id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__CkoV4lzYhT3hg8C4 | A dog takes 3 leaps for every 8 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is : Choose the correct choice from the following options: A) 9 : 8 B) 9 : 9 C) 9 : 6 D) 9 : 1 E) 9 : 2 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 8</gadget>
<output>9/8 = around 1.125</output>
<result>A</result> | A | 1.125 | A dog takes 3 leaps for every 8 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is : | {
"A": "9 : 8",
"B": "9 : 9",
"C": "9 : 6",
"D": "9 : 1",
"E": "9 : 2"
} | divide(multiply(3, 3), 8) | multiply(n0,n2)|divide(#0,n1)| | "explanation : dog : hare = ( 3 * 3 ) leaps of hare : 8 leaps of hare = 9 : 5 . answer : a ) 9 : 8" | other |
math_qa__eikr0priJzPxQ0f6 | A retailer bought a coat at wholesale and marked it up 90% to its initial price of $76. By how many more dollars does he need to increase the price to achieve a 100% markup? Choose the correct choice from the following answers:
A) 2
B) 4
C) 6
D) 8
E) 10 | <gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) + 1</gadget>
<output>19/10 = around 1.9</output>
<gadget id="calculator">76 / (19/10)</gadget>
<output>40</output>
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">80 - 76</gadget>
<output>4</output>
<result>B</result> | B | 4 | A retailer bought a coat at wholesale and marked it up 90% to its initial price of $76. By how many more dollars does he need to increase the price to achieve a 100% markup? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | subtract(multiply(divide(76, add(divide(90, 100), const_1)), const_2), 76) | divide(n0,n2)|add(#0,const_1)|divide(n1,#1)|multiply(#2,const_2)|subtract(#3,n1) | let x be the wholesale price . then 1.9 x = 76 and x = 76 / 1.9 = 40 . to achieve a 100 % markup , the price needs to be $ 80 . the retailer needs to increase the price by $ 4 more . the answer is b . | general |
math_qa__X4e19VXxenYHd1GU | If
BAT = 58
HAT = 52
CAT = 57
then
whats RAT = ? Choose the correct answer: A) 42 B) 45 C) 34 D) 76 E) 25 | <gadget id="calculator">57 + 3</gadget>
<output>60</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">60 - 18</gadget>
<output>42</output>
<result>A</result> | A | 42 | If
BAT = 58
HAT = 52
CAT = 57
then
whats RAT = ? | {
"A": "42",
"B": "45",
"C": "34",
"D": "76",
"E": "25"
} | subtract(add(57, const_3), multiply(multiply(const_3, const_3), const_2)) | add(n2,const_3)|multiply(const_3,const_3)|multiply(#1,const_2)|subtract(#0,#2) | a 42 | general |
math_qa__tU3lz9ijWRM0fC2C | There are 5 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 16 other amateurs, what is the total number of chess games possible to be played in the tournament? Choose the correct choice from the following options: A) 10 B) 20 C) 40 D) 60 E) 120 | <gadget id="calculator">5 * 16</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<result>C</result> | C | 40 | There are 5 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 16 other amateurs, what is the total number of chess games possible to be played in the tournament? | {
"A": "10",
"B": "20",
"C": "40",
"D": "60",
"E": "120"
} | divide(multiply(5, 16), const_2) | multiply(n0,n1)|divide(#0,const_2)| | "each person is one participant of 4 games . so there are in all 16 * 5 = 80 instances of one participant games . but each game has 2 participants so total number of games = 80 / 2 = 40 c" | general |
math_qa__Xf11c8XAI1BN9BKR | Find the highest common factor of 36 and 84.
Answers:
A) 12 B) 10 C) 16 D) 19 E) 18 | <gadget id="calculator">gcd(36, 84)</gadget>
<output>12</output>
<result>A</result> | A | 12 | Find the highest common factor of 36 and 84. | {
"A": "12",
"B": "10",
"C": "16",
"D": "19",
"E": "18"
} | gcd(36, 84) | gcd(n0,n1)| | "36 = 2 ^ 2 x 3 ^ 2 84 = 2 ^ 2 x 3 x 7 h . c . f . = 2 ^ 2 x 3 = 12 . answer : option a" | other |
math_qa__3Syc2rnTZPDqmSNF | A basket contains 7 apples, of which 1 is spoiled and the rest are good. If we select 2 apples from the basket simultaneously and at random, what is the probability that the 2 apples selected will include the spoiled apple?
Choose the correct option.
A) 1 / 5
B) 2 / 7
C) 2 / 9
D) 3 / 5
E) 4 / 11 | <gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">binomial(6, 1)</gadget>
<output>6</output>
<gadget id="calculator">binomial(7, 2)</gadget>
<output>21</output>
<gadget id="calculator">6 / 21</gadget>
<output>2/7 = around 0.285714</output>
<result>B</result> | B | 0.285714 | A basket contains 7 apples, of which 1 is spoiled and the rest are good. If we select 2 apples from the basket simultaneously and at random, what is the probability that the 2 apples selected will include the spoiled apple? | {
"A": "1 / 5",
"B": "2 / 7",
"C": "2 / 9",
"D": "3 / 5",
"E": "4 / 11"
} | divide(choose(subtract(7, 1), 1), choose(7, 2)) | choose(n0,n2)|subtract(n0,n1)|choose(#1,n1)|divide(#2,#0)| | "the total number of ways to choose 2 apples is 7 c 2 = 21 the number of ways that include the spoiled apple is 6 c 1 = 6 p ( the spoiled apple is included ) = 6 / 21 = 2 / 7 the answer is b ." | probability |
math_qa__gQLDPqsyTNrNK7a3 | The cost price of a radio is Rs.1500 and it was sold for Rs.1275, find the loss %? Choose the correct option
A) 15 %
B) 16 %
C) 17 %
D) 78 %
E) 28 % | <gadget id="calculator">1_500 - 1_275</gadget>
<output>225</output>
<gadget id="calculator">225 / 1_500</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 100</gadget>
<output>15</output>
<result>A</result> | A | 15 | The cost price of a radio is Rs.1500 and it was sold for Rs.1275, find the loss %? | {
"A": "15 %",
"B": "16 %",
"C": "17 %",
"D": "78 %",
"E": "28 %"
} | multiply(divide(subtract(1500, 1275), 1500), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "1500 - - - - 225 100 - - - - ? = > 15 % answer : a" | gain |
math_qa__FHLIA2o0qKWeQ8Oi | A boat can travel with a speed of 22 km/hr in still water. If the speed of the stream is 5 km/hr, find the time taken by the boat to go 54 km downstream
Choose the most appropriate option: A) 5 hours B) 4 hours C) 3 hours D) 2 hours E) none of these | <gadget id="calculator">22 + 5</gadget>
<output>27</output>
<gadget id="calculator">54 / 27</gadget>
<output>2</output>
<result>D</result> | D | 2 | A boat can travel with a speed of 22 km/hr in still water. If the speed of the stream is 5 km/hr, find the time taken by the boat to go 54 km downstream | {
"A": "5 hours",
"B": "4 hours",
"C": "3 hours",
"D": "2 hours",
"E": "none of these"
} | divide(54, add(22, 5)) | add(n0,n1)|divide(n2,#0)| | "explanation : speed of the boat in still water = 22 km / hr speed of the stream = 5 km / hr speed downstream = ( 22 + 5 ) = 27 km / hr distance travelled downstream = 54 km time taken = distance / speed = 54 / 27 = 2 hours . answer : option d" | physics |
math_qa__OlPhNNco56w5ucnz | The average age of 15 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is
Choices
A) 22
B) 37
C) 99
D) 38
E) 27 | <gadget id="calculator">21 + 23</gadget>
<output>44</output>
<gadget id="calculator">44 / 2</gadget>
<output>22</output>
<gadget id="calculator">1 * 15</gadget>
<output>15</output>
<gadget id="calculator">22 + 15</gadget>
<output>37</output>
<result>B</result> | B | 37 | The average age of 15 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is | {
"A": "22",
"B": "37",
"C": "99",
"D": "38",
"E": "27"
} | add(divide(add(21, 23), const_2), multiply(const_1, 15)) | add(n1,n2)|multiply(n0,const_1)|divide(#0,const_2)|add(#2,#1)| | "total age increased = ( 15 * 2 ) years = 30 years . sum of ages of two new men = ( 21 + 23 + 30 ) years = 74 years average age of two new men = ( 74 / 2 ) years = 37 years . answer : b" | general |
math_qa__IfTr8Y5Eq8eR5hhj | How long does a train 110 m long running at the speed of 90 km/hr takes to cross a bridge 132 m length?
Choose the most appropriate option.
A) 12.9 sec
B) 9.68 sec
C) 17.9 sec
D) 16.8 sec
E) 14.9 sec | <gadget id="calculator">110 + 132</gadget>
<output>242</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">90 * (5/18)</gadget>
<output>25</output>
<gadget id="calculator">242 / 25</gadget>
<output>242/25 = around 9.68</output>
<result>B</result> | B | 9.68 | How long does a train 110 m long running at the speed of 90 km/hr takes to cross a bridge 132 m length? | {
"A": "12.9 sec",
"B": "9.68 sec",
"C": "17.9 sec",
"D": "16.8 sec",
"E": "14.9 sec"
} | divide(add(110, 132), multiply(90, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "speed = 90 * 5 / 18 = 25 m / sec total distance covered = 110 + 132 = 242 m . required time = 242 / 25 = 9.68 sec . answer : b" | physics |
math_qa__RLAAXBJt6WXeQsyn | Sum of the numbers from 1 to 29 is Choose the correct choice from the following choices:
A) 400
B) 430
C) 435
D) 405
E) none of these | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">12 + 6</gadget>
<output>18</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">18 + 7</gadget>
<output>25</output>
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">25 + 8</gadget>
<output>33</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">33 + 9</gadget>
<output>42</output>
<gadget id="calculator">10 + 42</gadget>
<output>52</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">52 + 11</gadget>
<output>63</output>
<gadget id="calculator">63 + 12</gadget>
<output>75</output>
<gadget id="calculator">12 + 1</gadget>
<output>13</output>
<gadget id="calculator">75 + 13</gadget>
<output>88</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<gadget id="calculator">88 + 14</gadget>
<output>102</output>
<gadget id="calculator">12 + 3</gadget>
<output>15</output>
<gadget id="calculator">102 + 15</gadget>
<output>117</output>
<gadget id="calculator">15 + 1</gadget>
<output>16</output>
<gadget id="calculator">117 + 16</gadget>
<output>133</output>
<gadget id="calculator">16 + 1</gadget>
<output>17</output>
<gadget id="calculator">133 + 17</gadget>
<output>150</output>
<gadget id="calculator">17 + 1</gadget>
<output>18</output>
<gadget id="calculator">150 + 18</gadget>
<output>168</output>
<gadget id="calculator">18 + 1</gadget>
<output>19</output>
<gadget id="calculator">168 + 19</gadget>
<output>187</output>
<gadget id="calculator">19 + 1</gadget>
<output>20</output>
<gadget id="calculator">187 + 20</gadget>
<output>207</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">207 + 21</gadget>
<output>228</output>
<gadget id="calculator">21 + 1</gadget>
<output>22</output>
<gadget id="calculator">228 + 22</gadget>
<output>250</output>
<gadget id="calculator">22 + 1</gadget>
<output>23</output>
<gadget id="calculator">250 + 23</gadget>
<output>273</output>
<gadget id="calculator">23 + 1</gadget>
<output>24</output>
<gadget id="calculator">273 + 24</gadget>
<output>297</output>
<gadget id="calculator">24 + 1</gadget>
<output>25</output>
<gadget id="calculator">297 + 25</gadget>
<output>322</output>
<gadget id="calculator">25 + 1</gadget>
<output>26</output>
<gadget id="calculator">322 + 26</gadget>
<output>348</output>
<gadget id="calculator">26 + 1</gadget>
<output>27</output>
<gadget id="calculator">348 + 27</gadget>
<output>375</output>
<gadget id="calculator">27 + 1</gadget>
<output>28</output>
<gadget id="calculator">375 + 28</gadget>
<output>403</output>
<gadget id="calculator">403 + 29</gadget>
<output>432</output>
<result>C</result> | C | 435 | Sum of the numbers from 1 to 29 is | {
"A": "400",
"B": "430",
"C": "435",
"D": "405",
"E": "none of these"
} | add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(const_10, add(add(add(add(add(add(add(1, const_2), const_4), add(add(1, const_2), const_2)), add(add(add(1, const_2), const_2), 1)), add(add(add(add(1, const_2), const_2), 1), 1)), add(add(add(add(add(1, const_2), const_2), 1), 1), 1)), add(add(add(add(add(add(1, const_2), const_2), 1), 1), 1), 1))), add(const_10, 1)), const_12), add(const_12, 1)), add(const_12, const_2)), add(const_12, add(1, const_2))), add(add(const_12, add(1, const_2)), 1)), add(add(add(const_12, add(1, const_2)), 1), 1)), add(add(add(add(const_12, add(1, const_2)), 1), 1), 1)), add(add(add(add(add(const_12, add(1, const_2)), 1), 1), 1), 1)), add(add(add(add(add(add(const_12, add(1, const_2)), 1), 1), 1), 1), 1)), add(add(add(add(add(add(add(const_12, add(1, const_2)), 1), 1), 1), 1), 1), 1)), add(add(add(add(add(add(add(add(const_12, add(1, const_2)), 1), 1), 1), 1), 1), 1), 1)), add(add(add(add(add(add(add(add(add(const_12, add(1, const_2)), 1), 1), 1), 1), 1), 1), 1), 1)), add(add(add(add(add(add(add(add(add(add(const_12, add(1, const_2)), 1), 1), 1), 1), 1), 1), 1), 1), 1)), add(add(add(add(add(add(add(add(add(add(add(const_12, add(1, const_2)), 1), 1), 1), 1), 1), 1), 1), 1), 1), 1)), add(add(add(add(add(add(add(add(add(add(add(add(const_12, add(1, const_2)), 1), 1), 1), 1), 1), 1), 1), 1), 1), 1), 1)), add(add(add(add(add(add(add(add(add(add(add(add(add(const_12, add(1, const_2)), 1), 1), 1), 1), 1), 1), 1), 1), 1), 1), 1), 1)), add(add(add(add(add(add(add(add(add(add(add(add(add(add(const_12, add(1, const_2)), 1), 1), 1), 1), 1), 1), 1), 1), 1), 1), 1), 1), 1)), 29) | add(n0,const_2)|add(n0,const_10)|add(n0,const_12)|add(const_12,const_2)|add(#0,const_4)|add(#0,const_2)|add(#0,const_12)|add(#4,#5)|add(n0,#5)|add(n0,#6)|add(#7,#8)|add(n0,#8)|add(n0,#9)|add(#10,#11)|add(n0,#11)|add(n0,#12)|add(#13,#14)|add(n0,#14)|add(n0,#15)|add(#16,#17)|add(n0,#18)|add(#19,const_10)|add(n0,#20)|add(#21,#1)|add(n0,#22)|add(#23,const_12)|add(n0,#24)|add(#25,#2)|add(n0,#26)|add(#27,#3)|add(n0,#28)|add(#29,#6)|add(n0,#30)|add(#31,#9)|add(n0,#32)|add(#33,#12)|add(n0,#34)|add(#35,#15)|add(#37,#18)|add(#38,#20)|add(#39,#22)|add(#40,#24)|add(#41,#26)|add(#42,#28)|add(#43,#30)|add(#44,#32)|add(#45,#34)|add(#46,#36)|add(n1,#47) | explanation : sum of first n natural numbers = 1 + 2 + 3 + . . . . . n = n ( n + 1 ) / 2 substitute n = 29 . so s 20 = 29 ã — 30 / 2 = 435 correct option : c | general |
math_qa__PEPBigxjBGSrGtKZ | 20 percent of the programmers in a startup company weigh 200 pounds or more . 20 - 5 percent of the programmers that are under 200 pounds in that same company weigh 100 pounds or less . what percent of the programmers in the startup company weigh between 100 and 200 pounds ?
Pick one.
A) 15 % B) 20 % C) 25 % D) 60 % E) 75 % | <gadget id="calculator">20 - 5</gadget>
<output>15</output>
<gadget id="calculator">200 * 15</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 100</gadget>
<output>30</output>
<gadget id="calculator">30 + 30</gadget>
<output>60</output>
<result>D</result> | D | 60 | 20 percent of the programmers in a startup company weigh 200 pounds or more . 20 - 5 percent of the programmers that are under 200 pounds in that same company weigh 100 pounds or less . what percent of the programmers in the startup company weigh between 100 and 200 pounds ? | {
"A": "15 %",
"B": "20 %",
"C": "25 %",
"D": "60 %",
"E": "75 %"
} | add(divide(multiply(200, subtract(20, 5)), 100), divide(multiply(200, subtract(20, 5)), 100)) | subtract(n0,n3)|multiply(n1,#0)|divide(#1,n5)|add(#2,#2) | initially 80 % and 20 % split 80 % is further divided as 25 % and 75 % q is asking about that 75 % let total be ' 100 ' then that 75 % is ( 3 / 4 ) ∗ 80 so , the required % is [ ( 3 / 4 ) ∗ 80 / 100 ] ∗ 100 = 60 % answer : d | general |
math_qa__9kP6sdA25pyXy5K6 | Lisa and Robert have taken the same number of photos on their school trip. Lisa has taken 3 times as many photos as Claire and Robert has taken 12 more photos than Claire. How many photos has Claire taken? Select the correct option:
A) 6 B) 8 C) 10 D) 12 E) 14 | <gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>A</result> | A | 6 | Lisa and Robert have taken the same number of photos on their school trip. Lisa has taken 3 times as many photos as Claire and Robert has taken 12 more photos than Claire. How many photos has Claire taken? | {
"A": "6",
"B": "8",
"C": "10",
"D": "12",
"E": "14"
} | divide(12, subtract(3, const_1)) | subtract(n0,const_1)|divide(n1,#0)| | "explanation : l = r l = 3 c r = c + 12 we can substitute r for l in the second equation : r = 3 c . if r is equal to both 3 c and c + 12 , we can say 3 c = c + 12 , and solve for c . 3 c = c + 12 2 c = 12 c = 6 answer : ( a )" | general |
math_qa__a5HTHfa9DUzGw8rz | A man has Rs.10350 in the form of Rs.50 notes and Rs.500 notes. The total number of notes are 72.Find the number of notes of Rs.50 denomination. Choose the correct choice
A) 15 B) 21 C) 17 D) 37 E) 57 | <gadget id="calculator">500 * 72</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 - 10_350</gadget>
<output>25_650</output>
<gadget id="calculator">500 - 50</gadget>
<output>450</output>
<gadget id="calculator">25_650 / 450</gadget>
<output>57</output>
<result>E</result> | E | 57 | A man has Rs.10350 in the form of Rs.50 notes and Rs.500 notes. The total number of notes are 72.Find the number of notes of Rs.50 denomination. | {
"A": "15",
"B": "21",
"C": "17",
"D": "37",
"E": "57"
} | divide(subtract(multiply(500, 72), 10350), subtract(500, 50)) | multiply(n2,n3)|subtract(n2,n1)|subtract(#0,n0)|divide(#2,#1)| | "total money = rs . 10350 . let 50 rupees note was x . then 500 rupees note = 72 - x now , 50 * x + 500 * ( 72 - x ) = 10350 50 x + 36000 - 500 x = 10350 - 450 x = - 25650 x = 57 . no . of 50 rupees note = 57 . answer : option e" | general |
math_qa__70H8MMmNzcqzR9md | It takes Avery 3 hours to build a brick wall while Tom can do it in 5 hours. If the two start working together and after an hour Avery leaves, how much time will it take Tom to complete the wall on his own? Choose one:
A) 100
B) 110
C) 120
D) 130
E) 140 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/3) + (1/5)</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">1 - (8/15)</gadget>
<output>7/15 = around 0.466667</output>
<gadget id="calculator">(7/15) / (1/5)</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">(7/3) * 60</gadget>
<output>140</output>
<result>E</result> | E | 140 | It takes Avery 3 hours to build a brick wall while Tom can do it in 5 hours. If the two start working together and after an hour Avery leaves, how much time will it take Tom to complete the wall on his own? | {
"A": "100",
"B": "110",
"C": "120",
"D": "130",
"E": "140"
} | multiply(divide(subtract(const_1, add(divide(const_1, 3), divide(const_1, 5))), divide(const_1, 5)), const_60) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|subtract(const_1,#2)|divide(#3,#1)|multiply(#4,const_60)| | "avery takes 3 hours tom takes 2 hours efficiency of avery is 1 / 3 units / hr efficiency of tom is 1 / 5 units / hr combined efficiency of tom and avery is 1 / 3 + 1 / 5 = 8 / 15 units / hr since they worked for 1 hour they completed 8 / 15 units of work and 7 / 15 units of work is left which is to be completed by tom ( since avery left ) so time taken by tom to complete the remaining work will be 7 / 15 / 1 / 5 hours = > 7 / 3 * 60 = 140 minutes . . . answer will be ( e )" | physics |
math_qa__HQsxzubciE1lLDpF | A flagpole 18 meters high casts a shadow of length 45 meters. If a building under similar conditions casts a shadow of length 65 meters, what is the height of the building (in meters)? Options:
A) 22 B) 24 C) 26 D) 28 E) 30 | <gadget id="calculator">18 / 45</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">65 * (2/5)</gadget>
<output>26</output>
<result>C</result> | C | 26 | A flagpole 18 meters high casts a shadow of length 45 meters. If a building under similar conditions casts a shadow of length 65 meters, what is the height of the building (in meters)? | {
"A": "22",
"B": "24",
"C": "26",
"D": "28",
"E": "30"
} | multiply(65, divide(18, 45)) | divide(n0,n1)|multiply(n2,#0)| | "the height : length ratio will be equal in both cases . 18 / 45 = x / 65 x = 26 the answer is c ." | physics |
math_qa__37F3G4Z2lGBpw6EK | The simple interest and the true discount on a certain sum for a given time and at a given rate are Rs. 85 and Rs. 75 respectively. The sum is: Choose the correct choice from the following choices
A) 1360 B) 637.5 C) 1600 D) 1800 E) none | <gadget id="calculator">85 * 75</gadget>
<output>6_375</output>
<gadget id="calculator">85 - 75</gadget>
<output>10</output>
<gadget id="calculator">6_375 / 10</gadget>
<output>1_275/2 = around 637.5</output>
<result>B</result> | B | 637.5 | The simple interest and the true discount on a certain sum for a given time and at a given rate are Rs. 85 and Rs. 75 respectively. The sum is: | {
"A": "1360",
"B": "637.5",
"C": "1600",
"D": "1800",
"E": "none"
} | divide(multiply(85, 75), subtract(85, 75)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)| | "sol . sum = s . i . * t . d . / ( s . i ) - ( t . d . ) = 85 * 75 / ( 85 - 75 ) = rs . 637.5 . answer b" | gain |
math_qa__wy9N1x6I0zjOs8td | A multiple choice test consists of 4 questions, and each question has 5 answer choices. In how many W ways can the test be completed if every question is unanswered? Choose the correct choice:
A) 24 B) 120 C) 625 D) 720 E) 1024 | <gadget id="calculator">5 ** 4</gadget>
<output>625</output>
<result>C</result> | C | 625 | A multiple choice test consists of 4 questions, and each question has 5 answer choices. In how many W ways can the test be completed if every question is unanswered? | {
"A": "24",
"B": "120",
"C": "625",
"D": "720",
"E": "1024"
} | power(5, 4) | power(n1,n0)| | "5 choices for each of the 4 questions , thus total w of 5 * 5 * 5 * 5 = 5 ^ 4 = 625 ways to answer all of them . answer : c ." | general |
math_qa__mpXYbw870e9Z4wE8 | If 36 men can do a piece of work in 25 hours, in how many hours will 12 men do it?
Choices
A) 22 B) 38 C) 60 D) 88 E) 75 | <gadget id="calculator">36 * 25</gadget>
<output>900</output>
<gadget id="calculator">900 / 12</gadget>
<output>75</output>
<result>E</result> | E | 75 | If 36 men can do a piece of work in 25 hours, in how many hours will 12 men do it? | {
"A": "22",
"B": "38",
"C": "60",
"D": "88",
"E": "75"
} | divide(multiply(36, 25), 12) | multiply(n0,n1)|divide(#0,n2)| | "explanation : let the required no of hours be x . then less men , more hours ( indirect proportion ) \ inline \ fn _ jvn \ therefore 12 : 36 : : 25 : x \ inline \ fn _ jvn \ leftrightarrow ( 12 x x ) = ( 36 x 25 ) \ inline \ fn _ jvn \ leftrightarrow \ inline \ fn _ jvn x = \ frac { 36 \ times 25 } { 12 } = 75 hence , 12 men can do it in 75 hours . answer : e ) 75" | physics |
math_qa__Puk3JeTgSipQyNBZ | Rahim bought 40 books for Rs.600 from one shop and 20 books for Rs.240 from another. What is the average price he paid per book ? Choose the correct choice from the following choices: A) s . 14 B) s . 18 C) s . 12 D) s . 11 E) s . 10 | <gadget id="calculator">600 + 240</gadget>
<output>840</output>
<gadget id="calculator">40 + 20</gadget>
<output>60</output>
<gadget id="calculator">840 / 60</gadget>
<output>14</output>
<result>A</result> | A | 14 | Rahim bought 40 books for Rs.600 from one shop and 20 books for Rs.240 from another. What is the average price he paid per book ? | {
"A": "s . 14",
"B": "s . 18",
"C": "s . 12",
"D": "s . 11",
"E": "s . 10"
} | divide(add(600, 240), add(40, 20)) | add(n1,n3)|add(n0,n2)|divide(#0,#1)| | "average price per book = ( 600 + 240 ) / ( 40 + 20 ) = 840 / 60 = rs . 14 answer : a" | general |
math_qa__7FYuk4V6vs7TAjnF | The salary of A, B, C, D, E is Rs. 9000, Rs. 5000, Rs. 11000, Rs. 7000, Rs. 9000 per month respectively, then the average salary of A, B, C, D, and E per month is Choose the correct choice from the following answers:
A) rs . 7000
B) rs . 8200
C) rs . 8500
D) rs . 9000
E) none | <gadget id="calculator">9_000 + 5_000</gadget>
<output>14_000</output>
<gadget id="calculator">14_000 + 11_000</gadget>
<output>25_000</output>
<gadget id="calculator">25_000 + 7_000</gadget>
<output>32_000</output>
<gadget id="calculator">32_000 + 9_000</gadget>
<output>41_000</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">41_000 / 5</gadget>
<output>8_200</output>
<result>B</result> | B | 8,200 | The salary of A, B, C, D, E is Rs. 9000, Rs. 5000, Rs. 11000, Rs. 7000, Rs. 9000 per month respectively, then the average salary of A, B, C, D, and E per month is | {
"A": "rs . 7000",
"B": "rs . 8200",
"C": "rs . 8500",
"D": "rs . 9000",
"E": "none"
} | divide(add(add(add(add(9000, 5000), 11000), 7000), 9000), add(const_4, const_1)) | add(n0,n1)|add(const_1,const_4)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "answer average salary = 9000 + 5000 + 11000 + 7000 + 9000 / 5 = rs . 8200 correct option : b" | general |
math_qa__HYp1OmFleiqfvuVp | A grocer has a sale of Rs. 7435, Rs. 7920, Rs. 7855, Rs. 8230 and Rs. 7560 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 7500? Options:
A) 500 B) 2000 C) 5000 D) 6000 E) 7000 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 7_500</gadget>
<output>45_000</output>
<gadget id="calculator">7_435 + 7_920</gadget>
<output>15_355</output>
<gadget id="calculator">15_355 + 7_855</gadget>
<output>23_210</output>
<gadget id="calculator">23_210 + 8_230</gadget>
<output>31_440</output>
<gadget id="calculator">31_440 + 7_560</gadget>
<output>39_000</output>
<gadget id="calculator">45_000 - 39_000</gadget>
<output>6_000</output>
<result>D</result> | D | 6,000 | A grocer has a sale of Rs. 7435, Rs. 7920, Rs. 7855, Rs. 8230 and Rs. 7560 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 7500? | {
"A": "500",
"B": "2000",
"C": "5000",
"D": "6000",
"E": "7000"
} | subtract(multiply(add(5, const_1), 7500), add(add(add(add(7435, 7920), 7855), 8230), 7560)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "total sale for 5 months = rs . ( 7435 + 7920 + 7855 + 8230 + 7560 ) = rs . 39000 . required sale = rs . [ ( 7500 x 6 ) - 39000 ] = rs . ( 45000 - 39000 ) = rs . 6000 answer : option d" | general |
math_qa__QbQM12JDLffFz6Ly | David obtained 96, 95, 82, 97 and 95 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ?
Choose the correct choice from the following answers
A) 75
B) 95
C) 93
D) 165
E) 11 | <gadget id="calculator">96 + 95</gadget>
<output>191</output>
<gadget id="calculator">191 + 82</gadget>
<output>273</output>
<gadget id="calculator">273 + 97</gadget>
<output>370</output>
<gadget id="calculator">370 + 95</gadget>
<output>465</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">465 / 5</gadget>
<output>93</output>
<result>C</result> | C | 93 | David obtained 96, 95, 82, 97 and 95 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ? | {
"A": "75",
"B": "95",
"C": "93",
"D": "165",
"E": "11"
} | divide(add(add(add(add(96, 95), 82), 97), 95), add(const_2, const_3)) | add(n0,n1)|add(const_2,const_3)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "explanation : average = ( 96 + 95 + 82 + 97 + 95 ) / 5 = 465 / 5 = 93 . answer : c" | general |
math_qa__eqRoi8uP6SsKDKb3 | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8100. If his salary for the month of May is Rs.6500, find his salary for the month of January?
Choose the correct choice from the following answers: A) 2177 B) 2876 C) 4500 D) 2981 E) 6100 | <gadget id="calculator">8_000 * 4</gadget>
<output>32_000</output>
<gadget id="calculator">8_100 * 4</gadget>
<output>32_400</output>
<gadget id="calculator">32_400 - 6_500</gadget>
<output>25_900</output>
<gadget id="calculator">32_000 - 25_900</gadget>
<output>6_100</output>
<result>E</result> | E | 6,100 | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8100. If his salary for the month of May is Rs.6500, find his salary for the month of January? | {
"A": "2177",
"B": "2876",
"C": "4500",
"D": "2981",
"E": "6100"
} | subtract(multiply(8000, const_4), subtract(multiply(8100, const_4), 6500)) | multiply(n0,const_4)|multiply(n1,const_4)|subtract(#1,n2)|subtract(#0,#2)| | "sum of the salaries of the person for the months of january , february , march and april = 4 * 8000 = 32000 - - - - ( 1 ) sum of the salaries of the person for the months of february , march , april and may = 4 * 8100 = 32400 - - - - ( 2 ) ( 2 ) - ( 1 ) i . e . may - jan = 400 salary of may is rs . 6500 salary of january = rs . 6100 . answer : e" | general |
math_qa__LAYgGCMcnHiFsLSs | A invested some money in 10% stock at 96.If B wants to invest in an equally good 12% stock ,he must purchase a stock worth of : Choose the correct choice from the following choices:
A) rs . 80
B) rs . 115.20
C) rs . 120
D) rs . 125.40
E) none of these | <gadget id="calculator">96 / 10</gadget>
<output>48/5 = around 9.6</output>
<gadget id="calculator">(48/5) * 12</gadget>
<output>576/5 = around 115.2</output>
<result>B</result> | B | 115.2 | A invested some money in 10% stock at 96.If B wants to invest in an equally good 12% stock ,he must purchase a stock worth of : | {
"A": "rs . 80",
"B": "rs . 115.20",
"C": "rs . 120",
"D": "rs . 125.40",
"E": "none of these"
} | multiply(divide(96, 10), 12) | divide(n1,n0)|multiply(n2,#0) | explanation : for an income of rs . 10 , investment = rs . 96 . for an income of rs . 12 , investment = ( 96 / 10 x 12 ) = 115.20 answer : b | gain |
math_qa__C2zYfYBnTB7mTJL8 | A watch was sold at a loss of 8%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
Choose one
A) 1000 B) 2876 C) 1977 D) 1167 E) 2711 | <gadget id="calculator">140 * 100</gadget>
<output>14_000</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 - 8</gadget>
<output>92</output>
<gadget id="calculator">104 - 92</gadget>
<output>12</output>
<gadget id="calculator">14_000 / 12</gadget>
<output>3_500/3 = around 1_166.666667</output>
<result>D</result> | D | 1,167 | A watch was sold at a loss of 8%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? | {
"A": "1000",
"B": "2876",
"C": "1977",
"D": "1167",
"E": "2711"
} | divide(multiply(140, const_100), subtract(add(const_100, 4), subtract(const_100, 8))) | add(const_100,n2)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3)| | "92 % 104 % - - - - - - - - 12 % - - - - 140 100 % - - - - ? = > rs . 1167 answer : d" | gain |
math_qa__8q4yM5433AidVRSm | A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 4400. What is the share of B ? Choose the correct option
A) 1100 B) 800 C) 1400 D) 1200 E) none of them | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 3</gadget>
<output>2</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 3</gadget>
<output>11</output>
<gadget id="calculator">2 / 11</gadget>
<output>2/11 = around 0.181818</output>
<gadget id="calculator">4_400 * (2/11)</gadget>
<output>800</output>
<result>B</result> | B | 800 | A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 4400. What is the share of B ? | {
"A": "1100",
"B": "800",
"C": "1400",
"D": "1200",
"E": "none of them"
} | multiply(4400, divide(const_2, add(add(multiply(const_2, const_3), multiply(divide(const_2, const_3), const_3)), const_3))) | divide(const_2,const_3)|multiply(const_2,const_3)|multiply(#0,const_3)|add(#1,#2)|add(#3,const_3)|divide(const_2,#4)|multiply(n1,#5) | let c ' s capital = rs . x . then , b ' s capital = rs . ( 2 / 3 ) x a ’ s capital = rs . ( 3 x ( 2 / 3 ) . x ) = rs . 2 x . ratio of their capitals = 2 x : ( 2 / 3 ) x : x = 6 : 2 : 3 . hence , b ' s share = rs . ( 4400 x ( 2 / 11 ) ) = rs . 800 . answer is b | gain |
math_qa__3vQSjtmiZTeJR4LL | J is 25% less than P and 20% less than T. T is e% less than P. What is the value of e? Choose the correct answer.
A) 93.5
B) 90
C) 6.75
D) 6.25
E) 2 | <gadget id="calculator">25 * 25</gadget>
<output>625</output>
<gadget id="calculator">625 / 100</gadget>
<output>25/4 = around 6.25</output>
<result>D</result> | D | 6.25 | J is 25% less than P and 20% less than T. T is e% less than P. What is the value of e? | {
"A": "93.5",
"B": "90",
"C": "6.75",
"D": "6.25",
"E": "2"
} | divide(multiply(25, 25), const_100) | multiply(n0,n0)|divide(#0,const_100)| | "usually we can solve every question of this type by choosing appropriate value of the variable and deriving the value of other related variables . let , p = 400 then j = ( 75 / 100 ) * 400 = 300 also j = ( 80 / 100 ) * t i . e . t = 300 * 100 / 80 = 375 and t = [ 1 - ( e / 100 ) ] * p i . e . 100 - e = 100 * t / p = 100 * 375 / 400 = 93.75 i . e . e = 6.25 answer : option d" | gain |
math_qa__lWobzuDHjnyjgxWw | Walking at 5/6th of its usual speed a cab is 12mnts late. Find its usual time to cover the journey? Pick.
A) 25 m B) 45 m C) 32 m D) 50 m E) 60 m | <gadget id="calculator">5 * 12</gadget>
<output>60</output>
<result>E</result> | E | 60 | Walking at 5/6th of its usual speed a cab is 12mnts late. Find its usual time to cover the journey? | {
"A": "25 m",
"B": "45 m",
"C": "32 m",
"D": "50 m",
"E": "60 m"
} | multiply(5, 12) | multiply(n0,n2)| | "new speed = 5 / 6 th of usual speed new time = 6 / 5 th of usual time 6 / 5 ut - ut = 12 m ut / 5 = 12 m ut = 60 m answer is e" | physics |
math_qa__fy9FnadcRh7ruS9l | 6 points lie on the circumference of a ellipse . what is the positive difference between the number of triangles and the number of quadrilaterals that can be created by connecting these points ?
Choices: A) 4 B) 6 C) 5 D) 15 E) 20 | <gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">720 / 36</gadget>
<output>20</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">720 / 48</gadget>
<output>15</output>
<gadget id="calculator">20 - 15</gadget>
<output>5</output>
<result>C</result> | C | 5 | 6 points lie on the circumference of a ellipse . what is the positive difference between the number of triangles and the number of quadrilaterals that can be created by connecting these points ? | {
"A": "4",
"B": "6",
"C": "5",
"D": "15",
"E": "20"
} | subtract(divide(factorial(6), multiply(factorial(const_3), factorial(const_3))), divide(factorial(6), multiply(factorial(const_4), factorial(const_2)))) | factorial(n0)|factorial(const_3)|factorial(const_4)|factorial(const_2)|multiply(#1,#1)|multiply(#2,#3)|divide(#0,#4)|divide(#0,#5)|subtract(#6,#7) | number of triangles can be formed out of 6 points = 6 c 3 = 20 number of quadrilaterals can be formed out of 6 points = 6 c 4 = 15 20 - 15 = 5 . answer = c | geometry |
math_qa__JHp4KvwYyVfBpoII | The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction? Answers:
A) 2 / 3 B) 3 / 5 C) 4 / 7 D) 5 / 9 E) none of these | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">5 / 9</gadget>
<output>5/9 = around 0.555556</output>
<result>D</result> | D | 0.555556 | The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction? | {
"A": "2 / 3",
"B": "3 / 5",
"C": "4 / 7",
"D": "5 / 9",
"E": "none of these"
} | divide(subtract(multiply(3, const_2), const_1), subtract(multiply(5, const_2), const_1)) | multiply(n2,const_2)|multiply(n3,const_2)|subtract(#0,const_1)|subtract(#1,const_1)|divide(#2,#3) | let the numerator and denominator of the fraction be ' n ' and ' d ' respectively . d = 2 n - 1 ( n + 1 ) / ( d + 1 ) = 3 / 5 5 n + 5 = 3 d + 3 5 n + 5 = 3 ( 2 n - 1 ) + 3 = > n = 5 d = 2 n - 1 = > d = 9 hence the fraction is : 5 / 9 answer : d | general |
math_qa__K6ey9C38jPyF231g | set s consists of integers { 13 , 57 } . if two numbers are chosen from set s at random , what is the probability that the product of 2 numbers is more than 15 ?
Select
A) 1 / 2
B) 1 / 3
C) 1 / 5
D) 1 / 6
E) 2 / 3 | <gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<result>B</result> | B | 0.333333 | set s consists of integers { 13 , 57 } . if two numbers are chosen from set s at random , what is the probability that the product of 2 numbers is more than 15 ? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 5",
"D": "1 / 6",
"E": "2 / 3"
} | divide(const_2, divide(divide(factorial(const_4), 2), 2)) | factorial(const_4)|divide(#0,n2)|divide(#1,n2)|divide(const_2,#2) | number of ways you can choose 2 from 4 = 4 c 2 = 6 e = event of getting the 2 numbers product is more than 15 = ( 3,7 ) , ( 5,7 ) = 2 probability = 2 / 6 = 1 / 3 answer is b | general |
math_qa__uNcl9LsM3OsW9d7Y | A dealer offers a cash discount of 20% and still makes a profit of 20% when he further allows 10 articles to be sold at the cost price of 9 articles to a particular sticky bargainer. How much percent above the cost price were his articles listed?
Choose the correct choice from the following choices
A) 50 % B) 55 % C) 60 % D) 66 + ( 2 / 3 ) % E) 80 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">10 - 9</gadget>
<output>1</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(6/5) / (9/10)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/3) / (4/5)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) - 1</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 100</gadget>
<output>200/3 = around 66.666667</output>
<result>D</result> | D | 66 | A dealer offers a cash discount of 20% and still makes a profit of 20% when he further allows 10 articles to be sold at the cost price of 9 articles to a particular sticky bargainer. How much percent above the cost price were his articles listed? | {
"A": "50 %",
"B": "55 %",
"C": "60 %",
"D": "66 + ( 2 / 3 ) %",
"E": "80 %"
} | multiply(subtract(divide(divide(divide(add(const_100, 20), const_100), subtract(const_1, divide(subtract(10, 9), 10))), divide(subtract(const_100, 20), const_100)), const_1), const_100) | add(n1,const_100)|subtract(n2,n3)|subtract(const_100,n0)|divide(#0,const_100)|divide(#1,n2)|divide(#2,const_100)|subtract(const_1,#4)|divide(#3,#6)|divide(#7,#5)|subtract(#8,const_1)|multiply(#9,const_100)| | "given cash discount - 20 % profit - 20 % items sold - 10 price sold at = list price of 9 assume list price = $ 10 total invoice = $ 90 - 20 % cash discount = $ 72 let cost price of 10 items be x so total cost = 10 * x given the shopkeeper had a profit of 20 % 10 * x * 120 / 100 = 72 or x = $ 6 which means his products were listed at $ 10 which is a 66 + ( 2 / 3 ) % markup over $ 6 answer d" | gain |
math_qa__khGOT3lTX46pwosv | In a certain warehouse, 40 percent of the packages weigh less than 75 pounds, and a total of 48 packages weigh less than 25 pounds. If 80 percent of the packages weigh at least 25 pounds, how many of the packages weigh at least 25 pounds but less than 75 pounds?
Options.
A) 8
B) 64
C) 48
D) 102
E) 144 | <gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">48 / 20</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 100</gadget>
<output>240</output>
<gadget id="calculator">240 * 40</gadget>
<output>9_600</output>
<gadget id="calculator">9_600 / 100</gadget>
<output>96</output>
<gadget id="calculator">96 - 48</gadget>
<output>48</output>
<result>C</result> | C | 48 | In a certain warehouse, 40 percent of the packages weigh less than 75 pounds, and a total of 48 packages weigh less than 25 pounds. If 80 percent of the packages weigh at least 25 pounds, how many of the packages weigh at least 25 pounds but less than 75 pounds? | {
"A": "8",
"B": "64",
"C": "48",
"D": "102",
"E": "144"
} | subtract(divide(multiply(multiply(divide(48, subtract(const_100, 80)), const_100), 40), const_100), 48) | subtract(const_100,n4)|divide(n2,#0)|multiply(#1,const_100)|multiply(n0,#2)|divide(#3,const_100)|subtract(#4,n2)| | "if 80 % of the packages weigh at least 25 pounds this means that 20 % of the packages weigh less than 25 pounds let t = total number of packages so , 20 % of t = # of packages that weigh less than 25 pounds 48 packages weigh less than 25 pounds great . so , 20 % of t = 48 rewrite to get : 0.2 t = 48 solve : t = 240 40 % of the packages weigh less than 75 pounds so , 40 % oft = number of packages that weigh less than 75 pounds 40 % of 240 = 96 , so 96 packages weigh less than 75 pounds of those 96 packages that weigh less than 75 pounds , 48 packages weigh less than 25 pounds . so , the number of packages that weight between 25 and 75 pounds = 96 - 48 = 48 = c" | general |
math_qa__ftsFLTxtSMGOuDn3 | If 0.5% of A =95 paise, then the value of A is ?
Choose the correct choice from the following answers
A) rs . 190
B) rs . 17
C) rs . 1.70
D) rs . 4.25
E) none | <gadget id="calculator">95 / 0.5</gadget>
<output>190</output>
<result>A</result> | A | 190 | If 0.5% of A =95 paise, then the value of A is ? | {
"A": "rs . 190",
"B": "rs . 17",
"C": "rs . 1.70",
"D": "rs . 4.25",
"E": "none"
} | divide(95, 0.5) | divide(n1,n0)| | "answer ∵ 0.5 / 100 of a = 95 / 100 ∴ a = rs . ( 95 / 0.5 ) = rs . 190 correct option : a" | gain |
math_qa__APeP3YbWwDDIcwSd | A company produces 60000 bottles of water everyday. If a case can hold 5 bottles of water .How many cases are required by the company to hold its one day production Pick.
A) 12000 B) 4500 C) 5000 D) 8000 E) 9000 | <gadget id="calculator">60_000 / 5</gadget>
<output>12_000</output>
<result>A</result> | A | 12,000 | A company produces 60000 bottles of water everyday. If a case can hold 5 bottles of water .How many cases are required by the company to hold its one day production | {
"A": "12000",
"B": "4500",
"C": "5000",
"D": "8000",
"E": "9000"
} | divide(60000, 5) | divide(n0,n1)| | "number of bottles that can be held in a case = 5 number of cases required to hold 60000 bottles = 60000 / 5 = 12000 cases . so the answer is a = 12000" | physics |
math_qa__IQfOTgzpe3Pubkxm | Cost is expressed by the formula tb^4. If b is doubled, the new cost E is what percent of the original cost? Choose the most appropriate option:
A) e = 200
B) e = 600
C) e = 800
D) e = 1600
E) 50 | <gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 100</gadget>
<output>1_600</output>
<result>D</result> | D | 1,600 | Cost is expressed by the formula tb^4. If b is doubled, the new cost E is what percent of the original cost? | {
"A": "e = 200",
"B": "e = 600",
"C": "e = 800",
"D": "e = 1600",
"E": "50"
} | multiply(power(const_2, 4), const_100) | power(const_2,n0)|multiply(#0,const_100)| | "original cost e , c 1 = t 1 * b 1 ^ 4 new cost c 2 = t 2 * b 2 ^ 4 . . . . only b is doubled so t 2 = t 1 and b 2 = 2 b 1 c 2 = t 2 * ( 2 b 1 ) ^ 4 = 16 ( t 1 * b 1 ^ 4 ) = 16 c 1 16 times c 1 = > 1600 % of c 1 ans d = 1600" | general |
math_qa__U5GD5Uhl23qsk3sO | If 1/12 of the passengers on a ship are from North America, 1/4 are Europeans, 1/9 are from Africa, 1/6 are from Asia and the remaining 42 people are citizens of other continents, then how many passengers are on board the ship?
Choose the correct choice from the following choices
A) 96
B) 100
C) 104
D) 108
E) 112 | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/12) + (1/4)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/3) + (1/9)</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(4/9) + (1/6)</gadget>
<output>11/18 = around 0.611111</output>
<gadget id="calculator">1 - (11/18)</gadget>
<output>7/18 = around 0.388889</output>
<gadget id="calculator">42 / (7/18)</gadget>
<output>108</output>
<result>D</result> | D | 108 | If 1/12 of the passengers on a ship are from North America, 1/4 are Europeans, 1/9 are from Africa, 1/6 are from Asia and the remaining 42 people are citizens of other continents, then how many passengers are on board the ship? | {
"A": "96",
"B": "100",
"C": "104",
"D": "108",
"E": "112"
} | divide(42, subtract(1, add(add(add(divide(1, 12), divide(1, 4)), divide(1, 9)), divide(1, 6)))) | divide(n0,n1)|divide(n0,n3)|divide(n0,n5)|divide(n0,n7)|add(#0,#1)|add(#4,#2)|add(#5,#3)|subtract(n0,#6)|divide(n8,#7)| | "1 / 12 + 1 / 4 + 1 / 9 + 1 / 6 = ( 3 + 9 + 4 + 6 ) / 36 = 11 / 18 let x be the number of passengers on the ship . 42 = ( 7 / 18 ) x x = 108 the answer is d ." | general |
math_qa__wfR1sX2uIBIYAcDA | By selling an article at Rs.500, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%? Select:
A) s . 600
B) s . 480
C) s . 300
D) s . 450
E) s . 550 | <gadget id="calculator">500 * 100</gadget>
<output>50_000</output>
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">50_000 / 125</gadget>
<output>400</output>
<gadget id="calculator">400 * 25</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 100</gadget>
<output>100</output>
<gadget id="calculator">400 - 100</gadget>
<output>300</output>
<result>C</result> | C | 300 | By selling an article at Rs.500, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%? | {
"A": "s . 600",
"B": "s . 480",
"C": "s . 300",
"D": "s . 450",
"E": "s . 550"
} | subtract(divide(multiply(500, const_100), add(25, const_100)), divide(multiply(divide(multiply(500, const_100), add(25, const_100)), 25), const_100)) | add(n1,const_100)|multiply(n0,const_100)|divide(#1,#0)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "sp = 500 profit = 25 % cp = ( sp ) * [ 100 / ( 100 + p ) ] = 500 * [ 100 / 125 ] = 400 loss = 25 % = 25 % of 400 = rs . 100 sp = cp - loss = 400 - 100 = rs . 300 answer : c" | gain |
math_qa__QL0JWrbENLcMKl5F | A hiker walking at a constant rate of 5 kilometers per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 25 kilometers per hour. The cyclist stops and waits for the hiker 5 minutes after passing her while the hiker continues to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up? Choose the correct choice from the following choices:
A) 10 B) 15 C) 20 D) 25 E) 30 | <gadget id="calculator">5 / 60</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">25 * (1/12)</gadget>
<output>25/12 = around 2.083333</output>
<gadget id="calculator">5 * (1/12)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(25/12) - (5/12)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) / 5</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 60</gadget>
<output>20</output>
<result>C</result> | C | 20 | A hiker walking at a constant rate of 5 kilometers per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 25 kilometers per hour. The cyclist stops and waits for the hiker 5 minutes after passing her while the hiker continues to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up? | {
"A": "10",
"B": "15",
"C": "20",
"D": "25",
"E": "30"
} | multiply(divide(subtract(multiply(25, divide(5, const_60)), multiply(5, divide(5, const_60))), 5), const_60) | divide(n2,const_60)|multiply(n1,#0)|multiply(n0,#0)|subtract(#1,#2)|divide(#3,n0)|multiply(#4,const_60)| | "in 5 minutes , the cyclist travels a distance of ( 5 / 60 ) * 25 = 25 / 12 km . the time it takes the hiker to complete this distance is ( 25 / 12 ) / 5 = 5 / 12 hours = 25 minutes the cyclist needs to wait 25 - 5 = 20 minutes the answer is c ." | physics |
math_qa__QqYiqr95xUQaVJoA | Each employee of Company X is a member of precisely 1 of 3 shifts of employees. Among the 60 members of the first shift, 20 percent participate in the pension program; among the 50 members of the second shift, 40 percent participate in the pension program; and among the 40 members of the third shift, 10 percent participate in the pension program. What percent of the workers at Company X participate in the pension program? Choices
A) 20 % B) 24 % C) 36 % D) 37.5 % E) 70 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 60</gadget>
<output>12</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 50</gadget>
<output>20</output>
<gadget id="calculator">12 + 20</gadget>
<output>32</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 40</gadget>
<output>4</output>
<gadget id="calculator">32 + 4</gadget>
<output>36</output>
<gadget id="calculator">60 + 50</gadget>
<output>110</output>
<gadget id="calculator">110 + 40</gadget>
<output>150</output>
<gadget id="calculator">36 / 150</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">(6/25) * 100</gadget>
<output>24</output>
<result>B</result> | B | 24 | Each employee of Company X is a member of precisely 1 of 3 shifts of employees. Among the 60 members of the first shift, 20 percent participate in the pension program; among the 50 members of the second shift, 40 percent participate in the pension program; and among the 40 members of the third shift, 10 percent participate in the pension program. What percent of the workers at Company X participate in the pension program? | {
"A": "20 %",
"B": "24 %",
"C": "36 %",
"D": "37.5 %",
"E": "70 %"
} | multiply(divide(add(add(multiply(divide(20, const_100), 60), multiply(divide(40, const_100), 50)), multiply(divide(10, const_100), 40)), add(add(60, 50), 40)), const_100) | add(n2,n4)|divide(n3,const_100)|divide(n5,const_100)|divide(n7,const_100)|add(n5,#0)|multiply(n2,#1)|multiply(n4,#2)|multiply(n5,#3)|add(#5,#6)|add(#8,#7)|divide(#9,#4)|multiply(#10,const_100) | 60 members & 20 percent = 12 50 members & 40 percent = 20 40 members & 10 percent = 4 = > 36 / 150 ∗ 100 = 24 % answer b | physics |
math_qa__uaYdB6KC0iRhoa5Q | A farmer spent $35 on feed for chickens and goats. He spent 40% money on chicken feed, which he bought at a 60% discount off the full price, and spent the rest on goat feed, which he bought at full price. If the farmer had paid full price for both the chicken feed and the goat feed, what amount would he have spent on the chicken feed and goat feed combined?
Options:
A) $ 37.80 B) $ 38.50 C) $ 39.20 D) $ 39.50 E) $ 51 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">35 * (2/5)</gadget>
<output>14</output>
<gadget id="calculator">14 + 35</gadget>
<output>49</output>
<result>E</result> | E | 51 | A farmer spent $35 on feed for chickens and goats. He spent 40% money on chicken feed, which he bought at a 60% discount off the full price, and spent the rest on goat feed, which he bought at full price. If the farmer had paid full price for both the chicken feed and the goat feed, what amount would he have spent on the chicken feed and goat feed combined? | {
"A": "$ 37.80",
"B": "$ 38.50",
"C": "$ 39.20",
"D": "$ 39.50",
"E": "$ 51"
} | add(multiply(35, divide(40, const_100)), 35) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)| | "a farmer spent 40 % money on chicken feed , so he spent 0.4 * $ 35 = $ 14 on chicken feed , thus he spent the remaining 35 - 14 = $ 21 on goat feed . now , since he bought chicken feed at a 20 % discount then the original price of it was x * 0.4 = $ 14 - - > x = $ 35 . therefore if the farmer had paid full price for both the chicken feed and the goat feed , then he would he have spent 35 + 21 = $ 51 . answer : e ." | gain |
math_qa__EpbPnXmPEzaxUHr0 | The ratio of the amount of the oil bill for the month of February to the amount of the oil bill for the month of January was 5:4. If the oil bill for February had been $30 more, the corresponding ratio would have been 3:2. How much was the oil bill for January? Choose the correct choice from the following:
A) $ 60
B) $ 80
C) $ 100
D) $ 120
E) $ 140 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(3/2) - (5/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">30 / (1/4)</gadget>
<output>120</output>
<result>D</result> | D | 120 | The ratio of the amount of the oil bill for the month of February to the amount of the oil bill for the month of January was 5:4. If the oil bill for February had been $30 more, the corresponding ratio would have been 3:2. How much was the oil bill for January? | {
"A": "$ 60",
"B": "$ 80",
"C": "$ 100",
"D": "$ 120",
"E": "$ 140"
} | divide(30, subtract(divide(3, 2), divide(5, 4))) | divide(n3,n4)|divide(n0,n1)|subtract(#0,#1)|divide(n2,#2)| | "5 : 4 = 15 : 12 and 3 : 2 = 18 : 12 . an increase in $ 30 increases the ratio by 3 : 12 . therefore an increase in $ 10 increases the ratio by 1 : 12 . therefore , january ' s bill was 12 ( $ 10 ) = $ 120 . the answer is d ." | general |
math_qa__k26SIoIkzNQFiSKw | A driver goes on a trip of 50 kilometers, the first 25 kilometers at 66 kilometers per hour and the remaining distance at 33 kilometers per hour. What is the average speed of the entire trip in kilometers per hour? Choose the most appropriate option.
A) 38 B) 40 C) 44 D) 45 E) 48 | <gadget id="calculator">25 / 66</gadget>
<output>25/66 = around 0.378788</output>
<gadget id="calculator">50 - 25</gadget>
<output>25</output>
<gadget id="calculator">25 / 33</gadget>
<output>25/33 = around 0.757576</output>
<gadget id="calculator">(25/66) + (25/33)</gadget>
<output>25/22 = around 1.136364</output>
<gadget id="calculator">50 / (25/22)</gadget>
<output>44</output>
<result>C</result> | C | 44 | A driver goes on a trip of 50 kilometers, the first 25 kilometers at 66 kilometers per hour and the remaining distance at 33 kilometers per hour. What is the average speed of the entire trip in kilometers per hour? | {
"A": "38",
"B": "40",
"C": "44",
"D": "45",
"E": "48"
} | divide(50, add(divide(25, 66), divide(subtract(50, 25), 33))) | divide(n1,n2)|subtract(n0,n1)|divide(#1,n3)|add(#0,#2)|divide(n0,#3) | the time for the first part of the trip was 25 / 66 hours . the time for the second part of the trip was 25 / 33 hours . the total time fro the trip was 25 / 66 + 25 / 33 = 75 / 66 = 25 / 22 hours . the average speed for the trip was 50 / ( 25 / 22 ) = 44 kph the answer is c . | physics |
math_qa__e7c5sWe5WPKBlLy5 | At what rate percent per annum will a sum of money double in 10years? Choose the correct choice from the following answers:
A) 10 % B) 15 % C) 18 % D) 20 % E) 25 % | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<result>A</result> | A | 10 | At what rate percent per annum will a sum of money double in 10years? | {
"A": "10 %",
"B": "15 %",
"C": "18 %",
"D": "20 %",
"E": "25 %"
} | divide(const_100, 10) | divide(const_100,n0)| | "let principle = p s . i . = p t = 10 yrs rate = 100 * p / p * 10 = 10 % answer is a" | gain |
math_qa__RxSYnj5b3HDfaDCP | A certain company expects quarterly earnings of $0.80 per share of stock, half of which will be distributed as dividends to shareholders while the rest will be used for research and development. If earnings are greater than expected , shareholders will receive an additional $0.04 per share for each additional $0.10 of per share earnings. If quarterly earnings are $1.10 per share, what will be the dividend paid to a person who owns 600 shares of the company's stock? Select the correct option:
A) $ 92 B) $ 312 C) $ 104 D) $ 120 E) $ 240 | <gadget id="calculator">0.8 / 2</gadget>
<output>0.4</output>
<gadget id="calculator">1.1 - 0.8</gadget>
<output>0.3</output>
<gadget id="calculator">0.3 * 10</gadget>
<output>3</output>
<gadget id="calculator">3 * 0.04</gadget>
<output>0.12</output>
<gadget id="calculator">0.4 + 0.12</gadget>
<output>0.52</output>
<gadget id="calculator">0.52 * 600</gadget>
<output>312</output>
<result>B</result> | B | 312 | A certain company expects quarterly earnings of $0.80 per share of stock, half of which will be distributed as dividends to shareholders while the rest will be used for research and development. If earnings are greater than expected , shareholders will receive an additional $0.04 per share for each additional $0.10 of per share earnings. If quarterly earnings are $1.10 per share, what will be the dividend paid to a person who owns 600 shares of the company's stock? | {
"A": "$ 92",
"B": "$ 312",
"C": "$ 104",
"D": "$ 120",
"E": "$ 240"
} | multiply(add(divide(0.8, const_2), multiply(multiply(subtract(1.1, 0.8), const_10), 0.04)), 600) | divide(n0,const_2)|subtract(n3,n0)|multiply(#1,const_10)|multiply(n1,#2)|add(#0,#3)|multiply(n4,#4) | eps actual > eps expected . each gets and additional . 12 per share . thus . 52 * 600 - - > $ 312 answer is b | general |
math_qa__C4SYPHr4vUxS1eSe | In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 10 percent of revenues. The profits in 2009 were what percent of the profits in 2008?
Choose the correct choice from the following options:
A) 80 % B) 105 % C) 120 % D) 124.2 % E) 138 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">10 * (4/5)</gadget>
<output>8</output>
<gadget id="calculator">8 / 10</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 100</gadget>
<output>80</output>
<result>A</result> | A | 80 | In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 10 percent of revenues. The profits in 2009 were what percent of the profits in 2008? | {
"A": "80 %",
"B": "105 %",
"C": "120 %",
"D": "124.2 %",
"E": "138 %"
} | multiply(divide(multiply(10, subtract(const_1, divide(20, const_100))), 10), const_100) | divide(n3,const_100)|subtract(const_1,#0)|multiply(n4,#1)|divide(#2,n1)|multiply(#3,const_100)| | "x = profits r = revenue x / r = 0,1 x = 10 r = 100 2009 : r = 80 x / 80 = 0,10 = 10 / 100 x = 80 * 10 / 100 x = 8 8 / 10 = 0.8 = 800 % , answer a" | gain |
math_qa__PWpEBRVCuekCwQM3 | If the areas of the three adjacent faces of a cuboidal box are 120 cm², 72 cm² and 60 cm² respectively, then find the volume of the box. Choose the correct choice from the following answers.
A) 120 m ³ B) 400 m ³ C) 660 m ³ D) 720 cm m ³ E) none | <gadget id="calculator">120 * 60</gadget>
<output>7_200</output>
<gadget id="calculator">7_200 / 72</gadget>
<output>100</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">120 / 10</gadget>
<output>12</output>
<gadget id="calculator">60 / 10</gadget>
<output>6</output>
<gadget id="calculator">10 * 12 * 6</gadget>
<output>720</output>
<result>D</result> | D | 720 | If the areas of the three adjacent faces of a cuboidal box are 120 cm², 72 cm² and 60 cm² respectively, then find the volume of the box. | {
"A": "120 m ³",
"B": "400 m ³",
"C": "660 m ³",
"D": "720 cm m ³",
"E": "none"
} | volume_rectangular_prism(sqrt(divide(multiply(120, 60), 72)), divide(120, sqrt(divide(multiply(120, 60), 72))), divide(60, sqrt(divide(multiply(120, 60), 72)))) | multiply(n0,n2)|divide(#0,n1)|sqrt(#1)|divide(n0,#2)|divide(n2,#2)|volume_rectangular_prism(#3,#4,#2) | sol . let the length , breadth and height of the box be , l , b , and h respectively , then , volume = lbh = √ ( lbh ) ² = √ lb * bh * lh = √ 120 * 72 * 60 = 720 cm ³ answer d | geometry |
math_qa__sJaCYIgUOZqejoIf | Solution A is 20% barium and Solution B is 80% barium. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% barium solution? Choose the correct option: A) 6 : 4 B) 6 : 14 C) 4 : 4 D) 4 : 6 E) 3 : 7 | <gadget id="calculator">80 / 20</gadget>
<output>4</output>
<gadget id="calculator">4 / 4</gadget>
<output>1</output>
<result>C</result> | C | 1 | Solution A is 20% barium and Solution B is 80% barium. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% barium solution? | {
"A": "6 : 4",
"B": "6 : 14",
"C": "4 : 4",
"D": "4 : 6",
"E": "3 : 7"
} | divide(divide(80, 20), divide(80, 20)) | divide(n1,n0)|divide(#0,#0) | forget the volumes for the time being . you have to mix 20 % and 80 % solutions to get 50 % . this is very straight forward since 50 is int he middle of 20 and 80 so we need both solutions in equal quantities . if this does n ' t strike , use w 1 / w 2 = ( a 2 - aavg ) / ( aavg - a 1 ) w 1 / w 2 = ( 80 - 50 ) / ( 50 - 20 ) = 1 / 1 so the volume of the two solutions will be equal . answer has to be 4 : 4 = c | other |
math_qa__qEjEyty9gagA9D4O | A cyclist bikes x distance at 12 miles per hour and returns over the same path at 8 miles per hour. What is the cyclist's average rate for the round trip in miles per hour?
Choose the correct answer.
A) 8.1
B) 8.3
C) 9.6
D) 8.9
E) 9.0 | <gadget id="calculator">12 + 8</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>C</result> | C | 9.6 | A cyclist bikes x distance at 12 miles per hour and returns over the same path at 8 miles per hour. What is the cyclist's average rate for the round trip in miles per hour? | {
"A": "8.1",
"B": "8.3",
"C": "9.6",
"D": "8.9",
"E": "9.0"
} | divide(add(12, 8), const_2) | add(n0,n1)|divide(#0,const_2)| | "distance = d 1 = x miles speed = s 1 = 12 miles per hour time = t 1 = distance / speed = x / 12 2 . going from b to a distance = d 2 = x miles speed = s 2 = 8 miles per hour time = t 2 = distance / speed = x / 8 3 . average speed = total distance / total time total distance = x + x = 2 x total time = x / 12 + x / 8 = x ( 1 / 12 + 1 / 8 ) = = 5 x / 24 speed = 2 x / ( 5 x / 24 ) = 48 / 5 = 9.6 answer : c" | physics |
math_qa__UodtJzl6hceYfSfe | In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 85 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ? Choose the correct option:
A) 50 % B) 59 % C) 54 % D) 55 % E) 57 % | <gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">60 * (17/20)</gadget>
<output>51</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">40 * (1/5)</gadget>
<output>8</output>
<gadget id="calculator">51 + 8</gadget>
<output>59</output>
<result>B</result> | B | 59 | In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 85 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ? | {
"A": "50 %",
"B": "59 %",
"C": "54 %",
"D": "55 %",
"E": "57 %"
} | add(multiply(60, divide(85, const_100)), multiply(subtract(const_100, 60), divide(20, const_100))) | divide(n1,const_100)|divide(n2,const_100)|subtract(const_100,n0)|multiply(n0,#0)|multiply(#1,#2)|add(#3,#4)| | "say there are total of 100 registered voters in that city . thus 60 are democrats and 40 are republicans . 60 * 0.85 = 51 democrats are expected to vote for candidate a ; 40 * 0.20 = 8 republicans are expected to vote for candidate a . thus total of 51 + 8 = 59 registered voters are expected to vote for candidate a , which is 59 % of the total number of registered voters . answer : b ." | gain |
math_qa__pLlV1elAVnfX9uGc | While driving from A-ville to B-town, Harriet drove at a constant speed of 100 kilometers per hour. Upon arriving in B-town, Harriet immediately turned and drove back to A-ville at a constant speed of 150 kilometers per hour. If the entire trip took 5 hours, how many minutes did it take Harriet to drive from A-ville to B-town? Pick one
A) 138 B) 148 C) 150 D) 162 E) 180 | <gadget id="calculator">100 * 5</gadget>
<output>500</output>
<gadget id="calculator">100 + 150</gadget>
<output>250</output>
<gadget id="calculator">500 / 250</gadget>
<output>2</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">3 * 60</gadget>
<output>180</output>
<result>E</result> | E | 180 | While driving from A-ville to B-town, Harriet drove at a constant speed of 100 kilometers per hour. Upon arriving in B-town, Harriet immediately turned and drove back to A-ville at a constant speed of 150 kilometers per hour. If the entire trip took 5 hours, how many minutes did it take Harriet to drive from A-ville to B-town? | {
"A": "138",
"B": "148",
"C": "150",
"D": "162",
"E": "180"
} | multiply(subtract(5, divide(multiply(100, 5), add(100, 150))), const_60) | add(n0,n1)|multiply(n0,n2)|divide(#1,#0)|subtract(n2,#2)|multiply(#3,const_60)| | "5 hr = 300 min . if harriet spend equal hrs on each leg she will spend 150 min on each . since speed a - b is less than speed b - a and distance on each leg is the same , time spent on a - b is more than 150 min , which mean we can eliminate ans . a , b and c . now let plug in ans . d or e and verify which one give same distance on each leg . e . t = 180 min * leg a - b - - - > d = 100.180 / 60 = 18000 / 60 * leg b - a - - - - > d = 150 * 120 / 60 = 18000 / 60 so the correct ans . ise" | physics |
math_qa__Di8zITgZWuAXtHdq | At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 15 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank? Choices: A) 3 / 25 B) 11 / 36 C) 5 / 9 D) 2 / 3 E) 25 / 36 | <gadget id="calculator">50 * 5</gadget>
<output>250</output>
<gadget id="calculator">250 / 30</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">(25/3) / 15</gadget>
<output>5/9 = around 0.555556</output>
<result>C</result> | C | 0.555556 | At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 15 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank? | {
"A": "3 / 25",
"B": "11 / 36",
"C": "5 / 9",
"D": "2 / 3",
"E": "25 / 36"
} | divide(divide(multiply(50, 5), 30), 15) | multiply(n0,n4)|divide(#0,n2)|divide(#1,n3) | gas used = ( 5 hours ) * ( 50 miles / hour ) * ( 1 gallon / 30 miles ) = 8 + 1 / 3 gallons portion used = ( 8 + 1 / 3 ) / 15 = 5 / 9 ans c | physics |
math_qa__rgXX8HzCt68JBN4x | Robert ate 13 chocolates, Nickel ate 4 chocolates. How many more chocolates did Robert ate than nickel? Pick one.
A) 4
B) 7
C) 9
D) 5
E) 2 | <gadget id="calculator">13 - 4</gadget>
<output>9</output>
<result>C</result> | C | 9 | Robert ate 13 chocolates, Nickel ate 4 chocolates. How many more chocolates did Robert ate than nickel? | {
"A": "4",
"B": "7",
"C": "9",
"D": "5",
"E": "2"
} | subtract(13, 4) | subtract(n0,n1)| | 13 - 4 = 9 . answer is c | general |
math_qa__zWLOcqlxBoVOjVHZ | By selling an article at Rs.150, a profit of 25% is made. Find its cost price? Choose one:
A) s . 486 B) s . 455 C) s . 487 D) s . 120 E) s . 489 | <gadget id="calculator">150 * 100</gadget>
<output>15_000</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">15_000 / 125</gadget>
<output>120</output>
<result>D</result> | D | 120 | By selling an article at Rs.150, a profit of 25% is made. Find its cost price? | {
"A": "s . 486",
"B": "s . 455",
"C": "s . 487",
"D": "s . 120",
"E": "s . 489"
} | divide(multiply(150, const_100), add(const_100, 25)) | add(n1,const_100)|multiply(n0,const_100)|divide(#1,#0)| | "sp = 150 cp = ( sp ) * [ 100 / ( 100 + p ) ] = 150 * [ 100 / ( 100 + 25 ) ] = 150 * [ 100 / 125 ] = rs . 120 answer : d" | gain |
math_qa__7tpkxrFHrNjiO5Ia | Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 600 kms and City A and City C is 360 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)
Choices
A) 8 / 3 B) 3 / 8 C) 8 / 5 D) 5 / 8 E) 20 / 9 | <gadget id="calculator">600 / 3</gadget>
<output>200</output>
<gadget id="calculator">360 / 4</gadget>
<output>90</output>
<gadget id="calculator">200 / 90</gadget>
<output>20/9 = around 2.222222</output>
<result>E</result> | E | 2.222222 | Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 600 kms and City A and City C is 360 kms. What is the ratio of their average speed of travel? (Eddy: Freddy) | {
"A": "8 / 3",
"B": "3 / 8",
"C": "8 / 5",
"D": "5 / 8",
"E": "20 / 9"
} | divide(divide(600, 3), divide(360, 4)) | divide(n2,n0)|divide(n3,n1)|divide(#0,#1)| | "distance traveled by eddy = 600 km time taken by eddy = 3 hours average speed of eddy = 600 / 3 = 200 km / hour distance traveled by freddy = 360 km time taken by freddy = 4 hours average speed of freddy = 360 / 4 = 90 km / hour ratio of average speed of eddy to freddy = 200 / 90 = 20 / 9 answer e" | physics |
math_qa__wHVzkGVENUUO2GDr | Excluding stoppages, the speed of a bus is 5454 kmph and including stoppages, it is 4545kmph. For how many minutes does the bus stop per hour? Select the correct option:
A) 12 B) 11 C) 10 D) 9 E) 8 | <gadget id="calculator">5_454 - 4_545</gadget>
<output>909</output>
<gadget id="calculator">909 / 5_454</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">60 * (1/6)</gadget>
<output>10</output>
<result>C</result> | C | 10 | Excluding stoppages, the speed of a bus is 5454 kmph and including stoppages, it is 4545kmph. For how many minutes does the bus stop per hour? | {
"A": "12",
"B": "11",
"C": "10",
"D": "9",
"E": "8"
} | multiply(const_60, divide(subtract(5454, 4545), 5454)) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_60)| | "explanation : speed of the bus excluding stoppages = 54 = 54 kmph speed of the bus including stoppages = 45 = 45 kmph loss in speed when including stoppages = 54 â ˆ ’ 45 = 9 kmph = 54 â ˆ ’ 45 = 9 kmph â ‡ ’ â ‡ ’ in 11 hour , bus covers 99 km less due to stoppages . hence , time in which the bus stops per hour = time taken to cover 99 km = distancespeed = 954 hour = 16 hour = distancespeed = 954 hour = 16 hour = 606 min = 10 min answer is c" | physics |
math_qa__oE6hPCLtG5479lS3 | Sheela deposits Rs. 2500 in bank savings account. If this is 25% of her monthly income. What is her monthly income in? Select.
A) 10000 B) 20000 C) 25000 D) 22235 E) none of these | <gadget id="calculator">2_500 * 100</gadget>
<output>250_000</output>
<gadget id="calculator">250_000 / 25</gadget>
<output>10_000</output>
<result>A</result> | A | 10,000 | Sheela deposits Rs. 2500 in bank savings account. If this is 25% of her monthly income. What is her monthly income in? | {
"A": "10000",
"B": "20000",
"C": "25000",
"D": "22235",
"E": "none of these"
} | divide(multiply(2500, const_100), 25) | multiply(n0,const_100)|divide(#0,n1) | explanation : 25 % of income = rs . 2500 100 % of income = 2500 x 100 / 25 = rs . 10000 answer : a | gain |
math_qa__68f6rZ18RKxC8Oua | In one hour, a boat goes 15 km along the stream and 5 km against the stream. the sped of the boat in still water (in km/hr) is :
Choose the correct choice from the following choices:
A) 3 B) 5 C) 8 D) 9 E) 10 | <gadget id="calculator">15 + 5</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>E</result> | E | 10 | In one hour, a boat goes 15 km along the stream and 5 km against the stream. the sped of the boat in still water (in km/hr) is : | {
"A": "3",
"B": "5",
"C": "8",
"D": "9",
"E": "10"
} | divide(add(15, 5), const_2) | add(n0,n1)|divide(#0,const_2)| | "solution speed in still water = 1 / 2 ( 15 + 5 ) km / hr = 10 kmph . answer e" | gain |
math_qa__u8YPYucOZ1tv5S77 | If a certain number is divided by 3, the quotient, dividend, and divisor, added together, will amount to 63. What is the number? Choose the correct choice from the following
A) 18 B) 28 C) 45 D) 38 E) 59 | <gadget id="calculator">63 - 3</gadget>
<output>60</output>
<gadget id="calculator">60 * 3</gadget>
<output>180</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">180 / 4</gadget>
<output>45</output>
<result>C</result> | C | 45 | If a certain number is divided by 3, the quotient, dividend, and divisor, added together, will amount to 63. What is the number? | {
"A": "18",
"B": "28",
"C": "45",
"D": "38",
"E": "59"
} | divide(multiply(subtract(63, 3), 3), add(3, const_1)) | add(n0,const_1)|subtract(n1,n0)|multiply(n0,#1)|divide(#2,#0)| | "let x = the number sought . then x / 3 + x + 3 = 63 . and x = 45 . c" | general |
math_qa__oOcFrckJg3FzChn4 | An electric pump can fill a tank in 7 hours. Because of a leak in the tank, it took 14hours to fill the tank. If the tank is full, how much time will the leak take to empty it? Choose the correct choice from the following choices
A) 10 hours B) 12 hours C) 8 hours D) 5 hours E) 14 hours | <gadget id="calculator">14 / 1</gadget>
<output>14</output>
<result>E</result> | E | 14 | An electric pump can fill a tank in 7 hours. Because of a leak in the tank, it took 14hours to fill the tank. If the tank is full, how much time will the leak take to empty it? | {
"A": "10 hours",
"B": "12 hours",
"C": "8 hours",
"D": "5 hours",
"E": "14 hours"
} | divide(14, const_1) | divide(n1,const_1)| | "work done by the leak in 1 hour = 1 / 7 - 1 / 14 = 1 / 14 the leak will empty the tank in 14 hours answer is e" | physics |
math_qa__YCVf7cwyFJWywSZu | A vendor sells 30 percent of the apples he had and throws away 20 percent of the remainder. The next day, the vendor sells 50 percent of the remaining apples and throws away the rest. In total, what percent of his apples does the vendor throw away? Select the correct option.
A) 40 B) 42 C) 44 D) 46 E) 48 | <gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 70</gadget>
<output>14</output>
<gadget id="calculator">70 - 14</gadget>
<output>56</output>
<gadget id="calculator">56 / 2</gadget>
<output>28</output>
<gadget id="calculator">28 + 14</gadget>
<output>42</output>
<result>B</result> | B | 42 | A vendor sells 30 percent of the apples he had and throws away 20 percent of the remainder. The next day, the vendor sells 50 percent of the remaining apples and throws away the rest. In total, what percent of his apples does the vendor throw away? | {
"A": "40",
"B": "42",
"C": "44",
"D": "46",
"E": "48"
} | add(divide(subtract(subtract(const_100, 30), multiply(divide(20, const_100), subtract(const_100, 30))), const_2), multiply(divide(20, const_100), subtract(const_100, 30))) | divide(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|subtract(#1,#2)|divide(#3,const_2)|add(#4,#2) | let x be the original number of apples . on day one , the vendor throws away ( 0.2 ) ( 0.7 ) x = 0.14 x . the remaining apples are ( 0.8 ) ( 0.7 ) x = 0.56 x . on day two , the vendor throws away ( 0.5 ) ( 0.56 ) x = 0.28 x . the vendor throws away a total of 0.14 x + 0.28 x = 0.42 x . the vendor throws away 42 percent of the apples . the answer is b . | general |
math_qa__puk93yjmPdSSq8mh | There is a train and car. The ratio btw the speed of a train & a car is 16:15 respectively. Also, a bus covered a distance of 480km in 8h. The speed of the bus is 3/4th of the speed of the train. How much distance will the car cover in 6h? Choose the correct choice
A) 300 km B) 320 km C) 370 km D) 430 km E) 450 km | <gadget id="calculator">480 / 8</gadget>
<output>60</output>
<gadget id="calculator">60 * 4</gadget>
<output>240</output>
<gadget id="calculator">240 / 3</gadget>
<output>80</output>
<gadget id="calculator">80 * 15</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 16</gadget>
<output>75</output>
<gadget id="calculator">75 * 6</gadget>
<output>450</output>
<result>E</result> | E | 450 | There is a train and car. The ratio btw the speed of a train & a car is 16:15 respectively. Also, a bus covered a distance of 480km in 8h. The speed of the bus is 3/4th of the speed of the train. How much distance will the car cover in 6h? | {
"A": "300 km",
"B": "320 km",
"C": "370 km",
"D": "430 km",
"E": "450 km"
} | multiply(divide(multiply(divide(multiply(divide(480, 8), 4), 3), 15), 16), 6) | divide(n2,n3)|multiply(n5,#0)|divide(#1,n4)|multiply(n1,#2)|divide(#3,n0)|multiply(n6,#4) | sol . speed of bus = 480 / 8 = 60 km / h speed of train = ( 60 * 4 ) / 3 = 80 km / h speed of train : speed of car = 16 : 15 speed of car = 80 / 16 * 15 = 75 km / h distance covered by car in 6 hr = 75 × 6 = 450 km e | physics |
math_qa__ao5RN1xOIIb7JdBS | If the simple interest on a sum of money for 2 years at 5% per annum is Rs.50, what is the compound interest on the same at the same rate and for the same time? Choose the correct choice from the following:
A) rs . 52 B) rs . 51.25 C) rs . 54.25 D) rs . 60 E) rs . 70 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 2</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">50 / (1/10)</gadget>
<output>500</output>
<gadget id="calculator">500 * 5</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 / 100</gadget>
<output>25</output>
<gadget id="calculator">25 + 500</gadget>
<output>525</output>
<gadget id="calculator">525 * 5</gadget>
<output>2_625</output>
<gadget id="calculator">2_625 / 100</gadget>
<output>105/4 = around 26.25</output>
<gadget id="calculator">525 + (105/4)</gadget>
<output>2_205/4 = around 551.25</output>
<gadget id="calculator">(2_205/4) - 500</gadget>
<output>205/4 = around 51.25</output>
<result>B</result> | B | 51.25 | If the simple interest on a sum of money for 2 years at 5% per annum is Rs.50, what is the compound interest on the same at the same rate and for the same time? | {
"A": "rs . 52",
"B": "rs . 51.25",
"C": "rs . 54.25",
"D": "rs . 60",
"E": "rs . 70"
} | subtract(add(add(divide(multiply(divide(50, multiply(divide(5, const_100), 2)), 5), const_100), divide(50, multiply(divide(5, const_100), 2))), divide(multiply(add(divide(multiply(divide(50, multiply(divide(5, const_100), 2)), 5), const_100), divide(50, multiply(divide(5, const_100), 2))), 5), const_100)), divide(50, multiply(divide(5, const_100), 2))) | divide(n1,const_100)|multiply(n0,#0)|divide(n2,#1)|multiply(n1,#2)|divide(#3,const_100)|add(#4,#2)|multiply(n1,#5)|divide(#6,const_100)|add(#5,#7)|subtract(#8,#2)| | "simple interest for 2 years = rs . 50 ie . for 1 years rs . 25 . . in the first year the s . i and c . i are same ie . rs . 25 . so in the 2 nd year in c . i calculated for 1 years interest also . so in second years for rs . 25 interest is 25 * 5 / 100 = 1.25 . so total c . p = 51.25 . answer : b" | gain |
math_qa__0yLt7wgwheYfOg0G | Of 61 players on a cricket team, 37 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? Select.
A) 53 B) 55 C) 59 D) 71 E) 92 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">61 - 37</gadget>
<output>24</output>
<gadget id="calculator">(2/3) * 24</gadget>
<output>16</output>
<gadget id="calculator">37 + 16</gadget>
<output>53</output>
<result>A</result> | A | 53 | Of 61 players on a cricket team, 37 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? | {
"A": "53",
"B": "55",
"C": "59",
"D": "71",
"E": "92"
} | add(37, multiply(subtract(const_1, divide(const_1, const_3)), subtract(61, 37))) | divide(const_1,const_3)|subtract(n0,n1)|subtract(const_1,#0)|multiply(#2,#1)|add(n1,#3)| | "total = 61 thrower = 37 rest = 61 - 37 = 24 left handed = 24 / 3 = 8 right handed = 16 if all thrower are right handed then total right handed is 37 + 16 = 53 so a . 53 is the right answer" | general |
math_qa__BbH1JXuNuw5oQvts | A person bought 118 glass bowls at a rate of Rs. 12 per bowl. He sold 102 of them at Rs. 15 and the remaining broke. What is the percentage gain for A? Options.
A) 40 B) 300 / 11 C) 243 / 7 D) 475 / 59 E) 279 / 8 | <gadget id="calculator">102 * 15</gadget>
<output>1_530</output>
<gadget id="calculator">118 * 12</gadget>
<output>1_416</output>
<gadget id="calculator">1_530 - 1_416</gadget>
<output>114</output>
<gadget id="calculator">114 / 1_416</gadget>
<output>19/236 = around 0.080508</output>
<gadget id="calculator">(19/236) * 100</gadget>
<output>475/59 = around 8.050847</output>
<result>D</result> | D | 8.050847 | A person bought 118 glass bowls at a rate of Rs. 12 per bowl. He sold 102 of them at Rs. 15 and the remaining broke. What is the percentage gain for A? | {
"A": "40",
"B": "300 / 11",
"C": "243 / 7",
"D": "475 / 59",
"E": "279 / 8"
} | multiply(divide(subtract(multiply(102, 15), multiply(118, 12)), multiply(118, 12)), const_100) | multiply(n2,n3)|multiply(n0,n1)|subtract(#0,#1)|divide(#2,#1)|multiply(#3,const_100) | cp = 118 * 12 = 1416 and sp = 102 * 15 = 1530 gain % = 100 * ( 1530 - 1416 ) / 1100 = 11400 / 1416 = 475 / 59 answer : d | gain |
math_qa__YEXtxA8ewZISlEW4 | An engineering student has to secure 36% marks to pass. He gets 130 marks and fails by 14 marks. The maximum No. of marks obtained by him is?
Choose the correct choice from the following choices:
A) 300 B) 400 C) 500 D) 600 E) 700 | <gadget id="calculator">130 + 14</gadget>
<output>144</output>
<gadget id="calculator">144 * 100</gadget>
<output>14_400</output>
<gadget id="calculator">14_400 / 36</gadget>
<output>400</output>
<result>B</result> | B | 400 | An engineering student has to secure 36% marks to pass. He gets 130 marks and fails by 14 marks. The maximum No. of marks obtained by him is? | {
"A": "300",
"B": "400",
"C": "500",
"D": "600",
"E": "700"
} | divide(multiply(add(130, 14), const_100), 36) | add(n1,n2)|multiply(#0,const_100)|divide(#1,n0)| | "130 14 - - - - - - - 361 - - - - - - 144 100 % - - - - - - ? = > 400 answer : b" | gain |
math_qa__6lPIUzjpQ8iCCwex | What is the CP of Rs 100 stock at 2 discount, with 1/5% brokerage?
Choose the correct answer.
A) 99.6 B) 96.2 C) 97.5 D) 98.2 E) none of these | <gadget id="calculator">100 - 2</gadget>
<output>98</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">98 + (1/5)</gadget>
<output>491/5 = around 98.2</output>
<result>D</result> | D | 98.2 | What is the CP of Rs 100 stock at 2 discount, with 1/5% brokerage? | {
"A": "99.6",
"B": "96.2",
"C": "97.5",
"D": "98.2",
"E": "none of these"
} | add(subtract(100, 2), divide(1, 5)) | divide(n2,n3)|subtract(n0,n1)|add(#0,#1)| | "explanation : use the formula , cp = 100 â € “ discount + brokerage % cp = 100 - 2 + 1 / 5 98.2 thus the cp is rs 98.2 . answer d" | gain |
math_qa__FuMZuCRrzcIlHLj0 | Two trains of length 100 meters and 200 meters are 840 meters apart. They are moving towards each other on parallel tracks, at speeds of 54 km/h and 72 km/h. After how many seconds will the trains meet?
Pick.
A) 20 B) 22 C) 24 D) 26 E) 28 | <gadget id="calculator">54 + 72</gadget>
<output>126</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">126 * (5/18)</gadget>
<output>35</output>
<gadget id="calculator">840 / 35</gadget>
<output>24</output>
<result>C</result> | C | 24 | Two trains of length 100 meters and 200 meters are 840 meters apart. They are moving towards each other on parallel tracks, at speeds of 54 km/h and 72 km/h. After how many seconds will the trains meet? | {
"A": "20",
"B": "22",
"C": "24",
"D": "26",
"E": "28"
} | divide(840, multiply(add(54, 72), const_0_2778)) | add(n3,n4)|multiply(#0,const_0_2778)|divide(n2,#1)| | "the speeds are 54000 / 3600 = 15 m / s and 72000 / 3600 = 20 m / s the relative speed is 35 m / s . time = 840 / 35 = 24 seconds the answer is c ." | physics |
math_qa__fZdoli5Mlrtq9fy8 | If a man walks to his office at ¾ of his usual rate, he reaches office 1/3 of an hour late than usual. What is his usual time to reach office?
Choose the most appropriate option
A) 2 hour B) 5 hour C) 1 hour D) 3 hour E) 2 hour | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(3/4) * (1/3)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / (1/4)</gadget>
<output>1</output>
<result>C</result> | C | 1 | If a man walks to his office at ¾ of his usual rate, he reaches office 1/3 of an hour late than usual. What is his usual time to reach office? | {
"A": "2 hour",
"B": "5 hour",
"C": "1 hour",
"D": "3 hour",
"E": "2 hour"
} | divide(multiply(divide(3, const_4), divide(1, 3)), subtract(const_1, divide(3, const_4))) | divide(n1,const_4)|divide(n0,n1)|multiply(#0,#1)|subtract(const_1,#0)|divide(#2,#3) | c 1 hour speed ratio = 1 : 3 / 4 = 4 : 3 time ratio = 3 : 4 1 - - - - - - - - 1 / 3 3 - - - - - - - - - ? 1 hour | gain |
math_qa__7G11pEx4TKK47xtz | A batsman in his 15th innings makes a score of 85, and thereby increases his average by 3. What is his average after the 15th innings? He had never been ’not out’.
Choose the correct option
A) 47 B) 37 C) 39 D) 43 E) 42 | <gadget id="calculator">3 * 15</gadget>
<output>45</output>
<gadget id="calculator">85 - 45</gadget>
<output>40</output>
<gadget id="calculator">40 + 3</gadget>
<output>43</output>
<result>D</result> | D | 43 | A batsman in his 15th innings makes a score of 85, and thereby increases his average by 3. What is his average after the 15th innings? He had never been ’not out’. | {
"A": "47",
"B": "37",
"C": "39",
"D": "43",
"E": "42"
} | add(subtract(85, multiply(3, 15)), 3) | multiply(n0,n2)|subtract(n1,#0)|add(n2,#1)| | "average score before 15 th innings = 85 - 3 × 15 = 40 average score after 15 th innings = > 40 + 3 = 43 answer : d" | general |
math_qa__FzGeJCG6Menn8h21 | A candidate appearing for an examination has to secure 40% marks to pass paper I. But he secured only 40 marks and failed by 20 marks. What is the maximum mark for paper I? Select the correct option.
A) 110 B) 120 C) 130 D) 140 E) 150 | <gadget id="calculator">40 + 20</gadget>
<output>60</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">60 / (2/5)</gadget>
<output>150</output>
<result>E</result> | E | 150 | A candidate appearing for an examination has to secure 40% marks to pass paper I. But he secured only 40 marks and failed by 20 marks. What is the maximum mark for paper I? | {
"A": "110",
"B": "120",
"C": "130",
"D": "140",
"E": "150"
} | divide(add(40, 20), divide(40, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "he secured 40 marks nd fail by 20 marks so total marks for pass the examinatn = 60 let toal marks x x * 40 / 100 = 60 x = 150 answer : e" | gain |
math_qa__KkRGw3006MbIncJj | Two-third of a positive number and 49/216 of its reciprocal are equal. The number is: Choose the correct choice from the following
A) 5 / 12
B) 7 / 12
C) 25 / 144
D) 144 / 25
E) 146 / 25 | <gadget id="calculator">49 * 3</gadget>
<output>147</output>
<gadget id="calculator">216 * 2</gadget>
<output>432</output>
<gadget id="calculator">147 / 432</gadget>
<output>49/144 = around 0.340278</output>
<gadget id="calculator">(49/144) ** (1/2)</gadget>
<output>7/12 = around 0.583333</output>
<result>B</result> | B | 0.583333 | Two-third of a positive number and 49/216 of its reciprocal are equal. The number is: | {
"A": "5 / 12",
"B": "7 / 12",
"C": "25 / 144",
"D": "144 / 25",
"E": "146 / 25"
} | sqrt(divide(multiply(49, const_3), multiply(216, const_2))) | multiply(n0,const_3)|multiply(n1,const_2)|divide(#0,#1)|sqrt(#2)| | "let the number be x . then , 2 / 3 x = 49 / 216 * 1 / x x 2 = 49 / 216 * 3 / 2 = 49 / 144 x = 7 / 12 answer : b" | general |
math_qa__bsxF3uOYLXDQrAU8 | A race course is 400 m long. AA and BB run a race and AA wins by 5m. BB and CC run over the same course and BB win by 4m. CC and DD run over it and DD wins by 16m. If AA and DD run over it, then who would win and by how much? Choose the correct choice from the following
A) 7.1 m B) 7.2 m C) 8 m D) 9 m E) 11 m | <gadget id="calculator">16 - 5</gadget>
<output>11</output>
<gadget id="calculator">11 / 4</gadget>
<output>11/4 = around 2.75</output>
<gadget id="calculator">(11/4) + 5</gadget>
<output>31/4 = around 7.75</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(31/4) - (1/4)</gadget>
<output>15/2 = around 7.5</output>
<result>B</result> | B | 7.2 | A race course is 400 m long. AA and BB run a race and AA wins by 5m. BB and CC run over the same course and BB win by 4m. CC and DD run over it and DD wins by 16m. If AA and DD run over it, then who would win and by how much? | {
"A": "7.1 m",
"B": "7.2 m",
"C": "8 m",
"D": "9 m",
"E": "11 m"
} | subtract(add(divide(subtract(16, 5), 4), 5), const_0_25) | subtract(n3,n1)|divide(#0,n2)|add(n1,#1)|subtract(#2,const_0_25) | if aa covers 400 m , bb covers 395 m if bb covers 400 m , cc covers 396 m if dd covers 400 m , cc covers 384 m now if bb covers 395 m , then cc will cover 396400 × 395 = 391.05396400 × 395 = 391.05 m if cc covers 391.05 m , then dd will cover 400384 × 391.05 = 407.24400384 × 391.05 = 407.24 if aa and dd run over 400 m , then dd win by 7.2 m option b | physics |
math_qa__LYJZk89HGv4siUup | A boat takes 19 hours for travelling downstream from point A to point B and coming back to a point C midway between A and B. If the velocity of the stream is 4 kmph and the speed of the boat in still water is 14 kmph, what is the distance between A and B ? Select
A) 160 km B) 180 km C) 200 km D) 220 km E) 240 km | <gadget id="calculator">14 + 4</gadget>
<output>18</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">14 - 4</gadget>
<output>10</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/18) + (1/20)</gadget>
<output>19/180 = around 0.105556</output>
<gadget id="calculator">19 / (19/180)</gadget>
<output>180</output>
<result>B</result> | B | 180 | A boat takes 19 hours for travelling downstream from point A to point B and coming back to a point C midway between A and B. If the velocity of the stream is 4 kmph and the speed of the boat in still water is 14 kmph, what is the distance between A and B ? | {
"A": "160 km",
"B": "180 km",
"C": "200 km",
"D": "220 km",
"E": "240 km"
} | divide(19, add(divide(const_1, add(14, 4)), divide(const_1, multiply(subtract(14, 4), const_2)))) | add(n1,n2)|subtract(n2,n1)|divide(const_1,#0)|multiply(#1,const_2)|divide(const_1,#3)|add(#2,#4)|divide(n0,#5) | down stream speed : ( 14 + 4 ) km / hr = 18 km / hr up stream speed : ( 14 - 4 ) km / hr = 10 km / hr ( x / 18 ) + ( x / 2 / 20 ) = 19 x = 180 km answer : b | physics |
math_qa__OVVPS9e6mNPL6EP9 | A man's speed with the current is 18 km/hr and the speed of the current is 3.4 km/hr. The man's speed against the current is Choose one
A) 9 B) 10.4 C) 11.2 D) 12.5 E) 13 | <gadget id="calculator">18 - 3.4</gadget>
<output>14.6</output>
<gadget id="calculator">14.6 - 3.4</gadget>
<output>11.2</output>
<result>C</result> | C | 11.2 | A man's speed with the current is 18 km/hr and the speed of the current is 3.4 km/hr. The man's speed against the current is | {
"A": "9",
"B": "10.4",
"C": "11.2",
"D": "12.5",
"E": "13"
} | subtract(subtract(18, 3.4), 3.4) | subtract(n0,n1)|subtract(#0,n1)| | "man ' s rate in still water = ( 18 - 3.4 ) km / hr = 14.6 km / hr . man ' s rate against the current = ( 14.6 - 3.4 ) km / hr = 11.2 km / hr . answer : c" | gain |
math_qa__lJxiESOUcIhqWMLd | In Town P, 60 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town P are females? Choose the correct choice from the following:
A) 20 %
B) 25 %
C) 30 %
D) 35 %
E) 40 % | <gadget id="calculator">60 - 48</gadget>
<output>12</output>
<gadget id="calculator">12 / 60</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>A</result> | A | 20 | In Town P, 60 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town P are females? | {
"A": "20 %",
"B": "25 %",
"C": "30 %",
"D": "35 %",
"E": "40 %"
} | multiply(divide(subtract(60, 48), 60), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "the percent of the population who are employed females is 60 - 48 = 12 % the percent of employed people who are female is 12 % / 60 % = 20 % . the answer is a ." | gain |
math_qa__bE7cRdV6paTjgxxt | Average monthly income of a family of 4 earning members was Rs. 782. One of the earning members died and therefore, the average income came down to Rs 650. The income of the deceased was?
Choose the correct choice from the following choices:
A) rs . 1178 B) rs . 820 C) rs . 990 D) rs . 1385 E) none | <gadget id="calculator">782 * 4</gadget>
<output>3_128</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">650 * 3</gadget>
<output>1_950</output>
<gadget id="calculator">3_128 - 1_950</gadget>
<output>1_178</output>
<result>A</result> | A | 1,178 | Average monthly income of a family of 4 earning members was Rs. 782. One of the earning members died and therefore, the average income came down to Rs 650. The income of the deceased was? | {
"A": "rs . 1178",
"B": "rs . 820",
"C": "rs . 990",
"D": "rs . 1385",
"E": "none"
} | subtract(multiply(782, 4), multiply(650, subtract(4, const_1))) | multiply(n0,n1)|subtract(n0,const_1)|multiply(n2,#1)|subtract(#0,#2)| | "answer income of the deceased = total income of 4 members - total income of remaining 3 members . = 782 x 4 - 650 x 3 rs . = 1178 rs . correct option : a" | general |
math_qa__OhJulxDi9joKj1PY | A train 350 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train? Choose the correct choice from the following: A) 5 sec B) 9 sec C) 12 sec D) 21 sec E) 18 sec | <gadget id="calculator">68 - 8</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">350 / (50/3)</gadget>
<output>21</output>
<result>D</result> | D | 21 | A train 350 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train? | {
"A": "5 sec",
"B": "9 sec",
"C": "12 sec",
"D": "21 sec",
"E": "18 sec"
} | divide(350, multiply(subtract(68, 8), const_0_2778)) | subtract(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of the train relative to man = ( 68 - 8 ) kmph = ( 60 * 5 / 18 ) m / sec = ( 50 / 3 ) m / sec time taken by the train to cross the man = time taken by it to cover 350 m at 50 / 3 m / sec = 350 * 3 / 50 sec = 21 sec answer : d" | physics |
math_qa__HBihi8er6ra83KeV | What is remainder of the division (1125*1127*1129)/12?
Answers
A) 0
B) 3
C) 1
D) 2
E) 4 | <gadget id="calculator">1_125 * 1_127</gadget>
<output>1_267_875</output>
<gadget id="calculator">1_267_875 * 1_129</gadget>
<output>1_431_430_875</output>
<gadget id="calculator">1_431_430_875 - 3</gadget>
<output>1_431_430_872</output>
<gadget id="calculator">1_431_430_875 - 1_431_430_872</gadget>
<output>3</output>
<result>B</result> | B | 3 | What is remainder of the division (1125*1127*1129)/12? | {
"A": "0",
"B": "3",
"C": "1",
"D": "2",
"E": "4"
} | subtract(multiply(multiply(1125, 1127), 1129), subtract(multiply(multiply(1125, 1127), 1129), const_3)) | multiply(n0,n1)|multiply(n2,#0)|subtract(#1,const_3)|subtract(#1,#2)| | "remainder will be number / 100 here as the divisor is two digit number = 12 . hence checking for the last two digits = 5 * 7 * 9 = 15 thus remainder = 3 . answer : b" | general |
math_qa__cVN7U82yLUaMc6nO | The average salary of all the workers in a workshop is Rs.8000. The average salary of 7 technicians is Rs.8000 and the average salary of the rest is Rs.6000. The total number of workers in the workshop is
Choose the correct option:
A) 20 B) 21 C) 22 D) 7 E) 24 | <gadget id="calculator">8_000 - 8_000</gadget>
<output>0</output>
<gadget id="calculator">7 * 0</gadget>
<output>0</output>
<gadget id="calculator">8_000 - 6_000</gadget>
<output>2_000</output>
<gadget id="calculator">0 / 2_000</gadget>
<output>0</output>
<gadget id="calculator">7 + 0</gadget>
<output>7</output>
<result>D</result> | D | 7 | The average salary of all the workers in a workshop is Rs.8000. The average salary of 7 technicians is Rs.8000 and the average salary of the rest is Rs.6000. The total number of workers in the workshop is | {
"A": "20",
"B": "21",
"C": "22",
"D": "7",
"E": "24"
} | add(7, divide(multiply(7, subtract(8000, 8000)), subtract(8000, 6000))) | subtract(n2,n0)|subtract(n0,n3)|multiply(n1,#0)|divide(#2,#1)|add(n1,#3)| | "solution let the toatl number of workers be x . then 8000 x = ( 8000 x 7 ) + 6000 ( x - 7 ) x = 7 . answer d" | general |
math_qa__M22wE36Da3ahDgDr | A library has an average of 140 visitors on Sundays and 80 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is : Choose the correct option:
A) 90
B) 100
C) 105
D) 110
E) 125 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">30 / 7</gadget>
<output>30/7 = around 4.285714</output>
<gadget id="calculator">floor(30/7)</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 140</gadget>
<output>700</output>
<gadget id="calculator">30 - 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 80</gadget>
<output>2_000</output>
<gadget id="calculator">700 + 2_000</gadget>
<output>2_700</output>
<gadget id="calculator">2_700 / 30</gadget>
<output>90</output>
<result>A</result> | A | 90 | A library has an average of 140 visitors on Sundays and 80 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is : | {
"A": "90",
"B": "100",
"C": "105",
"D": "110",
"E": "125"
} | divide(add(multiply(add(floor(divide(30, add(const_3, const_4))), const_1), 140), multiply(subtract(30, add(floor(divide(30, add(const_3, const_4))), const_1)), 80)), 30) | add(const_3,const_4)|divide(n2,#0)|floor(#1)|add(#2,const_1)|multiply(n0,#3)|subtract(n2,#3)|multiply(n1,#5)|add(#4,#6)|divide(#7,n2)| | "explanation : since the month begins with a sunday , so there will be five sundays in the month , required average = ( 140 * 5 + 80 * 25 ) / 30 = 2700 / 30 = 90 answer : a ) 90" | general |
math_qa__tjqV45L4Nnre2pE3 | The diagonal of a rhombus are 62 m and 80 m. Its area is: Pick one: A) 1940 B) 2480 C) 2460 D) 2500 E) 1980 | <gadget id="calculator">(62 * 80) / 2</gadget>
<output>2_480</output>
<result>B</result> | B | 2,480 | The diagonal of a rhombus are 62 m and 80 m. Its area is: | {
"A": "1940",
"B": "2480",
"C": "2460",
"D": "2500",
"E": "1980"
} | rhombus_area(62, 80) | rhombus_area(n0,n1)| | "area of the rhombus = 1 / 2 d 1 d 2 = ( 1 / 2 ã — 62 ã — 80 ) cm ( power ) 2 = 62 ã — 40 = 2480 cm ( power ) 2 answer is b ." | geometry |
math_qa__ly3tmKY5p6VgyKku | The distance from City A to City B is 180 miles. While driving from City A to City B, Bob drives at a constant speed of 40 miles per hour. Alice leaves City A 30 minutes after Bob. What is the minimum constant speed in miles per hour that Alice must exceed in order to arrive in City B before Bob?
Pick one: A) 45 B) 48 C) 50 D) 52 E) 54 | <gadget id="calculator">180 / 40</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">30 / 60</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(9/2) - (1/2)</gadget>
<output>4</output>
<gadget id="calculator">180 / 4</gadget>
<output>45</output>
<result>A</result> | A | 45 | The distance from City A to City B is 180 miles. While driving from City A to City B, Bob drives at a constant speed of 40 miles per hour. Alice leaves City A 30 minutes after Bob. What is the minimum constant speed in miles per hour that Alice must exceed in order to arrive in City B before Bob? | {
"A": "45",
"B": "48",
"C": "50",
"D": "52",
"E": "54"
} | divide(180, subtract(divide(180, 40), divide(30, const_60))) | divide(n0,n1)|divide(n2,const_60)|subtract(#0,#1)|divide(n0,#2)| | "the time it takes bob to drive to city b is 180 / 40 = 4.5 hours . alice needs to take less than 4 hours for the trip . alice needs to exceed a constant speed of 180 / 4 = 45 miles per hour . the answer is a ." | physics |
math_qa__T3VqgRQ1fXbdUfNO | A soccer store typically sells replica jerseys at a discount of 30 percent to 50 percent off list price. During the annual summer sale, everything in the store is an additional 20 percent off the original list price. If a replica jersey's list price is $80, approximately what percent of the list price is the lowest possible sale price? Choose the correct option: A) 20 B) 25 C) 30 D) 40 E) 50 | <gadget id="calculator">80 / 2</gadget>
<output>40</output>
<result>D</result> | D | 40 | A soccer store typically sells replica jerseys at a discount of 30 percent to 50 percent off list price. During the annual summer sale, everything in the store is an additional 20 percent off the original list price. If a replica jersey's list price is $80, approximately what percent of the list price is the lowest possible sale price? | {
"A": "20",
"B": "25",
"C": "30",
"D": "40",
"E": "50"
} | divide(80, const_2) | divide(n3,const_2)| | "let the list price be 2 x for min sale price , the first discount given should be 50 % , 2 x becomes x here now , during summer sale additional 20 % off is given ie sale price becomes 0.8 x it is given lise price is $ 80 = > 2 x = 80 = > x = 40 and 0.8 x = 32 so lowest sale price is 32 , which is 40 % of 80 hence , d is the answer" | general |
math_qa__7NxkRwwGyLNTl4G9 | Find the least number must be added to 228712 so that remaining no.is divisible by 9? Choose the correct choice from the following choices: A) 5 B) 3 C) 1 D) 6 E) 2 | <gadget id="calculator">228_712 % 9</gadget>
<output>4</output>
<gadget id="calculator">9 - 4</gadget>
<output>5</output>
<result>A</result> | A | 5 | Find the least number must be added to 228712 so that remaining no.is divisible by 9? | {
"A": "5",
"B": "3",
"C": "1",
"D": "6",
"E": "2"
} | subtract(9, reminder(228712, 9)) | reminder(n0,n1)|subtract(n1,#0) | on dividing 228712 by 9 we get the remainder 4 , so 5 should be subtracted a | general |
math_qa__mqFwoAagCNzvtdaa | How many revolutions will a circular wheel make to travel a distance of 3 km, given that the radius is 2.4 m? Choose the correct choice from the following answers:
A) 11085.7
B) 15085.7
C) 35085.7
D) 15015.7
E) 15083.7 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">(22/7) * 2</gadget>
<output>44/7 = around 6.285714</output>
<gadget id="calculator">(44/7) * 2.4</gadget>
<output>15.085714</output>
<gadget id="calculator">15.085714 * 1_000</gadget>
<output>15_085.714</output>
<gadget id="calculator">3 * 1_000</gadget>
<output>3_000</output>
<gadget id="calculator">15_085.714 - 3_000</gadget>
<output>12_085.714</output>
<gadget id="calculator">12_085.714 - 1_000</gadget>
<output>11_085.714</output>
<result>A</result> | A | 11,085.7 | How many revolutions will a circular wheel make to travel a distance of 3 km, given that the radius is 2.4 m? | {
"A": "11085.7",
"B": "15085.7",
"C": "35085.7",
"D": "15015.7",
"E": "15083.7"
} | subtract(subtract(multiply(multiply(multiply(divide(add(multiply(const_2, const_10), const_2), add(const_4, const_3)), const_2), 2.4), const_1000), multiply(const_3, const_1000)), const_1000) | add(const_3,const_4)|multiply(const_10,const_2)|multiply(const_1000,const_3)|add(#1,const_2)|divide(#3,#0)|multiply(#4,const_2)|multiply(n1,#5)|multiply(#6,const_1000)|subtract(#7,#2)|subtract(#8,const_1000) | 2 * 22 / 7 * 2.4 * x = 15085.7 x = 1000 answer : a | physics |
math_qa__eTvIKwB4bdZ0Xh3j | If 4 gallons of gasoline are added to a tank that is already filled to 3/4 of its capacity, the tank is then filled to 9/10 of its capacity. How many gallons does the tank hold?
Choose the correct option.
A) 20 B) 24 C) 36 D) 40 E) 60 | <gadget id="calculator">9 / 10</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(9/10) - (3/4)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">4 / (3/20)</gadget>
<output>80/3 = around 26.666667</output>
<gadget id="calculator">(80/3) * (3/4)</gadget>
<output>20</output>
<gadget id="calculator">20 + 4</gadget>
<output>24</output>
<result>B</result> | B | 24 | If 4 gallons of gasoline are added to a tank that is already filled to 3/4 of its capacity, the tank is then filled to 9/10 of its capacity. How many gallons does the tank hold? | {
"A": "20",
"B": "24",
"C": "36",
"D": "40",
"E": "60"
} | add(multiply(divide(4, subtract(divide(9, 10), divide(3, 4))), divide(3, 4)), 4) | divide(n3,n4)|divide(n1,n2)|subtract(#0,#1)|divide(n0,#2)|multiply(#3,#1)|add(n0,#4)| | "let the capacity of the tank = c ( 3 / 4 ) c + 4 = ( 9 / 10 ) c = > ( 9 / 10 ) c - ( 3 / 4 ) c = 4 = > ( 3 / 20 ) c = 4 = > c = ( 4 * 20 ) / 3 = 26.66 number of gallons of gasoline that the tank currently holds = 3 / 4 * c + 4 = 19.99 + 4 = 23.99 = 24 answer b" | general |
math_qa__RGO2kcXFV6Y6CcGH | A drink vendor has 50 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required?
Choose the correct choice from the following answers.
A) 135 B) 237 C) 281 D) 300 E) 380 | <gadget id="calculator">gcd(50, 144)</gadget>
<output>2</output>
<gadget id="calculator">gcd(2, 368)</gadget>
<output>2</output>
<gadget id="calculator">368 / 2</gadget>
<output>184</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">144 / 2</gadget>
<output>72</output>
<gadget id="calculator">25 + 72</gadget>
<output>97</output>
<gadget id="calculator">184 + 97</gadget>
<output>281</output>
<result>C</result> | C | 281 | A drink vendor has 50 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required? | {
"A": "135",
"B": "237",
"C": "281",
"D": "300",
"E": "380"
} | add(divide(368, gcd(gcd(50, 144), 368)), add(divide(50, gcd(gcd(50, 144), 368)), divide(144, gcd(gcd(50, 144), 368)))) | gcd(n0,n1)|gcd(n2,#0)|divide(n0,#1)|divide(n1,#1)|divide(n2,#1)|add(#2,#3)|add(#5,#4)| | "the number of liters in each can = hcf of 50 , 144 and 368 = 2 liters . number of cans of maaza = 50 / 2 = 25 number of cans of pepsi = 144 / 2 = 72 number of cans of sprite = 368 / 2 = 184 the total number of cans required = 25 + 72 + 184 = 281 cans . answer : c" | general |
math_qa__QsalrT99hgzrxZZn | Express a speed of 36 kmph in meters per second? Choose the most appropriate option: A) 10 mps B) 76 mps C) 26 mps D) 97 mps E) 16 mps | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 36</gadget>
<output>10</output>
<result>A</result> | A | 10 | Express a speed of 36 kmph in meters per second? | {
"A": "10 mps",
"B": "76 mps",
"C": "26 mps",
"D": "97 mps",
"E": "16 mps"
} | multiply(const_0_2778, 36) | multiply(n0,const_0_2778)| | "36 * 5 / 18 = 10 mps answer : a" | physics |
math_qa__ujLiYDiIpW7mecLi | Lily shop runs a sale on goldfish and platys. If one customer buys 13 goldfish and 12 platys for $5.60, and another buys 14 goldfish and 21 platys for $8.05, what is the ratio of the price of goldfish to platys? Choose the correct answer.
A) 0.8 B) 0.75 C) 8 / 9 D) 5 / 7 E) 6 / 8 | <gadget id="calculator">5.6 / 8.05</gadget>
<output>0.695652</output>
<result>D</result> | D | 0.714286 | Lily shop runs a sale on goldfish and platys. If one customer buys 13 goldfish and 12 platys for $5.60, and another buys 14 goldfish and 21 platys for $8.05, what is the ratio of the price of goldfish to platys? | {
"A": "0.8",
"B": "0.75",
"C": "8 / 9",
"D": "5 / 7",
"E": "6 / 8"
} | divide(5.6, 8.05) | divide(n2,n5) | the approach of plugging in the numbers is a fine approach . but , in this case , the answer was the first option and thus , by plugging in a number in the ration given , we arrived at the answer quickly ! however , what if the correct ratio was option d or c ? in any case , the algebraic solution is n ' t that complex if you realize a key concept : the number 7 can be factored out of the second equation ! here ' s the working : lily shop runs a sale on goldfish and platys . 13 x + 12 y = 5.60 < < < < < equation 1 14 x + 21 y = 8.05 < < < < < equation 2 2 x + 3 y = 1.15 [ factor out 7 from equation 2 ] < < < < < equation 3 8 x + 12 y = 4.6 [ multiply equation 3 with 4 ] 5 x = 1.0 [ equation 1 - equation 2 ] x = 0.2 3 y = 1.15 - 0.4 = 0.75 [ substitute for x in equation 1 ] y = 0.25 x / y = 0.2 / 0.25 = 20 / 25 = 4 / 5 = 0.8 [ answer a ] the whole thing must have taken me about 45 s : d | other |
math_qa__1JrJBoH3mdkM9WyT | In a class,9 students like to play Basketball and 8 like to play Cricket. 6 students like to play on both Basketball and Cricket. How many students like to play Basketball or Cricket or both?
Options: A) 12 B) 11 C) 16 D) 18 E) 22 | <gadget id="calculator">9 + 8</gadget>
<output>17</output>
<gadget id="calculator">17 - 6</gadget>
<output>11</output>
<result>B</result> | B | 11 | In a class,9 students like to play Basketball and 8 like to play Cricket. 6 students like to play on both Basketball and Cricket. How many students like to play Basketball or Cricket or both? | {
"A": "12",
"B": "11",
"C": "16",
"D": "18",
"E": "22"
} | subtract(add(9, 8), 6) | add(n0,n1)|subtract(#0,n2)| | "draw a venn diagram yourself ! b + c - bc = number of students that play either basketball or cricket 9 + 8 - 6 = 11 b )" | other |
math_qa__0w2QOTmSxPmX4ZuY | In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7000, the number of valid votes that the other candidate got, was: Choose the correct choice from the following options: A) 2800 B) 2700 C) 2900 D) 2200 E) 2520 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">55 / 100</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">1 - (11/20)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">(4/5) * (9/20)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(9/25) * 7_000</gadget>
<output>2_520</output>
<result>E</result> | E | 2,520 | In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7000, the number of valid votes that the other candidate got, was: | {
"A": "2800",
"B": "2700",
"C": "2900",
"D": "2200",
"E": "2520"
} | multiply(multiply(subtract(const_1, divide(20, const_100)), subtract(const_1, divide(55, const_100))), 7000) | divide(n1,const_100)|divide(n0,const_100)|subtract(const_1,#0)|subtract(const_1,#1)|multiply(#2,#3)|multiply(n2,#4)| | "e number of valid votes = 80 % of 7000 = 5600 . valid votes polled by other candidate = 45 % of 6000 = ( 45 / 100 x 5600 ) = 2520 ." | gain |
math_qa__tPBjKg9bGsbswo14 | If daily wages of a man is double to that of a woman, how many men should work for 10 days to earn Rs.14400? Given that wages for 40 women for 30 days are Rs.21600. Choose the correct choice from the following answers:
A) 12
B) 14
C) 16
D) 20
E) 40 | <gadget id="calculator">40 * 30</gadget>
<output>1_200</output>
<gadget id="calculator">21_600 / 1_200</gadget>
<output>18</output>
<gadget id="calculator">2 * 18</gadget>
<output>36</output>
<gadget id="calculator">10 * 36</gadget>
<output>360</output>
<gadget id="calculator">14_400 / 360</gadget>
<output>40</output>
<result>E</result> | E | 40 | If daily wages of a man is double to that of a woman, how many men should work for 10 days to earn Rs.14400? Given that wages for 40 women for 30 days are Rs.21600. | {
"A": "12",
"B": "14",
"C": "16",
"D": "20",
"E": "40"
} | divide(14400, multiply(10, multiply(const_2, divide(21600, multiply(40, 30))))) | multiply(n2,n3)|divide(n4,#0)|multiply(#1,const_2)|multiply(n0,#2)|divide(n1,#3)| | "explanation : wages of 1 woman for 1 day = 21600 / 40 ã — 30 wages of 1 man for 1 day = 21600 ã — 2 / 40 ã — 30 wages of 1 man for 10 days = 21600 ã — 2 ã — 10 / 40 ã — 30 number of men = 14400 / ( 21600 ã — 2 ã — 10 / 40 ã — 30 ) = 144 / ( 216 ã — 20 / 40 ã — 30 ) = 40 answer : option e" | physics |
math_qa__6vna2LAbEEitGSCI | The rate of spin of a certain gyroscope doubled every 10 seconds from the moment a particular stopwatch started. If after a minute and a half the gyroscope reached a speed of 1600 meters per second, what was the speed, in meters per second, when the stopwatch was started?
Choose the correct choice from the following choices:
A) 25 / 3
B) 25 / 4
C) 25 / 8
D) 25 / 16
E) 25 / 32 | <gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 + 60</gadget>
<output>90</output>
<gadget id="calculator">90 / 10</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">2 ** 8</gadget>
<output>256</output>
<gadget id="calculator">1_600 / 256</gadget>
<output>25/4 = around 6.25</output>
<gadget id="calculator">(25/4) / 2</gadget>
<output>25/8 = around 3.125</output>
<result>C</result> | C | 3.125 | The rate of spin of a certain gyroscope doubled every 10 seconds from the moment a particular stopwatch started. If after a minute and a half the gyroscope reached a speed of 1600 meters per second, what was the speed, in meters per second, when the stopwatch was started? | {
"A": "25 / 3",
"B": "25 / 4",
"C": "25 / 8",
"D": "25 / 16",
"E": "25 / 32"
} | divide(divide(1600, power(const_2, subtract(divide(add(divide(const_60, const_2), const_60), 10), const_1))), const_2) | divide(const_60,const_2)|add(#0,const_60)|divide(#1,n0)|subtract(#2,const_1)|power(const_2,#3)|divide(n1,#4)|divide(#5,const_2)| | "let x be the original speed when the stopwatch was started . in 90 seconds , the speed doubled 9 times . 2 ^ 9 * x = 1600 x = ( 2 ^ 6 * 25 ) / 2 ^ 9 = 25 / 8 the answer is c ." | physics |
math_qa__xVPlYar2ligCyavA | If two different solutions of alcohol with a respective proportion of water to alcohol of 3:1 and 2:3 were combined, what is the concentration of alcohol in the new solution if the original solutions were mixed in equal amounts?
Select the correct option.
A) 30.0 % B) 36.6 % C) 42.5 % D) 44.4 % E) 60.0 % | <gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">4 / 9</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">(4/9) * 100</gadget>
<output>400/9 = around 44.444444</output>
<result>C</result> | C | 42.5 | If two different solutions of alcohol with a respective proportion of water to alcohol of 3:1 and 2:3 were combined, what is the concentration of alcohol in the new solution if the original solutions were mixed in equal amounts? | {
"A": "30.0 %",
"B": "36.6 %",
"C": "42.5 %",
"D": "44.4 %",
"E": "60.0 %"
} | multiply(divide(add(1, 3), add(add(1, 3), add(3, 2))), const_100) | add(n0,n1)|add(n0,n2)|add(#0,#1)|divide(#0,#2)|multiply(#3,const_100) | alcohol : water first mixture - - 3 : 1 - - 15 : 5 second mixture - - 2 : 3 - - 8 : 12 equal amounts of the mixture were combined , hence the final mixture will be in the ratio - - ( 15 + 8 ) : ( 5 + 12 ) - - 23 : 17 % of alcohol - - 17 / ( 23 + 17 ) * 100 = ( 17 / 40 ) * 100 = 42.5 answer : c | general |
math_qa__opk220KKy6Q2jhKn | if the sum of 3 consecutive even numbers is 44 more than the average of these numbers , then the largest of these numbers is ? Pick one.
A) 24 B) 66 C) 9 D) 7 E) 01 | <gadget id="calculator">44 - 4</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">20 + 3</gadget>
<output>23</output>
<gadget id="calculator">23 + 1</gadget>
<output>24</output>
<result>A</result> | A | 24 | if the sum of 3 consecutive even numbers is 44 more than the average of these numbers , then the largest of these numbers is ? | {
"A": "24",
"B": "66",
"C": "9",
"D": "7",
"E": "01"
} | add(add(divide(subtract(44, const_4), const_2), 3), const_1) | subtract(n1,const_4)|divide(#0,const_2)|add(n0,#1)|add(#2,const_1) | answer : 24 explanation : let the smallest of these number be x . the other two numbers are ( x + 2 ) and ( x + 4 ) . x + ( x + 2 ) + ( x + 4 ) = ( x + ( x + 2 ) + ( x + 4 ) ) / 3 + 44 3 x + 3 * ( x + 2 ) + 3 * ( x + 4 ) = x + ( x + 2 ) + ( x + 4 ) + 132 9 x + 18 = 3 x + 138 6 x = 120 x = 20 therefore , the largest number is 24 . answer : a | general |
math_qa__v3qLUqKcdby0J0Jv | Solution Y is 30 percent liquid X and 70 percent water. If 4 kilograms of water evaporate from 8 kilograms of solution Y and 4 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new solution is liquid X? Answers
A) 40 % B) 41 1 / 2 % C) 44 % D) 45 % E) 46 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">8 * (3/10)</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">4 * (3/10)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(12/5) + (6/5)</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">8 * (7/10)</gadget>
<output>28/5 = around 5.6</output>
<gadget id="calculator">(28/5) - 4</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">4 * (7/10)</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">(8/5) + (14/5)</gadget>
<output>22/5 = around 4.4</output>
<gadget id="calculator">(18/5) + (22/5)</gadget>
<output>8</output>
<gadget id="calculator">(18/5) / 8</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">100 * (9/20)</gadget>
<output>45</output>
<result>D</result> | D | 45 | Solution Y is 30 percent liquid X and 70 percent water. If 4 kilograms of water evaporate from 8 kilograms of solution Y and 4 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new solution is liquid X? | {
"A": "40 %",
"B": "41 1 / 2 %",
"C": "44 %",
"D": "45 %",
"E": "46 %"
} | multiply(const_100, divide(add(multiply(8, divide(30, const_100)), multiply(4, divide(30, const_100))), add(add(multiply(8, divide(30, const_100)), multiply(4, divide(30, const_100))), add(subtract(multiply(8, divide(70, const_100)), 4), multiply(4, divide(70, const_100)))))) | divide(n0,const_100)|divide(n1,const_100)|multiply(n3,#0)|multiply(n2,#0)|multiply(n2,#1)|multiply(n3,#1)|add(#2,#3)|subtract(#5,n2)|add(#4,#7)|add(#6,#8)|divide(#6,#9)|multiply(#10,const_100)| | "in 8 kilograms of solution y there are 0.3 * 8 = 2.4 kilograms of solution x ; after 4 kilograms of water are replaced by 4 kilograms of solution y , to the existing 2.4 kilograms of solution x , 0.3 * 4 = 1.2 kilograms of solution x are added , so in the new solution of 8 kilograms there are 2.4 + 1.2 = 3.6 kilograms of solution x , which is 3.6 / 8 * 100 = 45 % of this new solution . answer : d ." | gain |
math_qa__qxGF9L26lYoNgIYf | A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6600?
Choose the correct choice from the following choices:
A) s . 4991 B) s . 5591 C) s . 6001 D) s . 6991 E) s . 7991 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 6_600</gadget>
<output>39_600</output>
<gadget id="calculator">6_435 + 6_927</gadget>
<output>13_362</output>
<gadget id="calculator">13_362 + 6_855</gadget>
<output>20_217</output>
<gadget id="calculator">20_217 + 7_230</gadget>
<output>27_447</output>
<gadget id="calculator">27_447 + 6_562</gadget>
<output>34_009</output>
<gadget id="calculator">39_600 - 34_009</gadget>
<output>5_591</output>
<result>B</result> | B | 5,591 | A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6600? | {
"A": "s . 4991",
"B": "s . 5591",
"C": "s . 6001",
"D": "s . 6991",
"E": "s . 7991"
} | subtract(multiply(add(5, const_1), 6600), add(add(add(add(6435, 6927), 6855), 7230), 6562)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "total fr 5 mnths = ( 6435 + 6927 + 6855 + 7230 + 6562 ) = rs 34009 . reqd . sale = rs . [ ( 6600 * 6 ) - 34009 ] = rs . ( 39600 - 34009 ) = rs . 5591 . answer : b" | general |
math_qa__4puUKEUYVGa4bRSA | A can run 3 Kms in 3 min 18 sec and B can run same distance in 3 min 40 sec, then by how much distance A can beat B? Choose the correct answer.
A) 300 m B) 220 m C) 280 m D) 195 m E) 295 m | <gadget id="calculator">3 * 1_000</gadget>
<output>3_000</output>
<gadget id="calculator">3 * 60</gadget>
<output>180</output>
<gadget id="calculator">180 + 40</gadget>
<output>220</output>
<gadget id="calculator">180 + 18</gadget>
<output>198</output>
<gadget id="calculator">220 - 198</gadget>
<output>22</output>
<gadget id="calculator">3_000 * 22</gadget>
<output>66_000</output>
<gadget id="calculator">66_000 / 220</gadget>
<output>300</output>
<result>A</result> | A | 300 | A can run 3 Kms in 3 min 18 sec and B can run same distance in 3 min 40 sec, then by how much distance A can beat B? | {
"A": "300 m",
"B": "220 m",
"C": "280 m",
"D": "195 m",
"E": "295 m"
} | divide(multiply(multiply(3, const_1000), subtract(add(multiply(3, const_60), 40), add(multiply(3, const_60), 18))), add(multiply(3, const_60), 40)) | multiply(n0,const_1000)|multiply(n0,const_60)|add(n4,#1)|add(n2,#1)|subtract(#2,#3)|multiply(#0,#4)|divide(#5,#2) | distance travelled = 3000 m time taken by a = 3 m 18 s time taken by b = 3 m 40 sec = 220 sec speed of b = 3000 m / 220 s = 150 / 11 m / s difference between time of a and b = 22 sec when time will be 3 m 18 s a will have travelled 3000 m but b need 22 sec more to finish . distance travelled by b in 22 sec = ( 150 / 11 ) * 22 = 300 m hence , a beat b by 300 m answer : a | physics |
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