role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
student | 4? | 18,181 | 235 | [] |
volunteer | Now that we have 9 in the first half, are there the same amount on both sides of the second line you drew? | 18,181 | 236 | [] |
student | oh i see | 18,181 | 237 | [] |
student | mhm | 18,181 | 238 | [] |
student | yepp | 18,181 | 239 | [] |
student | do 3? | 18,181 | 240 | [] |
volunteer | You're still making 4 groups but we're gonna split the 1st half and then the second half | 18,181 | 241 | [] |
volunteer | We're splitting the first 9 right now and since 9 is odd we have to exclude the number in the middle of the 9 | 18,181 | 242 | [] |
student | Ok | 18,181 | 243 | [] |
student | lik this or? | 18,181 | 244 | [] |
student | sorry im rlly trying to understand | 18,181 | 245 | [] |
student | hello? | 18,181 | 246 | [] |
volunteer | Sorry I had to do something real quick | 18,181 | 247 | [] |
student | its ok | 18,181 | 248 | [] |
volunteer | Do you remember the 1st problem we did where it was 17 numbers? | 18,181 | 249 | [] |
student | yes | 18,181 | 250 | [] |
student | 41 was split | 18,181 | 251 | [] |
volunteer | Yeah | 18,181 | 252 | [] |
volunteer | We had to do that because it's odd so to split it in half we don't include the middle number | 18,181 | 253 | [] |
student | mhm | 18,181 | 254 | [] |
volunteer | Here since we're splitting 9 numbers into half it's the same thing | 18,181 | 255 | [] |
volunteer | We have to take out the middle number like we took out 41 earlier to split it in half | 18,181 | 256 | [] |
student | ok | 18,181 | 257 | [] |
student | so split 66? | 18,181 | 258 | [] |
volunteer | Splitting the whole thing in half was splitting 18 so we don't split any numbers, after that we're splitting 9 numbers so we split the 59 | 18,181 | 259 | [] |
volunteer | If what you're splitting is odd you split the middle number if it's even you don't | 18,181 | 260 | [] |
student | can you do it on the board bc im still not getting it | 18,181 | 261 | [] |
volunteer | Okay | 18,181 | 262 | [] |
volunteer | We started by splitting the 18 numbers in half and since 18 is even we don't split the middle number and just draw a line between the 66s | 18,181 | 263 | [] |
volunteer | Now there's 9 numbers on one side (50 55 56 57 59 59 60 65 66) and 9 on the other (66 69 70 72 74 75 81 81 85) | 18,181 | 264 | [] |
student | Ok I see | 18,181 | 265 | [] |
volunteer | Now we split the first 9 numbers in half and since 9 is odd we split the middle number(the first 59) so one side is 50 55 56 57 and one is 59 60 65 66 | 18,181 | 266 | [] |
volunteer | Same thing with the second half | 18,181 | 267 | [] |
student | ok I see | 18,181 | 268 | [] |
student | 58 for 57 & 59? | 18,181 | 269 | [] |
volunteer | This time the line is on 59 so Q1 is just 59 | 18,181 | 270 | [] |
student | ok | 18,181 | 271 | [] |
student | samething for 4? | 18,181 | 272 | [] |
student | 74 | 18,181 | 273 | [] |
volunteer | Yeah | 18,181 | 274 | [] |
student | ok so its | 18,181 | 275 | [] |
student | 50, 66, 74, and 85 | 18,181 | 276 | [] |
volunteer | You forgot Q1 but those are right | 18,181 | 277 | [] |
student | i mean 50, 59, 66, 74, 85 | 18,181 | 278 | [] |
volunteer | Yeah that's perfect | 18,181 | 279 | [] |
student | thank you! | 18,181 | 280 | [] |
volunteer | hello | 18,189 | 0 | [] |
student | Hi, I wanted your help with a question like Find (f⋅g)(x) when f(x)=x^2+4x−21 and g(x)=3/x^2−9 | 18,189 | 1 | [] |
volunteer | okay give me one moment | 18,189 | 2 | [] |
student | Wait how did you do that? | 18,189 | 3 | [] |
volunteer | give me one sec im going to write it out then explain | 18,189 | 4 | [] |
volunteer | okay so in step one we multiple the numerator | 18,189 | 5 | [] |
volunteer | so 3 * x^2 +4x-21 | 18,189 | 6 | [] |
student | Why 3? | 18,189 | 7 | [] |
volunteer | the g(x)= 3/x^2 -9 | 18,189 | 8 | [] |
volunteer | the numerator you provided shows a three | 18,189 | 9 | [] |
student | Right will that be it all the time? | 18,189 | 10 | [] |
volunteer | yes | 18,189 | 11 | [] |
student | Okay got it | 18,189 | 12 | [] |
volunteer | if it makes it easier you can also do this | 18,189 | 13 | [] |
volunteer | so you see how i wrote a one under the f(x)? | 18,189 | 14 | [] |
student | Yes | 18,189 | 15 | [] |
student | I'm sorry, I am getting a call. I'll be back in 2 minutes | 18,189 | 16 | [] |
volunteer | if you make it into a fraction it is easy to remember to multiple across | 18,189 | 17 | [] |
volunteer | no worries | 18,189 | 18 | [] |
volunteer | ill be here | 18,189 | 19 | [] |
student | Okay I'm back | 18,189 | 20 | [] |
volunteer | welcome back | 18,189 | 21 | [] |
student | Thank you. | 18,189 | 22 | [] |
volunteer | so you see how it is easy to multiply across when you make the f(x) a fraction also | 18,189 | 23 | [] |
student | Yes | 18,189 | 24 | [] |
volunteer | okay so then we need to factor (x^2+4x-21) | 18,189 | 25 | [] |
volunteer | do you know how? | 18,189 | 26 | [] |
volunteer | or would you like me to explain how | 18,189 | 27 | [] |
student | Right I have problems with factoring. I can never remember how to | 18,189 | 28 | [] |
volunteer | oh okay well what we are looking for is two number which can add up to "B" or in this situation 4 and those same numbers must multiply to be "C" or in this situation -21 | 18,189 | 29 | [] |
student | 7 and -3 | 18,189 | 30 | [] |
volunteer | so if we take 7 and 3 that would multiply to 21 but it would not add to 4. thus we need to make the 3 negative so we get +4 and -21. if we did it where the 7 is negative then we get -4 and -21 which would be incorrect | 18,189 | 31 | [] |
volunteer | does that make sense? | 18,189 | 32 | [] |
student | Yes | 18,189 | 33 | [] |
volunteer | okay so you would do the same with the denominator which is (x^2-9) | 18,189 | 34 | [] |
student | Right how do we do this since nothing equals x^2 | 18,189 | 35 | [] |
volunteer | 3 x 3 = 9 but we need it to be negative thus we make one of the threes negative | 18,189 | 36 | [] |
volunteer | so the important thing you need to learn moving forward is the formula | 18,189 | 37 | [] |
volunteer | so x^2+bx+c | 18,189 | 38 | [] |
volunteer | so since the 9 has no x next to is we know it is c | 18,189 | 39 | [] |
volunteer | does that make sense | 18,189 | 40 | [] |
student | Yes what is bx though? | 18,189 | 41 | [] |
volunteer | there is no bx so if it helps you understand it better you can make it a 0x | 18,189 | 42 | [] |
volunteer | so then you need two numbers which would add to 0 and multiply to -9 | 18,189 | 43 | [] |
volunteer | thus 3-3=0 3 * -3= -9 | 18,189 | 44 | [] |
student | Okay got it | 18,189 | 45 | [] |
volunteer | do you want me to write it out and explain it on the board? | 18,189 | 46 | [] |
volunteer | does it make sense? | 18,189 | 47 | [] |
student | I think so. | 18,189 | 48 | [] |
volunteer | im going to continue explaining but im going to return to this when we finish so i can give you another example to help you get it | 18,189 | 49 | [] |
volunteer | so then in step two we see what is the same and cancel it out | 18,189 | 50 | [] |
student | Right | 18,189 | 51 | [] |
volunteer | which then leaves us with 3(x+7)/(x+3) | 18,189 | 52 | [] |
student | I understand that. Why does x not equal plus or negative 3? | 18,189 | 53 | [] |
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