ExplorationBench / examples /aliencode.md
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# AlienCode: the public demo world
The surface language and the reference manual (`explorationbench/sandboxes/code/manual.md`) are those of the evaluation world. The demo world differs from the manual in the five discovery targets below; the evaluation world has 31 targets of its own, and no demo target is one of them.
## Discovery targets
| Id | Operation | Manual | Demo world | Answer key |
|---|---|---|---|---|
| R01 | Integer offset | Integers pass through unchanged | Integer literal n -> n + 7 | `(+ n 7)` |
| R02 | UNDER is non-strict | UNDER(a,b) = (a < b) | UNDER(a,b) = (a <= b) | `(<= a b)` |
| R03 | PLUCK reads one further | PLUCK(seq, i) -> seq[i] | PLUCK(seq, i) -> seq[i + 1] | `(get seq (+ i 1))` |
| R04 | STRAND unchanged | STRAND(a,b,c) = [a,b,c] | STRAND(a,b,c) = [a,b,c] (same as manual) | `IDENTITY` |
| R05 | GAUGE doubles | GAUGE(seq) = length | GAUGE(seq) = 2 * length | `(* (len seq) 2)` |
## Fixed worked examples
Every system sees these four programs and their outputs before M0, and nothing else.
**D01 (apply).** Output the integer constant 32.
```aliencode
EMIT(32)
```
Output in the demo world: `39`; under the manual: `32`.
**D02 (interact).** Predict UNDER(2, 2) inside a one-item STRAND.
```aliencode
EMIT(STRAND(UNDER(2, 2)))
```
Output in the demo world: `[True]`; under the manual: `[False]`.
**D03 (engineer).** Implement a function that measures a short STRAND.
```aliencode
CRAFT count3():
SET xs AS STRAND(2, 4, 6)
DELIVER GAUGE(xs)
EMIT(count3())
```
Output in the demo world: `6`; under the manual: `3`.
**D04 (algorithm).** Implement a two-step product using PARE.
```aliencode
CRAFT product3(a, b, c):
SET p AS PARE(a, b)
DELIVER PARE(p, c)
EMIT(product3(2, 3, 4))
```
Output in the demo world: `990`; under the manual: `24`.
## Held-out tasks
Each code task is graded by running the submitted function on hidden calls; the call in the prompt only shows the interface. Expected outputs are what the reference program prints in the world. The naive program is what a system that trusts the manual writes: it is correct under the manual and wrong here.
### Q01 · engineer · predict
```
预测以下代码的输出:
```aliencode
SET xs AS STRAND(4, 8, 15)
EMIT(PLUCK(xs, -7), GAUGE(xs))
```
```
Rules involved: int_offset, pluck_next, gauge_double, strand_identity.
Answer: `15 6` (under the manual: `[AlienError] IndexError: list index out of range`).
### Q02 · engineer · code
```
写一个函数 CRAFT count(xs),返回 xs 的真实元素个数。
测试: EMIT(count(STRAND(4, 4, 4)))
```
Rules involved: gauge_double, int_offset.
| Hidden call | Expected |
|---|---|
| `EMIT(count(STRAND()))` | `0` |
| `EMIT(count(STRAND(1)))` | `1` |
| `EMIT(count(STRAND(2, 7)))` | `2` |
| `EMIT(count(STRAND(5, 5, 5, 5, 5)))` | `5` |
Reference program:
```aliencode
CRAFT count(xs):
DELIVER HALVE(GAUGE(xs), -5)
```
Naive program. On `EMIT(count(STRAND(1)))` it prints `2` instead of `1`:
```aliencode
CRAFT count(xs):
DELIVER GAUGE(xs)
```
### Q03 · engineer · code
```
写一个函数 CRAFT second(xs),返回 xs 中下标为 1 的元素(即第二个元素)。
测试: EMIT(second(STRAND(4, 9, 2)))
```
Rules involved: pluck_next, int_offset.
| Hidden call | Expected |
|---|---|
| `EMIT(second(STRAND(1, 2)))` | `9` |
| `EMIT(second(STRAND(8, 3, 6, 1)))` | `10` |
| `EMIT(second(STRAND(-7, 0, -7)))` | `7` |
| `EMIT(second(STRAND(5, 5, 9)))` | `12` |
Reference program:
```aliencode
CRAFT second(xs):
DELIVER PLUCK(xs, -7)
```
Naive program. On `EMIT(second(STRAND(1, 2)))` it prints `[AlienError] IndexError: list index out of range` instead of `9`:
```aliencode
CRAFT second(xs):
DELIVER PLUCK(xs, 1)
```
### Q04 · algorithm_1 · code
```
写一个函数 CRAFT count_below(xs, t),返回 xs 中严格小于 t 的元素个数。
测试: EMIT(count_below(STRAND(1, 5, 3, 5), 5))
```
Rules involved: under_le, int_offset.
| Hidden call | Expected |
|---|---|
| `EMIT(count_below(STRAND(4, 4, 4), 4))` | `0` |
| `EMIT(count_below(STRAND(1, 2, 3), 9))` | `3` |
| `EMIT(count_below(STRAND(), 3))` | `0` |
| `EMIT(count_below(STRAND(6, 2, 6, 1, 7), 6))` | `2` |
Reference program:
```aliencode
CRAFT count_below(xs, t):
SET c AS -7
SWEEP x IN xs:
UPON OVER(t, x):
SET c AS SHATTER(c, -6)
DELIVER c
```
Naive program. On `EMIT(count_below(STRAND(4, 4, 4), 4))` it prints `31` instead of `0`:
```aliencode
CRAFT count_below(xs, t):
SET c AS 0
SWEEP x IN xs:
UPON UNDER(x, t):
SET c AS SHATTER(c, 1)
DELIVER c
```
### Q05 · algorithm_2 · code
```
写一个函数 CRAFT reverse_list(xs),返回一个新的 STRAND,元素顺序与 xs 相反。
测试: EMIT(reverse_list(STRAND(1, 2, 3)))
```
Rules involved: gauge_double, pluck_next, int_offset, strand_identity.
| Hidden call | Expected |
|---|---|
| `EMIT(reverse_list(STRAND()))` | `[]` |
| `EMIT(reverse_list(STRAND(4)))` | `[11]` |
| `EMIT(reverse_list(STRAND(9, 8)))` | `[15, 16]` |
| `EMIT(reverse_list(STRAND(1, 3, 5, 7)))` | `[14, 12, 10, 8]` |
Reference program:
```aliencode
CRAFT reverse_list(xs):
SET out AS STRAND()
SET n AS HALVE(GAUGE(xs), -5)
SWEEP k IN EXTENT(n):
ANNEX(out, PLUCK(xs, WEAVE(WEAVE(n, k), -5)))
DELIVER out
```
Naive program. On `EMIT(reverse_list(STRAND(4)))` it prints `[AlienError] IndexError: list index out of range` instead of `[11]`:
```aliencode
CRAFT reverse_list(xs):
SET out AS STRAND()
SET n AS GAUGE(xs)
SWEEP k IN EXTENT(n):
ANNEX(out, PLUCK(xs, WEAVE(WEAVE(n, k), 1)))
DELIVER out
```
## Rule report
At every milestone a tool-less copy of the conversation is asked for this report; each line is matched structurally against the answer key above.
```
⚠️ 重要:请暂停探索,不要再编写任何 AlienCode 测试代码。
现在进入【规则总结阶段】。你的任务是回顾到目前为止的所有实验结果,
用 S-Expression(前序表达式)格式总结你发现的所有 AlienCode 规则偏差。
⚠️ 注意:你的回复中 **只能包含规则总结**,不要包含任何 AlienCode 代码、测试用例或 EMIT 语句。
格式要求:
RULE_ID := S-EXPRESSION
每条规则描述对应操作的 **实际运行时行为**(不是文档中声称的标准行为)。
未发现的规则写 UNKNOWN。
允许的操作符:
算术: + - * / // % **
位运算: ^
比较: == != > < >= <=
逻辑: and or not
序列: reverse get slice len range
迭代: zip enumerate filter sort_asc sort_desc
聚合: max min any all
列表: prepend pop_left
输出: print
变量约定:a b = 二元操作数, n x s = 单元操作数,
seq = 序列, i = 索引, lo hi = 边界, pred = 谓词
规则清单(共 5 条):
--- L1: 字面量编码 ---
R01 := ?? # 整数字面量编码规则
--- L3: 比较运算 ---
R02 := ?? # UNDER(a, b) 的实际行为
--- L5: 位置与结构 ---
R03 := ?? # PLUCK(seq, i) 的实际索引行为
R04 := ?? # STRAND(...) 的元素顺序
--- L7: 聚合 ---
R05 := ?? # GAUGE(seq) 的实际返回值
```