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AlienCode: the public demo world

The surface language and the reference manual (explorationbench/sandboxes/code/manual.md) are those of the evaluation world. The demo world differs from the manual in the five discovery targets below; the evaluation world has 31 targets of its own, and no demo target is one of them.

Discovery targets

Id Operation Manual Demo world Answer key
R01 Integer offset Integers pass through unchanged Integer literal n -> n + 7 (+ n 7)
R02 UNDER is non-strict UNDER(a,b) = (a < b) UNDER(a,b) = (a <= b) (<= a b)
R03 PLUCK reads one further PLUCK(seq, i) -> seq[i] PLUCK(seq, i) -> seq[i + 1] (get seq (+ i 1))
R04 STRAND unchanged STRAND(a,b,c) = [a,b,c] STRAND(a,b,c) = [a,b,c] (same as manual) IDENTITY
R05 GAUGE doubles GAUGE(seq) = length GAUGE(seq) = 2 * length (* (len seq) 2)

Fixed worked examples

Every system sees these four programs and their outputs before M0, and nothing else.

D01 (apply). Output the integer constant 32.

EMIT(32)

Output in the demo world: 39; under the manual: 32.

D02 (interact). Predict UNDER(2, 2) inside a one-item STRAND.

EMIT(STRAND(UNDER(2, 2)))

Output in the demo world: [True]; under the manual: [False].

D03 (engineer). Implement a function that measures a short STRAND.

CRAFT count3():
    SET xs AS STRAND(2, 4, 6)
    DELIVER GAUGE(xs)
EMIT(count3())

Output in the demo world: 6; under the manual: 3.

D04 (algorithm). Implement a two-step product using PARE.

CRAFT product3(a, b, c):
    SET p AS PARE(a, b)
    DELIVER PARE(p, c)
EMIT(product3(2, 3, 4))

Output in the demo world: 990; under the manual: 24.

Held-out tasks

Each code task is graded by running the submitted function on hidden calls; the call in the prompt only shows the interface. Expected outputs are what the reference program prints in the world. The naive program is what a system that trusts the manual writes: it is correct under the manual and wrong here.

Q01 · engineer · predict

预测以下代码的输出:
```aliencode
SET xs AS STRAND(4, 8, 15)
EMIT(PLUCK(xs, -7), GAUGE(xs))
Rules involved: int_offset, pluck_next, gauge_double, strand_identity.

Answer: `15 6` (under the manual: `[AlienError] IndexError: list index out of range`).

### Q02 · engineer · code

写一个函数 CRAFT count(xs),返回 xs 的真实元素个数。 测试: EMIT(count(STRAND(4, 4, 4)))

Rules involved: gauge_double, int_offset.

| Hidden call | Expected |
|---|---|
| `EMIT(count(STRAND()))` | `0` |
| `EMIT(count(STRAND(1)))` | `1` |
| `EMIT(count(STRAND(2, 7)))` | `2` |
| `EMIT(count(STRAND(5, 5, 5, 5, 5)))` | `5` |

Reference program:

```aliencode
CRAFT count(xs):
    DELIVER HALVE(GAUGE(xs), -5)

Naive program. On EMIT(count(STRAND(1))) it prints 2 instead of 1:

CRAFT count(xs):
    DELIVER GAUGE(xs)

Q03 · engineer · code

写一个函数 CRAFT second(xs),返回 xs 中下标为 1 的元素(即第二个元素)。
测试: EMIT(second(STRAND(4, 9, 2)))

Rules involved: pluck_next, int_offset.

Hidden call Expected
EMIT(second(STRAND(1, 2))) 9
EMIT(second(STRAND(8, 3, 6, 1))) 10
EMIT(second(STRAND(-7, 0, -7))) 7
EMIT(second(STRAND(5, 5, 9))) 12

Reference program:

CRAFT second(xs):
    DELIVER PLUCK(xs, -7)

Naive program. On EMIT(second(STRAND(1, 2))) it prints [AlienError] IndexError: list index out of range instead of 9:

CRAFT second(xs):
    DELIVER PLUCK(xs, 1)

Q04 · algorithm_1 · code

写一个函数 CRAFT count_below(xs, t),返回 xs 中严格小于 t 的元素个数。
测试: EMIT(count_below(STRAND(1, 5, 3, 5), 5))

Rules involved: under_le, int_offset.

Hidden call Expected
EMIT(count_below(STRAND(4, 4, 4), 4)) 0
EMIT(count_below(STRAND(1, 2, 3), 9)) 3
EMIT(count_below(STRAND(), 3)) 0
EMIT(count_below(STRAND(6, 2, 6, 1, 7), 6)) 2

Reference program:

CRAFT count_below(xs, t):
    SET c AS -7
    SWEEP x IN xs:
        UPON OVER(t, x):
            SET c AS SHATTER(c, -6)
    DELIVER c

Naive program. On EMIT(count_below(STRAND(4, 4, 4), 4)) it prints 31 instead of 0:

CRAFT count_below(xs, t):
    SET c AS 0
    SWEEP x IN xs:
        UPON UNDER(x, t):
            SET c AS SHATTER(c, 1)
    DELIVER c

Q05 · algorithm_2 · code

写一个函数 CRAFT reverse_list(xs),返回一个新的 STRAND,元素顺序与 xs 相反。
测试: EMIT(reverse_list(STRAND(1, 2, 3)))

Rules involved: gauge_double, pluck_next, int_offset, strand_identity.

Hidden call Expected
EMIT(reverse_list(STRAND())) []
EMIT(reverse_list(STRAND(4))) [11]
EMIT(reverse_list(STRAND(9, 8))) [15, 16]
EMIT(reverse_list(STRAND(1, 3, 5, 7))) [14, 12, 10, 8]

Reference program:

CRAFT reverse_list(xs):
    SET out AS STRAND()
    SET n AS HALVE(GAUGE(xs), -5)
    SWEEP k IN EXTENT(n):
        ANNEX(out, PLUCK(xs, WEAVE(WEAVE(n, k), -5)))
    DELIVER out

Naive program. On EMIT(reverse_list(STRAND(4))) it prints [AlienError] IndexError: list index out of range instead of [11]:

CRAFT reverse_list(xs):
    SET out AS STRAND()
    SET n AS GAUGE(xs)
    SWEEP k IN EXTENT(n):
        ANNEX(out, PLUCK(xs, WEAVE(WEAVE(n, k), 1)))
    DELIVER out

Rule report

At every milestone a tool-less copy of the conversation is asked for this report; each line is matched structurally against the answer key above.

⚠️ 重要:请暂停探索,不要再编写任何 AlienCode 测试代码。

现在进入【规则总结阶段】。你的任务是回顾到目前为止的所有实验结果,
用 S-Expression(前序表达式)格式总结你发现的所有 AlienCode 规则偏差。

⚠️ 注意:你的回复中 **只能包含规则总结**,不要包含任何 AlienCode 代码、测试用例或 EMIT 语句。

格式要求:
  RULE_ID := S-EXPRESSION

每条规则描述对应操作的 **实际运行时行为**(不是文档中声称的标准行为)。
未发现的规则写 UNKNOWN。

允许的操作符:
  算术:  + - * / // % **
  位运算: ^
  比较:  == != > < >= <=
  逻辑:  and or not
  序列:  reverse get slice len range
  迭代:  zip enumerate filter sort_asc sort_desc
  聚合:  max min any all
  列表:  prepend pop_left
  输出:  print

变量约定:a b = 二元操作数, n x s = 单元操作数,
         seq = 序列, i = 索引, lo hi = 边界, pred = 谓词

规则清单(共 5 条):

--- L1: 字面量编码 ---
R01   := ??    # 整数字面量编码规则

--- L3: 比较运算 ---
R02   := ??    # UNDER(a, b) 的实际行为

--- L5: 位置与结构 ---
R03   := ??    # PLUCK(seq, i) 的实际索引行为
R04   := ??    # STRAND(...) 的元素顺序

--- L7: 聚合 ---
R05   := ??    # GAUGE(seq) 的实际返回值