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8
student
4?
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volunteer
Now that we have 9 in the first half, are there the same amount on both sides of the second line you drew?
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student
oh i see
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student
mhm
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student
yepp
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student
do 3?
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volunteer
You're still making 4 groups but we're gonna split the 1st half and then the second half
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volunteer
We're splitting the first 9 right now and since 9 is odd we have to exclude the number in the middle of the 9
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student
Ok
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student
lik this or?
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student
sorry im rlly trying to understand
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student
hello?
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volunteer
Sorry I had to do something real quick
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student
its ok
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volunteer
Do you remember the 1st problem we did where it was 17 numbers?
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student
yes
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student
41 was split
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volunteer
Yeah
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volunteer
We had to do that because it's odd so to split it in half we don't include the middle number
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student
mhm
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volunteer
Here since we're splitting 9 numbers into half it's the same thing
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volunteer
We have to take out the middle number like we took out 41 earlier to split it in half
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student
ok
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student
so split 66?
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volunteer
Splitting the whole thing in half was splitting 18 so we don't split any numbers, after that we're splitting 9 numbers so we split the 59
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volunteer
If what you're splitting is odd you split the middle number if it's even you don't
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student
can you do it on the board bc im still not getting it
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volunteer
Okay
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volunteer
We started by splitting the 18 numbers in half and since 18 is even we don't split the middle number and just draw a line between the 66s
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volunteer
Now there's 9 numbers on one side (50 55 56 57 59 59 60 65 66) and 9 on the other (66 69 70 72 74 75 81 81 85)
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student
Ok I see
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volunteer
Now we split the first 9 numbers in half and since 9 is odd we split the middle number(the first 59) so one side is 50 55 56 57 and one is 59 60 65 66
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volunteer
Same thing with the second half
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student
ok I see
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student
58 for 57 & 59?
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volunteer
This time the line is on 59 so Q1 is just 59
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student
ok
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student
samething for 4?
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student
74
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volunteer
Yeah
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student
ok so its
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student
50, 66, 74, and 85
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volunteer
You forgot Q1 but those are right
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student
i mean 50, 59, 66, 74, 85
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volunteer
Yeah that's perfect
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student
thank you!
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volunteer
hello
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student
Hi, I wanted your help with a question like Find (f⋅g)(x) when f(x)=x^2+4x−21 and g(x)=3/x^2−9
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volunteer
okay give me one moment
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student
Wait how did you do that?
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volunteer
give me one sec im going to write it out then explain
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volunteer
okay so in step one we multiple the numerator
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volunteer
so 3 * x^2 +4x-21
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student
Why 3?
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volunteer
the g(x)= 3/x^2 -9
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volunteer
the numerator you provided shows a three
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student
Right will that be it all the time?
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volunteer
yes
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student
Okay got it
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volunteer
if it makes it easier you can also do this
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volunteer
so you see how i wrote a one under the f(x)?
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student
Yes
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student
I'm sorry, I am getting a call. I'll be back in 2 minutes
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volunteer
if you make it into a fraction it is easy to remember to multiple across
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volunteer
no worries
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volunteer
ill be here
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student
Okay I'm back
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volunteer
welcome back
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student
Thank you.
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volunteer
so you see how it is easy to multiply across when you make the f(x) a fraction also
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student
Yes
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volunteer
okay so then we need to factor (x^2+4x-21)
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volunteer
do you know how?
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volunteer
or would you like me to explain how
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student
Right I have problems with factoring. I can never remember how to
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volunteer
oh okay well what we are looking for is two number which can add up to "B" or in this situation 4 and those same numbers must multiply to be "C" or in this situation -21
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student
7 and -3
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volunteer
so if we take 7 and 3 that would multiply to 21 but it would not add to 4. thus we need to make the 3 negative so we get +4 and -21. if we did it where the 7 is negative then we get -4 and -21 which would be incorrect
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volunteer
does that make sense?
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student
Yes
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volunteer
okay so you would do the same with the denominator which is (x^2-9)
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student
Right how do we do this since nothing equals x^2
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volunteer
3 x 3 = 9 but we need it to be negative thus we make one of the threes negative
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volunteer
so the important thing you need to learn moving forward is the formula
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volunteer
so x^2+bx+c
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volunteer
so since the 9 has no x next to is we know it is c
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volunteer
does that make sense
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student
Yes what is bx though?
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volunteer
there is no bx so if it helps you understand it better you can make it a 0x
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volunteer
so then you need two numbers which would add to 0 and multiply to -9
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volunteer
thus 3-3=0 3 * -3= -9
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student
Okay got it
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volunteer
do you want me to write it out and explain it on the board?
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volunteer
does it make sense?
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student
I think so.
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volunteer
im going to continue explaining but im going to return to this when we finish so i can give you another example to help you get it
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volunteer
so then in step two we see what is the same and cancel it out
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student
Right
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volunteer
which then leaves us with 3(x+7)/(x+3)
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student
I understand that. Why does x not equal plus or negative 3?
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