role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | so the best way to explain it is the denominator can never be 0 | 18,189 | 54 | [] |
volunteer | x-3=0 and x+3=0 is not possible thus x cannot equal - or + 3 | 18,189 | 55 | [] |
volunteer | does this make sense | 18,189 | 56 | [] |
student | Yes | 18,189 | 57 | [] |
volunteer | okay so going back to the example | 18,189 | 58 | [] |
student | Could I try this one on my own | 18,189 | 59 | [] |
volunteer | yes | 18,189 | 60 | [] |
volunteer | okay so in fx what is b and what is c | 18,189 | 61 | [] |
student | 5x and -14 | 18,189 | 62 | [] |
volunteer | perfect | 18,189 | 63 | [] |
student | So it needs to add to 5 and multiply to -14 | 18,189 | 64 | [] |
volunteer | add to -5 and multiply to -14 | 18,189 | 65 | [] |
student | Right | 18,189 | 66 | [] |
volunteer | you have to be careful with those thats how they like to trick you on a test | 18,189 | 67 | [] |
volunteer | okay you can continue | 18,189 | 68 | [] |
volunteer | let me know if you have questions | 18,189 | 69 | [] |
student | Is that right? | 18,189 | 70 | [] |
volunteer | yes | 18,189 | 71 | [] |
volunteer | youre doing great | 18,189 | 72 | [] |
student | Would it be (x+4)(x-4) | 18,189 | 73 | [] |
volunteer | correct | 18,189 | 74 | [] |
student | Got it | 18,189 | 75 | [] |
student | I have nothing to cancel | 18,189 | 76 | [] |
volunteer | you need one more thing for your final answer | 18,189 | 77 | [] |
volunteer | that is okay sometimes there wont be anything to cancel out | 18,189 | 78 | [] |
student | Is that correct | 18,189 | 79 | [] |
volunteer | so what you have would stay the same and then you would also state the x does not equal + or -4 | 18,189 | 80 | [] |
volunteer | you got it | 18,189 | 81 | [] |
student | Okay great. Can I try one more | 18,189 | 82 | [] |
volunteer | sure thing | 18,189 | 83 | [] |
volunteer |
there you go | 18,189 | 84 | [] |
student | Is that correct? | 18,189 | 85 | [] |
volunteer | yes | 18,189 | 86 | [] |
volunteer | Good job | 18,189 | 87 | [] |
volunteer | great | 18,189 | 88 | [] |
student | That made it alot easier. Thank you so much | 18,189 | 89 | [] |
student | Do you have anymore time? | 18,189 | 90 | [] |
volunteer | no problem im glad i made it easier to understand | 18,189 | 91 | [] |
volunteer | yes i have a bit more time | 18,189 | 92 | [] |
volunteer | if you dont mind when we finish our session please leave a positive review for me :) | 18,189 | 93 | [] |
student | Determine the domain of the function: x-7/4x^2 -3x - 10 | 18,189 | 94 | [] |
student | Of course, you are great | 18,189 | 95 | [] |
volunteer | thank you! so are you! | 18,189 | 96 | [] |
volunteer | is it okay if i clear the screen? | 18,189 | 97 | [] |
student | Give me one moment to put the equation down on my paper | 18,189 | 98 | [] |
volunteer | okay no problem let me know when it is okay to clear it | 18,189 | 99 | [] |
student | Done, you can clear | 18,189 | 100 | [] |
volunteer | the first step is to make the denominator equal to 0 | 18,189 | 101 | [] |
volunteer | do you know the quadratic formula? | 18,189 | 102 | [] |
student | Maybe | 18,189 | 103 | [] |
volunteer | this is the formula | 18,189 | 104 | [] |
volunteer | does it look familiar? | 18,189 | 105 | [] |
student | Yes a little | 18,189 | 106 | [] |
volunteer | okay so first lets identify what is a= b= c= | 18,189 | 107 | [] |
volunteer | so similar to earlier we are going to look at the denominator is step one | 18,189 | 108 | [] |
volunteer | so A= 4 B= -3 C= -10 | 18,189 | 109 | [] |
volunteer | does that make sense? | 18,189 | 110 | [] |
student | Yes because it just goes in order, that doesn't change right? | 18,189 | 111 | [] |
volunteer | correct | 18,189 | 112 | [] |
student | Okay good | 18,189 | 113 | [] |
volunteer | easy way to remember even if the did try to change the order | 18,189 | 114 | [] |
volunteer | is x^2 is always a | 18,189 | 115 | [] |
volunteer | x is always b | 18,189 | 116 | [] |
volunteer | and then number with no x is always c | 18,189 | 117 | [] |
volunteer | okay do you think you are able to condense this down or would you like help? | 18,189 | 118 | [] |
student | I can try | 18,189 | 119 | [] |
student | Do we do in the sqaure root first? | 18,189 | 120 | [] |
volunteer | you can | 18,189 | 121 | [] |
volunteer | is that meant to be a 4 or 9? | 18,189 | 122 | [] |
student | 4 | 18,189 | 123 | [] |
volunteer | explain how you got 4 | 18,189 | 124 | [] |
student | Sorry I did mean 9 lol, not sure why I wrote 4 | 18,189 | 125 | [] |
volunteer | all good | 18,189 | 126 | [] |
volunteer | remember the denominator is for the whole equation | 18,189 | 127 | [] |
student | Now what do we do? | 18,189 | 128 | [] |
volunteer | we can condense some more | 18,189 | 129 | [] |
volunteer | also the sign you have next to X is incorrect | 18,189 | 130 | [] |
volunteer | so -4(4)= -16 X -10 = 160 | 18,189 | 131 | [] |
student | How did you get 13? | 18,189 | 132 | [] |
volunteer | okay so if we do the square root 169 it is equal to 13 | 18,189 | 133 | [] |
student | Oh wait | 18,189 | 134 | [] |
student | I know | 18,189 | 135 | [] |
volunteer | okay | 18,189 | 136 | [] |
volunteer | so now you must solve for both of the following | 18,189 | 137 | [] |
volunteer | does this make sense how i set it up? | 18,189 | 138 | [] |
student | Yes | 18,189 | 139 | [] |
volunteer | so it can be written this way | 18,189 | 140 | [] |
volunteer | there is also the way with the infinity signs but idk if you have seen that in class | 18,189 | 141 | [] |
student | Yes I do, how do I do that | 18,189 | 142 | [] |
volunteer | so the way you set it up if the left is the most - and as you go across it becomes more postive | 18,189 | 143 | [] |
volunteer | do you see that or does it make sense? | 18,189 | 144 | [] |
student | I don't understand | 18,189 | 145 | [] |
volunteer | - infinity is the most negative | 18,189 | 146 | [] |
volunteer | then followed by -5/4 | 18,189 | 147 | [] |
volunteer | then -5,4 to positive 2 | 18,189 | 148 | [] |
volunteer | then 2 , positive infinity | 18,189 | 149 | [] |
student | Why the 2 though? | 18,189 | 150 | [] |
volunteer | it make sense if you use your graphing calculator to see it | 18,189 | 151 | [] |
volunteer | we got 2 from earlier | 18,189 | 152 | [] |
volunteer | will highlight it in pink | 18,189 | 153 | [] |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.