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math_qa__gjhC7o2fz7e8lZRM
A man can swim in still water at 15 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is? Choose the correct choice from the following answers: A) 3.9 B) 5 C) 5.3 D) 1.5 E) 5.2
<gadget id="calculator">15 / 3</gadget> <output>5</output> <result>B</result>
B
5
A man can swim in still water at 15 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
{ "A": "3.9", "B": "5", "C": "5.3", "D": "1.5", "E": "5.2" }
divide(15, const_3)
divide(n0,const_3)|
"m = 15 s = x ds = 15 + x us = 15 - x 15 + x = ( 15 - x ) 2 15 + x = 30 - 2 x 3 x = 15 x = 5 answer : b"
general
math_qa__vV7nG1vm5iIaALrs
There are 134 toys coloured red and white in a box. Two red toys are removed from the lot and now there are twice as many red ones as white ones. How many of red colour toys are there now? Pick one. A) 76 B) 86 C) 90 D) 88 E) 78
<gadget id="calculator">134 * 2</gadget> <output>268</output> <gadget id="calculator">268 + 2</gadget> <output>270</output> <gadget id="calculator">270 / 3</gadget> <output>90</output> <gadget id="calculator">90 - 2</gadget> <output>88</output> <result>D</result>
D
88
There are 134 toys coloured red and white in a box. Two red toys are removed from the lot and now there are twice as many red ones as white ones. How many of red colour toys are there now?
{ "A": "76", "B": "86", "C": "90", "D": "88", "E": "78" }
subtract(divide(add(multiply(134, const_2), const_2), const_3), const_2)
multiply(n0,const_2)|add(#0,const_2)|divide(#1,const_3)|subtract(#2,const_2)
r + w = 134 two red toys are removed from the lot and now there are twice red ones as white ones r - 2 = 2 w sub 1 st one we get 134 - w - 2 = 2 w 132 = 3 w w = 44 r = 88 actually red will be 90 now 88 answer : d
general
math_qa__ecY8IOuiNdQKPVJY
A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 340 m long platform? Choose the correct option: A) 19 B) 27 C) 29 D) 46 E) 28
<gadget id="calculator">10 / 36</gadget> <output>5/18 = around 0.277778</output> <gadget id="calculator">(5/18) * 36</gadget> <output>10</output> <gadget id="calculator">10 * 12</gadget> <output>120</output> <gadget id="calculator">340 + 120</gadget> <output>460</output> <gadget id="calculator">460 / 10</gadget> <output>46</output> <result>D</result>
D
46
A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 340 m long platform?
{ "A": "19", "B": "27", "C": "29", "D": "46", "E": "28" }
divide(add(340, multiply(multiply(const_0_2778, 36), 12)), multiply(const_0_2778, 36))
multiply(n0,const_0_2778)|multiply(n1,#0)|add(n2,#1)|divide(#2,#0)|
"let the length of the train be x m . when a train crosses an electric pole , the distance covered is its own length . so , x = 12 * 36 * 5 / 18 m = 120 m . time taken to cross the platform = ( 120 + 340 ) / 36 * 5 / 18 = 46 min . answer : d"
physics
math_qa__gLi54lt7q2cBzlEr
A shopkeeper sells 20% of his stock at 20% profit ans sells the remaining at a loss of 10%. He incurred an overall loss of Rs. 500. Find the total worth of the stock? Choose the correct choice. A) 13500 B) 12000 C) 12500 D) 15000 E) 15500
<gadget id="calculator">10 / 100</gadget> <output>1/10 = around 0.1</output> <gadget id="calculator">100 - 20</gadget> <output>80</output> <gadget id="calculator">80 / 100</gadget> <output>4/5 = around 0.8</output> <gadget id="calculator">(1/10) * (4/5)</gadget> <output>2/25 = around 0.08</output> <gadget id="calculator">20 / 100</gadget> <output>1/5 = around 0.2</output> <gadget id="calculator">(1/5) * (1/5)</gadget> <output>1/25 = around 0.04</output> <gadget id="calculator">(2/25) - (1/25)</gadget> <output>1/25 = around 0.04</output> <gadget id="calculator">500 / (1/25)</gadget> <output>12_500</output> <result>C</result>
C
12,500
A shopkeeper sells 20% of his stock at 20% profit ans sells the remaining at a loss of 10%. He incurred an overall loss of Rs. 500. Find the total worth of the stock?
{ "A": "13500", "B": "12000", "C": "12500", "D": "15000", "E": "15500" }
divide(500, subtract(multiply(divide(10, const_100), divide(subtract(const_100, 20), const_100)), multiply(divide(20, const_100), divide(20, const_100))))
divide(n2,const_100)|divide(n1,const_100)|divide(n0,const_100)|subtract(const_100,n0)|divide(#3,const_100)|multiply(#1,#2)|multiply(#0,#4)|subtract(#6,#5)|divide(n3,#7)|
"let the total worth of the stock be rs . x . the sp of 20 % of the stock = 1 / 5 * x * 6 / 5 = 6 x / 25 the sp of 80 % of the stock = 4 / 5 * x * 0.9 = 24 x / 25 total sp = 6 x / 25 + 18 x / 25 = 49 x / 50 overall loss = x - 24 x / 50 = x / 25 x / 25 = 500 = > x = 12500 answer : c"
gain
math_qa__PPOJThYYyddlZmLi
Triangle XYZ is an isosceles right triangle. If side XY is longer than side YZ, and the area of the triangle is 25, what is the measure of side XY? Choices: A) 10 B) 4 √ 2 C) 8 D) 8 √ 2 E) can not be determined from the information provided
<gadget id="calculator">25 ** (1/2)</gadget> <output>5</output> <gadget id="calculator">2 ** (1/2)</gadget> <output>sqrt(2) = around 1.414214</output> <gadget id="calculator">5 * (sqrt(2))</gadget> <output>5*sqrt(2) = around 7.071068</output> <gadget id="calculator">(5*sqrt(2)) ** 2</gadget> <output>50</output> <gadget id="calculator">50 + 50</gadget> <output>100</output> <gadget id="calculator">100 ** (1/2)</gadget> <output>10</output> <result>A</result>
A
10
Triangle XYZ is an isosceles right triangle. If side XY is longer than side YZ, and the area of the triangle is 25, what is the measure of side XY?
{ "A": "10", "B": "4 √ 2", "C": "8", "D": "8 √ 2", "E": "can not be determined from the information provided" }
sqrt(add(power(multiply(sqrt(25), sqrt(const_2)), const_2), power(multiply(sqrt(25), sqrt(const_2)), const_2)))
sqrt(n0)|sqrt(const_2)|multiply(#0,#1)|power(#2,const_2)|add(#3,#3)|sqrt(#4)|
"ans a . . 10 . . xy being larger means it is the hyp . . area = ( 1 / 2 ) * ( yz ) ^ 2 = 25 or yz = 5 * \ sqrt { 2 } . . therefore hyp = xy = 10"
geometry
math_qa__44DtHPqn79xwkMoo
A pharmaceutical company received $2 million in royalties on the first $12; million in sales of generic equivalent of one of its products and then $4 million in royalties on the next $48 million in sales. By approximately what percent did the ratio of royalties to sales decrease from the first $12 million in sales to the next $48 million in sales? Options: A) 20 % B) 25 % C) 30 % D) 50 % E) 55 %
<gadget id="calculator">2 / 12</gadget> <output>1/6 = around 0.166667</output> <gadget id="calculator">4 / 48</gadget> <output>1/12 = around 0.083333</output> <gadget id="calculator">(1/6) - (1/12)</gadget> <output>1/12 = around 0.083333</output> <gadget id="calculator">(1/12) / (1/6)</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">(1/2) * 100</gadget> <output>50</output> <result>D</result>
D
50
A pharmaceutical company received $2 million in royalties on the first $12; million in sales of generic equivalent of one of its products and then $4 million in royalties on the next $48 million in sales. By approximately what percent did the ratio of royalties to sales decrease from the first $12 million in sales to the next $48 million in sales?
{ "A": "20 %", "B": "25 %", "C": "30 %", "D": "50 %", "E": "55 %" }
multiply(divide(subtract(divide(2, 12), divide(4, 48)), divide(2, 12)), const_100)
divide(n0,n1)|divide(n2,n3)|subtract(#0,#1)|divide(#2,#0)|multiply(#3,const_100)
change in ratio of royalties to sales = 2 / 12 - 4 / 48 = 1 / 12 % decrease = ( 1 / 12 ) / ( 2 / 12 ) * 100 = 50 % ( approx ) answer : d )
general
math_qa__U3QxVMc0GwOOYma2
An ore contains 25% of an alloy that has 90% iron. Other than this, in remaining 75% of the ore ,there is no iron. How many kgs of the ore are needed to obtain 60 kg. of pure iron.? Choose one: A) 266.69 B) 266.67 C) 266.66 D) 263.66 E) 266.61
<gadget id="calculator">100 * 60</gadget> <output>6_000</output> <gadget id="calculator">25 * 90</gadget> <output>2_250</output> <gadget id="calculator">2_250 / 100</gadget> <output>45/2 = around 22.5</output> <gadget id="calculator">6_000 / (45/2)</gadget> <output>800/3 = around 266.666667</output> <result>D</result>
D
263.66
An ore contains 25% of an alloy that has 90% iron. Other than this, in remaining 75% of the ore ,there is no iron. How many kgs of the ore are needed to obtain 60 kg. of pure iron.?
{ "A": "266.69", "B": "266.67", "C": "266.66", "D": "263.66", "E": "266.61" }
divide(multiply(const_100, 60), divide(multiply(25, 90), const_100))
multiply(n3,const_100)|multiply(n0,n1)|divide(#1,const_100)|divide(#0,#2)|
"explanation : let us take 100 x kgs of ore . now it contains 25 x kgs of alloy and it contains 90 % ( 25 x ) kgs of iron . 90 % ( 25 x ) = 60 kg ⇒ x = 60 × 10090 × 12560 × 10090 × 125 = 8383 so iron ore required = 100 × 8383 = 266.66 answer : d"
gain
math_qa__TaVmkjeLVDtsUDc8
The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 43 degrees. Find the temperature on Friday? Choices: A) 65 degrees B) 73 degrees C) 37 degrees D) 35 degrees E) 74 degrees
<gadget id="calculator">48 * 4</gadget> <output>192</output> <gadget id="calculator">46 * 4</gadget> <output>184</output> <gadget id="calculator">192 - 184</gadget> <output>8</output> <gadget id="calculator">43 - 8</gadget> <output>35</output> <result>D</result>
D
35
The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 43 degrees. Find the temperature on Friday?
{ "A": "65 degrees", "B": "73 degrees", "C": "37 degrees", "D": "35 degrees", "E": "74 degrees" }
subtract(43, subtract(multiply(48, const_4), multiply(46, const_4)))
multiply(n0,const_4)|multiply(n1,const_4)|subtract(#0,#1)|subtract(n2,#2)
m + tu + w + th = 4 * 48 = 192 tu + w + th + f = 4 * 46 = 184 m = 43 tu + w + th = 192 - 43 = 149 f = 184 – 149 = 35 answer : d
general
math_qa__C2N3Cfk9rNCVQEQN
What is the probability that the sum of two dice will yield a 4, and then when both are thrown again, their sum will again yield a 4? assume that each die has 3 sides with faces numbered 1 to 3. Choose the correct choice from the following answers A) 1 / 144 B) 1 / 36 C) 1 / 9 D) 1 / 6 E) 1 / 3
<gadget id="calculator">3 ** 2</gadget> <output>9</output> <gadget id="calculator">3 / 9</gadget> <output>1/3 = around 0.333333</output> <gadget id="calculator">(1/3) * (1/3)</gadget> <output>1/9 = around 0.111111</output> <result>C</result>
C
0.111111
What is the probability that the sum of two dice will yield a 4, and then when both are thrown again, their sum will again yield a 4? assume that each die has 3 sides with faces numbered 1 to 3.
{ "A": "1 / 144", "B": "1 / 36", "C": "1 / 9", "D": "1 / 6", "E": "1 / 3" }
multiply(divide(3, power(3, const_2)), divide(3, power(3, const_2)))
power(n2,const_2)|divide(n2,#0)|multiply(#1,#1)|
"solution - rolling dices is an independent event . the combinations to get 4 are ( 1,3 ) , ( 3,1 ) , ( 2,2 ) , and total combinations of both dices is 9 . the probability of getting 4 in first attempt is 3 / 9 = 1 / 3 . probability of getting 4 again in second attempt = ( 1 / 3 ) * ( 1 / 3 ) = 1 / 9 . ans c"
probability
math_qa__BsitpV1f2pIvIXpF
Albert father was 48 years of age when she was born while her mother was 46 years old when her brother 2 years younger to her was born. What is the difference between the ages of her parents? Choose the correct choice from the following options A) 2 B) 4 C) 6 D) 8 E) 10
<gadget id="calculator">2 + 3</gadget> <output>5</output> <gadget id="calculator">5 + 4</gadget> <output>9</output> <gadget id="calculator">9 - 5</gadget> <output>4</output> <result>B</result>
B
4
Albert father was 48 years of age when she was born while her mother was 46 years old when her brother 2 years younger to her was born. What is the difference between the ages of her parents?
{ "A": "2", "B": "4", "C": "6", "D": "8", "E": "10" }
subtract(add(add(const_2, const_3), const_4), add(const_2, const_3))
add(const_2,const_3)|add(#0,const_4)|subtract(#1,#0)
mother ' s age when albert ' s brother was born = 46 years father ' s age when albert ' s brother was born = 48 + 2 = 50 years required difference = 50 - 46 = 4 years answer is b
general
math_qa__EC3ZHwy2oKqPyXd7
What was the principal , if at 12% per annum the interest after 3 years amounted to Rs.5888 less than the sum lent? Choose the correct choice from the following choices. A) 9000 B) 3000 C) 5000 D) 1300 E) 9200
<gadget id="calculator">12 * 3</gadget> <output>36</output> <gadget id="calculator">36 / 100</gadget> <output>9/25 = around 0.36</output> <gadget id="calculator">1 - (9/25)</gadget> <output>16/25 = around 0.64</output> <gadget id="calculator">5_888 / (16/25)</gadget> <output>9_200</output> <result>E</result>
E
9,200
What was the principal , if at 12% per annum the interest after 3 years amounted to Rs.5888 less than the sum lent?
{ "A": "9000", "B": "3000", "C": "5000", "D": "1300", "E": "9200" }
divide(5888, subtract(const_1, divide(multiply(12, 3), const_100)))
multiply(n0,n1)|divide(#0,const_100)|subtract(const_1,#1)|divide(n2,#2)
p - 2336 = ( p * 12 * 3 ) / 100 p = 9200 answer : e
gain
math_qa__xr6g6vzKjl1raFwk
On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 14 more transactions than Cal. How much transactions did Jade handled? Choose the correct option: A) 80 B) 81 C) 82 D) 83 E) 84
<gadget id="calculator">90 / 100</gadget> <output>9/10 = around 0.9</output> <gadget id="calculator">10 + 100</gadget> <output>110</output> <gadget id="calculator">(9/10) * 110</gadget> <output>99</output> <gadget id="calculator">99 * 2</gadget> <output>198</output> <gadget id="calculator">198 / 3</gadget> <output>66</output> <gadget id="calculator">66 + 14</gadget> <output>80</output> <result>A</result>
A
80
On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 14 more transactions than Cal. How much transactions did Jade handled?
{ "A": "80", "B": "81", "C": "82", "D": "83", "E": "84" }
add(divide(multiply(multiply(divide(90, const_100), add(10, const_100)), 2), 3), 14)
add(n1,const_100)|divide(n0,const_100)|multiply(#0,#1)|multiply(n2,#2)|divide(#3,n3)|add(n4,#4)|
"solution : mabel handled 90 transactions anthony handled 10 % more transactions than mabel anthony = 90 + 90 × 10 % = 90 + 90 × 0.10 = 90 + 9 = 99 cal handled 2 / 3 rds of the transactions than anthony handled cal = 2 / 3 × 99 = 66 jade handled 14 more transactions than cal . jade = 66 + 14 = 80 jade handled = 80 transactions . answer : a"
general
math_qa__HtPKBHs5qfUOdxre
Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 12 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is? Pick: A) 19 : 2 B) 18 : 3 C) 11 : 1 D) 11 : 5 E) 11 : 4
<gadget id="calculator">62.5 * 12</gadget> <output>750</output> <gadget id="calculator">750 / 100</gadget> <output>15/2 = around 7.5</output> <gadget id="calculator">87.5 * 4</gadget> <output>350</output> <gadget id="calculator">350 / 100</gadget> <output>7/2 = around 3.5</output> <gadget id="calculator">(15/2) + (7/2)</gadget> <output>11</output> <gadget id="calculator">12 - (15/2)</gadget> <output>9/2 = around 4.5</output> <gadget id="calculator">4 - (7/2)</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">(9/2) + (1/2)</gadget> <output>5</output> <gadget id="calculator">11 / 5</gadget> <output>11/5 = around 2.2</output> <result>D</result>
D
2.2
Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 12 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is?
{ "A": "19 : 2", "B": "18 : 3", "C": "11 : 1", "D": "11 : 5", "E": "11 : 4" }
divide(add(divide(multiply(62.5, 12), const_100), divide(multiply(87.5, 4), const_100)), add(subtract(12, divide(multiply(62.5, 12), const_100)), subtract(4, divide(multiply(87.5, 4), const_100))))
multiply(n0,n2)|multiply(n1,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)|subtract(n2,#2)|subtract(n3,#3)|add(#5,#6)|divide(#4,#7)|
"quantity of alcohol in vessel p = 62.5 / 100 * 2 = 15 / 2 litres quantity of alcohol in vessel q = 87.5 / 100 * 4 = 7 / 2 litres quantity of alcohol in the mixture formed = 15 / 2 + 7 / 2 = 11 litres as 16 litres of mixture is formed , ratio of alcohol and water in the mixture formed = 11 : 5 answer : d"
other
math_qa__so1qAmJRdeCVrqpS
On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price R per glass on the second day? Pick. A) $ 015 B) $ 0.20 C) $ 0.30 D) $ 0.40 E) $ 0.45
<gadget id="calculator">1 + 1</gadget> <output>2</output> <gadget id="calculator">2 * 0.6</gadget> <output>1.2</output> <gadget id="calculator">1 + 2</gadget> <output>3</output> <gadget id="calculator">1.2 / 3</gadget> <output>0.4</output> <result>D</result>
D
0.4
On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price R per glass on the second day?
{ "A": "$ 015", "B": "$ 0.20", "C": "$ 0.30", "D": "$ 0.40", "E": "$ 0.45" }
divide(multiply(add(const_1, const_1), 0.60), add(const_1, const_2))
add(const_1,const_1)|add(const_1,const_2)|multiply(n0,#0)|divide(#2,#1)|
"on the first day 1 unit of orange juice and 1 unit of water was used to make 2 units of orangeade ; on the second day 1 unit of orange juice and 2 units of water was used to make 3 units of orangeade ; so , the ratio of the amount of orangeade made on the first day to the amount of orangeade made on the second day is 2 to 3 . naturally the ratio of the # of glasses of orangeade made on the first day to the # of glasses of orangeade made on the second day is 2 to 3 . we are told thatthe revenue from selling the orangeade was the same for both daysso the revenue from 2 glasses on the first day equals to the revenue from 3 glasses on the second day . say the price of the glass of the orangeade on the second day was $ x then 2 * 0.6 = 3 * x - - > x = $ 0.4 . answer : d ."
general
math_qa__bUjUEM4cYmOQJ3ik
Two numbers are in the ratio of 2:3 . if 4 is added in both numbers the ratio becomes 5:7. Find the difference between numbers. Choose the correct choice from the following options: A) 8 B) 6 C) 4 D) 2 E) 10
<gadget id="calculator">7 * 4</gadget> <output>28</output> <gadget id="calculator">5 * 4</gadget> <output>20</output> <gadget id="calculator">28 - 20</gadget> <output>8</output> <gadget id="calculator">8 * 2</gadget> <output>16</output> <gadget id="calculator">3 / 2</gadget> <output>3/2 = around 1.5</output> <gadget id="calculator">16 * (3/2)</gadget> <output>24</output> <gadget id="calculator">24 - 16</gadget> <output>8</output> <result>A</result>
A
8
Two numbers are in the ratio of 2:3 . if 4 is added in both numbers the ratio becomes 5:7. Find the difference between numbers.
{ "A": "8", "B": "6", "C": "4", "D": "2", "E": "10" }
subtract(multiply(multiply(subtract(multiply(7, 4), multiply(5, 4)), 2), divide(3, 2)), multiply(subtract(multiply(7, 4), multiply(5, 4)), 2))
divide(n1,n0)|multiply(n2,n4)|multiply(n2,n3)|subtract(#1,#2)|multiply(n0,#3)|multiply(#0,#4)|subtract(#5,#4)
we ' re told that two numbers are in the ratio of 2 : 3 . thus , the two numbers could be . . . 2 and 3 4 and 6 6 and 9 8 and 12 10 and 15 etc . we ' re told that adding 4 to each number changes the ratio of the numbers to 5 : 7 . we ' re asked for the difference between the original numbers . since adding 4 makes the first number a multiple of 5 , this limits the possibilities . . . . 2 + 4 = 6 not possible 4 + 4 = 8 not possible 6 + 4 = 10 this is possible . . . using this example , we would have . . . 6 and 9 , after adding 4 to each , becomes 10 and 13 . . . this is not a ratio of 5 to 7 though ( even though it ' s pretty close ) , so we have to keep looking . . . . the next value that becomes a multiple of 5 when you add 4 to it is . . . 16 . . . 16 + 4 = 20 with 16 and 24 , after adding 4 to each , we have 20 and 28 . this is a ratio of 5 to 7 , so we have our pair of original numbers . the difference between them is 8 . final answer : a
other
math_qa__z2hULQESrOlOySWw
After successive discounts of 20%, 10% and 5% a certain good is sold for Rs. 6600. Find the actual price of the good. Choose the correct choice from the following answers: A) s . 6000 B) s . 9000 C) s . 10800 D) s . 9649 E) s . 9980
<gadget id="calculator">6_600 * 100</gadget> <output>660_000</output> <gadget id="calculator">100 - 20</gadget> <output>80</output> <gadget id="calculator">80 * 10</gadget> <output>800</output> <gadget id="calculator">800 / 100</gadget> <output>8</output> <gadget id="calculator">80 - 8</gadget> <output>72</output> <gadget id="calculator">72 * 5</gadget> <output>360</output> <gadget id="calculator">360 / 100</gadget> <output>18/5 = around 3.6</output> <gadget id="calculator">72 - (18/5)</gadget> <output>342/5 = around 68.4</output> <gadget id="calculator">660_000 / (342/5)</gadget> <output>550_000/57 = around 9_649.122807</output> <result>D</result>
D
9,649
After successive discounts of 20%, 10% and 5% a certain good is sold for Rs. 6600. Find the actual price of the good.
{ "A": "s . 6000", "B": "s . 9000", "C": "s . 10800", "D": "s . 9649", "E": "s . 9980" }
divide(multiply(6600, const_100), subtract(subtract(subtract(const_100, 20), divide(multiply(subtract(const_100, 20), 10), const_100)), divide(multiply(subtract(subtract(const_100, 20), divide(multiply(subtract(const_100, 20), 10), const_100)), 5), const_100)))
multiply(n3,const_100)|subtract(const_100,n0)|multiply(n1,#1)|divide(#2,const_100)|subtract(#1,#3)|multiply(n2,#4)|divide(#5,const_100)|subtract(#4,#6)|divide(#0,#7)|
"let actual price was 100 . after three successive discount this will become , 100 = = 20 % discount = > 80 = = 10 % discount = > 72 = = 5 % discount = 68.4 now compare , 68.4 = 6600 1 = 6600 / 68.4 100 = ( 6600 * 100 ) / 68.4 = rs . 9649 . answer : option d"
gain
math_qa__YOG2770qn3jRT201
In a certain accounting class of 100 students, 70% of the students took the final exam on the assigned day while the rest of the students took the exam on a make-up date. If the students on the assigned day had an average score of 55%, and the students on the make-up date had an average score of 95%, what was the average score for the entire class? Choose the correct choice from the following: A) 60 % B) 65 % C) 67 % D) 70 % E) 75 %
<gadget id="calculator">70 * 55</gadget> <output>3_850</output> <gadget id="calculator">100 - 70</gadget> <output>30</output> <gadget id="calculator">95 * 30</gadget> <output>2_850</output> <gadget id="calculator">3_850 + 2_850</gadget> <output>6_700</output> <gadget id="calculator">6_700 / 100</gadget> <output>67</output> <result>C</result>
C
67
In a certain accounting class of 100 students, 70% of the students took the final exam on the assigned day while the rest of the students took the exam on a make-up date. If the students on the assigned day had an average score of 55%, and the students on the make-up date had an average score of 95%, what was the average score for the entire class?
{ "A": "60 %", "B": "65 %", "C": "67 %", "D": "70 %", "E": "75 %" }
divide(add(multiply(70, 55), multiply(95, subtract(100, 70))), 100)
multiply(n1,n2)|subtract(n0,n1)|multiply(n3,#1)|add(#0,#2)|divide(#3,n0)|
"70 % of the class scored 55 % and 30 % of the class scored 95 % . the difference between 55 % and 95 % is 40 % . the average will be 55 % + 0.3 ( 40 % ) = 67 % . the answer is c ."
general
math_qa__EsDGV0zavSFegCG9
The length of the bridge, which a train 110 meters long and travelling at 45 km/hr can cross in 30 seconds, is? Choose the correct choice from the following answers: A) 265 B) 288 C) 245 D) 776 E) 232
<gadget id="calculator">1_000 / 1</gadget> <output>1_000</output> <gadget id="calculator">45 * 1_000</gadget> <output>45_000</output> <gadget id="calculator">3_600 / 1</gadget> <output>3_600</output> <gadget id="calculator">45_000 / 3_600</gadget> <output>25/2 = around 12.5</output> <gadget id="calculator">(25/2) * 30</gadget> <output>375</output> <gadget id="calculator">375 - 110</gadget> <output>265</output> <result>A</result>
A
265
The length of the bridge, which a train 110 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
{ "A": "265", "B": "288", "C": "245", "D": "776", "E": "232" }
subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 110)
speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)
speed = ( 45 * 5 / 18 ) m / sec = ( 25 / 2 ) m / sec . time = 30 sec . let the length of bridge be x meters . then , ( 110 + x ) / 30 = 25 / 2 = = > 2 ( 110 + x ) = 750 = = > x = 265 m . answer : a
physics
math_qa__Yg7Zrxbkz3QPQWKN
Excluding stoppages, the speed of a bus is 64 kmph and including stoppages, it is 50 kmph. For how many minutes does the bus stop per hour? Choose one. A) 15.5 B) 12.3 C) 10.5 D) 10.12 E) 13.12
<gadget id="calculator">64 - 50</gadget> <output>14</output> <gadget id="calculator">14 / 64</gadget> <output>7/32 = around 0.21875</output> <gadget id="calculator">60 * (7/32)</gadget> <output>105/8 = around 13.125</output> <result>E</result>
E
13.12
Excluding stoppages, the speed of a bus is 64 kmph and including stoppages, it is 50 kmph. For how many minutes does the bus stop per hour?
{ "A": "15.5", "B": "12.3", "C": "10.5", "D": "10.12", "E": "13.12" }
multiply(const_60, divide(subtract(64, 50), 64))
subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_60)|
"due to stoppages , it covers 14 km less . time taken to cover 14 km = ( ( 14 / 64 ) ã — 60 ) = 13.12 min . option ( e ) is correct"
physics
math_qa__3Boxsg852987adUw
A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it? Answers. A) 8 hours B) 10 hours C) 12 hours D) 24 hours E) none of the above
<gadget id="calculator">1 / 3</gadget> <output>1/3 = around 0.333333</output> <gadget id="calculator">1 / 2</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">1 / 4</gadget> <output>1/4 = around 0.25</output> <gadget id="calculator">(1/2) - (1/4)</gadget> <output>1/4 = around 0.25</output> <gadget id="calculator">(1/3) - (1/4)</gadget> <output>1/12 = around 0.083333</output> <gadget id="calculator">1 / (1/12)</gadget> <output>12</output> <result>C</result>
C
12
A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?
{ "A": "8 hours", "B": "10 hours", "C": "12 hours", "D": "24 hours", "E": "none of the above" }
divide(const_1, subtract(divide(const_1, 3), subtract(divide(const_1, 2), divide(const_1, 4))))
divide(const_1,n1)|divide(const_1,n2)|divide(const_1,n0)|subtract(#1,#2)|subtract(#0,#3)|divide(const_1,#4)|
"a ' s 1 hour ' s work = 1 / 4 ; ( b + c ) ' s 1 hour ' s work = 1 / 3 ; ( b + c ) ' s 1 hour ' s work = 1 / 2 ( a + b + c ) ' s 1 hour ' s work = ( 1 / 4 + 1 / 3 ) = 7 / 12 b ' s 1 hour ' s work = ( 7 / 12 - 1 / 2 ) = 1 / 12 b alone will take 12 hours to do the work . answer = c"
physics
math_qa__yu4vBTS59XfVXTU7
The moon revolves around the earth at a speed of approximately 1.02 kilometers per second. This approximate speed is how many kilometers per hour? Choose the correct choice from the following choices. A) 60 B) 61.2 C) 62.5 D) 3,600 E) 3,672
<gadget id="calculator">1.02 * 3_600</gadget> <output>3_672</output> <result>E</result>
E
3,672
The moon revolves around the earth at a speed of approximately 1.02 kilometers per second. This approximate speed is how many kilometers per hour?
{ "A": "60", "B": "61.2", "C": "62.5", "D": "3,600", "E": "3,672" }
multiply(1.02, const_3600)
multiply(n0,const_3600)|
"moon revolves around the earth at a speed of 1.02 kilometers per second . one hour equal to 60 minutes . one minute equals to 60 seconds . so one hour equals to 3600 seconds . so one hour , speed = 1.02 * 3600 = 3672 kilometers per hour . option e is correct"
physics
math_qa__vWeJV1mskUpjUgxZ
The ratio of football players, baseball players, soccer players, and basketball players in a school is 10:7:5:4. How many athletes are in the school if 16 players are on the basketball team? Choose the correct choice from the following answers A) 40 B) 92 C) 104 D) 208 E) 80
<gadget id="calculator">5 * 16</gadget> <output>80</output> <gadget id="calculator">80 / 4</gadget> <output>20</output> <gadget id="calculator">20 + 16</gadget> <output>36</output> <gadget id="calculator">7 * 16</gadget> <output>112</output> <gadget id="calculator">112 / 4</gadget> <output>28</output> <gadget id="calculator">36 + 28</gadget> <output>64</output> <gadget id="calculator">10 * 16</gadget> <output>160</output> <gadget id="calculator">160 / 4</gadget> <output>40</output> <gadget id="calculator">64 + 40</gadget> <output>104</output> <result>C</result>
C
104
The ratio of football players, baseball players, soccer players, and basketball players in a school is 10:7:5:4. How many athletes are in the school if 16 players are on the basketball team?
{ "A": "40", "B": "92", "C": "104", "D": "208", "E": "80" }
add(add(add(divide(multiply(5, 16), 4), 16), divide(multiply(7, 16), 4)), divide(multiply(10, 16), 4))
multiply(n2,n4)|multiply(n1,n4)|multiply(n0,n4)|divide(#0,n3)|divide(#1,n3)|divide(#2,n3)|add(n4,#3)|add(#6,#4)|add(#7,#5)
the ratio is 10 football players : 7 baseball players : 5 soccer players : 4 basketball players . divide 16 by 4 to find 1 ` ` part ' ' of the ratio . 16 / 4 = 4 multiply 4 by 5 to find the number of soccer players . 4 * 5 = 20 multiply 4 by 7 to find the number of baseball players . 4 * 7 = 28 multiply 4 by 10 to find the number of football players . 4 * 10 = 40 . add them all up to find total athletes . 16 + 20 + 28 + 40 = 104 the answer is c .
other
math_qa__wQiMokqDFRSJeYxB
40% of a number is more than 20% of 650 by 190. Find the number? Choose the correct choice from the following answers: A) 299 B) 277 C) 800 D) 289 E) 271
<gadget id="calculator">650 * 20</gadget> <output>13_000</output> <gadget id="calculator">13_000 / 100</gadget> <output>130</output> <gadget id="calculator">130 + 190</gadget> <output>320</output> <gadget id="calculator">320 * 100</gadget> <output>32_000</output> <gadget id="calculator">32_000 / 40</gadget> <output>800</output> <result>C</result>
C
800
40% of a number is more than 20% of 650 by 190. Find the number?
{ "A": "299", "B": "277", "C": "800", "D": "289", "E": "271" }
divide(multiply(add(divide(multiply(650, 20), const_100), 190), const_100), 40)
multiply(n1,n2)|divide(#0,const_100)|add(n3,#1)|multiply(#2,const_100)|divide(#3,n0)|
"( 40 / 100 ) * x – ( 20 / 100 ) * 650 = 190 2 / 5 x = 320 x = 800 answer : c"
gain
math_qa__s7YXLaXZ3Bc6B2fC
What is the sum of the digits of integer k, if k = (10^30- 36) Choices. A) 251 B) 260 C) 263 D) 269 E) 262
<gadget id="calculator">10 - 1</gadget> <output>9</output> <gadget id="calculator">30 - 2</gadget> <output>28</output> <gadget id="calculator">9 * 28</gadget> <output>252</output> <gadget id="calculator">252 + 10</gadget> <output>262</output> <result>E</result>
E
262
What is the sum of the digits of integer k, if k = (10^30- 36)
{ "A": "251", "B": "260", "C": "263", "D": "269", "E": "262" }
add(multiply(subtract(10, const_1), subtract(30, const_2)), const_10)
subtract(n0,const_1)|subtract(n1,const_2)|multiply(#0,#1)|add(#2,const_10)
there are 31 digits in 10 ^ 30 when we subtract 36 from it , there will be 30 digits left . 10 ^ 30 can be written as 9999999 . . . . ( 30 times ) + 1 so , 10 ^ 30 - 36 = 9999999 . . . . ( 30 times ) + 1 - 36 = 9999999 . . . . ( 30 times ) - 35 consider the last 2 digits , 99 - 35 = 64 the last 2 digits will be 64 . and our number would be 99999 . . . . . . 99964 with 2 less 9 s after subtraction . number of 9 s left are 28 and the last two digits are 64 the sum of the digits will be ( 28 * 9 ) + 6 + 4 = 262 answer : - e
general
math_qa__NFlQcEdFMNJLjvPc
If a#b = ab – b + b^2, then 3#7 = Choose the correct choice from the following choices: A) 2 B) 63 C) 15 D) 21 E) 35
<gadget id="calculator">3 * 7</gadget> <output>21</output> <gadget id="calculator">21 - 7</gadget> <output>14</output> <gadget id="calculator">7 ** 2</gadget> <output>49</output> <gadget id="calculator">14 + 49</gadget> <output>63</output> <result>B</result>
B
63
If a#b = ab – b + b^2, then 3#7 =
{ "A": "2", "B": "63", "C": "15", "D": "21", "E": "35" }
add(subtract(multiply(3, 7), 7), power(7, const_2))
multiply(n1,n2)|power(n2,const_2)|subtract(#0,n2)|add(#1,#2)
solution - simply substitute 3 and 7 in equation in the place of a and b respectively . 3 # 7 = 3 * 7 - 7 + 7 ^ 2 = 21 - 7 + 49 = 63 . ans b
general
math_qa__wOpXlmOxSlIMaWQH
A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average(arithmetic mean) of the other 20 numbers in the list, then n is what fraction W of the sum of the 21 numbers in the list? Choose the most appropriate option: A) 1 / 20 B) 1 / 6 C) 1 / 5 D) 4 / 21 E) 5 / 21
<gadget id="calculator">1 * 1</gadget> <output>1</output> <gadget id="calculator">20 / 4</gadget> <output>5</output> <gadget id="calculator">5 + 21</gadget> <output>26</output> <gadget id="calculator">26 / 4</gadget> <output>13/2 = around 6.5</output> <gadget id="calculator">(13/2) * 2</gadget> <output>13</output> <gadget id="calculator">13 - 4</gadget> <output>9</output> <gadget id="calculator">9 - 3</gadget> <output>6</output> <gadget id="calculator">1 / 6</gadget> <output>1/6 = around 0.166667</output> <result>B</result>
B
0.166667
A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average(arithmetic mean) of the other 20 numbers in the list, then n is what fraction W of the sum of the 21 numbers in the list?
{ "A": "1 / 20", "B": "1 / 6", "C": "1 / 5", "D": "4 / 21", "E": "5 / 21" }
divide(multiply(const_1, const_1), subtract(subtract(multiply(divide(add(divide(20, 4), 21), 4), const_2), 4), const_3))
divide(n2,n1)|multiply(const_1,const_1)|add(n0,#0)|divide(#2,n1)|multiply(#3,const_2)|subtract(#4,n1)|subtract(#5,const_3)|divide(#1,#6)|
"this is how i used to calculate which i think works pretty well : if you let the average of the 20 other numbers equal a , can you write this equation for sum of the list ( s ) n + 20 a = s the question tells us that n = 4 a plug this back into the first equation and you get that the sum is 24 a 4 a + 20 a = 24 a therefore fraction w of n to the total would be 4 a / 24 a or 1 / 6 answer b"
general
math_qa__0KLHPwxDYaB3gkDq
Jerry went to a shop and bought things worth Rs. 40, out of which 30 % went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items? Answers: A) 19 B) 19.7 C) 21.3 D) 31.5 E) 34.7
<gadget id="calculator">30 / 100</gadget> <output>3/10 = around 0.3</output> <gadget id="calculator">100 / 6</gadget> <output>50/3 = around 16.666667</output> <gadget id="calculator">(3/10) * (50/3)</gadget> <output>5</output> <gadget id="calculator">5 + (3/10)</gadget> <output>53/10 = around 5.3</output> <gadget id="calculator">40 - (53/10)</gadget> <output>347/10 = around 34.7</output> <result>E</result>
E
34.7
Jerry went to a shop and bought things worth Rs. 40, out of which 30 % went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
{ "A": "19", "B": "19.7", "C": "21.3", "D": "31.5", "E": "34.7" }
subtract(40, add(multiply(divide(30, const_100), divide(const_100, 6)), divide(30, const_100)))
divide(n1,const_100)|divide(const_100,n2)|multiply(#0,#1)|add(#0,#2)|subtract(n0,#3)|
"total cost of the items he purchased = rs . 40 given that out of this rs . 40 , 30 % is given as tax = > total tax incurred = 30 % = rs . 30 / 100 let the cost of the tax free items = x given that tax rate = 6 % ∴ ( 40 − 30 / 100 − x ) 6 / 100 = 30 / 100 ⇒ 6 ( 40 − 0.3 − x ) = 30 ⇒ ( 40 − 0.3 − x ) = 5 ⇒ x = 40 − 0.3 − 5 = 34.7 e )"
gain
math_qa__86dEFJn46qrMmcJP
A no.when divided by 142 gives a remainder 110, what remainder will be obtainedby dividingthe same no.14? Options A) 16 B) 17 C) 18 D) 19 E) 20
<gadget id="calculator">142 + 110</gadget> <output>252</output> <gadget id="calculator">252 / 14</gadget> <output>18</output> <result>C</result>
C
18
A no.when divided by 142 gives a remainder 110, what remainder will be obtainedby dividingthe same no.14?
{ "A": "16", "B": "17", "C": "18", "D": "19", "E": "20" }
divide(add(142, 110), 14)
add(n0,n1)|divide(#0,n2)
142 + 110 = 252 / 14 = 18 ( remainder ) c
general
math_qa__9ExRTPZPGKCzCqiC
One pipe can fill a tank four times as fast as another pipe. If together the two pipes can fill the tank in 40 minutes, then the slower pipe alone will be able to fill the tank in? Choose the correct choice from the following choices. A) 100 min B) 150 min C) 200 min D) 250 min E) 300 min
<gadget id="calculator">1 + 4</gadget> <output>5</output> <gadget id="calculator">5 * 40</gadget> <output>200</output> <result>C</result>
C
200
One pipe can fill a tank four times as fast as another pipe. If together the two pipes can fill the tank in 40 minutes, then the slower pipe alone will be able to fill the tank in?
{ "A": "100 min", "B": "150 min", "C": "200 min", "D": "250 min", "E": "300 min" }
multiply(add(const_1, const_4), 40)
add(const_1,const_4)|multiply(n0,#0)|
"let the slower pipe alone fill the tank in x minutes then , faster pipe will fill it in x / 4 minutes 1 / x + 4 / x = 1 / 40 5 / x = 1 / 40 x = 200 min answer is c"
physics
math_qa__X2RtAl9VhfJVk4vw
A scale 6 ft. 8 inches long is divided into 5 equal parts. Find the length of each part. Choose the most appropriate option: A) 20 inches B) 77 inches C) 16 inches D) 97 inches E) 66 inches
<gadget id="calculator">6 * 12</gadget> <output>72</output> <gadget id="calculator">72 + 8</gadget> <output>80</output> <gadget id="calculator">80 / 5</gadget> <output>16</output> <result>C</result>
C
16
A scale 6 ft. 8 inches long is divided into 5 equal parts. Find the length of each part.
{ "A": "20 inches", "B": "77 inches", "C": "16 inches", "D": "97 inches", "E": "66 inches" }
divide(add(multiply(6, const_12), 8), 5)
multiply(n0,const_12)|add(n1,#0)|divide(#1,n2)|
"explanation : total length of scale in inches = ( 6 * 12 ) + 8 = 80 inches length of each of the 5 parts = 80 / 5 = 16 inches answer : c"
general
math_qa__F8RXjSeZoywHhKEh
The area of rhombus is 150 cm square. The length of one of the its diagonals is 10 cm. The length of the other diagonal is: Choose the correct answer A) 15 cm B) 20 cm C) 25 cm D) 30 cm E) none of these
<gadget id="calculator">150 * 2</gadget> <output>300</output> <gadget id="calculator">300 / 10</gadget> <output>30</output> <result>D</result>
D
30
The area of rhombus is 150 cm square. The length of one of the its diagonals is 10 cm. The length of the other diagonal is:
{ "A": "15 cm", "B": "20 cm", "C": "25 cm", "D": "30 cm", "E": "none of these" }
divide(multiply(150, const_2), 10)
multiply(n0,const_2)|divide(#0,n1)
explanation : we know the product of diagonals is 1 / 2 * ( product of diagonals ) let one diagonal be d 1 and d 2 so as per question 1 / 2 ∗ d 1 ∗ d 2 = 150 1 / 2 ∗ 10 ∗ d 2 = 150 d 2 = 150 / 5 = 30 option d
geometry
math_qa__h38aMoaqsbv4Btn5
Machine A can finish a job in 4 hours, Machine В can finish the job in 3 hours, and Machine С can finish the job in 6 hours. How many hours will it take for A, B, and С together to finish the job? Pick: A) 3 / 2 B) 4 / 3 C) 5 / 4 D) 6 / 5 E) 8 / 7
<gadget id="calculator">1 / 4</gadget> <output>1/4 = around 0.25</output> <gadget id="calculator">1 / 3</gadget> <output>1/3 = around 0.333333</output> <gadget id="calculator">(1/4) + (1/3)</gadget> <output>7/12 = around 0.583333</output> <gadget id="calculator">1 / 6</gadget> <output>1/6 = around 0.166667</output> <gadget id="calculator">(7/12) + (1/6)</gadget> <output>3/4 = around 0.75</output> <gadget id="calculator">1 / (3/4)</gadget> <output>4/3 = around 1.333333</output> <result>B</result>
B
1.333333
Machine A can finish a job in 4 hours, Machine В can finish the job in 3 hours, and Machine С can finish the job in 6 hours. How many hours will it take for A, B, and С together to finish the job?
{ "A": "3 / 2", "B": "4 / 3", "C": "5 / 4", "D": "6 / 5", "E": "8 / 7" }
inverse(add(add(inverse(4), inverse(3)), inverse(6)))
inverse(n0)|inverse(n1)|inverse(n2)|add(#0,#1)|add(#3,#2)|inverse(#4)|
"the combined rate is 1 / 4 + 1 / 3 + 1 / 6 = 9 / 12 of the job per hour . the time to complete the job is 12 / 9 = 4 / 3 hours . the answer is b ."
physics
math_qa__zz1CVx8OeNNkZbrQ
If 10 litres of an oil of Rs.55 per litres be mixed with 5 litres of another oil of Rs.66 per litre then what is the rate of mixed oil per litre? Choose the correct choice from the following answers: A) rs . 49.17 B) rs . 51.03 C) rs . 58.66 D) rs . 55.33 E) none of the above
<gadget id="calculator">10 * 55</gadget> <output>550</output> <gadget id="calculator">5 * 66</gadget> <output>330</output> <gadget id="calculator">550 + 330</gadget> <output>880</output> <gadget id="calculator">10 + 5</gadget> <output>15</output> <gadget id="calculator">880 / 15</gadget> <output>176/3 = around 58.666667</output> <result>C</result>
C
58.66
If 10 litres of an oil of Rs.55 per litres be mixed with 5 litres of another oil of Rs.66 per litre then what is the rate of mixed oil per litre?
{ "A": "rs . 49.17", "B": "rs . 51.03", "C": "rs . 58.66", "D": "rs . 55.33", "E": "none of the above" }
divide(add(multiply(10, 55), multiply(5, 66)), add(10, 5))
add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)
55 * 10 = 550 66 * 5 = 330 880 / 15 = 58.66 answer : c
gain
math_qa__wbkZaJTwKy8EQwCR
After spending Rs. 5000 on rent, Rs. 1500 on milk, Rs. 4500 on groceries, Rs.2500 On childrens education Rs. 2000 on petrol and Rs. 700 on miscellaneous expenses, Mr. Kishore saved 10% of his monthly salary. How much did he save in Rs. ? Choose the correct option: A) 2160 B) 2350 C) 2000 D) 2300 E) 1800
<gadget id="calculator">5_000 + 1_500</gadget> <output>6_500</output> <gadget id="calculator">6_500 + 4_500</gadget> <output>11_000</output> <gadget id="calculator">11_000 + 2_500</gadget> <output>13_500</output> <gadget id="calculator">13_500 + 2_000</gadget> <output>15_500</output> <gadget id="calculator">15_500 + 700</gadget> <output>16_200</output> <gadget id="calculator">16_200 * 100</gadget> <output>1_620_000</output> <gadget id="calculator">100 - 10</gadget> <output>90</output> <gadget id="calculator">1_620_000 / 90</gadget> <output>18_000</output> <gadget id="calculator">18_000 - 16_200</gadget> <output>1_800</output> <result>E</result>
E
1,800
After spending Rs. 5000 on rent, Rs. 1500 on milk, Rs. 4500 on groceries, Rs.2500 On childrens education Rs. 2000 on petrol and Rs. 700 on miscellaneous expenses, Mr. Kishore saved 10% of his monthly salary. How much did he save in Rs. ?
{ "A": "2160", "B": "2350", "C": "2000", "D": "2300", "E": "1800" }
subtract(divide(multiply(add(add(add(add(add(5000, 1500), 4500), 2500), 2000), 700), const_100), subtract(const_100, 10)), add(add(add(add(add(5000, 1500), 4500), 2500), 2000), 700))
add(n0,n1)|subtract(const_100,n6)|add(n2,#0)|add(n3,#2)|add(n4,#3)|add(n5,#4)|multiply(#5,const_100)|divide(#6,#1)|subtract(#7,#5)|
"explanation : total exp = 5000 + 1500 + 4500 + 2500 + 2000 + 700 = 16200 exp in % = 100 - 10 = 90 % , 16200 = 90 % saving = 10 % = 16200 x 10 / 90 = rs . 1800 answer : e"
general
math_qa__BSS2u66ZE0gNRqna
If the radius of a circle decreased by 50% its area is decreased by: Choose the correct choice: A) 75 B) 79 C) 72 D) 70 E) 80
<gadget id="calculator">50 / 100</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">(1/2) ** 2</gadget> <output>1/4 = around 0.25</output> <gadget id="calculator">(1/4) * 100</gadget> <output>25</output> <gadget id="calculator">100 - 25</gadget> <output>75</output> <result>A</result>
A
75
If the radius of a circle decreased by 50% its area is decreased by:
{ "A": "75", "B": "79", "C": "72", "D": "70", "E": "80" }
subtract(const_100, multiply(power(divide(50, const_100), const_2), const_100))
divide(n0,const_100)|power(#0,const_2)|multiply(#1,const_100)|subtract(const_100,#2)
original area = π r ( power ) 2 new area = π ( r / 2 ) ( power ) 2 = ( π r ( power ) 2 ) / 4 reduction in area = [ ( π r ( power ) 2 - ( π r ( power ) 2 ) / 4 ] 2 = ( 3 π r ( power ) 2 ) / 4 reduction percent = ( ( 3 π r ( power ) 2 ) / 4 × 1 / ( π r ( power ) 2 × 100 ) % = 75 % answer is a .
geometry
math_qa__hppWNBayKzPF2GTm
When 2/9 of the votes on a certain resolution have been counted, 3/4 of those counted are in favor of the resolution. What fraction e of the remaining votes must be against the resolution so that the total count will result in a vote of 2 to 1 against the resolution? Choose the correct option: A) 11 / 14 B) 13 / 18 C) 4 / 7 D) 3 / 7 E) 3 / 14
<gadget id="calculator">1 + 2</gadget> <output>3</output> <gadget id="calculator">2 / 3</gadget> <output>2/3 = around 0.666667</output> <gadget id="calculator">2 / 9</gadget> <output>2/9 = around 0.222222</output> <gadget id="calculator">3 / 4</gadget> <output>3/4 = around 0.75</output> <gadget id="calculator">(2/9) * (3/4)</gadget> <output>1/6 = around 0.166667</output> <gadget id="calculator">(2/9) - (1/6)</gadget> <output>1/18 = around 0.055556</output> <gadget id="calculator">(2/3) - (1/18)</gadget> <output>11/18 = around 0.611111</output> <gadget id="calculator">9 - 2</gadget> <output>7</output> <gadget id="calculator">7 / 9</gadget> <output>7/9 = around 0.777778</output> <gadget id="calculator">(11/18) / (7/9)</gadget> <output>11/14 = around 0.785714</output> <result>A</result>
A
0.785714
When 2/9 of the votes on a certain resolution have been counted, 3/4 of those counted are in favor of the resolution. What fraction e of the remaining votes must be against the resolution so that the total count will result in a vote of 2 to 1 against the resolution?
{ "A": "11 / 14", "B": "13 / 18", "C": "4 / 7", "D": "3 / 7", "E": "3 / 14" }
divide(subtract(divide(2, add(1, 2)), subtract(divide(2, 9), multiply(divide(2, 9), divide(3, 4)))), divide(subtract(9, 2), 9))
add(n0,n5)|divide(n0,n1)|divide(n2,n3)|subtract(n1,n0)|divide(n0,#0)|divide(#3,n1)|multiply(#1,#2)|subtract(#1,#6)|subtract(#4,#7)|divide(#8,#5)
if we use variable for total votes there will be too many fractions to manipulate with , so pick some smart # : let set total # of votes is 18 . 2 / 9 of the votes on a certain resolution have been counted - - > 4 counted and 18 - 4 = 14 votes left to be counted ; 3 / 4 of those counted are in favor of the resolution - - > 3 in favor and 1 against ; ratio of those who voted against to those who voted for to be 2 to 1 there should be total of 18 * 2 / 3 = 12 people who voted against , so in the remaining 14 votes there should be 12 - 1 = 11 people who voted against . thus e = 11 / 14 of the remaining votes must be against . answer : a .
general
math_qa__sy97M7wa7eIQw7eC
If a large pizza has a radius that is 50% larger that that of a medium pizza, what is the percent increase in area between a medium and a large pizza? Select the correct option. A) 25 % B) 50 % C) 75 % D) 125 % E) 150 %
<gadget id="calculator">50 / 100</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">1 + (1/2)</gadget> <output>3/2 = around 1.5</output> <gadget id="calculator">(3/2) ** 2</gadget> <output>9/4 = around 2.25</output> <gadget id="calculator">(9/4) - 1</gadget> <output>5/4 = around 1.25</output> <gadget id="calculator">(5/4) * 100</gadget> <output>125</output> <result>D</result>
D
125
If a large pizza has a radius that is 50% larger that that of a medium pizza, what is the percent increase in area between a medium and a large pizza?
{ "A": "25 %", "B": "50 %", "C": "75 %", "D": "125 %", "E": "150 %" }
multiply(subtract(power(add(const_1, divide(50, const_100)), const_2), const_1), const_100)
divide(n0,const_100)|add(#0,const_1)|power(#1,const_2)|subtract(#2,const_1)|multiply(#3,const_100)|
"let the radius of medium pizza be r . then the radius of large pizza is 1.5 r . the area of the medium pizza is pi * r ^ 2 the area of the large pizza is pi * ( 1.5 * r ) ^ 2 = 2.25 * pi * r ^ 2 , an increase of 125 % . the answer is d ."
gain
math_qa__KFyt8KjbqVtGlOJl
If it takes 10 kids 6 hours to wear out their teacher, how long would it take 15 kids? Choose the correct choice from the following choices. A) 5 hours B) 4 hours C) 3 hours D) 2 hours E) 1 hour
<gadget id="calculator">10 * 6</gadget> <output>60</output> <gadget id="calculator">60 / 15</gadget> <output>4</output> <result>B</result>
B
4
If it takes 10 kids 6 hours to wear out their teacher, how long would it take 15 kids?
{ "A": "5 hours", "B": "4 hours", "C": "3 hours", "D": "2 hours", "E": "1 hour" }
divide(multiply(10, 6), 15)
multiply(n0,n1)|divide(#0,n2)
10 * 6 = 15 * x x = 4 answer : b
physics
math_qa__kMeTatx25dWuBb5p
The mass of 1 cubic meter of a substance is 500 kg under certain conditions. What is the volume in cubic centimeters of 1 gram of this substance under these conditions? (1 kg =1,000 grams and 1 cubic meter = 1,000,000 cubic centimeters) Pick one A) 0.1 B) 0 C) 1 D) 2 E) 3
<gadget id="calculator">1_000 * 1_000</gadget> <output>1_000_000</output> <gadget id="calculator">500 * 1_000</gadget> <output>500_000</output> <gadget id="calculator">1_000_000 / 500_000</gadget> <output>2</output> <result>D</result>
D
2
The mass of 1 cubic meter of a substance is 500 kg under certain conditions. What is the volume in cubic centimeters of 1 gram of this substance under these conditions? (1 kg =1,000 grams and 1 cubic meter = 1,000,000 cubic centimeters)
{ "A": "0.1", "B": "0", "C": "1", "D": "2", "E": "3" }
divide(multiply(1,000, 1,000), multiply(500, 1,000))
multiply(n4,n4)|multiply(n1,n4)|divide(#0,#1)|
"500 kg - 1 cubic meter ; 500,000 g - 1 cubic meter ; 500,000 g - 1 , 000,000 cubic centimeters ; 1 g - 1 , 000,000 / 500,000 = 10 / 5 = 2 cubic centimeters . answer : d ."
geometry
math_qa__3VJLQes0YPYnp6BY
John found that the average of 15 numbers is 40. If 13 is added to each number then the mean of number is? Answers: A) 53 B) 45 C) 65 D) 78 E) 64
<gadget id="calculator">40 + 13</gadget> <output>53</output> <result>A</result>
A
53
John found that the average of 15 numbers is 40. If 13 is added to each number then the mean of number is?
{ "A": "53", "B": "45", "C": "65", "D": "78", "E": "64" }
add(40, 13)
add(n1,n2)|
"( x + x 1 + . . . x 14 ) / 15 = 40 53 option a"
general
math_qa__XgeGms4XkXfjVKnV
A straight line in the xy- plane has y-intercept of 10 . On this line the x-coordinate of the point is 100 and y-coordinate is 1000 then what is the slope of the line? Choose the correct answer A) 2 B) 5.5 C) 6.5 D) 3.2 E) 9.9
<gadget id="calculator">1_000 - 10</gadget> <output>990</output> <gadget id="calculator">990 / 100</gadget> <output>99/10 = around 9.9</output> <result>E</result>
E
9.9
A straight line in the xy- plane has y-intercept of 10 . On this line the x-coordinate of the point is 100 and y-coordinate is 1000 then what is the slope of the line?
{ "A": "2", "B": "5.5", "C": "6.5", "D": "3.2", "E": "9.9" }
divide(subtract(1000, 10), 100)
subtract(n2,n0)|divide(#0,n1)
eq of line = y = mx + c c = 10 x = 100 y = 100 m + 10 , substitute y by 1000 as given in question . 1000 = 100 m + 10 , m = 9.9 . correct option is e
general
math_qa__hRhEoi3g9raTkX5N
A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. What is the length of the bridge (in metres)? Choose the correct choice from the following options. A) 1280 B) 1250 C) 1320 D) 1340 E) 1350
<gadget id="calculator">5 * 1_000</gadget> <output>5_000</output> <gadget id="calculator">5_000 / 60</gadget> <output>250/3 = around 83.333333</output> <gadget id="calculator">(250/3) * 15</gadget> <output>1_250</output> <result>B</result>
B
1,250
A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. What is the length of the bridge (in metres)?
{ "A": "1280", "B": "1250", "C": "1320", "D": "1340", "E": "1350" }
multiply(divide(multiply(5, const_1000), const_60), 15)
multiply(n0,const_1000)|divide(#0,const_60)|multiply(n1,#1)
speed = 5 km / hr time = 15 minutes = 1 / 4 hour length of the bridge = distance travelled by the man = speed × time = 5 × 1 / 4 km = 5 × ( 1 / 4 ) × 1000 metre = 1250 metre answer is b
physics
math_qa__Rw06gAgXHAIBkfzp
The length of the bridge, which a train 160 metres long and travelling at 45 km/hr can cross in 30 seconds, is: Choices. A) 200 m B) 215 m C) 245 m D) 250 m E) 270 m
<gadget id="calculator">1_000 / 1</gadget> <output>1_000</output> <gadget id="calculator">45 * 1_000</gadget> <output>45_000</output> <gadget id="calculator">3_600 / 1</gadget> <output>3_600</output> <gadget id="calculator">45_000 / 3_600</gadget> <output>25/2 = around 12.5</output> <gadget id="calculator">(25/2) * 30</gadget> <output>375</output> <gadget id="calculator">375 - 160</gadget> <output>215</output> <result>B</result>
B
215
The length of the bridge, which a train 160 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
{ "A": "200 m", "B": "215 m", "C": "245 m", "D": "250 m", "E": "270 m" }
subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 160)
speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)|
"let the length of the bridge : l the equation now is l + 160 / 12.5 m / s ( 45 km / hr or 12.5 m / s ) = 30 solving , l = 215 m answer : b"
physics
math_qa__oMsZmfP1l1iiu9GS
A trader mixes 80 kg of tea at 15 per kg with 20 kg of tea at cost price of 20 per kg. In order to earn a profit of 40%, what should be the sale price of the mixed tea? Choose the correct choice from the following choices. A) 22.4 B) 22 C) 20 D) 19.2 E) none of these
<gadget id="calculator">80 * 15</gadget> <output>1_200</output> <gadget id="calculator">20 * 20</gadget> <output>400</output> <gadget id="calculator">1_200 + 400</gadget> <output>1_600</output> <gadget id="calculator">80 + 20</gadget> <output>100</output> <gadget id="calculator">1_600 / 100</gadget> <output>16</output> <gadget id="calculator">16 * 40</gadget> <output>640</output> <gadget id="calculator">640 / 100</gadget> <output>32/5 = around 6.4</output> <gadget id="calculator">(32/5) + 16</gadget> <output>112/5 = around 22.4</output> <result>A</result>
A
22.4
A trader mixes 80 kg of tea at 15 per kg with 20 kg of tea at cost price of 20 per kg. In order to earn a profit of 40%, what should be the sale price of the mixed tea?
{ "A": "22.4", "B": "22", "C": "20", "D": "19.2", "E": "none of these" }
add(divide(multiply(divide(add(multiply(80, 15), multiply(20, 20)), add(80, 20)), 40), const_100), divide(add(multiply(80, 15), multiply(20, 20)), add(80, 20)))
add(n0,n2)|multiply(n0,n1)|multiply(n2,n2)|add(#1,#2)|divide(#3,#0)|multiply(n4,#4)|divide(#5,const_100)|add(#6,#4)
c . p . of mixture = 80 × 15 + 20 × 20 / 80 + 20 = 16 ∴ s . p . = ( 100 + 40 ) / 100 × 16 = 22.4 answer a
gain
math_qa__EBXMHMlEmtRRllnP
A box contains 100 balls, numbered from 1 to 100. If 3 balls are selected at random and with replacement from the box. If the 3 numbers on the balls selected contain two odd and one even. What is the probability Z that the first ball picked up is odd numbered? Choose the most appropriate option: A) 0 B) 1 / 3 C) 1 / 2 D) 2 / 3 E) 1
<gadget id="calculator">2 / 3</gadget> <output>2/3 = around 0.666667</output> <result>D</result>
D
0.666667
A box contains 100 balls, numbered from 1 to 100. If 3 balls are selected at random and with replacement from the box. If the 3 numbers on the balls selected contain two odd and one even. What is the probability Z that the first ball picked up is odd numbered?
{ "A": "0", "B": "1 / 3", "C": "1 / 2", "D": "2 / 3", "E": "1" }
divide(const_2, 3)
divide(const_2,n3)|
"answer - d selecting the balls either even or odd is having probability 50 / 100 = 1 / 2 we have already selected 3 balls with 2 odd numbers and 1 even number . so we have 3 combinations ooe , oeo , eoo . we have 3 outcomes and 2 are favourable as in 2 cases 1 st number is odd . so probability z is 2 / 3 . d"
probability
math_qa__NMZTIc1K8KqaBqIA
if the price of a book is first decreased by 30% and then increased by 40%, then the net change in the price will be : Select: A) 10 B) 388 C) 37 D) 29 E) 2
<gadget id="calculator">100 * 30</gadget> <output>3_000</output> <gadget id="calculator">3_000 / 100</gadget> <output>30</output> <gadget id="calculator">100 - 30</gadget> <output>70</output> <gadget id="calculator">70 / 100</gadget> <output>7/10 = around 0.7</output> <gadget id="calculator">100 * 40</gadget> <output>4_000</output> <gadget id="calculator">4_000 / 100</gadget> <output>40</output> <gadget id="calculator">100 + 40</gadget> <output>140</output> <gadget id="calculator">140 / 100</gadget> <output>7/5 = around 1.4</output> <gadget id="calculator">(7/10) * (7/5)</gadget> <output>49/50 = around 0.98</output> <gadget id="calculator">(49/50) * 100</gadget> <output>98</output> <gadget id="calculator">100 - 98</gadget> <output>2</output> <result>E</result>
E
2
if the price of a book is first decreased by 30% and then increased by 40%, then the net change in the price will be :
{ "A": "10", "B": "388", "C": "37", "D": "29", "E": "2" }
subtract(const_100, multiply(multiply(divide(subtract(const_100, divide(multiply(const_100, 30), const_100)), const_100), divide(add(const_100, divide(multiply(const_100, 40), const_100)), const_100)), const_100))
multiply(n0,const_100)|multiply(n1,const_100)|divide(#0,const_100)|divide(#1,const_100)|add(#3,const_100)|subtract(const_100,#2)|divide(#5,const_100)|divide(#4,const_100)|multiply(#6,#7)|multiply(#8,const_100)|subtract(const_100,#9)|
"explanation : let the original price be rs . 100 . decreased by 30 % = 70 then increased 40 % on rs 70 = 70 + 28 = 98 net change in price = 100 - 98 = 2 answer : e"
general
math_qa__5f526fGxyf1peIiK
Two pipes A and B can fill a cistern in 37 ½ min and 45 minutes respectively. Both the pipes are opened. The cistern will be filled in just half an hour, if the pipe B is turned off after Choices: A) 6 minutes B) 9 minutes C) 45 minutes D) 3 minutes E) 4 minutes
<gadget id="calculator">2 + 3</gadget> <output>5</output> <gadget id="calculator">45 / 5</gadget> <output>9</output> <result>B</result>
B
9
Two pipes A and B can fill a cistern in 37 ½ min and 45 minutes respectively. Both the pipes are opened. The cistern will be filled in just half an hour, if the pipe B is turned off after
{ "A": "6 minutes", "B": "9 minutes", "C": "45 minutes", "D": "3 minutes", "E": "4 minutes" }
divide(45, add(const_2, const_3))
add(const_2,const_3)|divide(n1,#0)
if pipe b is turned off after x mins , then ( 2 * 30 ) / 75 + x / 45 = 1 x / 45 = 1 - 60 / 75 = 1 / 5 x = 45 / 5 = 9 mins answer : b
physics
math_qa__5UBQBXIT5XGb7yHy
All the milk in container A which was filled to its brim was poured into two containers B and C. The quantity of milk in container B was 62.5% less than the capacity of container A. If 158 liters was now transferred from C to B, then both the containers would have equal quantities of milk. What was the initial quantity of milk in container A? Choose the correct choice from the following: A) 1264 B) 1723 C) 1129 D) 2613 E) 1372
<gadget id="calculator">1 / 2</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">62.5 / 100</gadget> <output>0.625</output> <gadget id="calculator">1 - 0.625</gadget> <output>0.375</output> <gadget id="calculator">(1/2) - 0.375</gadget> <output>0.125</output> <gadget id="calculator">158 / 0.125</gadget> <output>1_264</output> <result>A</result>
A
1,264
All the milk in container A which was filled to its brim was poured into two containers B and C. The quantity of milk in container B was 62.5% less than the capacity of container A. If 158 liters was now transferred from C to B, then both the containers would have equal quantities of milk. What was the initial quantity of milk in container A?
{ "A": "1264", "B": "1723", "C": "1129", "D": "2613", "E": "1372" }
divide(158, subtract(inverse(const_2), subtract(const_1, divide(62.5, const_100))))
divide(n0,const_100)|inverse(const_2)|subtract(const_1,#0)|subtract(#1,#2)|divide(n1,#3)|
"a b has 62.5 % or ( 5 / 8 ) of the milk in a . therefore , let the quantity of milk in container a ( initially ) be 8 k . quantity of milk in b = 8 k - 5 k = 3 k . quantity of milk in container c = 8 k - 3 k = 5 k container : a b c quantity of milk : 8 k 3 k 5 k it is given that if 158 liters was transferred from container c to container b , then both the containers would have equal quantities of milk . 5 k - 158 = 3 k + 158 = > 2 k = 316 = > k = 158 the initial quantity of milk in a = 8 k = 8 * 158 = 1264 liters ."
general
math_qa__wfq65EnmTBZxmi2u
Two spies agreed to meet at a gas station between noon and 1pm, but they have both forgotten the arranged time. Each arrives at a random time between noon and 1pm and stays for 6 minutes unless the other is there before the 6 minutes are up. Assuming all random times are equally likely, what is the probability that they will meet within the hour (noon to 1pm)? Select the correct option: A) 0.12 B) 0.15 C) 0.17 D) 0.19 E) 0.25
<gadget id="calculator">6 * 3</gadget> <output>18</output> <gadget id="calculator">18 + 1</gadget> <output>19</output> <gadget id="calculator">19 / 100</gadget> <output>19/100 = around 0.19</output> <result>D</result>
D
0.19
Two spies agreed to meet at a gas station between noon and 1pm, but they have both forgotten the arranged time. Each arrives at a random time between noon and 1pm and stays for 6 minutes unless the other is there before the 6 minutes are up. Assuming all random times are equally likely, what is the probability that they will meet within the hour (noon to 1pm)?
{ "A": "0.12", "B": "0.15", "C": "0.17", "D": "0.19", "E": "0.25" }
divide(add(multiply(6, const_3), 1), const_100)
multiply(n2,const_3)|add(n0,#0)|divide(#1,const_100)
the probability that they do not meet is represented by the total of the areas of the two outer triangles in the figure below , which is 0.81 . so the probability of a meeting is 1 - 0.81 = 0 . 19 . correct answer d
general
math_qa__kRsenL5DKn9B8ktz
The water level in a rectangular swimming pool measuring 50 feet by 25 feet is to be lowered by 6 inches. How many gallons of water must be removed? (1 cu ft = 7.5 gallons) Select the correct option: A) 100 B) 250 C) 750 D) 1200 E) 4687.5
<gadget id="calculator">10 + 2</gadget> <output>12</output> <gadget id="calculator">6 / 12</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">50 * 25 * (1/2)</gadget> <output>625</output> <gadget id="calculator">625 * 7.5</gadget> <output>4_687.5</output> <result>E</result>
E
4,687.5
The water level in a rectangular swimming pool measuring 50 feet by 25 feet is to be lowered by 6 inches. How many gallons of water must be removed? (1 cu ft = 7.5 gallons)
{ "A": "100", "B": "250", "C": "750", "D": "1200", "E": "4687.5" }
multiply(volume_rectangular_prism(50, 25, divide(6, add(const_10, const_2))), 7.5)
add(const_10,const_2)|divide(n2,#0)|volume_rectangular_prism(n0,n1,#1)|multiply(n4,#2)|
"6 inches = 1 / 2 feet ( there are 12 inches in a foot . ) , so 50 * 25 * 1 / 2 = 625 feet ^ 3 of water must be removed , which equals to 625 * 7.5 = 4687.5 gallons . answer : e ."
geometry
math_qa__sM5F43GBOCitR9Bl
If 34 men do a work in 40 days, in how many days will 20 men do it? Choices. A) 65 B) 68 C) 61 D) 55 E) 74
<gadget id="calculator">34 * 40</gadget> <output>1_360</output> <gadget id="calculator">1_360 / 20</gadget> <output>68</output> <result>B</result>
B
68
If 34 men do a work in 40 days, in how many days will 20 men do it?
{ "A": "65", "B": "68", "C": "61", "D": "55", "E": "74" }
divide(multiply(34, 40), 20)
multiply(n0,n1)|divide(#0,n2)|
"34 * 40 = 20 * x x = 68 days answer : b"
physics
math_qa__6bNgY5vED8NWQIlN
Susan finds that she spends her free time during summer vacation between swimming, reading, and hanging out with friends in a ratio of 1:4:10. How many hours did she spend reading if she hung out with her friends for 20 hours? Choose the correct answer: A) 2 B) 4 C) 5 D) 8 E) 10
<gadget id="calculator">1 + 4</gadget> <output>5</output> <gadget id="calculator">5 + 10</gadget> <output>15</output> <gadget id="calculator">20 * 15</gadget> <output>300</output> <gadget id="calculator">300 / 10</gadget> <output>30</output> <gadget id="calculator">30 * 4</gadget> <output>120</output> <gadget id="calculator">120 / 15</gadget> <output>8</output> <result>D</result>
D
8
Susan finds that she spends her free time during summer vacation between swimming, reading, and hanging out with friends in a ratio of 1:4:10. How many hours did she spend reading if she hung out with her friends for 20 hours?
{ "A": "2", "B": "4", "C": "5", "D": "8", "E": "10" }
divide(multiply(divide(multiply(20, add(add(1, 4), 10)), 10), 4), add(add(1, 4), 10))
add(n0,n1)|add(n2,#0)|multiply(n3,#1)|divide(#2,n2)|multiply(n1,#3)|divide(#4,#1)
the ratio is 1 hour swimming : 4 hours reading : 10 hours hanging out with friends . divide 20 by 10 to find 1 ` ` part ' ' of the ratio . 20 / 10 = 2 multiply this by 4 to find the hours spent reading . 2 * 4 = 8 the answer is d .
other
math_qa__GTVU1pJtWWeY4pJ3
3 ltr of water is added with 11 ltr of a solution containing 42%of alcohol in the water. The %of alcohol in the new mixture is? Pick: A) 23 % B) 35 % C) 33 % D) 40 % E) 45 %
<gadget id="calculator">42 / 100</gadget> <output>21/50 = around 0.42</output> <gadget id="calculator">(21/50) * 11</gadget> <output>231/50 = around 4.62</output> <gadget id="calculator">3 + 11</gadget> <output>14</output> <gadget id="calculator">(231/50) / 14</gadget> <output>33/100 = around 0.33</output> <gadget id="calculator">100 * (33/100)</gadget> <output>33</output> <result>C</result>
C
33
3 ltr of water is added with 11 ltr of a solution containing 42%of alcohol in the water. The %of alcohol in the new mixture is?
{ "A": "23 %", "B": "35 %", "C": "33 %", "D": "40 %", "E": "45 %" }
multiply(const_100, divide(multiply(divide(42, const_100), 11), add(3, 11)))
add(n0,n1)|divide(n2,const_100)|multiply(n1,#1)|divide(#2,#0)|multiply(#3,const_100)|
"we have a 11 litre solution containing 42 % of alcohol in the water . = > quantity of alcohol in the solution = 11 × 42 / 100 now 3 litre of water is added to the solution . = > total quantity of the new solution = 11 + 3 = 14 percentage of alcohol in the new solution = 11 × 42 / 100 14 × 100 = 11 × 4210014 × 100 = 11 × 3 / 100 = 33 % c"
general
math_qa__TEYPJzgb3q29sAN3
When positive integer X is divided by positive integer Y, the remainder is 1.44. If X/Y = 96.12, what is the value of Y? Choose the most appropriate option A) 96 B) 75 C) 48 D) 25 E) 12
<gadget id="calculator">floor(96.12)</gadget> <output>96</output> <gadget id="calculator">96.12 - 96</gadget> <output>0.12</output> <gadget id="calculator">1.44 / 0.12</gadget> <output>12</output> <result>E</result>
E
12
When positive integer X is divided by positive integer Y, the remainder is 1.44. If X/Y = 96.12, what is the value of Y?
{ "A": "96", "B": "75", "C": "48", "D": "25", "E": "12" }
divide(1.44, subtract(96.12, floor(96.12)))
floor(n1)|subtract(n1,#0)|divide(n0,#1)|
"when positive integer x is divided by positive integer y , the remainder is 1.44 - - > x = qy + 1.44 ; x / y = 96.12 - - > x = 96 y + 0.12 y ( so q above equals to 96 ) ; 0.12 y = 1.44 - - > y = 12 . answer : e ."
general
math_qa__9w5GI9kdl3R001Gw
Bruce and Anne can clean their house in 4 hours working together at their respective constant rates. If Anne’s speed were doubled, they could clean their house in 3 hours working at their respective rates. How many E hours does it currently take Anne to clean the house on her own? Choose the correct choice from the following A) 6 B) 7 C) 8 D) 12 E) 14
<gadget id="calculator">1 / 3</gadget> <output>1/3 = around 0.333333</output> <gadget id="calculator">1 / 4</gadget> <output>1/4 = around 0.25</output> <gadget id="calculator">(1/3) - (1/4)</gadget> <output>1/12 = around 0.083333</output> <gadget id="calculator">1 / (1/12)</gadget> <output>12</output> <result>D</result>
D
12
Bruce and Anne can clean their house in 4 hours working together at their respective constant rates. If Anne’s speed were doubled, they could clean their house in 3 hours working at their respective rates. How many E hours does it currently take Anne to clean the house on her own?
{ "A": "6", "B": "7", "C": "8", "D": "12", "E": "14" }
inverse(subtract(divide(const_1, 3), divide(const_1, 4)))
divide(const_1,n1)|divide(const_1,n0)|subtract(#0,#1)|inverse(#2)
lets suppose anne and bruce take a and b hrs working separately so in 1 hour they can together finish 1 / a + 1 / b portion of the work which equals 1 / 4 ( as the work is completed in 4 hours ) after anne doubles her rate of work the portion completed by the both is 1 / a + 2 / b which is equal to 1 / 3 ( as the work is completed in e = 3 hours ) solving these 2 equations we can find b as 12 so , d
physics
math_qa__cnfwf2XUAJZH41IT
Sophia finished 23 of a book. She calculated that she finished 90 more pages than she has yet to read. How long is her book? Choose the correct choice from the following choices A) 180 B) 200 C) 250 D) 270 E) 300
<gadget id="calculator">2 / 3</gadget> <output>2/3 = around 0.666667</output> <gadget id="calculator">1 - (2/3)</gadget> <output>1/3 = around 0.333333</output> <gadget id="calculator">(2/3) - (1/3)</gadget> <output>1/3 = around 0.333333</output> <gadget id="calculator">90 / (1/3)</gadget> <output>270</output> <result>D</result>
D
270
Sophia finished 23 of a book. She calculated that she finished 90 more pages than she has yet to read. How long is her book?
{ "A": "180", "B": "200", "C": "250", "D": "270", "E": "300" }
divide(90, subtract(divide(const_2, const_3), subtract(const_1, divide(const_2, const_3))))
divide(const_2,const_3)|subtract(const_1,#0)|subtract(#0,#1)|divide(n1,#2)|
"let x be the total number of pages in the book , then she finished 23 ⋅ x pages . then she has x − 23 ⋅ x = 13 ⋅ x pages left . 23 ⋅ x − 13 ⋅ x = 90 13 ⋅ x = 90 x = 270 . so answer is d ."
general
math_qa__GBBOv1AvgAnEnmxH
on dividing a N by 9,remainder is 8. the quotient obtained when divided by 11,leaves remainder 9. now the quotient when divided by 13,leaves remainder 8. find the remainder when when the N is divided by 1287 Choose the correct choice from the following answers: A) 871 B) 881 C) 891 D) 904 E) 987
<gadget id="calculator">9 * 9</gadget> <output>81</output> <gadget id="calculator">81 * 11</gadget> <output>891</output> <result>B</result>
B
881
on dividing a N by 9,remainder is 8. the quotient obtained when divided by 11,leaves remainder 9. now the quotient when divided by 13,leaves remainder 8. find the remainder when when the N is divided by 1287
{ "A": "871", "B": "881", "C": "891", "D": "904", "E": "987" }
multiply(multiply(9, 9), 11)
multiply(n0,n0)|multiply(n2,#0)
take from the last step division suppose no . is n which is divided by 13 and remainder 8 = 13 n + 8 now 13 n + 8 will be the no . which is divided by 11 and remainder is 9 = [ 11 * ( 13 n + 8 ) ] + 9 now this no . is used for the very first step which is divider is 9 and remainder is 8 = { 9 * [ 11 * ( 13 n + 8 ) ] + 9 } + 8 solve and ans is 881 answer : b
general
math_qa__l9fw94siqzyvenHx
A sports retailer ordered white and yellow tennis balls in equal number but the dispatch clerk of the tennis ball company erred and dispatched 50 extra yellow balls and making ratio of white balls to yellow balls 7/11. How many tennis balls did the retailer order originally. Choose the correct choice from the following answers: A) 17.5 B) 130 C) 175 D) 195 E) 220
<gadget id="calculator">7 * 50</gadget> <output>350</output> <gadget id="calculator">11 - 7</gadget> <output>4</output> <gadget id="calculator">350 / 4</gadget> <output>175/2 = around 87.5</output> <gadget id="calculator">(175/2) * 2</gadget> <output>175</output> <result>C</result>
C
175
A sports retailer ordered white and yellow tennis balls in equal number but the dispatch clerk of the tennis ball company erred and dispatched 50 extra yellow balls and making ratio of white balls to yellow balls 7/11. How many tennis balls did the retailer order originally.
{ "A": "17.5", "B": "130", "C": "175", "D": "195", "E": "220" }
multiply(divide(multiply(7, 50), subtract(11, 7)), const_2)
multiply(n0,n1)|subtract(n2,n1)|divide(#0,#1)|multiply(#2,const_2)|
"white : yellow = x : ( x + 50 ) = 7 : 11 - - > 11 x = 7 x + 350 - - > x = 87.5 . the total # of balls originally x + x = 87.5 + 87.5 = 175 . answer : c ."
general
math_qa__L96F51ZfARNFX960
Two cars are traveling in the same direction along the same route. The red car travels at a constant speed of 10 miles per hour, and the black car is traveling at a constant speed of 50 miles per hour. If the red car is 20 miles ahead of the black car, how many hours will it take the black car to overtake the red car? Choose the most appropriate option A) 0.1 B) 0.5 C) 1 D) 1.2 E) 2
<gadget id="calculator">50 - 10</gadget> <output>40</output> <gadget id="calculator">20 / 40</gadget> <output>1/2 = around 0.5</output> <result>B</result>
B
0.5
Two cars are traveling in the same direction along the same route. The red car travels at a constant speed of 10 miles per hour, and the black car is traveling at a constant speed of 50 miles per hour. If the red car is 20 miles ahead of the black car, how many hours will it take the black car to overtake the red car?
{ "A": "0.1", "B": "0.5", "C": "1", "D": "1.2", "E": "2" }
divide(20, subtract(50, 10))
subtract(n1,n0)|divide(n2,#0)|
"option b 20 + 10 t = 50 t t = 0.5"
physics
math_qa__BEDF3I52vpioiEZ4
An equilateral triangle and three squares are combined as shown above, forming a shape of area 48+4√3. What is the perimeter of the shape formed by the triangle and squares? Choose the correct choice from the following options: A) 18 B) 27 C) 36 D) 48 E) 64
<gadget id="calculator">3 ** 2</gadget> <output>9</output> <gadget id="calculator">9 * 4</gadget> <output>36</output> <result>C</result>
C
36
An equilateral triangle and three squares are combined as shown above, forming a shape of area 48+4√3. What is the perimeter of the shape formed by the triangle and squares?
{ "A": "18", "B": "27", "C": "36", "D": "48", "E": "64" }
multiply(power(3, const_2), 4)
power(n2,const_2)|multiply(n1,#0)
triangle area = root ( 3 ) s ^ 2 / 4 area of 3 squares together = 3 s ^ 2 root ( 3 ) s ^ 2 / 4 + 3 s ^ 2 = 48 + 4 root ( 3 ) root ( 3 ) / 4 s ^ 2 = 4 root ( 3 ) s ^ 2 = 16 = > s = 4 there are 3 sides of each square = 3 ( 4 ) ( 3 ) = 36 option c
geometry
math_qa__7QdvrrN5pIJPnDZp
If 10 litres of an oil of Rs.54 per litres be mixed with 5 litres of another oil of Rs.66 per litre then what is the rate of mixed oil per litre? Select the correct option: A) rs . 49.17 B) rs . 58 C) rs . 54.17 D) rs . 55.33 E) none of the above
<gadget id="calculator">10 * 54</gadget> <output>540</output> <gadget id="calculator">5 * 66</gadget> <output>330</output> <gadget id="calculator">540 + 330</gadget> <output>870</output> <gadget id="calculator">10 + 5</gadget> <output>15</output> <gadget id="calculator">870 / 15</gadget> <output>58</output> <result>B</result>
B
58
If 10 litres of an oil of Rs.54 per litres be mixed with 5 litres of another oil of Rs.66 per litre then what is the rate of mixed oil per litre?
{ "A": "rs . 49.17", "B": "rs . 58", "C": "rs . 54.17", "D": "rs . 55.33", "E": "none of the above" }
divide(add(multiply(10, 54), multiply(5, 66)), add(10, 5))
add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)|
"54 * 10 = 540 66 * 5 = 330 870 / 15 = 58 answer : b"
gain
math_qa__CMtEccB4GLs84TJY
A tank is filled by 3 pipes A,B,C in 10 hours. Pipe C is twice as fast as B and B is twice as fast as A. How much will pipe A alone take to fill the tank ? Select: A) 20 hr B) 52 hr C) 70 hr D) 66 hr E) 48 hr
<gadget id="calculator">2 * 2</gadget> <output>4</output> <gadget id="calculator">4 + 2</gadget> <output>6</output> <gadget id="calculator">6 + 1</gadget> <output>7</output> <gadget id="calculator">7 * 10</gadget> <output>70</output> <result>C</result>
C
70
A tank is filled by 3 pipes A,B,C in 10 hours. Pipe C is twice as fast as B and B is twice as fast as A. How much will pipe A alone take to fill the tank ?
{ "A": "20 hr", "B": "52 hr", "C": "70 hr", "D": "66 hr", "E": "48 hr" }
multiply(add(add(multiply(const_2, const_2), const_2), const_1), 10)
multiply(const_2,const_2)|add(#0,const_2)|add(#1,const_1)|multiply(n1,#2)|
"suppose pipe a alone take x hours to fill the tank then pipe b and c will take x / 2 and x / 4 hours respectively to fill the tank . 1 / x + 2 / x + 4 / x = 1 / 10 7 / x = 1 / 10 x = 70 hours answer is c"
physics
math_qa__kwf3gVoHRAc9vtGq
The difference between a positive proper fraction and its reciprocal is 9/20. The fraction is Choose the correct choice from the following: A) 4 / 5 B) 7 / 11 C) 7 / 13 D) 7 / 15 E) 8 / 11
<gadget id="calculator">9 - 4</gadget> <output>5</output> <gadget id="calculator">4 / 5</gadget> <output>4/5 = around 0.8</output> <result>A</result>
A
0.8
The difference between a positive proper fraction and its reciprocal is 9/20. The fraction is
{ "A": "4 / 5", "B": "7 / 11", "C": "7 / 13", "D": "7 / 15", "E": "8 / 11" }
divide(const_4, subtract(9, const_4))
subtract(n0,const_4)|divide(const_4,#0)
let the required fraction be x . then 1 - x = 9 x 20 1 - x 2 = 9 x 20 20 - 20 x 2 = 9 x 20 x 2 + 9 x - 20 = 0 20 x 2 + 25 x - 16 x - 20 = 0 5 x ( 4 x + 5 ) - 4 ( 4 x + 5 ) = 0 ( 4 x + 5 ) ( 5 x - 4 ) = 0 x = 4 / 5 a )
general
math_qa__ph8FvnilKDXa5JU4
Rahul can do a work in 3 days while Rajesh can do the same work in 2days. Both of them finish the work together and get $2250. What is the share of Rahul? Choose the most appropriate option: A) $ 50 B) $ 40 C) $ 60 D) $ 100 E) $ 900
<gadget id="calculator">3 + 2</gadget> <output>5</output> <gadget id="calculator">2 / 5</gadget> <output>2/5 = around 0.4</output> <gadget id="calculator">(2/5) * 2_250</gadget> <output>900</output> <result>E</result>
E
900
Rahul can do a work in 3 days while Rajesh can do the same work in 2days. Both of them finish the work together and get $2250. What is the share of Rahul?
{ "A": "$ 50", "B": "$ 40", "C": "$ 60", "D": "$ 100", "E": "$ 900" }
multiply(divide(2, add(3, 2)), 2250)
add(n0,n1)|divide(n1,#0)|multiply(n2,#1)|
"rahul ' s wages : rajesh ' s wages = 1 / 3 : 1 / 2 = 2 : 3 rahul ' s share = 2250 * 2 / 5 = $ 900 answer is e"
physics
math_qa__5MutHK7lGoaZBZsI
HCF and LCM two numbers are 20 and 396 respectively. If one of the numbers is 36, then the other number is? Choose the correct answer: A) 36 B) 66 C) 132 D) 264 E) 220
<gadget id="calculator">20 * 396</gadget> <output>7_920</output> <gadget id="calculator">7_920 / 36</gadget> <output>220</output> <result>E</result>
E
220
HCF and LCM two numbers are 20 and 396 respectively. If one of the numbers is 36, then the other number is?
{ "A": "36", "B": "66", "C": "132", "D": "264", "E": "220" }
divide(multiply(20, 396), 36)
multiply(n0,n1)|divide(#0,n2)
20 * 396 = 36 * x x = 220 answer : e
physics
math_qa__WTUHE2ioxJf3ZruJ
A train running at the speed of 60 km/hr crosses a pole in 15 seconds. What is the length of the train? Select: A) 187 m B) 250 m C) 876 m D) 150 m E) 267 m
<gadget id="calculator">60 * 1_000</gadget> <output>60_000</output> <gadget id="calculator">60_000 / 3_600</gadget> <output>50/3 = around 16.666667</output> <gadget id="calculator">(50/3) * 15</gadget> <output>250</output> <result>B</result>
B
250
A train running at the speed of 60 km/hr crosses a pole in 15 seconds. What is the length of the train?
{ "A": "187 m", "B": "250 m", "C": "876 m", "D": "150 m", "E": "267 m" }
multiply(divide(multiply(60, const_1000), const_3600), 15)
multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)|
"speed = ( 60 * 5 / 18 ) m / sec = ( 50 / 3 ) m / sec length of the train = ( speed x time ) = ( 50 / 3 * 15 ) m = 250 m . answer : b"
physics
math_qa__2QTM8cNix4Nv2WBk
the ratio of toddlers to infants at a day care center is 7 to 3 . if 12 more infants join the day care to change the ratio to 7 to 5 , how many toddlers are there at this day care center ? Choose the most appropriate option. A) 24 B) 36 C) 42 D) 72 E) 120
<gadget id="calculator">7 * 7</gadget> <output>49</output> <gadget id="calculator">5 * 3</gadget> <output>15</output> <gadget id="calculator">49 - 15</gadget> <output>34</output> <gadget id="calculator">34 + 12</gadget> <output>46</output> <gadget id="calculator">46 - 4</gadget> <output>42</output> <result>C</result>
C
42
the ratio of toddlers to infants at a day care center is 7 to 3 . if 12 more infants join the day care to change the ratio to 7 to 5 , how many toddlers are there at this day care center ?
{ "A": "24", "B": "36", "C": "42", "D": "72", "E": "120" }
subtract(add(subtract(multiply(7, 7), multiply(5, 3)), 12), const_4)
multiply(n0,n0)|multiply(n1,n4)|subtract(#0,#1)|add(n2,#2)|subtract(#3,const_4)
5 x - 3 x = 12 so , 2 x = 6 hence no of toddlers is 6 * 7 = 42 answer will be ( c ) 42
other
math_qa__9cA8lnz5deN80OFv
Without stoppages, a train travels certain distance with an average speed of 400 km/h, and with stoppages, it covers the same distance with an average speed of 360 km/h. How many minutes per hour the train stops ? Choose the correct choice: A) 3 B) 4 C) 5 D) 6 E) 7
<gadget id="calculator">360 / 400</gadget> <output>9/10 = around 0.9</output> <gadget id="calculator">(9/10) * 60</gadget> <output>54</output> <gadget id="calculator">60 - 54</gadget> <output>6</output> <result>D</result>
D
6
Without stoppages, a train travels certain distance with an average speed of 400 km/h, and with stoppages, it covers the same distance with an average speed of 360 km/h. How many minutes per hour the train stops ?
{ "A": "3", "B": "4", "C": "5", "D": "6", "E": "7" }
subtract(const_60, multiply(divide(360, 400), const_60))
divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)|
"due to stoppages , it covers 40 km less . time taken to cover 40 km = 40 ⠁ „ 400 h = 1 ⠁ „ 10 h = 1 ⠁ „ 10 ã — 60 min = 6 min answer d"
physics
math_qa__ApjebOHeBkh2SzVX
Express a speed of 18 kmph in meters per second? Pick: A) 10 mps B) 06 mps C) 09 mps D) 05 mps E) 11 mps
<gadget id="calculator">10 / 36</gadget> <output>5/18 = around 0.277778</output> <gadget id="calculator">(5/18) * 18</gadget> <output>5</output> <result>D</result>
D
5
Express a speed of 18 kmph in meters per second?
{ "A": "10 mps", "B": "06 mps", "C": "09 mps", "D": "05 mps", "E": "11 mps" }
multiply(const_0_2778, 18)
multiply(n0,const_0_2778)
d 5 mps 18 * 5 / 18 = 5 mps
physics
math_qa__EbKVzgvsEpQ87JAX
Each of the 30 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and the average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the average weight of the boxes in the shipment is to be reduced to 15 pounds by removing some of the 20-pound boxes, how many 20-pound boxes must be removed? Choose the correct choice from the following answers: A) 8 B) 12 C) 18 D) 20 E) 24
<gadget id="calculator">20 * 30</gadget> <output>600</output> <gadget id="calculator">30 * 18</gadget> <output>540</output> <gadget id="calculator">600 - 540</gadget> <output>60</output> <gadget id="calculator">20 - 10</gadget> <output>10</output> <gadget id="calculator">60 / 10</gadget> <output>6</output> <gadget id="calculator">10 * 6</gadget> <output>60</output> <gadget id="calculator">30 - 6</gadget> <output>24</output> <gadget id="calculator">20 * 24</gadget> <output>480</output> <gadget id="calculator">60 + 480</gadget> <output>540</output> <gadget id="calculator">30 * 15</gadget> <output>450</output> <gadget id="calculator">540 - 450</gadget> <output>90</output> <gadget id="calculator">20 - 15</gadget> <output>5</output> <gadget id="calculator">90 / 5</gadget> <output>18</output> <result>C</result>
C
18
Each of the 30 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and the average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the average weight of the boxes in the shipment is to be reduced to 15 pounds by removing some of the 20-pound boxes, how many 20-pound boxes must be removed?
{ "A": "8", "B": "12", "C": "18", "D": "20", "E": "24" }
divide(subtract(add(multiply(10, divide(subtract(multiply(20, 30), multiply(30, 18)), subtract(20, 10))), multiply(20, subtract(30, divide(subtract(multiply(20, 30), multiply(30, 18)), subtract(20, 10))))), multiply(30, 15)), subtract(20, 15))
multiply(n0,n2)|multiply(n0,n3)|multiply(n0,n4)|subtract(n2,n1)|subtract(n2,n4)|subtract(#0,#1)|divide(#5,#3)|multiply(n1,#6)|subtract(n0,#6)|multiply(n2,#8)|add(#7,#9)|subtract(#10,#2)|divide(#11,#4)|
"if the average of 10 - pound and 20 - pound boxes is 18 , the ratio of 10 - pound boxes : 20 - pound boxes is 1 : 4 . so out of 30 boxes , 6 are 10 - pound boxes and 24 are 20 - pound boxes . if the average of 10 and 20 - pound boxes is to be 15 , the ratio of 10 - pound boxes : 20 - pound boxes should be 1 : 1 . the number of 10 pound boxes remain the same so we still have 6 of them . to get a ratio of 1 : 1 , the number of 20 - pound boxes must be 6 . we need to remove 18 of the 20 - pound boxes . the answer is c ."
general
math_qa__VdZBuMwCYVqkz7vk
A train 280 m long, running with a speed of 72 km/hr will pass a tree in? Options A) 17 sec B) 16 sec C) 18 sec D) 14 sec E) 12 sec
<gadget id="calculator">72 * 1_000</gadget> <output>72_000</output> <gadget id="calculator">280 / 72_000</gadget> <output>7/1_800 = around 0.003889</output> <gadget id="calculator">(7/1_800) * 3_600</gadget> <output>14</output> <result>D</result>
D
14
A train 280 m long, running with a speed of 72 km/hr will pass a tree in?
{ "A": "17 sec", "B": "16 sec", "C": "18 sec", "D": "14 sec", "E": "12 sec" }
multiply(divide(280, multiply(72, const_1000)), const_3600)
multiply(n1,const_1000)|divide(n0,#0)|multiply(#1,const_3600)|
"speed = 72 * 5 / 18 = 20 m / sec time taken = 280 * 1 / 20 = 14 sec answer : d"
physics
math_qa__PvFBlneaOyNFZNuF
In a coconut grove, (x + 4) trees yield 60 nuts per year, x trees yield 120 nuts per year and (x – 4) trees yield 180 nuts per year. If the average yield per year per tree be 100, find x. Choose the correct choice. A) 3 B) 4 C) 8 D) 9 E) none of the above
<gadget id="calculator">180 * 4</gadget> <output>720</output> <gadget id="calculator">60 * 4</gadget> <output>240</output> <gadget id="calculator">720 - 240</gadget> <output>480</output> <gadget id="calculator">60 + 120</gadget> <output>180</output> <gadget id="calculator">180 + 180</gadget> <output>360</output> <gadget id="calculator">100 * 3</gadget> <output>300</output> <gadget id="calculator">360 - 300</gadget> <output>60</output> <gadget id="calculator">480 / 60</gadget> <output>8</output> <result>C</result>
C
8
In a coconut grove, (x + 4) trees yield 60 nuts per year, x trees yield 120 nuts per year and (x – 4) trees yield 180 nuts per year. If the average yield per year per tree be 100, find x.
{ "A": "3", "B": "4", "C": "8", "D": "9", "E": "none of the above" }
divide(subtract(multiply(180, 4), multiply(60, 4)), subtract(add(add(60, 120), 180), multiply(100, const_3)))
add(n1,n2)|multiply(n0,n4)|multiply(n0,n1)|multiply(n5,const_3)|add(n4,#0)|subtract(#1,#2)|subtract(#4,#3)|divide(#5,#6)
( x + 4 ) × 60 + x × 120 + ( x − 4 ) × 180 / ( x + 4 ) + x + ( x − 4 ) = 100 ⇒ 360 x − 480 / 3 x = 100 ⇒ 60 x = 480 ⇒ x = 8 answer c
general
math_qa__V2BySEZ5woIm5IEr
In one hour,a boat goes 16 km along the stream and 6 km against the stream.The speed of the boat in still water (in km/hr) is : Choose the correct choice from the following choices: A) 3 B) 11 C) 8 D) 9 E) 10
<gadget id="calculator">16 + 6</gadget> <output>22</output> <gadget id="calculator">22 / 2</gadget> <output>11</output> <result>B</result>
B
11
In one hour,a boat goes 16 km along the stream and 6 km against the stream.The speed of the boat in still water (in km/hr) is :
{ "A": "3", "B": "11", "C": "8", "D": "9", "E": "10" }
divide(add(16, 6), const_2)
add(n0,n1)|divide(#0,const_2)|
"solution speed in still water = 1 / 2 ( 16 + 6 ) kmph . = 11 kmph . answer b"
physics
math_qa__NSF5CU74cDI7mSdR
How long does a train 120 m long running at the speed of 70 km/hr takes to cross a bridge 150 m length? Pick: A) 12.7 sec B) 13.9 sec C) 18.1 sec D) 17.1 sec E) 19.7 sec
<gadget id="calculator">120 + 150</gadget> <output>270</output> <gadget id="calculator">10 / 36</gadget> <output>5/18 = around 0.277778</output> <gadget id="calculator">70 * (5/18)</gadget> <output>175/9 = around 19.444444</output> <gadget id="calculator">270 / (175/9)</gadget> <output>486/35 = around 13.885714</output> <result>B</result>
B
13.9
How long does a train 120 m long running at the speed of 70 km/hr takes to cross a bridge 150 m length?
{ "A": "12.7 sec", "B": "13.9 sec", "C": "18.1 sec", "D": "17.1 sec", "E": "19.7 sec" }
divide(add(120, 150), multiply(70, const_0_2778))
add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)|
"speed = 70 * 5 / 18 = 19.4 m / sec total distance covered = 120 + 150 = 270 m . required time = 270 / 19.4 ' = 13.9 sec . answer : b"
physics
math_qa__81qjYc6VJyMMsDu1
A palindrome is a number that reads the same forward and backward, such as 121. How many odd, 4-digit numbers are palindromes? Choose the correct choice from the following choices: A) 40 B) 45 C) 50 D) 90 E) 2500
<gadget id="calculator">4 / 2</gadget> <output>2</output> <gadget id="calculator">10 ** 2</gadget> <output>100</output> <gadget id="calculator">100 / 2</gadget> <output>50</output> <result>C</result>
C
50
A palindrome is a number that reads the same forward and backward, such as 121. How many odd, 4-digit numbers are palindromes?
{ "A": "40", "B": "45", "C": "50", "D": "90", "E": "2500" }
divide(power(const_10, divide(4, const_2)), const_2)
divide(n1,const_2)|power(const_10,#0)|divide(#1,const_2)
first recognize you only need to consider the first two digits ( because the second two are just the first two flipped ) there are 90 possibilities for the first two digits of a 4 digit number , 10 - 99 inclusive . everything starting with a 1 , 3,5 , 7,9 will be odd , which is 5 / 9 ths of the combinations . 5 / 9 * 90 = 50 answer : c
general
math_qa__btim3LKsuzk8ShBH
In an aquarium there is 14 purple fish, 8 orange fish,12 pink fish, 3 golden fish. How many fish are there in an aquarium? Choose the correct answer: A) 27 B) 37 C) 17 D) 47 E) 07
<gadget id="calculator">3 * 12</gadget> <output>36</output> <result>B</result>
B
37
In an aquarium there is 14 purple fish, 8 orange fish,12 pink fish, 3 golden fish. How many fish are there in an aquarium?
{ "A": "27", "B": "37", "C": "17", "D": "47", "E": "07" }
multiply(3, 12)
multiply(n2,n3)
14 + 8 + 12 + 3 = 37 . answer is b
general
math_qa__PA2NliliXInNeHJg
Last year, for every 100 million vehicles that traveled on a certain highway, 100 vehicles were involved in accidents. If 2 billion vehicles traveled on the highway last year, how many of those vehicles were involved in accidents? (1 billion = 1,000,000,000) Choose the correct option A) 500 B) 1500 C) 2500 D) 2000 E) 1000
<gadget id="calculator">2 * 10</gadget> <output>20</output> <gadget id="calculator">100 * 20</gadget> <output>2_000</output> <result>D</result>
D
2,000
Last year, for every 100 million vehicles that traveled on a certain highway, 100 vehicles were involved in accidents. If 2 billion vehicles traveled on the highway last year, how many of those vehicles were involved in accidents? (1 billion = 1,000,000,000)
{ "A": "500", "B": "1500", "C": "2500", "D": "2000", "E": "1000" }
multiply(100, multiply(2, const_10))
multiply(n2,const_10)|multiply(n1,#0)|
"to solve we will set up a proportion . we know that “ 100 million vehicles is to 100 accidents as 2 billion vehicles is to x accidents ” . to express everything in terms of “ millions ” , we can use 2,000 million rather than 2 billion . creating a proportion we have : 100 / 100 = 2,000 / x cross multiplying gives us : 100 x = 2,000 * 100 x = 20 * 100 = 2000 answer : d"
general
math_qa__gw9kCkUovFQgw04i
the population of locusts in a certain swarm doubles every two hours . if 4 hours ago there were 1000 locusts in the swarm , in approximately how many hours will the swarm population exceed 128000 locusts ? Choose the correct choice from the following choices: A) 12 B) 8 C) 4 D) 10 E) 16
<gadget id="calculator">10 / 2</gadget> <output>5</output> <gadget id="calculator">5 * 2</gadget> <output>10</output> <result>D</result>
D
10
the population of locusts in a certain swarm doubles every two hours . if 4 hours ago there were 1000 locusts in the swarm , in approximately how many hours will the swarm population exceed 128000 locusts ?
{ "A": "12", "B": "8", "C": "4", "D": "10", "E": "16" }
multiply(divide(const_10, const_2), const_2)
divide(const_10,const_2)|multiply(#0,const_2)
- 4 hours : 1,000 - 2 hours : 2,000 now : 4,000 + 2 hours : 8,000 + 4 hours : 16,000 + 6 hours : 32,000 + 8 hours : 64,000 + 10 hours : 128,000 answer : d
general
math_qa__kfAIDtnuwvRQm4Tw
An error 2% in excess is made while measuring the sideofa square. The % of error in the calculated area of the square is? Select A) 4.00 % B) 4.04 % C) 4.16 % D) 4.30 % E) 5 %
<gadget id="calculator">100 + 2</gadget> <output>102</output> <gadget id="calculator">102 * 102</gadget> <output>10_404</output> <gadget id="calculator">100 * 100</gadget> <output>10_000</output> <gadget id="calculator">10_404 - 10_000</gadget> <output>404</output> <gadget id="calculator">404 / 100</gadget> <output>101/25 = around 4.04</output> <result>B</result>
B
4.04
An error 2% in excess is made while measuring the sideofa square. The % of error in the calculated area of the square is?
{ "A": "4.00 %", "B": "4.04 %", "C": "4.16 %", "D": "4.30 %", "E": "5 %" }
divide(subtract(multiply(add(const_100, 2), add(const_100, 2)), multiply(const_100, const_100)), const_100)
add(n0,const_100)|multiply(const_100,const_100)|multiply(#0,#0)|subtract(#2,#1)|divide(#3,const_100)
100 cm is read as 102 cm . a 1 = ( 100 x 100 ) cm 2 and a 2 ( 102 x 102 ) cm 2 . ( a 2 - a 1 ) = [ ( 102 ) 2 - ( 100 ) 2 ] = ( 102 + 100 ) x ( 102 - 100 ) = 404 cm 2 . percentage error = 404 x 100 % = 4.04 % 100 x 100 b
geometry
math_qa__9Lu7Jk1dPNxi9gdL
Of the diplomats attending a summit conference, 22 speak French, 32 do not speak Russian, and 20% of the diplomats speak neither French nor Russian. If 10% of the diplomats speak both languages, then how many diplomats attended the conference? Choose the correct choice from the following choices A) 72 B) 96 C) 100 D) 120 E) 150
<gadget id="calculator">32 - 22</gadget> <output>10</output> <gadget id="calculator">20 / 100</gadget> <output>1/5 = around 0.2</output> <gadget id="calculator">10 / 100</gadget> <output>1/10 = around 0.1</output> <gadget id="calculator">(1/5) - (1/10)</gadget> <output>1/10 = around 0.1</output> <gadget id="calculator">10 / (1/10)</gadget> <output>100</output> <result>C</result>
C
100
Of the diplomats attending a summit conference, 22 speak French, 32 do not speak Russian, and 20% of the diplomats speak neither French nor Russian. If 10% of the diplomats speak both languages, then how many diplomats attended the conference?
{ "A": "72", "B": "96", "C": "100", "D": "120", "E": "150" }
divide(subtract(32, 22), subtract(divide(20, const_100), divide(10, const_100)))
divide(n2,const_100)|divide(n3,const_100)|subtract(n1,n0)|subtract(#0,#1)|divide(#2,#3)|
"{ total } = { french } + { russian } - { both } + { neither } { total } = 22 + ( { total } - 32 ) - ( 0.1 * { total } ) + 0.2 * { total } solving gives { total } = 100 . answer : c ."
other
math_qa__pKUIKqFuBHBHSZbs
A football team lost 5 yards and then gained 10. What is the team's progress? Pick: A) 2 B) 4 C) 5 D) 6 E) 8
<gadget id="calculator">10 - 5</gadget> <output>5</output> <result>C</result>
C
5
A football team lost 5 yards and then gained 10. What is the team's progress?
{ "A": "2", "B": "4", "C": "5", "D": "6", "E": "8" }
subtract(10, 5)
subtract(n1,n0)|
"for lost , use negative . for gain , use positive . progress = - 5 + 10 = 5 yards c"
gain
math_qa__tuGbWmEb2ZKiBIi1
Weights of two friends Ram and Shyam are in the ratio 2:5. If Ram's weight is increased by 10% and total weight of Ram and Shyam become 82.8 kg, with an increases of 15%. By what percent did the weight of Shyam has to be increased? Choose the correct choice from the following: A) 17 % B) 10 % C) 21 % D) 16 % E) none
<gadget id="calculator">15 - 10</gadget> <output>5</output> <gadget id="calculator">2 / 5</gadget> <output>2/5 = around 0.4</output> <gadget id="calculator">5 * (2/5)</gadget> <output>2</output> <gadget id="calculator">15 + 2</gadget> <output>17</output> <result>A</result>
A
17
Weights of two friends Ram and Shyam are in the ratio 2:5. If Ram's weight is increased by 10% and total weight of Ram and Shyam become 82.8 kg, with an increases of 15%. By what percent did the weight of Shyam has to be increased?
{ "A": "17 %", "B": "10 %", "C": "21 %", "D": "16 %", "E": "none" }
add(15, multiply(subtract(15, 10), divide(2, 5)))
divide(n0,n1)|subtract(n4,n2)|multiply(#0,#1)|add(n4,#2)|
"solution : given ratio of ram and shayam ' s weight = 2 : 5 hence , ( x - 15 ) / ( 15 - 10 ) = 2 / 5 or , x = 17 % . answer : option a"
gain
math_qa__S93qD2He4s9CtOij
What is the tens digit of 36^12? Choose the correct option. A) 1 B) 3 C) 5 D) 7 E) 9
<gadget id="calculator">4 + 1</gadget> <output>5</output> <gadget id="calculator">12 % 5</gadget> <output>2</output> <gadget id="calculator">36 ** 2</gadget> <output>1_296</output> <gadget id="calculator">1_296 % 100</gadget> <output>96</output> <gadget id="calculator">96 / 10</gadget> <output>48/5 = around 9.6</output> <gadget id="calculator">floor(48/5)</gadget> <output>9</output> <result>E</result>
E
9
What is the tens digit of 36^12?
{ "A": "1", "B": "3", "C": "5", "D": "7", "E": "9" }
floor(divide(reminder(power(36, reminder(12, add(const_4, const_1))), const_100), const_10))
add(const_1,const_4)|reminder(n1,#0)|power(n0,#1)|reminder(#2,const_100)|divide(#3,const_10)|floor(#4)|
"36 ^ 10 = 6 ^ 24 ( 6 ^ 2 ) = 6 * 6 = 36 ( 6 ^ 3 ) = 36 * 6 = . 16 ( 6 ^ 4 ) = . 16 * 6 = . . 96 ( 6 ^ 5 ) = . . 96 * 6 = . . 76 ( 6 ^ 6 ) = . . 76 * 6 = . . . 56 ( 6 ^ 7 ) = . . . . 56 * 6 = . . . . 36 if you see there is a pattern here in tens digits 3 , 1,9 , 7,5 , 3,1 and so on . . . continue the pattern up to 6 ^ 24 ( dont actually calculate full values ) and answer is e : 9"
general
math_qa__Ujc9gB9DNGX924oW
The area of a triangle is with base 3m and height 4m? Choose the correct choice from the following answers A) 4 m 2 B) 6 m 2 C) 18 m 2 D) 19 m 2 E) 12 m 2
<gadget id="calculator">(3 * 4) / 2</gadget> <output>6</output> <result>B</result>
B
6
The area of a triangle is with base 3m and height 4m?
{ "A": "4 m 2", "B": "6 m 2", "C": "18 m 2", "D": "19 m 2", "E": "12 m 2" }
triangle_area(3, 4)
triangle_area(n0,n1)|
"1 / 2 * 3 * 4 = 6 m 2 answer : b"
geometry
math_qa__rLlsc85OxqfPl7Ds
Calculate 469160 x 9999 = ? Choose the correct choice from the following choices: A) 4691130840 B) 4686970743 C) 4691100843 D) 4586870843 E) none
<gadget id="calculator">469_160 * 9_999</gadget> <output>4_691_130_840</output> <result>A</result>
A
4,691,130,840
Calculate 469160 x 9999 = ?
{ "A": "4691130840", "B": "4686970743", "C": "4691100843", "D": "4586870843", "E": "none" }
multiply(469160, 9999)
multiply(n0,n1)|
"answer 469160 x 9999 = 469160 x ( 10000 - 1 ) = 4691600000 - 469160 = 4691130840 . option : a"
general
math_qa__5x4qxCHsYCYRffQp
The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years, The ratio of the number of boys to the number of girls in the class is : Choose the correct choice from the following. A) 2 : 9 B) 2 : 3 C) 2 : 1 D) 2 : 2 E) 2 : 6
<gadget id="calculator">15.8 - 15.4</gadget> <output>0.4</output> <gadget id="calculator">16.4 - 15.8</gadget> <output>0.6</output> <gadget id="calculator">0.4 / 0.6</gadget> <output>0.666667</output> <result>B</result>
B
0.666667
The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years, The ratio of the number of boys to the number of girls in the class is :
{ "A": "2 : 9", "B": "2 : 3", "C": "2 : 1", "D": "2 : 2", "E": "2 : 6" }
divide(subtract(15.8, 15.4), subtract(16.4, 15.8))
subtract(n0,n2)|subtract(n1,n0)|divide(#0,#1)|
"explanation : let the ratio be k : 1 . then , k * 16.4 + 1 * 15.4 = ( k + 1 ) * 15.8 < = > ( 16.4 - 15.8 ) k = ( 15.8 - 15.4 ) < = > k = 0.4 / 0.6 = 2 / 3 . required ratio = 2 / 3 : 1 = 2 : 3 . answer : b"
general
math_qa__NyVMtJzbsGp7eguK
At what rate percent on simple interest will Rs.850 amount to Rs.950 in 5 years? Choose the correct choice from the following answers. A) 2.35 % B) 5.95 % C) 4.35 % D) 5.33 % E) 6.33 %
<gadget id="calculator">950 - 850</gadget> <output>100</output> <gadget id="calculator">100 / 850</gadget> <output>2/17 = around 0.117647</output> <gadget id="calculator">(2/17) / 5</gadget> <output>2/85 = around 0.023529</output> <gadget id="calculator">(2/85) * 100</gadget> <output>40/17 = around 2.352941</output> <result>A</result>
A
2.35
At what rate percent on simple interest will Rs.850 amount to Rs.950 in 5 years?
{ "A": "2.35 %", "B": "5.95 %", "C": "4.35 %", "D": "5.33 %", "E": "6.33 %" }
multiply(divide(divide(subtract(950, 850), 850), 5), const_100)
subtract(n1,n0)|divide(#0,n0)|divide(#1,n2)|multiply(#2,const_100)|
"100 = ( 850 * 5 * r ) / 100 r = 2.35 % answer : a"
gain
math_qa__y4J1ecZ5TGlgUot5
If 4 people are selected from a group of 9 married couples, what is the probability that none of them would be married to each other? Choose the correct choice from the following options: A) 1 / 33 B) 2 / 85 C) 1 / 3 D) 56 / 85 E) 11 / 85
<gadget id="calculator">9 * 2</gadget> <output>18</output> <gadget id="calculator">18 / 18</gadget> <output>1</output> <gadget id="calculator">4 * 4</gadget> <output>16</output> <gadget id="calculator">18 - 1</gadget> <output>17</output> <gadget id="calculator">16 / 17</gadget> <output>16/17 = around 0.941176</output> <gadget id="calculator">1 * (16/17)</gadget> <output>16/17 = around 0.941176</output> <gadget id="calculator">16 - 2</gadget> <output>14</output> <gadget id="calculator">14 / 16</gadget> <output>7/8 = around 0.875</output> <gadget id="calculator">(16/17) * (7/8)</gadget> <output>14/17 = around 0.823529</output> <gadget id="calculator">14 - 2</gadget> <output>12</output> <gadget id="calculator">16 - 1</gadget> <output>15</output> <gadget id="calculator">12 / 15</gadget> <output>4/5 = around 0.8</output> <gadget id="calculator">(14/17) * (4/5)</gadget> <output>56/85 = around 0.658824</output> <result>D</result>
D
0.658824
If 4 people are selected from a group of 9 married couples, what is the probability that none of them would be married to each other?
{ "A": "1 / 33", "B": "2 / 85", "C": "1 / 3", "D": "56 / 85", "E": "11 / 85" }
multiply(multiply(multiply(divide(multiply(9, const_2), multiply(9, const_2)), divide(multiply(const_4, const_4), subtract(multiply(9, const_2), const_1))), divide(subtract(multiply(const_4, const_4), const_2), multiply(const_4, const_4))), divide(subtract(subtract(multiply(const_4, const_4), const_2), const_2), subtract(multiply(const_4, const_4), const_1)))
multiply(const_4,const_4)|multiply(n1,const_2)|divide(#1,#1)|subtract(#0,const_2)|subtract(#0,const_1)|subtract(#1,const_1)|divide(#3,#0)|divide(#0,#5)|subtract(#3,const_2)|divide(#8,#4)|multiply(#2,#7)|multiply(#6,#10)|multiply(#9,#11)
if we are to select 4 people from 9 couples without any restriction , how many ways can we make the selection ? 18 ! / 4 ! 14 ! = 3060 if we are to select 4 people from 9 couples with restriction that no married couple can both make it to the group , only a representative ? 9 ! / 4 ! 5 ! = 126 but we know that to select a person from each couple , take 2 possibilities 126 * 2 * 2 * 2 * 2 = 2016 probability = desired / all possibilities = 2016 / 3060 = 56 / 85 answer : d
probability
math_qa__mTTQOyW8Y2Q6mv99
Joe went on a diet 4 months ago when he weighed 222 pounds. If he now weighs 198 pounds and continues to lose at the same average monthly rate, in approximately how many months will he weigh 180 pounds? Choices. A) 3 B) 3.5 C) 3 D) 4.5 E) 5
<gadget id="calculator">198 - 180</gadget> <output>18</output> <gadget id="calculator">222 - 198</gadget> <output>24</output> <gadget id="calculator">24 / 4</gadget> <output>6</output> <gadget id="calculator">18 / 6</gadget> <output>3</output> <result>C</result>
C
3
Joe went on a diet 4 months ago when he weighed 222 pounds. If he now weighs 198 pounds and continues to lose at the same average monthly rate, in approximately how many months will he weigh 180 pounds?
{ "A": "3", "B": "3.5", "C": "3", "D": "4.5", "E": "5" }
divide(subtract(198, 180), divide(subtract(222, 198), 4))
subtract(n2,n3)|subtract(n1,n2)|divide(#1,n0)|divide(#0,#2)
222 - 198 = 24 pounds lost in 4 months 24 / 4 = 6 , so joe is losing weight at a rate of 6 pounds per month . . . . in approximately how many months will he weigh 180 pounds ? a simple approach is to just list the weights . now : 198 lbs in 1 month : 192 lbs in 2 months : 186 lbs in 3 months : 180 lbs answer : c
general
math_qa__yWzTvxm0tiJcfzjy
If the perimeter of a rectangular stadium is 800 m, its length when its breadth is 300 m is? Pick one A) 500 B) 400 C) 300 D) 200 E) 100
<gadget id="calculator">800 / 2</gadget> <output>400</output> <gadget id="calculator">400 - 300</gadget> <output>100</output> <result>E</result>
E
100
If the perimeter of a rectangular stadium is 800 m, its length when its breadth is 300 m is?
{ "A": "500", "B": "400", "C": "300", "D": "200", "E": "100" }
subtract(divide(800, const_2), 300)
divide(n0,const_2)|subtract(#0,n1)|
2 ( l + 300 ) = 800 = > l = 100 m answer : e
physics
math_qa__AyYQDbonqmb6iYKD
The ratio between the current age of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years? Choose the correct choice from the following: A) 7 : 8 B) 8 : 9 C) 4 : 6 D) 4 : 8 E) 5 : 8
<gadget id="calculator">6 * 4</gadget> <output>24</output> <gadget id="calculator">24 + 4</gadget> <output>28</output> <gadget id="calculator">28 + 4</gadget> <output>32</output> <gadget id="calculator">28 / 32</gadget> <output>7/8 = around 0.875</output> <result>A</result>
A
0.875
The ratio between the current age of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years?
{ "A": "7 : 8", "B": "8 : 9", "C": "4 : 6", "D": "4 : 8", "E": "5 : 8" }
divide(add(multiply(6, 4), 4), add(add(multiply(6, 4), 4), 4))
multiply(n0,n2)|add(n2,#0)|add(n2,#1)|divide(#1,#2)
a 7 : 8 if a ’ s age and b ’ s age will be 6 a years and 7 a years correspondingly then , 7 a – 6 a = 4 a = 4 needed ratio = ( 6 a + 4 ) : ( 7 a + 4 ) = 28 : 32 = 7 : 8
other
math_qa__m0buMGGvXwBoobQ5
The milk level in a rectangular box measuring 56 feet by 25 feet is to be lowered by 6 inches. How many gallons of milk must be removed? (1 cu ft = 7.5 gallons) Choose the correct choice from the following choices: A) 100 B) 250 C) 750 D) 5250 E) 5635
<gadget id="calculator">56 * 25</gadget> <output>1_400</output> <gadget id="calculator">1 / 2</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">1_400 * (1/2)</gadget> <output>700</output> <gadget id="calculator">700 * 7.5</gadget> <output>5_250</output> <result>D</result>
D
5,250
The milk level in a rectangular box measuring 56 feet by 25 feet is to be lowered by 6 inches. How many gallons of milk must be removed? (1 cu ft = 7.5 gallons)
{ "A": "100", "B": "250", "C": "750", "D": "5250", "E": "5635" }
multiply(multiply(multiply(56, 25), divide(1, const_2)), 7.5)
divide(n3,const_2)|multiply(n0,n1)|multiply(#0,#1)|multiply(n4,#2)|
"6 inches = 1 / 2 feet ( there are 12 inches in a foot . ) , so 56 * 25 * 1 / 2 = 700 feet ^ 3 of milk must be removed , which equals to 700 * 7.5 = 5250 gallons . answer : d ."
general
math_qa__3C99fnxUcNQa5oJN
How many quarters are equal to 3 dollars? Choose the correct option: A) 1 B) 8 C) 12 D) 9 E) 7
<gadget id="calculator">3 * 4</gadget> <output>12</output> <result>C</result>
C
12
How many quarters are equal to 3 dollars?
{ "A": "1", "B": "8", "C": "12", "D": "9", "E": "7" }
multiply(3, const_4)
multiply(n0,const_4)|
"3 * 4 = 12 quarters answer : c"
general
math_qa__2NVEDDU5ReUw1RRC
The purchase price of an article is $48. In order to include 20% of cost for overhead and to provide $12 of net profit, the markup should be Choose the correct answer A) 15 % B) 25 % C) 35 % D) 40 % E) 45 %
<gadget id="calculator">12 / 48</gadget> <output>1/4 = around 0.25</output> <gadget id="calculator">(1/4) * 100</gadget> <output>25</output> <gadget id="calculator">25 + 20</gadget> <output>45</output> <result>E</result>
E
45
The purchase price of an article is $48. In order to include 20% of cost for overhead and to provide $12 of net profit, the markup should be
{ "A": "15 %", "B": "25 %", "C": "35 %", "D": "40 %", "E": "45 %" }
add(multiply(divide(12, 48), const_100), 20)
divide(n2,n0)|multiply(#0,const_100)|add(n1,#1)|
"cost price of article = 48 $ % of overhead cost = 20 net profit = 12 $ we need to calculate % markup net profit as % of cost price = ( 12 / 48 ) * 100 = 25 % total markup should be = 25 + 20 = 45 % answer e"
gain
math_qa__wtaXVjYCTc9l8ahs
Pipe A can fill a tank in 10 hrs and pipe B can fill it in 8 hrs. If both the pipes are opened in the empty tank.There is an outlet pipe in 3/4 th of the tank. In how many hours will it be fill 3/4th of that tank? Select. A) 3 hr B) 3.10 hr C) 3.15 hr D) 3.20 hr E) 3.30 hr
<gadget id="calculator">3 / 4</gadget> <output>3/4 = around 0.75</output> <gadget id="calculator">1 / 10</gadget> <output>1/10 = around 0.1</output> <gadget id="calculator">1 / 8</gadget> <output>1/8 = around 0.125</output> <gadget id="calculator">(1/10) + (1/8)</gadget> <output>9/40 = around 0.225</output> <gadget id="calculator">1 / (9/40)</gadget> <output>40/9 = around 4.444444</output> <gadget id="calculator">(3/4) * (40/9)</gadget> <output>10/3 = around 3.333333</output> <result>D</result>
D
3.2
Pipe A can fill a tank in 10 hrs and pipe B can fill it in 8 hrs. If both the pipes are opened in the empty tank.There is an outlet pipe in 3/4 th of the tank. In how many hours will it be fill 3/4th of that tank?
{ "A": "3 hr", "B": "3.10 hr", "C": "3.15 hr", "D": "3.20 hr", "E": "3.30 hr" }
multiply(divide(3, 4), inverse(add(divide(const_1, 10), divide(const_1, 8))))
divide(n2,n3)|divide(const_1,n0)|divide(const_1,n1)|add(#1,#2)|inverse(#3)|multiply(#0,#4)
part filled a in 1 hr = ( 1 / 10 ) part filled b in 1 hr = ( 1 / 8 ) part filled by ( a + b ) together in 1 hr = ( 1 / 10 ) + ( 1 / 8 ) = 18 / 80 so , the tank will be full in 80 / 18 hrs . time taken to fill exact 3 / 4 th of the tank = ( 80 / 18 ) * ( 3 / 4 ) = 3.20 hrs answer : d
physics
math_qa__GzqkoXBbujv8NEki
A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 30 as remainder. Find the no. is? Options A) 122443 B) 154546 C) 165454 D) 186545 E) 220030
<gadget id="calculator">555 + 445</gadget> <output>1_000</output> <gadget id="calculator">1_000 * 2</gadget> <output>2_000</output> <gadget id="calculator">555 - 445</gadget> <output>110</output> <gadget id="calculator">2_000 * 110</gadget> <output>220_000</output> <gadget id="calculator">220_000 + 30</gadget> <output>220_030</output> <result>E</result>
E
220,030
A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 30 as remainder. Find the no. is?
{ "A": "122443", "B": "154546", "C": "165454", "D": "186545", "E": "220030" }
add(multiply(multiply(add(555, 445), 2), subtract(555, 445)), 30)
add(n0,n1)|subtract(n0,n1)|multiply(n2,#0)|multiply(#2,#1)|add(n3,#3)|
"( 555 + 445 ) * 2 * 110 + 30 = 220000 + 30 = 220030 e"
general
math_qa__6cVYscgGO0Mdcx4c
There are some rabbits and peacocks in a zoo. The total number of their heads is 60 and total number of their legs is 192. Find the number of total rabbits? Choices A) 36 B) 77 C) 88 D) 99 E) 22
<gadget id="calculator">2 * 60</gadget> <output>120</output> <gadget id="calculator">192 - 120</gadget> <output>72</output> <gadget id="calculator">4 - 2</gadget> <output>2</output> <gadget id="calculator">72 / 2</gadget> <output>36</output> <result>A</result>
A
36
There are some rabbits and peacocks in a zoo. The total number of their heads is 60 and total number of their legs is 192. Find the number of total rabbits?
{ "A": "36", "B": "77", "C": "88", "D": "99", "E": "22" }
divide(subtract(192, multiply(const_2, 60)), subtract(const_4, const_2))
multiply(n0,const_2)|subtract(const_4,const_2)|subtract(n1,#0)|divide(#2,#1)
let the number of rabbits and peacocks be ' r ' and ' p ' respectively . as each animal has only one head , so r + p = 60 - - - ( 1 ) each rabbit has 4 legs and each peacock has 2 legs . total number of legs of rabbits and peacocks , 4 r + 2 p = 192 - - - ( 2 ) multiplying equation ( 1 ) by 2 and subtracting it from equation ( 2 ) , we get = > 2 r = 72 = > r = 36 . answer : a
general
math_qa__Le11U5Ngz64CH9AQ
A person can row at 10 kmph in still water. If the velocity of the current is 2 kmph and it takes him 10 hour to row to a place and come back, how far is the place? Choices A) 24 km B) 30 km C) 48 km D) 12 km E) 48 km
<gadget id="calculator">10 - 2</gadget> <output>8</output> <gadget id="calculator">10 + 2</gadget> <output>12</output> <gadget id="calculator">8 * 12</gadget> <output>96</output> <gadget id="calculator">96 * 10</gadget> <output>960</output> <gadget id="calculator">8 + 12</gadget> <output>20</output> <gadget id="calculator">960 / 20</gadget> <output>48</output> <result>E</result>
E
48
A person can row at 10 kmph in still water. If the velocity of the current is 2 kmph and it takes him 10 hour to row to a place and come back, how far is the place?
{ "A": "24 km", "B": "30 km", "C": "48 km", "D": "12 km", "E": "48 km" }
divide(multiply(multiply(subtract(10, 2), add(10, 2)), 10), add(subtract(10, 2), add(10, 2)))
add(n0,n1)|subtract(n0,n1)|add(#0,#1)|multiply(#0,#1)|multiply(n2,#3)|divide(#4,#2)|
"speed of down stream = 10 + 2 = 12 kmph speed of upstream = 10 - 2 = 8 kmph let the required distance be xkm x / 12 + x / 8 = 10 2 x + 3 x = 240 x = 48 km answer is e"
physics
math_qa__i4h7AqFQucAoGtII
From a group of 3 boys and 3 girls, 2 children are to be randomly selected. What is the probability that 1 boy and 1 girl will be selected? Choose the correct option. A) 1 / 10 B) 4 / 9 C) 1 / 2 D) 9 / 15 E) 2 / 3
<gadget id="calculator">binomial(3, 2)</gadget> <output>3</output> <gadget id="calculator">3 * 3</gadget> <output>9</output> <gadget id="calculator">3 + 3</gadget> <output>6</output> <gadget id="calculator">binomial(6, 2)</gadget> <output>15</output> <gadget id="calculator">9 / 15</gadget> <output>3/5 = around 0.6</output> <result>D</result>
D
0.6
From a group of 3 boys and 3 girls, 2 children are to be randomly selected. What is the probability that 1 boy and 1 girl will be selected?
{ "A": "1 / 10", "B": "4 / 9", "C": "1 / 2", "D": "9 / 15", "E": "2 / 3" }
divide(multiply(choose(3, const_2), choose(3, const_2)), choose(add(3, 3), 2))
add(n0,n0)|choose(n0,const_2)|choose(n0,const_2)|choose(#0,n2)|multiply(#1,#2)|divide(#4,#3)|
"the total number of ways to choose 2 children from 6 is 6 c 2 = 15 the number of ways to choose 1 boy and 1 girl is 3 * 3 = 9 p ( 1 boy and 1 girl ) = 9 / 15 the answer is d ."
probability
math_qa__m3fNOJopByrTqgmY
(169)^2 - (168)^2 = Choose the correct choice from the following answers: A) 1 B) 100 C) 229 D) 329 E) 337
<gadget id="calculator">169 ** 2</gadget> <output>28_561</output> <gadget id="calculator">168 ** 2</gadget> <output>28_224</output> <gadget id="calculator">28_561 - 28_224</gadget> <output>337</output> <result>E</result>
E
337
(169)^2 - (168)^2 =
{ "A": "1", "B": "100", "C": "229", "D": "329", "E": "337" }
subtract(power(169, 2), power(168, 2))
power(n0,n1)|power(n2,n1)|subtract(#0,#1)
using the formula : ( a + 1 ) ^ 2 - a ^ 2 = 2 a + 1 so , answer = 168 * 2 + 1 = 336 + 1 = 337 = answer = e
general