Instruction stringlengths 45 106 | input_code stringlengths 1 13.7k | output_code stringlengths 1 13.7k |
|---|---|---|
Rewrite the snippet below in Java so it works the same as the original REXX code. |
options replace format comments java crossref symbols nobinary utf8
numeric digits 5000 -- set up numeric precision
babbageNr = babbage() -- call a function to perform the analysis and capture the result
babbageSq = babbageNr ** 2 -- calculate the square of the result
-- display results using a library function
System.out.printf("%,10d\u00b2 == %,12d%n", [Integer(babbageNr), Integer(babbageSq)])
return
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-- A function method to answer Babbage's question:
-- "What is the smallest positive integer whose square ends in the digits 269,696?"
-- — Babbage, letter to Lord Bowden, 1837;
-- see Hollingdale and Tootill, Electronic Computers, second edition, 1970, p. 125.
-- (He thought the answer might be 99,736, whose square is 9,947,269,696; but he couldn't be certain.)
method babbage() public static binary
n = int 104 -- (integer arithmatic)
-- begin a processing loop to determine the value
-- starting point: 104
loop while ((n * n) // 1000000) \= 269696
-- loop continues while the remainder of n squared divided by 1,000,000 is not equal to 269,696
if n // 10 == 4 then do
-- increment n by 2 if the remainder of n divided by 10 equals 4
n = n + 2
end
if n // 10 == 6 then do
-- increment n by 8 if the remainder of n divided by 10 equals 6
n = n + 8
end
end
return n -- end the function and return the result
| public class Test {
public static void main(String[] args) {
int n = 0;
do {
n++;
} while (n * n % 1000_000 != 269696);
System.out.println(n);
}
}
|
Translate this program into Java but keep the logic exactly as in REXX. |
options replace format comments java crossref symbols nobinary utf8
numeric digits 5000 -- set up numeric precision
babbageNr = babbage() -- call a function to perform the analysis and capture the result
babbageSq = babbageNr ** 2 -- calculate the square of the result
-- display results using a library function
System.out.printf("%,10d\u00b2 == %,12d%n", [Integer(babbageNr), Integer(babbageSq)])
return
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-- A function method to answer Babbage's question:
-- "What is the smallest positive integer whose square ends in the digits 269,696?"
-- — Babbage, letter to Lord Bowden, 1837;
-- see Hollingdale and Tootill, Electronic Computers, second edition, 1970, p. 125.
-- (He thought the answer might be 99,736, whose square is 9,947,269,696; but he couldn't be certain.)
method babbage() public static binary
n = int 104 -- (integer arithmatic)
-- begin a processing loop to determine the value
-- starting point: 104
loop while ((n * n) // 1000000) \= 269696
-- loop continues while the remainder of n squared divided by 1,000,000 is not equal to 269,696
if n // 10 == 4 then do
-- increment n by 2 if the remainder of n divided by 10 equals 4
n = n + 2
end
if n // 10 == 6 then do
-- increment n by 8 if the remainder of n divided by 10 equals 6
n = n + 8
end
end
return n -- end the function and return the result
| public class Test {
public static void main(String[] args) {
int n = 0;
do {
n++;
} while (n * n % 1000_000 != 269696);
System.out.println(n);
}
}
|
Preserve the algorithm and functionality while converting the code from REXX to Python. |
options replace format comments java crossref symbols nobinary utf8
numeric digits 5000 -- set up numeric precision
babbageNr = babbage() -- call a function to perform the analysis and capture the result
babbageSq = babbageNr ** 2 -- calculate the square of the result
-- display results using a library function
System.out.printf("%,10d\u00b2 == %,12d%n", [Integer(babbageNr), Integer(babbageSq)])
return
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-- A function method to answer Babbage's question:
-- "What is the smallest positive integer whose square ends in the digits 269,696?"
-- — Babbage, letter to Lord Bowden, 1837;
-- see Hollingdale and Tootill, Electronic Computers, second edition, 1970, p. 125.
-- (He thought the answer might be 99,736, whose square is 9,947,269,696; but he couldn't be certain.)
method babbage() public static binary
n = int 104 -- (integer arithmatic)
-- begin a processing loop to determine the value
-- starting point: 104
loop while ((n * n) // 1000000) \= 269696
-- loop continues while the remainder of n squared divided by 1,000,000 is not equal to 269,696
if n // 10 == 4 then do
-- increment n by 2 if the remainder of n divided by 10 equals 4
n = n + 2
end
if n // 10 == 6 then do
-- increment n by 8 if the remainder of n divided by 10 equals 6
n = n + 8
end
end
return n -- end the function and return the result
|
n=0
while n**2 % 1000000 != 269696:
n += 1
print(n)
|
Generate a Python translation of this REXX snippet without changing its computational steps. |
options replace format comments java crossref symbols nobinary utf8
numeric digits 5000 -- set up numeric precision
babbageNr = babbage() -- call a function to perform the analysis and capture the result
babbageSq = babbageNr ** 2 -- calculate the square of the result
-- display results using a library function
System.out.printf("%,10d\u00b2 == %,12d%n", [Integer(babbageNr), Integer(babbageSq)])
return
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-- A function method to answer Babbage's question:
-- "What is the smallest positive integer whose square ends in the digits 269,696?"
-- — Babbage, letter to Lord Bowden, 1837;
-- see Hollingdale and Tootill, Electronic Computers, second edition, 1970, p. 125.
-- (He thought the answer might be 99,736, whose square is 9,947,269,696; but he couldn't be certain.)
method babbage() public static binary
n = int 104 -- (integer arithmatic)
-- begin a processing loop to determine the value
-- starting point: 104
loop while ((n * n) // 1000000) \= 269696
-- loop continues while the remainder of n squared divided by 1,000,000 is not equal to 269,696
if n // 10 == 4 then do
-- increment n by 2 if the remainder of n divided by 10 equals 4
n = n + 2
end
if n // 10 == 6 then do
-- increment n by 8 if the remainder of n divided by 10 equals 6
n = n + 8
end
end
return n -- end the function and return the result
|
n=0
while n**2 % 1000000 != 269696:
n += 1
print(n)
|
Produce a language-to-language conversion: from REXX to VB, same semantics. |
options replace format comments java crossref symbols nobinary utf8
numeric digits 5000 -- set up numeric precision
babbageNr = babbage() -- call a function to perform the analysis and capture the result
babbageSq = babbageNr ** 2 -- calculate the square of the result
-- display results using a library function
System.out.printf("%,10d\u00b2 == %,12d%n", [Integer(babbageNr), Integer(babbageSq)])
return
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-- A function method to answer Babbage's question:
-- "What is the smallest positive integer whose square ends in the digits 269,696?"
-- — Babbage, letter to Lord Bowden, 1837;
-- see Hollingdale and Tootill, Electronic Computers, second edition, 1970, p. 125.
-- (He thought the answer might be 99,736, whose square is 9,947,269,696; but he couldn't be certain.)
method babbage() public static binary
n = int 104 -- (integer arithmatic)
-- begin a processing loop to determine the value
-- starting point: 104
loop while ((n * n) // 1000000) \= 269696
-- loop continues while the remainder of n squared divided by 1,000,000 is not equal to 269,696
if n // 10 == 4 then do
-- increment n by 2 if the remainder of n divided by 10 equals 4
n = n + 2
end
if n // 10 == 6 then do
-- increment n by 8 if the remainder of n divided by 10 equals 6
n = n + 8
end
end
return n -- end the function and return the result
| Sub Baggage_Problem()
Dim i As Long
i = 520
Do While ((i * i) Mod 1000000) <> 269696
i = i + 4
Loop
Debug.Print "The smallest positive integer whose square ends in the digits 269 696 is : " & i & vbCrLf & _
"Its square is : " & i * i
End Sub
|
Convert this REXX snippet to VB and keep its semantics consistent. |
options replace format comments java crossref symbols nobinary utf8
numeric digits 5000 -- set up numeric precision
babbageNr = babbage() -- call a function to perform the analysis and capture the result
babbageSq = babbageNr ** 2 -- calculate the square of the result
-- display results using a library function
System.out.printf("%,10d\u00b2 == %,12d%n", [Integer(babbageNr), Integer(babbageSq)])
return
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-- A function method to answer Babbage's question:
-- "What is the smallest positive integer whose square ends in the digits 269,696?"
-- — Babbage, letter to Lord Bowden, 1837;
-- see Hollingdale and Tootill, Electronic Computers, second edition, 1970, p. 125.
-- (He thought the answer might be 99,736, whose square is 9,947,269,696; but he couldn't be certain.)
method babbage() public static binary
n = int 104 -- (integer arithmatic)
-- begin a processing loop to determine the value
-- starting point: 104
loop while ((n * n) // 1000000) \= 269696
-- loop continues while the remainder of n squared divided by 1,000,000 is not equal to 269,696
if n // 10 == 4 then do
-- increment n by 2 if the remainder of n divided by 10 equals 4
n = n + 2
end
if n // 10 == 6 then do
-- increment n by 8 if the remainder of n divided by 10 equals 6
n = n + 8
end
end
return n -- end the function and return the result
| Sub Baggage_Problem()
Dim i As Long
i = 520
Do While ((i * i) Mod 1000000) <> 269696
i = i + 4
Loop
Debug.Print "The smallest positive integer whose square ends in the digits 269 696 is : " & i & vbCrLf & _
"Its square is : " & i * i
End Sub
|
Change the following REXX code into Go without altering its purpose. |
options replace format comments java crossref symbols nobinary utf8
numeric digits 5000 -- set up numeric precision
babbageNr = babbage() -- call a function to perform the analysis and capture the result
babbageSq = babbageNr ** 2 -- calculate the square of the result
-- display results using a library function
System.out.printf("%,10d\u00b2 == %,12d%n", [Integer(babbageNr), Integer(babbageSq)])
return
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-- A function method to answer Babbage's question:
-- "What is the smallest positive integer whose square ends in the digits 269,696?"
-- — Babbage, letter to Lord Bowden, 1837;
-- see Hollingdale and Tootill, Electronic Computers, second edition, 1970, p. 125.
-- (He thought the answer might be 99,736, whose square is 9,947,269,696; but he couldn't be certain.)
method babbage() public static binary
n = int 104 -- (integer arithmatic)
-- begin a processing loop to determine the value
-- starting point: 104
loop while ((n * n) // 1000000) \= 269696
-- loop continues while the remainder of n squared divided by 1,000,000 is not equal to 269,696
if n // 10 == 4 then do
-- increment n by 2 if the remainder of n divided by 10 equals 4
n = n + 2
end
if n // 10 == 6 then do
-- increment n by 8 if the remainder of n divided by 10 equals 6
n = n + 8
end
end
return n -- end the function and return the result
| package main
import "fmt"
func main() {
const (
target = 269696
modulus = 1000000
)
for n := 1; ; n++ {
square := n * n
ending := square % modulus
if ending == target {
fmt.Println("The smallest number whose square ends with",
target, "is", n,
)
return
}
}
}
|
Port the following code from REXX to Go with equivalent syntax and logic. |
options replace format comments java crossref symbols nobinary utf8
numeric digits 5000 -- set up numeric precision
babbageNr = babbage() -- call a function to perform the analysis and capture the result
babbageSq = babbageNr ** 2 -- calculate the square of the result
-- display results using a library function
System.out.printf("%,10d\u00b2 == %,12d%n", [Integer(babbageNr), Integer(babbageSq)])
return
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-- A function method to answer Babbage's question:
-- "What is the smallest positive integer whose square ends in the digits 269,696?"
-- — Babbage, letter to Lord Bowden, 1837;
-- see Hollingdale and Tootill, Electronic Computers, second edition, 1970, p. 125.
-- (He thought the answer might be 99,736, whose square is 9,947,269,696; but he couldn't be certain.)
method babbage() public static binary
n = int 104 -- (integer arithmatic)
-- begin a processing loop to determine the value
-- starting point: 104
loop while ((n * n) // 1000000) \= 269696
-- loop continues while the remainder of n squared divided by 1,000,000 is not equal to 269,696
if n // 10 == 4 then do
-- increment n by 2 if the remainder of n divided by 10 equals 4
n = n + 2
end
if n // 10 == 6 then do
-- increment n by 8 if the remainder of n divided by 10 equals 6
n = n + 8
end
end
return n -- end the function and return the result
| package main
import "fmt"
func main() {
const (
target = 269696
modulus = 1000000
)
for n := 1; ; n++ {
square := n * n
ending := square % modulus
if ending == target {
fmt.Println("The smallest number whose square ends with",
target, "is", n,
)
return
}
}
}
|
Produce a language-to-language conversion: from Ruby to C, same semantics. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
|
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
int main() {
int current = 0,
square;
while (((square=current*current) % 1000000 != 269696) && (square<INT_MAX)) {
current++;
}
if (square>+INT_MAX)
printf("Condition not satisfied before INT_MAX reached.");
else
printf ("The smallest number whose square ends in 269696 is %d\n", current);
return 0 ;
}
|
Convert this Ruby snippet to C and keep its semantics consistent. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
|
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
int main() {
int current = 0,
square;
while (((square=current*current) % 1000000 != 269696) && (square<INT_MAX)) {
current++;
}
if (square>+INT_MAX)
printf("Condition not satisfied before INT_MAX reached.");
else
printf ("The smallest number whose square ends in 269696 is %d\n", current);
return 0 ;
}
|
Rewrite this program in C# while keeping its functionality equivalent to the Ruby version. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
| namespace Babbage_Problem
{
class iterateNumbers
{
public iterateNumbers()
{
long baseNumberSquared = 0;
long baseNumber = 0;
do
{
baseNumber += 1;
baseNumberSquared = baseNumber * baseNumber;
}
while (Right6Digits(baseNumberSquared) != 269696);
Console.WriteLine("The smallest integer whose square ends in 269,696 is " + baseNumber);
Console.WriteLine("The square is " + baseNumberSquared);
}
private long Right6Digits(long baseNumberSquared)
{
string numberAsString = baseNumberSquared.ToString();
if (numberAsString.Length < 6) { return baseNumberSquared; };
numberAsString = numberAsString.Substring(numberAsString.Length - 6);
return long.Parse(numberAsString);
}
}
}}
|
Rewrite this program in C# while keeping its functionality equivalent to the Ruby version. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
| namespace Babbage_Problem
{
class iterateNumbers
{
public iterateNumbers()
{
long baseNumberSquared = 0;
long baseNumber = 0;
do
{
baseNumber += 1;
baseNumberSquared = baseNumber * baseNumber;
}
while (Right6Digits(baseNumberSquared) != 269696);
Console.WriteLine("The smallest integer whose square ends in 269,696 is " + baseNumber);
Console.WriteLine("The square is " + baseNumberSquared);
}
private long Right6Digits(long baseNumberSquared)
{
string numberAsString = baseNumberSquared.ToString();
if (numberAsString.Length < 6) { return baseNumberSquared; };
numberAsString = numberAsString.Substring(numberAsString.Length - 6);
return long.Parse(numberAsString);
}
}
}}
|
Rewrite the snippet below in C++ so it works the same as the original Ruby code. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
| #include <iostream>
int main( ) {
int current = 0 ;
while ( ( current * current ) % 1000000 != 269696 )
current++ ;
std::cout << "The square of " << current << " is " << (current * current) << " !\n" ;
return 0 ;
}
|
Write the same algorithm in C++ as shown in this Ruby implementation. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
| #include <iostream>
int main( ) {
int current = 0 ;
while ( ( current * current ) % 1000000 != 269696 )
current++ ;
std::cout << "The square of " << current << " is " << (current * current) << " !\n" ;
return 0 ;
}
|
Change the programming language of this snippet from Ruby to Java without modifying what it does. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
| public class Test {
public static void main(String[] args) {
int n = 0;
do {
n++;
} while (n * n % 1000_000 != 269696);
System.out.println(n);
}
}
|
Port the following code from Ruby to Java with equivalent syntax and logic. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
| public class Test {
public static void main(String[] args) {
int n = 0;
do {
n++;
} while (n * n % 1000_000 != 269696);
System.out.println(n);
}
}
|
Ensure the translated Python code behaves exactly like the original Ruby snippet. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
|
n=0
while n**2 % 1000000 != 269696:
n += 1
print(n)
|
Can you help me rewrite this code in Python instead of Ruby, keeping it the same logically? | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
|
n=0
while n**2 % 1000000 != 269696:
n += 1
print(n)
|
Transform the following Ruby implementation into VB, maintaining the same output and logic. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
| Sub Baggage_Problem()
Dim i As Long
i = 520
Do While ((i * i) Mod 1000000) <> 269696
i = i + 4
Loop
Debug.Print "The smallest positive integer whose square ends in the digits 269 696 is : " & i & vbCrLf & _
"Its square is : " & i * i
End Sub
|
Generate an equivalent VB version of this Ruby code. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
| Sub Baggage_Problem()
Dim i As Long
i = 520
Do While ((i * i) Mod 1000000) <> 269696
i = i + 4
Loop
Debug.Print "The smallest positive integer whose square ends in the digits 269 696 is : " & i & vbCrLf & _
"Its square is : " & i * i
End Sub
|
Convert the following code from Ruby to Go, ensuring the logic remains intact. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
| package main
import "fmt"
func main() {
const (
target = 269696
modulus = 1000000
)
for n := 1; ; n++ {
square := n * n
ending := square % modulus
if ending == target {
fmt.Println("The smallest number whose square ends with",
target, "is", n,
)
return
}
}
}
|
Write the same code in Go as shown below in Ruby. | n = 0
n = n + 2 until (n*n).modulo(1000000) == 269696
print n
| package main
import "fmt"
func main() {
const (
target = 269696
modulus = 1000000
)
for n := 1; ; n++ {
square := n * n
ending := square % modulus
if ending == target {
fmt.Println("The smallest number whose square ends with",
target, "is", n,
)
return
}
}
}
|
Write the same code in C as shown below in Scala. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
|
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
int main() {
int current = 0,
square;
while (((square=current*current) % 1000000 != 269696) && (square<INT_MAX)) {
current++;
}
if (square>+INT_MAX)
printf("Condition not satisfied before INT_MAX reached.");
else
printf ("The smallest number whose square ends in 269696 is %d\n", current);
return 0 ;
}
|
Translate the given Scala code snippet into C without altering its behavior. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
|
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
int main() {
int current = 0,
square;
while (((square=current*current) % 1000000 != 269696) && (square<INT_MAX)) {
current++;
}
if (square>+INT_MAX)
printf("Condition not satisfied before INT_MAX reached.");
else
printf ("The smallest number whose square ends in 269696 is %d\n", current);
return 0 ;
}
|
Maintain the same structure and functionality when rewriting this code in C#. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
| namespace Babbage_Problem
{
class iterateNumbers
{
public iterateNumbers()
{
long baseNumberSquared = 0;
long baseNumber = 0;
do
{
baseNumber += 1;
baseNumberSquared = baseNumber * baseNumber;
}
while (Right6Digits(baseNumberSquared) != 269696);
Console.WriteLine("The smallest integer whose square ends in 269,696 is " + baseNumber);
Console.WriteLine("The square is " + baseNumberSquared);
}
private long Right6Digits(long baseNumberSquared)
{
string numberAsString = baseNumberSquared.ToString();
if (numberAsString.Length < 6) { return baseNumberSquared; };
numberAsString = numberAsString.Substring(numberAsString.Length - 6);
return long.Parse(numberAsString);
}
}
}}
|
Convert the following code from Scala to C#, ensuring the logic remains intact. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
| namespace Babbage_Problem
{
class iterateNumbers
{
public iterateNumbers()
{
long baseNumberSquared = 0;
long baseNumber = 0;
do
{
baseNumber += 1;
baseNumberSquared = baseNumber * baseNumber;
}
while (Right6Digits(baseNumberSquared) != 269696);
Console.WriteLine("The smallest integer whose square ends in 269,696 is " + baseNumber);
Console.WriteLine("The square is " + baseNumberSquared);
}
private long Right6Digits(long baseNumberSquared)
{
string numberAsString = baseNumberSquared.ToString();
if (numberAsString.Length < 6) { return baseNumberSquared; };
numberAsString = numberAsString.Substring(numberAsString.Length - 6);
return long.Parse(numberAsString);
}
}
}}
|
Maintain the same structure and functionality when rewriting this code in C++. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
| #include <iostream>
int main( ) {
int current = 0 ;
while ( ( current * current ) % 1000000 != 269696 )
current++ ;
std::cout << "The square of " << current << " is " << (current * current) << " !\n" ;
return 0 ;
}
|
Change the following Scala code into C++ without altering its purpose. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
| #include <iostream>
int main( ) {
int current = 0 ;
while ( ( current * current ) % 1000000 != 269696 )
current++ ;
std::cout << "The square of " << current << " is " << (current * current) << " !\n" ;
return 0 ;
}
|
Ensure the translated Java code behaves exactly like the original Scala snippet. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
| public class Test {
public static void main(String[] args) {
int n = 0;
do {
n++;
} while (n * n % 1000_000 != 269696);
System.out.println(n);
}
}
|
Preserve the algorithm and functionality while converting the code from Scala to Java. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
| public class Test {
public static void main(String[] args) {
int n = 0;
do {
n++;
} while (n * n % 1000_000 != 269696);
System.out.println(n);
}
}
|
Produce a language-to-language conversion: from Scala to Python, same semantics. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
|
n=0
while n**2 % 1000000 != 269696:
n += 1
print(n)
|
Generate a Python translation of this Scala snippet without changing its computational steps. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
|
n=0
while n**2 % 1000000 != 269696:
n += 1
print(n)
|
Produce a functionally identical VB code for the snippet given in Scala. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
| Sub Baggage_Problem()
Dim i As Long
i = 520
Do While ((i * i) Mod 1000000) <> 269696
i = i + 4
Loop
Debug.Print "The smallest positive integer whose square ends in the digits 269 696 is : " & i & vbCrLf & _
"Its square is : " & i * i
End Sub
|
Write the same code in VB as shown below in Scala. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
| Sub Baggage_Problem()
Dim i As Long
i = 520
Do While ((i * i) Mod 1000000) <> 269696
i = i + 4
Loop
Debug.Print "The smallest positive integer whose square ends in the digits 269 696 is : " & i & vbCrLf & _
"Its square is : " & i * i
End Sub
|
Rewrite this program in Go while keeping its functionality equivalent to the Scala version. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
| package main
import "fmt"
func main() {
const (
target = 269696
modulus = 1000000
)
for n := 1; ; n++ {
square := n * n
ending := square % modulus
if ending == target {
fmt.Println("The smallest number whose square ends with",
target, "is", n,
)
return
}
}
}
|
Rewrite the snippet below in Go so it works the same as the original Scala code. | fun main(args: Array<String>) {
var number = 520L
var square = 520 * 520L
while (true) {
val last6 = square.toString().takeLast(6)
if (last6 == "269696") {
println("The smallest number is $number whose square is $square")
return
}
number += 2
square = number * number
}
}
| package main
import "fmt"
func main() {
const (
target = 269696
modulus = 1000000
)
for n := 1; ; n++ {
square := n * n
ending := square % modulus
if ending == target {
fmt.Println("The smallest number whose square ends with",
target, "is", n,
)
return
}
}
}
|
Translate this program into C but keep the logic exactly as in Swift. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
|
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
int main() {
int current = 0,
square;
while (((square=current*current) % 1000000 != 269696) && (square<INT_MAX)) {
current++;
}
if (square>+INT_MAX)
printf("Condition not satisfied before INT_MAX reached.");
else
printf ("The smallest number whose square ends in 269696 is %d\n", current);
return 0 ;
}
|
Change the programming language of this snippet from Swift to C without modifying what it does. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
|
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
int main() {
int current = 0,
square;
while (((square=current*current) % 1000000 != 269696) && (square<INT_MAX)) {
current++;
}
if (square>+INT_MAX)
printf("Condition not satisfied before INT_MAX reached.");
else
printf ("The smallest number whose square ends in 269696 is %d\n", current);
return 0 ;
}
|
Rewrite the snippet below in C# so it works the same as the original Swift code. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
| namespace Babbage_Problem
{
class iterateNumbers
{
public iterateNumbers()
{
long baseNumberSquared = 0;
long baseNumber = 0;
do
{
baseNumber += 1;
baseNumberSquared = baseNumber * baseNumber;
}
while (Right6Digits(baseNumberSquared) != 269696);
Console.WriteLine("The smallest integer whose square ends in 269,696 is " + baseNumber);
Console.WriteLine("The square is " + baseNumberSquared);
}
private long Right6Digits(long baseNumberSquared)
{
string numberAsString = baseNumberSquared.ToString();
if (numberAsString.Length < 6) { return baseNumberSquared; };
numberAsString = numberAsString.Substring(numberAsString.Length - 6);
return long.Parse(numberAsString);
}
}
}}
|
Please provide an equivalent version of this Swift code in C++. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
| #include <iostream>
int main( ) {
int current = 0 ;
while ( ( current * current ) % 1000000 != 269696 )
current++ ;
std::cout << "The square of " << current << " is " << (current * current) << " !\n" ;
return 0 ;
}
|
Maintain the same structure and functionality when rewriting this code in C++. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
| #include <iostream>
int main( ) {
int current = 0 ;
while ( ( current * current ) % 1000000 != 269696 )
current++ ;
std::cout << "The square of " << current << " is " << (current * current) << " !\n" ;
return 0 ;
}
|
Transform the following Swift implementation into Java, maintaining the same output and logic. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
| public class Test {
public static void main(String[] args) {
int n = 0;
do {
n++;
} while (n * n % 1000_000 != 269696);
System.out.println(n);
}
}
|
Please provide an equivalent version of this Swift code in Java. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
| public class Test {
public static void main(String[] args) {
int n = 0;
do {
n++;
} while (n * n % 1000_000 != 269696);
System.out.println(n);
}
}
|
Port the following code from Swift to Python with equivalent syntax and logic. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
|
n=0
while n**2 % 1000000 != 269696:
n += 1
print(n)
|
Write the same algorithm in Python as shown in this Swift implementation. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
|
n=0
while n**2 % 1000000 != 269696:
n += 1
print(n)
|
Maintain the same structure and functionality when rewriting this code in VB. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
| Sub Baggage_Problem()
Dim i As Long
i = 520
Do While ((i * i) Mod 1000000) <> 269696
i = i + 4
Loop
Debug.Print "The smallest positive integer whose square ends in the digits 269 696 is : " & i & vbCrLf & _
"Its square is : " & i * i
End Sub
|
Produce a language-to-language conversion: from Swift to VB, same semantics. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
| Sub Baggage_Problem()
Dim i As Long
i = 520
Do While ((i * i) Mod 1000000) <> 269696
i = i + 4
Loop
Debug.Print "The smallest positive integer whose square ends in the digits 269 696 is : " & i & vbCrLf & _
"Its square is : " & i * i
End Sub
|
Generate a Go translation of this Swift snippet without changing its computational steps. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
| package main
import "fmt"
func main() {
const (
target = 269696
modulus = 1000000
)
for n := 1; ; n++ {
square := n * n
ending := square % modulus
if ending == target {
fmt.Println("The smallest number whose square ends with",
target, "is", n,
)
return
}
}
}
|
Convert this Swift snippet to Go and keep its semantics consistent. | import Swift
for i in 2...Int.max {
if i * i % 1000000 == 269696 {
print(i, "is the smallest number that ends with 269696")
break
}
}
| package main
import "fmt"
func main() {
const (
target = 269696
modulus = 1000000
)
for n := 1; ; n++ {
square := n * n
ending := square % modulus
if ending == target {
fmt.Println("The smallest number whose square ends with",
target, "is", n,
)
return
}
}
}
|
Generate an equivalent C version of this Tcl code. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
|
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
int main() {
int current = 0,
square;
while (((square=current*current) % 1000000 != 269696) && (square<INT_MAX)) {
current++;
}
if (square>+INT_MAX)
printf("Condition not satisfied before INT_MAX reached.");
else
printf ("The smallest number whose square ends in 269696 is %d\n", current);
return 0 ;
}
|
Keep all operations the same but rewrite the snippet in C. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
|
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
int main() {
int current = 0,
square;
while (((square=current*current) % 1000000 != 269696) && (square<INT_MAX)) {
current++;
}
if (square>+INT_MAX)
printf("Condition not satisfied before INT_MAX reached.");
else
printf ("The smallest number whose square ends in 269696 is %d\n", current);
return 0 ;
}
|
Convert this Tcl snippet to C# and keep its semantics consistent. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
| namespace Babbage_Problem
{
class iterateNumbers
{
public iterateNumbers()
{
long baseNumberSquared = 0;
long baseNumber = 0;
do
{
baseNumber += 1;
baseNumberSquared = baseNumber * baseNumber;
}
while (Right6Digits(baseNumberSquared) != 269696);
Console.WriteLine("The smallest integer whose square ends in 269,696 is " + baseNumber);
Console.WriteLine("The square is " + baseNumberSquared);
}
private long Right6Digits(long baseNumberSquared)
{
string numberAsString = baseNumberSquared.ToString();
if (numberAsString.Length < 6) { return baseNumberSquared; };
numberAsString = numberAsString.Substring(numberAsString.Length - 6);
return long.Parse(numberAsString);
}
}
}}
|
Ensure the translated C# code behaves exactly like the original Tcl snippet. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
| namespace Babbage_Problem
{
class iterateNumbers
{
public iterateNumbers()
{
long baseNumberSquared = 0;
long baseNumber = 0;
do
{
baseNumber += 1;
baseNumberSquared = baseNumber * baseNumber;
}
while (Right6Digits(baseNumberSquared) != 269696);
Console.WriteLine("The smallest integer whose square ends in 269,696 is " + baseNumber);
Console.WriteLine("The square is " + baseNumberSquared);
}
private long Right6Digits(long baseNumberSquared)
{
string numberAsString = baseNumberSquared.ToString();
if (numberAsString.Length < 6) { return baseNumberSquared; };
numberAsString = numberAsString.Substring(numberAsString.Length - 6);
return long.Parse(numberAsString);
}
}
}}
|
Translate this program into C++ but keep the logic exactly as in Tcl. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
| #include <iostream>
int main( ) {
int current = 0 ;
while ( ( current * current ) % 1000000 != 269696 )
current++ ;
std::cout << "The square of " << current << " is " << (current * current) << " !\n" ;
return 0 ;
}
|
Change the following Tcl code into C++ without altering its purpose. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
| #include <iostream>
int main( ) {
int current = 0 ;
while ( ( current * current ) % 1000000 != 269696 )
current++ ;
std::cout << "The square of " << current << " is " << (current * current) << " !\n" ;
return 0 ;
}
|
Ensure the translated Java code behaves exactly like the original Tcl snippet. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
| public class Test {
public static void main(String[] args) {
int n = 0;
do {
n++;
} while (n * n % 1000_000 != 269696);
System.out.println(n);
}
}
|
Convert this Tcl block to Java, preserving its control flow and logic. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
| public class Test {
public static void main(String[] args) {
int n = 0;
do {
n++;
} while (n * n % 1000_000 != 269696);
System.out.println(n);
}
}
|
Rewrite this program in Python while keeping its functionality equivalent to the Tcl version. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
|
n=0
while n**2 % 1000000 != 269696:
n += 1
print(n)
|
Write the same algorithm in Python as shown in this Tcl implementation. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
|
n=0
while n**2 % 1000000 != 269696:
n += 1
print(n)
|
Change the programming language of this snippet from Tcl to VB without modifying what it does. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
| Sub Baggage_Problem()
Dim i As Long
i = 520
Do While ((i * i) Mod 1000000) <> 269696
i = i + 4
Loop
Debug.Print "The smallest positive integer whose square ends in the digits 269 696 is : " & i & vbCrLf & _
"Its square is : " & i * i
End Sub
|
Convert this Tcl snippet to VB and keep its semantics consistent. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
| Sub Baggage_Problem()
Dim i As Long
i = 520
Do While ((i * i) Mod 1000000) <> 269696
i = i + 4
Loop
Debug.Print "The smallest positive integer whose square ends in the digits 269 696 is : " & i & vbCrLf & _
"Its square is : " & i * i
End Sub
|
Translate the given Tcl code snippet into Go without altering its behavior. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
| package main
import "fmt"
func main() {
const (
target = 269696
modulus = 1000000
)
for n := 1; ; n++ {
square := n * n
ending := square % modulus
if ending == target {
fmt.Println("The smallest number whose square ends with",
target, "is", n,
)
return
}
}
}
|
Generate an equivalent Go version of this Tcl code. | for {set i 1} {![string match *269696 [expr $i*$i]]} {incr i} {}
puts "$i squared is [expr $i*$i]"
| package main
import "fmt"
func main() {
const (
target = 269696
modulus = 1000000
)
for n := 1; ; n++ {
square := n * n
ending := square % modulus
if ending == target {
fmt.Println("The smallest number whose square ends with",
target, "is", n,
)
return
}
}
}
|
Translate this program into PHP but keep the logic exactly as in Rust. | fn main() {
let mut current = 0;
while (current * current) % 1_000_000 != 269_696 {
current += 1;
}
println!(
"The smallest number whose square ends in 269696 is {}",
current
);
}
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Translate this program into PHP but keep the logic exactly as in Rust. | fn main() {
let mut current = 0;
while (current * current) % 1_000_000 != 269_696 {
current += 1;
}
println!(
"The smallest number whose square ends in 269696 is {}",
current
);
}
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Port the provided Ada code into PHP while preserving the original functionality. |
with Ada.Text_IO;
procedure Babbage_Problem is
type Number is range 1 .. 99_736*99_736;
X: Number := 1;
begin
while not (((X*X) mod 1_000_000) = 269_696) loop
X := X+1;
end loop;
Ada.Text_IO.Put_Line(Number'Image(X));
end Babbage_Problem;
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Write the same algorithm in PHP as shown in this Ada implementation. |
with Ada.Text_IO;
procedure Babbage_Problem is
type Number is range 1 .. 99_736*99_736;
X: Number := 1;
begin
while not (((X*X) mod 1_000_000) = 269_696) loop
X := X+1;
end loop;
Ada.Text_IO.Put_Line(Number'Image(X));
end Babbage_Problem;
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Convert this Arturo snippet to PHP and keep its semantics consistent. | n: new 0
while [269696 <> (n^2) % 1000000]
-> inc 'n
print n
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Port the following code from Arturo to PHP with equivalent syntax and logic. | n: new 0
while [269696 <> (n^2) % 1000000]
-> inc 'n
print n
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Rewrite the snippet below in PHP so it works the same as the original AWK code. |
BEGIN {
n = 0
do {
n = n + 1
} while (n*n !~ /269696$/)
print("The smallest number whose square ends in 269696 is " n)
print("Its square is " n*n)
exit(0)
}
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Can you help me rewrite this code in PHP instead of AWK, keeping it the same logically? |
BEGIN {
n = 0
do {
n = n + 1
} while (n*n !~ /269696$/)
print("The smallest number whose square ends in 269696 is " n)
print("Its square is " n*n)
exit(0)
}
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Convert this BBC_Basic block to PHP, preserving its control flow and logic. |
LET n = 0
REPEAT
LET n = n + 1
UNTIL n^2 MOD 1000000 = 269696
PRINT "The smallest number whose square ends in 269696 is" n
PRINT "Its square is" n^2
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Preserve the algorithm and functionality while converting the code from BBC_Basic to PHP. |
LET n = 0
REPEAT
LET n = n + 1
UNTIL n^2 MOD 1000000 = 269696
PRINT "The smallest number whose square ends in 269696 is" n
PRINT "Its square is" n^2
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Produce a functionally identical PHP code for the snippet given in Clojure. |
(defn babbage? [n]
(let [square (* n n)]
(= 269696 (mod square 1000000))))
(first (filter babbage? (range)))
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Translate the given Clojure code snippet into PHP without altering its behavior. |
(defn babbage? [n]
(let [square (* n n)]
(= 269696 (mod square 1000000))))
(first (filter babbage? (range)))
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Generate a PHP translation of this Common_Lisp snippet without changing its computational steps. | (defun babbage-test (n)
"A generic function for any ending of a number"
(when (> n 0)
(do* ((i 0 (1+ i))
(d (expt 10 (1+ (truncate (log n) (log 10))))) )
((= (mod (* i i) d) n) i) )))
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Ensure the translated PHP code behaves exactly like the original Common_Lisp snippet. | (defun babbage-test (n)
"A generic function for any ending of a number"
(when (> n 0)
(do* ((i 0 (1+ i))
(d (expt 10 (1+ (truncate (log n) (log 10))))) )
((= (mod (* i i) d) n) i) )))
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Port the following code from D to PHP with equivalent syntax and logic. |
import std.math;
import std.stdio;
void main( )
{
int k = cast(int)(sqrt(269696.0));
if (k % 2 == 1)
k = k - 1;
while ((k * k) % 1000000 != 269696)
k = k + 2;
writefln("%d * %d = %d", k, k, k*k);
}
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Change the programming language of this snippet from D to PHP without modifying what it does. |
import std.math;
import std.stdio;
void main( )
{
int k = cast(int)(sqrt(269696.0));
if (k % 2 == 1)
k = k - 1;
while ((k * k) % 1000000 != 269696)
k = k + 2;
writefln("%d * %d = %d", k, k, k*k);
}
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Write a version of this Elixir function in PHP with identical behavior. | defmodule Babbage do
def problem(n) when rem(n*n,1000000)==269696, do: n
def problem(n), do: problem(n+2)
end
IO.puts Babbage.problem(0)
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Convert this Elixir block to PHP, preserving its control flow and logic. | defmodule Babbage do
def problem(n) when rem(n*n,1000000)==269696, do: n
def problem(n), do: problem(n+2)
end
IO.puts Babbage.problem(0)
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Generate a PHP translation of this Erlang snippet without changing its computational steps. | -module(solution1).
-export([main/0]).
babbage(N,E) when N*N rem 1000000 == 269696 ->
io:fwrite("~p",[N]);
babbage(N,E) ->
case E of
4 -> babbage(N+2,6);
6 -> babbage(N+8,4)
end.
main()->
babbage(4,4).
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Write the same algorithm in PHP as shown in this Erlang implementation. | -module(solution1).
-export([main/0]).
babbage(N,E) when N*N rem 1000000 == 269696 ->
io:fwrite("~p",[N]);
babbage(N,E) ->
case E of
4 -> babbage(N+2,6);
6 -> babbage(N+8,4)
end.
main()->
babbage(4,4).
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Convert this F# block to PHP, preserving its control flow and logic. | Seq.initInfinite id
|> Seq.skipWhile (fun n->(n*n % 1000000) <> 269696)
|> Seq.head |> printfn "%d"
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Rewrite the snippet below in PHP so it works the same as the original F# code. | Seq.initInfinite id
|> Seq.skipWhile (fun n->(n*n % 1000000) <> 269696)
|> Seq.head |> printfn "%d"
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Port the following code from Factor to PHP with equivalent syntax and logic. |
USING: kernel math math.ranges prettyprint sequences ;
518 99,736 2 <range>
[ sq 1,000,000 mod 269,696 = ]
find
.
drop
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Transform the following Factor implementation into PHP, maintaining the same output and logic. |
USING: kernel math math.ranges prettyprint sequences ;
518 99,736 2 <range>
[ sq 1,000,000 mod 269,696 = ]
find
.
drop
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Can you help me rewrite this code in PHP instead of Forth, keeping it the same logically? |
: BABBAGE
1
BEGIN
1+
DUP DUP
*
1000000 MOD
269696 =
UNTIL
. ;
BABBAGE
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Port the provided Forth code into PHP while preserving the original functionality. |
: BABBAGE
1
BEGIN
1+
DUP DUP
*
1000000 MOD
269696 =
UNTIL
. ;
BABBAGE
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Rewrite the snippet below in PHP so it works the same as the original Fortran code. | DO 3 N=1,99736
IF(MODF(N*N,1000000)-269696)3,4,3
3 CONTINUE
4 PRINT 5,N
5 FORMAT(I6)
STOP
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Port the provided Fortran code into PHP while preserving the original functionality. | DO 3 N=1,99736
IF(MODF(N*N,1000000)-269696)3,4,3
3 CONTINUE
4 PRINT 5,N
5 FORMAT(I6)
STOP
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Keep all operations the same but rewrite the snippet in PHP. | int n=104;
while( (n**2)%1000000 != 269696 )
{ if (n%10==4) n=n+2;
if (n%10==6) n=n+8;
}
println n+"^2== "+n**2 ;
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Please provide an equivalent version of this Groovy code in PHP. | int n=104;
while( (n**2)%1000000 != 269696 )
{ if (n%10==4) n=n+2;
if (n%10==6) n=n+8;
}
println n+"^2== "+n**2 ;
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Port the following code from Haskell to PHP with equivalent syntax and logic. |
findBabbageNumber :: Integer
findBabbageNumber =
head (filter ((269696 ==) . flip mod 1000000 . (^ 2)) [1 ..])
main :: IO ()
main =
(putStrLn . unwords)
(zipWith
(++)
(show <$> ([id, (^ 2)] <*> [findBabbageNumber]))
[" ^ 2 equals", " !"])
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Generate an equivalent PHP version of this Haskell code. |
findBabbageNumber :: Integer
findBabbageNumber =
head (filter ((269696 ==) . flip mod 1000000 . (^ 2)) [1 ..])
main :: IO ()
main =
(putStrLn . unwords)
(zipWith
(++)
(show <$> ([id, (^ 2)] <*> [findBabbageNumber]))
[" ^ 2 equals", " !"])
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Convert this J snippet to PHP and keep its semantics consistent. | square=: ^&2
modulo1e6=: 1000000&|
trythese=: i. 1000000
which=: I.
which 269696=modulo1e6 square trythese
25264 99736 150264 224736 275264 349736 400264 474736 525264 599736 650264 724736 775264 849736 900264 974736
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Preserve the algorithm and functionality while converting the code from J to PHP. | square=: ^&2
modulo1e6=: 1000000&|
trythese=: i. 1000000
which=: I.
which 269696=modulo1e6 square trythese
25264 99736 150264 224736 275264 349736 400264 474736 525264 599736 650264 724736 775264 849736 900264 974736
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Rewrite this program in PHP while keeping its functionality equivalent to the Julia version. | function babbage(x::Integer)
i = big(0)
d = floor(log10(x)) + 1
while i ^ 2 % 10 ^ d != x
i += 1
end
return i
end
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Convert this Julia snippet to PHP and keep its semantics consistent. | function babbage(x::Integer)
i = big(0)
d = floor(log10(x)) + 1
while i ^ 2 % 10 ^ d != x
i += 1
end
return i
end
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
Write a version of this Lua function in PHP with identical behavior. |
k = math.floor(math.sqrt(269696))
if k % 2 == 1 then
k = k - 1
end
while not ((k * k) % 1000000 == 269696) do
k = k + 2
end
io.write(string.format("%d * %d = %d\n", k, k, k * k))
| <?php
for (
$i = 1 ; // Initial positive integer to check
($i * $i) % 1000000 !== 269696 ; // While i*i does not end with the digits 269,696
$i++ // ... go to next integer
);
echo $i, ' * ', $i, ' = ', ($i * $i), PHP_EOL; // Print the result
|
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