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Convert this Julia block to C++, preserving its control flow and logic.
function lookandsay(s::String) rst = IOBuffer() c = 1 for i in 1:length(s) if i != length(s) && s[i] == s[i+1] c += 1 else print(rst, c, s[i]) c = 1 end end String(take!(rst)) end function lookandsayseq(n::Integer) rst = Vector{String}(undef, n) rst[1] = "1" for i in 2:n rst[i] = lookandsay(rst[i-1]) end rst end println(lookandsayseq(10))
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Generate a Java translation of this Julia snippet without changing its computational steps.
function lookandsay(s::String) rst = IOBuffer() c = 1 for i in 1:length(s) if i != length(s) && s[i] == s[i+1] c += 1 else print(rst, c, s[i]) c = 1 end end String(take!(rst)) end function lookandsayseq(n::Integer) rst = Vector{String}(undef, n) rst[1] = "1" for i in 2:n rst[i] = lookandsay(rst[i-1]) end rst end println(lookandsayseq(10))
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Preserve the algorithm and functionality while converting the code from Julia to Python.
function lookandsay(s::String) rst = IOBuffer() c = 1 for i in 1:length(s) if i != length(s) && s[i] == s[i+1] c += 1 else print(rst, c, s[i]) c = 1 end end String(take!(rst)) end function lookandsayseq(n::Integer) rst = Vector{String}(undef, n) rst[1] = "1" for i in 2:n rst[i] = lookandsay(rst[i-1]) end rst end println(lookandsayseq(10))
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Convert this Julia snippet to VB and keep its semantics consistent.
function lookandsay(s::String) rst = IOBuffer() c = 1 for i in 1:length(s) if i != length(s) && s[i] == s[i+1] c += 1 else print(rst, c, s[i]) c = 1 end end String(take!(rst)) end function lookandsayseq(n::Integer) rst = Vector{String}(undef, n) rst[1] = "1" for i in 2:n rst[i] = lookandsay(rst[i-1]) end rst end println(lookandsayseq(10))
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Rewrite this program in Go while keeping its functionality equivalent to the Julia version.
function lookandsay(s::String) rst = IOBuffer() c = 1 for i in 1:length(s) if i != length(s) && s[i] == s[i+1] c += 1 else print(rst, c, s[i]) c = 1 end end String(take!(rst)) end function lookandsayseq(n::Integer) rst = Vector{String}(undef, n) rst[1] = "1" for i in 2:n rst[i] = lookandsay(rst[i-1]) end rst end println(lookandsayseq(10))
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Produce a functionally identical C code for the snippet given in Lua.
function lookAndSay S put 0 into C put char 1 of S into lastChar repeat with i = 2 to length(S) add 1 to C if char i of S is lastChar then next repeat put C & lastChar after R put 0 into C put char i of S into lastChar end repeat return R & C + 1 & lastChar end lookAndSay on demoLookAndSay put 1 into x repeat 10 put x & cr after message put lookAndSay(x) into x end repeat put x after message end demoLookAndSay
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Convert this Lua snippet to C# and keep its semantics consistent.
function lookAndSay S put 0 into C put char 1 of S into lastChar repeat with i = 2 to length(S) add 1 to C if char i of S is lastChar then next repeat put C & lastChar after R put 0 into C put char i of S into lastChar end repeat return R & C + 1 & lastChar end lookAndSay on demoLookAndSay put 1 into x repeat 10 put x & cr after message put lookAndSay(x) into x end repeat put x after message end demoLookAndSay
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Port the provided Lua code into C++ while preserving the original functionality.
function lookAndSay S put 0 into C put char 1 of S into lastChar repeat with i = 2 to length(S) add 1 to C if char i of S is lastChar then next repeat put C & lastChar after R put 0 into C put char i of S into lastChar end repeat return R & C + 1 & lastChar end lookAndSay on demoLookAndSay put 1 into x repeat 10 put x & cr after message put lookAndSay(x) into x end repeat put x after message end demoLookAndSay
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Port the following code from Lua to Java with equivalent syntax and logic.
function lookAndSay S put 0 into C put char 1 of S into lastChar repeat with i = 2 to length(S) add 1 to C if char i of S is lastChar then next repeat put C & lastChar after R put 0 into C put char i of S into lastChar end repeat return R & C + 1 & lastChar end lookAndSay on demoLookAndSay put 1 into x repeat 10 put x & cr after message put lookAndSay(x) into x end repeat put x after message end demoLookAndSay
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Convert this Lua snippet to Python and keep its semantics consistent.
function lookAndSay S put 0 into C put char 1 of S into lastChar repeat with i = 2 to length(S) add 1 to C if char i of S is lastChar then next repeat put C & lastChar after R put 0 into C put char i of S into lastChar end repeat return R & C + 1 & lastChar end lookAndSay on demoLookAndSay put 1 into x repeat 10 put x & cr after message put lookAndSay(x) into x end repeat put x after message end demoLookAndSay
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Write the same algorithm in VB as shown in this Lua implementation.
function lookAndSay S put 0 into C put char 1 of S into lastChar repeat with i = 2 to length(S) add 1 to C if char i of S is lastChar then next repeat put C & lastChar after R put 0 into C put char i of S into lastChar end repeat return R & C + 1 & lastChar end lookAndSay on demoLookAndSay put 1 into x repeat 10 put x & cr after message put lookAndSay(x) into x end repeat put x after message end demoLookAndSay
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Translate the given Lua code snippet into Go without altering its behavior.
function lookAndSay S put 0 into C put char 1 of S into lastChar repeat with i = 2 to length(S) add 1 to C if char i of S is lastChar then next repeat put C & lastChar after R put 0 into C put char i of S into lastChar end repeat return R & C + 1 & lastChar end lookAndSay on demoLookAndSay put 1 into x repeat 10 put x & cr after message put lookAndSay(x) into x end repeat put x after message end demoLookAndSay
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Produce a functionally identical C code for the snippet given in Mathematica.
LookAndSay[n_Integer?Positive]:= Reverse @@@ Tally /@ Split @ IntegerDigits @ n // Flatten // FromDigits
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Keep all operations the same but rewrite the snippet in C#.
LookAndSay[n_Integer?Positive]:= Reverse @@@ Tally /@ Split @ IntegerDigits @ n // Flatten // FromDigits
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Port the following code from Mathematica to C++ with equivalent syntax and logic.
LookAndSay[n_Integer?Positive]:= Reverse @@@ Tally /@ Split @ IntegerDigits @ n // Flatten // FromDigits
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Translate this program into Java but keep the logic exactly as in Mathematica.
LookAndSay[n_Integer?Positive]:= Reverse @@@ Tally /@ Split @ IntegerDigits @ n // Flatten // FromDigits
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Port the provided Mathematica code into Python while preserving the original functionality.
LookAndSay[n_Integer?Positive]:= Reverse @@@ Tally /@ Split @ IntegerDigits @ n // Flatten // FromDigits
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Rewrite the snippet below in VB so it works the same as the original Mathematica code.
LookAndSay[n_Integer?Positive]:= Reverse @@@ Tally /@ Split @ IntegerDigits @ n // Flatten // FromDigits
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Port the provided Mathematica code into Go while preserving the original functionality.
LookAndSay[n_Integer?Positive]:= Reverse @@@ Tally /@ Split @ IntegerDigits @ n // Flatten // FromDigits
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Keep all operations the same but rewrite the snippet in C.
iterator lookAndSay(n: int): string = var current = "1" yield current for round in 2..n: var ch = current[0] var count = 1 var next = "" for i in 1..current.high: if current[i] == ch: inc count else: next.add $count & ch ch = current[i] count = 1 current = next & $count & ch yield current for s in lookAndSay(12): echo s
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Keep all operations the same but rewrite the snippet in C#.
iterator lookAndSay(n: int): string = var current = "1" yield current for round in 2..n: var ch = current[0] var count = 1 var next = "" for i in 1..current.high: if current[i] == ch: inc count else: next.add $count & ch ch = current[i] count = 1 current = next & $count & ch yield current for s in lookAndSay(12): echo s
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Write the same algorithm in C++ as shown in this Nim implementation.
iterator lookAndSay(n: int): string = var current = "1" yield current for round in 2..n: var ch = current[0] var count = 1 var next = "" for i in 1..current.high: if current[i] == ch: inc count else: next.add $count & ch ch = current[i] count = 1 current = next & $count & ch yield current for s in lookAndSay(12): echo s
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Translate this program into Java but keep the logic exactly as in Nim.
iterator lookAndSay(n: int): string = var current = "1" yield current for round in 2..n: var ch = current[0] var count = 1 var next = "" for i in 1..current.high: if current[i] == ch: inc count else: next.add $count & ch ch = current[i] count = 1 current = next & $count & ch yield current for s in lookAndSay(12): echo s
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Transform the following Nim implementation into Python, maintaining the same output and logic.
iterator lookAndSay(n: int): string = var current = "1" yield current for round in 2..n: var ch = current[0] var count = 1 var next = "" for i in 1..current.high: if current[i] == ch: inc count else: next.add $count & ch ch = current[i] count = 1 current = next & $count & ch yield current for s in lookAndSay(12): echo s
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Rewrite this program in VB while keeping its functionality equivalent to the Nim version.
iterator lookAndSay(n: int): string = var current = "1" yield current for round in 2..n: var ch = current[0] var count = 1 var next = "" for i in 1..current.high: if current[i] == ch: inc count else: next.add $count & ch ch = current[i] count = 1 current = next & $count & ch yield current for s in lookAndSay(12): echo s
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Preserve the algorithm and functionality while converting the code from Nim to Go.
iterator lookAndSay(n: int): string = var current = "1" yield current for round in 2..n: var ch = current[0] var count = 1 var next = "" for i in 1..current.high: if current[i] == ch: inc count else: next.add $count & ch ch = current[i] count = 1 current = next & $count & ch yield current for s in lookAndSay(12): echo s
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Please provide an equivalent version of this OCaml code in C.
let rec seeAndSay = function | [], nys -> List.rev nys | x::xs, [] -> seeAndSay(xs, [x; 1]) | x::xs, y::n::nys when x=y -> seeAndSay(xs, y::1+n::nys) | x::xs, nys -> seeAndSay(xs, x::1::nys)
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Port the following code from OCaml to C# with equivalent syntax and logic.
let rec seeAndSay = function | [], nys -> List.rev nys | x::xs, [] -> seeAndSay(xs, [x; 1]) | x::xs, y::n::nys when x=y -> seeAndSay(xs, y::1+n::nys) | x::xs, nys -> seeAndSay(xs, x::1::nys)
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Keep all operations the same but rewrite the snippet in C++.
let rec seeAndSay = function | [], nys -> List.rev nys | x::xs, [] -> seeAndSay(xs, [x; 1]) | x::xs, y::n::nys when x=y -> seeAndSay(xs, y::1+n::nys) | x::xs, nys -> seeAndSay(xs, x::1::nys)
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Change the programming language of this snippet from OCaml to Java without modifying what it does.
let rec seeAndSay = function | [], nys -> List.rev nys | x::xs, [] -> seeAndSay(xs, [x; 1]) | x::xs, y::n::nys when x=y -> seeAndSay(xs, y::1+n::nys) | x::xs, nys -> seeAndSay(xs, x::1::nys)
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Write the same code in Python as shown below in OCaml.
let rec seeAndSay = function | [], nys -> List.rev nys | x::xs, [] -> seeAndSay(xs, [x; 1]) | x::xs, y::n::nys when x=y -> seeAndSay(xs, y::1+n::nys) | x::xs, nys -> seeAndSay(xs, x::1::nys)
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Write the same algorithm in VB as shown in this OCaml implementation.
let rec seeAndSay = function | [], nys -> List.rev nys | x::xs, [] -> seeAndSay(xs, [x; 1]) | x::xs, y::n::nys when x=y -> seeAndSay(xs, y::1+n::nys) | x::xs, nys -> seeAndSay(xs, x::1::nys)
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Preserve the algorithm and functionality while converting the code from OCaml to Go.
let rec seeAndSay = function | [], nys -> List.rev nys | x::xs, [] -> seeAndSay(xs, [x; 1]) | x::xs, y::n::nys when x=y -> seeAndSay(xs, y::1+n::nys) | x::xs, nys -> seeAndSay(xs, x::1::nys)
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Transform the following Pascal implementation into C, maintaining the same output and logic.
program LookAndSayDemo(input, output); uses SysUtils; function LookAndSay(s: string): string; var item: char; index: integer; count: integer; begin Result := ''; item := s[1]; count := 1; for index := 2 to length(s) do if item = s[index] then inc(count) else begin Result := Result + intTostr(count) + item; item := s[index]; count := 1; end; Result := Result + intTostr(count) + item; end; var number: string; begin writeln('Press RETURN to continue and ^C to stop.'); number := '1'; while not eof(input) do begin write(number); readln; number := LookAndSay(number); end; end.
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Transform the following Pascal implementation into C++, maintaining the same output and logic.
program LookAndSayDemo(input, output); uses SysUtils; function LookAndSay(s: string): string; var item: char; index: integer; count: integer; begin Result := ''; item := s[1]; count := 1; for index := 2 to length(s) do if item = s[index] then inc(count) else begin Result := Result + intTostr(count) + item; item := s[index]; count := 1; end; Result := Result + intTostr(count) + item; end; var number: string; begin writeln('Press RETURN to continue and ^C to stop.'); number := '1'; while not eof(input) do begin write(number); readln; number := LookAndSay(number); end; end.
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Rewrite this program in Java while keeping its functionality equivalent to the Pascal version.
program LookAndSayDemo(input, output); uses SysUtils; function LookAndSay(s: string): string; var item: char; index: integer; count: integer; begin Result := ''; item := s[1]; count := 1; for index := 2 to length(s) do if item = s[index] then inc(count) else begin Result := Result + intTostr(count) + item; item := s[index]; count := 1; end; Result := Result + intTostr(count) + item; end; var number: string; begin writeln('Press RETURN to continue and ^C to stop.'); number := '1'; while not eof(input) do begin write(number); readln; number := LookAndSay(number); end; end.
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Keep all operations the same but rewrite the snippet in Python.
program LookAndSayDemo(input, output); uses SysUtils; function LookAndSay(s: string): string; var item: char; index: integer; count: integer; begin Result := ''; item := s[1]; count := 1; for index := 2 to length(s) do if item = s[index] then inc(count) else begin Result := Result + intTostr(count) + item; item := s[index]; count := 1; end; Result := Result + intTostr(count) + item; end; var number: string; begin writeln('Press RETURN to continue and ^C to stop.'); number := '1'; while not eof(input) do begin write(number); readln; number := LookAndSay(number); end; end.
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Produce a functionally identical VB code for the snippet given in Pascal.
program LookAndSayDemo(input, output); uses SysUtils; function LookAndSay(s: string): string; var item: char; index: integer; count: integer; begin Result := ''; item := s[1]; count := 1; for index := 2 to length(s) do if item = s[index] then inc(count) else begin Result := Result + intTostr(count) + item; item := s[index]; count := 1; end; Result := Result + intTostr(count) + item; end; var number: string; begin writeln('Press RETURN to continue and ^C to stop.'); number := '1'; while not eof(input) do begin write(number); readln; number := LookAndSay(number); end; end.
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Change the programming language of this snippet from Pascal to Go without modifying what it does.
program LookAndSayDemo(input, output); uses SysUtils; function LookAndSay(s: string): string; var item: char; index: integer; count: integer; begin Result := ''; item := s[1]; count := 1; for index := 2 to length(s) do if item = s[index] then inc(count) else begin Result := Result + intTostr(count) + item; item := s[index]; count := 1; end; Result := Result + intTostr(count) + item; end; var number: string; begin writeln('Press RETURN to continue and ^C to stop.'); number := '1'; while not eof(input) do begin write(number); readln; number := LookAndSay(number); end; end.
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Transform the following Perl implementation into C, maintaining the same output and logic.
sub lookandsay { my $str = shift; $str =~ s/((.)\2*)/length($1) . $2/ge; return $str; } my $num = "1"; foreach (1..10) { print "$num\n"; $num = lookandsay($num); }
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Keep all operations the same but rewrite the snippet in C#.
sub lookandsay { my $str = shift; $str =~ s/((.)\2*)/length($1) . $2/ge; return $str; } my $num = "1"; foreach (1..10) { print "$num\n"; $num = lookandsay($num); }
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Can you help me rewrite this code in C++ instead of Perl, keeping it the same logically?
sub lookandsay { my $str = shift; $str =~ s/((.)\2*)/length($1) . $2/ge; return $str; } my $num = "1"; foreach (1..10) { print "$num\n"; $num = lookandsay($num); }
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Translate this program into Java but keep the logic exactly as in Perl.
sub lookandsay { my $str = shift; $str =~ s/((.)\2*)/length($1) . $2/ge; return $str; } my $num = "1"; foreach (1..10) { print "$num\n"; $num = lookandsay($num); }
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Write the same code in Python as shown below in Perl.
sub lookandsay { my $str = shift; $str =~ s/((.)\2*)/length($1) . $2/ge; return $str; } my $num = "1"; foreach (1..10) { print "$num\n"; $num = lookandsay($num); }
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Translate this program into VB but keep the logic exactly as in Perl.
sub lookandsay { my $str = shift; $str =~ s/((.)\2*)/length($1) . $2/ge; return $str; } my $num = "1"; foreach (1..10) { print "$num\n"; $num = lookandsay($num); }
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Change the following Perl code into Go without altering its purpose.
sub lookandsay { my $str = shift; $str =~ s/((.)\2*)/length($1) . $2/ge; return $str; } my $num = "1"; foreach (1..10) { print "$num\n"; $num = lookandsay($num); }
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Port the provided PowerShell code into C while preserving the original functionality.
function Get-LookAndSay ($n = 1) { $re = [regex] '(.)\1*' $ret = "" foreach ($m in $re.Matches($n)) { $ret += [string] $m.Length + $m.Value[0] } return $ret } function Get-MultipleLookAndSay ($n) { if ($n -eq 0) { return @() } else { $a = 1 $a for ($i = 1; $i -lt $n; $i++) { $a = Get-LookAndSay $a $a } } }
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Port the following code from PowerShell to C# with equivalent syntax and logic.
function Get-LookAndSay ($n = 1) { $re = [regex] '(.)\1*' $ret = "" foreach ($m in $re.Matches($n)) { $ret += [string] $m.Length + $m.Value[0] } return $ret } function Get-MultipleLookAndSay ($n) { if ($n -eq 0) { return @() } else { $a = 1 $a for ($i = 1; $i -lt $n; $i++) { $a = Get-LookAndSay $a $a } } }
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Translate the given PowerShell code snippet into C++ without altering its behavior.
function Get-LookAndSay ($n = 1) { $re = [regex] '(.)\1*' $ret = "" foreach ($m in $re.Matches($n)) { $ret += [string] $m.Length + $m.Value[0] } return $ret } function Get-MultipleLookAndSay ($n) { if ($n -eq 0) { return @() } else { $a = 1 $a for ($i = 1; $i -lt $n; $i++) { $a = Get-LookAndSay $a $a } } }
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Rewrite the snippet below in Java so it works the same as the original PowerShell code.
function Get-LookAndSay ($n = 1) { $re = [regex] '(.)\1*' $ret = "" foreach ($m in $re.Matches($n)) { $ret += [string] $m.Length + $m.Value[0] } return $ret } function Get-MultipleLookAndSay ($n) { if ($n -eq 0) { return @() } else { $a = 1 $a for ($i = 1; $i -lt $n; $i++) { $a = Get-LookAndSay $a $a } } }
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Produce a language-to-language conversion: from PowerShell to Python, same semantics.
function Get-LookAndSay ($n = 1) { $re = [regex] '(.)\1*' $ret = "" foreach ($m in $re.Matches($n)) { $ret += [string] $m.Length + $m.Value[0] } return $ret } function Get-MultipleLookAndSay ($n) { if ($n -eq 0) { return @() } else { $a = 1 $a for ($i = 1; $i -lt $n; $i++) { $a = Get-LookAndSay $a $a } } }
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Port the following code from PowerShell to VB with equivalent syntax and logic.
function Get-LookAndSay ($n = 1) { $re = [regex] '(.)\1*' $ret = "" foreach ($m in $re.Matches($n)) { $ret += [string] $m.Length + $m.Value[0] } return $ret } function Get-MultipleLookAndSay ($n) { if ($n -eq 0) { return @() } else { $a = 1 $a for ($i = 1; $i -lt $n; $i++) { $a = Get-LookAndSay $a $a } } }
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Maintain the same structure and functionality when rewriting this code in Go.
function Get-LookAndSay ($n = 1) { $re = [regex] '(.)\1*' $ret = "" foreach ($m in $re.Matches($n)) { $ret += [string] $m.Length + $m.Value[0] } return $ret } function Get-MultipleLookAndSay ($n) { if ($n -eq 0) { return @() } else { $a = 1 $a for ($i = 1; $i -lt $n; $i++) { $a = Get-LookAndSay $a $a } } }
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Translate this program into C but keep the logic exactly as in R.
look.and.say <- function(x, return.an.int=FALSE) { xstr <- unlist(strsplit(as.character(x), "")) rlex <- rle(xstr) odds <- as.character(rlex$lengths) evens <- rlex$values newstr <- as.vector(rbind(odds, evens)) newstr <- paste(newstr, collapse="") if(return.an.int) as.integer(newstr) else newstr }
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Convert this R block to C#, preserving its control flow and logic.
look.and.say <- function(x, return.an.int=FALSE) { xstr <- unlist(strsplit(as.character(x), "")) rlex <- rle(xstr) odds <- as.character(rlex$lengths) evens <- rlex$values newstr <- as.vector(rbind(odds, evens)) newstr <- paste(newstr, collapse="") if(return.an.int) as.integer(newstr) else newstr }
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Write the same code in C++ as shown below in R.
look.and.say <- function(x, return.an.int=FALSE) { xstr <- unlist(strsplit(as.character(x), "")) rlex <- rle(xstr) odds <- as.character(rlex$lengths) evens <- rlex$values newstr <- as.vector(rbind(odds, evens)) newstr <- paste(newstr, collapse="") if(return.an.int) as.integer(newstr) else newstr }
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Convert this R block to Java, preserving its control flow and logic.
look.and.say <- function(x, return.an.int=FALSE) { xstr <- unlist(strsplit(as.character(x), "")) rlex <- rle(xstr) odds <- as.character(rlex$lengths) evens <- rlex$values newstr <- as.vector(rbind(odds, evens)) newstr <- paste(newstr, collapse="") if(return.an.int) as.integer(newstr) else newstr }
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Rewrite this program in Python while keeping its functionality equivalent to the R version.
look.and.say <- function(x, return.an.int=FALSE) { xstr <- unlist(strsplit(as.character(x), "")) rlex <- rle(xstr) odds <- as.character(rlex$lengths) evens <- rlex$values newstr <- as.vector(rbind(odds, evens)) newstr <- paste(newstr, collapse="") if(return.an.int) as.integer(newstr) else newstr }
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Translate the given R code snippet into VB without altering its behavior.
look.and.say <- function(x, return.an.int=FALSE) { xstr <- unlist(strsplit(as.character(x), "")) rlex <- rle(xstr) odds <- as.character(rlex$lengths) evens <- rlex$values newstr <- as.vector(rbind(odds, evens)) newstr <- paste(newstr, collapse="") if(return.an.int) as.integer(newstr) else newstr }
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Rewrite the snippet below in Go so it works the same as the original R code.
look.and.say <- function(x, return.an.int=FALSE) { xstr <- unlist(strsplit(as.character(x), "")) rlex <- rle(xstr) odds <- as.character(rlex$lengths) evens <- rlex$values newstr <- as.vector(rbind(odds, evens)) newstr <- paste(newstr, collapse="") if(return.an.int) as.integer(newstr) else newstr }
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Ensure the translated C code behaves exactly like the original Racket snippet.
#lang racket (define (encode str) (regexp-replace* #px"(.)\\1*" str (lambda (m c) (~a (string-length m) c)))) (define (look-and-say-sequence n) (reverse (for/fold ([r '("1")]) ([n n]) (cons (encode (car r)) r)))) (for-each displayln (look-and-say-sequence 10))
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Produce a functionally identical C# code for the snippet given in Racket.
#lang racket (define (encode str) (regexp-replace* #px"(.)\\1*" str (lambda (m c) (~a (string-length m) c)))) (define (look-and-say-sequence n) (reverse (for/fold ([r '("1")]) ([n n]) (cons (encode (car r)) r)))) (for-each displayln (look-and-say-sequence 10))
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Port the following code from Racket to C++ with equivalent syntax and logic.
#lang racket (define (encode str) (regexp-replace* #px"(.)\\1*" str (lambda (m c) (~a (string-length m) c)))) (define (look-and-say-sequence n) (reverse (for/fold ([r '("1")]) ([n n]) (cons (encode (car r)) r)))) (for-each displayln (look-and-say-sequence 10))
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Translate this program into Java but keep the logic exactly as in Racket.
#lang racket (define (encode str) (regexp-replace* #px"(.)\\1*" str (lambda (m c) (~a (string-length m) c)))) (define (look-and-say-sequence n) (reverse (for/fold ([r '("1")]) ([n n]) (cons (encode (car r)) r)))) (for-each displayln (look-and-say-sequence 10))
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Port the following code from Racket to Python with equivalent syntax and logic.
#lang racket (define (encode str) (regexp-replace* #px"(.)\\1*" str (lambda (m c) (~a (string-length m) c)))) (define (look-and-say-sequence n) (reverse (for/fold ([r '("1")]) ([n n]) (cons (encode (car r)) r)))) (for-each displayln (look-and-say-sequence 10))
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Keep all operations the same but rewrite the snippet in VB.
#lang racket (define (encode str) (regexp-replace* #px"(.)\\1*" str (lambda (m c) (~a (string-length m) c)))) (define (look-and-say-sequence n) (reverse (for/fold ([r '("1")]) ([n n]) (cons (encode (car r)) r)))) (for-each displayln (look-and-say-sequence 10))
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Produce a language-to-language conversion: from Racket to Go, same semantics.
#lang racket (define (encode str) (regexp-replace* #px"(.)\\1*" str (lambda (m c) (~a (string-length m) c)))) (define (look-and-say-sequence n) (reverse (for/fold ([r '("1")]) ([n n]) (cons (encode (car r)) r)))) (for-each displayln (look-and-say-sequence 10))
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Convert this COBOL snippet to C and keep its semantics consistent.
IDENTIFICATION DIVISION. PROGRAM-ID. LOOK-AND-SAY-SEQ. DATA DIVISION. WORKING-STORAGE SECTION. 01 SEQUENCES. 02 CUR-SEQ PIC X(80) VALUE "1". 02 CUR-CHARS REDEFINES CUR-SEQ PIC X OCCURS 80 TIMES INDEXED BY CI. 02 CUR-LENGTH PIC 99 COMP VALUE 1. 02 NEXT-SEQ PIC X(80). 02 NEXT-CHARS REDEFINES NEXT-SEQ PIC X OCCURS 80 TIMES INDEXED BY NI. 01 ALG-STATE. 02 STEP-AMOUNT PIC 99 VALUE 14. 02 ITEM-COUNT PIC 9. PROCEDURE DIVISION. LOOK-AND-SAY. DISPLAY CUR-SEQ. SET CI TO 1. SET NI TO 1. MAKE-NEXT-ENTRY. MOVE 0 TO ITEM-COUNT. IF CI IS GREATER THAN CUR-LENGTH GO TO STEP-DONE. TALLY-ITEM. ADD 1 TO ITEM-COUNT. SET CI UP BY 1. IF CI IS NOT GREATER THAN CUR-LENGTH AND CUR-CHARS(CI) IS EQUAL TO CUR-CHARS(CI - 1) GO TO TALLY-ITEM. INSERT-ENTRY. MOVE ITEM-COUNT TO NEXT-CHARS(NI). MOVE CUR-CHARS(CI - 1) TO NEXT-CHARS(NI + 1). SET NI UP BY 2. GO TO MAKE-NEXT-ENTRY. STEP-DONE. MOVE NEXT-SEQ TO CUR-SEQ. SET NI DOWN BY 1. SET CUR-LENGTH TO NI. SUBTRACT 1 FROM STEP-AMOUNT. IF STEP-AMOUNT IS NOT EQUAL TO ZERO GO TO LOOK-AND-SAY. STOP RUN.
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Can you help me rewrite this code in C# instead of COBOL, keeping it the same logically?
IDENTIFICATION DIVISION. PROGRAM-ID. LOOK-AND-SAY-SEQ. DATA DIVISION. WORKING-STORAGE SECTION. 01 SEQUENCES. 02 CUR-SEQ PIC X(80) VALUE "1". 02 CUR-CHARS REDEFINES CUR-SEQ PIC X OCCURS 80 TIMES INDEXED BY CI. 02 CUR-LENGTH PIC 99 COMP VALUE 1. 02 NEXT-SEQ PIC X(80). 02 NEXT-CHARS REDEFINES NEXT-SEQ PIC X OCCURS 80 TIMES INDEXED BY NI. 01 ALG-STATE. 02 STEP-AMOUNT PIC 99 VALUE 14. 02 ITEM-COUNT PIC 9. PROCEDURE DIVISION. LOOK-AND-SAY. DISPLAY CUR-SEQ. SET CI TO 1. SET NI TO 1. MAKE-NEXT-ENTRY. MOVE 0 TO ITEM-COUNT. IF CI IS GREATER THAN CUR-LENGTH GO TO STEP-DONE. TALLY-ITEM. ADD 1 TO ITEM-COUNT. SET CI UP BY 1. IF CI IS NOT GREATER THAN CUR-LENGTH AND CUR-CHARS(CI) IS EQUAL TO CUR-CHARS(CI - 1) GO TO TALLY-ITEM. INSERT-ENTRY. MOVE ITEM-COUNT TO NEXT-CHARS(NI). MOVE CUR-CHARS(CI - 1) TO NEXT-CHARS(NI + 1). SET NI UP BY 2. GO TO MAKE-NEXT-ENTRY. STEP-DONE. MOVE NEXT-SEQ TO CUR-SEQ. SET NI DOWN BY 1. SET CUR-LENGTH TO NI. SUBTRACT 1 FROM STEP-AMOUNT. IF STEP-AMOUNT IS NOT EQUAL TO ZERO GO TO LOOK-AND-SAY. STOP RUN.
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Write a version of this COBOL function in C++ with identical behavior.
IDENTIFICATION DIVISION. PROGRAM-ID. LOOK-AND-SAY-SEQ. DATA DIVISION. WORKING-STORAGE SECTION. 01 SEQUENCES. 02 CUR-SEQ PIC X(80) VALUE "1". 02 CUR-CHARS REDEFINES CUR-SEQ PIC X OCCURS 80 TIMES INDEXED BY CI. 02 CUR-LENGTH PIC 99 COMP VALUE 1. 02 NEXT-SEQ PIC X(80). 02 NEXT-CHARS REDEFINES NEXT-SEQ PIC X OCCURS 80 TIMES INDEXED BY NI. 01 ALG-STATE. 02 STEP-AMOUNT PIC 99 VALUE 14. 02 ITEM-COUNT PIC 9. PROCEDURE DIVISION. LOOK-AND-SAY. DISPLAY CUR-SEQ. SET CI TO 1. SET NI TO 1. MAKE-NEXT-ENTRY. MOVE 0 TO ITEM-COUNT. IF CI IS GREATER THAN CUR-LENGTH GO TO STEP-DONE. TALLY-ITEM. ADD 1 TO ITEM-COUNT. SET CI UP BY 1. IF CI IS NOT GREATER THAN CUR-LENGTH AND CUR-CHARS(CI) IS EQUAL TO CUR-CHARS(CI - 1) GO TO TALLY-ITEM. INSERT-ENTRY. MOVE ITEM-COUNT TO NEXT-CHARS(NI). MOVE CUR-CHARS(CI - 1) TO NEXT-CHARS(NI + 1). SET NI UP BY 2. GO TO MAKE-NEXT-ENTRY. STEP-DONE. MOVE NEXT-SEQ TO CUR-SEQ. SET NI DOWN BY 1. SET CUR-LENGTH TO NI. SUBTRACT 1 FROM STEP-AMOUNT. IF STEP-AMOUNT IS NOT EQUAL TO ZERO GO TO LOOK-AND-SAY. STOP RUN.
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Translate this program into Java but keep the logic exactly as in COBOL.
IDENTIFICATION DIVISION. PROGRAM-ID. LOOK-AND-SAY-SEQ. DATA DIVISION. WORKING-STORAGE SECTION. 01 SEQUENCES. 02 CUR-SEQ PIC X(80) VALUE "1". 02 CUR-CHARS REDEFINES CUR-SEQ PIC X OCCURS 80 TIMES INDEXED BY CI. 02 CUR-LENGTH PIC 99 COMP VALUE 1. 02 NEXT-SEQ PIC X(80). 02 NEXT-CHARS REDEFINES NEXT-SEQ PIC X OCCURS 80 TIMES INDEXED BY NI. 01 ALG-STATE. 02 STEP-AMOUNT PIC 99 VALUE 14. 02 ITEM-COUNT PIC 9. PROCEDURE DIVISION. LOOK-AND-SAY. DISPLAY CUR-SEQ. SET CI TO 1. SET NI TO 1. MAKE-NEXT-ENTRY. MOVE 0 TO ITEM-COUNT. IF CI IS GREATER THAN CUR-LENGTH GO TO STEP-DONE. TALLY-ITEM. ADD 1 TO ITEM-COUNT. SET CI UP BY 1. IF CI IS NOT GREATER THAN CUR-LENGTH AND CUR-CHARS(CI) IS EQUAL TO CUR-CHARS(CI - 1) GO TO TALLY-ITEM. INSERT-ENTRY. MOVE ITEM-COUNT TO NEXT-CHARS(NI). MOVE CUR-CHARS(CI - 1) TO NEXT-CHARS(NI + 1). SET NI UP BY 2. GO TO MAKE-NEXT-ENTRY. STEP-DONE. MOVE NEXT-SEQ TO CUR-SEQ. SET NI DOWN BY 1. SET CUR-LENGTH TO NI. SUBTRACT 1 FROM STEP-AMOUNT. IF STEP-AMOUNT IS NOT EQUAL TO ZERO GO TO LOOK-AND-SAY. STOP RUN.
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Generate a Python translation of this COBOL snippet without changing its computational steps.
IDENTIFICATION DIVISION. PROGRAM-ID. LOOK-AND-SAY-SEQ. DATA DIVISION. WORKING-STORAGE SECTION. 01 SEQUENCES. 02 CUR-SEQ PIC X(80) VALUE "1". 02 CUR-CHARS REDEFINES CUR-SEQ PIC X OCCURS 80 TIMES INDEXED BY CI. 02 CUR-LENGTH PIC 99 COMP VALUE 1. 02 NEXT-SEQ PIC X(80). 02 NEXT-CHARS REDEFINES NEXT-SEQ PIC X OCCURS 80 TIMES INDEXED BY NI. 01 ALG-STATE. 02 STEP-AMOUNT PIC 99 VALUE 14. 02 ITEM-COUNT PIC 9. PROCEDURE DIVISION. LOOK-AND-SAY. DISPLAY CUR-SEQ. SET CI TO 1. SET NI TO 1. MAKE-NEXT-ENTRY. MOVE 0 TO ITEM-COUNT. IF CI IS GREATER THAN CUR-LENGTH GO TO STEP-DONE. TALLY-ITEM. ADD 1 TO ITEM-COUNT. SET CI UP BY 1. IF CI IS NOT GREATER THAN CUR-LENGTH AND CUR-CHARS(CI) IS EQUAL TO CUR-CHARS(CI - 1) GO TO TALLY-ITEM. INSERT-ENTRY. MOVE ITEM-COUNT TO NEXT-CHARS(NI). MOVE CUR-CHARS(CI - 1) TO NEXT-CHARS(NI + 1). SET NI UP BY 2. GO TO MAKE-NEXT-ENTRY. STEP-DONE. MOVE NEXT-SEQ TO CUR-SEQ. SET NI DOWN BY 1. SET CUR-LENGTH TO NI. SUBTRACT 1 FROM STEP-AMOUNT. IF STEP-AMOUNT IS NOT EQUAL TO ZERO GO TO LOOK-AND-SAY. STOP RUN.
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Can you help me rewrite this code in VB instead of COBOL, keeping it the same logically?
IDENTIFICATION DIVISION. PROGRAM-ID. LOOK-AND-SAY-SEQ. DATA DIVISION. WORKING-STORAGE SECTION. 01 SEQUENCES. 02 CUR-SEQ PIC X(80) VALUE "1". 02 CUR-CHARS REDEFINES CUR-SEQ PIC X OCCURS 80 TIMES INDEXED BY CI. 02 CUR-LENGTH PIC 99 COMP VALUE 1. 02 NEXT-SEQ PIC X(80). 02 NEXT-CHARS REDEFINES NEXT-SEQ PIC X OCCURS 80 TIMES INDEXED BY NI. 01 ALG-STATE. 02 STEP-AMOUNT PIC 99 VALUE 14. 02 ITEM-COUNT PIC 9. PROCEDURE DIVISION. LOOK-AND-SAY. DISPLAY CUR-SEQ. SET CI TO 1. SET NI TO 1. MAKE-NEXT-ENTRY. MOVE 0 TO ITEM-COUNT. IF CI IS GREATER THAN CUR-LENGTH GO TO STEP-DONE. TALLY-ITEM. ADD 1 TO ITEM-COUNT. SET CI UP BY 1. IF CI IS NOT GREATER THAN CUR-LENGTH AND CUR-CHARS(CI) IS EQUAL TO CUR-CHARS(CI - 1) GO TO TALLY-ITEM. INSERT-ENTRY. MOVE ITEM-COUNT TO NEXT-CHARS(NI). MOVE CUR-CHARS(CI - 1) TO NEXT-CHARS(NI + 1). SET NI UP BY 2. GO TO MAKE-NEXT-ENTRY. STEP-DONE. MOVE NEXT-SEQ TO CUR-SEQ. SET NI DOWN BY 1. SET CUR-LENGTH TO NI. SUBTRACT 1 FROM STEP-AMOUNT. IF STEP-AMOUNT IS NOT EQUAL TO ZERO GO TO LOOK-AND-SAY. STOP RUN.
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Please provide an equivalent version of this COBOL code in Go.
IDENTIFICATION DIVISION. PROGRAM-ID. LOOK-AND-SAY-SEQ. DATA DIVISION. WORKING-STORAGE SECTION. 01 SEQUENCES. 02 CUR-SEQ PIC X(80) VALUE "1". 02 CUR-CHARS REDEFINES CUR-SEQ PIC X OCCURS 80 TIMES INDEXED BY CI. 02 CUR-LENGTH PIC 99 COMP VALUE 1. 02 NEXT-SEQ PIC X(80). 02 NEXT-CHARS REDEFINES NEXT-SEQ PIC X OCCURS 80 TIMES INDEXED BY NI. 01 ALG-STATE. 02 STEP-AMOUNT PIC 99 VALUE 14. 02 ITEM-COUNT PIC 9. PROCEDURE DIVISION. LOOK-AND-SAY. DISPLAY CUR-SEQ. SET CI TO 1. SET NI TO 1. MAKE-NEXT-ENTRY. MOVE 0 TO ITEM-COUNT. IF CI IS GREATER THAN CUR-LENGTH GO TO STEP-DONE. TALLY-ITEM. ADD 1 TO ITEM-COUNT. SET CI UP BY 1. IF CI IS NOT GREATER THAN CUR-LENGTH AND CUR-CHARS(CI) IS EQUAL TO CUR-CHARS(CI - 1) GO TO TALLY-ITEM. INSERT-ENTRY. MOVE ITEM-COUNT TO NEXT-CHARS(NI). MOVE CUR-CHARS(CI - 1) TO NEXT-CHARS(NI + 1). SET NI UP BY 2. GO TO MAKE-NEXT-ENTRY. STEP-DONE. MOVE NEXT-SEQ TO CUR-SEQ. SET NI DOWN BY 1. SET CUR-LENGTH TO NI. SUBTRACT 1 FROM STEP-AMOUNT. IF STEP-AMOUNT IS NOT EQUAL TO ZERO GO TO LOOK-AND-SAY. STOP RUN.
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Write a version of this REXX function in C with identical behavior.
parse arg N ! . if N=='' | N=="," then N= 20 if !=='' | !=="," then != 1 do j=1 for abs(N) if j\==1 then != lookNsay(!) if N<0 then say 'length['j"]:" length(!) else say '['j"]:" ! end exit 0 lookNsay: procedure; parse arg x,,$ fin = '0'x x= x || fin do k=1 by 0 y= substr(x, k, 1) if y== fin then return $ _= verify(x, y, , k) - k $= $ || _ || y k= k + _ end
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Generate a C# translation of this REXX snippet without changing its computational steps.
parse arg N ! . if N=='' | N=="," then N= 20 if !=='' | !=="," then != 1 do j=1 for abs(N) if j\==1 then != lookNsay(!) if N<0 then say 'length['j"]:" length(!) else say '['j"]:" ! end exit 0 lookNsay: procedure; parse arg x,,$ fin = '0'x x= x || fin do k=1 by 0 y= substr(x, k, 1) if y== fin then return $ _= verify(x, y, , k) - k $= $ || _ || y k= k + _ end
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Change the following REXX code into C++ without altering its purpose.
parse arg N ! . if N=='' | N=="," then N= 20 if !=='' | !=="," then != 1 do j=1 for abs(N) if j\==1 then != lookNsay(!) if N<0 then say 'length['j"]:" length(!) else say '['j"]:" ! end exit 0 lookNsay: procedure; parse arg x,,$ fin = '0'x x= x || fin do k=1 by 0 y= substr(x, k, 1) if y== fin then return $ _= verify(x, y, , k) - k $= $ || _ || y k= k + _ end
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Ensure the translated Java code behaves exactly like the original REXX snippet.
parse arg N ! . if N=='' | N=="," then N= 20 if !=='' | !=="," then != 1 do j=1 for abs(N) if j\==1 then != lookNsay(!) if N<0 then say 'length['j"]:" length(!) else say '['j"]:" ! end exit 0 lookNsay: procedure; parse arg x,,$ fin = '0'x x= x || fin do k=1 by 0 y= substr(x, k, 1) if y== fin then return $ _= verify(x, y, , k) - k $= $ || _ || y k= k + _ end
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Change the programming language of this snippet from REXX to Python without modifying what it does.
parse arg N ! . if N=='' | N=="," then N= 20 if !=='' | !=="," then != 1 do j=1 for abs(N) if j\==1 then != lookNsay(!) if N<0 then say 'length['j"]:" length(!) else say '['j"]:" ! end exit 0 lookNsay: procedure; parse arg x,,$ fin = '0'x x= x || fin do k=1 by 0 y= substr(x, k, 1) if y== fin then return $ _= verify(x, y, , k) - k $= $ || _ || y k= k + _ end
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Write the same code in VB as shown below in REXX.
parse arg N ! . if N=='' | N=="," then N= 20 if !=='' | !=="," then != 1 do j=1 for abs(N) if j\==1 then != lookNsay(!) if N<0 then say 'length['j"]:" length(!) else say '['j"]:" ! end exit 0 lookNsay: procedure; parse arg x,,$ fin = '0'x x= x || fin do k=1 by 0 y= substr(x, k, 1) if y== fin then return $ _= verify(x, y, , k) - k $= $ || _ || y k= k + _ end
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Preserve the algorithm and functionality while converting the code from REXX to Go.
parse arg N ! . if N=='' | N=="," then N= 20 if !=='' | !=="," then != 1 do j=1 for abs(N) if j\==1 then != lookNsay(!) if N<0 then say 'length['j"]:" length(!) else say '['j"]:" ! end exit 0 lookNsay: procedure; parse arg x,,$ fin = '0'x x= x || fin do k=1 by 0 y= substr(x, k, 1) if y== fin then return $ _= verify(x, y, , k) - k $= $ || _ || y k= k + _ end
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Rewrite this program in C while keeping its functionality equivalent to the Ruby version.
class String def lookandsay gsub(/(.)\1*/){ |s| s.size.to_s + s[0] } end end ss = '1' 12.times { puts ss; ss = ss.to_s.lookandsay }
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Write the same algorithm in C# as shown in this Ruby implementation.
class String def lookandsay gsub(/(.)\1*/){ |s| s.size.to_s + s[0] } end end ss = '1' 12.times { puts ss; ss = ss.to_s.lookandsay }
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Translate the given Ruby code snippet into C++ without altering its behavior.
class String def lookandsay gsub(/(.)\1*/){ |s| s.size.to_s + s[0] } end end ss = '1' 12.times { puts ss; ss = ss.to_s.lookandsay }
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Transform the following Ruby implementation into Java, maintaining the same output and logic.
class String def lookandsay gsub(/(.)\1*/){ |s| s.size.to_s + s[0] } end end ss = '1' 12.times { puts ss; ss = ss.to_s.lookandsay }
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Port the provided Ruby code into Python while preserving the original functionality.
class String def lookandsay gsub(/(.)\1*/){ |s| s.size.to_s + s[0] } end end ss = '1' 12.times { puts ss; ss = ss.to_s.lookandsay }
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Port the following code from Ruby to VB with equivalent syntax and logic.
class String def lookandsay gsub(/(.)\1*/){ |s| s.size.to_s + s[0] } end end ss = '1' 12.times { puts ss; ss = ss.to_s.lookandsay }
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Port the provided Ruby code into Go while preserving the original functionality.
class String def lookandsay gsub(/(.)\1*/){ |s| s.size.to_s + s[0] } end end ss = '1' 12.times { puts ss; ss = ss.to_s.lookandsay }
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Change the programming language of this snippet from Scala to C without modifying what it does.
fun lookAndSay(s: String): String { val sb = StringBuilder() var digit = s[0] var count = 1 for (i in 1 until s.length) { if (s[i] == digit) count++ else { sb.append("$count$digit") digit = s[i] count = 1 } } return sb.append("$count$digit").toString() } fun main(args: Array<String>) { var las = "1" for (i in 1..15) { println(las) las = lookAndSay(las) } }
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Write a version of this Scala function in C# with identical behavior.
fun lookAndSay(s: String): String { val sb = StringBuilder() var digit = s[0] var count = 1 for (i in 1 until s.length) { if (s[i] == digit) count++ else { sb.append("$count$digit") digit = s[i] count = 1 } } return sb.append("$count$digit").toString() } fun main(args: Array<String>) { var las = "1" for (i in 1..15) { println(las) las = lookAndSay(las) } }
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Convert this Scala snippet to C++ and keep its semantics consistent.
fun lookAndSay(s: String): String { val sb = StringBuilder() var digit = s[0] var count = 1 for (i in 1 until s.length) { if (s[i] == digit) count++ else { sb.append("$count$digit") digit = s[i] count = 1 } } return sb.append("$count$digit").toString() } fun main(args: Array<String>) { var las = "1" for (i in 1..15) { println(las) las = lookAndSay(las) } }
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Produce a language-to-language conversion: from Scala to Java, same semantics.
fun lookAndSay(s: String): String { val sb = StringBuilder() var digit = s[0] var count = 1 for (i in 1 until s.length) { if (s[i] == digit) count++ else { sb.append("$count$digit") digit = s[i] count = 1 } } return sb.append("$count$digit").toString() } fun main(args: Array<String>) { var las = "1" for (i in 1..15) { println(las) las = lookAndSay(las) } }
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Preserve the algorithm and functionality while converting the code from Scala to Python.
fun lookAndSay(s: String): String { val sb = StringBuilder() var digit = s[0] var count = 1 for (i in 1 until s.length) { if (s[i] == digit) count++ else { sb.append("$count$digit") digit = s[i] count = 1 } } return sb.append("$count$digit").toString() } fun main(args: Array<String>) { var las = "1" for (i in 1..15) { println(las) las = lookAndSay(las) } }
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)
Convert the following code from Scala to VB, ensuring the logic remains intact.
fun lookAndSay(s: String): String { val sb = StringBuilder() var digit = s[0] var count = 1 for (i in 1 until s.length) { if (s[i] == digit) count++ else { sb.append("$count$digit") digit = s[i] count = 1 } } return sb.append("$count$digit").toString() } fun main(args: Array<String>) { var las = "1" for (i in 1..15) { println(las) las = lookAndSay(las) } }
function looksay( n ) dim i dim accum dim res dim c res = vbnullstring do if n = vbnullstring then exit do accum = 0 c = left( n,1 ) do while left( n, 1 ) = c accum = accum + 1 n = mid(n,2) loop if accum > 0 then res = res & accum & c end if loop looksay = res end function
Change the programming language of this snippet from Scala to Go without modifying what it does.
fun lookAndSay(s: String): String { val sb = StringBuilder() var digit = s[0] var count = 1 for (i in 1 until s.length) { if (s[i] == digit) count++ else { sb.append("$count$digit") digit = s[i] count = 1 } } return sb.append("$count$digit").toString() } fun main(args: Array<String>) { var las = "1" for (i in 1..15) { println(las) las = lookAndSay(las) } }
package main import ( "fmt" "strconv" ) func lss(s string) (r string) { c := s[0] nc := 1 for i := 1; i < len(s); i++ { d := s[i] if d == c { nc++ continue } r += strconv.Itoa(nc) + string(c) c = d nc = 1 } return r + strconv.Itoa(nc) + string(c) } func main() { s := "1" fmt.Println(s) for i := 0; i < 8; i++ { s = lss(s) fmt.Println(s) } }
Port the provided Swift code into C while preserving the original functionality.
func lookAndSay(_ seq: [Int]) -> [Int] { var result = [Int]() var cur = seq[0] var curRunLength = 1 for i in seq.dropFirst() { if cur == i { curRunLength += 1 } else { result.append(curRunLength) result.append(cur) curRunLength = 1 cur = i } } result.append(curRunLength) result.append(cur) return result } var seq = [1] for i in 0..<10 { print("Seq \(i): \(seq)") seq = lookAndSay(seq) }
#include <stdio.h> #include <stdlib.h> int main() { char *a = malloc(2), *b = 0, *x, c; int cnt, len = 1; for (sprintf(a, "1"); (b = realloc(b, len * 2 + 1)); a = b, b = x) { puts(x = a); for (len = 0, cnt = 1; (c = *a); ) { if (c == *++a) cnt++; else if (c) { len += sprintf(b + len, "%d%c", cnt, c); cnt = 1; } } } return 0; }
Write the same code in C# as shown below in Swift.
func lookAndSay(_ seq: [Int]) -> [Int] { var result = [Int]() var cur = seq[0] var curRunLength = 1 for i in seq.dropFirst() { if cur == i { curRunLength += 1 } else { result.append(curRunLength) result.append(cur) curRunLength = 1 cur = i } } result.append(curRunLength) result.append(cur) return result } var seq = [1] for i in 0..<10 { print("Seq \(i): \(seq)") seq = lookAndSay(seq) }
using System; using System.Text; using System.Linq; class Program { static string lookandsay(string number) { StringBuilder result = new StringBuilder(); char repeat = number[0]; number = number.Substring(1, number.Length-1)+" "; int times = 1; foreach (char actual in number) { if (actual != repeat) { result.Append(Convert.ToString(times)+repeat); times = 1; repeat = actual; } else { times += 1; } } return result.ToString(); } static void Main(string[] args) { string num = "1"; foreach (int i in Enumerable.Range(1, 10)) { Console.WriteLine(num); num = lookandsay(num); } } }
Produce a language-to-language conversion: from Swift to C++, same semantics.
func lookAndSay(_ seq: [Int]) -> [Int] { var result = [Int]() var cur = seq[0] var curRunLength = 1 for i in seq.dropFirst() { if cur == i { curRunLength += 1 } else { result.append(curRunLength) result.append(cur) curRunLength = 1 cur = i } } result.append(curRunLength) result.append(cur) return result } var seq = [1] for i in 0..<10 { print("Seq \(i): \(seq)") seq = lookAndSay(seq) }
#include <iostream> #include <sstream> #include <string> std::string lookandsay(const std::string& s) { std::ostringstream r; for (std::size_t i = 0; i != s.length();) { auto new_i = s.find_first_not_of(s[i], i + 1); if (new_i == std::string::npos) new_i = s.length(); r << new_i - i << s[i]; i = new_i; } return r.str(); } int main() { std::string laf = "1"; std::cout << laf << '\n'; for (int i = 0; i < 10; ++i) { laf = lookandsay(laf); std::cout << laf << '\n'; } }
Port the following code from Swift to Java with equivalent syntax and logic.
func lookAndSay(_ seq: [Int]) -> [Int] { var result = [Int]() var cur = seq[0] var curRunLength = 1 for i in seq.dropFirst() { if cur == i { curRunLength += 1 } else { result.append(curRunLength) result.append(cur) curRunLength = 1 cur = i } } result.append(curRunLength) result.append(cur) return result } var seq = [1] for i in 0..<10 { print("Seq \(i): \(seq)") seq = lookAndSay(seq) }
public static String lookandsay(String number){ StringBuilder result= new StringBuilder(); char repeat= number.charAt(0); number= number.substring(1) + " "; int times= 1; for(char actual: number.toCharArray()){ if(actual != repeat){ result.append(times + "" + repeat); times= 1; repeat= actual; }else{ times+= 1; } } return result.toString(); }
Transform the following Swift implementation into Python, maintaining the same output and logic.
func lookAndSay(_ seq: [Int]) -> [Int] { var result = [Int]() var cur = seq[0] var curRunLength = 1 for i in seq.dropFirst() { if cur == i { curRunLength += 1 } else { result.append(curRunLength) result.append(cur) curRunLength = 1 cur = i } } result.append(curRunLength) result.append(cur) return result } var seq = [1] for i in 0..<10 { print("Seq \(i): \(seq)") seq = lookAndSay(seq) }
def lookandsay(number): result = "" repeat = number[0] number = number[1:]+" " times = 1 for actual in number: if actual != repeat: result += str(times)+repeat times = 1 repeat = actual else: times += 1 return result num = "1" for i in range(10): print num num = lookandsay(num)