; z < t; ++z) {
cin >> n;
for (int i = 0; i < n; ++i) {
long long temp;
cin >> temp;
s.push_back(temp);
}
sort(s.begin(), s.end());
min_ = s[1] - s[... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
const int M = 1e9 + 7;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int s[n];
for (int i = 0; i < n; i++) {
cin >> s[i];
}
sort(s, s + n);
int ans = 1000;
... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
const int INF = 1e5 + 5;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int t;
cin >> t;
while (t) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int min = a[1] - a[0];
for (int i = 2; i < ... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
void solve(void) {
int n;
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n);
int res = 9999;
for (int i = 0; i < n - 1; i++) {
if (abs(arr[i] - arr[i + 1]) < res) {
res = abs(arr[i] - arr[i + 1]);
}
}... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int arr[n];
int dif = INT_MAX;
for (int i = 0; i < n; i++) cin >> arr[i];
int locmin;
for (int i = 0; i < n - 1; i++) {
for (int j = i + 1; j < n; j++) {
locmin = ab... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
;
int t, n, i, x, min;
cin >> t;
while (t--) {
cin >> n;
int arr[n];
for (i = 0; i < n; i++) cin >> arr[i];
sort(arr, arr + n);
min = abs(arr[0] - arr[1]);
for (i = 1; i < n - ... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
const long long int MOD = 1e9 + 7;
long long int power(long long int x, long long int y, long long int p) {
long long int res = 1;
x = x % p;
while (y > 0) {
if (y & 1) res = (res * x) % p;
y = y >> 1;
x = (x * x) % p;
}
return res;
}
long long int gcd... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
long long int power(long long int x, long long int n) {
long long int result = 1;
while (n) {
if (n % 2 == 1) result = result * x;
n = n / 2;
x = x * x;
}
return result;
}
long long int gcd(long long int a, long long int b) {
if (!b) return a;
return gcd(b, a % b);
}
lon... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
for (size_t rq = 0; rq < t; ++rq) {
int n, s, ans = 0;
vector<int> vec;
cin >> n;
for (size_t i = 0; i < n; ++i) {
cin >> s;
vec.push_back(s);
}
sort(vec.begin(), vec.end());
ans = vec[n - 1] - vec[... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
long long fx[4] = {1, -1, 0, 0};
long long fy[4] = {0, 0, 1, -1};
bool sortinrev(const pair<int, int> &a, const pair<int, int> &b) {
return a.first > b.first;
}
long long pw(long long a, long long b) {
long long ans = 1;
for (long long i = 1; i <= b; ++i) ans = (ans *... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
long long dij[10][10];
double pi = acos(-1);
long long a[1000010], b[1 << 20];
long long gcd(long long x, long long y) { return y ? gcd(y, x % y) : x; }
double C(long long n, long long m) {
if (m < 0 || m > n) return 0;
double ans = 1;
for (double i = 1; i <= m; i++) ... | ### Prompt
Please create a solution in CPP to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 7;
const int mod = 1e9 + 7;
int num[maxn];
int main() {
int t, n, m, ans;
scanf("%d", &t);
while (t--) {
ans = 1000000;
scanf("%d", &n);
for (int i = 0; i < n; i++) scanf("%d", &num[i]);
sort(num, num + n);
for (int i = 1; i ... | ### Prompt
Create a solution in cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int test;
cin >> test;
for (int tt = 0; tt < test; tt++) {
int n;
cin >> n;
vector<int> a(n);
for (int &x : a) {
cin >> x;
}
sort(a.begin(), a.end());
int result = a[n - 1] - a[0];
for (int i = 1; i < n; i++) {
... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
int t;
cin >> t;
while (t--) {
long long n;
cin >> n;
long long a[n];
for (long long i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
long long min = a[1] - a[0], cur... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
void program() {
int n, temp;
cin >> n;
vector<int> a;
for (int i = 0; i < n; i++) {
cin >> temp;
a.push_back(temp);
}
sort(a.begin(), a.end());
int dif1, flag, minimum = a[1] - a[0];
for (int i = 1; i < n - 1; i++) {
dif1 = a[i + 1] - a[i];
... | ### Prompt
Generate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int T;
cin >> T;
for (int i = 1; i <= T; i++) {
int n;
cin >> n;
vector<int> v;
for (int j = 1; j <= n; j++) {
int x;
cin >> x;
v.push_back(x);
}
sort(v.begin(), v.end());
int ans = v[1] - v[0];
for (int j... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int m = INT_MAX;
for (int i = 0; i < n - 1; i++) {
if (a[i + 1] - a[i] < m) {
m = a[i + 1] - a[i];
}
}
cout << m << endl;
}
int main(... | ### Prompt
Please create a solution in cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, a, b, c, d, e, f;
vector<int> v;
cin >> t;
for (a = 0; a < t; a++) {
cin >> b;
f = 999;
for (c = 0; c < b; c++) {
cin >> d;
v.push_back(d);
}
sort(v.begin(), v.end());
for (c = b - 1; c > 0; c--) {
e = v[... | ### Prompt
Construct a cpp code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
const long long int mod = 1000000000 + 7;
long long int mul(long long int a, long long int b) {
return ((a % mod) * (b % mod)) % mod;
}
long long int add(long long int a, long long int b) {
return ((a % mod) + (b % mod)) % mod;
}
void solve() {
int n;
cin >> n;
ve... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> a(n);
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a.begin(), a.end());
int sub1 = a[n - 1] - a[0];
int i = 0, check = 0;
while (i < n - 1 && check ... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, x;
int size;
int min;
vector<int> num;
cin >> n;
for (int i = 0; i < n; i++) {
cin >> size;
for (int j = 0; j < size; j++) {
cin >> x;
num.push_back(x);
}
sort(num.begin(), num.end());
min = abs(num[1] - num[0]... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, x, m = 1001;
cin >> n;
vector<int> v;
for (int i = 0; i < n; i++) {
cin >> x;
v.push_back(x);
}
sort(v.begin(), v.end());
for (int i = 0; i < n - 1; i++) m = min(m, v[i + 1] - v... | ### Prompt
Create a solution in CPP for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int min = 1000;
int diff[n - 1];
for (int i = 0; i < n - 1; i++) diff[i] = a[i + 1] - a[i];
for (int i =... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, s[55];
scanf("%d", &t);
while (t--) {
scanf("%d", &n);
for (int i = 0; i < n; i++) scanf("%d", &s[i]);
sort(s, s + n);
int ans = 2000;
for (int i = 1; i < n; i++) {
if (s[i] - s[i - 1] < ans) ans = s[i] - s[i - 1];
... | ### Prompt
Create a solution in CPP for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int dx[] = {0, 1};
int dy[] = {1, 0};
const long double Pi = acos(-1), e = 2.718;
const int N = 1e6 + 10, mod = 1e9 + 7;
int main() {
ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
int T;
cin >> T;
while (T--) {
int n;
cin >> n;
vector<int> a(n);... | ### Prompt
Create a solution in CPP for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
void merge(int *array, int a, int b, int c) {
int x = c + 50;
int y = a;
int z = b;
int subray[x];
for (int i = a; i <= c; i++) {
if ((array[y] > array[z] && y < b) || z > c) {
subray[i] = array[y];
y++;
} else {
subray[i] = array[z];
... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t;
cin >> t;
while (t--) {
long long int n;
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
int diff = 0, min = 1000000000;
sort(arr, arr + n);... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
int mina(int p) {
int a[p];
for (int j = 0; j < p; j++) {
cin >> a[j];
}
sort(a, a + p);
int minb = (int)1e9;
for (int k = 0; k < p - 1; k++) {
if (a[k + 1] - a[k] < minb) {
minb = a[k + 1] - a[k];
}
}
return minb;
}
int main() {
ios::syn... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
void printarray(int arr[], int n) {
for (int i = 0; i < n; i++) cout << arr[i] << " ";
cout << "\n";
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cerr.tie(0);
int t;
cin >> t;
for (int i = 0; i < t; i++) {
int n;
cin >>... | ### Prompt
Please create a solution in CPP to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
for (int i = 0; i < n; i++) {
for (int j = 0; j < (n - i - 1); j++) {
if (a[j] > a[j + 1]) {
int x = a[j];
... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> v(n);
for (auto &z : v) cin >> z;
sort(v.begin(), v.end());
int res = 1e9;
for (int i = 0; i < n - 1; ++i) {
res = min(res, abs(v[i] - v[i + 1]));
}
cout... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int test;
cin >> test;
while (test--) {
long long int num;
cin >> num;
long long int arr[num + 1];
for (long long int i = 0; i < num; i++) cin >> arr[i];
sort(arr, arr + num);
long long int ans = arr[1] - arr[0];
for ... | ### Prompt
Construct a cpp code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
int getMinDiff(int arr[], int n) {
int freq[100001] = {0};
for (int i = 0; i < n; i++) {
freq[arr[i]]++;
if (freq[arr[i]] > 1) return 0;
}
int mn = INT_MAX;
for (int i = 0; i < 100001; i++) {
if (freq[i] > 0) {
i++;
int cnt = 1;
while... | ### Prompt
In CPP, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int t;
cin >> t;
while (t--) {
int n;
cin >> n;
long long int a[n + 1];
for (long long int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
long long int res = a[n - 1];
long long int m;
for (long lon... | ### Prompt
Your task is to create a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n = 0;
cin >> n;
vector<int> v(n);
for (int i = 0; i < v.size(); i++) cin >> v[i];
sort(v.begin(), v.end());
vector<int> ans(n);
ans[0] = INT_MAX;
for (int i = 1; i < n; i++) {
ans[i] = v[i] - v[i - 1];
}
cout << *min_element(ans.b... | ### Prompt
Please create a solution in CPP to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int tc;
cin >> tc;
while (tc--) {
int n;
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n);
int minn = INT_MAX;
for (int i = 0... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, g, a;
cin >> n;
int s[n];
for (int i = 0; i < n; i++) {
cin >> s[i];
}
a = max(s[0], s[n - 1]);
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i != j) {... | ### Prompt
Create a solution in Cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n;
cin >> n;
vector<int> v;
for (int i = 0; i < n; i++) {
int x;
cin >> x;
v.push_back(x);
}
sort(v.begin(), v.end());
int diff = INT_MAX;
for (int i = 0; i < n - 1; i++) {
diff = min(diff, v[i + 1] - v[i]);
}
cout << d... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int k, A[10000];
cin >> k;
for (int t = 1; t <= k; t++) {
int n;
int ans = INT_MAX;
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> A[i];
}
sort(A + 1, A + 1 + n);
for (int i = 1; i < n; i++) {
ans = min(ans, A[i + ... | ### Prompt
Create a solution in cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int s[n + 1];
for (int i = 1; i <= n; cin >> s[i], ++i)
;
sort(s + 1, s + n + 1);
for (int i = n; i >= 2; --i) s[i] -= s[i - 1];
int res = 0x3f3f3f3f;
for (int i = 2; i ... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
int n, k, asdasjkd, adsnamsd, a[101], mna, mnb, b[101];
int ans;
int main() {
int t23 = 1;
cin >> t23;
for (int qwe = 1; qwe <= t23; qwe++) {
cin >> n;
for (int i = 1; i <= n; i++) cin >> a[i];
ans = 1e9;
sort(a + 1, a + n + 1);
for (int i = 2; i <... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n;
cin >> t;
for (int i = 0; i < t; i++) {
cin >> n;
vector<int> a;
for (int j = 0; j < n; j++) {
int k;
cin >> k;
a.push_back(k);
}
sort(a.begin(), a.end());
int min = 10000;
for (int j = 0; j < n - 1;... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int TN = 1;
void sol() {
long long n;
cin >> n;
vector<long long> a(n);
for (int i = 0; i < n; ++i) {
cin >> a[i];
}
sort(a.begin(), a.end());
long long ans = 1e18;
for (int i = 1; i < n; ++i) {
ans = min(ans, a[i] - a[i - 1]);
}
cout << ans << '... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
int t, n, a[10000];
int main() {
int t = 1;
cin >> t;
while (t--) {
cin >> n;
int ans = 1000000;
for (int i = 1; i <= n; i++) cin >> a[i];
for (int i = 1; i <= n; i++)
for (int j = i + 1; j <= n; j++) ans = min(ans, abs(a[i] - a[j]));
cout <<... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
int main() {
int t;
scanf("%d", &t);
while (t--) {
int n;
scanf("%d", &n);
int a[n];
for (int i = 0; i < n; i++) {
scanf("%d", &a[i]);
}
for (int i = 0; i < n; i++) {
for (int j = 0; j < n - i - 1; j++) {
if (a[j + 1] < a[j]) {
int t =... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
const double pi = 3.14159265358979323846;
using namespace std;
int main() {
int t, n;
cin >> t;
while (t--) {
cin >> n;
int* arr = new int[n];
set<int> s;
for (int i = 0; i < n; i++) {
cin >> arr[i];
s.insert(arr[i]);
}
sort(arr, arr + n);
int best ... | ### Prompt
Please create a solution in CPP to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
long long mod = 998244353;
int main() {
long long t;
cin >> t;
while (t--) {
long long n;
cin >> n;
long long a[n];
for (long long i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
long long min = a[n - 1];
for (long long i = 0; i < n - 1; i+... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
long long n;
cin >> n;
vector<long long> vec;
while (n--) {
long long a;
cin >> a;
vec.push_back(a);
}
sort(vec.begin(), vec.end());
long long d = LLONG_MAX;
for (int i = 0; ... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(!cin.tie(0));
long long int t;
cin >> t;
for (long long int p = 1; p <= t; p++) {
long long int n;
cin >> n;
vector<long long int> a(n);
vector<long long int> diff(n - 1);
for (long long int i = 0; i < n; i+... | ### Prompt
In CPP, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
const long long INF = 1e9 + 7;
const long long mod = 998244353;
int32_t main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
long long T;
cin >> T;
while (T--) {
long long n;
cin >> n;
long long s[n];
long long i, j, l;
for (i ... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
const int INF = 0x3f3f3f3f;
const int MAX = 2e5 + 5;
long long gcd(long long x, long long y) { return y == 0 ? x : gcd(y, x % y); }
int s[MAX];
int main() {
std::ios::sync_with_stdio(false);
int T;
int n;
cin >> T;
while (T--) {
cin >> n;
for (int i = 0; i... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization("unroll-loops")
using namespace std;
const long long MOD = 1e+9 + 7;
const long long INF = 0x7f7f7f7f7f7f7f7f;
const int INFi = 0x7f7f7f7f;
const long long MAXN = 1e+5 + 7;
vector<long long> adj[MAXN];
lon... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
vector<int> a;
int main() {
ios_base::sync_with_stdio(false);
int q, small;
cin >> q;
while (q--) {
int n;
cin >> n;
a.clear();
a.resize(n);
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a.begin(), a.end());
small = 999;
... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> a(n);
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a.begin(), a.end());
int ans = 1E5;
for (int i = 1; i < n; i++) {
ans = min(ans, a[i] - a[i - 1... | ### Prompt
Please create a solution in CPP to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int min = INT_MAX, ans;
for (int i = 0; i < n - 1; i++) {
if ((a[i + 1] - a[i]) < min) {
ans = a[i... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n;
cin >> n;
vector<int> a(n);
for (int i = 0; i < n; ++i) cin >> a[i];
sort(a.begin(), a.end());
vector<int> diff(n - 1);
int ind = 0;
for (int i = 0; i < n - 1; ++i) {
diff[ind++] = abs(a[i + 1] - a[i]);
}
sort(diff.begin(), diff... | ### Prompt
Generate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t;
cin >> t;
for (int l = 0; l < t; ++l) {
int n;
cin >> n;
int mn = 1000;
int a[n];
for (int i = 0; i < n; ++i) cin >> a[i];
sort(a, a + n);
for (int i = 1; ... | ### Prompt
Generate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long t, n, b, k, i, c;
cin >> t;
while (t--) {
cin >> n;
long long a[n];
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
c = a[n - 1] - a[0];
for (i = 1; i < n; i++) {
if (a[i] - a[i - 1] < c) c = a[i] - a[i - 1];
... | ### Prompt
Create a solution in cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int tests(void);
int main() {
ios_base::sync_with_stdio(0);
cin.tie(NULL);
cout.tie(NULL);
int test;
cin >> test;
while (test--) {
tests();
}
return 0;
}
int tests() {
int n, mini = INT_MAX, sum;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int t;
cin >> t;
while (t--) {
long long int n;
cin >> n;
vector<long long int> vec(n);
vector<long long int> v;
for (long long int i = 0; i < n; i++) cin >> vec[i];
for (int i = 0; i < n; i++) {
for (int j = i + 1;... | ### Prompt
Please create a solution in cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
#pragma GCC target( \
"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,tune=native")
#pragma GCC optimize("unroll-loops")
using namespace std;
const long double EPS = 0.001;
const long double EPS2 = 1e-6;
const long double PI = acos(-1);
const int MOD7 = 1000000007;
const int MOD9 = 100000... | ### Prompt
In CPP, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
int athlete(int a[], int n) {
int diff = 0, min = INT_MAX;
sort(a, a + n);
for (int i = 1; i < n; i++) {
diff = a[i] - a[i - 1];
if (diff <= min) {
min = diff;
}
}
return min;
}
int main() {
int t, n, at;
int a[50];
cin >> t;
for (int i =... | ### Prompt
Please create a solution in cpp to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
int main() {
int t;
scanf("%d", &t);
for (int i = 0; i < t; i++) {
int n;
scanf("%d", &n);
int ar[n];
for (int i = 0; i < n; i++) {
scanf("%d", &ar[i]);
}
int temp;
for (int i = 0; i < n - 1; i++) {
for (int j = i + 1; j < n; j++) {
if (ar[i... | ### Prompt
Create a solution in Cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int a[10005];
int n, z;
int t, sum;
int ans;
int main() {
cin >> t;
while (t--) {
z = 0;
cin >> n;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int y = 10000;
for (int i = 1; i < n; i++) {
z = a[i] - a[i - 1];
... | ### Prompt
Generate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int num[60], flag[2000];
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t;
cin >> t;
while (t--) {
int n, f = 1;
cin >> n;
memset(flag, 0, sizeof(flag));
for (int i = 1; i <= n; i++) {
cin >> num[i];
if (flag[num[i... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int a[51], n;
cin >> n;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int res = INT_MAX;
for (int i = 1; i < n; i++) {
res = min(res, a[i] - a[i - 1]);
}
cout << res << endl;
... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
const long long inf = 1e18;
long long add(long long x, long long y) {
long long res = x + y;
return (res >= 1000000007 ? res - 1000000007 : res);
}
long long mul(long long x, long long y) {
long long res = x * y;
return (res >= 1000000007 ? res % 1000000007 : res);
... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
long long int minn(long long int a, long long int b) {
if (a > b)
return b;
else
return a;
}
long long int power(long long int x, long long int y, long long int p) {
long long int res = 1;
x = x % p;
if (x == 0) return 0;
while (y > 0) {
if (y & 1) r... | ### Prompt
Generate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int arr[n + 3];
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n);
int m = 10000;
for (int i = 0; i < n - 1; i++) {
if (arr[i + 1] - arr[i] < m) {
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, min = 999999999;
cin >> n;
vector<int> arr(n);
int val;
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr.begin(), arr.end());
for (int i = 0; i < n - 1; i++) {
if (ar... | ### Prompt
In cpp, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
int min(int a, int b) {
if (a < b) return a;
return b;
}
int main() {
int t, n;
scanf("%d", &t);
for (int l = 0; l < t; l++) {
scanf("%d", &n);
int a[n];
for (int i = 0; i < n; i++) scanf("%d", &a[i]);
if (n == 2) {
printf("%d\n", -min((a[0] - a[1]), (a[1] - a[0]... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int j, t;
cin >> t;
for (j = 0; j < t; j++) {
int n, i, x;
cin >> n;
int a[100] = {0};
for (i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int mi = 0;
mi = a[1] - a[0];
for (i = 0; i < n - 1; i++) {
x =... | ### Prompt
Create a solution in cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
vector<int> v;
for (int i = 0; i < n - 1; i++) {
v.push_back(a[i + 1] - a[i]);
}
int... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
long long int t, n, s = 0, A[1000000];
int main() {
cin >> t;
for (int y = 1; y <= t; y++) {
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> A[i];
}
sort(A + 1, A + n + 1);
s = A[2] - A[1];
for (int i = 1; i <= n - 1; i++) {
if (s > A... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int isalpha(int *arr, int n) {
int ans = INT_MAX;
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
ans = min(ans, abs(arr[i] - arr[j]));
}
}
return ans;
}
int main() {
int test;
scanf("%d", &test);
while (test--) {
int n;
s... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
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