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MNLP_M3_mathqa

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{ "label": [ "A", "B", "C", "D" ], "text": [ "23.75", "22", "20.8", "19.2" ] }
[ "C" ]
a trader mixes 80 kg of tea at 15 per kg with 20 kg of tea at cost price of 20 per kg . in order to earn a profit of 30 % , what should be the sale price of the mixed tea ?
"c . p . of mixture = 80 Γ— 15 + 20 Γ— 20 / 80 + 20 = 16 ∴ s . p . = ( 100 + 30 ) / 100 Γ— 16 = 20.8 answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "40.2", "40.4", "40.6", "40.8" ] }
[ "A" ]
the average of 10 numbers is 40.2 . later it is found that two numbers have been wrongly copied . the first is 18 greater than the actual number and the second number added is 13 instead of 31 . find the correct average .
sum of 10 numbers = 402 corrected sum of 10 numbers = 402 – 13 + 31 – 18 = 402 hence , new average = 402 ⁄ 10 = 40.2 answer a
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "50 kmph", "60 kmph", "65 kmph", "16 kmph" ] }
[ "D" ]
a car takes 6 hours to cover a distance of 144 km . how much should the speed in kmph be maintained to cover the same direction in 3 / 2 th of the previous time ?
"time = 6 distence = 144 3 / 2 of 6 hours = 6 * 3 / 2 = 9 hours required speed = 144 / 9 = 16 kmph d )"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1 / 10", "1 / 50", "1 / 75", "1 / 25" ] }
[ "A" ]
what will be the fraction of 10 %
"explanation : 10 * 1 / 100 = 1 / 10 option a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 480", "rs . 760", "rs . 860", "rs . 960" ] }
[ "A" ]
a man buys an item at rs . 600 and sells it at the loss of 20 percent . then what is the selling price of that item
"explanation : here always remember , when ever x % loss , it means s . p . = ( 100 - x ) % of c . p when ever x % profit , it means s . p . = ( 100 + x ) % of c . p so here will be ( 100 - x ) % of c . p . = 80 % of 600 = 80 / 100 * 600 = 480 option a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "14 m', '", "18 m', '", "24 m', '", "16 m', '" ] }
[ "D" ]
if length of a room is three times of its breadth and its area is 12 sq . m . what is perimeter of room ?
let breadth = x m . and length = 3 x m . x * 3 x = 12 , x ^ 2 = 4 , x = 2 . length = 6 m , breadth = 2 m . perimeter = 2 * ( 6 + 2 ) = 16 m answer d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "2 / 15", "3 / 5", "1 / 6", "1 / 7" ] }
[ "A" ]
what is difference between biggest and smallest fraction among 2 / 3 , 3 / 4 , 4 / 5 and 5 / 7
explanation : 2 / 3 = . 66 , 3 / 4 = . 75 , 4 / 5 = . 8 and 5 / 7 = . 71 so biggest is 4 / 5 and smallest is 2 / 3 their difference is 4 / 5 - 2 / 3 = 2 / 15 option a
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 40", "rs . 50", "rs . 49", "rs . 59" ] }
[ "D" ]
the profit obtained by selling an article for rs . 66 is the same as the loss obtained by selling it for rs . 52 . what is the cost price of the article ?
"s . p 1 - c . p = c . p – s . p 2 66 - c . p = c . p - 52 2 c . p = 66 + 52 ; c . p = 118 / 2 = 59 answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "$ 10900", "$ 19000", "$ 190000", "$ 1900" ] }
[ "C" ]
a man spend 1 / 5 of his salary on food , 1 / 10 of his salary on house rent and 3 / 5 salary on clothes . he still has $ 19000 left with him . find salary . .
"[ 1 / ( x 1 / y 1 + x 2 / y 2 + x 3 / y 3 ) ] * total amount = balance amount [ 1 - ( 1 / 5 + 1 / 10 + 3 / 5 ) } * total salary = $ 19000 , = [ 1 - 9 / 10 ] * total salary = $ 19000 , total salary = $ 19000 * 10 = $ 190000 , correct answer ( c )"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "35.67 %", "64.75 %", "68.57 %", "69.10 %" ] }
[ "D" ]
in an examination , there were 2,000 candidates , out of which 900 candidates were girls and rest were boys . if 30 % of the boys and 32 % of the girls passed , then the total percentage of failed candidates is ?
"girls = 900 , boys = 1100 passed = ( 30 % of 1100 ) + ( 32 % of 900 ) = 330 + 288 = 618 failed = 2000 - 618 = 1382 failed % = [ ( 1382 / 2000 ) x 100 ] % = 69.1 % . answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "30,000", "5,000", "80,000", "120,000" ] }
[ "B" ]
a , b and c started a shop by investing rs . 5,000 , rs . 15,000 and rs . 30,000 respectively . at the end of the year , the profits were distributed among them . if c Γ’ € β„’ s share of profit be rs . 3000 , then the total profit was :
sol . a : b : c = 5000 : 15000 : 30000 = 1 : 3 : 6 . so , c Γ’ € β„’ s share : total profit = 6 : 10 let the total profit be rs . x . then , 6 / 10 = 3000 / x or x = 3000 * 10 / 6 = 5000 . answer b
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 300", "rs . 200", "rs . 240", "rs . 400" ] }
[ "D" ]
if x gets 25 % more than y and y gets 20 % more than z , the share of z out of rs . 1480 will be :
"z share = z , y = 1.2 z x = 1.25 Γ£ β€” 1.2 z , x + y + z = 1480 ( 1.25 Γ£ β€” 1.2 + 1.2 + 1 ) z = 1480 3.7 z = 1480 , z = 400 answer : . d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "6 hours", "5 hours", "7 hours", "8 hours" ] }
[ "B" ]
a truck covers a distance of 240 km at a certain speed in 8 hours . how much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 0 km more than that travelled by the truck ?
"explanation : speed of the truck = distance / time = 240 / 8 = 30 kmph now , speed of car = ( speed of truck + 18 ) kmph = ( 30 + 18 ) = 48 kmph distance travelled by car = 240 + 0 = 240 km time taken by car = distance / speed = 240 / 48 = 5 hours . answer – b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "429", "280", "360", "450" ] }
[ "A" ]
the banker Γ’ € β„’ s discount of a certain sum of money is rs . 78 and the true discount on the same sum for the same time is rs . 66 . the sum due is
sol . sum = b . d . * t . d . / b . d . - t . d . = rs . [ 78 * 66 / 78 - 66 ] = rs . [ 78 * 66 / 12 ] = rs . 429 answer a
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "19", "14", "8", "9.5" ] }
[ "A" ]
the average of 5 quantities is 10 . the average of 3 of them is 4 . what is the average of remaining 2 numbers ?
answer : a ( 5 x 10 - 3 x 4 ) / 2 = 19
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 258.80", "rs . 358.80", "rs . 458.80", "rs . 520.80" ] }
[ "D" ]
a tank is 25 m long 12 m wide and 6 m deep . the cost of plastering its walls and bottom at 70 paise per sq m is
"explanation : area to be plastered = [ 2 ( l + b ) Γ£ β€” h ] + ( l Γ£ β€” b ) = [ 2 ( 25 + 12 ) Γ£ β€” 6 ] + ( 25 Γ£ β€” 12 ) = 744 sq m cost of plastering = 744 Γ£ β€” ( 70 / 100 ) = rs . 520.80 answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "3 / 5", "3 / 6", "3 / 7", "3 / 8" ] }
[ "D" ]
a can finish a work in 8 days and b can do same work in half the time taken by a . then working together , what part of same work they can finish in a day ?
"explanation : please note in this question , we need to answer part of work for a day rather than complete work . it was worth mentioning here because many do mistake at this point in hurry to solve the question so lets solve now , a ' s 1 day work = 1 / 8 b ' s 1 day work = 1 / 4 [ because b take half the time than a ] ( a + b ) ' s one day work = ( 1 / 8 + 1 / 4 ) = 3 / 8 so in one day 3 / 8 work will be done answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "63", "74.31", "72.43", "73.43" ] }
[ "A" ]
a mathematics teacher tabulated the marks secured by 35 students of 8 th class . the average of their marks was 62 . if the marks secured by reema was written as 50 instead of 85 then find the correct average marks up to two decimal places .
"total marks = 35 x 62 = 2170 corrected total marks = 2170 - 50 + 85 = 2205 correct average = 2205 / 35 = 63 answer : a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "0", "2", "0", "3" ] }
[ "C" ]
what is the remainder when 7 ^ 74 - 5 ^ 74 is divided by 8 ?
"easiest way for me : 7 ^ 74 - 5 ^ 74 = ( 49 ) ^ 37 - 25 ^ 37 = ( 48 + 1 ) ^ 37 - ( 24 + 1 ) ^ 37 - > remainder is 1 ^ 37 - 1 ^ 37 = 0 ans : c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1240", "1120", "1190", "1806" ] }
[ "D" ]
the banker ' s gain on a sum due 6 years hence at 12 % per annum is rs . 756 . what is the banker ' s discount ?
"explanation : td = ( bg Γ— 100 ) / tr = ( 756 Γ— 100 ) / ( 6 Γ— 12 ) = rs . 1050 bg = bd – td = > 756 = bd - 1050 = > bd = 1050 + 756 = 1806 answer : option d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "15 %", "16 %", "0.125 %", "0.2083 %" ] }
[ "B" ]
farm tax is levied on the 60 % of the cultivated land . the tax department collected total $ 5000 through the farm tax from the village of mr . william . mr . william paid only $ 480 as farm tax . the percentage of total land of mr . willam over the total taxable land of the village is :
"this will be equal to the percentage of total cultivated land he holds over the total cultivated land in the village . that leads to ( 480 / 5000 ) x 100 = 9.6 % in percentage terms . but the question asks ratio between his total land to total cultivated land . hence the answer is 9.6 % x ( 100 / 60 ) = 16 % the correct answer is ( b ) ."
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1 / 20", "1 / 50", "1 / 75", "3 / 25" ] }
[ "D" ]
what will be the fraction of 12 %
"explanation : 12 * 1 / 100 = 3 / 25 . option d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "25 %", "33.33 %", "40 %", "7.69 %" ] }
[ "D" ]
a rectangle having length 120 cm and width 50 cm . if the length of the rectangle is increased by ten percent then how much percent the breadth should be decreased so as to maintain the same area .
"explanation : solution : ( 10 / ( 120 + 10 ) * 100 ) % = 7.69 % answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 300", "rs . 200", "rs . 100", "rs . 350" ] }
[ "C" ]
if x gets 25 % more than y and y gets 20 % more than z , the share of z out of rs . 370 will be :
z share = z , y = 1.2 z x = 1.25 Γ£ β€” 1.2 z , x + y + z = 740 ( 1.25 Γ£ β€” 1.2 + 1.2 + 1 ) z = 37 3.7 z = 370 , z = 100 answer : . c
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 25561.80", "rs . 37500.80", "rs . 50561.80", "rs . 60000" ] }
[ "C" ]
a man sells a car to his friend at 11 % loss . if the friend sells it for rs . 54000 and gains 20 % , the original c . p . of the car was :
explanation : s . p = rs . 54,000 . gain earned = 20 % c . p = rs . [ 100 / 120 Γ£ β€” 54000 ] = rs . 45000 this is the price the first person sold to the second at at loss of 11 % . now s . p = rs . 45000 and loss = 11 % c . p . rs . [ 100 / 89 Γ£ β€” 45000 ] = rs . 50561.80 . correct option : c
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1.9532", "1.0025", "1.5693", "1.0266" ] }
[ "A" ]
given that 268 x 74 = 19532 , find the value of 2.68 x . 74 .
"solution sum of decimals places = ( 2 + 2 ) = 4 . therefore , = 2.68 Γ— . 74 = 1.9532 answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1200", "2400", "1400", "2500" ] }
[ "D" ]
an inspector rejects 0.08 % of the meters as defective , how many meters he examine to reject 2 meteres
explanation : it means that 0.08 % of x = 2 = > ( 8 / 100 Γ— 100 Γ— x ) = 2 = > x = 2 Γ— 100 Γ— 100 / 8 = > x = 2500 option d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "55 %", "60 %", "65 %", "75 %" ] }
[ "A" ]
if an examination 63 % of the candidates in english , 65 % passed in mathematics , and 27 % failed in both subjects . what is the pass percentage ?
fail in english = 100 - 63 = 37 % fail in maths = 100 - 65 = 35 % so pass % = 100 - ( 37 + 35 - 27 ) = 55 % answer : a
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "26 km", "32 km", "30 km", "28 km" ] }
[ "B" ]
a man travelled a distance of 80 km in 7 hours partly on foot at the rate of 8 km per hour and partly on bicycle at 16 km per hour . find the distance travelled on foot .
total time = 7 hrs let the distance travelled by foot @ 8 kmph be x kms ? distance travlled by bicycle @ 16 kmph be ( 80 - x ) kms atq . 7 hr = x / 8 + ( 80 - x ) / 16 ? 7 = ( 2 x + 80 - x ) / 16 ? x = 32 kms answer : b .
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1 / 2", "1 / 6", "1 / 7", "1 / 8" ] }
[ "A" ]
a can finish a work in 6 days and b can do same work in half the time taken by a . then working together , what part of same work they can finish in a day ?
"explanation : please note in this question , we need to answer part of work for a day rather than complete work . it was worth mentioning here because many do mistake at this point in hurry to solve the question so lets solve now , a ' s 1 day work = 1 / 6 b ' s 1 day work = 1 / 3 [ because b take half the time than a ] ( a + b ) ' s one day work = ( 1 / 6 + 1 / 3 ) = 1 / 2 so in one day 1 / 2 work will be done answer : a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "7580", "7960", "8290", "2160" ] }
[ "D" ]
a leak in the bottom of a tank can empty the full tank in 4 hours . an inlet pipe fills water at the rate of 6 litres a minute . when the tank is full , the inlet is opened and due to the leak , the tank is empty in 12 hours . how many litres does the cistern hold ?
solution work done by the inlet in 1 hour = ( 1 / 4 - 1 / 12 ) = 1 / 6 . work done by the inlet in 1 min . = ( 1 / 6 Γ— 1 / 60 ) = 0.002778 volume of 0.002778 part = 6 litres . therefore , volume of whole = ( . 002778 Γ— 6 ) β€Ή = β€Ί 2160 litres . answer d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "148 mins", "140 mins", "136 mins", "132 minw" ] }
[ "A" ]
one pipe can fill a tank three times as fast as another pipe . if together the two pipes can fill the tank in 37 minutes , then the slower pipe alone will be able to fill the tank in
"explanation : let the slower pipe alone fill the tank in x minutes then faster will fill in x / 3 minutes . part filled by slower pipe in 1 minute = 1 / x part filled by faster pipe in 1 minute = 3 / x part filled by both in 1 minute = 1 / x + 3 / x = 1 / 37 = > 4 / x = 1 / 37 x = 37 βˆ— 4 = 148 mins option a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "240 km", "120 km", "360 km", "180 km" ] }
[ "C" ]
a boat takes 38 hours for travelling downstream from point a to point b and coming back to point c midway between a and b . if the velocity of the stream is 4 kmph and the speed of the boat in still water is 14 kmph , what is the distance between a and b ?
"explanation : velocity of the stream = 4 kmph speed of the boat in still water is 14 kmph speed downstream = ( 14 + 4 ) = 18 kmph speed upstream = ( 14 - 4 ) = 10 kmph let the distance between a and b be x km time taken to travel downstream from a to b + time taken to travel upstream from b to c ( mid of a and b ) = 38 hours β‡’ x / 18 + ( x / 2 ) 10 = 38 β‡’ x / 18 + x / 20 = 38 β‡’ 19 x / 180 = 38 β‡’ x / 180 = 2 β‡’ x = 360 i . e . , the distance between a and b = 360 km . answer : option c"
MathQA
{ "label": [ "B", "C", "D", "E" ], "text": [ "1 hour 7 min", "1 hour 15 min", "1 hour 30 min", "1 hour 10 min" ] }
[ "B" ]
a boatman goes 3 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes . how long will it take to go 5 km in stationary water ?
"speed ( upstream ) = 3 / 1 = 3 kmhr speed ( downstream ) = 1 / ( 10 / 60 ) = 6 kmhr speed in still water = 1 / 2 ( 3 + 6 ) = 4.5 kmhr time taken in stationary = 5 / 4.5 = 1 hrs 7 min answer : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "81 mins", "64 mins", "52 mins", "40 mins" ] }
[ "D" ]
walking at 4 / 5 of his usual speed a man is 10 mins too late . find his usual time .
"speed = s , time = t , 4 / 5 s * ( t + 10 ) = st t = 40 answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1.2", "10.92", "12.98", "12.38" ] }
[ "B" ]
the simple interest on rs . 26 for 6 months at the rate of 7 paise per rupeeper month is
"sol . s . i . = rs . [ 26 * 7 / 100 * 6 ] = rs . 10.92 answer b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "10368", "10638", "10836", "10846" ] }
[ "A" ]
find the smallest number of five digits exactly divisible by 16 , 24,36 and 54 .
"smallest number of five digits is 10000 . required number must be divisible by l . c . m . of 16,24 , 36,54 i . e 432 , on dividing 10000 by 432 , we get 64 as remainder . therefore , required number = 10000 + ( 432 – 64 ) = 10368 . answer is a ."
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "βˆ’ 220", "βˆ’ 100", "100", "135" ] }
[ "B" ]
if the average ( arithmetic mean ) of a and b is 110 , and the average of b and c is 160 , what is the value of a βˆ’ c ?
"( a + b ) / 2 = 110 = = = > a + b = 220 ( b + c ) / 2 = 160 = = = > b + c = 320 ( a + b ) - ( b + c ) = 220 - 320 = = = > a + b - b - c = - 100 = = = > a - c = - 100 answer : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "40 m 3', '", "42 m 3', '", "44 m 3', '", "46 m 3', '" ] }
[ "C" ]
a circular well with a diameter of 2 meters , is dug to a depth of 14 meters . what is the volume of the earth dug out .
explanation : volume = Ο€ r 2 hvolume = ( 22 / 7 βˆ— 1 βˆ— 1 βˆ— 14 ) m 3 = 44 m 3 option c
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ ". 7", ". 07", ". 05", "0.07" ] }
[ "B" ]
what decimal fraction is 70 ml of a litre ?
"answer required fraction = 70 / 1000 = 7 / 100 = . 07 correct option : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "750', '", "850', '", "950', '", "1050', '" ] }
[ "A" ]
unit size cubes are stacked inside a big rectangular box having dimensions corresponding to three consecutive multiples of 5 . choose exact number of cubes that can completely fill the box .
let the dimensions of the box be , length = 5 * a , breadth = 5 * ( a + 1 ) , height = 5 * ( a + 2 ) hence , volume = 5 * 5 * 5 * a * ( a + 1 ) * ( a + 2 ) among any 3 consecutive positive integers , we will either have ( a number that is divisible by both 23 ) or ( a number divisible by 2 and another number divisible by 3 ) . volume = multiple of ( 125 * 2 * 3 ) 750 = 125 * 2 * 3 answer : a
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "8 / 15", "7 / 15", "1 / 15", "3 / 15" ] }
[ "A" ]
p is able to do a piece of work in 15 days and q can do the same work in 20 days . if they can work together for 4 days , what is the fraction of work left ?
explanation : p ' s 1 - day work = 1 / 15 q ' s 1 - day work = 1 / 20 work done by ( p + q ) in 1 day = 1 / 15 + 1 / 20 = 7 / 60 . work done by them in 4 days = ( 7 / 60 ) * 4 = 7 / 15 . work left = 1 - ( 7 / 15 ) = 8 / 15 . answer is a
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1.2 kg", "1.5 kg", "1.4 kg", "1.9 kg" ] }
[ "C" ]
when processing flower - nectar into honey bees ' extract , a considerable amount of water gets reduced . how much flower - nectar must be processed to yield 1 kg of honey , if nectar contains 50 % water , and the honey obtained from this nectar contains 30 % water ?
"explanation : flower - nectar contains 50 % of non - water part . in honey this non - water part constitutes 70 % ( 100 - 30 ) . therefore 0.5 x amount of flower - nectar = 0.70 x amount of honey = 0.70 x 1 kg therefore amount of flower - nectar needed = ( 0.70 / 0.51 ) kg = 1.4 kgs answer : c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "12", "15", "5", "9" ] }
[ "D" ]
solve for x and check : 6 x = 54
"solution : dividing each side by 6 , we obtain ( 6 x / 6 ) = ( 54 / 6 ) therefore : x = 9 check : 6 x = 54 ( 6 * 9 ) = 54 54 = 54 answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "2436", "2801", "- 2801", "- 1601" ] }
[ "D" ]
- 64 x 29 + 165 = ?
"given exp . = - 64 x ( 30 - 1 ) + 165 = - ( 64 x 30 ) + 64 + 165 = - 1830 + 229 = - 1601 answer is d"
MathQA
{ "label": [ "A", "B", "C", "E" ], "text": [ "9", "18", "17", "19" ] }
[ "E" ]
how many multiples of 5 are there between 5 to 105 ?
"explanation : as you know , multiples of 5 are integers having 0 or 5 in the digit to the extreme right ( i . e . the units place ) . so the numbers are 10 , 15 , 20 , 25 , 30 , 35 , 40 , 45 , 50 , 55 , 60 , 65 , 70 , 75 , 80 , 85 , 90 , 95 , 100 . answer : e"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "28000", "30000", "42000", "34000" ] }
[ "C" ]
a & b started a partnership business . a ' s investment was thrice the investment of b and the period of his investment was two times the period of investments of b . if b received rs 6000 as profit , what is their total profit ?
explanation : suppose b ' s investment = x . then a ' s investment = 3 x suppose bs period of investment = y , then a ' s period of investment = 2 y a : b = 3 x * 2 y : xy = 6 : 1 total profit * 1 / 7 = 6000 = > total profit = 6000 * 7 = 42000 . answer : option c
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "21.5", "10.6", "8", "9.5" ] }
[ "A" ]
the average of 5 quantities is 11 . the average of 3 of them is 4 . what is the average of remaining 2 numbers ?
"answer : a ( 5 x 11 - 3 x 4 ) / 2 = 21.5"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "35.5", "37.5", "38.5", "40.5" ] }
[ "C" ]
find the average of first 10 multiples of 7
"explanation : = 7 ( 1 + 2 + 3 + . . . + 10 ) 10 = 7 ( 10 ( 10 + 1 ) ) 10 Γ— 2 = 7 ( 110 ) 10 Γ— 2 = 38.5 answer : option c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "76 kg", "76.5 kg", "85 kg", "90 kg" ] }
[ "C" ]
the average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg . what might be the weight of the new person ?
"sol . total weight increased = ( 8 Γ— 2.5 ) kg = 20 kg . weight of new person = ( 65 + 20 ) kg = 85 kg . answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "148", "152", "156", "169" ] }
[ "D" ]
the ratio of ducks and frogs in a pond is 31 : 39 respectively . the average number of ducks and frogs in the pond is 152 . what is the number of frogs in the pond ?
"solution : ratio of ducks and frogs in pond , = 31 : 39 . average of ducks and frogs in pond , = 152 . so , total number of ducks and frogs in the pond , = 2 * 152 = 304 . therefore , number of frogs , = ( 304 * 39 ) / 70 = 169 . answer : option d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 1200", "rs . 1300", "rs . 1500", "rs . 3000" ] }
[ "D" ]
a man invests rs . 6,000 at the rate of 5 % per annum . how much more should he invest at the rate of 8 % , so that he can earn a total of 6 % per annum ?
"explanation : interest on rs . 6000 at 5 % per annum = ( 6000 Γ— 5 Γ— 1 ) / 100 = rs . 300 let his additional investment at 8 % = x interest on rs . x at 8 % per annum = ( x Γ— 8 Γ— 1 ) / 100 = 2 x / 25 . to earn 6 % per annum for the total , interest = ( 6000 + x ) Γ— 6 Γ— 1 / 100 . = > 300 + 2 x / 25 = ( 6000 + x ) Γ— 6 Γ— 1 / 100 . = > 30000 + 8 x = ( 6000 + x ) Γ— 6 . = > 30000 + 8 x = 36000 + 6 x . = > 2 x = 6000 . = > x = 3000 . answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "36", "39", "42", "44" ] }
[ "D" ]
a batsman makes a score of 92 runs in the 17 th inning and thus increases his average by 3 . find his average after 17 th inning .
"let the average after 17 th inning = x . then , average after 16 th inning = ( x – 3 ) . ∴ 16 ( x – 3 ) + 92 = 17 x or x = ( 92 – 48 ) = 44 . answer d"
MathQA
{ "label": [ "B", "C", "D", "E" ], "text": [ "0.02", "0.002", "0.0002", "2" ] }
[ "C" ]
0.004 Γ— 0.5 = ?
"explanation : 0.004 Γ— 0.5 = 0.002 . answer : option c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 880", "rs . 890", "rs . 1800", "rs . 900" ] }
[ "C" ]
if the compound interest on a certain sum of money for 6 years at 10 % per annum be rs . 993 , what would be the simple interest ?
"let p = principal a - amount we have a = p ( 1 + r / 100 ) 3 and ci = a - p atq 993 = p ( 1 + r / 100 ) 3 - p ? p = 3000 / - now si @ 10 % on 3000 / - for 6 yrs = ( 3000 x 10 x 6 ) / 100 = 1800 / - answer : c ."
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "2736", "2309", "- 2801", "- 2241" ] }
[ "D" ]
- 69 * 39 + 450 = ?
"= > - 69 * ( 40 - 1 ) + 450 ; = > - ( 69 * 40 ) + 69 + 450 ; = > - 2760 + 519 = - 2241 . correct option : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "22.4 %", "50 %", "25 %", "52 %" ] }
[ "A" ]
a retailer buys a radio for rs 225 . his overhead expenses are rs 20 . he sellis the radio for rs 300 . the profit percent of the retailer is
"explanation : cost price = ( 225 + 20 ) = 245 sell price = 300 gain = ( 55 / 245 ) * 100 = 22.4 % . answer : a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "100 m", "125 m", "130 m", "150 m" ] }
[ "D" ]
a train speeds past a pole in 15 seconds and a platfrom 100 m long in 25 seconds . its length is :
"sol . let the length of the train be x metres and its speed be y m / sec . they , x / y = 15 β‡’ y = x / 15 ∴ x + 100 / 25 = x / 15 ⇔ x = 150 m . answer d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "38.5", "37.5", "37.0", "36.5" ] }
[ "B" ]
the average of 50 numbers is 38 . if two numbers 45 and 55 are discarded , the average of the remaining set of numbers is
average of the remaining set of numbers [ 50 x 38 - ( 45 + 55 ) ] / ( 50 - 2 ) = ( 1900 - 100 ) / 48 = 37.5 answer : b
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "16.7 %", "20 %", "24.67 %", "33.33 %" ] }
[ "A" ]
if the price of petrol increases by 20 , by how much must a user cut down his consumption so that his expenditure on petrol remains constant ?
"explanation : let us assume before increase the petrol will be rs . 100 . after increase it will be rs ( 100 + 20 ) i . e 120 . now , his consumption should be reduced to : - = ( 120 βˆ’ 100 ) / 120 βˆ— 100 . hence , the consumption should be reduced to 16.7 % . answer : a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "15 mins", "20 mins", "25 mins", "30 mins" ] }
[ "D" ]
a tank can be filled by two pipes a and b in 60 minutes and 40 minutes respectively . how many minutes will it take to fill the tank from empty state if b is used for the first half time and then a and b fill it together for the other half
"explanation : let the total time be x mins . part filled in first half means in x / 2 = 1 / 40 part filled in second half means in x / 2 = 1 / 60 + 1 / 40 = 1 / 24 total = x / 2 βˆ— 1 / 40 + x / 2 βˆ— 1 / 24 = 1 = > x / 2 ( 1 / 40 + 1 / 24 ) = 1 = > x / 2 βˆ— 1 / 15 = 1 = > x = 30 mins option d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "35.2 m 2", "44 m 2", "48 m 2", "36 m 2" ] }
[ "A" ]
the diameter of a garden roller is 1.4 m and it is 2 m long . how much area will it cover in 4 revolutions ? ( use Γ― € = 22 Γ’  β€ž 7 )
"required area covered in 5 revolutions = 4 Γ£ β€” 2 Γ― € rh = 4 Γ£ β€” 2 Γ£ β€” 22 Γ’  β€ž 7 Γ£ β€” 0.7 Γ£ β€” 2 = 35.2 m 2 answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "50.9", "52.9", "51.9", "53.25" ] }
[ "C" ]
a school has 4 section of chemistry in class x having 70 , 35 , 45 and 42 students . the mean marks obtained in chemistry test are 50 , 60 , 55 and 45 respectively for the 4 sections . determine the overall average of marks per student .
"required average marks = 70 Γ£ β€” 50 + 35 Γ£ β€” 60 + 45 Γ£ β€” 55 + 42 Γ£ β€” 45 / 70 + 35 + 45 + 42 = 3500 + 2100 + 2475 + 1890 / 192 = 9965 Γ’  β€ž 192 = 51.90 answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "16060", "14000", "18000", "12000" ] }
[ "D" ]
ashok borrowed some money at the rate of 6 % p . a . for the first two years , at the rate of 9 % p . a . for the next 3 years and at the rate of 14 % p . a . for the period beyond 5 years . if he pays a total interest of 11400 / - at the end of 9 years , how much money did he borrow ?
we have , si = p Γ— r Γ— t / 100 ∴ 11400 = p Γ— 6 Γ— 2 / 100 + p Γ— 9 Γ— 3 / 100 + p Γ— 14 Γ— 4 / 100 or , 12 p + 27 p + 56 p = 11400 Γ— 100 or , 95 p = 11400 Γ— 100 ∴ p = 12000 answer d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 147.50", "rs . 785.50", "rs . 178.50", "rs . 258.50" ] }
[ "C" ]
teas worth rs . 126 per kg and rs . 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2 . if the mixture is worth rs 156 per kg , the price of the third variety per kg will be ?
"explanation : since first and second varieties are mixed in equal proportions . so , their average price = rs . ( 126 + 135 ) / 2 . = > rs . 130.50 . so , the mixture is formed by mixing two varieties , one at rs . 130.50 per kg and the other at say , rs . x per kg in the ratio 2 : 2 , i . e . , 1 : 1 . we have to find x . by the rule of alligation , we have : cost of 1 kg cost of 1 kg of 1 st kind of 2 nd kind ( rs . 130.50 ) ( rs . x ) \ / mean price ( rs . 156 ) / \ x Γ’ Λ† ’ 156 22.50 = > x Γ’ Λ† ’ ( 156 / 22.50 ) = 1 . = > x Γ’ Λ† ’ 156 = 22.50 . = > x = 178.50 rs . answer : c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1 : 1", "3 : 2", "4 : 3", "5 : 3" ] }
[ "A" ]
in what ratio must tea at rs . 64 per kg be mixed with tea at rs . 74 per kg so that the mixture must be worth rs . 69 per kg ?
"required ratio = 500 : 500 = 1 : 1 answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "724", "804", "814", "9000" ] }
[ "D" ]
what is the least number of square tiles required to pave the floor of a room 50 m 00 cm long and 11 m 25 cm broad ?
solution length of largest tile = h . c . f . of 5000 cm & 1125 cm = 25 cm . area of each tile = ( 25 x 25 ) cm 2 ∴ required number of tiles = [ 5000 x 1125 / 25 x 25 ] = 9000 . answer d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "648", "1800", "2700", "2160" ] }
[ "D" ]
running at the same constant rate , 6 identical machines can produce a total of 270 bottles per minute . at this rate , how many bottles could 12 such machines produce in 4 minutes ?
"solution let the required number of bottles be x . more machines , more bottles ( direct proportion ) more minutes , more bottles ( direct proportion ) Γ’ Λ† Β΄ 6 Γ£ β€” 1 Γ£ β€” x = 12 Γ£ β€” 4 Γ£ β€” 270 Γ’ ‑ ” x = 12 x 4 x 270 / 6 = 2160 . answer d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "21 : 23", "23 : 45", "22 : 7", "25 : 29" ] }
[ "C" ]
x starts a business with rs . 77000 . y joins in the business after 5 months with rs . 42000 . what will be the ratio in which they should share the profit at the end of the year ?
"explanation : ratio in which they should share the profit = ratio of the investments multiplied by the time period = 77000 * 12 : 42000 * 7 = 77 * 12 : 42 * 7 = 11 * 2 : 7 = 22 : 7 . answer : option c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "9 km", "72.5 km", "190.75 km", "885.5 km" ] }
[ "D" ]
on a scale of map , 0.6 cm represent 6.6 km . if the distance between the points on the map is 80.5 cm , the actual distance between these points is :
solution let the actual distance be x km . then , more distance on the map , more is the actual distance ( direct proportion ) ∴ 0.6 : 80.5 : : 6.6 : x ⇔ 0.6 x = 80.5 Γ— 6.6 ⇔ x = ⇔ x = 80.5 x 6.6 / 0.6 = x = 885.5 . answer d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "$ 60", "$ 64", "$ 80", "$ 96" ] }
[ "C" ]
if greg buys 3 shirts , 6 trousers and 4 ties , the total cost is $ 80 . if greg buys 7 shirts , 2 trousers and 4 ties , the total cost is $ 80 . how much will it cost him to buy 5 trousers , 4 shirts and 4 ties ?
"solution : 3 x + 6 y + 4 z = 80 7 x + 2 y + 4 z = 80 adding both the equations = 10 x + 8 y + 8 z = 160 5 x + 4 y + 4 z = 80 ans c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "6800", "5800", "4800", "6500" ] }
[ "A" ]
a is a working partner and b is a sleeping partner in a business . a puts in 60,000 and b 40,000 . a gets 20 % of the profit for managing the business , and the rest is divided in proportion to their capitals . find the share of a in profit of 10000 .
"the amount a gets for managing = 20 % of rs . 10000 = 2000 remaining profit = 10000 – 2000 = 8000 this is to be divided in the ratio 3 : 2 . share of a = 3 / 5 of 8000 = 4800 β‡’ total share of a = 4800 + 2000 = 6800 . answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "40 m 2", "44 m 2", "48 m 2", "36 m 2" ] }
[ "B" ]
the diameter of a garden roller is 1.4 m and it is 2 m long . how much area will it cover in 5 revolutions ? ( use Ο€ = 22 ⁄ 7 )
"required area covered in 5 revolutions = 5 Γ— 2 Ο€ rh = 5 Γ— 2 Γ— 22 ⁄ 7 Γ— 0.7 Γ— 2 = 44 m 2 answer b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "2", "4", "5", "6" ] }
[ "A" ]
in a coconut grove , ( x + 1 ) trees yield 60 nuts per year , x trees yield 120 nuts per year and ( x – 1 ) trees yield 180 nuts per year . if the average yield per year per tree be 100 , find x .
"( x + 1 ) Γ— 60 + x Γ— 120 + ( x βˆ’ 1 ) Γ— 180 / ( x + 1 ) + x + ( x βˆ’ 1 ) = 100 β‡’ 360 x βˆ’ 120 / 3 x = 100 β‡’ 60 x = 120 β‡’ x = 2 answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "858", "859", "869", "4320" ] }
[ "A" ]
the least number which when increased by 6 each divisible by each one of 24 , 32 , 36 and 54 is :
"solution required number = ( l . c . m . of 24 , 32 , 36 , 54 ) - 5 = 864 - 6 = 858 . answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "91", "10", "1001", "1911" ] }
[ "B" ]
the maximum number of students among them 1230 pens and 920 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is :
"explanation : required number of students = h . c . f of 1230 and 920 = 10 . answer : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "29.2 %", "12.5 %", "13 %", "11.3 %" ] }
[ "A" ]
what percent of a day is 7 hours ?
explanation : solution : required percentage = ( 7 / 100 * 24 ) = 29.2 % answer : a
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "10 %", "45.8 %", "25 %", "52 %" ] }
[ "B" ]
a retailer buys a radio for rs 225 . his overhead expenses are rs 15 . he sellis the radio for rs 350 . the profit percent of the retailer is
"explanation : cost price = ( 225 + 15 ) = 240 sell price = 350 gain = ( 110 / 240 ) * 100 = 45.8 % . answer : b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "100", "110", "120", "130" ] }
[ "C" ]
if 80 lamps can be lighted 5 hours per day for 10 days for rs . 21.25 , then the number of lamps which can be lighted 4 hours daily for 30 days for rs . 76.50 , is ?
explanation : ( hrs / day 4 : 5 ) : ( money 21.25 : 76.50 ) : ( days 30 : 10 ) : : 80 : x 4 * 21.25 * 30 * x = 5 * 76.50 * 10 * 80 so x = 120 answer : c
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1 : 2", "3 : 4", "2 : 3", "3 : 2" ] }
[ "C" ]
the average age of a class is 15.8 years . the average age of the boys in the class is 16.4 years and that of the girls is 15.4 years . what is the ratio of boys to girls in the class ?
"let number of boys = x ; let number of girls = y total numbers of students = x + y ( x + y ) Γ— 15.8 = 16.4 x + 15.4 y 0.6 x = 0.4 y x / y = 0.4 / 0.6 = 2 / 3 answer : c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "2", "20", "0.2", "0.02" ] }
[ "D" ]
0.0006 ? = 0.03
"explanation : required answer = 0.0006 / 0.03 = 0.06 / 3 = 0.02 . answer : option d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1964", "1984", "2964", "2984" ] }
[ "D" ]
3034 βˆ’ ( 1002 Γ· 20.04 ) = ?
"explanation : = 3034 βˆ’ ( 1002 / 2004 Γ— 100 ) = 3034 βˆ’ 50 = 2984 option d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs 108000", "rs 144000", "rs 132000", "rs 152400" ] }
[ "D" ]
two persons raj and ramu started working for a company in similar jobs on january 1 , 1991 . raj ' s initial monthly salary was rs 400 , which increases by rs 40 after every year . ramu ' s initial monthly salary was rs 500 which increases by rs 20 after every 6 months . if these arrangements continue till december 31 , 200 . find the total salary they received during that period .
explanation : raj ' s salary as on 1 jan 1991 is rs 400 per month . his increment in his month salary is rs 40 per annum his total salary from 1 jan 1991 to 31 st dec 2000 i . e . in ten years = > 12 [ 2 ( 400 ) + ( 10 βˆ’ 1 ) 40 ] Γ— 10 / 2 . = > rs 69600 . ramu ' s salary as on jan 1 st 1991 is rs 550 and his half yearly increment in his month salary is rs 20 . his total salary from 1 jan 1991 to dec 31 , 2000 = > 6 [ 2 ( 500 ) + ( 20 βˆ’ 1 ) 20 ] Γ— 20 / 2 . = > rs 82000 . total salary of raj and ramu in the ten year period : = > rs . 69600 + rs . 82800 . = > rs 1 , 52400 . answer : d
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "6999.2", "6876.1", "6654", "7000" ] }
[ "B" ]
shanmukham buys good worth rs . 6650 . he gets a rebate of 6 % on it . after getting the rebate , he pays sales tax @ 10 % . find the amount he will have to pay for the goods
explanation : rebate = 6 % of rs . 6650 = rs . 6 / 100 x 6650 = rs . 399 . sales tax = 10 % of rs . ( 6650 399 ) = rs . 10 / 100 x 6251 = rs . 625.10 final amount = rs . ( 6251 + 625.10 ) = rs . 6876.10 answer : b
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "71", "910", "1001", "1911" ] }
[ "A" ]
the maximum numbers of students among them 781 pens and 710 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is
"olution required number of students . = h . c . f of 781 and 710 . Γ’ € ΒΉ = Γ’ € ΒΊ 71 . answer a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "4.37 %", "5.8 %", "6.8 %", "8.75 %" ] }
[ "B" ]
the population of a town increased from 1 , 45,000 to 2 , 30,500 in a decade . the average percent increase of population per year is :
"explanation : increase in 10 years = ( 230500 - 145000 ) = 85500 . increase % = ( 85500 / 145000 x 100 ) % = 58 % . required average = ( 58 / 10 ) % = 5.8 % . answer : option b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 1200", "rs . 1300", "rs . 1500", "rs . 2000" ] }
[ "D" ]
a man invests rs . 4,000 at the rate of 5 % per annum . how much more should he invest at the rate of 8 % , so that he can earn a total of 6 % per annum ?
"explanation : interest on rs . 4000 at 5 % per annum = ( 4000 Γ— 5 Γ— 1 ) / 100 = rs . 200 let his additional investment at 8 % = x interest on rs . x at 8 % per annum = ( x Γ— 8 Γ— 1 ) / 100 = 2 x / 25 . to earn 6 % per annum for the total , interest = ( 4000 + x ) Γ— 6 Γ— 1 / 100 . = > 200 + 2 x / 25 = ( 4000 + x ) Γ— 6 Γ— 1 / 100 . = > 20000 + 8 x = ( 4000 + x ) Γ— 6 . = > 20000 + 8 x = 24000 + 6 x . = > 2 x = 4000 . = > x = 2000 . answer : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1240", "1120", "1190", "1290" ] }
[ "D" ]
the banker ' s gain on a sum due 6 years hence at 12 % per annum is rs . 540 . what is the banker ' s discount ?
"explanation : td = ( bg Γ— 100 ) / tr = ( 540 Γ— 100 ) / ( 6 Γ— 12 ) = ( 90 Γ— 100 ) / 12 = ( 15 Γ— 100 ) 2 / = rs . 750 bg = bd – td = > 540 = bd - 750 = > bd = 540 + 750 = 1290 answer : option d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "40", "50", "54", "60" ] }
[ "D" ]
a and b can together finish a work in 30 days . they worked together for 20 days and then b left . after another 20 days , a finished the remaining work . in how many days a alone can finish the job ?
"( a + b ) ' s 20 days work = ( 1 / 30 * 20 ) = 2 / 3 . remaining work = ( 1 - 2 / 3 ) = 1 / 3 . now , 1 / 3 work is done by a in 20 days . whole work will be done by a in ( 20 * 3 ) = 60 days . correct option : d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "65", "69", "74", "75" ] }
[ "C" ]
kamal obtained 76 , 60 , 82 , 67 and 85 marks ( out of 100 ) in english , mathematics , physics , chemistry and biology . what are his average marks ?
"sol . average = 76 + 60 + 82 + 67 + 85 / 5 ) = ( 375 / 5 ) = 74 . answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "12.5 %", "20 %", "25 %", "50 %" ] }
[ "A" ]
ritesh and co . generated revenue of rs . 2,500 in 2006 . this was 12.5 % of its gross revenue . in 2007 , the gross revenue grew by rs . 2,500 . what is the percentage increase in the revenue in 2007 ?
"explanation : given , ritesh and co . generated revenue of rs . 2,500 in 2006 and that this was 12.5 % of the gross revenue . hence , if 2500 is 12.5 % of the revenue , then 100 % ( gross revenue ) is : = > ( 100 / 12.5 ) Γ— 2500 . = > 20,000 . hence , the total revenue by end of 2007 is rs . 10,000 . in 2006 , revenue grew by rs . 2500 . this is a growth of : = > ( 2500 / 20000 ) Γ— 100 . = > 12.5 % . answer : a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "1680579288", "1223441288", "2142579288", "2142339288" ] }
[ "A" ]
( 23341379 x 72 ) = ?
"explanation : 23341379 x 72 = 23341379 ( 70 + 2 ) = ( 23341379 x 70 ) + ( 23341379 x 2 ) = 1633896530 + 46682758 = 1680579288 . answer : option a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "25 %", "50 %", "100 %", "150 %" ] }
[ "C" ]
the cost price of an article is 25 % of the marked price . calculate the gain percent after allowing a discount of 50 % .
"sol . let marked price = rs . 100 . then , c . p . = rs . 25 . s . p = rs . 50 . Γ’ Λ† Β΄ gain % = [ 25 / 25 * 100 ] % = 100.0 % . answer c"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "rs . 200", "rs . 720", "rs . 300", "rs . 150" ] }
[ "B" ]
the cost of 3 pens and 5 pencils is rs . 240 . also the cost of one pen and one pencil is in the ratio of 5 : 1 respectively . what is the cost of one dozen pens ?
"explanation : let the cost of one pen is β€˜ 5 x ’ and pencil is β€˜ x ’ 3 x 5 x + 5 x = rs . 240 15 x + 5 x = rs . 240 x = 240 / 20 = 12 : . cost of 1 pen = 5 x = 5 x 12 = 60 : . cost of 12 pens , i . e . ( one dozen ) = 60 x 12 = rs . 720 answer : option b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "4830", "5120", "6420", "8960" ] }
[ "B" ]
a metallic sheet is of rectangular shape with dimensions 48 m x 36 m . from each of its corners , a square is cut off so as to make an open box . if the length of the square is 8 m , the volume of the box ( in m 3 ) is :
"explanation clearly , l = ( 48 – 16 ) m = 32 m , b = ( 36 - 16 ) m = 20 m , h = 8 m . volume of the box = ( 32 x 20 x 8 ) m 3 = 5120 m 3 . answer b"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "5.1", "4.1", "3.1", "2.1" ] }
[ "A" ]
what is 15 percent of 34
"explanation : it will be 15 % of 34 = ( 15 / 100 ) * 34 = 5.10 answer : option a"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "75142", "64851", "5149", "69993" ] }
[ "D" ]
the difference between the local value and the face value of 7 in the numeral 32675149 is ?
"( local value of 7 ) - ( face value of 7 ) = ( 70000 - 7 ) = 69993 d )"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "30 %", "47 %", "90 %", "100 %" ] }
[ "B" ]
in a restaurant , the profit is 110 % of the cost . if the cost increases by 12 % but the selling price remains constant , approximately what percentage of the selling price is the profit ?
explanation : let c . p . = rs . 100 . then , profit = rs . 110 , s . p . = rs . 210 . new c . p . = 112 % of rs . 100 = rs . 112 new s . p . = rs . 210 . profit = rs . ( 210 - 112 ) = rs . 98 . required percentage = ( 98 / 210 * 100 ) % = 47 % appox answer : b
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "151", "149", "152", "251" ] }
[ "D" ]
the mean of 30 values was 250 . it was detected on rechecking that one value 165 was wrongly copied as 135 for the computation of the mean . find the correct mean .
"corrected mean = 250 Γ— 30 βˆ’ 135 + 165 / 30 = 7500 βˆ’ 135 + 165 / 30 = 7530 / 30 = 251 answer d"
MathQA
{ "label": [ "A", "B", "C", "D" ], "text": [ "150", "155", "160", "165" ] }
[ "A" ]
if 31 % of a number is 46.5 , the number is ?
"answer let 31 % of a = 46.5 β‡’ ( 31 x a ) / 100 = 46.5 ∴ a = ( 46.5 x 100 ) / 31 = 150 correct option : a"
MathQA