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Can you help me rewrite this code in C instead of Python, keeping it the same logically?
strings = "here are Some sample strings to be sorted".split() def mykey(x): return -len(x), x.upper() print sorted(strings, key=mykey)
#include <stdlib.h> #include <string.h> #include <strings.h> int mycmp(const void *s1, const void *s2) { const char *l = *(const char **)s1, *r = *(const char **)s2; size_t ll = strlen(l), lr = strlen(r); if (ll > lr) return -1; if (ll < lr) return 1; return strcasecmp(l, r); } int main() { const char *strings[] = { "Here", "are", "some", "sample", "strings", "to", "be", "sorted" }; qsort(strings, sizeof(strings)/sizeof(*strings), sizeof(*strings), mycmp); return 0; }
Keep all operations the same but rewrite the snippet in C.
import random def is_Prime(n): if n!=int(n): return False n=int(n) if n==0 or n==1 or n==4 or n==6 or n==8 or n==9: return False if n==2 or n==3 or n==5 or n==7: return True s = 0 d = n-1 while d%2==0: d>>=1 s+=1 assert(2**s * d == n-1) def trial_composite(a): if pow(a, d, n) == 1: return False for i in range(s): if pow(a, 2**i * d, n) == n-1: return False return True for i in range(8): a = random.randrange(2, n) if trial_composite(a): return False return True def isPrime(n: int) -> bool: if (n <= 1) : return False if (n <= 3) : return True if (n % 2 == 0 or n % 3 == 0) : return False i = 5 while(i * i <= n) : if (n % i == 0 or n % (i + 2) == 0) : return False i = i + 6 return True def rotations(n: int)-> set((int,)): a = str(n) return set(int(a[i:] + a[:i]) for i in range(len(a))) def isCircular(n: int) -> bool: return all(isPrime(int(o)) for o in rotations(n)) from itertools import product def main(): result = [2, 3, 5, 7] first = '137' latter = '1379' for i in range(1, 6): s = set(int(''.join(a)) for a in product(first, *((latter,) * i))) while s: a = s.pop() b = rotations(a) if isCircular(a): result.append(min(b)) s -= b result.sort() return result assert [2, 3, 5, 7, 11, 13, 17, 37, 79, 113, 197, 199, 337, 1193, 3779, 11939, 19937, 193939, 199933] == main() repunit = lambda n: int('1' * n) def repmain(n: int) -> list: result = [] i = 2 while len(result) < n: if is_Prime(repunit(i)): result.append(i) i += 1 return result assert [2, 19, 23, 317, 1031] == repmain(5)
#include <stdbool.h> #include <stdint.h> #include <stdio.h> #include <stdlib.h> #include <string.h> #include <gmp.h> bool is_prime(uint32_t n) { if (n == 2) return true; if (n < 2 || n % 2 == 0) return false; for (uint32_t p = 3; p * p <= n; p += 2) { if (n % p == 0) return false; } return true; } uint32_t cycle(uint32_t n) { uint32_t m = n, p = 1; while (m >= 10) { p *= 10; m /= 10; } return m + 10 * (n % p); } bool is_circular_prime(uint32_t p) { if (!is_prime(p)) return false; uint32_t p2 = cycle(p); while (p2 != p) { if (p2 < p || !is_prime(p2)) return false; p2 = cycle(p2); } return true; } void test_repunit(uint32_t digits) { char* str = malloc(digits + 1); if (str == 0) { fprintf(stderr, "Out of memory\n"); exit(1); } memset(str, '1', digits); str[digits] = 0; mpz_t bignum; mpz_init_set_str(bignum, str, 10); free(str); if (mpz_probab_prime_p(bignum, 10)) printf("R(%u) is probably prime.\n", digits); else printf("R(%u) is not prime.\n", digits); mpz_clear(bignum); } int main() { uint32_t p = 2; printf("First 19 circular primes:\n"); for (int count = 0; count < 19; ++p) { if (is_circular_prime(p)) { if (count > 0) printf(", "); printf("%u", p); ++count; } } printf("\n"); printf("Next 4 circular primes:\n"); uint32_t repunit = 1, digits = 1; for (; repunit < p; ++digits) repunit = 10 * repunit + 1; mpz_t bignum; mpz_init_set_ui(bignum, repunit); for (int count = 0; count < 4; ) { if (mpz_probab_prime_p(bignum, 15)) { if (count > 0) printf(", "); printf("R(%u)", digits); ++count; } ++digits; mpz_mul_ui(bignum, bignum, 10); mpz_add_ui(bignum, bignum, 1); } mpz_clear(bignum); printf("\n"); test_repunit(5003); test_repunit(9887); test_repunit(15073); test_repunit(25031); test_repunit(35317); test_repunit(49081); return 0; }
Produce a functionally identical C code for the snippet given in Python.
txt = "Hello, world! " left = True def draw(): global txt background(128) text(txt, 10, height / 2) if frameCount % 10 == 0: if (left): txt = rotate(txt, 1) else: txt = rotate(txt, -1) println(txt) def mouseReleased(): global left left = not left def rotate(text, startIdx): rotated = text[startIdx:] + text[:startIdx] return rotated
#include <stdlib.h> #include <string.h> #include <gtk/gtk.h> const gchar *hello = "Hello World! "; gint direction = -1; gint cx=0; gint slen=0; GtkLabel *label; void change_dir(GtkLayout *o, gpointer d) { direction = -direction; } gchar *rotateby(const gchar *t, gint q, gint l) { gint i, cl = l, j; gchar *r = malloc(l+1); for(i=q, j=0; cl > 0; cl--, i = (i + 1)%l, j++) r[j] = t[i]; r[l] = 0; return r; } gboolean scroll_it(gpointer data) { if ( direction > 0 ) cx = (cx + 1) % slen; else cx = (cx + slen - 1 ) % slen; gchar *scrolled = rotateby(hello, cx, slen); gtk_label_set_text(label, scrolled); free(scrolled); return TRUE; } int main(int argc, char **argv) { GtkWidget *win; GtkButton *button; PangoFontDescription *pd; gtk_init(&argc, &argv); win = gtk_window_new(GTK_WINDOW_TOPLEVEL); gtk_window_set_title(GTK_WINDOW(win), "Basic Animation"); g_signal_connect(G_OBJECT(win), "delete-event", gtk_main_quit, NULL); label = (GtkLabel *)gtk_label_new(hello); pd = pango_font_description_new(); pango_font_description_set_family(pd, "monospace"); gtk_widget_modify_font(GTK_WIDGET(label), pd); button = (GtkButton *)gtk_button_new(); gtk_container_add(GTK_CONTAINER(button), GTK_WIDGET(label)); gtk_container_add(GTK_CONTAINER(win), GTK_WIDGET(button)); g_signal_connect(G_OBJECT(button), "clicked", G_CALLBACK(change_dir), NULL); slen = strlen(hello); g_timeout_add(125, scroll_it, NULL); gtk_widget_show_all(GTK_WIDGET(win)); gtk_main(); return 0; }
Write the same code in C as shown below in Python.
txt = "Hello, world! " left = True def draw(): global txt background(128) text(txt, 10, height / 2) if frameCount % 10 == 0: if (left): txt = rotate(txt, 1) else: txt = rotate(txt, -1) println(txt) def mouseReleased(): global left left = not left def rotate(text, startIdx): rotated = text[startIdx:] + text[:startIdx] return rotated
#include <stdlib.h> #include <string.h> #include <gtk/gtk.h> const gchar *hello = "Hello World! "; gint direction = -1; gint cx=0; gint slen=0; GtkLabel *label; void change_dir(GtkLayout *o, gpointer d) { direction = -direction; } gchar *rotateby(const gchar *t, gint q, gint l) { gint i, cl = l, j; gchar *r = malloc(l+1); for(i=q, j=0; cl > 0; cl--, i = (i + 1)%l, j++) r[j] = t[i]; r[l] = 0; return r; } gboolean scroll_it(gpointer data) { if ( direction > 0 ) cx = (cx + 1) % slen; else cx = (cx + slen - 1 ) % slen; gchar *scrolled = rotateby(hello, cx, slen); gtk_label_set_text(label, scrolled); free(scrolled); return TRUE; } int main(int argc, char **argv) { GtkWidget *win; GtkButton *button; PangoFontDescription *pd; gtk_init(&argc, &argv); win = gtk_window_new(GTK_WINDOW_TOPLEVEL); gtk_window_set_title(GTK_WINDOW(win), "Basic Animation"); g_signal_connect(G_OBJECT(win), "delete-event", gtk_main_quit, NULL); label = (GtkLabel *)gtk_label_new(hello); pd = pango_font_description_new(); pango_font_description_set_family(pd, "monospace"); gtk_widget_modify_font(GTK_WIDGET(label), pd); button = (GtkButton *)gtk_button_new(); gtk_container_add(GTK_CONTAINER(button), GTK_WIDGET(label)); gtk_container_add(GTK_CONTAINER(win), GTK_WIDGET(button)); g_signal_connect(G_OBJECT(button), "clicked", G_CALLBACK(change_dir), NULL); slen = strlen(hello); g_timeout_add(125, scroll_it, NULL); gtk_widget_show_all(GTK_WIDGET(win)); gtk_main(); return 0; }
Port the following code from Python to C with equivalent syntax and logic.
from math import log def getDigit(num, base, digit_num): return (num // base ** digit_num) % base def makeBlanks(size): return [ [] for i in range(size) ] def split(a_list, base, digit_num): buckets = makeBlanks(base) for num in a_list: buckets[getDigit(num, base, digit_num)].append(num) return buckets def merge(a_list): new_list = [] for sublist in a_list: new_list.extend(sublist) return new_list def maxAbs(a_list): return max(abs(num) for num in a_list) def split_by_sign(a_list): buckets = [[], []] for num in a_list: if num < 0: buckets[0].append(num) else: buckets[1].append(num) return buckets def radixSort(a_list, base): passes = int(round(log(maxAbs(a_list), base)) + 1) new_list = list(a_list) for digit_num in range(passes): new_list = merge(split(new_list, base, digit_num)) return merge(split_by_sign(new_list))
#include <stdio.h> #include <limits.h> #include <stdlib.h> #include <time.h> #define ARR_LEN(ARR) (sizeof ARR / sizeof *ARR) #define RAND_RNG(M,N) (M + rand() / (RAND_MAX / (N - M + 1) + 1)); static void swap(unsigned *a, unsigned *b) { unsigned tmp = *a; *a = *b; *b = tmp; } static void rad_sort_u(unsigned *from, unsigned *to, unsigned bit) { if (!bit || to < from + 1) return; unsigned *ll = from, *rr = to - 1; for (;;) { while (ll < rr && !(*ll & bit)) ll++; while (ll < rr && (*rr & bit)) rr--; if (ll >= rr) break; swap(ll, rr); } if (!(bit & *ll) && ll < to) ll++; bit >>= 1; rad_sort_u(from, ll, bit); rad_sort_u(ll, to, bit); } static void radix_sort(int *a, const size_t len) { size_t i; unsigned *x = (unsigned*) a; for (i = 0; i < len; i++) x[i] ^= INT_MIN; rad_sort_u(x, x + len, INT_MIN); for (i = 0; i < len; i++) x[i] ^= INT_MIN; } int main(void) { srand(time(NULL)); int x[16]; for (size_t i = 0; i < ARR_LEN(x); i++) x[i] = RAND_RNG(-128,127) radix_sort(x, ARR_LEN(x)); for (size_t i = 0; i < ARR_LEN(x); i++) printf("%d%c", x[i], i + 1 < ARR_LEN(x) ? ' ' : '\n'); }
Preserve the algorithm and functionality while converting the code from Python to C.
[(x,y,z) for x in xrange(1,n+1) for y in xrange(x,n+1) for z in xrange(y,n+1) if x**2 + y**2 == z**2]
for (int i = f + 1; i <= t; i ++) { e = e->nx = listNew(sizeof i, &i); }
Convert the following code from Python to C, ensuring the logic remains intact.
[(x,y,z) for x in xrange(1,n+1) for y in xrange(x,n+1) for z in xrange(y,n+1) if x**2 + y**2 == z**2]
for (int i = f + 1; i <= t; i ++) { e = e->nx = listNew(sizeof i, &i); }
Maintain the same structure and functionality when rewriting this code in C.
def selection_sort(lst): for i, e in enumerate(lst): mn = min(range(i,len(lst)), key=lst.__getitem__) lst[i], lst[mn] = lst[mn], e return lst
#include <stdio.h> void selection_sort (int *a, int n) { int i, j, m, t; for (i = 0; i < n; i++) { for (j = i, m = i; j < n; j++) { if (a[j] < a[m]) { m = j; } } t = a[i]; a[i] = a[m]; a[m] = t; } } int main () { int a[] = {4, 65, 2, -31, 0, 99, 2, 83, 782, 1}; int n = sizeof a / sizeof a[0]; int i; for (i = 0; i < n; i++) printf("%d%s", a[i], i == n - 1 ? "\n" : " "); selection_sort(a, n); for (i = 0; i < n; i++) printf("%d%s", a[i], i == n - 1 ? "\n" : " "); return 0; }
Port the provided Python code into C while preserving the original functionality.
def jacobi(a, n): if n <= 0: raise ValueError("'n' must be a positive integer.") if n % 2 == 0: raise ValueError("'n' must be odd.") a %= n result = 1 while a != 0: while a % 2 == 0: a /= 2 n_mod_8 = n % 8 if n_mod_8 in (3, 5): result = -result a, n = n, a if a % 4 == 3 and n % 4 == 3: result = -result a %= n if n == 1: return result else: return 0
#include <stdlib.h> #include <stdio.h> #define SWAP(a, b) (((a) ^= (b)), ((b) ^= (a)), ((a) ^= (b))) int jacobi(unsigned long a, unsigned long n) { if (a >= n) a %= n; int result = 1; while (a) { while ((a & 1) == 0) { a >>= 1; if ((n & 7) == 3 || (n & 7) == 5) result = -result; } SWAP(a, n); if ((a & 3) == 3 && (n & 3) == 3) result = -result; a %= n; } if (n == 1) return result; return 0; } void print_table(unsigned kmax, unsigned nmax) { printf("n\\k|"); for (int k = 0; k <= kmax; ++k) printf("%'3u", k); printf("\n----"); for (int k = 0; k <= kmax; ++k) printf("---"); putchar('\n'); for (int n = 1; n <= nmax; n += 2) { printf("%-2u |", n); for (int k = 0; k <= kmax; ++k) printf("%'3d", jacobi(k, n)); putchar('\n'); } } int main() { print_table(20, 21); return 0; }
Preserve the algorithm and functionality while converting the code from Python to C.
def jacobi(a, n): if n <= 0: raise ValueError("'n' must be a positive integer.") if n % 2 == 0: raise ValueError("'n' must be odd.") a %= n result = 1 while a != 0: while a % 2 == 0: a /= 2 n_mod_8 = n % 8 if n_mod_8 in (3, 5): result = -result a, n = n, a if a % 4 == 3 and n % 4 == 3: result = -result a %= n if n == 1: return result else: return 0
#include <stdlib.h> #include <stdio.h> #define SWAP(a, b) (((a) ^= (b)), ((b) ^= (a)), ((a) ^= (b))) int jacobi(unsigned long a, unsigned long n) { if (a >= n) a %= n; int result = 1; while (a) { while ((a & 1) == 0) { a >>= 1; if ((n & 7) == 3 || (n & 7) == 5) result = -result; } SWAP(a, n); if ((a & 3) == 3 && (n & 3) == 3) result = -result; a %= n; } if (n == 1) return result; return 0; } void print_table(unsigned kmax, unsigned nmax) { printf("n\\k|"); for (int k = 0; k <= kmax; ++k) printf("%'3u", k); printf("\n----"); for (int k = 0; k <= kmax; ++k) printf("---"); putchar('\n'); for (int n = 1; n <= nmax; n += 2) { printf("%-2u |", n); for (int k = 0; k <= kmax; ++k) printf("%'3d", jacobi(k, n)); putchar('\n'); } } int main() { print_table(20, 21); return 0; }
Convert the following code from Python to C, ensuring the logic remains intact.
from random import seed, random from time import time from operator import itemgetter from collections import namedtuple from math import sqrt from copy import deepcopy def sqd(p1, p2): return sum((c1 - c2) ** 2 for c1, c2 in zip(p1, p2)) class KdNode(object): __slots__ = ("dom_elt", "split", "left", "right") def __init__(self, dom_elt, split, left, right): self.dom_elt = dom_elt self.split = split self.left = left self.right = right class Orthotope(object): __slots__ = ("min", "max") def __init__(self, mi, ma): self.min, self.max = mi, ma class KdTree(object): __slots__ = ("n", "bounds") def __init__(self, pts, bounds): def nk2(split, exset): if not exset: return None exset.sort(key=itemgetter(split)) m = len(exset) // 2 d = exset[m] while m + 1 < len(exset) and exset[m + 1][split] == d[split]: m += 1 d = exset[m] s2 = (split + 1) % len(d) return KdNode(d, split, nk2(s2, exset[:m]), nk2(s2, exset[m + 1:])) self.n = nk2(0, pts) self.bounds = bounds T3 = namedtuple("T3", "nearest dist_sqd nodes_visited") def find_nearest(k, t, p): def nn(kd, target, hr, max_dist_sqd): if kd is None: return T3([0.0] * k, float("inf"), 0) nodes_visited = 1 s = kd.split pivot = kd.dom_elt left_hr = deepcopy(hr) right_hr = deepcopy(hr) left_hr.max[s] = pivot[s] right_hr.min[s] = pivot[s] if target[s] <= pivot[s]: nearer_kd, nearer_hr = kd.left, left_hr further_kd, further_hr = kd.right, right_hr else: nearer_kd, nearer_hr = kd.right, right_hr further_kd, further_hr = kd.left, left_hr n1 = nn(nearer_kd, target, nearer_hr, max_dist_sqd) nearest = n1.nearest dist_sqd = n1.dist_sqd nodes_visited += n1.nodes_visited if dist_sqd < max_dist_sqd: max_dist_sqd = dist_sqd d = (pivot[s] - target[s]) ** 2 if d > max_dist_sqd: return T3(nearest, dist_sqd, nodes_visited) d = sqd(pivot, target) if d < dist_sqd: nearest = pivot dist_sqd = d max_dist_sqd = dist_sqd n2 = nn(further_kd, target, further_hr, max_dist_sqd) nodes_visited += n2.nodes_visited if n2.dist_sqd < dist_sqd: nearest = n2.nearest dist_sqd = n2.dist_sqd return T3(nearest, dist_sqd, nodes_visited) return nn(t.n, p, t.bounds, float("inf")) def show_nearest(k, heading, kd, p): print(heading + ":") print("Point: ", p) n = find_nearest(k, kd, p) print("Nearest neighbor:", n.nearest) print("Distance: ", sqrt(n.dist_sqd)) print("Nodes visited: ", n.nodes_visited, "\n") def random_point(k): return [random() for _ in range(k)] def random_points(k, n): return [random_point(k) for _ in range(n)] if __name__ == "__main__": seed(1) P = lambda *coords: list(coords) kd1 = KdTree([P(2, 3), P(5, 4), P(9, 6), P(4, 7), P(8, 1), P(7, 2)], Orthotope(P(0, 0), P(10, 10))) show_nearest(2, "Wikipedia example data", kd1, P(9, 2)) N = 400000 t0 = time() kd2 = KdTree(random_points(3, N), Orthotope(P(0, 0, 0), P(1, 1, 1))) t1 = time() text = lambda *parts: "".join(map(str, parts)) show_nearest(2, text("k-d tree with ", N, " random 3D points (generation time: ", t1-t0, "s)"), kd2, random_point(3))
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <math.h> #include <time.h> #define MAX_DIM 3 struct kd_node_t{ double x[MAX_DIM]; struct kd_node_t *left, *right; }; inline double dist(struct kd_node_t *a, struct kd_node_t *b, int dim) { double t, d = 0; while (dim--) { t = a->x[dim] - b->x[dim]; d += t * t; } return d; } inline void swap(struct kd_node_t *x, struct kd_node_t *y) { double tmp[MAX_DIM]; memcpy(tmp, x->x, sizeof(tmp)); memcpy(x->x, y->x, sizeof(tmp)); memcpy(y->x, tmp, sizeof(tmp)); } struct kd_node_t* find_median(struct kd_node_t *start, struct kd_node_t *end, int idx) { if (end <= start) return NULL; if (end == start + 1) return start; struct kd_node_t *p, *store, *md = start + (end - start) / 2; double pivot; while (1) { pivot = md->x[idx]; swap(md, end - 1); for (store = p = start; p < end; p++) { if (p->x[idx] < pivot) { if (p != store) swap(p, store); store++; } } swap(store, end - 1); if (store->x[idx] == md->x[idx]) return md; if (store > md) end = store; else start = store; } } struct kd_node_t* make_tree(struct kd_node_t *t, int len, int i, int dim) { struct kd_node_t *n; if (!len) return 0; if ((n = find_median(t, t + len, i))) { i = (i + 1) % dim; n->left = make_tree(t, n - t, i, dim); n->right = make_tree(n + 1, t + len - (n + 1), i, dim); } return n; } int visited; void nearest(struct kd_node_t *root, struct kd_node_t *nd, int i, int dim, struct kd_node_t **best, double *best_dist) { double d, dx, dx2; if (!root) return; d = dist(root, nd, dim); dx = root->x[i] - nd->x[i]; dx2 = dx * dx; visited ++; if (!*best || d < *best_dist) { *best_dist = d; *best = root; } if (!*best_dist) return; if (++i >= dim) i = 0; nearest(dx > 0 ? root->left : root->right, nd, i, dim, best, best_dist); if (dx2 >= *best_dist) return; nearest(dx > 0 ? root->right : root->left, nd, i, dim, best, best_dist); } #define N 1000000 #define rand1() (rand() / (double)RAND_MAX) #define rand_pt(v) { v.x[0] = rand1(); v.x[1] = rand1(); v.x[2] = rand1(); } int main(void) { int i; struct kd_node_t wp[] = { {{2, 3}}, {{5, 4}}, {{9, 6}}, {{4, 7}}, {{8, 1}}, {{7, 2}} }; struct kd_node_t testNode = {{9, 2}}; struct kd_node_t *root, *found, *million; double best_dist; root = make_tree(wp, sizeof(wp) / sizeof(wp[1]), 0, 2); visited = 0; found = 0; nearest(root, &testNode, 0, 2, &found, &best_dist); printf(">> WP tree\nsearching for (%g, %g)\n" "found (%g, %g) dist %g\nseen %d nodes\n\n", testNode.x[0], testNode.x[1], found->x[0], found->x[1], sqrt(best_dist), visited); million =(struct kd_node_t*) calloc(N, sizeof(struct kd_node_t)); srand(time(0)); for (i = 0; i < N; i++) rand_pt(million[i]); root = make_tree(million, N, 0, 3); rand_pt(testNode); visited = 0; found = 0; nearest(root, &testNode, 0, 3, &found, &best_dist); printf(">> Million tree\nsearching for (%g, %g, %g)\n" "found (%g, %g, %g) dist %g\nseen %d nodes\n", testNode.x[0], testNode.x[1], testNode.x[2], found->x[0], found->x[1], found->x[2], sqrt(best_dist), visited); int sum = 0, test_runs = 100000; for (i = 0; i < test_runs; i++) { found = 0; visited = 0; rand_pt(testNode); nearest(root, &testNode, 0, 3, &found, &best_dist); sum += visited; } printf("\n>> Million tree\n" "visited %d nodes for %d random findings (%f per lookup)\n", sum, test_runs, sum/(double)test_runs); return 0; }
Write the same algorithm in C as shown in this Python implementation.
from random import seed, random from time import time from operator import itemgetter from collections import namedtuple from math import sqrt from copy import deepcopy def sqd(p1, p2): return sum((c1 - c2) ** 2 for c1, c2 in zip(p1, p2)) class KdNode(object): __slots__ = ("dom_elt", "split", "left", "right") def __init__(self, dom_elt, split, left, right): self.dom_elt = dom_elt self.split = split self.left = left self.right = right class Orthotope(object): __slots__ = ("min", "max") def __init__(self, mi, ma): self.min, self.max = mi, ma class KdTree(object): __slots__ = ("n", "bounds") def __init__(self, pts, bounds): def nk2(split, exset): if not exset: return None exset.sort(key=itemgetter(split)) m = len(exset) // 2 d = exset[m] while m + 1 < len(exset) and exset[m + 1][split] == d[split]: m += 1 d = exset[m] s2 = (split + 1) % len(d) return KdNode(d, split, nk2(s2, exset[:m]), nk2(s2, exset[m + 1:])) self.n = nk2(0, pts) self.bounds = bounds T3 = namedtuple("T3", "nearest dist_sqd nodes_visited") def find_nearest(k, t, p): def nn(kd, target, hr, max_dist_sqd): if kd is None: return T3([0.0] * k, float("inf"), 0) nodes_visited = 1 s = kd.split pivot = kd.dom_elt left_hr = deepcopy(hr) right_hr = deepcopy(hr) left_hr.max[s] = pivot[s] right_hr.min[s] = pivot[s] if target[s] <= pivot[s]: nearer_kd, nearer_hr = kd.left, left_hr further_kd, further_hr = kd.right, right_hr else: nearer_kd, nearer_hr = kd.right, right_hr further_kd, further_hr = kd.left, left_hr n1 = nn(nearer_kd, target, nearer_hr, max_dist_sqd) nearest = n1.nearest dist_sqd = n1.dist_sqd nodes_visited += n1.nodes_visited if dist_sqd < max_dist_sqd: max_dist_sqd = dist_sqd d = (pivot[s] - target[s]) ** 2 if d > max_dist_sqd: return T3(nearest, dist_sqd, nodes_visited) d = sqd(pivot, target) if d < dist_sqd: nearest = pivot dist_sqd = d max_dist_sqd = dist_sqd n2 = nn(further_kd, target, further_hr, max_dist_sqd) nodes_visited += n2.nodes_visited if n2.dist_sqd < dist_sqd: nearest = n2.nearest dist_sqd = n2.dist_sqd return T3(nearest, dist_sqd, nodes_visited) return nn(t.n, p, t.bounds, float("inf")) def show_nearest(k, heading, kd, p): print(heading + ":") print("Point: ", p) n = find_nearest(k, kd, p) print("Nearest neighbor:", n.nearest) print("Distance: ", sqrt(n.dist_sqd)) print("Nodes visited: ", n.nodes_visited, "\n") def random_point(k): return [random() for _ in range(k)] def random_points(k, n): return [random_point(k) for _ in range(n)] if __name__ == "__main__": seed(1) P = lambda *coords: list(coords) kd1 = KdTree([P(2, 3), P(5, 4), P(9, 6), P(4, 7), P(8, 1), P(7, 2)], Orthotope(P(0, 0), P(10, 10))) show_nearest(2, "Wikipedia example data", kd1, P(9, 2)) N = 400000 t0 = time() kd2 = KdTree(random_points(3, N), Orthotope(P(0, 0, 0), P(1, 1, 1))) t1 = time() text = lambda *parts: "".join(map(str, parts)) show_nearest(2, text("k-d tree with ", N, " random 3D points (generation time: ", t1-t0, "s)"), kd2, random_point(3))
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <math.h> #include <time.h> #define MAX_DIM 3 struct kd_node_t{ double x[MAX_DIM]; struct kd_node_t *left, *right; }; inline double dist(struct kd_node_t *a, struct kd_node_t *b, int dim) { double t, d = 0; while (dim--) { t = a->x[dim] - b->x[dim]; d += t * t; } return d; } inline void swap(struct kd_node_t *x, struct kd_node_t *y) { double tmp[MAX_DIM]; memcpy(tmp, x->x, sizeof(tmp)); memcpy(x->x, y->x, sizeof(tmp)); memcpy(y->x, tmp, sizeof(tmp)); } struct kd_node_t* find_median(struct kd_node_t *start, struct kd_node_t *end, int idx) { if (end <= start) return NULL; if (end == start + 1) return start; struct kd_node_t *p, *store, *md = start + (end - start) / 2; double pivot; while (1) { pivot = md->x[idx]; swap(md, end - 1); for (store = p = start; p < end; p++) { if (p->x[idx] < pivot) { if (p != store) swap(p, store); store++; } } swap(store, end - 1); if (store->x[idx] == md->x[idx]) return md; if (store > md) end = store; else start = store; } } struct kd_node_t* make_tree(struct kd_node_t *t, int len, int i, int dim) { struct kd_node_t *n; if (!len) return 0; if ((n = find_median(t, t + len, i))) { i = (i + 1) % dim; n->left = make_tree(t, n - t, i, dim); n->right = make_tree(n + 1, t + len - (n + 1), i, dim); } return n; } int visited; void nearest(struct kd_node_t *root, struct kd_node_t *nd, int i, int dim, struct kd_node_t **best, double *best_dist) { double d, dx, dx2; if (!root) return; d = dist(root, nd, dim); dx = root->x[i] - nd->x[i]; dx2 = dx * dx; visited ++; if (!*best || d < *best_dist) { *best_dist = d; *best = root; } if (!*best_dist) return; if (++i >= dim) i = 0; nearest(dx > 0 ? root->left : root->right, nd, i, dim, best, best_dist); if (dx2 >= *best_dist) return; nearest(dx > 0 ? root->right : root->left, nd, i, dim, best, best_dist); } #define N 1000000 #define rand1() (rand() / (double)RAND_MAX) #define rand_pt(v) { v.x[0] = rand1(); v.x[1] = rand1(); v.x[2] = rand1(); } int main(void) { int i; struct kd_node_t wp[] = { {{2, 3}}, {{5, 4}}, {{9, 6}}, {{4, 7}}, {{8, 1}}, {{7, 2}} }; struct kd_node_t testNode = {{9, 2}}; struct kd_node_t *root, *found, *million; double best_dist; root = make_tree(wp, sizeof(wp) / sizeof(wp[1]), 0, 2); visited = 0; found = 0; nearest(root, &testNode, 0, 2, &found, &best_dist); printf(">> WP tree\nsearching for (%g, %g)\n" "found (%g, %g) dist %g\nseen %d nodes\n\n", testNode.x[0], testNode.x[1], found->x[0], found->x[1], sqrt(best_dist), visited); million =(struct kd_node_t*) calloc(N, sizeof(struct kd_node_t)); srand(time(0)); for (i = 0; i < N; i++) rand_pt(million[i]); root = make_tree(million, N, 0, 3); rand_pt(testNode); visited = 0; found = 0; nearest(root, &testNode, 0, 3, &found, &best_dist); printf(">> Million tree\nsearching for (%g, %g, %g)\n" "found (%g, %g, %g) dist %g\nseen %d nodes\n", testNode.x[0], testNode.x[1], testNode.x[2], found->x[0], found->x[1], found->x[2], sqrt(best_dist), visited); int sum = 0, test_runs = 100000; for (i = 0; i < test_runs; i++) { found = 0; visited = 0; rand_pt(testNode); nearest(root, &testNode, 0, 3, &found, &best_dist); sum += visited; } printf("\n>> Million tree\n" "visited %d nodes for %d random findings (%f per lookup)\n", sum, test_runs, sum/(double)test_runs); return 0; }
Translate the given Python code snippet into C without altering its behavior.
def square(n): return n * n numbers = [1, 3, 5, 7] squares1 = [square(n) for n in numbers] squares2a = map(square, numbers) squares2b = map(lambda x: x*x, numbers) squares3 = [n * n for n in numbers] isquares1 = (n * n for n in numbers) import itertools isquares2 = itertools.imap(square, numbers)
#ifndef CALLBACK_H #define CALLBACK_H void map(int* array, int len, void(*callback)(int,int)); #endif
Change the following Python code into C without altering its purpose.
>>> class Borg(object): __state = {} def __init__(self): self.__dict__ = self.__state >>> b1 = Borg() >>> b2 = Borg() >>> b1 is b2 False >>> b1.datum = range(5) >>> b1.datum [0, 1, 2, 3, 4] >>> b2.datum [0, 1, 2, 3, 4] >>> b1.datum is b2.datum True >>>
#ifndef SILLY_H #define SILLY_H extern void JumpOverTheDog( int numberOfTimes); extern int PlayFetchWithDog( float weightOfStick); #endif
Change the programming language of this snippet from Python to C without modifying what it does.
>>> sum([.1, .1, .1, .1, .1, .1, .1, .1, .1, .1]) 0.9999999999999999 >>> from math import fsum >>> fsum([.1, .1, .1, .1, .1, .1, .1, .1, .1, .1]) 1.0
#include <fenv.h> #include <stdio.h> void safe_add(volatile double interval[2], volatile double a, volatile double b) { #pragma STDC FENV_ACCESS ON unsigned int orig; orig = fegetround(); fesetround(FE_DOWNWARD); interval[0] = a + b; fesetround(FE_UPWARD); interval[1] = a + b; fesetround(orig); } int main() { const double nums[][2] = { {1, 2}, {0.1, 0.2}, {1e100, 1e-100}, {1e308, 1e308}, }; double ival[2]; int i; for (i = 0; i < sizeof(nums) / sizeof(nums[0]); i++) { safe_add(ival, nums[i][0], nums[i][1]); printf("%.17g + %.17g =\n", nums[i][0], nums[i][1]); printf(" [%.17g, %.17g]\n", ival[0], ival[1]); printf(" size %.17g\n\n", ival[1] - ival[0]); } return 0; }
Keep all operations the same but rewrite the snippet in C.
>>> dog = 'Benjamin'; Dog = 'Samba'; DOG = 'Bernie' >>> print ('The three dogs are named ',dog,', ',Dog,', and ',DOG) The three dogs are named Benjamin , Samba , and Bernie >>>
#include <stdio.h> static const char *dog = "Benjamin"; static const char *Dog = "Samba"; static const char *DOG = "Bernie"; int main() { printf("The three dogs are named %s, %s and %s.\n", dog, Dog, DOG); return 0; }
Translate this program into C but keep the logic exactly as in Python.
for i in xrange(10, -1, -1): print i
int i; for(i = 10; i >= 0; --i) printf("%d\n",i);
Keep all operations the same but rewrite the snippet in C.
with open(filename, 'w') as f: f.write(data)
#define _CRT_SECURE_NO_WARNINGS #include <stdio.h> int main(void) { return 0 >= fputs("ANY STRING TO WRITE TO A FILE AT ONCE.", freopen("sample.txt","wb",stdout)); }
Generate a C translation of this Python snippet without changing its computational steps.
for i in 1..5: for j in 1..i: stdout.write("*") echo("")
int i, j; for (i = 1; i <= 5; i++) { for (j = 1; j <= i; j++) putchar('*'); puts(""); }
Maintain the same structure and functionality when rewriting this code in C.
from itertools import count from pprint import pformat import re import heapq def pal_part_gen(odd=True): for i in count(1): fwd = str(i) rev = fwd[::-1][1:] if odd else fwd[::-1] yield int(fwd + rev) def pal_ordered_gen(): yield from heapq.merge(pal_part_gen(odd=True), pal_part_gen(odd=False)) def is_gapful(x): return (x % (int(str(x)[0]) * 10 + (x % 10)) == 0) if __name__ == '__main__': start = 100 for mx, last in [(20, 20), (100, 15), (1_000, 10)]: print(f"\nLast {last} of the first {mx} binned-by-last digit " f"gapful numbers >= {start}") bin = {i: [] for i in range(1, 10)} gen = (i for i in pal_ordered_gen() if i >= start and is_gapful(i)) while any(len(val) < mx for val in bin.values()): g = next(gen) val = bin[g % 10] if len(val) < mx: val.append(g) b = {k:v[-last:] for k, v in bin.items()} txt = pformat(b, width=220) print('', re.sub(r"[{},\[\]]", '', txt))
#include <stdbool.h> #include <stdio.h> #include <stdint.h> typedef uint64_t integer; integer reverse(integer n) { integer rev = 0; while (n > 0) { rev = rev * 10 + (n % 10); n /= 10; } return rev; } typedef struct palgen_tag { integer power; integer next; int digit; bool even; } palgen_t; void init_palgen(palgen_t* palgen, int digit) { palgen->power = 10; palgen->next = digit * palgen->power - 1; palgen->digit = digit; palgen->even = false; } integer next_palindrome(palgen_t* p) { ++p->next; if (p->next == p->power * (p->digit + 1)) { if (p->even) p->power *= 10; p->next = p->digit * p->power; p->even = !p->even; } return p->next * (p->even ? 10 * p->power : p->power) + reverse(p->even ? p->next : p->next/10); } bool gapful(integer n) { integer m = n; while (m >= 10) m /= 10; return n % (n % 10 + 10 * m) == 0; } void print(int len, integer array[][len]) { for (int digit = 1; digit < 10; ++digit) { printf("%d: ", digit); for (int i = 0; i < len; ++i) printf(" %llu", array[digit - 1][i]); printf("\n"); } } int main() { const int n1 = 20, n2 = 15, n3 = 10; const int m1 = 100, m2 = 1000; integer pg1[9][n1]; integer pg2[9][n2]; integer pg3[9][n3]; for (int digit = 1; digit < 10; ++digit) { palgen_t pgen; init_palgen(&pgen, digit); for (int i = 0; i < m2; ) { integer n = next_palindrome(&pgen); if (!gapful(n)) continue; if (i < n1) pg1[digit - 1][i] = n; else if (i < m1 && i >= m1 - n2) pg2[digit - 1][i - (m1 - n2)] = n; else if (i >= m2 - n3) pg3[digit - 1][i - (m2 - n3)] = n; ++i; } } printf("First %d palindromic gapful numbers ending in:\n", n1); print(n1, pg1); printf("\nLast %d of first %d palindromic gapful numbers ending in:\n", n2, m1); print(n2, pg2); printf("\nLast %d of first %d palindromic gapful numbers ending in:\n", n3, m2); print(n3, pg3); return 0; }
Convert this Python block to C, preserving its control flow and logic.
from itertools import count from pprint import pformat import re import heapq def pal_part_gen(odd=True): for i in count(1): fwd = str(i) rev = fwd[::-1][1:] if odd else fwd[::-1] yield int(fwd + rev) def pal_ordered_gen(): yield from heapq.merge(pal_part_gen(odd=True), pal_part_gen(odd=False)) def is_gapful(x): return (x % (int(str(x)[0]) * 10 + (x % 10)) == 0) if __name__ == '__main__': start = 100 for mx, last in [(20, 20), (100, 15), (1_000, 10)]: print(f"\nLast {last} of the first {mx} binned-by-last digit " f"gapful numbers >= {start}") bin = {i: [] for i in range(1, 10)} gen = (i for i in pal_ordered_gen() if i >= start and is_gapful(i)) while any(len(val) < mx for val in bin.values()): g = next(gen) val = bin[g % 10] if len(val) < mx: val.append(g) b = {k:v[-last:] for k, v in bin.items()} txt = pformat(b, width=220) print('', re.sub(r"[{},\[\]]", '', txt))
#include <stdbool.h> #include <stdio.h> #include <stdint.h> typedef uint64_t integer; integer reverse(integer n) { integer rev = 0; while (n > 0) { rev = rev * 10 + (n % 10); n /= 10; } return rev; } typedef struct palgen_tag { integer power; integer next; int digit; bool even; } palgen_t; void init_palgen(palgen_t* palgen, int digit) { palgen->power = 10; palgen->next = digit * palgen->power - 1; palgen->digit = digit; palgen->even = false; } integer next_palindrome(palgen_t* p) { ++p->next; if (p->next == p->power * (p->digit + 1)) { if (p->even) p->power *= 10; p->next = p->digit * p->power; p->even = !p->even; } return p->next * (p->even ? 10 * p->power : p->power) + reverse(p->even ? p->next : p->next/10); } bool gapful(integer n) { integer m = n; while (m >= 10) m /= 10; return n % (n % 10 + 10 * m) == 0; } void print(int len, integer array[][len]) { for (int digit = 1; digit < 10; ++digit) { printf("%d: ", digit); for (int i = 0; i < len; ++i) printf(" %llu", array[digit - 1][i]); printf("\n"); } } int main() { const int n1 = 20, n2 = 15, n3 = 10; const int m1 = 100, m2 = 1000; integer pg1[9][n1]; integer pg2[9][n2]; integer pg3[9][n3]; for (int digit = 1; digit < 10; ++digit) { palgen_t pgen; init_palgen(&pgen, digit); for (int i = 0; i < m2; ) { integer n = next_palindrome(&pgen); if (!gapful(n)) continue; if (i < n1) pg1[digit - 1][i] = n; else if (i < m1 && i >= m1 - n2) pg2[digit - 1][i - (m1 - n2)] = n; else if (i >= m2 - n3) pg3[digit - 1][i - (m2 - n3)] = n; ++i; } } printf("First %d palindromic gapful numbers ending in:\n", n1); print(n1, pg1); printf("\nLast %d of first %d palindromic gapful numbers ending in:\n", n2, m1); print(n2, pg2); printf("\nLast %d of first %d palindromic gapful numbers ending in:\n", n3, m2); print(n3, pg3); return 0; }
Rewrite the snippet below in C so it works the same as the original Python code.
import turtle as t def sier(n,length): if n == 0: return for i in range(3): sier(n - 1, length / 2) t.fd(length) t.rt(120)
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <math.h> long long x, y, dx, dy, scale, clen, cscale; typedef struct { double r, g, b; } rgb; rgb ** pix; void sc_up() { scale *= 2; x *= 2; y *= 2; cscale *= 3; } void h_rgb(long long x, long long y) { rgb *p = &pix[y][x]; # define SAT 1 double h = 6.0 * clen / cscale; double VAL = 1; double c = SAT * VAL; double X = c * (1 - fabs(fmod(h, 2) - 1)); switch((int)h) { case 0: p->r += c; p->g += X; return; case 1: p->r += X; p->g += c; return; case 2: p->g += c; p->b += X; return; case 3: p->g += X; p->b += c; return; case 4: p->r += X; p->b += c; return; default: p->r += c; p->b += X; } } void iter_string(const char * str, int d) { long long len; while (*str != '\0') { switch(*(str++)) { case 'X': if (d) iter_string("XHXVX", d - 1); else{ clen ++; h_rgb(x/scale, y/scale); x += dx; y -= dy; } continue; case 'V': len = 1LLU << d; while (len--) { clen ++; h_rgb(x/scale, y/scale); y += dy; } continue; case 'H': len = 1LLU << d; while(len --) { clen ++; h_rgb(x/scale, y/scale); x -= dx; } continue; } } } void sierp(long leng, int depth) { long i; long h = leng + 20, w = leng + 20; rgb *buf = malloc(sizeof(rgb) * w * h); pix = malloc(sizeof(rgb *) * h); for (i = 0; i < h; i++) pix[i] = buf + w * i; memset(buf, 0, sizeof(rgb) * w * h); x = y = 10; dx = leng; dy = leng; scale = 1; clen = 0; cscale = 3; for (i = 0; i < depth; i++) sc_up(); iter_string("VXH", depth); unsigned char *fpix = malloc(w * h * 3); double maxv = 0, *dbuf = (double*)buf; for (i = 3 * w * h - 1; i >= 0; i--) if (dbuf[i] > maxv) maxv = dbuf[i]; for (i = 3 * h * w - 1; i >= 0; i--) fpix[i] = 255 * dbuf[i] / maxv; printf("P6\n%ld %ld\n255\n", w, h); fflush(stdout); fwrite(fpix, h * w * 3, 1, stdout); } int main(int c, char ** v) { int size, depth; depth = (c > 1) ? atoi(v[1]) : 10; size = 1 << depth; fprintf(stderr, "size: %d depth: %d\n", size, depth); sierp(size, depth + 2); return 0; }
Port the provided Python code into C while preserving the original functionality.
import turtle as t def sier(n,length): if n == 0: return for i in range(3): sier(n - 1, length / 2) t.fd(length) t.rt(120)
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <math.h> long long x, y, dx, dy, scale, clen, cscale; typedef struct { double r, g, b; } rgb; rgb ** pix; void sc_up() { scale *= 2; x *= 2; y *= 2; cscale *= 3; } void h_rgb(long long x, long long y) { rgb *p = &pix[y][x]; # define SAT 1 double h = 6.0 * clen / cscale; double VAL = 1; double c = SAT * VAL; double X = c * (1 - fabs(fmod(h, 2) - 1)); switch((int)h) { case 0: p->r += c; p->g += X; return; case 1: p->r += X; p->g += c; return; case 2: p->g += c; p->b += X; return; case 3: p->g += X; p->b += c; return; case 4: p->r += X; p->b += c; return; default: p->r += c; p->b += X; } } void iter_string(const char * str, int d) { long long len; while (*str != '\0') { switch(*(str++)) { case 'X': if (d) iter_string("XHXVX", d - 1); else{ clen ++; h_rgb(x/scale, y/scale); x += dx; y -= dy; } continue; case 'V': len = 1LLU << d; while (len--) { clen ++; h_rgb(x/scale, y/scale); y += dy; } continue; case 'H': len = 1LLU << d; while(len --) { clen ++; h_rgb(x/scale, y/scale); x -= dx; } continue; } } } void sierp(long leng, int depth) { long i; long h = leng + 20, w = leng + 20; rgb *buf = malloc(sizeof(rgb) * w * h); pix = malloc(sizeof(rgb *) * h); for (i = 0; i < h; i++) pix[i] = buf + w * i; memset(buf, 0, sizeof(rgb) * w * h); x = y = 10; dx = leng; dy = leng; scale = 1; clen = 0; cscale = 3; for (i = 0; i < depth; i++) sc_up(); iter_string("VXH", depth); unsigned char *fpix = malloc(w * h * 3); double maxv = 0, *dbuf = (double*)buf; for (i = 3 * w * h - 1; i >= 0; i--) if (dbuf[i] > maxv) maxv = dbuf[i]; for (i = 3 * h * w - 1; i >= 0; i--) fpix[i] = 255 * dbuf[i] / maxv; printf("P6\n%ld %ld\n255\n", w, h); fflush(stdout); fwrite(fpix, h * w * 3, 1, stdout); } int main(int c, char ** v) { int size, depth; depth = (c > 1) ? atoi(v[1]) : 10; size = 1 << depth; fprintf(stderr, "size: %d depth: %d\n", size, depth); sierp(size, depth + 2); return 0; }
Convert this Python snippet to C and keep its semantics consistent.
from itertools import accumulate, chain, takewhile def primeSums(): return ( x for x in enumerate( accumulate( chain([(0, 0)], primes()), lambda a, p: (p, p + a[1]) ) ) if isPrime(x[1][1]) ) def main(): for x in takewhile( lambda t: 1000 > t[1][0], primeSums() ): print(f'{x[0]} -> {x[1][1]}') def isPrime(n): if n in (2, 3): return True if 2 > n or 0 == n % 2: return False if 9 > n: return True if 0 == n % 3: return False def p(x): return 0 == n % x or 0 == n % (2 + x) return not any(map(p, range(5, 1 + int(n ** 0.5), 6))) def primes(): n = 2 dct = {} while True: if n in dct: for p in dct[n]: dct.setdefault(n + p, []).append(p) del dct[n] else: yield n dct[n * n] = [n] n = 1 + n if __name__ == '__main__': main()
#include <stdbool.h> #include <stdio.h> bool is_prime(int n) { int i = 5; if (n < 2) { return false; } if (n % 2 == 0) { return n == 2; } if (n % 3 == 0) { return n == 3; } while (i * i <= n) { if (n % i == 0) { return false; } i += 2; if (n % i == 0) { return false; } i += 4; } return true; } int main() { const int start = 1; const int stop = 1000; int sum = 0; int count = 0; int sc = 0; int p; for (p = start; p < stop; p++) { if (is_prime(p)) { count++; sum += p; if (is_prime(sum)) { printf("The sum of %3d primes in [2, %3d] is %5d which is also prime\n", count, p, sum); sc++; } } } printf("There are %d summerized primes in [%d, %d)\n", sc, start, stop); return 0; }
Write the same algorithm in C as shown in this Python implementation.
from itertools import accumulate, chain, takewhile def primeSums(): return ( x for x in enumerate( accumulate( chain([(0, 0)], primes()), lambda a, p: (p, p + a[1]) ) ) if isPrime(x[1][1]) ) def main(): for x in takewhile( lambda t: 1000 > t[1][0], primeSums() ): print(f'{x[0]} -> {x[1][1]}') def isPrime(n): if n in (2, 3): return True if 2 > n or 0 == n % 2: return False if 9 > n: return True if 0 == n % 3: return False def p(x): return 0 == n % x or 0 == n % (2 + x) return not any(map(p, range(5, 1 + int(n ** 0.5), 6))) def primes(): n = 2 dct = {} while True: if n in dct: for p in dct[n]: dct.setdefault(n + p, []).append(p) del dct[n] else: yield n dct[n * n] = [n] n = 1 + n if __name__ == '__main__': main()
#include <stdbool.h> #include <stdio.h> bool is_prime(int n) { int i = 5; if (n < 2) { return false; } if (n % 2 == 0) { return n == 2; } if (n % 3 == 0) { return n == 3; } while (i * i <= n) { if (n % i == 0) { return false; } i += 2; if (n % i == 0) { return false; } i += 4; } return true; } int main() { const int start = 1; const int stop = 1000; int sum = 0; int count = 0; int sc = 0; int p; for (p = start; p < stop; p++) { if (is_prime(p)) { count++; sum += p; if (is_prime(sum)) { printf("The sum of %3d primes in [2, %3d] is %5d which is also prime\n", count, p, sum); sc++; } } } printf("There are %d summerized primes in [%d, %d)\n", sc, start, stop); return 0; }
Convert the following code from Python to C, ensuring the logic remains intact.
from itertools import chain def main(): print( sorted(nub(concat([ [5, 1, 3, 8, 9, 4, 8, 7], [3, 5, 9, 8, 4], [1, 3, 7, 9] ]))) ) def concat(xs): return list(chain(*xs)) def nub(xs): return list(dict.fromkeys(xs)) if __name__ == '__main__': main()
#include <stdio.h> #include <stdlib.h> #include <string.h> #define COUNTOF(a) (sizeof(a)/sizeof(a[0])) void fatal(const char* message) { fprintf(stderr, "%s\n", message); exit(1); } void* xmalloc(size_t n) { void* ptr = malloc(n); if (ptr == NULL) fatal("Out of memory"); return ptr; } int icompare(const void* p1, const void* p2) { const int* ip1 = p1; const int* ip2 = p2; return (*ip1 < *ip2) ? -1 : ((*ip1 > *ip2) ? 1 : 0); } size_t unique(int* array, size_t len) { size_t out_index = 0; int prev; for (size_t i = 0; i < len; ++i) { if (i == 0 || prev != array[i]) array[out_index++] = array[i]; prev = array[i]; } return out_index; } int* common_sorted_list(const int** arrays, const size_t* lengths, size_t count, size_t* size) { size_t len = 0; for (size_t i = 0; i < count; ++i) len += lengths[i]; int* array = xmalloc(len * sizeof(int)); for (size_t i = 0, offset = 0; i < count; ++i) { memcpy(array + offset, arrays[i], lengths[i] * sizeof(int)); offset += lengths[i]; } qsort(array, len, sizeof(int), icompare); *size = unique(array, len); return array; } void print(const int* array, size_t len) { printf("["); for (size_t i = 0; i < len; ++i) { if (i > 0) printf(", "); printf("%d", array[i]); } printf("]\n"); } int main() { const int a[] = {5, 1, 3, 8, 9, 4, 8, 7}; const int b[] = {3, 5, 9, 8, 4}; const int c[] = {1, 3, 7, 9}; size_t len = 0; const int* arrays[] = {a, b, c}; size_t lengths[] = {COUNTOF(a), COUNTOF(b), COUNTOF(c)}; int* sorted = common_sorted_list(arrays, lengths, COUNTOF(arrays), &len); print(sorted, len); free(sorted); return 0; }
Rewrite this program in C while keeping its functionality equivalent to the Python version.
from itertools import chain def main(): print( sorted(nub(concat([ [5, 1, 3, 8, 9, 4, 8, 7], [3, 5, 9, 8, 4], [1, 3, 7, 9] ]))) ) def concat(xs): return list(chain(*xs)) def nub(xs): return list(dict.fromkeys(xs)) if __name__ == '__main__': main()
#include <stdio.h> #include <stdlib.h> #include <string.h> #define COUNTOF(a) (sizeof(a)/sizeof(a[0])) void fatal(const char* message) { fprintf(stderr, "%s\n", message); exit(1); } void* xmalloc(size_t n) { void* ptr = malloc(n); if (ptr == NULL) fatal("Out of memory"); return ptr; } int icompare(const void* p1, const void* p2) { const int* ip1 = p1; const int* ip2 = p2; return (*ip1 < *ip2) ? -1 : ((*ip1 > *ip2) ? 1 : 0); } size_t unique(int* array, size_t len) { size_t out_index = 0; int prev; for (size_t i = 0; i < len; ++i) { if (i == 0 || prev != array[i]) array[out_index++] = array[i]; prev = array[i]; } return out_index; } int* common_sorted_list(const int** arrays, const size_t* lengths, size_t count, size_t* size) { size_t len = 0; for (size_t i = 0; i < count; ++i) len += lengths[i]; int* array = xmalloc(len * sizeof(int)); for (size_t i = 0, offset = 0; i < count; ++i) { memcpy(array + offset, arrays[i], lengths[i] * sizeof(int)); offset += lengths[i]; } qsort(array, len, sizeof(int), icompare); *size = unique(array, len); return array; } void print(const int* array, size_t len) { printf("["); for (size_t i = 0; i < len; ++i) { if (i > 0) printf(", "); printf("%d", array[i]); } printf("]\n"); } int main() { const int a[] = {5, 1, 3, 8, 9, 4, 8, 7}; const int b[] = {3, 5, 9, 8, 4}; const int c[] = {1, 3, 7, 9}; size_t len = 0; const int* arrays[] = {a, b, c}; size_t lengths[] = {COUNTOF(a), COUNTOF(b), COUNTOF(c)}; int* sorted = common_sorted_list(arrays, lengths, COUNTOF(arrays), &len); print(sorted, len); free(sorted); return 0; }
Port the provided Python code into C while preserving the original functionality.
def ncsub(seq, s=0): if seq: x = seq[:1] xs = seq[1:] p2 = s % 2 p1 = not p2 return [x + ys for ys in ncsub(xs, s + p1)] + ncsub(xs, s + p2) else: return [[]] if s >= 3 else []
#include <assert.h> #include <stdio.h> int main(int c, char **v) { unsigned int n = 1 << (c - 1), i = n, j, k; assert(n); while (i--) { if (!(i & (i + (i & -(int)i)))) continue; for (j = n, k = 1; j >>= 1; k++) if (i & j) printf("%s ", v[k]); putchar('\n'); } return 0; }
Ensure the translated C code behaves exactly like the original Python snippet.
from functools import wraps from turtle import * def memoize(obj): cache = obj.cache = {} @wraps(obj) def memoizer(*args, **kwargs): key = str(args) + str(kwargs) if key not in cache: cache[key] = obj(*args, **kwargs) return cache[key] return memoizer @memoize def fibonacci_word(n): assert n > 0 if n == 1: return "1" if n == 2: return "0" return fibonacci_word(n - 1) + fibonacci_word(n - 2) def draw_fractal(word, step): for i, c in enumerate(word, 1): forward(step) if c == "0": if i % 2 == 0: left(90) else: right(90) def main(): n = 25 step = 1 width = 1050 height = 1050 w = fibonacci_word(n) setup(width=width, height=height) speed(0) setheading(90) left(90) penup() forward(500) right(90) backward(500) pendown() tracer(10000) hideturtle() draw_fractal(w, step) getscreen().getcanvas().postscript(file="fibonacci_word_fractal.eps") exitonclick() if __name__ == '__main__': main()
#include <stdio.h> int main(void) { puts( "%!PS-Adobe-3.0 EPSF\n" "%%BoundingBox: -10 -10 400 565\n" "/a{0 0 moveto 0 .4 translate 0 0 lineto stroke -1 1 scale}def\n" "/b{a 90 rotate}def"); char i; for (i = 'c'; i <= 'z'; i++) printf("/%c{%c %c}def\n", i, i-1, i-2); puts("0 setlinewidth z showpage\n%%EOF"); return 0; }
Port the provided Python code into C while preserving the original functionality.
primes = [2, 3, 5, 7, 11, 13, 17, 19] def count_twin_primes(limit: int) -> int: global primes if limit > primes[-1]: ram_limit = primes[-1] + 90000000 - len(primes) reasonable_limit = min(limit, primes[-1] ** 2, ram_limit) - 1 while reasonable_limit < limit: ram_limit = primes[-1] + 90000000 - len(primes) if ram_limit > primes[-1]: reasonable_limit = min(limit, primes[-1] ** 2, ram_limit) else: reasonable_limit = min(limit, primes[-1] ** 2) sieve = list({x for prime in primes for x in range(primes[-1] + prime - (primes[-1] % prime), reasonable_limit, prime)}) primes += [x - 1 for i, x in enumerate(sieve) if i and x - 1 != sieve[i - 1] and x - 1 < limit] count = len([(x, y) for (x, y) in zip(primes, primes[1:]) if x + 2 == y]) return count def test(limit: int): count = count_twin_primes(limit) print(f"Number of twin prime pairs less than {limit} is {count}\n") test(10) test(100) test(1000) test(10000) test(100000) test(1000000) test(10000000) test(100000000)
#include <stdbool.h> #include <stdint.h> #include <stdio.h> bool isPrime(int64_t n) { int64_t i; if (n < 2) return false; if (n % 2 == 0) return n == 2; if (n % 3 == 0) return n == 3; if (n % 5 == 0) return n == 5; if (n % 7 == 0) return n == 7; if (n % 11 == 0) return n == 11; if (n % 13 == 0) return n == 13; if (n % 17 == 0) return n == 17; if (n % 19 == 0) return n == 19; for (i = 23; i * i <= n; i += 2) { if (n % i == 0) return false; } return true; } int countTwinPrimes(int limit) { int count = 0; int64_t p3 = true, p2 = true, p1 = false; int64_t i; for (i = 5; i <= limit; i++) { p3 = p2; p2 = p1; p1 = isPrime(i); if (p3 && p1) { count++; } } return count; } void test(int limit) { int count = countTwinPrimes(limit); printf("Number of twin prime pairs less than %d is %d\n", limit, count); } int main() { test(10); test(100); test(1000); test(10000); test(100000); test(1000000); test(10000000); test(100000000); return 0; }
Port the provided Python code into C while preserving the original functionality.
import cmath class Complex(complex): def __repr__(self): rp = '%7.5f' % self.real if not self.pureImag() else '' ip = '%7.5fj' % self.imag if not self.pureReal() else '' conj = '' if ( self.pureImag() or self.pureReal() or self.imag < 0.0 ) else '+' return '0.0' if ( self.pureImag() and self.pureReal() ) else rp + conj + ip def pureImag(self): return abs(self.real) < 0.000005 def pureReal(self): return abs(self.imag) < 0.000005 def croots(n): if n <= 0: return None return (Complex(cmath.rect(1, 2 * k * cmath.pi / n)) for k in range(n)) for nr in range(2, 11): print(nr, list(croots(nr)))
#include <stdio.h> #include <math.h> int main() { double a, c, s, PI2 = atan2(1, 1) * 8; int n, i; for (n = 1; n < 10; n++) for (i = 0; i < n; i++) { c = s = 0; if (!i ) c = 1; else if(n == 4 * i) s = 1; else if(n == 2 * i) c = -1; else if(3 * n == 4 * i) s = -1; else a = i * PI2 / n, c = cos(a), s = sin(a); if (c) printf("%.2g", c); printf(s == 1 ? "i" : s == -1 ? "-i" : s ? "%+.2gi" : "", s); printf(i == n - 1 ?"\n":", "); } return 0; }
Change the programming language of this snippet from Python to C without modifying what it does.
print 2**64*2**64
#include <stdio.h> #include <string.h> void longmulti(const char *a, const char *b, char *c) { int i = 0, j = 0, k = 0, n, carry; int la, lb; if (!strcmp(a, "0") || !strcmp(b, "0")) { c[0] = '0', c[1] = '\0'; return; } if (a[0] == '-') { i = 1; k = !k; } if (b[0] == '-') { j = 1; k = !k; } if (i || j) { if (k) c[0] = '-'; longmulti(a + i, b + j, c + k); return; } la = strlen(a); lb = strlen(b); memset(c, '0', la + lb); c[la + lb] = '\0'; # define I(a) (a - '0') for (i = la - 1; i >= 0; i--) { for (j = lb - 1, k = i + j + 1, carry = 0; j >= 0; j--, k--) { n = I(a[i]) * I(b[j]) + I(c[k]) + carry; carry = n / 10; c[k] = (n % 10) + '0'; } c[k] += carry; } # undef I if (c[0] == '0') memmove(c, c + 1, la + lb); return; } int main() { char c[1024]; longmulti("-18446744073709551616", "-18446744073709551616", c); printf("%s\n", c); return 0; }
Generate a C translation of this Python snippet without changing its computational steps.
import math def solvePell(n): x = int(math.sqrt(n)) y, z, r = x, 1, x << 1 e1, e2 = 1, 0 f1, f2 = 0, 1 while True: y = r * z - y z = (n - y * y) // z r = (x + y) // z e1, e2 = e2, e1 + e2 * r f1, f2 = f2, f1 + f2 * r a, b = f2 * x + e2, f2 if a * a - n * b * b == 1: return a, b for n in [61, 109, 181, 277]: x, y = solvePell(n) print("x^2 - %3d * y^2 = 1 for x = %27d and y = %25d" % (n, x, y))
#include <math.h> #include <stdbool.h> #include <stdint.h> #include <stdio.h> struct Pair { uint64_t v1, v2; }; struct Pair makePair(uint64_t a, uint64_t b) { struct Pair r; r.v1 = a; r.v2 = b; return r; } struct Pair solvePell(int n) { int x = (int) sqrt(n); if (x * x == n) { return makePair(1, 0); } else { int y = x; int z = 1; int r = 2 * x; struct Pair e = makePair(1, 0); struct Pair f = makePair(0, 1); uint64_t a = 0; uint64_t b = 0; while (true) { y = r * z - y; z = (n - y * y) / z; r = (x + y) / z; e = makePair(e.v2, r * e.v2 + e.v1); f = makePair(f.v2, r * f.v2 + f.v1); a = e.v2 + x * f.v2; b = f.v2; if (a * a - n * b * b == 1) { break; } } return makePair(a, b); } } void test(int n) { struct Pair r = solvePell(n); printf("x^2 - %3d * y^2 = 1 for x = %21llu and y = %21llu\n", n, r.v1, r.v2); } int main() { test(61); test(109); test(181); test(277); return 0; }
Translate the given Python code snippet into C without altering its behavior.
import random digits = '123456789' size = 4 chosen = ''.join(random.sample(digits,size)) print % (size, size) guesses = 0 while True: guesses += 1 while True: guess = raw_input('\nNext guess [%i]: ' % guesses).strip() if len(guess) == size and \ all(char in digits for char in guess) \ and len(set(guess)) == size: break print "Problem, try again. You need to enter %i unique digits from 1 to 9" % size if guess == chosen: print '\nCongratulations you guessed correctly in',guesses,'attempts' break bulls = cows = 0 for i in range(size): if guess[i] == chosen[i]: bulls += 1 elif guess[i] in chosen: cows += 1 print ' %i Bulls\n %i Cows' % (bulls, cows)
#include <stdio.h> #include <stdarg.h> #include <stdlib.h> #include <stdbool.h> #include <curses.h> #include <string.h> #define MAX_NUM_TRIES 72 #define LINE_BEGIN 7 #define LAST_LINE 18 int yp=LINE_BEGIN, xp=0; char number[5]; char guess[5]; #define MAX_STR 256 void mvaddstrf(int y, int x, const char *fmt, ...) { va_list args; char buf[MAX_STR]; va_start(args, fmt); vsprintf(buf, fmt, args); move(y, x); clrtoeol(); addstr(buf); va_end(args); } void ask_for_a_number() { int i=0; char symbols[] = "123456789"; move(5,0); clrtoeol(); addstr("Enter four digits: "); while(i<4) { int c = getch(); if ( (c >= '1') && (c <= '9') && (symbols[c-'1']!=0) ) { addch(c); symbols[c-'1'] = 0; guess[i++] = c; } } } void choose_the_number() { int i=0, j; char symbols[] = "123456789"; while(i<4) { j = rand() % 9; if ( symbols[j] != 0 ) { number[i++] = symbols[j]; symbols[j] = 0; } } }
Translate the given Python code snippet into C without altering its behavior.
def bubble_sort(seq): changed = True while changed: changed = False for i in range(len(seq) - 1): if seq[i] > seq[i+1]: seq[i], seq[i+1] = seq[i+1], seq[i] changed = True return seq if __name__ == "__main__": from random import shuffle testset = [_ for _ in range(100)] testcase = testset.copy() shuffle(testcase) assert testcase != testset bubble_sort(testcase) assert testcase == testset
#include <stdio.h> void bubble_sort (int *a, int n) { int i, t, j = n, s = 1; while (s) { s = 0; for (i = 1; i < j; i++) { if (a[i] < a[i - 1]) { t = a[i]; a[i] = a[i - 1]; a[i - 1] = t; s = 1; } } j--; } } int main () { int a[] = {4, 65, 2, -31, 0, 99, 2, 83, 782, 1}; int n = sizeof a / sizeof a[0]; int i; for (i = 0; i < n; i++) printf("%d%s", a[i], i == n - 1 ? "\n" : " "); bubble_sort(a, n); for (i = 0; i < n; i++) printf("%d%s", a[i], i == n - 1 ? "\n" : " "); return 0; }
Port the provided Python code into C while preserving the original functionality.
def product_of_divisors(n): assert(isinstance(n, int) and 0 < n) ans = i = j = 1 while i*i <= n: if 0 == n%i: ans *= i j = n//i if j != i: ans *= j i += 1 return ans if __name__ == "__main__": print([product_of_divisors(n) for n in range(1,51)])
#include <math.h> #include <stdio.h> unsigned int divisor_count(unsigned int n) { unsigned int total = 1; unsigned int p; for (; (n & 1) == 0; n >>= 1) { ++total; } for (p = 3; p * p <= n; p += 2) { unsigned int count = 1; for (; n % p == 0; n /= p) { ++count; } total *= count; } if (n > 1) { total *= 2; } return total; } unsigned int divisor_product(unsigned int n) { return pow(n, divisor_count(n) / 2.0); } int main() { const unsigned int limit = 50; unsigned int n; printf("Product of divisors for the first %d positive integers:\n", limit); for (n = 1; n <= limit; ++n) { printf("%11d", divisor_product(n)); if (n % 5 == 0) { printf("\n"); } } return 0; }
Translate the given Python code snippet into C without altering its behavior.
def product_of_divisors(n): assert(isinstance(n, int) and 0 < n) ans = i = j = 1 while i*i <= n: if 0 == n%i: ans *= i j = n//i if j != i: ans *= j i += 1 return ans if __name__ == "__main__": print([product_of_divisors(n) for n in range(1,51)])
#include <math.h> #include <stdio.h> unsigned int divisor_count(unsigned int n) { unsigned int total = 1; unsigned int p; for (; (n & 1) == 0; n >>= 1) { ++total; } for (p = 3; p * p <= n; p += 2) { unsigned int count = 1; for (; n % p == 0; n /= p) { ++count; } total *= count; } if (n > 1) { total *= 2; } return total; } unsigned int divisor_product(unsigned int n) { return pow(n, divisor_count(n) / 2.0); } int main() { const unsigned int limit = 50; unsigned int n; printf("Product of divisors for the first %d positive integers:\n", limit); for (n = 1; n <= limit; ++n) { printf("%11d", divisor_product(n)); if (n % 5 == 0) { printf("\n"); } } return 0; }
Transform the following Python implementation into C, maintaining the same output and logic.
import shutil shutil.copyfile('input.txt', 'output.txt')
#include <stdio.h> int main(int argc, char **argv) { FILE *in, *out; int c; in = fopen("input.txt", "r"); if (!in) { fprintf(stderr, "Error opening input.txt for reading.\n"); return 1; } out = fopen("output.txt", "w"); if (!out) { fprintf(stderr, "Error opening output.txt for writing.\n"); fclose(in); return 1; } while ((c = fgetc(in)) != EOF) { fputc(c, out); } fclose(out); fclose(in); return 0; }
Write the same algorithm in C as shown in this Python implementation.
x = int(raw_input("Number 1: ")) y = int(raw_input("Number 2: ")) print "Sum: %d" % (x + y) print "Difference: %d" % (x - y) print "Product: %d" % (x * y) print "Quotient: %d" % (x / y) print "Remainder: %d" % (x % y) print "Quotient: %d with Remainder: %d" % divmod(x, y) print "Power: %d" % x**y raw_input( )
#include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int a, b; if (argc < 3) exit(1); b = atoi(argv[--argc]); if (b == 0) exit(2); a = atoi(argv[--argc]); printf("a+b = %d\n", a+b); printf("a-b = %d\n", a-b); printf("a*b = %d\n", a*b); printf("a/b = %d\n", a/b); printf("a%%b = %d\n", a%b); return 0; }
Convert this Python snippet to C and keep its semantics consistent.
m=((1, 1, 1, 1), (2, 4, 8, 16), (3, 9, 27, 81), (4, 16, 64, 256), (5, 25,125, 625)) print(zip(*m))
#include <stdio.h> void transpose(void *dest, void *src, int src_h, int src_w) { int i, j; double (*d)[src_h] = dest, (*s)[src_w] = src; for (i = 0; i < src_h; i++) for (j = 0; j < src_w; j++) d[j][i] = s[i][j]; } int main() { int i, j; double a[3][5] = {{ 0, 1, 2, 3, 4 }, { 5, 6, 7, 8, 9 }, { 1, 0, 0, 0, 42}}; double b[5][3]; transpose(b, a, 3, 5); for (i = 0; i < 5; i++) for (j = 0; j < 3; j++) printf("%g%c", b[i][j], j == 2 ? '\n' : ' '); return 0; }
Can you help me rewrite this code in C instead of Python, keeping it the same logically?
import sys sys.setrecursionlimit(1025) def a(in_k, x1, x2, x3, x4, x5): k = [in_k] def b(): k[0] -= 1 return a(k[0], b, x1, x2, x3, x4) return x4() + x5() if k[0] <= 0 else b() x = lambda i: lambda: i print(a(10, x(1), x(-1), x(-1), x(1), x(0)))
#include <stdio.h> #include <stdlib.h> typedef struct arg { int (*fn)(struct arg*); int *k; struct arg *x1, *x2, *x3, *x4, *x5; } ARG; int f_1 (ARG* _) { return -1; } int f0 (ARG* _) { return 0; } int f1 (ARG* _) { return 1; } int eval(ARG* a) { return a->fn(a); } #define MAKE_ARG(...) (&(ARG){__VA_ARGS__}) #define FUN(...) MAKE_ARG(B, &k, __VA_ARGS__) int A(ARG*); int B(ARG* a) { int k = *a->k -= 1; return A(FUN(a, a->x1, a->x2, a->x3, a->x4)); } int A(ARG* a) { return *a->k <= 0 ? eval(a->x4) + eval(a->x5) : B(a); } int main(int argc, char **argv) { int k = argc == 2 ? strtol(argv[1], 0, 0) : 10; printf("%d\n", A(FUN(MAKE_ARG(f1), MAKE_ARG(f_1), MAKE_ARG(f_1), MAKE_ARG(f1), MAKE_ARG(f0)))); return 0; }
Translate this program into C but keep the logic exactly as in Python.
>>> def a(answer): print(" return answer >>> def b(answer): print(" return answer >>> for i in (False, True): for j in (False, True): print ("\nCalculating: x = a(i) and b(j)") x = a(i) and b(j) print ("Calculating: y = a(i) or b(j)") y = a(i) or b(j) Calculating: x = a(i) and b(j) Calculating: y = a(i) or b(j) Calculating: x = a(i) and b(j) Calculating: y = a(i) or b(j) Calculating: x = a(i) and b(j) Calculating: y = a(i) or b(j) Calculating: x = a(i) and b(j) Calculating: y = a(i) or b(j)
#include <stdio.h> #include <stdbool.h> bool a(bool in) { printf("I am a\n"); return in; } bool b(bool in) { printf("I am b\n"); return in; } #define TEST(X,Y,O) \ do { \ x = a(X) O b(Y); \ printf(#X " " #O " " #Y " = %s\n\n", x ? "true" : "false"); \ } while(false); int main() { bool x; TEST(false, true, &&); TEST(true, false, ||); TEST(true, false, &&); TEST(false, false, ||); return 0; }
Convert the following code from Python to C, ensuring the logic remains intact.
>>> def a(answer): print(" return answer >>> def b(answer): print(" return answer >>> for i in (False, True): for j in (False, True): print ("\nCalculating: x = a(i) and b(j)") x = a(i) and b(j) print ("Calculating: y = a(i) or b(j)") y = a(i) or b(j) Calculating: x = a(i) and b(j) Calculating: y = a(i) or b(j) Calculating: x = a(i) and b(j) Calculating: y = a(i) or b(j) Calculating: x = a(i) and b(j) Calculating: y = a(i) or b(j) Calculating: x = a(i) and b(j) Calculating: y = a(i) or b(j)
#include <stdio.h> #include <stdbool.h> bool a(bool in) { printf("I am a\n"); return in; } bool b(bool in) { printf("I am b\n"); return in; } #define TEST(X,Y,O) \ do { \ x = a(X) O b(Y); \ printf(#X " " #O " " #Y " = %s\n\n", x ? "true" : "false"); \ } while(false); int main() { bool x; TEST(false, true, &&); TEST(true, false, ||); TEST(true, false, &&); TEST(false, false, ||); return 0; }
Convert this Python snippet to C and keep its semantics consistent.
import sys print(sys.getrecursionlimit())
#include <stdio.h> void recurse(unsigned int i) { printf("%d\n", i); recurse(i+1); } int main() { recurse(0); return 0; }
Port the provided Python code into C while preserving the original functionality.
import sys print(sys.getrecursionlimit())
#include <stdio.h> void recurse(unsigned int i) { printf("%d\n", i); recurse(i+1); } int main() { recurse(0); return 0; }
Generate a C translation of this Python snippet without changing its computational steps.
import sys print(sys.getrecursionlimit())
#include <stdio.h> void recurse(unsigned int i) { printf("%d\n", i); recurse(i+1); } int main() { recurse(0); return 0; }
Transform the following Python implementation into C, maintaining the same output and logic.
class Isprime(): multiples = {2} primes = [2] nmax = 2 def __init__(self, nmax): if nmax > self.nmax: self.check(nmax) def check(self, n): if type(n) == float: if not n.is_integer(): return False n = int(n) multiples = self.multiples if n <= self.nmax: return n not in multiples else: primes, nmax = self.primes, self.nmax newmax = max(nmax*2, n) for p in primes: multiples.update(range(p*((nmax + p + 1) // p), newmax+1, p)) for i in range(nmax+1, newmax+1): if i not in multiples: primes.append(i) multiples.update(range(i*2, newmax+1, i)) self.nmax = newmax return n not in multiples __call__ = check def carmichael(p1): ans = [] if isprime(p1): for h3 in range(2, p1): g = h3 + p1 for d in range(1, g): if (g * (p1 - 1)) % d == 0 and (-p1 * p1) % h3 == d % h3: p2 = 1 + ((p1 - 1)* g // d) if isprime(p2): p3 = 1 + (p1 * p2 // h3) if isprime(p3): if (p2 * p3) % (p1 - 1) == 1: ans += [tuple(sorted((p1, p2, p3)))] return ans isprime = Isprime(2) ans = sorted(sum((carmichael(n) for n in range(62) if isprime(n)), [])) print(',\n'.join(repr(ans[i:i+5])[1:-1] for i in range(0, len(ans)+1, 5)))
#include <stdio.h> #define mod(n,m) ((((n) % (m)) + (m)) % (m)) int is_prime(unsigned int n) { if (n <= 3) { return n > 1; } else if (!(n % 2) || !(n % 3)) { return 0; } else { unsigned int i; for (i = 5; i*i <= n; i += 6) if (!(n % i) || !(n % (i + 2))) return 0; return 1; } } void carmichael3(int p1) { if (!is_prime(p1)) return; int h3, d, p2, p3; for (h3 = 1; h3 < p1; ++h3) { for (d = 1; d < h3 + p1; ++d) { if ((h3 + p1)*(p1 - 1) % d == 0 && mod(-p1 * p1, h3) == d % h3) { p2 = 1 + ((p1 - 1) * (h3 + p1)/d); if (!is_prime(p2)) continue; p3 = 1 + (p1 * p2 / h3); if (!is_prime(p3) || (p2 * p3) % (p1 - 1) != 1) continue; printf("%d %d %d\n", p1, p2, p3); } } } } int main(void) { int p1; for (p1 = 2; p1 < 62; ++p1) carmichael3(p1); return 0; }
Rewrite the snippet below in C so it works the same as the original Python code.
black = color(0) white = color(255) def setup(): size(320, 240) def draw(): loadPixels() for i in range(len(pixels)): if random(1) < 0.5: pixels[i] = black else: pixels[i] = white updatePixels() fill(0, 128) rect(0, 0, 60, 20) fill(255) text(frameRate, 5, 15)
#include <stdlib.h> #include <stdio.h> #include <time.h> #include <SDL/SDL.h> unsigned int frames = 0; unsigned int t_acc = 0; void print_fps () { static Uint32 last_t = 0; Uint32 t = SDL_GetTicks(); Uint32 dt = t - last_t; t_acc += dt; if (t_acc > 1000) { unsigned int el_time = t_acc / 1000; printf("- fps: %g\n", (float) frames / (float) el_time); t_acc = 0; frames = 0; } last_t = t; } void blit_noise(SDL_Surface *surf) { unsigned int i; long dim = surf->w * surf->h; while (1) { SDL_LockSurface(surf); for (i=0; i < dim; ++i) { ((unsigned char *)surf->pixels)[i] = ((rand() & 1) ? 255 : 0); } SDL_UnlockSurface(surf); SDL_Flip(surf); ++frames; print_fps(); } } int main(void) { SDL_Surface *surf = NULL; srand((unsigned int)time(NULL)); SDL_Init(SDL_INIT_TIMER | SDL_INIT_VIDEO); surf = SDL_SetVideoMode(320, 240, 8, SDL_DOUBLEBUF | SDL_HWSURFACE); blit_noise(surf); }
Rewrite this program in C while keeping its functionality equivalent to the Python version.
try: from msvcrt import getch except ImportError: def getch(): import sys, tty, termios fd = sys.stdin.fileno() old_settings = termios.tcgetattr(fd) try: tty.setraw(sys.stdin.fileno()) ch = sys.stdin.read(1) finally: termios.tcsetattr(fd, termios.TCSADRAIN, old_settings) return ch print "Press Y or N to continue" while True: char = getch() if char.lower() in ("y", "n"): print char break
#include <stdio.h> #include <termios.h> #include <unistd.h> #include <fcntl.h> #include <sys/time.h> void set_mode(int want_key) { static struct termios old, new; if (!want_key) { tcsetattr(STDIN_FILENO, TCSANOW, &old); return; } tcgetattr(STDIN_FILENO, &old); new = old; new.c_lflag &= ~(ICANON); tcsetattr(STDIN_FILENO, TCSANOW, &new); } int get_key(int no_timeout) { int c = 0; struct timeval tv; fd_set fs; tv.tv_usec = tv.tv_sec = 0; FD_ZERO(&fs); FD_SET(STDIN_FILENO, &fs); select(STDIN_FILENO + 1, &fs, 0, 0, no_timeout ? 0 : &tv); if (FD_ISSET(STDIN_FILENO, &fs)) { c = getchar(); set_mode(0); } return c; } int main() { int c; while(1) { set_mode(1); while (get_key(0)); printf("Prompt again [Y/N]? "); fflush(stdout); c = get_key(1); if (c == 'Y' || c == 'y') { printf("\n"); continue; } if (c == 'N' || c == 'n') { printf("\nDone\n"); break; } printf("\nYes or no?\n"); } return 0; }
Keep all operations the same but rewrite the snippet in C.
try: from msvcrt import getch except ImportError: def getch(): import sys, tty, termios fd = sys.stdin.fileno() old_settings = termios.tcgetattr(fd) try: tty.setraw(sys.stdin.fileno()) ch = sys.stdin.read(1) finally: termios.tcsetattr(fd, termios.TCSADRAIN, old_settings) return ch print "Press Y or N to continue" while True: char = getch() if char.lower() in ("y", "n"): print char break
#include <stdio.h> #include <termios.h> #include <unistd.h> #include <fcntl.h> #include <sys/time.h> void set_mode(int want_key) { static struct termios old, new; if (!want_key) { tcsetattr(STDIN_FILENO, TCSANOW, &old); return; } tcgetattr(STDIN_FILENO, &old); new = old; new.c_lflag &= ~(ICANON); tcsetattr(STDIN_FILENO, TCSANOW, &new); } int get_key(int no_timeout) { int c = 0; struct timeval tv; fd_set fs; tv.tv_usec = tv.tv_sec = 0; FD_ZERO(&fs); FD_SET(STDIN_FILENO, &fs); select(STDIN_FILENO + 1, &fs, 0, 0, no_timeout ? 0 : &tv); if (FD_ISSET(STDIN_FILENO, &fs)) { c = getchar(); set_mode(0); } return c; } int main() { int c; while(1) { set_mode(1); while (get_key(0)); printf("Prompt again [Y/N]? "); fflush(stdout); c = get_key(1); if (c == 'Y' || c == 'y') { printf("\n"); continue; } if (c == 'N' || c == 'n') { printf("\nDone\n"); break; } printf("\nYes or no?\n"); } return 0; }
Keep all operations the same but rewrite the snippet in C.
try: from msvcrt import getch except ImportError: def getch(): import sys, tty, termios fd = sys.stdin.fileno() old_settings = termios.tcgetattr(fd) try: tty.setraw(sys.stdin.fileno()) ch = sys.stdin.read(1) finally: termios.tcsetattr(fd, termios.TCSADRAIN, old_settings) return ch print "Press Y or N to continue" while True: char = getch() if char.lower() in ("y", "n"): print char break
#include <stdio.h> #include <termios.h> #include <unistd.h> #include <fcntl.h> #include <sys/time.h> void set_mode(int want_key) { static struct termios old, new; if (!want_key) { tcsetattr(STDIN_FILENO, TCSANOW, &old); return; } tcgetattr(STDIN_FILENO, &old); new = old; new.c_lflag &= ~(ICANON); tcsetattr(STDIN_FILENO, TCSANOW, &new); } int get_key(int no_timeout) { int c = 0; struct timeval tv; fd_set fs; tv.tv_usec = tv.tv_sec = 0; FD_ZERO(&fs); FD_SET(STDIN_FILENO, &fs); select(STDIN_FILENO + 1, &fs, 0, 0, no_timeout ? 0 : &tv); if (FD_ISSET(STDIN_FILENO, &fs)) { c = getchar(); set_mode(0); } return c; } int main() { int c; while(1) { set_mode(1); while (get_key(0)); printf("Prompt again [Y/N]? "); fflush(stdout); c = get_key(1); if (c == 'Y' || c == 'y') { printf("\n"); continue; } if (c == 'N' || c == 'n') { printf("\nDone\n"); break; } printf("\nYes or no?\n"); } return 0; }
Please provide an equivalent version of this Python code in C.
def perf1(n): sum = 0 for i in range(1, n): if n % i == 0: sum += i return sum == n
#include "stdio.h" #include "math.h" int perfect(int n) { int max = (int)sqrt((double)n) + 1; int tot = 1; int i; for (i = 2; i < max; i++) if ( (n % i) == 0 ) { tot += i; int q = n / i; if (q > i) tot += q; } return tot == n; } int main() { int n; for (n = 2; n < 33550337; n++) if (perfect(n)) printf("%d\n", n); return 0; }
Write the same algorithm in C as shown in this Python implementation.
def perf1(n): sum = 0 for i in range(1, n): if n % i == 0: sum += i return sum == n
#include "stdio.h" #include "math.h" int perfect(int n) { int max = (int)sqrt((double)n) + 1; int tot = 1; int i; for (i = 2; i < max; i++) if ( (n % i) == 0 ) { tot += i; int q = n / i; if (q > i) tot += q; } return tot == n; } int main() { int n; for (n = 2; n < 33550337; n++) if (perfect(n)) printf("%d\n", n); return 0; }
Write the same code in C as shown below in Python.
def conjugate_transpose(m): return tuple(tuple(n.conjugate() for n in row) for row in zip(*m)) def mmul( ma, mb): return tuple(tuple(sum( ea*eb for ea,eb in zip(a,b)) for b in zip(*mb)) for a in ma) def mi(size): 'Complex Identity matrix' sz = range(size) m = [[0 + 0j for i in sz] for j in sz] for i in range(size): m[i][i] = 1 + 0j return tuple(tuple(row) for row in m) def __allsame(vector): first, rest = vector[0], vector[1:] return all(i == first for i in rest) def __allnearsame(vector, eps=1e-14): first, rest = vector[0], vector[1:] return all(abs(first.real - i.real) < eps and abs(first.imag - i.imag) < eps for i in rest) def isequal(matrices, eps=1e-14): 'Check any number of matrices for equality within eps' x = [len(m) for m in matrices] if not __allsame(x): return False y = [len(m[0]) for m in matrices] if not __allsame(y): return False for s in range(x[0]): for t in range(y[0]): if not __allnearsame([m[s][t] for m in matrices], eps): return False return True def ishermitian(m, ct): return isequal([m, ct]) def isnormal(m, ct): return isequal([mmul(m, ct), mmul(ct, m)]) def isunitary(m, ct): mct, ctm = mmul(m, ct), mmul(ct, m) mctx, mcty, cmx, ctmy = len(mct), len(mct[0]), len(ctm), len(ctm[0]) ident = mi(mctx) return isequal([mct, ctm, ident]) def printm(comment, m): print(comment) fields = [['%g%+gj' % (f.real, f.imag) for f in row] for row in m] width = max(max(len(f) for f in row) for row in fields) lines = (', '.join('%*s' % (width, f) for f in row) for row in fields) print('\n'.join(lines)) if __name__ == '__main__': for matrix in [ ((( 3.000+0.000j), (+2.000+1.000j)), (( 2.000-1.000j), (+1.000+0.000j))), ((( 1.000+0.000j), (+1.000+0.000j), (+0.000+0.000j)), (( 0.000+0.000j), (+1.000+0.000j), (+1.000+0.000j)), (( 1.000+0.000j), (+0.000+0.000j), (+1.000+0.000j))), ((( 2**0.5/2+0.000j), (+2**0.5/2+0.000j), (+0.000+0.000j)), (( 0.000+2**0.5/2j), (+0.000-2**0.5/2j), (+0.000+0.000j)), (( 0.000+0.000j), (+0.000+0.000j), (+0.000+1.000j)))]: printm('\nMatrix:', matrix) ct = conjugate_transpose(matrix) printm('Its conjugate transpose:', ct) print('Hermitian? %s.' % ishermitian(matrix, ct)) print('Normal? %s.' % isnormal(matrix, ct)) print('Unitary? %s.' % isunitary(matrix, ct))
#include<stdlib.h> #include<stdio.h> #include<complex.h> typedef struct { int rows, cols; complex **z; } matrix; matrix transpose (matrix a) { int i, j; matrix b; b.rows = a.cols; b.cols = a.rows; b.z = malloc (b.rows * sizeof (complex *)); for (i = 0; i < b.rows; i++) { b.z[i] = malloc (b.cols * sizeof (complex)); for (j = 0; j < b.cols; j++) { b.z[i][j] = conj (a.z[j][i]); } } return b; } int isHermitian (matrix a) { int i, j; matrix b = transpose (a); if (b.rows == a.rows && b.cols == a.cols) { for (i = 0; i < b.rows; i++) { for (j = 0; j < b.cols; j++) { if (b.z[i][j] != a.z[i][j]) return 0; } } } else return 0; return 1; } matrix multiply (matrix a, matrix b) { matrix c; int i, j; if (a.cols == b.rows) { c.rows = a.rows; c.cols = b.cols; c.z = malloc (c.rows * (sizeof (complex *))); for (i = 0; i < c.rows; i++) { c.z[i] = malloc (c.cols * sizeof (complex)); c.z[i][j] = 0 + 0 * I; for (j = 0; j < b.cols; j++) { c.z[i][j] += a.z[i][j] * b.z[j][i]; } } } return c; } int isNormal (matrix a) { int i, j; matrix a_ah, ah_a; if (a.rows != a.cols) return 0; a_ah = multiply (a, transpose (a)); ah_a = multiply (transpose (a), a); for (i = 0; i < a.rows; i++) { for (j = 0; j < a.cols; j++) { if (a_ah.z[i][j] != ah_a.z[i][j]) return 0; } } return 1; } int isUnitary (matrix a) { matrix b; int i, j; if (isNormal (a) == 1) { b = multiply (a, transpose(a)); for (i = 0; i < b.rows; i++) { for (j = 0; j < b.cols; j++) { if ((i == j && b.z[i][j] != 1) || (i != j && b.z[i][j] != 0)) return 0; } } return 1; } return 0; } int main () { complex z = 3 + 4 * I; matrix a, aT; int i, j; printf ("Enter rows and columns :"); scanf ("%d%d", &a.rows, &a.cols); a.z = malloc (a.rows * sizeof (complex *)); printf ("Randomly Generated Complex Matrix A is : "); for (i = 0; i < a.rows; i++) { printf ("\n"); a.z[i] = malloc (a.cols * sizeof (complex)); for (j = 0; j < a.cols; j++) { a.z[i][j] = rand () % 10 + rand () % 10 * I; printf ("\t%f + %fi", creal (a.z[i][j]), cimag (a.z[i][j])); } } aT = transpose (a); printf ("\n\nTranspose of Complex Matrix A is : "); for (i = 0; i < aT.rows; i++) { printf ("\n"); aT.z[i] = malloc (aT.cols * sizeof (complex)); for (j = 0; j < aT.cols; j++) { aT.z[i][j] = rand () % 10 + rand () % 10 * I; printf ("\t%f + %fi", creal (aT.z[i][j]), cimag (aT.z[i][j])); } } printf ("\n\nComplex Matrix A %s hermitian", isHermitian (a) == 1 ? "is" : "is not"); printf ("\n\nComplex Matrix A %s unitary", isUnitary (a) == 1 ? "is" : "is not"); printf ("\n\nComplex Matrix A %s normal", isNormal (a) == 1 ? "is" : "is not"); return 0; }
Maintain the same structure and functionality when rewriting this code in C.
def conjugate_transpose(m): return tuple(tuple(n.conjugate() for n in row) for row in zip(*m)) def mmul( ma, mb): return tuple(tuple(sum( ea*eb for ea,eb in zip(a,b)) for b in zip(*mb)) for a in ma) def mi(size): 'Complex Identity matrix' sz = range(size) m = [[0 + 0j for i in sz] for j in sz] for i in range(size): m[i][i] = 1 + 0j return tuple(tuple(row) for row in m) def __allsame(vector): first, rest = vector[0], vector[1:] return all(i == first for i in rest) def __allnearsame(vector, eps=1e-14): first, rest = vector[0], vector[1:] return all(abs(first.real - i.real) < eps and abs(first.imag - i.imag) < eps for i in rest) def isequal(matrices, eps=1e-14): 'Check any number of matrices for equality within eps' x = [len(m) for m in matrices] if not __allsame(x): return False y = [len(m[0]) for m in matrices] if not __allsame(y): return False for s in range(x[0]): for t in range(y[0]): if not __allnearsame([m[s][t] for m in matrices], eps): return False return True def ishermitian(m, ct): return isequal([m, ct]) def isnormal(m, ct): return isequal([mmul(m, ct), mmul(ct, m)]) def isunitary(m, ct): mct, ctm = mmul(m, ct), mmul(ct, m) mctx, mcty, cmx, ctmy = len(mct), len(mct[0]), len(ctm), len(ctm[0]) ident = mi(mctx) return isequal([mct, ctm, ident]) def printm(comment, m): print(comment) fields = [['%g%+gj' % (f.real, f.imag) for f in row] for row in m] width = max(max(len(f) for f in row) for row in fields) lines = (', '.join('%*s' % (width, f) for f in row) for row in fields) print('\n'.join(lines)) if __name__ == '__main__': for matrix in [ ((( 3.000+0.000j), (+2.000+1.000j)), (( 2.000-1.000j), (+1.000+0.000j))), ((( 1.000+0.000j), (+1.000+0.000j), (+0.000+0.000j)), (( 0.000+0.000j), (+1.000+0.000j), (+1.000+0.000j)), (( 1.000+0.000j), (+0.000+0.000j), (+1.000+0.000j))), ((( 2**0.5/2+0.000j), (+2**0.5/2+0.000j), (+0.000+0.000j)), (( 0.000+2**0.5/2j), (+0.000-2**0.5/2j), (+0.000+0.000j)), (( 0.000+0.000j), (+0.000+0.000j), (+0.000+1.000j)))]: printm('\nMatrix:', matrix) ct = conjugate_transpose(matrix) printm('Its conjugate transpose:', ct) print('Hermitian? %s.' % ishermitian(matrix, ct)) print('Normal? %s.' % isnormal(matrix, ct)) print('Unitary? %s.' % isunitary(matrix, ct))
#include<stdlib.h> #include<stdio.h> #include<complex.h> typedef struct { int rows, cols; complex **z; } matrix; matrix transpose (matrix a) { int i, j; matrix b; b.rows = a.cols; b.cols = a.rows; b.z = malloc (b.rows * sizeof (complex *)); for (i = 0; i < b.rows; i++) { b.z[i] = malloc (b.cols * sizeof (complex)); for (j = 0; j < b.cols; j++) { b.z[i][j] = conj (a.z[j][i]); } } return b; } int isHermitian (matrix a) { int i, j; matrix b = transpose (a); if (b.rows == a.rows && b.cols == a.cols) { for (i = 0; i < b.rows; i++) { for (j = 0; j < b.cols; j++) { if (b.z[i][j] != a.z[i][j]) return 0; } } } else return 0; return 1; } matrix multiply (matrix a, matrix b) { matrix c; int i, j; if (a.cols == b.rows) { c.rows = a.rows; c.cols = b.cols; c.z = malloc (c.rows * (sizeof (complex *))); for (i = 0; i < c.rows; i++) { c.z[i] = malloc (c.cols * sizeof (complex)); c.z[i][j] = 0 + 0 * I; for (j = 0; j < b.cols; j++) { c.z[i][j] += a.z[i][j] * b.z[j][i]; } } } return c; } int isNormal (matrix a) { int i, j; matrix a_ah, ah_a; if (a.rows != a.cols) return 0; a_ah = multiply (a, transpose (a)); ah_a = multiply (transpose (a), a); for (i = 0; i < a.rows; i++) { for (j = 0; j < a.cols; j++) { if (a_ah.z[i][j] != ah_a.z[i][j]) return 0; } } return 1; } int isUnitary (matrix a) { matrix b; int i, j; if (isNormal (a) == 1) { b = multiply (a, transpose(a)); for (i = 0; i < b.rows; i++) { for (j = 0; j < b.cols; j++) { if ((i == j && b.z[i][j] != 1) || (i != j && b.z[i][j] != 0)) return 0; } } return 1; } return 0; } int main () { complex z = 3 + 4 * I; matrix a, aT; int i, j; printf ("Enter rows and columns :"); scanf ("%d%d", &a.rows, &a.cols); a.z = malloc (a.rows * sizeof (complex *)); printf ("Randomly Generated Complex Matrix A is : "); for (i = 0; i < a.rows; i++) { printf ("\n"); a.z[i] = malloc (a.cols * sizeof (complex)); for (j = 0; j < a.cols; j++) { a.z[i][j] = rand () % 10 + rand () % 10 * I; printf ("\t%f + %fi", creal (a.z[i][j]), cimag (a.z[i][j])); } } aT = transpose (a); printf ("\n\nTranspose of Complex Matrix A is : "); for (i = 0; i < aT.rows; i++) { printf ("\n"); aT.z[i] = malloc (aT.cols * sizeof (complex)); for (j = 0; j < aT.cols; j++) { aT.z[i][j] = rand () % 10 + rand () % 10 * I; printf ("\t%f + %fi", creal (aT.z[i][j]), cimag (aT.z[i][j])); } } printf ("\n\nComplex Matrix A %s hermitian", isHermitian (a) == 1 ? "is" : "is not"); printf ("\n\nComplex Matrix A %s unitary", isUnitary (a) == 1 ? "is" : "is not"); printf ("\n\nComplex Matrix A %s normal", isNormal (a) == 1 ? "is" : "is not"); return 0; }
Keep all operations the same but rewrite the snippet in C.
from math import floor, pow def isPrime(n): for i in range(2, int(n**0.5) + 1): if n % i == 0: return False return True def odd(n): return n and 1 != 0 def jacobsthal(n): return floor((pow(2,n)+odd(n))/3) def jacobsthal_lucas(n): return int(pow(2,n)+pow(-1,n)) def jacobsthal_oblong(n): return jacobsthal(n)*jacobsthal(n+1) if __name__ == '__main__': print("First 30 Jacobsthal numbers:") for j in range(0, 30): print(jacobsthal(j), end=" ") print("\n\nFirst 30 Jacobsthal-Lucas numbers: ") for j in range(0, 30): print(jacobsthal_lucas(j), end = '\t') print("\n\nFirst 20 Jacobsthal oblong numbers: ") for j in range(0, 20): print(jacobsthal_oblong(j), end=" ") print("\n\nFirst 10 Jacobsthal primes: ") for j in range(3, 33): if isPrime(jacobsthal(j)): print(jacobsthal(j))
#include <stdio.h> #include <gmp.h> void jacobsthal(mpz_t r, unsigned long n) { mpz_t s; mpz_init(s); mpz_set_ui(r, 1); mpz_mul_2exp(r, r, n); mpz_set_ui(s, 1); if (n % 2) mpz_neg(s, s); mpz_sub(r, r, s); mpz_div_ui(r, r, 3); } void jacobsthal_lucas(mpz_t r, unsigned long n) { mpz_t a; mpz_init(a); mpz_set_ui(r, 1); mpz_mul_2exp(r, r, n); mpz_set_ui(a, 1); if (n % 2) mpz_neg(a, a); mpz_add(r, r, a); } int main() { int i, count; mpz_t jac[30], j; printf("First 30 Jacobsthal numbers:\n"); for (i = 0; i < 30; ++i) { mpz_init(jac[i]); jacobsthal(jac[i], i); gmp_printf("%9Zd ", jac[i]); if (!((i+1)%5)) printf("\n"); } printf("\nFirst 30 Jacobsthal-Lucas numbers:\n"); mpz_init(j); for (i = 0; i < 30; ++i) { jacobsthal_lucas(j, i); gmp_printf("%9Zd ", j); if (!((i+1)%5)) printf("\n"); } printf("\nFirst 20 Jacobsthal oblong numbers:\n"); for (i = 0; i < 20; ++i) { mpz_mul(j, jac[i], jac[i+1]); gmp_printf("%11Zd ", j); if (!((i+1)%5)) printf("\n"); } printf("\nFirst 20 Jacobsthal primes:\n"); for (i = 0, count = 0; count < 20; ++i) { jacobsthal(j, i); if (mpz_probab_prime_p(j, 15) > 0) { gmp_printf("%Zd\n", j); ++count; } } return 0; }
Rewrite the snippet below in C so it works the same as the original Python code.
from math import floor, pow def isPrime(n): for i in range(2, int(n**0.5) + 1): if n % i == 0: return False return True def odd(n): return n and 1 != 0 def jacobsthal(n): return floor((pow(2,n)+odd(n))/3) def jacobsthal_lucas(n): return int(pow(2,n)+pow(-1,n)) def jacobsthal_oblong(n): return jacobsthal(n)*jacobsthal(n+1) if __name__ == '__main__': print("First 30 Jacobsthal numbers:") for j in range(0, 30): print(jacobsthal(j), end=" ") print("\n\nFirst 30 Jacobsthal-Lucas numbers: ") for j in range(0, 30): print(jacobsthal_lucas(j), end = '\t') print("\n\nFirst 20 Jacobsthal oblong numbers: ") for j in range(0, 20): print(jacobsthal_oblong(j), end=" ") print("\n\nFirst 10 Jacobsthal primes: ") for j in range(3, 33): if isPrime(jacobsthal(j)): print(jacobsthal(j))
#include <stdio.h> #include <gmp.h> void jacobsthal(mpz_t r, unsigned long n) { mpz_t s; mpz_init(s); mpz_set_ui(r, 1); mpz_mul_2exp(r, r, n); mpz_set_ui(s, 1); if (n % 2) mpz_neg(s, s); mpz_sub(r, r, s); mpz_div_ui(r, r, 3); } void jacobsthal_lucas(mpz_t r, unsigned long n) { mpz_t a; mpz_init(a); mpz_set_ui(r, 1); mpz_mul_2exp(r, r, n); mpz_set_ui(a, 1); if (n % 2) mpz_neg(a, a); mpz_add(r, r, a); } int main() { int i, count; mpz_t jac[30], j; printf("First 30 Jacobsthal numbers:\n"); for (i = 0; i < 30; ++i) { mpz_init(jac[i]); jacobsthal(jac[i], i); gmp_printf("%9Zd ", jac[i]); if (!((i+1)%5)) printf("\n"); } printf("\nFirst 30 Jacobsthal-Lucas numbers:\n"); mpz_init(j); for (i = 0; i < 30; ++i) { jacobsthal_lucas(j, i); gmp_printf("%9Zd ", j); if (!((i+1)%5)) printf("\n"); } printf("\nFirst 20 Jacobsthal oblong numbers:\n"); for (i = 0; i < 20; ++i) { mpz_mul(j, jac[i], jac[i+1]); gmp_printf("%11Zd ", j); if (!((i+1)%5)) printf("\n"); } printf("\nFirst 20 Jacobsthal primes:\n"); for (i = 0, count = 0; count < 20; ++i) { jacobsthal(j, i); if (mpz_probab_prime_p(j, 15) > 0) { gmp_printf("%Zd\n", j); ++count; } } return 0; }
Can you help me rewrite this code in C instead of Python, keeping it the same logically?
from itertools import zip_longest def beadsort(l): return list(map(sum, zip_longest(*[[1] * e for e in l], fillvalue=0))) print(beadsort([5,3,1,7,4,1,1]))
#include <stdio.h> #include <stdlib.h> void bead_sort(int *a, int len) { int i, j, max, sum; unsigned char *beads; # define BEAD(i, j) beads[i * max + j] for (i = 1, max = a[0]; i < len; i++) if (a[i] > max) max = a[i]; beads = calloc(1, max * len); for (i = 0; i < len; i++) for (j = 0; j < a[i]; j++) BEAD(i, j) = 1; for (j = 0; j < max; j++) { for (sum = i = 0; i < len; i++) { sum += BEAD(i, j); BEAD(i, j) = 0; } for (i = len - sum; i < len; i++) BEAD(i, j) = 1; } for (i = 0; i < len; i++) { for (j = 0; j < max && BEAD(i, j); j++); a[i] = j; } free(beads); } int main() { int i, x[] = {5, 3, 1, 7, 4, 1, 1, 20}; int len = sizeof(x)/sizeof(x[0]); bead_sort(x, len); for (i = 0; i < len; i++) printf("%d\n", x[i]); return 0; }
Write a version of this Python function in C with identical behavior.
def _init(): "digit sections for forming numbers" digi_bits = .strip() lines = [[d.replace('.', ' ') for d in ln.strip().split()] for ln in digi_bits.strip().split('\n') if ' formats = '<2 >2 <2 >2'.split() digits = [[f"{dig:{f}}" for dig in line] for f, line in zip(formats, lines)] return digits _digits = _init() def _to_digits(n): assert 0 <= n < 10_000 and int(n) == n return [int(digit) for digit in f"{int(n):04}"][::-1] def num_to_lines(n): global _digits d = _to_digits(n) lines = [ ''.join((_digits[1][d[1]], '┃', _digits[0][d[0]])), ''.join((_digits[0][ 0], '┃', _digits[0][ 0])), ''.join((_digits[3][d[3]], '┃', _digits[2][d[2]])), ] return lines def cjoin(c1, c2, spaces=' '): return [spaces.join(by_row) for by_row in zip(c1, c2)] if __name__ == '__main__': for pow10 in range(4): step = 10 ** pow10 print(f'\nArabic {step}-to-{9*step} by {step} in Cistercian:\n') lines = num_to_lines(step) for n in range(step*2, step*10, step): lines = cjoin(lines, num_to_lines(n)) print('\n'.join(lines)) numbers = [0, 5555, 6789, 6666] print(f'\nArabic {str(numbers)[1:-1]} in Cistercian:\n') lines = num_to_lines(numbers[0]) for n in numbers[1:]: lines = cjoin(lines, num_to_lines(n)) print('\n'.join(lines))
#include <stdio.h> #define GRID_SIZE 15 char canvas[GRID_SIZE][GRID_SIZE]; void initN() { int i, j; for (i = 0; i < GRID_SIZE; i++) { for (j = 0; j < GRID_SIZE; j++) { canvas[i][j] = ' '; } canvas[i][5] = 'x'; } } void horizontal(size_t c1, size_t c2, size_t r) { size_t c; for (c = c1; c <= c2; c++) { canvas[r][c] = 'x'; } } void vertical(size_t r1, size_t r2, size_t c) { size_t r; for (r = r1; r <= r2; r++) { canvas[r][c] = 'x'; } } void diagd(size_t c1, size_t c2, size_t r) { size_t c; for (c = c1; c <= c2; c++) { canvas[r + c - c1][c] = 'x'; } } void diagu(size_t c1, size_t c2, size_t r) { size_t c; for (c = c1; c <= c2; c++) { canvas[r - c + c1][c] = 'x'; } } void drawOnes(int v) { switch (v) { case 1: horizontal(6, 10, 0); break; case 2: horizontal(6, 10, 4); break; case 3: diagd(6, 10, 0); break; case 4: diagu(6, 10, 4); break; case 5: drawOnes(1); drawOnes(4); break; case 6: vertical(0, 4, 10); break; case 7: drawOnes(1); drawOnes(6); break; case 8: drawOnes(2); drawOnes(6); break; case 9: drawOnes(1); drawOnes(8); break; default: break; } } void drawTens(int v) { switch (v) { case 1: horizontal(0, 4, 0); break; case 2: horizontal(0, 4, 4); break; case 3: diagu(0, 4, 4); break; case 4: diagd(0, 4, 0); break; case 5: drawTens(1); drawTens(4); break; case 6: vertical(0, 4, 0); break; case 7: drawTens(1); drawTens(6); break; case 8: drawTens(2); drawTens(6); break; case 9: drawTens(1); drawTens(8); break; default: break; } } void drawHundreds(int hundreds) { switch (hundreds) { case 1: horizontal(6, 10, 14); break; case 2: horizontal(6, 10, 10); break; case 3: diagu(6, 10, 14); break; case 4: diagd(6, 10, 10); break; case 5: drawHundreds(1); drawHundreds(4); break; case 6: vertical(10, 14, 10); break; case 7: drawHundreds(1); drawHundreds(6); break; case 8: drawHundreds(2); drawHundreds(6); break; case 9: drawHundreds(1); drawHundreds(8); break; default: break; } } void drawThousands(int thousands) { switch (thousands) { case 1: horizontal(0, 4, 14); break; case 2: horizontal(0, 4, 10); break; case 3: diagd(0, 4, 10); break; case 4: diagu(0, 4, 14); break; case 5: drawThousands(1); drawThousands(4); break; case 6: vertical(10, 14, 0); break; case 7: drawThousands(1); drawThousands(6); break; case 8: drawThousands(2); drawThousands(6); break; case 9: drawThousands(1); drawThousands(8); break; default: break; } } void draw(int v) { int thousands = v / 1000; v %= 1000; int hundreds = v / 100; v %= 100; int tens = v / 10; int ones = v % 10; if (thousands > 0) { drawThousands(thousands); } if (hundreds > 0) { drawHundreds(hundreds); } if (tens > 0) { drawTens(tens); } if (ones > 0) { drawOnes(ones); } } void write(FILE *out) { int i; for (i = 0; i < GRID_SIZE; i++) { fprintf(out, "%-.*s", GRID_SIZE, canvas[i]); putc('\n', out); } } void test(int n) { printf("%d:\n", n); initN(); draw(n); write(stdout); printf("\n\n"); } int main() { test(0); test(1); test(20); test(300); test(4000); test(5555); test(6789); test(9999); return 0; }
Rewrite the snippet below in C so it works the same as the original Python code.
def _init(): "digit sections for forming numbers" digi_bits = .strip() lines = [[d.replace('.', ' ') for d in ln.strip().split()] for ln in digi_bits.strip().split('\n') if ' formats = '<2 >2 <2 >2'.split() digits = [[f"{dig:{f}}" for dig in line] for f, line in zip(formats, lines)] return digits _digits = _init() def _to_digits(n): assert 0 <= n < 10_000 and int(n) == n return [int(digit) for digit in f"{int(n):04}"][::-1] def num_to_lines(n): global _digits d = _to_digits(n) lines = [ ''.join((_digits[1][d[1]], '┃', _digits[0][d[0]])), ''.join((_digits[0][ 0], '┃', _digits[0][ 0])), ''.join((_digits[3][d[3]], '┃', _digits[2][d[2]])), ] return lines def cjoin(c1, c2, spaces=' '): return [spaces.join(by_row) for by_row in zip(c1, c2)] if __name__ == '__main__': for pow10 in range(4): step = 10 ** pow10 print(f'\nArabic {step}-to-{9*step} by {step} in Cistercian:\n') lines = num_to_lines(step) for n in range(step*2, step*10, step): lines = cjoin(lines, num_to_lines(n)) print('\n'.join(lines)) numbers = [0, 5555, 6789, 6666] print(f'\nArabic {str(numbers)[1:-1]} in Cistercian:\n') lines = num_to_lines(numbers[0]) for n in numbers[1:]: lines = cjoin(lines, num_to_lines(n)) print('\n'.join(lines))
#include <stdio.h> #define GRID_SIZE 15 char canvas[GRID_SIZE][GRID_SIZE]; void initN() { int i, j; for (i = 0; i < GRID_SIZE; i++) { for (j = 0; j < GRID_SIZE; j++) { canvas[i][j] = ' '; } canvas[i][5] = 'x'; } } void horizontal(size_t c1, size_t c2, size_t r) { size_t c; for (c = c1; c <= c2; c++) { canvas[r][c] = 'x'; } } void vertical(size_t r1, size_t r2, size_t c) { size_t r; for (r = r1; r <= r2; r++) { canvas[r][c] = 'x'; } } void diagd(size_t c1, size_t c2, size_t r) { size_t c; for (c = c1; c <= c2; c++) { canvas[r + c - c1][c] = 'x'; } } void diagu(size_t c1, size_t c2, size_t r) { size_t c; for (c = c1; c <= c2; c++) { canvas[r - c + c1][c] = 'x'; } } void drawOnes(int v) { switch (v) { case 1: horizontal(6, 10, 0); break; case 2: horizontal(6, 10, 4); break; case 3: diagd(6, 10, 0); break; case 4: diagu(6, 10, 4); break; case 5: drawOnes(1); drawOnes(4); break; case 6: vertical(0, 4, 10); break; case 7: drawOnes(1); drawOnes(6); break; case 8: drawOnes(2); drawOnes(6); break; case 9: drawOnes(1); drawOnes(8); break; default: break; } } void drawTens(int v) { switch (v) { case 1: horizontal(0, 4, 0); break; case 2: horizontal(0, 4, 4); break; case 3: diagu(0, 4, 4); break; case 4: diagd(0, 4, 0); break; case 5: drawTens(1); drawTens(4); break; case 6: vertical(0, 4, 0); break; case 7: drawTens(1); drawTens(6); break; case 8: drawTens(2); drawTens(6); break; case 9: drawTens(1); drawTens(8); break; default: break; } } void drawHundreds(int hundreds) { switch (hundreds) { case 1: horizontal(6, 10, 14); break; case 2: horizontal(6, 10, 10); break; case 3: diagu(6, 10, 14); break; case 4: diagd(6, 10, 10); break; case 5: drawHundreds(1); drawHundreds(4); break; case 6: vertical(10, 14, 10); break; case 7: drawHundreds(1); drawHundreds(6); break; case 8: drawHundreds(2); drawHundreds(6); break; case 9: drawHundreds(1); drawHundreds(8); break; default: break; } } void drawThousands(int thousands) { switch (thousands) { case 1: horizontal(0, 4, 14); break; case 2: horizontal(0, 4, 10); break; case 3: diagd(0, 4, 10); break; case 4: diagu(0, 4, 14); break; case 5: drawThousands(1); drawThousands(4); break; case 6: vertical(10, 14, 0); break; case 7: drawThousands(1); drawThousands(6); break; case 8: drawThousands(2); drawThousands(6); break; case 9: drawThousands(1); drawThousands(8); break; default: break; } } void draw(int v) { int thousands = v / 1000; v %= 1000; int hundreds = v / 100; v %= 100; int tens = v / 10; int ones = v % 10; if (thousands > 0) { drawThousands(thousands); } if (hundreds > 0) { drawHundreds(hundreds); } if (tens > 0) { drawTens(tens); } if (ones > 0) { drawOnes(ones); } } void write(FILE *out) { int i; for (i = 0; i < GRID_SIZE; i++) { fprintf(out, "%-.*s", GRID_SIZE, canvas[i]); putc('\n', out); } } void test(int n) { printf("%d:\n", n); initN(); draw(n); write(stdout); printf("\n\n"); } int main() { test(0); test(1); test(20); test(300); test(4000); test(5555); test(6789); test(9999); return 0; }
Rewrite this program in C while keeping its functionality equivalent to the Python version.
>>> y = str( 5**4**3**2 ) >>> print ("5**4**3**2 = %s...%s and has %i digits" % (y[:20], y[-20:], len(y))) 5**4**3**2 = 62060698786608744707...92256259918212890625 and has 183231 digits
#include <gmp.h> #include <stdio.h> #include <string.h> int main() { mpz_t a; mpz_init_set_ui(a, 5); mpz_pow_ui(a, a, 1 << 18); int len = mpz_sizeinbase(a, 10); printf("GMP says size is: %d\n", len); char *s = mpz_get_str(0, 10, a); printf("size really is %d\n", len = strlen(s)); printf("Digits: %.20s...%s\n", s, s + len - 20); return 0; }
Generate an equivalent C version of this Python code.
import math shades = ('.',':','!','*','o','e','&',' def normalize(v): len = math.sqrt(v[0]**2 + v[1]**2 + v[2]**2) return (v[0]/len, v[1]/len, v[2]/len) def dot(x,y): d = x[0]*y[0] + x[1]*y[1] + x[2]*y[2] return -d if d < 0 else 0 def draw_sphere(r, k, ambient, light): for i in range(int(math.floor(-r)),int(math.ceil(r)+1)): x = i + 0.5 line = '' for j in range(int(math.floor(-2*r)),int(math.ceil(2*r)+1)): y = j/2 + 0.5 if x*x + y*y <= r*r: vec = normalize((x,y,math.sqrt(r*r - x*x - y*y))) b = dot(light,vec)**k + ambient intensity = int((1-b)*(len(shades)-1)) line += shades[intensity] if 0 <= intensity < len(shades) else shades[0] else: line += ' ' print(line) light = normalize((30,30,-50)) draw_sphere(20,4,0.1, light) draw_sphere(10,2,0.4, light)
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <ctype.h> #include <math.h> const char *shades = ".:!*oe&#%@"; double light[3] = { 30, 30, -50 }; void normalize(double * v) { double len = sqrt(v[0]*v[0] + v[1]*v[1] + v[2]*v[2]); v[0] /= len; v[1] /= len; v[2] /= len; } double dot(double *x, double *y) { double d = x[0]*y[0] + x[1]*y[1] + x[2]*y[2]; return d < 0 ? -d : 0; } void draw_sphere(double R, double k, double ambient) { int i, j, intensity; double b; double vec[3], x, y; for (i = floor(-R); i <= ceil(R); i++) { x = i + .5; for (j = floor(-2 * R); j <= ceil(2 * R); j++) { y = j / 2. + .5; if (x * x + y * y <= R * R) { vec[0] = x; vec[1] = y; vec[2] = sqrt(R * R - x * x - y * y); normalize(vec); b = pow(dot(light, vec), k) + ambient; intensity = (1 - b) * (sizeof(shades) - 1); if (intensity < 0) intensity = 0; if (intensity >= sizeof(shades) - 1) intensity = sizeof(shades) - 2; putchar(shades[intensity]); } else putchar(' '); } putchar('\n'); } } int main() { normalize(light); draw_sphere(20, 4, .1); draw_sphere(10, 2, .4); return 0; }
Produce a functionally identical C code for the snippet given in Python.
import math shades = ('.',':','!','*','o','e','&',' def normalize(v): len = math.sqrt(v[0]**2 + v[1]**2 + v[2]**2) return (v[0]/len, v[1]/len, v[2]/len) def dot(x,y): d = x[0]*y[0] + x[1]*y[1] + x[2]*y[2] return -d if d < 0 else 0 def draw_sphere(r, k, ambient, light): for i in range(int(math.floor(-r)),int(math.ceil(r)+1)): x = i + 0.5 line = '' for j in range(int(math.floor(-2*r)),int(math.ceil(2*r)+1)): y = j/2 + 0.5 if x*x + y*y <= r*r: vec = normalize((x,y,math.sqrt(r*r - x*x - y*y))) b = dot(light,vec)**k + ambient intensity = int((1-b)*(len(shades)-1)) line += shades[intensity] if 0 <= intensity < len(shades) else shades[0] else: line += ' ' print(line) light = normalize((30,30,-50)) draw_sphere(20,4,0.1, light) draw_sphere(10,2,0.4, light)
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <ctype.h> #include <math.h> const char *shades = ".:!*oe&#%@"; double light[3] = { 30, 30, -50 }; void normalize(double * v) { double len = sqrt(v[0]*v[0] + v[1]*v[1] + v[2]*v[2]); v[0] /= len; v[1] /= len; v[2] /= len; } double dot(double *x, double *y) { double d = x[0]*y[0] + x[1]*y[1] + x[2]*y[2]; return d < 0 ? -d : 0; } void draw_sphere(double R, double k, double ambient) { int i, j, intensity; double b; double vec[3], x, y; for (i = floor(-R); i <= ceil(R); i++) { x = i + .5; for (j = floor(-2 * R); j <= ceil(2 * R); j++) { y = j / 2. + .5; if (x * x + y * y <= R * R) { vec[0] = x; vec[1] = y; vec[2] = sqrt(R * R - x * x - y * y); normalize(vec); b = pow(dot(light, vec), k) + ambient; intensity = (1 - b) * (sizeof(shades) - 1); if (intensity < 0) intensity = 0; if (intensity >= sizeof(shades) - 1) intensity = sizeof(shades) - 2; putchar(shades[intensity]); } else putchar(' '); } putchar('\n'); } } int main() { normalize(light); draw_sphere(20, 4, .1); draw_sphere(10, 2, .4); return 0; }
Produce a functionally identical C code for the snippet given in Python.
from pprint import pprint as pp from glob import glob try: reduce except: from functools import reduce try: raw_input except: raw_input = input def parsetexts(fileglob='InvertedIndex/T*.txt'): texts, words = {}, set() for txtfile in glob(fileglob): with open(txtfile, 'r') as f: txt = f.read().split() words |= set(txt) texts[txtfile.split('\\')[-1]] = txt return texts, words def termsearch(terms): return reduce(set.intersection, (invindex[term] for term in terms), set(texts.keys())) texts, words = parsetexts() print('\nTexts') pp(texts) print('\nWords') pp(sorted(words)) invindex = {word:set(txt for txt, wrds in texts.items() if word in wrds) for word in words} print('\nInverted Index') pp({k:sorted(v) for k,v in invindex.items()}) terms = ["what", "is", "it"] print('\nTerm Search for: ' + repr(terms)) pp(sorted(termsearch(terms)))
#include <stdio.h> #include <stdlib.h> char chr_legal[] = "abcdefghijklmnopqrstuvwxyz0123456789_-./"; int chr_idx[256] = {0}; char idx_chr[256] = {0}; #define FNAME 0 typedef struct trie_t *trie, trie_t; struct trie_t { trie next[sizeof(chr_legal)]; int eow; }; trie trie_new() { return calloc(sizeof(trie_t), 1); } #define find_word(r, w) trie_trav(r, w, 1) trie trie_trav(trie root, const char * str, int no_create) { int c; while (root) { if ((c = str[0]) == '\0') { if (!root->eow && no_create) return 0; break; } if (! (c = chr_idx[c]) ) { str++; continue; } if (!root->next[c]) { if (no_create) return 0; root->next[c] = trie_new(); } root = root->next[c]; str++; } return root; } int trie_all(trie root, char path[], int depth, int (*callback)(char *)) { int i; if (root->eow && !callback(path)) return 0; for (i = 1; i < sizeof(chr_legal); i++) { if (!root->next[i]) continue; path[depth] = idx_chr[i]; path[depth + 1] = '\0'; if (!trie_all(root->next[i], path, depth + 1, callback)) return 0; } return 1; } void add_index(trie root, const char *word, const char *fname) { trie x = trie_trav(root, word, 0); x->eow = 1; if (!x->next[FNAME]) x->next[FNAME] = trie_new(); x = trie_trav(x->next[FNAME], fname, 0); x->eow = 1; } int print_path(char *path) { printf(" %s", path); return 1; } const char *files[] = { "f1.txt", "source/f2.txt", "other_file" }; const char *text[][5] ={{ "it", "is", "what", "it", "is" }, { "what", "is", "it", 0 }, { "it", "is", "a", "banana", 0 }}; trie init_tables() { int i, j; trie root = trie_new(); for (i = 0; i < sizeof(chr_legal); i++) { chr_idx[(int)chr_legal[i]] = i + 1; idx_chr[i + 1] = chr_legal[i]; } #define USE_ADVANCED_FILE_HANDLING 0 #if USE_ADVANCED_FILE_HANDLING void read_file(const char * fname) { char cmd[1024]; char word[1024]; sprintf(cmd, "perl -p -e 'while(/(\\w+)/g) {print lc($1),\"\\n\"}' %s", fname); FILE *in = popen(cmd, "r"); while (!feof(in)) { fscanf(in, "%1000s", word); add_index(root, word, fname); } pclose(in); }; read_file("f1.txt"); read_file("source/f2.txt"); read_file("other_file"); #else for (i = 0; i < 3; i++) { for (j = 0; j < 5; j++) { if (!text[i][j]) break; add_index(root, text[i][j], files[i]); } } #endif return root; } void search_index(trie root, const char *word) { char path[1024]; printf("Search for \"%s\": ", word); trie found = find_word(root, word); if (!found) printf("not found\n"); else { trie_all(found->next[FNAME], path, 0, print_path); printf("\n"); } } int main() { trie root = init_tables(); search_index(root, "what"); search_index(root, "is"); search_index(root, "banana"); search_index(root, "boo"); return 0; }
Convert the following code from Python to C, ensuring the logic remains intact.
>>> import fractions >>> def lcm(a,b): return abs(a * b) / fractions.gcd(a,b) if a and b else 0 >>> lcm(12, 18) 36 >>> lcm(-6, 14) 42 >>> assert lcm(0, 2) == lcm(2, 0) == 0 >>>
#include <stdio.h> int gcd(int m, int n) { int tmp; while(m) { tmp = m; m = n % m; n = tmp; } return n; } int lcm(int m, int n) { return m / gcd(m, n) * n; } int main() { printf("lcm(35, 21) = %d\n", lcm(21,35)); return 0; }
Change the programming language of this snippet from Python to C without modifying what it does.
>>> import fractions >>> def lcm(a,b): return abs(a * b) / fractions.gcd(a,b) if a and b else 0 >>> lcm(12, 18) 36 >>> lcm(-6, 14) 42 >>> assert lcm(0, 2) == lcm(2, 0) == 0 >>>
#include <stdio.h> int gcd(int m, int n) { int tmp; while(m) { tmp = m; m = n % m; n = tmp; } return n; } int lcm(int m, int n) { return m / gcd(m, n) * n; } int main() { printf("lcm(35, 21) = %d\n", lcm(21,35)); return 0; }
Rewrite this program in C while keeping its functionality equivalent to the Python version.
>>> import fractions >>> def lcm(a,b): return abs(a * b) / fractions.gcd(a,b) if a and b else 0 >>> lcm(12, 18) 36 >>> lcm(-6, 14) 42 >>> assert lcm(0, 2) == lcm(2, 0) == 0 >>>
#include <stdio.h> int gcd(int m, int n) { int tmp; while(m) { tmp = m; m = n % m; n = tmp; } return n; } int lcm(int m, int n) { return m / gcd(m, n) * n; } int main() { printf("lcm(35, 21) = %d\n", lcm(21,35)); return 0; }
Maintain the same structure and functionality when rewriting this code in C.
def factors(x): factors = [] i = 2 s = int(x ** 0.5) while i < s: if x % i == 0: factors.append(i) x = int(x / i) s = int(x ** 0.5) i += 1 factors.append(x) return factors print("First 10 Fermat numbers:") for i in range(10): fermat = 2 ** 2 ** i + 1 print("F{} = {}".format(chr(i + 0x2080) , fermat)) print("\nFactors of first few Fermat numbers:") for i in range(10): fermat = 2 ** 2 ** i + 1 fac = factors(fermat) if len(fac) == 1: print("F{} -> IS PRIME".format(chr(i + 0x2080))) else: print("F{} -> FACTORS: {}".format(chr(i + 0x2080), fac))
#include <stdlib.h> #include <stdio.h> #include <gmp.h> void mpz_factors(mpz_t n) { int factors = 0; mpz_t s, m, p; mpz_init(s), mpz_init(m), mpz_init(p); mpz_set_ui(m, 3); mpz_set(p, n); mpz_sqrt(s, p); while (mpz_cmp(m, s) < 0) { if (mpz_divisible_p(p, m)) { gmp_printf("%Zd ", m); mpz_fdiv_q(p, p, m); mpz_sqrt(s, p); factors ++; } mpz_add_ui(m, m, 2); } if (factors == 0) printf("PRIME\n"); else gmp_printf("%Zd\n", p); } int main(int argc, char const *argv[]) { mpz_t fermat; mpz_init_set_ui(fermat, 3); printf("F(0) = 3 -> PRIME\n"); for (unsigned i = 1; i < 10; i ++) { mpz_sub_ui(fermat, fermat, 1); mpz_mul(fermat, fermat, fermat); mpz_add_ui(fermat, fermat, 1); gmp_printf("F(%d) = %Zd -> ", i, fermat); mpz_factors(fermat); } return 0; }
Change the following Python code into C without altering its purpose.
from random import randrange while True: a = randrange(20) print(a) if a == 10: break b = randrange(20) print(b)
int main(){ time_t t; int a, b; srand((unsigned)time(&t)); for(;;){ a = rand() % 20; printf("%d\n", a); if(a == 10) break; b = rand() % 20; printf("%d\n", b); } return 0; }
Convert this Python snippet to C and keep its semantics consistent.
lp = open("/dev/lp0") lp.write("Hello World!\n") lp.close()
#include <stdio.h> int main() { FILE *lp; lp = fopen("/dev/lp0","w"); fprintf(lp,"Hello world!\n"); fclose(lp); return 0; }
Rewrite the snippet below in C so it works the same as the original Python code.
lp = open("/dev/lp0") lp.write("Hello World!\n") lp.close()
#include <stdio.h> int main() { FILE *lp; lp = fopen("/dev/lp0","w"); fprintf(lp,"Hello world!\n"); fclose(lp); return 0; }
Produce a language-to-language conversion: from Python to C, same semantics.
def water_collected(tower): N = len(tower) highest_left = [0] + [max(tower[:n]) for n in range(1,N)] highest_right = [max(tower[n:N]) for n in range(1,N)] + [0] water_level = [max(min(highest_left[n], highest_right[n]) - tower[n], 0) for n in range(N)] print("highest_left: ", highest_left) print("highest_right: ", highest_right) print("water_level: ", water_level) print("tower_level: ", tower) print("total_water: ", sum(water_level)) print("") return sum(water_level) towers = [[1, 5, 3, 7, 2], [5, 3, 7, 2, 6, 4, 5, 9, 1, 2], [2, 6, 3, 5, 2, 8, 1, 4, 2, 2, 5, 3, 5, 7, 4, 1], [5, 5, 5, 5], [5, 6, 7, 8], [8, 7, 7, 6], [6, 7, 10, 7, 6]] [water_collected(tower) for tower in towers]
#include<stdlib.h> #include<stdio.h> int getWater(int* arr,int start,int end,int cutoff){ int i, sum = 0; for(i=start;i<=end;i++) sum += ((arr[cutoff] > arr[i])?(arr[cutoff] - arr[i]):0); return sum; } int netWater(int* arr,int size){ int i, j, ref1, ref2, marker, markerSet = 0,sum = 0; if(size<3) return 0; for(i=0;i<size-1;i++){ start:if(i!=size-2 && arr[i]>arr[i+1]){ ref1 = i; for(j=ref1+1;j<size;j++){ if(arr[j]>=arr[ref1]){ ref2 = j; sum += getWater(arr,ref1+1,ref2-1,ref1); i = ref2; goto start; } else if(j!=size-1 && arr[j] < arr[j+1] && (markerSet==0||(arr[j+1]>=arr[marker]))){ marker = j+1; markerSet = 1; } } if(markerSet==1){ sum += getWater(arr,ref1+1,marker-1,marker); i = marker; markerSet = 0; goto start; } } } return sum; } int main(int argC,char* argV[]) { int *arr,i; if(argC==1) printf("Usage : %s <followed by space separated series of integers>"); else{ arr = (int*)malloc((argC-1)*sizeof(int)); for(i=1;i<argC;i++) arr[i-1] = atoi(argV[i]); printf("Water collected : %d",netWater(arr,argC-1)); } return 0; }
Port the provided Python code into C while preserving the original functionality.
from sympy import isprime def descending(xs=range(10)): for x in xs: yield x yield from descending(x*10 + d for d in range(x%10)) for i, p in enumerate(sorted(filter(isprime, descending()))): print(f'{p:9d}', end=' ' if (1 + i)%8 else '\n') print()
#include <stdio.h> int ispr(unsigned int n) { if ((n & 1) == 0 || n < 2) return n == 2; for (unsigned int j = 3; j * j <= n; j += 2) if (n % j == 0) return 0; return 1; } int main() { unsigned int c = 0, nc, pc = 9, i, a, b, l, ps[128], nxt[128]; for (a = 0, b = 1; a < pc; a = b++) ps[a] = b; while (1) { nc = 0; for (i = 0; i < pc; i++) { if (ispr(a = ps[i])) printf("%8d%s", a, ++c % 5 == 0 ? "\n" : " "); for (b = a * 10, l = a % 10 + b++; b < l; b++) nxt[nc++] = b; } if (nc > 1) for(i = 0, pc = nc; i < pc; i++) ps[i] = nxt[i]; else break; } printf("\n%d descending primes found", c); }
Write a version of this Python function in C with identical behavior.
import math def SquareFree ( _number ) : max = (int) (math.sqrt ( _number )) for root in range ( 2, max+1 ): if 0 == _number % ( root * root ): return False return True def ListSquareFrees( _start, _end ): count = 0 for i in range ( _start, _end+1 ): if True == SquareFree( i ): print ( "{}\t".format(i), end="" ) count += 1 print ( "\n\nTotal count of square-free numbers between {} and {}: {}".format(_start, _end, count)) ListSquareFrees( 1, 100 ) ListSquareFrees( 1000000000000, 1000000000145 )
#include <stdio.h> #include <stdlib.h> #include <math.h> #define TRUE 1 #define FALSE 0 #define TRILLION 1000000000000 typedef unsigned char bool; typedef unsigned long long uint64; void sieve(uint64 limit, uint64 *primes, uint64 *length) { uint64 i, count, p, p2; bool *c = calloc(limit + 1, sizeof(bool)); primes[0] = 2; count = 1; p = 3; for (;;) { p2 = p * p; if (p2 > limit) break; for (i = p2; i <= limit; i += 2 * p) c[i] = TRUE; for (;;) { p += 2; if (!c[p]) break; } } for (i = 3; i <= limit; i += 2) { if (!c[i]) primes[count++] = i; } *length = count; free(c); } void squareFree(uint64 from, uint64 to, uint64 *results, uint64 *len) { uint64 i, j, p, p2, np, count = 0, limit = (uint64)sqrt((double)to); uint64 *primes = malloc((limit + 1) * sizeof(uint64)); bool add; sieve(limit, primes, &np); for (i = from; i <= to; ++i) { add = TRUE; for (j = 0; j < np; ++j) { p = primes[j]; p2 = p * p; if (p2 > i) break; if (i % p2 == 0) { add = FALSE; break; } } if (add) results[count++] = i; } *len = count; free(primes); } int main() { uint64 i, *sf, len; sf = malloc(1000000 * sizeof(uint64)); printf("Square-free integers from 1 to 145:\n"); squareFree(1, 145, sf, &len); for (i = 0; i < len; ++i) { if (i > 0 && i % 20 == 0) { printf("\n"); } printf("%4lld", sf[i]); } printf("\n\nSquare-free integers from %ld to %ld:\n", TRILLION, TRILLION + 145); squareFree(TRILLION, TRILLION + 145, sf, &len); for (i = 0; i < len; ++i) { if (i > 0 && i % 5 == 0) { printf("\n"); } printf("%14lld", sf[i]); } printf("\n\nNumber of square-free integers:\n"); int a[5] = {100, 1000, 10000, 100000, 1000000}; for (i = 0; i < 5; ++i) { squareFree(1, a[i], sf, &len); printf(" from %d to %d = %lld\n", 1, a[i], len); } free(sf); return 0; }
Port the provided Python code into C while preserving the original functionality.
from __future__ import division def jaro(s, t): s_len = len(s) t_len = len(t) if s_len == 0 and t_len == 0: return 1 match_distance = (max(s_len, t_len) // 2) - 1 s_matches = [False] * s_len t_matches = [False] * t_len matches = 0 transpositions = 0 for i in range(s_len): start = max(0, i - match_distance) end = min(i + match_distance + 1, t_len) for j in range(start, end): if t_matches[j]: continue if s[i] != t[j]: continue s_matches[i] = True t_matches[j] = True matches += 1 break if matches == 0: return 0 k = 0 for i in range(s_len): if not s_matches[i]: continue while not t_matches[k]: k += 1 if s[i] != t[k]: transpositions += 1 k += 1 return ((matches / s_len) + (matches / t_len) + ((matches - transpositions / 2) / matches)) / 3 def main(): for s, t in [('MARTHA', 'MARHTA'), ('DIXON', 'DICKSONX'), ('JELLYFISH', 'SMELLYFISH')]: print("jaro(%r, %r) = %.10f" % (s, t, jaro(s, t))) if __name__ == '__main__': main()
#include <stdlib.h> #include <string.h> #include <ctype.h> #include <stdio.h> #define TRUE 1 #define FALSE 0 #define max(a, b) ((a) > (b) ? (a) : (b)) #define min(a, b) ((a) < (b) ? (a) : (b)) double jaro(const char *str1, const char *str2) { int str1_len = strlen(str1); int str2_len = strlen(str2); if (str1_len == 0) return str2_len == 0 ? 1.0 : 0.0; int match_distance = (int) max(str1_len, str2_len)/2 - 1; int *str1_matches = calloc(str1_len, sizeof(int)); int *str2_matches = calloc(str2_len, sizeof(int)); double matches = 0.0; double transpositions = 0.0; for (int i = 0; i < str1_len; i++) { int start = max(0, i - match_distance); int end = min(i + match_distance + 1, str2_len); for (int k = start; k < end; k++) { if (str2_matches[k]) continue; if (str1[i] != str2[k]) continue; str1_matches[i] = TRUE; str2_matches[k] = TRUE; matches++; break; } } if (matches == 0) { free(str1_matches); free(str2_matches); return 0.0; } int k = 0; for (int i = 0; i < str1_len; i++) { if (!str1_matches[i]) continue; while (!str2_matches[k]) k++; if (str1[i] != str2[k]) transpositions++; k++; } transpositions /= 2.0; free(str1_matches); free(str2_matches); return ((matches / str1_len) + (matches / str2_len) + ((matches - transpositions) / matches)) / 3.0; } int main() { printf("%f\n", jaro("MARTHA", "MARHTA")); printf("%f\n", jaro("DIXON", "DICKSONX")); printf("%f\n", jaro("JELLYFISH", "SMELLYFISH")); }
Change the programming language of this snippet from Python to C without modifying what it does.
from collections import Counter def decompose_sum(s): return [(a,s-a) for a in range(2,int(s/2+1))] all_pairs = set((a,b) for a in range(2,100) for b in range(a+1,100) if a+b<100) product_counts = Counter(c*d for c,d in all_pairs) unique_products = set((a,b) for a,b in all_pairs if product_counts[a*b]==1) s_pairs = [(a,b) for a,b in all_pairs if all((x,y) not in unique_products for (x,y) in decompose_sum(a+b))] product_counts = Counter(c*d for c,d in s_pairs) p_pairs = [(a,b) for a,b in s_pairs if product_counts[a*b]==1] sum_counts = Counter(c+d for c,d in p_pairs) final_pairs = [(a,b) for a,b in p_pairs if sum_counts[a+b]==1] print(final_pairs)
#include <stdbool.h> #include <stdio.h> #include <stdlib.h> typedef struct node_t { int x, y; struct node_t *prev, *next; } node; node *new_node(int x, int y) { node *n = malloc(sizeof(node)); n->x = x; n->y = y; n->next = NULL; n->prev = NULL; return n; } void free_node(node **n) { if (n == NULL) { return; } (*n)->prev = NULL; (*n)->next = NULL; free(*n); *n = NULL; } typedef struct list_t { node *head; node *tail; } list; list make_list() { list lst = { NULL, NULL }; return lst; } void append_node(list *const lst, int x, int y) { if (lst == NULL) { return; } node *n = new_node(x, y); if (lst->head == NULL) { lst->head = n; lst->tail = n; } else { n->prev = lst->tail; lst->tail->next = n; lst->tail = n; } } void remove_node(list *const lst, const node *const n) { if (lst == NULL || n == NULL) { return; } if (n->prev != NULL) { n->prev->next = n->next; if (n->next != NULL) { n->next->prev = n->prev; } else { lst->tail = n->prev; } } else { if (n->next != NULL) { n->next->prev = NULL; lst->head = n->next; } } free_node(&n); } void free_list(list *const lst) { node *ptr; if (lst == NULL) { return; } ptr = lst->head; while (ptr != NULL) { node *nxt = ptr->next; free_node(&ptr); ptr = nxt; } lst->head = NULL; lst->tail = NULL; } void print_list(const list *lst) { node *it; if (lst == NULL) { return; } for (it = lst->head; it != NULL; it = it->next) { int sum = it->x + it->y; int prod = it->x * it->y; printf("[%d, %d] S=%d P=%d\n", it->x, it->y, sum, prod); } } void print_count(const list *const lst) { node *it; int c = 0; if (lst == NULL) { return; } for (it = lst->head; it != NULL; it = it->next) { c++; } if (c == 0) { printf("no candidates\n"); } else if (c == 1) { printf("one candidate\n"); } else { printf("%d candidates\n", c); } } void setup(list *const lst) { int x, y; if (lst == NULL) { return; } for (x = 2; x <= 98; x++) { for (y = x + 1; y <= 98; y++) { if (x + y <= 100) { append_node(lst, x, y); } } } } void remove_by_sum(list *const lst, const int sum) { node *it; if (lst == NULL) { return; } it = lst->head; while (it != NULL) { int s = it->x + it->y; if (s == sum) { remove_node(lst, it); it = lst->head; } else { it = it->next; } } } void remove_by_prod(list *const lst, const int prod) { node *it; if (lst == NULL) { return; } it = lst->head; while (it != NULL) { int p = it->x * it->y; if (p == prod) { remove_node(lst, it); it = lst->head; } else { it = it->next; } } } void statement1(list *const lst) { short *unique = calloc(100000, sizeof(short)); node *it, *nxt; for (it = lst->head; it != NULL; it = it->next) { int prod = it->x * it->y; unique[prod]++; } it = lst->head; while (it != NULL) { int prod = it->x * it->y; nxt = it->next; if (unique[prod] == 1) { remove_by_sum(lst, it->x + it->y); it = lst->head; } else { it = nxt; } } free(unique); } void statement2(list *const candidates) { short *unique = calloc(100000, sizeof(short)); node *it, *nxt; for (it = candidates->head; it != NULL; it = it->next) { int prod = it->x * it->y; unique[prod]++; } it = candidates->head; while (it != NULL) { int prod = it->x * it->y; nxt = it->next; if (unique[prod] > 1) { remove_by_prod(candidates, prod); it = candidates->head; } else { it = nxt; } } free(unique); } void statement3(list *const candidates) { short *unique = calloc(100, sizeof(short)); node *it, *nxt; for (it = candidates->head; it != NULL; it = it->next) { int sum = it->x + it->y; unique[sum]++; } it = candidates->head; while (it != NULL) { int sum = it->x + it->y; nxt = it->next; if (unique[sum] > 1) { remove_by_sum(candidates, sum); it = candidates->head; } else { it = nxt; } } free(unique); } int main() { list candidates = make_list(); setup(&candidates); print_count(&candidates); statement1(&candidates); print_count(&candidates); statement2(&candidates); print_count(&candidates); statement3(&candidates); print_count(&candidates); print_list(&candidates); free_list(&candidates); return 0; }
Change the following Python code into C without altering its purpose.
from itertools import count, islice def _basechange_int(num, b): if num == 0: return [0] result = [] while num != 0: num, d = divmod(num, b) result.append(d) return result[::-1] def fairshare(b=2): for i in count(): yield sum(_basechange_int(i, b)) % b if __name__ == '__main__': for b in (2, 3, 5, 11): print(f"{b:>2}: {str(list(islice(fairshare(b), 25)))[1:-1]}")
#include <stdio.h> #include <stdlib.h> int turn(int base, int n) { int sum = 0; while (n != 0) { int rem = n % base; n = n / base; sum += rem; } return sum % base; } void fairshare(int base, int count) { int i; printf("Base %2d:", base); for (i = 0; i < count; i++) { int t = turn(base, i); printf(" %2d", t); } printf("\n"); } void turnCount(int base, int count) { int *cnt = calloc(base, sizeof(int)); int i, minTurn, maxTurn, portion; if (NULL == cnt) { printf("Failed to allocate space to determine the spread of turns.\n"); return; } for (i = 0; i < count; i++) { int t = turn(base, i); cnt[t]++; } minTurn = INT_MAX; maxTurn = INT_MIN; portion = 0; for (i = 0; i < base; i++) { if (cnt[i] > 0) { portion++; } if (cnt[i] < minTurn) { minTurn = cnt[i]; } if (cnt[i] > maxTurn) { maxTurn = cnt[i]; } } printf(" With %d people: ", base); if (0 == minTurn) { printf("Only %d have a turn\n", portion); } else if (minTurn == maxTurn) { printf("%d\n", minTurn); } else { printf("%d or %d\n", minTurn, maxTurn); } free(cnt); } int main() { fairshare(2, 25); fairshare(3, 25); fairshare(5, 25); fairshare(11, 25); printf("How many times does each get a turn in 50000 iterations?\n"); turnCount(191, 50000); turnCount(1377, 50000); turnCount(49999, 50000); turnCount(50000, 50000); turnCount(50001, 50000); return 0; }
Preserve the algorithm and functionality while converting the code from Python to C.
import numpy as np class Revolver: def __init__(self): self.cylinder = np.array([False] * 6) def unload(self): self.cylinder[:] = False def load(self): while self.cylinder[1]: self.cylinder[:] = np.roll(self.cylinder, 1) self.cylinder[1] = True def spin(self): self.cylinder[:] = np.roll(self.cylinder, np.random.randint(1, high=7)) def fire(self): shot = self.cylinder[0] self.cylinder[:] = np.roll(self.cylinder, 1) return shot def LSLSFSF(self): self.unload() self.load() self.spin() self.load() self.spin() if self.fire(): return True self.spin() if self.fire(): return True return False def LSLSFF(self): self.unload() self.load() self.spin() self.load() self.spin() if self.fire(): return True if self.fire(): return True return False def LLSFSF(self): self.unload() self.load() self.load() self.spin() if self.fire(): return True self.spin() if self.fire(): return True return False def LLSFF(self): self.unload() self.load() self.load() self.spin() if self.fire(): return True if self.fire(): return True return False if __name__ == '__main__': REV = Revolver() TESTCOUNT = 100000 for (name, method) in [['load, spin, load, spin, fire, spin, fire', REV.LSLSFSF], ['load, spin, load, spin, fire, fire', REV.LSLSFF], ['load, load, spin, fire, spin, fire', REV.LLSFSF], ['load, load, spin, fire, fire', REV.LLSFF]]: percentage = 100 * sum([method() for _ in range(TESTCOUNT)]) / TESTCOUNT print("Method", name, "produces", percentage, "per cent deaths.")
#include <stdbool.h> #include <stdio.h> #include <stdlib.h> #include <string.h> #include <time.h> static int nextInt(int size) { return rand() % size; } static bool cylinder[6]; static void rshift() { bool t = cylinder[5]; int i; for (i = 4; i >= 0; i--) { cylinder[i + 1] = cylinder[i]; } cylinder[0] = t; } static void unload() { int i; for (i = 0; i < 6; i++) { cylinder[i] = false; } } static void load() { while (cylinder[0]) { rshift(); } cylinder[0] = true; rshift(); } static void spin() { int lim = nextInt(6) + 1; int i; for (i = 1; i < lim; i++) { rshift(); } } static bool fire() { bool shot = cylinder[0]; rshift(); return shot; } static int method(const char *s) { unload(); for (; *s != '\0'; s++) { switch (*s) { case 'L': load(); break; case 'S': spin(); break; case 'F': if (fire()) { return 1; } break; } } return 0; } static void append(char *out, const char *txt) { if (*out != '\0') { strcat(out, ", "); } strcat(out, txt); } static void mstring(const char *s, char *out) { for (; *s != '\0'; s++) { switch (*s) { case 'L': append(out, "load"); break; case 'S': append(out, "spin"); break; case 'F': append(out, "fire"); break; } } } static void test(char *src) { char buffer[41] = ""; const int tests = 100000; int sum = 0; int t; double pc; for (t = 0; t < tests; t++) { sum += method(src); } mstring(src, buffer); pc = 100.0 * sum / tests; printf("%-40s produces %6.3f%% deaths.\n", buffer, pc); } int main() { srand(time(0)); test("LSLSFSF"); test("LSLSFF"); test("LLSFSF"); test("LLSFF"); return 0; }
Convert the following code from Python to C, ensuring the logic remains intact.
from collections import namedtuple from pprint import pprint as pp OpInfo = namedtuple('OpInfo', 'prec assoc') L, R = 'Left Right'.split() ops = { '^': OpInfo(prec=4, assoc=R), '*': OpInfo(prec=3, assoc=L), '/': OpInfo(prec=3, assoc=L), '+': OpInfo(prec=2, assoc=L), '-': OpInfo(prec=2, assoc=L), '(': OpInfo(prec=9, assoc=L), ')': OpInfo(prec=0, assoc=L), } NUM, LPAREN, RPAREN = 'NUMBER ( )'.split() def get_input(inp = None): 'Inputs an expression and returns list of (TOKENTYPE, tokenvalue)' if inp is None: inp = input('expression: ') tokens = inp.strip().split() tokenvals = [] for token in tokens: if token in ops: tokenvals.append((token, ops[token])) else: tokenvals.append((NUM, token)) return tokenvals def shunting(tokenvals): outq, stack = [], [] table = ['TOKEN,ACTION,RPN OUTPUT,OP STACK,NOTES'.split(',')] for token, val in tokenvals: note = action = '' if token is NUM: action = 'Add number to output' outq.append(val) table.append( (val, action, ' '.join(outq), ' '.join(s[0] for s in stack), note) ) elif token in ops: t1, (p1, a1) = token, val v = t1 note = 'Pop ops from stack to output' while stack: t2, (p2, a2) = stack[-1] if (a1 == L and p1 <= p2) or (a1 == R and p1 < p2): if t1 != RPAREN: if t2 != LPAREN: stack.pop() action = '(Pop op)' outq.append(t2) else: break else: if t2 != LPAREN: stack.pop() action = '(Pop op)' outq.append(t2) else: stack.pop() action = '(Pop & discard "(")' table.append( (v, action, ' '.join(outq), ' '.join(s[0] for s in stack), note) ) break table.append( (v, action, ' '.join(outq), ' '.join(s[0] for s in stack), note) ) v = note = '' else: note = '' break note = '' note = '' if t1 != RPAREN: stack.append((token, val)) action = 'Push op token to stack' else: action = 'Discard ")"' table.append( (v, action, ' '.join(outq), ' '.join(s[0] for s in stack), note) ) note = 'Drain stack to output' while stack: v = '' t2, (p2, a2) = stack[-1] action = '(Pop op)' stack.pop() outq.append(t2) table.append( (v, action, ' '.join(outq), ' '.join(s[0] for s in stack), note) ) v = note = '' return table if __name__ == '__main__': infix = '3 + 4 * 2 / ( 1 - 5 ) ^ 2 ^ 3' print( 'For infix expression: %r\n' % infix ) rp = shunting(get_input(infix)) maxcolwidths = [len(max(x, key=len)) for x in zip(*rp)] row = rp[0] print( ' '.join('{cell:^{width}}'.format(width=width, cell=cell) for (width, cell) in zip(maxcolwidths, row))) for row in rp[1:]: print( ' '.join('{cell:<{width}}'.format(width=width, cell=cell) for (width, cell) in zip(maxcolwidths, row))) print('\n The final output RPN is: %r' % rp[-1][2])
#include <sys/types.h> #include <regex.h> #include <stdio.h> typedef struct { const char *s; int len, prec, assoc; } str_tok_t; typedef struct { const char * str; int assoc, prec; regex_t re; } pat_t; enum assoc { A_NONE, A_L, A_R }; pat_t pat_eos = {"", A_NONE, 0}; pat_t pat_ops[] = { {"^\\)", A_NONE, -1}, {"^\\*\\*", A_R, 3}, {"^\\^", A_R, 3}, {"^\\*", A_L, 2}, {"^/", A_L, 2}, {"^\\+", A_L, 1}, {"^-", A_L, 1}, {0} }; pat_t pat_arg[] = { {"^[-+]?[0-9]*\\.?[0-9]+([eE][-+]?[0-9]+)?"}, {"^[a-zA-Z_][a-zA-Z_0-9]*"}, {"^\\(", A_L, -1}, {0} }; str_tok_t stack[256]; str_tok_t queue[256]; int l_queue, l_stack; #define qpush(x) queue[l_queue++] = x #define spush(x) stack[l_stack++] = x #define spop() stack[--l_stack] void display(const char *s) { int i; printf("\033[1;1H\033[JText | %s", s); printf("\nStack| "); for (i = 0; i < l_stack; i++) printf("%.*s ", stack[i].len, stack[i].s); printf("\nQueue| "); for (i = 0; i < l_queue; i++) printf("%.*s ", queue[i].len, queue[i].s); puts("\n\n<press enter>"); getchar(); } int prec_booster; #define fail(s1, s2) {fprintf(stderr, "[Error %s] %s\n", s1, s2); return 0;} int init(void) { int i; pat_t *p; for (i = 0, p = pat_ops; p[i].str; i++) if (regcomp(&(p[i].re), p[i].str, REG_NEWLINE|REG_EXTENDED)) fail("comp", p[i].str); for (i = 0, p = pat_arg; p[i].str; i++) if (regcomp(&(p[i].re), p[i].str, REG_NEWLINE|REG_EXTENDED)) fail("comp", p[i].str); return 1; } pat_t* match(const char *s, pat_t *p, str_tok_t * t, const char **e) { int i; regmatch_t m; while (*s == ' ') s++; *e = s; if (!*s) return &pat_eos; for (i = 0; p[i].str; i++) { if (regexec(&(p[i].re), s, 1, &m, REG_NOTEOL)) continue; t->s = s; *e = s + (t->len = m.rm_eo - m.rm_so); return p + i; } return 0; } int parse(const char *s) { pat_t *p; str_tok_t *t, tok; prec_booster = l_queue = l_stack = 0; display(s); while (*s) { p = match(s, pat_arg, &tok, &s); if (!p || p == &pat_eos) fail("parse arg", s); if (p->prec == -1) { prec_booster += 100; continue; } qpush(tok); display(s); re_op: p = match(s, pat_ops, &tok, &s); if (!p) fail("parse op", s); tok.assoc = p->assoc; tok.prec = p->prec; if (p->prec > 0) tok.prec = p->prec + prec_booster; else if (p->prec == -1) { if (prec_booster < 100) fail("unmatched )", s); tok.prec = prec_booster; } while (l_stack) { t = stack + l_stack - 1; if (!(t->prec == tok.prec && t->assoc == A_L) && t->prec <= tok.prec) break; qpush(spop()); display(s); } if (p->prec == -1) { prec_booster -= 100; goto re_op; } if (!p->prec) { display(s); if (prec_booster) fail("unmatched (", s); return 1; } spush(tok); display(s); } if (p->prec > 0) fail("unexpected eol", s); return 1; } int main() { int i; const char *tests[] = { "3 + 4 * 2 / ( 1 - 5 ) ^ 2 ^ 3", "123", "3+4 * 2 / ( 1 - 5 ) ^ 2 ^ 3.14", "(((((((1+2+3**(4 + 5))))))", "a^(b + c/d * .1e5)!", "(1**2)**3", "2 + 2 *", 0 }; if (!init()) return 1; for (i = 0; tests[i]; i++) { printf("Testing string `%s' <enter>\n", tests[i]); getchar(); printf("string `%s': %s\n\n", tests[i], parse(tests[i]) ? "Ok" : "Error"); } return 0; }
Translate the given Python code snippet into C without altering its behavior.
Python 3.2.2 (default, Sep 4 2011, 09:51:08) [MSC v.1500 32 bit (Intel)] on win32 Type "copyright", "credits" or "license()" for more information. >>> def f(x): return abs(x) ** 0.5 + 5 * x**3 >>> print(', '.join('%s:%s' % (x, v if v<=400 else "TOO LARGE!") for x,v in ((y, f(float(y))) for y in input('\nnumbers: ').strip().split()[:11][::-1]))) 11 numbers: 1 2 3 4 5 6 7 8 9 10 11 11:TOO LARGE!, 10:TOO LARGE!, 9:TOO LARGE!, 8:TOO LARGE!, 7:TOO LARGE!, 6:TOO LARGE!, 5:TOO LARGE!, 4:322.0, 3:136.73205080756887, 2:41.41421356237309, 1:6.0 >>>
#include<math.h> #include<stdio.h> int main () { double inputs[11], check = 400, result; int i; printf ("\nPlease enter 11 numbers :"); for (i = 0; i < 11; i++) { scanf ("%lf", &inputs[i]); } printf ("\n\n\nEvaluating f(x) = |x|^0.5 + 5x^3 for the given inputs :"); for (i = 10; i >= 0; i--) { result = sqrt (fabs (inputs[i])) + 5 * pow (inputs[i], 3); printf ("\nf(%lf) = "); if (result > check) { printf ("Overflow!"); } else { printf ("%lf", result); } } return 0; }
Produce a language-to-language conversion: from Python to C, same semantics.
>>> def middle_three_digits(i): s = str(abs(i)) length = len(s) assert length >= 3 and length % 2 == 1, "Need odd and >= 3 digits" mid = length // 2 return s[mid-1:mid+2] >>> passing = [123, 12345, 1234567, 987654321, 10001, -10001, -123, -100, 100, -12345] >>> failing = [1, 2, -1, -10, 2002, -2002, 0] >>> for x in passing + failing: try: answer = middle_three_digits(x) except AssertionError as error: answer = error print("middle_three_digits(%s) returned: %r" % (x, answer)) middle_three_digits(123) returned: '123' middle_three_digits(12345) returned: '234' middle_three_digits(1234567) returned: '345' middle_three_digits(987654321) returned: '654' middle_three_digits(10001) returned: '000' middle_three_digits(-10001) returned: '000' middle_three_digits(-123) returned: '123' middle_three_digits(-100) returned: '100' middle_three_digits(100) returned: '100' middle_three_digits(-12345) returned: '234' middle_three_digits(1) returned: AssertionError('Need odd and >= 3 digits',) middle_three_digits(2) returned: AssertionError('Need odd and >= 3 digits',) middle_three_digits(-1) returned: AssertionError('Need odd and >= 3 digits',) middle_three_digits(-10) returned: AssertionError('Need odd and >= 3 digits',) middle_three_digits(2002) returned: AssertionError('Need odd and >= 3 digits',) middle_three_digits(-2002) returned: AssertionError('Need odd and >= 3 digits',) middle_three_digits(0) returned: AssertionError('Need odd and >= 3 digits',) >>>
#include <stdio.h> #include <stdlib.h> #include <string.h> char * mid3(int n) { static char buf[32]; int l; sprintf(buf, "%d", n > 0 ? n : -n); l = strlen(buf); if (l < 3 || !(l & 1)) return 0; l = l / 2 - 1; buf[l + 3] = 0; return buf + l; } int main(void) { int x[] = {123, 12345, 1234567, 987654321, 10001, -10001, -123, -100, 100, -12345, 1, 2, -1, -10, 2002, -2002, 0, 1234567890}; int i; char *m; for (i = 0; i < sizeof(x)/sizeof(x[0]); i++) { if (!(m = mid3(x[i]))) m = "error"; printf("%d: %s\n", x[i], m); } return 0; }
Translate the given Python code snippet into C without altering its behavior.
def divisors(n): divs = [1] for ii in range(2, int(n ** 0.5) + 3): if n % ii == 0: divs.append(ii) divs.append(int(n / ii)) divs.append(n) return list(set(divs)) def is_prime(n): return len(divisors(n)) == 2 def primes(): ii = 1 while True: ii += 1 if is_prime(ii): yield ii def prime(n): generator = primes() for ii in range(n - 1): generator.__next__() return generator.__next__() def n_divisors(n): ii = 0 while True: ii += 1 if len(divisors(ii)) == n: yield ii def sequence(max_n=None): if max_n is not None: for ii in range(1, max_n + 1): if is_prime(ii): yield prime(ii) ** (ii - 1) else: generator = n_divisors(ii) for jj, out in zip(range(ii - 1), generator): pass yield generator.__next__() else: ii = 1 while True: ii += 1 if is_prime(ii): yield prime(ii) ** (ii - 1) else: generator = n_divisors(ii) for jj, out in zip(range(ii - 1), generator): pass yield generator.__next__() if __name__ == '__main__': for item in sequence(15): print(item)
#include <math.h> #include <stdbool.h> #include <stdint.h> #include <stdio.h> #define LIMIT 15 int smallPrimes[LIMIT]; static void sieve() { int i = 2, j; int p = 5; smallPrimes[0] = 2; smallPrimes[1] = 3; while (i < LIMIT) { for (j = 0; j < i; j++) { if (smallPrimes[j] * smallPrimes[j] <= p) { if (p % smallPrimes[j] == 0) { p += 2; break; } } else { smallPrimes[i++] = p; p += 2; break; } } } } static bool is_prime(uint64_t n) { uint64_t i; for (i = 0; i < LIMIT; i++) { if (n % smallPrimes[i] == 0) { return n == smallPrimes[i]; } } i = smallPrimes[LIMIT - 1] + 2; for (; i * i <= n; i += 2) { if (n % i == 0) { return false; } } return true; } static uint64_t divisor_count(uint64_t n) { uint64_t count = 1; uint64_t d; while (n % 2 == 0) { n /= 2; count++; } for (d = 3; d * d <= n; d += 2) { uint64_t q = n / d; uint64_t r = n % d; uint64_t dc = 0; while (r == 0) { dc += count; n = q; q = n / d; r = n % d; } count += dc; } if (n != 1) { return count *= 2; } return count; } static uint64_t OEISA073916(size_t n) { uint64_t count = 0; uint64_t result = 0; size_t i; if (is_prime(n)) { return (uint64_t)pow(smallPrimes[n - 1], n - 1); } for (i = 1; count < n; i++) { if (n % 2 == 1) { uint64_t root = (uint64_t)sqrt(i); if (root * root != i) { continue; } } if (divisor_count(i) == n) { count++; result = i; } } return result; } int main() { size_t n; sieve(); for (n = 1; n <= LIMIT; n++) { if (n == 13) { printf("A073916(%lu) = One more bit needed to represent result.\n", n); } else { printf("A073916(%lu) = %llu\n", n, OEISA073916(n)); } } return 0; }
Please provide an equivalent version of this Python code in C.
def divisors(n): divs = [1] for ii in range(2, int(n ** 0.5) + 3): if n % ii == 0: divs.append(ii) divs.append(int(n / ii)) divs.append(n) return list(set(divs)) def sequence(max_n=None): n = 0 while True: n += 1 ii = 0 if max_n is not None: if n > max_n: break while True: ii += 1 if len(divisors(ii)) == n: yield ii break if __name__ == '__main__': for item in sequence(15): print(item)
#include <stdio.h> #define MAX 15 int count_divisors(int n) { int i, count = 0; for (i = 1; i * i <= n; ++i) { if (!(n % i)) { if (i == n / i) count++; else count += 2; } } return count; } int main() { int i, k, n, seq[MAX]; for (i = 0; i < MAX; ++i) seq[i] = 0; printf("The first %d terms of the sequence are:\n", MAX); for (i = 1, n = 0; n < MAX; ++i) { k = count_divisors(i); if (k <= MAX && seq[k - 1] == 0) { seq[k - 1] = i; ++n; } } for (i = 0; i < MAX; ++i) printf("%d ", seq[i]); printf("\n"); return 0; }
Can you help me rewrite this code in C instead of Python, keeping it the same logically?
def divisors(n): divs = [1] for ii in range(2, int(n ** 0.5) + 3): if n % ii == 0: divs.append(ii) divs.append(int(n / ii)) divs.append(n) return list(set(divs)) def sequence(max_n=None): n = 0 while True: n += 1 ii = 0 if max_n is not None: if n > max_n: break while True: ii += 1 if len(divisors(ii)) == n: yield ii break if __name__ == '__main__': for item in sequence(15): print(item)
#include <stdio.h> #define MAX 15 int count_divisors(int n) { int i, count = 0; for (i = 1; i * i <= n; ++i) { if (!(n % i)) { if (i == n / i) count++; else count += 2; } } return count; } int main() { int i, k, n, seq[MAX]; for (i = 0; i < MAX; ++i) seq[i] = 0; printf("The first %d terms of the sequence are:\n", MAX); for (i = 1, n = 0; n < MAX; ++i) { k = count_divisors(i); if (k <= MAX && seq[k - 1] == 0) { seq[k - 1] = i; ++n; } } for (i = 0; i < MAX; ++i) printf("%d ", seq[i]); printf("\n"); return 0; }
Port the provided Python code into C while preserving the original functionality.
import time from collections import deque from operator import itemgetter from typing import Tuple Pancakes = Tuple[int, ...] def flip(pancakes: Pancakes, position: int) -> Pancakes: return tuple([*reversed(pancakes[:position]), *pancakes[position:]]) def pancake(n: int) -> Tuple[Pancakes, int]: init_stack = tuple(range(1, n + 1)) stack_flips = {init_stack: 0} queue = deque([init_stack]) while queue: stack = queue.popleft() flips = stack_flips[stack] + 1 for i in range(2, n + 1): flipped = flip(stack, i) if flipped not in stack_flips: stack_flips[flipped] = flips queue.append(flipped) return max(stack_flips.items(), key=itemgetter(1)) if __name__ == "__main__": start = time.time() for n in range(1, 10): pancakes, p = pancake(n) print(f"pancake({n}) = {p:>2}. Example: {list(pancakes)}") print(f"\nTook {time.time() - start:.3} seconds.")
#include <stdio.h> int pancake(int n) { int gap = 2, sum = 2, adj = -1; while (sum < n) { adj++; gap = gap * 2 - 1; sum += gap; } return n + adj; } int main() { int i, j; for (i = 0; i < 4; i++) { for (j = 1; j < 6; j++) { int n = i * 5 + j; printf("p(%2d) = %2d ", n, pancake(n)); } printf("\n"); } return 0; }
Please provide an equivalent version of this Python code in C.
import random board = [[" " for x in range(8)] for y in range(8)] piece_list = ["R", "N", "B", "Q", "P"] def place_kings(brd): while True: rank_white, file_white, rank_black, file_black = random.randint(0,7), random.randint(0,7), random.randint(0,7), random.randint(0,7) diff_list = [abs(rank_white - rank_black), abs(file_white - file_black)] if sum(diff_list) > 2 or set(diff_list) == set([0, 2]): brd[rank_white][file_white], brd[rank_black][file_black] = "K", "k" break def populate_board(brd, wp, bp): for x in range(2): if x == 0: piece_amount = wp pieces = piece_list else: piece_amount = bp pieces = [s.lower() for s in piece_list] while piece_amount != 0: piece_rank, piece_file = random.randint(0, 7), random.randint(0, 7) piece = random.choice(pieces) if brd[piece_rank][piece_file] == " " and pawn_on_promotion_square(piece, piece_rank) == False: brd[piece_rank][piece_file] = piece piece_amount -= 1 def fen_from_board(brd): fen = "" for x in brd: n = 0 for y in x: if y == " ": n += 1 else: if n != 0: fen += str(n) fen += y n = 0 if n != 0: fen += str(n) fen += "/" if fen.count("/") < 7 else "" fen += " w - - 0 1\n" return fen def pawn_on_promotion_square(pc, pr): if pc == "P" and pr == 0: return True elif pc == "p" and pr == 7: return True return False def start(): piece_amount_white, piece_amount_black = random.randint(0, 15), random.randint(0, 15) place_kings(board) populate_board(board, piece_amount_white, piece_amount_black) print(fen_from_board(board)) for x in board: print(x) start()
#include <stdio.h> #include <math.h> #include <string.h> #include <stdlib.h> #include <time.h> #define TRUE 1 #define FALSE 0 typedef int bool; char grid[8][8]; void placeKings() { int r1, r2, c1, c2; for (;;) { r1 = rand() % 8; c1 = rand() % 8; r2 = rand() % 8; c2 = rand() % 8; if (r1 != r2 && abs(r1 - r2) > 1 && abs(c1 - c2) > 1) { grid[r1][c1] = 'K'; grid[r2][c2] = 'k'; return; } } } void placePieces(const char *pieces, bool isPawn) { int n, r, c; int numToPlace = rand() % strlen(pieces); for (n = 0; n < numToPlace; ++n) { do { r = rand() % 8; c = rand() % 8; } while (grid[r][c] != 0 || (isPawn && (r == 7 || r == 0))); grid[r][c] = pieces[n]; } } void toFen() { char fen[80], ch; int r, c, countEmpty = 0, index = 0; for (r = 0; r < 8; ++r) { for (c = 0; c < 8; ++c) { ch = grid[r][c]; printf("%2c ", ch == 0 ? '.' : ch); if (ch == 0) { countEmpty++; } else { if (countEmpty > 0) { fen[index++] = countEmpty + 48; countEmpty = 0; } fen[index++] = ch; } } if (countEmpty > 0) { fen[index++] = countEmpty + 48; countEmpty = 0; } fen[index++]= '/'; printf("\n"); } strcpy(fen + index, " w - - 0 1"); printf("%s\n", fen); } char *createFen() { placeKings(); placePieces("PPPPPPPP", TRUE); placePieces("pppppppp", TRUE); placePieces("RNBQBNR", FALSE); placePieces("rnbqbnr", FALSE); toFen(); } int main() { srand(time(NULL)); createFen(); return 0; }
Maintain the same structure and functionality when rewriting this code in C.
from collections import deque from itertools import dropwhile, islice, takewhile from textwrap import wrap from typing import Iterable, Iterator Digits = str def esthetic_nums(base: int) -> Iterator[int]: queue: deque[tuple[int, int]] = deque() queue.extendleft((d, d) for d in range(1, base)) while True: num, lsd = queue.pop() yield num new_lsds = (d for d in (lsd - 1, lsd + 1) if 0 <= d < base) num *= base queue.extendleft((num + d, d) for d in new_lsds) def to_digits(num: int, base: int) -> Digits: digits: list[str] = [] while num: num, d = divmod(num, base) digits.append("0123456789abcdef"[d]) return "".join(reversed(digits)) if digits else "0" def pprint_it(it: Iterable[str], indent: int = 4, width: int = 80) -> None: joined = ", ".join(it) lines = wrap(joined, width=width - indent) for line in lines: print(f"{indent*' '}{line}") print() def task_2() -> None: nums: Iterator[int] for base in range(2, 16 + 1): start, stop = 4 * base, 6 * base nums = esthetic_nums(base) nums = islice(nums, start - 1, stop) print( f"Base-{base} esthetic numbers from " f"index {start} through index {stop} inclusive:\n" ) pprint_it(to_digits(num, base) for num in nums) def task_3(lower: int, upper: int, base: int = 10) -> None: nums: Iterator[int] = esthetic_nums(base) nums = dropwhile(lambda num: num < lower, nums) nums = takewhile(lambda num: num <= upper, nums) print( f"Base-{base} esthetic numbers with " f"magnitude between {lower:,} and {upper:,}:\n" ) pprint_it(to_digits(num, base) for num in nums) if __name__ == "__main__": print("======\nTask 2\n======\n") task_2() print("======\nTask 3\n======\n") task_3(1_000, 9_999) print("======\nTask 4\n======\n") task_3(100_000_000, 130_000_000)
#include <stdio.h> #include <string.h> #include <locale.h> typedef int bool; typedef unsigned long long ull; #define TRUE 1 #define FALSE 0 char as_digit(int d) { return (d >= 0 && d <= 9) ? d + '0' : d - 10 + 'a'; } void revstr(char *str) { int i, len = strlen(str); char t; for (i = 0; i < len/2; ++i) { t = str[i]; str[i] = str[len - i - 1]; str[len - i - 1] = t; } } char* to_base(char s[], ull n, int b) { int i = 0; while (n) { s[i++] = as_digit(n % b); n /= b; } s[i] = '\0'; revstr(s); return s; } ull uabs(ull a, ull b) { return a > b ? a - b : b - a; } bool is_esthetic(ull n, int b) { int i, j; if (!n) return FALSE; i = n % b; n /= b; while (n) { j = n % b; if (uabs(i, j) != 1) return FALSE; n /= b; i = j; } return TRUE; } ull esths[45000]; int le = 0; void dfs(ull n, ull m, ull i) { ull d, i1, i2; if (i >= n && i <= m) esths[le++] = i; if (i == 0 || i > m) return; d = i % 10; i1 = i * 10 + d - 1; i2 = i1 + 2; if (d == 0) { dfs(n, m, i2); } else if (d == 9) { dfs(n, m, i1); } else { dfs(n, m, i1); dfs(n, m, i2); } } void list_esths(ull n, ull n2, ull m, ull m2, int per_line, bool all) { int i; le = 0; for (i = 0; i < 10; ++i) { dfs(n2, m2, i); } printf("Base 10: %'d esthetic numbers between %'llu and %'llu:\n", le, n, m); if (all) { for (i = 0; i < le; ++i) { printf("%llu ", esths[i]); if (!(i+1)%per_line) printf("\n"); } } else { for (i = 0; i < per_line; ++i) printf("%llu ", esths[i]); printf("\n............\n"); for (i = le - per_line; i < le; ++i) printf("%llu ", esths[i]); } printf("\n\n"); } int main() { ull n; int b, c; char ch[15] = {0}; for (b = 2; b <= 16; ++b) { printf("Base %d: %dth to %dth esthetic numbers:\n", b, 4*b, 6*b); for (n = 1, c = 0; c < 6 * b; ++n) { if (is_esthetic(n, b)) { if (++c >= 4 * b) printf("%s ", to_base(ch, n, b)); } } printf("\n\n"); } char *oldLocale = setlocale(LC_NUMERIC, NULL); setlocale(LC_NUMERIC, ""); list_esths(1000, 1010, 9999, 9898, 16, TRUE); list_esths(1e8, 101010101, 13*1e7, 123456789, 9, TRUE); list_esths(1e11, 101010101010, 13*1e10, 123456789898, 7, FALSE); list_esths(1e14, 101010101010101, 13*1e13, 123456789898989, 5, FALSE); list_esths(1e17, 101010101010101010, 13*1e16, 123456789898989898, 4, FALSE); setlocale(LC_NUMERIC, oldLocale); return 0; }
Translate the given Python code snippet into C without altering its behavior.
>>> from itertools import permutations >>> def f1(p): i = 0 while True: p0 = p[0] if p0 == 1: break p[:p0] = p[:p0][::-1] i += 1 return i >>> def fannkuch(n): return max(f1(list(p)) for p in permutations(range(1, n+1))) >>> for n in range(1, 11): print(n,fannkuch(n)) 1 0 2 1 3 2 4 4 5 7 6 10 7 16 8 22 9 30 10 38 >>>
#include <stdio.h> #include <string.h> typedef struct { char v[16]; } deck; typedef unsigned int uint; uint n, d, best[16]; void tryswaps(deck *a, uint f, uint s) { # define A a->v # define B b.v if (d > best[n]) best[n] = d; while (1) { if ((A[s] == s || (A[s] == -1 && !(f & 1U << s))) && (d + best[s] >= best[n] || A[s] == -1)) break; if (d + best[s] <= best[n]) return; if (!--s) return; } d++; deck b = *a; for (uint i = 1, k = 2; i <= s; k <<= 1, i++) { if (A[i] != i && (A[i] != -1 || (f & k))) continue; for (uint j = B[0] = i; j--;) B[i - j] = A[j]; tryswaps(&b, f | k, s); } d--; } int main(void) { deck x; memset(&x, -1, sizeof(x)); x.v[0] = 0; for (n = 1; n < 13; n++) { tryswaps(&x, 1, n - 1); printf("%2d: %d\n", n, best[n]); } return 0; }
Translate the given Python code snippet into C without altering its behavior.
from sys import argv unit2mult = {"arshin": 0.7112, "centimeter": 0.01, "diuym": 0.0254, "fut": 0.3048, "kilometer": 1000.0, "liniya": 0.00254, "meter": 1.0, "milia": 7467.6, "piad": 0.1778, "sazhen": 2.1336, "tochka": 0.000254, "vershok": 0.04445, "versta": 1066.8} if __name__ == '__main__': assert len(argv) == 3, 'ERROR. Need two arguments - number then units' try: value = float(argv[1]) except: print('ERROR. First argument must be a (float) number') raise unit = argv[2] assert unit in unit2mult, ( 'ERROR. Only know the following units: ' + ' '.join(unit2mult.keys()) ) print("%g %s to:" % (value, unit)) for unt, mlt in sorted(unit2mult.items()): print(' %10s: %g' % (unt, value * unit2mult[unit] / mlt))
#include<string.h> #include<stdlib.h> #include<ctype.h> #include<stdio.h> #define UNITS_LENGTH 13 int main(int argC,char* argV[]) { int i,reference; char *units[UNITS_LENGTH] = {"kilometer","meter","centimeter","tochka","liniya","diuym","vershok","piad","fut","arshin","sazhen","versta","milia"}; double factor, values[UNITS_LENGTH] = {1000.0,1.0,0.01,0.000254,0.00254,0.0254,0.04445,0.1778,0.3048,0.7112,2.1336,1066.8,7467.6}; if(argC!=3) printf("Usage : %s followed by length as <value> <unit>"); else{ for(i=0;argV[2][i]!=00;i++) argV[2][i] = tolower(argV[2][i]); for(i=0;i<UNITS_LENGTH;i++){ if(strstr(argV[2],units[i])!=NULL){ reference = i; factor = atof(argV[1])*values[i]; break; } } printf("%s %s is equal in length to : \n",argV[1],argV[2]); for(i=0;i<UNITS_LENGTH;i++){ if(i!=reference) printf("\n%lf %s",factor/values[i],units[i]); } } return 0; }
Write the same algorithm in C as shown in this Python implementation.
import subprocess import time class Tlogger(object): def __init__(self): self.counts = 0 self.tottime = 0.0 self.laststart = 0.0 self.lastreport = time.time() def logstart(self): self.laststart = time.time() def logend(self): self.counts +=1 self.tottime += (time.time()-self.laststart) if (time.time()-self.lastreport)>5.0: self.report() def report(self): if ( self.counts > 4*self.tottime): print "Subtask execution rate: %f times/second"% (self.counts/self.tottime); else: print "Average execution time: %f seconds"%(self.tottime/self.counts); self.lastreport = time.time() def taskTimer( n, subproc_args ): logger = Tlogger() for x in range(n): logger.logstart() p = subprocess.Popen(subproc_args) p.wait() logger.logend() logger.report() import timeit import sys def main( ): s = timer = timeit.Timer(s) rzlts = timer.repeat(5, 5000) for t in rzlts: print "Time for 5000 executions of statement = ",t print " print "Command:",sys.argv[2:] print "" for k in range(3): taskTimer( int(sys.argv[1]), sys.argv[2:]) main()
#include <stdio.h> #include <time.h> struct rate_state_s { time_t lastFlush; time_t period; size_t tickCount; }; void tic_rate(struct rate_state_s* pRate) { pRate->tickCount += 1; time_t now = time(NULL); if((now - pRate->lastFlush) >= pRate->period) { size_t tps = 0.0; if(pRate->tickCount > 0) tps = pRate->tickCount / (now - pRate->lastFlush); printf("%u tics per second.\n", tps); pRate->tickCount = 0; pRate->lastFlush = now; } } void something_we_do() { volatile size_t anchor = 0; size_t x = 0; for(x = 0; x < 0xffff; ++x) { anchor = x; } } int main() { time_t start = time(NULL); struct rate_state_s rateWatch; rateWatch.lastFlush = start; rateWatch.tickCount = 0; rateWatch.period = 5; time_t latest = start; for(latest = start; (latest - start) < 20; latest = time(NULL)) { something_we_do(); tic_rate(&rateWatch); } return 0; }
Write a version of this Python function in C with identical behavior.
def divisors(n): divs = [1] for ii in range(2, int(n ** 0.5) + 3): if n % ii == 0: divs.append(ii) divs.append(int(n / ii)) divs.append(n) return list(set(divs)) def sequence(max_n=None): previous = 0 n = 0 while True: n += 1 ii = previous if max_n is not None: if n > max_n: break while True: ii += 1 if len(divisors(ii)) == n: yield ii previous = ii break if __name__ == '__main__': for item in sequence(15): print(item)
#include <stdio.h> #define MAX 15 int count_divisors(int n) { int i, count = 0; for (i = 1; i * i <= n; ++i) { if (!(n % i)) { if (i == n / i) count++; else count += 2; } } return count; } int main() { int i, next = 1; printf("The first %d terms of the sequence are:\n", MAX); for (i = 1; next <= MAX; ++i) { if (next == count_divisors(i)) { printf("%d ", i); next++; } } printf("\n"); return 0; }
Convert this Python block to C, preserving its control flow and logic.
from math import floor from collections import deque from typing import Dict, Generator def padovan_r() -> Generator[int, None, None]: last = deque([1, 1, 1], 4) while True: last.append(last[-2] + last[-3]) yield last.popleft() _p, _s = 1.324717957244746025960908854, 1.0453567932525329623 def padovan_f(n: int) -> int: return floor(_p**(n-1) / _s + .5) def padovan_l(start: str='A', rules: Dict[str, str]=dict(A='B', B='C', C='AB') ) -> Generator[str, None, None]: axiom = start while True: yield axiom axiom = ''.join(rules[ch] for ch in axiom) if __name__ == "__main__": from itertools import islice print("The first twenty terms of the sequence.") print(str([padovan_f(n) for n in range(20)])[1:-1]) r_generator = padovan_r() if all(next(r_generator) == padovan_f(n) for n in range(64)): print("\nThe recurrence and floor based algorithms match to n=63 .") else: print("\nThe recurrence and floor based algorithms DIFFER!") print("\nThe first 10 L-system string-lengths and strings") l_generator = padovan_l(start='A', rules=dict(A='B', B='C', C='AB')) print('\n'.join(f" {len(string):3} {repr(string)}" for string in islice(l_generator, 10))) r_generator = padovan_r() l_generator = padovan_l(start='A', rules=dict(A='B', B='C', C='AB')) if all(len(next(l_generator)) == padovan_f(n) == next(r_generator) for n in range(32)): print("\nThe L-system, recurrence and floor based algorithms match to n=31 .") else: print("\nThe L-system, recurrence and floor based algorithms DIFFER!")
#include <stdio.h> #include <stdlib.h> #include <math.h> #include <string.h> int pRec(int n) { static int *memo = NULL; static size_t curSize = 0; if (curSize <= (size_t) n) { size_t lastSize = curSize; while (curSize <= (size_t) n) curSize += 1024 * sizeof(int); memo = realloc(memo, curSize * sizeof(int)); memset(memo + lastSize, 0, (curSize - lastSize) * sizeof(int)); } if (memo[n] == 0) { if (n<=2) memo[n] = 1; else memo[n] = pRec(n-2) + pRec(n-3); } return memo[n]; } int pFloor(int n) { long double p = 1.324717957244746025960908854; long double s = 1.0453567932525329623; return powl(p, n-1)/s + 0.5; } void nextLSystem(const char *prev, char *buf) { while (*prev) { switch (*prev++) { case 'A': *buf++ = 'B'; break; case 'B': *buf++ = 'C'; break; case 'C': *buf++ = 'A'; *buf++ = 'B'; break; } } *buf = '\0'; } int main() { #define BUFSZ 8192 char buf1[BUFSZ], buf2[BUFSZ]; int i; printf("P_0 .. P_19: "); for (i=0; i<20; i++) printf("%d ", pRec(i)); printf("\n"); printf("The floor- and recurrence-based functions "); for (i=0; i<64; i++) { if (pRec(i) != pFloor(i)) { printf("do not match at %d: %d != %d.\n", i, pRec(i), pFloor(i)); break; } } if (i == 64) { printf("match from P_0 to P_63.\n"); } printf("\nThe first 10 L-system strings are:\n"); for (strcpy(buf1, "A"), i=0; i<10; i++) { printf("%s\n", buf1); strcpy(buf2, buf1); nextLSystem(buf2, buf1); } printf("\nThe floor- and L-system-based functions "); for (strcpy(buf1, "A"), i=0; i<32; i++) { if ((int)strlen(buf1) != pFloor(i)) { printf("do not match at %d: %d != %d\n", i, (int)strlen(buf1), pFloor(i)); break; } strcpy(buf2, buf1); nextLSystem(buf2, buf1); } if (i == 32) { printf("match from P_0 to P_31.\n"); } return 0; }
Transform the following Python implementation into C, maintaining the same output and logic.
def setup(): size(800, 400) background(255) stroke(0, 255, 0) tree(width / 2.3, height, width / 1.8, height, 10) def tree(x1, y1, x2, y2, depth): if depth <= 0: return dx = (x2 - x1) dy = (y1 - y2) x3 = (x2 - dy) y3 = (y2 - dx) x4 = (x1 - dy) y4 = (y1 - dx) x5 = (x4 + 0.5 * (dx - dy)) y5 = (y4 - 0.5 * (dx + dy)) beginShape() fill(0.0, 255.0 / depth, 0.0) vertex(x1, y1) vertex(x2, y2) vertex(x3, y3) vertex(x4, y4) vertex(x1, y1) endShape() beginShape() fill(0.0, 255.0 / depth, 0.0) vertex(x3, y3) vertex(x4, y4) vertex(x5, y5) vertex(x3, y3) endShape() tree(x4, y4, x5, y5, depth - 1) tree(x5, y5, x3, y3, depth - 1)
#include<graphics.h> #include<stdlib.h> #include<stdio.h> #include<time.h> typedef struct{ double x,y; }point; void pythagorasTree(point a,point b,int times){ point c,d,e; c.x = b.x - (a.y - b.y); c.y = b.y - (b.x - a.x); d.x = a.x - (a.y - b.y); d.y = a.y - (b.x - a.x); e.x = d.x + ( b.x - a.x - (a.y - b.y) ) / 2; e.y = d.y - ( b.x - a.x + a.y - b.y ) / 2; if(times>0){ setcolor(rand()%15 + 1); line(a.x,a.y,b.x,b.y); line(c.x,c.y,b.x,b.y); line(c.x,c.y,d.x,d.y); line(a.x,a.y,d.x,d.y); pythagorasTree(d,e,times-1); pythagorasTree(e,c,times-1); } } int main(){ point a,b; double side; int iter; time_t t; printf("Enter initial side length : "); scanf("%lf",&side); printf("Enter number of iterations : "); scanf("%d",&iter); a.x = 6*side/2 - side/2; a.y = 4*side; b.x = 6*side/2 + side/2; b.y = 4*side; initwindow(6*side,4*side,"Pythagoras Tree ?"); srand((unsigned)time(&t)); pythagorasTree(a,b,iter); getch(); closegraph(); return 0; }
Port the following code from Python to C with equivalent syntax and logic.
from sys import stdin, stdout def char_in(): return stdin.read(1) def char_out(c): stdout.write(c) def odd(prev = lambda: None): a = char_in() if not a.isalpha(): prev() char_out(a) return a != '.' def clos(): char_out(a) prev() return odd(clos) def even(): while True: c = char_in() char_out(c) if not c.isalpha(): return c != '.' e = False while odd() if e else even(): e = not e
#include <stdio.h> #include <ctype.h> static int owp(int odd) { int ch, ret; ch = getc(stdin); if (!odd) { putc(ch, stdout); if (ch == EOF || ch == '.') return EOF; if (ispunct(ch)) return 0; owp(odd); return 0; } else { if (ispunct(ch)) return ch; ret = owp(odd); putc(ch, stdout); return ret; } } int main(int argc, char **argv) { int ch = 1; while ((ch = owp(!ch)) != EOF) { if (ch) putc(ch, stdout); if (ch == '.') break; } return 0; }
Convert this Python snippet to C and keep its semantics consistent.
a1 = [0, 1403580, -810728] m1 = 2**32 - 209 a2 = [527612, 0, -1370589] m2 = 2**32 - 22853 d = m1 + 1 class MRG32k3a(): def __init__(self, seed_state=123): self.seed(seed_state) def seed(self, seed_state): assert 0 <seed_state < d, f"Out of Range 0 x < {d}" self.x1 = [seed_state, 0, 0] self.x2 = [seed_state, 0, 0] def next_int(self): "return random int in range 0..d" x1i = sum(aa * xx for aa, xx in zip(a1, self.x1)) % m1 x2i = sum(aa * xx for aa, xx in zip(a2, self.x2)) % m2 self.x1 = [x1i] + self.x1[:2] self.x2 = [x2i] + self.x2[:2] z = (x1i - x2i) % m1 answer = (z + 1) return answer def next_float(self): "return random float between 0 and 1" return self.next_int() / d if __name__ == '__main__': random_gen = MRG32k3a() random_gen.seed(1234567) for i in range(5): print(random_gen.next_int()) random_gen.seed(987654321) hist = {i:0 for i in range(5)} for i in range(100_000): hist[int(random_gen.next_float() *5)] += 1 print(hist)
#include <math.h> #include <stdio.h> #include <stdint.h> int64_t mod(int64_t x, int64_t y) { int64_t m = x % y; if (m < 0) { if (y < 0) { return m - y; } else { return m + y; } } return m; } const static int64_t a1[3] = { 0, 1403580, -810728 }; const static int64_t m1 = (1LL << 32) - 209; const static int64_t a2[3] = { 527612, 0, -1370589 }; const static int64_t m2 = (1LL << 32) - 22853; const static int64_t d = (1LL << 32) - 209 + 1; static int64_t x1[3]; static int64_t x2[3]; void seed(int64_t seed_state) { x1[0] = seed_state; x1[1] = 0; x1[2] = 0; x2[0] = seed_state; x2[1] = 0; x2[2] = 0; } int64_t next_int() { int64_t x1i = mod((a1[0] * x1[0] + a1[1] * x1[1] + a1[2] * x1[2]), m1); int64_t x2i = mod((a2[0] * x2[0] + a2[1] * x2[1] + a2[2] * x2[2]), m2); int64_t z = mod(x1i - x2i, m1); x1[2] = x1[1]; x1[1] = x1[0]; x1[0] = x1i; x2[2] = x2[1]; x2[1] = x2[0]; x2[0] = x2i; return z + 1; } double next_float() { return (double)next_int() / d; } int main() { int counts[5] = { 0, 0, 0, 0, 0 }; int i; seed(1234567); printf("%lld\n", next_int()); printf("%lld\n", next_int()); printf("%lld\n", next_int()); printf("%lld\n", next_int()); printf("%lld\n", next_int()); printf("\n"); seed(987654321); for (i = 0; i < 100000; i++) { int64_t value = floor(next_float() * 5); counts[value]++; } for (i = 0; i < 5; i++) { printf("%d: %d\n", i, counts[i]); } return 0; }
Write the same code in C as shown below in Python.
from math import prod largest = [0] def iscolorful(n): if 0 <= n < 10: return True dig = [int(c) for c in str(n)] if 1 in dig or 0 in dig or len(dig) > len(set(dig)): return False products = list(set(dig)) for i in range(len(dig)): for j in range(i+2, len(dig)+1): p = prod(dig[i:j]) if p in products: return False products.append(p) largest[0] = max(n, largest[0]) return True print('Colorful numbers for 1:25, 26:50, 51:75, and 76:100:') for i in range(1, 101, 25): for j in range(25): if iscolorful(i + j): print(f'{i + j: 5,}', end='') print() csum = 0 for i in range(8): j = 0 if i == 0 else 10**i k = 10**(i+1) - 1 n = sum(iscolorful(x) for x in range(j, k+1)) csum += n print(f'The count of colorful numbers between {j} and {k} is {n}.') print(f'The largest possible colorful number is {largest[0]}.') print(f'The total number of colorful numbers is {csum}.')
#include <locale.h> #include <stdbool.h> #include <stdio.h> #include <time.h> bool colorful(int n) { if (n < 0 || n > 98765432) return false; int digit_count[10] = {}; int digits[8] = {}; int num_digits = 0; for (int m = n; m > 0; m /= 10) { int d = m % 10; if (n > 9 && (d == 0 || d == 1)) return false; if (++digit_count[d] > 1) return false; digits[num_digits++] = d; } int products[36] = {}; for (int i = 0, product_count = 0; i < num_digits; ++i) { for (int j = i, p = 1; j < num_digits; ++j) { p *= digits[j]; for (int k = 0; k < product_count; ++k) { if (products[k] == p) return false; } products[product_count++] = p; } } return true; } static int count[8]; static bool used[10]; static int largest = 0; void count_colorful(int taken, int n, int digits) { if (taken == 0) { for (int d = 0; d < 10; ++d) { used[d] = true; count_colorful(d < 2 ? 9 : 1, d, 1); used[d] = false; } } else { if (colorful(n)) { ++count[digits - 1]; if (n > largest) largest = n; } if (taken < 9) { for (int d = 2; d < 10; ++d) { if (!used[d]) { used[d] = true; count_colorful(taken + 1, n * 10 + d, digits + 1); used[d] = false; } } } } } int main() { setlocale(LC_ALL, ""); clock_t start = clock(); printf("Colorful numbers less than 100:\n"); for (int n = 0, count = 0; n < 100; ++n) { if (colorful(n)) printf("%2d%c", n, ++count % 10 == 0 ? '\n' : ' '); } count_colorful(0, 0, 0); printf("\n\nLargest colorful number: %'d\n", largest); printf("\nCount of colorful numbers by number of digits:\n"); int total = 0; for (int d = 0; d < 8; ++d) { printf("%d  %'d\n", d + 1, count[d]); total += count[d]; } printf("\nTotal: %'d\n", total); clock_t end = clock(); printf("\nElapsed time: %f seconds\n", (end - start + 0.0) / CLOCKS_PER_SEC); return 0; }
Write the same code in C as shown below in Python.
from math import prod largest = [0] def iscolorful(n): if 0 <= n < 10: return True dig = [int(c) for c in str(n)] if 1 in dig or 0 in dig or len(dig) > len(set(dig)): return False products = list(set(dig)) for i in range(len(dig)): for j in range(i+2, len(dig)+1): p = prod(dig[i:j]) if p in products: return False products.append(p) largest[0] = max(n, largest[0]) return True print('Colorful numbers for 1:25, 26:50, 51:75, and 76:100:') for i in range(1, 101, 25): for j in range(25): if iscolorful(i + j): print(f'{i + j: 5,}', end='') print() csum = 0 for i in range(8): j = 0 if i == 0 else 10**i k = 10**(i+1) - 1 n = sum(iscolorful(x) for x in range(j, k+1)) csum += n print(f'The count of colorful numbers between {j} and {k} is {n}.') print(f'The largest possible colorful number is {largest[0]}.') print(f'The total number of colorful numbers is {csum}.')
#include <locale.h> #include <stdbool.h> #include <stdio.h> #include <time.h> bool colorful(int n) { if (n < 0 || n > 98765432) return false; int digit_count[10] = {}; int digits[8] = {}; int num_digits = 0; for (int m = n; m > 0; m /= 10) { int d = m % 10; if (n > 9 && (d == 0 || d == 1)) return false; if (++digit_count[d] > 1) return false; digits[num_digits++] = d; } int products[36] = {}; for (int i = 0, product_count = 0; i < num_digits; ++i) { for (int j = i, p = 1; j < num_digits; ++j) { p *= digits[j]; for (int k = 0; k < product_count; ++k) { if (products[k] == p) return false; } products[product_count++] = p; } } return true; } static int count[8]; static bool used[10]; static int largest = 0; void count_colorful(int taken, int n, int digits) { if (taken == 0) { for (int d = 0; d < 10; ++d) { used[d] = true; count_colorful(d < 2 ? 9 : 1, d, 1); used[d] = false; } } else { if (colorful(n)) { ++count[digits - 1]; if (n > largest) largest = n; } if (taken < 9) { for (int d = 2; d < 10; ++d) { if (!used[d]) { used[d] = true; count_colorful(taken + 1, n * 10 + d, digits + 1); used[d] = false; } } } } } int main() { setlocale(LC_ALL, ""); clock_t start = clock(); printf("Colorful numbers less than 100:\n"); for (int n = 0, count = 0; n < 100; ++n) { if (colorful(n)) printf("%2d%c", n, ++count % 10 == 0 ? '\n' : ' '); } count_colorful(0, 0, 0); printf("\n\nLargest colorful number: %'d\n", largest); printf("\nCount of colorful numbers by number of digits:\n"); int total = 0; for (int d = 0; d < 8; ++d) { printf("%d  %'d\n", d + 1, count[d]); total += count[d]; } printf("\nTotal: %'d\n", total); clock_t end = clock(); printf("\nElapsed time: %f seconds\n", (end - start + 0.0) / CLOCKS_PER_SEC); return 0; }
Write the same algorithm in C as shown in this Python implementation.
from datetime import date, timedelta from math import floor, sin, pi def biorhythms(birthdate,targetdate): print("Born: "+birthdate+" Target: "+targetdate) birthdate = date.fromisoformat(birthdate) targetdate = date.fromisoformat(targetdate) days = (targetdate - birthdate).days print("Day: "+str(days)) cycle_labels = ["Physical", "Emotional", "Mental"] cycle_lengths = [23, 28, 33] quadrants = [("up and rising", "peak"), ("up but falling", "transition"), ("down and falling", "valley"), ("down but rising", "transition")] for i in range(3): label = cycle_labels[i] length = cycle_lengths[i] position = days % length quadrant = int(floor((4 * position) / length)) percentage = int(round(100 * sin(2 * pi * position / length),0)) transition_date = targetdate + timedelta(days=floor((quadrant + 1)/4 * length) - position) trend, next = quadrants[quadrant] if percentage > 95: description = "peak" elif percentage < -95: description = "valley" elif abs(percentage) < 5: description = "critical transition" else: description = str(percentage)+"% ("+trend+", next "+next+" "+str(transition_date)+")" print(label+" day "+str(position)+": "+description) biorhythms("1943-03-09","1972-07-11")
#include <stdio.h> #include <stdlib.h> #include <math.h> int day(int y, int m, int d) { return 367 * y - 7 * (y + (m + 9) / 12) / 4 + 275 * m / 9 + d - 730530; } void cycle(int diff, int l, char *t) { int p = round(100 * sin(2 * M_PI * diff / l)); printf("%12s cycle: %3i%%", t, p); if (abs(p) < 15) printf(" (critical day)"); printf("\n"); } int main(int argc, char *argv[]) { int diff; if (argc < 7) { printf("Usage:\n"); printf("cbio y1 m1 d1 y2 m2 d2\n"); exit(1); } diff = abs(day(atoi(argv[1]), atoi(argv[2]), atoi(argv[3])) - day(atoi(argv[4]), atoi(argv[5]), atoi(argv[6]))); printf("Age: %u days\n", diff); cycle(diff, 23, "Physical"); cycle(diff, 28, "Emotional"); cycle(diff, 33, "Intellectual"); }
Rewrite the snippet below in C so it works the same as the original Python code.
from datetime import date, timedelta from math import floor, sin, pi def biorhythms(birthdate,targetdate): print("Born: "+birthdate+" Target: "+targetdate) birthdate = date.fromisoformat(birthdate) targetdate = date.fromisoformat(targetdate) days = (targetdate - birthdate).days print("Day: "+str(days)) cycle_labels = ["Physical", "Emotional", "Mental"] cycle_lengths = [23, 28, 33] quadrants = [("up and rising", "peak"), ("up but falling", "transition"), ("down and falling", "valley"), ("down but rising", "transition")] for i in range(3): label = cycle_labels[i] length = cycle_lengths[i] position = days % length quadrant = int(floor((4 * position) / length)) percentage = int(round(100 * sin(2 * pi * position / length),0)) transition_date = targetdate + timedelta(days=floor((quadrant + 1)/4 * length) - position) trend, next = quadrants[quadrant] if percentage > 95: description = "peak" elif percentage < -95: description = "valley" elif abs(percentage) < 5: description = "critical transition" else: description = str(percentage)+"% ("+trend+", next "+next+" "+str(transition_date)+")" print(label+" day "+str(position)+": "+description) biorhythms("1943-03-09","1972-07-11")
#include <stdio.h> #include <stdlib.h> #include <math.h> int day(int y, int m, int d) { return 367 * y - 7 * (y + (m + 9) / 12) / 4 + 275 * m / 9 + d - 730530; } void cycle(int diff, int l, char *t) { int p = round(100 * sin(2 * M_PI * diff / l)); printf("%12s cycle: %3i%%", t, p); if (abs(p) < 15) printf(" (critical day)"); printf("\n"); } int main(int argc, char *argv[]) { int diff; if (argc < 7) { printf("Usage:\n"); printf("cbio y1 m1 d1 y2 m2 d2\n"); exit(1); } diff = abs(day(atoi(argv[1]), atoi(argv[2]), atoi(argv[3])) - day(atoi(argv[4]), atoi(argv[5]), atoi(argv[6]))); printf("Age: %u days\n", diff); cycle(diff, 23, "Physical"); cycle(diff, 28, "Emotional"); cycle(diff, 33, "Intellectual"); }
Port the following code from Python to C with equivalent syntax and logic.
>>> import sqlite3 >>> conn = sqlite3.connect(':memory:') >>> conn.execute() <sqlite3.Cursor object at 0x013265C0> >>>
#include <stdio.h> #include <stdlib.h> #include <sqlite3.h> const char *code = "CREATE TABLE address (\n" " addrID INTEGER PRIMARY KEY AUTOINCREMENT,\n" " addrStreet TEXT NOT NULL,\n" " addrCity TEXT NOT NULL,\n" " addrState TEXT NOT NULL,\n" " addrZIP TEXT NOT NULL)\n" ; int main() { sqlite3 *db = NULL; char *errmsg; if ( sqlite3_open("address.db", &db) == SQLITE_OK ) { if ( sqlite3_exec(db, code, NULL, NULL, &errmsg) != SQLITE_OK ) { fprintf(stderr, errmsg); sqlite3_free(errmsg); sqlite3_close(db); exit(EXIT_FAILURE); } sqlite3_close(db); } else { fprintf(stderr, "cannot open db...\n"); sqlite3_close(db); exit(EXIT_FAILURE); } return EXIT_SUCCESS; }