Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	excellent	13,524	55	[]
volunteer	now how can we change 4d to d?	13,524	56	[]
student	Last thing to do would be to divide everything by 4 correct?	13,524	57	[]
volunteer	yes	13,524	58	[]
volunteer	Now a comment	13,524	59	[]
volunteer	since 4 is positive that is fine	13,524	60	[]
volunteer	IF it were negative it would reverse the inequality DO u know that?	13,524	61	[]
student	Yes	13,524	62	[]
volunteer	wait	13,524	63	[]
volunteer	it does not reverse	13,524	64	[]
volunteer	since 4 > 0	13,524	65	[]
student	What do you mean?	13,524	66	[]
volunteer	I will write	13,524	67	[]
volunteer	my writing is ot so good but do you see what I mean?	13,524	68	[]
student	Yes but shouldn’t the sign change since we have divided by a negative?	13,524	69	[]
volunteer	Yes but we divided all by 4 ad 4 is not meg	13,524	70	[]
volunteer	neg*	13,524	71	[]
volunteer	see what I wrote	13,524	72	[]
volunteer	My commenbt was correct but I htink it was confusing	13,524	73	[]
student	Alright that makes sense	13,524	74	[]
volunteer	OK so I think we have the answer	13,524	75	[]
volunteer	Now can you grpah it?	13,524	76	[]
student	Like that?	13,524	77	[]
volunteer	wait I will scroll	13,524	78	[]
volunteer	yes	13,524	79	[]
volunteer	and what kind of dots at each end open or closed?	13,524	80	[]
student	Closed	13,524	81	[]
volunteer	I agree	13,524	82	[]
volunteer	Did you see the cnfetti?	13,524	83	[]
student	Yes!	13,524	84	[]
student	Thank youuu	13,524	85	[]
volunteer	good	13,524	86	[]
volunteer	OK might you have a TI-84 cal;ciultor?	13,524	87	[]
student	Unfortunately not	13,524	88	[]
volunteer	OK no problem	13,524	89	[]
volunteer	I think they can grpah inequal	13,524	90	[]
volunteer	But thii fine	13,524	91	[]
volunteer	you did vey well	13,524	92	[]
volunteer	very*	13,524	93	[]
volunteer	sorry I confsuded you about the sign	13,524	94	[]
student	No problem you explained it very well!	13,524	95	[]
volunteer	Good thanks	13,524	96	[]
student	Have a lovely day!	13,524	97	[]
volunteer	You too BYE BYE	13,524	98	[]
student	:]	13,524	99	[]
volunteer	Hi Liam	13,550	0	[ { "pii_type": "PERSON", "surrogate": "Liam", "start": 3, "end": 7 } ]
student	Hello could you help me understand inverse trig functions	13,550	1	[]
student	like with derivatives and implicit differentiation	13,550	2	[]
volunteer	OK. Do you have a specific question or problem you'd like to work on?	13,550	3	[]
student	I guess just understanding in general but let me pull one up	13,550	4	[]
student	have you taken calculus?	13,550	5	[]
volunteer	Yes.	13,550	6	[]
student	Okay, im in BC not AB but that was the only option	13,550	7	[]
volunteer	No problem.	13,550	8	[]
volunteer	The problem shows how to find the derivative of the "inverse tangent" function.	13,550	9	[]
student	i know the derivative of the inverse tan and the inverses of trig functions and are familiar with that	13,550	10	[]
student	okay	13,550	11	[]
volunteer	So you need help with "implicit differentiation" ?	13,550	12	[]
student	no just this concept like why change sec squared y to Noah squared Tampa and how then did it transform to x	13,550	13	[ { "pii_type": "PERSON", "surrogate": "Noah", "start": 54, "end": 58 }, { "pii_type": "LOCATION", "surrogate": "Tampa", "start": 67, "end": 72 } ]
student	why does tan y =x	13,550	14	[]
volunteer	Let's start with sec^2(y) = tan^2(y)+1. It's a trigonometric identity. I can explain if you wish.	13,550	15	[]
student	i am familar with the concept	13,550	16	[]
student	i dont need help with that	13,550	17	[]
volunteer	So you need help with tan y = x?	13,550	18	[]
student	i guess yes	13,550	19	[]
student	like i understand when im looking at it but when im doing an actual problem im scared im going ot mess up	13,550	20	[]
student	let me replace it with an actual problem	13,550	21	[]
volunteer	OK.	13,550	22	[]
student	so finding the derivative	13,550	23	[]
volunteer	I think you mean something a bit different. I'll write.	13,550	24	[]
student	okay	13,550	25	[]
volunteer	Is this what you meant?	13,550	26	[]
student	yes apolgies	13,550	27	[]
student	is all i do is plug in x/2 into the derivative of inverse sin	13,550	28	[]
volunteer	Yes. You also need the chain rule.	13,550	29	[]
volunteer	I can show you if you wish.	13,550	30	[]
student	i know the chain rule	13,550	31	[]
student	is it purely just 1/ the square root of (x/2)^2-1) switch the 1 and x/2	13,550	32	[]
volunteer	It would be: 1/√(1-(x/2)^2)*(1/2).	13,550	33	[]
student	adn the 1/2 is from the chain rule?	13,550	34	[]
volunteer	Correct.	13,550	35	[]
student	okay i think i get that it seems simple enough	13,550	36	[]
volunteer	Awesome!	13,550	37	[]
student	could i ask one more questions?	13,550	38	[]
volunteer	Sure.	13,550	39	[]
volunteer	You'll need to use implicit differentiation to solve this problem.	13,550	40	[]
student	okay	13,550	41	[]
student	would the first step be e to the y - e to the y^2 * 2y*dy/dx=1-3x^2	13,550	42	[]
volunteer	Yes. Then solve the equation for dy/dx = ?	13,550	43	[]
volunteer	You forget one thing.	13,550	44	[]
volunteer	*forgot	13,550	45	[]
volunteer	The first term would be (e^y)*dy/dx.	13,550	46	[]
student	oh oh is it e*dy/dx - 2ye to the dy/dx	13,550	47	[]
student	ah i see	13,550	48	[]
student	and -2yeto the y^2 *dy/dx is because of the chain rule?	13,550	49	[]
volunteer	Yes.	13,550	50	[]
volunteer	I wrote above your uploaded page.	13,550	51	[]
student	okay thanks!	13,550	52	[]
student	so whenever you have e the power (in this case y ^2) will be what we are using for chain rule?	13,550	53	[]
student	like it would be f of the deravitive of f(g(x))*g(x)	13,550	54	[]

Subsets and Splits

No community queries yet

The top public SQL queries from the community will appear here once available.