role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
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volunteer | or P and Q are polynomials in X and PFU obviously can't, can't be have a root, can't have a root. | 15,082 | 124 | [] |
volunteer | that will um | 15,082 | 125 | [] |
volunteer | affect the expression. | 15,082 | 126 | [] |
volunteer | Actually, that's not right. I can't say it can't have fruits it's just that it, we don't consider | 15,082 | 127 | [] |
volunteer | the times when uh P(x) has the root. We just don't include that in our domain. | 15,082 | 128 | [] |
volunteer | cause we know that they'll be undefined. | 15,082 | 129 | [] |
volunteer | Um, and this is assuming you can't just | 15,082 | 130 | [] |
volunteer | factor out and then get rid of the term. | 15,082 | 131 | [] |
volunteer | It just won't be, it just be irrational at that point. | 15,082 | 132 | [] |
volunteer | So you can factor out and get rid of the roots. | 15,082 | 133 | [] |
student | oh okay | 15,082 | 134 | [] |
volunteer | Anyway. | 15,082 | 135 | [] |
volunteer | Um, so if the degree of PF X | 15,082 | 136 | [] |
volunteer | is less than q of x. | 15,082 | 137 | [] |
volunteer | the rational fraction is called proper. | 15,082 | 138 | [] |
volunteer | Right, because just like we have our um | 15,082 | 139 | [] |
volunteer | fractions by itself, when we have a fraction that is, that has a numerator that is smaller than the denominator, we call that a proper fraction. | 15,082 | 140 | [] |
volunteer | right? Because you can't divide anymore. | 15,082 | 141 | [] |
student | right | 15,082 | 142 | [] |
volunteer | Whereas if the numerator is greater than the the denominator, then you have an improper fraction because then you can | 15,082 | 143 | [] |
volunteer | pull it out like, you know, 4/3, something like that, and you can, it's like 1 and 1/3, um | 15,082 | 144 | [] |
volunteer | you get the point | 15,082 | 145 | [] |
volunteer | So the improper, so it's otherwise, OK, the improper or rational facts could be reduced to the proper rational right. | 15,082 | 146 | [] |
volunteer | Function by long division process. Thus, if POX is improper, then P over Q is equal tot of X + R(x) over Q of X. | 15,082 | 147 | [] |
volunteer | which is um realizing now important. | 15,082 | 148 | [] |
volunteer | I was trying to do a problem and it gave me this and I | 15,082 | 149 | [] |
volunteer | feel like I applied it wrong. | 15,082 | 150 | [] |
volunteer | Anyway. | 15,082 | 151 | [] |
volunteer | TFX is a polynomial in X and | 15,082 | 152 | [] |
volunteer | R(x) over Qx is a proper rational fraction. | 15,082 | 153 | [] |
volunteer | as we know how to integrate polynomials, the integration of any rational function is reduced to the integration of a proper rational function. | 15,082 | 154 | [] |
volunteer | So basically, if you get a | 15,082 | 155 | [] |
volunteer | um | 15,082 | 156 | [] |
volunteer | rational function | 15,082 | 157 | [] |
volunteer | and you find that the degree of the enumerator is greater than the degree of the denominator | 15,082 | 158 | [] |
volunteer | Then you perform long division. | 15,082 | 159 | [] |
volunteer | to get a form. | 15,082 | 160 | [] |
volunteer | um to get a uh | 15,082 | 161 | [] |
volunteer | the function into a form of a proper function. | 15,082 | 162 | [] |
volunteer | right? So that PE is always equal to or less than q. The the degree, I'm sorry. | 15,082 | 163 | [] |
volunteer | I think specifically it has to be | 15,082 | 164 | [] |
volunteer | it doesn't say what happens when the degrees are equal to each other. | 15,082 | 165 | [] |
volunteer | We're just assuming from the table | 15,082 | 166 | [] |
volunteer | that | 15,082 | 167 | [] |
student | wait, can i get 5 mins pls | 15,082 | 168 | [] |
volunteer | the degree of the numerator | 15,082 | 169 | [] |
volunteer | yeah | 15,082 | 170 | [] |
volunteer | take your time | 15,082 | 171 | [] |
volunteer | Mhm | 15,082 | 172 | [] |
student | i'm back | 15,082 | 173 | [] |
volunteer | Welcome back. | 15,082 | 174 | [] |
student | thank you! | 15,082 | 175 | [] |
volunteer | Hm | 15,082 | 176 | [] |
student | let's continue | 15,082 | 177 | [] |
volunteer | Yeah, um. | 15,082 | 178 | [] |
volunteer | so | 15,082 | 179 | [] |
volunteer | what um | 15,082 | 180 | [] |
volunteer | so I said, I, I went right where we left off. So thus, if P over q is improper, i.e. | 15,082 | 181 | [] |
volunteer | that | 15,082 | 182 | [] |
volunteer | um | 15,082 | 183 | [] |
volunteer | if | 15,082 | 184 | [] |
volunteer | oh, OK, if, if the degree of P | 15,082 | 185 | [] |
volunteer | is greater than or equal to | 15,082 | 186 | [] |
volunteer | the degree of Q | 15,082 | 187 | [] |
volunteer | then their function is called proper. | 15,082 | 188 | [] |
volunteer | and if it's improper | 15,082 | 189 | [] |
volunteer | then we need to um | 15,082 | 190 | [] |
volunteer | do long division to make sure that P over q is improper, which means that | 15,082 | 191 | [] |
volunteer | even if P has the same degree as Q. | 15,082 | 192 | [] |
volunteer | you have to perform long you have to perform long division to get | 15,082 | 193 | [] |
volunteer | this form | 15,082 | 194 | [] |
volunteer | to be able to make it um | 15,082 | 195 | [] |
volunteer | integradable, eat more or, or be able to redefine it such that it's easier to integrate. | 15,082 | 196 | [] |
student | convert into mixed fraction? | 15,082 | 197 | [] |
volunteer | kind of | 15,082 | 198 | [] |
volunteer | Yeah, you want to convert it into mixed fraction, basically. | 15,082 | 199 | [] |
student | okay | 15,082 | 200 | [] |
volunteer | Yeah | 15,082 | 201 | [] |
volunteer | Um | 15,082 | 202 | [] |
volunteer | yeah, it's, and then, uh, let's see. And R(x) is a polynomial inex. | 15,082 | 203 | [] |
volunteer | P Q y over Q is a proper rational function, as we know how to integrate polynomials, integration of inter rational function is reduced to the integration of a proper rational function. | 15,082 | 204 | [] |
volunteer | So they're saying that integration of any rational function. | 15,082 | 205 | [] |
volunteer | can be reduced to the innovation of a proper rational function or saying more than likely that they're saying that you pretty much have to do it. | 15,082 | 206 | [] |
volunteer | The rational fractions, which | 15,082 | 207 | [] |
volunteer | we shall consider here for integration purposes will be those whose denominators can be factored into linear and quadratic factors. | 15,082 | 208 | [] |
volunteer | So it's saying right here that the ones that they will consider, means that there are other forms with higher degree denominators, but they're just only considering linear and 1st and 2nd order. | 15,082 | 209 | [] |
volunteer | denominators | 15,082 | 210 | [] |
student | ohh okay | 15,082 | 211 | [] |
volunteer | And then assuming we want to evaluate where P overq is a proper rational function it's always possible to write the innergra. | 15,082 | 212 | [] |
volunteer | as the sum of simpler rational functions by using partial fraction decomposition, which is basically what you're saying. | 15,082 | 213 | [] |
volunteer | Um, kind of | 15,082 | 214 | [] |
volunteer | you know, if it's greater, then you have to kind of mixed fractions, um, but | 15,082 | 215 | [] |
volunteer | just trying to write it as something that's more understandable. | 15,082 | 216 | [] |
volunteer | Then after this, the integration could be carried out easily using the already known methods, and that's the | 15,082 | 217 | [] |
volunteer | big thing here, the past few chapters, it's just they've been giving you known methods. | 15,082 | 218 | [] |
volunteer | right? All these different tools | 15,082 | 219 | [] |
volunteer | so if you can figure out how | 15,082 | 220 | [] |
volunteer | the, the square peg can fit this can fit the whole. | 15,082 | 221 | [] |
volunteer | then, you know | 15,082 | 222 | [] |
volunteer | it certainly helps to | 15,082 | 223 | [] |
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