id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__eCh0glwSMmTuLMnu | 69 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?
Pick.
A) 20
B) 23
C) 24
D) 25
E) 26 | <gadget id="calculator">69 * 12</gadget>
<output>828</output>
<gadget id="calculator">828 * 5</gadget>
<output>4_140</output>
<gadget id="calculator">30 * 6</gadget>
<output>180</output>
<gadget id="calculator">4_140 / 180</gadget>
<output>23</output>
<result>B</result> | B | 23 | 69 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work? | {
"A": "20",
"B": "23",
"C": "24",
"D": "25",
"E": "26"
} | divide(multiply(multiply(69, 12), 5), multiply(30, 6)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|divide(#2,#1)| | "according to the chain rule , m 1 x t 1 = m 2 x t 2 therefore , 69 x 12 x 5 = 30 x 6 x x x = 23 hence , the number of days = 23 . answer : b" | physics |
math_qa__tyaZVO6Q2uEE7wBw | How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 11 inches than that of a rectangular sheet of paper measuring 5.5 inches by 11 inches? Choose the correct choice from the following choices:
A) 50 % B) 87 % C) 100 % D) 187 % E) 200 % | <gadget id="calculator">11 * 11</gadget>
<output>121</output>
<gadget id="calculator">121 * 2</gadget>
<output>242</output>
<gadget id="calculator">5.5 * 11</gadget>
<output>60.5</output>
<gadget id="calculator">60.5 * 2</gadget>
<output>121</output>
<gadget id="calculator">242 - 121</gadget>
<output>121</output>
<gadget id="calculator">121 / 121</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>C</result> | C | 100 | How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 11 inches than that of a rectangular sheet of paper measuring 5.5 inches by 11 inches? | {
"A": "50 %",
"B": "87 %",
"C": "100 %",
"D": "187 %",
"E": "200 %"
} | multiply(divide(subtract(multiply(rectangle_area(11, 11), const_2), multiply(rectangle_area(5.5, 11), const_2)), rectangle_area(11, 11)), const_100) | rectangle_area(n0,n1)|rectangle_area(n0,n2)|multiply(#0,const_2)|multiply(#1,const_2)|subtract(#2,#3)|divide(#4,#0)|multiply(#5,const_100)| | "let ' s just look at the dimensions ( no calculation needed ) . with dimension 11 the same , the other dimension 11 is twice 5.5 then the area will be double which means 100 % greater . the answer is c ." | geometry |
math_qa__6arTNkMMEOcDHI1z | A certain college's enrollment at the beginning of 1992 was 40 percent greater than it was at the beginning of 1991, and its enrollment at the beginning of 1993 was 15 percent greater than it was at the beginning of 1992. The college's enrollment at the beginning of 1993 was what percent greater than its enrollment at the beginning of 1991 ? Choose the correct option.
A) 63 % B) 24 % C) 50 % D) 55 % E) 61 % | <gadget id="calculator">100 + 40</gadget>
<output>140</output>
<gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">115 / 100</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">140 * (23/20)</gadget>
<output>161</output>
<gadget id="calculator">161 - 100</gadget>
<output>61</output>
<result>E</result> | E | 61 | A certain college's enrollment at the beginning of 1992 was 40 percent greater than it was at the beginning of 1991, and its enrollment at the beginning of 1993 was 15 percent greater than it was at the beginning of 1992. The college's enrollment at the beginning of 1993 was what percent greater than its enrollment at the beginning of 1991 ? | {
"A": "63 %",
"B": "24 %",
"C": "50 %",
"D": "55 %",
"E": "61 %"
} | subtract(multiply(add(const_100, 40), divide(add(const_100, 15), const_100)), const_100) | add(n1,const_100)|add(n4,const_100)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,const_100)| | "suppose enrollment in 1991 was 100 then enrollment in 1992 will be 140 and enrollment in 1993 will be 140 * 1.15 = 161 increase in 1993 from 1991 = 161 - 100 = 61 answer : e" | gain |
math_qa__EZDVgMATeyrNWXQc | If the cost price is 75% of the selling price, then what is the profit percent? Choose one.
A) 5 % B) 11 % C) 13 % D) 21 % E) 33 % | <gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">25 / 75</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>E</result> | E | 33 | If the cost price is 75% of the selling price, then what is the profit percent? | {
"A": "5 %",
"B": "11 %",
"C": "13 %",
"D": "21 %",
"E": "33 %"
} | multiply(divide(subtract(const_100, 75), 75), const_100) | subtract(const_100,n0)|divide(#0,n0)|multiply(#1,const_100)| | "let s . p . = $ 100 c . p . = $ 75 profit = $ 25 profit % = 25 / 75 * 100 = 25 / 6 = 33 % approximately answer is e" | gain |
math_qa__PFfe3Zbj5O6cPtT4 | Two brothers Ram and Ravi appeared for an exam. The probability of selection of Ram is 5/7 and that of Ravi is 1/5. Find the probability that both of them are selected. Choose the correct choice from the following.
A) 2 / 35
B) 2 / 3
C) 7 / 35
D) 1 / 7
E) 7 / 5 | <gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(5/7) * (1/5)</gadget>
<output>1/7 = around 0.142857</output>
<result>D</result> | D | 0.142857 | Two brothers Ram and Ravi appeared for an exam. The probability of selection of Ram is 5/7 and that of Ravi is 1/5. Find the probability that both of them are selected. | {
"A": "2 / 35",
"B": "2 / 3",
"C": "7 / 35",
"D": "1 / 7",
"E": "7 / 5"
} | multiply(divide(5, 7), divide(1, 5)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)| | "let a be the event that ram is selected and b is the event that ravi is selected . p ( a ) = 5 / 7 p ( b ) = 1 / 5 let c be the event that both are selected . p ( c ) = p ( a ) x p ( b ) as a and b are independent events : = 5 / 7 x 1 / 5 = 1 / 7 answer : d" | general |
math_qa__IGlapHmpdKBlEnWr | Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.145. How much was lent at 5%?
Choose the most appropriate option.
A) 2333 B) 2777 C) 2688 D) 500 E) 2871 | <gadget id="calculator">6 * 2_500</gadget>
<output>15_000</output>
<gadget id="calculator">15_000 / 100</gadget>
<output>150</output>
<gadget id="calculator">145 - 150</gadget>
<output>-5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(1/20) - (3/50)</gadget>
<output>-1/100 = around -0.01</output>
<gadget id="calculator">(-5) / (-1/100)</gadget>
<output>500</output>
<result>D</result> | D | 500 | Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.145. How much was lent at 5%? | {
"A": "2333",
"B": "2777",
"C": "2688",
"D": "500",
"E": "2871"
} | divide(subtract(145, divide(multiply(6, 2500), const_100)), subtract(divide(5, const_100), divide(6, const_100))) | divide(n1,const_100)|divide(n2,const_100)|multiply(n0,n2)|divide(#2,const_100)|subtract(#0,#1)|subtract(n3,#3)|divide(#5,#4)| | "( x * 5 * 1 ) / 100 + [ ( 2500 - x ) * 6 * 1 ] / 100 = 145 x = 500 answer : d" | gain |
math_qa__cUsRhufkvZRZyq7s | Find the mean proportional between 49 & 64? Pick one.
A) 59 B) 61 C) 56 D) 65 E) 67 | <gadget id="calculator">49 + 64</gadget>
<output>113</output>
<gadget id="calculator">113 / 2</gadget>
<output>113/2 = around 56.5</output>
<result>C</result> | C | 56 | Find the mean proportional between 49 & 64? | {
"A": "59",
"B": "61",
"C": "56",
"D": "65",
"E": "67"
} | divide(add(49, 64), const_2) | add(n0,n1)|divide(#0,const_2)| | "formula = √ a × b a = 49 and b = 64 √ 49 × 64 = 7 × 8 = 56 c" | general |
math_qa__Yj01PMsG7OyHC4Mt | 50% of a number is 10 less than 3/5th of that number. What is the number? Choose one
A) 100
B) 50
C) 150
D) 200
E) 75 | <gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">50 * 20</gadget>
<output>1_000</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">60 - 50</gadget>
<output>10</output>
<gadget id="calculator">1_000 / 10</gadget>
<output>100</output>
<result>A</result> | A | 100 | 50% of a number is 10 less than 3/5th of that number. What is the number? | {
"A": "100",
"B": "50",
"C": "150",
"D": "200",
"E": "75"
} | divide(multiply(multiply(10, 5), divide(const_100, 5)), subtract(multiply(divide(const_100, 5), 3), 50)) | divide(const_100,n3)|multiply(n1,n3)|multiply(#0,#1)|multiply(n2,#0)|subtract(#3,n0)|divide(#2,#4)| | "let the number be x then , 3 x / 5 - ( 50 % of x ) = 10 3 x / 5 - 50 x / 100 = 10 x = 100 answer is a" | general |
math_qa__Ex0h9CBlIBkaEVnX | 17+18=35. How many such 2 consecutive numbers are there less than 200 when added gives a sum which is divisible by 5? Choose one: A) 80 B) 40 C) 50 D) 60 E) 20 | <gadget id="calculator">200 / 5</gadget>
<output>40</output>
<result>B</result> | B | 40 | 17+18=35. How many such 2 consecutive numbers are there less than 200 when added gives a sum which is divisible by 5? | {
"A": "80",
"B": "40",
"C": "50",
"D": "60",
"E": "20"
} | divide(200, 5) | divide(n4,n5) | since 2 + 3 = 5 & 7 + 8 = 15 any combination with these no be will give u desirable result . . . so total no in 100 will be 20 & that ' s why in 200 , it will be 40 answer : b | general |
math_qa__kYtqTkwVdRwfnrpA | The profit earned by selling an article for 872 is equal to the loss incurred when the same article is sold for 448. What should be the sale price of the article for making 50 per cent profit? Choose one:
A) 960
B) 990
C) 1,200
D) 920
E) none of these | <gadget id="calculator">872 + 448</gadget>
<output>1_320</output>
<gadget id="calculator">1_320 / 2</gadget>
<output>660</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">660 * (3/2)</gadget>
<output>990</output>
<result>B</result> | B | 990 | The profit earned by selling an article for 872 is equal to the loss incurred when the same article is sold for 448. What should be the sale price of the article for making 50 per cent profit? | {
"A": "960",
"B": "990",
"C": "1,200",
"D": "920",
"E": "none of these"
} | multiply(divide(add(872, 448), const_2), add(const_1, divide(50, const_100))) | add(n0,n1)|divide(n2,const_100)|add(#1,const_1)|divide(#0,const_2)|multiply(#2,#3)| | "let the profit or loss be x and 872 – x = 448 + x or , x = 424 ⁄ 2 = 212 \ cost price of the article = 872 – x = 448 + x = 660 \ sp of the article = 660 × 150 ⁄ 100 = 990 answer b" | gain |
math_qa__ekUax0wAKGnj51od | A candidate got 40% of the votes polled and he lost to his rival by 2000 votes. How many votes were cast? Choose the correct choice from the following answers.
A) 10000 B) 2028 C) 2775 D) 5496 E) 6851 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) - (2/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2_000 / (1/5)</gadget>
<output>10_000</output>
<result>A</result> | A | 10,000 | A candidate got 40% of the votes polled and he lost to his rival by 2000 votes. How many votes were cast? | {
"A": "10000",
"B": "2028",
"C": "2775",
"D": "5496",
"E": "6851"
} | divide(2000, subtract(subtract(const_1, divide(40, const_100)), divide(40, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|subtract(#1,#0)|divide(n1,#2)| | "40 % - - - - - - - - - - - l 60 % - - - - - - - - - - - w - - - - - - - - - - - - - - - - - - 20 % - - - - - - - - - - 2000 100 % - - - - - - - - - ? = > 10000 answer : a" | gain |
math_qa__AsFnD6veIHFUzowA | One night 17 percent of the female officers on a police force were on duty. If 170 police officers were on duty that night and half of these were female officers, how many female officers were on the police force?
Choose the correct choice from the following
A) 400 B) 420 C) 450 D) 480 E) 500 | <gadget id="calculator">170 / 2</gadget>
<output>85</output>
<gadget id="calculator">17 / 100</gadget>
<output>17/100 = around 0.17</output>
<gadget id="calculator">85 / (17/100)</gadget>
<output>500</output>
<result>E</result> | E | 500 | One night 17 percent of the female officers on a police force were on duty. If 170 police officers were on duty that night and half of these were female officers, how many female officers were on the police force? | {
"A": "400",
"B": "420",
"C": "450",
"D": "480",
"E": "500"
} | divide(divide(170, const_2), divide(17, const_100)) | divide(n1,const_2)|divide(n0,const_100)|divide(#0,#1) | let x be the number of female police officers on the police force . the number of female police officers on duty was 85 . 0.17 x = 85 x = 500 the answer is e . | gain |
math_qa__atiYhgu8yt9ygt7R | The circumferences of two circles are 396 meters and 704 meters. Find the difference between the areas of the larger and the smaller circles?
Choose the correct answer
A) 29960 sq m
B) 26950 sq m
C) 43120 sq m
D) 27680 sq m
E) 27786 sq m | <gadget id="calculator">2 * pi</gadget>
<output>2*pi = around 6.283185</output>
<gadget id="calculator">704 / (2*pi)</gadget>
<output>352/pi = around 112.04508</output>
<gadget id="calculator">pi * ((352/pi) ** 2)</gadget>
<output>123904/pi = around 39_439.868138</output>
<gadget id="calculator">396 / (2*pi)</gadget>
<output>198/pi = around 63.025357</output>
<gadget id="calculator">pi * ((198/pi) ** 2)</gadget>
<output>39204/pi = around 12_479.020778</output>
<gadget id="calculator">(123904/pi) - (39204/pi)</gadget>
<output>84700/pi = around 26_960.84736</output>
<result>B</result> | B | 26,950 | The circumferences of two circles are 396 meters and 704 meters. Find the difference between the areas of the larger and the smaller circles? | {
"A": "29960 sq m",
"B": "26950 sq m",
"C": "43120 sq m",
"D": "27680 sq m",
"E": "27786 sq m"
} | subtract(circle_area(divide(704, multiply(const_2, const_pi))), circle_area(divide(396, multiply(const_2, const_pi)))) | multiply(const_2,const_pi)|divide(n1,#0)|divide(n0,#0)|circle_area(#1)|circle_area(#2)|subtract(#3,#4)| | "let the radii of the smaller and the larger circles be s m and l m respectively . 2 ∏ s = 396 and 2 ∏ l = 704 s = 396 / 2 ∏ and l = 704 / 2 ∏ difference between the areas = ∏ l ^ 2 - ∏ s ^ 2 = ∏ { 198 ^ 2 / ∏ ^ 2 - 352 ^ 2 / ∏ ^ 2 } = 198 ^ 2 / ∏ - 352 ^ 2 / ∏ = ( 198 - 352 ) ( 198 + 352 ) / ∏ = ( 154 ) ( 550 ) / ( 22 / 7 ) = 26950 sq m answer : b" | geometry |
math_qa__3Rzb4hcEqzrfuAsT | If a - b = 3 and a^2 + b^2 = 27, find the value of ab. Select: A) 12 B) 15 C) 10 D) 18 E) 9 | <gadget id="calculator">27 ** (1/2)</gadget>
<output>3*sqrt(3) = around 5.196152</output>
<gadget id="calculator">(3*sqrt(3)) - 3</gadget>
<output>-3 + 3*sqrt(3) = around 2.196152</output>
<gadget id="calculator">(-3 + 3*sqrt(3)) / 2</gadget>
<output>-3/2 + 3*sqrt(3)/2 = around 1.098076</output>
<gadget id="calculator">3 + (-3/2 + 3*sqrt(3)/2)</gadget>
<output>3/2 + 3*sqrt(3)/2 = around 4.098076</output>
<gadget id="calculator">(3/2 + 3*sqrt(3)/2) * (-3/2 + 3*sqrt(3)/2)</gadget>
<output>(-3/2 + 3*sqrt(3)/2)*(3/2 + 3*sqrt(3)/2) = around 4.5</output>
<gadget id="calculator">((-3/2 + 3*sqrt(3)/2)*(3/2 + 3*sqrt(3)/2)) * 2</gadget>
<output>2*(-3/2 + 3*sqrt(3)/2)*(3/2 + 3*sqrt(3)/2) = around 9</output>
<result>E</result> | E | 9 | If a - b = 3 and a^2 + b^2 = 27, find the value of ab. | {
"A": "12",
"B": "15",
"C": "10",
"D": "18",
"E": "9"
} | multiply(multiply(add(3, divide(subtract(sqrt(27), 3), 2)), divide(subtract(sqrt(27), 3), 2)), 2) | sqrt(n3)|subtract(#0,n0)|divide(#1,n1)|add(n0,#2)|multiply(#3,#2)|multiply(n1,#4)| | "2 ab = ( a ^ 2 + b ^ 2 ) - ( a - b ) ^ 2 = 27 - 9 = 18 ab = 9 . answer is e ." | general |
math_qa__zGtgiwTkJsGmSPnF | In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 2 to the thrice of the remainder. The dividend is?
Choose the correct choice from the following choices:
A) 75
B) 78
C) 80
D) 82
E) 86 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 + 2</gadget>
<output>20</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">20 * 4</gadget>
<output>80</output>
<gadget id="calculator">80 + 6</gadget>
<output>86</output>
<result>E</result> | E | 86 | In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 2 to the thrice of the remainder. The dividend is? | {
"A": "75",
"B": "78",
"C": "80",
"D": "82",
"E": "86"
} | add(multiply(add(multiply(6, const_3), 2), divide(add(multiply(6, const_3), 2), 5)), 6) | multiply(n0,const_3)|add(n2,#0)|divide(#1,n1)|multiply(#1,#2)|add(n0,#3)| | "divisor = ( 6 * 3 ) + 2 = 20 5 * quotient = 20 quotient = 4 . dividend = ( divisor * quotient ) + remainder dividend = ( 20 * 4 ) + 6 = 86 e )" | general |
math_qa__87cXrfMftyuqBheN | The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 6 years ? Choose the most appropriate option:
A) 3277 B) 2977 C) 7119 D) 6077 E) 17112 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">4 * 10_000</gadget>
<output>40_000</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) ** 6</gadget>
<output>729/4_096 = around 0.177979</output>
<gadget id="calculator">40_000 * (729/4_096)</gadget>
<output>455_625/64 = around 7_119.140625</output>
<result>C</result> | C | 7,119 | The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 6 years ? | {
"A": "3277",
"B": "2977",
"C": "7119",
"D": "6077",
"E": "17112"
} | multiply(multiply(4, multiply(const_100, const_100)), power(divide(3, 4), 6)) | divide(n0,n1)|multiply(const_100,const_100)|multiply(n1,#1)|power(#0,n3)|multiply(#2,#3)| | "explanation : 40,000 * ( 3 / 4 ) ^ 6 answer : c" | general |
math_qa__s7GX4EgvMdy0xUe7 | there are 50 employees in the office of abc company . of these , 22 have taken an accounting course , 14 have taken a course in finance and 15 have taken a marketing course . 10 of the employees have taken exactly two of the courses and 1 employee has taken all 3 of the courses . how many of the 50 employees have taken none of the courses ? Choices:
A) 11 B) 5 C) 9 D) 8 E) 10 | <gadget id="calculator">22 + 14</gadget>
<output>36</output>
<gadget id="calculator">36 + 15</gadget>
<output>51</output>
<gadget id="calculator">51 - 10</gadget>
<output>41</output>
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">41 - 2</gadget>
<output>39</output>
<gadget id="calculator">50 - 39</gadget>
<output>11</output>
<result>A</result> | A | 11 | there are 50 employees in the office of abc company . of these , 22 have taken an accounting course , 14 have taken a course in finance and 15 have taken a marketing course . 10 of the employees have taken exactly two of the courses and 1 employee has taken all 3 of the courses . how many of the 50 employees have taken none of the courses ? | {
"A": "11",
"B": "5",
"C": "9",
"D": "8",
"E": "10"
} | subtract(50, subtract(subtract(add(add(22, 14), 15), 10), multiply(1, const_2))) | add(n1,n2)|multiply(n5,const_2)|add(n3,#0)|subtract(#2,n4)|subtract(#3,#1)|subtract(n0,#4) | 50 employees . counting every different attendand to the courses we have : accounting : 22 finance : 14 marketing : 15 which would add up to 51 different attendands , which is not possible . now 10 have taken exactly 2 courses , which means that there are 10 less different attendands . say that 10 of the finance attentands also attended accounting . 51 - 10 = 41 1 person has taken all three courses . as above , we subtract him from the number of different attendands . since this time the person took all three courses , we have to substract him two times . 41 - 2 = 39 . answer : a | general |
math_qa__arHVnqT2rBMgeUcI | If an object travels 80 feet in 2 seconds, what is the object’s approximate speed in miles per hour? (Note: 1 mile = 5280 feet) Choose the correct choice from the following: A) 21.21 B) 24.24 C) 27.27 D) 30.35 E) 33.33 | <gadget id="calculator">80 / 5_280</gadget>
<output>1/66 = around 0.015152</output>
<gadget id="calculator">1 / 3_600</gadget>
<output>1/3_600 = around 0.000278</output>
<gadget id="calculator">2 * (1/3_600)</gadget>
<output>1/1_800 = around 0.000556</output>
<gadget id="calculator">(1/66) / (1/1_800)</gadget>
<output>300/11 = around 27.272727</output>
<result>C</result> | C | 27.27 | If an object travels 80 feet in 2 seconds, what is the object’s approximate speed in miles per hour? (Note: 1 mile = 5280 feet) | {
"A": "21.21",
"B": "24.24",
"C": "27.27",
"D": "30.35",
"E": "33.33"
} | divide(divide(80, 5280), multiply(2, divide(1, const_3600))) | divide(n0,n3)|divide(n2,const_3600)|multiply(n1,#1)|divide(#0,#2)| | "80 feet / 2 seconds = 40 feet / second ( 40 feet / second ) * ( 3600 seconds / hour ) * ( 1 mile / 5280 feet ) = 27.27 miles / hour ( approximately ) the answer is c ." | physics |
math_qa__iovk934BN1qLplix | What is the sum of all possible 3-digit numbers that can be constructed using the digits 1, 2, and 4 if each digit can be used only once in each number? Pick:
A) 1210 B) 1221 C) 1332 D) 1443 E) 1554 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">7 * 100</gadget>
<output>700</output>
<gadget id="calculator">7 * 10</gadget>
<output>70</output>
<gadget id="calculator">700 + 70</gadget>
<output>770</output>
<gadget id="calculator">770 + 7</gadget>
<output>777</output>
<gadget id="calculator">777 * 2</gadget>
<output>1_554</output>
<result>E</result> | E | 1,554 | What is the sum of all possible 3-digit numbers that can be constructed using the digits 1, 2, and 4 if each digit can be used only once in each number? | {
"A": "1210",
"B": "1221",
"C": "1332",
"D": "1443",
"E": "1554"
} | multiply(add(add(multiply(add(add(4, 2), 1), const_100), multiply(add(add(4, 2), 1), const_10)), add(add(4, 2), 1)), const_2) | add(n2,n3)|add(n1,#0)|multiply(#1,const_100)|multiply(#1,const_10)|add(#2,#3)|add(#4,#1)|multiply(#5,const_2) | there are 6 possible arrangements of the three numbers . then each number will be in the hundreds , tens , and ones place two times each . the sum is 2 ( 111 ) + 2 ( 222 ) + 2 ( 444 ) = 1554 the answer is e . | general |
math_qa__B5kAkZrP5LiHckVy | A number when divided by 5 gives a number which is 8 more than the remainder obtained on dividing the same number by 34. Such a least possible number X is Choose the correct choice.
A) 74 B) x = 75 C) x = 175 D) x = 680 E) 690 | <gadget id="calculator">34 * 2</gadget>
<output>68</output>
<gadget id="calculator">8 * 5</gadget>
<output>40</output>
<gadget id="calculator">68 - 40</gadget>
<output>28</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">28 / 4</gadget>
<output>7</output>
<gadget id="calculator">68 + 7</gadget>
<output>75</output>
<result>B</result> | B | 75 | A number when divided by 5 gives a number which is 8 more than the remainder obtained on dividing the same number by 34. Such a least possible number X is | {
"A": "74",
"B": "x = 75",
"C": "x = 175",
"D": "x = 680",
"E": "690"
} | add(multiply(34, const_2), divide(subtract(multiply(34, const_2), multiply(8, 5)), subtract(5, const_1))) | multiply(n2,const_2)|multiply(n0,n1)|subtract(n0,const_1)|subtract(#0,#1)|divide(#3,#2)|add(#4,#0)| | "i solved this question by plugging in numbers from the answer choices . a . ) 74 starting with answer choice a , i immediately eliminated it because 74 is not even divisible by 5 . b . ) 75 i divide 75 / 5 and get 15 as an answer . i divide 75 / 34 and get a remainder of 7 . 15 - 7 = 8 so i know the correct answer isb" | general |
math_qa__KeRPeDtvbIYelU4q | If 1=x. 2=2x 3=4x....
what is 2x*6x+5x/4x-56x Choose the most appropriate option.
A) 1 B) 22 C) 23 D) 10 E) 25 | <gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">12 - 2</gadget>
<output>10</output>
<result>D</result> | D | 10 | If 1=x. 2=2x 3=4x....
what is 2x*6x+5x/4x-56x | {
"A": "1",
"B": "22",
"C": "23",
"D": "10",
"E": "25"
} | subtract(divide(multiply(multiply(2, 6), 2), const_2), const_2) | multiply(n1,n6)|multiply(n1,#0)|divide(#1,const_2)|subtract(#2,const_2) | let 1 = x 2 = 2 x 3 = 4 x 4 = 8 x 5 = 16 x 6 = 32 x 7 = 64 x now given 2 x * 6 x + 5 x / 4 x - 56 x i can write it as = 2 x * ( 2 x + 4 x ) + ( x + 4 x ) / 4 x - ( 64 x - 8 x ) now by putting the values i get = 2 * ( 2 + 3 ) + ( 8 + 1 ) / 3 - ( 7 - 4 ) = 2 * 5 + 9 / 3 - 3 = 10 + 9 / 3 - 3 = 10 + 3 - 3 = 10 answer : d | general |
math_qa__NTq2fXWMSEOub9oN | The closest approximation of A(69.28 × 0.004)/0.03 is
Choose the correct option: A) 0.092 B) 0.92 C) 9.2 D) 92 E) 920 | <gadget id="calculator">0.004 / 0.03</gadget>
<output>0.133333</output>
<gadget id="calculator">0.133333 * 69.28</gadget>
<output>9.23731</output>
<result>C</result> | C | 9.2 | The closest approximation of A(69.28 × 0.004)/0.03 is | {
"A": "0.092",
"B": "0.92",
"C": "9.2",
"D": "92",
"E": "920"
} | multiply(divide(0.004, 0.03), 69.28) | divide(n1,n2)|multiply(n0,#0)| | "a ( 69.28 × 0.004 ) / 0.03 1 . 0.004 = 4 × 10 ^ ( - 3 ) 2 . 0.03 = 3 × 10 ^ ( - 2 ) 3 . ( a × b ) / c = a × ( b / c ) 4 . 0.004 / 0.03 = 4 × 10 ^ ( - 3 ) / ( 3 × 10 ^ ( - 2 ) ) = 4 × 10 ^ ( - 3 - ( - 2 ) ) / 3 = 4 × 10 ^ ( - 1 ) / 3 = ( 4 / 3 ) × 10 ^ ( - 1 ) = 1.333 × 10 ^ ( - 1 ) therefore , ( 69.28 × 0.004 ) / 0.03 = 69.28 × ( 0.004 / 0.03 ) = 69.28 × 1.33 × 10 ^ ( - 1 ) = 69.28 × 1.33 / 10 = 6.928 * 1.33 now , 7 × 2 = 14 7 × 1 = 7 or better : 6.9 × 1 = 6.9 6.9 × 2 = 13.8 hence , 6.9 < 6.928 × 1.33 < 13.8 9.2 is the only answer that satisfies this condition . c" | general |
math_qa__yv4kU8yDNJofOocW | A number exceeds 20% of itself by 40. The number is ? Choices:
A) 50
B) 60
C) 80
D) 320
E) none | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">40 / (4/5)</gadget>
<output>50</output>
<result>A</result> | A | 50 | A number exceeds 20% of itself by 40. The number is ? | {
"A": "50",
"B": "60",
"C": "80",
"D": "320",
"E": "none"
} | divide(40, subtract(const_1, divide(20, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1) | answer ∵ a - 20 % of a = 40 ⇒ a - a / 5 = 40 ⇒ 4 a / 5 = 40 ∴ a = ( 5 x 40 ) / 4 = 50 . correct option : a | gain |
math_qa__VJDHH23S9vpFSJzG | Mark and Ann together were allocated n boxes of cookies to sell for a club project. Mark sold 8 boxes less than n and Ann sold 2 boxes less than n. If Mark and Ann have each sold at least one box of cookies, but together they have sold less than n boxes, what is the value of n?
Choices
A) 5
B) 6
C) 7
D) 8
E) 9 | <gadget id="calculator">8 + 1</gadget>
<output>9</output>
<result>E</result> | E | 9 | Mark and Ann together were allocated n boxes of cookies to sell for a club project. Mark sold 8 boxes less than n and Ann sold 2 boxes less than n. If Mark and Ann have each sold at least one box of cookies, but together they have sold less than n boxes, what is the value of n? | {
"A": "5",
"B": "6",
"C": "7",
"D": "8",
"E": "9"
} | add(8, const_1) | add(n0,const_1)| | "if n = 9 mark sold 1 box and ann sold 7 boxes total 8 < 9 answer : e" | general |
math_qa__b0WInQ72wTVrmEmF | A store reduced the price of all items in the store by 9% on the first day and by another 10% on the second day. The price of items on the second day was what percent of the price before the first reduction took place? Choose the correct option
A) 80.0 B) 80.9 C) 81.0 D) 81.1 E) 81.9 | <gadget id="calculator">100 - 9</gadget>
<output>91</output>
<gadget id="calculator">91 / 100</gadget>
<output>91/100 = around 0.91</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(91/100) * (9/10)</gadget>
<output>819/1_000 = around 0.819</output>
<gadget id="calculator">(819/1_000) * 100</gadget>
<output>819/10 = around 81.9</output>
<result>E</result> | E | 81.9 | A store reduced the price of all items in the store by 9% on the first day and by another 10% on the second day. The price of items on the second day was what percent of the price before the first reduction took place? | {
"A": "80.0",
"B": "80.9",
"C": "81.0",
"D": "81.1",
"E": "81.9"
} | multiply(multiply(divide(subtract(const_100, 9), const_100), divide(subtract(const_100, 10), const_100)), const_100) | subtract(const_100,n0)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|multiply(#4,const_100)| | "consider price of the all items as $ 100 after a initial reduction of 9 % price becomes = 0.91 * 100 = $ 91 after the final reduction of 10 % price becomes = 0.9 * 91 = $ 81.9 price of all items on second day is 81.9 % of price on first day correct answer option e" | gain |
math_qa__ctf6HtcTZ9g6mj4O | The maximum number of students among them 890 pens and 630 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: Choose the correct choice from the following answers:
A) 10
B) 910
C) 1001
D) 1911
E) none of these | <gadget id="calculator">gcd(890, 630)</gadget>
<output>10</output>
<result>A</result> | A | 10 | The maximum number of students among them 890 pens and 630 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: | {
"A": "10",
"B": "910",
"C": "1001",
"D": "1911",
"E": "none of these"
} | gcd(890, 630) | gcd(n0,n1)| | "explanation : required number of students = h . c . f of 890 and 630 = 10 . answer : a" | general |
math_qa__W1Dy9VW9rRYlO7Q7 | A certain bacteria colony doubles in size every day for 22 days, at which point it reaches the limit of its habitat and can no longer grow. If two bacteria colonies start growing simultaneously, how many days will it take them to reach the habitat’s limit? Choose the correct answer:
A) 6.33 B) 7.5 C) 21 D) 15 E) 19 | <gadget id="calculator">22 / 22</gadget>
<output>1</output>
<gadget id="calculator">22 - 1</gadget>
<output>21</output>
<result>C</result> | C | 21 | A certain bacteria colony doubles in size every day for 22 days, at which point it reaches the limit of its habitat and can no longer grow. If two bacteria colonies start growing simultaneously, how many days will it take them to reach the habitat’s limit? | {
"A": "6.33",
"B": "7.5",
"C": "21",
"D": "15",
"E": "19"
} | subtract(22, divide(22, 22)) | divide(n0,n0)|subtract(n0,#0)| | "if there is one bacteria colony , then it will reach the limit of its habitat in 20 days . if there are two bacteria colonies , then in order to reach the limit of habitat they would need to double one time less than in case with one colony . thus colonies need to double 21 times . answer : c . similar questions to practice : hope it helps ." | physics |
math_qa__olhRwsAIHCzlYhw9 | On a purchase of $110, a store offered a payment plan consisting of a $10 down payment and 12 monthly payments of $10 each. What percent of the purchase price, to the nearest tenth of a percent, did the customer pay in interest by using this plan? Pick one:
A) 9.5 %
B) 10.5 %
C) 11.5 %
D) 9.1 %
E) 12.5 % | <gadget id="calculator">10 * 12</gadget>
<output>120</output>
<gadget id="calculator">120 + 10</gadget>
<output>130</output>
<gadget id="calculator">130 - 120</gadget>
<output>10</output>
<gadget id="calculator">10 / 110</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">(1/11) * 100</gadget>
<output>100/11 = around 9.090909</output>
<result>D</result> | D | 9.1 | On a purchase of $110, a store offered a payment plan consisting of a $10 down payment and 12 monthly payments of $10 each. What percent of the purchase price, to the nearest tenth of a percent, did the customer pay in interest by using this plan? | {
"A": "9.5 %",
"B": "10.5 %",
"C": "11.5 %",
"D": "9.1 %",
"E": "12.5 %"
} | multiply(divide(subtract(add(multiply(10, 12), 10), multiply(10, 12)), 110), const_100) | multiply(n2,n3)|add(n1,#0)|subtract(#1,#0)|divide(#2,n0)|multiply(#3,const_100)| | "12 * 10 + 10 = 130 ( 10 / 110 ) * 100 = 9.1 answer : d" | gain |
math_qa__xtkY0hjSxl5JDj6R | Laura took out a charge account at the General Store and agreed to pay 9% simple annual interest. If she charges $35 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments? Choose the correct choice from the following answers: A) $ 2.10 B) $ 37.10 C) $ 37.16 D) $ 38.10 E) $ 38.15 | <gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">(9/100) * 35</gadget>
<output>63/20 = around 3.15</output>
<gadget id="calculator">(63/20) + 35</gadget>
<output>763/20 = around 38.15</output>
<result>E</result> | E | 38.15 | Laura took out a charge account at the General Store and agreed to pay 9% simple annual interest. If she charges $35 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments? | {
"A": "$ 2.10",
"B": "$ 37.10",
"C": "$ 37.16",
"D": "$ 38.10",
"E": "$ 38.15"
} | add(multiply(divide(9, const_100), 35), 35) | divide(n0,const_100)|multiply(n1,#0)|add(n1,#1) | principal that is amount taken by laura at year beginning = 35 $ rate of interest = 9 % interest = ( 9 / 100 ) * 35 = 3.15 $ total amount that laura owes a year later = 35 + 3.15 = 38.15 $ answer e | general |
math_qa__BD1r9BW1yysM20CE | The sum of two numbers is 72, and one of them is 12 more than the other. What are the two numbers? Pick one
A) 36 - 48 B) 50 - 34 C) 60 - 24 D) 30 - 42 E) 21 - 63 | <gadget id="calculator">72 - 12</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>D</result> | D | 30 | The sum of two numbers is 72, and one of them is 12 more than the other. What are the two numbers? | {
"A": "36 - 48",
"B": "50 - 34",
"C": "60 - 24",
"D": "30 - 42",
"E": "21 - 63"
} | divide(subtract(72, 12), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "in this problem , we are asked to find two numbers . therefore , we must let x be one of them . let x , then , be the first number . we are told that the other number is 12 more , x + 12 . the problem states that their sum is 72 : word problem = 72 the line over x + 12 is a grouping symbol called a vinculum . it saves us writing parentheses . we have : 2 x = 72 â ˆ ’ 12 = 60 . x = 60 / 2 = 30 . this is the first number . therefore the other number is x + 12 = 30 + 12 = 42 . the sum of 30 + 42 is 72 . d" | general |
math_qa__DJ6qSd06IqXliQZi | Bob wants to run a mile in the same time as his sister. If Bob’s time for a mile is currently 10 minutes 20 seconds and his sister’s time is currently 9 minutes 36 seconds, by what percent does Bob need to improve his time in order run a mile in the same time as his sister? Choose the correct option
A) 3 % B) 5 % C) 7 % D) 10 % E) 12 % | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">9 * 60</gadget>
<output>540</output>
<gadget id="calculator">540 + 36</gadget>
<output>576</output>
<gadget id="calculator">10 * 60</gadget>
<output>600</output>
<gadget id="calculator">600 + 20</gadget>
<output>620</output>
<gadget id="calculator">576 / 620</gadget>
<output>144/155 = around 0.929032</output>
<gadget id="calculator">1 - (144/155)</gadget>
<output>11/155 = around 0.070968</output>
<gadget id="calculator">100 * (11/155)</gadget>
<output>220/31 = around 7.096774</output>
<result>C</result> | C | 7 | Bob wants to run a mile in the same time as his sister. If Bob’s time for a mile is currently 10 minutes 20 seconds and his sister’s time is currently 9 minutes 36 seconds, by what percent does Bob need to improve his time in order run a mile in the same time as his sister? | {
"A": "3 %",
"B": "5 %",
"C": "7 %",
"D": "10 %",
"E": "12 %"
} | multiply(multiply(10, 10), subtract(const_1, divide(add(multiply(9, const_60), 36), add(multiply(10, const_60), 20)))) | multiply(n0,n0)|multiply(n2,const_60)|multiply(n0,const_60)|add(n3,#1)|add(n1,#2)|divide(#3,#4)|subtract(const_1,#5)|multiply(#0,#6)| | "bob ' s time = 620 secs . his sis ' time = 576 secs . percent increase needed = ( 620 - 576 / 620 ) * 100 = 44 / 640 * 100 = 7 % . ans ( c ) ." | physics |
math_qa__Q21laK6OmBjqDQtW | An amount of money is to be divided between P, Q and R in the ratio of 3:7:12. If the difference between the shares of P and Q is Rs.3200, what will be the difference between Q and R's share? Answers: A) 2788 B) 4000 C) 7282 D) 2782 E) 2729 | <gadget id="calculator">12 - 7</gadget>
<output>5</output>
<gadget id="calculator">7 - 3</gadget>
<output>4</output>
<gadget id="calculator">3_200 / 4</gadget>
<output>800</output>
<gadget id="calculator">5 * 800</gadget>
<output>4_000</output>
<result>B</result> | B | 4,000 | An amount of money is to be divided between P, Q and R in the ratio of 3:7:12. If the difference between the shares of P and Q is Rs.3200, what will be the difference between Q and R's share? | {
"A": "2788",
"B": "4000",
"C": "7282",
"D": "2782",
"E": "2729"
} | multiply(subtract(12, 7), divide(3200, subtract(7, 3))) | subtract(n1,n0)|subtract(n2,n1)|divide(n3,#0)|multiply(#2,#1)| | "4 - - - 3200 5 - - - ? = > 4000 answer : b" | general |
math_qa__evQbfnYDop1E20KC | John purchased a grinder and a mobile for Rs. 15000 &Rs. 8000 respectively. He sold the grinder at a loss of 4% and the mobile phone at a profit of 15%. Overall how much he make a profit.
Choose the correct choice from the following options:
A) s . 90 B) s . 620 C) s . 600 D) s . 650 E) s . 690 | <gadget id="calculator">8_000 / 100</gadget>
<output>80</output>
<gadget id="calculator">15 * 80</gadget>
<output>1_200</output>
<gadget id="calculator">15_000 / 100</gadget>
<output>150</output>
<gadget id="calculator">4 * 150</gadget>
<output>600</output>
<gadget id="calculator">1_200 - 600</gadget>
<output>600</output>
<result>C</result> | C | 600 | John purchased a grinder and a mobile for Rs. 15000 &Rs. 8000 respectively. He sold the grinder at a loss of 4% and the mobile phone at a profit of 15%. Overall how much he make a profit. | {
"A": "s . 90",
"B": "s . 620",
"C": "s . 600",
"D": "s . 650",
"E": "s . 690"
} | subtract(multiply(15, divide(8000, const_100)), multiply(4, divide(15000, const_100))) | divide(n1,const_100)|divide(n0,const_100)|multiply(n3,#0)|multiply(n2,#1)|subtract(#2,#3)| | "let the sp of the refrigerator and the mobile phone be rs . r and rs . m respectively . r = 15000 ( 1 - 4 / 100 ) = 15000 - 600 m = 8000 ( 1 + 15 / 100 ) = 8000 + 120 total sp - total cp = r + m - ( 15000 + 8000 ) = - 600 + 1200 = rs . 600 as this is positive , an overall profit of rs . 600 was made . c" | gain |
math_qa__5vvvf0sGGmcGPQNC | In a kilometer race, A beats B by 50 meters or 20 seconds. What time does A take to complete the race? Choose the correct choice from the following:
A) 380 sec
B) 190 sec
C) 726 sec
D) 127 sec
E) 128 sec | <gadget id="calculator">1 * 1_000</gadget>
<output>1_000</output>
<gadget id="calculator">50 / 20</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">1_000 / (5/2)</gadget>
<output>400</output>
<gadget id="calculator">400 - 20</gadget>
<output>380</output>
<result>A</result> | A | 380 | In a kilometer race, A beats B by 50 meters or 20 seconds. What time does A take to complete the race? | {
"A": "380 sec",
"B": "190 sec",
"C": "726 sec",
"D": "127 sec",
"E": "128 sec"
} | subtract(divide(multiply(const_1, const_1000), divide(50, 20)), 20) | divide(n0,n1)|multiply(const_1,const_1000)|divide(#1,#0)|subtract(#2,n1)| | "time taken by b run 1000 meters = ( 1000 * 20 ) / 50 = 400 sec . time taken by a = 400 - 20 = 380 sec . answer : a" | physics |
math_qa__mq5lI9D5ZvDABDI5 | If I walk at 5 km/h, I miss the bus by 12 minutes. If I walk at 6 km/h, I reach 15 minutes before the arrival of the bus. How far I walk to reach the bus stand ? Choose the correct answer: A) 11.0 km B) 13.8 km C) 11.5 km D) 12.5 km E) 13.5 km | <gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">6 - 5</gadget>
<output>1</output>
<gadget id="calculator">30 / 1</gadget>
<output>30</output>
<gadget id="calculator">12 + 15</gadget>
<output>27</output>
<gadget id="calculator">27 / 60</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">30 * (9/20)</gadget>
<output>27/2 = around 13.5</output>
<result>E</result> | E | 13.5 | If I walk at 5 km/h, I miss the bus by 12 minutes. If I walk at 6 km/h, I reach 15 minutes before the arrival of the bus. How far I walk to reach the bus stand ? | {
"A": "11.0 km",
"B": "13.8 km",
"C": "11.5 km",
"D": "12.5 km",
"E": "13.5 km"
} | multiply(divide(multiply(5, 6), subtract(6, 5)), divide(add(12, 15), const_60)) | add(n1,n3)|multiply(n0,n2)|subtract(n2,n0)|divide(#1,#2)|divide(#0,const_60)|multiply(#3,#4)| | "d = product of speed difference of time / difference of speed d = 5 x 6 / 60 [ 12 â ˆ ’ ( â ˆ ’ 15 ) / 6 - 5 ] [ here , â € “ ve sign indicates before the schedule time ] â ‡ ’ d = 13.5 km answer e" | physics |
math_qa__BJGe1eghe6WrrmCm | A rectangular tank needs to be coated with insulation. The tank has dimensions of 4 feet, 5 feet, and 3 feet. Each square foot of insulation costs $20. How much will it cost to cover the surface of the tank with insulation? Select the correct option
A) $ 1220 B) $ 1330 C) $ 1550 D) $ 1770 E) $ 1880 | <gadget id="calculator">2 * (4 * 5 + 5 * 3 + 4 * 3)</gadget>
<output>94</output>
<gadget id="calculator">94 * 20</gadget>
<output>1_880</output>
<result>E</result> | E | 1,880 | A rectangular tank needs to be coated with insulation. The tank has dimensions of 4 feet, 5 feet, and 3 feet. Each square foot of insulation costs $20. How much will it cost to cover the surface of the tank with insulation? | {
"A": "$ 1220",
"B": "$ 1330",
"C": "$ 1550",
"D": "$ 1770",
"E": "$ 1880"
} | multiply(surface_rectangular_prism(4, 5, 3), 20) | surface_rectangular_prism(n0,n1,n2)|multiply(n3,#0)| | "the total surface area is 2 ( 3 * 4 + 4 * 5 + 3 * 5 ) = 94 square feet the total cost is 94 * $ 20 = $ 1880 the answer is e ." | geometry |
math_qa__rUDY4U4VM807LP0H | A sum of money deposited at C.I. amounts to Rs.3650 in 2 years and to Rs.4015 in 3 years. Find the rate percent? Pick one
A) 10 % B) 15 % C) 20 % D) 25 % E) 30 % | <gadget id="calculator">4_015 - 3_650</gadget>
<output>365</output>
<gadget id="calculator">365 / 3_650</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 100</gadget>
<output>10</output>
<result>A</result> | A | 10 | A sum of money deposited at C.I. amounts to Rs.3650 in 2 years and to Rs.4015 in 3 years. Find the rate percent? | {
"A": "10 %",
"B": "15 %",
"C": "20 %",
"D": "25 %",
"E": "30 %"
} | multiply(divide(subtract(4015, 3650), 3650), const_100) | subtract(n2,n0)|divide(#0,n0)|multiply(#1,const_100)| | "explanation : 3650 - - - - - - - - 365 100 - - - - - - - - ? ( 10 % ) answer : option a" | gain |
math_qa__g2N1f6pUJHCInkx2 | If 5 - 5/X = 4 + 4/X, then X = Choices: A) 1 B) 9 C) - 1 D) 5 / 4 E) - 4 / 5 | <gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">9 / 1</gadget>
<output>9</output>
<result>B</result> | B | 9 | If 5 - 5/X = 4 + 4/X, then X = | {
"A": "1",
"B": "9",
"C": "- 1",
"D": "5 / 4",
"E": "- 4 / 5"
} | divide(add(4, 5), subtract(5, 4)) | add(n3,n1)|subtract(n0,n2)|divide(#0,#1)| | "we ' re given the equation 5 - 5 / x = 4 + 4 / x . we ' re asked for the value of x . the common - denominator of these 4 numbers is x , so we need to multiply both sides of the equation by x , giving us . . . 5 x - 5 x / x = 4 x + 4 x / x we can then eliminate that denominator , which gives us . . . . 5 x - 5 = 4 x + 4 9 = x b" | general |
math_qa__JDHmBgjn65OVANEh | Two trains are moving in opposite direction @ 60 kmph and 90 kmph.Their lengths are 1.10 km and 0.9 km respectively.The time taken by the slower train to cross the faster train in seconds is
Choose the correct choice.
A) 36 B) 45 C) 48 D) 49 E) 50 | <gadget id="calculator">1.1 + 0.9</gadget>
<output>2</output>
<gadget id="calculator">1_000 * 2</gadget>
<output>2_000</output>
<gadget id="calculator">60 + 90</gadget>
<output>150</output>
<gadget id="calculator">1_000 / 3_600</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">150 * (5/18)</gadget>
<output>125/3 = around 41.666667</output>
<gadget id="calculator">1 / (125/3)</gadget>
<output>3/125 = around 0.024</output>
<gadget id="calculator">2_000 * (3/125)</gadget>
<output>48</output>
<result>C</result> | C | 48 | Two trains are moving in opposite direction @ 60 kmph and 90 kmph.Their lengths are 1.10 km and 0.9 km respectively.The time taken by the slower train to cross the faster train in seconds is | {
"A": "36",
"B": "45",
"C": "48",
"D": "49",
"E": "50"
} | multiply(multiply(const_1000, add(1.1, 0.9)), inverse(multiply(add(60, 90), divide(const_1000, const_3600)))) | add(n0,n1)|add(n2,n3)|divide(const_1000,const_3600)|multiply(#0,#2)|multiply(#1,const_1000)|inverse(#3)|multiply(#5,#4) | r . s = ( 60 + 90 ) kmph = > ( 150 * 5 / 18 ) m / sec = > ( 125 / 3 ) m / sec distance covered = ( 1.10 + 0.9 ) km = ( 2 * 1000 ) = 2000 m . required time = ( 2000 * 3 / 125 ) = 48 sec . answer : c | physics |
math_qa__cGqCjwwwRmTchYP0 | A sum amounts to Rs.8820 in 2 years at the rate of 5% p.a. If interest was compounded yearly then what was the principal?
Select: A) s . 4000 B) s . 5000 C) s . 4500 D) s . 4800 E) s . 8000 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">8_820 / (441/400)</gadget>
<output>8_000</output>
<result>E</result> | E | 8,000 | A sum amounts to Rs.8820 in 2 years at the rate of 5% p.a. If interest was compounded yearly then what was the principal? | {
"A": "s . 4000",
"B": "s . 5000",
"C": "s . 4500",
"D": "s . 4800",
"E": "s . 8000"
} | divide(8820, power(add(divide(5, const_100), const_1), 2)) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|divide(n0,#2)| | "ci = 8820 , r = 5 , n = 2 ci = p [ 1 + r / 100 ] ^ 2 = p [ 1 + 5 / 100 ] ^ 2 8820 = p [ 21 / 20 ] ^ 2 8820 [ 20 / 21 ] ^ 2 8000 answer : e" | gain |
math_qa__RFeNQYSAk24ryi20 | A gardener wants to plant trees in his garden in rows in such a way that the number of trees in each row to be the same. If there are 24 rows the number of trees in each row is 42 if there are 12 more rows find the number of trees in each row? Pick one
A) 21 B) 28 C) 34 D) 32 E) 76 | <gadget id="calculator">24 * 42</gadget>
<output>1_008</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">1_008 / 36</gadget>
<output>28</output>
<result>B</result> | B | 28 | A gardener wants to plant trees in his garden in rows in such a way that the number of trees in each row to be the same. If there are 24 rows the number of trees in each row is 42 if there are 12 more rows find the number of trees in each row? | {
"A": "21",
"B": "28",
"C": "34",
"D": "32",
"E": "76"
} | divide(multiply(24, 42), add(24, 12)) | add(n0,n2)|multiply(n0,n1)|divide(#1,#0) | required number of trees = 24 / 36 * 42 = 28 . answer : b | general |
math_qa__aJBkhOKAqNwtRKJQ | A contractor undertook to do a piece of work in 10 days. He employed certain number of laboures but 5 of them were absent from the very first day and the rest could finish the work in only 13 days. Find the number of men originally employed ?
Choose the correct choice.
A) 21.6
B) 23.6
C) 22.6
D) 21.8
E) 21.3 | <gadget id="calculator">13 * 5</gadget>
<output>65</output>
<gadget id="calculator">13 - 10</gadget>
<output>3</output>
<gadget id="calculator">65 / 3</gadget>
<output>65/3 = around 21.666667</output>
<result>A</result> | A | 21.6 | A contractor undertook to do a piece of work in 10 days. He employed certain number of laboures but 5 of them were absent from the very first day and the rest could finish the work in only 13 days. Find the number of men originally employed ? | {
"A": "21.6",
"B": "23.6",
"C": "22.6",
"D": "21.8",
"E": "21.3"
} | divide(multiply(13, 5), subtract(13, 10)) | multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "let the number of men originally employed be x . 10 x = 13 ( x â € “ 5 ) or x = 21.6 answer a" | physics |
math_qa__YSDiYyH40ZyhU143 | In a race where 16 cars are running, the chance that car X will win is 1/4, that Y will win is 1/12 and that Z will win is 1/7. Assuming that a dead heat is impossible, find the chance that one of them will win.
Select the correct option
A) 1 / 140
B) 10 / 21
C) 27 / 410
D) 11 / 21
E) 57 / 120 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/4) + (1/12)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">(1/3) + (1/7)</gadget>
<output>10/21 = around 0.47619</output>
<result>B</result> | B | 0.47619 | In a race where 16 cars are running, the chance that car X will win is 1/4, that Y will win is 1/12 and that Z will win is 1/7. Assuming that a dead heat is impossible, find the chance that one of them will win. | {
"A": "1 / 140",
"B": "10 / 21",
"C": "27 / 410",
"D": "11 / 21",
"E": "57 / 120"
} | add(add(divide(1, 4), divide(1, 12)), divide(1, 7)) | divide(n1,n2)|divide(n1,n4)|divide(n1,n6)|add(#0,#1)|add(#3,#2)| | "required probability = p ( x ) + p ( y ) + p ( z ) ( all the events are mutually exclusive ) . = 1 / 4 + 1 / 12 + 1 / 7 = 10 / 21 answer : b" | general |
math_qa__l3iPzZ8qblIUP2d1 | A 20% stock yielding 10% is quoted at : Options.
A) 83.33
B) 110
C) 200
D) 120
E) 160 | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">10 * 20</gadget>
<output>200</output>
<result>C</result> | C | 200 | A 20% stock yielding 10% is quoted at : | {
"A": "83.33",
"B": "110",
"C": "200",
"D": "120",
"E": "160"
} | multiply(divide(const_100, 10), 20) | divide(const_100,n1)|multiply(n0,#0)| | "solution to earn rs . 10 , money invested = rs . 100 . to earn rs . 20 , money invested = rs . ( 100 / 10 x 20 ) = rs . 200 . â ˆ ´ market value of rs . 100 stock = rs . 200 answer c" | gain |
math_qa__yXsOaTnuBZaQinDZ | A cricket player whose bowling average was 24.50 runs per wicket, takes 5 wicket for 52 runs in a match. Due to this his average decreases by 0.50. What will be the number of wickets taken by him till the last match?
Choose the correct choice from the following: A) 64 B) 72 C) 141 D) 96 E) 108 | <gadget id="calculator">24.5 - 0.5</gadget>
<output>24</output>
<gadget id="calculator">24 * 5</gadget>
<output>120</output>
<gadget id="calculator">120 - 52</gadget>
<output>68</output>
<gadget id="calculator">68 / 0.5</gadget>
<output>136</output>
<result>C</result> | C | 141 | A cricket player whose bowling average was 24.50 runs per wicket, takes 5 wicket for 52 runs in a match. Due to this his average decreases by 0.50. What will be the number of wickets taken by him till the last match? | {
"A": "64",
"B": "72",
"C": "141",
"D": "96",
"E": "108"
} | divide(subtract(multiply(subtract(24.50, 0.50), 5), 52), 0.50) | subtract(n0,n3)|multiply(n1,#0)|subtract(#1,n2)|divide(#2,n3)| | "average = total runs / total wickets total runs after last match = 24.50 w + 52 total wickets after last match = w + 5 ( 24.50 w + 52 ) / ( w + 5 ) = 24.5 - 0.50 = 24 w = 136 so total wickets aftr last match = w + 5 = 141 answer : c" | general |
math_qa__xRHQfjZrkA8yPhbE | A polling company found that, of 300 households surveyed, 120 spent at least $100 per month on both gasoline and electricity, 60 spent at least $100 per month on gasoline but not on electricity, and for every household that did not spend at least $100 per month on gasoline or electricity, 4 spent at least $100 per month on electricity but not on gasoline. How many of the 300 households did not spend at least $100 per month on either gasoline or electricity? Options:
A) 24 B) 30 C) 36 D) 90 E) 96 | <gadget id="calculator">120 + 60</gadget>
<output>180</output>
<gadget id="calculator">300 - 180</gadget>
<output>120</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">120 / 5</gadget>
<output>24</output>
<result>A</result> | A | 24 | A polling company found that, of 300 households surveyed, 120 spent at least $100 per month on both gasoline and electricity, 60 spent at least $100 per month on gasoline but not on electricity, and for every household that did not spend at least $100 per month on gasoline or electricity, 4 spent at least $100 per month on electricity but not on gasoline. How many of the 300 households did not spend at least $100 per month on either gasoline or electricity? | {
"A": "24",
"B": "30",
"C": "36",
"D": "90",
"E": "96"
} | divide(subtract(300, add(120, 60)), add(4, const_1)) | add(n1,n3)|add(n6,const_1)|subtract(n0,#0)|divide(#2,#1) | 120 spend $ 100 on gas & electricity 60 spend $ 100 on gas but not on electricity for every one that spent < $ 100 on both there are 4 that spent $ 100 on electricity not gas let the ones that spent on neither be x the ones that spent on just electricity will be 4 x total households = those who spend > $ 100 on both + those who spend > $ 100 on just one + those who spend < $ 100 on both = 120 + 60 + 4 x + x 300 = 180 + 5 x implies x = 24 answer is ( a ) | other |
math_qa__7MTBtGnSJJWEHRrL | The cash realised on selling a 14% stock is Rs.107.25, brokerage being 1/4% is?
Choose one
A) 366 B) 107 C) 102 D) 192 E) 122 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">107.25 - (1/4)</gadget>
<output>107</output>
<result>B</result> | B | 107 | The cash realised on selling a 14% stock is Rs.107.25, brokerage being 1/4% is? | {
"A": "366",
"B": "107",
"C": "102",
"D": "192",
"E": "122"
} | subtract(107.25, divide(1, 4)) | divide(n2,n3)|subtract(n1,#0)| | "cash realised = rs . ( 107.25 - 0.25 ) = rs . 107 . answer : b" | general |
math_qa__xuLF6oz9IwVDi8nD | A shopkeeper sold an article offering a discount of 5% and earned a profit of 38.7%. What would have been the percentage of profit earned if no discount had been offered?
Choose the correct choice from the following answers.
A) 28.5 B) 46 C) 30 D) data inadequate E) none of these | <gadget id="calculator">100 + 38.7</gadget>
<output>138.7</output>
<gadget id="calculator">138.7 * 100</gadget>
<output>13_870</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">13_870 / 95</gadget>
<output>146</output>
<gadget id="calculator">146 - 100</gadget>
<output>46</output>
<result>B</result> | B | 46 | A shopkeeper sold an article offering a discount of 5% and earned a profit of 38.7%. What would have been the percentage of profit earned if no discount had been offered? | {
"A": "28.5",
"B": "46",
"C": "30",
"D": "data inadequate",
"E": "none of these"
} | subtract(divide(multiply(add(const_100, 38.7), const_100), subtract(const_100, 5)), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,const_100)|divide(#2,#1)|subtract(#3,const_100)| | "giving no discount to customer implies selling the product on printed price . suppose the cost price of the article is 100 . then printed price = 100 ã — ( 100 + 38.7 ) / ( 100 â ˆ ’ 5 ) = 146 hence , required % profit = 146 â € “ 100 = 46 % answer b" | gain |
math_qa__PNdH7k5dVj5dL1dY | The price of rice is reduced by 2%. How many kilograms of rice can now be bought for the money which was sufficient to buy 49 kg of rice earlier? Answers: A) 48 kg B) 49 kg C) 50 kg D) 51 kg E) none | <gadget id="calculator">100 * 49</gadget>
<output>4_900</output>
<gadget id="calculator">100 - 2</gadget>
<output>98</output>
<gadget id="calculator">4_900 / 98</gadget>
<output>50</output>
<result>C</result> | C | 50 | The price of rice is reduced by 2%. How many kilograms of rice can now be bought for the money which was sufficient to buy 49 kg of rice earlier? | {
"A": "48 kg",
"B": "49 kg",
"C": "50 kg",
"D": "51 kg",
"E": "none"
} | divide(multiply(const_100, 49), subtract(const_100, const_2)) | multiply(n1,const_100)|subtract(const_100,const_2)|divide(#0,#1) | sol . let the original price be rs . 100 per kg . money required to buy 49 kg of rice = rs . ( 100 x 49 ) = rs . 4900 . new price = rs . 98 per kg . ∴ quantity of rice bought = [ 4900 / 98 ] kg = 50 kg . answer c | other |
math_qa__UW3hTWwiJp1UKXSs | Set A contains all the even numbers between 10 and 50 inclusive. Set B contains all the even numbers between 110 and 150 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A? Select:
A) 2100 B) 2550 C) 5050 D) 6275 E) 11325 | <gadget id="calculator">110 - 10</gadget>
<output>100</output>
<gadget id="calculator">50 - 10</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">100 * 21</gadget>
<output>2_100</output>
<result>A</result> | A | 2,100 | Set A contains all the even numbers between 10 and 50 inclusive. Set B contains all the even numbers between 110 and 150 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A? | {
"A": "2100",
"B": "2550",
"C": "5050",
"D": "6275",
"E": "11325"
} | multiply(subtract(110, 10), add(divide(subtract(50, 10), const_2), const_1)) | subtract(n1,n0)|subtract(n2,n0)|divide(#0,const_2)|add(#2,const_1)|multiply(#3,#1)| | "set a contains 10 , 12,14 , 16 . . . 50 set b contains 110 , 112 , 114 . . . 150 number of terms in each set = 21 difference between corresponding terms in set a and b = 100 difference between sum of set b and set a = 100 * 21 = 2100 answer a" | general |
math_qa__xfEa8djjIXPcguSo | What is the number of integers from 1 to 1000 (inclusive) that are divisible by neither 15 nor by 20? Choose the correct choice
A) 887
B) 678
C) 765
D) 345
E) 256 | <gadget id="calculator">1_000 / 15</gadget>
<output>200/3 = around 66.666667</output>
<gadget id="calculator">1_000 / 20</gadget>
<output>50</output>
<gadget id="calculator">(200/3) + 50</gadget>
<output>350/3 = around 116.666667</output>
<gadget id="calculator">15 * 20</gadget>
<output>300</output>
<gadget id="calculator">1_000 / 300</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">(350/3) - (10/3)</gadget>
<output>340/3 = around 113.333333</output>
<gadget id="calculator">1_000 - (340/3)</gadget>
<output>2_660/3 = around 886.666667</output>
<result>A</result> | A | 887 | What is the number of integers from 1 to 1000 (inclusive) that are divisible by neither 15 nor by 20? | {
"A": "887",
"B": "678",
"C": "765",
"D": "345",
"E": "256"
} | subtract(1000, subtract(add(divide(1000, 15), divide(1000, 20)), divide(1000, multiply(15, 20)))) | divide(n1,n2)|divide(n1,n3)|multiply(n2,n3)|add(#0,#1)|divide(n1,#2)|subtract(#3,#4)|subtract(n1,#5)| | "in 1000 consecutive numbers , number of multiples of 15 = 1000 / 15 = 66 ( ignore decimals ) in 1000 consecutive numbers , number of multiples of 20 = 1000 / 20 = 50 number of multiples of 15 * 20 i . e . 300 = 1000 / 300 = 3 number of integers from 1 to 1000 that are divisible by neither 15 nor by 20 = 1000 - ( 66 + 50 - 3 ) { using the concept of sets here ) = 887 answer is a" | other |
math_qa__ZZW5bWyViIhEFKWJ | If x is an integer such that 5 < x < 21, 7 < x < 18, 13 > x > 2, 12 > x > 9, and x + 1 < 13, then x is Pick: A) 3 B) 5 C) 7 D) 9 E) 11 | <gadget id="calculator">13 - 1</gadget>
<output>12</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<result>E</result> | E | 11 | If x is an integer such that 5 < x < 21, 7 < x < 18, 13 > x > 2, 12 > x > 9, and x + 1 < 13, then x is | {
"A": "3",
"B": "5",
"C": "7",
"D": "9",
"E": "11"
} | subtract(subtract(13, 1), 1) | subtract(n4,n8)|subtract(#0,n8) | 5 < x < 21 , 7 < x < 18 , 2 < x < 13 9 < x < 12 x < 13 from above : 10 < x < 12 - - > x = 11 . answer : e . | general |
math_qa__UWPzkLg9drmFxFuB | The denominator of a fraction is 15 greater than the numerator. If the numerator and the denominator are increased by 3, the resulting fraction is equal to 3â„4. What is the value of the original fraction?
Choose the correct answer:
A) 23 / 38 B) 29 / 44 C) 33 / 48 D) 38 / 53 E) 42 / 57 | <gadget id="calculator">3 + 15</gadget>
<output>18</output>
<gadget id="calculator">3 * 18</gadget>
<output>54</output>
<gadget id="calculator">54 - 4</gadget>
<output>50</output>
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">50 / 1</gadget>
<output>50</output>
<gadget id="calculator">50 + 15</gadget>
<output>65</output>
<gadget id="calculator">50 / 65</gadget>
<output>10/13 = around 0.769231</output>
<result>E</result> | E | 0.736842 | The denominator of a fraction is 15 greater than the numerator. If the numerator and the denominator are increased by 3, the resulting fraction is equal to 3â„4. What is the value of the original fraction? | {
"A": "23 / 38",
"B": "29 / 44",
"C": "33 / 48",
"D": "38 / 53",
"E": "42 / 57"
} | divide(divide(subtract(multiply(3, add(3, 15)), 4), subtract(4, 3)), add(divide(subtract(multiply(3, add(3, 15)), 4), subtract(4, 3)), 15)) | add(n0,n1)|subtract(n3,n2)|multiply(n2,#0)|subtract(#2,n3)|divide(#3,#1)|add(n0,#4)|divide(#4,#5)| | "let the numerator be x . then the denominator is x + 15 . x + 3 / x + 18 = 3 / 4 . 4 x + 12 = 3 x + 54 . x = 42 . the original fraction is 42 / 57 . the answer is e ." | general |
math_qa__ZHH3Cf06avTD3tEG | A grocer has a sale of Rs. 6345, Rs. 6927, Rs.6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
Choices.
A) rs . 3000
B) rs . 4991
C) rs . 5991
D) rs . 6001
E) none | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 6_500</gadget>
<output>39_000</output>
<gadget id="calculator">6_345 + 6_927</gadget>
<output>13_272</output>
<gadget id="calculator">13_272 + 6_855</gadget>
<output>20_127</output>
<gadget id="calculator">20_127 + 7_230</gadget>
<output>27_357</output>
<gadget id="calculator">27_357 + 6_562</gadget>
<output>33_919</output>
<gadget id="calculator">39_000 - 33_919</gadget>
<output>5_081</output>
<result>B</result> | B | 4,991 | A grocer has a sale of Rs. 6345, Rs. 6927, Rs.6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500? | {
"A": "rs . 3000",
"B": "rs . 4991",
"C": "rs . 5991",
"D": "rs . 6001",
"E": "none"
} | subtract(multiply(add(5, const_1), 6500), add(add(add(add(6345, 6927), 6855), 7230), 6562)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "sol . total sale for 5 months = rs . ( 6435 + 6927 + 6855 + 7230 + 6562 ) = rs . 34009 . ∴ required sale = rs . [ ( 6500 x 6 ) - 34009 ] = rs . ( 39000 - 34009 ) = rs . 4991 . answer b" | general |
math_qa__Yv1t5GEzn1nKoyJh | At Deluxe paint store, Fuchsia paint is made by mixing 4 parts of red paint with 2 parts of blue paint. Mauve paint is made by mixing 3 parts of red paint with 6 parts blue paint. How many liters of blue paint must be added to 24 liters of Fuchsia to change it to Mauve paint?
Choose the correct option
A) 9 B) 12 C) 15 D) 16 E) 24 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">24 * (2/3)</gadget>
<output>16</output>
<gadget id="calculator">3 / 6</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">16 / (1/2)</gadget>
<output>32</output>
<gadget id="calculator">6 / 6</gadget>
<output>1</output>
<gadget id="calculator">32 * 1</gadget>
<output>32</output>
<gadget id="calculator">24 - 16</gadget>
<output>8</output>
<gadget id="calculator">32 - 8</gadget>
<output>24</output>
<result>E</result> | E | 24 | At Deluxe paint store, Fuchsia paint is made by mixing 4 parts of red paint with 2 parts of blue paint. Mauve paint is made by mixing 3 parts of red paint with 6 parts blue paint. How many liters of blue paint must be added to 24 liters of Fuchsia to change it to Mauve paint? | {
"A": "9",
"B": "12",
"C": "15",
"D": "16",
"E": "24"
} | subtract(multiply(divide(multiply(24, divide(4, add(4, 2))), divide(3, add(4, 2))), divide(6, add(4, 2))), subtract(24, multiply(24, divide(4, add(4, 2))))) | add(n0,n1)|divide(n0,#0)|divide(n2,#0)|divide(n3,#0)|multiply(n4,#1)|divide(#4,#2)|subtract(n4,#4)|multiply(#5,#3)|subtract(#7,#6)| | "in 24 liters , red = 4 / 6 * 24 = 16 and blue = 8 so , 16 / ( 8 + x ) = 3 / 6 or , x = 24 ( answer e )" | general |
math_qa__2Scz0poYXAmhBO5q | H.C.F of 136, 144 and a third number is 8 and their L.C.M is 2^4 * 3^2 * 17 * 7. The third number is:
Choices:
A) 154
B) 248
C) 360
D) 424
E) 168 | <gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">16 * 9</gadget>
<output>144</output>
<gadget id="calculator">144 * 17</gadget>
<output>2_448</output>
<gadget id="calculator">2_448 * 7</gadget>
<output>17_136</output>
<gadget id="calculator">8 * 17_136</gadget>
<output>137_088</output>
<gadget id="calculator">136 * 144</gadget>
<output>19_584</output>
<gadget id="calculator">137_088 / 19_584</gadget>
<output>7</output>
<gadget id="calculator">7 * 8</gadget>
<output>56</output>
<gadget id="calculator">56 * 3</gadget>
<output>168</output>
<result>E</result> | E | 168 | H.C.F of 136, 144 and a third number is 8 and their L.C.M is 2^4 * 3^2 * 17 * 7. The third number is: | {
"A": "154",
"B": "248",
"C": "360",
"D": "424",
"E": "168"
} | multiply(multiply(divide(multiply(8, multiply(multiply(multiply(power(2, 4), power(3, 2)), 17), 7)), multiply(136, 144)), 8), const_3) | multiply(n0,n1)|power(n3,n4)|power(n5,n3)|multiply(#1,#2)|multiply(n7,#3)|multiply(n8,#4)|multiply(n2,#5)|divide(#6,#0)|multiply(n2,#7)|multiply(#8,const_3) | 136 = 2 ^ 3 * 17 ; 144 = 2 ^ 4 * 3 ^ 2 h . c . f = 2 ^ 3 = 8 since h . c . f is the product of lowest powers of common factors , so the third number must have ( 2 ^ 3 ) as its factor . since l . c . m is the product of highest powers of common prime factors , so the third number must have 3 and 7 as its factors . third number = 2 ^ 3 * 3 * 7 = 168 answer : e | general |
math_qa__1TvI6EBK9PYno1q6 | From the beginning to the end of 2007, the price of a stock rose 20 percent. In 2008, it dropped 25 percent. In 2009, it rose 25 percent. What percent of the stock’s 2007 starting price was the price of the stock at the end of 2009? Choose the correct answer
A) 80 B) 90 C) 95 D) 100 E) 112.5 | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">100 * (6/5)</gadget>
<output>120</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">120 * (3/4)</gadget>
<output>90</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">90 * (5/4)</gadget>
<output>225/2 = around 112.5</output>
<result>E</result> | E | 112.5 | From the beginning to the end of 2007, the price of a stock rose 20 percent. In 2008, it dropped 25 percent. In 2009, it rose 25 percent. What percent of the stock’s 2007 starting price was the price of the stock at the end of 2009? | {
"A": "80",
"B": "90",
"C": "95",
"D": "100",
"E": "112.5"
} | multiply(multiply(multiply(const_100, divide(add(const_100, 20), const_100)), divide(subtract(const_100, 25), const_100)), divide(add(const_100, 25), const_100)) | add(n5,const_100)|add(n1,const_100)|subtract(const_100,n3)|divide(#0,const_100)|divide(#2,const_100)|divide(#1,const_100)|multiply(#5,const_100)|multiply(#4,#6)|multiply(#3,#7)| | "assume a value at the beginning of 2007 . as this is a % question , assume p = 100 . at the end of 2007 it becmae = 1.2 * 100 = 120 at the end of 2008 it decreased by 25 % = 120 * . 75 = 90 at the end of 2009 it increased by 25 % = 90 * 1.25 = 112.5 thus ratio = 112.5 / 100 = 1.125 ( in % terms = 12.5 % ) . thus e is the correct answer ." | gain |
math_qa__DWRpFD9spXpekp0f | Express a speed of 70 kmph in meters per second? Choose the correct choice from the following answers.
A) 10 mps B) 19.44 mps C) 97.44 mps D) 17.44 mps E) 18.44 mps | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 70</gadget>
<output>175/9 = around 19.444444</output>
<result>B</result> | B | 19.44 | Express a speed of 70 kmph in meters per second? | {
"A": "10 mps",
"B": "19.44 mps",
"C": "97.44 mps",
"D": "17.44 mps",
"E": "18.44 mps"
} | multiply(const_0_2778, 70) | multiply(n0,const_0_2778)| | "70 * 5 / 18 = 19.44 mps answer : b" | physics |
math_qa__ExjmPH6TRg82x6Qs | If n = (33)^43 + (43)^32 what is the units digit of n? Select.
A) 0 B) 2 C) 4 D) 6 E) 8 | <gadget id="calculator">33 % 10</gadget>
<output>3</output>
<gadget id="calculator">43 % 4</gadget>
<output>3</output>
<gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">43 % 10</gadget>
<output>3</output>
<gadget id="calculator">3 ** 4</gadget>
<output>81</output>
<gadget id="calculator">27 + 81</gadget>
<output>108</output>
<gadget id="calculator">108 % 100</gadget>
<output>8</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<result>B</result> | B | 2 | If n = (33)^43 + (43)^32 what is the units digit of n? | {
"A": "0",
"B": "2",
"C": "4",
"D": "6",
"E": "8"
} | subtract(reminder(add(power(reminder(33, const_10), reminder(43, const_4)), power(reminder(43, const_10), const_4)), const_100), multiply(const_2, const_3)) | multiply(const_2,const_3)|reminder(n0,const_10)|reminder(n1,const_4)|reminder(n1,const_10)|power(#1,#2)|power(#3,const_4)|add(#4,#5)|reminder(#6,const_100)|subtract(#7,#0) | first of all , the units digit of ( 33 ) ^ 43 is the same as that of 3 ^ 43 and the units digit of ( 43 ) ^ 32 is the same as that of 3 ^ 32 . so , we need to find the units digit of 3 ^ 43 + 3 ^ 33 . next , the units digit of 3 in positive integer power repeats in blocks of four { 3 , 9 , 7 , 1 } : 3 ^ 1 = 3 ( the units digit is 3 ) 3 ^ 2 = 9 ( the units digit is 9 ) 3 ^ 3 = 27 ( the units digit is 7 ) 3 ^ 4 = 81 ( the units digit is 1 ) 3 ^ 5 = 243 ( the units digit is 3 again ! ) . . . thus : the units digit of 3 ^ 43 is the same as the units digit of 3 ^ 3 , so 7 ( 43 divided by the cyclicity of 4 gives the remainder of 3 ) . the units digit of 3 ^ 33 is the same as the units digit of 3 ^ 1 , so 3 ( 33 divided by the cyclicity of 4 gives the remainder of 1 ) . therefore the units digit of ( 33 ) ^ 43 + ( 43 ) ^ 32 is 7 + 5 = 2 . answer : b . | general |
math_qa__f4BTrwm7kb05uZLw | On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 20 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets? Choose the correct choice from the following choices: A) 20 % B) 25 % C) 30 % D) 35 % E) 40 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">20 / (4/5)</gadget>
<output>25</output>
<result>B</result> | B | 25 | On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 20 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets? | {
"A": "20 %",
"B": "25 %",
"C": "30 %",
"D": "35 %",
"E": "40 %"
} | divide(20, subtract(const_1, divide(20, const_100))) | divide(n1,const_100)|subtract(const_1,#0)|divide(n0,#1)| | "let t be the total number of passengers . let x be the number of people with round trip tickets . 0.2 t had round trip tickets and took their cars . 0.8 x had round trip tickets and took their cars . 0.8 x = 0.2 t x = 0.25 t the answer is b ." | gain |
math_qa__YhV1oMqOuU71VUbK | A train running at the speed of 126 km/hr crosses a pole in 9 seconds. Find the length of the train.
Choose the correct choice from the following answers:
A) 150 meter
B) 286 meter
C) 186 meter
D) 315 meter
E) 265 meter | <gadget id="calculator">126 * 1_000</gadget>
<output>126_000</output>
<gadget id="calculator">126_000 / 3_600</gadget>
<output>35</output>
<gadget id="calculator">35 * 9</gadget>
<output>315</output>
<result>D</result> | D | 315 | A train running at the speed of 126 km/hr crosses a pole in 9 seconds. Find the length of the train. | {
"A": "150 meter",
"B": "286 meter",
"C": "186 meter",
"D": "315 meter",
"E": "265 meter"
} | multiply(divide(multiply(126, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 126 * ( 5 / 18 ) m / sec = 35 m / sec length of train ( distance ) = speed * time ( 35 ) * 9 = 315 meter answer : d" | physics |
math_qa__cCVedBcE6o7C4ZWt | What is the smallest number which when diminished by 20, is divisible 15, 30, 45 and 60? Choose the correct choice from the following answers.
A) 200 B) 220 C) 240 D) 322 E) 342 | <gadget id="calculator">lcm(15, 30)</gadget>
<output>30</output>
<gadget id="calculator">lcm(45, 60)</gadget>
<output>180</output>
<gadget id="calculator">lcm(30, 180)</gadget>
<output>180</output>
<gadget id="calculator">180 + 20</gadget>
<output>200</output>
<result>A</result> | A | 200 | What is the smallest number which when diminished by 20, is divisible 15, 30, 45 and 60? | {
"A": "200",
"B": "220",
"C": "240",
"D": "322",
"E": "342"
} | add(lcm(lcm(15, 30), lcm(45, 60)), 20) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|add(n0,#2)| | "required number = ( lcm of 15 , 30 , 45 and 60 ) + 20 = 180 + 20 = 200 option a" | general |
math_qa__lRmPk7bZTv0MElKz | Mrs. Evans gave a test to her freshmen economics class, which has 25 students enrolled and 22 of them answered question 1 correctly. If 20 answered question 2 correctly and 3 did not take the test then how many answered both questions correctly? Select the correct option
A) 30
B) 20
C) 23
D) 17
E) 19 | <gadget id="calculator">22 + 20</gadget>
<output>42</output>
<gadget id="calculator">42 + 3</gadget>
<output>45</output>
<gadget id="calculator">45 - 25</gadget>
<output>20</output>
<result>B</result> | B | 20 | Mrs. Evans gave a test to her freshmen economics class, which has 25 students enrolled and 22 of them answered question 1 correctly. If 20 answered question 2 correctly and 3 did not take the test then how many answered both questions correctly? | {
"A": "30",
"B": "20",
"C": "23",
"D": "17",
"E": "19"
} | subtract(add(add(22, 20), 3), 25) | add(n1,n3)|add(n5,#0)|subtract(#1,n0)| | "total number of enrolled students = 25 number of students who did not take test = 3 hence , number of students who took test = 25 - 3 = 22 number of students who answered q 2 correctly = 20 , therefore , all students who took test answered q 2 correctly . so , number of students who answered q 1 correctly , also answered q 2 correctly = 20 . number of students who answered both q 1 & q 2 correctly = 20 . answer : b" | other |
math_qa__xHdvOr9043Un9yTe | In two alloys, copper and tin are related in the ratios of 4:1 and 1:3. 10kg of Ist alloy, 16 kg of 2nd alloy and some pure copper melted together. An alloy obtained in which the ratio of copper and tin was 3:2. Find the weight of the new alloy.
Pick one:
A) 34 kg B) 35 kg C) 36 kg D) 30 kg E) 32 kg | <gadget id="calculator">10 + 16</gadget>
<output>26</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">16 * (3/4)</gadget>
<output>12</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">10 / 5</gadget>
<output>2</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<gadget id="calculator">14 * 3</gadget>
<output>42</output>
<gadget id="calculator">42 / 2</gadget>
<output>21</output>
<gadget id="calculator">21 - 12</gadget>
<output>9</output>
<gadget id="calculator">26 + 9</gadget>
<output>35</output>
<result>B</result> | B | 35 | In two alloys, copper and tin are related in the ratios of 4:1 and 1:3. 10kg of Ist alloy, 16 kg of 2nd alloy and some pure copper melted together. An alloy obtained in which the ratio of copper and tin was 3:2. Find the weight of the new alloy. | {
"A": "34 kg",
"B": "35 kg",
"C": "36 kg",
"D": "30 kg",
"E": "32 kg"
} | add(add(10, 16), subtract(divide(multiply(add(multiply(16, divide(3, 4)), divide(10, add(4, 1))), 3), 2), multiply(16, divide(3, 4)))) | add(n4,n5)|add(n0,n1)|divide(n3,n0)|divide(n4,#1)|multiply(n5,#2)|add(#3,#4)|multiply(n3,#5)|divide(#6,n6)|subtract(#7,#4)|add(#0,#8) | suppose x kg of pure copper is melted with 10 kg of ist alloy and 16 kg of 2 nd alloy , then pure cooper in new alloy = 10 * 4 / 5 + 16 * 1 / 4 + x = 12 + x kg pure tin in new alloy = 10 * 1 / 5 + 16 * 3 / 4 = 14 kg as per given condition ( 12 + x ) / 14 = 3 / 2 24 + 2 x = 42 x = 9 kg total weight of new alloy = 10 + 16 + 9 = 35 kg answer : b | other |
math_qa__975QXXbH1ma2YqwR | A farmer planned to plough a field by doing 120 hectares a day. After two days of work he increased his daily productivity by 25% and he finished the job two days ahead of schedule.
a) What is the area of the field?
b) In how many days did the farmer get the job done?
c) In how many days did the farmer plan to get the job done? Choose the correct choice from the following answers: A) 2337 B) 2667 C) 1440 D) 2887 E) 2661 | <gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">120 * 25</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 100</gadget>
<output>30</output>
<gadget id="calculator">120 + 30</gadget>
<output>150</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">150 * 8</gadget>
<output>1_200</output>
<gadget id="calculator">240 + 1_200</gadget>
<output>1_440</output>
<result>C</result> | C | 1,440 | A farmer planned to plough a field by doing 120 hectares a day. After two days of work he increased his daily productivity by 25% and he finished the job two days ahead of schedule.
a) What is the area of the field?
b) In how many days did the farmer get the job done?
c) In how many days did the farmer plan to get the job done? | {
"A": "2337",
"B": "2667",
"C": "1440",
"D": "2887",
"E": "2661"
} | add(multiply(120, const_2), multiply(add(120, divide(multiply(120, 25), const_100)), multiply(const_4, const_2))) | multiply(n0,const_2)|multiply(n0,n1)|multiply(const_2,const_4)|divide(#1,const_100)|add(n0,#3)|multiply(#4,#2)|add(#0,#5) | first of all we will find the new daily productivity of the farmer in hectares per day : 25 % of 120 hectares is 25100 ⋅ 120 = 3025100 ⋅ 120 = 30 hectares , therefore 120 + 30 = 150120 + 30 = 150 hectares is the new daily productivity . lets x be the planned number of days allotted for the job . then the farm is 120 ⋅ x 120 ⋅ x hectares . on the other hand , we get the same area if we add 120 ⋅ 2120 ⋅ 2 hectares to 150 ( x − 4 ) 150 ( x − 4 ) hectares . then we get the equation 120 x = 120 ⋅ 2 + 150 ( x − 4 ) 120 x = 120 ⋅ 2 + 150 ( x − 4 ) x = 12 x = 12 so , the job was initially supposed to take 12 days , but actually the field was ploughed in 12 - 2 = 10 days . the field ' s area is 120 ⋅ 12 = 1440120 ⋅ 12 = 1440 hectares . answer : c | physics |
math_qa__vYxwI9Iem0OJcLTm | 12 men complete a work in 9 days. After they have worked for 6 days, 6 more men join them. How many days will they take to complete the remaining work? Choose the correct choice from the following.
A) 2 days B) 7 days C) 8 days D) 9 days E) 45 days | <gadget id="calculator">12 * 9</gadget>
<output>108</output>
<gadget id="calculator">12 * 6</gadget>
<output>72</output>
<gadget id="calculator">108 - 72</gadget>
<output>36</output>
<gadget id="calculator">12 + 6</gadget>
<output>18</output>
<gadget id="calculator">36 / 18</gadget>
<output>2</output>
<result>A</result> | A | 2 | 12 men complete a work in 9 days. After they have worked for 6 days, 6 more men join them. How many days will they take to complete the remaining work? | {
"A": "2 days",
"B": "7 days",
"C": "8 days",
"D": "9 days",
"E": "45 days"
} | divide(subtract(multiply(12, 9), multiply(12, 6)), add(12, 6)) | add(n0,n2)|multiply(n0,n1)|multiply(n0,n2)|subtract(#1,#2)|divide(#3,#0) | 1 man ' s 1 day work = 1 / 108 12 men ' s 6 day ' s work = 1 / 9 * 6 = 2 / 3 remaining work = 1 - 2 / 3 = 1 / 3 18 men ' s 1 day work = 1 / 108 * 18 = 1 / 6 1 / 6 work is done by them in 1 day . 1 / 3 work is done by them in 6 * 1 / 3 = 2 days . answer : a | physics |
math_qa__jdqHpfnlae9vCm7O | Joe has a total of $200 in his two pockets. He takes one fourth of the
money in his left pocket and puts it in his right pocket. He then takes
$20 from his left pocket and puts it in his right pocket. If he now has
an equal amount of money in each pocket, then how much money did he
originally have in his left pocket? Select the correct option
A) $ 120 B) $ 130 C) $ 140 D) $ 150 E) $ 160 | <gadget id="calculator">200 + 20</gadget>
<output>220</output>
<gadget id="calculator">220 + 20</gadget>
<output>240</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) + (3/4)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">240 / (3/2)</gadget>
<output>160</output>
<result>E</result> | E | 160 | Joe has a total of $200 in his two pockets. He takes one fourth of the
money in his left pocket and puts it in his right pocket. He then takes
$20 from his left pocket and puts it in his right pocket. If he now has
an equal amount of money in each pocket, then how much money did he
originally have in his left pocket? | {
"A": "$ 120",
"B": "$ 130",
"C": "$ 140",
"D": "$ 150",
"E": "$ 160"
} | divide(add(add(200, 20), 20), add(subtract(const_1, divide(const_1, const_4)), subtract(const_1, divide(const_1, const_4)))) | add(n0,n1)|divide(const_1,const_4)|add(n1,#0)|subtract(const_1,#1)|add(#3,#3)|divide(#2,#4) | joe had $ 100 in his left and $ 100 in his right pocket at the end . so , he had $ 120 in his left pocket ( and $ 80 in his right pocket ) before moving $ 20 from his left to his right pocket . thus , he had $ 160 in his left pocket originally ( solve x − x / 4 = 120 ) . correct answer e | general |
math_qa__0JWzHFccshPbiJrS | If 5 machines can produce 20 units in 10 hours, how long would it take 20 machines to produce 200 units?
Choose the correct choice from the following options
A) 50 hours B) 40 hours C) 25 hours D) 12 hours E) 8 hours | <gadget id="calculator">20 / 10</gadget>
<output>2</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 20</gadget>
<output>8</output>
<gadget id="calculator">200 / 8</gadget>
<output>25</output>
<result>C</result> | C | 25 | If 5 machines can produce 20 units in 10 hours, how long would it take 20 machines to produce 200 units? | {
"A": "50 hours",
"B": "40 hours",
"C": "25 hours",
"D": "12 hours",
"E": "8 hours"
} | divide(200, multiply(divide(divide(20, 10), 5), 20)) | divide(n1,n2)|divide(#0,n0)|multiply(n1,#1)|divide(n4,#2) | here , we ' re told that 5 machines can produce 20 units in 10 hours . . . . that means that each machine works for 10 hours apiece . since there are 5 machines ( and we ' re meant to assume that each machine does the same amount of work ) , then the 5 machines equally created the 20 units . 20 units / 5 machines = 4 units are made by each machine every 10 hours now that we know how long it takes each machine to make 4 units , we can break this down further if we choose to . . . 10 hours / 4 units = 2.5 hours per unit when 1 machine is working . the prompt asks us how long would it take 20 machines to produce 200 units . if 20 machines each work for 2.5 hours , then we ' ll have 20 units . since 200 units is ' 10 times ' 20 , we need ' 10 times ' more time . ( 2.5 hours ) ( 10 times ) = 25 hours final answer : [ reveal ] spoiler : c | physics |
math_qa__nXa417fuxAG4jnzL | The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 60 per cent. The two reductions together are equal to a single reduction of
Select the correct option
A) 45 % B) 70 % C) 35 % D) 32.5 % E) 30 % | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">(2/5) * 75</gadget>
<output>30</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<result>B</result> | B | 70 | The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 60 per cent. The two reductions together are equal to a single reduction of | {
"A": "45 %",
"B": "70 %",
"C": "35 %",
"D": "32.5 %",
"E": "30 %"
} | subtract(const_100, multiply(divide(subtract(const_100, 60), const_100), subtract(const_100, 25))) | subtract(const_100,n1)|subtract(const_100,n0)|divide(#0,const_100)|multiply(#2,#1)|subtract(const_100,#3)| | "price = p initially price reduced by 25 % which means new price is 3 / 4 p now on this new price further 60 percent is reduced which means the new price is merely 40 percent of 3 / 4 p = = > ( 3 / 4 ) x ( 2 / 5 ) p = 6 / 20 p is the new price after both deduction which is 30 percent of the original value p . this implies this entire series of deduction is worth having discounted 70 % of p . so answer is b = 70 %" | general |
math_qa__Xu1DxCBv96u4OKS8 | Given a number, there is an algorithm described here to find it's sum and number of factors. For example, let us take the number 1225? Choose the correct choice.
A) 1767
B) 1800
C) 1812
D) 1890
E) none | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">1 + 7</gadget>
<output>8</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">1_225 / 5</gadget>
<output>245</output>
<gadget id="calculator">245 / 5</gadget>
<output>49</output>
<gadget id="calculator">8 + 49</gadget>
<output>57</output>
<gadget id="calculator">1 + 5</gadget>
<output>6</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">6 + 25</gadget>
<output>31</output>
<gadget id="calculator">57 * 31</gadget>
<output>1_767</output>
<result>A</result> | A | 1,767 | Given a number, there is an algorithm described here to find it's sum and number of factors. For example, let us take the number 1225? | {
"A": "1767",
"B": "1800",
"C": "1812",
"D": "1890",
"E": "none"
} | multiply(add(add(const_1, add(const_3, const_4)), divide(divide(1225, add(const_2, const_3)), add(const_2, const_3))), add(add(const_1, add(const_2, const_3)), power(add(const_2, const_3), const_2))) | add(const_3,const_4)|add(const_2,const_3)|add(#0,const_1)|add(#1,const_1)|divide(n0,#1)|power(#1,const_2)|add(#3,#5)|divide(#4,#1)|add(#2,#7)|multiply(#8,#6) | solving for 1225 = 52 × 72 sum of divisors = ( ap + 1 – 1 ) / ( a – 1 ) × ( bq + 1 – 1 ) / ( b – 1 ) here a = 5 , b = 7 prime factors p = 2 and q = 2 sum of divisors = ( 53 – 1 ) / ( 5 – 1 ) × ( 73 – 1 ) / ( 7 – 1 ) = ( 124 / 4 ) × ( 342 / 6 ) = ( 31 × 57 ) = 1767 option a | general |
math_qa__FJWERqk52OUs1wJO | Total 60 cows 20 cow gives each 2 liter milk 20 cow gives each 3/4 liter milk 20 cow gives each 1/4 liter milk this is split into 3 son per each 20 cows & 20 liter milk how? Options.
A) 20 B) 10 C) 15 D) 16 E) 18 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 20</gadget>
<output>15</output>
<gadget id="calculator">(3/4) + 15</gadget>
<output>63/4 = around 15.75</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 20</gadget>
<output>5</output>
<gadget id="calculator">(63/4) + 5</gadget>
<output>83/4 = around 20.75</output>
<result>A</result> | A | 20 | Total 60 cows 20 cow gives each 2 liter milk 20 cow gives each 3/4 liter milk 20 cow gives each 1/4 liter milk this is split into 3 son per each 20 cows & 20 liter milk how? | {
"A": "20",
"B": "10",
"C": "15",
"D": "16",
"E": "18"
} | add(add(divide(3, 4), multiply(divide(3, 4), 20)), multiply(const_0_25, 20)) | divide(n4,n5)|multiply(n1,const_0_25)|multiply(n1,#0)|add(#0,#2)|add(#3,#1) | 20 cow 2 liter each = 40 liter 20 cow 3 / 4 liter each = 3 / 4 = 0.75 * 20 = 15 20 cow 1 / 4 liter each = 1 / 4 = 0.25 * 20 = 5 add 40 + 15 + 5 = 60 milk split into 3 son each 20 liter then 60 / 3 = 20 answer : a | general |
math_qa__57wx3TyXteEqfM54 | X starts a business with Rs.45000. Y joins in the business after 5 months with Rs.30000. What will be the ratio in which they should share the profit at the end of the year?
Select the correct option.
A) 1 : 2
B) 2 : 1
C) 1 : 3
D) 3 : 1
E) 18 : 7 | <gadget id="calculator">45_000 * 12</gadget>
<output>540_000</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">30_000 * 7</gadget>
<output>210_000</output>
<gadget id="calculator">540_000 / 210_000</gadget>
<output>18/7 = around 2.571429</output>
<result>E</result> | E | 2.571429 | X starts a business with Rs.45000. Y joins in the business after 5 months with Rs.30000. What will be the ratio in which they should share the profit at the end of the year? | {
"A": "1 : 2",
"B": "2 : 1",
"C": "1 : 3",
"D": "3 : 1",
"E": "18 : 7"
} | divide(multiply(45000, const_12), multiply(30000, add(const_4, const_3))) | add(const_3,const_4)|multiply(n0,const_12)|multiply(n2,#0)|divide(#1,#2) | explanation : ratio in which they should share the profit = ratio of the investments multiplied by the time period = 45000 ã — 12 : 30000 ã — 7 = 45 ã — 12 : 30 ã — 7 = 3 ã — 12 : 2 ã — 7 = 18 : 7 answer : option e | other |
math_qa__hAOg4oRGnVjSso63 | Ashok and Pyarelal invested money together in a business and share a capital of Ashok is 1/9 of that of Pyarelal.if the incur a loss of Rs 2000 then loss of Pyarelal? Choose the correct choice from the following choices
A) 1600 B) 1700 C) 1800 D) 1900 E) 1000 | <gadget id="calculator">9 * 2_000</gadget>
<output>18_000</output>
<gadget id="calculator">1 + 9</gadget>
<output>10</output>
<gadget id="calculator">18_000 / 10</gadget>
<output>1_800</output>
<result>C</result> | C | 1,800 | Ashok and Pyarelal invested money together in a business and share a capital of Ashok is 1/9 of that of Pyarelal.if the incur a loss of Rs 2000 then loss of Pyarelal? | {
"A": "1600",
"B": "1700",
"C": "1800",
"D": "1900",
"E": "1000"
} | divide(multiply(9, 2000), add(1, 9)) | add(n0,n1)|multiply(n1,n2)|divide(#1,#0)| | "let the capital of pyarelal be x , then capital of ashok = x / 9 so ratio of investment of pyarelal and ashok = x : x / 9 = 9 x : x hence out of the total loss of 2000 , loss of pyarelal = 2000 * 9 x / 10 x = 1800 answer : c" | gain |
math_qa__LFPWpTbnDxZY16gO | A store sells chairs and tables. If the price of 2 chairs and 1 table is 60% of the price of 1 chair and 2 tables, and the price of 1 table and 1 chair is $60, what is the price, in dollars, of 1 table? (Assume that every chair has the same price and every table has the same price.) Choose the correct answer
A) 105 / 2 B) 45 C) 44 D) 52 E) 50 | <gadget id="calculator">60 * 2</gadget>
<output>120</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">60 * (3/5)</gadget>
<output>36</output>
<gadget id="calculator">120 - 36</gadget>
<output>84</output>
<gadget id="calculator">(3/5) + 1</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">84 / (8/5)</gadget>
<output>105/2 = around 52.5</output>
<result>A</result> | A | 52.5 | A store sells chairs and tables. If the price of 2 chairs and 1 table is 60% of the price of 1 chair and 2 tables, and the price of 1 table and 1 chair is $60, what is the price, in dollars, of 1 table? (Assume that every chair has the same price and every table has the same price.) | {
"A": "105 / 2",
"B": "45",
"C": "44",
"D": "52",
"E": "50"
} | divide(subtract(multiply(60, 2), multiply(60, divide(60, const_100))), add(divide(60, const_100), 1)) | divide(n2,const_100)|multiply(n7,n0)|add(#0,n1)|multiply(n7,#0)|subtract(#1,#3)|divide(#4,#2)| | "let c = chair ; t = table 2 c + 1 t = 0.6 ( 1 c + 2 t ) or c ( 2 - 0.6 ) = 1.2 t - 1 t or 1.4 c = 0.2 t therefore c = 0.2 / 1.4 t = 1 / 7 t ic + 1 t = 60 or 1 / 7 t + 1 t = 60 therefore t = 60 * 7 / 8 = 105 / 2 a" | gain |
math_qa__2IhGxdk5jU7WbQ6b | There is a square of side 6cm . A circle is inscribed inside the square. Find the ratio of the area of circle to square.
Select the correct option:
A) 11 / 14
B) 1 / 14
C) 13 / 14
D) 12 / 14
E) 5 / 14 | <gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">pi * (3 ** 2)</gadget>
<output>9*pi = around 28.274334</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">(9*pi) / 36</gadget>
<output>pi/4 = around 0.785398</output>
<result>A</result> | A | 0.785714 | There is a square of side 6cm . A circle is inscribed inside the square. Find the ratio of the area of circle to square. | {
"A": "11 / 14",
"B": "1 / 14",
"C": "13 / 14",
"D": "12 / 14",
"E": "5 / 14"
} | divide(circle_area(divide(6, const_2)), square_area(6)) | divide(n0,const_2)|square_area(n0)|circle_area(#0)|divide(#2,#1) | let the side of square = a unit so area of square = a ^ 2 diameter of inscribed circle = side of square = a radius of circle = a / 2 area of circle = ( 22 / 7 ) ( a / 2 ) ^ 2 ratio of area of circle to square = { ( 22 / 7 ) ( a / 2 ) ^ 2 } / a ^ 2 = 11 / 14 answer : a | geometry |
math_qa__iIMmMjK7thSHXL9Q | If p and q are prime numbers, how many divisors does the product p^4 * q^9 have? Select the correct option
A) 30
B) 35
C) 40
D) 50
E) 60 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<result>D</result> | D | 50 | If p and q are prime numbers, how many divisors does the product p^4 * q^9 have? | {
"A": "30",
"B": "35",
"C": "40",
"D": "50",
"E": "60"
} | multiply(add(4, const_1), add(9, const_1)) | add(n0,const_1)|add(n1,const_1)|multiply(#0,#1)| | "when a number n = a ^ x * b ^ y , where a and b are prime numbers , and x , y are positive integers , the number of divisors of n = ( x + 1 ) ( y + 1 ) therefore , the answer is d . 5 * 10 = 50" | general |
math_qa__cqXHYWy3KwIengvY | 30 is subtracted from 40% of a number, the result is 50. Find the number? Choose the correct choice from the following options:
A) 200
B) 997
C) 266
D) 288
E) 271 | <gadget id="calculator">30 + 50</gadget>
<output>80</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">80 / (2/5)</gadget>
<output>200</output>
<result>A</result> | A | 200 | 30 is subtracted from 40% of a number, the result is 50. Find the number? | {
"A": "200",
"B": "997",
"C": "266",
"D": "288",
"E": "271"
} | divide(add(30, 50), divide(40, const_100)) | add(n0,n2)|divide(n1,const_100)|divide(#0,#1)| | "( 40 / 100 ) * x – 30 = 50 4 x = 800 x = 200 answer : a" | gain |
math_qa__8Ii41tHbXtzcNKyE | Calculate how many days it will take for 5 boys to paint a 65 m long wall if 2 boys can paint a 40 m long wall in 4 days, Pick: A) 2.6 days B) 3.6 days C) 5.6 days D) 6 days E) 2 days | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 * 65</gadget>
<output>520</output>
<gadget id="calculator">40 * 5</gadget>
<output>200</output>
<gadget id="calculator">520 / 200</gadget>
<output>13/5 = around 2.6</output>
<result>A</result> | A | 2.6 | Calculate how many days it will take for 5 boys to paint a 65 m long wall if 2 boys can paint a 40 m long wall in 4 days, | {
"A": "2.6 days",
"B": "3.6 days",
"C": "5.6 days",
"D": "6 days",
"E": "2 days"
} | divide(multiply(multiply(2, 4), 65), multiply(40, 5)) | multiply(n2,n4)|multiply(n0,n3)|multiply(n1,#0)|divide(#2,#1)| | "the length of wall painted by one boy in one day = 40 / 2 * 1 / 4 = 5 m no . of days required to paint 50 m cloth by 8 boys = 65 / 5 * 1 / 5 = 2.6 days . a" | physics |
math_qa__vv7p1DPieHeXpK74 | If a - b = 3 and a2 + b2 = 29, find the value of ab? Pick: A) 10 B) 12 C) 14 D) 17 E) 18 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">29 - 9</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>A</result> | A | 10 | If a - b = 3 and a2 + b2 = 29, find the value of ab? | {
"A": "10",
"B": "12",
"C": "14",
"D": "17",
"E": "18"
} | divide(subtract(29, power(3, 2)), 2) | power(n0,n1)|subtract(n3,#0)|divide(#1,n1)| | "2 ab = ( a 2 + b 2 ) - ( a - b ) 2 = 29 - 9 = 20 ab = 10 a )" | general |
math_qa__GXVJWRcgvfyZwo4B | Mary invested a certain sum of money in a bank that paid simple interest. The amount grew to $260 at the end of 2 years. She waited for another 4 years and got a final amount of $380. What was the principal amount that she invested at the beginning? Pick: A) $ 200 B) $ 220 C) $ 230 D) $ 240 E) $ 250 | <gadget id="calculator">380 - 260</gadget>
<output>120</output>
<gadget id="calculator">120 / 4</gadget>
<output>30</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">260 - 60</gadget>
<output>200</output>
<result>A</result> | A | 200 | Mary invested a certain sum of money in a bank that paid simple interest. The amount grew to $260 at the end of 2 years. She waited for another 4 years and got a final amount of $380. What was the principal amount that she invested at the beginning? | {
"A": "$ 200",
"B": "$ 220",
"C": "$ 230",
"D": "$ 240",
"E": "$ 250"
} | subtract(260, multiply(divide(subtract(380, 260), 4), 2)) | subtract(n3,n0)|divide(#0,n2)|multiply(n1,#1)|subtract(n0,#2)| | "what shall be the rate of interest . ? does that is not required for the calculation ? not really ! keep in mind that the interest earned each year will be the same in simple interest . at the end of 2 years , amount = $ 260 at the end of 6 years , amount = $ 380 this means she earned an interest of $ 120 in 4 years . or $ 30 in each year . we know that the interest earned each year will be the same . therefore she must have earned $ 60 in 2 years . hence principal amount = $ 260 - $ 60 = $ 200 option a" | gain |
math_qa__DlcQH3kLdVfcJlBo | Pipe A can fill a tank in 32 minutes. Pipe B can fill the same tank 5 times faster than pipe A. If both the pipes are connected to the tank so that they fill the tank simultaneously, how long will it take for the empty tank to overflow? Pick: A) 4 minutes B) 2 / 7 minutes C) 32 / 7 minutes D) 224 / 7 minutes E) 28 minutes | <gadget id="calculator">1 / 32</gadget>
<output>1/32 = around 0.03125</output>
<gadget id="calculator">5 / 32</gadget>
<output>5/32 = around 0.15625</output>
<gadget id="calculator">(1/32) + (5/32)</gadget>
<output>3/16 = around 0.1875</output>
<gadget id="calculator">(1/32) + (3/16)</gadget>
<output>7/32 = around 0.21875</output>
<gadget id="calculator">1 / (7/32)</gadget>
<output>32/7 = around 4.571429</output>
<result>C</result> | C | 4.571429 | Pipe A can fill a tank in 32 minutes. Pipe B can fill the same tank 5 times faster than pipe A. If both the pipes are connected to the tank so that they fill the tank simultaneously, how long will it take for the empty tank to overflow? | {
"A": "4 minutes",
"B": "2 / 7 minutes",
"C": "32 / 7 minutes",
"D": "224 / 7 minutes",
"E": "28 minutes"
} | inverse(add(divide(const_1, 32), add(divide(const_1, 32), divide(5, 32)))) | divide(const_1,n0)|divide(n1,n0)|add(#0,#1)|add(#2,#0)|inverse(#3)| | "pipe a can fill a tank in 32 minutes - - > the rate of a = 1 / 32 tank / minute ; pipe b can fill the same tank 5 times fasterthan pipe a - - > the rate of b = 1 / 32 + 5 / 32 = 6 / 32 tank / minute . their combined rate = 1 / 32 + 6 / 32 = 7 / 32 tank / minute ; therefore , a and b can fill the tank in 32 / 7 minutes . answer : c" | physics |
math_qa__jRqCV7AHaoo6vxbE | One side of a rectangular field is 4 m and its length along diagonal is 5 m. What is the area of the field?
Choose the correct option:
A) 12 B) 27 C) 98 D) 27 E) 29 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">25 - 16</gadget>
<output>9</output>
<gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<result>A</result> | A | 12 | One side of a rectangular field is 4 m and its length along diagonal is 5 m. What is the area of the field? | {
"A": "12",
"B": "27",
"C": "98",
"D": "27",
"E": "29"
} | rectangle_area(4, sqrt(subtract(power(5, const_2), power(4, const_2)))) | power(n1,const_2)|power(n0,const_2)|subtract(#0,#1)|sqrt(#2)|rectangle_area(n0,#3)| | "lb = 3 * 4 = 12 answer : a" | geometry |
math_qa__MPhoeaOMCTNKsTdG | The speed of a train is 64 kmph. What is the distance covered by it in 9 minutes? Options:
A) 10 kmph
B) 11 kmph
C) 88 kmph
D) 18 kmph
E) 12 kmph | <gadget id="calculator">9 / 60</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 64</gadget>
<output>48/5 = around 9.6</output>
<result>A</result> | A | 10 | The speed of a train is 64 kmph. What is the distance covered by it in 9 minutes? | {
"A": "10 kmph",
"B": "11 kmph",
"C": "88 kmph",
"D": "18 kmph",
"E": "12 kmph"
} | multiply(divide(9, const_60), 64) | divide(n1,const_60)|multiply(n0,#0)| | "64 * 9 / 60 = 9.6 kmph answer : a" | physics |
math_qa__7QIZ4i1kYm3lr6iY | If it is a 3x3 matrix, for which elements in first row are (V, 50, W), second row (196,X, Y)and in third row are (269, Z, 123).It is given that the sum of the numbers in each row, column, diagonal are same. Then find the value of (Y + Z).
Pick:
A) 1012
B) 1011
C) 1212
D) 1122
E) 1021 | <gadget id="calculator">269 + 123</gadget>
<output>392</output>
<gadget id="calculator">392 - 50</gadget>
<output>342</output>
<gadget id="calculator">269 + 342</gadget>
<output>611</output>
<gadget id="calculator">611 - 123</gadget>
<output>488</output>
<gadget id="calculator">196 + 269</gadget>
<output>465</output>
<gadget id="calculator">465 - 50</gadget>
<output>415</output>
<gadget id="calculator">342 + 415</gadget>
<output>757</output>
<gadget id="calculator">757 - 123</gadget>
<output>634</output>
<gadget id="calculator">488 + 634</gadget>
<output>1_122</output>
<result>D</result> | D | 1,122 | If it is a 3x3 matrix, for which elements in first row are (V, 50, W), second row (196,X, Y)and in third row are (269, Z, 123).It is given that the sum of the numbers in each row, column, diagonal are same. Then find the value of (Y + Z). | {
"A": "1012",
"B": "1011",
"C": "1212",
"D": "1122",
"E": "1021"
} | add(subtract(add(269, subtract(add(269, 123), 50)), 123), subtract(add(subtract(add(269, 123), 50), subtract(add(196, 269), 50)), 123)) | add(n4,n5)|add(n3,n4)|subtract(#0,n2)|subtract(#1,n2)|add(n4,#2)|add(#2,#3)|subtract(#4,n5)|subtract(#5,n5)|add(#6,#7) | v 50 w 196 x y 269 z 123 in 1 st row and 1 st column v + 196 + 269 = v + 50 + w w = 415 again , in 2 nd column and 3 rd row 50 + x + z = 269 + z + 123 x = 342 as sum of each row column and diagonal are same . so , 269 + 342 + 415 = 1026 415 + y + 123 = 1026 y = 488 269 + z + 123 = 1026 z = 634 y + z = 488 + 634 = 1122 answer : d | general |
math_qa__oxZ2Skar13xECphA | In an examination 35% of the students passed and 455 failed. How many students appeared for the examination? Choose the correct choice from the following: A) 540 B) 400 C) 700 D) 650 E) 840 | <gadget id="calculator">455 * 100</gadget>
<output>45_500</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">45_500 / 65</gadget>
<output>700</output>
<result>C</result> | C | 700 | In an examination 35% of the students passed and 455 failed. How many students appeared for the examination? | {
"A": "540",
"B": "400",
"C": "700",
"D": "650",
"E": "840"
} | divide(multiply(455, const_100), subtract(const_100, 35)) | multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "let the number of students appeared be x then , 65 % of x = 455 65 x / 100 = 455 x = 455 * 100 / 65 = 700 answer is c" | gain |
math_qa__g8ZyYoAhw8T8dsSR | A bag contains an equal number of one rupee, 50 paise and 25 paise coins respectively. If the total value is 140, how many coins of each type are there? Select the correct option
A) 20 coins B) 30 coins C) 40 coins D) 80 coins E) none of these | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/4) + (1/2)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) + 1</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">140 / (7/4)</gadget>
<output>80</output>
<result>D</result> | D | 80 | A bag contains an equal number of one rupee, 50 paise and 25 paise coins respectively. If the total value is 140, how many coins of each type are there? | {
"A": "20 coins",
"B": "30 coins",
"C": "40 coins",
"D": "80 coins",
"E": "none of these"
} | divide(140, add(add(inverse(const_4), inverse(const_2)), const_1)) | inverse(const_4)|inverse(const_2)|add(#0,#1)|add(#2,const_1)|divide(n2,#3) | let number of each type of coin = x . then , 1 × x + . 50 × x + . 25 x = 140 ⇒ 1.75 x = 140 ⇒ x = 80 coins answer d | general |
math_qa__xLngA4r0Evzue6HK | A 80 gallon solution of salt and water is 10% salt. How many gallons of water must be added to the solution in order to decrease the salt to 8% of the volume? Choose the correct choice from the following answers:
A) 20 B) 12 C) 13 D) 14 E) 16 | <gadget id="calculator">10 - 8</gadget>
<output>2</output>
<gadget id="calculator">80 * 2</gadget>
<output>160</output>
<gadget id="calculator">160 / 8</gadget>
<output>20</output>
<result>A</result> | A | 20 | A 80 gallon solution of salt and water is 10% salt. How many gallons of water must be added to the solution in order to decrease the salt to 8% of the volume? | {
"A": "20",
"B": "12",
"C": "13",
"D": "14",
"E": "16"
} | divide(multiply(80, subtract(10, 8)), 8) | subtract(n1,n2)|multiply(n0,#0)|divide(#1,n2)| | "amount of salt = 8.0 assume x gallons of water are added . 8.0 / 80 + x = 8 / 100 800 = 8 x + 640 8 x = 160 x = 20 correct option : a" | general |
math_qa__L9RhuJPZOxS4WAzZ | The average height of 35 boys in a class was calculated as 184cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places?
Pick
A) 187.89 cm B) 182.29 cm C) 123.98 cm D) 149.98 cm E) 146.89 cm | <gadget id="calculator">35 * 184</gadget>
<output>6_440</output>
<gadget id="calculator">6_440 - 166</gadget>
<output>6_274</output>
<gadget id="calculator">6_274 + 106</gadget>
<output>6_380</output>
<gadget id="calculator">6_380 / 35</gadget>
<output>1_276/7 = around 182.285714</output>
<gadget id="calculator">floor(1_276/7)</gadget>
<output>182</output>
<result>B</result> | B | 182.29 | The average height of 35 boys in a class was calculated as 184cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places? | {
"A": "187.89 cm",
"B": "182.29 cm",
"C": "123.98 cm",
"D": "149.98 cm",
"E": "146.89 cm"
} | floor(divide(add(subtract(multiply(35, 184), 166), 106), 35)) | multiply(n0,n1)|subtract(#0,n2)|add(n3,#1)|divide(#2,n0)|floor(#3)| | "calculated average height of 35 boys = 184 cm . wrong total height of 35 boys = 184 * 35 cm . this was as a result of an actual height of 106 cm being wrongly written as 166 cm . correct total height of 35 boys = 183 cm - ( 166 cm + 106 cm ) / 35 = 184 cm - 60 / 35 cm = 184 cm - 1.71 cm = 182.29 cm . answer : b" | general |
math_qa__Fi6SyVmbrwR0s8ud | A certain country had a total annual expenditure of $2.4 x 10^11 last year. If the population of the country was 240 million last year, what was the per capita expenditure? Select:
A) $ 500
B) $ 1,000
C) $ 2,000
D) $ 3,000
E) $ 5,000 | <gadget id="calculator">10 ** 11</gadget>
<output>100_000_000_000</output>
<gadget id="calculator">2.4 * 100_000_000_000</gadget>
<output>240_000_000_000</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">10 ** 6</gadget>
<output>1_000_000</output>
<gadget id="calculator">240 * 1_000_000</gadget>
<output>240_000_000</output>
<gadget id="calculator">240_000_000_000 / 240_000_000</gadget>
<output>1_000</output>
<result>B</result> | B | 1,000 | A certain country had a total annual expenditure of $2.4 x 10^11 last year. If the population of the country was 240 million last year, what was the per capita expenditure? | {
"A": "$ 500",
"B": "$ 1,000",
"C": "$ 2,000",
"D": "$ 3,000",
"E": "$ 5,000"
} | divide(multiply(2.4, power(10, 11)), multiply(240, power(10, add(const_4, const_2)))) | add(const_2,const_4)|power(n1,n2)|multiply(n0,#1)|power(n1,#0)|multiply(n3,#3)|divide(#2,#4)| | "total expenditure / population = per capita expenditure hence , ( 2,4 x 10 ^ 11 ) / 240 000 000 = ( 2,4 x 10 ^ 11 ) / ( 2,4 x 10 ^ 8 ) = 1 x 10 ^ ( 11 - 8 ) = 1 x 10 ^ 3 = 1000 . answer is b ." | general |
math_qa__B72Tie8FQZjRRpYW | There were two candidates in an election. Winner candidate received 62% of votes and won the election by 336 votes. Find the number of votes casted to the winning candidate? Choose the correct option
A) 288 B) 744 C) 788 D) 868 E) 177 | <gadget id="calculator">100 - 62</gadget>
<output>38</output>
<gadget id="calculator">62 - 38</gadget>
<output>24</output>
<gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">336 / (6/25)</gadget>
<output>1_400</output>
<gadget id="calculator">1_400 * 62</gadget>
<output>86_800</output>
<gadget id="calculator">86_800 / 100</gadget>
<output>868</output>
<result>D</result> | D | 868 | There were two candidates in an election. Winner candidate received 62% of votes and won the election by 336 votes. Find the number of votes casted to the winning candidate? | {
"A": "288",
"B": "744",
"C": "788",
"D": "868",
"E": "177"
} | divide(multiply(divide(336, divide(subtract(62, subtract(const_100, 62)), const_100)), 62), const_100) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)|multiply(n0,#3)|divide(#4,const_100)| | "w = 62 % l = 38 % 62 % - 38 % = 24 % 24 % - - - - - - - - 336 62 % - - - - - - - - ? = > 868 answer : d" | gain |
math_qa__F1D4nIKmQL1e2VqG | A train running at the speed of 60 km/hr crosses a pole in 3 seconds. What is the length of the train? Select the correct option:
A) 120 metres
B) 180 metres
C) 324 metres
D) 50 metres
E) 180 metres | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 3</gadget>
<output>50</output>
<result>D</result> | D | 50 | A train running at the speed of 60 km/hr crosses a pole in 3 seconds. What is the length of the train? | {
"A": "120 metres",
"B": "180 metres",
"C": "324 metres",
"D": "50 metres",
"E": "180 metres"
} | multiply(divide(multiply(60, const_1000), const_3600), 3) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = ( 60 x 5 / 18 ) / m / sec = 50 / 3 m / sec . length of the train = ( speed x time ) . length of the train = 50 x 3 / 3 m = 50 m . answer : option d" | physics |
math_qa__TYVo1d9YbysPVUP8 | Jennifer had $90 to spend on herself. She spent 1/5 of the money on a sandwich, 1/6 for a ticket to a museum, and 1/2 of it on a book. How much money does Jennifer have left over?
Choose the correct option: A) $ 12 B) $ 14 C) $ 5 D) $ 15 E) $ 0 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">90 * (1/5)</gadget>
<output>18</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">90 * (1/6)</gadget>
<output>15</output>
<gadget id="calculator">18 + 15</gadget>
<output>33</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">90 * (1/2)</gadget>
<output>45</output>
<gadget id="calculator">33 + 45</gadget>
<output>78</output>
<gadget id="calculator">90 - 78</gadget>
<output>12</output>
<result>A</result> | A | 12 | Jennifer had $90 to spend on herself. She spent 1/5 of the money on a sandwich, 1/6 for a ticket to a museum, and 1/2 of it on a book. How much money does Jennifer have left over? | {
"A": "$ 12",
"B": "$ 14",
"C": "$ 5",
"D": "$ 15",
"E": "$ 0"
} | subtract(90, add(add(multiply(90, divide(1, 5)), multiply(90, divide(1, 6))), multiply(90, divide(1, 2)))) | divide(n1,n2)|divide(n1,n4)|divide(n1,n6)|multiply(n0,#0)|multiply(n0,#1)|multiply(n0,#2)|add(#3,#4)|add(#6,#5)|subtract(n0,#7)| | "1 / 5 x $ 90 = $ 15 for sandwich 1 / 6 x $ 90 = $ 45 for museum 1 / 2 x $ 90 = $ 78 for book $ 15 + $ 45 + $ 18 = $ 78 spent $ 90 - $ 78 = $ 12 left over correct answer a" | general |
math_qa__egkAD19FiWf4PRVG | The surface of a cube is 24sq cm. Find its volume? Choose the correct choice:
A) 8
B) 6
C) 4
D) 3
E) 1 | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">24 / 6</gadget>
<output>4</output>
<gadget id="calculator">4 ** (1/2)</gadget>
<output>2</output>
<gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<result>A</result> | A | 8 | The surface of a cube is 24sq cm. Find its volume? | {
"A": "8",
"B": "6",
"C": "4",
"D": "3",
"E": "1"
} | volume_cube(sqrt(divide(24, add(const_2, const_4)))) | add(const_2,const_4)|divide(n0,#0)|sqrt(#1)|volume_cube(#2)| | "6 a 2 = 24 a = 2 = > a 3 = 8 cc answer : a" | geometry |
math_qa__JR43IJZrpGXcgprk | In one hour, a boat goes 11km along the stream and 5 km against it. Find the speed of the boat in still water Choose the correct choice from the following answers:
A) 6 B) 7 C) 8 D) 9 E) 10 | <gadget id="calculator">11 + 5</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>C</result> | C | 8 | In one hour, a boat goes 11km along the stream and 5 km against it. Find the speed of the boat in still water | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | divide(add(11, 5), const_2) | add(n0,n1)|divide(#0,const_2)| | "explanation : we know we can calculate it by 1 / 2 ( a + b ) = > 1 / 2 ( 11 + 5 ) = 1 / 2 ( 16 ) = 8 km / hr answer is c" | physics |
math_qa__vE3wB7kjE5be9G74 | How long does a train 145 meters long running at the rate of 54 kmph take to cross a bridge 660 meters in length? Answers.
A) 52.66 B) 53.66 C) 54.66 D) 58.66 E) 59.66 | <gadget id="calculator">145 + 660</gadget>
<output>805</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">54 * (5/18)</gadget>
<output>15</output>
<gadget id="calculator">805 / 15</gadget>
<output>161/3 = around 53.666667</output>
<result>B</result> | B | 53.66 | How long does a train 145 meters long running at the rate of 54 kmph take to cross a bridge 660 meters in length? | {
"A": "52.66",
"B": "53.66",
"C": "54.66",
"D": "58.66",
"E": "59.66"
} | divide(add(145, 660), multiply(54, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "t = ( 660 + 145 ) / 54 * 18 / 5 t = 53.66 answer : b" | physics |
math_qa__9vzDseeAKoREl8yI | In a group of ducks and cows, the total number of legs are 36 more than twice the no. of heads. Find the total no.of buffaloes. Choose one
A) 10 B) 12 C) 13 D) 15 E) 18 | <gadget id="calculator">36 / 2</gadget>
<output>18</output>
<result>E</result> | E | 18 | In a group of ducks and cows, the total number of legs are 36 more than twice the no. of heads. Find the total no.of buffaloes. | {
"A": "10",
"B": "12",
"C": "13",
"D": "15",
"E": "18"
} | divide(36, const_2) | divide(n0,const_2)| | "let the number of buffaloes be x and the number of ducks be y = > 4 x + 2 y = 2 ( x + y ) + 36 = > 2 x = 36 = > x = 18 e" | general |
math_qa__Mq7vzxFuczpxyG4B | In Town X, 60 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?
Answers.
A) 16 % B) 20 % C) 31 % D) 40 % E) 52 % | <gadget id="calculator">60 - 48</gadget>
<output>12</output>
<gadget id="calculator">12 / 60</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>B</result> | B | 20 | In Town X, 60 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females? | {
"A": "16 %",
"B": "20 %",
"C": "31 %",
"D": "40 %",
"E": "52 %"
} | multiply(divide(subtract(60, 48), 60), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "we are asked to find the percentage of females in employed people . total employed people 60 % , out of which 48 are employed males , hence 12 % are employed females . ( employed females ) / ( total employed people ) = 12 / 60 = 1 / 5 = 20 % answer : b ." | gain |
math_qa__A4QsbMwP8oux2ajO | Find large number from below question The difference of two numbers is 1335. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder Pick:
A) 1254
B) 1376
C) 1456
D) 1599
E) 1635 | <gadget id="calculator">1_335 - 15</gadget>
<output>1_320</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">1_320 / 5</gadget>
<output>264</output>
<gadget id="calculator">264 * 6</gadget>
<output>1_584</output>
<result>D</result> | D | 1,599 | Find large number from below question The difference of two numbers is 1335. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder | {
"A": "1254",
"B": "1376",
"C": "1456",
"D": "1599",
"E": "1635"
} | multiply(divide(subtract(1335, 15), subtract(6, const_1)), 6) | subtract(n0,n2)|subtract(n1,const_1)|divide(#0,#1)|multiply(n1,#2)| | "let the smaller number be x . then larger number = ( x + 1335 ) . x + 1335 = 6 x + 15 5 x = 1320 x = 264 large number = 264 + 1335 = 1599 d" | general |
math_qa__QrjxhUGsMn4LcK5G | What is the product of all the possible values of x if x^2 - 9x + 20? Choose the most appropriate option:
A) – 29
B) – 12
C) 12
D) 20
E) 168 | <gadget id="calculator">20 / 1</gadget>
<output>20</output>
<result>D</result> | D | 20 | What is the product of all the possible values of x if x^2 - 9x + 20? | {
"A": "– 29",
"B": "– 12",
"C": "12",
"D": "20",
"E": "168"
} | divide(20, const_1) | divide(n2,const_1)| | "explanation : = > y = x ^ 2 - 9 x + 20 = > y = ( x - 4 ) ( x - 5 ) = > x = 4 , y = 5 product y = ( 4 ) ( 5 ) = 20 answer option 20 answer : d" | general |
math_qa__sAGBbmedv0GdSctI | In a group of ducks and cows, the total number of legs are 28 more than twice the number of heads. Find the total number of cows. Choose the correct choice from the following:
A) 14 B) 12 C) 16 D) 8 E) 6 | <gadget id="calculator">28 / 2</gadget>
<output>14</output>
<result>A</result> | A | 14 | In a group of ducks and cows, the total number of legs are 28 more than twice the number of heads. Find the total number of cows. | {
"A": "14",
"B": "12",
"C": "16",
"D": "8",
"E": "6"
} | divide(28, const_2) | divide(n0,const_2)| | "explanation : let the number of ducks be d and number of cows be c then , total number of legs = 2 d + 4 c = 2 ( d + 2 c ) total number of heads = c + d given that total number of legs are 28 more than twice the number of heads = > 2 ( d + 2 c ) = 28 + 2 ( c + d ) = > d + 2 c = 14 + c + d = > 2 c = 14 + c = > c = 14 i . e . , total number of cows = 14 answer : a" | general |
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