role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | First, you find the zero of x-2, which is 2. Then you take the coefficients of all the other terms in the equation and write them in this format. Does this look familiar to you? | 14,081 | 9 | [] |
student | yes | 14,081 | 10 | [] |
volunteer | First, we brought the first coefficient down and did not do anything with it. Then, we multiplied it by 2. This is what would be added to the second coefficient. | 14,081 | 11 | [] |
volunteer | Then, we bring down that value and multiply it by two and add it to the next coefficient. We keep repeating this process until the end. 7, the last number on the rectangle is the remainder. | 14,081 | 12 | [] |
volunteer | The number before 7 would not have an x, and then the next number before that would have x, and the next number before that has x^2 and so on. The quotient should always be one degree lower than the dividend. | 14,081 | 13 | [] |
student | okay | 14,081 | 14 | [] |
volunteer | Do you want to do another synthetic division problem or try to learn another concept? | 14,081 | 15 | [] |
student | try another problem | 14,081 | 16 | [] |
volunteer | Do you want to try solving this on your own first? | 14,081 | 17 | [] |
student | yes | 14,081 | 18 | [] |
volunteer | You are doing it mostly right. The only mistake is that you have to bring the 4 down by itself. Then you start the series of multiplications | 14,081 | 19 | [] |
student | okay, can you show me? | 14,081 | 20 | [] |
student | ohh okay i get it | 14,081 | 21 | [] |
volunteer | Do you know how to write the quotient and remainder? | 14,081 | 22 | [] |
student | not exactly, i think so but it's probably not right | 14,081 | 23 | [] |
volunteer | You can try and then we can check | 14,081 | 24 | [] |
student | okay | 14,081 | 25 | [] |
student | do i use variables or no | 14,081 | 26 | [] |
volunteer | You use x in the quotient. | 14,081 | 27 | [] |
volunteer | The first term of the quotient should be one degree lower than the divided. If the first term on the dividend is x^4, then the first term of the quotient will be x^3. | 14,081 | 28 | [] |
student | can you write it for me so i can see | 14,081 | 29 | [] |
volunteer | Do you have any specific questions about the process of synthetic division? | 14,081 | 30 | [] |
student | not really | 14,081 | 31 | [] |
volunteer | Do you want to do another synthetic division problem or learn another concept? | 14,081 | 32 | [] |
student | learn another concept | 14,081 | 33 | [] |
volunteer | Which concept are you the most worried about for your test? We can cover that. | 14,081 | 34 | [] |
student | all of it but probably the theorems or rational functions | 14,081 | 35 | [] |
volunteer | Ok, do you need to know how to graph rational functions for your test? | 14,081 | 36 | [] |
volunteer | I can do an example showing graphing. | 14,081 | 37 | [] |
student | yes please, just in case | 14,081 | 38 | [] |
volunteer | To find the vertical asymptote, we solve the bottom part of the function, in this case X-2. The vertical asymptote is at x=2. | 14,081 | 39 | [] |
volunteer | For horizontal asymptotes, there are some special rules. I am going to write them out under the graph. | 14,081 | 40 | [] |
student | okay' | 14,081 | 41 | [] |
volunteer | When the largest degree of both the numerator and the denominator is the same, you divide their coefficients to find the horizontal asymptote. | 14,081 | 42 | [] |
volunteer | If the degree at the bottom of the rational function is greater than the top, the horizontal asymptote is always y=0. | 14,081 | 43 | [] |
volunteer | In our original equation, both only has x. So we divide the coefficients, 1/1 to get a horizontal asymptote of y=1. | 14,081 | 44 | [] |
volunteer | The next step, after figuring out the asymptotes is to find the x-intercept. To find this, we find the solution to the top of the equation. In X+3=0, X=-3. This is a point we plot on the graph. | 14,081 | 45 | [] |
volunteer | Then we draw a graph approaching the asymptotes going through the x-intercept. | 14,081 | 46 | [] |
volunteer | Then we draw a graph on the side opposite to it. | 14,081 | 47 | [] |
volunteer | Do you have any questions, I know that was a lot of information | 14,081 | 48 | [] |
student | not really i think i just need to practice utt | 14,081 | 49 | [] |
student | it | 14,081 | 50 | [] |
volunteer | Do you want to go over remainder theorem? | 14,081 | 51 | [] |
student | umm that's okay i have to go to dance and then i'll come back and start another session to finish the topics, but thank you I really appreciate it | 14,081 | 52 | [] |
volunteer | Ok, it was great working with you. Good luck on your test. | 14,081 | 53 | [] |
student | thank you | 14,081 | 54 | [] |
volunteer | hi StudentA | 14,365 | 0 | [
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"pii_type": "PERSON",
"surrogate": "StudentA",
"start": 3,
"end": 11
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] |
student | hi i need help i have a test tomorrow | 14,365 | 1 | [] |
volunteer | on Saturday? | 14,365 | 2 | [] |
student | Precalc now pre calc | 14,365 | 3 | [] |
student | please help | 14,365 | 4 | [] |
volunteer | you'studying, studying? | 14,365 | 5 | [] |
student | Precalculus cource | 14,365 | 6 | [] |
volunteer | OK | 14,365 | 7 | [] |
volunteer | the rules say I shouldn'tutor student, math class is OK, help students anyway, if I can | 14,365 | 8 | [] |
student | thank you so much | 14,365 | 9 | [] |
student | i need help on difference of quotient and verifying a inverse | 14,365 | 10 | [] |
volunteer | wow, that's getting very close to calculus | 14,365 | 11 | [] |
student | it is? | 14,365 | 12 | [] |
volunteer | yes. difference quotient is almost a derivative, and a derivative is most definitely calculus | 14,365 | 13 | [] |
volunteer | let's see the problem | 14,365 | 14 | [] |
student | ok ill bring it up | 14,365 | 15 | [] |
volunteer | I tutor all math subjects except calculus, and had to look up difference quotient | 14,365 | 16 | [] |
student | is there a calculus option on here? | 14,365 | 17 | [] |
volunteer | there are 2, I think | 14,365 | 18 | [] |
volunteer | but let's see if I can help you | 14,365 | 19 | [] |
student | ok | 14,365 | 20 | [] |
student | so its f(x)=-^2+5x | 14,365 | 21 | [] |
volunteer | -x^2? | 14,365 | 22 | [] |
student | wait no sorry | 14,365 | 23 | [] |
student | f(x)=-2x^2+5x | 14,365 | 24 | [] |
student | this | 14,365 | 25 | [] |
volunteer | do you know the formula for the difference quotient? | 14,365 | 26 | [] |
student | no | 14,365 | 27 | [] |
volunteer | I'll put it on the board | 14,365 | 28 | [] |
student | ok | 14,365 | 29 | [] |
volunteer | can you guess what to do next? | 14,365 | 30 | [] |
student | wait its over that and not h? | 14,365 | 31 | [] |
volunteer | the x's cancel and you get h | 14,365 | 32 | [] |
student | ohhhh ok | 14,365 | 33 | [] |
volunteer | writing it this way shows that you are using x+h and x in both numerator and denominator | 14,365 | 34 | [] |
student | ohhhh ok | 14,365 | 35 | [] |
volunteer | so, what next? | 14,365 | 36 | [] |
student | we should plug in the equation | 14,365 | 37 | [] |
volunteer | yes, plug in x+h and plug in x on the top | 14,365 | 38 | [] |
volunteer | go ahead | 14,365 | 39 | [] |
volunteer | work on the board | 14,365 | 40 | [] |
volunteer | good start | 14,365 | 41 | [] |
student | what do i do with the 5x | 14,365 | 42 | [] |
volunteer | replace x with x+h again | 14,365 | 43 | [] |
volunteer | let me make it smaller to give you more room | 14,365 | 44 | [] |
student | ok thanks | 14,365 | 45 | [] |
volunteer | there | 14,365 | 46 | [] |
volunteer | now the -fx) | 14,365 | 47 | [] |
volunteer | -f(x) | 14,365 | 48 | [] |
student | do i expand the biononiaml | 14,365 | 49 | [] |
volunteer | put the -f(x), first | 14,365 | 50 | [] |
student | huh where | 14,365 | 51 | [] |
volunteer | numerator | 14,365 | 52 | [] |
volunteer | f(x+h)-f(x), right? | 14,365 | 53 | [] |
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