role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
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volunteer | So we have another angle | 4,385 | 902 | [] |
volunteer | Uh, now we need to have this 3rd angle and we can very easily know which angle it should be because | 4,385 | 903 | [] |
volunteer | uh, the side is included. The side is between both of these angles. So, uh, if we see this | 4,385 | 904 | [] |
volunteer | so we do, this one is the | 4,385 | 905 | [] |
volunteer | side and | 4,385 | 906 | [] |
volunteer | this is the angle, so another angle should be? | 4,385 | 907 | [] |
volunteer | uh, tell me, should it be this or this? | 4,385 | 908 | [] |
volunteer | This is one and this is 2. | 4,385 | 909 | [] |
volunteer | What do you think | 4,385 | 910 | [] |
volunteer | The side should be included between these two angles. It should be between the two angles. So should the angle be 1 or 2? | 4,385 | 911 | [] |
volunteer | 2 | 4,385 | 912 | [] |
volunteer | know how to | 4,385 | 913 | [] |
volunteer | how 2? | 4,385 | 914 | [] |
student | no | 4,385 | 915 | [] |
volunteer | No | 4,385 | 916 | [] |
volunteer | ? | 4,385 | 917 | [] |
student | it would be wrong because of side angle side | 4,385 | 918 | [] |
volunteer | I think you're confused | 4,385 | 919 | [] |
volunteer | Yeah, exactly. It would be wrong because of side. | 4,385 | 920 | [] |
volunteer | No, we | 4,385 | 921 | [] |
student | and so it is on because angle side angle | 4,385 | 922 | [] |
volunteer | uh, we are not using side angle side. We are using angle, side angle. | 4,385 | 923 | [] |
volunteer | Uh, so it is on because | 4,385 | 924 | [] |
volunteer | uh, it is one, yeah, it's one. I think you mean lung. | 4,385 | 925 | [] |
volunteer | So yeah, it should be one, right? because uh the site should be between these struggle. If I take this angle, the site is not between these two angles, but if I take this angle, then the side is between these two angles. | 4,385 | 926 | [] |
volunteer | Uh, so, | 4,385 | 927 | [] |
volunteer | in this triangle, basically the green triangle that you see. | 4,385 | 928 | [] |
volunteer | uh angle one is this. What do you think in the blue blue triangle should angle 1B. Should it be the same one, it's basically common in both the triangles, right? | 4,385 | 929 | [] |
volunteer | Does this make sense | 4,385 | 930 | [] |
student | yes! | 4,385 | 931 | [] |
volunteer | Yeah | 4,385 | 932 | [] |
volunteer | So | 4,385 | 933 | [] |
volunteer | we just need to name this angle in two different ways, basically, to say that uh it's equal. | 4,385 | 934 | [] |
volunteer | Uh, I'll just | 4,385 | 935 | [] |
volunteer | uh erase some stuff from here. | 4,385 | 936 | [] |
volunteer | So yes | 4,385 | 937 | [] |
volunteer | uh, in one way I can write this angle is angle CFA. | 4,385 | 938 | [] |
volunteer | is equal to a DFB. | 4,385 | 939 | [] |
volunteer | Does this make sense | 4,385 | 940 | [] |
student | yes I understand the statement | 4,385 | 941 | [] |
volunteer | What is, I will see if you understood it. And we'll see if a CFA is this angle. The angle DFB DFB again is the same and so we are saying that this angle is equal to this angle, so | 4,385 | 942 | [] |
volunteer | basically, we are using the reflexive property. | 4,385 | 943 | [] |
volunteer | Uh, don't you think this should be our statement over here. | 4,385 | 944 | [] |
student | this cant be reflexive since it would have to be the exact same letters | 4,385 | 945 | [] |
volunteer | OK, so it needs the same letters. | 4,385 | 946 | [] |
volunteer | So instead of using the full CFA name, you can simply write on the left, equals angle left. | 4,385 | 947 | [] |
volunteer | Try this. We can also use this, right? | 4,385 | 948 | [] |
student | yes! I will try | 4,385 | 949 | [] |
volunteer | Yeah. | 4,385 | 950 | [] |
volunteer | So here are the main challenges like uh what will the, the system considered correct because we know the concept and everything, uh, but it's more like what will the | 4,385 | 951 | [] |
volunteer | that algorithm consider connect | 4,385 | 952 | [] |
student | yes! it workd | 4,385 | 953 | [] |
student | thanks! | 4,385 | 954 | [] |
volunteer | OK, perfect. Uh, do you have any doubt on this problem? | 4,385 | 955 | [] |
student | no I understand it | 4,385 | 956 | [] |
volunteer | OK. Um, any other questions? | 4,385 | 957 | [] |
student | that all for now! Thanks! | 4,385 | 958 | [] |
volunteer | OK, thank you. Uh, in fact, I also learned so many things today, um, the terminologies and stuff, and it was, it was nice teaching you. Thank you. | 4,385 | 959 | [] |
volunteer | Have a good night | 4,385 | 960 | [] |
student | Thank you so much! Have a good night! bye! | 4,385 | 961 | [] |
student | Hi | 7,645 | 0 | [] |
volunteer | hi | 7,645 | 1 | [] |
volunteer | how can i help you? | 7,645 | 2 | [] |
student | So I'm doing angular & linear speed problems in pre calc and I don't get them. I have word problems and I can paste one here | 7,645 | 3 | [] |
volunteer | sure | 7,645 | 4 | [] |
volunteer | which one? | 7,645 | 5 | [] |
student | We can start with the first one. Can you also show me how to draw the diagram circle? | 7,645 | 6 | [] |
volunteer | sure | 7,645 | 7 | [] |
volunteer | you have to draw a diagram? | 7,645 | 8 | [] |
student | My teacher doesn't require it but it helps me visualize. | 7,645 | 9 | [] |
volunteer | oh | 7,645 | 10 | [] |
volunteer | okay do you know the formula for Distance along the surface between two latitudes | 7,645 | 11 | [] |
student | s = theta * radius | 7,645 | 12 | [] |
volunteer | yup | 7,645 | 13 | [] |
volunteer | so the first one is Sarah | 7,645 | 14 | [
{
"pii_type": "PERSON",
"surrogate": "Sarah",
"start": 20,
"end": 25
}
] |
volunteer | equator | 7,645 | 15 | [] |
volunteer | but you have to convert the theta from degree to radians | 7,645 | 16 | [] |
student | so 19.43 * 180/pi? | 7,645 | 17 | [] |
volunteer | pi/180 | 7,645 | 18 | [] |
volunteer | basically your question says that this angle is given | 7,645 | 19 | [] |
student | ~.339 | 7,645 | 20 | [] |
volunteer | and from this you have to calculate the rest | 7,645 | 21 | [] |
student | Got it | 7,645 | 22 | [] |
volunteer | for equator the formula should be theta*pi | 7,645 | 23 | [] |
volunteer | if you want to convert it to radian you to multiply pi/180 with it | 7,645 | 24 | [] |
volunteer | what is the result? | 7,645 | 25 | [] |
student | 19.43*pi=61.04 | 7,645 | 26 | [] |
volunteer | then? | 7,645 | 27 | [] |
volunteer | this is correct | 7,645 | 28 | [] |
volunteer | but you have to convert it to radian | 7,645 | 29 | [] |
student | 19.43* pi/180 =0.339 | 7,645 | 30 | [] |
volunteer | how? | 7,645 | 31 | [] |
volunteer | i get it | 7,645 | 32 | [] |
volunteer | but you missed to multiply it with the radius | 7,645 | 33 | [] |
student | ooh okay wait | 7,645 | 34 | [] |
student | so that times 3960 = 1342.91 | 7,645 | 35 | [] |
volunteer | yes | 7,645 | 36 | [] |
volunteer | perfect | 7,645 | 37 | [] |
volunteer | you got the first one | 7,645 | 38 | [] |
student | omg there was confetti | 7,645 | 39 | [] |
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