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{ "label": [ "A", "B", "C", "D" ], "text": [ "1394", "1294", "1194", "1094" ] }
[ "A" ]
find the least number which when divided by 20 , 25,35 and 40 leaves remainders 14 , 19,29 and 34 respectively .
"here , ( 20 - 14 ) = 6 , ( 25 – 19 ) = 6 , ( 35 - 29 ) = 6 and ( 40 - 34 ) = 6 . therefore , required number = ( l . c . m . of 20,25 , 35,40 ) – 6 = 1394 . answer is a ."
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "0.94", "9.4", "0.094", "94" ] }
[ "A" ]
subtracting 6 % of a from a is equivalent to multiplying a by how much ?
"answer let a - 6 % of a = ab . β‡’ ( 94 x a ) / 100 = ab ∴ b = 0.94 correct option : a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "146", "148", "150", "152" ] }
[ "C" ]
how many 3 digit numbers are completely divisible 6 ?
"explanation : 100 / 6 = 16 , remainder = 4 . hence 2 more should be added to 100 to get the minimum 3 digit number divisible by 6 . = > minimum 3 digit number divisible by 6 = 100 + 2 = 102 999 / 6 = 166 , remainder = 3 . hence 3 should be decreased from 999 to get the maximum 3 digit number divisible by 6 . = > maxim...
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "2 : 1", "3 : 1", "5 : 2", "1 : 1" ] }
[ "A" ]
a good train and a passenger train are running on parallel tracks in the same direction . the driver of the goods train observes that the passenger train coming from behind overtakes and crosses his train completely in 60 sec . whereas a passenger on the passenger train marks that he crosses the goods train in 40 sec ....
explanation : let , the speeds of the two trains be s and 2 s m / s respectively . also , suppose that the lengths of the two trains are p and q metres respectively . then , = > ( p + q ) / ( 2 s βˆ’ s ) = 60 . - - - - - - - - - - - - - - ( 1 ) and , = > p / ( 2 s βˆ’ s ) = 40 . - - - - - - - - - - - - - - ( 2 ) on dividin...
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "380", "350", "333", "310" ] }
[ "C" ]
( 3164 + 6160 ) / 28
"explanation : as per bodmas rule , first we will solve the equation in bracket then we will go for division = ( 9324 ) / 28 = 333 option c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "βˆ’ 2 %", "2 %", "22 %", "25 %" ] }
[ "D" ]
the price of a consumer good increased by pp % during 20122012 and decreased by 1212 % during 20132013 . if no other change took place in the price of the good and the price of the good at the end of 20132013 was 1010 % higher than the price at the beginning of 20122012 , what was the value of pp ?
as per question = > price was simple 10 percent greater hence x [ 1 + 10 / 100 ] must be the final price . equating the two we get = > x [ 110 / 100 ] = x [ 1 + p / 100 ] [ 88 / 100 ] = > 44 p + 4400 = 5500 = > 44 p = 1100 = > p = 1100 / 44 = > 100 / 4 = > 25 . so p must be 25 answer : d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 27,000", "rs . 26,000", "rs . 30,000", "rs . 36,000" ] }
[ "B" ]
jayant opened a shop investing rs . 30,000 . madhu joined him 2 months later , investing rs . 45,000 . they earned a profit of rs . 52,000 after completion of one year . what will be madhu ' s share of profit ?
"30,000 * 12 = 45,000 * 8 1 : 1 madhu ' s share = 1 / 2 * 52,000 i . e . rs . 26,000 answer : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "3", "5", "7", "9" ] }
[ "B" ]
if the a radio is sold for rs 490 and sold for rs 465.50 . find loss percentage .
cost price = rs 490 , selling price = 465.50 . loss = rs ( 490 - 465.50 ) = rs 24.50 . loss % = [ ( 24.50 / 490 ) * 100 ] % = 5 % answer is b
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 130", "rs . 17", "rs . 1.70", "rs . 4.25" ] }
[ "A" ]
if 0.5 % of a = 65 paise , then the value of a is ?
answer ∡ 0.5 / 100 of a = 65 / 100 ∴ a = rs . ( 65 / 0.5 ) = rs . 130 correct option : a
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1", "4", "9", "11" ] }
[ "D" ]
suppose a , b , and c are positive integers with a < b < c such that 1 / a + 1 / b + 1 / c = 1 . what is a + b + c ?
first note that we must have 1 / a < 1 , so a > 1 . since 1 / a > 1 / b > 1 / c , we must also have 1 / a > 1 / 3 ; so a < 3 . thus , a / 2 . now 1 / b + 1 / c = 1 / 2 where 2 < b < c . similar to before , 1 / b > 1 / 4 , so b < 4 . thus , b = 3 . with a = 2 and b = 3 we have 1 / 2 + 1 / 3 + 1 / c = 1 , which is satisf...
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "4", "7", "6", "12" ] }
[ "C" ]
two sets of 3 consecutive positive integers have exactly one integer in common . the sum of the integers in the set with greater numbers is how much greater than the sum of the integers in the other set ?
"a = ( 2 , 3,4 ) , sum of this = 9 b = ( 4 , 5,6 ) , sum of this = 15 , the differenct between 15 - 9 = 6 hence , 6 is the answer i . e . c"
MathQA
{ "label": [ "A", "B", "C", "E" ], "text": [ "30", "40", "60", "74" ] }
[ "E" ]
how many pieces of 75 cm can be cut from a rope 55.5 meters long ?
"explanation : total pieces of 75 cm that can be cut from a rope of 55.5 meters long is = ( 55.5 meters ) / ( 75 cm ) = ( 55.5 meters ) / ( 0.75 meters ) = 74 answer : e"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "80", "60", "- 60", "- 70" ] }
[ "C" ]
a merchant gains or loses , in a bargain , a certain sum . in a second bargain , he gains 380 dollars , and , in a third , loses 70 . in the end he finds he has gained 250 dollars , by the 3 together . how much did he gain or lose bv the first ?
in this sum , as the profit and loss are opposite in their nature , they must be distinguished by contrary signs . if the profit is marked + , the loss must be - . let x = the sum required . then according to the statement x + 380 - 70 = 250 and x = - 60 . answer c
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1", "0", "2", "3" ] }
[ "B" ]
what is the remainder when 7 ^ 74 - 5 ^ 74 is divided by 12 ?
"easiest way for me : 7 ^ 74 - 5 ^ 74 = ( 49 ) ^ 37 - 25 ^ 37 = ( 12 * 4 + 1 ) ^ 37 - ( 12 * 2 + 1 ) ^ 37 - > remainder is 1 ^ 37 - 1 ^ 37 = 0 ans : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 1600", "rs . 1500", "rs . 2000", "rs . 2500" ] }
[ "A" ]
a sum of money is to be distributed among a , b , c , d in the proportion of 5 : 2 : 4 : 3 . if c gets rs . 800 more than d , what is b ' s share ?
"let the shares of a , b , c and d be rs . 5 x , rs . 2 x , rs . 4 x and rs . 3 x respectively . then , 4 x - 3 x = 800 x = 800 . b ' s share = rs . 2 x = rs . ( 2 x 800 ) = rs . 1600 . answer = a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "42000", "46000", "54000", "40000" ] }
[ "D" ]
a is a working partner and b is a sleeping partner in a business . a puts in 80,000 and b 70,000 . a gets 25 % of the profit for managing the business , and the rest is divided in proportion to their capitals . find the profit if b get 14000 .
"let amount distributed between a and b is x ratio of capital between a and b is 8 : 7 if b get 14000 then x * 7 / 15 = 14000 x * 7 = 210000 x = 30000 let total profit = y y * 75 / 100 = 30000 y = 40000 answer d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "22.8 kg", "34.2 kg", "28 kg", "26.5 kg" ] }
[ "B" ]
if 11.25 m of a uniform steel rod weighs 42.75 kg . what will be the weight of 9 m of the same rod ?
"explanation : let the required weight be x kg . then , less length , less weight ( direct proportion ) = > 11.25 : 9 : : 42.75 : x = > 11.25 x x = 9 x 42.75 = > x = ( 9 x 42.75 ) / 11.25 = > x = 34.2 answer : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 1200", "rs . 1300", "rs . 1500", "rs . 2000" ] }
[ "C" ]
a man invests rs . 3,000 at the rate of 5 % per annum . how much more should he invest at the rate of 8 % , so that he can earn a total of 6 % per annum ?
"explanation : interest on rs . 3000 at 5 % per annum = ( 3000 Γ— 5 Γ— 1 ) / 100 = rs . 150 let his additional investment at 8 % = x interest on rs . x at 8 % per annum = ( x Γ— 8 Γ— 1 ) / 100 = 2 x / 25 . to earn 6 % per annum for the total , interest = ( 3000 + x ) Γ— 6 Γ— 1 / 100 . = > 150 + 2 x / 25 = ( 3000 + x ) Γ— 6 Γ— ...
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "14", "18", "24", "28" ] }
[ "B" ]
15 binders can bind 1400 books in 21 days . how many binders will be required to bind 1600 books in 20 days ?
"binders books days 15 1400 21 x 1600 20 x / 15 = ( 1600 / 1400 ) * ( 21 / 20 ) = > x = 18 answer : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "0.54202", "0.54204", "0.542022", "0.542025" ] }
[ "D" ]
the average of numbers 0.54204 , 0.54203 , 0.54202 and 0.54201 is ?
"answer average = ( 0.54204 + 0.54203 + 0.54202 + 0.54201 ) / 4 = 2.1681 / 4 = 0.542025 correct option : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "0.00315", "0.0315", "0.315", "0.0351" ] }
[ "A" ]
0.007 x 0.45 = ?
"7 x 45 = 315 sum of decimal places = 5 therefore , 0.007 x 0.45 = 0.00315 answer is a ."
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "65", "69", "72", "79" ] }
[ "D" ]
kamal obtained 96 , 65 , 82 , 67 and 85 marks ( out of 100 ) in english , mathematics , physics , chemistry and biology . what are his average marks ?
"sol . average = 96 + 65 + 82 + 67 + 85 / 5 ) = ( 395 / 5 ) = 79 . answer d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 16363.64", "rs . 10 , 000.64", "rs . 15 , 000,64", "rs . 21 , 353.64" ] }
[ "A" ]
a man took a loan from a bank at the rate of 11 % p . a . simple interest . after 3 years he had to pay rs . 5400 interest only for the period . the principal amount borrowed by him was :
"solution principal = rs . ( 100 x 5400 / 11 x 3 ) = rs . 16363.64 . answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "5 : 9", "2 : 3", "3 : 4", "4 : 5" ] }
[ "A" ]
find the ratio in which rice at rs . 7.20 a kg be mixed with rice at rs . 5.80 a kg to produce a mixture worth rs . 6.30 a kg ?
"solution required ratio = 50 : 90 = 5 : 9 answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "29997", "299997", "297", "0" ] }
[ "B" ]
the difference between the place values of two threes in the numerical 40378273 is
"required difference = ( 300000 - 3 ) = 299997 . answer is b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "65", "69", "72", "75" ] }
[ "B" ]
kamal obtained 66 , 65 , 77 , 62 and 75 marks ( out of 100 ) in english , mathematics , physics , chemistry and biology . what are his average marks ?
sol . average = 66 + 65 + 77 + 62 + 75 / 5 ) = ( 345 / 5 ) = 69 . answer b
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 962", "rs . 672", "rs . 540", "rs . 876" ] }
[ "C" ]
the cost of the paint is rs . 30 per kg . if 1 kg of paint covers 18 sq . ft , how much will it cost to paint outside of a cube having 6 feet each side
"explanation : surface area of a cube = 6 x 6 ^ 2 = 216 sq . ft quantity of paint required = ( 216 / 18 ) = 12 kg cost of painting = 30 x 18 = rs . 540 answer : c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "277", "36", "45", "72" ] }
[ "C" ]
? % of 360 = 162
"? % of 360 = 162 or , ? = 162 Γ— 100 / 360 = 45 answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "108", "120", "134", "144" ] }
[ "A" ]
p , q , r enter into a partnership & their share are in the ratio 1 / 2 : 1 / 3 : 1 / 4 , after two months , p withdraws half of the capitals & after 10 months , a profit of rs 378 is divided among them . what is r ' s share ?
explanation : the ratio of their initial investment = 1 / 2 : 1 / 3 : 1 / 4 = 6 : 4 : 3 let ' s take the initial investment of p , q and r as 6 x , 4 x and 3 x respectively a : b : c = ( 6 x * 2 + 3 x * 10 ) : 4 x * 12 : 3 x * 12 = ( 12 + 30 ) : 4 * 12 : 3 * 12 = ( 4 + 10 ) : 4 * 4 : 12 = 14 : 16 : 12 = 7 : 8 : 6 r ' s...
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "23.4 %", "44.5 %", "55.3 %", "57.4 %" ] }
[ "C" ]
the cost price of an article is 56 % of the marked price . calculate the gain percent after allowing a discount of 13 % .
"sol . let marked price = rs . 100 . then , c . p . = rs . 56 . s . p = rs . 87 . Γ’ Λ† Β΄ gain % = [ 31 / 56 * 100 ] % = 55.3 % . answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1 : 3", "2 : 3", "3 : 4", "6 : 7" ] }
[ "D" ]
find the ratio in which rice at rs . 7.00 a kg be mixed with rice at rs . 5.70 a kg to produce a mixture worth rs . 6.30 a kg ?
"solution required ratio = 60 : 70 = 6 : 7 answer d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1 / 4", "1 / 5", "1 / 10", "1 / 11" ] }
[ "A" ]
what will be the fraction of 25 %
"explanation : it will 25 * 1 / 100 = 1 / 4 option a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "2 / 5", "3 / 5", "7 / 12", "1 / 7" ] }
[ "C" ]
what is difference between biggest and smallest fraction among 2 / 3 , 3 / 4 , 4 / 5 and 5 / 4
"explanation : 2 / 3 = . 66 , 3 / 4 = . 75 , 4 / 5 = . 8 and 5 / 4 = 1.25 so biggest is 5 / 4 and smallest is 2 / 3 their difference is 5 / 4 - 2 / 3 = 7 / 12 option c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 27,000", "rs . 24,000", "rs . 30,000", "rs . 29,000" ] }
[ "D" ]
jayant opened a shop investing rs . 30,000 . madhu joined him 2 months later , investing rs . 45,000 . they earned a profit of rs . 58,000 after completion of one year . what will be madhu ' s share of profit ?
30,000 * 12 = 45,000 * 8 1 : 1 madhu ' s share = 1 / 2 * 58,000 i . e . rs . 29,000 answer : d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "0.1 %", "1 %", "7 %", "10 %" ] }
[ "B" ]
i gain 70 paise on rs . 70 . my gain percent is
"solution gain % = ( 0.70 / 70 Γ— 100 ) % = 1 % . answer b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "12.5 %", "40 %", "67 %", "125 %" ] }
[ "C" ]
the ratio 2 : 3 expressed as a percent equals
"solution 2 : 3 = 2 / 3 = ( 2 / 3 x 100 ) % . = 66.6 % . answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "20,20", "46,14", "25,15", "30,10" ] }
[ "B" ]
the ages of two persons differ by 32 years . if 5 years ago , the elder one be 5 times as old as the younger one , their present ages ( in years ) are respectively
"explanation : let their ages be x and ( x + 32 ) years . 5 ( x - 5 ) = ( x + 32 - 5 ) or 4 x = 52 or x = 14 . their present ages are 46 years and 14 years option b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "724", "804", "11413", "844" ] }
[ "C" ]
what is the least number of square tiles required to pave the floor of a room 10 m 17 cm long and 9 m 9 cm broad ?
"solution length of largest tile = h . c . f . of 1017 cm & 909 cm = 9 cm . area of each tile = ( 9 x 9 ) cm 2 ∴ required number of tiles = [ 1017 x 909 / 9 x 9 ] = 11413 . answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 2000", "rs . 10000", "rs . 15000", "rs . 20000" ] }
[ "C" ]
consider a lady took a loan from a bank at the rate of 12 % p . a . simple interest . after 3 years she had to pay rs . 5400 interest only for the period . the principal amount borrowed by her was
"explanation : principal = rs . ( 100 Γ— 5400 / 12 Γ— 3 ) = > rs . 15,000 . answer : c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "172", "173", "174", "175" ] }
[ "C" ]
the average of a batsman for 40 innings is 50 runs . his highest score exceeds his lowest score by 172 runs . if these two innings are excluded , his average drops by 2 runs . find his highest score .
total runs = 40 Γ— 50 = 2000 let his highest score be = x then his lowest score = x – 172 now 200 βˆ’ x βˆ’ ( x βˆ’ 172 ) / 38 = 48 β‡’ 2 x = 2172 – 1824 β‡’ x = 174 answer c
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "4", "7", "8", "10" ] }
[ "D" ]
49 Γ£ β€” 49 Γ£ β€” 49 Γ£ β€” 49 x 49 = 7 ?
"49 Γ£ β€” 49 Γ£ β€” 49 Γ£ β€” 49 x 49 = 7 ? or , 7 ( 2 ) Γ£ β€” 7 ( 2 ) Γ£ β€” 7 ( 2 ) Γ£ β€” 7 ( 2 ) x 7 ( 2 ) = 7 ? or 7 ( 10 ) = 7 ? or , ? = 10 answer d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "3.6", "6", "18", "3" ] }
[ "D" ]
reena took a loan of $ . 1200 with simple interest for as many years as the rate of interest . if she paid $ 108 as interest at the end of the loan period , what was the rate of interest ?
let rate = r % and time = r years . then , 1200 x r x r / 100 = 108 12 r 2 = 108 r 2 = 9 r = 3 . answer : d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1 : 9", "1 : 225", "1 : 52", "1 : 522" ] }
[ "A" ]
a cube of edge 6 cm is cut into cubes each of edge 2 cm . the ratio of the total surface area of one of the small cubes to that of the large cube is equal to :
"sol . required ratio = 6 * 2 * 2 / 6 * 6 * 6 = 1 / 9 = 1 : 9 . answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "2880", "1800", "2700", "10800" ] }
[ "A" ]
running at the same constant rate , 6 identical machines can produce a total of 270 bottles per minute . at this rate , how many bottles could 16 such machines produce in 4 minutes ?
"solution let the required number of bottles be x . more machines , more bottles ( direct proportion ) more minutes , more bottles ( direct proportion ) Γ’ Λ† Β΄ 6 Γ£ β€” 1 Γ£ β€” x = 16 Γ£ β€” 4 Γ£ β€” 270 Γ’ ‑ ” x = 16 x 4 x 270 / 6 = 2880 . answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 120", "rs . 160", "rs . 270", "rs . 300" ] }
[ "C" ]
a sum of rs . 1530 has been divided among a , b and c such that a gets of what b gets and b gets of what c gets . b ’ s share is :
"explanation let c ’ s share = rs . x then , b ’ s share = rs . x / 4 , a ’ s share = rs . ( 2 / 3 x x / 4 ) = rs . x / 6 = x / 6 + x / 4 + x = 1530 = > 17 x / 12 = 1530 = > 1530 x 12 / 17 = rs . 1080 hence , b ’ s share = rs . ( 1080 / 4 ) = rs . 270 . answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "6.32 hr", "8 hr", "8.5 hr", "10 hr" ] }
[ "A" ]
two pipes can fill the cistern in 10 hr and 12 hr respectively , while the third empty it in 40 hr . if all pipes are opened simultaneously , then the cistern will be filled in
"solution : work done by all the tanks working together in 1 hour . 1 / 10 + 1 / 12 βˆ’ 1 / 40 = 3 / 19 hence , tank will be filled in 19 / 3 = 6.32 hour option ( a )"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "20,000", "21,200", "28,200", "13,500" ] }
[ "D" ]
a , b and c start a business each investing 20000 . after 5 months a withdrew 10000 , b withdrew 15000 and c invests 5000 more . at the end of the year , a total profit of 58000 was recorded . find the share of b .
ratio of the capitals of a , b and c = 20000 Γ£ β€” 5 + 10000 Γ£ β€” 7 : 20000 Γ£ β€” 5 + 5000 Γ£ β€” 7 : 20000 Γ£ β€” 5 + 25000 Γ£ β€” 7 = 170000 : 135000 : 275000 = 170 : 135 : 275 . b Γ’ € β„’ s share = ( 58000 Γ£ β€” 135 Γ’  β€ž 580 ) = 13500 answer d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1.6 km", "2 km", "3.6 km", "4.8 km" ] }
[ "D" ]
the speed of a boat in still water is 12 km / hr and the rate of current is 4 km / hr . the distance travelled downstream in 18 minutes is
"explanation : speed downstreams = ( 12 + 4 ) kmph = 16 kmph . distance travelled = ( 16 x 18 / 60 ) km = 4.8 km option d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "12 kmph", "13 kmph", "14 kmph", "15 kmph" ] }
[ "D" ]
a boat covers a certain distance downstream in 1 hour , while it comes back in 1 Β½ hours . if the speed of the stream be 3 kmph , what is the speed of the boat in still water ?
sol . let the speed of the boat in still water be x kmph . then , speed downstream = ( x + 3 ) kmph , speed upstream = ( x - 3 ) kmph . ∴ ( x + 3 ) * 1 = ( x - 3 ) * 3 / 2 ⇔ 2 x + 6 = 3 x - 9 ⇔ x = 15 kmph . answer d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "15", "19", "18", "22" ] }
[ "C" ]
find the average of all the numbers between 9 and 26 which are divisible by 5 .
"sol . average = ( 10 + 15 + 20 + 25 / 4 ) = 70 / 4 = 17.5 answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "4.0 m", "4.1 m", "4.2 m", "4.3 m" ] }
[ "C" ]
a rectangular tank measuring 5 m Γ— 4.5 m Γ— 2.1 m is dug in the centre of the field measuring 13.5 m Γ— 2.5 . the earth dug out is spread evenly over the remaining portion of a field . how much is the level of the field raised ?
area of the field = 13.5 Γ— 2.5 = 33.75 m 2 area covered by the rectangular tank = 5 Γ— 4.5 = 22.50 m 2 area of the field on which the earth dug out is to be spread = 33.75 – 22.50 = 11.25 m 2 let the required height be h . then , 11.25 Γ— h = 5 Γ— 4.5 Γ— 2.1 or h = 4.2 m answer c
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "5000", "5600", "5400", "4500" ] }
[ "B" ]
if 15 % of 30 % of 50 % of a number is 126 , then what is the number ?
"let the number be a given , 15 / 100 * 30 / 100 * 50 / 100 * a = 126 = > 3 / 20 * 3 / 10 * 1 / 2 * a = 126 = > a = 10 * 20 * 10 * 2 = 5600 . answer : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "225 m", "100 m", "120 m", "180 m" ] }
[ "A" ]
two trains travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 10 seconds . the length of the faster train is
"solution relative speed = ( 36 + 45 ) km / hr = ( 81 x 5 / 18 ) m / sec = ( 45 / 2 ) m / sec length of the train = ( 45 / 2 x 10 ) m = 225 m . answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "5", "17", "13", "23" ] }
[ "A" ]
when 242 is divided by a certain divisor the remainder obtained is 4 . when 698 is divided by the same divisor the remainder obtained is 8 . however , when the sum of the two numbers 242 and 698 is divided by the divisor , the remainder obtained is 7 . what is the value of the divisor ?
"let that divisor be x since remainder is 4 or 8 it means divisor is greater than 8 . now 242 - 4 = 238 = kx ( k is an integer and 234 is divisble by x ) similarly 698 - 8 = 690 = lx ( l is an integer and 689 is divisible by x ) adding both 698 and 242 = ( 238 + 690 ) + 4 + 8 = x ( k + l ) + 12 when we divide this numb...
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 3200", "rs . 3600", "rs . 2400", "rs . 4000" ] }
[ "A" ]
p , q and r have rs . 8000 among themselves . r has two - thirds of the total amount with p and q . find the amount with r ?
"let the amount with r be rs . r r = 2 / 3 ( total amount with p and q ) r = 2 / 3 ( 8000 - r ) = > 3 r = 16000 - 2 r = > 5 r = 16000 = > r = 3200 . answer : a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "4.04 %", "4.00 %", "4.14 %", "5.04 %" ] }
[ "A" ]
an error 2 % in excess is made while measuring the side of a square . the percentage of error in the calculated area of the square is
"100 cm is read as 102 cm . a 1 = ( 100 x 100 ) cm 2 and a 2 ( 102 x 102 ) cm 2 . ( a 2 - a 1 ) = [ ( 102 ) 2 - ( 100 ) 2 ] = ( 102 + 100 ) x ( 102 - 100 ) = 404 cm 2 . percentage error = 404 x 100 % = 4.04 % 100 x 100 a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "190", "204", "220", "230" ] }
[ "B" ]
if rs . 782 is divided into 3 parts , proportional to 1 / 2 : 2 / 3 : 3 / 4 find the first part .
explanation : 1 / 2 : 2 / 3 : 3 / 4 = 6 : 8 : 9 first part = 782 βˆ— 6 / 23 = 204 option b
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "25", "90", "35", "20" ] }
[ "B" ]
a contractor undertakes to built a walls in 50 days . he employs 60 peoples for the same . however after 25 days he finds that only 40 % of the work is complete . how many more man need to be employed to complete the work in time ?
"60 men complete 0.4 work in 25 days . applying the work rule , m 1 Γ— d 1 Γ— w 2 = m 2 Γ— d 2 Γ— w 1 we have , 60 Γ— 25 Γ— 0.6 = m 2 Γ— 25 Γ— 0.4 or m 2 = 60 Γ— 25 Γ— 0.6 / 25 Γ— 0.4 = 90 men answerb"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "30", "33.6", "39.8", "44.9" ] }
[ "C" ]
find the average of all prime numbers between 30 and 50 .
"sol . there are five prime numbers between 30 and 50 . they are 31 , 37 , 41 , 43 and 47 ∴ required average = [ 31 + 37 + 41 + 43 + 47 / 5 ] = 199 / 5 = 39.8 answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "7580", "7960", "8290", "4320" ] }
[ "D" ]
a leak in the bottom of a tank can empty the full tank in 6 hours . an inlet pipe fills water at the rate of 6 litres a minute . when the tank is full , the inlet is opened and due to the leak , the tank is empty in 12 hours . how many litres does the cistern hold ?
"solution work done by the inlet in 1 hour = ( 1 / 6 - 1 / 12 ) = 1 / 12 . work done by the inlet in 1 min . = ( 1 / 12 Γ— 1 / 60 ) = 0.001389 volume of 0.001389 part = 6 litres . therefore , volume of whole = 1 / 0.001389 x 6 β€Ή = β€Ί 4320 litres . answer d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "33.33 %", "25 %", "75 %", "66.66 %" ] }
[ "D" ]
if x is less than y by 40 % then y exceed x by :
"using formula ( x / ( 100 - x ) * 100 ) where x is percentage decrease ( here it is 40 % ) = > 40 / ( 100 - 40 ) * 100 = 66.66 % answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "50.15", "52.06", "51.25", "53.06" ] }
[ "B" ]
a school has 4 section of chemistry in class x having 55 , 35 , 45 and 42 students . the mean marks obtained in chemistry test are 50 , 60 , 55 and 45 respectively for the 4 sections . determine the overall average of marks per student .
"required average marks = 55 Γ£ β€” 50 + 35 Γ£ β€” 60 + 45 Γ£ β€” 55 + 42 Γ£ β€” 45 / 55 + 35 + 45 + 42 = 2750 + 2100 + 2475 + 1890 / 162 = 9215 Γ’  β€ž 177 = 52.06 answer b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "2", "3", "0", "5" ] }
[ "C" ]
what is the remainder when 9 ^ 1 + 9 ^ 2 + 9 ^ 3 + . . . + 9 ^ 9 is divided by 9 ?
"notice that in the brackets we have the sum of 9 odd multiples of 9 , which yields remainder of 0 upon division by 9 . answer : c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "20,196", "19,780", "19,680", "19,380" ] }
[ "A" ]
sonika bought a v . c . r . at the list price of 18,700 . if the rate of sales tax was 8 % , find the amount she had to pay for purchasing the v . c . r .
"sol . list price of v . c . r . = 18,700 rate of sales tax = 8 % ∴ sales tax = 8 % of 18,700 = 8 ⁄ 100 Γ— 18700 = 1496 so , total amount which sonika had to pay for purchasing the v . c . r . = 18,700 + 1496 = 20,196 . answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "973", "6973", "3996", "6084" ] }
[ "C" ]
the difference between the place value and the face value of 4 in the numeral 854973 is
"( place value of 4 ) - ( face value of 4 ) = ( 4000 - 4 ) = 3996 answer : option c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "7 / 10", "15 / 14", "4 / 5", "5 / 4" ] }
[ "A" ]
jack and jill are marathon runners . jack can finish a marathon ( 42 km ) in 6 hours and jill can run a marathon in 4.2 hours . what is the ratio of their average running speed ? ( jack : jill )
"average speed of jack = distance / time = 42 / 6 = 7 average speed of jill = 42 / ( 4.2 ) = 10 ratio of average speed of jack to jill = 7 / 10 answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 2000", "rs . 10000", "rs . 15000", "rs . 20000" ] }
[ "D" ]
consider a lady took a loan from a bank at the rate of 12 % p . a . simple interest . after 3 years she had to pay rs . 7200 interest only for the period . the principal amount borrowed by her was
explanation : principal = rs . ( 100 Γ— 7200 / 12 Γ— 3 ) = > rs . 20,000 . answer : d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "4", "16", "8", "8 √ 2" ] }
[ "B" ]
triangle xyz is an isosceles right triangle . if side xy is longer than side yz , and the area of the triangle is 64 , what is the measure of side xy ?
"ans b . . 16 . xy being larger means it is the hyp . . area = ( 1 / 2 ) * ( yz ) ^ 2 = 64 or yz = 8 * \ sqrt { 2 } . . therefore hyp = xy = 16"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "78", "40", "68", "88" ] }
[ "A" ]
a rectangular field is to be fenced on three sides leaving a side of 30 feet uncovered . if the area of the field is 720 sq . feet , how many feet of fencing will be required ?
"explanation we have : l = 30 ft and lb = 720 sq . ft . so , b = 24 ft . length of fencing = ( l + 2 b ) = ( 30 + 48 ) ft = 78 ft . answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "14 / 15", "15 / 14", "4 / 5", "21 / 25" ] }
[ "D" ]
jack and jill are marathon runners . jack can finish a marathon ( 42 km ) in 5 hours and jill can run a marathon in 4.2 hours . what is the ratio of their average running speed ? ( jack : jill )
"average speed of jack = distance / time = 42 / 5 average speed of jill = 42 / ( 4.2 ) = 10 ratio of average speed of jack to jill = ( 42 / 5 ) / 10 = 42 / 50 = 21 / 25 answer d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "15 %", "25 %", "0.125 %", "0.2083 %" ] }
[ "B" ]
farm tax is levied on the 50 % of the cultivated land . the tax department collected total $ 3840 through the farm tax from the village of mr . william . mr . william paid only $ 480 as farm tax . the percentage of total land of mr . willam over the total taxable land of the village is :
"this will be equal to the percentage of total cultivated land he holds over the total cultivated land in the village . that leads to ( 480 / 3840 ) x 100 = 12.5 % in percentage terms . but the question asks ratio between his total land to total cultivated land . hence the answer is 12.5 % x ( 100 / 50 ) = 25 % the cor...
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs 16,000", "rs 18,000", "rs 12,000", "rs 14,000" ] }
[ "C" ]
the value of a machine depreciates at the rate of 10 % every year . it was purchased 3 years ago . if its present value is rs 8,748 , its purchase price was ?
"we have p = 8748 , r = - 10 and n = 3 therefore , the purchase price of the machine = p / ( 1 + ( r / 100 ) ) n = 8748 / ( 1 - ( 10 / 100 ) ) 3 = 8748 x ( 100 / 90 ) x ( 100 / 90 ) x ( 100 / 90 ) = 12,000 . answer : c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "14 m", "29 m", "49 m", "7" ] }
[ "D" ]
the area of a parallelogram is 147 sq m and its base is thrice the corresponding height . then the length of the base is ?
b * h = 147 b * h = 147 = > b ^ 2 = 49 m . b = 7 answer : ( d )
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 120", "rs . 160", "rs . 240", "rs . 360" ] }
[ "D" ]
a sum of rs . 2040 has been divided among a , b and c such that a gets of what b gets and b gets of what c gets . b ’ s share is :
"explanation let c ’ s share = rs . x then , b ’ s share = rs . x / 4 , a ’ s share = rs . ( 2 / 3 x x / 4 ) = rs . x / 6 = x / 6 + x / 4 + x = 2040 = > 17 x / 12 = 2040 = > 2040 x 12 / 17 = rs . 1440 hence , b ’ s share = rs . ( 1440 / 4 ) = rs . 360 . answer d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "45 hours", "47 hours", "48 hours", "50 hours" ] }
[ "C" ]
a man ' s basic pay for a 40 hour week is rs . 20 . overtime is paid for at 25 % above the basic rate . in a certain week he worked overtime and his total wage was rs . 25 . he therefore worked for a total of :
explanation : basic rate per hour = rs . ( 20 / 40 ) = rs . 1 / 2 overtime per hour = 125 % of rs . 1 / 2 = 125 / 100 Γ— 1 / 2 = rs . 5 / 8 suppose he worked x hours overtime . then , 20 + 5 / 8 x = 25 or 5 / 8 x = 5 x = 5 Γ— 8 / 5 = 8 hours so he worked in all for ( 40 + 8 ) hours = 48 hours . correct option : c
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "20 %', '", "18 %', '", "36 %', '", "11 %', '" ] }
[ "D" ]
if the area of a circle decreases by 20 % , then the radius of a circle decreases by
if area of a circle decreased by x % then the radius of a circle decreases by ( 100 βˆ’ 10 √ 100 βˆ’ x ) % = ( 100 βˆ’ 10 √ 100 βˆ’ 20 ) % = ( 100 βˆ’ 10 √ 80 ) % = 100 - 89 = 11 % answer d
MathQA
{ "label": [ "A", "B", "C", "E" ], "text": [ "800", "500", "505", "506" ] }
[ "A" ]
evaluate 64 / . 08
"explanation : 64 / . 08 = 6400 / 8 = 800 option a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "2 : 1", "4 : 7", "8 : 77", "4 : 121" ] }
[ "D" ]
the ratio of radius of a circle and the side of a square is 2 : 11 . find the ratio of their areas :
"radius / side = 2 / 11 β‡’ area of circle / area of square = 4 / 121 answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "45 m", "50 m", "54 m", "72 m" ] }
[ "B" ]
a train overtakes two person who are walking in the same direction in which the train is going , at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively . the length of the train is :
let actual speed of train = s m / sec and length of train = l m . then , s - 2 Γ— 5 / 18 = l 9 β‡’ 9 s = l + 5 . . . … ( i ) and s - 4 Γ— 5 ⁄ 18 = l ⁄ 10 β‡’ 90 s = 9 l + 100 . . . . . ( ii ) by ( i ) & ( ii ) , we get l = 50 m . answer b
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "500", "600", "750", "800" ] }
[ "B" ]
a and b undertake to do a piece of work for rs . 1200 . a alone can do it in 6 days while b alone can do it in 8 days . with the help of c , they finish it in 3 days . find the share of a .
"c ' s 1 day ' s work = 1 / 3 - ( 1 / 6 + 1 / 8 ) = 24 a : b : c = ratio of their 1 day ' s work = 1 / 6 : 1 / 8 : 1 / 24 = 4 : 3 : 1 . a ’ s share = rs . ( 1200 * 4 / 8 ) = rs . 600 , b ' s share = rs . ( 1200 * 3 / 8 ) = rs . 450 c ' s share = rs . [ 1200 - ( 300 + 225 Β» ) = rs . 150 . answer is b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 200", "rs . 350", "rs . 275", "rs . 415" ] }
[ "D" ]
the mean daily profit made by a shopkeeper in a month of 30 days was rs . 350 . if the mean profit for the first fifteen days was rs . 285 , then the mean profit for the last 15 days would be
"average would be : 350 = ( 285 + x ) / 2 on solving , x = 415 . answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1.9332", "1.0025", "1.5693", "1.0266" ] }
[ "A" ]
given that 268 x 74 = 19332 , find the value of 2.68 x . 74 .
"solution sum of decimals places = ( 2 + 2 ) = 4 . therefore , = 2.68 Γ— . 74 = 1.9332 answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "420", "520", "620", "620" ] }
[ "B" ]
in a college , the ratio of the number of boys to girls is 8 : 5 . if there are 200 girls , the total number of students in the college is
explanation : let the boy are 8 x and girls are 5 x = > 5 x = 200 = > x = 40 total students = 8 x + 5 x = 13 x = 13 ( 40 ) = 520 answer : b
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "6 hr", "2 hr", "4 hr", "1 hr" ] }
[ "B" ]
a boatman can row 96 km downstream in 8 hr . if the speed of the current is 4 km / hr , then find in what time will be able to cover 8 km upstream ?
"explanation : speed downstream = 96 ⁄ 8 = 12 kmph speed of current = 4 km / hr speed of the boatman in still water = 12 - 4 = 8 kmph speed upstream = 8 - 4 = 4 kmph time taken to cover 8 km upstream = 8 ⁄ 4 = 2 hours . answer : option b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "227.623", "224.777", "233.523", "414.637" ] }
[ "A" ]
895.7 – 573.07 – 95.007 = ?
"solution given expression = 895.7 - ( 573.07 + 95.007 ) = 895.7 - 668.077 = 227.623 . answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1 : 1', '", "1 : 2', '", "2 : 3', '", "2 : 1', '" ] }
[ "D" ]
what will be the ratio between the area of a rectangle and the area of a triangle with one of the sides of the rectangle as base and a vertex on the opposite side of the rectangle ?
explanation : as far as questions of area or volume and surface area are concerned , it is all about formulas and very little logic . so its a sincere advice to get all formulas remembered before solving these questions . lets solve this , area of rectangle = l βˆ— b area of triangle = 1 / 2 l βˆ— b ratio = l βˆ— b : 1 / 2 l...
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "2200", "2520", "2600", "3354" ] }
[ "B" ]
the true discount on a bill due 9 months hence at 16 % per annum is rs . 270 . the amount of the bill is
"explanation : let p . w . be rs . x . then , s . i . on rs . x at 16 % for 9 months = rs . 270 . x Γ£ β€” 16 Γ£ β€” ( 9 / 12 ) Γ£ β€” ( 1 / 100 ) = 270 or x = 2250 . p . w . = rs . 2250 sum due = p . w . + t . d . = rs . ( 2250 270 ) = rs . 2520 answer : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "βˆ’ 220", "βˆ’ 100", "120", "135" ] }
[ "C" ]
if the average ( arithmetic mean ) of a and b is 150 , and the average of b and c is 90 , what is the value of a βˆ’ c ?
"a + b = 300 b + c = 180 a - c = 120 . imo option c ."
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "80", "150", "75", "90" ] }
[ "B" ]
if 40 % of 3 / 5 of a number is 36 , then the number is ?
"let the number be x . then 40 % of 3 / 5 of x = 36 40 / 100 * 3 / 5 * x = 36 x = ( 36 * 50 / 12 ) = 150 required number = 150 . correct option : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1", "3", "5", "6" ] }
[ "A" ]
if a is a positive integer , and if the units digit of a ^ 2 is 9 and the units digit of ( a + 1 ) ^ 2 is 4 , what is the units d digit of ( a + 2 ) ^ 2 ?
"i also got a . by punching in numers : d . . . 7 ^ 2 = . . . 9 . . . 8 ^ 2 = . . . 4 . . . 9 ^ 2 = . . . 1 . a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "3.84", "1.75", "3.52", "2.72" ] }
[ "C" ]
the weights of one liter vegetable ghee packet of two brands β€˜ a ’ and β€˜ b ’ are 900 gm and 850 gm respectively . if they are mixed in the ratio of 3 : 2 by volumes to form a mixture of 4 liters , what is the weight ( in kg ) of the mixture ?
"1 l a = 900 gm 1 l b = 850 gm we are mixing five parts ( 3 parts a plus 2 parts b , 5 parts total ) to get 4 l , so 5 x = 4 - - - > x = 4 / 5 . each ` ` part ' ' is 4 / 5 of a liter . so if we have 3 parts a , we have 900 * 3 * ( 4 / 5 ) = 2160 if we have 2 parts b , we have 850 * 2 * ( 4 / 5 ) = 1360 2160 + 1360 = 35...
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "5526", "5426", "5326", "5226" ] }
[ "A" ]
find the missing value : 8597 - ? = 7429 - 4358
"let 8597 - x = 7429 - 4358 . then , x = ( 8597 + 4358 ) - 7429 = 12955 - 7429 = 5526 . answer is a ."
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "3500", "4600", "5400", "4800" ] }
[ "B" ]
a is a working partner and b is a sleeping partner in a business . a puts in 50,000 and b 60,000 . a gets 12.5 % of the profit for managing the business , and the rest is divided in proportion to their capitals . find the share of a in profit of 8800 .
the amount a gets for managing = 12.5 % of rs . 8800 = 1100 remaining profit = 8800 – 1100 = 7700 this is to be divided in the ratio 5 : 6 . share of a = 5 / 11 of 7700 = 3500 β‡’ total share of a = 3500 + 1100 = 4600 . answer b
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "44001", "44000", "40400", "40401" ] }
[ "D" ]
a lady grows cauliflower in her garden that is in the shape of a square . each cauliflower takes 1 square foot of area in her garden . this year , she has increased her output by 401 cauliflower when compared to last year . the shape of the area used for growing the cauliflower has remained a square in both these years...
"explanatory answer the shape of the area used for growing cauliflower has remained a square in both the years . let the side of the square area used for growing cauliflower this year be x ft . therefore , the area of the ground used for cultivation this year = x 2 sq . ft . let the side of the square area used for gro...
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "880", "1450", "1600", "1800" ] }
[ "A" ]
the simple interest and the true discount on a certain sum for a given time and at a given rate are rs . 88 and rs . 80 respectively . the sum is :
"sol . sum = s . i . * t . d . / ( s . i ) - ( t . d . ) = 88 * 80 / ( 88 - 80 ) = rs . 880 . answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "0.01", "1 , 000,000", "0.001", "1,000" ] }
[ "B" ]
if 10000 microns = 1 decimeter , and 1000000000 angstroms = 1 decimeter , how many angstroms equal 1 micron ?
given that 10,000 microns = 1 decimeter = 10,000 , 000,000 angstroms so , 1 micron = 10,000 , 000,000 / 10,000 = 1 , 000,000 answer : b
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "12", "42", "30", "36" ] }
[ "B" ]
the ratio of three numbers is 6 : 7 : 5 and their sum is 108 . the second number of the three numbers is ?
"explanation : 6 : 7 : 5 total parts = 18 18 parts - - > 108 1 part - - - - > 6 the second number of the three numbers is = 7 7 parts - - - - > 42 answer : option b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "200 km", "222 km", "224 km", "248 km" ] }
[ "C" ]
a man complete a journey in 10 hours . he travels first half of the journey at the rate of 21 km / hr and second half at the rate of 24 km / hr . find the total journey in km
"explanation : let time taken to travel the first half = x hr then time taken to travel the second half = ( 10 - x ) hr distance covered in the the first half = 21 x [ because , distance = time * speed ] distance covered in the the second half = 24 ( 10 - x ) distance covered in the the first half = distance covered in...
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "21 %', '", "31 %', '", "41 %', '", "51 %', '" ] }
[ "A" ]
the radius of a sphere is increased by 10 % . the surface area increases by ?
since 4 x pi x radius x radius = surface area . therefore , net % change in area = ( x + y + xy / 100 ) % = [ 10 + 10 + ( 10 x 10 ) / 100 ] % or 21 % . answer : a
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "0.3408", "3.408", "34.08", "340.8" ] }
[ "A" ]
if 213 Γ— 16 = 3408 , then 0.16 Γ— 2.13 is equal to :
"solution 0.16 Γ— 2.13 = ( 16 / 100 x 213 / 100 ) = ( 16 x 213 / 10000 ) = 3408 / 10000 = 0.3408 . answer a"
MathQA