id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__24LgyrtP4ynOiQEQ | The roof of an apartment building is rectangular and its length is 4 times longer than its width. If the area of the roof is 676 feet squared, what is the difference between the length and the width of the roof? Choose the correct choice from the following:
A) 39 .
B) 40 .
C) 42 .
D) 44 .
E) 46 . | <gadget id="calculator">676 / 4</gadget>
<output>169</output>
<gadget id="calculator">169 ** (1/2)</gadget>
<output>13</output>
<gadget id="calculator">13 * 4</gadget>
<output>52</output>
<gadget id="calculator">52 - 13</gadget>
<output>39</output>
<result>A</result> | A | 39 | The roof of an apartment building is rectangular and its length is 4 times longer than its width. If the area of the roof is 676 feet squared, what is the difference between the length and the width of the roof? | {
"A": "39 .",
"B": "40 .",
"C": "42 .",
"D": "44 .",
"E": "46 ."
} | subtract(multiply(sqrt(divide(676, 4)), 4), sqrt(divide(676, 4))) | divide(n1,n0)|sqrt(#0)|multiply(#1,n0)|subtract(#2,#1)| | "let the width = x x * 4 x = 676 x ^ 2 = 169 x = 13 length = 4 * 13 = 52 difference = 52 - 13 = 39 a is the answer" | geometry |
math_qa__mOtuBqYQAVo4hHae | The area of a rectangular plot is 360 square metres. If the length is 25% less than the breadth, what is the breadth of the plot?
Options.
A) 32 m B) 12 m C) 20 m D) 22 m E) 25 m | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">360 / (3/4)</gadget>
<output>480</output>
<gadget id="calculator">480 ** (1/2)</gadget>
<output>4*sqrt(30) = around 21.908902</output>
<result>D</result> | D | 22 | The area of a rectangular plot is 360 square metres. If the length is 25% less than the breadth, what is the breadth of the plot? | {
"A": "32 m",
"B": "12 m",
"C": "20 m",
"D": "22 m",
"E": "25 m"
} | sqrt(divide(360, subtract(const_1, divide(25, const_100)))) | divide(n1,const_100)|subtract(const_1,#0)|divide(n0,#1)|sqrt(#2) | length = 75 % of breadth . length × breadth = 360 m 2 ⇒ 75 % of breadth × breadth = 360 m 2 ⇒ 75 / 100 × breadth × breadth = 360 m 2 ⇒ breadth × breadth = 480 m 2 ⇒ breadth = 22 m answer : d | geometry |
math_qa__KfuE8pazVfZfGGGy | A 60 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be? Select the correct option:
A) 73 B) 20 C) 83 D) 17.1 E) 52 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) + 1</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">60 / (7/5)</gadget>
<output>300/7 = around 42.857143</output>
<gadget id="calculator">60 - (300/7)</gadget>
<output>120/7 = around 17.142857</output>
<result>D</result> | D | 17.1 | A 60 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be? | {
"A": "73",
"B": "20",
"C": "83",
"D": "17.1",
"E": "52"
} | subtract(60, divide(60, add(divide(2, 5), const_1))) | divide(n1,n2)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)| | "explanation : 1 : 2 / 5 = 5 : 2 2 / 7 * 60 = 20 answer : option d" | physics |
math_qa__fzhs3oyY3ZiZPBsj | One week, a certain truck rental lot had a total of 24 trucks, all of which were on the lot Monday morning. If 50% of the trucks that were rented out during the week were returned to the lot on or before Saturday morning of that week, and if there were at least 12 trucks on the lot that Saturday morning, what is the greatest number of different trucks that could have been rented out during the week? Choose the correct option.
A) 24 B) 16 C) 12 D) 8 E) 4 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">24 * (1/2)</gadget>
<output>12</output>
<gadget id="calculator">12 + 12</gadget>
<output>24</output>
<result>A</result> | A | 24 | One week, a certain truck rental lot had a total of 24 trucks, all of which were on the lot Monday morning. If 50% of the trucks that were rented out during the week were returned to the lot on or before Saturday morning of that week, and if there were at least 12 trucks on the lot that Saturday morning, what is the greatest number of different trucks that could have been rented out during the week? | {
"A": "24",
"B": "16",
"C": "12",
"D": "8",
"E": "4"
} | add(12, multiply(24, divide(50, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n2,#1) | n - not rented trucks ; r - rented trucks n + r = 24 n + r / 2 = 12 r = 24 a | general |
math_qa__t6h3me5LLEkWwCl5 | If two projectiles are launched at the same moment from 1455 km apart and travel directly towards each other at 470 km per hour and 500 km per hour respectively, how many minutes will it take for them to meet? Answers.
A) 90 B) 85 C) 80 D) 75 E) 70 | <gadget id="calculator">470 + 500</gadget>
<output>970</output>
<gadget id="calculator">1_455 / 970</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 60</gadget>
<output>90</output>
<result>A</result> | A | 90 | If two projectiles are launched at the same moment from 1455 km apart and travel directly towards each other at 470 km per hour and 500 km per hour respectively, how many minutes will it take for them to meet? | {
"A": "90",
"B": "85",
"C": "80",
"D": "75",
"E": "70"
} | multiply(divide(1455, add(470, 500)), const_60) | add(n1,n2)|divide(n0,#0)|multiply(#1,const_60)| | "the projectiles travel a total of 970 km per hour . the time to meet is 1455 / 970 = 1.5 hours = 90 minutes the answer is a ." | physics |
math_qa__SiiiavirqbLhvvBC | If the least common addition of two prime numbers x and y is 36, where x < y, then the value of 4x + y is Choices.
A) 32 B) 45 C) 59 D) 73 E) 87 | <gadget id="calculator">36 * 2</gadget>
<output>72</output>
<gadget id="calculator">36 / 4</gadget>
<output>9</output>
<gadget id="calculator">72 + 9</gadget>
<output>81</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">81 + 6</gadget>
<output>87</output>
<result>E</result> | E | 87 | If the least common addition of two prime numbers x and y is 36, where x < y, then the value of 4x + y is | {
"A": "32",
"B": "45",
"C": "59",
"D": "73",
"E": "87"
} | add(add(multiply(36, const_2), divide(36, 4)), add(const_3, const_3)) | add(const_3,const_3)|divide(n0,n1)|multiply(n0,const_2)|add(#1,#2)|add(#3,#0) | ( x + y ) = 36 and both x an y are prime . the only values of x and y can be 17 and 19 ( x = 17 and y = 19 ) 4 x + y = 4 * 17 + 19 = 87 correct option : e | general |
math_qa__pHQg1gjEg4SvpvG5 | A man can do a job in 10 days. His father takes 20 days and his son finishes it in 25 days. How long will they take to complete the job if they all work together? Select the correct option: A) 6.3 B) 6.9 C) 5.3 D) 6.1 E) 6.2 | <gadget id="calculator">1 / 25</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/10) + (1/20)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(1/25) + (3/20)</gadget>
<output>19/100 = around 0.19</output>
<gadget id="calculator">1 / (19/100)</gadget>
<output>100/19 = around 5.263158</output>
<result>C</result> | C | 5.3 | A man can do a job in 10 days. His father takes 20 days and his son finishes it in 25 days. How long will they take to complete the job if they all work together? | {
"A": "6.3",
"B": "6.9",
"C": "5.3",
"D": "6.1",
"E": "6.2"
} | divide(const_1, add(divide(const_1, 25), add(divide(const_1, 10), divide(const_1, 20)))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|add(#3,#2)|divide(const_1,#4)| | "1 day work of the three persons = ( 1 / 10 + 1 / 20 + 1 / 25 ) = 19 / 100 so , all three together will complete the work in 100 / 19 = 5.3 days . answer : c" | physics |
math_qa__a5hvnVoH2yURFLUH | A train 2500 m long can cross an electric pole in 50 sec and then find the speed of the train?
Choose the correct choice from the following options
A) 178 B) 180 C) 182 D) 184 E) 186 | <gadget id="calculator">2_500 / 1_000</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">50 / 3_600</gadget>
<output>1/72 = around 0.013889</output>
<gadget id="calculator">(5/2) / (1/72)</gadget>
<output>180</output>
<result>B</result> | B | 180 | A train 2500 m long can cross an electric pole in 50 sec and then find the speed of the train? | {
"A": "178",
"B": "180",
"C": "182",
"D": "184",
"E": "186"
} | divide(divide(2500, const_1000), divide(50, const_3600)) | divide(n0,const_1000)|divide(n1,const_3600)|divide(#0,#1)| | "length = speed * time speed = l / t s = 2500 / 50 s = 50 m / sec speed = 50 * 18 / 5 ( to convert m / sec in to kmph multiply by 18 / 5 ) speed = 180 kmph answer : b" | physics |
math_qa__TeJ3SKKbHn8l86zX | A semicircle has a radius of 14. What is the approximate perimeter of the semicircle? Choose the correct choice from the following options
A) 72 B) 76 C) 80 D) 84 E) 88 | <gadget id="calculator">2 * pi * 14</gadget>
<output>28*pi = around 87.964594</output>
<gadget id="calculator">(28*pi) / 2</gadget>
<output>14*pi = around 43.982297</output>
<gadget id="calculator">2 * 14</gadget>
<output>28</output>
<gadget id="calculator">(14*pi) + 28</gadget>
<output>28 + 14*pi = around 71.982297</output>
<result>A</result> | A | 72 | A semicircle has a radius of 14. What is the approximate perimeter of the semicircle? | {
"A": "72",
"B": "76",
"C": "80",
"D": "84",
"E": "88"
} | add(divide(circumface(14), const_2), multiply(const_2, 14)) | circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "the perimeter of a circle is 2 * pi * r . the perimeter of a semicircle is 2 * pi * r / 2 + 2 r = pi * r + 2 r the perimeter is pi * 14 + 2 * 14 which is about 72 . the answer is a ." | geometry |
math_qa__jPjp9XnY2vxnFmbT | The average of 25 results is 24. The average of first 12 of those is 14 and the average of last 12 is 17. What is the 13th result? Choose the most appropriate option:
A) 740 B) 228 C) 690 D) 780 E) 458 | <gadget id="calculator">25 * 24</gadget>
<output>600</output>
<gadget id="calculator">12 * 17</gadget>
<output>204</output>
<gadget id="calculator">600 - 204</gadget>
<output>396</output>
<gadget id="calculator">12 * 14</gadget>
<output>168</output>
<gadget id="calculator">396 - 168</gadget>
<output>228</output>
<result>B</result> | B | 228 | The average of 25 results is 24. The average of first 12 of those is 14 and the average of last 12 is 17. What is the 13th result? | {
"A": "740",
"B": "228",
"C": "690",
"D": "780",
"E": "458"
} | subtract(subtract(multiply(25, 24), multiply(12, 17)), multiply(12, 14)) | multiply(n0,n1)|multiply(n2,n5)|multiply(n2,n3)|subtract(#0,#1)|subtract(#3,#2)| | "solution : sum of 1 st 12 results = 12 * 14 sum of last 12 results = 12 * 17 13 th result = x ( let ) now , 12 * 14 + 12 * 17 + x = 25 * 24 or , x = 228 . answer : option b" | general |
math_qa__7UIHelRQfHEkmD6e | A starts business with Rs.4500 and after 7 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the Capital ? Choose one: A) 24887 B) 20778 C) 16200 D) 9000 E) 2811 | <gadget id="calculator">4_500 * 12</gadget>
<output>54_000</output>
<gadget id="calculator">54_000 * 3</gadget>
<output>162_000</output>
<gadget id="calculator">12 - 7</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">162_000 / 10</gadget>
<output>16_200</output>
<result>C</result> | C | 16,200 | A starts business with Rs.4500 and after 7 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the Capital ? | {
"A": "24887",
"B": "20778",
"C": "16200",
"D": "9000",
"E": "2811"
} | divide(multiply(multiply(4500, const_12), 3), multiply(subtract(const_12, 7), 2)) | multiply(n0,const_12)|subtract(const_12,n1)|multiply(n3,#0)|multiply(n2,#1)|divide(#2,#3)| | "explanation : a invested rs . 3500 for 12 months . let b joined with investment x . and he invested for 12 - 7 = 5 months . so there profit ratio = ( 4500 ã — 12 ) : ( 5 x ) = 2 : 3 â ‡ ’ x = 16200 answer : c" | other |
math_qa__4ehczqp2ze7PNybq | The average of 6 no.'s is 3.95. The average of 2of them is 3.4, while the average of theother 2 is 3.85. What is the average of the remaining 2 no's?
Options: A) 2.3 B) 2.5 C) 3.5 D) 3.6 E) 4.6 | <gadget id="calculator">6 * 3.95</gadget>
<output>23.7</output>
<gadget id="calculator">2 * 3.4</gadget>
<output>6.8</output>
<gadget id="calculator">2 * 3.85</gadget>
<output>7.7</output>
<gadget id="calculator">6.8 + 7.7</gadget>
<output>14.5</output>
<gadget id="calculator">23.7 - 14.5</gadget>
<output>9.2</output>
<gadget id="calculator">9.2 / 2</gadget>
<output>4.6</output>
<result>E</result> | E | 4.6 | The average of 6 no.'s is 3.95. The average of 2of them is 3.4, while the average of theother 2 is 3.85. What is the average of the remaining 2 no's? | {
"A": "2.3",
"B": "2.5",
"C": "3.5",
"D": "3.6",
"E": "4.6"
} | divide(subtract(multiply(6, 3.95), add(multiply(2, 3.4), multiply(2, 3.85))), 2) | multiply(n0,n1)|multiply(n2,n3)|multiply(n2,n5)|add(#1,#2)|subtract(#0,#3)|divide(#4,n2)| | "sum of the remaining two numbers = ( 3.95 * 6 ) - [ ( 3.4 * 2 ) + ( 3.85 * 2 ) ] = 23.70 - ( 6.8 + 7.7 ) = 23.70 - 14.5 = 9.20 . required average = ( 9.2 / 2 ) = 4.6 . e" | general |
math_qa__Nj09ol1k1qRlgL8n | Some persons can do a piece of work in 12 days. Two times the number of such persons will do half of that work in
Choices
A) 9 B) 8 C) 4 D) 3 E) 1 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">12 * (1/2)</gadget>
<output>6</output>
<gadget id="calculator">6 * (1/2)</gadget>
<output>3</output>
<result>D</result> | D | 3 | Some persons can do a piece of work in 12 days. Two times the number of such persons will do half of that work in | {
"A": "9",
"B": "8",
"C": "4",
"D": "3",
"E": "1"
} | multiply(multiply(12, divide(const_1, const_2)), divide(const_1, const_2)) | divide(const_1,const_2)|multiply(n0,#0)|multiply(#0,#1)| | "explanation : let x men can do the in 12 days and the required number of days be z more men , less days [ indirect proportion ] less work , less days [ direct proportion ] answer : d ) 3 days" | physics |
math_qa__OLVTxRivTb8GCyUp | Find the number of zero’s in 173! (173 Factorial)? Choose the most appropriate option
A) 38
B) 39
C) 40
D) 41
E) 42 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">173 / 5</gadget>
<output>173/5 = around 34.6</output>
<gadget id="calculator">floor(173/5)</gadget>
<output>34</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">173 / 25</gadget>
<output>173/25 = around 6.92</output>
<gadget id="calculator">floor(173/25)</gadget>
<output>6</output>
<gadget id="calculator">34 + 6</gadget>
<output>40</output>
<gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<gadget id="calculator">173 / 125</gadget>
<output>173/125 = around 1.384</output>
<gadget id="calculator">floor(173/125)</gadget>
<output>1</output>
<gadget id="calculator">40 + 1</gadget>
<output>41</output>
<result>D</result> | D | 41 | Find the number of zero’s in 173! (173 Factorial)? | {
"A": "38",
"B": "39",
"C": "40",
"D": "41",
"E": "42"
} | add(add(floor(divide(173, add(const_1, const_4))), floor(divide(173, power(add(const_1, const_4), const_2)))), floor(divide(173, power(add(const_1, const_4), const_3)))) | add(const_1,const_4)|divide(n0,#0)|power(#0,const_2)|power(#0,const_3)|divide(n0,#2)|divide(n0,#3)|floor(#1)|floor(#4)|floor(#5)|add(#6,#7)|add(#9,#8) | no of zeroes in 173 ! is 173 / 5 = 34 ( quotient ) 34 / 5 = 6 ( quotient ) 6 / 5 = 1 ( quotient ) 34 + 6 + 1 = 41 ans 41 zeroes answer : d | other |
math_qa__f2qfEga3IiQqRHNP | When a person aged 39 is added to a group of n people, the average age increases by 2. When a person aged 15 is added instead, the average age decreases by 1. What is the value of E?
Choose the most appropriate option
A) 7
B) 8
C) 9
D) 10
E) 11 | <gadget id="calculator">39 - 15</gadget>
<output>24</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">24 / 3</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<result>A</result> | A | 7 | When a person aged 39 is added to a group of n people, the average age increases by 2. When a person aged 15 is added instead, the average age decreases by 1. What is the value of E? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | subtract(divide(subtract(39, 15), add(2, 1)), const_1) | add(n1,n3)|subtract(n0,n2)|divide(#1,#0)|subtract(#2,const_1) | a simple and elegant solution . as addition of 39 , shifts mean by 2 , and addition of 15 , shifts mean by 1 to the other side , we have the mean lying between 3915 , and in a ratio of 2 : 1 39 - 15 = 24 24 divide by 3 is 8 . meaning mean of the n terms is 15 + 8 = 39 - 16 = 23 now , from first statement , when a person aged 39 is added to a group of n people , the average age increases by 2 . e * 23 + 39 = 25 * ( e + 1 ) e = 7 ans . ( a ) | general |
math_qa__HCRs0mzu2P6Dpi3E | the present age of a father is 3 years more than 3 times the age of his son . 3 years hence , father as age will be 8 years more than twice the age of the son . find the present age of the father . Choose the correct option.
A) 88 B) 77 C) 33 D) 44 E) 27 | <gadget id="calculator">3 * 8</gadget>
<output>24</output>
<gadget id="calculator">24 + 3</gadget>
<output>27</output>
<result>E</result> | E | 27 | the present age of a father is 3 years more than 3 times the age of his son . 3 years hence , father as age will be 8 years more than twice the age of the son . find the present age of the father . | {
"A": "88",
"B": "77",
"C": "33",
"D": "44",
"E": "27"
} | add(multiply(3, 8), 3) | multiply(n0,n3)|add(n0,#0) | explanation : let the present age be ' x ' years . then father ' s present age is 3 x + 3 years . three years hence ( 3 x + 3 ) + 3 = 2 ( x + 3 ) + 8 x = 8 hence father ' s present age = 3 x + 3 = [ ( 3 x 8 ) + 3 ] = 27 years . answer : e | general |
math_qa__sQ7BfM0uiXGdV6GT | In measuring the sides of a rectangle, one side is taken 6% in excess, and the other 5% in deficit. Find the error percent in the area calculated from these measurements. Options
A) 0.11 % B) 0.7 % C) 0.4 % D) 0.6 % E) 0.8 % | <gadget id="calculator">6 - 5</gadget>
<output>1</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<result>B</result> | B | 0.7 | In measuring the sides of a rectangle, one side is taken 6% in excess, and the other 5% in deficit. Find the error percent in the area calculated from these measurements. | {
"A": "0.11 %",
"B": "0.7 %",
"C": "0.4 %",
"D": "0.6 %",
"E": "0.8 %"
} | subtract(subtract(6, 5), divide(multiply(6, 5), const_100)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,const_100)|subtract(#1,#2)| | "let x and y be the sides of the rectangle . then , correct area = xy . calculated area = ( 53 / 50 ) x ( 19 / 20 ) y = ( 144 / 143 ) ( xy ) error in measurement = ( 144 / 143 ) xy - xy = ( 1 / 143 ) xy error percentage = [ ( 1 / 143 ) xy ( 1 / xy ) 100 ] % = ( 7 / 10 ) % = 0.7 % . answer is b ." | geometry |
math_qa__pRZTKWM89ZhOnpBt | A courier charges for packages to a certain destination are 65 cents for the first 250 grams and 10 cents for each additional 100 grams or part thereof. What could be the weight in grams of a package for which the charge is $1.95?
Choices: A) 980 B) 1170 C) 1530 D) 1720 E) 1960 | <gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">1.95 - (13/20)</gadget>
<output>1.3</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) / 100</gadget>
<output>1/1_000 = around 0.001</output>
<gadget id="calculator">(1/1_000) * 250</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1.3 + (1/4)</gadget>
<output>1.55</output>
<gadget id="calculator">1.55 / (1/1_000)</gadget>
<output>1_550</output>
<result>C</result> | C | 1,530 | A courier charges for packages to a certain destination are 65 cents for the first 250 grams and 10 cents for each additional 100 grams or part thereof. What could be the weight in grams of a package for which the charge is $1.95? | {
"A": "980",
"B": "1170",
"C": "1530",
"D": "1720",
"E": "1960"
} | divide(add(subtract(1.95, divide(65, 100)), multiply(divide(divide(10, 100), 100), 250)), divide(divide(10, 100), 100)) | divide(n2,n3)|divide(n0,n3)|divide(#0,n3)|subtract(n4,#1)|multiply(n1,#2)|add(#4,#3)|divide(#5,#2)| | "the charge is 65 cents for the first 250 grams . this leaves a charge of $ 1.95 - $ 0.65 = $ 1.30 the charge for the next 1200 grams is $ 1.20 which leaves a charge of $ 0.10 the weight is somewhere between 1450 and 1550 . the answer is c ." | general |
math_qa__BxpvJks3XGcFL7xZ | If the diameter of circle R is 50% of the diameter of circle S, the area of circle R is what percent of the area of circle S? Answers
A) 35 % B) 25 % C) 20 % D) 15 % E) 10 % | <gadget id="calculator">pi * (50 ** 2)</gadget>
<output>2500*pi = around 7_853.981634</output>
<gadget id="calculator">(2500*pi) * 100</gadget>
<output>250000*pi = around 785_398.163397</output>
<gadget id="calculator">pi * (100 ** 2)</gadget>
<output>10000*pi = around 31_415.926536</output>
<gadget id="calculator">(250000*pi) / (10000*pi)</gadget>
<output>25</output>
<result>B</result> | B | 25 | If the diameter of circle R is 50% of the diameter of circle S, the area of circle R is what percent of the area of circle S? | {
"A": "35 %",
"B": "25 %",
"C": "20 %",
"D": "15 %",
"E": "10 %"
} | divide(multiply(circle_area(50), const_100), circle_area(const_100)) | circle_area(n0)|circle_area(const_100)|multiply(#0,const_100)|divide(#2,#1)| | "let diameter of circle r , dr = 50 and diameter of circle s , ds = 100 radius of circle r , rr = 25 radius of circle s , rs = 50 area of circle r / area of circle s = ( pi * rr ^ 2 ) / ( pi * rs ^ 2 ) = ( 25 / 50 ) ^ 2 = ( 5 / 10 ) ^ 2 = 25 % answer : b" | geometry |
math_qa__diXa2G1Mv4dCLFPm | A man's regular pay is $3 per hour up to 40 hours. Overtime is twice the payment for regular time. If he was paid $192, how many hours overtime did he work? Choose the correct answer
A) 8 B) 5 C) 9 D) 6 E) 12 | <gadget id="calculator">3 * 40</gadget>
<output>120</output>
<gadget id="calculator">192 - 120</gadget>
<output>72</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">72 / 6</gadget>
<output>12</output>
<result>E</result> | E | 12 | A man's regular pay is $3 per hour up to 40 hours. Overtime is twice the payment for regular time. If he was paid $192, how many hours overtime did he work? | {
"A": "8",
"B": "5",
"C": "9",
"D": "6",
"E": "12"
} | divide(subtract(192, multiply(3, 40)), multiply(3, const_2)) | multiply(n0,n1)|multiply(n0,const_2)|subtract(n2,#0)|divide(#2,#1)| | "at $ 3 per hour up to 40 hours , regular pay = $ 3 x 40 = $ 120 if total pay = $ 168 , overtime pay = $ 192 - $ 120 = $ 72 overtime rate ( twice regular ) = 2 x $ 3 = $ 6 per hour = > number of overtime hours = $ 72 / $ 6 = 12 ans is e" | physics |
math_qa__IBLxmvFInsmWtpNs | Excluding stoppages, the speed of a train is 55 kmph and including stoppages it is 40 kmph. Of how many minutes does the train stop per hour?
Choices.
A) 82
B) 16
C) 12
D) 82
E) 18 | <gadget id="calculator">40 / 55</gadget>
<output>8/11 = around 0.727273</output>
<gadget id="calculator">60 * (8/11)</gadget>
<output>480/11 = around 43.636364</output>
<gadget id="calculator">60 - (480/11)</gadget>
<output>180/11 = around 16.363636</output>
<result>B</result> | B | 16 | Excluding stoppages, the speed of a train is 55 kmph and including stoppages it is 40 kmph. Of how many minutes does the train stop per hour? | {
"A": "82",
"B": "16",
"C": "12",
"D": "82",
"E": "18"
} | subtract(const_60, multiply(const_60, divide(40, 55))) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "explanation : t = 15 / 55 * 60 = 16 answer : option b" | physics |
math_qa__0BipX5Zf9VWKOk73 | A train travels 210 km in 3 hours and 270 km in 4 hours.find the average speed of train. Choose the most appropriate option:
A) 80 kmph B) 69 kmph C) 70 kmph D) 90 kmph E) none of these | <gadget id="calculator">210 + 270</gadget>
<output>480</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">480 / 7</gadget>
<output>480/7 = around 68.571429</output>
<result>B</result> | B | 69 | A train travels 210 km in 3 hours and 270 km in 4 hours.find the average speed of train. | {
"A": "80 kmph",
"B": "69 kmph",
"C": "70 kmph",
"D": "90 kmph",
"E": "none of these"
} | divide(add(210, 270), add(3, 4)) | add(n0,n2)|add(n1,n3)|divide(#0,#1)| | "as we know that speed = distance / time for average speed = total distance / total time taken thus , total distance = 210 + 270 = 480 km thus , total speed = 7 hrs or , average speed = 480 / 7 or , 69 kmph . answer : b" | physics |
math_qa__y5XOuDrk3j5eSlC9 | 15 - 2 + 4 ÷ 1/2 × 8 = ? Answers:
A) 272
B) 77
C) 168
D) 56
E) 59 | <gadget id="calculator">15 - 2</gadget>
<output>13</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 / (1/2)</gadget>
<output>8</output>
<gadget id="calculator">8 * 8</gadget>
<output>64</output>
<gadget id="calculator">13 + 64</gadget>
<output>77</output>
<result>B</result> | B | 77 | 15 - 2 + 4 ÷ 1/2 × 8 = ? | {
"A": "272",
"B": "77",
"C": "168",
"D": "56",
"E": "59"
} | add(subtract(15, 2), multiply(divide(4, divide(const_1, const_2)), 8)) | divide(const_1,const_2)|subtract(n0,n1)|divide(n2,#0)|multiply(n5,#2)|add(#3,#1) | explanation : 15 - 2 + 4 ÷ 1 / 2 × 8 = 15 - 2 + 4 × 2 × 8 = 15 - 2 + 64 = 77 answer : option b | general |
math_qa__8ozWfQy6gSsVIaaF | The length of a rectangular garden is three times its width. If the area of the rectangular garden is 432 square meters, then what is the width of the rectangular garden? Choices:
A) 8
B) 9
C) 10
D) 11
E) 12 | <gadget id="calculator">432 / 3</gadget>
<output>144</output>
<gadget id="calculator">144 ** (1/2)</gadget>
<output>12</output>
<result>E</result> | E | 12 | The length of a rectangular garden is three times its width. If the area of the rectangular garden is 432 square meters, then what is the width of the rectangular garden? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | sqrt(divide(432, const_3)) | divide(n0,const_3)|sqrt(#0)| | "let x be the width of the garden . 3 x ^ 2 = 432 x ^ 2 = 144 x = 12 the answer is e ." | geometry |
math_qa__w1PbBo5YTHUIr3LT | When positive integer n is divided by 2, the remainder is 1. When n is divided by 7, the remainder is 5. What is the smallest positive integer p, such that (n + p) is a multiple of 10? Choose the correct choice from the following answers:
A) 1 B) 2 C) 5 D) 19 E) 20 | <gadget id="calculator">5 % 7</gadget>
<output>5</output>
<gadget id="calculator">10 - 5</gadget>
<output>5</output>
<result>C</result> | C | 5 | When positive integer n is divided by 2, the remainder is 1. When n is divided by 7, the remainder is 5. What is the smallest positive integer p, such that (n + p) is a multiple of 10? | {
"A": "1",
"B": "2",
"C": "5",
"D": "19",
"E": "20"
} | subtract(10, reminder(5, 7)) | reminder(n3,n2)|subtract(n4,#0)| | "when positive integer n is divided by 2 , the remainder is 1 i . e . , n = 2 x + 1 values of n can be one of { 1 , 3 , 5 , 7 , 9 , 11 , 13 , 15 , 17,19 , . . . . . . . . . . . . . . 31 , 33,35 . . . . . . . . . . . . . . . . . . } similarly , when n is divided by 7 , the remainder is 5 . . i . e . , n = 7 y + 5 values of n can be one of { 5 , 12 , 19 , 26 , 33 , 40 , 47 , 54 , 61 . . . . . . . . } combining both the sets we get n = { 19 , 52 , . . . . . . . . . . . } what is the smallest positive integer p , such that ( n + p ) is a multiple of 21 or 21 x in case of n = 5 p = 5 so for min value of p , we take min value of n . c is the answer ." | general |
math_qa__Y046oMm87M55Gxdp | There were totally 100 men.81 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married?
Answers.
A) 11
B) 12
C) 13
D) 14
E) 15 | <gadget id="calculator">100 - 81</gadget>
<output>19</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">19 + 25</gadget>
<output>44</output>
<gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">44 + 15</gadget>
<output>59</output>
<gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">59 + 30</gadget>
<output>89</output>
<gadget id="calculator">100 - 89</gadget>
<output>11</output>
<result>A</result> | A | 11 | There were totally 100 men.81 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married? | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | subtract(100, add(add(add(subtract(100, 81), subtract(100, 75)), subtract(100, 85)), subtract(100, 70))) | subtract(n0,n1)|subtract(n0,n2)|subtract(n0,n3)|subtract(n0,n4)|add(#0,#1)|add(#4,#2)|add(#5,#3)|subtract(n0,#6)| | "100 - ( 100 - 81 ) - ( 100 - 75 ) - ( 100 - 85 ) - ( 100 - 70 ) = 100 - 19 - 25 - 15 - 30 = 100 - 89 = 11 answer : a" | general |
math_qa__HpWKzIRRV2mQfm3X | Nicky and Cristina are running a 400 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? Choose the most appropriate option
A) 40 B) 25 C) 35 D) 30 E) 50 | <gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">36 / 3</gadget>
<output>12</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">12 + 18</gadget>
<output>30</output>
<result>D</result> | D | 30 | Nicky and Cristina are running a 400 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? | {
"A": "40",
"B": "25",
"C": "35",
"D": "30",
"E": "50"
} | add(divide(multiply(3, 12), 3), divide(multiply(3, 12), subtract(5, 3))) | multiply(n1,n3)|subtract(n2,n3)|divide(#0,n3)|divide(#0,#1)|add(#2,#3)| | "the distance traveled by both of them is the same at the time of overtaking . 3 ( t + 12 ) = 5 t t = 18 . cristina will catch up nicky in 18 seconds . so in 18 seconds cristina would cover = 18 * 5 = 90 meter . now time taken my nicky to cover 90 meter = 90 / 3 = 30 seconds . d" | physics |
math_qa__JQu1qbW8vyPJK8iR | Danny and Steve are running towards each other, each one from his own house. Danny can reach Steve's house in 35 minutes of running, which is half the time it takes Steve to reach Danny's house. If the two started to run at the same time, how much time longer will it take Steve to reach the halfway point between their houses than Danny to reach the halfway point between their houses? Pick one
A) 17.5 minutes .
B) 35 minutes .
C) 52.5 minutes .
D) 70 minutes .
E) 105 minutes . | <gadget id="calculator">35 / 2</gadget>
<output>35/2 = around 17.5</output>
<result>A</result> | A | 17.5 | Danny and Steve are running towards each other, each one from his own house. Danny can reach Steve's house in 35 minutes of running, which is half the time it takes Steve to reach Danny's house. If the two started to run at the same time, how much time longer will it take Steve to reach the halfway point between their houses than Danny to reach the halfway point between their houses? | {
"A": "17.5 minutes .",
"B": "35 minutes .",
"C": "52.5 minutes .",
"D": "70 minutes .",
"E": "105 minutes ."
} | divide(35, const_2) | divide(n0,const_2)| | "danny ' s time is 35 minutes . the time to reach halfway is 17.5 minutes . steve ' s time is 70 minutes . the time to reach halfway is 35 minutes . the time difference is 35 - 17.5 = 17.5 minutes the answer is a ." | physics |
math_qa__avjusdtLvgRrBeLn | A vessel of capacity 2 litre has 20% of alcohol and another vessel of capacity 6 litre had 40% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of Mixture? Choices
A) 31 % . B) 71 % . C) 49 % . D) 29 % . E) 28 % . | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 2</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 6</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(2/5) + (12/5)</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">(14/5) / 10</gadget>
<output>7/25 = around 0.28</output>
<gadget id="calculator">(7/25) * 100</gadget>
<output>28</output>
<result>E</result> | E | 28 | A vessel of capacity 2 litre has 20% of alcohol and another vessel of capacity 6 litre had 40% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of Mixture? | {
"A": "31 % .",
"B": "71 % .",
"C": "49 % .",
"D": "29 % .",
"E": "28 % ."
} | multiply(divide(add(multiply(divide(20, const_100), 2), multiply(divide(40, const_100), 6)), 10), const_100) | divide(n1,const_100)|divide(n3,const_100)|multiply(n0,#0)|multiply(n2,#1)|add(#2,#3)|divide(#4,n5)|multiply(#5,const_100)| | "20 % of 2 litres = 0.4 litres 40 % of 6 litres = 2.4 litres therefore , total quantity of alcohol is 2.8 litres . this mixture is in a 10 litre vessel . hence , the concentration of alcohol in this 10 litre vessel is 28 % answer : e" | general |
math_qa__uOd2f9PVwlckzwGE | In a kilometer race, A beats B by 60 meters or 10 seconds. What time does A take to complete the race?
Pick one: A) 199 sec B) 156.7 sec C) 726 sec D) 127 sec E) 128 sec | <gadget id="calculator">1 * 1_000</gadget>
<output>1_000</output>
<gadget id="calculator">60 / 10</gadget>
<output>6</output>
<gadget id="calculator">1_000 / 6</gadget>
<output>500/3 = around 166.666667</output>
<gadget id="calculator">(500/3) - 10</gadget>
<output>470/3 = around 156.666667</output>
<result>B</result> | B | 156.7 | In a kilometer race, A beats B by 60 meters or 10 seconds. What time does A take to complete the race? | {
"A": "199 sec",
"B": "156.7 sec",
"C": "726 sec",
"D": "127 sec",
"E": "128 sec"
} | subtract(divide(multiply(const_1, const_1000), divide(60, 10)), 10) | divide(n0,n1)|multiply(const_1,const_1000)|divide(#1,#0)|subtract(#2,n1)| | "time taken by b run 1000 meters = ( 1000 * 10 ) / 60 = 166.7 sec . time taken by a = 166.7 - 10 = 156.7 sec . answer : b" | physics |
math_qa__bwxqvcs3Ty0n62Dg | The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 120 metres?
Options.
A) 18 B) 24 C) 17 D) 12 E) 13 | <gadget id="calculator">15 + 3</gadget>
<output>18</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">18 * (5/18)</gadget>
<output>5</output>
<gadget id="calculator">120 / 5</gadget>
<output>24</output>
<result>B</result> | B | 24 | The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 120 metres? | {
"A": "18",
"B": "24",
"C": "17",
"D": "12",
"E": "13"
} | divide(120, multiply(add(15, 3), const_0_2778)) | add(n0,n1)|multiply(#0,const_0_2778)|divide(n2,#1)| | "speed of the boat downstream = 15 + 3 = 18 kmph = 18 * 5 / 18 = 5 m / s hence time taken to cover 120 m = 120 / 5 = 24 seconds . answer : b" | physics |
math_qa__GUmNmgM7SDAXF6Um | The perimeter of one face of a cube is 24 cm. Its volume will be:
Choose the correct choice from the following answers.
A) 216 cm 3 B) 400 cm 3 C) 250 cm 3 D) 625 cm 3 E) none of these | <gadget id="calculator">24 / 4</gadget>
<output>6</output>
<gadget id="calculator">6 ** 3</gadget>
<output>216</output>
<result>A</result> | A | 216 | The perimeter of one face of a cube is 24 cm. Its volume will be: | {
"A": "216 cm 3",
"B": "400 cm 3",
"C": "250 cm 3",
"D": "625 cm 3",
"E": "none of these"
} | volume_cube(square_edge_by_perimeter(24)) | square_edge_by_perimeter(n0)|volume_cube(#0)| | "explanation : edge of cude = 24 / 4 = 6 cm volume = a * a * a = 6 * 6 * 6 = 216 cm cube option a" | geometry |
math_qa__W5xdmQzNrf2HoffL | When a train moves at an average speed of 100 kmph it reaches its destination on time. When its average speed becomes 80 kmph, then it reaches its destination 20 minutes late. Find the length of journey rounded to two decimal places. Choices: A) 99.33 km B) 133.33 km C) 125.33 km D) 156.66 km E) none | <gadget id="calculator">20 / 60</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">100 * 80</gadget>
<output>8_000</output>
<gadget id="calculator">20 / 8_000</gadget>
<output>1/400 = around 0.0025</output>
<gadget id="calculator">(1/3) / (1/400)</gadget>
<output>400/3 = around 133.333333</output>
<result>B</result> | B | 133.33 | When a train moves at an average speed of 100 kmph it reaches its destination on time. When its average speed becomes 80 kmph, then it reaches its destination 20 minutes late. Find the length of journey rounded to two decimal places. | {
"A": "99.33 km",
"B": "133.33 km",
"C": "125.33 km",
"D": "156.66 km",
"E": "none"
} | divide(divide(20, const_60), divide(subtract(100, 80), multiply(100, 80))) | divide(n2,const_60)|multiply(n0,n1)|subtract(n0,n1)|divide(#2,#1)|divide(#0,#3) | sol . difference between timings = 20 min = 1 / 3 hr . let the length of journey be x km . then , x / 80 - x / 100 = 1 / 3 â ‡ ” 5 x - 4 x = 133.33 â ‡ ” x = 133.33 km . answer b | physics |
math_qa__aUQ9R9iFi8LdMgpd | A certain bacteria colony doubles in size every day for 20 days, at which point it reaches the limit of its habitat and can no longer grow. If two bacteria colonies start growing simultaneously, how many days will it take them to reach the habitat’s limit? Answers
A) 6.33
B) 7.5
C) 10
D) 15
E) 19 | <gadget id="calculator">20 / 20</gadget>
<output>1</output>
<gadget id="calculator">20 - 1</gadget>
<output>19</output>
<result>E</result> | E | 19 | A certain bacteria colony doubles in size every day for 20 days, at which point it reaches the limit of its habitat and can no longer grow. If two bacteria colonies start growing simultaneously, how many days will it take them to reach the habitat’s limit? | {
"A": "6.33",
"B": "7.5",
"C": "10",
"D": "15",
"E": "19"
} | subtract(20, divide(20, 20)) | divide(n0,n0)|subtract(n0,#0)| | "simultaneous grow = same amount of time in 20 days we should expect to have p ( 2 ) ^ 20 so if we have two things doing the job of getting us there then ; 2 ^ x + 2 ^ x = 20 2 ( 2 ) ^ x = 2 2 ^ ( x + 1 ) = 2 ^ 20 x + 1 = 20 x = 19 ; answer : e" | physics |
math_qa__8sjuFAdreTdynK87 | Julie put half of her savings in a savings account that pays an annual simple interest and half in a savings account that pays an annual compound interest. After two years she earned $120 and $126 from the simple interest account and the compound interest account respectively. If the interest rates for both accounts were the same, what was the amount of Julie's initial savings? Choose the correct choice from the following choices: A) 600 B) 720 C) 1080 D) 1200 E) 1440 | <gadget id="calculator">126 - 120</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">12 / 120</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">120 / (1/10)</gadget>
<output>1_200</output>
<result>D</result> | D | 1,200 | Julie put half of her savings in a savings account that pays an annual simple interest and half in a savings account that pays an annual compound interest. After two years she earned $120 and $126 from the simple interest account and the compound interest account respectively. If the interest rates for both accounts were the same, what was the amount of Julie's initial savings? | {
"A": "600",
"B": "720",
"C": "1080",
"D": "1200",
"E": "1440"
} | divide(120, divide(multiply(const_2, subtract(126, 120)), 120)) | subtract(n1,n0)|multiply(#0,const_2)|divide(#1,n0)|divide(n0,#2)| | "$ 120 for 2 years = $ 60 per year . extra $ 6 yearned with the compound interest is the percent yearned on percent . so , $ 6 is yearned on $ 60 , which means that the interest = 10 % . this on the other hand means that half of the savings = 60 * 10 = $ 600 . twice of that = $ 1,200 . answer : d ." | gain |
math_qa__sQ4gevlKdENS0e1T | Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 asquotient and the 15 as remainder? Pick one.
A) 1234 B) 1540 C) 1650 D) 1632 E) 1635 | <gadget id="calculator">1_365 - 15</gadget>
<output>1_350</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">1_350 / 5</gadget>
<output>270</output>
<gadget id="calculator">270 * 6</gadget>
<output>1_620</output>
<result>E</result> | E | 1,635 | Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 asquotient and the 15 as remainder? | {
"A": "1234",
"B": "1540",
"C": "1650",
"D": "1632",
"E": "1635"
} | multiply(divide(subtract(1365, 15), subtract(6, const_1)), 6) | subtract(n0,n2)|subtract(n1,const_1)|divide(#0,#1)|multiply(n1,#2)| | "let the smaller number be x . then larger number = ( x + 1365 ) . x + 1365 = 6 x + 15 5 x = 1350 x = 270 large number = 270 + 1365 = 1635 e" | general |
math_qa__XdvCJ0gaxCbmyJi1 | Joan and Karl each bought a sofa and the sum of their purchases was $600. If twice of what Joan paid was $90 more than what Karl paid, what did Joan pay for her sofa?
Options:
A) $ 190
B) $ 210
C) $ 230
D) $ 250
E) $ 270 | <gadget id="calculator">600 + 90</gadget>
<output>690</output>
<gadget id="calculator">690 / 3</gadget>
<output>230</output>
<result>C</result> | C | 230 | Joan and Karl each bought a sofa and the sum of their purchases was $600. If twice of what Joan paid was $90 more than what Karl paid, what did Joan pay for her sofa? | {
"A": "$ 190",
"B": "$ 210",
"C": "$ 230",
"D": "$ 250",
"E": "$ 270"
} | divide(add(600, 90), const_3) | add(n0,n1)|divide(#0,const_3) | j + k = 600 so k = 600 - j 2 j = k + 90 2 j = ( 600 - j ) + 90 3 j = 690 j = 230 the answer is c . | general |
math_qa__Av5ZQdsYzVNoHgvE | A reduction of 18% in the price of oil enables a house wife to obtain 8kgs more for Rs.1080, what is the reduced price for kg? Choose the correct choice from the following answers.
A) 72.15 B) 27.24 C) 24.25 D) 28.46 E) 20.9 | <gadget id="calculator">1_080 * 18</gadget>
<output>19_440</output>
<gadget id="calculator">19_440 / 100</gadget>
<output>972/5 = around 194.4</output>
<gadget id="calculator">(972/5) / 8</gadget>
<output>243/10 = around 24.3</output>
<result>C</result> | C | 24.25 | A reduction of 18% in the price of oil enables a house wife to obtain 8kgs more for Rs.1080, what is the reduced price for kg? | {
"A": "72.15",
"B": "27.24",
"C": "24.25",
"D": "28.46",
"E": "20.9"
} | divide(divide(multiply(1080, 18), const_100), 8) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)| | "1080 * ( 18 / 100 ) = 194 - - - - 8 ? - - - - 1 = > rs . 24.25 answer : c" | gain |
math_qa__x8DaRt0H12IDFDPw | A satellite is composed of 24 modular units, each of which is equipped with a set of sensors, some of which have been upgraded. Each unit contains the same number of non-upgraded sensors. If the number of non-upgraded sensors on one unit is 1/6 the total number of upgraded sensors on the entire satellite, what fraction of the sensors on the satellite have been upgraded? Choose the most appropriate option.
A) 5 / 6 B) 1 / 5 C) 1 / 6 D) 1 / 7 E) 1 / 24 | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 24</gadget>
<output>4</output>
<gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">24 + 96</gadget>
<output>120</output>
<gadget id="calculator">24 / 120</gadget>
<output>1/5 = around 0.2</output>
<result>B</result> | B | 0.2 | A satellite is composed of 24 modular units, each of which is equipped with a set of sensors, some of which have been upgraded. Each unit contains the same number of non-upgraded sensors. If the number of non-upgraded sensors on one unit is 1/6 the total number of upgraded sensors on the entire satellite, what fraction of the sensors on the satellite have been upgraded? | {
"A": "5 / 6",
"B": "1 / 5",
"C": "1 / 6",
"D": "1 / 7",
"E": "1 / 24"
} | divide(24, add(24, multiply(24, multiply(divide(1, 6), 24)))) | divide(n1,n2)|multiply(n0,#0)|multiply(n0,#1)|add(n0,#2)|divide(n0,#3)| | "let x be the number of upgraded sensors on the satellite . the number of non - upgraded sensors per unit is x / 6 . the number of non - upgraded sensors on the whole satellite is 24 ( x / 6 ) = 4 x . the fraction of sensors which have been upgraded is x / ( x + 4 x ) = x / 5 x = 1 / 5 the answer is b ." | general |
math_qa__Aqkl4qJQDV1ycoeY | A copy machine, working at a constant rate, makes 30 copies per minute. A second copy machine, working at a constant rate, makes 55 copies per minute. Working together at their respective rates, how many copies do the two machines make in half an hour ? Options.
A) 90 B) 2,700 C) 4,500 D) 2,550 E) 324,000 | <gadget id="calculator">30 + 55</gadget>
<output>85</output>
<gadget id="calculator">85 * 60</gadget>
<output>5_100</output>
<gadget id="calculator">5_100 / 2</gadget>
<output>2_550</output>
<result>D</result> | D | 2,550 | A copy machine, working at a constant rate, makes 30 copies per minute. A second copy machine, working at a constant rate, makes 55 copies per minute. Working together at their respective rates, how many copies do the two machines make in half an hour ? | {
"A": "90",
"B": "2,700",
"C": "4,500",
"D": "2,550",
"E": "324,000"
} | divide(multiply(add(30, 55), const_60), const_2) | add(n0,n1)|multiply(#0,const_60)|divide(#1,const_2)| | "together the two machines make 30 + 55 = 85 copies per minute . so , in half an hour they will make 85 * 30 = 2,550 copies . answer : d ." | physics |
math_qa__vCkGJK0X3vLo4Rdp | The average salary of the employees in a office is Rs.120/month.The avg salary of officers is Rs.450 and of non officers is Rs 110. If the no.of officers is 15,then find the No of nonofficers in the office.
Pick one: A) 400 B) 420 C) 430 D) 495 E) 510 | <gadget id="calculator">15 * 450</gadget>
<output>6_750</output>
<gadget id="calculator">15 * 120</gadget>
<output>1_800</output>
<gadget id="calculator">6_750 - 1_800</gadget>
<output>4_950</output>
<gadget id="calculator">120 - 110</gadget>
<output>10</output>
<gadget id="calculator">4_950 / 10</gadget>
<output>495</output>
<result>D</result> | D | 495 | The average salary of the employees in a office is Rs.120/month.The avg salary of officers is Rs.450 and of non officers is Rs 110. If the no.of officers is 15,then find the No of nonofficers in the office. | {
"A": "400",
"B": "420",
"C": "430",
"D": "495",
"E": "510"
} | divide(subtract(multiply(15, 450), multiply(15, 120)), subtract(120, 110)) | multiply(n1,n3)|multiply(n0,n3)|subtract(n0,n2)|subtract(#0,#1)|divide(#3,#2) | let no . of non - officers be x 15 * 450 + x * 110 = ( x + 15 ) 120 x = 495 d | general |
math_qa__36ATHBpaedLYpARl | There are 15 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played? Choose one
A) 10 B) 30 C) 105 D) 60 E) 90 | <gadget id="calculator">15 - 1</gadget>
<output>14</output>
<gadget id="calculator">15 * 14</gadget>
<output>210</output>
<gadget id="calculator">210 / 2</gadget>
<output>105</output>
<result>C</result> | C | 105 | There are 15 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played? | {
"A": "10",
"B": "30",
"C": "105",
"D": "60",
"E": "90"
} | divide(multiply(15, subtract(15, const_1)), const_2) | subtract(n0,const_1)|multiply(n0,#0)|divide(#1,const_2) | 15 players are there . two players play one game with one another . so 15 c 2 = 15 x 14 / 2 = 105 so option c is correct | general |
math_qa__TLytS4FC9weUf94G | Two heavily loaded sixteen-wheeler transport trucks are 855 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway? Options
A) 90 B) 130 C) 135 D) 320 E) 450 | <gadget id="calculator">855 - 90</gadget>
<output>765</output>
<gadget id="calculator">90 + 80</gadget>
<output>170</output>
<gadget id="calculator">765 / 170</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">90 - 80</gadget>
<output>10</output>
<gadget id="calculator">(9/2) * 10</gadget>
<output>45</output>
<gadget id="calculator">90 + 45</gadget>
<output>135</output>
<result>C</result> | C | 135 | Two heavily loaded sixteen-wheeler transport trucks are 855 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway? | {
"A": "90",
"B": "130",
"C": "135",
"D": "320",
"E": "450"
} | add(90, multiply(divide(subtract(855, 90), add(90, 80)), subtract(90, 80))) | add(n1,n2)|subtract(n0,n1)|subtract(n1,n2)|divide(#1,#0)|multiply(#3,#2)|add(n1,#4)| | "i ' ve been reading the website for a while and i ' m always keen to see different approaches so i would like to share one that works for me : short version : truck a travels for an hour . distance remaining = 855 - 90 = 765 k ratio of speeds 9 : 8 - > 765 / 17 = 45 truck a = 90 + 45 * 9 = 495 truck b = 45 * 8 = 360 delta = 135 km answer c" | general |
math_qa__qxW6MgiaH66HUNJx | A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 300. How much did he have with him in the beginning? Choose the correct choice from the following answers:
A) s 200
B) s 750
C) s 300
D) s 450
E) s 550 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) / 5</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(2/3) - (2/15)</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">(8/15) / 4</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(8/15) - (2/15)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">300 / (2/5)</gadget>
<output>750</output>
<result>B</result> | B | 750 | A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 300. How much did he have with him in the beginning? | {
"A": "s 200",
"B": "s 750",
"C": "s 300",
"D": "s 450",
"E": "s 550"
} | divide(300, subtract(subtract(subtract(1, divide(1, 3)), divide(subtract(1, divide(1, 3)), 5)), divide(subtract(subtract(1, divide(1, 3)), divide(subtract(1, divide(1, 3)), 5)), 4))) | divide(n0,n1)|subtract(n0,#0)|divide(#1,n3)|subtract(#1,#2)|divide(#3,n5)|subtract(#3,#4)|divide(n6,#5)| | "suppose the amount in the beginning was rs ’ x ’ money spent on clothes = rs 1 x / 3 balance = rs 2 x / 3 money spent on food = 1 / 5 of 2 x / 3 = rs 2 x / 15 balance = 2 x / 3 - 2 x / 15 = rs 8 x / 15 money spent on travel = 1 / 4 of 8 x / 15 = rs 2 x / 15 = 8 x / 15 - 2 x / 15 = 6 x / 15 = rs 2 x / 5 therefore 2 x / 5 = 300 = 750 answer : b" | general |
math_qa__uSQF66Ij7zEBgMPD | A student is ranked 16th from right and 6th from left. How many students are there in totality ? Choose the correct choice from the following choices: A) 18 B) 19 C) 20 D) 21 E) 22 | <gadget id="calculator">16 + 6</gadget>
<output>22</output>
<gadget id="calculator">22 - 1</gadget>
<output>21</output>
<result>D</result> | D | 21 | A student is ranked 16th from right and 6th from left. How many students are there in totality ? | {
"A": "18",
"B": "19",
"C": "20",
"D": "21",
"E": "22"
} | subtract(add(16, 6), const_1) | add(n0,n1)|subtract(#0,const_1)| | "from right 16 , from left 6 total = 16 + 6 - 1 = 21 answer : d" | general |
math_qa__g67wiTJSfNp3qhMP | The sum of the first 50 positive even integers is 2550. What is the sum W of even integers from 102 to 200 inclusive? Pick one
A) 5100 B) 7550 C) 10100 D) 15500 E) 20100 | <gadget id="calculator">200 + 102</gadget>
<output>302</output>
<gadget id="calculator">302 / 2</gadget>
<output>151</output>
<gadget id="calculator">200 - 102</gadget>
<output>98</output>
<gadget id="calculator">98 / 2</gadget>
<output>49</output>
<gadget id="calculator">49 + 1</gadget>
<output>50</output>
<gadget id="calculator">151 * 50</gadget>
<output>7_550</output>
<result>B</result> | B | 7,550 | The sum of the first 50 positive even integers is 2550. What is the sum W of even integers from 102 to 200 inclusive? | {
"A": "5100",
"B": "7550",
"C": "10100",
"D": "15500",
"E": "20100"
} | multiply(divide(add(200, 102), const_2), add(divide(subtract(200, 102), const_2), const_1)) | add(n2,n3)|subtract(n3,n2)|divide(#1,const_2)|divide(#0,const_2)|add(#2,const_1)|multiply(#4,#3)| | "my solution is : first 50 even integers : 2 4 6 8 < . . . > integers from 102 to 200 102 104 106 108 < . . . > we notice that each integer from the second set is 100 more than the respective integer in the first set . since we have 50 even integers from 102 to 200 , then : w = 2550 + ( 100 * 50 ) = 7550 . b" | general |
math_qa__2sg67RrjcGr7Pbrs | If a number x is 10% less than another number y and y is 10% more than 125, then x is equal to Select:
A) 143 B) 150 C) 123.75 D) 140.55 E) none | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">125 * (11/10)</gadget>
<output>275/2 = around 137.5</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(275/2) * (9/10)</gadget>
<output>495/4 = around 123.75</output>
<result>C</result> | C | 123.75 | If a number x is 10% less than another number y and y is 10% more than 125, then x is equal to | {
"A": "143",
"B": "150",
"C": "123.75",
"D": "140.55",
"E": "none"
} | multiply(multiply(125, add(const_1, divide(10, const_100))), divide(subtract(const_100, 10), const_100)) | divide(n0,const_100)|subtract(const_100,n0)|add(#0,const_1)|divide(#1,const_100)|multiply(n2,#2)|multiply(#3,#4) | solution y = 125 + 10 % of 125 = 125 + 12.50 = 137.50 . x = 137.50 - 10 % of 137.50 = 137.50 - 13.75 = 123.75 . answer c | general |
math_qa__7IXY6BxREgXyrMJv | If a car had traveled 30 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 90 km, at what speed did it travel? Choose one:
A) 35 kmh B) 45 kmh C) 60 kmh D) 75 kmh E) 90 kmh | <gadget id="calculator">90 * 30</gadget>
<output>2_700</output>
<gadget id="calculator">2 * 2_700</gadget>
<output>5_400</output>
<gadget id="calculator">5_400 * 4</gadget>
<output>21_600</output>
<gadget id="calculator">30 ** 2</gadget>
<output>900</output>
<gadget id="calculator">21_600 + 900</gadget>
<output>22_500</output>
<gadget id="calculator">22_500 ** (1/2)</gadget>
<output>150</output>
<gadget id="calculator">150 - 30</gadget>
<output>120</output>
<gadget id="calculator">120 / 2</gadget>
<output>60</output>
<result>C</result> | C | 60 | If a car had traveled 30 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 90 km, at what speed did it travel? | {
"A": "35 kmh",
"B": "45 kmh",
"C": "60 kmh",
"D": "75 kmh",
"E": "90 kmh"
} | divide(subtract(sqrt(add(multiply(multiply(const_2, multiply(90, 30)), const_4), power(30, const_2))), 30), const_2) | multiply(n0,n2)|power(n0,const_2)|multiply(#0,const_2)|multiply(#2,const_4)|add(#3,#1)|sqrt(#4)|subtract(#5,n0)|divide(#6,const_2)| | "time = distance / speed difference in time = 1 / 2 hrs 90 / x - 90 / ( x + 30 ) = 1 / 2 substitute the value of x from the options . - - > x = 60 - - > 90 / 60 - 90 / 90 = 3 / 2 - 1 = 1 / 2 answer : c" | physics |
math_qa__VDRyQeXRHjeJ3Gn4 | The length and width of a rectangle are integer values. What is the area of the smallest such rectangle that can be inscribed in a circle whose radius is also an integer
Choose the correct choice from the following choices.
A) 12 B) 45 C) 36 D) 48 E) 60 | <gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">4 + 40</gadget>
<output>44</output>
<result>B</result> | B | 45 | The length and width of a rectangle are integer values. What is the area of the smallest such rectangle that can be inscribed in a circle whose radius is also an integer | {
"A": "12",
"B": "45",
"C": "36",
"D": "48",
"E": "60"
} | add(const_4, rectangle_area(const_10, const_4)) | rectangle_area(const_10,const_4)|add(#0,const_4) | if we consider all pythagorean triplets with integral values , we have the following results : - ( 3 , 4,5 ) , ( 6 , 8,10 ) . . . . . . . . the diameter of the circle is 5 in the 1 st case and 10 in the 2 nd . but the question says that radius of the circle is also an integer hence the 1 st triplet will be ruled out . we are left with the 2 nd triplet where radius of the circle = 5 , hence the sides of the rectangle are 6 and 8 making the area = 45 . b | geometry |
math_qa__VwjIDGHG59gAzxfm | Janet invited her Boy and Girl friends to her party at the ratio of 3:7. If 30% of the Boys and 70% of the Girls will be coming for the party from Texas, How many Janet invited friends will be coming from Texas. Choose the correct choice from the following options.
A) 62 %
B) 52 %
C) 57 %
D) 56 %
E) 58 % | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 7</gadget>
<output>49/10 = around 4.9</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 3</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(49/10) + (9/10)</gadget>
<output>29/5 = around 5.8</output>
<gadget id="calculator">(29/5) * 10</gadget>
<output>58</output>
<result>E</result> | E | 58 | Janet invited her Boy and Girl friends to her party at the ratio of 3:7. If 30% of the Boys and 70% of the Girls will be coming for the party from Texas, How many Janet invited friends will be coming from Texas. | {
"A": "62 %",
"B": "52 %",
"C": "57 %",
"D": "56 %",
"E": "58 %"
} | multiply(add(multiply(divide(70, const_100), 7), multiply(divide(30, const_100), 3)), const_10) | divide(n3,const_100)|divide(n2,const_100)|multiply(n1,#0)|multiply(n0,#1)|add(#2,#3)|multiply(#4,const_10) | let total no of janet invited friends be 100 , boys 30 and girls 70 , so total number of janet ' s invited guests coming from texas for both boys and girls respectively 30 * 30 / 100 = 9 and 70 * 70 / 100 = 49 so total 58 of janet ' s invited guest out of the 100 invited guests will be coming from texas . . so required % is 58 % answer : e | other |
math_qa__4qfu9Qloa1xXQPey | A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 3 hours. How long will B alone take to do it? Choose the correct choice:
A) 12 B) 9 C) 8 D) 6 E) 4 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) - (1/4)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/3) - (1/12)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / (1/4)</gadget>
<output>4</output>
<result>E</result> | E | 4 | A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 3 hours. How long will B alone take to do it? | {
"A": "12",
"B": "9",
"C": "8",
"D": "6",
"E": "4"
} | divide(const_1, subtract(divide(const_1, 3), subtract(divide(const_1, 3), divide(const_1, 4)))) | divide(const_1,n1)|divide(const_1,n2)|divide(const_1,n0)|subtract(#1,#2)|subtract(#0,#3)|divide(const_1,#4)| | "a ' s 1 hour ' s work = 1 / 4 ; ( b + c ) ' s 1 hour ' s work = 1 / 3 ; ( a + c ) ' s 1 hour ' s work = 1 / 3 . ( a + b + c ) ' s 1 hour ' s work = ( 1 / 4 + 1 / 3 ) = 7 / 12 . b ' s 1 hour ' s work = ( 7 / 12 - 1 / 3 ) = 1 / 4 . therefore a alone will take 4 hours to do the work . e" | physics |
math_qa__fMf6veka0bJPUmBU | Cost is expressed by the formula tb^4. If b is doubled, the new cost is what percent of the original cost? Choose the correct choice from the following answers
A) 200 B) 600 C) 800 D) 1600 E) 50 | <gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 100</gadget>
<output>1_600</output>
<result>D</result> | D | 1,600 | Cost is expressed by the formula tb^4. If b is doubled, the new cost is what percent of the original cost? | {
"A": "200",
"B": "600",
"C": "800",
"D": "1600",
"E": "50"
} | multiply(power(const_2, 4), const_100) | power(const_2,n0)|multiply(#0,const_100)| | "original cost c 1 = t 1 * b 1 ^ 4 new cost c 2 = t 2 * b 2 ^ 4 . . . . only b is doubled so t 2 = t 1 and b 2 = 2 b 1 c 2 = t 2 * ( 2 b 1 ) ^ 4 = 16 ( t 1 * b 1 ^ 4 ) = 16 c 1 16 times c 1 = > 1600 % of c 1 ans d = 1600" | general |
math_qa__kWtBBHdZkMAOfcjJ | 3 people each took 5 tests . if the ranges of their scores in the 5 practice tests were 17 , 28 and 35 , 45 what is the minimum possible range in scores of the 3 test - takers ?
Options:
A) a 17 B) 28 C) 35 D) 45 E) 80 | <gadget id="calculator">35 + 5</gadget>
<output>40</output>
<gadget id="calculator">40 + 5</gadget>
<output>45</output>
<result>D</result> | D | 45 | 3 people each took 5 tests . if the ranges of their scores in the 5 practice tests were 17 , 28 and 35 , 45 what is the minimum possible range in scores of the 3 test - takers ? | {
"A": "a 17",
"B": "28",
"C": "35",
"D": "45",
"E": "80"
} | add(add(35, 5), 5) | add(n1,n5)|add(n1,#0) | it is finding the minimum range between all their scores , if all test taker scores are between 0 and maximum range we will have : a - 0 and 17 b - 0 and 28 c - 0 and 35 d - 0 and 45 therefore the minimum range is 45 , it cant be any lower however you play with the numbers . d | general |
math_qa__QXcJUEDntThs3q5d | A sum of money is distributed among A,B,C,D in the proportion of 5:3:2:3. If A gets $1000 more than B, what is the C's share? Choose one
A) $ 2000 B) $ 5000 C) $ 8000 D) $ 1500 E) $ 1000 | <gadget id="calculator">1_000 + 1_000</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 * 2</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 / 4</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 3</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 3</gadget>
<output>1_000</output>
<result>E</result> | E | 1,000 | A sum of money is distributed among A,B,C,D in the proportion of 5:3:2:3. If A gets $1000 more than B, what is the C's share? | {
"A": "$ 2000",
"B": "$ 5000",
"C": "$ 8000",
"D": "$ 1500",
"E": "$ 1000"
} | divide(multiply(divide(multiply(add(1000, 1000), const_2.0), const_4.0), 3), 3) | add(n4,n4)|multiply(const_2.0,#0)|divide(#1,const_4.0)|multiply(n1,#2)|divide(#3,n3)| | "let the shares of a , b , c , d are 5 x , 3 x , 2 x , 3 x 5 x - 3 x = 1000 x = 500 c ' s share = 2 x = $ 1000 answer is e" | general |
math_qa__K1hNIOfrQe1Nulgy | Two boys starts from the same place walking at the rate of 5.5 kmph and 7.5 kmph respectively in the same direction. What time will they take to be 32 km apart?
Choose one:
A) 18
B) 16
C) 19
D) 15
E) 34 | <gadget id="calculator">7.5 - 5.5</gadget>
<output>2</output>
<gadget id="calculator">32 / 2</gadget>
<output>16</output>
<result>B</result> | B | 16 | Two boys starts from the same place walking at the rate of 5.5 kmph and 7.5 kmph respectively in the same direction. What time will they take to be 32 km apart? | {
"A": "18",
"B": "16",
"C": "19",
"D": "15",
"E": "34"
} | divide(32, subtract(7.5, 5.5)) | subtract(n1,n0)|divide(n2,#0)| | "explanation : relative speed = 7.5 - 5.5 = 2 kmph ( because they walk in the same direction ) distance = 32 km time = distance / speed = 32 / 2 = 16 hr answer : b" | gain |
math_qa__ZoDiDIeoqg0MWGIc | Two thirds of the roads from A to B are at least 5 miles long, and 1/2 of the roads from B to C are at least 5 miles long. If you randomly pick a road from A to B and then randomly pick a road from B to C, what is the probability that at least one of the roads you pick is at least 5 miles long?
Options:
A) 5 / 6
B) 1 / 4
C) 2 / 3
D) 3 / 4
E) 11 / 12 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 - (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/3) * (1/2)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 - (1/6)</gadget>
<output>5/6 = around 0.833333</output>
<result>A</result> | A | 0.833333 | Two thirds of the roads from A to B are at least 5 miles long, and 1/2 of the roads from B to C are at least 5 miles long. If you randomly pick a road from A to B and then randomly pick a road from B to C, what is the probability that at least one of the roads you pick is at least 5 miles long? | {
"A": "5 / 6",
"B": "1 / 4",
"C": "2 / 3",
"D": "3 / 4",
"E": "11 / 12"
} | subtract(const_1, multiply(subtract(const_1, divide(const_2, const_3.0)), subtract(const_1, divide(1, 2)))) | divide(const_2,const_3.0)|divide(n1,n2)|subtract(const_1,#0)|subtract(const_1,#1)|multiply(#2,#3)|subtract(const_1,#4)| | "so please : find the probability of the event thatnoneof the roads you pick will be at least 5 miles long and subtract from 1 to get the probability thatat least oneof the roads you pick will be at least 5 miles long : p = 1 - 1 / 3 * 1 / 2 = 5 / 6 . answer : a ." | physics |
math_qa__kx9dYAdBOaZmmyrx | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 18000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is Select the correct option
A) 20 B) 21 C) 42 D) 23 E) 24 | <gadget id="calculator">18_000 - 8_000</gadget>
<output>10_000</output>
<gadget id="calculator">7 * 10_000</gadget>
<output>70_000</output>
<gadget id="calculator">8_000 - 6_000</gadget>
<output>2_000</output>
<gadget id="calculator">70_000 / 2_000</gadget>
<output>35</output>
<gadget id="calculator">7 + 35</gadget>
<output>42</output>
<result>C</result> | C | 42 | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 18000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is | {
"A": "20",
"B": "21",
"C": "42",
"D": "23",
"E": "24"
} | add(7, divide(multiply(7, subtract(18000, 8000)), subtract(8000, 6000))) | subtract(n2,n0)|subtract(n0,n3)|multiply(n1,#0)|divide(#2,#1)|add(n1,#3)| | "solution let the toatl number of workers be x . then 8000 x = ( 18000 x 7 ) + 6000 ( x - 7 ) x = 42 answer c" | general |
math_qa__MN4ohHlQsdWIwIQf | A sum of Rs. 427 is to be divided among A, B and C in such a way that 3 times A’s share, 4 times B’s share and 7 times C’s share are all equal. The share of C is ? Choose the correct choice from the following answers
A) 23 B) 87 C) 84 D) 26 E) 19 | <gadget id="calculator">7 / 7</gadget>
<output>1</output>
<gadget id="calculator">7 / 3</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">7 / 4</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">(7/3) + (7/4)</gadget>
<output>49/12 = around 4.083333</output>
<gadget id="calculator">1 + (49/12)</gadget>
<output>61/12 = around 5.083333</output>
<gadget id="calculator">427 / (61/12)</gadget>
<output>84</output>
<result>C</result> | C | 84 | A sum of Rs. 427 is to be divided among A, B and C in such a way that 3 times A’s share, 4 times B’s share and 7 times C’s share are all equal. The share of C is ? | {
"A": "23",
"B": "87",
"C": "84",
"D": "26",
"E": "19"
} | divide(427, add(divide(7, 7), add(divide(7, 3), divide(7, 4)))) | divide(n3,n1)|divide(n3,n2)|divide(n3,n3)|add(#0,#1)|add(#3,#2)|divide(n0,#4) | given total sum = rs . 427 and given that 3 times a ’ s share , 4 times b ’ s share and 7 times c ’ s share are all equal . = > 3 a = 4 b = 7 c but given = > a + b + c = 427 now express a and b in terms of c i . e = > ( 7 c / 3 ) + ( 7 c / 4 ) + c = 427 = > c = 84 answer : c | general |
math_qa__eb2eJ0oyDOBN2NVr | If x and t are integers and 2x–t= 11, then 4x+ t CANNOT be Choices: A) – 5 B) 1 C) 13 D) 17 E) 551 | <gadget id="calculator">4 + 11</gadget>
<output>15</output>
<gadget id="calculator">15 + 2</gadget>
<output>17</output>
<result>D</result> | D | 17 | If x and t are integers and 2x–t= 11, then 4x+ t CANNOT be | {
"A": "– 5",
"B": "1",
"C": "13",
"D": "17",
"E": "551"
} | add(add(4, 11), 2) | add(n1,n2)|add(n0,#0) | 2 x - t = 11 . . . . t = 2 x - 11 4 x + t = 4 x + 2 x - 11 = 6 x - 11 6 x - 11 = - 5 . . . x = 1 6 x - 11 = 1 . . . x = 2 6 x - 11 = 13 . . . x = 4 6 x - 11 = 17 . . x is not integer 6 x - 11 = 551 . . x is not integer i think the choice e is 55 not 551 . otherwise both de can not be solution = d | general |
math_qa__NqqZxpFGLTv6ZjhE | Excluding stoppages, the speed of a bus is 40 kmph and including stoppages, it is 30 kmph. For how many minutes does the bus stop per hour? Choose the correct choice from the following:
A) 10 min B) 12 min C) 18 min D) 15 min E) 20 min | <gadget id="calculator">40 - 30</gadget>
<output>10</output>
<gadget id="calculator">10 / 40</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">60 * (1/4)</gadget>
<output>15</output>
<result>D</result> | D | 15 | Excluding stoppages, the speed of a bus is 40 kmph and including stoppages, it is 30 kmph. For how many minutes does the bus stop per hour? | {
"A": "10 min",
"B": "12 min",
"C": "18 min",
"D": "15 min",
"E": "20 min"
} | multiply(const_60, divide(subtract(40, 30), 40)) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_60)| | "due to stoppages , it covers 10 km less . time taken to cover 10 km = ( 10 / 40 x 60 ) min = 15 min answer : d" | physics |
math_qa__QF1gJyXA0DuDUKkP | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 54° of the circle, what percentage of MegaTek employees are in manufacturing? Answers
A) 15 %
B) 25 %
C) 30 %
D) 35 %
E) 72 % | <gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">54 / 360</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 100</gadget>
<output>15</output>
<result>A</result> | A | 15 | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 54° of the circle, what percentage of MegaTek employees are in manufacturing? | {
"A": "15 %",
"B": "25 %",
"C": "30 %",
"D": "35 %",
"E": "72 %"
} | multiply(divide(54, divide(const_3600, const_10)), const_100) | divide(const_3600,const_10)|divide(n0,#0)|multiply(#1,const_100)| | answer : a 54 ° divided by 360 ° equals 0.15 , therefore the sector is equal to 15 % of the total | physics |
math_qa__fmLDwQy7LDZczxnD | Nicky and Cristina are running a 100 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
Choices
A) 30 B) 35 C) 40 D) 25 E) 60 | <gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">36 / 3</gadget>
<output>12</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">12 + 18</gadget>
<output>30</output>
<result>A</result> | A | 30 | Nicky and Cristina are running a 100 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? | {
"A": "30",
"B": "35",
"C": "40",
"D": "25",
"E": "60"
} | add(divide(multiply(3, 12), 3), divide(multiply(3, 12), subtract(5, 3))) | multiply(n1,n3)|subtract(n2,n3)|divide(#0,n3)|divide(#0,#1)|add(#2,#3)| | "the distance traveled by both of them is the same at the time of overtaking . 3 ( t + 12 ) = 5 t t = 18 . cristina will catch up nicky in 18 seconds . so in 18 seconds cristina would cover = 18 * 5 = 90 meter . now time taken my nicky to cover 90 meter = 90 / 3 = 30 seconds . a" | physics |
math_qa__1NwHMTGJwhLiUk4y | Find the value of 582964 x 99999 = m? Pick:
A) 58210607666 B) 58310607896 C) 58295817036 D) 58591650836 E) 58310692816 | <gadget id="calculator">99_999 - 4</gadget>
<output>99_995</output>
<gadget id="calculator">99_995 * 582_964</gadget>
<output>58_293_485_180</output>
<result>C</result> | C | 58,295,817,036 | Find the value of 582964 x 99999 = m? | {
"A": "58210607666",
"B": "58310607896",
"C": "58295817036",
"D": "58591650836",
"E": "58310692816"
} | multiply(subtract(99999, const_4), 582964) | subtract(n1,const_4)|multiply(#0,n0)| | "582964 x 99999 = 582964 x ( 10000 - 1 ) = 582964 x 100000 - 582964 x 1 = 58296400000 - 582964 = 58295817036 c" | general |
math_qa__fXTOfTMHRhnCZUSI | A big container is 30% full with water. If 18 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container? Options.
A) 36 liters B) 40 liters C) 45 liters D) 54 liters E) 60 liters | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/4) - (3/10)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">18 / (9/20)</gadget>
<output>40</output>
<result>B</result> | B | 40 | A big container is 30% full with water. If 18 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container? | {
"A": "36 liters",
"B": "40 liters",
"C": "45 liters",
"D": "54 liters",
"E": "60 liters"
} | divide(18, subtract(divide(3, 4), divide(30, const_100))) | divide(n2,n3)|divide(n0,const_100)|subtract(#0,#1)|divide(n1,#2)| | "a big container is 30 % full with water and after 18 liters of water is added , the container becomes 75 % full . hence these 18 liters account for 45 % of the container , which means that the capacity of it is 18 / 0.45 = 40 liters . or : if the capacity of the container is x liters then : 0.3 x + 18 = 0.75 x - - > x = 40 liters . answer : b ." | general |
math_qa__vevqHU3ZCIlQqTie | A 300 m long train crosses a platform in 51 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
Choose one:
A) 287 B) 350 C) 828 D) 277 E) 550 | <gadget id="calculator">300 / 18</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 51</gadget>
<output>850</output>
<gadget id="calculator">850 - 300</gadget>
<output>550</output>
<result>E</result> | E | 550 | A 300 m long train crosses a platform in 51 sec while it crosses a signal pole in 18 sec. What is the length of the platform? | {
"A": "287",
"B": "350",
"C": "828",
"D": "277",
"E": "550"
} | subtract(multiply(speed(300, 18), 51), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 18 = 50 / 3 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 5 a = 50 / 3 3 x + 900 = 2550 = > x = 550 m . answer : e" | physics |
math_qa__VNrN5HZjQ0BPWbdY | Find avrg speed if a man travels at speed of 32km/hr up and 48km/hr dawn at an altitude of 230m. Choose the correct choice from the following answers.
A) 25.8 B) 26.8 C) 38.4 D) 34.4 E) 29.8 | <gadget id="calculator">2 * 32</gadget>
<output>64</output>
<gadget id="calculator">64 * 48</gadget>
<output>3_072</output>
<gadget id="calculator">32 + 48</gadget>
<output>80</output>
<gadget id="calculator">3_072 / 80</gadget>
<output>192/5 = around 38.4</output>
<result>C</result> | C | 38.4 | Find avrg speed if a man travels at speed of 32km/hr up and 48km/hr dawn at an altitude of 230m. | {
"A": "25.8",
"B": "26.8",
"C": "38.4",
"D": "34.4",
"E": "29.8"
} | divide(multiply(multiply(const_2, 32), 48), add(32, 48)) | add(n0,n1)|multiply(n0,const_2)|multiply(n1,#1)|divide(#2,#0)| | "avg speed = 2 * x * y / ( x + y ) = 2 * 32 * 48 ( 32 + 48 ) = 38.4 answer : c" | physics |
math_qa__PyLhkX9biSp3Yk2d | The average age of 15 students of a class is 15 years. Out of these, the average age of 7 students is 14 years and that of the other 7 students is 16 years, The age of the 15th student is Options:
A) 11 B) 12 C) 13 D) 14 E) 15 | <gadget id="calculator">15 * 15</gadget>
<output>225</output>
<gadget id="calculator">7 * 14</gadget>
<output>98</output>
<gadget id="calculator">7 * 16</gadget>
<output>112</output>
<gadget id="calculator">98 + 112</gadget>
<output>210</output>
<gadget id="calculator">225 - 210</gadget>
<output>15</output>
<result>E</result> | E | 15 | The average age of 15 students of a class is 15 years. Out of these, the average age of 7 students is 14 years and that of the other 7 students is 16 years, The age of the 15th student is | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | subtract(multiply(15, 15), add(multiply(7, 14), multiply(7, 16))) | multiply(n0,n0)|multiply(n2,n3)|multiply(n4,n5)|add(#1,#2)|subtract(#0,#3)| | "explanation : age of the 15 th student = [ 15 * 15 - ( 14 * 7 + 16 * 7 ) ] = 15 years . answer : e" | general |
math_qa__MPrDMODzwb9FLSFL | Joe invested a certain sum of money in a simple interest bond whose value grew to $400 at the end of 3 years and to $500 at the end of another 5 years. What was the rate of interest in which he invested his sum? Choose the correct choice from the following choices:
A) 4.76 %
B) 5.88 %
C) 6.33 %
D) 7.75 %
E) 8.33 % | <gadget id="calculator">500 - 400</gadget>
<output>100</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">400 - 60</gadget>
<output>340</output>
<gadget id="calculator">20 / 340</gadget>
<output>1/17 = around 0.058824</output>
<gadget id="calculator">(1/17) * 100</gadget>
<output>100/17 = around 5.882353</output>
<result>B</result> | B | 5.88 | Joe invested a certain sum of money in a simple interest bond whose value grew to $400 at the end of 3 years and to $500 at the end of another 5 years. What was the rate of interest in which he invested his sum? | {
"A": "4.76 %",
"B": "5.88 %",
"C": "6.33 %",
"D": "7.75 %",
"E": "8.33 %"
} | multiply(divide(divide(subtract(500, 400), 5), subtract(400, multiply(divide(subtract(500, 400), 5), 3))), const_100) | subtract(n2,n0)|divide(#0,n3)|multiply(n1,#1)|subtract(n0,#2)|divide(#1,#3)|multiply(#4,const_100) | in 5 years , the value grew $ 100 , so the simple interest was $ 20 per year . in 3 years , the total interest was 3 * $ 20 = $ 60 the principal is $ 400 - $ 60 = 340 . the interest rate is $ 20 / $ 340 = 1 / 17 which is about 5.88 % the answer is b . | gain |
math_qa__V6Ygpf25Z0H8dV1p | In February Wilson’s earnings were 40 percent of his family’s total income. In March Wilson earned 25 percent less than in February. If the rest of his family’s income was the same in both months, then, in March, Wilson’s earnings were approximately what percent Z of his family’s total income? Choose the correct choice from the following:
A) 15 % B) 17 % C) 24 % D) 30 % E) 33 % | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * (2/5)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(2/5) - (1/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(3/10) / (9/10)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>E</result> | E | 33 | In February Wilson’s earnings were 40 percent of his family’s total income. In March Wilson earned 25 percent less than in February. If the rest of his family’s income was the same in both months, then, in March, Wilson’s earnings were approximately what percent Z of his family’s total income? | {
"A": "15 %",
"B": "17 %",
"C": "24 %",
"D": "30 %",
"E": "33 %"
} | multiply(divide(subtract(divide(40, const_100), multiply(divide(25, const_100), divide(40, const_100))), subtract(const_1, multiply(divide(25, const_100), divide(40, const_100)))), const_100) | divide(n0,const_100)|divide(n1,const_100)|multiply(#1,#0)|subtract(#0,#2)|subtract(const_1,#2)|divide(#3,#4)|multiply(#5,const_100)| | "lets suppose the total family income in feb = 100 x wilson ' s earning in feb = 40 % of 100 x = 40 x earnings of remaining family in feb = 100 x - 40 x = 60 x wilson ' s earning in march = 75 % of wilson ' s feb earnings = 75 % of 40 x = 30 x earnings of remaining family in march = earnings of remaining family in feb = 60 x thus wilson ' s earning as % of total family income in march z = 30 x / ( 30 + 60 ) x = 30 x / 90 x = 33.33 % thus answer is e" | general |
math_qa__X9Oo1my6OLAsI6qL | A reduction in the price of petrol by 10% enables a motorist to buy 5 gallons more for $250. Find the original price of petrol? Select the correct option.
A) $ 11 B) $ 5 C) $ 45 D) $ 400 E) $ 5.5 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 250</gadget>
<output>225</output>
<gadget id="calculator">250 - 225</gadget>
<output>25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">5 - (1/2)</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">25 / (9/2)</gadget>
<output>50/9 = around 5.555556</output>
<result>E</result> | E | 5.5 | A reduction in the price of petrol by 10% enables a motorist to buy 5 gallons more for $250. Find the original price of petrol? | {
"A": "$ 11",
"B": "$ 5",
"C": "$ 45",
"D": "$ 400",
"E": "$ 5.5"
} | divide(subtract(250, multiply(subtract(const_1, divide(10, const_100)), 250)), subtract(5, divide(const_1, const_2))) | divide(n0,const_100)|divide(const_1,const_2)|subtract(const_1,#0)|subtract(n1,#1)|multiply(n2,#2)|subtract(n2,#4)|divide(#5,#3)| | "price decreased by 10 % , so 9 / 10 times , which means that original gallons bought increased 10 / 9 times . since this increase equals to 5 gallons then 45 gallons were bought originally ( 45 * 10 / 9 = 50 - - > increase 5 gallons ) . hence original price was 250 / 45 = $ 5.5 answer : e ." | gain |
math_qa__7Kp5hSqyI9cwewAC | (258% of 1265) ÷6 = ? Choices: A) 125 B) 175 C) 225 D) 375 E) 544 | <gadget id="calculator">258 / 100</gadget>
<output>129/50 = around 2.58</output>
<gadget id="calculator">(129/50) * 1_265</gadget>
<output>32_637/10 = around 3_263.7</output>
<gadget id="calculator">(32_637/10) / 6</gadget>
<output>10_879/20 = around 543.95</output>
<result>E</result> | E | 544 | (258% of 1265) ÷6 = ? | {
"A": "125",
"B": "175",
"C": "225",
"D": "375",
"E": "544"
} | divide(multiply(divide(258, const_100), 1265), 6) | divide(n0,const_100)|multiply(n1,#0)|divide(#1,n2)| | "explanation : ? = ( 258 x 1265 / 100 ) ÷ 6 = 326370 / 600 = 544 answer : option e" | general |
math_qa__3I8wDwBgJfTv9GAV | If (1/5)^n * (1/4)^18 = 1/(2*(10)^35), then n =
Answers:
A) 40 B) 45 C) 35 D) 30 E) 25 | <gadget id="calculator">35 - 10</gadget>
<output>25</output>
<gadget id="calculator">25 + 10</gadget>
<output>35</output>
<result>C</result> | C | 35 | If (1/5)^n * (1/4)^18 = 1/(2*(10)^35), then n = | {
"A": "40",
"B": "45",
"C": "35",
"D": "30",
"E": "25"
} | add(subtract(35, 10), 10) | subtract(n8,n7)|add(n7,#0) | ( 1 / 5 ) ^ m ( 1 / 4 ) ^ 18 = 1 / { 2 ( 10 ) ^ 35 } 2 ( 10 ) ^ 35 / 4 ^ 18 = 5 ^ m [ 2 ( 2 ^ 35 ) ( 5 ^ 35 ) ] / [ 2 ^ 36 ] = 5 ^ m 5 ^ 35 = 5 ^ m n = 35 c | general |
math_qa__lvED9za62D4VL88x | let exp ( m , n ) = m to the power n . if exp ( 10 , m ) = n exp ( 22 ) where m and n are integers then n = ___ ?
Answers
A) 24 B) 25 C) 26 D) 27 E) 28 | <gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">100 / 4</gadget>
<output>25</output>
<result>B</result> | B | 25 | let exp ( m , n ) = m to the power n . if exp ( 10 , m ) = n exp ( 22 ) where m and n are integers then n = ___ ? | {
"A": "24",
"B": "25",
"C": "26",
"D": "27",
"E": "28"
} | divide(power(10, const_2), power(const_2, const_2)) | power(n0,const_2)|power(const_2,const_2)|divide(#0,#1) | 10 ^ m = n * ( 2 ^ 2 ) ( 2 * 5 ) ^ m = n * ( 2 ^ 2 ) ( 2 ^ m ) * ( 5 ^ m ) = n * ( 2 ^ 2 ) now equate both side we get m = 2 and ( 5 ^ m ) = n ( 5 ^ 2 ) = n = > n = 25 answer : b | general |
math_qa__fRIpQ6K3YCzywuU8 | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 90 units raises the average to 52 units per day, what is the value of n ? Answers:
A) 30
B) 19
C) 10
D) 9
E) 7 | <gadget id="calculator">90 - 50</gadget>
<output>40</output>
<gadget id="calculator">52 - 50</gadget>
<output>2</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">20 - 1</gadget>
<output>19</output>
<result>B</result> | B | 19 | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 90 units raises the average to 52 units per day, what is the value of n ? | {
"A": "30",
"B": "19",
"C": "10",
"D": "9",
"E": "7"
} | subtract(divide(subtract(90, 50), subtract(52, 50)), const_1) | subtract(n1,n0)|subtract(n2,n0)|divide(#0,#1)|subtract(#2,const_1)| | "( average production for n days ) * n = ( total production for n days ) - - > 50 n = ( total production for n days ) ; ( total production for n days ) + 90 = ( average production for n + 1 days ) * ( n + 1 ) - - > 50 n + 90 = 52 * ( n + 1 ) - - > n = 19 . or as 40 extra units increased the average for n + 1 days by 2 units per day then 40 / ( n + 1 ) = 2 - - > n = 19 . answer : b ." | general |
math_qa__3FxBJa08OqTyyh9i | An escalator moves towards the top level at the rate of 8 ft.sec and its length is 160 feet. If a person walks on the moving escalator at the rate of 2 feet per second towards the top level, how much time does he take to cover the entire length. Choose the correct choice from the following answers
A) 14 sec B) 10 sec C) 16 sec D) 8 sec E) 9 sec | <gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">160 / 10</gadget>
<output>16</output>
<result>C</result> | C | 16 | An escalator moves towards the top level at the rate of 8 ft.sec and its length is 160 feet. If a person walks on the moving escalator at the rate of 2 feet per second towards the top level, how much time does he take to cover the entire length. | {
"A": "14 sec",
"B": "10 sec",
"C": "16 sec",
"D": "8 sec",
"E": "9 sec"
} | divide(160, add(8, 2)) | add(n0,n2)|divide(n1,#0)| | "time taken to cover the entire length = tot . dist / resultant speed = 160 / ( 8 + 2 ) = 16 sec answer : c" | gain |
math_qa__ZomNNHuRFBQH80gw | A photograph is copied onto a sheet of paper 8.5 inches by 10 inches. A 1.5 inch margin is left all around. What area in square inches does the picture cover? Select the correct option
A) 76
B) 65
C) 59.5
D) 49
E) 38.5 | <gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">8.5 - 3</gadget>
<output>5.5</output>
<gadget id="calculator">7 * 5.5</gadget>
<output>38.5</output>
<result>E</result> | E | 38.5 | A photograph is copied onto a sheet of paper 8.5 inches by 10 inches. A 1.5 inch margin is left all around. What area in square inches does the picture cover? | {
"A": "76",
"B": "65",
"C": "59.5",
"D": "49",
"E": "38.5"
} | rectangle_area(subtract(10, const_3), subtract(8.5, const_3)) | subtract(n1,const_3)|subtract(n0,const_3)|rectangle_area(#0,#1) | area covered by photograph = ( 8.5 - 3 ) * ( 10 - 3 ) = 5.5 * 7 = 38.5 answer e | geometry |
math_qa__2SDRWl3dfMgspbJM | When positive integer e is divided by 13, the remainder is 2. When n is divided by 8, the remainder is 5. How many such values are less than 180? Choose the correct choice from the following answers:
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">13 - 5</gadget>
<output>8</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">8 - 7</gadget>
<output>1</output>
<result>B</result> | B | 1 | When positive integer e is divided by 13, the remainder is 2. When n is divided by 8, the remainder is 5. How many such values are less than 180? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | subtract(subtract(13, 5), add(5, 2)) | add(n1,n3)|subtract(n0,n3)|subtract(#1,#0) | the equation that can be formed e is 13 x + 2 = 8 y + 5 . . 13 x - 3 = 8 y . . . as we can see x can take only odd values as the rhs will always be even . . also x can take values till 13 as 13 * 14 > 180 . . now we have to substitue x as 1 , 35 , 79 , 1113 . . . once we find 7 fitting in , any other value need not be checked as every 4 th value will give us answer so next value will be 15 . . ans 1 . . b | general |
math_qa__tMfcDtbaDex9vpMf | On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.48 per glass on the first day, what was the price per glass on the second day?
Choose the correct answer
A) $ 015 B) $ 0.20 C) $ 0.30 D) $ 0.32 E) $ 0.45 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 0.48</gadget>
<output>0.96</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">0.96 / 3</gadget>
<output>0.32</output>
<result>D</result> | D | 0.32 | On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.48 per glass on the first day, what was the price per glass on the second day? | {
"A": "$ 015",
"B": "$ 0.20",
"C": "$ 0.30",
"D": "$ 0.32",
"E": "$ 0.45"
} | divide(multiply(add(const_1, const_1), 0.48), add(const_1, const_2)) | add(const_1,const_1)|add(const_1,const_2)|multiply(n0,#0)|divide(#2,#1)| | "on the first day 1 unit of orange juice and 1 unit of water was used to make 2 units of orangeade ; on the second day 1 unit of orange juice and 2 units of water was used to make 3 units of orangeade ; so , the ratio of the amount of orangeade made on the first day to the amount of orangeade made on the second day is 2 to 3 . naturally the ratio of the # of glasses of orangeade made on the first day to the # of glasses of orangeade made on the second day is 2 to 3 . we are told thatthe revenue from selling the orangeade was the same for both daysso the revenue from 2 glasses on the first day equals to the revenue from 3 glasses on the second day . say the price of the glass of the orangeade on the second day was $ x then 2 * 0.48 = 3 * x - - > x = $ 0.32 . answer : d ." | general |
math_qa__0XBymoIi5y3Up7fl | amit , sumit and pramit go to a seaside town to spend a vacation there and on the first day everybody decides to visit different tourist locations . after breakfast , each of them boards a different tourist vehicle from the nearest bus - depot . after 3 hours , sumit who had gone to a famous beach , calls on the mobile of pramit and claims that he has observed a shark in the waters . pramit learns from the local guide that at that time of the year , only 8 sea - creatures ( including a shark ) are observable and the probability of observing any creature is equal . however , amit and pramit later recall during their discussion that sumit has a reputation for not telling the truth 5 out of 6 times . what is the probability that sumit actually observed a shark in the waters ? Choose the correct choice from the following.
A) 1 / 36 B) 1 / 30 C) 5 / 36 D) 1 / 24 E) 1 / 28 | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/8) * (1/6)</gadget>
<output>1/48 = around 0.020833</output>
<gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">(5/6) * (7/8)</gadget>
<output>35/48 = around 0.729167</output>
<gadget id="calculator">(1/48) + (35/48)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(1/48) / (3/4)</gadget>
<output>1/36 = around 0.027778</output>
<result>A</result> | A | 0.027778 | amit , sumit and pramit go to a seaside town to spend a vacation there and on the first day everybody decides to visit different tourist locations . after breakfast , each of them boards a different tourist vehicle from the nearest bus - depot . after 3 hours , sumit who had gone to a famous beach , calls on the mobile of pramit and claims that he has observed a shark in the waters . pramit learns from the local guide that at that time of the year , only 8 sea - creatures ( including a shark ) are observable and the probability of observing any creature is equal . however , amit and pramit later recall during their discussion that sumit has a reputation for not telling the truth 5 out of 6 times . what is the probability that sumit actually observed a shark in the waters ? | {
"A": "1 / 36",
"B": "1 / 30",
"C": "5 / 36",
"D": "1 / 24",
"E": "1 / 28"
} | divide(multiply(divide(const_1, 8), divide(const_1, 6)), add(multiply(divide(const_1, 8), divide(const_1, 6)), multiply(divide(5, 6), divide(add(6, const_1), 8)))) | add(n3,const_1)|divide(const_1,n1)|divide(const_1,n3)|divide(n2,n3)|divide(#0,n1)|multiply(#1,#2)|multiply(#3,#4)|add(#5,#6)|divide(#5,#7) | explanation : the probability that sumit actually sees a shark , given that he claimed to have seen one . = > p ( he actually sees the shark and reports truth ) / p ( he claims of seeing a shark ) . = > p ( sees the shark ) p ( reports truth ) / ( p ( he sees a shark ) p ( reports truth ) + p ( does n ' t see ) p ( reports false ) . = > ( 1 / 8 × 1 / 6 ) / ( 1 / 8 × 1.6 + 7 / 8 × 5 / 6 ) = > 1 / 36 . answer : a | general |
math_qa__BbfcqTdRkHIXOoCO | A certain sum is invested at simple interest at 15% p.a. for two years instead of investing at 10% p.a. for the same time period. Therefore the interest received is more by Rs. 840. Find the sum? Choose the correct choice from the following options:
A) s . 8400 B) s . 9000 C) s . 14000 D) s . 17000 E) s . 27000 | <gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">840 / (1/10)</gadget>
<output>8_400</output>
<result>A</result> | A | 8,400 | A certain sum is invested at simple interest at 15% p.a. for two years instead of investing at 10% p.a. for the same time period. Therefore the interest received is more by Rs. 840. Find the sum? | {
"A": "s . 8400",
"B": "s . 9000",
"C": "s . 14000",
"D": "s . 17000",
"E": "s . 27000"
} | divide(840, divide(multiply(subtract(15, 10), const_2), const_100)) | subtract(n0,n1)|multiply(#0,const_2)|divide(#1,const_100)|divide(n2,#2)| | "let the sum be rs . x . ( x * 15 * 2 ) / 100 - ( x * 10 * 2 ) / 100 = 840 = > 30 x / 100 - 20 x / 100 = 840 = > 10 x / 100 = 840 = > x = 8400 . answer : a" | gain |
math_qa__2MyrnBawSC7nPCXs | A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 950gm. for a kg.His gain is …%. Choose one:
A) 5.3 % B) 8.2 % C) 4.3 % D) 8.3 % E) 8.0 % | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">950 / 1_000</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">1 / (19/20)</gadget>
<output>20/19 = around 1.052632</output>
<gadget id="calculator">(20/19) - 1</gadget>
<output>1/19 = around 0.052632</output>
<gadget id="calculator">(1/19) * 100</gadget>
<output>100/19 = around 5.263158</output>
<result>A</result> | A | 5.3 | A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 950gm. for a kg.His gain is …%. | {
"A": "5.3 %",
"B": "8.2 %",
"C": "4.3 %",
"D": "8.3 %",
"E": "8.0 %"
} | multiply(subtract(inverse(divide(950, multiply(multiply(add(const_4, const_1), const_2), const_100))), const_1), const_100) | add(const_1,const_4)|multiply(#0,const_2)|multiply(#1,const_100)|divide(n0,#2)|inverse(#3)|subtract(#4,const_1)|multiply(#5,const_100) | he sells 950 grams of pulses and gains 50 grams . if he sells 100 grams of pulses then he will gain ( 50 / 950 ) * 100 = 5.26 4 . a software engineer has the capability of thinking 100 lines of code in five minutes and can type 100 lines of code in 10 minutes . he takes a break for five minutes after every ten minutes . how many lines of codes will he complete typing after an hour ? answer : a | gain |
math_qa__oZBFa8MqYgBBT8qg | There are 7 players in a bowling team with an average weight of 121 Kg. If two new players join the team, one weighs 110 Kg and the second weighs 60 Kg, what will be the new average weight? Choose the correct option:
A) 115 kg .
B) 118 kg .
C) 113 kg .
D) 110 kg .
E) 112 kg . | <gadget id="calculator">7 * 121</gadget>
<output>847</output>
<gadget id="calculator">110 + 60</gadget>
<output>170</output>
<gadget id="calculator">847 + 170</gadget>
<output>1_017</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<gadget id="calculator">1_017 / 9</gadget>
<output>113</output>
<result>C</result> | C | 113 | There are 7 players in a bowling team with an average weight of 121 Kg. If two new players join the team, one weighs 110 Kg and the second weighs 60 Kg, what will be the new average weight? | {
"A": "115 kg .",
"B": "118 kg .",
"C": "113 kg .",
"D": "110 kg .",
"E": "112 kg ."
} | divide(add(multiply(7, 121), add(110, 60)), add(7, const_2)) | add(n2,n3)|add(n0,const_2)|multiply(n0,n1)|add(#0,#2)|divide(#3,#1) | the new average will be = ( 121 * 7 + 110 + 60 ) / 9 = 113 kgs c is the answer | general |
math_qa__Wgu4rqNrcBh4BEjq | A student scored an average of 70 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics?
Choose the correct choice from the following choices:
A) 130 B) 120 C) 110 D) 180 E) 150 | <gadget id="calculator">90 * 2</gadget>
<output>180</output>
<gadget id="calculator">70 * 2</gadget>
<output>140</output>
<gadget id="calculator">180 + 140</gadget>
<output>320</output>
<gadget id="calculator">70 * 3</gadget>
<output>210</output>
<gadget id="calculator">320 - 210</gadget>
<output>110</output>
<result>C</result> | C | 110 | A student scored an average of 70 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics? | {
"A": "130",
"B": "120",
"C": "110",
"D": "180",
"E": "150"
} | subtract(add(multiply(90, const_2), multiply(70, const_2)), multiply(70, 3)) | multiply(n2,const_2)|multiply(n3,const_2)|multiply(n0,n1)|add(#0,#1)|subtract(#3,#2)| | "given m + p + c = 70 * 3 = 210 - - - ( 1 ) m + p = 90 * 2 = 180 - - - ( 2 ) p + c = 70 * 2 = 140 - - - ( 3 ) where m , p and c are marks obtained by the student in mathematics , physics and chemistry . p = ( 2 ) + ( 3 ) - ( 1 ) = 180 + 140 - 210 = 110 answer : c" | general |
math_qa__lynS914rZTyUWRUO | a box contains 3 pairs of blue gloves and two pairs of green gloves . each pair consists of a left - hand glove and a right - hand glove . each of the gloves is separate from its mate and thoroughly mixed together with the others in the box . if 3 gloves are randomly selected from the box , what is the probability that a matched set ( i . e . , a left - and right - hand glove of the same color ) will be among the 3 gloves selected ? Choose the correct answer:
A) 3 / 10 B) 23 / 60 C) 7 / 12 D) 41 / 60 E) 5 / 6 | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">6 / 60</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 60</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/10) + (1/5)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<result>D</result> | D | 0.683333 | a box contains 3 pairs of blue gloves and two pairs of green gloves . each pair consists of a left - hand glove and a right - hand glove . each of the gloves is separate from its mate and thoroughly mixed together with the others in the box . if 3 gloves are randomly selected from the box , what is the probability that a matched set ( i . e . , a left - and right - hand glove of the same color ) will be among the 3 gloves selected ? | {
"A": "3 / 10",
"B": "23 / 60",
"C": "7 / 12",
"D": "41 / 60",
"E": "5 / 6"
} | subtract(const_1, add(divide(add(3, 3), multiply(add(3, 3), const_10)), divide(add(const_10, const_2), multiply(add(3, 3), const_10)))) | add(n0,n0)|add(const_10,const_2)|multiply(#0,const_10)|divide(#0,#2)|divide(#1,#2)|add(#3,#4)|subtract(const_1,#5) | you can use the ' calculating the reverse ' method used by bunuel above or if you would like to calculate the probability of getting a matched set in the usual way , you can think of it in this way : bleft ( 3 ) , bright ( 3 ) , gleft ( 2 ) , gright ( 2 ) bleft , bright , g get a bleft and bright in ( 3 / 10 ) * ( 3 / 9 ) ways . then get any green in 4 / 8 ways . probability of getting b pair and a g = ( 3 / 10 ) * ( 3 / 9 ) * ( 4 / 8 ) * 3 ! ( you multiply by 3 ! here because you could pick in some other order e . g . bright , bleft , g or bleft , g , bright etc ) bleft , bright , b get a bleft and bright in ( 3 / 10 ) * ( 3 / 9 ) ways . then get any blue in 4 / 8 ways . probability of getting b pair and another b = ( 3 / 10 ) * ( 3 / 9 ) * ( 4 / 8 ) * 3 ! / 2 ! ( you multiply by 3 ! here to account for the order e . g . bright , bleft , bleft or bleft , bright , bright etc but two gloves will be identical so you divide by 2 ! ) gleft , gright , b get a gleft and gright in ( 2 / 10 ) * ( 2 / 9 ) ways . then get any blue in 6 / 8 ways . probability of getting g pair and a b = ( 2 / 10 ) * ( 2 / 9 ) * ( 6 / 8 ) * 3 ! gleft , gright , g get a gleft and gright in ( 2 / 10 ) * ( 2 / 9 ) ways . then get any other g in 2 / 8 ways . probability of getting g pair and a g = ( 2 / 10 ) * ( 2 / 9 ) * ( 2 / 8 ) * 3 ! / 2 ! adding them all up , you get 41 / 60 . answer : d | general |
math_qa__AgejwRkI1WuZIJlI | The output of a factory is increased by 10% to keep up with rising demand. To handle the holiday rush, this new output is increased by 30%. By approximately what percent would the output of the factory now have to be decreased in order to restore the original output? Choose the correct choice from the following choices.
A) 20 %
B) 24 %
C) 30 %
D) 32 %
E) 79 % | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">110 / 100</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">130 / 100</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">(11/10) * (13/10)</gadget>
<output>143/100 = around 1.43</output>
<gadget id="calculator">(143/100) - 1</gadget>
<output>43/100 = around 0.43</output>
<gadget id="calculator">(43/100) / (143/100)</gadget>
<output>43/143 = around 0.300699</output>
<gadget id="calculator">(43/143) * 100</gadget>
<output>4_300/143 = around 30.06993</output>
<result>C</result> | C | 30 | The output of a factory is increased by 10% to keep up with rising demand. To handle the holiday rush, this new output is increased by 30%. By approximately what percent would the output of the factory now have to be decreased in order to restore the original output? | {
"A": "20 %",
"B": "24 %",
"C": "30 %",
"D": "32 %",
"E": "79 %"
} | multiply(divide(subtract(multiply(divide(add(const_100, const_10), const_100), divide(add(const_100, 30), const_100)), const_1), multiply(divide(add(const_100, const_10), const_100), divide(add(const_100, 30), const_100))), const_100) | add(const_10,const_100)|add(n1,const_100)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|subtract(#4,const_1)|divide(#5,#4)|multiply(#6,const_100) | take it as original output = 100 . to meet demand increase by 10 % , then output = 110 . to meet holiday demand , new output increase by 30 % then output equals 143 to restore new holidy demand output to original 100 . final - initial / final * 100 = 43 / 143 * 100 = 30 % approxiamately . option c is correct . | general |
math_qa__nAwIYgLCYfQT18ZV | A 300 meter long train crosses a platform in 54 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? Choose the correct choice from the following choices: A) 99 B) 289 C) 350 D) 882 E) 600 | <gadget id="calculator">300 / 18</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 54</gadget>
<output>900</output>
<gadget id="calculator">900 - 300</gadget>
<output>600</output>
<result>E</result> | E | 600 | A 300 meter long train crosses a platform in 54 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? | {
"A": "99",
"B": "289",
"C": "350",
"D": "882",
"E": "600"
} | subtract(multiply(divide(300, 18), 54), 300) | divide(n0,n2)|multiply(n1,#0)|subtract(#1,n0) | speed = [ 300 / 18 ] m / sec = 50 / 3 m / sec . let the length of the platform be x meters . then , x + 300 / 54 = 50 / 3 3 ( x + 300 ) = 2700 è x = 350 m . answer : e | physics |
math_qa__XmrpB6P5CvpFRX3y | 150 ml of 30% sulphuric acid was added to approximate 400 ml of 12% sulphuric acid solution. Find the approximate concentration E of the acid in the mixture? Choose the correct choice from the following answers
A) 1 / 2 B) 1 / 3 C) 1 / 4 D) 1 / 6 E) 1 / 5 | <gadget id="calculator">150 * 30</gadget>
<output>4_500</output>
<gadget id="calculator">4_500 / 100</gadget>
<output>45</output>
<gadget id="calculator">400 * 12</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 100</gadget>
<output>48</output>
<gadget id="calculator">45 + 48</gadget>
<output>93</output>
<gadget id="calculator">150 + 400</gadget>
<output>550</output>
<gadget id="calculator">93 / 550</gadget>
<output>93/550 = around 0.169091</output>
<result>D</result> | D | 0.166667 | 150 ml of 30% sulphuric acid was added to approximate 400 ml of 12% sulphuric acid solution. Find the approximate concentration E of the acid in the mixture? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 6",
"E": "1 / 5"
} | divide(add(divide(multiply(150, 30), const_100), divide(multiply(400, 12), const_100)), add(150, 400)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|divide(#1,const_100)|divide(#2,const_100)|add(#3,#4)|divide(#5,#0)| | "do not need any computation 30 % - - - - - - - - - - - 21 % - - - - - - - - - 12 % if volume of both sol . were equal the concentration e would be 21 % = 1 / 5 , but 12 % is more than 3 times only possibility is 1 / 6 d" | general |
math_qa__iVQN1LLEuvwVlY43 | What is the smallest integer k for which 64^k > 4^19? Choose the correct choice from the following options.
A) 4 B) 5 C) 6 D) 7 E) 8 | <gadget id="calculator">19 / 3</gadget>
<output>19/3 = around 6.333333</output>
<gadget id="calculator">floor(19/3)</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<result>D</result> | D | 7 | What is the smallest integer k for which 64^k > 4^19? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | add(floor(divide(19, const_3)), const_1) | divide(n2,const_3)|floor(#0)|add(#1,const_1) | 64 ^ k > 4 ^ 19 4 ^ ( 3 k ) > 4 ^ 19 3 k > 19 k = 7 the answer is d . | general |
math_qa__ItJnVe0K4Z5CtY78 | A cistern 6m long and 5 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is: Choose the correct choice from the following answers.
A) 49 m 2 B) 50 m 2 C) 53.5 m 2 D) 55 m 2 E) 57.5 m 2 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 5</gadget>
<output>25/4 = around 6.25</output>
<gadget id="calculator">(5/4) * 6</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(25/4) + (15/2)</gadget>
<output>55/4 = around 13.75</output>
<gadget id="calculator">2 * (55/4)</gadget>
<output>55/2 = around 27.5</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">(55/2) + 30</gadget>
<output>115/2 = around 57.5</output>
<result>E</result> | E | 57.5 | A cistern 6m long and 5 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is: | {
"A": "49 m 2",
"B": "50 m 2",
"C": "53.5 m 2",
"D": "55 m 2",
"E": "57.5 m 2"
} | add(multiply(const_2, add(multiply(add(divide(25, const_100), 1), 5), multiply(add(divide(25, const_100), 1), 6))), multiply(5, 6)) | divide(n3,const_100)|multiply(n0,n1)|add(n2,#0)|multiply(n1,#2)|multiply(n0,#2)|add(#3,#4)|multiply(#5,const_2)|add(#6,#1)| | "area of the wet surface = [ 2 ( lb + bh + lh ) - lb ] = 2 ( bh + lh ) + lb = [ 2 ( 5 x 1.25 + 6 x 1.25 ) + 6 x 5 ] m 2 = 57.5 m 2 . answer : option e" | physics |
math_qa__dMSJbEvZZRNBpDcN | A train 1600 m long can cross a pole in 40 sec and then find the speed of the train? Choose the correct answer
A) 140 B) 142 C) 144 D) 146 E) 148 | <gadget id="calculator">1_600 / 1_000</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">40 / 3_600</gadget>
<output>1/90 = around 0.011111</output>
<gadget id="calculator">(8/5) / (1/90)</gadget>
<output>144</output>
<result>C</result> | C | 144 | A train 1600 m long can cross a pole in 40 sec and then find the speed of the train? | {
"A": "140",
"B": "142",
"C": "144",
"D": "146",
"E": "148"
} | divide(divide(1600, const_1000), divide(40, const_3600)) | divide(n0,const_1000)|divide(n1,const_3600)|divide(#0,#1)| | "length = speed * time speed = l / t s = 1600 / 40 s = 40 m / sec speed = 40 * 18 / 5 ( to convert m / sec in to kmph multiply by 18 / 5 ) speed = 144 kmph answer : c" | physics |
math_qa__9cKaQNFW7btr8QxA | A jar contains only red, yellow, and orange marbles. If there are 3 red, 5 yellow, and 4 orange marbles, and 3 marbles are chosen from the jar at random without replacing any of them, what is the probability that 2 yellow, 1 red, and no orange marbles will be chosen? Answers:
A) 1 / 60 B) 1 / 45 C) 2 / 45 D) 3 / 22 E) 5 / 22 | <gadget id="calculator">binomial(5, 2)</gadget>
<output>10</output>
<gadget id="calculator">binomial(3, 1)</gadget>
<output>3</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">9 + 3</gadget>
<output>12</output>
<gadget id="calculator">binomial(12, 3)</gadget>
<output>220</output>
<gadget id="calculator">30 / 220</gadget>
<output>3/22 = around 0.136364</output>
<result>D</result> | D | 0.136364 | A jar contains only red, yellow, and orange marbles. If there are 3 red, 5 yellow, and 4 orange marbles, and 3 marbles are chosen from the jar at random without replacing any of them, what is the probability that 2 yellow, 1 red, and no orange marbles will be chosen? | {
"A": "1 / 60",
"B": "1 / 45",
"C": "2 / 45",
"D": "3 / 22",
"E": "5 / 22"
} | divide(multiply(choose(5, 2), choose(3, 1)), choose(add(add(5, 4), 3), 3)) | add(n1,n2)|choose(n1,n4)|choose(n0,n5)|add(n0,#0)|multiply(#1,#2)|choose(#3,n0)|divide(#4,#5) | 5 c 2 * 3 c 1 = 10 * 3 = 30 12 c 3 = 220 3 / 22 answer : d | probability |
math_qa__QcNCcuPdZLkFtKp4 | If 10! - 2*(5!)^2 is divisible by 10^n, what is the greatest value of n?
Answers:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">1 * 5</gadget>
<output>5</output>
<result>E</result> | E | 5 | If 10! - 2*(5!)^2 is divisible by 10^n, what is the greatest value of n? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | multiply(const_1, 5) | multiply(n2,const_1) | = 10 ∗ 9 ∗ 8 ∗ 7 ∗ 6 ∗ 5 ! − 2 ∗ 5 ! ∗ 5 ∗ 4 ∗ 3 ∗ 2 ∗ 1 = 5 ! ∗ 10 ∗ 3 ∗ 8 ( 125 ) = 5 ∗ ( 2 ∗ 2 ) ∗ 3 ∗ 2 ∗ ( 5 ∗ 2 ) ∗ 24 ∗ 5 ∗ 5 ∗ 5 = 5 ∗ 2 ∗ 5 ∗ 2 ∗ 5 ∗ 2 ∗ 5 ∗ 2 ∗ 24 ∗ 5 ∗ 3 = 10 ^ 4 ∗ 2 ^ 4 ∗ 5 ∗ 3 = 10 ^ 4 ∗ 5 ∗ 2 ∗ 12 ∗ 3 = 10 ^ 5 ∗ 36 answer : e | general |
math_qa__tFIeTNtX9WHFDJrr | in a 3 digit number , the 100 digit is 2 more than the tens digit and the units digit is 2 less than the tens digit . if the sum of the digits is 27 , find the number ? Choose one.
A) 867 B) 1179 C) 1196 D) 1098 E) 1197 | <gadget id="calculator">27 / 3</gadget>
<output>9</output>
<gadget id="calculator">9 + 2</gadget>
<output>11</output>
<gadget id="calculator">11 * 100</gadget>
<output>1_100</output>
<gadget id="calculator">9 * 10</gadget>
<output>90</output>
<gadget id="calculator">1_100 + 90</gadget>
<output>1_190</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">1_190 + 7</gadget>
<output>1_197</output>
<result>E</result> | E | 1,197 | in a 3 digit number , the 100 digit is 2 more than the tens digit and the units digit is 2 less than the tens digit . if the sum of the digits is 27 , find the number ? | {
"A": "867",
"B": "1179",
"C": "1196",
"D": "1098",
"E": "1197"
} | add(add(multiply(add(divide(27, 3), 2), const_100), multiply(divide(27, 3), const_10)), subtract(divide(27, 3), 2)) | divide(n4,n0)|add(n2,#0)|multiply(#0,const_10)|subtract(#0,n2)|multiply(#1,const_100)|add(#4,#2)|add(#5,#3) | e 1197 let the three digit numbers be 100 a + 10 b + c a = b + 2 c = b - 2 a + b + c = 3 b = 27 = > b = 9 so a = 11 and b = 7 hence the three digit number is : 1197 | general |
math_qa__c8WCFQk3P0XfmEaY | At what rate percent on simple interest will Rs.750 amount to Rs.900 in 2 years?
Choose the correct choice from the following.
A) 10 %
B) 2 %
C) 4 %
D) 5 %
E) 3 % | <gadget id="calculator">900 - 750</gadget>
<output>150</output>
<gadget id="calculator">150 / 750</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) / 2</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 100</gadget>
<output>10</output>
<result>A</result> | A | 10 | At what rate percent on simple interest will Rs.750 amount to Rs.900 in 2 years? | {
"A": "10 %",
"B": "2 %",
"C": "4 %",
"D": "5 %",
"E": "3 %"
} | multiply(divide(divide(subtract(900, 750), 750), 2), const_100) | subtract(n1,n0)|divide(#0,n0)|divide(#1,n2)|multiply(#2,const_100)| | "150 = ( 750 * 2 * r ) / 100 r = 10 % answer : a" | gain |
math_qa__DmyaLDXZ5FytTtyI | square of 99=? Pick one: A) 9001 B) 9621 C) 9431 D) 9801 E) 9601 | <gadget id="calculator">99 * 99</gadget>
<output>9_801</output>
<result>D</result> | D | 9,801 | square of 99=? | {
"A": "9001",
"B": "9621",
"C": "9431",
"D": "9801",
"E": "9601"
} | multiply(99, 99) | multiply(n0,n0) | square of ( 100 - 1 ) = 10000 + 1 - 200 9801 answer d | geometry |
math_qa__0SGqe4xjqp5JHjIk | If 36 men can do a piece of work in 25 hours, in how many hours will 15 men do it ? Select: A) 10 hours B) 40 hours C) 20 hours D) 60 hours E) none of them | <gadget id="calculator">36 * 25</gadget>
<output>900</output>
<gadget id="calculator">900 / 15</gadget>
<output>60</output>
<result>D</result> | D | 60 | If 36 men can do a piece of work in 25 hours, in how many hours will 15 men do it ? | {
"A": "10 hours",
"B": "40 hours",
"C": "20 hours",
"D": "60 hours",
"E": "none of them"
} | divide(multiply(36, 25), 15) | multiply(n0,n1)|divide(#0,n2)| | "let the required number of hours be x . then , less men , more hours ( indirect proportion ) 15 : 36 : : 25 : x = ( 15 x x ) = ( 36 x 25 ) = ( 36 x 25 ) / 15 = 60 hence , 15 men can do it in 60 hours . answer is d ." | physics |
math_qa__mnWZeeIIK56TqQoE | Nina has exactly enough money to purchase 6 widgets. If the cost of each widget were reduced by $1, then Nina would have exactly enough money to purchase 8 widgets. How much money does Nina have?
Choose the correct choice from the following:
A) $ 22
B) $ 24
C) $ 30
D) $ 36
E) $ 40 | <gadget id="calculator">1 * 8</gadget>
<output>8</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<result>B</result> | B | 24 | Nina has exactly enough money to purchase 6 widgets. If the cost of each widget were reduced by $1, then Nina would have exactly enough money to purchase 8 widgets. How much money does Nina have? | {
"A": "$ 22",
"B": "$ 24",
"C": "$ 30",
"D": "$ 36",
"E": "$ 40"
} | multiply(divide(multiply(1, 8), subtract(8, 6)), 6) | multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1)|multiply(n0,#2)| | "b its is . let price = x ( x - 1 ) 8 = 6 x x = 4 hence total money = 6 * 4 = 24" | general |
math_qa__hKhKiYlvtdTHvwyo | A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 210, then how much amount should C pay as his share of rent? Choose the correct choice from the following:
A) 54 B) 45 C) 25 D) 15 E) 55 | <gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">10 * 7</gadget>
<output>70</output>
<gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">70 + 60</gadget>
<output>130</output>
<gadget id="calculator">130 + 45</gadget>
<output>175</output>
<gadget id="calculator">45 / 175</gadget>
<output>9/35 = around 0.257143</output>
<gadget id="calculator">210 * (9/35)</gadget>
<output>54</output>
<result>A</result> | A | 54 | A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 210, then how much amount should C pay as his share of rent? | {
"A": "54",
"B": "45",
"C": "25",
"D": "15",
"E": "55"
} | multiply(210, divide(multiply(15, 3), add(add(multiply(10, 7), multiply(12, 5)), multiply(15, 3)))) | multiply(n4,n5)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|add(#3,#0)|divide(#0,#4)|multiply(n6,#5)| | "a : b : c = 10 × 7 : 12 × 5 : 15 × 3 = 2 × 7 : 12 × 1 : 3 × 3 = 14 : 12 : 9 amount that c should pay = 210 × 9 / 35 = 6 × 9 = 54 answer is a" | general |
math_qa__2fvFsKIcqR3EKqC9 | If 50 honey bees make 50 grams of honey in 50 days, then 1 honey bee will make 1 gram of honey in how many days?
Choices:
A) 1
B) 3.5
C) 20
D) 49
E) 50 | <gadget id="calculator">1 / 50</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">1 / (1/50)</gadget>
<output>50</output>
<result>E</result> | E | 50 | If 50 honey bees make 50 grams of honey in 50 days, then 1 honey bee will make 1 gram of honey in how many days? | {
"A": "1",
"B": "3.5",
"C": "20",
"D": "49",
"E": "50"
} | divide(1, divide(1, 50)) | divide(n3,n0)|divide(n3,#0)| | "explanation : let the required number days be x . less honey bees , more days ( indirect proportion ) less honey , less days ( direct proportion ) honey bees 1 : 50 : : 50 : x honey 50 : 1 = > 1 x 50 x x = 50 x 1 x 50 = > x = 50 . answer : e" | physics |
math_qa__lqz9cQa7M6lijwKn | The charge for a single room at Hotel P is 55 percent less than the charge for a single room at Hotel R and 10 percent less than the charge for a single room at Hotel G. The charge for a single room at Hotel R is what percent greater than the charge for a single room at Hotel G? Select the correct option
A) 50 % B) 60 % C) 75 % D) 80 % E) 100 % | <gadget id="calculator">100 - 55</gadget>
<output>45</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">45 / 90</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 / 50</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>E</result> | E | 100 | The charge for a single room at Hotel P is 55 percent less than the charge for a single room at Hotel R and 10 percent less than the charge for a single room at Hotel G. The charge for a single room at Hotel R is what percent greater than the charge for a single room at Hotel G? | {
"A": "50 %",
"B": "60 %",
"C": "75 %",
"D": "80 %",
"E": "100 %"
} | multiply(divide(subtract(const_100, multiply(divide(subtract(const_100, 55), subtract(const_100, 10)), const_100)), multiply(divide(subtract(const_100, 55), subtract(const_100, 10)), const_100)), const_100) | subtract(const_100,n0)|subtract(const_100,n1)|divide(#0,#1)|multiply(#2,const_100)|subtract(const_100,#3)|divide(#4,#3)|multiply(#5,const_100)| | "p = 0.45 r = 0.9 g r = 0.9 g / 0.45 = 2 g thus r is 100 % greater than g . the answer is e ." | gain |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.