prefix stringlengths 0 918k | middle stringlengths 0 812k | suffix stringlengths 0 962k |
|---|---|---|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Create a function that takes a value (string) representing a number
// and returns the closest integer to it. If the number is equi... | } | |
from typing import List
def search(lst: List[int]) -> int:
"""
You are given a non-empty list of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times i... | maxValue = key | return maxValue
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You're given an array array list of deposit and withdrawal operations on a bank account that starts with
// zero balance. Your task... | long balance = 0; | for (long op : operations) {
balance += op;
if (balance < 0) {
return true;
}
}
return false;
}
} |
from typing import List
def total_match(lst1: List[str], lst2: List[str]) -> List[str]:
"""
Write a function that accepts two lists of strings and returns the list that has
total number of chars in the all strings of the list less than the other list.
if the two lists have the same number of chars, r... | count2 = sum([len(s) for s in lst2]) | if count1 == count2:
return lst1
if count1 < count2:
return lst1
return lst2
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Insert a number 'delimeter' between every two consecutive elements of input array list `numbers'
// >>> intersperse((new ArrayList<... | if ((i < (numbers.size() - 1))) { | result.add(delimeter);
}
}
return result;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// remove_vowels is a function that takes string and returns string without vowels.
// >>> removeVowels((""))
// ("")
// >>> r... | String newText = ""; | for (int i = 0; i < text.length(); i++) {
if (vowels.indexOf(text.charAt(i)) == -1) {
newText += text.charAt(i);
}
}
return newText;
}
} |
//For a given array of integers, return an array consisting of a sum and a product of all the integers in an array.
// Empty sum should be equal to 0 and empty product should be equal to 1.
// >>> sum_product([])
// [0, 1]
// >>> sum_product([1, 2, 3, 4])
// [10, 24]
function sum_product(numbers){
if(numbers.length... | } | return [sum, product];
}
|
from typing import List
def count_nums(arr: List[int]) -> int:
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2,... | n = 0 | for i in arr:
if i < 0:
i = abs(i)
s = -1 * int(str(i)[0])
for j in str(i)[1:]:
s += int(j)
else:
s = 0
for j in str(i):
s += int(j)
if s > 0:
n += 1
return n
|
from typing import List
def count_up_to(n: int) -> List[int]:
"""Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
>>> count_up_to(5)
[2, 3]
>>> count_up_to(11)
[2, 3, 5, 7]
>>> count... | if n <= 1: | return []
result = []
for number in range(2, n):
is_prime = True
for divisor in range(2, number):
if number % divisor == 0:
is_prime = False
break
if is_prime:
result.append(number)
return result
|
def x_or_y(n: int, x: int, y: int) -> int:
"""A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
>>> x_or_y(7, 34, 12)
34
>>> x_or_y(15, 8, 5)
5
"""
if n < 2:
return y
for i in range(2, n... | if n % i == 0: | return y
return x
|
//In this problem, you will implement a function that takes two arrays of numbers,
// and determines whether it is possible to perform an exchange of elements
// between them to make lst1 an array of only even numbers.
// There is no limit on the number of exchanged elements between lst1 and lst2.
// If it is possible ... | }else{ | return "NO";
}
}
|
//You are given a string s.
// if s[i] is a letter, reverse its case from lower to upper or vise versa,
// otherwise keep it as it is.
// If the string contains no letters, reverse the string.
// The function should return the resulted string.
// Examples
// >>> solve("1234")
// "4321"
// >>> solve("ab")
// "AB"
// >>... | return s.split('').reverse().join(''); | }
|
from typing import List
def below_threshold(l: List[int], t: int) -> bool:
"""Return True if all numbers in the list l are below threshold t.
>>> below_threshold([1, 2, 4, 10], 100)
True
>>> below_threshold([1, 20, 4, 10], 5)
False
"""
for num in l:
if num >= t: | return False | return True
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Complete the function that takes two integers and returns
// the product of their unit digits.
// Assume the input is always v... | } | |
//This function takes an array l and returns an array l' such that
// l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
// to the values of the corresponding indicies of l, but sorted.
// >>> sort_third([1, 2, 3])
// [1, 2, 3]
//... | } | }
return x;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Change numerical base of input number x to base.
// return string representation after the conversion.
// base numbers are less... | while (x>0) { | sb.append(x%base);
x = x/base;
}
return sb.reverse().toString();
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a string text, replace all spaces in it with underscores,
// and if a string has more than 2 consecutive spaces,
// the... | return result; | }
} |
from typing import List
def match_parens(lst: List[str]) -> str:
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will b... | open_parens -= 1 | else:
close_parens += 1
if open_parens == 0 and close_parens == 0:
return 'Yes'
return 'No'
|
//Return true if a given number is prime, and false otherwise.
// >>> is_prime(6)
// false
// >>> is_prime(101)
// true
// >>> is_prime(11)
// true
// >>> is_prime(13441)
// true
// >>> is_prime(61)
// true
// >>> is_prime(4)
// false
// >>> is_prime(1)
// false
function is_prime(n){
if (n==1) {
return fals... | return true; | }
if (n%2==0) {
return false;
}
var limit = Math.sqrt(n);
for (var i = 3; i <= limit; i += 2) {
if (n%i==0) {
return false;
}
}
return true;
}
|
from typing import List
def match_parens(lst: List[str]) -> str:
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will b... | close_parens = 0 | for c in s:
if c == '(':
open_parens += 1
elif c == ')':
if open_parens:
open_parens -= 1
else:
close_parens += 1
if open_parens == 0 and close_parens == 0:
return 'Yes'
return... |
def is_palindrome(text: str) -> bool:
"""
Checks if given string is a palindrome
>>> is_palindrome('')
True
>>> is_palindrome('aba')
True
>>> is_palindrome('aaaaa')
True
>>> is_palindrome('zbcd')
False
"""
length = len(text)
for i in range(length): | if text[i] != text[-i - 1]: | return False
return True
|
def solve(s: str) -> str:
"""You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
>>> solve('1234')
'... | return ''.join(l.swapcase() if l.isalpha() else l for l in s) | |
def fib4(n: int) -> int:
"""The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-... | else: | return fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4)
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a string s.
// if s[i] is a letter, reverse its case from lower to upper or vise versa,
// otherwise keep it as ... | sb.append(Character.toLowerCase(s.charAt(i))); | } else {
sb.append(Character.toUpperCase(s.charAt(i)));
}
} else {
sb.append(s.charAt(i));
}
}
if (letterNotFound) {
return sb.reverse().toString();
}
return sb.toString();
}
} |
from typing import List
def smallest_change(arr: List[int]) -> int:
"""
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change ... | start += 1 | end -= 1
return count
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input are two strings a and b consisting only of 1s and 0s.
// Perform binary XOR on these inputs and return result also as a strin... | } | return c.toString();
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function vowels_count which takes a string representing
// a word as input and returns the number of vowels in the string.
... | } | return sum;
}
} |
//Your task is to write a function that returns true if a number x is a simple
// power of n and false in other cases.
// x is a simple power of n if n**int=x
// For example:
// >>> is_simple_power(1, 4)
// true
// >>> is_simple_power(2, 2)
// true
// >>> is_simple_power(8, 2)
// true
// >>> is_simple_power(3, 2)
// fa... | } | |
//From a given array of integers, generate an array of rolling maximum element found until given moment
// in the sequence.
// >>> rolling_max([1, 2, 3, 2, 3, 4, 2])
// [1, 2, 3, 3, 3, 4, 4]
function rolling_max(numbers){
let max = [];
let tempMax = 0;
for(let i = 0; i < numbers.length; i++){
if(tem... | } | max.push(tempMax);
}
return max;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given an array array list of integers.
// You need to find the largest prime value and return the sum of its digits.
//... | } | else {
int l = 1;
while (l <= (int) number) {
if (number % l == 0) {
counter++;
}
l++;
}
}
if (counter == 2) {
if (number > largestPrime... |
from typing import List
def separate_paren_groups(paren_string: str) -> List[str]:
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the list of those.
Separate groups are balanced (each open brace ... | for c in paren_string: | if c == '(':
open_count += 1
elif c == ')':
open_count -= 1
group += c
if open_count == 0:
groups.append(group)
group = ''
return groups
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of integers, sort the integers that are between 1 and 9 inclusive,
// reverse the resulting array array l... | String[] a = new String[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"}; | ArrayList<String> res = new ArrayList<String>();
ArrayList<Long> good = new ArrayList<Long>();
for (Long i : arr) {
if (i >= 1 && i <= 9) {
good.add(i);
}
}
good.sort(new Comparator<Long>() {
public int compare(Long i1, Long i2)... |
from typing import List
def count_nums(arr: List[int]) -> int:
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2,... | if i < 0: | i = abs(i)
s = -1 * int(str(i)[0])
for j in str(i)[1:]:
s += int(j)
else:
s = 0
for j in str(i):
s += int(j)
if s > 0:
n += 1
return n
|
def valid_date(date: str) -> bool:
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or hi... | return False | return True |
from typing import List
def count_nums(arr: List[int]) -> int:
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2,... | for j in str(i)[1:]: | s += int(j)
else:
s = 0
for j in str(i):
s += int(j)
if s > 0:
n += 1
return n
|
def add(x: int, y: int) -> int:
"""Add two numbers x and y
>>> add(2, 3)
5
>>> add(5, 7)
12
"""
| return x + y | |
//The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
// fib4(0) -> 0
// fib4(1) -> 0
// fib4(2) -> 2
// fib4(3) -> 0
// fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
// Please write a function to efficiently compute the n-th element of the fib4 number sequen... | prev[0] = prev[1]; | prev[1] = prev[2];
prev[2] = prev[3];
prev[3] = curr;
}
return prev[3];
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// For a given array list of input numbers, calculate Mean Absolute Deviation
// around the mean of this dataset.
// Mean Absolute... | } | } |
//Given an array of integers, sort the integers that are between 1 and 9 inclusive,
// reverse the resulting array, and then replace each digit by its corresponding name from
// "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
// For example:
// >>> by_length([2, 1, 1, 4, 5, 8, 2, 3])
// ["Eight"... | var arr3 = []; | for(var i = 0; i < arr2.length; i++){
var num = arr2[i];
if(num == 1){
arr3.push("One");
}
else if(num == 2){
arr3.push("Two");
}
else if(num == 3){
arr3.push("Three");
}
else if(num == 4){
arr3.push("Fou... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You will be given a number in decimal form and your task is to convert it to
// binary format. The function should return a string,... | } | |
//Given a positive integer n, return the product of the odd digits.
// Return 0 if all digits are even.
// For example:
// >>> digits(1)
// 1
// >>> digits(4)
// 0
// >>> digits(235)
// 15
function digits(n){
if(!n){
return "error";
}
if(n < 0){
return "error";
}
var temp = 0;
va... | for(n; n > 0; n = Math.floor(n/10)){ | temp = n % 10;
if(temp % 2 != 0){
prod *= temp;
odd = false;
}
}
if(odd){
return 0;
}
return prod;
}
|
def int_to_mini_roman(number: int) -> str:
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19)
'xix'
>>> int_to_mini_roman(152)
'clii'
>>> int_to_mini_roman(... | 4: 'iv', | 1: 'i'
}
roman_numeral = ''
for key in sorted(roman_numerals.keys(), reverse=True):
roman_numeral += roman_numerals[key] * (number // key)
number = number % key
return roman_numeral
|
def valid_date(date: str) -> bool:
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or hi... | return False | if len(str(date_list[2])) != 4:
return False
return True |
def choose_num(x: int, y: int) -> int:
"""This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
>>> choose_num(12, 15)
14
>>> choose_num... | return max(even_numbers) if even_numbers else -1 | |
//Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
// For each of the group, output the deepest level of nesting of parentheses.
// E.g. (()()) has maximum two levels of nesting while ((())) has three.
// >>> parse_nested_parens("(()()) ((())) () ((())()())")
//... | if (level > maxlevel){ | maxlevel = level;
}
}
else if (paren_string[i] == ")"){
level -= 1;
}
else if (paren_string[i] == " "){
result.push(maxlevel);
maxlevel = 0;
level = 0;
}
}
result.push(maxlevel);
return result... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into s... | temp.append(c); | if (open_paren == 0) {
output.add(temp.toString());
}
}
}
return output;
}
} |
//Return n-th Fibonacci number.
// >>> fib(10)
// 55
// >>> fib(1)
// 1
// >>> fib(8)
// 21
function fib(n){
if(n <= 2){
return 1;
} else {
return fib(n-1) + fib(n-2);
} | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// remove_vowels is a function that takes string and returns string without vowels.
// >>> removeVowels((""))
// ("")
// >>> r... | } | } |
from typing import List
def sort_even(l: List[int]) -> List[int]:
"""This function takes a list l and returns a list l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
>>> sort_even([1, 2, 3])
[... | if l: | temp: List[int] = []
for i in range(0, len(l), 2):
temp.append(l[i])
temp.sort()
for i in range(0, len(l), 2):
l[i] = temp[i // 2]
return l |
//Write a function that accepts two arrays of strings and returns the array that has
// total number of chars in the all strings of the array less than the other array.
// if the two arrays have the same number of chars, return the first array.
// Examples
// >>> total_match([], [])
// []
// >>> total_match(["hi", "ad... | if(sum_lst1 > sum_lst2){ | return lst2;
}
else{
return lst1;
}
}
|
//You are given an array of integers.
// You need to find the largest prime value and return the sum of its digits.
// Examples:
// >>> skjkasdkd([0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3])
// 10
// >>> skjkasdkd([1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1])
// 25
// >>> skj... | } | return true;
}
let max = Math.max(...lst.filter(x=>prime(x)));
let digits = String(max).split('');
let sum = 0;
for (let i=0; i<digits.length; i++){
sum += Number(digits[i]);
}
return sum;
} |
from typing import List
def can_arrange(arr: List[int]) -> int:
"""Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
... | ans = -1 | for i in range(len(arr)):
if i != 0 and arr[i] < arr[i - 1]:
ans = i
return ans
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// xs represent coefficients of a polynomial.
// xs[0] + xs[1] * x + xs[2] * x^2 + ....
// Return derivative of this polynomial in... | for (int i = 1; i < xs.size(); i++) { | ans.add(xs.get(i) * i);
}
return ans;
}
} |
//You are given an array of two strings, both strings consist of open
// parentheses '(' or close parentheses ')' only.
// Your job is to check if it is possible to concatenate the two strings in
// some order, that the resulting string will be good.
// A string S is considered to be good if and only if all parentheses... | return stack.length === 0; | };
const str1 = lst[0];
const str2 = lst[1];
if (is_good(str1 + str2)){
return 'Yes';
}
if (is_good(str2 + str1)){
return 'Yes';
}
return 'No';
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You will be given the name of a class (a string) and an array array list of extensions.
// The extensions are to be used to load ad... | for (String s : extensions) { | int cap = (int)s.chars().filter(c -> Character.isUpperCase(c)).count();
int sm = (int)s.chars().filter(c -> Character.isLowerCase(c)).count();
int diff = cap - sm;
if (diff > strength) {
strength = diff;
strongest = s;
}
... |
//You have to write a function which validates a given date string and
// returns true if the date is valid otherwise false.
// The date is valid if all of the following rules are satisfied:
// 1. The date string is not empty.
// 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12... | var year = parseInt(date_arr[2]); | if(month < 1 || month > 12){
return false;
}else if(month == 2){
if(day < 1 || day > 29){
return false;
}
}else if((month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) && (day < 1 || day > 31)){
... |
from typing import List, Tuple, Optional
def largest_smallest_integers(lst: List[int]) -> Tuple[Optional[int], Optional[int]]:
"""
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in a list.
If there is no neg... | return (largest_negative, smallest_positive) | |
//We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
// numbers in the array will be randomly ordered. Your task is to determine if
// it is possible to get an array sorted in non-decreasing order by performing
// the following operation on the given array:
// You are allowed to perform right shift o... | var i = 0; | var temp = 0;
for(var i = 0; i < arr.length - 1; i++){
if(arr[i] > arr[i + 1]){
diff_count += 1;
}
}
if(diff_count > 1){
return false;
}
else{
return true;
}
} |
//Given an integer. return an array that has the number of even and odd digits respectively.
// Example:
// >>> even_odd_count(-12)
// [1, 1]
// >>> even_odd_count(123)
// [1, 2]
function even_odd_count(num){
num = Math.abs(num);
var evens = 0;
var odds = 0;
for(var i = 0; i < num.toString().length; i++){
if(num.... | odds ++; | }
}
return [evens, odds];
}
|
//Return true is array elements are monotonically increasing or decreasing.
// >>> monotonic([1, 2, 4, 20])
// true
// >>> monotonic([1, 20, 4, 10])
// false
// >>> monotonic([4, 1, 0, -10])
// true
function monotonic(l){
if(l.length <= 1){
return true;
}
if(l[0] < l[1]){ | for(var i = 1; i < l.length - 1; i++){ | if(l[i] > l[i + 1]){
return false;
}
}
}
else{
for(var i = 1; i < l.length - 1; i++){
if(l[i] < l[i + 1]){
return false;
}
}
}
return true;
}
|
//Given an array of integers nums, find the minimum sum of any non-empty sub-array
// of nums.
// Example
// >>> minSubArraySum([2, 3, 4, 1, 2, 4])
// 1
// >>> minSubArraySum([-1, -2, -3])
// -6
function minSubArraySum(nums){
let sum = 0;
let minSum = nums[0];
for(let i = 0; i < nums.length; i++){ | sum += nums[i]; | if(sum < minSum){
minSum = sum;
}
if(sum > 0){
sum = 0;
}
}
return minSum;
}
|
//Task
// Write a function that takes a string as input and returns the sum of the upper characters only'
// ASCII codes.
// Examples:
// >>> digitSum("")
// 0
// >>> digitSum("abAB")
// 131
// >>> digitSum("abcCd")
// 67
// >>> digitSum("helloE")
// 69
// >>> digitSum("woArBld")
// 131
// >>> digitSum("aAaaaXa")
// 15... | sum += s.charCodeAt(i); | }
}
return sum;
} |
//Given a string s and a natural number n, you have been tasked to implement
// a function that returns an array of all words from string s that contain exactly
// n consonants, in order these words appear in the string s.
// If the string s is empty then the function should return an empty array.
// Note: you may as... | if(n > 0){ | return selected.filter(e => e.match(/[bcdfghjklmnpqrstvwxyz]/gi).length == n);
}else{
return [];
}
}
|
//Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <= num <= 1000
// Examples:
// >>> int_to_mini_roman(19)
// "xix"
// >>> int_to_mini_roman(152)
// "clii"
// >>> int_to_mini_roman(426)
// "cdxxvi"
function int_to_mini_roman(number){
var r... | number -= key_list[i]; | break;
}
}
}
return output;
}
|
//Given an array arr of integers, find the minimum number of elements that
// need to be changed to make the array palindromic. A palindromic array is an array that
// is read the same backwards and forwards. In one change, you can change one element to any other element.
// For example:
// >>> smallest_change([1, 2, 3... | } | return changes;
} |
//You are given a non-empty array of positive integers. Return the greatest integer that is greater than
// zero, and has a frequency greater than or equal to the value of the integer itself.
// The frequency of an integer is the number of times it appears in the array.
// If no such a value exist, return -1.
// Exam... | if (keys[i] > max && h[keys[i]] >= keys[i]){ | max = keys[i];
}
}
if (max == 0){
return -1;
}
return max;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | } | while (num >= 1) {
res += "i";
num -= 1;
}
return res;
}
} |
//We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
// numbers in the array will be randomly ordered. Your task is to determine if
// it is possible to get an array sorted in non-decreasing order by performing
// the following operation on the given array:
// You are allowed to perform right shift o... | var temp = 0; | for(var i = 0; i < arr.length - 1; i++){
if(arr[i] > arr[i + 1]){
diff_count += 1;
}
}
if(diff_count > 1){
return false;
}
else{
return true;
}
} |
//There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
// Uranus, Neptune.
// Write a function that takes two planet names as strings planet1 and planet2.
// The function should return an array containing all planets whose orbit... | res.push(keys[i]); | }
return res;
} |
//Given a string 'text', return its md5 hash equivalent string.
// If 'text' is an empty string, return undefined.
// >>> string_to_md5("Hello world")
// "3e25960a79dbc69b674cd4ec67a72c62"
function string_to_md5(text){
if(text === ''){
return undefined;
}
return require('crypto').createHash('md5').u... | } | |
//For a given array of input numbers, calculate Mean Absolute Deviation
// around the mean of this dataset.
// Mean Absolute Deviation is the average absolute difference between each
// element and a centerpoint (mean in this case):
// MAD = average | x - x_mean |
// >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])
//... | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
// For each of the group... | } | }
result.add(max_depth);
}
return result;
}
} |
//You are given a non-empty array of positive integers. Return the greatest integer that is greater than
// zero, and has a frequency greater than or equal to the value of the integer itself.
// The frequency of an integer is the number of times it appears in the array.
// If no such a value exist, return -1.
// Exam... | } | return max;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that takes a message, and encodes in such a
// way that it swaps case of all letters, replaces all vowels in
... | } | |
//Given the lengths of the three sides of a triangle. Return the area of
// the triangle rounded to 2 decimal points if the three sides form a valid triangle.
// Otherwise return -1
// Three sides make a valid triangle when the sum of any two sides is greater
// than the third side.
// Example:
// >>> triangle_area(3... | if(a+b>c && a+c>b && b+c>a){ | var s = (a+b+c)/2;
return Math.sqrt(s*(s-a)*(s-b)*(s-c)).toFixed(2);
}else{
return -1;
}
}
|
from typing import List
def smallest_change(arr: List[int]) -> int:
"""
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change ... | while start < end: | if arr[start] != arr[end]:
count += 1
start += 1
end -= 1
return count
|
//Return true if a given number is prime, and false otherwise.
// >>> is_prime(6)
// false
// >>> is_prime(101)
// true
// >>> is_prime(11)
// true
// >>> is_prime(13441)
// true
// >>> is_prime(61)
// true
// >>> is_prime(4)
// false
// >>> is_prime(1)
// false
function is_prime(n){
if (n==1) {
return fals... | return false; | }
}
return true;
}
|
//Filter an input array of strings only for ones that contain given substring
// >>> filter_by_substring([], "a")
// []
// >>> filter_by_substring(["abc", "bacd", "cde", "array"], "a")
// ["abc", "bacd", "array"]
function filter_by_substring(strings, substring){
var filtered = [];
for(var i = 0; i < strings.len... | } | }
return filtered;
} |
//This function takes an array l and returns an array l' such that
// l' is identical to l in the odd indicies, while its values at the even indicies are equal
// to the values of the even indicies of l, but sorted.
// >>> sort_even([1, 2, 3])
// [1, 2, 3]
// >>> sort_even([5, 6, 3, 4])
// [3, 6, 5, 4]
function sort_ev... | var l2 = [] | for(var i = 0; i < l.length; i += 2){
l2.push(l[i])
}
l2.sort(function(a, b){return a - b})
for(var i = 0; i < l2.length; i++){
l[i * 2] = l2[i]
}
return l
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer n, return the product of the odd digits.
// Return 0 if all digits are even.
// For example:
// >>... | return digits(n / 10) * (n % 2 == 1 ? n % 10 : 1); | }
} |
//Write a function that accepts an array of strings as a parameter,
// deletes the strings that have odd lengths from it,
// and returns the resulted array with a sorted order,
// The array is always an array of strings and never an array of numbers,
// and it may contain duplicates.
// The order of the array should be... | if(a < b){ | return -1;
}
else if(a > b){
return 1;
}
else{
return 0;
}
}
});
}
var a = ["aa", "a", "aaa"];
var b = ["ab", "a", "aaa", "cd"]; |
//Return median of elements in the array l.
// >>> median([3, 1, 2, 4, 5])
// 3
// >>> median([-10, 4, 6, 1000, 10, 20])
// 15.0
function median(l){
let middle = Math.floor(l.length / 2); | let sorted = l.sort((a, b) => a - b); | if (l.length % 2 === 0) {
return (sorted[middle - 1] + sorted[middle]) / 2;
} else {
return sorted[middle];
}
}
|
from typing import Union
def rounded_avg(n: int, m: int) -> Union[str, int]:
"""You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater... | if n <= m: | rounded_avg = round(((n + m) / 2))
return(bin(rounded_avg))
else:
return(-1) |
//Input are two strings a and b consisting only of 1s and 0s.
// Perform binary XOR on these inputs and return result also as a string.
// >>> string_xor("010", "110")
// "100"
function string_xor(a, b){
var arrayA = [];
var arrayB = [];
var arrayXOR = [];
var result = '';
for (var i = 0; i < a.length; i++) {... | arrayXOR.push(0); | }
}
result = arrayXOR.join('');
return result;
} |
//There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
// Uranus, Neptune.
// Write a function that takes two planet names as strings planet1 and planet2.
// The function should return an array containing all planets whose orbit... | var position2 = keys.indexOf(planet2); | if(position1 > position2){
var temp = position1;
position1 = position2;
position2 = temp;
}
var res = [];
for(var i = position1 + 1; i < position2; i++){
res.push(keys[i]);
}
return res;
} |
//Given a string representing a space separated lowercase letters, return an object
// of the letter with the most repetition and containing the corresponding count.
// If several letters have the same occurrence, return all of them.
// Example:
// >>> histogram("a b c")
// {"a": 1, "b": 1, "c": 1}
// >>> histogram("a ... | } | var lst = test.split(" ");
var count = {};
for (var i = 0; i < lst.length; i++){
if (count[lst[i]]){
count[lst[i]] += 1;
}
else{
count[lst[i]] = 1;
}
}
console.log(count);
var max = 0;
var result = {};
for (var key in count){
if (count[key] > max){
max = count[key];... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that takes a string and returns an ordered version of it.
// Ordered version of string, is a string where all word... | } | } |
//Implement a function that takes an non-negative integer and returns an array of the first n
// integers that are prime numbers and less than n.
// for example:
// >>> count_up_to(5)
// [2, 3]
// >>> count_up_to(11)
// [2, 3, 5, 7]
// >>> count_up_to(0)
// []
// >>> count_up_to(20)
// [2, 3, 5, 7, 11, 13, 17, 19]
// >... | prime = false; | break;
}
}
if (prime) output.push(i);
}
return output;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of numbers, return whether or not they are sorted
// in ascending order. If array list has more than 1 du... | return false; | }
else {
seen_2_in_a_row = true;
}
}
else {
seen_2_in_a_row = false;
}
previous_... |
//Return maximum element in the array.
// >>> max_element([1, 2, 3])
// 3
// >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
// 123
function max_element(l){
return Math.max.apply(null, l); | } | |
from typing import Union
def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]:
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values ... | elif isinstance(a, float) and isinstance(b, float): | if a > b:
return a
elif a < b:
return b
else:
return None
elif isinstance(a, str) and isinstance(b, str):
a_tmp = a.replace(',', '.')
b_tmp = b.replace(',', '.')
if float(a_tmp) > float(b_tmp):
return a
elif floa... |
//Task
// We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
// then check if the result string is palindrome.
// A string is called palindrome if it reads the same backward as forward.
// You should return an array containing the result string and true/fa... | return result; | } |
from typing import List
def numerical_letter_grade(grades: List[float]) -> List[str]:
"""It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
Sh... | elif x > 1.3: | final.append('C-')
elif x > 1.0:
final.append('D+')
elif x > 0.7:
final.append('D')
elif x > 0.0:
final.append('D-')
else:
final.append('E')
return final
|
def get_closest_vowel(word: str) -> str:
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the a... | if word[i] in 'aeiouAEIOU' and word[i-1] not in 'aeiouAEIOU' and word[i+1] not in 'aeiouAEIOU': | return word[i]
return ''
|
//You will be given the name of a class (a string) and an array of extensions.
// The extensions are to be used to load additional classes to the class. The
// strength of the extension is as follows: Let CAP be the number of the uppercase
// letters in the extension's name, and let SM be the number of lowercase letter... | var output = class_name + "."; | var min_strength = 1;
for (var i = 0; i < extensions.length; i++) {
var strength = -1*(extensions[i].replace(/[^A-Z]/g, "").length - extensions[i].replace(/[^a-z]/g, "").length);
if (strength < min_strength) {
min_strength = strength;
output = class_name + "." + extensions[i];
}
}
return... |
//Given a string representing a space separated lowercase letters, return an object
// of the letter with the most repetition and containing the corresponding count.
// If several letters have the same occurrence, return all of them.
// Example:
// >>> histogram("a b c")
// {"a": 1, "b": 1, "c": 1}
// >>> histogram("a ... | } | else{
count[lst[i]] = 1;
}
}
console.log(count);
var max = 0;
var result = {};
for (var key in count){
if (count[key] > max){
max = count[key];
result = {};
result[key] = max;
}
else if (count[key] === max){
result[key] = max;
}
}
return result;
}
|
//Given two arrays operator, and operand. The first array has basic algebra operations, and
// the second array is an array of integers. Use the two given arrays to build the algebric
// expression and return the evaluation of this expression.
// The basic algebra operations:
// Addition ( + )
// Subtraction ( - )
... | } | }
answer = operand[0];
operand.splice(0, 1);
while(operand.length > 0){
switch(operator[0]){
case '+':
answer += operand[0];
break;
case '-':
answer -= operand[0];
break;
}
operand.splice(0, 1);
operator.splice(0, 1);
}
return answer;
}
|
def vowels_count(s: str) -> int:
"""Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
... | while i < len(s): | if (s[i] == 'a' or s[i] == 'e' or s[i] == 'i' or s[i] == 'o' or s[i] == 'u'):
count += 1
if (s[i] == 'y' and i == len(s) - 1):
count += 1
i += 1
return count
|
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | if (typeof key == "string"){ | if (case_type == -1){
if (key == key.toUpperCase()){
case_type = 1;
}
else if (key == key.toLowerCase()){
case_type = 0;
}
else{
return false;
}
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You're given an array array list of deposit and withdrawal operations on a bank account that starts with
// zero balance. Your task... | for (long op : operations) { | balance += op;
if (balance < 0) {
return true;
}
}
return false;
}
} |
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