choices dict | answerKey listlengths 1 1 | question stringlengths 8 751 | rationale stringlengths 8 1.53k | dataset stringclasses 1
value |
|---|---|---|---|---|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 : 2",
"2 : 1",
"2 : 3",
"4 : 3"
]
} | [
"D"
] | eight women can do a work in 10 days . ten men can complete the same work in 6 days . what is the ratio between the capacity of a man and a woman ? | "explanation : ( 8 ã — 10 ) women can complete the work in 1 day . â ˆ ´ 1 woman ' s 1 day ' s work = 1 / 80 ( 10 ã — 6 ) men can complete the work in 1 day . â ˆ ´ 1 man ' s 1 day ' s work = 1 / 60 so , required ratio = 1 / 80 : 1 / 60 = 4 : 3 answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"36",
"42",
"40",
"46"
]
} | [
"C"
] | if p and q are positive integers each greater than 1 , and 17 ( p + 1 ) = 25 ( q + 1 ) , what is the least possible value of p + q ? | "17 ( p + 1 ) = 29 ( q + 1 ) - - > ( p + 1 ) / ( q + 1 ) = 29 / 17 - - > the least positive value of p + 1 is 25 , so the least value of p is 24 and the least positive value of q + 1 is 17 , so the least value of q is 16 - - > the least value of p + q is 24 + 16 = 40 . answer : c ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 90000",
"rs . 36000",
"rs . 50000",
"rs . 45000"
]
} | [
"A"
] | ajay spends 50 % of his monthly income on household items , 25 % of his monthly income on buying cloths , 15 % of his monthly income on medicines and saves the remaining amount which is rs . 9000 . find his monthly income . | savings 10 % - 9000 expenditure 90 % - 81000 total - 90000 answer : a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 1000",
"1 / 506",
"253 / 500",
"253 / 1000"
]
} | [
"A"
] | ( 753 x 753 + 247 x 247 - 753 x 247 ) / ( 753 x 753 x 753 + 247 x 247 x 247 ) = ? | given exp . = ( a ^ 2 + b ^ 2 - ab ) / ( a ^ 3 + b ^ 3 ) = 1 / ( a + b ) = 1 / ( 753 + 247 ) = 1 / 1000 answer : a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"19 %",
"10 %",
"21 %",
"16 %"
]
} | [
"C"
] | weights of two friends ram and shyam are in the ratio 6 : 5 . if ram ' s weight is increased by 10 % and total weight of ram and shyam become 82.8 kg , with an increases of 15 % . by what percent did the weight of shyam has to be increased ? | "solution : given ratio of ram and shayam ' s weight = 6 : 5 hence , ( x - 15 ) / ( 15 - 10 ) = 6 / 5 or , x = 21 % . answer : option c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"475",
"234",
"289",
"345"
]
} | [
"A"
] | jaclyn buys $ 20 000 worth of debentures in a company . she earns 9.5 % p . a . simple interest , paid to her quarterly ( that is , every 3 months ) . if the agreed period of the debenture was 18 months : calculate the amount of interest jaclyn will earn for each quarter | "explanation : i = ( p x r x t ) / 100 = 30000 * 9.5 / 100 * ( 18 / 12 ) ^ 1 / 6 = 475 answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"6 : 5",
"9 : 25",
"5 : 6",
"25 : 9"
]
} | [
"C"
] | two interconnected , circular gears travel at the same circumferential rate . if gear a has a diameter of 60 centimeters and gear b has a diameter of 50 centimeters , what is the ratio of the number of revolutions that gear a makes per minute to the number of revolutions that gear b makes per minute ? | "same circumferential rate means that a point on both the gears would take same time to come back to the same position again . hence in other words , time taken by the point to cover the circumference of gear a = time take by point to cover the circumference of gear b time a = 2 * pi * 25 / speed a time b = 2 * pi * 30... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"64 : 65",
"65 : 64",
"19 : 65",
"65 : 19"
]
} | [
"D"
] | 3 bottles contain equal mixtures of spirit and water in the ratio 6 : 1 , 5 : 2 and 3 : 1 respectively . if all the solutions are mixed together , the ratio of spirit to water in the final mixture will be | given that all bottles contain equal amount of mixture say v . so in the first vessel - > water : spirit = 1 / 7 : 6 / 7 in the second bottle - > 2 / 7 : 5 / 7 in the third bottle - > l / 4 : 3 / 4 . hence , the final ratio is = ( ( 6 / 7 ) + ( 5 / 7 ) + ( 3 / 4 ) ) / ( ( 1 / 7 ) + ( 2 / 7 ) + ( 1 / 4 ) ) = 65 / 19 ans... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"- 2",
"- 1",
"- 1 / 3",
"0"
]
} | [
"A"
] | line m lies in the xy - plane . the y - intercept of line m is - 4 , and line m passes through the midpoint of the line segment whose endpoints are ( 2 , 4 ) and ( 6 , - 8 ) . what is the slope of line m ? | "ans : a solution : line m goes through midpoint of ( 2 , 4 ) and ( 6 , - 8 ) . midpoint is ( 4 , - 2 ) as we can see that the y axis of intercept point is ( 0 , - 4 ) means line m is parallel to x axis slope m = - 2 ans : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20",
"30",
"38",
"48"
]
} | [
"B"
] | the sum of 3 numbers is 98 . if the ratio of the first to the second is 2 : 3 and that of the second to the third is 5 : 8 , then the second number is : | a : b = 2 : 3 = 2 × 5 : 3 × 5 = 10 : 15 and b : c = 5 : 8 = 5 × 3 : 8 × 3 = 15 : 24 therefore , a : b : c = 10 : 15 : 24 ∴ a : b : c = 10 : 15 : 24 let the number be 10 x , 15 x and 24 x . then , 10 x + 15 x + 24 x = 98 or 49 x = 98 or x = 2 ⇒ second number = 15 x = 15 × 2 = 30 answer b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1200",
"120",
"360",
"200"
]
} | [
"D"
] | average age of students of an adult school is 42 years . 120 new students whose average age is 32 years joined the school . as a result the average age is decreased by 4 years . find the number of students of the school after joining of the new students . | "explanation : let the original no . of students be x . according to situation , 42 x + 120 * 32 = ( x + 120 ) 36 ⇒ x = 80 so , required no . of students after joining the new students = x + 120 = 200 . answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"18",
"750",
"24",
"20"
]
} | [
"D"
] | how many plants will be there in a circular bed whose outer edge measure 32 cms , allowing 4 cm 2 for each plant ? | "circumference of circular bed = 32 cm area of circular bed = ( 32 ) 2 â „ 4 ï € space for each plant = 4 cm 2 â ˆ ´ required number of plants = ( 32 ) 2 â „ 4 ï € ã · 4 = 20.36 = 20 ( approx ) answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1200",
"180",
"360",
"240"
]
} | [
"B"
] | average age of students of an adult school is 44 years . 120 new students whose average age is 32 years joined the school . as a result the average age is decreased by 4 years . find the number of students of the school after joining of the new students . | "explanation : let the original no . of students be x . according to situation , 44 x + 120 * 32 = ( x + 120 ) 36 ⇒ x = 60 so , required no . of students after joining the new students = x + 120 = 180 answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 11.81",
"rs . 12",
"rs . 12.25",
"rs . 12.31"
]
} | [
"A"
] | a fruit seller sells mangoes at the rate of rs . 9 per kg and thereby loses 20 % . at what price per kg , he should have sold them to make a profit of 5 % ? | "solution 85 : 9 = 105 : x x = ( 9 × 105 / 80 ) = rs . 11.81 hence , s . p per kg = rs . 11.81 answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 625",
"rs 300",
"rs 350",
"rs 375"
]
} | [
"B"
] | the sale price of a trolley bag including the sale tax is rs . 420 . the rate of sale tax is 12 % . if the shopkeeper has made a profit of 25 % , the cost price of the trolley bag is : | explanation : 112 % of s . p . = 420 s . p . = rs . ( 420 x 100 / 112 ) = rs . 375 . c . p . = rs ( 100 / 125 x 375 ) = rs 300 answer : b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5600",
"4600",
"4094",
"7200"
]
} | [
"C"
] | how many bricks each measuring 20 cm x 13.25 cm x 8 cm , will be needed to build a wall 7 m x 8 m x 15.5 m | "explanation : no . of bricks = volume of the wall / volume of 1 brick = ( 700 x 800 x 15.5 ) / ( 20 x 13.25 x 8 ) = 4094 answer : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"252",
"280",
"360",
"450"
]
} | [
"A"
] | the banker â € ™ s discount of a certain sum of money is rs . 42 and the true discount on the same sum for the same time is rs . 36 . the sum due is | "sol . sum = b . d . * t . d . / b . d . - t . d . = rs . [ 42 * 36 / 42 - 36 ] = rs . [ 42 * 36 / 6 ] = rs . 252 answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 432",
"rs . 422",
"rs . 419",
"rs . 442"
]
} | [
"C"
] | the true discount on a bill of rs . 2560 is rs . 360 . what is the banker ' s discount ? | "explanation : f = rs . 2560 td = rs . 360 pw = f - td = 2560 - 360 = rs . 2200 true discount is the simple interest on the present value for unexpired time = > simple interest on rs . 2200 for unexpired time = rs . 360 banker ' s discount is the simple interest on the face value of the bill for unexpired time = simple... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"35.24",
"36.16",
"36.24",
"36.46"
]
} | [
"D"
] | the mean of 50 observations was 36 . it was found later that an observation 46 was wrongly taken as 23 . the corrected new mean is | "solution correct sum = ( 36 x 50 + 46 - 23 ) = 1823 . â ˆ ´ correct mean = 1823 / 50 = 36.46 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"420",
"700",
"220",
"500"
]
} | [
"D"
] | a fruit seller had some oranges . he sells 40 % oranges and still has 300 oranges . how many oranges he had originally ? | "explanation : he sells 40 % of oranges and still there are 300 oranges remaining = > 60 % of oranges = 300 ⇒ ( 60 × total oranges ) / 100 = 300 ⇒ total oranges / 100 = 5 ⇒ total oranges = 5 × 100 = 500 answer : option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"8500",
"8900",
"8600",
"6970"
]
} | [
"C"
] | the difference between the place values of 9 and 4 in the number 529435 is | sol . = ( place value of 9 ) – ( place value of 4 ) = ( 9000 - 400 ) = 8600 answer c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 3000",
"rs . 3600",
"rs . 2400",
"rs . 4000"
]
} | [
"B"
] | p , q and r have rs . 9000 among themselves . r has two - thirds of the total amount with p and q . find the amount with r ? | "let the amount with r be rs . r r = 2 / 3 ( total amount with p and q ) r = 2 / 3 ( 9000 - r ) = > 3 r = 18000 - 2 r = > 5 r = 18000 = > r = 3600 . answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"22000",
"27000",
"16071",
"16789"
]
} | [
"C"
] | sheela deposits rs . 4500 in bank savings account . if this is 28 % of her monthly income . what is her monthly income in ? | "explanation : 28 % of income = rs . 4500 100 % of income = 4500 x 100 / 28 = rs . 16071 answer : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 4462.50",
"rs . 8032.50",
"rs . 8900",
"rs . 8925"
]
} | [
"D"
] | a sum fetched a total simple interest of rs . 4016.25 at the rate of 9 p . c . p . a . in 5 years . what is the sum ? | "solution principal = rs . ( 100 * 4016.25 / 9 * 5 ) = rs . ( 401625 / 45 ) = rs . 8925 answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3750",
"3600",
"7400",
"7500"
]
} | [
"A"
] | vijay sells a cupboard at 16 % below cost price . had he got rs . 1200 more , he would have made a profit of 16 % . what is the cost price of the cupboard ? | "explanation : cost price = 1200 / ( 0.16 + 0.16 ) = 1200 / 0.32 = rs . 3750 answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"- 2",
"- 1",
"0",
"2"
]
} | [
"D"
] | if q = ( x – 5 ) ^ 2 + ( x + 1 ) ^ 2 – 6 , then y is least when x = | let us transform the formula : q = ( x – 5 ) ² + ( x + 1 ) ² – 6 = x ² – 10 x + 25 + x ² + 2 x + 1 – 6 = 2 x ² – 8 x + 20 = 2 × ( x ² – 4 x + 10 ) = 2 × ( ( x ² – 4 x + 4 ) + 6 ) = 2 × ( ( x – 2 ) ² + 6 ) any square is greater or equal 0 . therefore the formula possess the least value when ( x – 2 ) ² = 0 . x – 2 = 0 x... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"750",
"500",
"800",
"850"
]
} | [
"B"
] | in an election between the two candidates , the candidates who gets 70 % of votes polled is winned by 200 vote ’ s majority . what is the total number of votes polled ? | "explanation : note : majority ( 40 % ) = difference in votes polled to win ( 70 % ) & defeated candidates ( 30 % ) 40 % = 70 % - 30 % 40 % - - - - - > 200 ( 40 * 5 = 200 ) 100 % - - - - - > 500 ( 100 * 5 = 500 ) answer : option b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"35 %",
"25 %",
"20 %",
"30 %"
]
} | [
"B"
] | a man ’ s wages were decreased by 50 % . again , the reduced wages were increased by 50 % . he has a loss of ? | here , x = - 50 and y = 50 therefore , the net % change in value = ( x + y + xy / 100 ) % = [ - 50 + 50 + ( - 50 x 50 ) / 100 ] % or - 25 % since the sign is negative , there is loss of 25 % answer : b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2.3 m",
"4.6 m",
"7.8 m",
"9.2 m"
]
} | [
"D"
] | the angle of elevation of a ladder leaning against a wall is 60 ° and the foot of the ladder is 4.6 m away from the wall . the length of the ladder is | solution let ab be the wall and bc be the ladder . then , < abc = 60 ° ac = 4.6 m . ; ac / bc = cos 60 ° = 1 / 2 ‹ = › bc = 2 × ac = ( 2 × 4.6 ) m = 9.2 m answer d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 20.25",
"rs . 22.50",
"rs . 25",
"rs . 42.75"
]
} | [
"B"
] | the interest on a certain deposit at 4.5 % p . a . is rs . 202.50 in one year . how much will the additional interest in one year be on the same deposit at 5 % p . a . ? | "solution s . i . = rs . 202.50 , r = 4.5 % , t = 1 year . principal = rs . ( 100 x 202.50 / 4.5 x 1 ) = rs . 4500 . now , p = rs . 4500 , r = 5 % , t = 1 year . s . i . = rs . ( 4500 x 5 x 1 / 1000 = rs . 225 . ∴ difference in interest = rs . ( 225 - 202.50 ) = rs . 22.50 . answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 49.17",
"rs . 51.03",
"rs . 56",
"rs . 55.33"
]
} | [
"C"
] | if 10 litres of an oil of rs . 50 per litres be mixed with 5 litres of another oil of rs . 68 per litre then what is the rate of mixed oil per litre ? | "50 * 10 = 500 68 * 5 = 340 840 / 15 = 56 answer : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2200",
"2240",
"1600",
"1354"
]
} | [
"B"
] | the true discount on a bill due 9 months hence at 16 % per annum is rs . 240 . the amount of the bill is | "explanation : let p . w . be rs . x . then , s . i . on rs . x at 16 % for 9 months = rs . 240 . x ã — 16 ã — ( 9 / 12 ) ã — ( 1 / 100 ) = 240 or x = 2000 . p . w . = rs . 2000 . sum due = p . w . + t . d . = rs . ( 2000 240 ) = rs . 2240 . answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"250",
"276",
"280",
"295"
]
} | [
"D"
] | a library has an average of 570 visitors on sundays and 240 on other days . the average number of visitors per day in a month of 30 days beginning with a sunday is : | "since the month begins with sunday , to there will be five sundays in the month average required = ( 570 x 5 + 240 x 25 ) / 30 ) = 295 answer : option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"80 kmph",
"69 kmph",
"70 kmph",
"90 kmph"
]
} | [
"B"
] | a train travels 210 km in 3 hours and 270 km in 4 hours . find the average speed of train . | "as we know that speed = distance / time for average speed = total distance / total time taken thus , total distance = 210 + 270 = 480 km thus , total speed = 7 hrs or , average speed = 480 / 7 or , 69 kmph . answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"99.33 km",
"133.33 km",
"125.33 km",
"156.66 km"
]
} | [
"B"
] | when a train moves at an average speed of 100 kmph it reaches its destination on time . when its average speed becomes 80 kmph , then it reaches its destination 20 minutes late . find the length of journey rounded to two decimal places . | sol . difference between timings = 20 min = 1 / 3 hr . let the length of journey be x km . then , x / 80 - x / 100 = 1 / 3 â ‡ ” 5 x - 4 x = 133.33 â ‡ ” x = 133.33 km . answer b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"144 mins",
"140 mins",
"136 mins",
"152 minw"
]
} | [
"D"
] | one pipe can fill a tank three times as fast as another pipe . if together the two pipes can fill the tank in 38 minutes , then the slower pipe alone will be able to fill the tank in | "explanation : let the slower pipe alone fill the tank in x minutes then faster will fill in x / 3 minutes . part filled by slower pipe in 1 minute = 1 / x part filled by faster pipe in 1 minute = 3 / x part filled by both in 1 minute = 1 / x + 3 / x = 1 / 38 = > 4 / x = 1 / 38 x = 38 ∗ 4 = 152 mins option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"143",
"150",
"123.75",
"140.55"
]
} | [
"C"
] | if a number x is 10 % less than another number y and y is 10 % more than 125 , then x is equal to | solution y = 125 + 10 % of 125 = 125 + 12.50 = 137.50 . x = 137.50 - 10 % of 137.50 = 137.50 - 13.75 = 123.75 . answer c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.1602",
"0.001602",
"1.6021",
"0.01602"
]
} | [
"B"
] | 16.02 ã — 0.0001 = ? | "16.02 ã — 0.0001 = 0.001602 the answer is b ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10",
"100",
"1000000",
"10000"
]
} | [
"C"
] | ( 1000 ) 7 ÷ ( 10 ) 15 = ? | "explanation : = ( 103 ) 7 / ( 10 ) 15 = ( 10 ) 21 / ( 10 ) 15 = 10 ( 6 ) = 1000000 option c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20000",
"6000",
"8000",
"10000"
]
} | [
"A"
] | a person spends 40 % of his salary on food , 25 % on house rent , 15 % on entertainment and 5 % on conveyance . if his savings at the end of the month is rs . 3000 , then his salary per month in rupees is : | "total expenditure = 40 + 25 + 15 + 5 = 85 % saving = ( 100 - 85 ) = 15 % 15 / 100 × salary = 3000 , salary = 20000 rs . answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"88888888",
"888888888",
"898989898",
"9999999998"
]
} | [
"B"
] | ( 12345679 x 72 ) = ? | "explanation : 12345679 x 72 = 12345679 x ( 70 + 2 ) = 12345679 x 70 + 12345679 x 2 = 864197530 + 24691358 = 888888888 answer : option b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10 hours",
"40 hours",
"20 hours",
"60 hours"
]
} | [
"D"
] | if 36 men can do a piece of work in 25 hours , in how many hours will 15 men do it ? | "let the required number of hours be x . then , less men , more hours ( indirect proportion ) 15 : 36 : : 25 : x = ( 15 x x ) = ( 36 x 25 ) = ( 36 x 25 ) / 15 = 60 hence , 15 men can do it in 60 hours . answer is d ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 1200",
"rs . 1300",
"rs . 3500",
"rs . 2000"
]
} | [
"C"
] | a man invests rs . 7,000 at the rate of 5 % per annum . how much more should he invest at the rate of 8 % , so that he can earn a total of 6 % per annum ? | "explanation : interest on rs . 7000 at 5 % per annum = ( 7000 × 5 × 1 ) / 100 = rs . 350 let his additional investment at 8 % = x interest on rs . x at 8 % per annum = ( x × 8 × 1 ) / 100 = 2 x / 25 . to earn 6 % per annum for the total , interest = ( 7000 + x ) × 6 × 1 / 100 . = > 350 + 2 x / 25 = ( 7000 + x ) × 6 × ... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.003",
"0.015",
"0.25",
"0.005"
]
} | [
"B"
] | double of quarter of 3 percent written as a decimal is : | "explanation : solution : ( 2 ) * ( 1 / 4 ) * 3 % = 2 * ( 1 / 4 * 3 / 100 ) = 0.015 . answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"960",
"990",
"1,200",
"920"
]
} | [
"B"
] | the profit earned by selling an article for 872 is equal to the loss incurred when the same article is sold for 448 . what should be the sale price of the article for making 50 per cent profit ? | "let the profit or loss be x and 872 – x = 448 + x or , x = 424 ⁄ 2 = 212 \ cost price of the article = 872 – x = 448 + x = 660 \ sp of the article = 660 × 150 ⁄ 100 = 990 answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"50",
"60",
"80",
"320"
]
} | [
"A"
] | a number exceeds 20 % of itself by 40 . the number is ? | answer ∵ a - 20 % of a = 40 ⇒ a - a / 5 = 40 ⇒ 4 a / 5 = 40 ∴ a = ( 5 x 40 ) / 4 = 50 . correct option : a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10",
"910",
"1001",
"1911"
]
} | [
"A"
] | the maximum number of students among them 890 pens and 630 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : | "explanation : required number of students = h . c . f of 890 and 630 = 10 . answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"48 kg",
"49 kg",
"50 kg",
"51 kg"
]
} | [
"C"
] | the price of rice is reduced by 2 % . how many kilograms of rice can now be bought for the money which was sufficient to buy 49 kg of rice earlier ? | sol . let the original price be rs . 100 per kg . money required to buy 49 kg of rice = rs . ( 100 x 49 ) = rs . 4900 . new price = rs . 98 per kg . ∴ quantity of rice bought = [ 4900 / 98 ] kg = 50 kg . answer c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 3000",
"rs . 4991",
"rs . 5991",
"rs . 6001"
]
} | [
"B"
] | a grocer has a sale of rs . 6345 , rs . 6927 , rs . 6855 , rs . 7230 and rs . 6562 for 5 consecutive months . how much sale must he have in the sixth month so that he gets an average sale of rs . 6500 ? | "sol . total sale for 5 months = rs . ( 6435 + 6927 + 6855 + 7230 + 6562 ) = rs . 34009 . ∴ required sale = rs . [ ( 6500 x 6 ) - 34009 ] = rs . ( 39000 - 34009 ) = rs . 4991 . answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1767",
"1800",
"1812",
"1890"
]
} | [
"A"
] | given a number , there is an algorithm described here to find it ' s sum and number of factors . for example , let us take the number 1225 ? | solving for 1225 = 52 × 72 sum of divisors = ( ap + 1 – 1 ) / ( a – 1 ) × ( bq + 1 – 1 ) / ( b – 1 ) here a = 5 , b = 7 prime factors p = 2 and q = 2 sum of divisors = ( 53 – 1 ) / ( 5 – 1 ) × ( 73 – 1 ) / ( 7 – 1 ) = ( 124 / 4 ) × ( 342 / 6 ) = ( 31 × 57 ) = 1767 option a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 500",
"rs . 1500",
"rs . 2000",
"rs . 2400"
]
} | [
"D"
] | a sum of money is to be distributed among a , b , c , d in the proportion of 5 : 2 : 4 : 3 . if c gets rs . 1200 more than d , what is b ' s share ? | "let the shares of a , b , c and d be rs . 5 x , rs . 2 x , rs . 4 x and rs . 3 x respectively . then , 4 x - 3 x = 1200 x = 1200 . b ' s share = rs . 2 x = rs . ( 2 x 1200 ) = rs . 2400 . answer = d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5 hours",
"4 hours",
"3 hours",
"2 hours"
]
} | [
"D"
] | a boat can travel with a speed of 22 km / hr in still water . if the speed of the stream is 5 km / hr , find the time taken by the boat to go 54 km downstream | "explanation : speed of the boat in still water = 22 km / hr speed of the stream = 5 km / hr speed downstream = ( 22 + 5 ) = 27 km / hr distance travelled downstream = 54 km time taken = distance / speed = 54 / 27 = 2 hours . answer : option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"400",
"430",
"435",
"405"
]
} | [
"C"
] | sum of the numbers from 1 to 29 is | explanation : sum of first n natural numbers = 1 + 2 + 3 + . . . . . n = n ( n + 1 ) / 2 substitute n = 29 . so s 20 = 29 ã — 30 / 2 = 435 correct option : c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1360",
"637.5",
"1600",
"1800"
]
} | [
"B"
] | the simple interest and the true discount on a certain sum for a given time and at a given rate are rs . 85 and rs . 75 respectively . the sum is : | "sol . sum = s . i . * t . d . / ( s . i ) - ( t . d . ) = 85 * 75 / ( 85 - 75 ) = rs . 637.5 . answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 7000",
"rs . 8200",
"rs . 8500",
"rs . 9000"
]
} | [
"B"
] | the salary of a , b , c , d , e is rs . 9000 , rs . 5000 , rs . 11000 , rs . 7000 , rs . 9000 per month respectively , then the average salary of a , b , c , d , and e per month is | "answer average salary = 9000 + 5000 + 11000 + 7000 + 9000 / 5 = rs . 8200 correct option : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 80",
"rs . 115.20",
"rs . 120",
"rs . 125.40"
]
} | [
"B"
] | a invested some money in 10 % stock at 96 . if b wants to invest in an equally good 12 % stock , he must purchase a stock worth of : | explanation : for an income of rs . 10 , investment = rs . 96 . for an income of rs . 12 , investment = ( 96 / 10 x 12 ) = 115.20 answer : b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1100",
"800",
"1400",
"1200"
]
} | [
"B"
] | a , band c enter into partnership . a invests 3 times as much as b and b invests two - third of what c invests . at the end of the year , the profit earned is rs . 4400 . what is the share of b ? | let c ' s capital = rs . x . then , b ' s capital = rs . ( 2 / 3 ) x a ’ s capital = rs . ( 3 x ( 2 / 3 ) . x ) = rs . 2 x . ratio of their capitals = 2 x : ( 2 / 3 ) x : x = 6 : 2 : 3 . hence , b ' s share = rs . ( 4400 x ( 2 / 11 ) ) = rs . 800 . answer is b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2 / 3",
"3 / 5",
"4 / 7",
"5 / 9"
]
} | [
"D"
] | the denominator of a fraction is 1 less than twice the numerator . if the numerator and denominator are both increased by 1 , the fraction becomes 3 / 5 . find the fraction ? | let the numerator and denominator of the fraction be ' n ' and ' d ' respectively . d = 2 n - 1 ( n + 1 ) / ( d + 1 ) = 3 / 5 5 n + 5 = 3 d + 3 5 n + 5 = 3 ( 2 n - 1 ) + 3 = > n = 5 d = 2 n - 1 = > d = 9 hence the fraction is : 5 / 9 answer : d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 190",
"rs . 17",
"rs . 1.70",
"rs . 4.25"
]
} | [
"A"
] | if 0.5 % of a = 95 paise , then the value of a is ? | "answer ∵ 0.5 / 100 of a = 95 / 100 ∴ a = rs . ( 95 / 0.5 ) = rs . 190 correct option : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10000",
"20000",
"25000",
"22235"
]
} | [
"A"
] | sheela deposits rs . 2500 in bank savings account . if this is 25 % of her monthly income . what is her monthly income in ? | explanation : 25 % of income = rs . 2500 100 % of income = 2500 x 100 / 25 = rs . 10000 answer : a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"99.6",
"96.2",
"97.5",
"98.2"
]
} | [
"D"
] | what is the cp of rs 100 stock at 2 discount , with 1 / 5 % brokerage ? | "explanation : use the formula , cp = 100 â € “ discount + brokerage % cp = 100 - 2 + 1 / 5 98.2 thus the cp is rs 98.2 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20,412",
"19,780",
"19,680",
"19,380"
]
} | [
"A"
] | sonika bought a v . c . r . at the list price of 18,900 . if the rate of sales tax was 8 % , find the amount she had to pay for purchasing the v . c . r . | "sol . list price of v . c . r . = 18,900 rate of sales tax = 8 % ∴ sales tax = 8 % of 18,900 = 8 ⁄ 100 × 18500 = 1512 so , total amount which sonika had to pay for purchasing the v . c . r . = 18,900 + 1512 = 20,412 . answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 1178",
"rs . 820",
"rs . 990",
"rs . 1385"
]
} | [
"A"
] | average monthly income of a family of 4 earning members was rs . 782 . one of the earning members died and therefore , the average income came down to rs 650 . the income of the deceased was ? | "answer income of the deceased = total income of 4 members - total income of remaining 3 members . = 782 x 4 - 650 x 3 rs . = 1178 rs . correct option : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5",
"0.05",
"0.5",
"50"
]
} | [
"B"
] | 0.0005 ? = 0.01 | "explanation : required answer = 0.0005 / 0.01 = 0.05 / 1 = 0.05 . answer : option b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"84 m",
"28 m",
"120 m",
"137 m"
]
} | [
"B"
] | 22 cubic centimetres of silver is drawn into a wire 1 mm in diameter . the length of the wire in metres will be : | "sol . let the length of the wire b h . radius = 1 / 2 mm = 1 / 20 cm . then , 22 / 7 * 1 / 20 * 1 / 20 * h = 22 ⇔ = [ 22 * 20 * 20 * 7 / 22 ] = 2800 cm = 28 m . answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"91",
"910",
"1001",
"1911"
]
} | [
"A"
] | the maximum numbers of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is | "olution required number of students . = h . c . f of 1001 and 910 . ‹ = › 91 . answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 880",
"rs . 890",
"rs . 895",
"rs . 900"
]
} | [
"D"
] | if the compound interest on a certain sum of money for 3 years at 10 % per annum be rs . 993 , what would be the simple interest ? | let p = principal a - amount we have a = p ( 1 + r / 100 ) 3 and ci = a - p atq 993 = p ( 1 + r / 100 ) 3 - p ? p = 3000 / - now si @ 10 % on 3000 / - for 3 yrs = ( 3000 x 10 x 3 ) / 100 = 900 / - answer : d . | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 34.38",
"rs . 38.98",
"rs . 37",
"rs . 37.62"
]
} | [
"D"
] | the present worth of a certain bill due sometime hence is rs . 800 and the true discount is rs . 36 . the banker ’ s discount is | "solution b . g = [ ( t . d ) ² / p . w ] = rs . ( 36 x 36 / 800 ) = rs . 1.62 b . d given , t . d = 36 = ( t . d + b . g ) = rs . ( 36 + 1.62 ) = rs . 37.62 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"80 m",
"100 m",
"90 m",
"180 m"
]
} | [
"C"
] | two trains travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 4 seconds . the length of the faster train is | solution relative speed = ( 36 + 45 ) km / hr = ( 81 x 5 / 18 ) m / sec = ( 45 / 2 ) m / sec length of the train = ( 45 / 2 x 4 ) m = 90 m . answer c | MathQA |
{
"label": [
"A",
"B",
"D",
"E"
],
"text": [
"32",
"37",
"60",
"50"
]
} | [
"D"
] | set x consists of 15 integers and has median of 20 and a range of 20 . what is the value of the greatest possible integer that can be present in the set ? | "note that both median and range do not restrict too many numbers in the set . range is only concerned with the smallest and greatest . median only cares about the middle . quick check of each option starting from the largest : ( e ) 50 range of 20 means the smallest integer will be 30 . so 20 can not lie in between an... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"33.33 %",
"25 %",
"75 %",
"53.85 %"
]
} | [
"D"
] | if x is less than y by 35 % then y exceed x by : | "using formula ( x / ( 100 - x ) * 100 ) where x is percentage decrease ( here it is 35 % ) = > 35 / ( 100 - 35 ) * 100 = 53.85 % answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5",
"4.15",
"4.25",
"5.5"
]
} | [
"B"
] | excluding stoppages , the speed of a bus is 48 kmph and including stoppages , it is 45 kmph . for how many minutes does the bus stop per hour ? | "due to stoppages , it covers 314 km less . time taken to cover 3 km = ( ( 3 / 48 ) ã — 60 ) = 4.15 min . option ( b ) is correct" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"67 %",
"80 %",
"90 %",
"100 %"
]
} | [
"A"
] | in a certain store , the profit is 320 % of the cost . if the cost increases by 40 % but the selling price remains constant , approximately what percentage of the selling price is the profit | explanation : let c . p . = rs . 100 . then , profit = rs . 320 , s . p . = rs . 420 . new c . p . = 140 % of rs . 100 = rs . 140 new s . p . = rs . 420 . profit = rs . ( 420 - 140 ) = rs . 280 required percentage = ( 280 / 420 ) * 100 = 66.67 % ( approx ) = 67 % answer : a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"40",
"44",
"48",
"55"
]
} | [
"D"
] | in a can , there is a mixture of milk and water in the ratio 4 : 5 . if it is filled with an additional 10 litres of milk the can would be full and ratio of milk and water would become 6 : 5 . find the capacity of the can ? | "let the capacity of the can be t litres . quantity of milk in the mixture before adding milk = 4 / 9 ( t - 10 ) after adding milk , quantity of milk in the mixture = 6 / 11 t . 6 t / 11 - 10 = 4 / 9 ( t - 10 ) 10 t = 990 - 440 = > t = 55 . answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"84",
"94",
"83",
"72"
]
} | [
"A"
] | the sum of digits of a two digit number is 12 , the difference between the digits is 4 . find the number | "description : = > x + y = 12 , x - y = 4 adding these 2 x = 16 = > x = 8 , y = 4 . thus the number is 84 answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"76 kg",
"80 kg",
"85 kg",
"97 kg"
]
} | [
"D"
] | the average weight of 10 persons increases by 3.2 kg when a new person comes in place of one of them weighing 65 kg . what might be the weight of the new person ? | "solution total weight increased = ( 10 x 3.2 ) kg = 32 kg . weight of new person = ( 65 + 32 ) kg = 97 kg . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"250",
"305",
"280",
"285"
]
} | [
"B"
] | a library has an average of 630 visitors on sundays and 240 on other days . the average number of visitors per day in a month of 30 days beginning with a sunday is : | "since the month begins with sunday , to there will be five sundays in the month average required = ( 630 x 5 + 240 x 25 / 30 ) = 305 answer : option b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 1000",
"rs 1515",
"rs 1525",
"rs 1250"
]
} | [
"A"
] | the sale price of a trolley bag including the sale tax is rs . 1232 . the rate of sale tax is 10 % . if the shopkeeper has made a profit of 12 % , the cost price of the trolley bag is : | "explanation : 110 % of s . p . = 1232 s . p . = rs . ( 1232 x 100 / 110 ) = rs . 1120 . c . p . = rs ( 100 / 112 x 1120 ) = rs 1000 answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"21000",
"30000",
"32000",
"34000"
]
} | [
"A"
] | a & b started a partnership business . a ' s investment was thrice the investment of b and the period of his investment was two times the period of investments of b . if b received rs 3000 as profit , what is their total profit ? | "explanation : suppose b ' s investment = x . then a ' s investment = 3 x suppose bs period of investment = y , then a ' s period of investment = 2 y a : b = 3 x * 2 y : xy = 6 : 1 total profit * 1 / 7 = 3000 = > total profit = 3000 * 7 = 21000 . answer : option a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2160",
"2350",
"2000",
"2300"
]
} | [
"B"
] | after spending rs . 5000 on rent , rs . 1500 on milk , rs . 4500 on groceries , rs . 2500 on childrens education rs . 2000 on petrol and rs . 5650 on miscellaneous expenses , mr . kishore saved 10 % of his monthly salary . how much did he save in rs . ? | explanation : total exp = 5000 + 1500 + 4500 + 2500 + 2000 + 5650 = 21150 exp in % = 100 - 10 = 90 % , 21150 = 90 % saving = 10 % = 21150 x 10 / 90 = rs . 2350 answer : b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.045388",
"4.5388",
"0.051872",
"473.88"
]
} | [
"C"
] | [ ( 3.242 x 16 ) / 100 ] = ? | "answer multiplying 3.242 x 16 = 5.1872 now divide 5.1872 by 100 so , 5.1872 ÷ 100 = 0.051872 ∴ shift the decimal two places to the left as 100 correct option : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0",
"2",
"3",
"5"
]
} | [
"A"
] | what is the unit digit in [ ( 6273 ) ^ 1793 x ( 625 ) ^ 317 x ( 341 ) ^ 491 ] ? | unit digit in ( 6374 ) ^ 1793 = unit digit in ( 4 ) ^ 1793 = unit digit in [ ( 4 ^ 2 ) ^ 896 x 4 ] = unit digit in ( 6 x 4 ) = 4 unit digit in ( 625 ) ^ 317 = unit digit in ( 5 ) ^ 317 = 5 unit digit in ( 341 ) ^ 491 = unit digit in ( 1 ) ^ 491 = 1 required digit = unit digit in ( 4 x 5 x 1 ) = 0 answer is 0 | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4586970843",
"4686970743",
"4690910862",
"4586870843"
]
} | [
"C"
] | calculate 469138 x 9999 = ? | "answer 469138 x 9999 = 469138 x ( 10000 - 1 ) = 4691380000 - 469138 = 4690910862 . option : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 175",
"rs . 92",
"rs . 112.50",
"rs . 116.50"
]
} | [
"A"
] | a 14 % stock yields 8 % . the market value of the stock is : | "solution to obtain rs . 8 , investment = rs . 100 . to obtain rs . 14 , investment = rs . ( 100 / 8 x 14 ) = rs . 175 ∴ market value of rs . 100 stock = rs . 175 answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 55.50",
"rs . 67.50",
"rs . 86.50",
"rs . 87.50"
]
} | [
"D"
] | the sides of a rectangular field are in the ratio 3 : 4 . if the area of the field is 7500 sq . m , the cost of fencing the field @ 25 paise per metre is | "solution let length = ( 3 x ) metres and breadth = ( 4 x ) metres . then , 3 x × 4 x = 7500 ⇔ 12 x 2 = 7500 ⇔ x 2 = 625 ⇔ x = 25 . so , length = 75 m and breadth = 100 m . perimeter = [ 2 ( 75 + 100 ) ] m = 350 m . ∴ cost of fencing = rs . ( 0.25 × 350 ) = rs . 87.50 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"- 3",
"1",
"- 1 / 3",
"0"
]
} | [
"B"
] | line m lies in the xy - plane . the y - intercept of line m is - 2 , and line m passes through the midpoint of the line segment whose endpoints are ( 2 , 4 ) and ( 6 , - 10 ) . what is the slope of line m ? | "ans : b solution : line m goes through midpoint of ( 2 , 4 ) and ( 6 , - 10 ) . midpoint is ( 4 , - 3 ) as we can see that the y axis of intercept point is ( 0 , - 2 ) means line m is parallel to x axis slope m = 1 ans : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"210",
"280",
"560",
"450"
]
} | [
"C"
] | the banker â € ™ s discount of a certain sum of money is rs . 80 and the true discount on the same sum for the same time is rs . 70 . the sum due is | "sol . sum = b . d . * t . d . / b . d . - t . d . = rs . [ 80 * 70 / 80 - 70 ] = rs . [ 80 * 70 / 10 ] = rs . 560 answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 7070",
"rs . 5991",
"rs . 6020",
"rs . 6850"
]
} | [
"A"
] | a grocer has a sale of rs . 5420 , rs . 5660 , rs . 6200 , rs . 6350 and rs . 6500 for 5 consecutive months . find the sale he should have in the sixth month , so that he gets an average sale of rs . 6200 ? | "explanation : total sale for 5 months = rs . ( 5420 + 5660 + 6200 + 6350 + 6500 ) = rs . 30,130 therefore , required sale = rs . [ ( 6200 * 6 ) – 30,130 ] = rs . ( 37200 – 30,130 ) = rs . 7070 answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 150.50",
"rs . 154.75",
"rs . 156.25",
"rs . 1093.75"
]
} | [
"D"
] | the present worth of rs . 1183 due in 2 years at 4 % per annum compound interest is | "solution present worth = rs . [ 1183 / ( 1 + 4 / 100 ) ² ] = rs . ( 1183 x 25 / 26 x 25 / 26 ) = rs . 1093.75 answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"120,60",
"240,120",
"280,90",
"220,140"
]
} | [
"B"
] | a third of arun â € ™ s marks in mathematics exceed a half of his marks in english by 20 . if he got 360 marks in two subjects together how many marks did he got in english ? | "let arun â € ™ s marks in mathematics and english be x and y then ( 1 / 3 ) x - ( 1 / 2 ) y = 20 2 x - 3 y = 120 â € ¦ â € ¦ > ( 1 ) x + y = 360 â € ¦ â € ¦ . > ( 2 ) solving ( 1 ) and ( 2 ) x = 240 and y = 120 answer is b ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"180000",
"138800",
"658560",
"116740"
]
} | [
"A"
] | 600 x 223 + 600 x 77 = ? | "= 600 x ( 223 + 77 ) ( by distributive law ) = 600 x 300 = 180000 answer is a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4550",
"5000",
"0.5",
"4000"
]
} | [
"A"
] | 5000 - 4500 ÷ 10.00 = ? | "answer given expression = 5000 - 4500 ÷ 10.00 = 5000 - 450 = 4550 correct option : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5 kg",
"2.4 kg",
"2.5 kg",
"10 kg"
]
} | [
"A"
] | fresh grapes contain 90 % by weight while dried grapes contain 20 % water by weight . what is the weight of dry grapes available from 40 kg of fresh grapes ? | "the weight of non - water in 20 kg of fresh grapes ( which is 100 - 90 = 10 % of whole weight ) will be the same as the weight of non - water in x kg of dried grapes ( which is 100 - 20 = 80 % of whole weight ) , so 40 â ˆ — 0.1 = x â ˆ — 0.8 - - > x = 5 answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"150",
"450",
"750",
"800"
]
} | [
"A"
] | a and b undertake to do a piece of work for rs . 1200 . a alone can do it in 6 days while b alone can do it in 8 days . with the help of c , they finish it in 3 days . find the share of c . | "c ' s 1 day ' s work = 1 / 3 - ( 1 / 6 + 1 / 8 ) = 24 a : b : c = ratio of their 1 day ' s work = 1 / 6 : 1 / 8 : 1 / 24 = 4 : 3 : 1 . a ’ s share = rs . ( 1200 * 4 / 8 ) = rs . 600 , b ' s share = rs . ( 1200 * 3 / 8 ) = rs . 450 c ' s share = rs . [ 1200 - ( 300 + 225 » ) = rs . 150 . answer is a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.003",
"0.0005",
"0.25",
"0.02"
]
} | [
"D"
] | double of quarter of 4 percent written as a decimal is : | explanation : solution : ( 2 ) * ( 1 / 4 ) * 4 % = 2 * ( 1 / 4 * 1 / 100 ) = 0.02 . answer : d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 16241.875",
"rs . 15041.85",
"rs . 15401.875",
"rs . 15041.875"
]
} | [
"D"
] | a sum fetched a total simple interest of rs . 6016.75 at the rate of 8 p . c . p . a . in 5 years . what is the sum ? | "explanation : principal = rs 100 x 6016.75 / 8 x 5 = rs . 601675 / 40 = rs . 15041.875 answer : option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"200 km",
"180 km",
"160 km",
"220 km"
]
} | [
"B"
] | a boat takes 19 hours for travelling downstream from point a to point b and coming back to a point c midway between a and b . if the velocity of the stream is 4 km / h and the speed of the boat in still water is 14 km / h , what is the distance between a and b ? | "speed of boat for downstream = 14 + 4 = 18 km / hr speed of boat for upstream = 14 – 4 = 10 km / hr distance = x x / 18 + ( x / 2 ) / 10 = 19 x = 180 km answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"15",
"16",
"30",
"31"
]
} | [
"D"
] | 6 bells commence tolling together and toll at the intervals of 24 , 68 , 1012 seconds resp . in 60 minutes how many times they will toll together . | explanation : lcm of 2 - 4 - 6 - 8 - 10 - 12 is 120 seconds , that is 2 minutes . now 60 / 2 = 30 adding one bell at the starting it will 30 + 1 = 31 answer : option d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"600",
"700",
"840",
"900"
]
} | [
"C"
] | if 4 ( p ' s capital ) = 6 ( q ' s capital ) = 10 ( r ' s capital ) , then out of the total profit of rs 4340 , r will receive | explanation : let p ' s capital = p , q ' s capital = q and r ' s capital = r then 4 p = 6 q = 10 r = > 2 p = 3 q = 5 r = > q = 2 p / 3 r = 2 p / 5 p : q : r = p : 2 p / 3 : 2 p / 5 = 15 : 10 : 6 r ' s share = 4340 * ( 6 / 31 ) = 140 * 6 = 840 . answer : option c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 18000",
"rs . 20000",
"rs . 25600",
"rs . 32000"
]
} | [
"C"
] | 10 percent of ram ' s monthly salary is equal to 8 percent of shyam ' s monthly salary . shyam ' s monthly salary is twice abhinav ' s monthly salary . if abhinav ' s annual salary is rs . 1.92 lakhs , find ram ' s monthly salary ? | let the monthly salaries of ram and shyam be rs . r and rs . s respectively . 10 / 100 r = 8 / 100 s r = 4 / 5 s monthly salary of abhinav = ( 1.92 lakhs ) / 12 = rs . 0.16 lakhs s = 2 ( 0.16 lakhs ) = 0.32 lakhs r = 4 / 5 ( 0.32 lakhs ) = rs . 25600 answer : c | MathQA |
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