Instruction stringlengths 45 106 | input_code stringlengths 1 13.7k | output_code stringlengths 1 13.7k |
|---|---|---|
Keep all operations the same but rewrite the snippet in C. | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Please provide an equivalent version of this Haskell code in C. | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Change the programming language of this snippet from Haskell to C# without modifying what it does. | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Port the following code from Haskell to C++ with equivalent syntax and logic. | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Can you help me rewrite this code in C++ instead of Haskell, keeping it the same logically? | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Generate an equivalent Java version of this Haskell code. | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Maintain the same structure and functionality when rewriting this code in Java. | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Port the provided Haskell code into Python while preserving the original functionality. | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Preserve the algorithm and functionality while converting the code from Haskell to Python. | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Maintain the same structure and functionality when rewriting this code in VB. | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Write the same algorithm in Go as shown in this Haskell implementation. | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Write the same code in Go as shown below in Haskell. | import Data.List (unfoldr)
import Data.Char (intToDigit)
sqrt2, napier, myPi :: [(Integer, Integer)]
sqrt2 = zip (1 : [2,2 ..]) [1,1 ..]
napier = zip (2 : [1 ..]) (1 : [1 ..])
myPi = zip (3 : [6,6 ..]) ((^ 2) <$> [1,3 ..])
approxCF
:: (Integral a, Fractional b)
=> Int -> [(a, a)] -> b
approxCF t = foldr (\(a,... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Rewrite the snippet below in C so it works the same as the original Icon code. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Generate a C translation of this Icon snippet without changing its computational steps. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Please provide an equivalent version of this Icon code in C#. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Keep all operations the same but rewrite the snippet in C#. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Rewrite the snippet below in C++ so it works the same as the original Icon code. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Generate a C++ translation of this Icon snippet without changing its computational steps. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Convert the following code from Icon to Java, ensuring the logic remains intact. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Can you help me rewrite this code in Java instead of Icon, keeping it the same logically? | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Generate a Python translation of this Icon snippet without changing its computational steps. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Transform the following Icon implementation into Python, maintaining the same output and logic. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Please provide an equivalent version of this Icon code in VB. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Produce a language-to-language conversion: from Icon to VB, same semantics. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Convert this Icon snippet to Go and keep its semantics consistent. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Please provide an equivalent version of this Icon code in Go. | $define EVAL_DEPTH 100
record continued_fraction (a, b)
procedure main ()
writes (" sqrt 2.0 = ")
write (evaluate_continued_fraction (continued_fraction (sqrt2_a, sqrt2_b),
EVAL_DEPTH))
writes (" e = ")
write (evaluate_continued_fraction (continued_fraction (e_a,... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Preserve the algorithm and functionality while converting the code from J to C. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Generate an equivalent C version of this J code. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Ensure the translated C# code behaves exactly like the original J snippet. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Port the provided J code into C# while preserving the original functionality. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Rewrite the snippet below in C++ so it works the same as the original J code. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Convert this J block to C++, preserving its control flow and logic. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Translate the given J code snippet into Java without altering its behavior. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Preserve the algorithm and functionality while converting the code from J to Java. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Produce a language-to-language conversion: from J to Python, same semantics. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Rewrite the snippet below in Python so it works the same as the original J code. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Rewrite the snippet below in VB so it works the same as the original J code. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Port the following code from J to VB with equivalent syntax and logic. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Change the programming language of this snippet from J to Go without modifying what it does. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Change the following J code into Go without altering its purpose. | cfrac=: +`% /
sqrt2=: cfrac 1 1,200$2 1x
pi=:cfrac 3, , ,&6"0 *:<:+:>:i.100x
e=: cfrac 2 1, , ,~"0 >:i.100x
dec =: (-@:[ (}.,'.',{.) ":@:<.@:(* 10x&^)~)"0
100 10 100 dec sqrt2, pi, e
1.4142135623730950488016887242096980785696718753769480731766797379907324784621205551109457595775322165
3.14... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Port the following code from Julia to C with equivalent syntax and logic. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Change the programming language of this snippet from Julia to C without modifying what it does. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Translate the given Julia code snippet into C# without altering its behavior. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Transform the following Julia implementation into C#, maintaining the same output and logic. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Convert this Julia snippet to C++ and keep its semantics consistent. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Preserve the algorithm and functionality while converting the code from Julia to C++. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Change the following Julia code into Java without altering its purpose. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Can you help me rewrite this code in Java instead of Julia, keeping it the same logically? | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Convert this Julia snippet to Python and keep its semantics consistent. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Produce a functionally identical Python code for the snippet given in Julia. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Generate an equivalent VB version of this Julia code. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Port the following code from Julia to VB with equivalent syntax and logic. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Rewrite the snippet below in Go so it works the same as the original Julia code. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Rewrite this program in Go while keeping its functionality equivalent to the Julia version. | using .Iterators: countfrom, flatten, repeated, zip
using .MathConstants: ℯ
using Printf
function cf(a₀, a, b = repeated(1))
m = BigInt[a₀ 1; 1 0]
for (aᵢ, bᵢ) ∈ zip(a, b)
m *= [aᵢ 1; bᵢ 0]
isapprox(m[1]/m[2], m[3]/m[4]; atol = 1e-12) && break
end
m[1]/m[2]
end
out((k, v)) = @printf "%2s: %.... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Port the provided Lua code into C while preserving the original functionality. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Rewrite the snippet below in C so it works the same as the original Lua code. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Rewrite the snippet below in C# so it works the same as the original Lua code. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Ensure the translated C# code behaves exactly like the original Lua snippet. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Keep all operations the same but rewrite the snippet in C++. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Rewrite this program in C++ while keeping its functionality equivalent to the Lua version. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Preserve the algorithm and functionality while converting the code from Lua to Java. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Translate the given Lua code snippet into Java without altering its behavior. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Write a version of this Lua function in Python with identical behavior. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Produce a language-to-language conversion: from Lua to Python, same semantics. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Translate the given Lua code snippet into VB without altering its behavior. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Rewrite the snippet below in VB so it works the same as the original Lua code. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Port the provided Lua code into Go while preserving the original functionality. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Transform the following Lua implementation into Go, maintaining the same output and logic. | function calc(fa, fb, expansions)
local a = 0.0
local b = 0.0
local r = 0.0
local i = expansions
while i > 0 do
a = fa(i)
b = fb(i)
r = b / (a + r)
i = i - 1
end
a = fa(0)
return a + r
end
function sqrt2a(n)
if n ~= 0 then
return 2.0
else
... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Please provide an equivalent version of this Mathematica code in C. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Port the following code from Mathematica to C with equivalent syntax and logic. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Produce a functionally identical C# code for the snippet given in Mathematica. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Convert this Mathematica block to C#, preserving its control flow and logic. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Rewrite the snippet below in C++ so it works the same as the original Mathematica code. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Change the following Mathematica code into C++ without altering its purpose. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Keep all operations the same but rewrite the snippet in Java. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Convert this Mathematica block to Java, preserving its control flow and logic. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Keep all operations the same but rewrite the snippet in Python. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Write the same algorithm in Python as shown in this Mathematica implementation. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Convert this Mathematica block to VB, preserving its control flow and logic. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Translate the given Mathematica code snippet into VB without altering its behavior. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Write a version of this Mathematica function in Go with identical behavior. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Translate the given Mathematica code snippet into Go without altering its behavior. | sqrt2=Function[n,{1,Transpose@{Array[2&,n],Array[1&,n]}}];
napier=Function[n,{2,Transpose@{Range[n],Prepend[Range[n-1],1]}}];
pi=Function[n,{3,Transpose@{Array[6&,n],Array[(2#-1)^2&,n]}}];
approx=Function[l,
N[Divide@@First@Fold[{{#2.#[[;;,1]],#2.#[[;;,2]]},#[[1]]}&,{{l[[2,1,1]]l[[1]]+l[[2,1,2]],l[[2,1,1]]},{l[[1]],1}... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Write the same algorithm in C as shown in this Nim implementation. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Preserve the algorithm and functionality while converting the code from Nim to C. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Convert this Nim snippet to C# and keep its semantics consistent. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Keep all operations the same but rewrite the snippet in C#. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Write the same algorithm in C++ as shown in this Nim implementation. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Translate the given Nim code snippet into C++ without altering its behavior. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
Transform the following Nim implementation into Java, maintaining the same output and logic. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... | import static java.lang.Math.pow;
import java.util.*;
import java.util.function.Function;
public class Test {
static double calc(Function<Integer, Integer[]> f, int n) {
double temp = 0;
for (int ni = n; ni >= 1; ni--) {
Integer[] p = f.apply(ni);
temp = p[1] / (double) (p[... |
Convert this Nim block to Python, preserving its control flow and logic. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Transform the following Nim implementation into Python, maintaining the same output and logic. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... | from fractions import Fraction
import itertools
try: zip = itertools.izip
except: pass
def CF(a, b, t):
terms = list(itertools.islice(zip(a, b), t))
z = Fraction(1,1)
for a, b in reversed(terms):
z = a + b / z
return z
def pRes(x, d):
q, x = divmod(x, 1)
res = str(q)
res += "."
for i in range(... |
Port the provided Nim code into VB while preserving the original functionality. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Translate this program into VB but keep the logic exactly as in Nim. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... | Public Const precision = 10000
Private Function continued_fraction(steps As Integer, rid_a As String, rid_b As String) As Double
Dim res As Double
res = 0
For n = steps To 1 Step -1
res = Application.Run(rid_b, n) / (Application.Run(rid_a, n) + res)
Next n
continued_fraction = Application.Run... |
Generate a Go translation of this Nim snippet without changing its computational steps. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Produce a functionally identical Go code for the snippet given in Nim. | proc calc(f: proc(n: int): tuple[a, b: float], n: int): float =
var a, b, temp = 0.0
for i in countdown(n, 1):
(a, b) = f(i)
temp = b / (a + temp)
(a, b) = f(0)
a + temp
proc sqrt2(n: int): tuple[a, b: float] =
if n > 0:
(2.0, 1.0)
else:
(1.0, 1.0)
proc napier(n: int): tuple[a, b: float] =... | package main
import "fmt"
type cfTerm struct {
a, b int
}
type cf []cfTerm
func cfSqrt2(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] = cfTerm{2, 1}
}
f[0].a = 1
return f
}
func cfNap(nTerms int) cf {
f := make(cf, nTerms)
for n := range f {
f[n] =... |
Rewrite the snippet below in C so it works the same as the original OCaml code. | let pi = 3, fun n -> ((2*n-1)*(2*n-1), 6)
and nap = 2, fun n -> (max 1 (n-1), n)
and root2 = 1, fun n -> (1, 2) in
let eval (i,f) k =
let rec frac n =
let a, b = f n in
float a /. (float b +.
if n >= k then 0.0 else frac (n+1)) in
float i +. frac 1 in
Printf.printf "sqrt(2)\t= %.15f\n" (eval root2 1... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Preserve the algorithm and functionality while converting the code from OCaml to C. | let pi = 3, fun n -> ((2*n-1)*(2*n-1), 6)
and nap = 2, fun n -> (max 1 (n-1), n)
and root2 = 1, fun n -> (1, 2) in
let eval (i,f) k =
let rec frac n =
let a, b = f n in
float a /. (float b +.
if n >= k then 0.0 else frac (n+1)) in
float i +. frac 1 in
Printf.printf "sqrt(2)\t= %.15f\n" (eval root2 1... |
#include <stdio.h>
typedef double (*coeff_func)(unsigned n);
double calc(coeff_func f_a, coeff_func f_b, unsigned expansions)
{
double a, b, r;
a = b = r = 0.0;
unsigned i;
for (i = expansions; i > 0; i--) {
a = f_a(i);
b = f_b(i);
r = b / (a + r);
}
a = f_a(0);
return a + r;
}
double sqrt2_a(unsi... |
Generate a C# translation of this OCaml snippet without changing its computational steps. | let pi = 3, fun n -> ((2*n-1)*(2*n-1), 6)
and nap = 2, fun n -> (max 1 (n-1), n)
and root2 = 1, fun n -> (1, 2) in
let eval (i,f) k =
let rec frac n =
let a, b = f n in
float a /. (float b +.
if n >= k then 0.0 else frac (n+1)) in
float i +. frac 1 in
Printf.printf "sqrt(2)\t= %.15f\n" (eval root2 1... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Port the provided OCaml code into C# while preserving the original functionality. | let pi = 3, fun n -> ((2*n-1)*(2*n-1), 6)
and nap = 2, fun n -> (max 1 (n-1), n)
and root2 = 1, fun n -> (1, 2) in
let eval (i,f) k =
let rec frac n =
let a, b = f n in
float a /. (float b +.
if n >= k then 0.0 else frac (n+1)) in
float i +. frac 1 in
Printf.printf "sqrt(2)\t= %.15f\n" (eval root2 1... | using System;
using System.Collections.Generic;
namespace ContinuedFraction {
class Program {
static double Calc(Func<int, int[]> f, int n) {
double temp = 0.0;
for (int ni = n; ni >= 1; ni--) {
int[] p = f(ni);
temp = p[1] / (p[0] + temp);
... |
Maintain the same structure and functionality when rewriting this code in C++. | let pi = 3, fun n -> ((2*n-1)*(2*n-1), 6)
and nap = 2, fun n -> (max 1 (n-1), n)
and root2 = 1, fun n -> (1, 2) in
let eval (i,f) k =
let rec frac n =
let a, b = f n in
float a /. (float b +.
if n >= k then 0.0 else frac (n+1)) in
float i +. frac 1 in
Printf.printf "sqrt(2)\t= %.15f\n" (eval root2 1... | #include <iomanip>
#include <iostream>
#include <tuple>
typedef std::tuple<double,double> coeff_t;
typedef coeff_t (*func_t)(int);
double calc(func_t func, int n)
{
double a, b, temp = 0;
for (; n > 0; --n) {
std::tie(a, b) = func(n);
temp = b / (a + temp);
}
std::tie(a, b) = func(0)... |
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