role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
student | yay | 7,645 | 40 | [] |
volunteer | yay | 7,645 | 41 | [] |
volunteer | can we go to the second? | 7,645 | 42 | [] |
student | yes | 7,645 | 43 | [] |
volunteer | the second one says we have to calculate the distance of the city from north pole | 7,645 | 44 | [] |
volunteer | so look at the figure | 7,645 | 45 | [] |
volunteer | we have to calculate the red arcdistance | 7,645 | 46 | [] |
volunteer | can you guess how can we do it? | 7,645 | 47 | [] |
student | not sure | 7,645 | 48 | [] |
volunteer | no worries | 7,645 | 49 | [] |
volunteer | we that formula that we used for the first question | 7,645 | 50 | [] |
volunteer | theta*R | 7,645 | 51 | [] |
volunteer | how can we calculate the theta for red? | 7,645 | 52 | [] |
volunteer | we know north to eqador is 90 degrees | 7,645 | 53 | [] |
student | to equator? | 7,645 | 54 | [] |
volunteer | yup | 7,645 | 55 | [] |
volunteer | north to equator | 7,645 | 56 | [] |
student | 90-19.43=70.57 | 7,645 | 57 | [] |
volunteer | perfect | 7,645 | 58 | [] |
volunteer | now if we want to determine the distance what should we do? | 7,645 | 59 | [] |
volunteer | you already know the theta | 7,645 | 60 | [] |
student | 70.57*pi/180*3960=4,877.448 | 7,645 | 61 | [] |
volunteer | yes | 7,645 | 62 | [] |
student | I love this confetti | 7,645 | 63 | [] |
volunteer | i love it toooo | 7,645 | 64 | [] |
volunteer | you got the second one too Maya | 7,645 | 65 | [] |
volunteer | yayyyy | 7,645 | 66 | [] |
student | yay im writing this down | 7,645 | 67 | [] |
volunteer | sure | 7,645 | 68 | [] |
volunteer | i am here, take your time | 7,645 | 69 | [] |
student | thanks. So for South Pole, do I add 90 to 19.43 | 7,645 | 70 | [] |
student | since it's different in the south | 7,645 | 71 | [] |
volunteer | Exactly! | 7,645 | 72 | [] |
volunteer | wow | 7,645 | 73 | [] |
student | im cooking | 7,645 | 74 | [] |
volunteer | you are so smart Maya | 7,645 | 75 | [
{
"pii_type": "PERSON",
"surrogate": "Maya",
"start": 17,
"end": 21
}
] |
student | lol thank you | 7,645 | 76 | [] |
student | CONFETTI YAY | 7,645 | 77 | [] |
volunteer | yaayyyyyy | 7,645 | 78 | [] |
student | so 19.43*pi/180*3960=7,563.259 | 7,645 | 79 | [] |
volunteer | yup | 7,645 | 80 | [] |
volunteer | perfect | 7,645 | 81 | [] |
student | yay I wrote it down | 7,645 | 82 | [] |
volunteer | yay | 7,645 | 83 | [] |
volunteer | do you need help with anything else, Maya? | 7,645 | 84 | [] |
student | can we do 3? the formulas are different there I'm pretty sure, and I haven't gotten them drilled into my head yet | 7,645 | 85 | [] |
volunteer | sure sure | 7,645 | 86 | [] |
student | the whole thing with revolutions and v | 7,645 | 87 | [] |
volunteer | whats wr? | 7,645 | 88 | [] |
student | linear velocity | 7,645 | 89 | [] |
volunteer | oh okay | 7,645 | 90 | [] |
student | v= 2pi/1 revolution 360 degrees/1 revolution | 7,645 | 91 | [] |
volunteer | so do you know any formula related to this? | 7,645 | 92 | [] |
student | v=rw | 7,645 | 93 | [] |
student | I forgot what w is | 7,645 | 94 | [] |
student | or w= theta/time | 7,645 | 95 | [] |
volunteer | w is 2pi*N | 7,645 | 96 | [] |
student | what's N | 7,645 | 97 | [] |
volunteer | 600 rpm | 7,645 | 98 | [] |
volunteer | N = rotational speed | 7,645 | 99 | [] |
student | oh I see | 7,645 | 100 | [] |
volunteer | okay first we calculate w | 7,645 | 101 | [] |
volunteer | can you try? | 7,645 | 102 | [] |
student | yes hmmmm | 7,645 | 103 | [] |
student | lowkey I'm not sure what to multiply because there are so many values | 7,645 | 104 | [] |
volunteer | put the values | 7,645 | 105 | [] |
volunteer | in this equation | 7,645 | 106 | [] |
volunteer | here N = 600 | 7,645 | 107 | [] |
student | 2*pi*600=3,769.911 | 7,645 | 108 | [] |
volunteer | yup | 7,645 | 109 | [] |
volunteer | now by doing this | 7,645 | 110 | [] |
volunteer | we have converted rpm to radians per min | 7,645 | 111 | [] |
volunteer | next step is to follow v = rw formula | 7,645 | 112 | [] |
volunteer | can you do it? | 7,645 | 113 | [] |
volunteer | r is 9 ft , given in the question | 7,645 | 114 | [] |
student | v= 9*5280 | 7,645 | 115 | [] |
student | 9*5280=47,520 | 7,645 | 116 | [] |
volunteer | yup | 7,645 | 117 | [] |
student | oh wow I was just plugging in hoping it's right | 7,645 | 118 | [] |
volunteer | but | 7,645 | 119 | [] |
volunteer | why did you do it? | 7,645 | 120 | [] |
student | if the radius is 9, the w of angular speed can be plugged in radians per minute | 7,645 | 121 | [] |
volunteer | but why? | 7,645 | 122 | [] |
student | not exactly sure | 7,645 | 123 | [] |
volunteer | see the problem says you have to and it with miles per hour unit | 7,645 | 124 | [] |
volunteer | but radius is given in feet | 7,645 | 125 | [] |
volunteer | not in miles | 7,645 | 126 | [] |
student | so we're converting | 7,645 | 127 | [] |
volunteer | yup | 7,645 | 128 | [] |
volunteer | check one more time if you conversion is right | 7,645 | 129 | [] |
volunteer | your* | 7,645 | 130 | [] |
volunteer | we are converting ft to mile | 7,645 | 131 | [] |
student | 9 ft * 1 mile/5280ft | 7,645 | 132 | [] |
volunteer | then we are dividing it 5280? | 7,645 | 133 | [] |
volunteer | right? | 7,645 | 134 | [] |
student | yes | 7,645 | 135 | [] |
volunteer | yup | 7,645 | 136 | [] |
volunteer | now plug it in with w | 7,645 | 137 | [] |
volunteer | v = rw | 7,645 | 138 | [] |
student | w= 600 revolution/min * 2pi/revolution= 1200pi/1 minute | 7,645 | 139 | [] |
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