Instruction stringlengths 45 106 | input_code stringlengths 1 13.7k | output_code stringlengths 1 13.7k |
|---|---|---|
Write the same algorithm in C as shown in this Delphi implementation. | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Maintain the same structure and functionality when rewriting this code in C#. | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Can you help me rewrite this code in C# instead of Delphi, keeping it the same logically? | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Generate an equivalent C++ version of this Delphi code. | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Change the following Delphi code into C++ without altering its purpose. | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Generate an equivalent Java version of this Delphi code. | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Keep all operations the same but rewrite the snippet in Java. | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Produce a functionally identical Python code for the snippet given in Delphi. | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Maintain the same structure and functionality when rewriting this code in Python. | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Generate a VB translation of this Delphi snippet without changing its computational steps. | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Can you help me rewrite this code in VB instead of Delphi, keeping it the same logically? | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Can you help me rewrite this code in Go instead of Delphi, keeping it the same logically? | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Produce a language-to-language conversion: from Delphi to Go, same semantics. | program Project1;
type
doublearray = array of Double;
function DotProduct(const A, B : doublearray): Double;
var
I: integer;
begin
assert (Length(A) = Length(B), 'Input arrays must be the same length');
Result := 0;
for I := 0 to Length(A) - 1 do
Result := Result + (A[I] * B[I]);
end;
var
x,y: doublearray;
begin
SetLength(x, 3);
SetLength(y, 3);
x[0] := 1; x[1] := 3; x[2] := -5;
y[0] := 4; y[1] :=-2; y[2] := -1;
WriteLn(DotProduct(x,y));
ReadLn;
end.
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Rewrite the snippet below in C so it works the same as the original Elixir code. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Keep all operations the same but rewrite the snippet in C. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Produce a functionally identical C# code for the snippet given in Elixir. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Please provide an equivalent version of this Elixir code in C++. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Translate the given Elixir code snippet into C++ without altering its behavior. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Produce a functionally identical Java code for the snippet given in Elixir. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Preserve the algorithm and functionality while converting the code from Elixir to Java. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Preserve the algorithm and functionality while converting the code from Elixir to Python. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Keep all operations the same but rewrite the snippet in Python. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Convert this Elixir snippet to VB and keep its semantics consistent. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Generate an equivalent VB version of this Elixir code. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Preserve the algorithm and functionality while converting the code from Elixir to Go. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Keep all operations the same but rewrite the snippet in Go. | defmodule Vector do
def dot_product(a,b) when length(a)==length(b), do: dot_product(a,b,0)
def dot_product(_,_) do
raise ArgumentError, message: "Vectors must have the same length."
end
defp dot_product([],[],product), do: product
defp dot_product([h1|t1], [h2|t2], product), do: dot_product(t1, t2, product+h1*h2)
end
IO.puts Vector.dot_product([1,3,-5],[4,-2,-1])
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Transform the following Erlang implementation into C, maintaining the same output and logic. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Generate a C translation of this Erlang snippet without changing its computational steps. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Can you help me rewrite this code in C# instead of Erlang, keeping it the same logically? | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Translate this program into C# but keep the logic exactly as in Erlang. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Can you help me rewrite this code in C++ instead of Erlang, keeping it the same logically? | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Ensure the translated C++ code behaves exactly like the original Erlang snippet. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Change the programming language of this snippet from Erlang to Java without modifying what it does. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Ensure the translated Java code behaves exactly like the original Erlang snippet. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Convert the following code from Erlang to Python, ensuring the logic remains intact. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Ensure the translated Python code behaves exactly like the original Erlang snippet. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Please provide an equivalent version of this Erlang code in VB. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Rewrite this program in VB while keeping its functionality equivalent to the Erlang version. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Maintain the same structure and functionality when rewriting this code in Go. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Change the following Erlang code into Go without altering its purpose. | dotProduct(A,B) when length(A) == length(B) -> dotProduct(A,B,0);
dotProduct(_,_) -> erlang:error('Vectors must have the same length.').
dotProduct([H1|T1],[H2|T2],P) -> dotProduct(T1,T2,P+H1*H2);
dotProduct([],[],P) -> P.
dotProduct([1,3,-5],[4,-2,-1]).
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Port the provided F# code into C while preserving the original functionality. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Convert this F# block to C, preserving its control flow and logic. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Transform the following F# implementation into C#, maintaining the same output and logic. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Transform the following F# implementation into C#, maintaining the same output and logic. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Port the provided F# code into C++ while preserving the original functionality. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Write a version of this F# function in C++ with identical behavior. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Translate the given F# code snippet into Java without altering its behavior. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Keep all operations the same but rewrite the snippet in Java. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Convert this F# snippet to Python and keep its semantics consistent. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Generate an equivalent Python version of this F# code. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Convert this F# block to VB, preserving its control flow and logic. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Write the same algorithm in VB as shown in this F# implementation. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Port the following code from F# to Go with equivalent syntax and logic. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Maintain the same structure and functionality when rewriting this code in Go. | let dot_product (a:array<'a>) (b:array<'a>) =
if Array.length a <> Array.length b then failwith "invalid argument: vectors must have the same lengths"
Array.fold2 (fun acc i j -> acc + (i * j)) 0 a b
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Please provide an equivalent version of this Factor code in C. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Produce a language-to-language conversion: from Factor to C, same semantics. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Convert this Factor block to C#, preserving its control flow and logic. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Generate a C# translation of this Factor snippet without changing its computational steps. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Port the following code from Factor to C++ with equivalent syntax and logic. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Write the same code in C++ as shown below in Factor. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Generate an equivalent Java version of this Factor code. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Generate an equivalent Java version of this Factor code. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Convert the following code from Factor to Python, ensuring the logic remains intact. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Rewrite this program in Python while keeping its functionality equivalent to the Factor version. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Convert this Factor block to VB, preserving its control flow and logic. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Convert the following code from Factor to VB, ensuring the logic remains intact. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Change the following Factor code into Go without altering its purpose. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Convert this Factor snippet to Go and keep its semantics consistent. | USING: kernel math.vectors sequences ;
: dot-product ( u v -- w )
2dup [ length ] bi@ =
[ v. ] [ "Vector lengths must be equal" throw ] if ;
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Keep all operations the same but rewrite the snippet in C. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Ensure the translated C code behaves exactly like the original Forth snippet. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Generate a C# translation of this Forth snippet without changing its computational steps. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Change the programming language of this snippet from Forth to C# without modifying what it does. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Translate this program into C++ but keep the logic exactly as in Forth. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Preserve the algorithm and functionality while converting the code from Forth to C++. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Change the following Forth code into Java without altering its purpose. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Convert this Forth block to Java, preserving its control flow and logic. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Rewrite this program in Python while keeping its functionality equivalent to the Forth version. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Convert this Forth block to Python, preserving its control flow and logic. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Generate an equivalent VB version of this Forth code. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Can you help me rewrite this code in VB instead of Forth, keeping it the same logically? | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Generate an equivalent Go version of this Forth code. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Convert the following code from Forth to Go, ensuring the logic remains intact. | [1,3,-5] [4,-2,-1] ' n:* ' n:+ a:dot . cr
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Write the same algorithm in C# as shown in this Fortran implementation. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Change the following Fortran code into C# without altering its purpose. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
Rewrite this program in C++ while keeping its functionality equivalent to the Fortran version. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Preserve the algorithm and functionality while converting the code from Fortran to C++. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| #include <iostream>
#include <numeric>
int main()
{
int a[] = { 1, 3, -5 };
int b[] = { 4, -2, -1 };
std::cout << std::inner_product(a, a + sizeof(a) / sizeof(a[0]), b, 0) << std::endl;
return 0;
}
|
Rewrite the snippet below in C so it works the same as the original Fortran code. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Ensure the translated C code behaves exactly like the original Fortran snippet. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Rewrite the snippet below in Go so it works the same as the original Fortran code. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| package main
import (
"errors"
"fmt"
"log"
)
var (
v1 = []int{1, 3, -5}
v2 = []int{4, -2, -1}
)
func dot(x, y []int) (r int, err error) {
if len(x) != len(y) {
return 0, errors.New("incompatible lengths")
}
for i, xi := range x {
r += xi * y[i]
}
return
}
func main() {
d, err := dot([]int{1, 3, -5}, []int{4, -2, -1})
if err != nil {
log.Fatal(err)
}
fmt.Println(d)
}
|
Can you help me rewrite this code in Java instead of Fortran, keeping it the same logically? | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Produce a language-to-language conversion: from Fortran to Java, same semantics. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| public class DotProduct {
public static void main(String[] args) {
double[] a = {1, 3, -5};
double[] b = {4, -2, -1};
System.out.println(dotProd(a,b));
}
public static double dotProd(double[] a, double[] b){
if(a.length != b.length){
throw new IllegalArgumentException("The dimensions have to be equal!");
}
double sum = 0;
for(int i = 0; i < a.length; i++){
sum += a[i] * b[i];
}
return sum;
}
}
|
Convert this Fortran block to Python, preserving its control flow and logic. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Produce a language-to-language conversion: from Fortran to Python, same semantics. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| def dotp(a,b):
assert len(a) == len(b), 'Vector sizes must match'
return sum(aterm * bterm for aterm,bterm in zip(a, b))
if __name__ == '__main__':
a, b = [1, 3, -5], [4, -2, -1]
assert dotp(a,b) == 3
|
Produce a language-to-language conversion: from Fortran to VB, same semantics. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Translate this program into VB but keep the logic exactly as in Fortran. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| Private Function dot_product(x As Variant, y As Variant) As Double
dot_product = WorksheetFunction.SumProduct(x, y)
End Function
Public Sub main()
Debug.Print dot_product([{1,3,-5}], [{4,-2,-1}])
End Sub
|
Transform the following Fortran implementation into PHP, maintaining the same output and logic. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| <?php
function dot_product($v1, $v2) {
if (count($v1) != count($v2))
throw new Exception('Arrays have different lengths');
return array_sum(array_map('bcmul', $v1, $v2));
}
echo dot_product(array(1, 3, -5), array(4, -2, -1)), "\n";
?>
|
Rewrite the snippet below in PHP so it works the same as the original Fortran code. | program test_dot_product
write (*, '(i0)') dot_product ([1, 3, -5], [4, -2, -1])
end program test_dot_product
| <?php
function dot_product($v1, $v2) {
if (count($v1) != count($v2))
throw new Exception('Arrays have different lengths');
return array_sum(array_map('bcmul', $v1, $v2));
}
echo dot_product(array(1, 3, -5), array(4, -2, -1)), "\n";
?>
|
Convert this Groovy snippet to C and keep its semantics consistent. | def dotProduct = { x, y ->
assert x && y && x.size() == y.size()
[x, y].transpose().collect{ xx, yy -> xx * yy }.sum()
}
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Can you help me rewrite this code in C instead of Groovy, keeping it the same logically? | def dotProduct = { x, y ->
assert x && y && x.size() == y.size()
[x, y].transpose().collect{ xx, yy -> xx * yy }.sum()
}
| #include <stdio.h>
#include <stdlib.h>
int dot_product(int *, int *, size_t);
int
main(void)
{
int a[3] = {1, 3, -5};
int b[3] = {4, -2, -1};
printf("%d\n", dot_product(a, b, sizeof(a) / sizeof(a[0])));
return EXIT_SUCCESS;
}
int
dot_product(int *a, int *b, size_t n)
{
int sum = 0;
size_t i;
for (i = 0; i < n; i++) {
sum += a[i] * b[i];
}
return sum;
}
|
Convert this Groovy snippet to C# and keep its semantics consistent. | def dotProduct = { x, y ->
assert x && y && x.size() == y.size()
[x, y].transpose().collect{ xx, yy -> xx * yy }.sum()
}
| static void Main(string[] args)
{
Console.WriteLine(DotProduct(new decimal[] { 1, 3, -5 }, new decimal[] { 4, -2, -1 }));
Console.Read();
}
private static decimal DotProduct(decimal[] vec1, decimal[] vec2)
{
if (vec1 == null)
return 0;
if (vec2 == null)
return 0;
if (vec1.Length != vec2.Length)
return 0;
decimal tVal = 0;
for (int x = 0; x < vec1.Length; x++)
{
tVal += vec1[x] * vec2[x];
}
return tVal;
}
|
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