task
stringclasses
5 values
input
stringlengths
89
339
canonicalization
### Instruction: Canonicalize the following SMILES string. c1(-c2ccc3c(c2)OCCO3)n(c(nc1)S[C@@H](C(N[C@@H](CC)C)=O)C)CC ### Response: CC[C@@H](C)NC(=O)[C@@H](C)Sc1ncc(-c2ccc3c(c2)OCCO3)n1CC
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [16*]c1ccccc1C#N Fragment 2: [1*]C(=O)[C@@H]1CCCO1 ### Response: N#Cc1ccccc1-c1ccc(COC(=O)[C@@H]2CCCO2)cc1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. Cc1c(N2C(=O)/C(=C\c3ccc4c(c3)C[C@@H](C)O4)SC2=S)c(=O)n(-c2ccccc2)n1C ### Response: 3
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CSC[C@H]1CCC[NH+]1Cc1cc(O)ccc1Br ### Response: 1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COc1ccc2c(c1)[C@@]1(SCCN1C(=O)c1ccco1)C(=O)N2Cc1ccc(C(F)(F)F)cc1 ### Response: 1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [11*]Sc1nnc([14*])n1N Fragment 2: [1*]C(=O)C[4*] ### Response: Cc1cc(Cl)ccc1NC(=O)CSc1nnc(C(C)C)n1N
canonicalization
### Instruction: Canonicalize the following SMILES string. c1c(occ1)C(=O)Nc1cccc(c1)NC(c1cc(ccc1Br)S(=O)(=O)N)=O ### Response: NS(=O)(=O)c1ccc(Br)c(C(=O)Nc2cccc(NC(=O)c3ccco3)c2)c1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. COc1cccc(-c2cc(C(=O)NCC(C)C)n3nc(-c4ccccc4)cc3n2)c1 ### Response: 1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Cn1ccnc1[C@H](NC(=O)c1ccc(-n2cnc3ccccc3c2=O)cc1)c1ccc(F)cc1 ### Response: 1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. Cc1ccc([C@H]2[NH+]=C3[C@H](C)CCCN3C2=[NH2+])cc1F ### Response: 1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Cc1cc(NC(=O)CS[C@@H](C)C(=O)Nc2cc(C)on2)no1 ### Response: 3
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CN(C[C@H]1CCC[C@@H]1O)C(=O)Cc1cccc(NC(=O)OC(C)(C)C)c1 ### Response: 1
canonicalization
### Instruction: Canonicalize the following SMILES string. c1c(ccc(C(=O)OCC)c1)NC(CCc1nc2sc3c(CCCC3)c2c(=O)[nH]1)=O ### Response: CCOC(=O)c1ccc(NC(=O)CCc2nc3sc4c(c3c(=O)[nH]2)CCCC4)cc1
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CC[C@H](C)C[C@@H](C)NC(=O)CCN1C(=O)[C@H]2CCCC[C@H]2C1=O ### Response: 1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [1*]C(=O)N[5*] Fragment 2: [15*][C@H]1CCC[C@@]1(C)CO ### Response: Cc1nc(CNC(=O)N[C@H]2CCC[C@@]2(C)CO)sc1C
ring_counting
### Instruction: Count the five-membered rings in the following molecule. CC1CCN(C(=O)c2ccc(NCc3ccco3)nc2)CC1 ### Response: 1
functional_group
### Instruction: Does the molecule contain a ether group? COc1ccc2cc(C(=O)N3CCC([C@@H](C)C(=O)NCc4cccc(F)c4)CC3)[nH]c2c1 ### Response: Yes
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CNC(=O)CS(=O)(=O)c1nc(C)c(C)n1C1CCCCC1 ### Response: 2
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Cc1ccc(C)c(OCC(=O)Nc2ccc(N3CCCC3)c(C)c2)c1 ### Response: 2
ring_counting
### Instruction: Count the five-membered rings in the following molecule. O=C(Cn1nc2c(cc1=O)CCCC2)N1CC[C@]2(O)CCCC[C@@H]2C1 ### Response: 0
functional_group
### Instruction: Does the molecule contain a aldehyde group? O=C(CN(c1ccccc1)S(=O)(=O)c1ccccc1F)NCC(F)(F)F ### Response: No
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Cc1n[nH]c2ncc(NC(=O)NCc3cccc(Cn4ccnc4)c3)cc12 ### Response: 1
functional_group
### Instruction: Does the molecule contain a amide group? Cc1noc(-c2ccc(C(=O)NNC(=S)N[C@@H](C)C3CC3)cc2)n1 ### Response: Yes
functional_group
### Instruction: Does the molecule contain a aromatic_ring group? CC(C)c1nncn1CCNC(=O)c1cc([N+](=O)[O-])ccc1Cl ### Response: Yes
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [14*]c1noc2ccccc12 Fragment 2: [5*]N1CC([15*])C1 ### Response: O=C(Cc1noc2ccccc12)N1CC(c2nc(-c3ncccn3)no2)C1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CCCCNC(=O)[C@H]1CCCN(C(=O)C(C)(C)CC(C)C)C1 ### Response: 5
canonicalization
### Instruction: Canonicalize the following SMILES string. c1ccccc1OCc1ccc(cc1)CNC(N1CC[C@H]([NH+]2CCCC2)C1)=O ### Response: O=C(NCc1ccc(COc2ccccc2)cc1)N1CC[C@H]([NH+]2CCCC2)C1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COc1ccc(CN[C@H]2CCN(c3ccccc3)C2=O)cc1O ### Response: 1
functional_group
### Instruction: Does the molecule contain a ether group? O=C1CC[C@H](C(=O)N2CCC(c3ccncc3)CC2)CN1CCN1CCOCC1 ### Response: Yes
canonicalization
### Instruction: Canonicalize the following SMILES string. Brc1c(Br)c(sc1)C(=O)CC1CC1 ### Response: O=C(CC1CC1)c1scc(Br)c1Br
functional_group
### Instruction: Does the molecule contain a amine group? COC(=O)[C@H](CC1=c2ccccc2=[NH+]C1)NC(=O)[C@H]1[NH+]=NC(=O)c2ccccc21 ### Response: Yes
ring_counting
### Instruction: Count the six-membered rings in the following molecule. Cc1cc(=O)nc2c3ccccc3n(CC(=O)N[C@@H]3CCCc4ccccc43)n12 ### Response: 4
canonicalization
### Instruction: Canonicalize the following SMILES string. c1cc(ccc1-n1c2nc(cc(C(F)(F)F)c2c(n1)C(C)C)-c1cnn(c1)CC)F ### Response: CCn1cc(-c2cc(C(F)(F)F)c3c(C(C)C)nn(-c4ccc(F)cc4)c3n2)cn1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [9*]n1c(=O)oc2ccccc21 Fragment 2: [5*]NC[C@@H]1CCCc2ccccc21 ### Response: C[C@@H](C(=O)NC[C@@H]1CCCc2ccccc21)n1c(=O)oc2ccccc21
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CC(=O)Nc1ccc(C(=O)N[C@@H](C)[C@H](C)N2CCOCC2)cc1 ### Response: 2
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CS[C@H]1CCC[C@H](NC(=O)NCCCC(C)(C)CO)C1 ### Response: 5
canonicalization
### Instruction: Canonicalize the following SMILES string. c1c(ccc(c1)C(=O)c1n(ccn1)C)NC(=O)[C@H]1C[C@@H]1c1ccccc1F ### Response: Cn1ccnc1C(=O)c1ccc(NC(=O)[C@H]2C[C@@H]2c2ccccc2F)cc1
functional_group
### Instruction: Does the molecule contain a sulfonyl group? CN(CC(C)(C)O)C(=O)N[C@H]1CC[C@H](C(=O)[O-])C1 ### Response: No
canonicalization
### Instruction: Canonicalize the following SMILES string. C([NH+](CC(=O)Nc1ncc(C)cc1)C)c1c2c(cccn2)c(cc1)F ### Response: Cc1ccc(NC(=O)C[NH+](C)Cc2ccc(F)c3cccnc23)nc1
functional_group
### Instruction: Does the molecule contain a sulfonyl group? Cc1sc([C@@H](C)[NH2+][C@@H](C)c2nccs2)nc1-c1ccc(Cl)cc1 ### Response: No
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [1*]C(=O)[C@@H]1CCN([5*])C1 Fragment 2: [5*]NC1CCCC1 ### Response: Cc1ccc2c(c1)cc(C(=O)N1CC[C@@H](C(=O)NC3CCCC3)C1)n2C
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CC(C)(C)c1nc(C[NH+]2CCCN(C(=O)[C@H]3CO[C@@H]4C=CC=C[C@@H]4O3)CC2)cs1 ### Response: 2
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Cc1ccccc1/[NH+]=c1\oc2ccc(Cl)cc2cc1C(=O)NC[C@@H]1CCCO1 ### Response: 1
canonicalization
### Instruction: Canonicalize the following SMILES string. [NH2+]1C[C@@H](CC1)COC(C1CCC1)=O ### Response: O=C(OC[C@@H]1CC[NH2+]C1)C1CCC1
canonicalization
### Instruction: Canonicalize the following SMILES string. c1ccc(cc1)-c1cc(n[nH]1)CN(CC)C[C@H](C)C#N ### Response: CCN(Cc1cc(-c2ccccc2)[nH]n1)C[C@H](C)C#N
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]N([5*])C(C)C Fragment 2: [5*]Nc1nnc([14*])s1 ### Response: CCCCCN(C(=O)Nc1nnc(C2CC2)s1)C(C)C
canonicalization
### Instruction: Canonicalize the following SMILES string. c1(N2CCC(CC2)CCNC(=O)[C@@H]2CCC[NH+](C)C2)cc[nH+]cc1 ### Response: C[NH+]1CCC[C@@H](C(=O)NCCC2CCN(c3cc[nH+]cc3)CC2)C1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]NCc1cscc1C Fragment 2: [1*]C(=O)CC(C)(C)C(=O)[O-] ### Response: Cc1cscc1CNC(=O)CC(C)(C)C(=O)[O-]
ring_counting
### Instruction: Count the five-membered rings in the following molecule. Cc1nn(Cc2nncn2-c2cccc(C(F)(F)F)c2)c(C)c1C ### Response: 2
functional_group
### Instruction: Does the molecule contain a amide group? Cc1ccc(NC(=O)N[C@@H](C)c2nnc3ccccn23)cc1-n1cnnn1 ### Response: Yes
canonicalization
### Instruction: Canonicalize the following SMILES string. CC(C)CCOc1cc(ccc1)NC(=O)c1sccc1 ### Response: CC(C)CCOc1cccc(NC(=O)c2cccs2)c1
canonicalization
### Instruction: Canonicalize the following SMILES string. c1c(cc(cc1F)F)COc1ccc(-c2nc(C(=O)NC3CC3)cs2)cc1OC ### Response: COc1cc(-c2nc(C(=O)NC3CC3)cs2)ccc1OCc1cc(F)cc(F)c1
functional_group
### Instruction: Does the molecule contain a nitro group? Cc1ccc(C(=O)CSc2ccc(S(=O)(=O)N3CCN(C)CC3)cn2)cc1C ### Response: No
functional_group
### Instruction: Does the molecule contain a nitrile group? C#CCNC(=O)[C@@]1(Cc2ccccc2-c2cccnc2)CC[NH+](Cc2ccccc2Cl)C1 ### Response: No
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COc1ccc(Br)cc1/C=C1\Oc2cc(OC(=O)C3CC3)ccc2C1=O ### Response: 1
canonicalization
### Instruction: Canonicalize the following SMILES string. C1CC[C@@H](OC[C@@H]2c3ccccc3OC2)[C@H]1C[NH3+] ### Response: [NH3+]C[C@H]1CCC[C@H]1OC[C@H]1COc2ccccc21
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CSc1nnc(Sc2ccc3nnc(C(F)F)n3n2)s1 ### Response: 1
canonicalization
### Instruction: Canonicalize the following SMILES string. c1(ccc2c(c1)cccc2)O[C@H](C)C(=O)NNC(c1cccc(C)c1)=O ### Response: Cc1cccc(C(=O)NNC(=O)[C@@H](C)Oc2ccc3ccccc3c2)c1
functional_group
### Instruction: Does the molecule contain a sulfonyl group? Cc1nc(-c2ccsc2)sc1C(=O)N1CCCCC1 ### Response: No
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? C[C@H](CCO)Sc1ccc(C(N)=O)cc1N ### Response: 4
canonicalization
### Instruction: Canonicalize the following SMILES string. N(C[C@H](c1ccccc1Cl)O)[C@@H]1c2c(OCC1)ccc(c2)F ### Response: O[C@H](CN[C@H]1CCOc2ccc(F)cc21)c1ccccc1Cl
ring_counting
### Instruction: Count the six-membered rings in the following molecule. C[C@@H]1SCCC[C@H]1[NH2+]CC1CC1 ### Response: 1
functional_group
### Instruction: Does the molecule contain a ether group? Nc1ccc(N2CC[C@@H]3CCCC[C@@H]3C2)[nH+]c1N ### Response: No
ring_counting
### Instruction: Count the five-membered rings in the following molecule. O=C(Nc1ccc(N2CCOCC2)nc1)c1cn(-c2ccccc2)nc1-c1ccccc1 ### Response: 1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COc1cc(C(=O)N2CCC[C@@H](c3nc4ccccc4[nH]3)C2)cc(Cl)c1OC(C)C ### Response: 3
canonicalization
### Instruction: Canonicalize the following SMILES string. [C@@H]([NH+]1CCC[C@@H](C1)c1nc(C)no1)(CC#N)C ### Response: Cc1noc([C@H]2CCC[NH+]([C@@H](C)CC#N)C2)n1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? O=C(C[NH+]1CCC(c2nnc(-c3ccco3)o2)CC1)c1ccc(Cl)cc1 ### Response: 2
functional_group
### Instruction: Does the molecule contain a halide group? O=C(N[C@H]1CCN(c2cccc(Cl)c2)C1)c1nccn2ccnc12 ### Response: Yes
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CC[C@H](NC(=O)N(C)[C@H]1CCN(c2ccccc2)C1=O)c1nccs1 ### Response: 1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? O=C(C[NH+]1CCC[C@H]1c1cccc(F)c1)NC1CCOCC1 ### Response: 2
ring_counting
### Instruction: Count the five-membered rings in the following molecule. Cc1ccoc1C[NH+]1CC[C@@H](C)[C@H](C)C1 ### Response: 1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. CCN1CCO[C@@H](c2ncc(Br)c(N)n2)C1 ### Response: 0
functional_group
### Instruction: Does the molecule contain a nitro group? CCOc1cccc(CN2CCc3ccccc3[C@H]2CO)c1OC(F)F ### Response: No
canonicalization
### Instruction: Canonicalize the following SMILES string. n1nc(CC)n(c1)CCNC(N1CCN(c2ccc(cc2)OC)CC1)=O ### Response: CCc1nncn1CCNC(=O)N1CCN(c2ccc(OC)cc2)CC1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. CCCc1nn(C)c(N(C)C[C@H]2CCC[NH+]2CC)c1N ### Response: 2
canonicalization
### Instruction: Canonicalize the following SMILES string. N(/n1c2ccccc2nc1C)=C\c1ccc(s1)[N+](=O)[O-] ### Response: Cc1nc2ccccc2n1/N=C/c1ccc([N+](=O)[O-])s1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? C=C(C)C[NH+]1CCC(N[C@@H](C)c2nc3c(s2)CCCC3)CC1 ### Response: 3
canonicalization
### Instruction: Canonicalize the following SMILES string. c1(SCC[C@H]2[C@](C([O-])=O)([NH2+]CC)CCC2)n[nH]c(n1C)=O ### Response: CC[NH2+][C@]1(C(=O)[O-])CCC[C@H]1CCSc1n[nH]c(=O)n1C
canonicalization
### Instruction: Canonicalize the following SMILES string. c1cccc(NC(=O)N2Cc3c(OCC2)ccc(c3)COCc2ccc(cc2)F)c1 ### Response: O=C(Nc1ccccc1)N1CCOc2ccc(COCc3ccc(F)cc3)cc2C1
canonicalization
### Instruction: Canonicalize the following SMILES string. N(C(=S)NCC=C)NC(c1csc(n1)-c1ccsc1)=O ### Response: C=CCNC(=S)NNC(=O)c1csc(-c2ccsc2)n1
canonicalization
### Instruction: Canonicalize the following SMILES string. c1cc(cc(c1)CS(=O)(c1cc(C(=O)[O-])c(F)cc1)=O)O ### Response: O=C([O-])c1cc(S(=O)(=O)Cc2cccc(O)c2)ccc1F
ring_counting
### Instruction: Count the five-membered rings in the following molecule. Cc1[nH]c2ccc(C(=O)Nc3cc(C(C)(C)C)nn3-c3ncccn3)cc2c1C ### Response: 2
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CCOC[C@H]1CCCN(S(=O)(=O)c2ccc(CC#N)cc2)C1 ### Response: 2
ring_counting
### Instruction: Count the six-membered rings in the following molecule. C[C@@H](Cn1cccn1)NC(=O)[C@H]1CC(=O)N(CC(F)(F)F)C1 ### Response: 0
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CCCNC(=O)Nc1c(C)cccc1C(C)C ### Response: 3
canonicalization
### Instruction: Canonicalize the following SMILES string. c1cc([C@@H](CNC([C@@H]([NH+](C)CCC)C)=O)C)ccc1 ### Response: CCC[NH+](C)[C@@H](C)C(=O)NC[C@@H](C)c1ccccc1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. Cc1ccc(N2C(=O)C[C@H](C(=O)Nc3cccc(Cn4ccnc4)c3)[C@H]2c2cccs2)cc1 ### Response: 3
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? NS(=O)(=O)N1CCN(CCn2c(=O)oc3cccnc32)CC1 ### Response: 2
canonicalization
### Instruction: Canonicalize the following SMILES string. c1(C[C@@H](CNC(=O)Nc2c(C)c(ccc2)NC(=O)C)[NH+](C)C)ccccc1 ### Response: CC(=O)Nc1cccc(NC(=O)NC[C@H](Cc2ccccc2)[NH+](C)C)c1C
ring_counting
### Instruction: Count the five-membered rings in the following molecule. CC(=O)c1cccc(OC[C@@H](O)C[NH+]2CCC(CO)CC2)c1 ### Response: 0
functional_group
### Instruction: Does the molecule contain a ether group? Cc1cc(CSc2nnc(N3CCOCC3)n2C[C@@H]2CCCO2)no1 ### Response: Yes
canonicalization
### Instruction: Canonicalize the following SMILES string. N([C@@H]1[C@H](CCCC1)C)C(COC(=O)Cn1nc(cc1C)C)=O ### Response: Cc1cc(C)n(CC(=O)OCC(=O)N[C@H]2CCCC[C@@H]2C)n1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [4*]Cc1ccc(C)c(F)c1 Fragment 2: [5*][NH2+][C@H]1CCCC1(C)C ### Response: Cc1ccc(C[NH2+][C@H]2CCCC2(C)C)cc1F
functional_group
### Instruction: Does the molecule contain a nitro group? COC(=O)[C@@H]1CCCC[C@H]1NC(=O)c1cc(Cl)c(OC)c(Cl)c1 ### Response: No
canonicalization
### Instruction: Canonicalize the following SMILES string. C1CCCCN1C(c1ccc(NC2=N[C@@H]3[C@H](CS(=O)(C3)=O)S2)cc1)=O ### Response: O=C(c1ccc(NC2=N[C@H]3CS(=O)(=O)C[C@@H]3S2)cc1)N1CCCCC1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CCNC(=O)N[C@@H]1CCCN(c2ccccc2Cl)C1=O ### Response: 2
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [14*]c1cccs1 Fragment 2: [5*]N1CCC[C@H]1[13*] ### Response: O=C(/C=C/c1ccc(S(=O)(=O)N2CCCCCC2)cc1)N1CCC[C@H]1c1cccs1
canonicalization
### Instruction: Canonicalize the following SMILES string. C1(C(=O)OCCCC)[C@@H](c2cc(Br)c(c(c2)OC)O)NC(N(C)C=1C)=O ### Response: CCCCOC(=O)C1=C(C)N(C)C(=O)N[C@@H]1c1cc(Br)c(O)c(OC)c1
canonicalization
### Instruction: Canonicalize the following SMILES string. c1cccc2c1=C1CCN(C[C@@H]1[NH+]=2)C(NCCC(=O)N[C@@]1(CCS(C1)(=O)=O)C)=O ### Response: C[C@@]1(NC(=O)CCNC(=O)N2CCC3=c4ccccc4=[NH+][C@H]3C2)CCS(=O)(=O)C1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CCCCN1C(=O)[C@@]2(NC(=O)c3ccccc3N2)c2ccccc21 ### Response: 4