Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	the square root of a large number, the standard deviation of the sample mean will always be much smaller	7,729	42	[]
volunteer	So there's much less variation	7,729	43	[]
student	So what is the stigma again?	7,729	44	[]
volunteer	Sigma, I'm gonna circle it in red. That's the standard deviation. I circled it in yellow.	7,729	45	[]
student	Um	7,729	46	[]
student	and access the like the wall score, right?	7,729	47	[]
volunteer	Well, yes, that's correct	7,729	48	[]
student	So the correct answer to this question is, it varies among the sample, but if the, it will vary with the sample me, but, but it will be based on the sample mean, right?	7,729	49	[]
volunteer	That's right. And the variation will be much smaller	7,729	50	[]
student	So it's basically like it varies among the sample mean of the population.	7,729	51	[]
volunteer	Right	7,729	52	[]
student	OK, I'm ready for number 2.	7,729	53	[]
volunteer	For number 2, we wrote the same formula I wrote on the board. So I'll write, I'll just start to write the data for number 2.	7,729	54	[]
volunteer	So it tells us	7,729	55	[]
volunteer	OK, let me read number 2. So a population has a standard deviation of 10	7,729	56	[]
volunteer	So we write	7,729	57	[]
volunteer	so	7,729	58	[]
volunteer	for X	7,729	59	[]
volunteer	the standard deviation is 10	7,729	60	[]
volunteer	and they're asking for	7,729	61	[]
volunteer	the standard deviation	7,729	62	[]
volunteer	of the distribution of means.	7,729	63	[]
volunteer	So the mean is x bar	7,729	64	[]
volunteer	and the formula for the standard deviation of the sample mean is sigma	7,729	65	[]
volunteer	over square root of n and for question A, they tell us that sigma.	7,729	66	[]
volunteer	is	7,729	67	[]
volunteer	2	7,729	68	[]
student	So it will be 10 divided by the square root of the um temple size, right?	7,729	69	[]
volunteer	That's right	7,729	70	[]
student	which gave me like	7,729	71	[]
student	which gave me 7.07.	7,729	72	[]
volunteer	Correct	7,729	73	[]
volunteer	And sometimes we write it like this	7,729	74	[]
volunteer	We write like a sigma and a little X bar to show that it's the standard deviation of the mean.	7,729	75	[]
volunteer	So like this	7,729	76	[]
volunteer	and then you do do the same for question B.	7,729	77	[]
volunteer	The only difference is question B is a different value of n.	7,729	78	[]
student	OK.	7,729	79	[]
student	because the way I solve it, it is like I put 10 square, which is 100 divided by 2, which gives me the um um and then I do the square root of 50, um, which also gives me the same answer, 7.07.	7,729	80	[]
volunteer	Yes, you can do it that way	7,729	81	[]
student	And the answer to the first question was that it varies among the population based on the sample of the mean, right?	7,729	82	[]
volunteer	Yes	7,729	83	[]
student	OK, I'm ready to move on to number 3.	7,729	84	[]
volunteer	Oh	7,729	85	[]
student	Oh, let me, let me, let us solve all parts of number one first, sorry.	7,729	86	[]
volunteer	OK	7,729	87	[]
volunteer	Mm.	7,729	88	[]
student	For number 2, I got phone number um 4B. I got um 10 divided by the square root of 3, which equals to 5.77.	7,729	89	[]
volunteer	That's correct	7,729	90	[]
volunteer	And you know it is that as the value of N.	7,729	91	[]
student	Or C, I have an answer of 5.	7,729	92	[]
volunteer	That's correct	7,729	93	[]
student	And then for D, I have an answer of um 3.33, 10 divided by the square root of 9.	7,729	94	[]
volunteer	That's right	7,729	95	[]
volunteer	Correct	7,729	96	[]
student	Let's move on to number 3 now.	7,729	97	[]
volunteer	Right	7,729	98	[]
student	So for A, I got um	7,729	99	[]
student	14.1.	7,729	100	[]
volunteer	Yes, that's correct.	7,729	101	[]
student	For me, I did the	7,729	102	[]
student	um, so I need my square, which 400 divided by 3, and then I get a square root of 13133.3 and then that equals to 11.5.	7,729	103	[]
volunteer	Yes, that works	7,729	104	[]
student	And then for C, I did 2 divided by the square root of 4 which is 10.	7,729	105	[]
volunteer	Yup, that's good	7,729	106	[]
student	And then for D, I got, I, I 400 divided by 9, which equals to 44.4, the square root of 44.4, which equals to 6.66.	7,729	107	[]
volunteer	You got it. That's correct	7,729	108	[]
student	OK, so I'm gonna give you a practice problem that requires um award problem type of thing now. We're gonna move on to that.	7,729	109	[]
volunteer	All right	7,729	110	[]
student	Mm imbu.	7,729	111	[]
student	OK.	7,729	112	[]
student	you cannot	7,729	113	[]
student	OK	7,729	114	[]
student	Hm.	7,729	115	[]
student	what's one name?	7,729	116	[]
student	19. A researcher is interested in whether people are able to identify emotions correctly when they are extremely tired. It is known that, using a particular method of measurement, the accuracy ratings of people in the general population (who are not extremely tired) are normally distributed with a mean of 82 and a vari...	7,729	117	[]
student	Solve this pro um	7,729	118	[]
student	solve this problem with um all the five steps of hypothesis testing.	7,729	119	[]
student	With the hypothesis testing procedure.	7,729	120	[]
volunteer	OK, I'm reading the problem	7,729	121	[]
volunteer	So it says a researcher is interested in whether people are able to identify emotions correctly when they are extremely tired. It is known that using a particular method of measurement	7,729	122	[]
volunteer	the accuracy ratings of people in the general population who are not extremely	7,729	123	[]
volunteer	are normally distributed	7,729	124	[]
volunteer	OK, so we'll note those numbers. So we have a first group of people who are not tired, so the meme	7,729	125	[]
volunteer	is 82 and the variance	7,729	126	[]
volunteer	that's the square of the standard deviation is 20. In the present study, however, the researcher arranges to test.	7,729	127	[]
volunteer	50 people who had no sleep the previous night. So obviously they're tired.	7,729	128	[]
volunteer	The mean accuracy for these 50 individuals	7,729	129	[]
volunteer	was 78, so that is the, that's our X bar is 78.	7,729	130	[]
volunteer	using the	7,729	131	[]
volunteer	0, the 0.05 level what?	7,729	132	[]
volunteer	should the researcher conclude?	7,729	133	[]
volunteer	Hey, carry out the Z test using 5 steps of hypothesis testing.	7,729	134	[]
volunteer	Make a drawing of the distributions involved. Explain your answer	7,729	135	[]
volunteer	etc	7,729	136	[]
volunteer	OK	7,729	137	[]
volunteer	OK, so	7,729	138	[]
student	OK	7,729	139	[]
volunteer	we have two things we're gonna do. We have a um	7,729	140	[]
volunteer	so we have a group	7,729	141	[]

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