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Change the programming language of this snippet from Delphi to C++ without modifying what it does.
var x: Integer = 5; label positive, negative, both; begin if (x > 0) then goto positive else goto negative; positive: writeln('pos'); goto both; negative: writeln('neg'); both: readln; end.
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Keep all operations the same but rewrite the snippet in C++.
var x: Integer = 5; label positive, negative, both; begin if (x > 0) then goto positive else goto negative; positive: writeln('pos'); goto both; negative: writeln('neg'); both: readln; end.
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Write a version of this Delphi function in Java with identical behavior.
var x: Integer = 5; label positive, negative, both; begin if (x > 0) then goto positive else goto negative; positive: writeln('pos'); goto both; negative: writeln('neg'); both: readln; end.
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Generate an equivalent Java version of this Delphi code.
var x: Integer = 5; label positive, negative, both; begin if (x > 0) then goto positive else goto negative; positive: writeln('pos'); goto both; negative: writeln('neg'); both: readln; end.
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Maintain the same structure and functionality when rewriting this code in Python.
var x: Integer = 5; label positive, negative, both; begin if (x > 0) then goto positive else goto negative; positive: writeln('pos'); goto both; negative: writeln('neg'); both: readln; end.
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Convert this Delphi snippet to Python and keep its semantics consistent.
var x: Integer = 5; label positive, negative, both; begin if (x > 0) then goto positive else goto negative; positive: writeln('pos'); goto both; negative: writeln('neg'); both: readln; end.
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Port the following code from Delphi to VB with equivalent syntax and logic.
var x: Integer = 5; label positive, negative, both; begin if (x > 0) then goto positive else goto negative; positive: writeln('pos'); goto both; negative: writeln('neg'); both: readln; end.
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Port the following code from Delphi to VB with equivalent syntax and logic.
var x: Integer = 5; label positive, negative, both; begin if (x > 0) then goto positive else goto negative; positive: writeln('pos'); goto both; negative: writeln('neg'); both: readln; end.
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Rewrite the snippet below in Go so it works the same as the original Delphi code.
var x: Integer = 5; label positive, negative, both; begin if (x > 0) then goto positive else goto negative; positive: writeln('pos'); goto both; negative: writeln('neg'); both: readln; end.
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Produce a language-to-language conversion: from Delphi to Go, same semantics.
var x: Integer = 5; label positive, negative, both; begin if (x > 0) then goto positive else goto negative; positive: writeln('pos'); goto both; negative: writeln('neg'); both: readln; end.
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Change the programming language of this snippet from Factor to C without modifying what it does.
USING: continuations prettyprint ; current-continuation short.
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Preserve the algorithm and functionality while converting the code from Factor to C.
USING: continuations prettyprint ; current-continuation short.
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Ensure the translated C# code behaves exactly like the original Factor snippet.
USING: continuations prettyprint ; current-continuation short.
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Can you help me rewrite this code in C++ instead of Factor, keeping it the same logically?
USING: continuations prettyprint ; current-continuation short.
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Write a version of this Factor function in C++ with identical behavior.
USING: continuations prettyprint ; current-continuation short.
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Please provide an equivalent version of this Factor code in Java.
USING: continuations prettyprint ; current-continuation short.
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Produce a language-to-language conversion: from Factor to Java, same semantics.
USING: continuations prettyprint ; current-continuation short.
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Convert the following code from Factor to Python, ensuring the logic remains intact.
USING: continuations prettyprint ; current-continuation short.
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Port the following code from Factor to Python with equivalent syntax and logic.
USING: continuations prettyprint ; current-continuation short.
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Translate the given Factor code snippet into VB without altering its behavior.
USING: continuations prettyprint ; current-continuation short.
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Write the same code in VB as shown below in Factor.
USING: continuations prettyprint ; current-continuation short.
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Maintain the same structure and functionality when rewriting this code in Go.
USING: continuations prettyprint ; current-continuation short.
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Please provide an equivalent version of this Factor code in Go.
USING: continuations prettyprint ; current-continuation short.
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Translate this program into C but keep the logic exactly as in Forth.
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Can you help me rewrite this code in C instead of Forth, keeping it the same logically?
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Can you help me rewrite this code in C# instead of Forth, keeping it the same logically?
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Keep all operations the same but rewrite the snippet in C#.
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Generate a C++ translation of this Forth snippet without changing its computational steps.
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Rewrite the snippet below in C++ so it works the same as the original Forth code.
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Translate the given Forth code snippet into Java without altering its behavior.
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Ensure the translated Java code behaves exactly like the original Forth snippet.
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Write a version of this Forth function in Python with identical behavior.
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Convert this Forth block to Python, preserving its control flow and logic.
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Write the same algorithm in VB as shown in this Forth implementation.
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Preserve the algorithm and functionality while converting the code from Forth to Go.
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Generate an equivalent Go version of this Forth code.
create goto1 1 cells allot create goto2 1 cells allot create goto3 1 cells allot create goto4 1 cells allot create goto5 1 cells allot create goto6 1 cells allot create goto7 1 cells allot create goto8 1 cells allot create goto9 1 cells allot create goto10 1 cells allot : proc1 [ here goto1 ! ] s" item1 " type goto7 @ >r exit [ here goto2 ! ] s" item2 " type goto8 @ >r exit [ here goto3 ! ] s" item3 " type goto9 @ >r exit [ here goto4 ! ] s" item4 " type goto10 @ >r exit [ here goto5 ! ] s" item5" type cr 2dup = if 2drop exit then 1+ goto6 @ >r ; : proc2 [ here goto6 ! ] s" line " type dup . s" --> item6 " type goto1 @ >r exit [ here goto7 ! ] s" item7 " type goto2 @ >r exit [ here goto8 ! ] s" item8 " type goto3 @ >r exit [ here goto9 ! ] s" item9 " type goto4 @ >r exit [ here goto10 ! ] s" item10 " type goto5 @ >r ; 5 1 proc2 bye
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Convert the following code from Haskell to C, ensuring the logic remains intact.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Keep all operations the same but rewrite the snippet in C.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Write a version of this Haskell function in C# with identical behavior.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Ensure the translated C# code behaves exactly like the original Haskell snippet.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Convert this Haskell block to C++, preserving its control flow and logic.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Maintain the same structure and functionality when rewriting this code in C++.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Convert this Haskell block to Java, preserving its control flow and logic.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Rewrite this program in Java while keeping its functionality equivalent to the Haskell version.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Rewrite this program in Python while keeping its functionality equivalent to the Haskell version.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Rewrite the snippet below in Python so it works the same as the original Haskell code.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Preserve the algorithm and functionality while converting the code from Haskell to VB.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Transform the following Haskell implementation into VB, maintaining the same output and logic.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Port the provided Haskell code into Go while preserving the original functionality.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Write the same algorithm in Go as shown in this Haskell implementation.
import Control.Monad.Cont data LabelT r m = LabelT (ContT r m ()) label :: ContT r m (LabelT r m) label = callCC subprog where subprog lbl = let l = LabelT (lbl l) in return l goto :: LabelT r m -> ContT r m b goto (LabelT l) = const undefined <$> l runProgram :: Monad m => ContT r m r -> m r runProgram program = runContT program return
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Change the programming language of this snippet from J to C without modifying what it does.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Please provide an equivalent version of this J code in C.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Change the following J code into C# without altering its purpose.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Produce a functionally identical C# code for the snippet given in J.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Convert this J block to C++, preserving its control flow and logic.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Write the same algorithm in C++ as shown in this J implementation.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Convert the following code from J to Java, ensuring the logic remains intact.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Generate an equivalent Java version of this J code.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Write a version of this J function in Python with identical behavior.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Keep all operations the same but rewrite the snippet in Python.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Preserve the algorithm and functionality while converting the code from J to VB.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Translate this program into VB but keep the logic exactly as in J.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Generate a Go translation of this J snippet without changing its computational steps.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Please provide an equivalent version of this J code in Go.
F=: verb define smoutput 'Now we are in F' G'' smoutput 'Now we are back in F' ) G=: verb define smoutput 'Now we are in G' throw. ) F'' Now we are in F Now we are in G
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Change the programming language of this snippet from Julia to C without modifying what it does.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Can you help me rewrite this code in C instead of Julia, keeping it the same logically?
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Convert the following code from Julia to C#, ensuring the logic remains intact.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Port the provided Julia code into C# while preserving the original functionality.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Generate a C++ translation of this Julia snippet without changing its computational steps.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Convert the following code from Julia to C++, ensuring the logic remains intact.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Rewrite the snippet below in Java so it works the same as the original Julia code.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Please provide an equivalent version of this Julia code in Java.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Write the same code in Python as shown below in Julia.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Keep all operations the same but rewrite the snippet in Python.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Transform the following Julia implementation into VB, maintaining the same output and logic.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Ensure the translated VB code behaves exactly like the original Julia snippet.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Ensure the translated Go code behaves exactly like the original Julia snippet.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Rewrite this program in Go while keeping its functionality equivalent to the Julia version.
function example() println("Hello ") @goto world println("Never printed") @label world println("world") end
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Preserve the algorithm and functionality while converting the code from Lua to C.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Change the programming language of this snippet from Lua to C without modifying what it does.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Produce a language-to-language conversion: from Lua to C#, same semantics.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Produce a functionally identical C# code for the snippet given in Lua.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Write the same algorithm in C++ as shown in this Lua implementation.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Change the programming language of this snippet from Lua to C++ without modifying what it does.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Translate the given Lua code snippet into Java without altering its behavior.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Translate this program into Java but keep the logic exactly as in Lua.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Change the programming language of this snippet from Lua to Python without modifying what it does.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Port the provided Lua code into Python while preserving the original functionality.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"
Please provide an equivalent version of this Lua code in VB.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Transform the following Lua implementation into VB, maintaining the same output and logic.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
Public Sub jump() Debug.Print "VBA only allows" GoTo 1 Debug.Print "no global jumps" 1: Debug.Print "jumps in procedures with GoTo" Debug.Print "However," On 2 GoSub one, two Debug.Print "named in the list after Debug.Print "and execution will continue on the next line" On 1 GoTo one, two Debug.Print "For On Error, see Exceptions" one: Debug.Print "On <n> GoTo let you jump to the n-th label" Debug.Print "and won Exit Sub two: Debug.Print "On <n> GoSub let you jump to the n-th label": Return End Sub
Write the same algorithm in Go as shown in this Lua implementation.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Transform the following Lua implementation into Go, maintaining the same output and logic.
goto skip_print print "won't print" ::skip_print:: ::loop:: print "infinite loop" goto loop goto next do ::next:: print "won't print" end ::next:: ::outside:: function nope () goto outside end goto inside function nope () ::inside:: end for i = 1, 10 do for j = 1, 10 do for k = 1, 10 do if i^2 + j^2 == k^2 then print(("found: i=%d j=%d k=%d"):format(i, j, k)) goto exit end end end end print "not found" ::exit::
package main import "fmt" func main() { outer: for i := 0; i < 4; i++ { for j := 0; j < 4; j++ { if i + j == 4 { continue outer } if i + j == 5 { break outer } fmt.Println(i + j) } } k := 3 if k == 3 { goto later } fmt.Println(k) later: k++ fmt.Println(k) }
Generate a C translation of this Nim snippet without changing its computational steps.
block outer: for i in 0..1000: for j in 0..1000: if i + j == 3: break outer
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Keep all operations the same but rewrite the snippet in C.
block outer: for i in 0..1000: for j in 0..1000: if i + j == 3: break outer
if (x > 0) goto positive; else goto negative; positive: printf("pos\n"); goto both; negative: printf("neg\n"); both: ...
Preserve the algorithm and functionality while converting the code from Nim to C#.
block outer: for i in 0..1000: for j in 0..1000: if i + j == 3: break outer
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Rewrite this program in C# while keeping its functionality equivalent to the Nim version.
block outer: for i in 0..1000: for j in 0..1000: if i + j == 3: break outer
if (x > 0) goto positive; else goto negative; positive: Console.WriteLine("pos\n"); goto both; negative: Console.WriteLine("neg\n"); both: ...
Write the same algorithm in C++ as shown in this Nim implementation.
block outer: for i in 0..1000: for j in 0..1000: if i + j == 3: break outer
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Ensure the translated C++ code behaves exactly like the original Nim snippet.
block outer: for i in 0..1000: for j in 0..1000: if i + j == 3: break outer
#include <iostream> #include <utility> using namespace std; int main(void) { cout << "Find a solution to i = 2 * j - 7\n"; pair<int, int> answer; for(int i = 0; true; i++) { for(int j = 0; j < i; j++) { if( i == 2 * j - 7) { answer = make_pair(i, j); goto loopexit; } } } loopexit: cout << answer.first << " = 2 * " << answer.second << " - 7\n\n"; goto spagetti; int k; k = 9; spagetti: cout << "k = " << k << "\n"; }
Keep all operations the same but rewrite the snippet in Java.
block outer: for i in 0..1000: for j in 0..1000: if i + j == 3: break outer
loop1: while (x != 0) { loop2: for (int i = 0; i < 10; i++) { loop3: do { if () { continue loop1; } if () { break loop2; } } while (y < 10); } }
Translate the given Nim code snippet into Python without altering its behavior.
block outer: for i in 0..1000: for j in 0..1000: if i + j == 3: break outer
from goto import goto, label label .start for i in range(1, 4): print i if i == 2: try: output = message except NameError: print "Oops - forgot to define 'message'! Start again." message = "Hello world" goto .start print output, "\n"