id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__j9DJ19RIvj8NVf17 | 22 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be : Choose the correct choice from the following answers.
A) 84 m B) 28 m C) 120 m D) 137 m E) none | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * pi</gadget>
<output>pi/4 = around 0.785398</output>
<gadget id="calculator">22 / (pi/4)</gadget>
<output>88/pi = around 28.01127</output>
<result>B</result> | B | 28 | 22 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be : | {
"A": "84 m",
"B": "28 m",
"C": "120 m",
"D": "137 m",
"E": "none"
} | divide(22, multiply(power(divide(1, const_2), const_2), const_pi)) | divide(n1,const_2)|power(#0,const_2)|multiply(#1,const_pi)|divide(n0,#2)| | "sol . let the length of the wire b h . radius = 1 / 2 mm = 1 / 20 cm . then , 22 / 7 * 1 / 20 * 1 / 20 * h = 22 ⇔ = [ 22 * 20 * 20 * 7 / 22 ] = 2800 cm = 28 m . answer b" | physics |
math_qa__rKboodqh1nyVaXBG | Two cyclists are moving towards each other at 10 miles/hour. They are now 50 miles apart. At this instance a fly starts from one cyclist and move towards other and moves to and fro till the two cyclist meet each other. If the fly is moving at 15 miles/hour, what is the total distance covered by the fly? Select.
A) 37.5 miles
B) 38.5 miles
C) 39.5 miles
D) 36.5 miles
E) 35.5 miles | <gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">25 / 10</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 15</gadget>
<output>75/2 = around 37.5</output>
<result>A</result> | A | 37.5 | Two cyclists are moving towards each other at 10 miles/hour. They are now 50 miles apart. At this instance a fly starts from one cyclist and move towards other and moves to and fro till the two cyclist meet each other. If the fly is moving at 15 miles/hour, what is the total distance covered by the fly? | {
"A": "37.5 miles",
"B": "38.5 miles",
"C": "39.5 miles",
"D": "36.5 miles",
"E": "35.5 miles"
} | multiply(divide(divide(50, const_2), 10), 15) | divide(n1,const_2)|divide(#0,n0)|multiply(n2,#1) | time taken by cyclists to meet = 50 / 20 2.5 hrs distance covered by fly during 2.5 hrs = 15 * 2.5 = 37.5 miles answer : a | physics |
math_qa__xB3IKESL5dcYBAg3 | Students at a school were on average 180 cm tall. The average female height was 170 cm, and the average male height was 184 cms. What was the ratio S of men to women? Pick: A) 5 : 2 B) 5 : 1 C) 4 : 3 D) 4 : 1 E) 3 : 1 | <gadget id="calculator">180 - 170</gadget>
<output>10</output>
<gadget id="calculator">184 - 180</gadget>
<output>4</output>
<gadget id="calculator">10 / 4</gadget>
<output>5/2 = around 2.5</output>
<result>A</result> | A | 2.5 | Students at a school were on average 180 cm tall. The average female height was 170 cm, and the average male height was 184 cms. What was the ratio S of men to women? | {
"A": "5 : 2",
"B": "5 : 1",
"C": "4 : 3",
"D": "4 : 1",
"E": "3 : 1"
} | divide(subtract(180, 170), subtract(184, 180)) | subtract(n0,n1)|subtract(n2,n0)|divide(#0,#1)| | ( a ) s = 184 x 5 + 170 x 2 = 1260 . a | general |
math_qa__76IErOxMWNdOJXxn | The maximum numbers of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is
Choose the correct choice from the following.
A) 91 B) 910 C) 1001 D) 1911 E) none | <gadget id="calculator">1_001 - 910</gadget>
<output>91</output>
<result>A</result> | A | 91 | The maximum numbers of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is | {
"A": "91",
"B": "910",
"C": "1001",
"D": "1911",
"E": "none"
} | subtract(1001, 910) | subtract(n0,n1)| | "olution required number of students . = h . c . f of 1001 and 910 . ‹ = › 91 . answer a" | general |
math_qa__I5ZUOaxl8ChtiH8S | When a train travels at a speed of 100kmph,it reaches the destination on time.when the same train travels at a speed of 50kmph,it reaches its destination 15min late.what is the length of journey? Choose the correct choice from the following answers: A) 15 km B) 50 km C) 60 km D) 85 km E) 95 km | <gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 50</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) / 50</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">60 * (1/4)</gadget>
<output>15</output>
<result>A</result> | A | 15 | When a train travels at a speed of 100kmph,it reaches the destination on time.when the same train travels at a speed of 50kmph,it reaches its destination 15min late.what is the length of journey? | {
"A": "15 km",
"B": "50 km",
"C": "60 km",
"D": "85 km",
"E": "95 km"
} | multiply(const_60, divide(multiply(divide(15, const_60), 50), 50)) | divide(n2,const_60)|multiply(n1,#0)|divide(#1,n1)|multiply(#2,const_60) | let x be the time reached with the speed 100 km / h 50 km / h - - - - > x + 15 distance is equal so 100 ( km / h ) × xhr = 50 ( km / h ) × ( x + 15 ) hr so 100 x = 50 x + 750 so the would be in km and x = 15 answer : a | physics |
math_qa__6tb68DpzDxVEoQFv | A circle graph shows how the MegaTech corporation allocates its Research and Development budget: 10% microphotonics; 24% home electronics; 15% food additives; 29% genetically modified microorganisms; 8% industrial lubricants; and the remainder for basic astrophysics. If the arc of each sector of the graph is proportional to the percentage of the budget it represents, how many degrees of the circle are used to represent basic astrophysics research? Choose the correct option.
A) 8 ° B) 10 ° C) 18 ° D) 36 ° E) 50 ° | <gadget id="calculator">10 + 24</gadget>
<output>34</output>
<gadget id="calculator">34 + 15</gadget>
<output>49</output>
<gadget id="calculator">49 + 29</gadget>
<output>78</output>
<gadget id="calculator">78 + 8</gadget>
<output>86</output>
<gadget id="calculator">100 - 86</gadget>
<output>14</output>
<gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">14 * 360</gadget>
<output>5_040</output>
<gadget id="calculator">5_040 / 100</gadget>
<output>252/5 = around 50.4</output>
<result>E</result> | E | 50 | A circle graph shows how the MegaTech corporation allocates its Research and Development budget: 10% microphotonics; 24% home electronics; 15% food additives; 29% genetically modified microorganisms; 8% industrial lubricants; and the remainder for basic astrophysics. If the arc of each sector of the graph is proportional to the percentage of the budget it represents, how many degrees of the circle are used to represent basic astrophysics research? | {
"A": "8 °",
"B": "10 °",
"C": "18 °",
"D": "36 °",
"E": "50 °"
} | divide(multiply(subtract(const_100, add(add(add(add(10, 24), 15), 29), 8)), divide(const_3600, const_10)), const_100) | add(n0,n1)|divide(const_3600,const_10)|add(n2,#0)|add(n3,#2)|add(n4,#3)|subtract(const_100,#4)|multiply(#1,#5)|divide(#6,const_100)| | "here all percentage when summed we need to get 100 % . as per data 10 + 24 + 15 + 29 + 8 = 86 % . so remaining 14 % is the balance for the astrophysics . since this is a circle all percentage must be equal to 360 degrees . 100 % - - - - 360 degrees then 14 % will be 50 degrees . . imo option e ." | gain |
math_qa__ntax85PWbX5d3sNt | A train running at the speed of 60 km/hr crosses a pole in 3 sec. What is the length of the train? Choose the correct choice from the following choices:
A) 50 B) 75 C) 100 D) 120 E) 25 | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 3</gadget>
<output>50</output>
<result>A</result> | A | 50 | A train running at the speed of 60 km/hr crosses a pole in 3 sec. What is the length of the train? | {
"A": "50",
"B": "75",
"C": "100",
"D": "120",
"E": "25"
} | multiply(divide(multiply(60, const_1000), const_3600), 3) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 60 * 5 / 18 = 50 / 3 m / sec length of the train = speed * time = 50 / 3 * 3 = 50 m answer : a" | physics |
math_qa__nhffIlUItEZKLMnP | If the compound interest on a certain sum of money for 3 years at 10% per annum be Rs. 993, what would be the simple interest? Pick one
A) rs . 880 B) rs . 890 C) rs . 895 D) rs . 900 E) none | <gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">300 * 10</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 * 10</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 * 3</gadget>
<output>90_000</output>
<gadget id="calculator">90_000 / 100</gadget>
<output>900</output>
<result>D</result> | D | 900 | If the compound interest on a certain sum of money for 3 years at 10% per annum be Rs. 993, what would be the simple interest? | {
"A": "rs . 880",
"B": "rs . 890",
"C": "rs . 895",
"D": "rs . 900",
"E": "none"
} | divide(multiply(multiply(multiply(multiply(3, const_100), 10), 10), 3), const_100) | multiply(n0,const_100)|multiply(n1,#0)|multiply(n1,#1)|multiply(n0,#2)|divide(#3,const_100) | let p = principal a - amount we have a = p ( 1 + r / 100 ) 3 and ci = a - p atq 993 = p ( 1 + r / 100 ) 3 - p ? p = 3000 / - now si @ 10 % on 3000 / - for 3 yrs = ( 3000 x 10 x 3 ) / 100 = 900 / - answer : d . | gain |
math_qa__S8JDAdV4QNdFjkCV | What least number must be subtracted from 427398 so that remaining no.is divisible by 13
Select the correct option.
A) 3 B) 5 C) 6 D) 7 E) 10 | <gadget id="calculator">427_398 / 13</gadget>
<output>427_398/13 = around 32_876.769231</output>
<gadget id="calculator">floor(427_398/13)</gadget>
<output>32_876</output>
<gadget id="calculator">32_876 * 13</gadget>
<output>427_388</output>
<gadget id="calculator">427_398 - 427_388</gadget>
<output>10</output>
<result>E</result> | E | 10 | What least number must be subtracted from 427398 so that remaining no.is divisible by 13 | {
"A": "3",
"B": "5",
"C": "6",
"D": "7",
"E": "10"
} | subtract(427398, multiply(floor(divide(427398, 13)), 13)) | divide(n0,n1)|floor(#0)|multiply(n1,#1)|subtract(n0,#2)| | "explanation : on dividing 427398 by 13 we get the remainder 10 , so 10 should be subtracted answer : option e" | general |
math_qa__5WFFPEjBQR2x8JZO | The present worth of a certain bill due sometime hence is Rs.800 and the true discount is Rs.36.The banker’s discount is Pick one:
A) rs . 34.38 B) rs . 38.98 C) rs . 37 D) rs . 37.62 E) none | <gadget id="calculator">36 ** 2</gadget>
<output>1_296</output>
<gadget id="calculator">1_296 / 800</gadget>
<output>81/50 = around 1.62</output>
<gadget id="calculator">36 + (81/50)</gadget>
<output>1_881/50 = around 37.62</output>
<result>D</result> | D | 37.62 | The present worth of a certain bill due sometime hence is Rs.800 and the true discount is Rs.36.The banker’s discount is | {
"A": "rs . 34.38",
"B": "rs . 38.98",
"C": "rs . 37",
"D": "rs . 37.62",
"E": "none"
} | add(36, divide(power(36, const_2), 800)) | power(n1,const_2)|divide(#0,n0)|add(n1,#1)| | "solution b . g = [ ( t . d ) ² / p . w ] = rs . ( 36 x 36 / 800 ) = rs . 1.62 b . d given , t . d = 36 = ( t . d + b . g ) = rs . ( 36 + 1.62 ) = rs . 37.62 . answer d" | gain |
math_qa__F9UYmEzDmbaEQj30 | An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 81 times the difference between the two numbers. How many coins did the old man have? Choices.
A) 24
B) 26
C) 30
D) 81
E) 40 | <gadget id="calculator">floor(81)</gadget>
<output>81</output>
<result>D</result> | D | 81 | An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 81 times the difference between the two numbers. How many coins did the old man have? | {
"A": "24",
"B": "26",
"C": "30",
"D": "81",
"E": "40"
} | floor(81) | floor(n0) | let the number of coins one son got be x and the number of coins another got be y . total = x + y . x ^ 2 - y ^ 2 = 81 ( x - y ) - - > x + y = 81 . answer : d . | general |
math_qa__AwyBZVbph9iJnBp8 | How much is it cost $0.50 each tire for 8 tires? Pick.
A) $ 3.00 B) $ 9.00 C) $ 2.00 D) $ 4.00 E) $ 7.00 | <gadget id="calculator">8 * 0.5</gadget>
<output>4</output>
<result>D</result> | D | 4 | How much is it cost $0.50 each tire for 8 tires? | {
"A": "$ 3.00",
"B": "$ 9.00",
"C": "$ 2.00",
"D": "$ 4.00",
"E": "$ 7.00"
} | multiply(8, 0.5) | multiply(n0,n1) | d . $ 4.00 | general |
math_qa__uUi97Uxg2lPmp2KY | It takes Avery 4 hours to build a brick wall while Tom can do it in 2 hours. If the two start working together and after an hour Avery leaves, how much time will it take Tom to complete the wall on his own? Choose the correct choice:
A) 20 B) 40 C) 30 D) 50 E) 60 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/4) + (1/2)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 60</gadget>
<output>30</output>
<result>C</result> | C | 30 | It takes Avery 4 hours to build a brick wall while Tom can do it in 2 hours. If the two start working together and after an hour Avery leaves, how much time will it take Tom to complete the wall on his own? | {
"A": "20",
"B": "40",
"C": "30",
"D": "50",
"E": "60"
} | multiply(divide(subtract(const_1, add(divide(const_1, 4), divide(const_1, 2))), divide(const_1, 2)), const_60) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|subtract(const_1,#2)|divide(#3,#1)|multiply(#4,const_60)| | "avery takes 4 hours tom takes 2 hours efficiency of avery is 1 / 4 units / hr efficiency of tom is 1 / 2 units / hr combined efficiency of tom and avery is 1 / 4 + 1 / 2 = 3 / 4 units / hr since they worked for 1 hour they completed 3 / 4 units of work and 1 / 4 units of work is left which is to be completed by tom ( since avery left ) so time taken by tom to complete the remaining work will be 1 / 4 / 1 / 2 hours = > 1 / 2 * 60 = 30 minutes . . . answer will be ( c )" | physics |
math_qa__Ohrrn1byk5l1KiIe | Two trains travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 4 seconds. The length of the faster train is Pick one: A) 80 m B) 100 m C) 90 m D) 180 m E) none | <gadget id="calculator">36 + 45</gadget>
<output>81</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">81 * (5/18)</gadget>
<output>45/2 = around 22.5</output>
<gadget id="calculator">(45/2) * 4</gadget>
<output>90</output>
<result>C</result> | C | 90 | Two trains travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 4 seconds. The length of the faster train is | {
"A": "80 m",
"B": "100 m",
"C": "90 m",
"D": "180 m",
"E": "none"
} | multiply(multiply(add(36, 45), const_0_2778), 4) | add(n0,n1)|multiply(#0,const_0_2778)|multiply(n2,#1) | solution relative speed = ( 36 + 45 ) km / hr = ( 81 x 5 / 18 ) m / sec = ( 45 / 2 ) m / sec length of the train = ( 45 / 2 x 4 ) m = 90 m . answer c | physics |
math_qa__VPNdyqJqbs2FKWYA | A small college reduced its faculty by approximately 23 percent to 195 professors. What was the original number of faculty members? Choose the most appropriate option: A) 253 B) 208 C) 224 D) 254 E) 302 | <gadget id="calculator">100 - 23</gadget>
<output>77</output>
<gadget id="calculator">77 / 100</gadget>
<output>77/100 = around 0.77</output>
<gadget id="calculator">195 / (77/100)</gadget>
<output>19_500/77 = around 253.246753</output>
<result>A</result> | A | 253 | A small college reduced its faculty by approximately 23 percent to 195 professors. What was the original number of faculty members? | {
"A": "253",
"B": "208",
"C": "224",
"D": "254",
"E": "302"
} | divide(195, divide(subtract(const_100, 23), const_100)) | subtract(const_100,n0)|divide(#0,const_100)|divide(n1,#1)| | "if x is the original number of faculty members , then after 23 % reduction in faculty members number is . 77 x but we are given . 77 x = 195 x = 253 so the original number of faculty members is 253 correct answer - a" | gain |
math_qa__6NkMXe2ZmkLlmErt | The current birth rate per certain number of people is 32, whereas corresponding death rate is 11 per same number of people. If the net growth rate in terms of population increase is 2.1 percent, find number of persons.(initally) Choose one:
A) 1000 B) 10000 C) 100 D) 2000 E) 20000 | <gadget id="calculator">32 - 11</gadget>
<output>21</output>
<gadget id="calculator">21 / 2.1</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<result>A</result> | A | 1,000 | The current birth rate per certain number of people is 32, whereas corresponding death rate is 11 per same number of people. If the net growth rate in terms of population increase is 2.1 percent, find number of persons.(initally) | {
"A": "1000",
"B": "10000",
"C": "100",
"D": "2000",
"E": "20000"
} | multiply(const_100, divide(subtract(32, 11), 2.1)) | subtract(n0,n1)|divide(#0,n2)|multiply(#1,const_100) | sol . net growth on x = ( 32 - 11 ) = 21 . net growth on 100 = ( 21 / x ã — 100 ) % = 2.1 % . then x = 1000 answer : a | gain |
math_qa__i4uLYAovgz4Ll08H | If A lends Rs.4000 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is? Choose one
A) 112.5 B) 122.5 C) 132.5 D) 114.5 E) 180 | <gadget id="calculator">4_000 * 11.5</gadget>
<output>46_000</output>
<gadget id="calculator">46_000 * 3</gadget>
<output>138_000</output>
<gadget id="calculator">138_000 / 100</gadget>
<output>1_380</output>
<gadget id="calculator">4_000 * 10</gadget>
<output>40_000</output>
<gadget id="calculator">40_000 * 3</gadget>
<output>120_000</output>
<gadget id="calculator">120_000 / 100</gadget>
<output>1_200</output>
<gadget id="calculator">1_380 - 1_200</gadget>
<output>180</output>
<result>E</result> | E | 180 | If A lends Rs.4000 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is? | {
"A": "112.5",
"B": "122.5",
"C": "132.5",
"D": "114.5",
"E": "180"
} | subtract(divide(multiply(multiply(4000, 11.5), 3), const_100), divide(multiply(multiply(4000, 10), 3), const_100)) | multiply(n0,n2)|multiply(n0,n1)|multiply(#0,n3)|multiply(n3,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,#5)| | "( 4000 * 1.5 * 3 ) / 100 = > 180 answer : e" | gain |
math_qa__C3LK4IGOozgipAXA | If x is less than y by 35% then y exceed x by: Pick one:
A) 33.33 % B) 25 % C) 75 % D) 53.85 % E) none of these | <gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">100 / 65</gadget>
<output>20/13 = around 1.538462</output>
<gadget id="calculator">(20/13) - 1</gadget>
<output>7/13 = around 0.538462</output>
<gadget id="calculator">(7/13) * 100</gadget>
<output>700/13 = around 53.846154</output>
<result>D</result> | D | 53.85 | If x is less than y by 35% then y exceed x by: | {
"A": "33.33 %",
"B": "25 %",
"C": "75 %",
"D": "53.85 %",
"E": "none of these"
} | multiply(subtract(divide(const_100, subtract(const_100, 35)), const_1), const_100) | subtract(const_100,n0)|divide(const_100,#0)|subtract(#1,const_1)|multiply(#2,const_100)| | "using formula ( x / ( 100 - x ) * 100 ) where x is percentage decrease ( here it is 35 % ) = > 35 / ( 100 - 35 ) * 100 = 53.85 % answer : d" | general |
math_qa__hPuDsXz0CqCodN7W | The average weight of 29 students is 28 kg. By the admission of a new student, the average weight is reduced to 27.3 kg. The weight of the new student is
Choose the correct choice:
A) 22 kg B) 21.6 kg C) 22.4 kg D) 21 kg E) 7 kg | <gadget id="calculator">29 + 1</gadget>
<output>30</output>
<gadget id="calculator">30 * 27.3</gadget>
<output>819</output>
<gadget id="calculator">29 * 28</gadget>
<output>812</output>
<gadget id="calculator">819 - 812</gadget>
<output>7</output>
<result>E</result> | E | 7 | The average weight of 29 students is 28 kg. By the admission of a new student, the average weight is reduced to 27.3 kg. The weight of the new student is | {
"A": "22 kg",
"B": "21.6 kg",
"C": "22.4 kg",
"D": "21 kg",
"E": "7 kg"
} | subtract(multiply(add(29, const_1), 27.3), multiply(29, 28)) | add(n0,const_1)|multiply(n0,n1)|multiply(n2,#0)|subtract(#2,#1)| | "exp . the total weight of 29 students = 29 * 28 the total weight of 30 students = 30 * 27.3 weight of the new student = ( 30 * 27.3 – 29 * 28 ) = 819 - 812 = 7 answer : e" | general |
math_qa__YKY0Y4svGqey7DZC | A train is 360 meter long is running at a speed of 60 km/hour. In what time will it pass a bridge of 140 meter length? Choose the correct choice from the following answers:
A) 27 seconds
B) 29 seconds
C) 40 seconds
D) 30 seconds
E) 12 seconds | <gadget id="calculator">360 + 140</gadget>
<output>500</output>
<gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">500 / (50/3)</gadget>
<output>30</output>
<result>D</result> | D | 30 | A train is 360 meter long is running at a speed of 60 km/hour. In what time will it pass a bridge of 140 meter length? | {
"A": "27 seconds",
"B": "29 seconds",
"C": "40 seconds",
"D": "30 seconds",
"E": "12 seconds"
} | divide(add(360, 140), divide(multiply(60, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "speed = 60 km / hr = 60 * ( 5 / 18 ) m / sec = 50 / 3 m / sec total distance = 360 + 140 = 500 meter time = distance / speed = 500 * ( 3 / 50 ) = 30 seconds answer : d" | physics |
math_qa__AsV6rLuHFllXm54D | A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40. What is the reduced price/dozen? Choose the correct choice from the following answers:
A) 3
B) 4
C) 5
D) 6
E) 9 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">40 * (2/5)</gadget>
<output>16</output>
<gadget id="calculator">16 / 64</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">12 * (1/4)</gadget>
<output>3</output>
<result>A</result> | A | 3 | A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40. What is the reduced price/dozen? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "9"
} | multiply(const_12, divide(multiply(40, divide(40, const_100)), 64)) | divide(n0,const_100)|multiply(n0,#0)|divide(#1,n1)|multiply(#2,const_12)| | "sol . lie purchases 6 a bananas mere for 4096 of rs 40 or , rs 16 . reduced price per do 3 a" | general |
math_qa__62JHLLzEctMOLSRk | A certain company has records stored with a record storage firm in 15-inch by 12-inch by 10-inch boxes. The boxes occupy 1.08 million cubic inches of space. If the company pays $0.4 per box per month for the record storage, what is the total amount that the company pays each month for record storage? Pick one:
A) a . 150
B) b . 300
C) c . 600
D) d . 240
E) e . 200 | <gadget id="calculator">15 * 12</gadget>
<output>180</output>
<gadget id="calculator">180 * 10</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 100</gadget>
<output>18</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) / 100</gadget>
<output>9/5_000 = around 0.0018</output>
<gadget id="calculator">1.08 / (9/5_000)</gadget>
<output>600</output>
<gadget id="calculator">0.4 * 600</gadget>
<output>240</output>
<result>D</result> | D | 240 | A certain company has records stored with a record storage firm in 15-inch by 12-inch by 10-inch boxes. The boxes occupy 1.08 million cubic inches of space. If the company pays $0.4 per box per month for the record storage, what is the total amount that the company pays each month for record storage? | {
"A": "a . 150",
"B": "b . 300",
"C": "c . 600",
"D": "d . 240",
"E": "e . 200"
} | multiply(0.4, divide(1.08, divide(divide(divide(multiply(multiply(15, 12), 10), const_100), const_100), const_100))) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,const_100)|divide(#2,const_100)|divide(#3,const_100)|divide(n3,#4)|multiply(n4,#5)| | "volume per box : 15 x 12 x 10 = 1,800 total volume : 1 , 080,000 number of boxes : total volume / volume per box = 1 , 080,000 / 1,800 = 600 price per month : number of boxes * price per box = 600 * 0.4 = 240 answer : d" | general |
math_qa__DIZBKFJzykDUnycV | In a group of people, if 30 people were made to stand in each column, 16 columns could be formed. If 60 people were made to stand in a column, how many columns could be formed? Answers
A) 6
B) 8
C) 10
D) 12
E) 14 | <gadget id="calculator">60 / 16</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">30 / (15/4)</gadget>
<output>8</output>
<result>B</result> | B | 8 | In a group of people, if 30 people were made to stand in each column, 16 columns could be formed. If 60 people were made to stand in a column, how many columns could be formed? | {
"A": "6",
"B": "8",
"C": "10",
"D": "12",
"E": "14"
} | divide(30, divide(60, 16)) | divide(n2,n1)|divide(n0,#0)| | "16 * 30 = 60 * n n = 8 the answer is b ." | other |
math_qa__cuijhUsnii7BCOD1 | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 5 inches by 24 inches and Jordan's rectangle is 2 inches long, how wide is Jordan's rectangle, in inches? Options: A) 65 B) 63 C) 52 D) 60 E) 68 | <gadget id="calculator">5 * 24</gadget>
<output>120</output>
<gadget id="calculator">120 / 2</gadget>
<output>60</output>
<result>D</result> | D | 60 | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 5 inches by 24 inches and Jordan's rectangle is 2 inches long, how wide is Jordan's rectangle, in inches? | {
"A": "65",
"B": "63",
"C": "52",
"D": "60",
"E": "68"
} | divide(rectangle_area(5, 24), 2) | rectangle_area(n0,n1)|divide(#0,n2)| | "area of carol ' s rectangle = 24 * 5 = 120 let width of jordan ' s rectangle = w since , the areas are equal 2 w = 120 = > w = 60 answer d" | geometry |
math_qa__keycLTPQ1u1fr8s1 | A man took loan from a bank at the rate of 12% p.a. S.I. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was? Answers.
A) 15002
B) 15001
C) 15000
D) 15007
E) 15009 | <gadget id="calculator">5_400 * 100</gadget>
<output>540_000</output>
<gadget id="calculator">540_000 / 3</gadget>
<output>180_000</output>
<gadget id="calculator">180_000 / 12</gadget>
<output>15_000</output>
<result>C</result> | C | 15,000 | A man took loan from a bank at the rate of 12% p.a. S.I. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was? | {
"A": "15002",
"B": "15001",
"C": "15000",
"D": "15007",
"E": "15009"
} | divide(divide(multiply(5400, const_100), 3), 12) | multiply(n2,const_100)|divide(#0,n1)|divide(#1,n0)| | principal = ( 100 * 5400 ) / ( 12 * 3 ) = rs . 15000 . answer : c | gain |
math_qa__OLXktDkjFQaLwcOS | How many numbers between 100 and 714 are divisible by 2, 3, and 7 together? Choose the correct choice:
A) 112 B) 77 C) 267 D) 15 E) 99 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 7</gadget>
<output>42</output>
<gadget id="calculator">714 / 42</gadget>
<output>17</output>
<gadget id="calculator">100 / 42</gadget>
<output>50/21 = around 2.380952</output>
<gadget id="calculator">17 - (50/21)</gadget>
<output>307/21 = around 14.619048</output>
<result>D</result> | D | 15 | How many numbers between 100 and 714 are divisible by 2, 3, and 7 together? | {
"A": "112",
"B": "77",
"C": "267",
"D": "15",
"E": "99"
} | subtract(divide(714, multiply(multiply(2, 3), 7)), divide(100, multiply(multiply(2, 3), 7))) | multiply(n2,n3)|multiply(n4,#0)|divide(n1,#1)|divide(n0,#1)|subtract(#2,#3)| | "explanation : as the division is by 2 , 3 , 7 together , the numbers are to be divisible by : 2 * 3 * 7 = 42 the limits are 100 and 714 the first number divisible is 42 * 3 = 126 to find out the last number divisible by 42 within 714 : 714 / 42 = 17 hence , 42 * 14 = 714 is the last number divisible by 42 within 714 hence , total numbers divisible by 2 , 3 , 7 together are ( 17 â € “ 2 ) = 15 answer : d" | general |
math_qa__yWgzb6lCufXusUcI | How many paying stones, each measuring 3 m * 2 m are required to pave a rectangular court yard 60 m long and 14m board? Select the correct option.
A) 99 B) 140 C) 26 D) 17 E) 12 | <gadget id="calculator">60 * 14</gadget>
<output>840</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">840 / 6</gadget>
<output>140</output>
<result>B</result> | B | 140 | How many paying stones, each measuring 3 m * 2 m are required to pave a rectangular court yard 60 m long and 14m board? | {
"A": "99",
"B": "140",
"C": "26",
"D": "17",
"E": "12"
} | divide(rectangle_area(60, 14), rectangle_area(3, 2)) | rectangle_area(n2,n3)|rectangle_area(n0,n1)|divide(#0,#1)| | "60 * 14 = 3 * 2 * x = > x = 140 answer : b" | physics |
math_qa__WDVmGkSufT7Ed7nN | A retailer bought a shirt at wholesale and marked it up 80% to its initial price of $36. By how many more dollars does he need to increase the price to achieve a 100% markup? Choose the correct choice from the following answers.
A) 2
B) 4
C) 6
D) 8
E) 10 | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 + (4/5)</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">36 / (9/5)</gadget>
<output>20</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">40 - 36</gadget>
<output>4</output>
<result>B</result> | B | 4 | A retailer bought a shirt at wholesale and marked it up 80% to its initial price of $36. By how many more dollars does he need to increase the price to achieve a 100% markup? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | subtract(multiply(divide(36, add(const_1, divide(80, const_100))), const_2), 36) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)|multiply(#2,const_2)|subtract(#3,n1) | let x be the wholesale price . then 1.8 x = 36 and x = 36 / 1.8 = 20 . to achieve a 100 % markup , the price needs to be $ 40 . the retailer needs to increase the price by $ 4 more . the answer is b . | general |
math_qa__2nYDaHpvHJ5kGQxh | in the city of san durango , 60 people own cats , dogs , or rabbits . if 30 people owned cats , 40 owned dogs , 16 owned rabbits , and 12 owned exactly two of the 3 types of pet , how many people owned all 3 ? Choose the most appropriate option:
A) 2 B) 4 C) 8 D) 7 E) 32 | <gadget id="calculator">30 + 40</gadget>
<output>70</output>
<gadget id="calculator">70 + 16</gadget>
<output>86</output>
<gadget id="calculator">86 - 12</gadget>
<output>74</output>
<gadget id="calculator">74 - 60</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<result>D</result> | D | 7 | in the city of san durango , 60 people own cats , dogs , or rabbits . if 30 people owned cats , 40 owned dogs , 16 owned rabbits , and 12 owned exactly two of the 3 types of pet , how many people owned all 3 ? | {
"A": "2",
"B": "4",
"C": "8",
"D": "7",
"E": "32"
} | divide(subtract(subtract(add(add(30, 40), 16), 12), 60), const_2) | add(n1,n2)|add(n3,#0)|subtract(#1,n4)|subtract(#2,n0)|divide(#3,const_2) | you are considering a case when cat dogs and rabbit are not exactly equal to 12 . the solution shall be 60 = 30 + 40 + 16 - 12 - 2 x and hence x shall be 7 . answer d | general |
math_qa__OGRgzrIg81u3pUnO | A certain company’s profit in 1996 was 17 percent greater than its profit in 1995, and its profit in 1997 was 25 percent greater than its profit in 1996. The company’s profit in 1997 was what percent greater than its profit in 1995? Choose one.
A) 5 % B) 18 % C) 33 % D) 35 % E) 46.25 % | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">17 / 100</gadget>
<output>17/100 = around 0.17</output>
<gadget id="calculator">1 + (17/100)</gadget>
<output>117/100 = around 1.17</output>
<gadget id="calculator">(5/4) * (117/100)</gadget>
<output>117/80 = around 1.4625</output>
<gadget id="calculator">(117/80) - 1</gadget>
<output>37/80 = around 0.4625</output>
<gadget id="calculator">(37/80) * 100</gadget>
<output>185/4 = around 46.25</output>
<result>E</result> | E | 46.25 | A certain company’s profit in 1996 was 17 percent greater than its profit in 1995, and its profit in 1997 was 25 percent greater than its profit in 1996. The company’s profit in 1997 was what percent greater than its profit in 1995? | {
"A": "5 %",
"B": "18 %",
"C": "33 %",
"D": "35 %",
"E": "46.25 %"
} | multiply(subtract(multiply(add(divide(25, const_100), const_1), add(const_1, divide(17, const_100))), const_1), const_100) | divide(n4,const_100)|divide(n1,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "profit in 1995 - 100 profit in 1996 - 117 % increae profit in 1997 in comparison to 1995 = 17 + 117 * 25 % = 46.25 correct option : e" | gain |
math_qa__QmRonN57fidxbYTF | A can give B 80 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race? Choose the correct choice from the following answers
A) 130.12 B) 130.43 C) 130.22 D) 111.0 E) 111.12 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 - 200</gadget>
<output>800</output>
<gadget id="calculator">1_000 * 800</gadget>
<output>800_000</output>
<gadget id="calculator">1_000 - 80</gadget>
<output>920</output>
<gadget id="calculator">800_000 / 920</gadget>
<output>20_000/23 = around 869.565217</output>
<gadget id="calculator">1_000 - (20_000/23)</gadget>
<output>3_000/23 = around 130.434783</output>
<result>B</result> | B | 130.43 | A can give B 80 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race? | {
"A": "130.12",
"B": "130.43",
"C": "130.22",
"D": "111.0",
"E": "111.12"
} | subtract(multiply(const_100, const_10), divide(multiply(multiply(const_100, const_10), subtract(multiply(const_100, const_10), 200)), subtract(multiply(const_100, const_10), 80))) | multiply(const_10,const_100)|subtract(#0,n1)|subtract(#0,n0)|multiply(#0,#1)|divide(#3,#2)|subtract(#0,#4) | a runs 1000 m while b runs 920 m and c runs 800 m . the number of meters that c runs when b runs 1000 m , = ( 1000 * 800 ) / 920 = 869.56 m b can give c = 1000 - 869.56 = 130.43 m . answer : b | physics |
math_qa__6LmbbDds8AhRfTvU | 30 square stone slabs of equal size were needed to cover a floor area of 58.8 sq.m. Find the length of each stone slab? Pick one
A) 140 cm B) 767 cm C) 88 cm D) 666 cm E) 776 cm | <gadget id="calculator">58.8 / 30</gadget>
<output>1.96</output>
<gadget id="calculator">1.96 ** (1/2)</gadget>
<output>1.4</output>
<gadget id="calculator">1.4 * 100</gadget>
<output>140</output>
<result>A</result> | A | 140 | 30 square stone slabs of equal size were needed to cover a floor area of 58.8 sq.m. Find the length of each stone slab? | {
"A": "140 cm",
"B": "767 cm",
"C": "88 cm",
"D": "666 cm",
"E": "776 cm"
} | multiply(sqrt(divide(58.8, 30)), const_100) | divide(n1,n0)|sqrt(#0)|multiply(#1,const_100)| | "area of each slab = 58.8 / 30 m 2 = 1.96 m 2 length of each slab √ 1.96 = 1.4 m = 140 cm" | geometry |
math_qa__1MGKHEH0jTUXTiGl | NHAI employs 100 men to build a highway of 2km in 50 days working 8 hours a day.if in 25 days they completed 1/3 part of work .than how many more emploies should NHAI hire to finish it in time working 10 hours a day Choose the correct choice from the following answers
A) 60
B) 70
C) 80
D) 50
E) 40 | <gadget id="calculator">100 * 25</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 * 8</gadget>
<output>20_000</output>
<gadget id="calculator">2 * 20_000</gadget>
<output>40_000</output>
<gadget id="calculator">25 * 10</gadget>
<output>250</output>
<gadget id="calculator">40_000 / 250</gadget>
<output>160</output>
<gadget id="calculator">160 - 100</gadget>
<output>60</output>
<result>A</result> | A | 60 | NHAI employs 100 men to build a highway of 2km in 50 days working 8 hours a day.if in 25 days they completed 1/3 part of work .than how many more emploies should NHAI hire to finish it in time working 10 hours a day | {
"A": "60",
"B": "70",
"C": "80",
"D": "50",
"E": "40"
} | subtract(divide(multiply(2, multiply(multiply(100, 25), 8)), multiply(25, 10)), 100) | multiply(n0,n4)|multiply(n4,n7)|multiply(n3,#0)|multiply(n1,#2)|divide(#3,#1)|subtract(#4,n0)| | "( m 1 * d 1 * h 1 ) / w 1 = ( m 2 * d 2 * h 2 ) / w 2 ( 100 * 25 * 8 ) / ( 1 / 3 ) = ( ( 100 + a ) * 25 * 10 ) ) / ( 2 / 3 ) 160 = 100 + a a = 60 answer : a" | physics |
math_qa__QzYb1sZBMHtxJOhP | The speed of a car increases by 2 kms after every one hour. If the distance travelling in the first one hour was 40 kms. what was the total distance traveled in 12 hours? Options: A) 252 kms B) 152 kms C) 612 kms D) 752 kms E) 152 kms | <gadget id="calculator">2 * 40</gadget>
<output>80</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">80 + 22</gadget>
<output>102</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">102 * 6</gadget>
<output>612</output>
<result>C</result> | C | 612 | The speed of a car increases by 2 kms after every one hour. If the distance travelling in the first one hour was 40 kms. what was the total distance traveled in 12 hours? | {
"A": "252 kms",
"B": "152 kms",
"C": "612 kms",
"D": "752 kms",
"E": "152 kms"
} | multiply(add(multiply(2, 40), multiply(subtract(12, const_1), 2)), divide(12, 2)) | divide(n2,n0)|multiply(n0,n1)|subtract(n2,const_1)|multiply(n0,#2)|add(#1,#3)|multiply(#4,#0)| | "explanation : total distance travelled in 12 hours = ( 40 + 42 + 44 + . . . . . upto 12 terms ) this is an a . p with first term , a = 40 , number of terms , n = 12 , d = 2 . required distance = 12 / 2 [ 2 x 40 + { 12 - 1 ) x 2 ] = 6 ( 102 ) = 612 kms . answer : c" | physics |
math_qa__vf5GF47vdeHZUwBO | In a house a hall is 20 m long, 15m wide and 5m high. Its interior has to be covered with mat. What will be the total expenditure if it costs Rs. 60 per square m? Select:
A) rs . 50000
B) rs . 52000
C) rs . 57000
D) rs . 60000
E) rs . 67000 | <gadget id="calculator">20 * 15</gadget>
<output>300</output>
<gadget id="calculator">300 * 2</gadget>
<output>600</output>
<gadget id="calculator">600 * 60</gadget>
<output>36_000</output>
<gadget id="calculator">20 * 5</gadget>
<output>100</output>
<gadget id="calculator">100 * 2</gadget>
<output>200</output>
<gadget id="calculator">200 * 60</gadget>
<output>12_000</output>
<gadget id="calculator">36_000 + 12_000</gadget>
<output>48_000</output>
<gadget id="calculator">15 * 5</gadget>
<output>75</output>
<gadget id="calculator">75 * 2</gadget>
<output>150</output>
<gadget id="calculator">150 * 60</gadget>
<output>9_000</output>
<gadget id="calculator">48_000 + 9_000</gadget>
<output>57_000</output>
<result>C</result> | C | 57,000 | In a house a hall is 20 m long, 15m wide and 5m high. Its interior has to be covered with mat. What will be the total expenditure if it costs Rs. 60 per square m? | {
"A": "rs . 50000",
"B": "rs . 52000",
"C": "rs . 57000",
"D": "rs . 60000",
"E": "rs . 67000"
} | add(add(multiply(multiply(multiply(20, 15), const_2), 60), multiply(multiply(multiply(20, 5), const_2), 60)), multiply(multiply(multiply(15, 5), const_2), 60)) | multiply(n0,n1)|multiply(n0,n2)|multiply(n1,n2)|multiply(#0,const_2)|multiply(#1,const_2)|multiply(#2,const_2)|multiply(n3,#3)|multiply(n3,#4)|multiply(n3,#5)|add(#6,#7)|add(#9,#8)| | "length ( l ) = 20 m , breadth ( b ) = 15 m and height ( h ) = 5 m total area of the hall to be covered with mat = 2 ( lb + bh + hl ) = 2 ( 20 * 15 + 15 * 5 + 5 * 20 ) = 2 ( 300 + 75 + 100 ) = 2 * 475 = 950 sq . m total expenditure = 60 * 950 = rs . 57000 c" | general |
math_qa__Dx0TZ0XlVSkbkOpV | A small island country of 5000 people has an emigration and immigration statistic per 500 persons of 50.4 and 15.4 respectively. How long will it take for the population to be half of its current number. Choose the correct choice from the following choices
A) 6.8 B) 8.5 C) 6.1 D) 9.1 E) 7.14 | <gadget id="calculator">5_000 / 2</gadget>
<output>2_500</output>
<gadget id="calculator">50.4 - 15.4</gadget>
<output>35</output>
<gadget id="calculator">5_000 / 500</gadget>
<output>10</output>
<gadget id="calculator">35 * 10</gadget>
<output>350</output>
<gadget id="calculator">2_500 / 350</gadget>
<output>50/7 = around 7.142857</output>
<result>E</result> | E | 7.14 | A small island country of 5000 people has an emigration and immigration statistic per 500 persons of 50.4 and 15.4 respectively. How long will it take for the population to be half of its current number. | {
"A": "6.8",
"B": "8.5",
"C": "6.1",
"D": "9.1",
"E": "7.14"
} | divide(divide(5000, const_2), multiply(subtract(50.4, 15.4), divide(5000, 500))) | divide(n0,const_2)|divide(n0,n1)|subtract(n2,n3)|multiply(#1,#2)|divide(#0,#3) | annual decrease is ( 500 + 15.4 - 50.4 ) * 10 = 4650 hence every year there is a decrease of 350 for the population to become half 2500 must emigrate therefore 2500 / 350 = 133.3 correct option is e ) 7.14 | other |
math_qa__waPWHKC2O4PspAf5 | The average weight of a class of 20 boys was calculated to be 58.4 kgs and it was later found that one weight was misread as 56 kg instead of 66 kg. What is the correct weight?
Select: A) 58 kgs B) 58.85 kgs C) 58.9 kgs D) 59 kgs E) 59.85 kgs | <gadget id="calculator">58.4 * 20</gadget>
<output>1_168</output>
<gadget id="calculator">66 - 56</gadget>
<output>10</output>
<gadget id="calculator">1_168 + 10</gadget>
<output>1_178</output>
<gadget id="calculator">1_178 / 20</gadget>
<output>589/10 = around 58.9</output>
<result>C</result> | C | 58.9 | The average weight of a class of 20 boys was calculated to be 58.4 kgs and it was later found that one weight was misread as 56 kg instead of 66 kg. What is the correct weight? | {
"A": "58 kgs",
"B": "58.85 kgs",
"C": "58.9 kgs",
"D": "59 kgs",
"E": "59.85 kgs"
} | divide(add(multiply(58.4, 20), subtract(66, 56)), 20) | multiply(n0,n1)|subtract(n3,n2)|add(#0,#1)|divide(#2,n0)| | "actual total weight is ( 20 x 58.4 - 56 + 66 ) = 1178 kgs actual average weight is 1178 / 20 = 58.9 kgs c" | general |
math_qa__Fgvqepy065Ge7wdK | In a certain store, the profit is 320% of the cost. If the cost increases by 40% but the selling price
remains constant, approximately what percentage of the selling price is the profit Choose the correct choice from the following answers: A) 67 % B) 80 % C) 90 % D) 100 % E) none of above | <gadget id="calculator">100 + 320</gadget>
<output>420</output>
<gadget id="calculator">100 + 40</gadget>
<output>140</output>
<gadget id="calculator">420 - 140</gadget>
<output>280</output>
<gadget id="calculator">280 / 420</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 100</gadget>
<output>200/3 = around 66.666667</output>
<result>A</result> | A | 67 | In a certain store, the profit is 320% of the cost. If the cost increases by 40% but the selling price
remains constant, approximately what percentage of the selling price is the profit | {
"A": "67 %",
"B": "80 %",
"C": "90 %",
"D": "100 %",
"E": "none of above"
} | multiply(divide(subtract(add(const_100, 320), add(const_100, 40)), add(const_100, 320)), const_100) | add(n0,const_100)|add(n1,const_100)|subtract(#0,#1)|divide(#2,#0)|multiply(#3,const_100) | explanation : let c . p . = rs . 100 . then , profit = rs . 320 , s . p . = rs . 420 . new c . p . = 140 % of rs . 100 = rs . 140 new s . p . = rs . 420 . profit = rs . ( 420 - 140 ) = rs . 280 required percentage = ( 280 / 420 ) * 100 = 66.67 % ( approx ) = 67 % answer : a | gain |
math_qa__y3qDQijIGzZawkTX | If the perimeter of a rectangular garden is 480 m, its length when its breadth is 100 m is?
Pick: A) 299 m B) 140 m C) 200 m D) 167 m E) 128 m | <gadget id="calculator">480 / 2</gadget>
<output>240</output>
<gadget id="calculator">240 - 100</gadget>
<output>140</output>
<result>B</result> | B | 140 | If the perimeter of a rectangular garden is 480 m, its length when its breadth is 100 m is? | {
"A": "299 m",
"B": "140 m",
"C": "200 m",
"D": "167 m",
"E": "128 m"
} | subtract(divide(480, const_2), 100) | divide(n0,const_2)|subtract(#0,n1)| | "2 ( l + 100 ) = 480 = > l = 140 m answer : b" | physics |
math_qa__HNvvAn240yOfuRBo | The H.C.F. of two numbers is 30 and the other two factors of their L.C.M. are 10 and 15. The larger of the two numbers is: Select the correct option:
A) 350
B) 250
C) 450
D) 500
E) 620 | <gadget id="calculator">30 * 15</gadget>
<output>450</output>
<result>C</result> | C | 450 | The H.C.F. of two numbers is 30 and the other two factors of their L.C.M. are 10 and 15. The larger of the two numbers is: | {
"A": "350",
"B": "250",
"C": "450",
"D": "500",
"E": "620"
} | multiply(30, 15) | multiply(n0,n2)| | "explanation : clearly , the numbers are ( 30 x 10 ) and ( 30 x 15 ) . { \ color { blue } \ therefore } larger number = ( 30 x 15 ) = 450 . answer : c ) 450" | other |
math_qa__rwM4hUAGD7chGpxj | In a particular state, 70% of the counties received some rain on Monday, and 50% of the counties received some rain on Tuesday. No rain fell either day in 20% of the counties in the state. What percent of the counties received some rain on Monday and Tuesday? Choose the correct choice: A) 20 % B) 40 % C) 50 % D) 60 % E) 70 % | <gadget id="calculator">70 + 50</gadget>
<output>120</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">120 - 80</gadget>
<output>40</output>
<result>B</result> | B | 40 | In a particular state, 70% of the counties received some rain on Monday, and 50% of the counties received some rain on Tuesday. No rain fell either day in 20% of the counties in the state. What percent of the counties received some rain on Monday and Tuesday? | {
"A": "20 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "70 %"
} | subtract(add(70, 50), subtract(const_100, 20)) | add(n0,n1)|subtract(const_100,n2)|subtract(#0,#1)| | "70 + 50 + 20 = 140 % the number is 40 % above 100 % because 40 % of the counties were counted twice . the answer is b ." | gain |
math_qa__U6l9yGLZDuA4XhcU | A train passes a platform in 16 seconds. The same train passes a man standing on the platform in 10 seconds. If the speed of the train is 54 km/hr, The length of the platform is Answers:
A) 40 B) 50 C) 90 D) 30 E) 20 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 54</gadget>
<output>15</output>
<gadget id="calculator">16 - 10</gadget>
<output>6</output>
<gadget id="calculator">15 * 6</gadget>
<output>90</output>
<result>C</result> | C | 90 | A train passes a platform in 16 seconds. The same train passes a man standing on the platform in 10 seconds. If the speed of the train is 54 km/hr, The length of the platform is | {
"A": "40",
"B": "50",
"C": "90",
"D": "30",
"E": "20"
} | multiply(multiply(const_0_2778, 54), subtract(16, 10)) | multiply(n2,const_0_2778)|subtract(n0,n1)|multiply(#0,#1)| | "speed of the train = 54 km / hr = ( 54 × 10 ) / 36 m / s = 15 m / s length of the train = speed × time taken to cross the man = 15 × 10 = 150 m let the length of the platform = l time taken to cross the platform = ( 150 + l ) / 15 = > ( 150 + l ) / 15 = 16 = > 150 + l = 15 × 16 = 240 = > l = 240 - 150 = 90 meter answer is c" | physics |
math_qa__o54JCCEvrK8N1vlj | If 35% of the 840 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class?
Choices.
A) 546
B) 550
C) 555
D) 532
E) 515 | <gadget id="calculator">840 / 100</gadget>
<output>42/5 = around 8.4</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">(42/5) * 65</gadget>
<output>546</output>
<result>A</result> | A | 546 | If 35% of the 840 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class? | {
"A": "546",
"B": "550",
"C": "555",
"D": "532",
"E": "515"
} | multiply(divide(840, const_100), subtract(const_100, 35)) | divide(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)| | "we know 35 % people study biology , therefore the no of people not studying = 100 - 35 = 65 % > therefore the people not studying biology out of a total 840 people are = 65 % of 840 > ( 65 / 100 ) * 840 = 546 people a" | other |
math_qa__q9Jmenaoj9lS4lBI | A train is 410 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length? Choices
A) 76 seconds B) 18 seconds C) 40 seconds D) 19 seconds E) 44 seconds | <gadget id="calculator">410 + 140</gadget>
<output>550</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">550 / (25/2)</gadget>
<output>44</output>
<result>E</result> | E | 44 | A train is 410 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length? | {
"A": "76 seconds",
"B": "18 seconds",
"C": "40 seconds",
"D": "19 seconds",
"E": "44 seconds"
} | divide(add(410, 140), divide(multiply(45, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "speed = 45 km / hr = 45 * ( 5 / 18 ) m / sec = 25 / 2 m / sec total distance = 410 + 140 = 550 meter time = distance / speed = 550 * ( 2 / 25 ) = 44 seconds answer : e" | physics |
math_qa__40uvEKdKYI72zvP9 | If A is thrice as fast as B and together can do a work in 30 days. In how many days A alone can do the work? Select.
A) 36 B) 42 C) 28 D) 54 E) 40 | <gadget id="calculator">30 * 4</gadget>
<output>120</output>
<gadget id="calculator">3 / 120</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">1 / (1/40)</gadget>
<output>40</output>
<result>E</result> | E | 40 | If A is thrice as fast as B and together can do a work in 30 days. In how many days A alone can do the work? | {
"A": "36",
"B": "42",
"C": "28",
"D": "54",
"E": "40"
} | inverse(divide(const_3, multiply(30, const_4))) | multiply(n0,const_4)|divide(const_3,#0)|inverse(#1) | a ’ s one day ’ s work = 1 / x b ’ s one day ’ s work = 1 / 3 x a + b ’ s one day ’ s work = 1 / x + 1 / 3 x = 1 / 30 = 3 + 1 / 3 x = 4 / 3 x = 1 / 30 x = 30 * 4 / 3 = 40 answer : e | physics |
math_qa__Vhvz8rHup1jc2NN9 | Angelina walked 200 meters from her home to the grocery at a constant speed. She then walked 300 meters to the gym at double the speed. She spent 50 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym? Choose the correct choice from the following choices.
A) 2
B) 3
C) 4
D) 6
E) 12 | <gadget id="calculator">300 / 2</gadget>
<output>150</output>
<gadget id="calculator">200 - 150</gadget>
<output>50</output>
<gadget id="calculator">50 / 50</gadget>
<output>1</output>
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<result>A</result> | A | 2 | Angelina walked 200 meters from her home to the grocery at a constant speed. She then walked 300 meters to the gym at double the speed. She spent 50 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym? | {
"A": "2",
"B": "3",
"C": "4",
"D": "6",
"E": "12"
} | multiply(divide(subtract(200, divide(300, const_2)), 50), const_2) | divide(n1,const_2)|subtract(n0,#0)|divide(#1,n2)|multiply(#2,const_2)| | "let the speed be x . . . so time taken from home to grocery = 200 / x . . the speed to gym = 2 x . . so time taken = 300 / 2 x = 150 / x . . its given 200 / x - 150 / x = 50 . . 50 / x = 50 . . x = 1 m / secs . . so grocery to gym = 2 * 1 = 2 m / s . . . answer : a" | physics |
math_qa__aG92o1tFuz7hz3JD | 15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 2 hrs. each would it take for 21 women if 3 women do as much work as 2 men? Choices.
A) 30 B) 20 C) 40 D) 60 E) 90 | <gadget id="calculator">15 * 21</gadget>
<output>315</output>
<gadget id="calculator">315 * 8</gadget>
<output>2_520</output>
<gadget id="calculator">21 * 2</gadget>
<output>42</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">42 * (2/3)</gadget>
<output>28</output>
<gadget id="calculator">2_520 / 28</gadget>
<output>90</output>
<result>E</result> | E | 90 | 15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 2 hrs. each would it take for 21 women if 3 women do as much work as 2 men? | {
"A": "30",
"B": "20",
"C": "40",
"D": "60",
"E": "90"
} | divide(multiply(multiply(15, 21), 8), multiply(multiply(21, 2), divide(2, 3))) | divide(n6,n5)|multiply(n0,n1)|multiply(n1,n3)|multiply(n2,#1)|multiply(#0,#2)|divide(#3,#4)| | "let 1 man does 1 unit / hr of work 15 m in 21 days of 8 hrs will do ( 15 * 21 * 8 ) units 3 w = 2 m 1 w = ( 2 / 3 ) units / hr 21 w with 2 hrs a day will take ( 15 * 21 * 8 ) / ( 21 * 2 * ( 2 / 3 ) ) days = > 90 days answer : e" | physics |
math_qa__9nFxeL6QoOanY5Dm | What is the sum of the greatest common factor and the lowest common multiple of 36 and 56? Choose the correct choice from the following choices.
A) 512 B) 508 C) 451 D) 516 E) 451 | <gadget id="calculator">36 * 56</gadget>
<output>2_016</output>
<gadget id="calculator">2_016 / 4</gadget>
<output>504</output>
<result>B</result> | B | 508 | What is the sum of the greatest common factor and the lowest common multiple of 36 and 56? | {
"A": "512",
"B": "508",
"C": "451",
"D": "516",
"E": "451"
} | divide(multiply(36, 56), const_4) | multiply(n0,n1)|divide(#0,const_4)| | "prime factorization of 36 = 2 x 2 x 3 x 3 prime factorization of 56 = 2 x 2 x 2 x 7 gcf = 4 lcm = 504 sum = 508 ans : b" | general |
math_qa__gduW5GmItpFo2QK3 | Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 7225, how much amount did Raghu invest ? Select the correct option: A) 1287 B) 2887 C) 2500 D) 1129 E) 1192 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(9/10) * (11/10)</gadget>
<output>99/100 = around 0.99</output>
<gadget id="calculator">(99/100) + (9/10)</gadget>
<output>189/100 = around 1.89</output>
<gadget id="calculator">(189/100) + 1</gadget>
<output>289/100 = around 2.89</output>
<gadget id="calculator">7_225 / (289/100)</gadget>
<output>2_500</output>
<result>C</result> | C | 2,500 | Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 7225, how much amount did Raghu invest ? | {
"A": "1287",
"B": "2887",
"C": "2500",
"D": "1129",
"E": "1192"
} | divide(7225, add(add(multiply(subtract(const_1, divide(10, const_100)), add(const_1, divide(10, const_100))), subtract(const_1, divide(10, const_100))), const_1)) | divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#0)|multiply(#1,#2)|add(#3,#2)|add(#4,const_1)|divide(n2,#5)| | "let money invested by raghu = rs . x money invested by trishul = 9 / 10 x = 0.9 x money invested by vishal = 9 / 10 x * 110 / 100 = 0.99 x also , x + 0.9 x + 0.99 x = 7225 = x = 7225 / 2.89 = 2500 therefore , amount invested by raghu is rs . 2500 . answer : c" | general |
math_qa__AChVmuK5y2qvHCVc | In a box of 8 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective? Options.
A) 1 / 12 B) 5 / 14 C) 2 / 13 D) 2 / 15 E) 1 / 17 | <gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">720 / 36</gadget>
<output>20</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">120 * 6</gadget>
<output>720</output>
<gadget id="calculator">40_320 / 720</gadget>
<output>56</output>
<gadget id="calculator">20 / 56</gadget>
<output>5/14 = around 0.357143</output>
<result>B</result> | B | 0.357143 | In a box of 8 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective? | {
"A": "1 / 12",
"B": "5 / 14",
"C": "2 / 13",
"D": "2 / 15",
"E": "1 / 17"
} | divide(divide(factorial(subtract(8, 2)), multiply(factorial(subtract(subtract(8, 2), 3)), factorial(3))), divide(factorial(8), multiply(factorial(subtract(8, 3)), factorial(3)))) | factorial(n2)|factorial(n0)|subtract(n0,n1)|subtract(n0,n2)|factorial(#2)|factorial(#3)|subtract(#2,n2)|factorial(#6)|multiply(#5,#0)|divide(#1,#8)|multiply(#7,#0)|divide(#4,#10)|divide(#11,#9)| | "first , there are 6 c 3 ways you can select 3 good pencils from 4 good ones . second , there are 8 c 3 ways you select 3 pencils from 6 ones in the box . then , the probability that neither pen will be defective is : 6 c 3 / 8 c 3 = 20 / 56 = 5 / 14 answer is b" | general |
math_qa__ictwX91rVfvyctcG | What is the area of square field whose side of length 17 m? Answers:
A) 225 B) 777 C) 266 D) 289 E) 261 | <gadget id="calculator">17 ** 2</gadget>
<output>289</output>
<result>D</result> | D | 289 | What is the area of square field whose side of length 17 m? | {
"A": "225",
"B": "777",
"C": "266",
"D": "289",
"E": "261"
} | square_area(17) | square_area(n0)| | "17 * 17 = 289 sq m answer : d" | geometry |
math_qa__Y8T1ocPcVdXKcozW | A sum is divided between A and B in the ratio of 1 : 2. A purchased a car from his part, which depreciates 14 2/7% per annum and B deposited his amount in a bank, which pays him 20% interest per annum compounded annually. By what percentage will the total sum of money increase after two years due to this investment pattern (approximately). Choose one
A) 22.48 % B) 20.48 % C) 24.48 % D) 25.48 % E) 26.48 % | <gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">40 + 7</gadget>
<output>47</output>
<gadget id="calculator">47 + 1</gadget>
<output>48</output>
<gadget id="calculator">48 / 100</gadget>
<output>12/25 = around 0.48</output>
<gadget id="calculator">20 + (12/25)</gadget>
<output>512/25 = around 20.48</output>
<result>B</result> | B | 20.48 | A sum is divided between A and B in the ratio of 1 : 2. A purchased a car from his part, which depreciates 14 2/7% per annum and B deposited his amount in a bank, which pays him 20% interest per annum compounded annually. By what percentage will the total sum of money increase after two years due to this investment pattern (approximately). | {
"A": "22.48 %",
"B": "20.48 %",
"C": "24.48 %",
"D": "25.48 %",
"E": "26.48 %"
} | add(20, divide(add(add(add(20, 20), 7), 1), const_100)) | add(n5,n5)|add(n4,#0)|add(n0,#1)|divide(#2,const_100)|add(n5,#3) | let the total money = 300 a ' s part = 100 b ' s part = 200 after 2 years a ' s part = 73.46 ( as it depreciates by 14.29 % per annum ) after 2 years b ' s part = 288 ( using the compound interest formula , a = p ( 1 + r / n ) ^ nt ) , where p = 200 , r = 0.2 , n = 1 , t = 2 ) so , after 2 years total amount = 361.46 therefore % increase in money = ( 361.46 - 300 ) * 100 / 300 = 20.48 % answer : b | general |
math_qa__3yBTwstIcyyiU2OV | How many seconds will a train 100 meters long take to cross a bridge 250 meters long if the speed of the train is 36 kmph? Choose the correct choice from the following answers.
A) 54 sec B) 35 sec C) 25 sec D) 45 sec E) 24 sec | <gadget id="calculator">250 + 100</gadget>
<output>350</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">350 / 10</gadget>
<output>35</output>
<result>B</result> | B | 35 | How many seconds will a train 100 meters long take to cross a bridge 250 meters long if the speed of the train is 36 kmph? | {
"A": "54 sec",
"B": "35 sec",
"C": "25 sec",
"D": "45 sec",
"E": "24 sec"
} | divide(add(250, 100), multiply(36, const_0_2778)) | add(n0,n1)|multiply(n2,const_0_2778)|divide(#0,#1)| | "d = 100 + 250 = 350 s = 36 * 5 / 18 = 10 mps t = 350 / 10 = 35 sec answer : b" | physics |
math_qa__YDXDO1PAphD8ceaO | Two trains of length 100 m and 160 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?
Answers:
A) 18 sec B) 70 sec C) 13 sec D) 20 sec E) 19 sec | <gadget id="calculator">100 + 160</gadget>
<output>260</output>
<gadget id="calculator">42 + 30</gadget>
<output>72</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">260 / 20</gadget>
<output>13</output>
<result>C</result> | C | 13 | Two trains of length 100 m and 160 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? | {
"A": "18 sec",
"B": "70 sec",
"C": "13 sec",
"D": "20 sec",
"E": "19 sec"
} | divide(add(100, 160), multiply(add(42, 30), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = ( 42 + 30 ) * 5 / 18 = 4 * 5 = 20 mps . distance covered in passing each other = 100 + 160 = 260 m . the time required = d / s = 260 / 20 = 13 sec . answer : c" | physics |
math_qa__INW09dH8XcrNDgdM | Pipe A fills a tank in 30 minutes. Pipe B can fill the same tank 5 times as fast as pipe A. If both the pipes were kept open when the tank is empty, how much time will it take for the tank to overflow? Choose the correct choice from the following.
A) 4 mins B) 6 mins C) 5 mins D) 3 mins E) 7 mins | <gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">5 / 30</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/30) + (1/6)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / (1/5)</gadget>
<output>5</output>
<result>C</result> | C | 5 | Pipe A fills a tank in 30 minutes. Pipe B can fill the same tank 5 times as fast as pipe A. If both the pipes were kept open when the tank is empty, how much time will it take for the tank to overflow? | {
"A": "4 mins",
"B": "6 mins",
"C": "5 mins",
"D": "3 mins",
"E": "7 mins"
} | inverse(add(divide(const_1, 30), divide(5, 30))) | divide(const_1,n0)|divide(n1,n0)|add(#0,#1)|inverse(#2)| | "let the total capacity of tank be 90 liters . capacity of tank filled in 1 minute by a = 3 liters . capacity of tank filled in 1 minute by b = 15 liters . therefore , capacity of the tank filled by both a and b in 1 minute = 18 liters . hence , time taken by both the pipes to overflow the tank = 90 / 18 = 5 minutes . answer : c" | physics |
math_qa__shhtZwOGFDHCM60z | The average age of a class of 15 students is 10 years. If the age of the teacher be included, then the average increased by 1year. Find the age of the teacher? Select.
A) 22 B) 23 C) 26 D) 29 E) 31 | <gadget id="calculator">15 + 1</gadget>
<output>16</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">16 * 11</gadget>
<output>176</output>
<gadget id="calculator">15 * 10</gadget>
<output>150</output>
<gadget id="calculator">176 - 150</gadget>
<output>26</output>
<result>C</result> | C | 26 | The average age of a class of 15 students is 10 years. If the age of the teacher be included, then the average increased by 1year. Find the age of the teacher? | {
"A": "22",
"B": "23",
"C": "26",
"D": "29",
"E": "31"
} | subtract(multiply(add(15, 1), add(10, 1)), multiply(15, 10)) | add(n0,n2)|add(n1,n2)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "total age of 15 persons = 15 * 10 = 150 years average age of 16 persons = 11 years total age of 16 persons = 16 * 11 = 176 years age of the teacher = 176 - 150 = 26 years answer is c" | general |
math_qa__gj417PhdMpE8qGCN | There are some birds in cage, 1/3rd fly away . Then 2/5th of the remaining left the cage , then 2/3rd of the remaining left the cage . At last 8 were remaining . How many birds were in total ? Choose the correct choice from the following answers:
A) 60
B) 27
C) 28
D) 26
E) 91 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(2/3) * (1/3)</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">(3/5) * (2/9)</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">8 / (2/15)</gadget>
<output>60</output>
<result>A</result> | A | 60 | There are some birds in cage, 1/3rd fly away . Then 2/5th of the remaining left the cage , then 2/3rd of the remaining left the cage . At last 8 were remaining . How many birds were in total ? | {
"A": "60",
"B": "27",
"C": "28",
"D": "26",
"E": "91"
} | divide(8, multiply(divide(3, 5), multiply(divide(2, 3), divide(1, 3)))) | divide(n1,n3)|divide(n2,n1)|divide(n0,n1)|multiply(#1,#2)|multiply(#0,#3)|divide(n6,#4) | sol : if x birds were there in total , then x × ( 1 – 1 / 3 ) × ( 1 – 2 / 5 ) × ( 1 – 2 / 3 ) = 8 x × 2 / 3 × 3 / 5 × 1 / 3 = 8 x = 60 answer : a | general |
math_qa__FoKTxcxRoHZjRTnn | x is 3 times as fast as y and working together , they can complete a work in 20 days . in how many days can y alone complete the work ? Choose the correct choice from the following.
A) 11 days B) 80 days C) 13 days D) 15 days E) 19 days | <gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 * 20</gadget>
<output>80</output>
<result>B</result> | B | 80 | x is 3 times as fast as y and working together , they can complete a work in 20 days . in how many days can y alone complete the work ? | {
"A": "11 days",
"B": "80 days",
"C": "13 days",
"D": "15 days",
"E": "19 days"
} | multiply(add(3, const_1), 20) | add(n0,const_1)|multiply(n1,#0) | x = 3 y x + y = 3 y + y = 4 y these 4 y people together can do the work in 20 days , which means y can alone do the work in 4 * 20 = 80 days . answer : b | physics |
math_qa__kvMPtCW7tiR2eqet | On dividing 199 by a number, the quotient is 11 and the remainder is 1. Find the divisor.
Choose one: A) 12 B) 14 C) 16 D) 18 E) 22 | <gadget id="calculator">199 / 11</gadget>
<output>199/11 = around 18.090909</output>
<gadget id="calculator">floor(199/11)</gadget>
<output>18</output>
<result>D</result> | D | 18 | On dividing 199 by a number, the quotient is 11 and the remainder is 1. Find the divisor. | {
"A": "12",
"B": "14",
"C": "16",
"D": "18",
"E": "22"
} | floor(divide(199, 11)) | divide(n0,n1)|floor(#0)| | "d = ( d - r ) / q = ( 199 - 1 ) / 11 = 198 / 11 = 18 d )" | general |
math_qa__riSaeuo4yWv9xGuQ | Of the diplomats who attended a summit conference: 20 spoke French, 32 did not speak Hindi and 20% of the diplomats spoke neither French nor Hindi. If 10% of the diplomats spoke both French and Hindi, then how many diplomats attended the conference? Choose the correct answer.
A) 70 B) 96 C) 108 D) 120 E) 150 | <gadget id="calculator">32 - 20</gadget>
<output>12</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">12 / (1/10)</gadget>
<output>120</output>
<result>D</result> | D | 120 | Of the diplomats who attended a summit conference: 20 spoke French, 32 did not speak Hindi and 20% of the diplomats spoke neither French nor Hindi. If 10% of the diplomats spoke both French and Hindi, then how many diplomats attended the conference? | {
"A": "70",
"B": "96",
"C": "108",
"D": "120",
"E": "150"
} | divide(subtract(32, 20), divide(10, const_100)) | divide(n3,const_100)|subtract(n1,n0)|divide(#1,#0)| | "2 x 2 matrix will be the easiest way to calculate this . text in black : given statements text in red : calculated values thus d = 120 is the correct answer" | other |
math_qa__7LSRbhxZYhJFYj38 | In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 59 liters and they are all empty, how much money total will it cost to fuel all cars? Choose the correct choice from the following answers.
A) 320.20 $
B) 380.20 $
C) 421.20 $
D) 451.20 $
E) 481.20 $ | <gadget id="calculator">0.65 * 59</gadget>
<output>38.35</output>
<gadget id="calculator">38.35 * 12</gadget>
<output>460.2</output>
<result>E</result> | E | 481.2 | In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 59 liters and they are all empty, how much money total will it cost to fuel all cars? | {
"A": "320.20 $",
"B": "380.20 $",
"C": "421.20 $",
"D": "451.20 $",
"E": "481.20 $"
} | multiply(multiply(0.65, 59), 12) | multiply(n1,n3)|multiply(n2,#0)| | "total cost = ( 1.75 * 12 ) + ( 0.65 * 12 * 59 ) = 481.20 hence answer will be ( e )" | general |
math_qa__Gs1aEXFjDRDlVXEV | what is the nearest no. to 2304 which is divisible by 21? Choose the correct choice from the following answers:
A) 2289
B) 2310
C) 2333
D) 2456
E) 2309 | <gadget id="calculator">2_304 % 21</gadget>
<output>15</output>
<gadget id="calculator">2_304 + 15</gadget>
<output>2_319</output>
<result>B</result> | B | 2,310 | what is the nearest no. to 2304 which is divisible by 21? | {
"A": "2289",
"B": "2310",
"C": "2333",
"D": "2456",
"E": "2309"
} | add(2304, reminder(2304, 21)) | reminder(n0,n1)|add(n0,#0) | remainder when 2304 is divided by 21 = 15 so , no . should added to make 15 to 21 = 6 no . = 2304 + 6 = 2310 answer b | general |
math_qa__tNtncklmyQ4ajzhI | The population of a town is 10000. It increases annually at the rate of 25% p.a. What will be its population after 2 years? Choices:
A) 14000
B) 14400
C) 14500
D) 15625
E) 14700 | <gadget id="calculator">10_000 * 25</gadget>
<output>250_000</output>
<gadget id="calculator">250_000 / 100</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 * 2</gadget>
<output>5_000</output>
<gadget id="calculator">10_000 + 5_000</gadget>
<output>15_000</output>
<result>D</result> | D | 15,625 | The population of a town is 10000. It increases annually at the rate of 25% p.a. What will be its population after 2 years? | {
"A": "14000",
"B": "14400",
"C": "14500",
"D": "15625",
"E": "14700"
} | add(10000, multiply(divide(multiply(10000, 25), const_100), const_2)) | multiply(n0,n1)|divide(#0,const_100)|multiply(#1,const_2)|add(n0,#2) | formula : 10000 × 125 / 100 × 125 / 100 = 15625 answer : d | gain |
math_qa__U3NqyAxguphSDZGH | If x and y are integers, what is the least positive number of 24x+20y? Answers.
A) 2 B) 3 C) 4 D) 6 E) 8 | <gadget id="calculator">24 - 20</gadget>
<output>4</output>
<result>C</result> | C | 4 | If x and y are integers, what is the least positive number of 24x+20y? | {
"A": "2",
"B": "3",
"C": "4",
"D": "6",
"E": "8"
} | subtract(24, 20) | subtract(n0,n1) | 24 x + 20 y = 4 ( 6 x + 5 y ) which will be a minimum positive number when 6 x + 5 y = 1 . 6 ( 1 ) + 5 ( - 1 ) = 1 then 4 ( 6 x + 5 y ) can have a minimum positive value of 4 . the answer is c . | general |
math_qa__llTP2eYvZWSvQvcf | Jane makes toy bears. When she works with an assistant, she makes 80 percent more bears per week and works 10 percent fewer hours each week. Having an assistant increases Jane’s output of toy bears per hour by what percent? Choose one
A) 20 % B) 80 % C) 100 % D) 180 % E) 200 % | <gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>C</result> | C | 100 | Jane makes toy bears. When she works with an assistant, she makes 80 percent more bears per week and works 10 percent fewer hours each week. Having an assistant increases Jane’s output of toy bears per hour by what percent? | {
"A": "20 %",
"B": "80 %",
"C": "100 %",
"D": "180 %",
"E": "200 %"
} | multiply(divide(10, subtract(subtract(const_100, 80), 10)), const_100) | subtract(const_100,n0)|subtract(#0,n1)|divide(n1,#1)|multiply(#2,const_100)| | "let ' s assume just jane 40 bears per 40 / hrs a week , so that is 1 bear / hr . with an assistant she makes 72 bears per 36 hours a week or 2 bears / hr ( [ 40 bears * 1.8 ] / [ 40 hrs * . 90 ] ) . [ ( 2 - 1 ) / 1 ] * 100 % = 100 % answer : c" | physics |
math_qa__jtaaA2h1PgdPcRqW | 3*11+3*12+3*15+11=? Choose the correct choice: A) 125 B) 126 C) 130 D) 148 E) 151 | <gadget id="calculator">3 * 11</gadget>
<output>33</output>
<gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">33 + 36</gadget>
<output>69</output>
<gadget id="calculator">3 * 15</gadget>
<output>45</output>
<gadget id="calculator">69 + 45</gadget>
<output>114</output>
<gadget id="calculator">114 + 11</gadget>
<output>125</output>
<result>A</result> | A | 125 | 3*11+3*12+3*15+11=? | {
"A": "125",
"B": "126",
"C": "130",
"D": "148",
"E": "151"
} | add(add(add(multiply(3, 11), multiply(3, 12)), multiply(3, 15)), 11) | multiply(n0,n1)|multiply(n0,n3)|multiply(n0,n5)|add(#0,#1)|add(#3,#2)|add(n6,#4)| | "we have : 3 * 11 = 33 3 * 12 = 36 3 * 15 = 45 all of this is : ( 33 + 36 + 45 ) + 11 = 114 + 11 = 125 correct answer a" | general |
math_qa__WbjxGii4uDhL4Rf2 | One pump drains one-half of a pond in 8 hours, and then a second pump starts draining the pond. The two pumps working together finish emptying the pond in one-half hour. How long would it take the second pump to drain the pond if it had to do the job alone? Choices:
A) 1 hour B) 1.1 hour C) 3 hours D) 5 hours E) 6 hours | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">1 - (1/16)</gadget>
<output>15/16 = around 0.9375</output>
<gadget id="calculator">1 / (15/16)</gadget>
<output>16/15 = around 1.066667</output>
<result>B</result> | B | 1.1 | One pump drains one-half of a pond in 8 hours, and then a second pump starts draining the pond. The two pumps working together finish emptying the pond in one-half hour. How long would it take the second pump to drain the pond if it had to do the job alone? | {
"A": "1 hour",
"B": "1.1 hour",
"C": "3 hours",
"D": "5 hours",
"E": "6 hours"
} | divide(const_1, subtract(const_1, divide(const_1, multiply(8, const_2)))) | multiply(n0,const_2)|divide(const_1,#0)|subtract(const_1,#1)|divide(const_1,#2) | first pump drains 1 / 2 of the tank in 8 hours so 16 hours it will take to drain the full tank . let , 2 nd pump drains the full tank in a hours so both together can drain ( 1 / 16 + 1 / a ) part in 1 hour son in 1 / 2 hour they drain 1 / 2 * ( 1 / 16 + 1 / a ) part of the tank given that in 1 / 2 hour they drain 1 / 2 of the tank hence we can say 1 / 2 * ( 1 / 16 + 1 / a ) = 1 / 2 solving u get a = 16 / 15 = 1.1 hence answer is b | physics |
math_qa__ipJYDGfIJ9zDal8N | The speed of a car is 50 km in the first hour and 60 km in the second hour. What is the average speed of the car? Choose the correct answer:
A) 79 kmph
B) 85 kmph
C) 55 kmph
D) 23 kmph
E) 14 kmph | <gadget id="calculator">50 + 60</gadget>
<output>110</output>
<gadget id="calculator">110 / 2</gadget>
<output>55</output>
<result>C</result> | C | 55 | The speed of a car is 50 km in the first hour and 60 km in the second hour. What is the average speed of the car? | {
"A": "79 kmph",
"B": "85 kmph",
"C": "55 kmph",
"D": "23 kmph",
"E": "14 kmph"
} | divide(add(50, 60), const_2) | add(n0,n1)|divide(#0,const_2)| | "s = ( 55 + 60 ) / 2 = 55 kmph answer : c" | physics |
math_qa__rN8KVy4zszB24352 | The top and bottom of a tower were seen
to be at angles of depression 30° and 60° from the top of a
hill of height 100 m. Find the height of the tower Select
A) 64.67 m
B) 66.67 m
C) 68.67 m
D) 56.67 m
E) 46.67 m | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">100 - (100/3)</gadget>
<output>200/3 = around 66.666667</output>
<result>B</result> | B | 66.67 | The top and bottom of a tower were seen
to be at angles of depression 30° and 60° from the top of a
hill of height 100 m. Find the height of the tower | {
"A": "64.67 m",
"B": "66.67 m",
"C": "68.67 m",
"D": "56.67 m",
"E": "46.67 m"
} | subtract(100, multiply(const_0_33, const_100)) | multiply(const_0_33,const_100)|subtract(n2,#0) | by making a diagram ac represents the hill and de represents the pole given that ac = 100 m anglexad = angleadb = 30 ° ( ∵ ax | | bd ) anglexae = angleaec = 60 ° ( ∵ ax | | ce ) let de = h then , bc = de = h , ab = ( 100 - h ) ( ∵ ac = 100 and bc = h ) , bd = ce tan 60 ° = acce = > 3 √ = 100 ce = > ce = 1003 √ - - - ( 1 ) tan 30 ° = abbd = > 13 √ = 100 − hbd = > 13 √ = 100 − h ( 1003 √ ) ( ∵ bd = ce and substituted the value of ce from equation 1 ) = > ( 100 − h ) = 13 √ × 1003 √ = 1003 = 33.33 = > h = 100 − 33.33 = 66.67 m i . e . , the height of the pole = 66.67 m answer : b | physics |
math_qa__G486MsQmrPip8d4V | The age of the daughter is same as the digit in the mother's age, but in reverse order. In thirteen years mother will be twice as old as daughter will be then. what is the difference in their current age ? Pick:
A) 15
B) 23
C) 27
D) 46
E) 32 | <gadget id="calculator">12 + 1</gadget>
<output>13</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">9 + 10</gadget>
<output>19</output>
<gadget id="calculator">13 + 19</gadget>
<output>32</output>
<gadget id="calculator">32 / 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 + 1</gadget>
<output>41</output>
<gadget id="calculator">10 + 4</gadget>
<output>14</output>
<gadget id="calculator">41 - 14</gadget>
<output>27</output>
<result>C</result> | C | 27 | The age of the daughter is same as the digit in the mother's age, but in reverse order. In thirteen years mother will be twice as old as daughter will be then. what is the difference in their current age ? | {
"A": "15",
"B": "23",
"C": "27",
"D": "46",
"E": "32"
} | subtract(add(multiply(divide(divide(add(add(const_12, const_1), add(subtract(const_10, const_1), const_10)), const_4), const_2), const_10), const_1), add(const_10, divide(divide(add(add(const_12, const_1), add(subtract(const_10, const_1), const_10)), const_4), const_2))) | add(const_1,const_12)|subtract(const_10,const_1)|add(#1,const_10)|add(#0,#2)|divide(#3,const_4)|divide(#4,const_2)|add(#5,const_10)|multiply(#5,const_10)|add(#7,const_1)|subtract(#8,#6) | daughter ' s age = 10 x + y so mother ' s age = 10 y + x . . after 13 years , 10 x + y + 13 = 2 * ( 10 y + x + 13 ) . . . . so 13 + 19 y = 8 x . . . check for odd values of y , y = 1 satisfies the eqn with x = 4 . . . so ages are 41 and 14 and ans as found correctly by u is c . . 27 | general |
math_qa__5YZlNveOSrSov9Sl | A larger cube has 125 cubic inch as a volume and in the cube there are 125 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 125 smaller cubes and the surface area of the larger cube, in square inch? Choose the most appropriate option: A) 54 B) 600 C) 81 D) 108 E) 120 | <gadget id="calculator">1 ** (1/3)</gadget>
<output>1</output>
<gadget id="calculator">6 * (1 ** 2)</gadget>
<output>6</output>
<gadget id="calculator">6 * 125</gadget>
<output>750</output>
<gadget id="calculator">125 ** (1/3)</gadget>
<output>5</output>
<gadget id="calculator">6 * (5 ** 2)</gadget>
<output>150</output>
<gadget id="calculator">750 - 150</gadget>
<output>600</output>
<result>B</result> | B | 600 | A larger cube has 125 cubic inch as a volume and in the cube there are 125 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 125 smaller cubes and the surface area of the larger cube, in square inch? | {
"A": "54",
"B": "600",
"C": "81",
"D": "108",
"E": "120"
} | subtract(multiply(surface_cube(cube_edge_by_volume(1)), 125), surface_cube(cube_edge_by_volume(125))) | cube_edge_by_volume(n2)|cube_edge_by_volume(n0)|surface_cube(#0)|surface_cube(#1)|multiply(n0,#2)|subtract(#4,#3)| | "volume of larger cube = 125 = 5 ^ 3 side of larger cube = 5 volume of smaller cube = 1 - - > side of smaller cube = 1 surface area of larger cube = 6 * 5 ^ 2 = 150 surface area of 27 smaller cubes = 125 * 6 * 1 = 750 difference = 750 - 150 = 600 answer : b" | geometry |
math_qa__gZ7kSCnW7CvnIZEF | if below equation are true
24$6=64
35$5=87
63$7=99
by using same logic what is the value of the below question
88$8=?
Choose the correct choice from the following:
A) 1621
B) 1711
C) 1611
D) 1511
E) 1311 | <gadget id="calculator">8 + 8</gadget>
<output>16</output>
<gadget id="calculator">16 * 100</gadget>
<output>1_600</output>
<gadget id="calculator">88 / 8</gadget>
<output>11</output>
<gadget id="calculator">1_600 + 11</gadget>
<output>1_611</output>
<result>C</result> | C | 1,611 | if below equation are true
24$6=64
35$5=87
63$7=99
by using same logic what is the value of the below question
88$8=? | {
"A": "1621",
"B": "1711",
"C": "1611",
"D": "1511",
"E": "1311"
} | add(multiply(add(8, 8), const_100), divide(88, 8)) | add(n10,n10)|divide(n9,n10)|multiply(#0,const_100)|add(#1,#2) | correct answer : c the number on the right side is formed as ( sum of digits of the 1 st number ) no 1 / no 2 ex : 35 $ 5 = 87 ( 3 + 5 = 8 ) ( 35 / 5 = 7 ) 63 $ 7 = 99 ( 6 + 3 = 9 ) ( 63 / 7 = 9 ) | other |
math_qa__iG5fe2QSvpZbT9P5 | The average weight of 10 persons increases by 3.2 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
Choose one:
A) 76 kg B) 80 kg C) 85 kg D) 97 kg E) none | <gadget id="calculator">10 * 3.2</gadget>
<output>32</output>
<gadget id="calculator">65 + 32</gadget>
<output>97</output>
<result>D</result> | D | 97 | The average weight of 10 persons increases by 3.2 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? | {
"A": "76 kg",
"B": "80 kg",
"C": "85 kg",
"D": "97 kg",
"E": "none"
} | add(65, multiply(10, 3.2)) | multiply(n0,n1)|add(n2,#0)| | "solution total weight increased = ( 10 x 3.2 ) kg = 32 kg . weight of new person = ( 65 + 32 ) kg = 97 kg . answer d" | general |
math_qa__XLBAIYZ0U2rgGroQ | The average of runs of a cricket player of 10 innings was 37. How many runs must he make in his next innings so as to increase his average of runs by 4 ?
Pick one
A) 76
B) 81
C) 85
D) 87
E) 89 | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">4 + 37</gadget>
<output>41</output>
<gadget id="calculator">11 * 41</gadget>
<output>451</output>
<gadget id="calculator">10 * 37</gadget>
<output>370</output>
<gadget id="calculator">451 - 370</gadget>
<output>81</output>
<result>B</result> | B | 81 | The average of runs of a cricket player of 10 innings was 37. How many runs must he make in his next innings so as to increase his average of runs by 4 ? | {
"A": "76",
"B": "81",
"C": "85",
"D": "87",
"E": "89"
} | subtract(multiply(add(10, const_1), add(4, 37)), multiply(10, 37)) | add(n0,const_1)|add(n1,n2)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "explanation : average = total runs / no . of innings = 37 so , total = average x no . of innings = 37 x 10 = 370 . now increase in avg = 4 runs . so , new avg = 37 + 4 = 41 runs total runs = new avg x new no . of innings = 41 x 11 = 451 runs made in the 11 th inning = 451 - 370 = 81 answer : b" | general |
math_qa__AFsSHbbgZdq6iNzt | A , B , and C started a partnership business by investing $45,000 , $63,000 , and $72,000 respectively. At the end of the year, the profit was distributed among them. If C's share of profit is $24,000, what is the total profit?
Choose the correct answer
A) $ 48,000 B) $ 52,000 C) $ 56,000 D) $ 60,000 E) $ 64,000 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 4</gadget>
<output>24</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">24 * 1_000</gadget>
<output>24_000</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 + 5</gadget>
<output>45</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 10</gadget>
<output>70</output>
<gadget id="calculator">70 + 2</gadget>
<output>72</output>
<gadget id="calculator">72 * 1_000</gadget>
<output>72_000</output>
<gadget id="calculator">45_000 / 72_000</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">24_000 * (5/8)</gadget>
<output>15_000</output>
<gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">60 + 3</gadget>
<output>63</output>
<gadget id="calculator">63 * 1_000</gadget>
<output>63_000</output>
<gadget id="calculator">63_000 / 72_000</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">24_000 * (7/8)</gadget>
<output>21_000</output>
<gadget id="calculator">15_000 + 21_000</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 + 24_000</gadget>
<output>60_000</output>
<result>D</result> | D | 60,000 | A , B , and C started a partnership business by investing $45,000 , $63,000 , and $72,000 respectively. At the end of the year, the profit was distributed among them. If C's share of profit is $24,000, what is the total profit? | {
"A": "$ 48,000",
"B": "$ 52,000",
"C": "$ 56,000",
"D": "$ 60,000",
"E": "$ 64,000"
} | add(add(multiply(multiply(add(multiply(const_2, multiply(add(const_2, const_3), const_2)), const_4), multiply(multiply(add(const_2, const_3), const_2), const_100)), divide(multiply(add(multiply(const_4, multiply(add(const_2, const_3), const_2)), add(const_2, const_3)), multiply(multiply(add(const_2, const_3), const_2), const_100)), multiply(add(multiply(add(const_3, const_4), multiply(add(const_2, const_3), const_2)), const_2), multiply(multiply(add(const_2, const_3), const_2), const_100)))), multiply(multiply(add(multiply(const_2, multiply(add(const_2, const_3), const_2)), const_4), multiply(multiply(add(const_2, const_3), const_2), const_100)), divide(multiply(add(multiply(add(const_2, const_4), multiply(add(const_2, const_3), const_2)), const_3), multiply(multiply(add(const_2, const_3), const_2), const_100)), multiply(add(multiply(add(const_3, const_4), multiply(add(const_2, const_3), const_2)), const_2), multiply(multiply(add(const_2, const_3), const_2), const_100))))), multiply(add(multiply(const_2, multiply(add(const_2, const_3), const_2)), const_4), multiply(multiply(add(const_2, const_3), const_2), const_100))) | add(const_2,const_3)|add(const_3,const_4)|add(const_2,const_4)|multiply(#0,const_2)|multiply(#3,const_4)|multiply(#3,const_100)|multiply(#1,#3)|multiply(#3,const_2)|multiply(#2,#3)|add(#0,#4)|add(#6,const_2)|add(#7,const_4)|add(#8,const_3)|multiply(#9,#5)|multiply(#10,#5)|multiply(#11,#5)|multiply(#12,#5)|divide(#13,#14)|divide(#16,#14)|multiply(#17,#15)|multiply(#18,#15)|add(#19,#20)|add(#21,#15) | a : b : c = 45000 : 63000 : 72000 which is a ratio of 5 : 7 : 8 . let the total profit be x . x * 8 / 20 = 24000 x = 24000 * 20 / 8 = 60,000 . the answer is d . | gain |
math_qa__NYu5dLh5fgArkI4N | A company decreased the price of its main product by 75%. Subsequently, the number of units sold increased such that the total revenue remained unchanged. What was the ratio of the percent increase in the units sold to the percent decrease of the original price for this product? Answers.
A) 1.33 B) 2.33 C) 3.33 D) 4.33 E) 1.45 | <gadget id="calculator">100 / 75</gadget>
<output>4/3 = around 1.333333</output>
<result>A</result> | A | 1.33 | A company decreased the price of its main product by 75%. Subsequently, the number of units sold increased such that the total revenue remained unchanged. What was the ratio of the percent increase in the units sold to the percent decrease of the original price for this product? | {
"A": "1.33",
"B": "2.33",
"C": "3.33",
"D": "4.33",
"E": "1.45"
} | divide(const_100, 75) | divide(const_100,n0)| | "for the total revenue to remain the same when the price is 3 / 4 , the number of products sold must 3 / 4 times . therefore increase in the number of products sold is 100 % = > the required ratio = 100 % / 75 % = 1.33 answer : a" | general |
math_qa__5QGBLMTiYqRdP4if | A's speed is 15/13 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that B beats A by 25% of the length of the race? Pick one
A) 35 % B) 48 % C) 52 % D) 42 % E) 46 % | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">13 / 15</gadget>
<output>13/15 = around 0.866667</output>
<gadget id="calculator">(3/4) * (13/15)</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">1 - (13/20)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(7/20) * 100</gadget>
<output>35</output>
<result>A</result> | A | 35 | A's speed is 15/13 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that B beats A by 25% of the length of the race? | {
"A": "35 %",
"B": "48 %",
"C": "52 %",
"D": "42 %",
"E": "46 %"
} | multiply(subtract(const_1, multiply(divide(subtract(const_100, 25), const_100), divide(13, 15))), const_100) | divide(n1,n0)|subtract(const_100,n2)|divide(#1,const_100)|multiply(#2,#0)|subtract(const_1,#3)|multiply(#4,const_100) | first calculate the distance , b has covered with his speed in the time , in which a reached 80 % of the race . then add the remaining distance as head start for b to win the race . its best to apply ratios concept here . since a ' s speed is 15 / 13 of b , therefore , b ' s speed is 13 / 15 of a distance covered by b = speed x time = ( 13 / 15 ) x ( 0.75 ) = 0.65 % ( which means b would have covered 0.65 of the race length during the time in which a has covered 0.75 of the race length . therefore to win , b needs a headstart of ( 1 - 0.65 = ) 0.35 of the race length . so the answer is a | general |
math_qa__Jjnmnb3YLyaHpRRf | company c sells a line of 20 products with an average retail price of $ 1200 . if none of these products sells for less than $ 400 , and exactly 10 of the products sell for less than $ 1000 , what is the greatest possible selling price of the most expensive product ? Choose the correct option
A) 12000 B) 11000 C) 10000 D) 13000 E) 15000 | <gadget id="calculator">20 * 1_200</gadget>
<output>24_000</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">9 * 1_000</gadget>
<output>9_000</output>
<gadget id="calculator">400 * 10</gadget>
<output>4_000</output>
<gadget id="calculator">9_000 + 4_000</gadget>
<output>13_000</output>
<gadget id="calculator">24_000 - 13_000</gadget>
<output>11_000</output>
<result>B</result> | B | 11,000 | company c sells a line of 20 products with an average retail price of $ 1200 . if none of these products sells for less than $ 400 , and exactly 10 of the products sell for less than $ 1000 , what is the greatest possible selling price of the most expensive product ? | {
"A": "12000",
"B": "11000",
"C": "10000",
"D": "13000",
"E": "15000"
} | subtract(multiply(20, 1200), add(multiply(subtract(10, const_1), 1000), multiply(400, 10))) | multiply(n0,n1)|multiply(n2,n3)|subtract(n3,const_1)|multiply(n4,#2)|add(#3,#1)|subtract(#0,#4) | the average price of 20 products is $ 1,200 means that the total price of 20 products is 20 * 1,200 = $ 24,000 . next , since exactly 10 of the products sell for less than $ 1,000 , then let ' s make these 10 items to be at $ 400 each ( min possible ) . now , the remaining 9 items can not be priced less than $ 1,000 , thus the minimum possible price of each of these 9 items is $ 1,000 . thus the minimum possible value of 19 products is 10 * 400 + 9 * 1,000 = $ 13,000 . therefore , the greatest possible selling price of the most expensive product is $ 24,000 - $ 13,000 = $ 11,000 . answer : b . | general |
math_qa__NDjE67lC47HXQvWO | In a box of 6 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective? Choose the correct choice from the following choices.
A) 1 / 2
B) 1 / 5
C) 2 / 3
D) 2 / 5
E) 1 / 7 | <gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">factorial(1)</gadget>
<output>1</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">1 * 6</gadget>
<output>6</output>
<gadget id="calculator">24 / 6</gadget>
<output>4</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">720 / 36</gadget>
<output>20</output>
<gadget id="calculator">4 / 20</gadget>
<output>1/5 = around 0.2</output>
<result>B</result> | B | 0.2 | In a box of 6 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective? | {
"A": "1 / 2",
"B": "1 / 5",
"C": "2 / 3",
"D": "2 / 5",
"E": "1 / 7"
} | divide(divide(factorial(subtract(6, 2)), multiply(factorial(subtract(subtract(6, 2), 3)), factorial(3))), divide(factorial(6), multiply(factorial(subtract(6, 3)), factorial(3)))) | factorial(n2)|factorial(n0)|subtract(n0,n1)|subtract(n0,n2)|factorial(#2)|factorial(#3)|subtract(#2,n2)|factorial(#6)|multiply(#5,#0)|divide(#1,#8)|multiply(#7,#0)|divide(#4,#10)|divide(#11,#9)| | "first , there are 4 c 3 ways you can select 3 good pencils from 4 good ones . second , there are 6 c 3 ways you select 3 pencils from 6 ones in the box . then , the probability that neither pen will be defective is : 4 c 3 / 6 c 3 = 4 / 20 = 1 / 5 answer is b" | general |
math_qa__shfCVQUgKG6wS2Qi | A candidate appearing for an examination has to secure 52% marks to pass paper I. But he secured only 45 marks and failed by 35 marks. What is the maximum mark for paper I? Options.
A) 110 B) 154 C) 130 D) 140 E) 150 | <gadget id="calculator">45 + 35</gadget>
<output>80</output>
<gadget id="calculator">52 / 100</gadget>
<output>13/25 = around 0.52</output>
<gadget id="calculator">80 / (13/25)</gadget>
<output>2_000/13 = around 153.846154</output>
<result>B</result> | B | 154 | A candidate appearing for an examination has to secure 52% marks to pass paper I. But he secured only 45 marks and failed by 35 marks. What is the maximum mark for paper I? | {
"A": "110",
"B": "154",
"C": "130",
"D": "140",
"E": "150"
} | divide(add(45, 35), divide(52, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "he secured 45 marks nd fail by 35 marks so total marks for pass the examinatn = 80 let toal marks x x * 52 / 100 = 80 x = 154 answer : b" | gain |
math_qa__HnQ7huhXUzba8EZx | Jim drove 768 miles of a 1200 miles journey. How many more miles does he need to drive to finish his journey? Select the correct option: A) 432 miles B) 651 miles C) 387 miles D) 954 miles E) 556 miles | <gadget id="calculator">1_200 - 768</gadget>
<output>432</output>
<result>A</result> | A | 432 | Jim drove 768 miles of a 1200 miles journey. How many more miles does he need to drive to finish his journey? | {
"A": "432 miles",
"B": "651 miles",
"C": "387 miles",
"D": "954 miles",
"E": "556 miles"
} | subtract(1200, 768) | subtract(n1,n0)| | "the number of miles to drive to finish his journey is given by 1200 - 768 = 432 miles correct answer a" | physics |
math_qa__44NXSNq2VLfavBg8 | If |20x-10| = 110, then find the product of the values of x? Choose the correct choice from the following answers.
A) - 45
B) 50
C) - 62
D) 35
E) - 30 | <gadget id="calculator">110 - 10</gadget>
<output>100</output>
<gadget id="calculator">110 + 10</gadget>
<output>120</output>
<gadget id="calculator">100 - 120</gadget>
<output>-20</output>
<gadget id="calculator">(-20) - 10</gadget>
<output>-30</output>
<result>E</result> | E | -30 | If |20x-10| = 110, then find the product of the values of x? | {
"A": "- 45",
"B": "50",
"C": "- 62",
"D": "35",
"E": "- 30"
} | subtract(subtract(subtract(110, 10), add(110, 10)), 10) | add(n1,n2)|subtract(n2,n1)|subtract(#1,#0)|subtract(#2,n1) | | 20 x - 10 | = 110 20 x - 10 = 110 or 20 x - 10 = - 110 20 x = 120 or 20 x = - 100 x = 6 or x = - 5 product = - 5 * 6 = - 30 answer is e | general |
math_qa__FdAcA78OmyWaJbqB | In a certain kindergarten, half of the children are allergic to peanuts, 10 children are not allergic to cashew nuts, 10 children are allergic to both peanuts and cashew nuts, and 18 children are allergic to cashew nuts. How many of the kindergarten's children are NOT allergic to peanuts and are NOT allergic to cashew nuts? Choose the correct choice from the following:
A) 14 B) 10 C) 8 D) 6 E) 4 | <gadget id="calculator">18 + 10</gadget>
<output>28</output>
<gadget id="calculator">28 / 2</gadget>
<output>14</output>
<gadget id="calculator">18 + 14</gadget>
<output>32</output>
<gadget id="calculator">32 - 10</gadget>
<output>22</output>
<gadget id="calculator">28 - 22</gadget>
<output>6</output>
<result>D</result> | D | 6 | In a certain kindergarten, half of the children are allergic to peanuts, 10 children are not allergic to cashew nuts, 10 children are allergic to both peanuts and cashew nuts, and 18 children are allergic to cashew nuts. How many of the kindergarten's children are NOT allergic to peanuts and are NOT allergic to cashew nuts? | {
"A": "14",
"B": "10",
"C": "8",
"D": "6",
"E": "4"
} | subtract(add(18, 10), subtract(add(18, divide(add(18, 10), const_2)), 10)) | add(n0,n2)|divide(#0,const_2)|add(n2,#1)|subtract(#2,n0)|subtract(#0,#3) | we are given children allergic to cashew nuts as 18 and not allergic to cashew nuts as 10 , so total = 10 + 18 = 28 . . . children allergic to both are 10 . . . 18 are allergic to cashew nuts , so and half or 28 / 2 = 14 are allergic to peanuts . . so children allergic to at least one of the two are 18 + 14 - 10 = 22 . . therefore children not allergic to any of the two are 28 - 22 = 6 answer : d | other |
math_qa__AbiR8qmmUw6Ze7Gz | The sum of number of boys and girls in a school is 300. If the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is? Choices:
A) 50 B) 40 C) 60 D) 100 E) 75 | <gadget id="calculator">300 / 100</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">300 / 4</gadget>
<output>75</output>
<result>E</result> | E | 75 | The sum of number of boys and girls in a school is 300. If the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is? | {
"A": "50",
"B": "40",
"C": "60",
"D": "100",
"E": "75"
} | divide(300, add(divide(300, const_100), const_1)) | divide(n0,const_100)|add(#0,const_1)|divide(n0,#1)| | "we have x + x % of 300 = 300 x + x / 100 * 300 = 300 4 * x = 300 x = 75 answer is e" | general |
math_qa__yad20Qp7heSOuD3w | On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.82 per glass on the first day, what was the price per glass on the second day?
Choices:
A) $ 015 B) $ 0.20 C) $ 0.30 D) $ 0.40 E) $ 0.55 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 0.82</gadget>
<output>1.64</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">1.64 / 3</gadget>
<output>0.546667</output>
<result>E</result> | E | 0.55 | On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.82 per glass on the first day, what was the price per glass on the second day? | {
"A": "$ 015",
"B": "$ 0.20",
"C": "$ 0.30",
"D": "$ 0.40",
"E": "$ 0.55"
} | divide(multiply(add(const_1, const_1), 0.82), add(const_1, const_2)) | add(const_1,const_1)|add(const_1,const_2)|multiply(n0,#0)|divide(#2,#1)| | "on the first day 1 unit of orange juice and 1 unit of water was used to make 2 units of orangeade ; on the second day 1 unit of orange juice and 2 units of water was used to make 3 units of orangeade ; so , the ratio of the amount of orangeade made on the first day to the amount of orangeade made on the second day is 2 to 3 . naturally the ratio of the # of glasses of orangeade made on the first day to the # of glasses of orangeade made on the second day is 2 to 3 . we are told thatthe revenue from selling the orangeade was the same for both daysso the revenue from 2 glasses on the first day equals to the revenue from 3 glasses on the second day . say the price of the glass of the orangeade on the second day was $ x then 2 * 0.82 = 3 * x - - > x = $ 0.55 . answer : e ." | general |
math_qa__nAxMMxhsl9AcTkTp | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 162° of the circle, what percentage of MegaTek employees are in manufacturing? Choices:
A) 20 % B) 25 % C) 30 % D) 45 % E) 72 % | <gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">162 / 360</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">(9/20) * 100</gadget>
<output>45</output>
<result>D</result> | D | 45 | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 162° of the circle, what percentage of MegaTek employees are in manufacturing? | {
"A": "20 %",
"B": "25 %",
"C": "30 %",
"D": "45 %",
"E": "72 %"
} | multiply(divide(162, divide(const_3600, const_10)), const_100) | divide(const_3600,const_10)|divide(n0,#0)|multiply(#1,const_100)| | answer : d 162 ° divided by 360 ° equals 0.45 , therefore the sector is equal to 45 % of the total | physics |
math_qa__ql634nFFzpEVshoJ | 1100 boys and 700 girls are examined in a test; 42% of the boys and 30% of the girls pass. The percentage of the total who failed is ? Options
A) 63.3 % B) 52.4 % C) 81.2 % D) 75.4 % E) 69.1 % | <gadget id="calculator">1_100 + 700</gadget>
<output>1_800</output>
<gadget id="calculator">42 / 100</gadget>
<output>21/50 = around 0.42</output>
<gadget id="calculator">1_100 * (21/50)</gadget>
<output>462</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">700 * (3/10)</gadget>
<output>210</output>
<gadget id="calculator">462 + 210</gadget>
<output>672</output>
<gadget id="calculator">1_800 - 672</gadget>
<output>1_128</output>
<gadget id="calculator">1_128 / 1_800</gadget>
<output>47/75 = around 0.626667</output>
<gadget id="calculator">100 * (47/75)</gadget>
<output>188/3 = around 62.666667</output>
<result>A</result> | A | 63.3 | 1100 boys and 700 girls are examined in a test; 42% of the boys and 30% of the girls pass. The percentage of the total who failed is ? | {
"A": "63.3 %",
"B": "52.4 %",
"C": "81.2 %",
"D": "75.4 %",
"E": "69.1 %"
} | multiply(const_100, divide(subtract(add(1100, 700), add(multiply(1100, divide(42, const_100)), multiply(700, divide(30, const_100)))), add(1100, 700))) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|subtract(#0,#5)|divide(#6,#0)|multiply(#7,const_100) | total number of students = 1100 + 700 = 1800 number of students passed = ( 42 % of 1100 + 30 % of 700 ) = 462 + 210 = 672 number of failures = 1128 * 100 / 1800 = 190 / 3 % = 63.3 % answer is a | general |
math_qa__hkfHokMDuMjQK80D | John makes $60 a week from his job. He earns a raise andnow makes $70 a week. What is the % increase? Choose the correct choice from the following answers:
A) 16 %
B) 16.66 %
C) 17 %
D) 17.2 %
E) 18 % | <gadget id="calculator">70 - 60</gadget>
<output>10</output>
<gadget id="calculator">10 / 60</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 100</gadget>
<output>50/3 = around 16.666667</output>
<result>B</result> | B | 16.66 | John makes $60 a week from his job. He earns a raise andnow makes $70 a week. What is the % increase? | {
"A": "16 %",
"B": "16.66 %",
"C": "17 %",
"D": "17.2 %",
"E": "18 %"
} | multiply(divide(subtract(70, 60), 60), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "increase = ( 10 / 60 ) * 100 = ( 1 / 6 ) * 100 = 16.66 % . b" | gain |
math_qa__rtKmA5maJDsTmnMg | Two heavily loaded sixteen-wheeler transport trucks are 690 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway? Choose the most appropriate option:
A) 120 B) 130 C) 150 D) 320 E) 450 | <gadget id="calculator">690 - 90</gadget>
<output>600</output>
<gadget id="calculator">90 + 80</gadget>
<output>170</output>
<gadget id="calculator">600 / 170</gadget>
<output>60/17 = around 3.529412</output>
<gadget id="calculator">90 - 80</gadget>
<output>10</output>
<gadget id="calculator">(60/17) * 10</gadget>
<output>600/17 = around 35.294118</output>
<gadget id="calculator">90 + (600/17)</gadget>
<output>2_130/17 = around 125.294118</output>
<result>A</result> | A | 120 | Two heavily loaded sixteen-wheeler transport trucks are 690 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway? | {
"A": "120",
"B": "130",
"C": "150",
"D": "320",
"E": "450"
} | add(90, multiply(divide(subtract(690, 90), add(90, 80)), subtract(90, 80))) | add(n1,n2)|subtract(n0,n1)|subtract(n1,n2)|divide(#1,#0)|multiply(#3,#2)|add(n1,#4)| | "i ' ve been reading the website for a while and i ' m always keen to see different approaches so i would like to share one that works for me : short version : truck a travels for an hour . distance remaining = 690 - 90 = 600 k ratio of speeds 9 : 8 - > 510 / 17 = 30 truck a = 90 + 30 * 9 = 360 truck b = 30 * 8 = 240 delta = 120 km answer a" | general |
math_qa__JLQMXsNf51aotGYP | On a map the distance between two mountains is 312 inches. The actual distance between the mountains is 136 km. Ram is camped at a location that on the map is 42 inch from the base of the mountain. How many km is he from the base of the mountain? Answers:
A) 14.83 B) 14.81 C) 14.8 D) 14.82 E) 18.3 | <gadget id="calculator">42 * 136</gadget>
<output>5_712</output>
<gadget id="calculator">5_712 / 312</gadget>
<output>238/13 = around 18.307692</output>
<result>E</result> | E | 18.3 | On a map the distance between two mountains is 312 inches. The actual distance between the mountains is 136 km. Ram is camped at a location that on the map is 42 inch from the base of the mountain. How many km is he from the base of the mountain? | {
"A": "14.83",
"B": "14.81",
"C": "14.8",
"D": "14.82",
"E": "18.3"
} | divide(multiply(42, 136), 312) | multiply(n1,n2)|divide(#0,n0)| | "explanation : since 312 inch = 136 km so 1 inch = 136 / 312 km so 42 inch = ( 136 ã — 42 ) / 312 = 18.3 km answer : e" | physics |
math_qa__i0FwrYz4XLn2c4UK | On a certain day, Tim invested $500 at 10 percent annual interest, compounded annually, and Lana invested 800 at 5 percent annual interest, compounded annually.The total amount of interest earned by Tim’s investment in the first 2 years was how much greater than the total amount of interest earned by Lana’s investment in the first 2 years? Options:
A) $ 5
B) $ 15
C) $ 23
D) $ 100
E) $ 105 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 2</gadget>
<output>121/100 = around 1.21</output>
<gadget id="calculator">500 * (121/100)</gadget>
<output>605</output>
<gadget id="calculator">605 - 500</gadget>
<output>105</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">(441/400) * 800</gadget>
<output>882</output>
<gadget id="calculator">882 - 800</gadget>
<output>82</output>
<gadget id="calculator">105 - 82</gadget>
<output>23</output>
<result>C</result> | C | 23 | On a certain day, Tim invested $500 at 10 percent annual interest, compounded annually, and Lana invested 800 at 5 percent annual interest, compounded annually.The total amount of interest earned by Tim’s investment in the first 2 years was how much greater than the total amount of interest earned by Lana’s investment in the first 2 years? | {
"A": "$ 5",
"B": "$ 15",
"C": "$ 23",
"D": "$ 100",
"E": "$ 105"
} | subtract(subtract(multiply(500, power(add(const_1, divide(10, const_100)), 2)), 500), subtract(multiply(power(add(const_1, divide(5, const_100)), 2), 800), 800)) | divide(n1,const_100)|divide(n3,const_100)|add(#0,const_1)|add(#1,const_1)|power(#2,n4)|power(#3,n4)|multiply(n0,#4)|multiply(n2,#5)|subtract(#6,n0)|subtract(#7,n2)|subtract(#8,#9)| | "compounded annually means that the interest is applied once per year . one can have 10 % annual interest compounded monthly - in this case 10 % / 12 would be applied each month , or 10 % annual interest compounded daily etc . with respect to the problem at hand , at the end of two years , tim would have 500 ( 1.10 ) ^ 2 = 500 ( 1.21 ) = 605 and lana would have 800 ( 1.05 ) ^ 2 = 800 ( 1.1025 ) = 882 thus , tim earned 105 dollars , while lana earned 82 dollars the difference is $ 23 and the answer is c ." | gain |
math_qa__BJdmFdFZwX3xmDv8 | In measuring the sides of a rectangle, one side is taken 8% in excess and other 5% in deficit. Find the error percentage in the area calculated from these measurements. Choose one:
A) 3.5 % B) 2.4 % C) 3 % D) 5 % E) 2.6 % | <gadget id="calculator">8 - 5</gadget>
<output>3</output>
<gadget id="calculator">8 * 5</gadget>
<output>40</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">3 - (2/5)</gadget>
<output>13/5 = around 2.6</output>
<result>E</result> | E | 2.6 | In measuring the sides of a rectangle, one side is taken 8% in excess and other 5% in deficit. Find the error percentage in the area calculated from these measurements. | {
"A": "3.5 %",
"B": "2.4 %",
"C": "3 %",
"D": "5 %",
"E": "2.6 %"
} | subtract(subtract(8, 5), divide(multiply(8, 5), const_100)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,const_100)|subtract(#1,#2)| | "let the sides of the rectangle be a and b . actual area of the rectangle without error = ab new side a ( 8 % in excess ) = a + 0.08 a = 1.08 a new side b ( 5 % in deficit ) = b - 0.05 b = 0.95 b area of the new rectangle = ( 1.08 a ) ( 0.95 b ) = ( 1.0260 ) ab say a = 1 and b = 1 area of the original rectangle = 1 area of the new rectangle = 1.026 change in the area calculation = . 026 error percentage in the area calculated = 2.6 % answer : e" | geometry |
math_qa__MIpVglVatqHHrQsn | Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.3200? Choose the correct choice from the following answers
A) 8100 B) 3388 C) 7767 D) 4050 E) 2288 | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 3_200</gadget>
<output>400</output>
<gadget id="calculator">3_200 + 400</gadget>
<output>3_600</output>
<gadget id="calculator">(1/8) * 3_600</gadget>
<output>450</output>
<gadget id="calculator">3_600 + 450</gadget>
<output>4_050</output>
<result>D</result> | D | 4,050 | Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.3200? | {
"A": "8100",
"B": "3388",
"C": "7767",
"D": "4050",
"E": "2288"
} | add(add(3200, multiply(divide(1, 8), 3200)), multiply(divide(1, 8), add(3200, multiply(divide(1, 8), 3200)))) | divide(n0,n1)|multiply(n2,#0)|add(n2,#1)|multiply(#2,#0)|add(#2,#3)| | "3200 * 9 / 8 * 9 / 8 = 4050 answer : d" | general |
math_qa__R0NHs4tHY2QG0A7X | on a certain test , bill scored 20 more points than john , but half as many points as sue . if the sum of the scores of the 3 students was 160 points , how many points did bill receive ? Choose the correct option
A) 30 B) 45 C) 50 D) 80 E) 100 | <gadget id="calculator">160 + 20</gadget>
<output>180</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">180 / 4</gadget>
<output>45</output>
<result>B</result> | B | 45 | on a certain test , bill scored 20 more points than john , but half as many points as sue . if the sum of the scores of the 3 students was 160 points , how many points did bill receive ? | {
"A": "30",
"B": "45",
"C": "50",
"D": "80",
"E": "100"
} | divide(add(160, 20), add(add(const_1, const_1), const_2)) | add(n0,n2)|add(const_1,const_1)|add(#1,const_2)|divide(#0,#2) | consider john ' s points as x so bill ' s points are x + 20 so sue ' s points are 2 x + 40 total of all three students is 4 x + 60 , but this total is given as 160 x = 25 so bill ' s points = 25 + 20 = 45 correct answer option b | general |
math_qa__gK6WhRUnCNNyZnKS | A man swims downstream 45 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water? Answers.
A) 2 B) 8 C) 9 D) 10 E) 10.5 | <gadget id="calculator">18 / 3</gadget>
<output>6</output>
<gadget id="calculator">45 / 3</gadget>
<output>15</output>
<gadget id="calculator">6 + 15</gadget>
<output>21</output>
<gadget id="calculator">21 / 2</gadget>
<output>21/2 = around 10.5</output>
<result>E</result> | E | 10.5 | A man swims downstream 45 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water? | {
"A": "2",
"B": "8",
"C": "9",
"D": "10",
"E": "10.5"
} | divide(add(divide(18, 3), divide(45, 3)), const_2) | divide(n1,n2)|divide(n0,n2)|add(#0,#1)|divide(#2,const_2)| | "45 - - - 3 ds = 15 ? - - - - 1 18 - - - - 3 us = 6 ? - - - - 1 m = ? m = ( 15 + 6 ) / 2 = 10.5 answer : e" | physics |
math_qa__GuyrQ69wnGxtZY2D | The product of two successive numbers is 1122. Which is the smaller of the two numbers?
Select
A) 34 B) 36 C) 33 D) 38 E) 31 | <gadget id="calculator">1_122 ** (1/2)</gadget>
<output>sqrt(1122) = around 33.496268</output>
<result>C</result> | C | 33 | The product of two successive numbers is 1122. Which is the smaller of the two numbers? | {
"A": "34",
"B": "36",
"C": "33",
"D": "38",
"E": "31"
} | sqrt(1122) | sqrt(n0)| | "c 33 from the given alternatives , 33 × 34 = 1122 ∴ smaller number = 33" | general |
math_qa__okDVWuxmwYpjcn85 | A library has an average of 630 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is: Choose one
A) 250
B) 305
C) 280
D) 285
E) none | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">30 / 7</gadget>
<output>30/7 = around 4.285714</output>
<gadget id="calculator">floor(30/7)</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 630</gadget>
<output>3_150</output>
<gadget id="calculator">30 - 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 240</gadget>
<output>6_000</output>
<gadget id="calculator">3_150 + 6_000</gadget>
<output>9_150</output>
<gadget id="calculator">9_150 / 30</gadget>
<output>305</output>
<result>B</result> | B | 305 | A library has an average of 630 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is: | {
"A": "250",
"B": "305",
"C": "280",
"D": "285",
"E": "none"
} | divide(add(multiply(add(floor(divide(30, add(const_3, const_4))), const_1), 630), multiply(subtract(30, add(floor(divide(30, add(const_3, const_4))), const_1)), 240)), 30) | add(const_3,const_4)|divide(n2,#0)|floor(#1)|add(#2,const_1)|multiply(n0,#3)|subtract(n2,#3)|multiply(n1,#5)|add(#4,#6)|divide(#7,n2)| | "since the month begins with sunday , to there will be five sundays in the month average required = ( 630 x 5 + 240 x 25 / 30 ) = 305 answer : option b" | general |
math_qa__Onp79sFdQjv6aDNY | The sale price of a trolley bag including the sale tax is Rs. 1232. The rate of sale tax is 10% . If the shopkeeper has made a profit of 12%, the cost price of the trolley bag is:
Choose one.
A) rs 1000
B) rs 1515
C) rs 1525
D) rs 1250
E) none of these | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1_232 * (1/10)</gadget>
<output>616/5 = around 123.2</output>
<gadget id="calculator">1_232 - (616/5)</gadget>
<output>5_544/5 = around 1_108.8</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) + 1</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">(5_544/5) / (28/25)</gadget>
<output>990</output>
<result>A</result> | A | 1,000 | The sale price of a trolley bag including the sale tax is Rs. 1232. The rate of sale tax is 10% . If the shopkeeper has made a profit of 12%, the cost price of the trolley bag is: | {
"A": "rs 1000",
"B": "rs 1515",
"C": "rs 1525",
"D": "rs 1250",
"E": "none of these"
} | divide(subtract(1232, multiply(1232, divide(10, const_100))), add(divide(12, const_100), const_1)) | divide(n1,const_100)|divide(n2,const_100)|add(#1,const_1)|multiply(n0,#0)|subtract(n0,#3)|divide(#4,#2)| | "explanation : 110 % of s . p . = 1232 s . p . = rs . ( 1232 x 100 / 110 ) = rs . 1120 . c . p . = rs ( 100 / 112 x 1120 ) = rs 1000 answer : a" | gain |
math_qa__sT3lx4s3wIODvWXA | Rs 4000 is divided into two parts such that one part is put out at 3% and the other at 5%. If the annual interest earned from both the investments be Rs 144, find the first part. Choose the correct choice
A) rs 4000 B) rs 2800 C) rs 3800 D) rs 3500 E) rs 3100 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">4_000 * (1/20)</gadget>
<output>200</output>
<gadget id="calculator">200 - 144</gadget>
<output>56</output>
<gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">(1/20) - (3/100)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">56 / (1/50)</gadget>
<output>2_800</output>
<result>B</result> | B | 2,800 | Rs 4000 is divided into two parts such that one part is put out at 3% and the other at 5%. If the annual interest earned from both the investments be Rs 144, find the first part. | {
"A": "rs 4000",
"B": "rs 2800",
"C": "rs 3800",
"D": "rs 3500",
"E": "rs 3100"
} | divide(subtract(multiply(4000, divide(5, const_100)), 144), subtract(divide(5, const_100), divide(3, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|subtract(#0,#1)|subtract(#2,n3)|divide(#4,#3)| | "explanation : average rate = ( 144 / 4000 ) * 100 = 3.6 ratio = 14 : 6 = 7 : 3 so , first part = ( 7 / 10 ) * 4000 = rs 2800 . answer : b" | gain |
math_qa__ItD1Ke0hTQM98mcM | A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 4.5 km long? Choose the correct choice from the following answers: A) 4 B) 3 C) 5 D) 6 E) 9 | <gadget id="calculator">24 + 1</gadget>
<output>25</output>
<gadget id="calculator">25 * 60</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 / 1_000</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + 4.5</gadget>
<output>6</output>
<result>D</result> | D | 6 | A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 4.5 km long? | {
"A": "4",
"B": "3",
"C": "5",
"D": "6",
"E": "9"
} | add(divide(multiply(add(24, const_1), 60), const_1000), 4.5) | add(n0,const_1)|multiply(n1,#0)|divide(#1,const_1000)|add(n4,#2)| | "d = 25 * 60 + 4500 = 6000 m t = 6000 / 60 * 18 / 5 = 360 sec = 6 mins answer : d" | physics |
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