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Port the following code from AWK to Python with equivalent syntax and logic.
function lookandsay(a) { s = "" c = 1 p = substr(a, 1, 1) for(i=2; i <= length(a); i++) { if ( p == substr(a, i, 1) ) { c++ } else { s = s sprintf("%d%s", c, p) p = substr(a, i, 1) c = 1 } } s = s sprintf("%d%s", c, p) return s } BEGIN { b = "1" print b for(k=1; k <= 10; k++) { b = lookandsay(b) print b } }
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Write the same code in VB as shown below in AWK.
function lookandsay(a) { s = "" c = 1 p = substr(a, 1, 1) for(i=2; i <= length(a); i++) { if ( p == substr(a, i, 1) ) { c++ } else { s = s sprintf("%d%s", c, p) p = substr(a, i, 1) c = 1 } } s = s sprintf("%d%s", c, p) return s } BEGIN { b = "1" print b for(k=1; k <= 10; k++) { b = lookandsay(b) print b } }
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Please provide an equivalent version of this AWK code in Go.
function lookandsay(a) { s = "" c = 1 p = substr(a, 1, 1) for(i=2; i <= length(a); i++) { if ( p == substr(a, i, 1) ) { c++ } else { s = s sprintf("%d%s", c, p) p = substr(a, i, 1) c = 1 } } s = s sprintf("%d%s", c, p) return s } BEGIN { b = "1" print b for(k=1; k <= 10; k++) { b = lookandsay(b) print b } }
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Ensure the translated C code behaves exactly like the original BBC_Basic snippet.
number$ = "1" FOR i% = 1 TO 10 number$ = FNlooksay(number$) PRINT number$ NEXT END DEF FNlooksay(n$) LOCAL i%, j%, c$, o$ i% = 1 REPEAT c$ = MID$(n$,i%,1) j% = i% + 1 WHILE MID$(n$,j%,1) = c$ j% += 1 ENDWHILE o$ += STR$(j%-i%) + c$ i% = j% UNTIL i% > LEN(n$) = o$
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Can you help me rewrite this code in C# instead of BBC_Basic, keeping it the same logically?
number$ = "1" FOR i% = 1 TO 10 number$ = FNlooksay(number$) PRINT number$ NEXT END DEF FNlooksay(n$) LOCAL i%, j%, c$, o$ i% = 1 REPEAT c$ = MID$(n$,i%,1) j% = i% + 1 WHILE MID$(n$,j%,1) = c$ j% += 1 ENDWHILE o$ += STR$(j%-i%) + c$ i% = j% UNTIL i% > LEN(n$) = o$
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Rewrite the snippet below in C++ so it works the same as the original BBC_Basic code.
number$ = "1" FOR i% = 1 TO 10 number$ = FNlooksay(number$) PRINT number$ NEXT END DEF FNlooksay(n$) LOCAL i%, j%, c$, o$ i% = 1 REPEAT c$ = MID$(n$,i%,1) j% = i% + 1 WHILE MID$(n$,j%,1) = c$ j% += 1 ENDWHILE o$ += STR$(j%-i%) + c$ i% = j% UNTIL i% > LEN(n$) = o$
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Write a version of this BBC_Basic function in Java with identical behavior.
number$ = "1" FOR i% = 1 TO 10 number$ = FNlooksay(number$) PRINT number$ NEXT END DEF FNlooksay(n$) LOCAL i%, j%, c$, o$ i% = 1 REPEAT c$ = MID$(n$,i%,1) j% = i% + 1 WHILE MID$(n$,j%,1) = c$ j% += 1 ENDWHILE o$ += STR$(j%-i%) + c$ i% = j% UNTIL i% > LEN(n$) = o$
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Can you help me rewrite this code in Python instead of BBC_Basic, keeping it the same logically?
number$ = "1" FOR i% = 1 TO 10 number$ = FNlooksay(number$) PRINT number$ NEXT END DEF FNlooksay(n$) LOCAL i%, j%, c$, o$ i% = 1 REPEAT c$ = MID$(n$,i%,1) j% = i% + 1 WHILE MID$(n$,j%,1) = c$ j% += 1 ENDWHILE o$ += STR$(j%-i%) + c$ i% = j% UNTIL i% > LEN(n$) = o$
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Can you help me rewrite this code in VB instead of BBC_Basic, keeping it the same logically?
number$ = "1" FOR i% = 1 TO 10 number$ = FNlooksay(number$) PRINT number$ NEXT END DEF FNlooksay(n$) LOCAL i%, j%, c$, o$ i% = 1 REPEAT c$ = MID$(n$,i%,1) j% = i% + 1 WHILE MID$(n$,j%,1) = c$ j% += 1 ENDWHILE o$ += STR$(j%-i%) + c$ i% = j% UNTIL i% > LEN(n$) = o$
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Port the following code from BBC_Basic to Go with equivalent syntax and logic.
number$ = "1" FOR i% = 1 TO 10 number$ = FNlooksay(number$) PRINT number$ NEXT END DEF FNlooksay(n$) LOCAL i%, j%, c$, o$ i% = 1 REPEAT c$ = MID$(n$,i%,1) j% = i% + 1 WHILE MID$(n$,j%,1) = c$ j% += 1 ENDWHILE o$ += STR$(j%-i%) + c$ i% = j% UNTIL i% > LEN(n$) = o$
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Rewrite this program in C while keeping its functionality equivalent to the Clojure version.
(defn digits-seq "Returns a seq of the digits of a number (L->R)." [n] (loop [digits (), number n] (if (zero? number) (seq digits) (recur (cons (mod number 10) digits) (quot number 10))))) (defn join-digits "Converts a digits-seq back in to a number." [ds] (reduce (fn [n d] (+ (* 10 n) d)) ds)) (defn look-and-say [n] (->> n digits-seq (partition-by identity) (mapcat (juxt count first)) join-digits))
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Port the provided Clojure code into C# while preserving the original functionality.
(defn digits-seq "Returns a seq of the digits of a number (L->R)." [n] (loop [digits (), number n] (if (zero? number) (seq digits) (recur (cons (mod number 10) digits) (quot number 10))))) (defn join-digits "Converts a digits-seq back in to a number." [ds] (reduce (fn [n d] (+ (* 10 n) d)) ds)) (defn look-and-say [n] (->> n digits-seq (partition-by identity) (mapcat (juxt count first)) join-digits))
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Convert this Clojure snippet to C++ and keep its semantics consistent.
(defn digits-seq "Returns a seq of the digits of a number (L->R)." [n] (loop [digits (), number n] (if (zero? number) (seq digits) (recur (cons (mod number 10) digits) (quot number 10))))) (defn join-digits "Converts a digits-seq back in to a number." [ds] (reduce (fn [n d] (+ (* 10 n) d)) ds)) (defn look-and-say [n] (->> n digits-seq (partition-by identity) (mapcat (juxt count first)) join-digits))
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Rewrite the snippet below in Java so it works the same as the original Clojure code.
(defn digits-seq "Returns a seq of the digits of a number (L->R)." [n] (loop [digits (), number n] (if (zero? number) (seq digits) (recur (cons (mod number 10) digits) (quot number 10))))) (defn join-digits "Converts a digits-seq back in to a number." [ds] (reduce (fn [n d] (+ (* 10 n) d)) ds)) (defn look-and-say [n] (->> n digits-seq (partition-by identity) (mapcat (juxt count first)) join-digits))
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Write a version of this Clojure function in Python with identical behavior.
(defn digits-seq "Returns a seq of the digits of a number (L->R)." [n] (loop [digits (), number n] (if (zero? number) (seq digits) (recur (cons (mod number 10) digits) (quot number 10))))) (defn join-digits "Converts a digits-seq back in to a number." [ds] (reduce (fn [n d] (+ (* 10 n) d)) ds)) (defn look-and-say [n] (->> n digits-seq (partition-by identity) (mapcat (juxt count first)) join-digits))
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Generate a VB translation of this Clojure snippet without changing its computational steps.
(defn digits-seq "Returns a seq of the digits of a number (L->R)." [n] (loop [digits (), number n] (if (zero? number) (seq digits) (recur (cons (mod number 10) digits) (quot number 10))))) (defn join-digits "Converts a digits-seq back in to a number." [ds] (reduce (fn [n d] (+ (* 10 n) d)) ds)) (defn look-and-say [n] (->> n digits-seq (partition-by identity) (mapcat (juxt count first)) join-digits))
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Write the same code in Go as shown below in Clojure.
(defn digits-seq "Returns a seq of the digits of a number (L->R)." [n] (loop [digits (), number n] (if (zero? number) (seq digits) (recur (cons (mod number 10) digits) (quot number 10))))) (defn join-digits "Converts a digits-seq back in to a number." [ds] (reduce (fn [n d] (+ (* 10 n) d)) ds)) (defn look-and-say [n] (->> n digits-seq (partition-by identity) (mapcat (juxt count first)) join-digits))
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Convert this Common_Lisp block to C, preserving its control flow and logic.
(defun compress (array &key (test 'eql) &aux (l (length array))) "Compresses array by returning a list of conses each of whose car is a number of occurrences and whose cdr is the element occurring. For instance, (compress \"abb\") produces ((1 . #\a) (2 . #\b))." (if (zerop l) nil (do* ((i 1 (1+ i)) (segments (acons 1 (aref array 0) '()))) ((eql i l) (nreverse segments)) (if (funcall test (aref array i) (cdar segments)) (incf (caar segments)) (setf segments (acons 1 (aref array i) segments)))))) (defun next-look-and-say (number) (reduce #'(lambda (n pair) (+ (* 100 n) (* 10 (car pair)) (parse-integer (string (cdr pair))))) (compress (princ-to-string number)) :initial-value 0))
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Rewrite the snippet below in C++ so it works the same as the original Common_Lisp code.
(defun compress (array &key (test 'eql) &aux (l (length array))) "Compresses array by returning a list of conses each of whose car is a number of occurrences and whose cdr is the element occurring. For instance, (compress \"abb\") produces ((1 . #\a) (2 . #\b))." (if (zerop l) nil (do* ((i 1 (1+ i)) (segments (acons 1 (aref array 0) '()))) ((eql i l) (nreverse segments)) (if (funcall test (aref array i) (cdar segments)) (incf (caar segments)) (setf segments (acons 1 (aref array i) segments)))))) (defun next-look-and-say (number) (reduce #'(lambda (n pair) (+ (* 100 n) (* 10 (car pair)) (parse-integer (string (cdr pair))))) (compress (princ-to-string number)) :initial-value 0))
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Keep all operations the same but rewrite the snippet in Java.
(defun compress (array &key (test 'eql) &aux (l (length array))) "Compresses array by returning a list of conses each of whose car is a number of occurrences and whose cdr is the element occurring. For instance, (compress \"abb\") produces ((1 . #\a) (2 . #\b))." (if (zerop l) nil (do* ((i 1 (1+ i)) (segments (acons 1 (aref array 0) '()))) ((eql i l) (nreverse segments)) (if (funcall test (aref array i) (cdar segments)) (incf (caar segments)) (setf segments (acons 1 (aref array i) segments)))))) (defun next-look-and-say (number) (reduce #'(lambda (n pair) (+ (* 100 n) (* 10 (car pair)) (parse-integer (string (cdr pair))))) (compress (princ-to-string number)) :initial-value 0))
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Change the programming language of this snippet from Common_Lisp to Python without modifying what it does.
(defun compress (array &key (test 'eql) &aux (l (length array))) "Compresses array by returning a list of conses each of whose car is a number of occurrences and whose cdr is the element occurring. For instance, (compress \"abb\") produces ((1 . #\a) (2 . #\b))." (if (zerop l) nil (do* ((i 1 (1+ i)) (segments (acons 1 (aref array 0) '()))) ((eql i l) (nreverse segments)) (if (funcall test (aref array i) (cdar segments)) (incf (caar segments)) (setf segments (acons 1 (aref array i) segments)))))) (defun next-look-and-say (number) (reduce #'(lambda (n pair) (+ (* 100 n) (* 10 (car pair)) (parse-integer (string (cdr pair))))) (compress (princ-to-string number)) :initial-value 0))
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Produce a language-to-language conversion: from Common_Lisp to VB, same semantics.
(defun compress (array &key (test 'eql) &aux (l (length array))) "Compresses array by returning a list of conses each of whose car is a number of occurrences and whose cdr is the element occurring. For instance, (compress \"abb\") produces ((1 . #\a) (2 . #\b))." (if (zerop l) nil (do* ((i 1 (1+ i)) (segments (acons 1 (aref array 0) '()))) ((eql i l) (nreverse segments)) (if (funcall test (aref array i) (cdar segments)) (incf (caar segments)) (setf segments (acons 1 (aref array i) segments)))))) (defun next-look-and-say (number) (reduce #'(lambda (n pair) (+ (* 100 n) (* 10 (car pair)) (parse-integer (string (cdr pair))))) (compress (princ-to-string number)) :initial-value 0))
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Rewrite this program in Go while keeping its functionality equivalent to the Common_Lisp version.
(defun compress (array &key (test 'eql) &aux (l (length array))) "Compresses array by returning a list of conses each of whose car is a number of occurrences and whose cdr is the element occurring. For instance, (compress \"abb\") produces ((1 . #\a) (2 . #\b))." (if (zerop l) nil (do* ((i 1 (1+ i)) (segments (acons 1 (aref array 0) '()))) ((eql i l) (nreverse segments)) (if (funcall test (aref array i) (cdar segments)) (incf (caar segments)) (setf segments (acons 1 (aref array i) segments)))))) (defun next-look-and-say (number) (reduce #'(lambda (n pair) (+ (* 100 n) (* 10 (car pair)) (parse-integer (string (cdr pair))))) (compress (princ-to-string number)) :initial-value 0))
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Port the provided D code into C while preserving the original functionality.
import std.stdio, std.algorithm, std.range; enum say = (in string s) pure => s.group.map!q{ text(a[1],a[0]) }.join; void main() { "1".recurrence!((t, n) => t[n - 1].say).take(8).writeln; }
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Translate the given D code snippet into C# without altering its behavior.
import std.stdio, std.algorithm, std.range; enum say = (in string s) pure => s.group.map!q{ text(a[1],a[0]) }.join; void main() { "1".recurrence!((t, n) => t[n - 1].say).take(8).writeln; }
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Write the same code in C++ as shown below in D.
import std.stdio, std.algorithm, std.range; enum say = (in string s) pure => s.group.map!q{ text(a[1],a[0]) }.join; void main() { "1".recurrence!((t, n) => t[n - 1].say).take(8).writeln; }
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Convert this D snippet to Java and keep its semantics consistent.
import std.stdio, std.algorithm, std.range; enum say = (in string s) pure => s.group.map!q{ text(a[1],a[0]) }.join; void main() { "1".recurrence!((t, n) => t[n - 1].say).take(8).writeln; }
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Preserve the algorithm and functionality while converting the code from D to Python.
import std.stdio, std.algorithm, std.range; enum say = (in string s) pure => s.group.map!q{ text(a[1],a[0]) }.join; void main() { "1".recurrence!((t, n) => t[n - 1].say).take(8).writeln; }
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Maintain the same structure and functionality when rewriting this code in VB.
import std.stdio, std.algorithm, std.range; enum say = (in string s) pure => s.group.map!q{ text(a[1],a[0]) }.join; void main() { "1".recurrence!((t, n) => t[n - 1].say).take(8).writeln; }
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Preserve the algorithm and functionality while converting the code from D to Go.
import std.stdio, std.algorithm, std.range; enum say = (in string s) pure => s.group.map!q{ text(a[1],a[0]) }.join; void main() { "1".recurrence!((t, n) => t[n - 1].say).take(8).writeln; }
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Keep all operations the same but rewrite the snippet in C.
defmodule LookAndSay do def next(n) do Enum.chunk_by(to_char_list(n), &(&1)) |> Enum.map(fn cl=[h|_] -> Enum.concat(to_char_list(length cl), [h]) end) |> Enum.concat |> List.to_integer end def sequence_from(n) do Stream.iterate n, &(next/1) end def main([start_str|_]) do {start_val,_} = Integer.parse(start_str) IO.inspect sequence_from(start_val) |> Enum.take 9 end def main([]) do main(["1"]) end end LookAndSay.main(System.argv)
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Keep all operations the same but rewrite the snippet in C#.
defmodule LookAndSay do def next(n) do Enum.chunk_by(to_char_list(n), &(&1)) |> Enum.map(fn cl=[h|_] -> Enum.concat(to_char_list(length cl), [h]) end) |> Enum.concat |> List.to_integer end def sequence_from(n) do Stream.iterate n, &(next/1) end def main([start_str|_]) do {start_val,_} = Integer.parse(start_str) IO.inspect sequence_from(start_val) |> Enum.take 9 end def main([]) do main(["1"]) end end LookAndSay.main(System.argv)
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Write a version of this Elixir function in C++ with identical behavior.
defmodule LookAndSay do def next(n) do Enum.chunk_by(to_char_list(n), &(&1)) |> Enum.map(fn cl=[h|_] -> Enum.concat(to_char_list(length cl), [h]) end) |> Enum.concat |> List.to_integer end def sequence_from(n) do Stream.iterate n, &(next/1) end def main([start_str|_]) do {start_val,_} = Integer.parse(start_str) IO.inspect sequence_from(start_val) |> Enum.take 9 end def main([]) do main(["1"]) end end LookAndSay.main(System.argv)
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Change the programming language of this snippet from Elixir to Java without modifying what it does.
defmodule LookAndSay do def next(n) do Enum.chunk_by(to_char_list(n), &(&1)) |> Enum.map(fn cl=[h|_] -> Enum.concat(to_char_list(length cl), [h]) end) |> Enum.concat |> List.to_integer end def sequence_from(n) do Stream.iterate n, &(next/1) end def main([start_str|_]) do {start_val,_} = Integer.parse(start_str) IO.inspect sequence_from(start_val) |> Enum.take 9 end def main([]) do main(["1"]) end end LookAndSay.main(System.argv)
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Generate an equivalent Python version of this Elixir code.
defmodule LookAndSay do def next(n) do Enum.chunk_by(to_char_list(n), &(&1)) |> Enum.map(fn cl=[h|_] -> Enum.concat(to_char_list(length cl), [h]) end) |> Enum.concat |> List.to_integer end def sequence_from(n) do Stream.iterate n, &(next/1) end def main([start_str|_]) do {start_val,_} = Integer.parse(start_str) IO.inspect sequence_from(start_val) |> Enum.take 9 end def main([]) do main(["1"]) end end LookAndSay.main(System.argv)
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Rewrite the snippet below in VB so it works the same as the original Elixir code.
defmodule LookAndSay do def next(n) do Enum.chunk_by(to_char_list(n), &(&1)) |> Enum.map(fn cl=[h|_] -> Enum.concat(to_char_list(length cl), [h]) end) |> Enum.concat |> List.to_integer end def sequence_from(n) do Stream.iterate n, &(next/1) end def main([start_str|_]) do {start_val,_} = Integer.parse(start_str) IO.inspect sequence_from(start_val) |> Enum.take 9 end def main([]) do main(["1"]) end end LookAndSay.main(System.argv)
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Can you help me rewrite this code in Go instead of Elixir, keeping it the same logically?
defmodule LookAndSay do def next(n) do Enum.chunk_by(to_char_list(n), &(&1)) |> Enum.map(fn cl=[h|_] -> Enum.concat(to_char_list(length cl), [h]) end) |> Enum.concat |> List.to_integer end def sequence_from(n) do Stream.iterate n, &(next/1) end def main([start_str|_]) do {start_val,_} = Integer.parse(start_str) IO.inspect sequence_from(start_val) |> Enum.take 9 end def main([]) do main(["1"]) end end LookAndSay.main(System.argv)
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Produce a functionally identical C code for the snippet given in Erlang.
-module(str). -export([look_and_say/1, look_and_say/2]). look_and_say([H|T]) -> lists:reverse(look_and_say(T,H,1,"")). look_and_say(_, 0) -> []; look_and_say(Start, Times) when Times > 0 -> [Start | look_and_say(look_and_say(Start), Times-1)]. look_and_say([], Current, N, Acc) -> [Current, $0+N | Acc]; look_and_say([H|T], H, N, Acc) -> look_and_say(T, H, N+1, Acc); look_and_say([H|T], Current, N, Acc) -> look_and_say(T, H, 1, [Current, $0+N | Acc]).
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Translate this program into C# but keep the logic exactly as in Erlang.
-module(str). -export([look_and_say/1, look_and_say/2]). look_and_say([H|T]) -> lists:reverse(look_and_say(T,H,1,"")). look_and_say(_, 0) -> []; look_and_say(Start, Times) when Times > 0 -> [Start | look_and_say(look_and_say(Start), Times-1)]. look_and_say([], Current, N, Acc) -> [Current, $0+N | Acc]; look_and_say([H|T], H, N, Acc) -> look_and_say(T, H, N+1, Acc); look_and_say([H|T], Current, N, Acc) -> look_and_say(T, H, 1, [Current, $0+N | Acc]).
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Rewrite this program in C++ while keeping its functionality equivalent to the Erlang version.
-module(str). -export([look_and_say/1, look_and_say/2]). look_and_say([H|T]) -> lists:reverse(look_and_say(T,H,1,"")). look_and_say(_, 0) -> []; look_and_say(Start, Times) when Times > 0 -> [Start | look_and_say(look_and_say(Start), Times-1)]. look_and_say([], Current, N, Acc) -> [Current, $0+N | Acc]; look_and_say([H|T], H, N, Acc) -> look_and_say(T, H, N+1, Acc); look_and_say([H|T], Current, N, Acc) -> look_and_say(T, H, 1, [Current, $0+N | Acc]).
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Translate the given Erlang code snippet into Java without altering its behavior.
-module(str). -export([look_and_say/1, look_and_say/2]). look_and_say([H|T]) -> lists:reverse(look_and_say(T,H,1,"")). look_and_say(_, 0) -> []; look_and_say(Start, Times) when Times > 0 -> [Start | look_and_say(look_and_say(Start), Times-1)]. look_and_say([], Current, N, Acc) -> [Current, $0+N | Acc]; look_and_say([H|T], H, N, Acc) -> look_and_say(T, H, N+1, Acc); look_and_say([H|T], Current, N, Acc) -> look_and_say(T, H, 1, [Current, $0+N | Acc]).
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Write the same code in Python as shown below in Erlang.
-module(str). -export([look_and_say/1, look_and_say/2]). look_and_say([H|T]) -> lists:reverse(look_and_say(T,H,1,"")). look_and_say(_, 0) -> []; look_and_say(Start, Times) when Times > 0 -> [Start | look_and_say(look_and_say(Start), Times-1)]. look_and_say([], Current, N, Acc) -> [Current, $0+N | Acc]; look_and_say([H|T], H, N, Acc) -> look_and_say(T, H, N+1, Acc); look_and_say([H|T], Current, N, Acc) -> look_and_say(T, H, 1, [Current, $0+N | Acc]).
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Can you help me rewrite this code in VB instead of Erlang, keeping it the same logically?
-module(str). -export([look_and_say/1, look_and_say/2]). look_and_say([H|T]) -> lists:reverse(look_and_say(T,H,1,"")). look_and_say(_, 0) -> []; look_and_say(Start, Times) when Times > 0 -> [Start | look_and_say(look_and_say(Start), Times-1)]. look_and_say([], Current, N, Acc) -> [Current, $0+N | Acc]; look_and_say([H|T], H, N, Acc) -> look_and_say(T, H, N+1, Acc); look_and_say([H|T], Current, N, Acc) -> look_and_say(T, H, 1, [Current, $0+N | Acc]).
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Keep all operations the same but rewrite the snippet in Go.
-module(str). -export([look_and_say/1, look_and_say/2]). look_and_say([H|T]) -> lists:reverse(look_and_say(T,H,1,"")). look_and_say(_, 0) -> []; look_and_say(Start, Times) when Times > 0 -> [Start | look_and_say(look_and_say(Start), Times-1)]. look_and_say([], Current, N, Acc) -> [Current, $0+N | Acc]; look_and_say([H|T], H, N, Acc) -> look_and_say(T, H, N+1, Acc); look_and_say([H|T], Current, N, Acc) -> look_and_say(T, H, 1, [Current, $0+N | Acc]).
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Translate this program into C but keep the logic exactly as in F#.
let rec brk p lst = match lst with | [] -> (lst, lst) | x::xs -> if p x then ([], lst) else let (ys, zs) = brk p xs (x::ys, zs) let span p lst = brk (not << p) lst let rec groupBy eq lst = match lst with | [] -> [] | x::xs -> let (ys,zs) = span (eq x) xs (x::ys)::groupBy eq zs let group lst : list<list<'a>> when 'a : equality = groupBy (=) lst
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Write a version of this F# function in C# with identical behavior.
let rec brk p lst = match lst with | [] -> (lst, lst) | x::xs -> if p x then ([], lst) else let (ys, zs) = brk p xs (x::ys, zs) let span p lst = brk (not << p) lst let rec groupBy eq lst = match lst with | [] -> [] | x::xs -> let (ys,zs) = span (eq x) xs (x::ys)::groupBy eq zs let group lst : list<list<'a>> when 'a : equality = groupBy (=) lst
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Change the following F# code into C++ without altering its purpose.
let rec brk p lst = match lst with | [] -> (lst, lst) | x::xs -> if p x then ([], lst) else let (ys, zs) = brk p xs (x::ys, zs) let span p lst = brk (not << p) lst let rec groupBy eq lst = match lst with | [] -> [] | x::xs -> let (ys,zs) = span (eq x) xs (x::ys)::groupBy eq zs let group lst : list<list<'a>> when 'a : equality = groupBy (=) lst
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Convert this F# snippet to Java and keep its semantics consistent.
let rec brk p lst = match lst with | [] -> (lst, lst) | x::xs -> if p x then ([], lst) else let (ys, zs) = brk p xs (x::ys, zs) let span p lst = brk (not << p) lst let rec groupBy eq lst = match lst with | [] -> [] | x::xs -> let (ys,zs) = span (eq x) xs (x::ys)::groupBy eq zs let group lst : list<list<'a>> when 'a : equality = groupBy (=) lst
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Ensure the translated Python code behaves exactly like the original F# snippet.
let rec brk p lst = match lst with | [] -> (lst, lst) | x::xs -> if p x then ([], lst) else let (ys, zs) = brk p xs (x::ys, zs) let span p lst = brk (not << p) lst let rec groupBy eq lst = match lst with | [] -> [] | x::xs -> let (ys,zs) = span (eq x) xs (x::ys)::groupBy eq zs let group lst : list<list<'a>> when 'a : equality = groupBy (=) lst
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Port the provided F# code into VB while preserving the original functionality.
let rec brk p lst = match lst with | [] -> (lst, lst) | x::xs -> if p x then ([], lst) else let (ys, zs) = brk p xs (x::ys, zs) let span p lst = brk (not << p) lst let rec groupBy eq lst = match lst with | [] -> [] | x::xs -> let (ys,zs) = span (eq x) xs (x::ys)::groupBy eq zs let group lst : list<list<'a>> when 'a : equality = groupBy (=) lst
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Convert the following code from F# to Go, ensuring the logic remains intact.
let rec brk p lst = match lst with | [] -> (lst, lst) | x::xs -> if p x then ([], lst) else let (ys, zs) = brk p xs (x::ys, zs) let span p lst = brk (not << p) lst let rec groupBy eq lst = match lst with | [] -> [] | x::xs -> let (ys,zs) = span (eq x) xs (x::ys)::groupBy eq zs let group lst : list<list<'a>> when 'a : equality = groupBy (=) lst
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Port the following code from Factor to C with equivalent syntax and logic.
: (look-and-say) ( str -- ) unclip-slice swap [ 1 ] 2dip [ 2dup = [ drop [ 1 + ] dip ] [ [ [ number>string % ] dip , 1 ] dip ] if ] each [ number>string % ] [ , ] bi* ; : look-and-say ( str -- str' ) [ (look-and-say) ] "" make ; "1" 10 [ dup print look-and-say ] times print
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Please provide an equivalent version of this Factor code in C#.
: (look-and-say) ( str -- ) unclip-slice swap [ 1 ] 2dip [ 2dup = [ drop [ 1 + ] dip ] [ [ [ number>string % ] dip , 1 ] dip ] if ] each [ number>string % ] [ , ] bi* ; : look-and-say ( str -- str' ) [ (look-and-say) ] "" make ; "1" 10 [ dup print look-and-say ] times print
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Generate an equivalent C++ version of this Factor code.
: (look-and-say) ( str -- ) unclip-slice swap [ 1 ] 2dip [ 2dup = [ drop [ 1 + ] dip ] [ [ [ number>string % ] dip , 1 ] dip ] if ] each [ number>string % ] [ , ] bi* ; : look-and-say ( str -- str' ) [ (look-and-say) ] "" make ; "1" 10 [ dup print look-and-say ] times print
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Port the following code from Factor to Java with equivalent syntax and logic.
: (look-and-say) ( str -- ) unclip-slice swap [ 1 ] 2dip [ 2dup = [ drop [ 1 + ] dip ] [ [ [ number>string % ] dip , 1 ] dip ] if ] each [ number>string % ] [ , ] bi* ; : look-and-say ( str -- str' ) [ (look-and-say) ] "" make ; "1" 10 [ dup print look-and-say ] times print
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Translate the given Factor code snippet into Python without altering its behavior.
: (look-and-say) ( str -- ) unclip-slice swap [ 1 ] 2dip [ 2dup = [ drop [ 1 + ] dip ] [ [ [ number>string % ] dip , 1 ] dip ] if ] each [ number>string % ] [ , ] bi* ; : look-and-say ( str -- str' ) [ (look-and-say) ] "" make ; "1" 10 [ dup print look-and-say ] times print
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Change the programming language of this snippet from Factor to VB without modifying what it does.
: (look-and-say) ( str -- ) unclip-slice swap [ 1 ] 2dip [ 2dup = [ drop [ 1 + ] dip ] [ [ [ number>string % ] dip , 1 ] dip ] if ] each [ number>string % ] [ , ] bi* ; : look-and-say ( str -- str' ) [ (look-and-say) ] "" make ; "1" 10 [ dup print look-and-say ] times print
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Preserve the algorithm and functionality while converting the code from Factor to Go.
: (look-and-say) ( str -- ) unclip-slice swap [ 1 ] 2dip [ 2dup = [ drop [ 1 + ] dip ] [ [ [ number>string % ] dip , 1 ] dip ] if ] each [ number>string % ] [ , ] bi* ; : look-and-say ( str -- str' ) [ (look-and-say) ] "" make ; "1" 10 [ dup print look-and-say ] times print
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Can you help me rewrite this code in C instead of Forth, keeping it the same logically?
create buf1 256 allot create buf2 256 allot buf1 value src buf2 value dest s" 1" src place : append-run dest count + tuck c! 1+ c! dest c@ 2 + dest c! ; : next-look-and-say 0 dest c! src 1+ c@ [char] 0 src count bounds do over i c@ = if 1+ else append-run i c@ [char] 1 then loop append-run src dest to src to dest ; : look-and-say 0 do next-look-and-say cr src count type loop ; 10 look-and-say
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Convert this Forth block to C#, preserving its control flow and logic.
create buf1 256 allot create buf2 256 allot buf1 value src buf2 value dest s" 1" src place : append-run dest count + tuck c! 1+ c! dest c@ 2 + dest c! ; : next-look-and-say 0 dest c! src 1+ c@ [char] 0 src count bounds do over i c@ = if 1+ else append-run i c@ [char] 1 then loop append-run src dest to src to dest ; : look-and-say 0 do next-look-and-say cr src count type loop ; 10 look-and-say
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Preserve the algorithm and functionality while converting the code from Forth to C++.
create buf1 256 allot create buf2 256 allot buf1 value src buf2 value dest s" 1" src place : append-run dest count + tuck c! 1+ c! dest c@ 2 + dest c! ; : next-look-and-say 0 dest c! src 1+ c@ [char] 0 src count bounds do over i c@ = if 1+ else append-run i c@ [char] 1 then loop append-run src dest to src to dest ; : look-and-say 0 do next-look-and-say cr src count type loop ; 10 look-and-say
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Write a version of this Forth function in Java with identical behavior.
create buf1 256 allot create buf2 256 allot buf1 value src buf2 value dest s" 1" src place : append-run dest count + tuck c! 1+ c! dest c@ 2 + dest c! ; : next-look-and-say 0 dest c! src 1+ c@ [char] 0 src count bounds do over i c@ = if 1+ else append-run i c@ [char] 1 then loop append-run src dest to src to dest ; : look-and-say 0 do next-look-and-say cr src count type loop ; 10 look-and-say
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Write a version of this Forth function in Python with identical behavior.
create buf1 256 allot create buf2 256 allot buf1 value src buf2 value dest s" 1" src place : append-run dest count + tuck c! 1+ c! dest c@ 2 + dest c! ; : next-look-and-say 0 dest c! src 1+ c@ [char] 0 src count bounds do over i c@ = if 1+ else append-run i c@ [char] 1 then loop append-run src dest to src to dest ; : look-and-say 0 do next-look-and-say cr src count type loop ; 10 look-and-say
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Transform the following Forth implementation into VB, maintaining the same output and logic.
create buf1 256 allot create buf2 256 allot buf1 value src buf2 value dest s" 1" src place : append-run dest count + tuck c! 1+ c! dest c@ 2 + dest c! ; : next-look-and-say 0 dest c! src 1+ c@ [char] 0 src count bounds do over i c@ = if 1+ else append-run i c@ [char] 1 then loop append-run src dest to src to dest ; : look-and-say 0 do next-look-and-say cr src count type loop ; 10 look-and-say
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Produce a language-to-language conversion: from Forth to Go, same semantics.
create buf1 256 allot create buf2 256 allot buf1 value src buf2 value dest s" 1" src place : append-run dest count + tuck c! 1+ c! dest c@ 2 + dest c! ; : next-look-and-say 0 dest c! src 1+ c@ [char] 0 src count bounds do over i c@ = if 1+ else append-run i c@ [char] 1 then loop append-run src dest to src to dest ; : look-and-say 0 do next-look-and-say cr src count type loop ; 10 look-and-say
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Rewrite the snippet below in C# so it works the same as the original Fortran code.
module LookAndSay implicit none contains subroutine look_and_say(in, out) character(len=*), intent(in) :: in character(len=*), intent(out) :: out integer :: i, c character(len=1) :: x character(len=2) :: d out = "" c = 1 x = in(1:1) do i = 2, len(trim(in)) if ( x == in(i:i) ) then c = c + 1 else write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) c = 1 x = in(i:i) end if end do write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) end subroutine look_and_say end module LookAndSay
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Convert the following code from Fortran to C++, ensuring the logic remains intact.
module LookAndSay implicit none contains subroutine look_and_say(in, out) character(len=*), intent(in) :: in character(len=*), intent(out) :: out integer :: i, c character(len=1) :: x character(len=2) :: d out = "" c = 1 x = in(1:1) do i = 2, len(trim(in)) if ( x == in(i:i) ) then c = c + 1 else write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) c = 1 x = in(i:i) end if end do write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) end subroutine look_and_say end module LookAndSay
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Change the programming language of this snippet from Fortran to C without modifying what it does.
module LookAndSay implicit none contains subroutine look_and_say(in, out) character(len=*), intent(in) :: in character(len=*), intent(out) :: out integer :: i, c character(len=1) :: x character(len=2) :: d out = "" c = 1 x = in(1:1) do i = 2, len(trim(in)) if ( x == in(i:i) ) then c = c + 1 else write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) c = 1 x = in(i:i) end if end do write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) end subroutine look_and_say end module LookAndSay
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Ensure the translated Java code behaves exactly like the original Fortran snippet.
module LookAndSay implicit none contains subroutine look_and_say(in, out) character(len=*), intent(in) :: in character(len=*), intent(out) :: out integer :: i, c character(len=1) :: x character(len=2) :: d out = "" c = 1 x = in(1:1) do i = 2, len(trim(in)) if ( x == in(i:i) ) then c = c + 1 else write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) c = 1 x = in(i:i) end if end do write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) end subroutine look_and_say end module LookAndSay
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Rewrite the snippet below in Python so it works the same as the original Fortran code.
module LookAndSay implicit none contains subroutine look_and_say(in, out) character(len=*), intent(in) :: in character(len=*), intent(out) :: out integer :: i, c character(len=1) :: x character(len=2) :: d out = "" c = 1 x = in(1:1) do i = 2, len(trim(in)) if ( x == in(i:i) ) then c = c + 1 else write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) c = 1 x = in(i:i) end if end do write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) end subroutine look_and_say end module LookAndSay
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Translate this program into VB but keep the logic exactly as in Fortran.
module LookAndSay implicit none contains subroutine look_and_say(in, out) character(len=*), intent(in) :: in character(len=*), intent(out) :: out integer :: i, c character(len=1) :: x character(len=2) :: d out = "" c = 1 x = in(1:1) do i = 2, len(trim(in)) if ( x == in(i:i) ) then c = c + 1 else write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) c = 1 x = in(i:i) end if end do write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) end subroutine look_and_say end module LookAndSay
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Transform the following Fortran implementation into PHP, maintaining the same output and logic.
module LookAndSay implicit none contains subroutine look_and_say(in, out) character(len=*), intent(in) :: in character(len=*), intent(out) :: out integer :: i, c character(len=1) :: x character(len=2) :: d out = "" c = 1 x = in(1:1) do i = 2, len(trim(in)) if ( x == in(i:i) ) then c = c + 1 else write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) c = 1 x = in(i:i) end if end do write(d, "(I2)") c out = trim(out) // trim(adjustl(d)) // trim(x) end subroutine look_and_say end module LookAndSay
<?php function lookAndSay($str) { return preg_replace_callback('#(.)\1*#', function($matches) { return strlen($matches[0]).$matches[1]; }, $str); } $num = "1"; foreach(range(1,10) as $i) { echo $num."<br/>"; $num = lookAndSay($num); } ?>
Can you help me rewrite this code in C instead of Groovy, keeping it the same logically?
def lookAndSay(sequence) { def encoded = new StringBuilder() (sequence.toString() =~ /(([0-9])\2*)/).each { matcher -> encoded.append(matcher[1].size()).append(matcher[2]) } encoded.toString() }
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Convert this Groovy block to C#, preserving its control flow and logic.
def lookAndSay(sequence) { def encoded = new StringBuilder() (sequence.toString() =~ /(([0-9])\2*)/).each { matcher -> encoded.append(matcher[1].size()).append(matcher[2]) } encoded.toString() }
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Convert the following code from Groovy to C++, ensuring the logic remains intact.
def lookAndSay(sequence) { def encoded = new StringBuilder() (sequence.toString() =~ /(([0-9])\2*)/).each { matcher -> encoded.append(matcher[1].size()).append(matcher[2]) } encoded.toString() }
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Port the following code from Groovy to Java with equivalent syntax and logic.
def lookAndSay(sequence) { def encoded = new StringBuilder() (sequence.toString() =~ /(([0-9])\2*)/).each { matcher -> encoded.append(matcher[1].size()).append(matcher[2]) } encoded.toString() }
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Generate a Python translation of this Groovy snippet without changing its computational steps.
def lookAndSay(sequence) { def encoded = new StringBuilder() (sequence.toString() =~ /(([0-9])\2*)/).each { matcher -> encoded.append(matcher[1].size()).append(matcher[2]) } encoded.toString() }
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Produce a functionally identical VB code for the snippet given in Groovy.
def lookAndSay(sequence) { def encoded = new StringBuilder() (sequence.toString() =~ /(([0-9])\2*)/).each { matcher -> encoded.append(matcher[1].size()).append(matcher[2]) } encoded.toString() }
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Please provide an equivalent version of this Groovy code in Go.
def lookAndSay(sequence) { def encoded = new StringBuilder() (sequence.toString() =~ /(([0-9])\2*)/).each { matcher -> encoded.append(matcher[1].size()).append(matcher[2]) } encoded.toString() }
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Convert the following code from Haskell to C, ensuring the logic remains intact.
import Control.Monad (liftM2) import Data.List (group) lookAndSay :: Integer -> Integer lookAndSay = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay2 :: Integer -> Integer lookAndSay2 = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay3 :: Integer -> Integer lookAndSay3 n = read (concatMap describe (group (show n))) where describe run = show (length run) ++ take 1 run main = mapM_ print (iterate lookAndSay 1)
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Ensure the translated C# code behaves exactly like the original Haskell snippet.
import Control.Monad (liftM2) import Data.List (group) lookAndSay :: Integer -> Integer lookAndSay = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay2 :: Integer -> Integer lookAndSay2 = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay3 :: Integer -> Integer lookAndSay3 n = read (concatMap describe (group (show n))) where describe run = show (length run) ++ take 1 run main = mapM_ print (iterate lookAndSay 1)
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Convert this Haskell block to Java, preserving its control flow and logic.
import Control.Monad (liftM2) import Data.List (group) lookAndSay :: Integer -> Integer lookAndSay = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay2 :: Integer -> Integer lookAndSay2 = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay3 :: Integer -> Integer lookAndSay3 n = read (concatMap describe (group (show n))) where describe run = show (length run) ++ take 1 run main = mapM_ print (iterate lookAndSay 1)
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Maintain the same structure and functionality when rewriting this code in Python.
import Control.Monad (liftM2) import Data.List (group) lookAndSay :: Integer -> Integer lookAndSay = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay2 :: Integer -> Integer lookAndSay2 = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay3 :: Integer -> Integer lookAndSay3 n = read (concatMap describe (group (show n))) where describe run = show (length run) ++ take 1 run main = mapM_ print (iterate lookAndSay 1)
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Ensure the translated VB code behaves exactly like the original Haskell snippet.
import Control.Monad (liftM2) import Data.List (group) lookAndSay :: Integer -> Integer lookAndSay = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay2 :: Integer -> Integer lookAndSay2 = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay3 :: Integer -> Integer lookAndSay3 n = read (concatMap describe (group (show n))) where describe run = show (length run) ++ take 1 run main = mapM_ print (iterate lookAndSay 1)
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Translate this program into Go but keep the logic exactly as in Haskell.
import Control.Monad (liftM2) import Data.List (group) lookAndSay :: Integer -> Integer lookAndSay = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay2 :: Integer -> Integer lookAndSay2 = read . concatMap (liftM2 (++) (show . length) (take 1)) . group . show lookAndSay3 :: Integer -> Integer lookAndSay3 n = read (concatMap describe (group (show n))) where describe run = show (length run) ++ take 1 run main = mapM_ print (iterate lookAndSay 1)
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Preserve the algorithm and functionality while converting the code from Icon to C.
procedure main() every 1 to 10 do write(n := nextlooknsayseq(\n | 1)) end procedure nextlooknsayseq(n) n2 := "" n ? until pos(0) do { i := tab(any(&digits)) | fail move(-1) n2 ||:= *tab(many(i)) || i } return n2 end
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Can you help me rewrite this code in C# instead of Icon, keeping it the same logically?
procedure main() every 1 to 10 do write(n := nextlooknsayseq(\n | 1)) end procedure nextlooknsayseq(n) n2 := "" n ? until pos(0) do { i := tab(any(&digits)) | fail move(-1) n2 ||:= *tab(many(i)) || i } return n2 end
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Write a version of this Icon function in C++ with identical behavior.
procedure main() every 1 to 10 do write(n := nextlooknsayseq(\n | 1)) end procedure nextlooknsayseq(n) n2 := "" n ? until pos(0) do { i := tab(any(&digits)) | fail move(-1) n2 ||:= *tab(many(i)) || i } return n2 end
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Change the following Icon code into Java without altering its purpose.
procedure main() every 1 to 10 do write(n := nextlooknsayseq(\n | 1)) end procedure nextlooknsayseq(n) n2 := "" n ? until pos(0) do { i := tab(any(&digits)) | fail move(-1) n2 ||:= *tab(many(i)) || i } return n2 end
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Please provide an equivalent version of this Icon code in Python.
procedure main() every 1 to 10 do write(n := nextlooknsayseq(\n | 1)) end procedure nextlooknsayseq(n) n2 := "" n ? until pos(0) do { i := tab(any(&digits)) | fail move(-1) n2 ||:= *tab(many(i)) || i } return n2 end
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Write the same algorithm in VB as shown in this Icon implementation.
procedure main() every 1 to 10 do write(n := nextlooknsayseq(\n | 1)) end procedure nextlooknsayseq(n) n2 := "" n ? until pos(0) do { i := tab(any(&digits)) | fail move(-1) n2 ||:= *tab(many(i)) || i } return n2 end
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Port the following code from Icon to Go with equivalent syntax and logic.
procedure main() every 1 to 10 do write(n := nextlooknsayseq(\n | 1)) end procedure nextlooknsayseq(n) n2 := "" n ? until pos(0) do { i := tab(any(&digits)) | fail move(-1) n2 ||:= *tab(many(i)) || i } return n2 end
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Transform the following J implementation into C, maintaining the same output and logic.
las=: ,@((# , {.);.1~ 1 , 2 ~:/\ ])&.(10x&#.inv)@]^:(1+i.@[)
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Produce a language-to-language conversion: from J to C#, same semantics.
las=: ,@((# , {.);.1~ 1 , 2 ~:/\ ])&.(10x&#.inv)@]^:(1+i.@[)
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Keep all operations the same but rewrite the snippet in C++.
las=: ,@((# , {.);.1~ 1 , 2 ~:/\ ])&.(10x&#.inv)@]^:(1+i.@[)
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Port the following code from J to Python with equivalent syntax and logic.
las=: ,@((# , {.);.1~ 1 , 2 ~:/\ ])&.(10x&#.inv)@]^:(1+i.@[)
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Convert this J snippet to VB and keep its semantics consistent.
las=: ,@((# , {.);.1~ 1 , 2 ~:/\ ])&.(10x&#.inv)@]^:(1+i.@[)
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Preserve the algorithm and functionality while converting the code from J to Go.
las=: ,@((# , {.);.1~ 1 , 2 ~:/\ ])&.(10x&#.inv)@]^:(1+i.@[)
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Can you help me rewrite this code in C instead of Julia, keeping it the same logically?
function lookandsay(s::String) rst = IOBuffer() c = 1 for i in 1:length(s) if i != length(s) && s[i] == s[i+1] c += 1 else print(rst, c, s[i]) c = 1 end end String(take!(rst)) end function lookandsayseq(n::Integer) rst = Vector{String}(undef, n) rst[1] = "1" for i in 2:n rst[i] = lookandsay(rst[i-1]) end rst end println(lookandsayseq(10))
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Generate an equivalent C# version of this Julia code.
function lookandsay(s::String) rst = IOBuffer() c = 1 for i in 1:length(s) if i != length(s) && s[i] == s[i+1] c += 1 else print(rst, c, s[i]) c = 1 end end String(take!(rst)) end function lookandsayseq(n::Integer) rst = Vector{String}(undef, n) rst[1] = "1" for i in 2:n rst[i] = lookandsay(rst[i-1]) end rst end println(lookandsayseq(10))
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }