Instruction stringlengths 45 106 | input_code stringlengths 1 13.7k | output_code stringlengths 1 13.7k |
|---|---|---|
Convert the following code from Factor to PHP, ensuring the logic remains intact. |
USING: arrays io kernel math math.ranges prettyprint sequences vectors ;
IN: rosetta.hailstone
: hailstone ( n -- seq )
[ 1vector ] keep
[ dup 1 number= ]
[
dup even? [ 2 / ] [ 3 * 1 + ] if
2dup swap push
] until
drop ;
<PRIVATE
: main ( -- )
27 hailstone dup dup
"The hailstone sequence from 27:" print
" has length " write length .
" starts with " write 4 head [ unparse ] map ", " join print
" ends with " write 4 tail* [ unparse ] map ", " join print
1 100000 [a,b)
[ [ hailstone length ] keep 2array ]
[ [ [ first ] bi@ > ] most ] map-reduce
first2
"The hailstone sequence from " write pprint
" has length " write pprint "." print ;
PRIVATE>
MAIN: main
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Can you help me rewrite this code in PHP instead of Factor, keeping it the same logically? |
USING: arrays io kernel math math.ranges prettyprint sequences vectors ;
IN: rosetta.hailstone
: hailstone ( n -- seq )
[ 1vector ] keep
[ dup 1 number= ]
[
dup even? [ 2 / ] [ 3 * 1 + ] if
2dup swap push
] until
drop ;
<PRIVATE
: main ( -- )
27 hailstone dup dup
"The hailstone sequence from 27:" print
" has length " write length .
" starts with " write 4 head [ unparse ] map ", " join print
" ends with " write 4 tail* [ unparse ] map ", " join print
1 100000 [a,b)
[ [ hailstone length ] keep 2array ]
[ [ [ first ] bi@ > ] most ] map-reduce
first2
"The hailstone sequence from " write pprint
" has length " write pprint "." print ;
PRIVATE>
MAIN: main
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Maintain the same structure and functionality when rewriting this code in PHP. | : hail-next
dup 1 and if 3 * 1+ else 2/ then ;
: .hail
begin dup . dup 1 > while hail-next repeat drop ;
: hail-len
1 begin over 1 > while swap hail-next swap 1+ repeat nip ;
27 hail-len . cr
27 .hail cr
: longest-hail
0 0 rot 1+ 1 do
i hail-len 2dup < if
nip nip i swap
else drop then
loop
swap . ." has hailstone sequence length " . ;
100000 longest-hail
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Convert this Forth block to PHP, preserving its control flow and logic. | : hail-next
dup 1 and if 3 * 1+ else 2/ then ;
: .hail
begin dup . dup 1 > while hail-next repeat drop ;
: hail-len
1 begin over 1 > while swap hail-next swap 1+ repeat nip ;
27 hail-len . cr
27 .hail cr
: longest-hail
0 0 rot 1+ 1 do
i hail-len 2dup < if
nip nip i swap
else drop then
loop
swap . ." has hailstone sequence length " . ;
100000 longest-hail
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Can you help me rewrite this code in PHP instead of Fortran, keeping it the same logically? | program Hailstone
implicit none
integer :: i, maxn
integer :: maxseqlen = 0, seqlen
integer, allocatable :: seq(:)
call hs(27, seqlen)
allocate(seq(seqlen))
call hs(27, seqlen, seq)
write(*,"(a,i0,a)") "Hailstone sequence for 27 has ", seqlen, " elements"
write(*,"(a,4(i0,a),3(i0,a),i0)") "Sequence = ", seq(1), ", ", seq(2), ", ", seq(3), ", ", seq(4), " ...., ", &
seq(seqlen-3), ", ", seq(seqlen-2), ", ", seq(seqlen-1), ", ", seq(seqlen)
do i = 1, 99999
call hs(i, seqlen)
if (seqlen > maxseqlen) then
maxseqlen = seqlen
maxn = i
end if
end do
write(*,*)
write(*,"(a,i0,a,i0,a)") "Longest sequence under 100000 is for ", maxn, " with ", maxseqlen, " elements"
deallocate(seq)
contains
subroutine hs(number, length, seqArray)
integer, intent(in) :: number
integer, intent(out) :: length
integer, optional, intent(inout) :: seqArray(:)
integer :: n
n = number
length = 1
if(present(seqArray)) seqArray(1) = n
do while(n /= 1)
if(mod(n,2) == 0) then
n = n / 2
else
n = n * 3 + 1
end if
length = length + 1
if(present(seqArray)) seqArray(length) = n
end do
end subroutine
end program
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Maintain the same structure and functionality when rewriting this code in PHP. | program Hailstone
implicit none
integer :: i, maxn
integer :: maxseqlen = 0, seqlen
integer, allocatable :: seq(:)
call hs(27, seqlen)
allocate(seq(seqlen))
call hs(27, seqlen, seq)
write(*,"(a,i0,a)") "Hailstone sequence for 27 has ", seqlen, " elements"
write(*,"(a,4(i0,a),3(i0,a),i0)") "Sequence = ", seq(1), ", ", seq(2), ", ", seq(3), ", ", seq(4), " ...., ", &
seq(seqlen-3), ", ", seq(seqlen-2), ", ", seq(seqlen-1), ", ", seq(seqlen)
do i = 1, 99999
call hs(i, seqlen)
if (seqlen > maxseqlen) then
maxseqlen = seqlen
maxn = i
end if
end do
write(*,*)
write(*,"(a,i0,a,i0,a)") "Longest sequence under 100000 is for ", maxn, " with ", maxseqlen, " elements"
deallocate(seq)
contains
subroutine hs(number, length, seqArray)
integer, intent(in) :: number
integer, intent(out) :: length
integer, optional, intent(inout) :: seqArray(:)
integer :: n
n = number
length = 1
if(present(seqArray)) seqArray(1) = n
do while(n /= 1)
if(mod(n,2) == 0) then
n = n / 2
else
n = n * 3 + 1
end if
length = length + 1
if(present(seqArray)) seqArray(length) = n
end do
end subroutine
end program
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Write the same algorithm in PHP as shown in this Groovy implementation. | def hailstone = { long start ->
def sequence = []
while (start != 1) {
sequence << start
start = (start % 2l == 0l) ? start / 2l : 3l * start + 1l
}
sequence << start
}
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Translate the given Groovy code snippet into PHP without altering its behavior. | def hailstone = { long start ->
def sequence = []
while (start != 1) {
sequence << start
start = (start % 2l == 0l) ? start / 2l : 3l * start + 1l
}
sequence << start
}
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Write the same code in PHP as shown below in Haskell. | import Data.List (maximumBy)
import Data.Ord (comparing)
collatz :: Int -> Int
collatz n
| even n = n `div` 2
| otherwise = 1 + 3 * n
hailstone :: Int -> [Int]
hailstone = takeWhile (1 /=) . iterate collatz
longestChain :: Int
longestChain =
fst $
maximumBy (comparing snd) $
(,) <*> (length . hailstone) <$> [1 .. 100000]
main :: IO ()
main =
mapM_
putStrLn
[ "Collatz sequence for 27: ",
(show . hailstone) 27,
"The number " <> show longestChain,
"has the longest hailstone sequence",
"for any number less then 100000. ",
"The sequence has length: "
<> (show . length . hailstone $ longestChain)
]
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Transform the following Haskell implementation into PHP, maintaining the same output and logic. | import Data.List (maximumBy)
import Data.Ord (comparing)
collatz :: Int -> Int
collatz n
| even n = n `div` 2
| otherwise = 1 + 3 * n
hailstone :: Int -> [Int]
hailstone = takeWhile (1 /=) . iterate collatz
longestChain :: Int
longestChain =
fst $
maximumBy (comparing snd) $
(,) <*> (length . hailstone) <$> [1 .. 100000]
main :: IO ()
main =
mapM_
putStrLn
[ "Collatz sequence for 27: ",
(show . hailstone) 27,
"The number " <> show longestChain,
"has the longest hailstone sequence",
"for any number less then 100000. ",
"The sequence has length: "
<> (show . length . hailstone $ longestChain)
]
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Generate an equivalent PHP version of this Icon code. | procedure hailstone(n)
while n > 1 do {
suspend n
n := if n%2 = 0 then n/2 else 3*n+1
}
suspend 1
end
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Rewrite this program in PHP while keeping its functionality equivalent to the Icon version. | procedure hailstone(n)
while n > 1 do {
suspend n
n := if n%2 = 0 then n/2 else 3*n+1
}
suspend 1
end
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Write the same code in PHP as shown below in J. | hailseq=: -:`(1 3&p.)@.(2&|) ^:(1 ~: ]) ^:a:"0
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Write the same code in PHP as shown below in J. | hailseq=: -:`(1 3&p.)@.(2&|) ^:(1 ~: ]) ^:a:"0
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Can you help me rewrite this code in PHP instead of Julia, keeping it the same logically? | function hailstonelength(n::Integer)
len = 1
while n > 1
n = ifelse(iseven(n), n ÷ 2, 3n + 1)
len += 1
end
return len
end
@show hailstonelength(27); nothing
@show findmax([hailstonelength(i) for i in 1:100_000]); nothing
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Produce a language-to-language conversion: from Julia to PHP, same semantics. | function hailstonelength(n::Integer)
len = 1
while n > 1
n = ifelse(iseven(n), n ÷ 2, 3n + 1)
len += 1
end
return len
end
@show hailstonelength(27); nothing
@show findmax([hailstonelength(i) for i in 1:100_000]); nothing
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Write the same code in PHP as shown below in Lua. | function hailstone( n, print_numbers )
local n_iter = 1
while n ~= 1 do
if print_numbers then print( n ) end
if n % 2 == 0 then
n = n / 2
else
n = 3 * n + 1
end
n_iter = n_iter + 1
end
if print_numbers then print( n ) end
return n_iter;
end
hailstone( 27, true )
max_i, max_iter = 0, 0
for i = 1, 100000 do
num = hailstone( i, false )
if num >= max_iter then
max_i = i
max_iter = num
end
end
print( string.format( "Needed %d iterations for the number %d.\n", max_iter, max_i ) )
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Maintain the same structure and functionality when rewriting this code in PHP. | function hailstone( n, print_numbers )
local n_iter = 1
while n ~= 1 do
if print_numbers then print( n ) end
if n % 2 == 0 then
n = n / 2
else
n = 3 * n + 1
end
n_iter = n_iter + 1
end
if print_numbers then print( n ) end
return n_iter;
end
hailstone( 27, true )
max_i, max_iter = 0, 0
for i = 1, 100000 do
num = hailstone( i, false )
if num >= max_iter then
max_i = i
max_iter = num
end
end
print( string.format( "Needed %d iterations for the number %d.\n", max_iter, max_i ) )
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Preserve the algorithm and functionality while converting the code from Mathematica to PHP. | HailstoneF[n_] := NestWhileList[If[OddQ[#], 3 # + 1, #/2] &, n, # > 1 &]
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Preserve the algorithm and functionality while converting the code from Mathematica to PHP. | HailstoneF[n_] := NestWhileList[If[OddQ[#], 3 # + 1, #/2] &, n, # > 1 &]
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Change the following MATLAB code into PHP without altering its purpose. | function x = hailstone(n)
x = n;
while n > 1
if n ~= floor(n / 2) * 2
n = n * 3 + 1;
else
n = n / 2;
end
x(end + 1) = n;
end
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Can you help me rewrite this code in PHP instead of MATLAB, keeping it the same logically? | function x = hailstone(n)
x = n;
while n > 1
if n ~= floor(n / 2) * 2
n = n * 3 + 1;
else
n = n / 2;
end
x(end + 1) = n;
end
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Convert this Nim block to PHP, preserving its control flow and logic. | proc hailstone(n: int): seq[int] =
result = @[n]
var n = n
while n > 1:
if (n and 1) == 1:
n = 3 * n + 1
else:
n = n div 2
result.add n
when isMainModule:
import strformat, strutils
let h = hailstone(27)
echo &"Hailstone sequence for number 27 has {h.len} elements."
let first = h[0..3].join(", ")
let last = h[^4..^1].join(", ")
echo &"This sequence begins with {first} and ends with {last}."
var m, mi = 0
for i in 1..<100_000:
let n = hailstone(i).len
if n > m:
m = n
mi = i
echo &"\nFor numbers < 100_000, maximum length {m} was found for Hailstone({mi})."
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Write the same code in PHP as shown below in Nim. | proc hailstone(n: int): seq[int] =
result = @[n]
var n = n
while n > 1:
if (n and 1) == 1:
n = 3 * n + 1
else:
n = n div 2
result.add n
when isMainModule:
import strformat, strutils
let h = hailstone(27)
echo &"Hailstone sequence for number 27 has {h.len} elements."
let first = h[0..3].join(", ")
let last = h[^4..^1].join(", ")
echo &"This sequence begins with {first} and ends with {last}."
var m, mi = 0
for i in 1..<100_000:
let n = hailstone(i).len
if n > m:
m = n
mi = i
echo &"\nFor numbers < 100_000, maximum length {m} was found for Hailstone({mi})."
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Translate the given OCaml code snippet into PHP without altering its behavior. | fun hail (x = 1) = [1]
| (x rem 2 = 0) = x :: hail (x div 2)
| x = x :: hail (x * 3 + 1)
fun hailstorm
([], i, largest, largest_at) = (largest_at, largest)
| (x :: xs, i, largest, largest_at) =
let
val k = len (hail x)
in
if k > largest then
hailstorm (xs, i + 1, k, i)
else
hailstorm (xs, i + 1, largest, largest_at)
end
| (x :: xs) = hailstorm (x :: xs, 1, 0, 0)
;
val h27 = hail 27;
print "hailstone sequence for the number 27 has ";
print ` len (h27);
print " elements starting with ";
print ` sub (h27, 0, 4);
print " and ending with ";
print ` sub (h27, len(h27)-4, len h27);
println ".";
val biggest = hailstorm ` iota (100000 - 1);
print "The number less than 100,000 which has the longest ";
print "hailstone sequence is at element ";
print ` ref (biggest, 0);
print " and is of length ";
println ` ref (biggest, 1);
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Preserve the algorithm and functionality while converting the code from OCaml to PHP. | fun hail (x = 1) = [1]
| (x rem 2 = 0) = x :: hail (x div 2)
| x = x :: hail (x * 3 + 1)
fun hailstorm
([], i, largest, largest_at) = (largest_at, largest)
| (x :: xs, i, largest, largest_at) =
let
val k = len (hail x)
in
if k > largest then
hailstorm (xs, i + 1, k, i)
else
hailstorm (xs, i + 1, largest, largest_at)
end
| (x :: xs) = hailstorm (x :: xs, 1, 0, 0)
;
val h27 = hail 27;
print "hailstone sequence for the number 27 has ";
print ` len (h27);
print " elements starting with ";
print ` sub (h27, 0, 4);
print " and ending with ";
print ` sub (h27, len(h27)-4, len h27);
println ".";
val biggest = hailstorm ` iota (100000 - 1);
print "The number less than 100,000 which has the longest ";
print "hailstone sequence is at element ";
print ` ref (biggest, 0);
print " and is of length ";
println ` ref (biggest, 1);
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Maintain the same structure and functionality when rewriting this code in PHP. | program ShowHailstoneSequence;
uses
SysUtils;
const
maxN = 10*1000*1000;
type
tiaArr = array[0..1000] of Uint64;
tIntArr = record
iaMaxPos : integer;
iaArr : tiaArr
end;
tpiaArr = ^tiaArr;
function HailstoneSeqCnt(n: UInt64): NativeInt;
begin
result := 0;
while not(ODD(n)) do
Begin
inc(result);
n := n shr 1;
end;
IF n > 1 then
repeat
repeat
n := (3*n+1) SHR 1;inc(result,2);
until NOT(Odd(n));
repeat
n := n shr 1; inc(result);
until odd(n);
until n = 1;
end;
procedure GetHailstoneSequence(aStartingNumber: NativeUint;var aHailstoneList: tIntArr);
var
maxPos: NativeInt;
n: UInt64;
pArr : tpiaArr;
begin
with aHailstoneList do
begin
maxPos := 0;
pArr := @iaArr;
end;
n := aStartingNumber;
pArr^[maxPos] := n;
while n <> 1 do
begin
if odd(n) then
n := (3*n+1)
else
n := n shr 1;
inc(maxPos);
pArr^[maxPos] := n;
end;
aHailstoneList.iaMaxPos := maxPos;
end;
var
i,Limit: NativeInt;
lList: tIntArr;
lAverageLength:Uint64;
lMaxSequence: NativeInt;
lMaxLength,lgth: NativeInt;
begin
lList.iaMaxPos := 0;
GetHailstoneSequence(27, lList);
with lList do
begin
Limit := iaMaxPos;
writeln(Format('sequence of %d has %d elements',[iaArr[0],Limit+1]));
write(iaArr[0],',',iaArr[1],',',iaArr[2],',',iaArr[3],'..');
For i := iaMaxPos-3 to iaMaxPos-1 do
write(iaArr[i],',');
writeln(iaArr[iaMaxPos]);
end;
Writeln;
lMaxSequence := 0;
lMaxLength := 0;
i := 1;
limit := 10*i;
writeln(' Limit : number with max length | average length');
repeat
lAverageLength:= 0;
repeat
lgth:= HailstoneSeqCnt(i);
inc(lAverageLength, lgth);
if lgth >= lMaxLength then
begin
lMaxSequence := i;
lMaxLength := lgth+1;
end;
inc(i);
until i = Limit;
Writeln(Format(' %10d : %9d | %4d | %7.3f',
[limit,lMaxSequence, lMaxLength,0.9*lAverageLength/Limit]));
limit := limit*10;
until Limit > maxN;
end.
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Preserve the algorithm and functionality while converting the code from Pascal to PHP. | program ShowHailstoneSequence;
uses
SysUtils;
const
maxN = 10*1000*1000;
type
tiaArr = array[0..1000] of Uint64;
tIntArr = record
iaMaxPos : integer;
iaArr : tiaArr
end;
tpiaArr = ^tiaArr;
function HailstoneSeqCnt(n: UInt64): NativeInt;
begin
result := 0;
while not(ODD(n)) do
Begin
inc(result);
n := n shr 1;
end;
IF n > 1 then
repeat
repeat
n := (3*n+1) SHR 1;inc(result,2);
until NOT(Odd(n));
repeat
n := n shr 1; inc(result);
until odd(n);
until n = 1;
end;
procedure GetHailstoneSequence(aStartingNumber: NativeUint;var aHailstoneList: tIntArr);
var
maxPos: NativeInt;
n: UInt64;
pArr : tpiaArr;
begin
with aHailstoneList do
begin
maxPos := 0;
pArr := @iaArr;
end;
n := aStartingNumber;
pArr^[maxPos] := n;
while n <> 1 do
begin
if odd(n) then
n := (3*n+1)
else
n := n shr 1;
inc(maxPos);
pArr^[maxPos] := n;
end;
aHailstoneList.iaMaxPos := maxPos;
end;
var
i,Limit: NativeInt;
lList: tIntArr;
lAverageLength:Uint64;
lMaxSequence: NativeInt;
lMaxLength,lgth: NativeInt;
begin
lList.iaMaxPos := 0;
GetHailstoneSequence(27, lList);
with lList do
begin
Limit := iaMaxPos;
writeln(Format('sequence of %d has %d elements',[iaArr[0],Limit+1]));
write(iaArr[0],',',iaArr[1],',',iaArr[2],',',iaArr[3],'..');
For i := iaMaxPos-3 to iaMaxPos-1 do
write(iaArr[i],',');
writeln(iaArr[iaMaxPos]);
end;
Writeln;
lMaxSequence := 0;
lMaxLength := 0;
i := 1;
limit := 10*i;
writeln(' Limit : number with max length | average length');
repeat
lAverageLength:= 0;
repeat
lgth:= HailstoneSeqCnt(i);
inc(lAverageLength, lgth);
if lgth >= lMaxLength then
begin
lMaxSequence := i;
lMaxLength := lgth+1;
end;
inc(i);
until i = Limit;
Writeln(Format(' %10d : %9d | %4d | %7.3f',
[limit,lMaxSequence, lMaxLength,0.9*lAverageLength/Limit]));
limit := limit*10;
until Limit > maxN;
end.
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Rewrite the snippet below in PHP so it works the same as the original Perl code. |
use warnings;
use strict;
my @h = hailstone(27);
print "Length of hailstone(27) = " . scalar @h . "\n";
print "[" . join(", ", @h[0 .. 3], "...", @h[-4 .. -1]) . "]\n";
my ($max, $n) = (0, 0);
for my $x (1 .. 99_999) {
@h = hailstone($x);
if (scalar @h > $max) {
($max, $n) = (scalar @h, $x);
}
}
print "Max length $max was found for hailstone($n) for numbers < 100_000\n";
sub hailstone {
my ($n) = @_;
my @sequence = ($n);
while ($n > 1) {
if ($n % 2 == 0) {
$n = int($n / 2);
} else {
$n = $n * 3 + 1;
}
push @sequence, $n;
}
return @sequence;
}
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Write the same algorithm in PHP as shown in this Perl implementation. |
use warnings;
use strict;
my @h = hailstone(27);
print "Length of hailstone(27) = " . scalar @h . "\n";
print "[" . join(", ", @h[0 .. 3], "...", @h[-4 .. -1]) . "]\n";
my ($max, $n) = (0, 0);
for my $x (1 .. 99_999) {
@h = hailstone($x);
if (scalar @h > $max) {
($max, $n) = (scalar @h, $x);
}
}
print "Max length $max was found for hailstone($n) for numbers < 100_000\n";
sub hailstone {
my ($n) = @_;
my @sequence = ($n);
while ($n > 1) {
if ($n % 2 == 0) {
$n = int($n / 2);
} else {
$n = $n * 3 + 1;
}
push @sequence, $n;
}
return @sequence;
}
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Write the same algorithm in PHP as shown in this PowerShell implementation. | function Get-HailStone {
param($n)
switch($n) {
1 {$n;return}
{$n % 2 -eq 0} {$n; return Get-Hailstone ($n = $n / 2)}
{$n % 2 -ne 0} {$n; return Get-Hailstone ($n = ($n * 3) +1)}
}
}
function Get-HailStoneBelowLimit {
param($UpperLimit)
for ($i = 1; $i -lt $UpperLimit; $i++) {
[pscustomobject]@{
'Number' = $i
'Count' = (Get-HailStone $i).count
}
}
}
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Ensure the translated PHP code behaves exactly like the original PowerShell snippet. | function Get-HailStone {
param($n)
switch($n) {
1 {$n;return}
{$n % 2 -eq 0} {$n; return Get-Hailstone ($n = $n / 2)}
{$n % 2 -ne 0} {$n; return Get-Hailstone ($n = ($n * 3) +1)}
}
}
function Get-HailStoneBelowLimit {
param($UpperLimit)
for ($i = 1; $i -lt $UpperLimit; $i++) {
[pscustomobject]@{
'Number' = $i
'Count' = (Get-HailStone $i).count
}
}
}
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Translate the given Racket code snippet into PHP without altering its behavior. | #lang racket
(define hailstone
(let ([t (make-hasheq)])
(hash-set! t 1 '(1))
(λ(n) (hash-ref! t n
(λ() (cons n (hailstone (if (even? n) (/ n 2) (+ (* 3 n) 1)))))))))
(define h27 (hailstone 27))
(printf "h(27) = ~s, ~s items\n"
`(,@(take h27 4) ... ,@(take-right h27 4))
(length h27))
(define N 100000)
(define longest
(for/fold ([m #f]) ([i (in-range 1 (add1 N))])
(define h (hailstone i))
(if (and m (> (cdr m) (length h))) m (cons i (length h)))))
(printf "for x<=~s, ~s has the longest sequence with ~s items\n"
N (car longest) (cdr longest))
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Produce a language-to-language conversion: from Racket to PHP, same semantics. | #lang racket
(define hailstone
(let ([t (make-hasheq)])
(hash-set! t 1 '(1))
(λ(n) (hash-ref! t n
(λ() (cons n (hailstone (if (even? n) (/ n 2) (+ (* 3 n) 1)))))))))
(define h27 (hailstone 27))
(printf "h(27) = ~s, ~s items\n"
`(,@(take h27 4) ... ,@(take-right h27 4))
(length h27))
(define N 100000)
(define longest
(for/fold ([m #f]) ([i (in-range 1 (add1 N))])
(define h (hailstone i))
(if (and m (> (cdr m) (length h))) m (cons i (length h)))))
(printf "for x<=~s, ~s has the longest sequence with ~s items\n"
N (car longest) (cdr longest))
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Generate an equivalent PHP version of this COBOL code. | identification division.
program-id. hailstones.
remarks. cobc -x hailstones.cob.
data division.
working-storage section.
01 most constant as 1000000.
01 coverage constant as 100000.
01 stones usage binary-long.
01 n usage binary-long.
01 storm usage binary-long.
01 show-arg pic 9(6).
01 show-default pic 99 value 27.
01 show-sequence usage binary-long.
01 longest usage binary-long occurs 2 times.
01 filler.
05 hail usage binary-long
occurs 0 to most depending on stones.
01 show pic z(10).
01 low-range usage binary-long.
01 high-range usage binary-long.
01 range usage binary-long.
01 remain usage binary-long.
01 unused usage binary-long.
procedure division.
accept show-arg from command-line
if show-arg less than 1 or greater than coverage then
move show-default to show-arg
end-if
move show-arg to show-sequence
move 1 to longest(1)
perform hailstone varying storm
from 1 by 1 until storm > coverage
display "Longest at: " longest(2) " with " longest(1) " elements"
goback.
hailstone.
move 0 to stones
move storm to n
perform until n equal 1
if stones > most then
display "too many hailstones" upon syserr
stop run
end-if
add 1 to stones
move n to hail(stones)
divide n by 2 giving unused remainder remain
if remain equal 0 then
divide 2 into n
else
compute n = 3 * n + 1
end-if
end-perform
add 1 to stones
move n to hail(stones)
if stones > longest(1) then
move stones to longest(1)
move storm to longest(2)
end-if
if storm equal show-sequence then
display show-sequence ": " with no advancing
perform varying range from 1 by 1 until range > stones
move 5 to low-range
compute high-range = stones - 4
if range < low-range or range > high-range then
move hail(range) to show
display function trim(show) with no advancing
if range < stones then
display ", " with no advancing
end-if
end-if
if range = low-range and stones > 8 then
display "..., " with no advancing
end-if
end-perform
display ": " stones " elements"
end-if
.
end program hailstones.
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Please provide an equivalent version of this COBOL code in PHP. | identification division.
program-id. hailstones.
remarks. cobc -x hailstones.cob.
data division.
working-storage section.
01 most constant as 1000000.
01 coverage constant as 100000.
01 stones usage binary-long.
01 n usage binary-long.
01 storm usage binary-long.
01 show-arg pic 9(6).
01 show-default pic 99 value 27.
01 show-sequence usage binary-long.
01 longest usage binary-long occurs 2 times.
01 filler.
05 hail usage binary-long
occurs 0 to most depending on stones.
01 show pic z(10).
01 low-range usage binary-long.
01 high-range usage binary-long.
01 range usage binary-long.
01 remain usage binary-long.
01 unused usage binary-long.
procedure division.
accept show-arg from command-line
if show-arg less than 1 or greater than coverage then
move show-default to show-arg
end-if
move show-arg to show-sequence
move 1 to longest(1)
perform hailstone varying storm
from 1 by 1 until storm > coverage
display "Longest at: " longest(2) " with " longest(1) " elements"
goback.
hailstone.
move 0 to stones
move storm to n
perform until n equal 1
if stones > most then
display "too many hailstones" upon syserr
stop run
end-if
add 1 to stones
move n to hail(stones)
divide n by 2 giving unused remainder remain
if remain equal 0 then
divide 2 into n
else
compute n = 3 * n + 1
end-if
end-perform
add 1 to stones
move n to hail(stones)
if stones > longest(1) then
move stones to longest(1)
move storm to longest(2)
end-if
if storm equal show-sequence then
display show-sequence ": " with no advancing
perform varying range from 1 by 1 until range > stones
move 5 to low-range
compute high-range = stones - 4
if range < low-range or range > high-range then
move hail(range) to show
display function trim(show) with no advancing
if range < stones then
display ", " with no advancing
end-if
end-if
if range = low-range and stones > 8 then
display "..., " with no advancing
end-if
end-perform
display ": " stones " elements"
end-if
.
end program hailstones.
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Ensure the translated PHP code behaves exactly like the original REXX snippet. |
options replace format comments java crossref savelog symbols binary
do
start = 27
hs = hailstone(start)
hsCount = hs.words
say 'The number' start 'has a hailstone sequence comprising' hsCount 'elements'
say ' its first four elements are:' hs.subword(1, 4)
say ' and last four elements are:' hs.subword(hsCount - 3)
hsMax = 0
hsCountMax = 0
llimit = 100000
loop x_ = 1 to llimit - 1
hs = hailstone(x_)
hsCount = hs.words
if hsCount > hsCountMax then do
hsMax = x_
hsCountMax = hsCount
end
end x_
say 'The number' hsMax 'has the longest hailstone sequence in the range 1 to' llimit - 1 'with a sequence length of' hsCountMax
catch ex = Exception
ex.printStackTrace
end
return
method hailstone(hn = long) public static returns Rexx signals IllegalArgumentException
hs = Rexx('')
if hn <= 0 then signal IllegalArgumentException('Invalid start point. Must be a positive integer greater than 0')
loop label n_ while hn > 1
hs = hs' 'hn
if hn // 2 \= 0 then hn = hn * 3 + 1
else hn = hn % 2
end n_
hs = hs' 'hn
return hs.strip
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Write the same algorithm in PHP as shown in this REXX implementation. |
options replace format comments java crossref savelog symbols binary
do
start = 27
hs = hailstone(start)
hsCount = hs.words
say 'The number' start 'has a hailstone sequence comprising' hsCount 'elements'
say ' its first four elements are:' hs.subword(1, 4)
say ' and last four elements are:' hs.subword(hsCount - 3)
hsMax = 0
hsCountMax = 0
llimit = 100000
loop x_ = 1 to llimit - 1
hs = hailstone(x_)
hsCount = hs.words
if hsCount > hsCountMax then do
hsMax = x_
hsCountMax = hsCount
end
end x_
say 'The number' hsMax 'has the longest hailstone sequence in the range 1 to' llimit - 1 'with a sequence length of' hsCountMax
catch ex = Exception
ex.printStackTrace
end
return
method hailstone(hn = long) public static returns Rexx signals IllegalArgumentException
hs = Rexx('')
if hn <= 0 then signal IllegalArgumentException('Invalid start point. Must be a positive integer greater than 0')
loop label n_ while hn > 1
hs = hs' 'hn
if hn // 2 \= 0 then hn = hn * 3 + 1
else hn = hn % 2
end n_
hs = hs' 'hn
return hs.strip
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Change the following Ruby code into PHP without altering its purpose. | def hailstone(n)
seq = [n]
until n == 1
n = n.even? ? n // 2 : n * 3 + 1
seq << n
end
seq
end
max_len = (1...100_000).max_by{|n| hailstone(n).size }
max = hailstone(max_len)
puts ([max_len, max.size, max.max, max.first(4), max.last(4)])
twenty_seven = hailstone(27)
puts ([twenty_seven.size, twenty_seven.first(4), max.last(4)])
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Convert the following code from Ruby to PHP, ensuring the logic remains intact. | def hailstone(n)
seq = [n]
until n == 1
n = n.even? ? n // 2 : n * 3 + 1
seq << n
end
seq
end
max_len = (1...100_000).max_by{|n| hailstone(n).size }
max = hailstone(max_len)
puts ([max_len, max.size, max.max, max.first(4), max.last(4)])
twenty_seven = hailstone(27)
puts ([twenty_seven.size, twenty_seven.first(4), max.last(4)])
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Can you help me rewrite this code in PHP instead of Scala, keeping it the same logically? | object HailstoneSequence extends App {
def hailstone(n: Int): Stream[Int] =
n #:: (if (n == 1) Stream.empty else hailstone(if (n % 2 == 0) n / 2 else n * 3 + 1))
val nr = args.headOption.map(_.toInt).getOrElse(27)
val collatz = hailstone(nr)
println(s"Use the routine to show that the hailstone sequence for the number: $nr.")
println(collatz.toList)
println(s"It has ${collatz.length} elements.")
println
println(
"Compute the number < 100,000, which has the longest hailstone sequence with that sequence's length.")
val (n, len) = (1 until 100000).map(n => (n, hailstone(n).length)).maxBy(_._2)
println(s"Longest hailstone sequence length= $len occurring with number $n.")
}
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Please provide an equivalent version of this Scala code in PHP. | object HailstoneSequence extends App {
def hailstone(n: Int): Stream[Int] =
n #:: (if (n == 1) Stream.empty else hailstone(if (n % 2 == 0) n / 2 else n * 3 + 1))
val nr = args.headOption.map(_.toInt).getOrElse(27)
val collatz = hailstone(nr)
println(s"Use the routine to show that the hailstone sequence for the number: $nr.")
println(collatz.toList)
println(s"It has ${collatz.length} elements.")
println
println(
"Compute the number < 100,000, which has the longest hailstone sequence with that sequence's length.")
val (n, len) = (1 until 100000).map(n => (n, hailstone(n).length)).maxBy(_._2)
println(s"Longest hailstone sequence length= $len occurring with number $n.")
}
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Generate an equivalent PHP version of this Swift code. | func hailstone(var n:Int) -> [Int] {
var arr = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = (3 * n) + 1
}
arr.append(n)
}
return arr
}
let n = hailstone(27)
println("hailstone(27): \(n[0...3]) ... \(n[n.count-4...n.count-1]) for a count of \(n.count).")
var longest = (n: 1, len: 1)
for i in 1...100_000 {
let new = hailstone(i)
if new.count > longest.len {
longest = (i, new.count)
}
}
println("Longest sequence for numbers under 100,000 is with \(longest.n). Which has \(longest.len) items.")
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Maintain the same structure and functionality when rewriting this code in PHP. | func hailstone(var n:Int) -> [Int] {
var arr = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = (3 * n) + 1
}
arr.append(n)
}
return arr
}
let n = hailstone(27)
println("hailstone(27): \(n[0...3]) ... \(n[n.count-4...n.count-1]) for a count of \(n.count).")
var longest = (n: 1, len: 1)
for i in 1...100_000 {
let new = hailstone(i)
if new.count > longest.len {
longest = (i, new.count)
}
}
println("Longest sequence for numbers under 100,000 is with \(longest.n). Which has \(longest.len) items.")
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Transform the following Tcl implementation into PHP, maintaining the same output and logic. | proc hailstone n {
while 1 {
lappend seq $n
if {$n == 1} {return $seq}
set n [expr {$n & 1 ? $n*3+1 : $n/2}]
}
}
set h27 [hailstone 27]
puts "h27 len=[llength $h27]"
puts "head4 = [lrange $h27 0 3]"
puts "tail4 = [lrange $h27 end-3 end]"
set maxlen [set max 0]
for {set i 1} {$i<100000} {incr i} {
set l [llength [hailstone $i]]
if {$l>$maxlen} {set maxlen $l;set max $i}
}
puts "max is $max, with length $maxlen"
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Write the same algorithm in PHP as shown in this Tcl implementation. | proc hailstone n {
while 1 {
lappend seq $n
if {$n == 1} {return $seq}
set n [expr {$n & 1 ? $n*3+1 : $n/2}]
}
}
set h27 [hailstone 27]
puts "h27 len=[llength $h27]"
puts "head4 = [lrange $h27 0 3]"
puts "tail4 = [lrange $h27 end-3 end]"
set maxlen [set max 0]
for {set i 1} {$i<100000} {incr i} {
set l [llength [hailstone $i]]
if {$l>$maxlen} {set maxlen $l;set max $i}
}
puts "max is $max, with length $maxlen"
| function hailstone($n,$seq=array()){
$sequence = $seq;
$sequence[] = $n;
if($n == 1){
return $sequence;
}else{
$n = ($n%2==0) ? $n/2 : (3*$n)+1;
return hailstone($n, $sequence);
}
}
$result = hailstone(27);
echo count($result) . ' Elements.<br>';
echo 'Starting with : ' . implode(",",array_slice($result,0,4)) .' and ending with : ' . implode(",",array_slice($result,count($result)-4)) . '<br>';
$maxResult = array(0);
for($i=1;$i<=100000;$i++){
$result = count(hailstone($i));
if($result > max($maxResult)){
$maxResult = array($i=>$result);
}
}
foreach($maxResult as $key => $val){
echo 'Number < 100000 with longest Hailstone seq.: ' . $key . ' with length of ' . $val;
}
|
Convert this C snippet to Rust and keep its semantics consistent. | #include <stdio.h>
#include <stdlib.h>
int hailstone(int n, int *arry)
{
int hs = 1;
while (n!=1) {
hs++;
if (arry) *arry++ = n;
n = (n&1) ? (3*n+1) : (n/2);
}
if (arry) *arry++ = n;
return hs;
}
int main()
{
int j, hmax = 0;
int jatmax, n;
int *arry;
for (j=1; j<100000; j++) {
n = hailstone(j, NULL);
if (hmax < n) {
hmax = n;
jatmax = j;
}
}
n = hailstone(27, NULL);
arry = malloc(n*sizeof(int));
n = hailstone(27, arry);
printf("[ %d, %d, %d, %d, ...., %d, %d, %d, %d] len=%d\n",
arry[0],arry[1],arry[2],arry[3],
arry[n-4], arry[n-3], arry[n-2], arry[n-1], n);
printf("Max %d at j= %d\n", hmax, jatmax);
free(arry);
return 0;
}
| fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
|
Please provide an equivalent version of this C++ code in Rust. | #include <iostream>
#include <vector>
#include <utility>
std::vector<int> hailstone(int i)
{
std::vector<int> v;
while(true){
v.push_back(i);
if (1 == i) break;
i = (i % 2) ? (3 * i + 1) : (i / 2);
}
return v;
}
std::pair<int,int> find_longest_hailstone_seq(int n)
{
std::pair<int, int> maxseq(0, 0);
int l;
for(int i = 1; i < n; ++i){
l = hailstone(i).size();
if (l > maxseq.second) maxseq = std::make_pair(i, l);
}
return maxseq;
}
int main () {
std::vector<int> h27;
h27 = hailstone(27);
int l = h27.size();
std::cout << "length of hailstone(27) is " << l;
std::cout << " first four elements of hailstone(27) are ";
std::cout << h27[0] << " " << h27[1] << " "
<< h27[2] << " " << h27[3] << std::endl;
std::cout << " last four elements of hailstone(27) are "
<< h27[l-4] << " " << h27[l-3] << " "
<< h27[l-2] << " " << h27[l-1] << std::endl;
std::pair<int,int> m = find_longest_hailstone_seq(100000);
std::cout << "the longest hailstone sequence under 100,000 is " << m.first
<< " with " << m.second << " elements." <<std::endl;
return 0;
}
| fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
|
Preserve the algorithm and functionality while converting the code from C# to Rust. | using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Hailstone
{
class Program
{
public static List<int> hs(int n,List<int> seq)
{
List<int> sequence = seq;
sequence.Add(n);
if (n == 1)
{
return sequence;
}else{
int newn = (n % 2 == 0) ? n / 2 : (3 * n) + 1;
return hs(newn, sequence);
}
}
static void Main(string[] args)
{
int n = 27;
List<int> sequence = hs(n,new List<int>());
Console.WriteLine(sequence.Count + " Elements");
List<int> start = sequence.GetRange(0, 4);
List<int> end = sequence.GetRange(sequence.Count - 4, 4);
Console.WriteLine("Starting with : " + string.Join(",", start) + " and ending with : " + string.Join(",", end));
int number = 0, longest = 0;
for (int i = 1; i < 100000; i++)
{
int count = (hs(i, new List<int>())).Count;
if (count > longest)
{
longest = count;
number = i;
}
}
Console.WriteLine("Number < 100000 with longest Hailstone seq.: " + number + " with length of " + longest);
}
}
}
| fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
|
Write the same algorithm in Rust as shown in this C# implementation. | using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Hailstone
{
class Program
{
public static List<int> hs(int n,List<int> seq)
{
List<int> sequence = seq;
sequence.Add(n);
if (n == 1)
{
return sequence;
}else{
int newn = (n % 2 == 0) ? n / 2 : (3 * n) + 1;
return hs(newn, sequence);
}
}
static void Main(string[] args)
{
int n = 27;
List<int> sequence = hs(n,new List<int>());
Console.WriteLine(sequence.Count + " Elements");
List<int> start = sequence.GetRange(0, 4);
List<int> end = sequence.GetRange(sequence.Count - 4, 4);
Console.WriteLine("Starting with : " + string.Join(",", start) + " and ending with : " + string.Join(",", end));
int number = 0, longest = 0;
for (int i = 1; i < 100000; i++)
{
int count = (hs(i, new List<int>())).Count;
if (count > longest)
{
longest = count;
number = i;
}
}
Console.WriteLine("Number < 100000 with longest Hailstone seq.: " + number + " with length of " + longest);
}
}
}
| fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
|
Write a version of this Go function in Rust with identical behavior. | package main
import "fmt"
func hs(n int, recycle []int) []int {
s := append(recycle[:0], n)
for n > 1 {
if n&1 == 0 {
n = n / 2
} else {
n = 3*n + 1
}
s = append(s, n)
}
return s
}
func main() {
seq := hs(27, nil)
fmt.Printf("hs(27): %d elements: [%d %d %d %d ... %d %d %d %d]\n",
len(seq), seq[0], seq[1], seq[2], seq[3],
seq[len(seq)-4], seq[len(seq)-3], seq[len(seq)-2], seq[len(seq)-1])
var maxN, maxLen int
for n := 1; n < 100000; n++ {
seq = hs(n, seq)
if len(seq) > maxLen {
maxN = n
maxLen = len(seq)
}
}
fmt.Printf("hs(%d): %d elements\n", maxN, maxLen)
}
| fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
|
Convert this Rust snippet to Python and keep its semantics consistent. | fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
| def hailstone(n):
seq = [n]
while n>1:
n = 3*n + 1 if n & 1 else n//2
seq.append(n)
return seq
if __name__ == '__main__':
h = hailstone(27)
assert len(h)==112 and h[:4]==[27, 82, 41, 124] and h[-4:]==[8, 4, 2, 1]
print("Maximum length %i was found for hailstone(%i) for numbers <100,000" %
max((len(hailstone(i)), i) for i in range(1,100000)))
|
Translate this program into VB but keep the logic exactly as in Rust. | fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
| Private Function hailstone(ByVal n As Long) As Collection
Dim s As New Collection
s.Add CStr(n), CStr(n)
i = 0
Do While n <> 1
If n Mod 2 = 0 Then
n = n / 2
Else
n = 3 * n + 1
End If
s.Add CStr(n), CStr(n)
Loop
Set hailstone = s
End Function
Private Function hailstone_count(ByVal n As Long)
Dim count As Long: count = 1
Do While n <> 1
If n Mod 2 = 0 Then
n = n / 2
Else
n = 3 * n + 1
End If
count = count + 1
Loop
hailstone_count = count
End Function
Public Sub rosetta()
Dim s As Collection, i As Long
Set s = hailstone(27)
Dim ls As Integer: ls = s.count
Debug.Print "hailstone(27) = ";
For i = 1 To 4
Debug.Print s(i); ", ";
Next i
Debug.Print "... ";
For i = s.count - 4 To s.count - 1
Debug.Print s(i); ", ";
Next i
Debug.Print s(s.count)
Debug.Print "length ="; ls
Dim hmax As Long: hmax = 1
Dim imax As Long: imax = 1
Dim count As Integer
For i = 2 To 100000# - 1
count = hailstone_count(i)
If count > hmax Then
hmax = count
imax = i
End If
Next i
Debug.Print "The longest hailstone sequence under 100,000 is"; imax; "with"; hmax; "elements."
End Sub
|
Write the same code in VB as shown below in Rust. | fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
| Private Function hailstone(ByVal n As Long) As Collection
Dim s As New Collection
s.Add CStr(n), CStr(n)
i = 0
Do While n <> 1
If n Mod 2 = 0 Then
n = n / 2
Else
n = 3 * n + 1
End If
s.Add CStr(n), CStr(n)
Loop
Set hailstone = s
End Function
Private Function hailstone_count(ByVal n As Long)
Dim count As Long: count = 1
Do While n <> 1
If n Mod 2 = 0 Then
n = n / 2
Else
n = 3 * n + 1
End If
count = count + 1
Loop
hailstone_count = count
End Function
Public Sub rosetta()
Dim s As Collection, i As Long
Set s = hailstone(27)
Dim ls As Integer: ls = s.count
Debug.Print "hailstone(27) = ";
For i = 1 To 4
Debug.Print s(i); ", ";
Next i
Debug.Print "... ";
For i = s.count - 4 To s.count - 1
Debug.Print s(i); ", ";
Next i
Debug.Print s(s.count)
Debug.Print "length ="; ls
Dim hmax As Long: hmax = 1
Dim imax As Long: imax = 1
Dim count As Integer
For i = 2 To 100000# - 1
count = hailstone_count(i)
If count > hmax Then
hmax = count
imax = i
End If
Next i
Debug.Print "The longest hailstone sequence under 100,000 is"; imax; "with"; hmax; "elements."
End Sub
|
Convert the following code from Java to Rust, ensuring the logic remains intact. | import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
class Hailstone {
public static List<Long> getHailstoneSequence(long n) {
if (n <= 0)
throw new IllegalArgumentException("Invalid starting sequence number");
List<Long> list = new ArrayList<Long>();
list.add(Long.valueOf(n));
while (n != 1) {
if ((n & 1) == 0)
n = n / 2;
else
n = 3 * n + 1;
list.add(Long.valueOf(n));
}
return list;
}
public static void main(String[] args) {
List<Long> sequence27 = getHailstoneSequence(27);
System.out.println("Sequence for 27 has " + sequence27.size() + " elements: " + sequence27);
long MAX = 100000;
{
long highestNumber = 1;
int highestCount = 1;
for (long i = 2; i < MAX; i++) {
int count = getHailstoneSequence(i).size();
if (count > highestCount) {
highestCount = count;
highestNumber = i;
}
}
System.out.println("Method 1, number " + highestNumber + " has the longest sequence, with a length of " + highestCount);
}
{
long highestNumber = 1;
int highestCount = 1;
for (long i = 2; i < MAX; i++) {
int count = 1;
long n = i;
while (n != 1) {
if ((n & 1) == 0)
n = n / 2;
else
n = 3 * n + 1;
count++;
}
if (count > highestCount) {
highestCount = count;
highestNumber = i;
}
}
System.out.println("Method 2, number " + highestNumber + " has the longest sequence, with a length of " + highestCount);
}
{
long highestNumber = 1;
long highestCount = 1;
Map<Long, Integer> sequenceMap = new HashMap<Long, Integer>();
sequenceMap.put(Long.valueOf(1), Integer.valueOf(1));
List<Long> currentList = new ArrayList<Long>();
for (long i = 2; i < MAX; i++) {
currentList.clear();
Long n = Long.valueOf(i);
Integer count = null;
while ((count = sequenceMap.get(n)) == null) {
currentList.add(n);
long nValue = n.longValue();
if ((nValue & 1) == 0)
n = Long.valueOf(nValue / 2);
else
n = Long.valueOf(3 * nValue + 1);
}
int curCount = count.intValue();
for (int j = currentList.size() - 1; j >= 0; j--)
sequenceMap.put(currentList.get(j), Integer.valueOf(++curCount));
if (curCount > highestCount) {
highestCount = curCount;
highestNumber = i;
}
}
System.out.println("Method 3, number " + highestNumber + " has the longest sequence, with a length of " + highestCount);
}
return;
}
}
| fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
|
Please provide an equivalent version of this Java code in Rust. | import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
class Hailstone {
public static List<Long> getHailstoneSequence(long n) {
if (n <= 0)
throw new IllegalArgumentException("Invalid starting sequence number");
List<Long> list = new ArrayList<Long>();
list.add(Long.valueOf(n));
while (n != 1) {
if ((n & 1) == 0)
n = n / 2;
else
n = 3 * n + 1;
list.add(Long.valueOf(n));
}
return list;
}
public static void main(String[] args) {
List<Long> sequence27 = getHailstoneSequence(27);
System.out.println("Sequence for 27 has " + sequence27.size() + " elements: " + sequence27);
long MAX = 100000;
{
long highestNumber = 1;
int highestCount = 1;
for (long i = 2; i < MAX; i++) {
int count = getHailstoneSequence(i).size();
if (count > highestCount) {
highestCount = count;
highestNumber = i;
}
}
System.out.println("Method 1, number " + highestNumber + " has the longest sequence, with a length of " + highestCount);
}
{
long highestNumber = 1;
int highestCount = 1;
for (long i = 2; i < MAX; i++) {
int count = 1;
long n = i;
while (n != 1) {
if ((n & 1) == 0)
n = n / 2;
else
n = 3 * n + 1;
count++;
}
if (count > highestCount) {
highestCount = count;
highestNumber = i;
}
}
System.out.println("Method 2, number " + highestNumber + " has the longest sequence, with a length of " + highestCount);
}
{
long highestNumber = 1;
long highestCount = 1;
Map<Long, Integer> sequenceMap = new HashMap<Long, Integer>();
sequenceMap.put(Long.valueOf(1), Integer.valueOf(1));
List<Long> currentList = new ArrayList<Long>();
for (long i = 2; i < MAX; i++) {
currentList.clear();
Long n = Long.valueOf(i);
Integer count = null;
while ((count = sequenceMap.get(n)) == null) {
currentList.add(n);
long nValue = n.longValue();
if ((nValue & 1) == 0)
n = Long.valueOf(nValue / 2);
else
n = Long.valueOf(3 * nValue + 1);
}
int curCount = count.intValue();
for (int j = currentList.size() - 1; j >= 0; j--)
sequenceMap.put(currentList.get(j), Integer.valueOf(++curCount));
if (curCount > highestCount) {
highestCount = curCount;
highestNumber = i;
}
}
System.out.println("Method 3, number " + highestNumber + " has the longest sequence, with a length of " + highestCount);
}
return;
}
}
| fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
|
Change the following Go code into Rust without altering its purpose. | package main
import "fmt"
func hs(n int, recycle []int) []int {
s := append(recycle[:0], n)
for n > 1 {
if n&1 == 0 {
n = n / 2
} else {
n = 3*n + 1
}
s = append(s, n)
}
return s
}
func main() {
seq := hs(27, nil)
fmt.Printf("hs(27): %d elements: [%d %d %d %d ... %d %d %d %d]\n",
len(seq), seq[0], seq[1], seq[2], seq[3],
seq[len(seq)-4], seq[len(seq)-3], seq[len(seq)-2], seq[len(seq)-1])
var maxN, maxLen int
for n := 1; n < 100000; n++ {
seq = hs(n, seq)
if len(seq) > maxLen {
maxN = n
maxLen = len(seq)
}
}
fmt.Printf("hs(%d): %d elements\n", maxN, maxLen)
}
| fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
|
Translate this program into Rust but keep the logic exactly as in C. | #include <stdio.h>
#include <stdlib.h>
int hailstone(int n, int *arry)
{
int hs = 1;
while (n!=1) {
hs++;
if (arry) *arry++ = n;
n = (n&1) ? (3*n+1) : (n/2);
}
if (arry) *arry++ = n;
return hs;
}
int main()
{
int j, hmax = 0;
int jatmax, n;
int *arry;
for (j=1; j<100000; j++) {
n = hailstone(j, NULL);
if (hmax < n) {
hmax = n;
jatmax = j;
}
}
n = hailstone(27, NULL);
arry = malloc(n*sizeof(int));
n = hailstone(27, arry);
printf("[ %d, %d, %d, %d, ...., %d, %d, %d, %d] len=%d\n",
arry[0],arry[1],arry[2],arry[3],
arry[n-4], arry[n-3], arry[n-2], arry[n-1], n);
printf("Max %d at j= %d\n", hmax, jatmax);
free(arry);
return 0;
}
| fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
|
Transform the following C++ implementation into Rust, maintaining the same output and logic. | #include <iostream>
#include <vector>
#include <utility>
std::vector<int> hailstone(int i)
{
std::vector<int> v;
while(true){
v.push_back(i);
if (1 == i) break;
i = (i % 2) ? (3 * i + 1) : (i / 2);
}
return v;
}
std::pair<int,int> find_longest_hailstone_seq(int n)
{
std::pair<int, int> maxseq(0, 0);
int l;
for(int i = 1; i < n; ++i){
l = hailstone(i).size();
if (l > maxseq.second) maxseq = std::make_pair(i, l);
}
return maxseq;
}
int main () {
std::vector<int> h27;
h27 = hailstone(27);
int l = h27.size();
std::cout << "length of hailstone(27) is " << l;
std::cout << " first four elements of hailstone(27) are ";
std::cout << h27[0] << " " << h27[1] << " "
<< h27[2] << " " << h27[3] << std::endl;
std::cout << " last four elements of hailstone(27) are "
<< h27[l-4] << " " << h27[l-3] << " "
<< h27[l-2] << " " << h27[l-1] << std::endl;
std::pair<int,int> m = find_longest_hailstone_seq(100000);
std::cout << "the longest hailstone sequence under 100,000 is " << m.first
<< " with " << m.second << " elements." <<std::endl;
return 0;
}
| fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
|
Write the same code in Python as shown below in Rust. | fn hailstone(start : u32) -> Vec<u32> {
let mut res = Vec::new();
let mut next = start;
res.push(start);
while next != 1 {
next = if next % 2 == 0 { next/2 } else { 3*next+1 };
res.push(next);
}
res
}
fn main() {
let test_num = 27;
let test_hailseq = hailstone(test_num);
println!("For {} number of elements is {} ", test_num, test_hailseq.len());
let fst_slice = test_hailseq[0..4].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
let last_slice = test_hailseq[test_hailseq.len()-4..].iter()
.fold("".to_owned(), |acc, i| { acc + &*(i.to_string()).to_owned() + ", " });
println!(" hailstone starting with {} ending with {} ", fst_slice, last_slice);
let max_range = 100000;
let mut max_len = 0;
let mut max_seed = 0;
for i_seed in 1..max_range {
let i_len = hailstone(i_seed).len();
if i_len > max_len {
max_len = i_len;
max_seed = i_seed;
}
}
println!("Longest sequence is {} element long for seed {}", max_len, max_seed);
}
| def hailstone(n):
seq = [n]
while n>1:
n = 3*n + 1 if n & 1 else n//2
seq.append(n)
return seq
if __name__ == '__main__':
h = hailstone(27)
assert len(h)==112 and h[:4]==[27, 82, 41, 124] and h[-4:]==[8, 4, 2, 1]
print("Maximum length %i was found for hailstone(%i) for numbers <100,000" %
max((len(hailstone(i)), i) for i in range(1,100000)))
|
Write a version of this Ada function in C# with identical behavior. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Maintain the same structure and functionality when rewriting this code in C#. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Write the same code in C as shown below in Ada. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Produce a functionally identical C code for the snippet given in Ada. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Port the following code from Ada to C++ with equivalent syntax and logic. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Convert this Ada block to C++, preserving its control flow and logic. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Preserve the algorithm and functionality while converting the code from Ada to Go. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Keep all operations the same but rewrite the snippet in Go. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Rewrite this program in Java while keeping its functionality equivalent to the Ada version. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Port the following code from Ada to Java with equivalent syntax and logic. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Translate this program into Python but keep the logic exactly as in Ada. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Change the following Ada code into Python without altering its purpose. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Ensure the translated VB code behaves exactly like the original Ada snippet. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Generate a VB translation of this Ada snippet without changing its computational steps. | with Ada.Text_IO; use Ada.Text_IO;
procedure Mfact is
function MultiFact (num : Natural; deg : Positive) return Natural is
Result, N : Integer := num;
begin
if N = 0 then return 1; end if;
loop
N := N - deg; exit when N <= 0; Result := Result * N;
end loop; return Result;
end MultiFact;
begin
for deg in 1..5 loop
Put("Degree"& Integer'Image(deg) &":");
for num in 1..10 loop Put(Integer'Image(MultiFact(num,deg))); end loop;
New_line;
end loop;
end Mfact;
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Transform the following Arturo implementation into C, maintaining the same output and logic. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Keep all operations the same but rewrite the snippet in C. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Write a version of this Arturo function in C# with identical behavior. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Produce a language-to-language conversion: from Arturo to C#, same semantics. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Ensure the translated C++ code behaves exactly like the original Arturo snippet. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Transform the following Arturo implementation into C++, maintaining the same output and logic. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Port the provided Arturo code into Java while preserving the original functionality. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Rewrite this program in Java while keeping its functionality equivalent to the Arturo version. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Change the programming language of this snippet from Arturo to Python without modifying what it does. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Port the provided Arturo code into Python while preserving the original functionality. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Rewrite the snippet below in VB so it works the same as the original Arturo code. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Change the following Arturo code into VB without altering its purpose. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Convert this Arturo snippet to Go and keep its semantics consistent. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Write the same algorithm in Go as shown in this Arturo implementation. | multifact: function [n deg][
if? n =< deg -> n
else -> n * multifact n-deg deg
]
loop 1..5 'i [
prints ["Degree" i ":"]
loop 1..10 'j [
prints [multifact j i " "]
]
print ""
]
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Port the following code from AutoHotKey to C with equivalent syntax and logic. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Ensure the translated C code behaves exactly like the original AutoHotKey snippet. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Produce a functionally identical C# code for the snippet given in AutoHotKey. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Port the following code from AutoHotKey to C# with equivalent syntax and logic. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Generate a C++ translation of this AutoHotKey snippet without changing its computational steps. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Port the following code from AutoHotKey to C++ with equivalent syntax and logic. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Convert this AutoHotKey snippet to Java and keep its semantics consistent. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Port the provided AutoHotKey code into Java while preserving the original functionality. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Transform the following AutoHotKey implementation into Python, maintaining the same output and logic. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Rewrite this program in Python while keeping its functionality equivalent to the AutoHotKey version. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Rewrite the snippet below in VB so it works the same as the original AutoHotKey code. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Ensure the translated VB code behaves exactly like the original AutoHotKey snippet. | Loop, 5 {
Output .= "Degree " (i := A_Index) ": "
Loop, 10
Output .= MultiFact(A_Index, i) (A_Index = 10 ? "`n" : ", ")
}
MsgBox, % Output
MultiFact(n, d) {
Result := n
while 1 < n -= d
Result *= n
return, Result
}
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
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