id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__wRAknOu7KxunBElH | If money is invested at r percent interest, compounded annually, the amount of investment will double in approximately 70/r years. If Pat's parents invested $ 10000 in a long term bond that pays 8 percent interest, compounded annually, what will be the approximate total amount of investment 18 years later, when Pat is ready for college? Choices
A) $ 40000 B) $ 15000 C) $ 12000 D) $ 10000 E) $ 9000 | <gadget id="calculator">10_000 * 2</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 * 2</gadget>
<output>40_000</output>
<result>A</result> | A | 40,000 | If money is invested at r percent interest, compounded annually, the amount of investment will double in approximately 70/r years. If Pat's parents invested $ 10000 in a long term bond that pays 8 percent interest, compounded annually, what will be the approximate total amount of investment 18 years later, when Pat is ready for college? | {
"A": "$ 40000",
"B": "$ 15000",
"C": "$ 12000",
"D": "$ 10000",
"E": "$ 9000"
} | multiply(multiply(10000, const_2), const_2) | multiply(n1,const_2)|multiply(#0,const_2) | since investment doubles in 70 / r years then for r = 8 it ' ll double in 70 / 8 = ~ 9 years ( we are not asked about the exact amount so such an approximation will do ) . thus in 18 years investment will double twice and become ( $ 10,000 * 2 ) * 2 = $ 40,000 ( after 9 years investment will become $ 10,000 * 2 = $ 20,000 and in another 9 years it ' ll become $ 20,000 * 2 = $ 40,000 ) . answer : a . | general |
math_qa__HbHbsTi410786x3x | In a ratio which is equal to 4:6, if the antecedent is 30, then the consequent is? Options: A) 72 B) 85 C) 64 D) 51 E) 45 | <gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">30 + 15</gadget>
<output>45</output>
<result>E</result> | E | 45 | In a ratio which is equal to 4:6, if the antecedent is 30, then the consequent is? | {
"A": "72",
"B": "85",
"C": "64",
"D": "51",
"E": "45"
} | add(30, divide(30, const_2)) | divide(n2,const_2)|add(n2,#0)| | "we have 4 / 6 = 30 / x 4 x = 30 * 6 x = 45 consequent = 45 answer is e" | other |
math_qa__MIMvT0LiTFetdpzT | A side of beef lost 35 percent of its weight in processing. If the side of beef weighed 560 pounds after processing, how many pounds did it weigh before processing? Choose the correct choice from the following options: A) 191 B) 355 C) 737 D) 861 E) 1,560 | <gadget id="calculator">560 * 100</gadget>
<output>56_000</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">56_000 / 65</gadget>
<output>11_200/13 = around 861.538462</output>
<result>D</result> | D | 861 | A side of beef lost 35 percent of its weight in processing. If the side of beef weighed 560 pounds after processing, how many pounds did it weigh before processing? | {
"A": "191",
"B": "355",
"C": "737",
"D": "861",
"E": "1,560"
} | divide(multiply(560, const_100), subtract(const_100, 35)) | multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "let weight of side of beef before processing = x ( 65 / 100 ) * x = 560 = > x = ( 560 * 100 ) / 65 = 861 answer d" | gain |
math_qa__tiEGnMvtXIHEtZZY | A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 240 per month. What is his monthly salary? Choose the correct choice from the following choices
A) 5000 B) 2999 C) 6000 D) 2990 E) 2771 | <gadget id="calculator">240 * 100</gadget>
<output>24_000</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">80 * (1/5)</gadget>
<output>16</output>
<gadget id="calculator">80 + 16</gadget>
<output>96</output>
<gadget id="calculator">100 - 96</gadget>
<output>4</output>
<gadget id="calculator">24_000 / 4</gadget>
<output>6_000</output>
<result>C</result> | C | 6,000 | A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 240 per month. What is his monthly salary? | {
"A": "5000",
"B": "2999",
"C": "6000",
"D": "2990",
"E": "2771"
} | divide(multiply(240, const_100), subtract(const_100, add(subtract(const_100, 20), multiply(subtract(const_100, 20), divide(20, const_100))))) | divide(n1,const_100)|multiply(n2,const_100)|subtract(const_100,n0)|multiply(#0,#2)|add(#3,#2)|subtract(const_100,#4)|divide(#1,#5)| | "income = rs . 100 expenditure = rs . 80 savings = rs . 20 present expenditure 80 * ( 20 / 100 ) = rs . 96 present savings = 100 â € “ 96 = rs . 4 100 - - - - - - 4 ? - - - - - - - - - 240 = > 6000 answer : c" | general |
math_qa__cwdKum1QqLMx1OxW | A case of 12 rolls of paper towels sells for $9. The cost of one roll sold individually is $1.What is the percent Q of savings per roll for the 12-roll package over the cost of 12 rolls purchased individually? Choose the correct choice from the following answers:
A) 9 %
B) 11 %
C) 15 %
D) 25 %
E) 90 % | <gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 100</gadget>
<output>75</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<result>D</result> | D | 25 | A case of 12 rolls of paper towels sells for $9. The cost of one roll sold individually is $1.What is the percent Q of savings per roll for the 12-roll package over the cost of 12 rolls purchased individually? | {
"A": "9 %",
"B": "11 %",
"C": "15 %",
"D": "25 %",
"E": "90 %"
} | subtract(const_100, multiply(divide(9, 12), const_100)) | divide(n1,n0)|multiply(#0,const_100)|subtract(const_100,#1) | cost of 12 paper towels individually = 1 * 12 = 12 cost of a set of 12 paper towels = 9 cost of one roll = 9 / 12 = 3 / 4 = 0.75 savings per roll = 1 - . 75 = 0.25 % of savings is q = . 25 / 1 * 100 = 25 % d is the answer . | general |
math_qa__xJcVFDaAw2wLkv66 | In what ratio mental A at Rs.68 per kg be mixed with another metal at Rs.96 per kg so that cost of alloy (mixture) is Rs.78 per kg? Select:
A) 5 : 8 B) 4 : 7 C) 3 : 7 D) 9 : 5 E) 9 : 8 | <gadget id="calculator">96 - 78</gadget>
<output>18</output>
<gadget id="calculator">96 - 68</gadget>
<output>28</output>
<gadget id="calculator">18 / 28</gadget>
<output>9/14 = around 0.642857</output>
<gadget id="calculator">1 - (9/14)</gadget>
<output>5/14 = around 0.357143</output>
<gadget id="calculator">(9/14) / (5/14)</gadget>
<output>9/5 = around 1.8</output>
<result>D</result> | D | 1.8 | In what ratio mental A at Rs.68 per kg be mixed with another metal at Rs.96 per kg so that cost of alloy (mixture) is Rs.78 per kg? | {
"A": "5 : 8",
"B": "4 : 7",
"C": "3 : 7",
"D": "9 : 5",
"E": "9 : 8"
} | divide(divide(subtract(96, 78), subtract(96, 68)), subtract(const_1, divide(subtract(96, 78), subtract(96, 68)))) | subtract(n1,n2)|subtract(n1,n0)|divide(#0,#1)|subtract(const_1,#2)|divide(#2,#3)| | "( 96 - 78 ) / ( 78 - 68 ) = 18 / 10 = 9 / 5 answer : d" | other |
math_qa__kUJLRDOjnQVSlfHT | arjun started a business with rs . 20000 and is joined afterwards by anoop with rs . 4000 . after how many months did anoop join if the profits at the end of the year are divided equally ? Pick: A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">20_000 * 12</gadget>
<output>240_000</output>
<gadget id="calculator">4_000 * 10</gadget>
<output>40_000</output>
<gadget id="calculator">240_000 / 40_000</gadget>
<output>6</output>
<result>D</result> | D | 6 | arjun started a business with rs . 20000 and is joined afterwards by anoop with rs . 4000 . after how many months did anoop join if the profits at the end of the year are divided equally ? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(multiply(20000, const_12), multiply(4000, const_10)) | multiply(n0,const_12)|multiply(n1,const_10)|divide(#0,#1) | suppose anoop joined after 3 months . then , 20000 * 12 = 40000 * ( 12 – x ) = > = > x = 6 . answer : d | general |
math_qa__MKcHg4NvYobafjhp | The length of a rectangle is increased by 20% and its breadth is decreased by 20%. What is the effect on its area? Pick one.
A) 1288 B) 9600 C) 1000 D) 10000 E) 2887 | <gadget id="calculator">20 + 100</gadget>
<output>120</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">120 * 80</gadget>
<output>9_600</output>
<result>B</result> | B | 9,600 | The length of a rectangle is increased by 20% and its breadth is decreased by 20%. What is the effect on its area? | {
"A": "1288",
"B": "9600",
"C": "1000",
"D": "10000",
"E": "2887"
} | multiply(add(20, const_100), subtract(const_100, 20)) | add(n0,const_100)|subtract(const_100,n1)|multiply(#0,#1)| | "100 * 100 = 10000 120 * 80 = 9600 answer : b" | geometry |
math_qa__LSH4eeSXIqIAOZvg | A perfect square is defined as the square of an integer and a perfect cube is defined as the cube of an integer. How many positive integers n are there such that n is less than 100,000 and at the same time n is a perfect square and a perfect cube? Pick
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 / 1</gadget>
<output>6</output>
<result>D</result> | D | 6 | A perfect square is defined as the square of an integer and a perfect cube is defined as the cube of an integer. How many positive integers n are there such that n is less than 100,000 and at the same time n is a perfect square and a perfect cube? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(add(const_4, const_2), const_1) | add(const_2,const_4)|divide(#0,const_1)| | "if n is a perfect square and a perfect cube , then n = a ^ 6 for some integer a . the numbers are 1 ^ 6 = 1 , 2 ^ 6 = 64 , 3 ^ 6 = 729 , 4 ^ 6 = 4096 , 5 ^ 6 = 15,625 , 6 ^ = 46,656 . the answer is d ." | geometry |
math_qa__G5xaWrRM8P3OdYVG | A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum? Choose the most appropriate option.
A) rs 4462.50 B) rs . 8032.50 C) rs . 8900 D) rs . 8925 E) none | <gadget id="calculator">4_016.25 * 100</gadget>
<output>401_625</output>
<gadget id="calculator">401_625 / 9</gadget>
<output>44_625</output>
<gadget id="calculator">44_625 / 5</gadget>
<output>8_925</output>
<result>D</result> | D | 8,925 | A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum? | {
"A": "rs 4462.50",
"B": "rs . 8032.50",
"C": "rs . 8900",
"D": "rs . 8925",
"E": "none"
} | divide(divide(multiply(4016.25, const_100), 9), 5) | multiply(n0,const_100)|divide(#0,n1)|divide(#1,n2)| | "solution principal = rs . ( 100 * 4016.25 / 9 * 5 ) = rs . ( 401625 / 45 ) = rs . 8925 answer d" | gain |
math_qa__iYtymEMlrjmuZV1n | Vijay sells a cupboard at 16% below cost price. Had he got Rs.1200 more, he would have made a profit of 16%. What is the cost price of the cupboard?
Choose the correct option:
A) 3750 B) 3600 C) 7400 D) 7500 E) none of these | <gadget id="calculator">100 + 16</gadget>
<output>116</output>
<gadget id="calculator">100 - 16</gadget>
<output>84</output>
<gadget id="calculator">116 - 84</gadget>
<output>32</output>
<gadget id="calculator">32 / 100</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">1_200 / (8/25)</gadget>
<output>3_750</output>
<result>A</result> | A | 3,750 | Vijay sells a cupboard at 16% below cost price. Had he got Rs.1200 more, he would have made a profit of 16%. What is the cost price of the cupboard? | {
"A": "3750",
"B": "3600",
"C": "7400",
"D": "7500",
"E": "none of these"
} | divide(1200, divide(subtract(add(const_100, 16), subtract(const_100, 16)), const_100)) | add(n0,const_100)|subtract(const_100,n0)|subtract(#0,#1)|divide(#2,const_100)|divide(n1,#3)| | "explanation : cost price = 1200 / ( 0.16 + 0.16 ) = 1200 / 0.32 = rs . 3750 answer a" | gain |
math_qa__LXklnt23Bpmfv1DE | a class of 35 students has an average height of 180 cm . 7 students whose average height is 120 cm , left the class and 7 others whose average height is 140 cm , joined . calculate the new average height of the students of the class ( in cm ) is ? Choose the correct choice from the following options: A) 204.6 cm B) 404.6 cm C) 224.6 cm D) 205.6 cm E) 256.6 cm | <gadget id="calculator">35 * 180</gadget>
<output>6_300</output>
<gadget id="calculator">7 * 140</gadget>
<output>980</output>
<gadget id="calculator">7 * 120</gadget>
<output>840</output>
<gadget id="calculator">980 - 840</gadget>
<output>140</output>
<gadget id="calculator">6_300 + 140</gadget>
<output>6_440</output>
<gadget id="calculator">6_440 / 35</gadget>
<output>184</output>
<gadget id="calculator">184 + 12</gadget>
<output>196</output>
<gadget id="calculator">196 + 4</gadget>
<output>200</output>
<gadget id="calculator">200 + 4</gadget>
<output>204</output>
<result>A</result> | A | 204.6 | a class of 35 students has an average height of 180 cm . 7 students whose average height is 120 cm , left the class and 7 others whose average height is 140 cm , joined . calculate the new average height of the students of the class ( in cm ) is ? | {
"A": "204.6 cm",
"B": "404.6 cm",
"C": "224.6 cm",
"D": "205.6 cm",
"E": "256.6 cm"
} | add(add(add(divide(add(multiply(35, 180), subtract(multiply(7, 140), multiply(7, 120))), 35), const_12), const_4), const_4) | multiply(n0,n1)|multiply(n2,n5)|multiply(n2,n3)|subtract(#1,#2)|add(#0,#3)|divide(#4,n0)|add(#5,const_12)|add(#6,const_4)|add(#7,const_4) | total height = 180 * 35 = 6300 cm . total height of those who left = 120 * 7 = 840 total height of those who joined = 140 * 7 = 980 new average = [ 6300 - 120 + 980 ] / 35 = 7160 / 35 cm . = 204.6 cm answer : a | general |
math_qa__OrppWumxaHDTsPul | At a certain food stand, the price of each apple is 40¢ and the price of each orange is 60¢. Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is 56¢. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is 50¢? Choose the correct choice from the following choices.
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">60 * 10</gadget>
<output>600</output>
<gadget id="calculator">56 * 10</gadget>
<output>560</output>
<gadget id="calculator">600 - 560</gadget>
<output>40</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">40 / 20</gadget>
<output>2</output>
<gadget id="calculator">2 * 40</gadget>
<output>80</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 60</gadget>
<output>480</output>
<gadget id="calculator">80 + 480</gadget>
<output>560</output>
<gadget id="calculator">50 * 10</gadget>
<output>500</output>
<gadget id="calculator">560 - 500</gadget>
<output>60</output>
<gadget id="calculator">60 - 50</gadget>
<output>10</output>
<gadget id="calculator">60 / 10</gadget>
<output>6</output>
<result>E</result> | E | 6 | At a certain food stand, the price of each apple is 40¢ and the price of each orange is 60¢. Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is 56¢. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is 50¢? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(subtract(add(multiply(divide(subtract(multiply(60, 10), multiply(56, 10)), subtract(60, 40)), 40), multiply(subtract(10, divide(subtract(multiply(60, 10), multiply(56, 10)), subtract(60, 40))), 60)), multiply(50, 10)), subtract(60, 50)) | multiply(n1,n2)|multiply(n2,n4)|multiply(n2,n5)|subtract(n1,n0)|subtract(n1,n5)|subtract(#0,#1)|divide(#5,#3)|multiply(n0,#6)|subtract(n2,#6)|multiply(n1,#8)|add(#7,#9)|subtract(#10,#2)|divide(#11,#4)| | "if the average price is 56 , then mary has 8 oranges and 2 apples ( a ratio of 4 : 1 ) . for the average price to be 50 , the ratio should be 1 : 1 . mary must put back 6 oranges . the answer is e ." | general |
math_qa__enxC0fzL7C7lY3LG | If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 12% per annum then the gain of B in a period of 3 years is? Choose the correct choice:
A) 200
B) 210
C) 220
D) 225
E) 230 | <gadget id="calculator">3_500 * 12</gadget>
<output>42_000</output>
<gadget id="calculator">42_000 * 3</gadget>
<output>126_000</output>
<gadget id="calculator">126_000 / 100</gadget>
<output>1_260</output>
<gadget id="calculator">3_500 * 10</gadget>
<output>35_000</output>
<gadget id="calculator">35_000 * 3</gadget>
<output>105_000</output>
<gadget id="calculator">105_000 / 100</gadget>
<output>1_050</output>
<gadget id="calculator">1_260 - 1_050</gadget>
<output>210</output>
<result>B</result> | B | 210 | If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 12% per annum then the gain of B in a period of 3 years is? | {
"A": "200",
"B": "210",
"C": "220",
"D": "225",
"E": "230"
} | subtract(divide(multiply(multiply(3500, 12), const_3), const_100), divide(multiply(multiply(3500, 10), 3), const_100)) | multiply(n0,n2)|multiply(n0,n1)|multiply(#0,const_3)|multiply(n3,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,#5) | ( 3500 * 2 * 3 ) / 100 = > 210 answer : b | gain |
math_qa__JIfOMWP4GOb1oBDx | Think of a number, divide it by 5 and add 10 to it. The result is 21. What is the number thought of? Choose one.
A) 24 B) 55 C) 297 D) 267 E) 29 | <gadget id="calculator">21 - 10</gadget>
<output>11</output>
<gadget id="calculator">11 * 5</gadget>
<output>55</output>
<result>B</result> | B | 55 | Think of a number, divide it by 5 and add 10 to it. The result is 21. What is the number thought of? | {
"A": "24",
"B": "55",
"C": "297",
"D": "267",
"E": "29"
} | multiply(subtract(21, 10), 5) | subtract(n2,n1)|multiply(n0,#0) | explanation : 21 - 10 = 11 11 x 5 = 55 answer : b | general |
math_qa__RwjK2NGJfHBmCRlm | A sum fetched a total simple interest of 4025.25 at the rate of 9 %.p.a. in 5 years. What is the sum? Choose one
A) 5768 B) 8925 C) 2345 D) 8945 E) 8723 | <gadget id="calculator">4_025.25 * 100</gadget>
<output>402_525</output>
<gadget id="calculator">402_525 / 9</gadget>
<output>44_725</output>
<gadget id="calculator">44_725 / 5</gadget>
<output>8_945</output>
<result>D</result> | D | 8,945 | A sum fetched a total simple interest of 4025.25 at the rate of 9 %.p.a. in 5 years. What is the sum? | {
"A": "5768",
"B": "8925",
"C": "2345",
"D": "8945",
"E": "8723"
} | divide(divide(multiply(4025.25, const_100), 9), 5) | multiply(n0,const_100)|divide(#0,n1)|divide(#1,n2)| | "principal = ( 100 x 4025.25 ) / ( 9 x 5 ) = 402525 / 45 = 8945 . answer d" | gain |
math_qa__k5R4KgAVeqx15qnY | the average of 6 numbers is 3.9 . the average of two of them is 3.4 , while the average of the other two is 3.85 . what is the average of the remaining two numbers ? Pick one: A) 4.7 B) 4.45 C) 4.2 D) 4.1 E) 4.9 | <gadget id="calculator">3.9 * 6</gadget>
<output>23.4</output>
<gadget id="calculator">3.4 * 2</gadget>
<output>6.8</output>
<gadget id="calculator">3.85 * 2</gadget>
<output>7.7</output>
<gadget id="calculator">6.8 + 7.7</gadget>
<output>14.5</output>
<gadget id="calculator">23.4 - 14.5</gadget>
<output>8.9</output>
<gadget id="calculator">8.9 / 2</gadget>
<output>4.45</output>
<result>B</result> | B | 4.45 | the average of 6 numbers is 3.9 . the average of two of them is 3.4 , while the average of the other two is 3.85 . what is the average of the remaining two numbers ? | {
"A": "4.7",
"B": "4.45",
"C": "4.2",
"D": "4.1",
"E": "4.9"
} | divide(subtract(multiply(3.9, 6), add(multiply(3.4, const_2), multiply(3.85, const_2))), const_2) | multiply(n0,n1)|multiply(n2,const_2)|multiply(n3,const_2)|add(#1,#2)|subtract(#0,#3)|divide(#4,const_2) | explanation : sum of the remaining two numbers = ( 3.9 * 6 ) - [ ( 3.4 * 2 ) + ( 3.85 * 2 ) ] = 23.40 - ( 6.8 + 7.7 ) = 23.40 - 14.5 = 8.90 . required average = ( 8.9 / 2 ) = 4.45 . answer : b ) 4.45 | general |
math_qa__rhFK9fBZvUgYOMGx | A merchant has selected two items to be placed on sale, one of which currently sells for 30 percent less than the other. If he wishes to raise the price of the cheaper item so that the two items are equally priced, by what percentage must he raise the price of the less expensive item? Choose the correct option.
A) 22 %
B) 30 %
C) 42 6 / 7 %
D) 70 %
E) 130 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(3/10) / (7/10)</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(3/7) * 100</gadget>
<output>300/7 = around 42.857143</output>
<result>C</result> | C | 42 | A merchant has selected two items to be placed on sale, one of which currently sells for 30 percent less than the other. If he wishes to raise the price of the cheaper item so that the two items are equally priced, by what percentage must he raise the price of the less expensive item? | {
"A": "22 %",
"B": "30 %",
"C": "42 6 / 7 %",
"D": "70 %",
"E": "130 %"
} | multiply(divide(divide(30, const_100), subtract(const_1, divide(30, const_100))), const_100) | divide(n0,const_100)|subtract(const_1,#0)|divide(#0,#1)|multiply(#2,const_100)| | "expensive item = $ 100 ; cheap item = $ 70 ; we must increase $ 70 to $ 100 , so by $ 30 , which is approximately 40 % increase : ( 100 - 70 ) / 70 = 3 / 7 = ~ 0.42 . answer : c ." | general |
math_qa__UScQQZCHDMv8qB6d | A WORKS TWICE AS FAST AS B. IF B CAN COMPLETE A WORK IN 12 DAYS INDEPENDENTLY, THE NUMBER OF DAYS IN WHICH A AND B CAN TOGETHER FINISH THE WORK IS:
Answers.
A) 4 days B) 6 days C) 8 days D) 18 days E) none of these | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">2 * (1/12)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/12) + (1/6)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / (1/4)</gadget>
<output>4</output>
<result>A</result> | A | 4 | A WORKS TWICE AS FAST AS B. IF B CAN COMPLETE A WORK IN 12 DAYS INDEPENDENTLY, THE NUMBER OF DAYS IN WHICH A AND B CAN TOGETHER FINISH THE WORK IS: | {
"A": "4 days",
"B": "6 days",
"C": "8 days",
"D": "18 days",
"E": "none of these"
} | inverse(add(divide(const_1, 12), multiply(const_2, divide(const_1, 12)))) | divide(const_1,n0)|multiply(#0,const_2)|add(#0,#1)|inverse(#2) | solution rates of worktio of raing of a and b = 2 : 1 . so , ratio of times taken = 1 : 2 ∴ a ’ s 1 day ’ s work = 1 / 6 b ’ s 1 day ’ s work = 1 / 12 ( a + b ) ' s 1 day ’ s work = ( 1 / 6 + 1 / 12 ) = 3 / 12 = 1 / 4 so , a and b together can finish the work in 4 days . answer a | physics |
math_qa__DQk90CeYAMtfW69F | The average weight of A, B and C is 45 kg. If the average weight of A and B be 41 kg and that of B and C be 43 kg, then the weight of B is:
Choose one:
A) 33 kg B) 31 kg C) 32 kg D) 36 kg E) 37 kg | <gadget id="calculator">41 * 2</gadget>
<output>82</output>
<gadget id="calculator">43 * 2</gadget>
<output>86</output>
<gadget id="calculator">82 + 86</gadget>
<output>168</output>
<gadget id="calculator">45 * 3</gadget>
<output>135</output>
<gadget id="calculator">168 - 135</gadget>
<output>33</output>
<result>A</result> | A | 33 | The average weight of A, B and C is 45 kg. If the average weight of A and B be 41 kg and that of B and C be 43 kg, then the weight of B is: | {
"A": "33 kg",
"B": "31 kg",
"C": "32 kg",
"D": "36 kg",
"E": "37 kg"
} | subtract(add(multiply(41, const_2), multiply(43, const_2)), multiply(45, const_3)) | multiply(n1,const_2)|multiply(n2,const_2)|multiply(n0,const_3)|add(#0,#1)|subtract(#3,#2)| | "a 33 kg let a , b , c represent their respective weights . then , we have : a + b + c = ( 45 x 3 ) = 135 . . . . ( i ) a + b = ( 41 x 2 ) = 82 . . . . ( ii ) b + c = ( 43 x 2 ) = 86 . . . . ( iii ) adding ( ii ) and ( iii ) , we get : a + 2 b + c = 168 . . . . ( iv ) subtracting ( i ) from ( iv ) , we get : b = 33 . b ' s weight = 33 kg . a" | general |
math_qa__Iig5ISp83BAmhMpo | The salary of a worker is first increased by 40% and afterwards reduced by 40%. What is the net change in the worker's salary? Pick:
A) 8 % decrease B) 8 % increase C) 16 % decrease D) 16 % increase E) no change | <gadget id="calculator">40 + 100</gadget>
<output>140</output>
<gadget id="calculator">140 * 40</gadget>
<output>5_600</output>
<gadget id="calculator">5_600 / 100</gadget>
<output>56</output>
<gadget id="calculator">140 - 56</gadget>
<output>84</output>
<gadget id="calculator">100 - 84</gadget>
<output>16</output>
<result>C</result> | C | 16 | The salary of a worker is first increased by 40% and afterwards reduced by 40%. What is the net change in the worker's salary? | {
"A": "8 % decrease",
"B": "8 % increase",
"C": "16 % decrease",
"D": "16 % increase",
"E": "no change"
} | subtract(const_100, subtract(add(40, const_100), divide(multiply(add(40, const_100), 40), const_100))) | add(n0,const_100)|multiply(n0,#0)|divide(#1,const_100)|subtract(#0,#2)|subtract(const_100,#3)| | "let x be the original salary . the final salary is 0.6 ( 1.4 x ) = 0.84 x the answer is c ." | gain |
math_qa__eWUsl0nr9B1Fbbc3 | If q = (x – 5)^2 + (x + 1)^2 – 6, then y is least when x = Choices
A) - 2 B) - 1 C) 0 D) 2 E) none of the above | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">2 - 10</gadget>
<output>-8</output>
<gadget id="calculator">(-8) / 2</gadget>
<output>-4</output>
<gadget id="calculator">(-4) / 2</gadget>
<output>-2</output>
<gadget id="calculator">-(-2)</gadget>
<output>2</output>
<result>D</result> | D | 2 | If q = (x – 5)^2 + (x + 1)^2 – 6, then y is least when x = | {
"A": "- 2",
"B": "- 1",
"C": "0",
"D": "2",
"E": "none of the above"
} | negate(divide(divide(subtract(2, multiply(5, 2)), 2), 2)) | multiply(n0,n1)|subtract(n1,#0)|divide(#1,n1)|divide(#2,n1)|negate(#3) | let us transform the formula : q = ( x – 5 ) ² + ( x + 1 ) ² – 6 = x ² – 10 x + 25 + x ² + 2 x + 1 – 6 = 2 x ² – 8 x + 20 = 2 × ( x ² – 4 x + 10 ) = 2 × ( ( x ² – 4 x + 4 ) + 6 ) = 2 × ( ( x – 2 ) ² + 6 ) any square is greater or equal 0 . therefore the formula possess the least value when ( x – 2 ) ² = 0 . x – 2 = 0 x = 2 the correct answer is choice ( d ) . | general |
math_qa__1xCFyXniXujmJxtV | What least number should be added to 1024, so that the sum is completely divisible by 25?
Choose the correct answer: A) 1 B) 3 C) 2 D) 0 E) 5 | <gadget id="calculator">1_024 % 25</gadget>
<output>24</output>
<gadget id="calculator">25 - 24</gadget>
<output>1</output>
<result>A</result> | A | 1 | What least number should be added to 1024, so that the sum is completely divisible by 25? | {
"A": "1",
"B": "3",
"C": "2",
"D": "0",
"E": "5"
} | subtract(25, reminder(1024, 25)) | reminder(n0,n1)|subtract(n1,#0)| | "1024 ã · 25 = 40 with remainder = 24 24 + 1 = 25 . hence 1 should be added to 1024 so that the sum will be divisible by 25 answer : option a" | general |
math_qa__nP1v8oWo9WJLNom7 | a student was asked to find the arithmetic mean of the numbers 3 , 117 , 915 , 138 , 1917 , 2114 and x . he found the mean to be 12 . what should be the remainder in the place of x ? Choose the correct choice from the following options
A) 5 B) 6 C) 7 D) 8 E) 9 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<result>C</result> | C | 7 | a student was asked to find the arithmetic mean of the numbers 3 , 117 , 915 , 138 , 1917 , 2114 and x . he found the mean to be 12 . what should be the remainder in the place of x ? | {
"A": "5",
"B": "6",
"C": "7",
"D": "8",
"E": "9"
} | add(const_4, const_3) | add(const_3,const_4) | we have ( 3 + 11 + 7 + 9 + 15 + 13 + 8 + 19 + 17 + 21 + 14 + x ) / 12 = 12 137 + x = 144 x = 7 answer is c | general |
math_qa__swicJS7kHjJdPzT3 | In an election between the two candidates, the candidates who gets 70% of votes polled is winned by 200 vote’s majority. What is the total number of votes polled? Choose one
A) 750 B) 500 C) 800 D) 850 E) none of these | <gadget id="calculator">100 * 200</gadget>
<output>20_000</output>
<gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">70 - 30</gadget>
<output>40</output>
<gadget id="calculator">20_000 / 40</gadget>
<output>500</output>
<result>B</result> | B | 500 | In an election between the two candidates, the candidates who gets 70% of votes polled is winned by 200 vote’s majority. What is the total number of votes polled? | {
"A": "750",
"B": "500",
"C": "800",
"D": "850",
"E": "none of these"
} | divide(multiply(const_100, 200), subtract(70, subtract(const_100, 70))) | multiply(n1,const_100)|subtract(const_100,n0)|subtract(n0,#1)|divide(#0,#2)| | "explanation : note : majority ( 40 % ) = difference in votes polled to win ( 70 % ) & defeated candidates ( 30 % ) 40 % = 70 % - 30 % 40 % - - - - - > 200 ( 40 * 5 = 200 ) 100 % - - - - - > 500 ( 100 * 5 = 500 ) answer : option b" | gain |
math_qa__8ZcgdmxyZmUS4Nfb | If w is 40 percent less than u,u is 40 percent less than y, and z is 46 percent less than y, then z is greater than w by what percent of w? Choices
A) 4 % B) 18 % C) 36 % D) 40 % E) 50 % | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * (3/5)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">46 / 100</gadget>
<output>23/50 = around 0.46</output>
<gadget id="calculator">1 - (23/50)</gadget>
<output>27/50 = around 0.54</output>
<gadget id="calculator">(9/25) / (27/50)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) / 100</gadget>
<output>1/150 = around 0.006667</output>
<gadget id="calculator">1 / (1/150)</gadget>
<output>150</output>
<gadget id="calculator">150 - 100</gadget>
<output>50</output>
<result>E</result> | E | 50 | If w is 40 percent less than u,u is 40 percent less than y, and z is 46 percent less than y, then z is greater than w by what percent of w? | {
"A": "4 %",
"B": "18 %",
"C": "36 %",
"D": "40 %",
"E": "50 %"
} | subtract(divide(const_1, divide(divide(multiply(subtract(const_1, divide(40, const_100)), subtract(const_1, divide(40, const_100))), subtract(const_1, divide(46, const_100))), const_100)), const_100) | divide(n0,const_100)|divide(n2,const_100)|subtract(const_1,#0)|subtract(const_1,#1)|multiply(#2,#2)|divide(#4,#3)|divide(#5,const_100)|divide(const_1,#6)|subtract(#7,const_100) | given w = 0.6 u , u = 0.6 y , z = 0.54 y , substituting , w = 2 / 3 z - - - - > z = 1.5 w and thus z is 50 % greater than w . e is the correct answer . | gain |
math_qa__jvb81uPFNXXLEUSF | The salary of a person was reduced by 15%. By what percent should his reduced salary be raised so as to bring it at par with his original salary? Choose the correct choice from the following options
A) 10 % B) 17.6 % C) 13.7 % D) 15.1 % E) 12.3 % | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">100 * (3/20)</gadget>
<output>15</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">15 / 85</gadget>
<output>3/17 = around 0.176471</output>
<gadget id="calculator">(3/17) * 100</gadget>
<output>300/17 = around 17.647059</output>
<result>B</result> | B | 17.6 | The salary of a person was reduced by 15%. By what percent should his reduced salary be raised so as to bring it at par with his original salary? | {
"A": "10 %",
"B": "17.6 %",
"C": "13.7 %",
"D": "15.1 %",
"E": "12.3 %"
} | multiply(divide(multiply(const_100, divide(15, const_100)), subtract(const_100, multiply(const_100, divide(15, const_100)))), const_100) | divide(n0,const_100)|multiply(#0,const_100)|subtract(const_100,#1)|divide(#1,#2)|multiply(#3,const_100)| | "let the original salary be $ 100 new salary = $ 85 increase on 85 = 15 increase on 100 = 15 / 85 * 100 = 17.6 % answer is b" | gain |
math_qa__WwBkNOCbgSVZF7Zd | Which of the numbers 1, 2, 3, 4, or 5 is nearest in value to the sum
2007/2999+8001/5998+2001/3999=? Choose the most appropriate option
A) 1
B) 2
C) 3
D) 4
E) 5 | <gadget id="calculator">5 / 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2_007 / 2_999</gadget>
<output>2_007/2_999 = around 0.669223</output>
<gadget id="calculator">8_001 / 5_998</gadget>
<output>8_001/5_998 = around 1.333945</output>
<gadget id="calculator">(2_007/2_999) + (8_001/5_998)</gadget>
<output>12_015/5_998 = around 2.003168</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">2_999 + 1_000</gadget>
<output>3_999</output>
<gadget id="calculator">2_001 / 3_999</gadget>
<output>667/1_333 = around 0.500375</output>
<gadget id="calculator">(12_015/5_998) + (667/1_333)</gadget>
<output>20_016_661/7_995_334 = around 2.503543</output>
<gadget id="calculator">(1/2) + (20_016_661/7_995_334)</gadget>
<output>12_007_164/3_997_667 = around 3.003543</output>
<result>C</result> | C | 3 | Which of the numbers 1, 2, 3, 4, or 5 is nearest in value to the sum
2007/2999+8001/5998+2001/3999=? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | add(divide(5, const_10), add(add(divide(2007, 2999), divide(8001, 5998)), divide(2001, add(2999, multiply(const_10, const_100))))) | divide(n5,n6)|divide(n7,n8)|divide(n4,const_10)|multiply(const_10,const_100)|add(#0,#1)|add(n6,#3)|divide(n9,#5)|add(#4,#6)|add(#7,#2) | the sum is a little more than ( 2 / 3 ) + ( 8 / 6 ) + ( 2 / 4 ) = 2.5 . correct answer c | general |
math_qa__7Hf0qePgKJL6vHMF | If Jake loses 12 pounds, he will weigh twice as much as his sister. Together they now weigh 156 pounds. What is Jake’s present weight, in pounds? Choose the correct choice
A) 108
B) 135
C) 139
D) 147
E) 188 | <gadget id="calculator">156 - 12</gadget>
<output>144</output>
<gadget id="calculator">144 / 3</gadget>
<output>48</output>
<gadget id="calculator">48 * 2</gadget>
<output>96</output>
<gadget id="calculator">96 + 12</gadget>
<output>108</output>
<result>A</result> | A | 108 | If Jake loses 12 pounds, he will weigh twice as much as his sister. Together they now weigh 156 pounds. What is Jake’s present weight, in pounds? | {
"A": "108",
"B": "135",
"C": "139",
"D": "147",
"E": "188"
} | add(multiply(divide(subtract(156, 12), const_3), const_2), 12) | subtract(n1,n0)|divide(#0,const_3)|multiply(#1,const_2)|add(n0,#2)| | "lets say j is the weight of jack and s is the wt of his sister . if he loses 8 pounds , he s twice as heavy as his sister . j - 12 = 2 * s also , together they weight 156 pounds j + s = 156 solvong the 2 equation , we get j = 108 pounds ! a" | general |
math_qa__LcZKYj35XK3hgoNl | The perimeter of an equilateral triangle is 60. If one of the sides of the equilateral triangle is the side of an isosceles triangle of perimeter 65, then how long is the base of isosceles triangle? Choose the correct choice from the following: A) 10 B) 15 C) 20 D) 25 E) 30 | <gadget id="calculator">60 / 3</gadget>
<output>20</output>
<gadget id="calculator">65 - 20</gadget>
<output>45</output>
<gadget id="calculator">45 - 20</gadget>
<output>25</output>
<result>D</result> | D | 25 | The perimeter of an equilateral triangle is 60. If one of the sides of the equilateral triangle is the side of an isosceles triangle of perimeter 65, then how long is the base of isosceles triangle? | {
"A": "10",
"B": "15",
"C": "20",
"D": "25",
"E": "30"
} | subtract(subtract(65, divide(60, const_3)), divide(60, const_3)) | divide(n0,const_3)|subtract(n1,#0)|subtract(#1,#0) | the base of the isosceles triangle is 65 - 20 - 20 = 25 units the answer is d . | geometry |
math_qa__HMnnAPz5C7nJsaK5 | The average age of a class of 19 students is 20 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher? Choices: A) 39 B) 41 C) 40 D) 42 E) 43 | <gadget id="calculator">19 + 1</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">20 * 21</gadget>
<output>420</output>
<gadget id="calculator">19 * 20</gadget>
<output>380</output>
<gadget id="calculator">420 - 380</gadget>
<output>40</output>
<result>C</result> | C | 40 | The average age of a class of 19 students is 20 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher? | {
"A": "39",
"B": "41",
"C": "40",
"D": "42",
"E": "43"
} | subtract(multiply(add(19, 1), add(20, 1)), multiply(19, 20)) | add(n0,n2)|add(n1,n2)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2) | total age of all students = 19 ã — 20 total age of all students + age of the teacher = 20 ã — 21 age of the teacher = 20 ã — 21 â ˆ ’ 20 ã — 19 = 20 ( 21 â ˆ ’ 19 ) = 20 ã — 2 = 40 answer is c . | general |
math_qa__i248ecxDD3seLtSe | The sum of all the integers d such that -26 < d < 24 is Choose the correct option
A) 0
B) - 2
C) - 25
D) - 49
E) - 51 | <gadget id="calculator">-26</gadget>
<output>-26</output>
<gadget id="calculator">(-26) + 1</gadget>
<output>-25</output>
<gadget id="calculator">(-25) + 1</gadget>
<output>-24</output>
<gadget id="calculator">(-25) + (-24)</gadget>
<output>-49</output>
<result>D</result> | D | -49 | The sum of all the integers d such that -26 < d < 24 is | {
"A": "0",
"B": "- 2",
"C": "- 25",
"D": "- 49",
"E": "- 51"
} | add(add(negate(26), const_1), add(add(negate(26), const_1), const_1)) | negate(n0)|add(#0,const_1)|add(#1,const_1)|add(#1,#2)| | "easy one - - 25 , - 24 , - 23 , - 22 , . . . . . . - 1,0 , 1 , 2 . . . . , 22 , 23 cancel everyhitng and we ' re left with - - 25 and - 24 d = - 49 . d is the answer ." | general |
math_qa__aAPYMYPtUCLO0nUV | An electric pump can fill a tank in 6 hours. Because of a leak in the tank, it took 12hours to fill the tank. If the tank is full, how much time will the leak take to empty it? Pick: A) 10 hours B) 12 hours C) 8 hours D) 5 hours E) 15 hours | <gadget id="calculator">12 / 1</gadget>
<output>12</output>
<result>B</result> | B | 12 | An electric pump can fill a tank in 6 hours. Because of a leak in the tank, it took 12hours to fill the tank. If the tank is full, how much time will the leak take to empty it? | {
"A": "10 hours",
"B": "12 hours",
"C": "8 hours",
"D": "5 hours",
"E": "15 hours"
} | divide(12, const_1) | divide(n1,const_1)| | "work done by the leak in 1 hour = 1 / 6 - 1 / 12 = 1 / 12 the leak will empty the tank in 12 hours answer is b" | physics |
math_qa__KGP0VLTcA5GDrSFm | m and n are the x and y coordinates, respectively, of a point in the coordinate plane. If the points (m, n) and (m + p, n + 4) both lie on the line defined by the equation x = (y/2) - (2/5), what is the value of p? Choose the correct answer.
A) 4 / 5 B) 1 C) 2 D) 5 E) 8 | <gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>C</result> | C | 2 | m and n are the x and y coordinates, respectively, of a point in the coordinate plane. If the points (m, n) and (m + p, n + 4) both lie on the line defined by the equation x = (y/2) - (2/5), what is the value of p? | {
"A": "4 / 5",
"B": "1",
"C": "2",
"D": "5",
"E": "8"
} | divide(4, 2) | divide(n0,n1)| | "( m , n ) m = x n = y m = n / 2 - 2 / 5 10 m = 5 n - 4 ( multiplied by 10 to simplify equation ) ( m + p , n + 4 ) m + p = x n + 4 = y m + p = ( n + 4 ) / 2 - 2 / 5 multiplied by 10 again 10 m + 10 p = 5 n + 20 - 4 use both equations to solve for p and you get 10 p = 20 p = 2 answer : c" | general |
math_qa__M986Paft00Bn8s34 | Lilly has 10 fish and Rosy has 14 fish. In total, how many fish do they have in all? Choose the correct choice from the following answers
A) 21 B) 22 C) 23 D) 24 E) 25 | <gadget id="calculator">10 + 14</gadget>
<output>24</output>
<result>D</result> | D | 24 | Lilly has 10 fish and Rosy has 14 fish. In total, how many fish do they have in all? | {
"A": "21",
"B": "22",
"C": "23",
"D": "24",
"E": "25"
} | add(10, 14) | add(n0,n1)| | "10 + 14 = 24 the answer is d ." | general |
math_qa__vSTc840ZoeRrEe54 | 3 years ago , the ratio of ages of p and q was 4 : 3 . 6 years from now , the ratio of their ages will be 7 : 6 . what is p ' s age at present ? Choices:
A) 9
B) 12
C) 15
D) 18
E) 21 | <gadget id="calculator">3 + 6</gadget>
<output>9</output>
<gadget id="calculator">9 * 7</gadget>
<output>63</output>
<gadget id="calculator">9 * 6</gadget>
<output>54</output>
<gadget id="calculator">63 - 54</gadget>
<output>9</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">7 * (3/4)</gadget>
<output>21/4 = around 5.25</output>
<gadget id="calculator">6 - (21/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">9 / (3/4)</gadget>
<output>12</output>
<gadget id="calculator">12 + 3</gadget>
<output>15</output>
<result>C</result> | C | 15 | 3 years ago , the ratio of ages of p and q was 4 : 3 . 6 years from now , the ratio of their ages will be 7 : 6 . what is p ' s age at present ? | {
"A": "9",
"B": "12",
"C": "15",
"D": "18",
"E": "21"
} | add(divide(subtract(multiply(add(3, 6), 7), multiply(add(3, 6), 6)), subtract(6, multiply(7, divide(3, 4)))), 3) | add(n0,n3)|divide(n0,n1)|multiply(n4,#0)|multiply(n3,#0)|multiply(n4,#1)|subtract(#2,#3)|subtract(n3,#4)|divide(#5,#6)|add(n0,#7) | 3 ( p - 3 ) / 4 = ( q - 3 ) . then q = 3 ( p - 3 ) / 4 + 3 6 ( p + 6 ) / 7 = q + 6 6 ( p + 6 ) / 7 = 3 ( p - 3 ) / 4 + 9 24 p + 144 = 21 p + 189 3 p = 45 p = 15 the answer is c . | other |
math_qa__IBUyuMSRDJy9yJDo | A student scored an average of 55 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics? Choices:
A) 86 B) 165 C) 76 D) 155 E) 26 | <gadget id="calculator">90 * 2</gadget>
<output>180</output>
<gadget id="calculator">70 * 2</gadget>
<output>140</output>
<gadget id="calculator">180 + 140</gadget>
<output>320</output>
<gadget id="calculator">55 * 3</gadget>
<output>165</output>
<gadget id="calculator">320 - 165</gadget>
<output>155</output>
<result>D</result> | D | 155 | A student scored an average of 55 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics? | {
"A": "86",
"B": "165",
"C": "76",
"D": "155",
"E": "26"
} | subtract(add(multiply(90, const_2), multiply(70, const_2)), multiply(55, 3)) | multiply(n2,const_2)|multiply(n3,const_2)|multiply(n0,n1)|add(#0,#1)|subtract(#3,#2)| | "given m + p + c = 55 * 3 = 165 - - - ( 1 ) m + p = 90 * 2 = 180 - - - ( 2 ) p + c = 70 * 2 = 140 - - - ( 3 ) where m , p and c are marks obtained by the student in mathematics , physics and chemistry . p = ( 2 ) + ( 3 ) - ( 1 ) = 180 + 140 - 165 = 155 answer : d" | general |
math_qa__mIzrAneL3Ii1GhFC | If x/y=4 and y is not '0' what % of x is 2x-y Choose one
A) 150 % B) 175 percent C) 200 % D) 250 % E) 350 % | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">7 * 25</gadget>
<output>175</output>
<result>B</result> | B | 175 | If x/y=4 and y is not '0' what % of x is 2x-y | {
"A": "150 %",
"B": "175 percent",
"C": "200 %",
"D": "250 %",
"E": "350 %"
} | multiply(add(add(4, const_1), 2), multiply(add(4, const_1), add(4, const_1))) | add(n0,const_1)|add(n2,#0)|multiply(#0,#0)|multiply(#1,#2) | let z be the percentt x * z / 100 = 2 x - y zx = 7 y * 100 z = 700 y / 4 y z = 350 / 2 z = 175 % answer : b | general |
math_qa__8qze976aSvSP9M5P | Find the principle on a certain sum of money at 11% per annum for 2 2/5 years if the amount being Rs.1120? Pick
A) 1000 B) 812.88 C) 827.78 D) 826.82 E) 886.08 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 5</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 11</gadget>
<output>132/5 = around 26.4</output>
<gadget id="calculator">(132/5) / 100</gadget>
<output>33/125 = around 0.264</output>
<gadget id="calculator">(33/125) + 1</gadget>
<output>158/125 = around 1.264</output>
<gadget id="calculator">1_120 / (158/125)</gadget>
<output>70_000/79 = around 886.075949</output>
<result>E</result> | E | 886.08 | Find the principle on a certain sum of money at 11% per annum for 2 2/5 years if the amount being Rs.1120? | {
"A": "1000",
"B": "812.88",
"C": "827.78",
"D": "826.82",
"E": "886.08"
} | divide(1120, add(divide(multiply(divide(add(multiply(2, 5), 2), 5), 11), const_100), const_1)) | multiply(n1,n3)|add(n1,#0)|divide(#1,n3)|multiply(n0,#2)|divide(#3,const_100)|add(#4,const_1)|divide(n4,#5)| | "1120 = p [ 1 + ( 5 * 12 / 5 ) / 100 ] p = 886.08 answer : e" | general |
math_qa__QLLigA7SuIpcec6b | A bowl was filled with 10 ounces of water, and 0.006 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period? Choose the correct choice from the following options: A) 0.004 % B) 0.04 % C) 0.40 % D) 3 % E) 40 % | <gadget id="calculator">50 * 0.006</gadget>
<output>0.3</output>
<gadget id="calculator">0.3 / 10</gadget>
<output>0.03</output>
<gadget id="calculator">0.03 * 100</gadget>
<output>3</output>
<result>D</result> | D | 3 | A bowl was filled with 10 ounces of water, and 0.006 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period? | {
"A": "0.004 %",
"B": "0.04 %",
"C": "0.40 %",
"D": "3 %",
"E": "40 %"
} | multiply(divide(multiply(50, 0.006), 10), const_100) | multiply(n1,n2)|divide(#0,n0)|multiply(#1,const_100)| | "total amount of water evaporated each day during a 50 - day period = . 006 * 50 = . 006 * 100 / 2 = . 6 / 2 = . 3 percent of the original amount of water evaporated during this period = ( . 3 / 10 ) * 100 % = 3 % answer d" | gain |
math_qa__dKINy3oCvcTwydvp | A number x is multiplied by 7, and this product is then divided by 5. If the positive square root of the result of these two operations equals x, what is the value of x if x≠0 ? Choose one.
A) 25 / 9 B) 9 / 5 C) 5 / 3 D) 7 / 5 E) 9 / 25 | <gadget id="calculator">7 / 5</gadget>
<output>7/5 = around 1.4</output>
<result>D</result> | D | 1.4 | A number x is multiplied by 7, and this product is then divided by 5. If the positive square root of the result of these two operations equals x, what is the value of x if x≠0 ? | {
"A": "25 / 9",
"B": "9 / 5",
"C": "5 / 3",
"D": "7 / 5",
"E": "9 / 25"
} | divide(7, 5) | divide(n0,n1) | sqrt ( 7 x / 5 ) to be perfect square x has to 7 / 5 ans : d | general |
math_qa__6sHyRxcLBlWn6lpu | In a games hour 4 different types of players came to the ground? cricket 10, hokey 12, football 16, softball 13. How many players are present in the ground?
Choose the correct option
A) 70
B) 52
C) 51
D) 49
E) 50 | <gadget id="calculator">10 + 12</gadget>
<output>22</output>
<gadget id="calculator">16 + 13</gadget>
<output>29</output>
<gadget id="calculator">22 + 29</gadget>
<output>51</output>
<result>C</result> | C | 51 | In a games hour 4 different types of players came to the ground? cricket 10, hokey 12, football 16, softball 13. How many players are present in the ground? | {
"A": "70",
"B": "52",
"C": "51",
"D": "49",
"E": "50"
} | add(add(10, 12), add(16, 13)) | add(n1,n2)|add(n3,n4)|add(#0,#1) | total number of players = 10 + 12 + 16 + 13 = 51 answer is c | physics |
math_qa__8xJJmUWNKJh1L3aZ | In 2 bags, there are to be put together 5 red and 12 white balls, neither bag being empty. How must the balls be divided so as to give a person who draws 1 ball from either bag- Pick one.
A) 9 / 18 B) 9 / 16 C) 9 / 11 D) 9 / 12 E) 9 / 13 | <gadget id="calculator">5 + 12</gadget>
<output>17</output>
<gadget id="calculator">17 - 1</gadget>
<output>16</output>
<gadget id="calculator">5 / 16</gadget>
<output>5/16 = around 0.3125</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 / 16</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(5/16) + (1/4)</gadget>
<output>9/16 = around 0.5625</output>
<result>B</result> | B | 0.5625 | In 2 bags, there are to be put together 5 red and 12 white balls, neither bag being empty. How must the balls be divided so as to give a person who draws 1 ball from either bag- | {
"A": "9 / 18",
"B": "9 / 16",
"C": "9 / 11",
"D": "9 / 12",
"E": "9 / 13"
} | add(divide(5, subtract(add(5, 12), 1)), divide(multiply(2, 2), subtract(add(5, 12), 1))) | add(n1,n2)|multiply(n0,n0)|subtract(#0,n3)|divide(n1,#2)|divide(#1,#2)|add(#3,#4) | ( 1 ) put 1 white in first bag , and all the remaining ball in second bag . probability = 12 × 0 + 12 × 51612 × 0 + 12 × 516 = 532532 ( 2 ) to maximize , we put 1 red in the first bag , and all the remaining in the second . probability = 12 × 1 + 12 × 43212 × 1 + 12 × 432 = 9 / 16 answer : b | general |
math_qa__xIfVCxbCl1WErUsg | Sandy leaves her home and walks toward Ed's house. Two hours later, Ed leaves his home and walks toward Sandy's house. The distance between their homes is 52 kilometers, Sandy's walking speed is 6 km/h, and Ed's walking speed is 4 km/h. How many kilometers will Sandy walk before she meets Ed? Select
A) 33 B) 34 C) 35 D) 36 E) 37 | <gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">52 - 12</gadget>
<output>40</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">40 / 10</gadget>
<output>4</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<result>D</result> | D | 36 | Sandy leaves her home and walks toward Ed's house. Two hours later, Ed leaves his home and walks toward Sandy's house. The distance between their homes is 52 kilometers, Sandy's walking speed is 6 km/h, and Ed's walking speed is 4 km/h. How many kilometers will Sandy walk before she meets Ed? | {
"A": "33",
"B": "34",
"C": "35",
"D": "36",
"E": "37"
} | add(multiply(divide(subtract(52, multiply(const_2, 6)), add(6, 4)), 6), multiply(const_2, 6)) | add(n1,n2)|multiply(n1,const_2)|subtract(n0,#1)|divide(#2,#0)|multiply(n1,#3)|add(#4,#1) | sandy walks 12 km in the first two hours so there are 40 km remaining . when ed starts walking , they complete a total of 10 km per hour . they will meet four hours after ed starts walking . since sandy walks for 6 hours , she walks 36 km . the answer is d . | physics |
math_qa__WalkWktfmnihIMv0 | Two bullet train s 140 m and 190 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is: Options
A) 15.8 sec . B) 12.8 sec . C) 11.88 sec . D) 10.8 sec . E) 08.8 sec . | <gadget id="calculator">140 + 190</gadget>
<output>330</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">330 / (250/9)</gadget>
<output>297/25 = around 11.88</output>
<result>C</result> | C | 11.88 | Two bullet train s 140 m and 190 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is: | {
"A": "15.8 sec .",
"B": "12.8 sec .",
"C": "11.88 sec .",
"D": "10.8 sec .",
"E": "08.8 sec ."
} | divide(add(140, 190), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = ( 60 + 40 ) km / hr = 100 x 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = ( 140 + 190 ) m = 330 m . required time = 330 x 9 / 250 = 54 / 5 = 11.88 sec . answer c" | physics |
math_qa__ErNgUESn1SulxOFb | The ratio between the number of sheep and the number of horses at the Stewart farm is 4 to 7, If each horse is fed 230 ounces of horse food per day and the farm needs a total 12,880 ounces of horse food per day, what is the number of sheep in the farm? Choose the correct option.
A) 18 B) 28 C) 32 D) 56 E) 60 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 10</gadget>
<output>80</output>
<gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">80 + 800</gadget>
<output>880</output>
<gadget id="calculator">12 * 1_000</gadget>
<output>12_000</output>
<gadget id="calculator">880 + 12_000</gadget>
<output>12_880</output>
<gadget id="calculator">12_880 / 230</gadget>
<output>56</output>
<gadget id="calculator">56 / 7</gadget>
<output>8</output>
<gadget id="calculator">8 * 4</gadget>
<output>32</output>
<result>C</result> | C | 32 | The ratio between the number of sheep and the number of horses at the Stewart farm is 4 to 7, If each horse is fed 230 ounces of horse food per day and the farm needs a total 12,880 ounces of horse food per day, what is the number of sheep in the farm? | {
"A": "18",
"B": "28",
"C": "32",
"D": "56",
"E": "60"
} | multiply(divide(divide(add(add(multiply(multiply(const_4, const_2), const_10), multiply(multiply(const_4, const_2), const_100)), multiply(const_12, const_1000)), 230), 7), 4) | multiply(const_2,const_4)|multiply(const_1000,const_12)|multiply(#0,const_10)|multiply(#0,const_100)|add(#2,#3)|add(#4,#1)|divide(#5,n2)|divide(#6,n1)|multiply(n0,#7)| | "actual number of horses = 12,880 / 230 ( hold it since it is a harder calculation ) ratio multiplier = 1288 / ( 23 * 7 ) actual number of sheep = 1288 / ( 23 * 7 ) * 4 . first divide 1288 by 7 to get : 184 * 4 / 23 use the last digit to figure out that 23 will go 8 times into 184 . confirm . 8 * 4 = 32 answer ( c )" | other |
math_qa__oM59KjfEQ4MWiQjR | There are 8 books on a shelf, of which 2 are paperbacks and 6 are hardbacks. How many possible selections of 3 books from this shelf include at least one paperback? Choose the correct answer: A) 40 B) 45 C) 36 D) 55 E) 60 | <gadget id="calculator">binomial(8, 3)</gadget>
<output>56</output>
<gadget id="calculator">binomial(6, 3)</gadget>
<output>20</output>
<gadget id="calculator">56 - 20</gadget>
<output>36</output>
<result>C</result> | C | 36 | There are 8 books on a shelf, of which 2 are paperbacks and 6 are hardbacks. How many possible selections of 3 books from this shelf include at least one paperback? | {
"A": "40",
"B": "45",
"C": "36",
"D": "55",
"E": "60"
} | subtract(choose(8, 3), choose(6, 3)) | choose(n0,n3)|choose(n2,n3)|subtract(#0,#1)| | "approach 1 at - least 1 paper back = total - no paper back 8 c 3 - 6 c 3 = 36 approach 2 at - least 1 paper back = 1 paper back , 3 hard back or 2 paper back 2 hard back = 2 c 1 * 6 c 2 + 2 c 2 * 6 c 1 = 36 answer is c" | probability |
math_qa__megGypkB6kkYDvBF | The H.C.F. of two numbers is 10 and the other two factors of their L.C.M. are 11 and 15. The larger of the two numbers is:
Select
A) 150 B) 300 C) 299 D) 322 E) 345 | <gadget id="calculator">10 * 15</gadget>
<output>150</output>
<result>A</result> | A | 150 | The H.C.F. of two numbers is 10 and the other two factors of their L.C.M. are 11 and 15. The larger of the two numbers is: | {
"A": "150",
"B": "300",
"C": "299",
"D": "322",
"E": "345"
} | multiply(10, 15) | multiply(n0,n2)| | "the numbers are ( 10 x 11 ) and ( 10 x 15 ) . larger number = ( 10 x 15 ) = 150 . answer : a" | other |
math_qa__MvHBHNby0xxD8rin | A man can row upstream at 25 kmph and downstream at 35 kmph, and then find the speed of the man in still water? Select.
A) 22
B) 77
C) 30
D) 99
E) 12 | <gadget id="calculator">25 + 35</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>C</result> | C | 30 | A man can row upstream at 25 kmph and downstream at 35 kmph, and then find the speed of the man in still water? | {
"A": "22",
"B": "77",
"C": "30",
"D": "99",
"E": "12"
} | divide(add(25, 35), const_2) | add(n0,n1)|divide(#0,const_2)| | "us = 25 ds = 35 m = ( 35 + 25 ) / 2 = 30 answer : c" | physics |
math_qa__ynOChXtaqLa9mW5k | Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: Choose the correct option
A) 50 m B) 72 m C) 80 m D) 82 m E) 92 m | <gadget id="calculator">46 - 36</gadget>
<output>10</output>
<gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 3_600</gadget>
<output>25/9 = around 2.777778</output>
<gadget id="calculator">(25/9) * 36</gadget>
<output>100</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<result>A</result> | A | 50 | Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: | {
"A": "50 m",
"B": "72 m",
"C": "80 m",
"D": "82 m",
"E": "92 m"
} | divide(multiply(divide(multiply(subtract(46, 36), const_1000), const_3600), 36), const_2) | subtract(n0,n1)|multiply(#0,const_1000)|divide(#1,const_3600)|multiply(n2,#2)|divide(#3,const_2)| | "let the length of each train be x metres . then , distance covered = 2 x metres . relative speed = ( 46 - 36 ) km / hr = ( 10 x ( 5 / 18 ) m / sec = ( 25 / 9 ) m / sec ( 2 x / 36 ) = ( 25 / 9 ) 2 x = 100 x = 50 . a" | general |
math_qa__Bp6MxCxAnDKRfhf7 | If the area of a square with sides of length 12 centimeters is equal to the area of a rectangle with a width of 6 centimeters, what is the length of the rectangle, in centimeters? Select:
A) 4
B) 8
C) 12
D) 24
E) 18 | <gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">144 / 6</gadget>
<output>24</output>
<result>D</result> | D | 24 | If the area of a square with sides of length 12 centimeters is equal to the area of a rectangle with a width of 6 centimeters, what is the length of the rectangle, in centimeters? | {
"A": "4",
"B": "8",
"C": "12",
"D": "24",
"E": "18"
} | divide(power(12, const_2), 6) | power(n0,const_2)|divide(#0,n1)| | "let length of rectangle = l 12 ^ 2 = l * 4 = > l = 144 / 6 = 24 answer d" | geometry |
math_qa__kUBWnUTFkNFYrwLF | The average of first 20 even numbers is? Choose the correct choice:
A) 19 B) 18 C) 16 D) 11 E) 21 | <gadget id="calculator">20 + 1</gadget>
<output>21</output>
<result>E</result> | E | 21 | The average of first 20 even numbers is? | {
"A": "19",
"B": "18",
"C": "16",
"D": "11",
"E": "21"
} | add(20, const_1) | add(n0,const_1)| | "sum of 20 even numbers = 20 * 21 = 420 average = 420 / 20 = 21 answer : e" | general |
math_qa__zQYkRI3XzJNsPUsc | The difference between the two numbers is 1/3 of the larger number. If the smaller one is 48 the larger one is Choose the correct option: A) 72 B) 60 C) 32 D) 96 E) 65 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">48 / (2/3)</gadget>
<output>72</output>
<result>A</result> | A | 72 | The difference between the two numbers is 1/3 of the larger number. If the smaller one is 48 the larger one is | {
"A": "72",
"B": "60",
"C": "32",
"D": "96",
"E": "65"
} | divide(48, subtract(const_1, divide(1, 3))) | divide(n0,n1)|subtract(const_1,#0)|divide(n2,#1) | explanation : let the larger number be x . then , x - 48 = 1 / 3 x x - x / 3 = 48 = > 2 x / 3 = 48 = > x = 72 answer : option a | general |
math_qa__8piZuAqdmeBCKWL0 | At an examination in which full marks were 500. A got 10% less than B, B got 25% more than C and C got 20% less than D. If A got 360marks, what percentage of full marks was obtained by D?
Choose the correct choice from the following choices
A) 88 % B) 90 % C) 80 % D) 87 % E) 20 % | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(9/10) * (5/4)</gadget>
<output>9/8 = around 1.125</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(9/8) * (4/5)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">360 / (9/10)</gadget>
<output>400</output>
<gadget id="calculator">400 / 500</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 100</gadget>
<output>80</output>
<result>C</result> | C | 80 | At an examination in which full marks were 500. A got 10% less than B, B got 25% more than C and C got 20% less than D. If A got 360marks, what percentage of full marks was obtained by D? | {
"A": "88 %",
"B": "90 %",
"C": "80 %",
"D": "87 %",
"E": "20 %"
} | multiply(divide(divide(360, multiply(multiply(divide(subtract(const_100, 10), const_100), divide(add(const_100, 25), const_100)), divide(subtract(const_100, 20), const_100))), 500), const_100) | add(n2,const_100)|subtract(const_100,n3)|subtract(const_100,n1)|divide(#1,const_100)|divide(#2,const_100)|divide(#0,const_100)|multiply(#4,#5)|multiply(#3,#6)|divide(n4,#7)|divide(#8,n0)|multiply(#9,const_100) | a b c d 90 100 80 100 a d 90 - - - - - 100 360 - - - - - - ? = 400 500 - - - - - - 400 100 - - - - - - - ? = > 80 % answer : c | general |
math_qa__WmFP5WZHSeNyuBNI | a local restaurant recently renovated its dining space , purchasing new tables and chairs to use in addition to the original tables and chairs . the new tables each seat 6 customers , while the original tables each seat 4 customers . altogether , the restaurant now has 40 tables and is capable of seating 212 customers . how many more new tables than original tables does the restaurant have ? Select
A) 8 B) 12 C) 20 D) 24 E) 28 | <gadget id="calculator">6 * 40</gadget>
<output>240</output>
<gadget id="calculator">240 - 212</gadget>
<output>28</output>
<gadget id="calculator">6 - 4</gadget>
<output>2</output>
<gadget id="calculator">28 / 2</gadget>
<output>14</output>
<gadget id="calculator">40 - 14</gadget>
<output>26</output>
<gadget id="calculator">26 - 14</gadget>
<output>12</output>
<result>B</result> | B | 12 | a local restaurant recently renovated its dining space , purchasing new tables and chairs to use in addition to the original tables and chairs . the new tables each seat 6 customers , while the original tables each seat 4 customers . altogether , the restaurant now has 40 tables and is capable of seating 212 customers . how many more new tables than original tables does the restaurant have ? | {
"A": "8",
"B": "12",
"C": "20",
"D": "24",
"E": "28"
} | subtract(subtract(40, divide(subtract(multiply(6, 40), 212), subtract(6, 4))), divide(subtract(multiply(6, 40), 212), subtract(6, 4))) | multiply(n0,n2)|subtract(n0,n1)|subtract(#0,n3)|divide(#2,#1)|subtract(n2,#3)|subtract(#4,#3) | if all the tables seated 4 , the number of customers could be 4 * 40 = 160 . 212 - 160 = 52 , so 52 / 2 = 26 tables must be tables seating 6 people . the number of tables seating 4 people is 40 - 26 = 14 . the number of new tables is 26 - 14 = 12 more than the number of old tables . the answer is b . | general |
math_qa__Wa1i4DxwxCzjJuZd | A circle and a rectangle have the same perimeter. The sides of the rectangle are 18 cm and 26 cm. What is the area of the circle ? Answers
A) 88 cm 2 B) 154 cm 2 C) 1250 cm 2 D) 616 cm 2 E) none of these | <gadget id="calculator">26 + 18</gadget>
<output>44</output>
<gadget id="calculator">44 / pi</gadget>
<output>44/pi = around 14.005635</output>
<gadget id="calculator">pi * ((44/pi) ** 2)</gadget>
<output>1936/pi = around 616.24794</output>
<result>D</result> | D | 616 | A circle and a rectangle have the same perimeter. The sides of the rectangle are 18 cm and 26 cm. What is the area of the circle ? | {
"A": "88 cm 2",
"B": "154 cm 2",
"C": "1250 cm 2",
"D": "616 cm 2",
"E": "none of these"
} | circle_area(divide(add(26, 18), const_pi)) | add(n0,n1)|divide(#0,const_pi)|circle_area(#1) | perimeter of the circle = 2 π r = 2 ( 18 + 26 ) ⇒ 2 × 22 ⁄ 7 × r = 88 ⇒ r = 14 ∴ area of the circle = π r 2 = 22 ⁄ 7 × 14 × 14 = 616 cm 2 answer d | geometry |
math_qa__5iQ4tmXpX6OjDwIF | The product of the squares of two positive integers is 400. How many pairs of positive integers satisfy this condition?
Answers.
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<result>D</result> | D | 3 | The product of the squares of two positive integers is 400. How many pairs of positive integers satisfy this condition? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | subtract(add(const_2, const_3), const_2) | add(const_2,const_3)|subtract(#0,const_2) | first break down 200 into 20 * 20 and further into the prime factors 2 * 2 * 5 * 2 * 2 * 5 . now we are looking for all the possible pairs ( 2 numbers ) of squares whose product results in 400 . 1 st : 2 ^ 2 * 10 ^ 2 ( i . e . the first two 2 ' s and two times 2 * 5 = 10 ) 2 nd : 4 ^ 2 * 5 ^ 2 ( i . e . two times 2 * 2 = 4 = 4 ^ 2 and 5 ^ 2 ) . 3 rd : 1 ^ 2 * 20 ^ 2 ( i . e . two times 2 * 2 * 5 and 1 ^ 2 = 1 ) answer d . | geometry |
math_qa__GxBBbr2bU2AE7RTh | N and M are each 3-digit integers. Each of the numbers 2, 3,4, 6, 7, and 8 is a digit of either N or M. What is the smallest possible positive difference between N and M?
Choose the correct option:
A) 39 B) 49 C) 58 D) 113 E) 131 | <gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">40 - 1</gadget>
<output>39</output>
<result>A</result> | A | 39 | N and M are each 3-digit integers. Each of the numbers 2, 3,4, 6, 7, and 8 is a digit of either N or M. What is the smallest possible positive difference between N and M? | {
"A": "39",
"B": "49",
"C": "58",
"D": "113",
"E": "131"
} | subtract(subtract(const_100, multiply(subtract(8, 2), const_10)), const_1) | subtract(n5,n1)|multiply(#0,const_10)|subtract(const_100,#1)|subtract(#2,const_1) | you have 6 digits : 2 , 3 , 4 , 6 , 7 , 8 each digit needs to be used to make two 3 digit numbers . this means that we will use each of the digits only once and in only one of the numbers . the numbers need to be as close to each other as possible . the numbers can not be equal so the greater number needs to be as small as possible and the smaller number needs to be as large as possible to be close to each other . the first digit ( hundreds digit ) of both numbers should be consecutive integers now let ' s think about the next digit ( the tens digit ) . to minimize the difference between the numbers , the tens digit of the greater number should be as small as possible and the tens digit of the smaller number should be as large as possible . so let ' s not use 2 and 8 in the hundreds places and reserve them for the tens places . now what are the options ? try and make a pair with ( 3 * * and 4 * * ) . make the 3 * * number as large as possible and make the 4 * * number as small as possible . 387 and 426 ( difference is 39 ) or try and make a pair with ( 6 * * and 7 * * ) . make the 6 * * number as large as possible and make the 7 * * number as small as possible . we get 684 and 723 ( difference is 39 ) a | general |
math_qa__bMdcaykgAfzHSyN7 | From the beginning to the end of 2007, the price of a stock rose 20 percent. In 2008, it dropped 25 percent. In 2009, it rose 35 percent. What percent of the stock’s 2007 starting price was the price of the stock at the end of 2009? Choose the correct answer
A) 80 B) 90 C) 95 D) 121.5 E) 108 | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">100 * (6/5)</gadget>
<output>120</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">120 * (3/4)</gadget>
<output>90</output>
<gadget id="calculator">100 + 35</gadget>
<output>135</output>
<gadget id="calculator">135 / 100</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">90 * (27/20)</gadget>
<output>243/2 = around 121.5</output>
<result>D</result> | D | 121.5 | From the beginning to the end of 2007, the price of a stock rose 20 percent. In 2008, it dropped 25 percent. In 2009, it rose 35 percent. What percent of the stock’s 2007 starting price was the price of the stock at the end of 2009? | {
"A": "80",
"B": "90",
"C": "95",
"D": "121.5",
"E": "108"
} | multiply(multiply(multiply(const_100, divide(add(const_100, 20), const_100)), divide(subtract(const_100, 25), const_100)), divide(add(const_100, 35), const_100)) | add(n5,const_100)|add(n1,const_100)|subtract(const_100,n3)|divide(#0,const_100)|divide(#2,const_100)|divide(#1,const_100)|multiply(#5,const_100)|multiply(#4,#6)|multiply(#3,#7) | assume a value at the beginning of 2007 . as this is a % question , assume p = 100 . at the end of 2007 it becmae = 1.2 * 100 = 120 at the end of 2008 it decreased by 25 % = 120 * . 75 = 90 at the end of 2009 it increased by 35 % = 90 * 1.35 = 121.5 thus ratio = 121.5 / 100 = 1.215 ( in % terms = 121.5 % ) . thus d is the correct answer . | gain |
math_qa__xbBJe9SP6n2hlpoU | You enter a weight loss challenge game and manage to lose 15% of your body weight. For the final weigh in you are forced to wear clothes that add 2% to your weight. What percentage of weight loss is measured at the final weigh in? Choose the correct choice from the following choices
A) 13.3 % B) 9.22 % C) 9 % D) 14 % E) 12 % | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">2 / 100</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">1 + (1/50)</gadget>
<output>51/50 = around 1.02</output>
<gadget id="calculator">(17/20) * (51/50)</gadget>
<output>867/1_000 = around 0.867</output>
<gadget id="calculator">1 - (867/1_000)</gadget>
<output>133/1_000 = around 0.133</output>
<gadget id="calculator">(133/1_000) * 100</gadget>
<output>133/10 = around 13.3</output>
<result>A</result> | A | 13.3 | You enter a weight loss challenge game and manage to lose 15% of your body weight. For the final weigh in you are forced to wear clothes that add 2% to your weight. What percentage of weight loss is measured at the final weigh in? | {
"A": "13.3 %",
"B": "9.22 %",
"C": "9 %",
"D": "14 %",
"E": "12 %"
} | multiply(subtract(const_1, multiply(subtract(const_1, divide(15, const_100)), add(const_1, divide(2, const_100)))), const_100) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|subtract(const_1,#4)|multiply(#5,const_100)| | "( 100 % - 15 % ) * ( 100 % + 2 % ) = 0.85 * 1.02 = 13.3 % the weigh in records your weight loss at 13.3 % ! the answer is a" | gain |
math_qa__Haq8h8Z8kCg6GLBG | If the average (arithmetic mean) of (2a+16) and (3a-8) is 89, what is the value of a? Choose the correct choice: A) 25 B) 30 C) 28 D) 34 E) 42 | <gadget id="calculator">89 * 2</gadget>
<output>178</output>
<gadget id="calculator">16 - 8</gadget>
<output>8</output>
<gadget id="calculator">178 - 8</gadget>
<output>170</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">170 / 5</gadget>
<output>34</output>
<result>D</result> | D | 34 | If the average (arithmetic mean) of (2a+16) and (3a-8) is 89, what is the value of a? | {
"A": "25",
"B": "30",
"C": "28",
"D": "34",
"E": "42"
} | divide(subtract(multiply(89, 2), subtract(16, 8)), add(2, 3)) | add(n0,n2)|multiply(n0,n4)|subtract(n1,n3)|subtract(#1,#2)|divide(#3,#0)| | "( ( 2 a + 16 ) + ( 3 a - 8 ) ) / 2 = ( 5 a + 8 ) / 2 = 89 a = 34 the answer is d ." | general |
math_qa__JcBwYzD7MT6sBI4H | if x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year , the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $ 92 . if $ 2000 is the total amount invested , how much is invested at 8 percent ?
Choices:
A) $ 600 B) $ 700 C) $ 800 D) $ 900 E) $ 1000 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 2_000</gadget>
<output>200</output>
<gadget id="calculator">200 - 92</gadget>
<output>108</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(2/25) + (1/10)</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">108 / (9/50)</gadget>
<output>600</output>
<result>A</result> | A | 600 | if x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year , the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $ 92 . if $ 2000 is the total amount invested , how much is invested at 8 percent ? | {
"A": "$ 600",
"B": "$ 700",
"C": "$ 800",
"D": "$ 900",
"E": "$ 1000"
} | divide(subtract(multiply(divide(10, const_100), 2000), 92), add(divide(8, const_100), divide(10, const_100))) | divide(n0,const_100)|divide(n1,const_100)|add(#1,#0)|multiply(n5,#0)|subtract(#3,n4)|divide(#4,#2) | 0.1 x = 0.08 ( 2000 - x ) + 92 0.18 x = 252 x = 1400 then the amount invested at 8 % is $ 2000 - $ 1400 = $ 600 the answer is a . | general |
math_qa__XR6gLBOCYKKcUL0S | A man’s wages were decreased by 50%. Again, the reduced wages were increased by 50%. He has a loss of? Answers: A) 35 % B) 25 % C) 20 % D) 30 % E) none of these | <gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">150 / 100</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 50</gadget>
<output>75</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<result>B</result> | B | 25 | A man’s wages were decreased by 50%. Again, the reduced wages were increased by 50%. He has a loss of? | {
"A": "35 %",
"B": "25 %",
"C": "20 %",
"D": "30 %",
"E": "none of these"
} | subtract(const_100, multiply(divide(add(const_100, 50), const_100), 50)) | add(n0,const_100)|divide(#0,const_100)|multiply(n0,#1)|subtract(const_100,#2) | here , x = - 50 and y = 50 therefore , the net % change in value = ( x + y + xy / 100 ) % = [ - 50 + 50 + ( - 50 x 50 ) / 100 ] % or - 25 % since the sign is negative , there is loss of 25 % answer : b | gain |
math_qa__ZNIQ7nOAzrFguOPc | A cubical block of metal weighs 7 pounds. How much will another cube of the same metal weigh if its sides are twice as long? Pick one
A) 48 B) 32 C) 24 D) 56 E) 12 | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">7 * 8</gadget>
<output>56</output>
<result>D</result> | D | 56 | A cubical block of metal weighs 7 pounds. How much will another cube of the same metal weigh if its sides are twice as long? | {
"A": "48",
"B": "32",
"C": "24",
"D": "56",
"E": "12"
} | multiply(7, multiply(const_2, const_4)) | multiply(const_2,const_4)|multiply(n0,#0)| | "for example our cube have a side 1 meter , so we have 1 cubical meter in this cube and this cubical meter weigth 7 pounds if we take cube with side 2 meters we will have 8 cubical meters in this cube 8 meters * 7 pounds = 56 pounds so answer is d and similar but more theoretical approach : if we have sides a and b than they have equal ration with their areas : a / b = a ^ 2 / b ^ 2 and they have equal ration with their volumes : a / b = a ^ 3 / b ^ 3 we have two sides 1 / 2 so their volume will be in ratio 1 / 8 weight of one cube * volume of another cube 7 * 8 = 56 so answer is d" | geometry |
math_qa__LXoOUgv2Zcp4QCAk | Two cubes of their volumes in the ratio 8 : 125. The ratio of their surface area is:
Choose the correct choice from the following: A) 1.5 : 5 B) 2 : 5 C) 3 : 5 D) 1 : 5 E) 4 : 5 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">8 ** (1/3)</gadget>
<output>2</output>
<gadget id="calculator">125 ** (1/3)</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<result>B</result> | B | 0.4 | Two cubes of their volumes in the ratio 8 : 125. The ratio of their surface area is: | {
"A": "1.5 : 5",
"B": "2 : 5",
"C": "3 : 5",
"D": "1 : 5",
"E": "4 : 5"
} | divide(power(8, const_0_33), power(125, const_0_33)) | power(n0,const_0_33)|power(n1,const_0_33)|divide(#0,#1) | the ratio of their surface area is 8 : 125 2 : 5 answer is b . | geometry |
math_qa__WGSCDTkeUwcYdmYl | Find the compound ratio of (4:3), (1:3) and (2:3) is
Choose the correct choice from the following.
A) 16 : 27 B) 12 : 13 C) 13 : 14 D) 14 : 15 E) 31 : 27 | <gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(4/3) * (1/3)</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">(4/3) * (4/9)</gadget>
<output>16/27 = around 0.592593</output>
<result>A</result> | A | 0.592593 | Find the compound ratio of (4:3), (1:3) and (2:3) is | {
"A": "16 : 27",
"B": "12 : 13",
"C": "13 : 14",
"D": "14 : 15",
"E": "31 : 27"
} | multiply(divide(4, 3), multiply(divide(4, 3), divide(1, 3))) | divide(n0,n1)|divide(n2,n1)|multiply(#0,#1)|multiply(#0,#2) | required ratio = 4 / 3 * 1 / 3 * 2 / 3 = 16 / 27 = 16 : 27 answer is a | other |
math_qa__663ReIq7Gfk79ZV7 | A train traveling at 72 kmph crosses a platform in 30 seconds and a man standing on the platform in 19 seconds. What is the length of the platform in meters?
Choose the correct choice from the following options.
A) 220 meters B) 360 meters C) 420 meters D) 600 meters E) can not be determined | <gadget id="calculator">72 * 1_000</gadget>
<output>72_000</output>
<gadget id="calculator">72_000 / 3_600</gadget>
<output>20</output>
<gadget id="calculator">20 * 30</gadget>
<output>600</output>
<gadget id="calculator">20 * 19</gadget>
<output>380</output>
<gadget id="calculator">600 - 380</gadget>
<output>220</output>
<result>A</result> | A | 220 | A train traveling at 72 kmph crosses a platform in 30 seconds and a man standing on the platform in 19 seconds. What is the length of the platform in meters? | {
"A": "220 meters",
"B": "360 meters",
"C": "420 meters",
"D": "600 meters",
"E": "can not be determined"
} | subtract(multiply(divide(multiply(72, const_1000), const_3600), 30), multiply(divide(multiply(72, const_1000), const_3600), 19)) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)|multiply(n2,#1)|subtract(#2,#3)| | "speed of the train in metres / sec = 72000 / 3600 = 20 distance travelled by train to cross the platform = 30 * 20 = 600 = length of train + length of platform distance travelled by train to cross the man = 19 * 20 = 380 = length of train length of platform = 600 - 380 = 220 answer : a" | physics |
math_qa__f2ZFYOywt6X9kbB2 | An escalator moves towards the top level at the rate of 11 ft.sec and its length is 140 feet. If a person walks on the moving escalator at the rate of 3 feet per second towards the top level, how much time does he take to cover the entire length. Choose the correct choice from the following options: A) 14 sec B) 10 sec C) 12 sec D) 8 sec E) 5 sec | <gadget id="calculator">11 + 3</gadget>
<output>14</output>
<gadget id="calculator">140 / 14</gadget>
<output>10</output>
<result>B</result> | B | 10 | An escalator moves towards the top level at the rate of 11 ft.sec and its length is 140 feet. If a person walks on the moving escalator at the rate of 3 feet per second towards the top level, how much time does he take to cover the entire length. | {
"A": "14 sec",
"B": "10 sec",
"C": "12 sec",
"D": "8 sec",
"E": "5 sec"
} | divide(140, add(11, 3)) | add(n0,n2)|divide(n1,#0) | explanation : time taken to cover the entire length = tot . dist / resultant speed = 140 / ( 11 + 3 ) = 10 sec answer : b | gain |
math_qa__HPVDufoEth7A8P05 | For how many unique pairs of nonnegative integers {a, b} is the equation a^2 - b^2 = 25 true? Choose one: A) 1 B) 3 C) 5 D) 2 E) 9 | <gadget id="calculator">log(25)</gadget>
<output>log(25) = around 3.218876</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">log(5)</gadget>
<output>log(5) = around 1.609438</output>
<gadget id="calculator">log(25) / log(5)</gadget>
<output>log(25)/log(5) = around 2</output>
<result>D</result> | D | 2 | For how many unique pairs of nonnegative integers {a, b} is the equation a^2 - b^2 = 25 true? | {
"A": "1",
"B": "3",
"C": "5",
"D": "2",
"E": "9"
} | divide(log(25), log(add(const_4, const_1))) | add(const_1,const_4)|log(n2)|log(#0)|divide(#1,#2) | answer d ( a + b ) ( a - b ) = 25 5 cases for ( a + b ) , ( a - b ) 25 , 1 5 , 5 answer d | general |
math_qa__CXxb8ys2FkMuROEL | Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 8, while all other numbers remain the same, what is the new average of Set S?
Select the correct option:
A) 6.6 B) 6.7 C) 6.8 D) 7.0 E) 6.9 | <gadget id="calculator">10 * 6.2</gadget>
<output>62</output>
<gadget id="calculator">62 + 8</gadget>
<output>70</output>
<gadget id="calculator">70 / 10</gadget>
<output>7</output>
<result>D</result> | D | 7 | Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 8, while all other numbers remain the same, what is the new average of Set S? | {
"A": "6.6",
"B": "6.7",
"C": "6.8",
"D": "7.0",
"E": "6.9"
} | divide(add(multiply(10, 6.2), 8), 10) | multiply(n0,n1)|add(n2,#0)|divide(#1,n0) | old set s - total is avg * no of elements = 6.2 * 10 = 62 if one number is increased by 8 then total increased to 62 + 8 = 70 new avg - 70 / 10 = 7.0 . hence answer is d . | general |
math_qa__xnQf8djC7KI63idf | 14 men can complete a piece of work in 32 days. In how many days can 16 men complete that piece of work? Select the correct option
A) 23
B) 27 3 / 4
C) 20 1 / 2
D) 27 1 / 2
E) 11 | <gadget id="calculator">32 * 14</gadget>
<output>448</output>
<gadget id="calculator">448 / 16</gadget>
<output>28</output>
<result>D</result> | D | 27 | 14 men can complete a piece of work in 32 days. In how many days can 16 men complete that piece of work? | {
"A": "23",
"B": "27 3 / 4",
"C": "20 1 / 2",
"D": "27 1 / 2",
"E": "11"
} | divide(multiply(32, 14), 16) | multiply(n0,n1)|divide(#0,n2)| | "14 * 32 = 16 * x = > x = 27 1 / 2 days answer : d" | physics |
math_qa__lteDhVtvrbCr8zfG | The angle of elevation of a ladder leaning against a wall is 60° and the foot of the ladder is 4.6 m away from the wall. The length of the ladder is
Choose the correct choice from the following choices: A) 2.3 m B) 4.6 m C) 7.8 m D) 9.2 m E) none | <gadget id="calculator">4.6 * 2</gadget>
<output>9.2</output>
<result>D</result> | D | 9.2 | The angle of elevation of a ladder leaning against a wall is 60° and the foot of the ladder is 4.6 m away from the wall. The length of the ladder is | {
"A": "2.3 m",
"B": "4.6 m",
"C": "7.8 m",
"D": "9.2 m",
"E": "none"
} | multiply(4.6, const_2) | multiply(n1,const_2) | solution let ab be the wall and bc be the ladder . then , < abc = 60 ° ac = 4.6 m . ; ac / bc = cos 60 ° = 1 / 2 ‹ = › bc = 2 × ac = ( 2 × 4.6 ) m = 9.2 m answer d | physics |
math_qa__vLHIRbBvxFYuxZkU | In a certain egg-processing plant, every egg must be inspected, and is either accepted for processing or rejected. For every 96 eggs accepted for processing, 4 eggs are rejected. If, on a particular day, 12 additional eggs were accepted, but the overall number of eggs inspected remained the same, the ratio of those accepted to those rejected would be 99 to 1. How many T eggs does the plant process per day? Choose the correct choice from the following choices: A) 100 B) 300 C) 400 D) 3,000 E) 4,000 | <gadget id="calculator">99 - 96</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<result>C</result> | C | 400 | In a certain egg-processing plant, every egg must be inspected, and is either accepted for processing or rejected. For every 96 eggs accepted for processing, 4 eggs are rejected. If, on a particular day, 12 additional eggs were accepted, but the overall number of eggs inspected remained the same, the ratio of those accepted to those rejected would be 99 to 1. How many T eggs does the plant process per day? | {
"A": "100",
"B": "300",
"C": "400",
"D": "3,000",
"E": "4,000"
} | multiply(divide(12, subtract(99, 96)), const_100) | subtract(n3,n0)|divide(n2,#0)|multiply(#1,const_100)| | "straight pluggin in for me . as usual , i started with c and got the answer . lets ' back calculate and see what we get let us consider eggs processed each day to be 400 so initial ratio of eggs processed and rejected is 96 : 4 or 24 : 1 so out of 400 eggs , there will be 384 eggs processed and 16 rejected . now if the no . of eggs inspected remain and 12 more eggs get accepted that means there t = 384 + 12 = 396 eggs accepted and 4 rejected . . . and the ratio will be 99 : 1 bingo . . . this is what the questions says . . . . its always a good idea to start with c ." | general |
math_qa__MGe98lHbpEYCzPPh | The sale price sarees listed for Rs.510 after successive discount is 12% and 15% is? Choose the correct answer.
A) 298 B) 237 C) 342 D) 381 E) 291 | <gadget id="calculator">510 * 12</gadget>
<output>6_120</output>
<gadget id="calculator">6_120 / 100</gadget>
<output>306/5 = around 61.2</output>
<gadget id="calculator">510 - (306/5)</gadget>
<output>2_244/5 = around 448.8</output>
<gadget id="calculator">(2_244/5) * 15</gadget>
<output>6_732</output>
<gadget id="calculator">6_732 / 100</gadget>
<output>1_683/25 = around 67.32</output>
<gadget id="calculator">(2_244/5) - (1_683/25)</gadget>
<output>9_537/25 = around 381.48</output>
<result>D</result> | D | 381 | The sale price sarees listed for Rs.510 after successive discount is 12% and 15% is? | {
"A": "298",
"B": "237",
"C": "342",
"D": "381",
"E": "291"
} | subtract(subtract(510, divide(multiply(510, 12), const_100)), divide(multiply(subtract(510, divide(multiply(510, 12), const_100)), 15), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4) | 510 * ( 88 / 100 ) * ( 85 / 100 ) = 381 answer : d | gain |
math_qa__Od6sL8Za6SS0oqmm | The interest on a certain deposit at 4.5% p.a. is Rs. 202.50 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a.? Choose the correct choice.
A) rs . 20.25 B) rs . 22.50 C) rs . 25 D) rs . 42.75 E) none | <gadget id="calculator">4.5 / 100</gadget>
<output>0.045</output>
<gadget id="calculator">202.5 / 0.045</gadget>
<output>4_500</output>
<gadget id="calculator">4_500 * 5</gadget>
<output>22_500</output>
<gadget id="calculator">22_500 / 100</gadget>
<output>225</output>
<gadget id="calculator">225 - 202.5</gadget>
<output>22.5</output>
<result>B</result> | B | 22.5 | The interest on a certain deposit at 4.5% p.a. is Rs. 202.50 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a.? | {
"A": "rs . 20.25",
"B": "rs . 22.50",
"C": "rs . 25",
"D": "rs . 42.75",
"E": "none"
} | subtract(divide(multiply(divide(202.50, divide(4.5, const_100)), 5), const_100), 202.50) | divide(n0,const_100)|divide(n1,#0)|multiply(n2,#1)|divide(#2,const_100)|subtract(#3,n1)| | "solution s . i . = rs . 202.50 , r = 4.5 % , t = 1 year . principal = rs . ( 100 x 202.50 / 4.5 x 1 ) = rs . 4500 . now , p = rs . 4500 , r = 5 % , t = 1 year . s . i . = rs . ( 4500 x 5 x 1 / 1000 = rs . 225 . ∴ difference in interest = rs . ( 225 - 202.50 ) = rs . 22.50 . answer b" | gain |
math_qa__jX2T4N3dGkYXV1ET | If a(a - 4) = 12 and b(b -4) = 12, where a ≠ b, then a + b =
Choose the correct choice from the following answers: A) − 48 B) − 5 C) 4 D) 46 E) 48 | <gadget id="calculator">4 + 12</gadget>
<output>16</output>
<gadget id="calculator">4 - 12</gadget>
<output>-8</output>
<gadget id="calculator">16 + (-8)</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<result>C</result> | C | 4 | If a(a - 4) = 12 and b(b -4) = 12, where a ≠ b, then a + b = | {
"A": "− 48",
"B": "− 5",
"C": "4",
"D": "46",
"E": "48"
} | subtract(subtract(subtract(subtract(add(add(4, 12), subtract(4, 12)), const_1), const_1), const_1), const_1) | add(n0,n1)|subtract(n0,n1)|add(#0,#1)|subtract(#2,const_1)|subtract(#3,const_1)|subtract(#4,const_1)|subtract(#5,const_1) | i . e . if a = 6 then b = - 2 or if a = - 2 then b = 6 but in each case a + b = - 2 + 6 = 4 answer : option c | general |
math_qa__Mo0BOg9DWr5QGp9h | The price of commodity X increases by 45 cents every year, while the price of commodity Y increases by 20 cents every year. In 2001, the price of commodity X was $4.20 and the price of commodity Y was $6.30. In which year will the price of commodity X be 65 cents more than the price of commodity Y? Choose the correct option:
A) 2010 B) 2011 C) 2012 D) 2013 E) 2014 | <gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">6.3 - 4.2</gadget>
<output>2.1</output>
<gadget id="calculator">(13/20) + 2.1</gadget>
<output>2.75</output>
<gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">(9/20) - 2.1</gadget>
<output>-1.65</output>
<gadget id="calculator">2.75 / (-1.65)</gadget>
<output>-1.666667</output>
<gadget id="calculator">2_001 + (-1.666667)</gadget>
<output>1_999.333333</output>
<result>C</result> | C | 2,012 | The price of commodity X increases by 45 cents every year, while the price of commodity Y increases by 20 cents every year. In 2001, the price of commodity X was $4.20 and the price of commodity Y was $6.30. In which year will the price of commodity X be 65 cents more than the price of commodity Y? | {
"A": "2010",
"B": "2011",
"C": "2012",
"D": "2013",
"E": "2014"
} | add(2001, divide(add(divide(65, const_100), subtract(6.30, 4.20)), subtract(divide(45, const_100), subtract(6.30, 4.20)))) | divide(n5,const_100)|divide(n0,const_100)|subtract(n4,n3)|add(#0,#2)|subtract(#1,#2)|divide(#3,#4)|add(n2,#5)| | "the price of commodity x increases 25 cents each year relative to commodity y . the price difference is $ 2.10 and commodity x needs to be 65 cents more than commodity y . $ 2.75 / 25 cents = 11 years the answer is 2001 + 11 years = 2012 . the answer is c ." | general |
math_qa__82y8kgEAzkTIiHE3 | A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 3 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
Options: A) 229 B) 288 C) 600 D) 720 E) 121 | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">30 * 6</gadget>
<output>180</output>
<gadget id="calculator">40 - 30</gadget>
<output>10</output>
<gadget id="calculator">180 / 10</gadget>
<output>18</output>
<gadget id="calculator">18 * 40</gadget>
<output>720</output>
<result>D</result> | D | 720 | A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 3 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet? | {
"A": "229",
"B": "288",
"C": "600",
"D": "720",
"E": "121"
} | multiply(divide(multiply(30, add(const_3, 3)), subtract(40, 30)), 40) | add(n2,const_3)|subtract(n3,n1)|multiply(n1,#0)|divide(#2,#1)|multiply(n3,#3)| | "d = 30 * 6 = 180 rs = 40 – 30 = 10 t = 180 / 10 = 18 d = 40 * 18 = 720 km answer : d" | physics |
math_qa__HmmVKq3zm92dauIc | When a merchant imported a certain item, she paid a 7 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that the merchant paid was $112.70, what was the total value of the item?
Choices
A) $ 2420 B) $ 2610 C) $ 2860 D) $ 3050 E) $ 3270 | <gadget id="calculator">7 / 100</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">112.7 / (7/100)</gadget>
<output>1_610</output>
<gadget id="calculator">1_000 + 1_610</gadget>
<output>2_610</output>
<result>B</result> | B | 2,610 | When a merchant imported a certain item, she paid a 7 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that the merchant paid was $112.70, what was the total value of the item? | {
"A": "$ 2420",
"B": "$ 2610",
"C": "$ 2860",
"D": "$ 3050",
"E": "$ 3270"
} | add(1,000, divide(112.70, divide(7, const_100))) | divide(n0,const_100)|divide(n2,#0)|add(#1,n1)| | "let x be the value of the item . 0.07 * ( x - 1000 ) = 112.70 x = 2610 the answer is b ." | general |
math_qa__TlxecO1ozaFTU4Bl | Compound X contains elements A and B at an approximate ratio, by weight, of 2:10. Approximately how many grams of element B are there in 300 grams of compound X? Choose the correct answer
A) 54 B) 162 C) 250 D) 270 E) 322 | <gadget id="calculator">300 * 10</gadget>
<output>3_000</output>
<gadget id="calculator">2 + 10</gadget>
<output>12</output>
<gadget id="calculator">3_000 / 12</gadget>
<output>250</output>
<result>C</result> | C | 250 | Compound X contains elements A and B at an approximate ratio, by weight, of 2:10. Approximately how many grams of element B are there in 300 grams of compound X? | {
"A": "54",
"B": "162",
"C": "250",
"D": "270",
"E": "322"
} | divide(multiply(300, 10), add(2, 10)) | add(n0,n1)|multiply(n1,n2)|divide(#1,#0)| | "total number of fractions = 2 + 10 = 12 element b constitutes = 10 out of 12 parts of x so in 300 gms of x have 300 * 10 / 12 = 250 gms of b and 300 - 250 = 50 gms of a . cross check : - a / b = 50 / 250 = 2 / 10 ( as given ) ans c" | other |
math_qa__ZgNZhQxnM8npkwdX | Find the cost of fencing around a circular field of diameter 26 m at the rate of Rs.1.50 a meter? Pick one:
A) 122.55
B) 132
C) 156
D) 158
E) 267 | <gadget id="calculator">26 / 2</gadget>
<output>13</output>
<gadget id="calculator">2 * pi * 13</gadget>
<output>26*pi = around 81.681409</output>
<gadget id="calculator">(26*pi) * 1.5</gadget>
<output>39.0*pi = around 122.522113</output>
<result>A</result> | A | 122.55 | Find the cost of fencing around a circular field of diameter 26 m at the rate of Rs.1.50 a meter? | {
"A": "122.55",
"B": "132",
"C": "156",
"D": "158",
"E": "267"
} | multiply(circumface(divide(26, const_2)), 1.50) | divide(n0,const_2)|circumface(#0)|multiply(n1,#1)| | "2 * 22 / 7 * 13 = 81.7 81.7 * 1 1 / 2 = rs . 122.55 answer : a" | physics |
math_qa__8UXVDWxB5tIkOZEo | A can give B a start of 50 metres or 10 seconds in a kilometer race. How long does A take to complete the race? Choose the correct choice from the following answers.
A) 200 seconds
B) 140 seconds
C) 220 seconds
D) 190 seconds
E) none | <gadget id="calculator">10 / 50</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 1_000</gadget>
<output>200</output>
<gadget id="calculator">200 - 10</gadget>
<output>190</output>
<result>D</result> | D | 190 | A can give B a start of 50 metres or 10 seconds in a kilometer race. How long does A take to complete the race? | {
"A": "200 seconds",
"B": "140 seconds",
"C": "220 seconds",
"D": "190 seconds",
"E": "none"
} | subtract(multiply(divide(10, 50), const_1000), 10) | divide(n1,n0)|multiply(#0,const_1000)|subtract(#1,n1) | solution : a can give b a start of 50 metres or 10 seconds in a 1000 m race . that is , b takes 10 seconds to run 50 metres . therefore , b will take ( 10 / 50 ) * 1000 = 200 seconds to run 1000 metres . a who can give b a start of 10 seconds will take 10 seconds lesser to run the 1000 m . hence , the time taken by a = 190 seconds . answer d | physics |
math_qa__jbYtN1frHjRxos45 | Last year Sandy saved 6% of her annual salary. This year, she made 10% more money than last year, and she saved 10% of her salary. The amount saved this year was what percent of the amount she saved last year? Choose the most appropriate option:
A) 133 % B) 145 % C) 158 % D) 170 % E) 183 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">(1/10) * 110</gadget>
<output>11</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 / 100</gadget>
<output>6</output>
<gadget id="calculator">11 / 6</gadget>
<output>11/6 = around 1.833333</output>
<gadget id="calculator">(11/6) * 100</gadget>
<output>550/3 = around 183.333333</output>
<result>E</result> | E | 183 | Last year Sandy saved 6% of her annual salary. This year, she made 10% more money than last year, and she saved 10% of her salary. The amount saved this year was what percent of the amount she saved last year? | {
"A": "133 %",
"B": "145 %",
"C": "158 %",
"D": "170 %",
"E": "183 %"
} | multiply(divide(multiply(divide(10, const_100), add(const_100, 10)), divide(multiply(6, const_100), const_100)), const_100) | add(n1,const_100)|divide(n2,const_100)|multiply(n0,const_100)|divide(#2,const_100)|multiply(#0,#1)|divide(#4,#3)|multiply(#5,const_100)| | "let last year ' s salary be x . last year , sandy save 0.06 x this year , sandy saved 0.1 * 1.1 x = 0.11 x 0.11 x / 0.06 x = 11 / 6 = 1.83 = 183 % the answer is e ." | gain |
math_qa__58G83XfOf42E11Uo | If 10 litres of an oil of Rs.50 per litres be mixed with 5 litres of another oil of Rs.68 per litre then what is the rate of mixed oil per litre? Choose the correct choice.
A) rs . 49.17 B) rs . 51.03 C) rs . 56 D) rs . 55.33 E) none of the above | <gadget id="calculator">10 * 50</gadget>
<output>500</output>
<gadget id="calculator">5 * 68</gadget>
<output>340</output>
<gadget id="calculator">500 + 340</gadget>
<output>840</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">840 / 15</gadget>
<output>56</output>
<result>C</result> | C | 56 | If 10 litres of an oil of Rs.50 per litres be mixed with 5 litres of another oil of Rs.68 per litre then what is the rate of mixed oil per litre? | {
"A": "rs . 49.17",
"B": "rs . 51.03",
"C": "rs . 56",
"D": "rs . 55.33",
"E": "none of the above"
} | divide(add(multiply(10, 50), multiply(5, 68)), add(10, 5)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)| | "50 * 10 = 500 68 * 5 = 340 840 / 15 = 56 answer : c" | gain |
math_qa__7upSZ0MxdqRisqKw | A broker invested her own money in the stock market. During the first year, she increased her stock market wealth by 90 percent. In the second year, largely as a result of a slump in the stock market, she suffered a 50 percent decrease in the value of her stock investments. What was the net increase or decrease on her overall stock investment wealth by the end of the second year? Choose the correct choice from the following options:
A) − 5 %
B) 5 %
C) 15 %
D) 20 %
E) 80 % | <gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 + (9/10)</gadget>
<output>19/10 = around 1.9</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 - (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(19/10) * (1/2)</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(19/20) - 1</gadget>
<output>-1/20 = around -0.05</output>
<gadget id="calculator">(-1/20) * 100</gadget>
<output>-5</output>
<result>A</result> | A | -5 | A broker invested her own money in the stock market. During the first year, she increased her stock market wealth by 90 percent. In the second year, largely as a result of a slump in the stock market, she suffered a 50 percent decrease in the value of her stock investments. What was the net increase or decrease on her overall stock investment wealth by the end of the second year? | {
"A": "− 5 %",
"B": "5 %",
"C": "15 %",
"D": "20 %",
"E": "80 %"
} | multiply(subtract(multiply(add(const_1, divide(90, const_100)), subtract(const_1, divide(50, const_100))), const_1), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "the actual answer is obtained by multiplying 140 % by 70 % and subtracting 100 % from this total . that is : 190 % × 50 % = 95 % ; 95 % − 100 % = - 5 % . answer : a" | gain |
math_qa__QkniG7uUHgPMETxt | What least number should be added to 1056, so that the sum is completely divisible by 23
Choose the correct choice from the following answers:
A) 4
B) 1
C) 2
D) 3
E) 5 | <gadget id="calculator">1_056 % 23</gadget>
<output>21</output>
<gadget id="calculator">23 - 21</gadget>
<output>2</output>
<result>C</result> | C | 2 | What least number should be added to 1056, so that the sum is completely divisible by 23 | {
"A": "4",
"B": "1",
"C": "2",
"D": "3",
"E": "5"
} | subtract(23, reminder(1056, 23)) | reminder(n0,n1)|subtract(n1,#0)| | "explanation : ( 1056 / 23 ) gives remainder 21 21 + 2 = 23 , so we need to add 2 answer : option c" | general |
math_qa__kZcumoB42z8HN0VK | The average temperature for Tuesday, Wednesday and Thursday was 52°C. The average temperature for Wednesday, Thursday and Friday was 54°C. If the temperature on Friday be 53°C, what was the Temperature on Tuesday? Select:
A) 39 ° c
B) 44 ° c
C) 37 ° c
D) 47 ° c
E) none of these | <gadget id="calculator">52 * 3</gadget>
<output>156</output>
<gadget id="calculator">54 * 3</gadget>
<output>162</output>
<gadget id="calculator">162 - 53</gadget>
<output>109</output>
<gadget id="calculator">156 - 109</gadget>
<output>47</output>
<result>D</result> | D | 47 | The average temperature for Tuesday, Wednesday and Thursday was 52°C. The average temperature for Wednesday, Thursday and Friday was 54°C. If the temperature on Friday be 53°C, what was the Temperature on Tuesday? | {
"A": "39 ° c",
"B": "44 ° c",
"C": "37 ° c",
"D": "47 ° c",
"E": "none of these"
} | subtract(multiply(52, const_3), subtract(multiply(54, const_3), 53)) | multiply(n0,const_3)|multiply(n1,const_3)|subtract(#1,n2)|subtract(#0,#2) | explanation : t + w + t = 52 × 3 = 156 ° c w + t + f = 54 × 3 = 162 ° c also , temperature on friday = 53 ° c temperature on tuesday = 156 + 53 - 162 = 47 ° c answer : option d | physics |
math_qa__rqH3TfZe9C4jytWK | The smallest number which when diminished by 6, is divisible by 12, 16, 18, 21 and 28 is Choose the correct choice from the following choices:
A) 1008
B) 1014
C) 1022
D) 1032
E) 1043 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">9 * 16</gadget>
<output>144</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">144 * 7</gadget>
<output>1_008</output>
<gadget id="calculator">1_008 + 6</gadget>
<output>1_014</output>
<result>B</result> | B | 1,014 | The smallest number which when diminished by 6, is divisible by 12, 16, 18, 21 and 28 is | {
"A": "1008",
"B": "1014",
"C": "1022",
"D": "1032",
"E": "1043"
} | add(multiply(multiply(power(const_3, const_2.0), power(const_2.0, const_4)), add(const_3, const_4)), 6) | add(const_3,const_4)|power(const_3,const_2.0)|power(const_2.0,const_4)|multiply(#1,#2)|multiply(#0,#3)|add(#4,n0)| | "required number = ( l . c . m of 12 , 16 , 18 , 21,28 ) + 6 = 1008 + 6 = 1014 answer : b" | general |
math_qa__iMKlO0NIPw26ASHz | The true discount on a bill due 9 months hence at 16% per annum is Rs. 240. The amount of the bill is Choose the correct choice:
A) 2200
B) 2240
C) 1600
D) 1354
E) none of these | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 16</gadget>
<output>12</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">240 / (3/25)</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 + 240</gadget>
<output>2_240</output>
<result>B</result> | B | 2,240 | The true discount on a bill due 9 months hence at 16% per annum is Rs. 240. The amount of the bill is | {
"A": "2200",
"B": "2240",
"C": "1600",
"D": "1354",
"E": "none of these"
} | add(divide(240, divide(multiply(divide(9, multiply(const_4, const_3)), 16), const_100)), 240) | multiply(const_3,const_4)|divide(n0,#0)|multiply(n1,#1)|divide(#2,const_100)|divide(n2,#3)|add(n2,#4)| | "explanation : let p . w . be rs . x . then , s . i . on rs . x at 16 % for 9 months = rs . 240 . x ã — 16 ã — ( 9 / 12 ) ã — ( 1 / 100 ) = 240 or x = 2000 . p . w . = rs . 2000 . sum due = p . w . + t . d . = rs . ( 2000 240 ) = rs . 2240 . answer : b" | gain |
math_qa__7y5essEbjlFMmZ0X | Instead of multiplying a number by 3, the number is divided by 5. What is the percentage of error obtained ?
Select the correct option.
A) 92.33 % B) 91.33 % C) 95.33 % D) 93.33 % E) 94.33 % | <gadget id="calculator">5 / 5</gadget>
<output>1</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/15) * 100</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">100 - (20/3)</gadget>
<output>280/3 = around 93.333333</output>
<result>D</result> | D | 93.33 | Instead of multiplying a number by 3, the number is divided by 5. What is the percentage of error obtained ? | {
"A": "92.33 %",
"B": "91.33 %",
"C": "95.33 %",
"D": "93.33 %",
"E": "94.33 %"
} | subtract(const_100, multiply(divide(divide(5, 5), multiply(3, 5)), const_100)) | divide(n1,n1)|multiply(n0,n1)|divide(#0,#1)|multiply(#2,const_100)|subtract(const_100,#3)| | "let the number be x the right number is 3 x the wrong number is x / 5 error is ( 3 x - x / 5 ) = 14 x / 5 percentage of error is ( ( 14 x / 5 ) / 3 x ) * 100 = 93.33 % answer : d" | general |
math_qa__GJ0BJxR5Fse9ESVo | A man sold 18 toys for Rs. 23100, gaining thereby the cost price of 3 toy find the cost price of a toy Options.
A) s . 600
B) s . 800
C) s . 500
D) s . 900
E) s . 1100 | <gadget id="calculator">18 + 3</gadget>
<output>21</output>
<gadget id="calculator">23_100 / 21</gadget>
<output>1_100</output>
<result>E</result> | E | 1,100 | A man sold 18 toys for Rs. 23100, gaining thereby the cost price of 3 toy find the cost price of a toy | {
"A": "s . 600",
"B": "s . 800",
"C": "s . 500",
"D": "s . 900",
"E": "s . 1100"
} | divide(23100, add(18, 3)) | add(n0,n2)|divide(n1,#0)| | "let the cost of one toy = x . then , cost of 18 toys = 18 x . gain = 3 x . sp of 18 toys = rs . 23100 . gain = sp â € “ cp 3 x = 23100 â € “ 18 x 21 x = 23100 x = rs . 1100 . answer : option e" | gain |
math_qa__xhj7yzmjFnMJuy9Y | In an objective competitive exam, a correct answer score 4 marks and on a wrong answer 2 marks are negatively added. A student scores 420 marks from 150 question. How many answers were correct ? Choose the correct option: A) 150 B) 155 C) 140 D) 120 E) 165 | <gadget id="calculator">150 * 2</gadget>
<output>300</output>
<gadget id="calculator">300 + 420</gadget>
<output>720</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">720 / 6</gadget>
<output>120</output>
<result>D</result> | D | 120 | In an objective competitive exam, a correct answer score 4 marks and on a wrong answer 2 marks are negatively added. A student scores 420 marks from 150 question. How many answers were correct ? | {
"A": "150",
"B": "155",
"C": "140",
"D": "120",
"E": "165"
} | divide(add(multiply(150, const_2), 420), add(4, 2)) | add(n0,n1)|multiply(n3,const_2)|add(n2,#1)|divide(#2,#0) | let x be the correct answer and y be the wrong answer so the total number of questions is ( x + y ) = 150 . . . . . ( 1 ) = > 4 x - 2 y = 420 . . . . . ( 2 ) by solving ( 1 ) & ( 2 ) , we get = > 6 x = 720 hence x = 120 therefore , number of correct answers are 120 . answer d | general |
math_qa__qICqocAXY2qFWiNu | In a division, divident is 690, divisior is 36 and quotient is 19. Find the remainder.
Pick
A) 4 B) 3 C) 2 D) 5 E) 6 | <gadget id="calculator">690 % 36</gadget>
<output>6</output>
<result>E</result> | E | 6 | In a division, divident is 690, divisior is 36 and quotient is 19. Find the remainder. | {
"A": "4",
"B": "3",
"C": "2",
"D": "5",
"E": "6"
} | reminder(690, 36) | reminder(n0,n1)| | "explanation : 690 = 36 x 19 + r 690 = 684 + r r = 690 - 684 = 6 answer : option e" | general |
math_qa__N50v2MvT8M745qoJ | A car traveled 75% of the way from town A to town B at an average speed of 50 miles per hour. The car travels at an average speed of S miles per hour for the remaining part of the trip. The average speed for the entire trip was 50 miles per hour. What is S ? Select:
A) 10
B) 20
C) 25
D) 30
E) 50 | <gadget id="calculator">50 + 50</gadget>
<output>100</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">100 / 50</gadget>
<output>2</output>
<gadget id="calculator">75 / 50</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">2 - (3/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">25 / (1/2)</gadget>
<output>50</output>
<result>E</result> | E | 50 | A car traveled 75% of the way from town A to town B at an average speed of 50 miles per hour. The car travels at an average speed of S miles per hour for the remaining part of the trip. The average speed for the entire trip was 50 miles per hour. What is S ? | {
"A": "10",
"B": "20",
"C": "25",
"D": "30",
"E": "50"
} | divide(subtract(add(50, 50), 75), subtract(divide(add(50, 50), 50), divide(75, 50))) | add(n1,n2)|divide(n0,n1)|divide(#0,n2)|subtract(#0,n0)|subtract(#2,#1)|divide(#3,#4)| | "total distance = 100 miles ( easier to work with % ) 75 % of the distance = 75 miles 25 % of the distance = 25 miles 1 st part of the trip → 75 / 50 = 1.5 2 nd part of the trip → 25 / s = t total trip → ( 75 + 25 ) / 50 = 1.5 + t » 100 / 50 = 1.5 + t » 2 = 1.5 + t » t = 0.5 back to 2 nd part of the trip formula : 25 / s = 0.5 » s = 50 ans e" | physics |
math_qa__IlLAXECLg9QKFTfh | Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 30 km/hr. For how many minutes does the bus stop per hour? Choose the correct option:
A) 22
B) 30
C) 77
D) 20
E) 99 | <gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">30 / 60</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 60</gadget>
<output>30</output>
<gadget id="calculator">60 - 30</gadget>
<output>30</output>
<result>B</result> | B | 30 | Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 30 km/hr. For how many minutes does the bus stop per hour? | {
"A": "22",
"B": "30",
"C": "77",
"D": "20",
"E": "99"
} | subtract(multiply(const_1, const_60), multiply(divide(30, 60), const_60)) | divide(n1,n0)|multiply(const_1,const_60)|multiply(#0,const_60)|subtract(#1,#2)| | "in 1 hr , the bus covers 60 km without stoppages and 30 km with stoppages . stoppage time = time take to travel ( 60 - 30 ) km i . e 30 km at 60 km / hr . stoppage time = 30 / 60 hrs = 30 min . answer : b" | general |
math_qa__Jy2Cmn6HykvaPNHk | Indu gave Bindu Rs.6250 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
Choose the correct choice
A) 5 B) 2 C) 10 D) 5 E) 1 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 + (1/25)</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) ** 2</gadget>
<output>676/625 = around 1.0816</output>
<gadget id="calculator">6_250 * (676/625)</gadget>
<output>6_760</output>
<gadget id="calculator">6_760 - 6_250</gadget>
<output>510</output>
<gadget id="calculator">6_250 * (1/25)</gadget>
<output>250</output>
<gadget id="calculator">250 * 2</gadget>
<output>500</output>
<gadget id="calculator">510 - 500</gadget>
<output>10</output>
<result>C</result> | C | 10 | Indu gave Bindu Rs.6250 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest? | {
"A": "5",
"B": "2",
"C": "10",
"D": "5",
"E": "1"
} | subtract(subtract(multiply(6250, power(add(const_1, divide(4, const_100)), 2)), 6250), multiply(multiply(6250, divide(4, const_100)), 2)) | divide(n2,const_100)|add(#0,const_1)|multiply(n0,#0)|multiply(n1,#2)|power(#1,n1)|multiply(n0,#4)|subtract(#5,n0)|subtract(#6,#3) | 6250 = d ( 100 / 4 ) 2 d = 10 answer : c | gain |
math_qa__KDRUJz2i6ujpvCre | if log102 = 0.3010, what is the value of log101600 ? Choose the correct choice from the following options:
A) 3.208
B) 3.202
C) 3.209
D) 3.204
E) 3.2112 | <gadget id="calculator">4 * 0.301</gadget>
<output>1.204</output>
<gadget id="calculator">log(100)</gadget>
<output>log(100) = around 4.60517</output>
<gadget id="calculator">log(10)</gadget>
<output>log(10) = around 2.302585</output>
<gadget id="calculator">log(100) / log(10)</gadget>
<output>log(100)/log(10) = around 2</output>
<gadget id="calculator">1.204 + (log(100)/log(10))</gadget>
<output>1.204 + log(100)/log(10) = around 3.204</output>
<result>D</result> | D | 3.204 | if log102 = 0.3010, what is the value of log101600 ? | {
"A": "3.208",
"B": "3.202",
"C": "3.209",
"D": "3.204",
"E": "3.2112"
} | add(multiply(const_4, 0.301), divide(log(const_100), log(const_10))) | log(const_100)|log(const_10)|multiply(n1,const_4)|divide(#0,#1)|add(#3,#2) | explanation : log 101600 = log 10 ( 16 × 100 ) = log 10 ( 16 ) + log 10 ( 100 ) = log 10 ( 24 ) + log 10 ( 102 ) = 4 log 10 ( 2 ) + 2 = ( 4 × 0.3010 ) + 2 = 1.204 + 2 = 3.204 answer : option d | other |
math_qa__STZR9K2furnpureg | A man can row his boat with the stream at 16 km/h and against the stream in 12 km/h. The man's rate is? Choose the correct answer.
A) 8 kmph B) 9 kmph C) 2 kmph D) 4 kmph E) 1 kmph | <gadget id="calculator">16 - 12</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>C</result> | C | 2 | A man can row his boat with the stream at 16 km/h and against the stream in 12 km/h. The man's rate is? | {
"A": "8 kmph",
"B": "9 kmph",
"C": "2 kmph",
"D": "4 kmph",
"E": "1 kmph"
} | divide(subtract(16, 12), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "ds = 16 us = 14 s = ? s = ( 16 - 2 ) / 2 = 2 kmph answer : c" | gain |
math_qa__yp7ysQsWLm7Cx59Y | If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ? Answers
A) 0.35 B) 3.5 C) 35 D) 350 E) 3500 | <gadget id="calculator">125 * 150</gadget>
<output>18_750</output>
<gadget id="calculator">18_750 * 175</gadget>
<output>3_281_250</output>
<gadget id="calculator">25 * 50</gadget>
<output>1_250</output>
<gadget id="calculator">1_250 * 75</gadget>
<output>93_750</output>
<gadget id="calculator">3_281_250 / 93_750</gadget>
<output>35</output>
<gadget id="calculator">35 * 20</gadget>
<output>700</output>
<gadget id="calculator">700 / 200</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(7/2) * 100</gadget>
<output>350</output>
<result>D</result> | D | 350 | If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ? | {
"A": "0.35",
"B": "3.5",
"C": "35",
"D": "350",
"E": "3500"
} | multiply(divide(multiply(divide(multiply(multiply(125, 150), 175), multiply(multiply(25, 50), 75)), 20), 200), const_100) | multiply(n0,n2)|multiply(n1,n3)|multiply(n4,#0)|multiply(n5,#1)|divide(#2,#3)|multiply(n6,#4)|divide(#5,n7)|multiply(#6,const_100) | first of all , let us write the information in form of equations and numbers 125 j = 5 k or 5 j = k ( i ) 150 k = 50 l or 3 k = l ( ii ) 175 l = 75 m or 7 l = 3 m ( iii ) we need to find a relation between j and m from ( i ) and ( ii ) , 15 j = l multiplying this by 7 , 105 j = 7 l = 3 m hence , 35 j = m now , we are asked : 20 % of m is equal to what percent of 200 % of j assume j = 1 , hence m = 35 20 % of m = 7 and 200 % of j = 2 20 % of m = 3.5 ( 200 % of j ) = ( 350 / 100 ) * ( 200 % of j ) hence 20 % of m = 350 % of 200 % of j . option d | gain |
math_qa__vk6HYgFYFxa6SKPi | A library has an average of 570 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is: Choose the correct choice from the following: A) 250 B) 276 C) 280 D) 295 E) none | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">30 / 7</gadget>
<output>30/7 = around 4.285714</output>
<gadget id="calculator">floor(30/7)</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 570</gadget>
<output>2_850</output>
<gadget id="calculator">30 - 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 240</gadget>
<output>6_000</output>
<gadget id="calculator">2_850 + 6_000</gadget>
<output>8_850</output>
<gadget id="calculator">8_850 / 30</gadget>
<output>295</output>
<result>D</result> | D | 295 | A library has an average of 570 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is: | {
"A": "250",
"B": "276",
"C": "280",
"D": "295",
"E": "none"
} | divide(add(multiply(add(floor(divide(30, add(const_3, const_4))), const_1), 570), multiply(subtract(30, add(floor(divide(30, add(const_3, const_4))), const_1)), 240)), 30) | add(const_3,const_4)|divide(n2,#0)|floor(#1)|add(#2,const_1)|multiply(n0,#3)|subtract(n2,#3)|multiply(n1,#5)|add(#4,#6)|divide(#7,n2)| | "since the month begins with sunday , to there will be five sundays in the month average required = ( 570 x 5 + 240 x 25 ) / 30 ) = 295 answer : option d" | general |
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