Instruction stringlengths 45 106 | input_code stringlengths 1 13.7k | output_code stringlengths 1 13.7k |
|---|---|---|
Can you help me rewrite this code in C instead of F#, keeping it the same logically? | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Port the following code from F# to C# with equivalent syntax and logic. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Maintain the same structure and functionality when rewriting this code in C#. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Port the following code from F# to C++ with equivalent syntax and logic. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Ensure the translated C++ code behaves exactly like the original F# snippet. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Translate this program into Java but keep the logic exactly as in F#. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Please provide an equivalent version of this F# code in Java. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Write the same algorithm in Python as shown in this F# implementation. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Maintain the same structure and functionality when rewriting this code in Python. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Please provide an equivalent version of this F# code in VB. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Convert the following code from F# to VB, ensuring the logic remains intact. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Keep all operations the same but rewrite the snippet in Go. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Keep all operations the same but rewrite the snippet in Go. | let rec mfact d = function
| n when n <= d -> n
| n -> n * mfact d (n-d)
[<EntryPoint>]
let main argv =
let (|UInt|_|) = System.UInt32.TryParse >> function | true, v -> Some v | false, _ -> None
let (maxDegree, maxN) =
match argv with
| [| UInt d; UInt n |] -> (int d, int n)
| [| UInt d |] -> (int d, 10)
| _ -> (5, 10)
let showFor d = List.init maxN (fun i -> mfact d (i+1)) |> printfn "%i: %A" d
ignore (List.init maxDegree (fun i -> showFor (i+1)))
0
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Port the provided Fortran code into C# while preserving the original functionality. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Convert this Fortran block to C#, preserving its control flow and logic. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Produce a language-to-language conversion: from Fortran to C++, same semantics. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Generate an equivalent C++ version of this Fortran code. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Rewrite this program in C while keeping its functionality equivalent to the Fortran version. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Translate the given Fortran code snippet into C without altering its behavior. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Ensure the translated Java code behaves exactly like the original Fortran snippet. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Write the same algorithm in Java as shown in this Fortran implementation. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Rewrite this program in Python while keeping its functionality equivalent to the Fortran version. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Convert this Fortran block to Python, preserving its control flow and logic. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Rewrite this program in VB while keeping its functionality equivalent to the Fortran version. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Convert this Fortran snippet to VB and keep its semantics consistent. | program test
implicit none
integer :: i, j, n
do i = 1, 5
write(*, "(a, i0, a)", advance = "no") "Degree ", i, ": "
do j = 1, 10
n = multifactorial(j, i)
write(*, "(i0, 1x)", advance = "no") n
end do
write(*,*)
end do
contains
function multifactorial (range, degree)
integer :: multifactorial, range, degree
integer :: k
multifactorial = product((/(k, k=range, 1, -degree)/))
end function multifactorial
end program test
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Keep all operations the same but rewrite the snippet in C. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Produce a functionally identical C code for the snippet given in Haskell. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Write the same algorithm in C# as shown in this Haskell implementation. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Can you help me rewrite this code in C# instead of Haskell, keeping it the same logically? | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Produce a functionally identical C++ code for the snippet given in Haskell. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Generate an equivalent C++ version of this Haskell code. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Keep all operations the same but rewrite the snippet in Java. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Rewrite the snippet below in Java so it works the same as the original Haskell code. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Transform the following Haskell implementation into Python, maintaining the same output and logic. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Port the provided Haskell code into Python while preserving the original functionality. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Preserve the algorithm and functionality while converting the code from Haskell to VB. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Ensure the translated VB code behaves exactly like the original Haskell snippet. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Produce a functionally identical Go code for the snippet given in Haskell. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Convert this Haskell snippet to Go and keep its semantics consistent. | mulfac :: (Num a, Enum a) => a -> [a]
mulfac k = 1 : s
where
s = [1 .. k] <> zipWith (*) s [k + 1 ..]
mulfac1 :: (Num a, Enum a) => a -> a -> a
mulfac1 k n = product [n, n - k .. 1]
main :: IO ()
main =
mapM_
(print . take 10 . tail . mulfac)
[1 .. 5]
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Rewrite this program in C while keeping its functionality equivalent to the J version. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Write the same algorithm in C as shown in this J implementation. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Generate an equivalent C# version of this J code. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Please provide an equivalent version of this J code in C#. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Change the programming language of this snippet from J to C++ without modifying what it does. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Generate a C++ translation of this J snippet without changing its computational steps. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Write the same algorithm in Java as shown in this J implementation. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Produce a language-to-language conversion: from J to Java, same semantics. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Produce a language-to-language conversion: from J to Python, same semantics. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Keep all operations the same but rewrite the snippet in Python. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Write the same algorithm in VB as shown in this J implementation. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Generate a VB translation of this J snippet without changing its computational steps. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Generate an equivalent Go version of this J code. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Please provide an equivalent version of this J code in Go. |
multifact=: */@([ - ] * i.@>.@%)&>
('';' degree'),multifact table >:i.10
┌─────────┬──────────────────────────────────────┐
│ │ degree │
├─────────┼──────────────────────────────────────┤
│multifact│ 1 2 3 4 5 6 7 8 9 10│
├─────────┼──────────────────────────────────────┤
│ 1 │ 1 1 1 1 1 1 1 1 1 1│
│ 2 │ 2 2 2 2 2 2 2 2 2 2│
│ 3 │ 6 3 3 3 3 3 3 3 3 3│
│ 4 │ 24 8 4 4 4 4 4 4 4 4│
│ 5 │ 120 15 10 5 5 5 5 5 5 5│
│ 6 │ 720 48 18 12 6 6 6 6 6 6│
│ 7 │ 5040 105 28 21 14 7 7 7 7 7│
│ 8 │ 40320 384 80 32 24 16 8 8 8 8│
│ 9 │ 362880 945 162 45 36 27 18 9 9 9│
│10 │3628800 3840 280 120 50 40 30 20 10 10│
└─────────┴──────────────────────────────────────┘
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Rewrite this program in C while keeping its functionality equivalent to the Julia version. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Generate an equivalent C version of this Julia code. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Transform the following Julia implementation into C#, maintaining the same output and logic. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Change the programming language of this snippet from Julia to C# without modifying what it does. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Produce a functionally identical C++ code for the snippet given in Julia. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Convert this Julia block to C++, preserving its control flow and logic. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Translate this program into Java but keep the logic exactly as in Julia. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Maintain the same structure and functionality when rewriting this code in Java. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Produce a functionally identical Python code for the snippet given in Julia. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Produce a language-to-language conversion: from Julia to Python, same semantics. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Port the following code from Julia to VB with equivalent syntax and logic. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Rewrite this program in VB while keeping its functionality equivalent to the Julia version. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Maintain the same structure and functionality when rewriting this code in Go. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Port the provided Julia code into Go while preserving the original functionality. | using Printf
function multifact(n::Integer, k::Integer)
n > 0 && k > 0 || throw(DomainError())
k > 1 || factorial(n)
return prod(n:-k:2)
end
const khi = 5
const nhi = 10
println("Showing multifactorial for n in [1, $nhi] and k in [1, $khi].")
for k = 1:khi
a = multifact.(1:nhi, k)
lab = "n" * "!" ^ k
@printf(" %-6s → %s\n", lab, a)
end
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Convert this Lua block to C, preserving its control flow and logic. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Convert this Lua snippet to C and keep its semantics consistent. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Translate this program into C# but keep the logic exactly as in Lua. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Ensure the translated C# code behaves exactly like the original Lua snippet. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Write a version of this Lua function in C++ with identical behavior. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Convert the following code from Lua to C++, ensuring the logic remains intact. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Maintain the same structure and functionality when rewriting this code in Java. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Keep all operations the same but rewrite the snippet in Java. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Change the programming language of this snippet from Lua to Python without modifying what it does. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Produce a language-to-language conversion: from Lua to Python, same semantics. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Maintain the same structure and functionality when rewriting this code in VB. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Convert this Lua snippet to VB and keep its semantics consistent. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Produce a functionally identical Go code for the snippet given in Lua. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Keep all operations the same but rewrite the snippet in Go. | function multiFact (n, degree)
local fact = 1
for i = n, 2, -degree do
fact = fact * i
end
return fact
end
print("Degree\t|\tMultifactorials 1 to 10")
print(string.rep("-", 52))
for d = 1, 5 do
io.write(" " .. d, "\t| ")
for n = 1, 10 do
io.write(multiFact(n, d) .. " ")
end
print()
end
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Generate a C translation of this Mathematica snippet without changing its computational steps. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Produce a functionally identical C code for the snippet given in Mathematica. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Write the same code in C# as shown below in Mathematica. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Rewrite this program in C# while keeping its functionality equivalent to the Mathematica version. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Ensure the translated C++ code behaves exactly like the original Mathematica snippet. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Keep all operations the same but rewrite the snippet in C++. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Write the same code in Java as shown below in Mathematica. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Produce a language-to-language conversion: from Mathematica to Java, same semantics. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
System.out.print(" " + multiFact(n, deg));
}
System.out.println();
}
}
}
|
Generate a Python translation of this Mathematica snippet without changing its computational steps. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Please provide an equivalent version of this Mathematica code in Python. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2, 3, 4, 10, 18, 28, 80, 162, 280]
4: [1, 2, 3, 4, 5, 12, 21, 32, 45, 120]
5: [1, 2, 3, 4, 5, 6, 14, 24, 36, 50]
6: [1, 2, 3, 4, 5, 6, 7, 16, 27, 40]
7: [1, 2, 3, 4, 5, 6, 7, 8, 18, 30]
8: [1, 2, 3, 4, 5, 6, 7, 8, 9, 20]
9: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>>
|
Write the same algorithm in VB as shown in this Mathematica implementation. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Transform the following Mathematica implementation into VB, maintaining the same output and logic. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WScript.StdOut.Write multifactorial(k,j)
Else
WScript.StdOut.Write multifactorial(k,j) & " "
End If
Next
WScript.StdOut.WriteLine
Next
|
Rewrite the snippet below in Go so it works the same as the original Mathematica code. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Generate an equivalent Go version of this Mathematica code. | Multifactorial[n_, d_] := Product[x, {x, n, 1, -d}]
Table[Multifactorial[j, i], {i, 5}, {j, 10}]//TableForm
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
fmt.Println()
}
}
|
Change the following Nim code into C without altering its purpose. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i), " "
stdout.write('\n')
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Please provide an equivalent version of this Nim code in C. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i), " "
stdout.write('\n')
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(void){
int i, j;
for (i = 1; i <= HIGHEST_DEGREE; i++){
printf("\nDegree %d: ", i);
for (j = 1; j <= LARGEST_NUMBER; j++){
printf("%d ", multifact(j, i));
}
}
}
|
Generate an equivalent C# version of this Nim code. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i), " "
stdout.write('\n')
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Please provide an equivalent version of this Nim code in C#. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i), " "
stdout.write('\n')
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
.Select(
degree =>
string.Join(" ",
Enumerable.Range(1, 10)
.Select(
number =>
Multifactorial(number, degree))))));
}
private static int Multifactorial(int number, int degree)
{
if (degree < 1)
{
throw new ArgumentOutOfRangeException("degree");
}
var count = 1 + (number - 1) / degree;
if (count < 1)
{
throw new ArgumentOutOfRangeException("number");
}
return Enumerable.Range(0, count)
.Aggregate(1, (accumulator, index) => accumulator * (number - degree * index));
}
}
}
|
Ensure the translated C++ code behaves exactly like the original Nim snippet. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i), " "
stdout.write('\n')
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
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