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Keep all operations the same but rewrite the snippet in VB.
fun main(args: Array<String>) { intArrayOf(4, 5, 6).forEach lambda@ { if (it == 5) return@lambda println(it) } println() loop@ for (i in 0 .. 3) { for (j in 0 .. 3) { if (i + j == 4) continue@loop if (i + j == 5) break@loop println(i + j) } } }
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Convert the following code from Scala to Go, ensuring the logic remains intact.
fun main(args: Array<String>) { intArrayOf(4, 5, 6).forEach lambda@ { if (it == 5) return@lambda println(it) } println() loop@ for (i in 0 .. 3) { for (j in 0 .. 3) { if (i + j == 4) continue@loop if (i + j == 5) break@loop println(i + j) } } }
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Maintain the same structure and functionality when rewriting this code in Go.
fun main(args: Array<String>) { intArrayOf(4, 5, 6).forEach lambda@ { if (it == 5) return@lambda println(it) } println() loop@ for (i in 0 .. 3) { for (j in 0 .. 3) { if (i + j == 4) continue@loop if (i + j == 5) break@loop println(i + j) } } }
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Translate the given Ada code snippet into C# without altering its behavior.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Combinations is generic type Integers is range <>; package Combinations is type Combination is array (Positive range <>) of Integers; procedure First (X : in out Combination); procedure Next (X : in out Combination); procedure Put (X : Combination); end Combinations; package body Combinations is procedure First (X : in out Combination) is begin X (1) := Integers'First; for I in 2..X'Last loop X (I) := X (I - 1) + 1; end loop; end First; procedure Next (X : in out Combination) is begin for I in reverse X'Range loop if X (I) < Integers'Val (Integers'Pos (Integers'Last) - X'Last + I) then X (I) := X (I) + 1; for J in I + 1..X'Last loop X (J) := X (J - 1) + 1; end loop; return; end if; end loop; raise Constraint_Error; end Next; procedure Put (X : Combination) is begin for I in X'Range loop Put (Integers'Image (X (I))); end loop; end Put; end Combinations; type Five is range 0..4; package Fives is new Combinations (Five); use Fives; X : Combination (1..3); begin First (X); loop Put (X); New_Line; Next (X); end loop; exception when Constraint_Error => null; end Test_Combinations;
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Produce a functionally identical C code for the snippet given in Ada.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Combinations is generic type Integers is range <>; package Combinations is type Combination is array (Positive range <>) of Integers; procedure First (X : in out Combination); procedure Next (X : in out Combination); procedure Put (X : Combination); end Combinations; package body Combinations is procedure First (X : in out Combination) is begin X (1) := Integers'First; for I in 2..X'Last loop X (I) := X (I - 1) + 1; end loop; end First; procedure Next (X : in out Combination) is begin for I in reverse X'Range loop if X (I) < Integers'Val (Integers'Pos (Integers'Last) - X'Last + I) then X (I) := X (I) + 1; for J in I + 1..X'Last loop X (J) := X (J - 1) + 1; end loop; return; end if; end loop; raise Constraint_Error; end Next; procedure Put (X : Combination) is begin for I in X'Range loop Put (Integers'Image (X (I))); end loop; end Put; end Combinations; type Five is range 0..4; package Fives is new Combinations (Five); use Fives; X : Combination (1..3); begin First (X); loop Put (X); New_Line; Next (X); end loop; exception when Constraint_Error => null; end Test_Combinations;
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Change the following Ada code into C++ without altering its purpose.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Combinations is generic type Integers is range <>; package Combinations is type Combination is array (Positive range <>) of Integers; procedure First (X : in out Combination); procedure Next (X : in out Combination); procedure Put (X : Combination); end Combinations; package body Combinations is procedure First (X : in out Combination) is begin X (1) := Integers'First; for I in 2..X'Last loop X (I) := X (I - 1) + 1; end loop; end First; procedure Next (X : in out Combination) is begin for I in reverse X'Range loop if X (I) < Integers'Val (Integers'Pos (Integers'Last) - X'Last + I) then X (I) := X (I) + 1; for J in I + 1..X'Last loop X (J) := X (J - 1) + 1; end loop; return; end if; end loop; raise Constraint_Error; end Next; procedure Put (X : Combination) is begin for I in X'Range loop Put (Integers'Image (X (I))); end loop; end Put; end Combinations; type Five is range 0..4; package Fives is new Combinations (Five); use Fives; X : Combination (1..3); begin First (X); loop Put (X); New_Line; Next (X); end loop; exception when Constraint_Error => null; end Test_Combinations;
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Convert the following code from Ada to Go, ensuring the logic remains intact.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Combinations is generic type Integers is range <>; package Combinations is type Combination is array (Positive range <>) of Integers; procedure First (X : in out Combination); procedure Next (X : in out Combination); procedure Put (X : Combination); end Combinations; package body Combinations is procedure First (X : in out Combination) is begin X (1) := Integers'First; for I in 2..X'Last loop X (I) := X (I - 1) + 1; end loop; end First; procedure Next (X : in out Combination) is begin for I in reverse X'Range loop if X (I) < Integers'Val (Integers'Pos (Integers'Last) - X'Last + I) then X (I) := X (I) + 1; for J in I + 1..X'Last loop X (J) := X (J - 1) + 1; end loop; return; end if; end loop; raise Constraint_Error; end Next; procedure Put (X : Combination) is begin for I in X'Range loop Put (Integers'Image (X (I))); end loop; end Put; end Combinations; type Five is range 0..4; package Fives is new Combinations (Five); use Fives; X : Combination (1..3); begin First (X); loop Put (X); New_Line; Next (X); end loop; exception when Constraint_Error => null; end Test_Combinations;
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Ensure the translated Java code behaves exactly like the original Ada snippet.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Combinations is generic type Integers is range <>; package Combinations is type Combination is array (Positive range <>) of Integers; procedure First (X : in out Combination); procedure Next (X : in out Combination); procedure Put (X : Combination); end Combinations; package body Combinations is procedure First (X : in out Combination) is begin X (1) := Integers'First; for I in 2..X'Last loop X (I) := X (I - 1) + 1; end loop; end First; procedure Next (X : in out Combination) is begin for I in reverse X'Range loop if X (I) < Integers'Val (Integers'Pos (Integers'Last) - X'Last + I) then X (I) := X (I) + 1; for J in I + 1..X'Last loop X (J) := X (J - 1) + 1; end loop; return; end if; end loop; raise Constraint_Error; end Next; procedure Put (X : Combination) is begin for I in X'Range loop Put (Integers'Image (X (I))); end loop; end Put; end Combinations; type Five is range 0..4; package Fives is new Combinations (Five); use Fives; X : Combination (1..3); begin First (X); loop Put (X); New_Line; Next (X); end loop; exception when Constraint_Error => null; end Test_Combinations;
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Translate this program into Python but keep the logic exactly as in Ada.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Combinations is generic type Integers is range <>; package Combinations is type Combination is array (Positive range <>) of Integers; procedure First (X : in out Combination); procedure Next (X : in out Combination); procedure Put (X : Combination); end Combinations; package body Combinations is procedure First (X : in out Combination) is begin X (1) := Integers'First; for I in 2..X'Last loop X (I) := X (I - 1) + 1; end loop; end First; procedure Next (X : in out Combination) is begin for I in reverse X'Range loop if X (I) < Integers'Val (Integers'Pos (Integers'Last) - X'Last + I) then X (I) := X (I) + 1; for J in I + 1..X'Last loop X (J) := X (J - 1) + 1; end loop; return; end if; end loop; raise Constraint_Error; end Next; procedure Put (X : Combination) is begin for I in X'Range loop Put (Integers'Image (X (I))); end loop; end Put; end Combinations; type Five is range 0..4; package Fives is new Combinations (Five); use Fives; X : Combination (1..3); begin First (X); loop Put (X); New_Line; Next (X); end loop; exception when Constraint_Error => null; end Test_Combinations;
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Ensure the translated VB code behaves exactly like the original Ada snippet.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Combinations is generic type Integers is range <>; package Combinations is type Combination is array (Positive range <>) of Integers; procedure First (X : in out Combination); procedure Next (X : in out Combination); procedure Put (X : Combination); end Combinations; package body Combinations is procedure First (X : in out Combination) is begin X (1) := Integers'First; for I in 2..X'Last loop X (I) := X (I - 1) + 1; end loop; end First; procedure Next (X : in out Combination) is begin for I in reverse X'Range loop if X (I) < Integers'Val (Integers'Pos (Integers'Last) - X'Last + I) then X (I) := X (I) + 1; for J in I + 1..X'Last loop X (J) := X (J - 1) + 1; end loop; return; end if; end loop; raise Constraint_Error; end Next; procedure Put (X : Combination) is begin for I in X'Range loop Put (Integers'Image (X (I))); end loop; end Put; end Combinations; type Five is range 0..4; package Fives is new Combinations (Five); use Fives; X : Combination (1..3); begin First (X); loop Put (X); New_Line; Next (X); end loop; exception when Constraint_Error => null; end Test_Combinations;
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Write the same algorithm in C as shown in this AutoHotKey implementation.
MsgBox % Comb(1,1) MsgBox % Comb(3,3) MsgBox % Comb(3,2) MsgBox % Comb(2,3) MsgBox % Comb(5,3) Comb(n,t) {  IfLess n,%t%, Return Loop %t% c%A_Index% := A_Index i := t+1, c%i% := n+1 Loop { Loop %t% i := t+1-A_Index, c .= c%i% " " c .= "`n"   j := 1, i := 2 Loop If (c%j%+1 = c%i%) c%j% := j, ++j, ++i Else Break If (j > t) Return c c%j% += 1 } }
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Change the programming language of this snippet from AutoHotKey to C# without modifying what it does.
MsgBox % Comb(1,1) MsgBox % Comb(3,3) MsgBox % Comb(3,2) MsgBox % Comb(2,3) MsgBox % Comb(5,3) Comb(n,t) {  IfLess n,%t%, Return Loop %t% c%A_Index% := A_Index i := t+1, c%i% := n+1 Loop { Loop %t% i := t+1-A_Index, c .= c%i% " " c .= "`n"   j := 1, i := 2 Loop If (c%j%+1 = c%i%) c%j% := j, ++j, ++i Else Break If (j > t) Return c c%j% += 1 } }
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Produce a language-to-language conversion: from AutoHotKey to C++, same semantics.
MsgBox % Comb(1,1) MsgBox % Comb(3,3) MsgBox % Comb(3,2) MsgBox % Comb(2,3) MsgBox % Comb(5,3) Comb(n,t) {  IfLess n,%t%, Return Loop %t% c%A_Index% := A_Index i := t+1, c%i% := n+1 Loop { Loop %t% i := t+1-A_Index, c .= c%i% " " c .= "`n"   j := 1, i := 2 Loop If (c%j%+1 = c%i%) c%j% := j, ++j, ++i Else Break If (j > t) Return c c%j% += 1 } }
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Maintain the same structure and functionality when rewriting this code in Java.
MsgBox % Comb(1,1) MsgBox % Comb(3,3) MsgBox % Comb(3,2) MsgBox % Comb(2,3) MsgBox % Comb(5,3) Comb(n,t) {  IfLess n,%t%, Return Loop %t% c%A_Index% := A_Index i := t+1, c%i% := n+1 Loop { Loop %t% i := t+1-A_Index, c .= c%i% " " c .= "`n"   j := 1, i := 2 Loop If (c%j%+1 = c%i%) c%j% := j, ++j, ++i Else Break If (j > t) Return c c%j% += 1 } }
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Produce a language-to-language conversion: from AutoHotKey to Python, same semantics.
MsgBox % Comb(1,1) MsgBox % Comb(3,3) MsgBox % Comb(3,2) MsgBox % Comb(2,3) MsgBox % Comb(5,3) Comb(n,t) {  IfLess n,%t%, Return Loop %t% c%A_Index% := A_Index i := t+1, c%i% := n+1 Loop { Loop %t% i := t+1-A_Index, c .= c%i% " " c .= "`n"   j := 1, i := 2 Loop If (c%j%+1 = c%i%) c%j% := j, ++j, ++i Else Break If (j > t) Return c c%j% += 1 } }
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Translate the given AutoHotKey code snippet into VB without altering its behavior.
MsgBox % Comb(1,1) MsgBox % Comb(3,3) MsgBox % Comb(3,2) MsgBox % Comb(2,3) MsgBox % Comb(5,3) Comb(n,t) {  IfLess n,%t%, Return Loop %t% c%A_Index% := A_Index i := t+1, c%i% := n+1 Loop { Loop %t% i := t+1-A_Index, c .= c%i% " " c .= "`n"   j := 1, i := 2 Loop If (c%j%+1 = c%i%) c%j% := j, ++j, ++i Else Break If (j > t) Return c c%j% += 1 } }
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Maintain the same structure and functionality when rewriting this code in Go.
MsgBox % Comb(1,1) MsgBox % Comb(3,3) MsgBox % Comb(3,2) MsgBox % Comb(2,3) MsgBox % Comb(5,3) Comb(n,t) {  IfLess n,%t%, Return Loop %t% c%A_Index% := A_Index i := t+1, c%i% := n+1 Loop { Loop %t% i := t+1-A_Index, c .= c%i% " " c .= "`n"   j := 1, i := 2 Loop If (c%j%+1 = c%i%) c%j% := j, ++j, ++i Else Break If (j > t) Return c c%j% += 1 } }
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Rewrite the snippet below in C so it works the same as the original AWK code.
BEGIN { if (length(r) == 0) r = 3 if (length(n) == 0) n = 5 for (i=1; i <= r; i++) { A[i] = i if (i < r ) printf i OFS else print i} while (A[1] < n - r + 1) { for (i = r; i >= 1; i--) { if (A[i] < n - r + i) { A[i]++ p = i break}} for (i = p + 1; i <= r; i++) A[i] = A[i - 1] + 1 for (i=1; i <= r; i++) { if (i < r) printf A[i] OFS else print A[i]}} exit}
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Change the following AWK code into C# without altering its purpose.
BEGIN { if (length(r) == 0) r = 3 if (length(n) == 0) n = 5 for (i=1; i <= r; i++) { A[i] = i if (i < r ) printf i OFS else print i} while (A[1] < n - r + 1) { for (i = r; i >= 1; i--) { if (A[i] < n - r + i) { A[i]++ p = i break}} for (i = p + 1; i <= r; i++) A[i] = A[i - 1] + 1 for (i=1; i <= r; i++) { if (i < r) printf A[i] OFS else print A[i]}} exit}
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Produce a language-to-language conversion: from AWK to C++, same semantics.
BEGIN { if (length(r) == 0) r = 3 if (length(n) == 0) n = 5 for (i=1; i <= r; i++) { A[i] = i if (i < r ) printf i OFS else print i} while (A[1] < n - r + 1) { for (i = r; i >= 1; i--) { if (A[i] < n - r + i) { A[i]++ p = i break}} for (i = p + 1; i <= r; i++) A[i] = A[i - 1] + 1 for (i=1; i <= r; i++) { if (i < r) printf A[i] OFS else print A[i]}} exit}
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Change the programming language of this snippet from AWK to Java without modifying what it does.
BEGIN { if (length(r) == 0) r = 3 if (length(n) == 0) n = 5 for (i=1; i <= r; i++) { A[i] = i if (i < r ) printf i OFS else print i} while (A[1] < n - r + 1) { for (i = r; i >= 1; i--) { if (A[i] < n - r + i) { A[i]++ p = i break}} for (i = p + 1; i <= r; i++) A[i] = A[i - 1] + 1 for (i=1; i <= r; i++) { if (i < r) printf A[i] OFS else print A[i]}} exit}
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Change the following AWK code into Python without altering its purpose.
BEGIN { if (length(r) == 0) r = 3 if (length(n) == 0) n = 5 for (i=1; i <= r; i++) { A[i] = i if (i < r ) printf i OFS else print i} while (A[1] < n - r + 1) { for (i = r; i >= 1; i--) { if (A[i] < n - r + i) { A[i]++ p = i break}} for (i = p + 1; i <= r; i++) A[i] = A[i - 1] + 1 for (i=1; i <= r; i++) { if (i < r) printf A[i] OFS else print A[i]}} exit}
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Change the programming language of this snippet from AWK to VB without modifying what it does.
BEGIN { if (length(r) == 0) r = 3 if (length(n) == 0) n = 5 for (i=1; i <= r; i++) { A[i] = i if (i < r ) printf i OFS else print i} while (A[1] < n - r + 1) { for (i = r; i >= 1; i--) { if (A[i] < n - r + i) { A[i]++ p = i break}} for (i = p + 1; i <= r; i++) A[i] = A[i - 1] + 1 for (i=1; i <= r; i++) { if (i < r) printf A[i] OFS else print A[i]}} exit}
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Write the same code in Go as shown below in AWK.
BEGIN { if (length(r) == 0) r = 3 if (length(n) == 0) n = 5 for (i=1; i <= r; i++) { A[i] = i if (i < r ) printf i OFS else print i} while (A[1] < n - r + 1) { for (i = r; i >= 1; i--) { if (A[i] < n - r + i) { A[i]++ p = i break}} for (i = p + 1; i <= r; i++) A[i] = A[i - 1] + 1 for (i=1; i <= r; i++) { if (i < r) printf A[i] OFS else print A[i]}} exit}
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Produce a functionally identical C code for the snippet given in BBC_Basic.
INSTALL @lib$+"SORTLIB" sort% = FN_sortinit(0,0) M% = 3 N% = 5 C% = FNfact(N%)/(FNfact(M%)*FNfact(N%-M%)) DIM s$(C%) PROCcomb(M%, N%, s$()) CALL sort%, s$(0) FOR I% = 0 TO C%-1 PRINT s$(I%) NEXT END DEF PROCcomb(C%, N%, s$()) LOCAL I%, U% FOR U% = 0 TO 2^N%-1 IF FNbits(U%) = C% THEN s$(I%) = FNlist(U%) I% += 1 ENDIF NEXT ENDPROC DEF FNbits(U%) LOCAL N% WHILE U% N% += 1 U% = U% AND (U%-1) ENDWHILE = N% DEF FNlist(U%) LOCAL N%, s$ WHILE U% IF U% AND 1 s$ += STR$(N%) + " " N% += 1 U% = U% >> 1 ENDWHILE = s$ DEF FNfact(N%) IF N%<=1 THEN = 1 ELSE = N%*FNfact(N%-1)
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Rewrite the snippet below in C# so it works the same as the original BBC_Basic code.
INSTALL @lib$+"SORTLIB" sort% = FN_sortinit(0,0) M% = 3 N% = 5 C% = FNfact(N%)/(FNfact(M%)*FNfact(N%-M%)) DIM s$(C%) PROCcomb(M%, N%, s$()) CALL sort%, s$(0) FOR I% = 0 TO C%-1 PRINT s$(I%) NEXT END DEF PROCcomb(C%, N%, s$()) LOCAL I%, U% FOR U% = 0 TO 2^N%-1 IF FNbits(U%) = C% THEN s$(I%) = FNlist(U%) I% += 1 ENDIF NEXT ENDPROC DEF FNbits(U%) LOCAL N% WHILE U% N% += 1 U% = U% AND (U%-1) ENDWHILE = N% DEF FNlist(U%) LOCAL N%, s$ WHILE U% IF U% AND 1 s$ += STR$(N%) + " " N% += 1 U% = U% >> 1 ENDWHILE = s$ DEF FNfact(N%) IF N%<=1 THEN = 1 ELSE = N%*FNfact(N%-1)
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Ensure the translated C++ code behaves exactly like the original BBC_Basic snippet.
INSTALL @lib$+"SORTLIB" sort% = FN_sortinit(0,0) M% = 3 N% = 5 C% = FNfact(N%)/(FNfact(M%)*FNfact(N%-M%)) DIM s$(C%) PROCcomb(M%, N%, s$()) CALL sort%, s$(0) FOR I% = 0 TO C%-1 PRINT s$(I%) NEXT END DEF PROCcomb(C%, N%, s$()) LOCAL I%, U% FOR U% = 0 TO 2^N%-1 IF FNbits(U%) = C% THEN s$(I%) = FNlist(U%) I% += 1 ENDIF NEXT ENDPROC DEF FNbits(U%) LOCAL N% WHILE U% N% += 1 U% = U% AND (U%-1) ENDWHILE = N% DEF FNlist(U%) LOCAL N%, s$ WHILE U% IF U% AND 1 s$ += STR$(N%) + " " N% += 1 U% = U% >> 1 ENDWHILE = s$ DEF FNfact(N%) IF N%<=1 THEN = 1 ELSE = N%*FNfact(N%-1)
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Convert this BBC_Basic snippet to Java and keep its semantics consistent.
INSTALL @lib$+"SORTLIB" sort% = FN_sortinit(0,0) M% = 3 N% = 5 C% = FNfact(N%)/(FNfact(M%)*FNfact(N%-M%)) DIM s$(C%) PROCcomb(M%, N%, s$()) CALL sort%, s$(0) FOR I% = 0 TO C%-1 PRINT s$(I%) NEXT END DEF PROCcomb(C%, N%, s$()) LOCAL I%, U% FOR U% = 0 TO 2^N%-1 IF FNbits(U%) = C% THEN s$(I%) = FNlist(U%) I% += 1 ENDIF NEXT ENDPROC DEF FNbits(U%) LOCAL N% WHILE U% N% += 1 U% = U% AND (U%-1) ENDWHILE = N% DEF FNlist(U%) LOCAL N%, s$ WHILE U% IF U% AND 1 s$ += STR$(N%) + " " N% += 1 U% = U% >> 1 ENDWHILE = s$ DEF FNfact(N%) IF N%<=1 THEN = 1 ELSE = N%*FNfact(N%-1)
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Please provide an equivalent version of this BBC_Basic code in Python.
INSTALL @lib$+"SORTLIB" sort% = FN_sortinit(0,0) M% = 3 N% = 5 C% = FNfact(N%)/(FNfact(M%)*FNfact(N%-M%)) DIM s$(C%) PROCcomb(M%, N%, s$()) CALL sort%, s$(0) FOR I% = 0 TO C%-1 PRINT s$(I%) NEXT END DEF PROCcomb(C%, N%, s$()) LOCAL I%, U% FOR U% = 0 TO 2^N%-1 IF FNbits(U%) = C% THEN s$(I%) = FNlist(U%) I% += 1 ENDIF NEXT ENDPROC DEF FNbits(U%) LOCAL N% WHILE U% N% += 1 U% = U% AND (U%-1) ENDWHILE = N% DEF FNlist(U%) LOCAL N%, s$ WHILE U% IF U% AND 1 s$ += STR$(N%) + " " N% += 1 U% = U% >> 1 ENDWHILE = s$ DEF FNfact(N%) IF N%<=1 THEN = 1 ELSE = N%*FNfact(N%-1)
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Translate this program into VB but keep the logic exactly as in BBC_Basic.
INSTALL @lib$+"SORTLIB" sort% = FN_sortinit(0,0) M% = 3 N% = 5 C% = FNfact(N%)/(FNfact(M%)*FNfact(N%-M%)) DIM s$(C%) PROCcomb(M%, N%, s$()) CALL sort%, s$(0) FOR I% = 0 TO C%-1 PRINT s$(I%) NEXT END DEF PROCcomb(C%, N%, s$()) LOCAL I%, U% FOR U% = 0 TO 2^N%-1 IF FNbits(U%) = C% THEN s$(I%) = FNlist(U%) I% += 1 ENDIF NEXT ENDPROC DEF FNbits(U%) LOCAL N% WHILE U% N% += 1 U% = U% AND (U%-1) ENDWHILE = N% DEF FNlist(U%) LOCAL N%, s$ WHILE U% IF U% AND 1 s$ += STR$(N%) + " " N% += 1 U% = U% >> 1 ENDWHILE = s$ DEF FNfact(N%) IF N%<=1 THEN = 1 ELSE = N%*FNfact(N%-1)
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Translate the given BBC_Basic code snippet into Go without altering its behavior.
INSTALL @lib$+"SORTLIB" sort% = FN_sortinit(0,0) M% = 3 N% = 5 C% = FNfact(N%)/(FNfact(M%)*FNfact(N%-M%)) DIM s$(C%) PROCcomb(M%, N%, s$()) CALL sort%, s$(0) FOR I% = 0 TO C%-1 PRINT s$(I%) NEXT END DEF PROCcomb(C%, N%, s$()) LOCAL I%, U% FOR U% = 0 TO 2^N%-1 IF FNbits(U%) = C% THEN s$(I%) = FNlist(U%) I% += 1 ENDIF NEXT ENDPROC DEF FNbits(U%) LOCAL N% WHILE U% N% += 1 U% = U% AND (U%-1) ENDWHILE = N% DEF FNlist(U%) LOCAL N%, s$ WHILE U% IF U% AND 1 s$ += STR$(N%) + " " N% += 1 U% = U% >> 1 ENDWHILE = s$ DEF FNfact(N%) IF N%<=1 THEN = 1 ELSE = N%*FNfact(N%-1)
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Produce a functionally identical C code for the snippet given in Clojure.
(defn combinations "If m=1, generate a nested list of numbers [0,n) If m>1, for each x in [0,n), and for each list in the recursion on [x+1,n), cons the two" [m n] (letfn [(comb-aux [m start] (if (= 1 m) (for [x (range start n)] (list x)) (for [x (range start n) xs (comb-aux (dec m) (inc x))] (cons x xs))))] (comb-aux m 0))) (defn print-combinations [m n] (doseq [line (combinations m n)] (doseq [n line] (printf "%s " n)) (printf "%n")))
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Keep all operations the same but rewrite the snippet in C#.
(defn combinations "If m=1, generate a nested list of numbers [0,n) If m>1, for each x in [0,n), and for each list in the recursion on [x+1,n), cons the two" [m n] (letfn [(comb-aux [m start] (if (= 1 m) (for [x (range start n)] (list x)) (for [x (range start n) xs (comb-aux (dec m) (inc x))] (cons x xs))))] (comb-aux m 0))) (defn print-combinations [m n] (doseq [line (combinations m n)] (doseq [n line] (printf "%s " n)) (printf "%n")))
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Write a version of this Clojure function in C++ with identical behavior.
(defn combinations "If m=1, generate a nested list of numbers [0,n) If m>1, for each x in [0,n), and for each list in the recursion on [x+1,n), cons the two" [m n] (letfn [(comb-aux [m start] (if (= 1 m) (for [x (range start n)] (list x)) (for [x (range start n) xs (comb-aux (dec m) (inc x))] (cons x xs))))] (comb-aux m 0))) (defn print-combinations [m n] (doseq [line (combinations m n)] (doseq [n line] (printf "%s " n)) (printf "%n")))
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Port the provided Clojure code into Java while preserving the original functionality.
(defn combinations "If m=1, generate a nested list of numbers [0,n) If m>1, for each x in [0,n), and for each list in the recursion on [x+1,n), cons the two" [m n] (letfn [(comb-aux [m start] (if (= 1 m) (for [x (range start n)] (list x)) (for [x (range start n) xs (comb-aux (dec m) (inc x))] (cons x xs))))] (comb-aux m 0))) (defn print-combinations [m n] (doseq [line (combinations m n)] (doseq [n line] (printf "%s " n)) (printf "%n")))
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Convert this Clojure block to Python, preserving its control flow and logic.
(defn combinations "If m=1, generate a nested list of numbers [0,n) If m>1, for each x in [0,n), and for each list in the recursion on [x+1,n), cons the two" [m n] (letfn [(comb-aux [m start] (if (= 1 m) (for [x (range start n)] (list x)) (for [x (range start n) xs (comb-aux (dec m) (inc x))] (cons x xs))))] (comb-aux m 0))) (defn print-combinations [m n] (doseq [line (combinations m n)] (doseq [n line] (printf "%s " n)) (printf "%n")))
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Generate an equivalent VB version of this Clojure code.
(defn combinations "If m=1, generate a nested list of numbers [0,n) If m>1, for each x in [0,n), and for each list in the recursion on [x+1,n), cons the two" [m n] (letfn [(comb-aux [m start] (if (= 1 m) (for [x (range start n)] (list x)) (for [x (range start n) xs (comb-aux (dec m) (inc x))] (cons x xs))))] (comb-aux m 0))) (defn print-combinations [m n] (doseq [line (combinations m n)] (doseq [n line] (printf "%s " n)) (printf "%n")))
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Generate a Go translation of this Clojure snippet without changing its computational steps.
(defn combinations "If m=1, generate a nested list of numbers [0,n) If m>1, for each x in [0,n), and for each list in the recursion on [x+1,n), cons the two" [m n] (letfn [(comb-aux [m start] (if (= 1 m) (for [x (range start n)] (list x)) (for [x (range start n) xs (comb-aux (dec m) (inc x))] (cons x xs))))] (comb-aux m 0))) (defn print-combinations [m n] (doseq [line (combinations m n)] (doseq [n line] (printf "%s " n)) (printf "%n")))
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Rewrite this program in C while keeping its functionality equivalent to the Common_Lisp version.
(defun map-combinations (m n fn) "Call fn with each m combination of the integers from 0 to n-1 as a list. The list may be destroyed after fn returns." (let ((combination (make-list m))) (labels ((up-from (low) (let ((start (1- low))) (lambda () (incf start)))) (mc (curr left needed comb-tail) (cond ((zerop needed) (funcall fn combination)) ((= left needed) (map-into comb-tail (up-from curr)) (funcall fn combination)) (t (setf (first comb-tail) curr) (mc (1+ curr) (1- left) (1- needed) (rest comb-tail)) (mc (1+ curr) (1- left) needed comb-tail))))) (mc 0 n m combination))))
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Translate the given Common_Lisp code snippet into C# without altering its behavior.
(defun map-combinations (m n fn) "Call fn with each m combination of the integers from 0 to n-1 as a list. The list may be destroyed after fn returns." (let ((combination (make-list m))) (labels ((up-from (low) (let ((start (1- low))) (lambda () (incf start)))) (mc (curr left needed comb-tail) (cond ((zerop needed) (funcall fn combination)) ((= left needed) (map-into comb-tail (up-from curr)) (funcall fn combination)) (t (setf (first comb-tail) curr) (mc (1+ curr) (1- left) (1- needed) (rest comb-tail)) (mc (1+ curr) (1- left) needed comb-tail))))) (mc 0 n m combination))))
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Write the same algorithm in C++ as shown in this Common_Lisp implementation.
(defun map-combinations (m n fn) "Call fn with each m combination of the integers from 0 to n-1 as a list. The list may be destroyed after fn returns." (let ((combination (make-list m))) (labels ((up-from (low) (let ((start (1- low))) (lambda () (incf start)))) (mc (curr left needed comb-tail) (cond ((zerop needed) (funcall fn combination)) ((= left needed) (map-into comb-tail (up-from curr)) (funcall fn combination)) (t (setf (first comb-tail) curr) (mc (1+ curr) (1- left) (1- needed) (rest comb-tail)) (mc (1+ curr) (1- left) needed comb-tail))))) (mc 0 n m combination))))
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Port the provided Common_Lisp code into Java while preserving the original functionality.
(defun map-combinations (m n fn) "Call fn with each m combination of the integers from 0 to n-1 as a list. The list may be destroyed after fn returns." (let ((combination (make-list m))) (labels ((up-from (low) (let ((start (1- low))) (lambda () (incf start)))) (mc (curr left needed comb-tail) (cond ((zerop needed) (funcall fn combination)) ((= left needed) (map-into comb-tail (up-from curr)) (funcall fn combination)) (t (setf (first comb-tail) curr) (mc (1+ curr) (1- left) (1- needed) (rest comb-tail)) (mc (1+ curr) (1- left) needed comb-tail))))) (mc 0 n m combination))))
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Write the same code in Python as shown below in Common_Lisp.
(defun map-combinations (m n fn) "Call fn with each m combination of the integers from 0 to n-1 as a list. The list may be destroyed after fn returns." (let ((combination (make-list m))) (labels ((up-from (low) (let ((start (1- low))) (lambda () (incf start)))) (mc (curr left needed comb-tail) (cond ((zerop needed) (funcall fn combination)) ((= left needed) (map-into comb-tail (up-from curr)) (funcall fn combination)) (t (setf (first comb-tail) curr) (mc (1+ curr) (1- left) (1- needed) (rest comb-tail)) (mc (1+ curr) (1- left) needed comb-tail))))) (mc 0 n m combination))))
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Can you help me rewrite this code in VB instead of Common_Lisp, keeping it the same logically?
(defun map-combinations (m n fn) "Call fn with each m combination of the integers from 0 to n-1 as a list. The list may be destroyed after fn returns." (let ((combination (make-list m))) (labels ((up-from (low) (let ((start (1- low))) (lambda () (incf start)))) (mc (curr left needed comb-tail) (cond ((zerop needed) (funcall fn combination)) ((= left needed) (map-into comb-tail (up-from curr)) (funcall fn combination)) (t (setf (first comb-tail) curr) (mc (1+ curr) (1- left) (1- needed) (rest comb-tail)) (mc (1+ curr) (1- left) needed comb-tail))))) (mc 0 n m combination))))
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Ensure the translated Go code behaves exactly like the original Common_Lisp snippet.
(defun map-combinations (m n fn) "Call fn with each m combination of the integers from 0 to n-1 as a list. The list may be destroyed after fn returns." (let ((combination (make-list m))) (labels ((up-from (low) (let ((start (1- low))) (lambda () (incf start)))) (mc (curr left needed comb-tail) (cond ((zerop needed) (funcall fn combination)) ((= left needed) (map-into comb-tail (up-from curr)) (funcall fn combination)) (t (setf (first comb-tail) curr) (mc (1+ curr) (1- left) (1- needed) (rest comb-tail)) (mc (1+ curr) (1- left) needed comb-tail))))) (mc 0 n m combination))))
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Generate a C translation of this D snippet without changing its computational steps.
T[][] comb(T)(in T[] arr, in int k) pure nothrow { if (k == 0) return [[]]; typeof(return) result; foreach (immutable i, immutable x; arr) foreach (suffix; arr[i + 1 .. $].comb(k - 1)) result ~= x ~ suffix; return result; } void main() { import std.stdio; [0, 1, 2, 3].comb(2).writeln; }
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Convert the following code from D to C#, ensuring the logic remains intact.
T[][] comb(T)(in T[] arr, in int k) pure nothrow { if (k == 0) return [[]]; typeof(return) result; foreach (immutable i, immutable x; arr) foreach (suffix; arr[i + 1 .. $].comb(k - 1)) result ~= x ~ suffix; return result; } void main() { import std.stdio; [0, 1, 2, 3].comb(2).writeln; }
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Please provide an equivalent version of this D code in C++.
T[][] comb(T)(in T[] arr, in int k) pure nothrow { if (k == 0) return [[]]; typeof(return) result; foreach (immutable i, immutable x; arr) foreach (suffix; arr[i + 1 .. $].comb(k - 1)) result ~= x ~ suffix; return result; } void main() { import std.stdio; [0, 1, 2, 3].comb(2).writeln; }
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Rewrite the snippet below in Java so it works the same as the original D code.
T[][] comb(T)(in T[] arr, in int k) pure nothrow { if (k == 0) return [[]]; typeof(return) result; foreach (immutable i, immutable x; arr) foreach (suffix; arr[i + 1 .. $].comb(k - 1)) result ~= x ~ suffix; return result; } void main() { import std.stdio; [0, 1, 2, 3].comb(2).writeln; }
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Transform the following D implementation into Python, maintaining the same output and logic.
T[][] comb(T)(in T[] arr, in int k) pure nothrow { if (k == 0) return [[]]; typeof(return) result; foreach (immutable i, immutable x; arr) foreach (suffix; arr[i + 1 .. $].comb(k - 1)) result ~= x ~ suffix; return result; } void main() { import std.stdio; [0, 1, 2, 3].comb(2).writeln; }
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Please provide an equivalent version of this D code in VB.
T[][] comb(T)(in T[] arr, in int k) pure nothrow { if (k == 0) return [[]]; typeof(return) result; foreach (immutable i, immutable x; arr) foreach (suffix; arr[i + 1 .. $].comb(k - 1)) result ~= x ~ suffix; return result; } void main() { import std.stdio; [0, 1, 2, 3].comb(2).writeln; }
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Keep all operations the same but rewrite the snippet in Go.
T[][] comb(T)(in T[] arr, in int k) pure nothrow { if (k == 0) return [[]]; typeof(return) result; foreach (immutable i, immutable x; arr) foreach (suffix; arr[i + 1 .. $].comb(k - 1)) result ~= x ~ suffix; return result; } void main() { import std.stdio; [0, 1, 2, 3].comb(2).writeln; }
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Rewrite this program in C while keeping its functionality equivalent to the Elixir version.
defmodule RC do def comb(0, _), do: [[]] def comb(_, []), do: [] def comb(m, [h|t]) do (for l <- comb(m-1, t), do: [h|l]) ++ comb(m, t) end end {m, n} = {3, 5} list = for i <- 1..n, do: i Enum.each(RC.comb(m, list), fn x -> IO.inspect x end)
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Keep all operations the same but rewrite the snippet in C#.
defmodule RC do def comb(0, _), do: [[]] def comb(_, []), do: [] def comb(m, [h|t]) do (for l <- comb(m-1, t), do: [h|l]) ++ comb(m, t) end end {m, n} = {3, 5} list = for i <- 1..n, do: i Enum.each(RC.comb(m, list), fn x -> IO.inspect x end)
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Write the same algorithm in C++ as shown in this Elixir implementation.
defmodule RC do def comb(0, _), do: [[]] def comb(_, []), do: [] def comb(m, [h|t]) do (for l <- comb(m-1, t), do: [h|l]) ++ comb(m, t) end end {m, n} = {3, 5} list = for i <- 1..n, do: i Enum.each(RC.comb(m, list), fn x -> IO.inspect x end)
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Translate the given Elixir code snippet into Java without altering its behavior.
defmodule RC do def comb(0, _), do: [[]] def comb(_, []), do: [] def comb(m, [h|t]) do (for l <- comb(m-1, t), do: [h|l]) ++ comb(m, t) end end {m, n} = {3, 5} list = for i <- 1..n, do: i Enum.each(RC.comb(m, list), fn x -> IO.inspect x end)
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Write the same algorithm in Python as shown in this Elixir implementation.
defmodule RC do def comb(0, _), do: [[]] def comb(_, []), do: [] def comb(m, [h|t]) do (for l <- comb(m-1, t), do: [h|l]) ++ comb(m, t) end end {m, n} = {3, 5} list = for i <- 1..n, do: i Enum.each(RC.comb(m, list), fn x -> IO.inspect x end)
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Rewrite this program in VB while keeping its functionality equivalent to the Elixir version.
defmodule RC do def comb(0, _), do: [[]] def comb(_, []), do: [] def comb(m, [h|t]) do (for l <- comb(m-1, t), do: [h|l]) ++ comb(m, t) end end {m, n} = {3, 5} list = for i <- 1..n, do: i Enum.each(RC.comb(m, list), fn x -> IO.inspect x end)
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Convert this Elixir block to Go, preserving its control flow and logic.
defmodule RC do def comb(0, _), do: [[]] def comb(_, []), do: [] def comb(m, [h|t]) do (for l <- comb(m-1, t), do: [h|l]) ++ comb(m, t) end end {m, n} = {3, 5} list = for i <- 1..n, do: i Enum.each(RC.comb(m, list), fn x -> IO.inspect x end)
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Change the following Erlang code into C without altering its purpose.
-module(comb). -compile(export_all). comb(0,_) -> [[]]; comb(_,[]) -> []; comb(N,[H|T]) -> [[H|L] || L <- comb(N-1,T)]++comb(N,T).
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Port the following code from Erlang to C# with equivalent syntax and logic.
-module(comb). -compile(export_all). comb(0,_) -> [[]]; comb(_,[]) -> []; comb(N,[H|T]) -> [[H|L] || L <- comb(N-1,T)]++comb(N,T).
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Convert this Erlang block to C++, preserving its control flow and logic.
-module(comb). -compile(export_all). comb(0,_) -> [[]]; comb(_,[]) -> []; comb(N,[H|T]) -> [[H|L] || L <- comb(N-1,T)]++comb(N,T).
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Keep all operations the same but rewrite the snippet in Java.
-module(comb). -compile(export_all). comb(0,_) -> [[]]; comb(_,[]) -> []; comb(N,[H|T]) -> [[H|L] || L <- comb(N-1,T)]++comb(N,T).
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Produce a functionally identical Python code for the snippet given in Erlang.
-module(comb). -compile(export_all). comb(0,_) -> [[]]; comb(_,[]) -> []; comb(N,[H|T]) -> [[H|L] || L <- comb(N-1,T)]++comb(N,T).
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Produce a functionally identical VB code for the snippet given in Erlang.
-module(comb). -compile(export_all). comb(0,_) -> [[]]; comb(_,[]) -> []; comb(N,[H|T]) -> [[H|L] || L <- comb(N-1,T)]++comb(N,T).
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Maintain the same structure and functionality when rewriting this code in Go.
-module(comb). -compile(export_all). comb(0,_) -> [[]]; comb(_,[]) -> []; comb(N,[H|T]) -> [[H|L] || L <- comb(N-1,T)]++comb(N,T).
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Can you help me rewrite this code in C instead of F#, keeping it the same logically?
let choose m n = let rec fC prefix m from = seq { let rec loopFor f = seq { match f with | [] -> () | x::xs -> yield (x, fC [] (m-1) xs) yield! loopFor xs } if m = 0 then yield prefix else for (i, s) in loopFor from do for x in s do yield prefix@[i]@x } fC [] m [0..(n-1)] [<EntryPoint>] let main argv = choose 3 5 |> Seq.iter (printfn "%A") 0
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Please provide an equivalent version of this F# code in C#.
let choose m n = let rec fC prefix m from = seq { let rec loopFor f = seq { match f with | [] -> () | x::xs -> yield (x, fC [] (m-1) xs) yield! loopFor xs } if m = 0 then yield prefix else for (i, s) in loopFor from do for x in s do yield prefix@[i]@x } fC [] m [0..(n-1)] [<EntryPoint>] let main argv = choose 3 5 |> Seq.iter (printfn "%A") 0
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Change the following F# code into C++ without altering its purpose.
let choose m n = let rec fC prefix m from = seq { let rec loopFor f = seq { match f with | [] -> () | x::xs -> yield (x, fC [] (m-1) xs) yield! loopFor xs } if m = 0 then yield prefix else for (i, s) in loopFor from do for x in s do yield prefix@[i]@x } fC [] m [0..(n-1)] [<EntryPoint>] let main argv = choose 3 5 |> Seq.iter (printfn "%A") 0
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Transform the following F# implementation into Java, maintaining the same output and logic.
let choose m n = let rec fC prefix m from = seq { let rec loopFor f = seq { match f with | [] -> () | x::xs -> yield (x, fC [] (m-1) xs) yield! loopFor xs } if m = 0 then yield prefix else for (i, s) in loopFor from do for x in s do yield prefix@[i]@x } fC [] m [0..(n-1)] [<EntryPoint>] let main argv = choose 3 5 |> Seq.iter (printfn "%A") 0
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Convert the following code from F# to Python, ensuring the logic remains intact.
let choose m n = let rec fC prefix m from = seq { let rec loopFor f = seq { match f with | [] -> () | x::xs -> yield (x, fC [] (m-1) xs) yield! loopFor xs } if m = 0 then yield prefix else for (i, s) in loopFor from do for x in s do yield prefix@[i]@x } fC [] m [0..(n-1)] [<EntryPoint>] let main argv = choose 3 5 |> Seq.iter (printfn "%A") 0
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Maintain the same structure and functionality when rewriting this code in VB.
let choose m n = let rec fC prefix m from = seq { let rec loopFor f = seq { match f with | [] -> () | x::xs -> yield (x, fC [] (m-1) xs) yield! loopFor xs } if m = 0 then yield prefix else for (i, s) in loopFor from do for x in s do yield prefix@[i]@x } fC [] m [0..(n-1)] [<EntryPoint>] let main argv = choose 3 5 |> Seq.iter (printfn "%A") 0
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Produce a functionally identical Go code for the snippet given in F#.
let choose m n = let rec fC prefix m from = seq { let rec loopFor f = seq { match f with | [] -> () | x::xs -> yield (x, fC [] (m-1) xs) yield! loopFor xs } if m = 0 then yield prefix else for (i, s) in loopFor from do for x in s do yield prefix@[i]@x } fC [] m [0..(n-1)] [<EntryPoint>] let main argv = choose 3 5 |> Seq.iter (printfn "%A") 0
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Produce a functionally identical C code for the snippet given in Factor.
USING: math.combinatorics prettyprint ; 5 iota 3 all-combinations .
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Write the same algorithm in C# as shown in this Factor implementation.
USING: math.combinatorics prettyprint ; 5 iota 3 all-combinations .
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Write a version of this Factor function in C++ with identical behavior.
USING: math.combinatorics prettyprint ; 5 iota 3 all-combinations .
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Port the following code from Factor to Java with equivalent syntax and logic.
USING: math.combinatorics prettyprint ; 5 iota 3 all-combinations .
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Maintain the same structure and functionality when rewriting this code in Python.
USING: math.combinatorics prettyprint ; 5 iota 3 all-combinations .
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Transform the following Factor implementation into VB, maintaining the same output and logic.
USING: math.combinatorics prettyprint ; 5 iota 3 all-combinations .
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Transform the following Factor implementation into Go, maintaining the same output and logic.
USING: math.combinatorics prettyprint ; 5 iota 3 all-combinations .
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Translate the given Fortran code snippet into C# without altering its behavior.
program Combinations use iso_fortran_env implicit none type comb_result integer, dimension(:), allocatable :: combs end type comb_result type(comb_result), dimension(:), pointer :: r integer :: i, j call comb(5, 3, r) do i = 0, choose(5, 3) - 1 do j = 2, 0, -1 write(*, "(I4, ' ')", advance="no") r(i)%combs(j) end do deallocate(r(i)%combs) write(*,*) "" end do deallocate(r) contains function choose(n, k, err) integer :: choose integer, intent(in) :: n, k integer, optional, intent(out) :: err integer :: imax, i, imin, ie ie = 0 if ( (n < 0 ) .or. (k < 0 ) ) then write(ERROR_UNIT, *) "negative in choose" choose = 0 ie = 1 else if ( n < k ) then choose = 0 else if ( n == k ) then choose = 1 else imax = max(k, n-k) imin = min(k, n-k) choose = 1 do i = imax+1, n choose = choose * i end do do i = 2, imin choose = choose / i end do end if end if if ( present(err) ) err = ie end function choose subroutine comb(n, k, co) integer, intent(in) :: n, k type(comb_result), dimension(:), pointer, intent(out) :: co integer :: i, j, s, ix, kx, hm, t integer :: err hm = choose(n, k, err) if ( err /= 0 ) then nullify(co) return end if allocate(co(0:hm-1)) do i = 0, hm-1 allocate(co(i)%combs(0:k-1)) end do do i = 0, hm-1 ix = i; kx = k do s = 0, n-1 if ( kx == 0 ) exit t = choose(n-(s+1), kx-1) if ( ix < t ) then co(i)%combs(kx-1) = s kx = kx - 1 else ix = ix - t end if end do end do end subroutine comb end program Combinations
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Rewrite this program in C++ while keeping its functionality equivalent to the Fortran version.
program Combinations use iso_fortran_env implicit none type comb_result integer, dimension(:), allocatable :: combs end type comb_result type(comb_result), dimension(:), pointer :: r integer :: i, j call comb(5, 3, r) do i = 0, choose(5, 3) - 1 do j = 2, 0, -1 write(*, "(I4, ' ')", advance="no") r(i)%combs(j) end do deallocate(r(i)%combs) write(*,*) "" end do deallocate(r) contains function choose(n, k, err) integer :: choose integer, intent(in) :: n, k integer, optional, intent(out) :: err integer :: imax, i, imin, ie ie = 0 if ( (n < 0 ) .or. (k < 0 ) ) then write(ERROR_UNIT, *) "negative in choose" choose = 0 ie = 1 else if ( n < k ) then choose = 0 else if ( n == k ) then choose = 1 else imax = max(k, n-k) imin = min(k, n-k) choose = 1 do i = imax+1, n choose = choose * i end do do i = 2, imin choose = choose / i end do end if end if if ( present(err) ) err = ie end function choose subroutine comb(n, k, co) integer, intent(in) :: n, k type(comb_result), dimension(:), pointer, intent(out) :: co integer :: i, j, s, ix, kx, hm, t integer :: err hm = choose(n, k, err) if ( err /= 0 ) then nullify(co) return end if allocate(co(0:hm-1)) do i = 0, hm-1 allocate(co(i)%combs(0:k-1)) end do do i = 0, hm-1 ix = i; kx = k do s = 0, n-1 if ( kx == 0 ) exit t = choose(n-(s+1), kx-1) if ( ix < t ) then co(i)%combs(kx-1) = s kx = kx - 1 else ix = ix - t end if end do end do end subroutine comb end program Combinations
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Rewrite the snippet below in C so it works the same as the original Fortran code.
program Combinations use iso_fortran_env implicit none type comb_result integer, dimension(:), allocatable :: combs end type comb_result type(comb_result), dimension(:), pointer :: r integer :: i, j call comb(5, 3, r) do i = 0, choose(5, 3) - 1 do j = 2, 0, -1 write(*, "(I4, ' ')", advance="no") r(i)%combs(j) end do deallocate(r(i)%combs) write(*,*) "" end do deallocate(r) contains function choose(n, k, err) integer :: choose integer, intent(in) :: n, k integer, optional, intent(out) :: err integer :: imax, i, imin, ie ie = 0 if ( (n < 0 ) .or. (k < 0 ) ) then write(ERROR_UNIT, *) "negative in choose" choose = 0 ie = 1 else if ( n < k ) then choose = 0 else if ( n == k ) then choose = 1 else imax = max(k, n-k) imin = min(k, n-k) choose = 1 do i = imax+1, n choose = choose * i end do do i = 2, imin choose = choose / i end do end if end if if ( present(err) ) err = ie end function choose subroutine comb(n, k, co) integer, intent(in) :: n, k type(comb_result), dimension(:), pointer, intent(out) :: co integer :: i, j, s, ix, kx, hm, t integer :: err hm = choose(n, k, err) if ( err /= 0 ) then nullify(co) return end if allocate(co(0:hm-1)) do i = 0, hm-1 allocate(co(i)%combs(0:k-1)) end do do i = 0, hm-1 ix = i; kx = k do s = 0, n-1 if ( kx == 0 ) exit t = choose(n-(s+1), kx-1) if ( ix < t ) then co(i)%combs(kx-1) = s kx = kx - 1 else ix = ix - t end if end do end do end subroutine comb end program Combinations
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Translate the given Fortran code snippet into Go without altering its behavior.
program Combinations use iso_fortran_env implicit none type comb_result integer, dimension(:), allocatable :: combs end type comb_result type(comb_result), dimension(:), pointer :: r integer :: i, j call comb(5, 3, r) do i = 0, choose(5, 3) - 1 do j = 2, 0, -1 write(*, "(I4, ' ')", advance="no") r(i)%combs(j) end do deallocate(r(i)%combs) write(*,*) "" end do deallocate(r) contains function choose(n, k, err) integer :: choose integer, intent(in) :: n, k integer, optional, intent(out) :: err integer :: imax, i, imin, ie ie = 0 if ( (n < 0 ) .or. (k < 0 ) ) then write(ERROR_UNIT, *) "negative in choose" choose = 0 ie = 1 else if ( n < k ) then choose = 0 else if ( n == k ) then choose = 1 else imax = max(k, n-k) imin = min(k, n-k) choose = 1 do i = imax+1, n choose = choose * i end do do i = 2, imin choose = choose / i end do end if end if if ( present(err) ) err = ie end function choose subroutine comb(n, k, co) integer, intent(in) :: n, k type(comb_result), dimension(:), pointer, intent(out) :: co integer :: i, j, s, ix, kx, hm, t integer :: err hm = choose(n, k, err) if ( err /= 0 ) then nullify(co) return end if allocate(co(0:hm-1)) do i = 0, hm-1 allocate(co(i)%combs(0:k-1)) end do do i = 0, hm-1 ix = i; kx = k do s = 0, n-1 if ( kx == 0 ) exit t = choose(n-(s+1), kx-1) if ( ix < t ) then co(i)%combs(kx-1) = s kx = kx - 1 else ix = ix - t end if end do end do end subroutine comb end program Combinations
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Maintain the same structure and functionality when rewriting this code in Java.
program Combinations use iso_fortran_env implicit none type comb_result integer, dimension(:), allocatable :: combs end type comb_result type(comb_result), dimension(:), pointer :: r integer :: i, j call comb(5, 3, r) do i = 0, choose(5, 3) - 1 do j = 2, 0, -1 write(*, "(I4, ' ')", advance="no") r(i)%combs(j) end do deallocate(r(i)%combs) write(*,*) "" end do deallocate(r) contains function choose(n, k, err) integer :: choose integer, intent(in) :: n, k integer, optional, intent(out) :: err integer :: imax, i, imin, ie ie = 0 if ( (n < 0 ) .or. (k < 0 ) ) then write(ERROR_UNIT, *) "negative in choose" choose = 0 ie = 1 else if ( n < k ) then choose = 0 else if ( n == k ) then choose = 1 else imax = max(k, n-k) imin = min(k, n-k) choose = 1 do i = imax+1, n choose = choose * i end do do i = 2, imin choose = choose / i end do end if end if if ( present(err) ) err = ie end function choose subroutine comb(n, k, co) integer, intent(in) :: n, k type(comb_result), dimension(:), pointer, intent(out) :: co integer :: i, j, s, ix, kx, hm, t integer :: err hm = choose(n, k, err) if ( err /= 0 ) then nullify(co) return end if allocate(co(0:hm-1)) do i = 0, hm-1 allocate(co(i)%combs(0:k-1)) end do do i = 0, hm-1 ix = i; kx = k do s = 0, n-1 if ( kx == 0 ) exit t = choose(n-(s+1), kx-1) if ( ix < t ) then co(i)%combs(kx-1) = s kx = kx - 1 else ix = ix - t end if end do end do end subroutine comb end program Combinations
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Generate an equivalent Python version of this Fortran code.
program Combinations use iso_fortran_env implicit none type comb_result integer, dimension(:), allocatable :: combs end type comb_result type(comb_result), dimension(:), pointer :: r integer :: i, j call comb(5, 3, r) do i = 0, choose(5, 3) - 1 do j = 2, 0, -1 write(*, "(I4, ' ')", advance="no") r(i)%combs(j) end do deallocate(r(i)%combs) write(*,*) "" end do deallocate(r) contains function choose(n, k, err) integer :: choose integer, intent(in) :: n, k integer, optional, intent(out) :: err integer :: imax, i, imin, ie ie = 0 if ( (n < 0 ) .or. (k < 0 ) ) then write(ERROR_UNIT, *) "negative in choose" choose = 0 ie = 1 else if ( n < k ) then choose = 0 else if ( n == k ) then choose = 1 else imax = max(k, n-k) imin = min(k, n-k) choose = 1 do i = imax+1, n choose = choose * i end do do i = 2, imin choose = choose / i end do end if end if if ( present(err) ) err = ie end function choose subroutine comb(n, k, co) integer, intent(in) :: n, k type(comb_result), dimension(:), pointer, intent(out) :: co integer :: i, j, s, ix, kx, hm, t integer :: err hm = choose(n, k, err) if ( err /= 0 ) then nullify(co) return end if allocate(co(0:hm-1)) do i = 0, hm-1 allocate(co(i)%combs(0:k-1)) end do do i = 0, hm-1 ix = i; kx = k do s = 0, n-1 if ( kx == 0 ) exit t = choose(n-(s+1), kx-1) if ( ix < t ) then co(i)%combs(kx-1) = s kx = kx - 1 else ix = ix - t end if end do end do end subroutine comb end program Combinations
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Produce a functionally identical VB code for the snippet given in Fortran.
program Combinations use iso_fortran_env implicit none type comb_result integer, dimension(:), allocatable :: combs end type comb_result type(comb_result), dimension(:), pointer :: r integer :: i, j call comb(5, 3, r) do i = 0, choose(5, 3) - 1 do j = 2, 0, -1 write(*, "(I4, ' ')", advance="no") r(i)%combs(j) end do deallocate(r(i)%combs) write(*,*) "" end do deallocate(r) contains function choose(n, k, err) integer :: choose integer, intent(in) :: n, k integer, optional, intent(out) :: err integer :: imax, i, imin, ie ie = 0 if ( (n < 0 ) .or. (k < 0 ) ) then write(ERROR_UNIT, *) "negative in choose" choose = 0 ie = 1 else if ( n < k ) then choose = 0 else if ( n == k ) then choose = 1 else imax = max(k, n-k) imin = min(k, n-k) choose = 1 do i = imax+1, n choose = choose * i end do do i = 2, imin choose = choose / i end do end if end if if ( present(err) ) err = ie end function choose subroutine comb(n, k, co) integer, intent(in) :: n, k type(comb_result), dimension(:), pointer, intent(out) :: co integer :: i, j, s, ix, kx, hm, t integer :: err hm = choose(n, k, err) if ( err /= 0 ) then nullify(co) return end if allocate(co(0:hm-1)) do i = 0, hm-1 allocate(co(i)%combs(0:k-1)) end do do i = 0, hm-1 ix = i; kx = k do s = 0, n-1 if ( kx == 0 ) exit t = choose(n-(s+1), kx-1) if ( ix < t ) then co(i)%combs(kx-1) = s kx = kx - 1 else ix = ix - t end if end do end do end subroutine comb end program Combinations
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Rewrite this program in PHP while keeping its functionality equivalent to the Fortran version.
program Combinations use iso_fortran_env implicit none type comb_result integer, dimension(:), allocatable :: combs end type comb_result type(comb_result), dimension(:), pointer :: r integer :: i, j call comb(5, 3, r) do i = 0, choose(5, 3) - 1 do j = 2, 0, -1 write(*, "(I4, ' ')", advance="no") r(i)%combs(j) end do deallocate(r(i)%combs) write(*,*) "" end do deallocate(r) contains function choose(n, k, err) integer :: choose integer, intent(in) :: n, k integer, optional, intent(out) :: err integer :: imax, i, imin, ie ie = 0 if ( (n < 0 ) .or. (k < 0 ) ) then write(ERROR_UNIT, *) "negative in choose" choose = 0 ie = 1 else if ( n < k ) then choose = 0 else if ( n == k ) then choose = 1 else imax = max(k, n-k) imin = min(k, n-k) choose = 1 do i = imax+1, n choose = choose * i end do do i = 2, imin choose = choose / i end do end if end if if ( present(err) ) err = ie end function choose subroutine comb(n, k, co) integer, intent(in) :: n, k type(comb_result), dimension(:), pointer, intent(out) :: co integer :: i, j, s, ix, kx, hm, t integer :: err hm = choose(n, k, err) if ( err /= 0 ) then nullify(co) return end if allocate(co(0:hm-1)) do i = 0, hm-1 allocate(co(i)%combs(0:k-1)) end do do i = 0, hm-1 ix = i; kx = k do s = 0, n-1 if ( kx == 0 ) exit t = choose(n-(s+1), kx-1) if ( ix < t ) then co(i)%combs(kx-1) = s kx = kx - 1 else ix = ix - t end if end do end do end subroutine comb end program Combinations
<?php $a=array(1,2,3,4,5); $k=3; $n=5; $c=array_splice($a, $k); $b=array_splice($a, 0, $k); $j=$k-1; print_r($b); while (1) { $m=array_search($b[$j]+1,$c); if ($m!==false) { $c[$m]-=1; $b[$j]=$b[$j]+1; print_r($b); } if ($b[$k-1]==$n) { $i=$k-1; while ($i >= 0) { if ($i == 0 && $b[$i] == $n-$k+1) break 2; $m=array_search($b[$i]+1,$c); if ($m!==false) { $c[$m]=$c[$m]-1; $b[$i]=$b[$i]+1; $g=$i; while ($g != $k-1) { array_unshift ($c, $b[$g+1]); $b[$g+1]=$b[$g]+1; $g++; } $c=array_diff($c,$b); print_r($b); break; } $i--; } } } ?>
Rewrite this program in C while keeping its functionality equivalent to the Groovy version.
def comb comb = { m, list -> def n = list.size() m == 0 ? [[]] : (0..(n-m)).inject([]) { newlist, k -> def sublist = (k+1 == n) ? [] : list[(k+1)..<n] newlist += comb(m-1, sublist).collect { [list[k]] + it } } }
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Port the provided Groovy code into C# while preserving the original functionality.
def comb comb = { m, list -> def n = list.size() m == 0 ? [[]] : (0..(n-m)).inject([]) { newlist, k -> def sublist = (k+1 == n) ? [] : list[(k+1)..<n] newlist += comb(m-1, sublist).collect { [list[k]] + it } } }
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Convert this Groovy block to C++, preserving its control flow and logic.
def comb comb = { m, list -> def n = list.size() m == 0 ? [[]] : (0..(n-m)).inject([]) { newlist, k -> def sublist = (k+1 == n) ? [] : list[(k+1)..<n] newlist += comb(m-1, sublist).collect { [list[k]] + it } } }
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Ensure the translated Java code behaves exactly like the original Groovy snippet.
def comb comb = { m, list -> def n = list.size() m == 0 ? [[]] : (0..(n-m)).inject([]) { newlist, k -> def sublist = (k+1 == n) ? [] : list[(k+1)..<n] newlist += comb(m-1, sublist).collect { [list[k]] + it } } }
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Translate the given Groovy code snippet into Python without altering its behavior.
def comb comb = { m, list -> def n = list.size() m == 0 ? [[]] : (0..(n-m)).inject([]) { newlist, k -> def sublist = (k+1 == n) ? [] : list[(k+1)..<n] newlist += comb(m-1, sublist).collect { [list[k]] + it } } }
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Change the programming language of this snippet from Groovy to VB without modifying what it does.
def comb comb = { m, list -> def n = list.size() m == 0 ? [[]] : (0..(n-m)).inject([]) { newlist, k -> def sublist = (k+1 == n) ? [] : list[(k+1)..<n] newlist += comb(m-1, sublist).collect { [list[k]] + it } } }
input "Enter n comb m. ", n input m outstr$ = "" call iterate (outstr$, 0, m-1, n-1) end subroutine iterate (curr$, start, stp, depth) for i = start to stp if depth = 0 then print curr$ + " " + string(i) call iterate (curr$ + " " + string(i), i+1, stp, depth-1) next i end subroutine
Generate a Go translation of this Groovy snippet without changing its computational steps.
def comb comb = { m, list -> def n = list.size() m == 0 ? [[]] : (0..(n-m)).inject([]) { newlist, k -> def sublist = (k+1 == n) ? [] : list[(k+1)..<n] newlist += comb(m-1, sublist).collect { [list[k]] + it } } }
package main import ( "fmt" ) func main() { comb(5, 3, func(c []int) { fmt.Println(c) }) } func comb(n, m int, emit func([]int)) { s := make([]int, m) last := m - 1 var rc func(int, int) rc = func(i, next int) { for j := next; j < n; j++ { s[i] = j if i == last { emit(s) } else { rc(i+1, j+1) } } return } rc(0, 0) }
Rewrite this program in C while keeping its functionality equivalent to the Haskell version.
comb :: Int -> [a] -> [[a]] comb 0 _ = [[]] comb _ [] = [] comb m (x:xs) = map (x:) (comb (m-1) xs) ++ comb m xs
#include <stdio.h> typedef unsigned long marker; marker one = 1; void comb(int pool, int need, marker chosen, int at) { if (pool < need + at) return; if (!need) { for (at = 0; at < pool; at++) if (chosen & (one << at)) printf("%d ", at); printf("\n"); return; } comb(pool, need - 1, chosen | (one << at), at + 1); comb(pool, need, chosen, at + 1); } int main() { comb(5, 3, 0, 0); return 0; }
Rewrite the snippet below in C# so it works the same as the original Haskell code.
comb :: Int -> [a] -> [[a]] comb 0 _ = [[]] comb _ [] = [] comb m (x:xs) = map (x:) (comb (m-1) xs) ++ comb m xs
using System; using System.Collections.Generic; public class Program { public static IEnumerable<int[]> Combinations(int m, int n) { int[] result = new int[m]; Stack<int> stack = new Stack<int>(); stack.Push(0); while (stack.Count > 0) { int index = stack.Count - 1; int value = stack.Pop(); while (value < n) { result[index++] = ++value; stack.Push(value); if (index == m) { yield return result; break; } } } } static void Main() { foreach (int[] c in Combinations(3, 5)) { Console.WriteLine(string.Join(",", c)); Console.WriteLine(); } } }
Port the following code from Haskell to C++ with equivalent syntax and logic.
comb :: Int -> [a] -> [[a]] comb 0 _ = [[]] comb _ [] = [] comb m (x:xs) = map (x:) (comb (m-1) xs) ++ comb m xs
#include <algorithm> #include <iostream> #include <string> void comb(int N, int K) { std::string bitmask(K, 1); bitmask.resize(N, 0); do { for (int i = 0; i < N; ++i) { if (bitmask[i]) std::cout << " " << i; } std::cout << std::endl; } while (std::prev_permutation(bitmask.begin(), bitmask.end())); } int main() { comb(5, 3); }
Generate a Java translation of this Haskell snippet without changing its computational steps.
comb :: Int -> [a] -> [[a]] comb 0 _ = [[]] comb _ [] = [] comb m (x:xs) = map (x:) (comb (m-1) xs) ++ comb m xs
import java.util.Collections; import java.util.LinkedList; public class Comb{ public static void main(String[] args){ System.out.println(comb(3,5)); } public static String bitprint(int u){ String s= ""; for(int n= 0;u > 0;++n, u>>= 1) if((u & 1) > 0) s+= n + " "; return s; } public static int bitcount(int u){ int n; for(n= 0;u > 0;++n, u&= (u - 1)); return n; } public static LinkedList<String> comb(int c, int n){ LinkedList<String> s= new LinkedList<String>(); for(int u= 0;u < 1 << n;u++) if(bitcount(u) == c) s.push(bitprint(u)); Collections.sort(s); return s; } }
Maintain the same structure and functionality when rewriting this code in Python.
comb :: Int -> [a] -> [[a]] comb 0 _ = [[]] comb _ [] = [] comb m (x:xs) = map (x:) (comb (m-1) xs) ++ comb m xs
>>> from itertools import combinations >>> list(combinations(range(5),3)) [(0, 1, 2), (0, 1, 3), (0, 1, 4), (0, 2, 3), (0, 2, 4), (0, 3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]