choices dict | answerKey listlengths 1 1 | question stringlengths 8 751 | rationale stringlengths 8 1.53k | dataset stringclasses 1
value |
|---|---|---|---|---|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 7000",
"rs . 8000",
"rs . 8800",
"rs . 9000"
]
} | [
"C"
] | the salary of a , b , c , d , e is rs . 8000 , rs . 5000 , rs . 15000 , rs . 7000 , rs . 9000 per month respectively , then the average salary of a , b , c , d , and e per month is | "answer average salary = 8000 + 5000 + 15000 + 7000 + 9000 / 5 = rs . 8800 correct option : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"120",
"180",
"200",
"220"
]
} | [
"A"
] | a number whose fifth part increased by 3 is equal to its fourth part diminished by 3 is ? | "answer let the number be n . then , ( n / 5 ) + 3 = ( n / 4 ) - 3 Γ’ β‘ β ( n / 4 ) - ( n / 5 ) = 6 Γ’ β‘ β ( 5 n - 4 n ) / 20 = 6 Γ’ Λ Β΄ n = 120 option : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"112",
"118",
"121",
"124"
]
} | [
"D"
] | a person buys 18 local tickets for rs 110 . each first class ticket costs rs 10 and each second class ticket costs rs 3 . what will another lot of 18 tickets in which the numbers of first class and second class tickets are interchanged cost ? | explanation : let , there are x first class ticket and ( 18 - x ) second class tickets . then , 110 = 10 x + 3 ( 18 β x ) . = > 110 = 10 x + 54 β 3 x . = > 7 x = 56 . = > x = 8 . if the number of the first class and second class tickets are interchanged , then the total cost would be 10 Γ 10 + 3 Γ 8 = 124 . answer : d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"92",
"39",
"87",
"96"
]
} | [
"D"
] | out of 3 given numbers , the first one is twice the second and 3 times the third . if the average of these numbers is 88 , then the difference between first and third is . | sum of three number is = 88 * 3 = 264 let three numbers are a , b , c and a is the highest and c is the lowest then , 2 b = a so b = a / 2 and 3 c = a so c = a / 3 we can write , a + b + c = 264 a + a / 2 + a / 3 = 264 11 a / 6 = 264 a = 144 so , c = 144 / 3 = 48 so there difference is = 144 - 48 = 96 answer d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 : 2",
"1 : 3",
"2 : 1",
"2 : 3"
]
} | [
"A"
] | 8 men and 2 boys working together can do 4 times as much work as a man and a boy . working capacity of man and boy is in the ratio | explanation : let 1 man 1 day work = x 1 boy 1 day work = y then 8 x + 2 y = 4 ( x + y ) = > 4 x = 2 y = > x / y = 2 / 4 = > x : y = 1 : 2 option a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"63",
"6973",
"5994",
"6084"
]
} | [
"A"
] | the difference between the place value and the face value of 7 in the numeral 856973 is | ( place value of 7 ) - ( face value of 7 ) = ( 70 - 7 ) = 63 answer : option a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4 kg",
"21.6 kg",
"22.4 kg",
"21 kg"
]
} | [
"A"
] | the average weight of 29 students is 28 kg . by the admission of a new student , the average weight is reduced to 27.2 kg . the weight of the new student is | "exp . the total weight of 29 students = 29 * 28 the total weight of 30 students = 30 * 27.2 weight of the new student = ( 30 * 27.2 β 29 * 28 ) = 816 - 812 = 4 answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 55.50",
"rs . 67.50",
"rs . 86.50",
"rs . 94.50"
]
} | [
"D"
] | the sides of a rectangular field are in the ratio 3 : 4 . if the area of the field is 8748 sq . m , the cost of fencing the field @ 25 paise per metre is | "solution let length = ( 3 x ) metres and breadth = ( 4 x ) metres . then , 3 x Γ 4 x = 8748 β 12 x 2 = 8748 β x 2 = 729 β x = 27 . so , length = 81 m and breadth = 108 m . perimeter = [ 2 ( 81 + 108 ) ] m = 378 m . β΄ cost of fencing = rs . ( 0.25 Γ 378 ) = rs . 94.50 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"12080",
"18060",
"20060",
"20040"
]
} | [
"C"
] | a fifth of arun Γ’ β¬ β’ s marks in mathematics exceed a third of his marks in english by 20 . if he got 260 marks in two subjects together how many marks did he got in english ? | let arun Γ’ β¬ β’ s marks in mathematics and english be x and y then ( 1 / 5 ) x - ( 1 / 3 ) y = 20 3 x - 5 y = 300 Γ’ β¬ Β¦ Γ’ β¬ Β¦ > ( 1 ) x + y = 260 Γ’ β¬ Β¦ Γ’ β¬ Β¦ . > ( 2 ) solving ( 1 ) and ( 2 ) x = 200 and y = 60 answer is c . | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"12 kms",
"16 kms",
"20 kms",
"24 kms"
]
} | [
"D"
] | a girl goes to her school from her house at a speed of 6 km / hr and returns at a speed of 4 km / hr . if she takes 10 hours in going and coming back , the distance between her school and house is | let distance be d 10 = d / 4 + d / 6 answer : d | MathQA |
{
"label": [
"B",
"C",
"D",
"E"
],
"text": [
"27",
"12",
"14.6",
"28"
]
} | [
"D"
] | excluding stoppages , the speed of a train is 45 kmph and including stoppages it is 34 kmph . of how many minutes does the train stop per hour ? | "explanation : t = 11 / 45 * 60 = 14.6 answer : option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20,000",
"21,000",
"28,200",
"20,500"
]
} | [
"C"
] | a , b and c start a business each investing 20,000 . after 5 months a withdrew 5000 , b withdrew 4000 and c invests 6000 more . at the end of the year , a total profit of 69,900 was recorded . find the share of b | "ratio of the capitals of a , b and c = 20000 Γ 5 + 15000 Γ 7 : 20000 Γ 5 + 16000 Γ 7 : 20000 Γ 5 + 26000 Γ 7 = 205000 : 212000 : 282000 = 205 : 212 : 282 . b β s share = ( 69900 Γ 212 β 699 ) = 21200 ; answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"15",
"26",
"28",
"4"
]
} | [
"D"
] | if the sum of a number and its square is 20 , what is the number ? | "let the number be x . then , x + x 2 = 20 ( x + 5 ) ( x - 4 ) = 0 x = 4 answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"β 220",
"β 100",
"β 90",
"135"
]
} | [
"C"
] | if the average ( arithmetic mean ) of a and b is 115 , and the average of b and c is 160 , what is the value of a β c ? | "question : a - c = ? ( a + b ) / 2 = 115 = = = > a + b = 230 ( b + c ) / 2 = 160 = = = > b + c = 320 ( a + b ) - ( b + c ) = 230 - 320 = = = > a + b - b - c = - 90 = = = > a - c = - 90 answer : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4",
"10",
"15",
"16"
]
} | [
"D"
] | 6 bells commence tolling together and toll at intervals of 2 , 4 , 6 , 8 10 and 12 seconds respectively . in 30 minutes , how many times do they toll together ? | l . c . m . of 2 , 4 , 6 , 8 , 10 , 12 is 120 . so , the bells will toll together after every 120 seconds ( 2 minutes ) . in 30 minutes , they will toll together 30 / 2 + 1 = 16 times answer d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"18 %",
"20 %",
"21 %",
"25 %"
]
} | [
"D"
] | two kinds of vodka are mixed in the ratio 1 : 2 and 2 : 1 and they are sold fetching the profit 25 % and 20 % respectively . if the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4 / 3 and 5 / 3 times respectively , then the mixture will fetch the profit of | answer : d . | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4 months",
"6 months",
"8 months",
"10 months"
]
} | [
"D"
] | a and b are partners in a business . a contributes 1 / 4 of the capital for 15 months and b received 2 / 3 of the profit . for how long b β s money was used ? | "sol . let the total profit be rs . z . then , b β share = rs . 2 z / 3 , a β s share = rs . [ z - 2 z / 3 ] = rs . z / 3 β΄ a : b = z / 3 : 2 z / 3 = 1 : 2 . let the total capital be rs . x and suppose b β s money was used for x months . then , [ 1 / 4 x * 15 ] / [ 3 / 4 x * y ] = 1 / 2 β y = [ 15 * 2 / 3 ] = 10 . thus... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"945",
"620",
"610",
"600"
]
} | [
"A"
] | what is the compound interest paid on a sum of rs . 4500 for the period of 2 years at 10 % per annum . | "solution = interest % for 1 st year = 10 interest % for 2 nd year = 10 + 10 % of 10 = 10 + 10 * 10 / 100 = 11 total % of interest = 10 + 11 = 21 total interest = 21 % 4500 = 4500 * ( 21 / 100 ) = 945 answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20,000",
"21,200",
"28,200",
"13,500"
]
} | [
"D"
] | a , b and c start a business each investing 20,000 . after 5 months a withdrew 10000 , b withdrew 15000 and c invests 5000 more . at the end of the year , a total profit of 58000 was recorded . find the share of b . | ratio of the capitals of a , b and c = 20000 Γ£ β 5 + 10000 Γ£ β 7 : 20000 Γ£ β 5 + 5000 Γ£ β 7 : 20000 Γ£ β 5 + 25000 Γ£ β 7 = 170000 : 135000 : 275000 = 170 : 135 : 275 . b Γ’ β¬ β’ s share = ( 58000 Γ£ β 135 Γ’ Β β 580 ) = 13500 answer d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0",
"100",
"6993",
"699930"
]
} | [
"D"
] | the difference between the place values of two sevens in the numeral 69758472 is | "required difference = ( 700000 - 70 ) = 699930 answer : option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"33.33 %",
"25 %",
"75 %",
"66.66 %"
]
} | [
"B"
] | if x is less than y by 20 % then y exceed x by : | using formula ( x / ( 100 - x ) * 100 ) where x is percentage decrease ( here it is 20 % ) = > 20 / ( 100 - 20 ) * 100 = 25 % answer : b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5 %",
"10 %",
"15 %",
"20 %"
]
} | [
"B"
] | a box contains either blue or red flags . the total number of flags in the box is an even number . a group of children are asked to pick up two flags each . if all the flags are used up in the process such that 60 % of the children have blue flags , and 50 % have red flags , what percentage of children have flags of bo... | "solution : let the total number of flags be 100 ( even number ) let the total number of ' blue ' flags alone be ' a ' let the total number of ' red ' flags alone be ' b ' let the total number of ' both ' flags be ' c ' we have given , total number of blue flags = 60 % = 60 = a + c total number of red flags = 50 % = 50... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 2522",
"rs . 2512",
"rs . 2572",
"rs . 2592"
]
} | [
"A"
] | find the compound interest on rs . 16,000 at 20 % per annum for 9 months , compounded quartely . | "solution principal = rs . 16,000 ; time = 9 months = 3 quarters ; amount = rs . [ 16000 x ( 1 + 5 / 100 ) Β³ ] = [ 16000 x 21 / 20 x 21 / 20 x 21 / 20 ] = rs . 18522 . c . i = rs . ( 18522 - 16000 ) = rs . 2522 . answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"12.5 %",
"40 %",
"80 %",
"200 %"
]
} | [
"D"
] | the ratio 6 : 3 expressed as a percent equals | "solution 6 : 3 = 6 / 3 = ( 6 / 3 x 100 ) % . = 200 % . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"31",
"0.31",
"0.0031",
"0.00031"
]
} | [
"A"
] | if the digits 31 in the decimal 0.00031 repeat indefinitely , what is the value of ( 10 ^ 5 - 10 ^ 3 ) ( 0.00031 ) ? | "99 * 0.31 = 30.69 approx . 31 answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"6 m",
"5 m",
"4 m",
"3 m"
]
} | [
"B"
] | a tiger is chasing its prey at a constant speed . it entire body passes a blade of grass in 1 second . it then runs above a fallen tree trunk that is 20 meters long in 5 seconds . what is the length of the tiger ? | sol . let the length of the tiger be x metres and its speed be y m / sec . then , x / y = 1 β y = x β΄ ( x + 20 ) / 5 = x β x = 5 m . answer b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1200",
"150",
"360",
"240"
]
} | [
"B"
] | average age of students of an adult school is 52 years . 120 new students whose average age is 32 years joined the school . as a result the average age is decreased by 4 years . find the number of students of the school after joining of the new students . | "explanation : let the original no . of students be x . according to situation , 52 x + 120 * 32 = ( x + 120 ) 36 β x = 30 so , required no . of students after joining the new students = x + 120 = 150 answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"450 min",
"540 min",
"630 min",
"360 min"
]
} | [
"C"
] | if a child walks at the rate of 5 m / min from his home , he is 6 minutes late for school , if he walks at the rate of 7 m / min he reaches half an hour earlier . how far is his school from his home ? | let the distance between home and school is x . let actual time to reach be t . thus , x / 5 = t + 6 - - - - ( 1 ) and x / 7 = t - 30 - - - - - ( 2 ) solving equation 1 and 2 x = 630 min answer : c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"117",
"126",
"252",
"336"
]
} | [
"B"
] | the least number which when divided by 3 , 4 , 5 and 6 leaves a remainder 6 , but when divided by 9 leaves no remainder , is | "explanation : l . c . m of 3 , 4 , 5 , 6 = 60 therefore required number is of the form 60 k + 6 . least value of k for which ( 60 k + 6 ) is divisible by 9 is k = 2 therefore required number = ( 60 x 2 + 6 ) = 126 . answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"18 %",
"20 %",
"17 %",
"19 %"
]
} | [
"D"
] | a shopkeeper labeled the price of his articles so as to earn a profit of 20 % on the cost price . he then sold the articles by offering a discount of 10 % on the labeled price . what is the actual percent profit earned in the deal ? | "explanation : let the cp of the article = rs . 100 . then labeled price = rs . 120 . sp = rs . 120 - 10 % of 120 = rs . 120 - 13 = rs . 118 . gain = rs . 118 Γ’ β¬ β rs . 100 = rs . 18 therefore , gain / profit percent = 18 % . answer : option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2500",
"2700",
"3000",
"3100"
]
} | [
"B"
] | in an election between two candidates , one got 55 % of the total valid votes , 20 % of the votes were invalid . if the total number of votes was 7500 , the number of valid votes that the other candidate got , was | solution number of valid votes = 80 % of 7500 = 6000 . valid votes polled by other candidates = 45 % of 6000 ( 45 / 100 Γ 6000 ) = 2700 . answer b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"500",
"698",
"780",
"737"
]
} | [
"D"
] | a sum of money at simple interest amounts to rs . 815 in 2 years and to rs . 854 in 3 years . the sum is : | "sol . s . i . for 1 year = rs . ( 854 - 815 ) = rs . 39 . s . i . for 2 years = rs . ( 39 * 2 ) = rs . 78 . Γ’ Λ Β΄ principal = rs . ( 815 - 78 ) = rs . 737 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2 km",
"2.4 km",
"2.5 km",
"3.4 km"
]
} | [
"B"
] | a man can row at 5 kmph in still water . if the velocity of current is 1 kmph and it takes him 1 hour to row to a plce and come back , how far is the place ? | "sol . speed downstream = ( 5 + 1 ) kmph = 6 kmph ; speed upstream = ( 5 - 1 ) kmph = 4 kmph . let the required distance be x km . then , x / 6 + x / 4 = 1 β 2 x + 3 x = 12 β 5 x = 12 β x = 2.4 km . answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4 / 19",
"7 / 19",
"12 / 19",
"24 / 77"
]
} | [
"D"
] | a box contains 24 electric bulbs , out of which 4 are defective . two bulbs are chosen at random from this box . the probability that at least one of these is defective is | "solution p ( none is defective ) = 20 c 2 / 24 c 2 = 53 / 77 . p ( at least one is defective ) = ( 1 - 53 / 77 ) = 24 / 77 . answer d" | MathQA |
{
"label": [
"A",
"C",
"D",
"E"
],
"text": [
"128 %",
"96 %",
"80 %",
"64 %"
]
} | [
"A"
] | mary ' s income is 60 % more than tim ' s income and tim ' s income is 20 % less than juan ' s income . what % of juan ' s income is mary ' s income . | even i got 96 % j = 100 t = 100 * 0.8 = 80 m = 80 * 1.6 = 128 if mary ' s income is x percent of j m = j * x / 100 x = m * 100 / j = 128 * 100 / 100 = 128 ans : a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"9800000",
"1000000",
"7500000",
"1200000"
]
} | [
"B"
] | a wooden box of dimensions 8 m x 7 m x 6 m is to carry rectangularboxes of dimensions 8 cm x 7 cm x 6 cm . the maximum number ofboxes that can be carried in the wooden box , is | explanation : number = ( 800 * 700 * 600 ) / 8 * 7 * 6 = 1000000 answer : b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 3000",
"rs . 607.39",
"rs . 1214.78",
"rs . 1518.48"
]
} | [
"D"
] | simple interest on a certain sum of money for 4 years at 10 % per annum is half the compound interest on rs . 3000 for 3 years at 12 % per annum . the sum placed on simple interest is | "solution c . i . = rs [ 3000 x ( 1 + 12 / 100 ) 3 - 3000 ] rs . ( 3000 x 112 / 100 x 112 / 100 x 112 / 100 - 3000 ) = rs . 1214.78 . sum = rs . [ 607.39 x 100 / 4 x 10 ] = rs . 1518.48 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"600",
"700",
"800",
"850"
]
} | [
"A"
] | in an election between the two candidates , the candidates who gets 70 % of votes polled is winned by 240 vote β s majority . what is the total number of votes polled ? | "explanation : note : majority ( 40 % ) = difference in votes polled to win ( 70 % ) & defeated candidates ( 30 % ) 40 % = 70 % - 30 % 40 % - - - - - > 280 ( 40 * 6 = 240 ) 100 % - - - - - > 600 ( 100 * 6 = 600 ) answer : option a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"45823",
"53836",
"44824",
"66524"
]
} | [
"B"
] | evaluate : 86 x 863 - 86 x 237 | "86 x 863 + 986 x 237 = 986 x ( 863 - 237 ) = 86 x 626 = 53836 . answer is b" | MathQA |
{
"label": [
"A",
"B",
"C",
"E"
],
"text": [
"28.5",
"27.675",
"30",
"42"
]
} | [
"E"
] | a shopkeeper sold an article offering a discount of 5 % and earned a profit of 34.9 % . what would have been the percentage of profit earned if no discount had been offered ? | "giving no discount to customer implies selling the product on printed price . suppose the cost price of the article is 100 . then printed price = 100 Γ£ β ( 100 + 34.9 ) / ( 100 Γ’ Λ β 5 ) = 142 hence , required % profit = 142 Γ’ β¬ β 100 = 42 % answer e" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 45,000",
"rs . 50,000",
"rs . 60,000",
"rs . 80,000"
]
} | [
"C"
] | x and y invested in a business . they earned some profit which they divided in the ratio of 2 : 3 . if x invested rs . 40,000 . the amount invested by y is | "solution suppose y invested rs . y then , 40000 / y = 2 / 3 βΉ = βΊ y = ( 40000 Γ 3 / 2 ) . βΉ = βΊ y = 60000 . answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2574",
"2500",
"1500",
"1574"
]
} | [
"C"
] | if the product of two numbers is 82500 and their h . c . f . is 55 , find their l . c . m . | "explanation : hcf * lcm = 82500 , because we know product of two numbers = product of hcf and lcm lcm = 82500 / 55 = 1500 option c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"9,6",
"7,3",
"9,3",
"6,6"
]
} | [
"B"
] | a man can row downstream at the rate of 10 km / hr and upstream at 4 km / hr . find man ' s rate in still water and the rate of current ? | "explanation : rate of still water = 1 / 2 ( 10 + 4 ) = 7 km / hr rate of current = 1 / 2 ( 10 - 4 ) = 3 km / hr answer : option b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4",
"8",
"16",
"1911"
]
} | [
"A"
] | the maximum number of students among them 1048 pens and 828 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : | "explanation : required number of students = h . c . f of 1048 and 828 = 4 . answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"659",
"698",
"780",
"910"
]
} | [
"A"
] | a sum of money at simple interest amounts to rs . 815 in 4 years and to rs . 854 in 5 years . the sum is : | "sol . s . i . for 1 year = rs . ( 854 - 815 ) = rs . 39 . s . i . for 4 years = rs . ( 39 * 4 ) = rs . 156 . Γ’ Λ Β΄ principal = rs . ( 815 - 156 ) = rs . 659 answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"12.5 %",
"20.83 %",
"25 %",
"50 %"
]
} | [
"B"
] | ritesh and co . generated revenue of rs . 1,500 in 2006 . this was 12.5 % of its gross revenue . in 2007 , the gross revenue grew by rs . 2,500 . what is the percentage increase in the revenue in 2007 ? | "explanation : given , ritesh and co . generated revenue of rs . 1,500 in 2006 and that this was 12.5 % of the gross revenue . hence , if 1250 is 12.5 % of the revenue , then 100 % ( gross revenue ) is : = > ( 100 / 12.5 ) Γ 1500 . = > 12,000 . hence , the total revenue by end of 2007 is rs . 12,000 . in 2006 , revenue... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"7",
"14",
"49",
"21"
]
} | [
"B"
] | β ( 14 ) ^ 2 | "explanation β ( 14 ) ^ 2 = ? or , ? = 14 answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"300",
"t = 400",
"t = 500",
"600"
]
} | [
"C"
] | there are 200 female managers in a certain company . find the total number t of female employees in the company , if 2 / 5 of all the employees are managers and 2 / 5 of all male employees are managers . | "{ managers } = { female managers } + { male managers } ; we are told that the total number of managers in the company is 2 / 5 of all the employees , thus { managers } = 2 / 5 ( m + f ) , where m and f are number of female and male employees , respectively . also , we know that 2 / 5 of all male employees are managers... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"24 %",
"20 %",
"17 %",
"18 %"
]
} | [
"A"
] | a shopkeeper labeled the price of his articles so as to earn a profit of 20 % on the cost price . he then sold the articles by offering a discount of 5 % on the labeled price . what is the actual percent profit earned in the deal ? | "explanation : let the cp of the article = rs . 100 . then labeled price = rs . 120 . sp = rs . 120 - 5 % of 120 = rs . 120 - 6 = rs . 124 . gain = rs . 124 Γ’ β¬ β rs . 100 = rs . 24 therefore , gain / profit percent = 24 % . answer : option a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"300",
"y = 400",
"y = 500",
"y = 600"
]
} | [
"C"
] | there are 200 female managers in a certain company . find the total number y of female employees in the company , if 2 / 5 of all the employees are managers and 2 / 5 of all male employees are managers . | "{ managers } = { female managers } + { male managers } ; we are told that the total number of managers in the company is 2 / 5 of all the employees , thus { managers } = 2 / 5 ( m + f ) , where m and f are number of female and male employees , respectively . also , we know that 2 / 5 of all male employees are managers... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 15000",
"rs . 15550",
"rs . 15600",
"rs . 28875"
]
} | [
"D"
] | the length of a room is 5.5 m and width is 3.75 m . find the cost of paving the floor by slabs at the rate of rs . 1400 per sq . metre . | "solution area of the floor = ( 5.5 Γ 3.75 ) m 2 = 20.625 m 2 β΄ cost of paving = rs . ( 1400 Γ 20.625 ) = 28875 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"30 %",
"25 %",
"75 %",
"20 %"
]
} | [
"D"
] | ashis ' s height is 25 % more than babji , by how much percent babji ' s height is less than ashis . | explanation : solution : babji is less than ashis by ( 25 / ( 100 + 25 ) * 100 ) % = 20 % answer : d | MathQA |
{
"label": [
"B",
"C",
"D",
"E"
],
"text": [
"5993",
"994",
"5994",
"995"
]
} | [
"B"
] | what is the difference between the place value and the face value of 7 in the numeral 297832 ? | explanation : place value of 6 = 7000 face value of 6 = 7 difference = 6000 - 7 = 5993 answer : b | MathQA |
{
"label": [
"B",
"C",
"D",
"E"
],
"text": [
"12.5 min",
"14.4 min",
"10.2 min",
"14.66 min"
]
} | [
"C"
] | a cistern is two - third full of water . pipe a can fill the remaining part in 12 minutes and pipe b in 8 minutes . once the cistern is emptied , how much time will they take to fill it together completely ? | as pipe a takes 12 min . to fill remaining one - third it takes 36 min . to fill completely . similarly pipe b takes 24 min . to fill completely so , total time taken by both together is reciprocal of : ( 1 / 36 ) + ( 1 / 24 ) = 5 / 72 ans : 14.4 min . answer : c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 22500",
"rs . 24500",
"rs . 26500",
"rs . 28500"
]
} | [
"A"
] | sahil purchased a machine at rs 9000 , then got it repaired at rs 5000 , then gave its transportation charges rs 1000 . then he sold it with 50 % of profit . at what price he actually sold it . | "explanation : question seems a bit tricky , but it is very simple . just calculate all cost price , then get 150 % of cp . c . p . = 9000 + 5000 + 1000 = 15000 150 % of 15000 = 150 / 100 * 15000 = 22500 option a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"12 kg",
"60 kg",
"108 kg",
"96 kg"
]
} | [
"C"
] | a boat having a length 3 m and breadth 2 m is floating on a lake . the boat sinks by 1.8 cm when a man gets on it . the mass of man is | "solution volume of water displaced = ( 3 x 2 x 0.018 ) m 3 = 0.108 m 3 . mass of man = volume of water displaced Γ density of water = ( 0.108 Γ 1000 ) kg = 108 kg . answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1954404",
"1981709",
"18362619",
"2031719"
]
} | [
"A"
] | 1398 x 1398 | "1398 x 1398 = ( 1398 ) 2 = ( 1400 - 2 ) 2 = ( 1400 ) 2 + ( 2 ) 2 - ( 2 x 1400 x 2 ) = 1954404 . answer : option a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 8000",
"rs . 12000",
"rs . 15000",
"rs . 6000"
]
} | [
"C"
] | in a express train passengers traveling in a . c . sleeper class , first class and sleeper class are in the ratio 1 : 2 : 3 , and fare to each class in the ratio 5 : 4 : 2 . if the income from this train is rs . 57000 , the income of a . c . sleeper class is | income is divided in the ratio 1 Γ 5 : 2 Γ 4 : 3 Γ 2 = 5 : 8 : 6 . now 5 x + 8 x + 6 x = 19 x = 57000 . β΄ x = 3000 . therefore income from a . c . sleeper class = 30005 = 15000 . answer : c . | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 1000",
"rs 1515",
"rs 800",
"rs 900"
]
} | [
"C"
] | the sale price of a trolley bag including the sale tax is rs . 1120 . the rate of sale tax is 12 % . if the shopkeeper has made a profit of 25 % , the cost price of the trolley bag is : | "explanation : 112 % of s . p . = 1120 s . p . = rs . ( 1120 x 100 / 112 ) = rs . 1000 . c . p . = rs ( 100 / 125 x 1000 ) = rs 800 . answer : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"22500",
"15500",
"18500",
"25000"
]
} | [
"C"
] | evaluate : 37 x 181 + 37 x 319 | "37 x 181 + 37 x 319 = 37 x ( 181 + 319 ) = 37 x 500 = 18500 . answer is c ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.09",
"0.08",
"0.1",
"0.07"
]
} | [
"A"
] | ( 0.15 ) ( power 3 ) - ( 0.06 ) ( power 3 ) / ( 0.15 ) ( power 2 ) + 0.009 + ( 0.06 ) ( power 2 ) is : | "given expression = ( 0.15 ) ( power 3 ) - ( 0.06 ) ( power 3 ) / ( 0.15 ) ( power 2 ) + ( 0.15 x 0.06 ) + ( 0.06 ) ( power 2 ) = a ( power 3 ) - b ( power 3 ) / a ( power 2 ) + ab + b ( power 2 ) = ( a - b ) = ( 0.15 - 0.06 ) = 0.09 answer is a ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 5",
"1 / 4",
"17 / 20",
"3 / 5"
]
} | [
"C"
] | 5 / 4 of all married couples have more than one child . 2 / 5 of all married couples have more than 3 children . what fraction of all married couples have 2 or 3 children ? | "plug in simple numbers . take 100 couples for example . 5 / 4 of 100 couples have more than one child = 125 couples . 2 / 5 of 100 couples have more than 3 kids = 40 couples . this implies that 40 couples are a subset of 125 couples we need to find couples that have 2 or 3 kids , so essentially , it is 125 - 40 = 85 .... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"44 %",
"120 %",
"96 %",
"40 %"
]
} | [
"C"
] | if the radius of a circle is increased by 40 % then the area is increased by : | "initially a = pi * r 2 now r 2 = 140 / 100 r then area = pi * ( 140 r / 100 ) 2 area = 196 r / 100 that is area increases from 100 to 196 = increase in area = 96 % answer : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 1360",
"rs . 1000",
"rs . 360",
"rs . 640"
]
} | [
"A"
] | the banker ' s gain on a sum due 3 years hence at 12 % per annum is rs . 360 . the banker ' s discount is : | "explanation : bg = rs . 360 t = 3 years r = 12 % td = ( bg Γ 100 ) / tr = ( 360 Γ 100 ) / ( 3 Γ 12 ) = rs . 1000 bg = bd β td = > bd = bg + td = 360 + 1000 = rs . 1360 answer : option a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 22000",
"rs . 24000",
"rs . 26000",
"rs . 30000"
]
} | [
"D"
] | sahil purchased a machine at rs 14000 , then got it repaired at rs 5000 , then gave its transportation charges rs 1000 . then he sold it with 50 % of profit . at what price he actually sold it . | "explanation : question seems a bit tricky , but it is very simple . just calculate all cost price , then get 150 % of cp . c . p . = 14000 + 5000 + 1000 = 20000 150 % of 20000 = 150 / 100 * 20000 = 30000 option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1158",
"1651",
"1653",
"1654"
]
} | [
"A"
] | if in a cricket one day match , there were no wide balls , no wides , no extras and no overthrows . what is the maximum number of runs that a batsman can score in 35 overs in an ideal case scenario ? | solution : 1158 explanation : for an ideal case , the batsman will hit a six on each ball . but if he hits six on the last ball of the over , the strike will change in the next over . thus , the best he can do in the last ball is run 3 runs so that he retains the strike even in the next over . thus the total runs that ... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"486000",
"568000",
"378000",
"474000"
]
} | [
"D"
] | evaluate : 1024 x 237 + 976 x 237 | "1024 x 237 + 976 x 237 = 237 x ( 1024 + 976 ) = 237 x 2000 = 474000 . answer is d ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"26 m",
"32 m",
"24 m",
"28 m"
]
} | [
"B"
] | for a race a distance of 224 meters can be covered by p in 28 seconds and q in 32 seconds . by what distance does p defeat q eventually ? | "explanation : this is a simple speed time problem . given conditions : = > speed of p = 224 / 28 = 8 m / s = > speed of q = 224 / 32 = 7 m / s = > difference in time taken = 4 seconds therefore , distance covered by p in that time = 8 m / s x 4 seconds = 32 metres answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"19 %",
"10 %",
"21 %",
"16 %"
]
} | [
"A"
] | weights of two friends ram and shyam are in the ratio 4 : 5 . if ram ' s weight is increased by 10 % and total weight of ram and shyam become 82.8 kg , with an increases of 15 % . by what percent did the weight of shyam has to be increased ? | "solution : given ratio of ram and shayam ' s weight = 4 : 5 hence , ( x - 15 ) / ( 15 - 10 ) = 4 / 5 or , x = 19 % . answer : option a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"7612",
"7614",
"7500",
"7615"
]
} | [
"C"
] | simplify : 100 x 100 - 50 x 50 | "( 100 ) ^ 2 - ( 50 ) ^ 2 = ( 100 + 50 ) ( 100 - 50 ) = 150 x 50 = 7500 . answer is c ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4038",
"8076",
"2052",
"4845.6"
]
} | [
"C"
] | mr yadav spends 60 % of his monthly salary on consumable items and 50 % of the remaining on clothes and transport . he saves the remaining amount . if his savings at the end of the year were 24624 , how much amount per month would he have spent on clothes and transport ? | "β΅ amount , he have spent in 1 month on clothes transport = amount spent on saving per month β΅ amount , spent on clothes and transport = 24624 β 12 = 2052 answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"80 kmph",
"60 kmph",
"70 kmph",
"100 kmph"
]
} | [
"D"
] | a train travels 250 km in 2 hours and 350 km in 4 hours . find the average speed of train . | "as we know that speed = distance / time for average speed = total distance / total time taken thus , total distance = 250 + 350 = 600 km thus , total speed = 6 hrs or , average speed = 600 / 6 or , 100 kmph . answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20 % loss",
"50 % profit",
"33.33 % loss",
"30.33 % loss"
]
} | [
"B"
] | if the cost price of 24 articles is equal to the selling price of 16 articles , what is the percentage of profit or loss that the merchant makes ? | "explanation : let cost price of 1 article be re . 1 . therefore , cost price of 24 articles = rs . 24 . selling price of 16 articles = rs . 24 therefore , selling price of 24 articles is : - = > 24 / 16 Γ£ β 24 = > 36 . therefore , profit = selling price - cost price . = > 36 Γ’ Λ β 24 = 12 . hence , the percentage of p... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0",
"1",
"27",
"54"
]
} | [
"A"
] | for any positive number x , the function [ x ] denotes the greatest integer less than or equal to x . for example , [ 1 ] = 1 , [ 1.367 ] = 1 and [ 1.988 ] = 1 . if k is a positive integer such that k ^ 2 is divisible by 45 and 80 , what is the units digit of k ^ 3 / 4000 ? | "it can not be determined . as we do not know the actual value of k . however minimum value of k is sq . rt of 3 ^ 2 * 4 ^ 2 * 5 ^ 2 = 60 * any integer k = [ lcm of 80 and 45 ] * ( any integer ) for value of k ( 60 ) * any integer unit value will be always zero . a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"35.67 %",
"66.90 %",
"68.57 %",
"69.57 %"
]
} | [
"B"
] | in an examination , there were 2,000 candidates , out of which 900 candidates were girls and rest were boys . if 34 % of the boys and 32 % of the girls passed , then the total percentage of failed candidates is ? | "girls = 900 , boys = 1100 passed = ( 34 % of 1100 ) + ( 32 % of 900 ) = 374 + 288 = 662 failed = 2000 - 662 = 1338 failed % = [ ( 1338 / 2000 ) x 100 ] % = 66.9 % . answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20 , 28",
"28 , 36",
"35 , 45",
"35 , 55"
]
} | [
"C"
] | the present ages of 3 persons are in proportions 4 : 7 : 9 . 7 years ago , the sum of their ages was 79 . find their present ages . | let their present ages be 4 x , 7 x and 9 x years respectively . then , ( 4 x - 7 ) + ( 7 x - 7 ) + ( 9 x - 7 ) = 79 20 x = 100 = > x = 5 their present ages are 20 , 35 and 45 years respectively . answer : c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"120 hours",
"240 hours",
"160 hours",
"480 hours"
]
} | [
"A"
] | speed of a boat in standing water is 8 kmph and the speed of the stream is 6 kmph . a man rows to place at a distance of 210 km and comes back to the starting point . the total time taken by him is : | "sol . speed upstream = 2 kmph ; speed downstream = 14 kmph . β΄ total time taken = [ 210 / 2 + 210 / 2 ] hours = 120 hours . answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"600",
"700",
"990",
"900"
]
} | [
"C"
] | i chose a number and divide it by 9 . then i subtracted 100 from the result and got 10 . what was the number i chose ? | "solution : let x be the number i chose , then x / 9 Γ’ Λ β 100 = 10 x / 9 = 110 x = 990 answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2000",
"500",
"900",
"1600"
]
} | [
"A"
] | find the value of 2.5 x [ ( 3.6 x 0.48 x 2.50 ) / ( 0.12 x 0.09 x 0.5 ) ] | "answer 2.5 x [ ( 3.6 x 0.48 x 2.50 ) / ( 0.12 x 0.09 x 0.5 ) ] = 2.5 x [ ( 36 x 48 x 250 ) / ( 12 x 9 x 5 ) ] = 2.5 x 4 x 4 x 50 = 2000 correct option : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 849.40",
"rs . 877.40",
"rs . 901.60",
"rs . 815.20"
]
} | [
"B"
] | the cost of 10 kg of apples is equal to the cost of 24 kg of rice . the cost of 6 kg of flour equals the cost of 2 kg of rice . the cost of each kg of flour is rs . 20.50 . find the total cost of 4 kg of apples , 3 kg of rice and 5 kg of flour ? | let the costs of each kg of apples and each kg of rice be rs . a and rs . r respectively . 10 a = 24 r and 6 * 20.50 = 2 r a = 12 / 5 r and r = 61.5 a = 147.6 required total cost = 4 * 147.6 + 3 * 61.5 + 5 * 20.5 = 590.4 + 184.5 + 102.5 = rs . 877.40 answer : b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 15000",
"rs . 8250",
"rs . 15600",
"rs . 16500"
]
} | [
"B"
] | the length of a room is 5.5 m and width is 3.75 m . find the cost of paving the floor by slabs at the rate of rs . 400 per sq . metre . | "solution area of the floor = ( 5.5 Γ 3.75 ) m 2 = 20.625 m 2 β΄ cost of paving = rs . ( 400 Γ 20.625 ) = 8250 . answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5 %",
"10 %",
"15 %",
"25 %"
]
} | [
"D"
] | if a ' s salary is 20 % less than b ' s salary , by how much percent is b ' s salary more than a ' s ? | solution required percentage βΉ = βΊ [ 20 / ( 100 - 20 ) x 100 ] % βΉ = βΊ 25 % answer d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"151",
"149",
"152",
"191.4"
]
} | [
"D"
] | the mean of 25 values was 190 . it was detected on rechecking that one value 165 was wrongly copied as 130 for the computation of the mean . find the correct mean . | "corrected mean = 190 Γ 25 β 130 + 165 / 25 = 4750 + 35 / 25 = 4785 / 25 = 191.4 answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"277",
"36",
"26",
"72"
]
} | [
"C"
] | ? % of 360 = 93.6 | "? % of 360 = 93.6 or , ? = 93.6 Γ 100 / 360 = 26 answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.01",
"0.0005",
"0.25",
"0.005"
]
} | [
"A"
] | double of quarter of 2 percent written as a decimal is : | "explanation : solution : ( 2 ) * ( 1 / 4 ) * 2 % = 2 * ( 1 / 4 * 2 / 100 ) = 0.01 . answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"14 kmph",
"15 kmph",
"13 kmph",
"12 kmph"
]
} | [
"B"
] | a boat covers a certain distance downstream in 1 hour , while it comes back in 11 β 2 hours . if the speed of the stream be 3 kmph , what is the speed of the boat in still water ? | "explanation : let the speed of the water in still water = x given that speed of the stream = 3 kmph speed downstream = ( x + 3 ) kmph speed upstream = ( x - 3 ) kmph he travels a certain distance downstream in 1 hour and come back in 11 β 2 hour . ie , distance travelled downstream in 1 hour = distance travelled upstr... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"101",
"107",
"111",
"185"
]
} | [
"C"
] | the product of two numbers is 4107 . if the h . c . f . of these numbers is 37 , then the greater number is : | "explanation let the numbers be 37 a and 37 b . then , 37 a x 37 b = 4107 ab = 3 . now , co - primes with product 3 are ( 1 , 3 ) . so , the required numbers are ( 37 x 1 , 37 x 3 ) i . e . , ( 37 , 111 ) . greater number = 111 . answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"40,12",
"20,10",
"25,15",
"30,10"
]
} | [
"A"
] | the ages of two persons differ by 28 years . if 5 years ago , the elder one be 5 times as old as the younger one , their present ages ( in years ) are respectively | "explanation : let their ages be x and ( x + 28 ) years . 5 ( x - 5 ) = ( x + 28 - 5 ) or 4 x = 48 or x = 12 . their present ages are 40 years and 12 years option a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 3",
"1 / 9",
"1 / 12",
"2 / 9"
]
} | [
"B"
] | what is the probability of getting a sum 9 from two throws of dice | "explanation : total number of cases = 6 * 6 = 36 favoured cases = [ ( 3,6 ) , ( 4,5 ) , ( 6,3 ) , ( 5,4 ) ] = 4 so probability = 4 / 36 = 1 / 9 answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"25",
"30",
"90",
"140"
]
} | [
"B"
] | if the average ( arithmetic mean ) of a and b is 45 and the average of b and c is 60 , what is the value of c Γ’ Λ β a ? | "the arithmetic mean of a and b = ( a + b ) / 2 = 45 - - a + b = 90 - - 1 similarly for b + c = 120 - - 2 subtracting 1 from 2 we have c - a = 30 ; answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3",
"5 1 / 2",
"6",
"8"
]
} | [
"A"
] | a can finish a work in 9 days and b can do the same work in 15 days . b worked for 10 days and left the job . in how many days , a alone can finish the remaining work ? | "b ' s 10 day ' s work = ( 1 / 15 * 10 ) = 2 / 3 remaining work = ( 1 - 2 / 3 ) = 1 / 3 now , 1 / 18 work is done by a in 1 day 1 / 3 work is done by a in ( 9 * 1 / 3 ) = 3 days . correct option : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"76",
"5776",
"304",
"1296"
]
} | [
"B"
] | find β ? / 19 = 4 ? | "answer let β n / 19 = 4 then β n = 19 x 4 = 76 β΄ n = 76 x 76 = 5776 . correct option : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10",
"100",
"1000",
"100000"
]
} | [
"D"
] | ( 1000 ) 7 Γ· ( 10 ) 16 = ? | "explanation : = ( 103 ) 7 / ( 10 ) 16 = ( 10 ) 21 / ( 10 ) 16 = 10 ( 5 ) = 100000 option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 690",
"rs 790",
"rs 890",
"rs 990"
]
} | [
"C"
] | a , b and c invested rs . 8000 , rs . 4000 and rs . 8000 respectively in a business . a left after six months . if after eight months , there was a gain of rs . 4005 , then what will be the share of b ? | "explanation : a : b : c = ( 8000 * 6 ) : ( 4000 * 8 ) : ( 8000 * 8 ) = 48 : 32 : 64 = 3 : 2 : 4 so b share = ( 2 / 9 ) * 4005 = rs 890 option c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"130 km",
"160 km",
"100 km",
"140 km"
]
} | [
"B"
] | a bus covered a distance of 250 km , partly at an average speed of 40 kmph and partly at 60 kmph . if the total time taken is 5.5 hours , then the distance covered at 40 kmph is | "let the partial distance covered at 40 kmph be x let the another partial distance covered at 60 kmph be ( 250 - x ) thus , x / 40 - ( 250 - x ) / 60 = 5.5 or , x / 40 + ( 250 - x ) / 60 = 5.5 or , ( 3 x + 500 - 2 x ) / / 120 = 5.5 or 500 + x = 660 x = 160 answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"427",
"859",
"869",
"861"
]
} | [
"D"
] | the least number which when increased by 3 each divisible by each one of 24 , 32 , 36 and 54 is : | "solution required number = ( l . c . m . of 24 , 32 , 36 , 54 ) - 3 = 864 - 3 = 861 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"7500",
"7525",
"7550",
"8000"
]
} | [
"B"
] | 7500 + ( 1250 / 50 ) | explanation : as per bodmas rule first we will solve the terms in the bracket then other . = 7500 + ( 25 ) = 7525 option b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"225",
"280",
"300",
"385"
]
} | [
"D"
] | a large field of 700 hectares is divided into two parts . the difference of the areas of the two parts is one β fifth of the average o fthe two areas . what is the area of the smaller part in hectares ? | "solution let the areas of the two parts be x and ( 700 - x ) hectares = [ x - ( 700 - x ) ] = 1 / 5 x [ x + ( 700 - x ) / 2 ] = 2 x - 700 = 70 x = 385 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"7724",
"7804",
"4144",
"7844"
]
} | [
"C"
] | what is the least number of square tiles required to pave the floor of a room 13 m 44 cm long and 4 m 44 cm broad ? | "solution length of largest tile = h . c . f . of 1344 cm & 444 cm = 12 cm . area of each tile = ( 12 x 12 ) cm 2 β΄ required number of tiles = [ 1344 x 444 / 12 x 12 ] = 4144 . answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 15",
"2 / 15",
"4 / 15",
"2 / 5"
]
} | [
"C"
] | after doing 3 / 5 of the biology homework on monday night , sanjay did 1 / 3 of the remaining homework on tuesday night . what fraction of the original homework would sanjay have to do on wednesday night to complete the biology assignment ? | sol . ( c ) remaining homework on monday night = 1 - ( 3 / 5 ) = 2 / 5 work done on tuesday night = 1 / 3 of 2 / 5 = 2 / 15 remaining homework to complete the biology assignment = 2 / 5 - 2 / 15 = ( 6 - 2 ) / 15 = 4 / 15 answer c | MathQA |
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