prefix stringlengths 0 918k | middle stringlengths 0 812k | suffix stringlengths 0 962k |
|---|---|---|
def file_name_check(file_name: str) -> str:
"""Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There shoul... | s_count = 0 | e_count = 0
for i in file_name:
if i.isdigit():
s_count += 1
if i == '.':
e_count += 1
if s_count > 3 or e_count != 1:
return 'No'
s_name = file_name.split('.')[0]
e_name = file_name.split('.')[1]
if not s_name or not e_name or not s_name[0].isalph... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// We have an array array list 'arr' of N integers arr[1], arr[2], ..., arr[N].The
// numbers in the array array list will be randomly... | if (arr.size() == 0) return true; | ArrayList<Long> sorted = new ArrayList<Long>(arr);
Collections.sort(sorted);
for (int i = 0; i < arr.size(); i++) {
ArrayList<Long> copy = new ArrayList<Long>(arr);
long last = copy.remove(copy.size() - 1);
copy.add(0, last);
if (copy.equals(sorted... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given an array array list of integers.
// You need to find the largest prime value and return the sum of its digits.
//... | return 0l; | }
else {
long output = 0l;
while (largestPrime > 0) {
output += largestPrime % 10;
largestPrime /= 10;
}
return output;
}
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupit... | } | ArrayList<String> planetsInBetween = new ArrayList<String>();
for (int i = indexMin + 1; i < indexMax; i++) {
planetsInBetween.add(planets.get(i));
}
return planetsInBetween;
} else {
return new ArrayList<String>();
}
}
} |
//I think we all remember that feeling when the result of some long-awaited
// event is finally known. The feelings and thoughts you have at that moment are
// definitely worth noting down and comparing.
// Your task is to determine if a person correctly guessed the results of a number of matches.
// You are given two ... | let result = []; | for(let i = 0; i < game.length; i++){
if(game[i] === guess[i]){
result.push(0);
} else {
result.push(Math.abs(game[i] - guess[i]));
}
}
return result;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You have to write a function which validates a given date string and
// returns true if the date is valid otherwise false.
// T... | if (parts.length != 3) return valid_date; | try {
int month = Integer.parseInt(parts[0]);
int day = Integer.parseInt(parts[1]);
int year = Integer.parseInt(parts[2]);
if (month < 1 || month > 12) return valid_date;
if (month == 2) {
if (day < 1 || day > 29) return valid_date;
... |
//Change numerical base of input number x to base.
// return string representation after the conversion.
// base numbers are less than 10.
// >>> change_base(8, 3)
// "22"
// >>> change_base(8, 2)
// "1000"
// >>> change_base(7, 2)
// "111"
function change_base(x, base){
let r = x % base;
let q = Math.floor(x /... | return change_base(q, base) + r.toString(); | }
|
//Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
// should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
// alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
// Examples
// >>> split... | } | return count;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a string representing a sentence,
// the sentence contains some words separated by a space,
// and you have to re... | ans.deleteCharAt(ans.length() - 1); | }
return ans.toString();
}
} |
//Given a positive floating point number, it can be decomposed into
// and integer part (largest integer smaller than given number) and decimals
// (leftover part always smaller than 1).
// Return the decimal part of the number.
// >>> truncate_number(3.5)
// 0.5
function truncate_number(number){
return number - Math.... | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list arr of integers, find the minimum number of elements that
// need to be changed to make the array array l... | count++; | }
first++;
last--;
}
return count;
}
} |
//Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
// For each of the group, output the deepest level of nesting of parentheses.
// E.g. (()()) has maximum two levels of nesting while ((())) has three.
// >>> parse_nested_parens("(()()) ((())) () ((())()())")
//... | } | }
else if (paren_string[i] == ")"){
level -= 1;
}
else if (paren_string[i] == " "){
result.push(maxlevel);
maxlevel = 0;
level = 0;
}
}
result.push(maxlevel);
return result;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Complete the function that takes two integers and returns
// the product of their unit digits.
// Assume the input is always v... | } | } |
//You are given a 2 dimensional data, as a nested arrays,
// which is similar to matrix, however, unlike matrices,
// each row may contain a different number of columns.
// Given lst, and integer x, find integers x in the array,
// and return array of arrays, [(x1, y1), (x2, y2) ...] such that
// each array is a coordi... | } | }
return coordinates.sort(function(a, b){
return a[0] - b[0] || b[1] - a[1];
});
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a word. Your task is to find the closest vowel that stands between
// two consonants from the right side of the word... | for (int i = idx.size() - 1; i >= 0; i--) { | int j = idx.get(i);
if (j == 0 || j == word.length() - 1) continue;
char left = word.charAt(j - 1);
char right = word.charAt(j + 1);
if (consonants.indexOf(left) != -1 && consonants.indexOf(right) != -1) {
return String.valueOf(word.charAt(j));... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that returns true if the object q will fly, and false otherwise.
// The object q will fly if it's balanced (it is ... | return true; | }
Long sum = 0l;
for (int i = 0; i < q.size(); i++) {
sum += q.get(i);
}
if (sum > w) {
return false;
}
for (int i = 0; i < q.size() / 2; i++) {
if (q.get(i) != q.get(q.size() - 1 - i)) {
return false;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the indicies that... | if (i % 3 == 0) { | l_s.add(l_e.get(j));
j++;
} else {
l_s.add(l_r.get(i - j));
}
}
return l_s;
}
} |
//For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
// >>> flip_case("Hello")
// "hELLO"
function flip_case(string){
var result = ""; | for(var i = 0; i < string.length; i++){ | if(string[i] == string[i].toUpperCase()){
result += string[i].toLowerCase();
}else{
result += string[i].toUpperCase();
}
}
return result;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of numbers, return whether or not they are sorted
// in ascending order. If array list has more than 1 du... | if (seen_2_in_a_row) { | return false;
}
else {
seen_2_in_a_row = true;
}
}
else {
seen_2_in_a_row = false;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given an array array list of integers.
// You need to find the largest prime value and return the sum of its digits.
//... | continue; | }
if (item == 2) {
counter = 1;
}
else {
int l = 1;
while (l <= (int) number) {
if (number % l == 0) {
counter++;
}
l++;
}
... |
//You are given a word. Your task is to find the closest vowel that stands between
// two consonants from the right side of the word (case sensitive).
// Vowels in the beginning and ending doesn't count. Return empty string if you didn't
// find any vowel met the above condition.
// You may assume that the given stri... | return "" | } else {
while (i >= 0) {
if (vowels.includes(word[i])) {
if (i > 0 && i < word.length - 1) {
if (!vowels.includes(word[i-1]) && !vowels.includes(word[i+1])) {
result.push(word[i]);
}
}
}
... |
from typing import Union
def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]:
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values ... | return b | else:
return None
elif isinstance(a, float) and isinstance(b, int):
if a > b:
return a
elif a < b:
return b
else:
return None
elif isinstance(a, str) and isinstance(b, int):
a_tmp = a.replace(',', '.')
if float(a_tmp... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Task
// Write a function that takes a string as input and returns the sum of the upper characters only'
// ASCII codes.
// ... | return s.chars().filter(i -> i >= 65 && i <= 90).sum(); | }
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Find how many times a given substring can be found in the original string. Count overlaping cases.
// >>> howManyTimes((""), ("a"))... | } | }
return count;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// brackets is a string of "(" and ")".
// return true if every opening bracket has a corresponding closing bracket.
// >>> correc... | } | }
return balance == 0;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of numbers, return whether or not they are sorted
// in ascending order. If array list has more than 1 du... | } | else {
seen_2_in_a_row = true;
}
}
else {
seen_2_in_a_row = false;
}
previous_number = number.intValue();
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a string representing a space separated lowercase letters, return a hash map
// of the letter with the most repetition and co... | } | long max = 0;
for (String key : hm.keySet()) {
if (hm.get(key) > max) {
max = hm.get(key);
}
}
for (String key : hm.keySet()) {
if (hm.get(key) == max) {
s.put(key, hm.get(key));
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | } | while (num >= 10) {
res += "x";
num -= 10;
}
if (num >= 9) {
res += "ix";
num -= 9;
}
if (num >= 5) {
res += "v";
num -= 5;
}
if (num >= 4) {
res += "iv";
num -= 4;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You will be given a string of words separated by commas or spaces. Your task is
// to split the string into words and return an arr... | return al; | }
} |
//Task
// Write a function that takes a string as input and returns the sum of the upper characters only'
// ASCII codes.
// Examples:
// >>> digitSum("")
// 0
// >>> digitSum("abAB")
// 131
// >>> digitSum("abcCd")
// 67
// >>> digitSum("helloE")
// 69
// >>> digitSum("woArBld")
// 131
// >>> digitSum("aAaaaXa")
// 15... | } | |
//Given a grid with N rows and N columns (N >= 2) and a positive integer k,
// each cell of the grid contains a value. Every integer in the range [1, N * N]
// inclusive appears exactly once on the cells of the grid.
// You have to find the minimum path of length k in the grid. You can start
// from any cell, and in e... | } | let nextCell = neighbours[0];
for(let i = 0; i < neighbours.length; i++){
let curr = neighbours[i];
if(curr < nextCell){
nextCell = curr;
}
}
currCell = nextCell;
}
return path;
} |
//Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> is_equal_to_sum_even(4)
// false
// >>> is_equal_to_sum_even(6)
// false
// >>> is_equal_to_sum_even(8)
// true
function is_equal_to_sum_even(n){
let m =0;
for(let i=2;i<n;i+=2){ | for(let j=2;j<n;j+=2){ | for(let k=2;k<n;k+=2){
for(let l=2;l<n;l+=2){
if((i+j+k+l)==n){
m=1;
break;
}
}
}
}
}
if(m==1){
return true;
}
else{
return false;
}... |
//Given a string, find out how many distinct characters (regardless of case) does it consist of
// >>> count_distinct_characters("xyzXYZ")
// 3
// >>> count_distinct_characters("Jerry")
// 4
function count_distinct_characters(string){
var arr = string.split("");
var result = []; | for(var i = 0; i < arr.length; i++){ | if(result.indexOf(arr[i].toLowerCase()) < 0){
result.push(arr[i].toLowerCase());
}
}
return result.length;
}
|
from typing import List, Optional
def next_smallest(lst: List[int]) -> Optional[int]:
"""
You are given a list of integers.
Write a function next_smallest() that returns the 2nd smallest element of the list.
Return None if there is no such element.
>>> next_smallest([1, 2, 3, 4, 5])
2
>>> n... | min1 = min(lst[0], lst[1]) | min2 = max(lst[0], lst[1])
for i in range(2, len(lst)):
if lst[i] < min1:
min2 = min1
min1 = lst[i]
elif lst[i] < min2:
min2 = lst[i]
return min2 if min1 != min2 else None
|
//Return sorted unique common elements for two arrays.
// >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
// [1, 5, 653]
// >>> common([5, 3, 2, 8], [3, 2])
// [2, 3]
function common(l1, l2){
| return [...new Set(l1.filter(n=>l2.includes(n)))].sort(); | }
|
def correct_bracketing(brackets: str) -> bool:
""" brackets is a string of "<" and ">".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing('<')
False
>>> correct_bracketing('<>')
True
>>> correct_bracketing('<<><>>')
True
>>> correct_bra... | return False | return num_left_brackets == 0
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the indicies that... | } | }
}
int j = 0;
for (int i = 0; i < l.size(); i++) {
if (i % 3 == 0) {
l_s.add(l_e.get(j));
j++;
} else {
l_s.add(l_r.get(i - j));
}
}
return l_s;
}
} |
//sum_to_n is a function that sums numbers from 1 to n.
// >>> sum_to_n(30)
// 465
// >>> sum_to_n(100)
// 5050
// >>> sum_to_n(5)
// 15
// >>> sum_to_n(10)
// 55
// >>> sum_to_n(1)
// 1
function sum_to_n(n){
var sum = 0;
for(var i = 1; i <= n; i++){ | sum += i; | }
return sum;
}
|
//Write a function that accepts an array of strings as a parameter,
// deletes the strings that have odd lengths from it,
// and returns the resulted array with a sorted order,
// The array is always an array of strings and never an array of numbers,
// and it may contain duplicates.
// The order of the array should be... | } | else{
return 0;
}
}
});
}
var a = ["aa", "a", "aaa"];
var b = ["ab", "a", "aaa", "cd"]; |
from typing import Union
def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]:
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values ... | return b | |
//You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Y... | return primes.includes(length) ? "YES" : "NO"; | }
|
//There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
// Uranus, Neptune.
// Write a function that takes two planet names as strings planet1 and planet2.
// The function should return an array containing all planets whose orbit... | var res = []; | for(var i = position1 + 1; i < position2; i++){
res.push(keys[i]);
}
return res;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return array list of prime factors of given integer in the order from smallest to largest.
// Each of the factors should be array l... | ArrayList<Long> factors = new ArrayList<Long>(); | for (long d = 2; d*d <= n; d++) {
while (n % d == 0) {
factors.add(d);
n /= d;
}
}
if (n > 1)
factors.add(n);
return factors;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the odd indicies,... | } | return res;
}
} |
//Given a positive integer n, return the count of the numbers of n-digit
// positive integers that start or end with 1.
function starts_one_ends(n){
let ones = [];
for(let i = Math.pow(10, n-1); i < Math.pow(10, n); i++){
if(i.toString().startsWith('1') || i.toString().endsWith('1')){
ones.p... | } | |
from typing import List
def count_up_to(n: int) -> List[int]:
"""Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
>>> count_up_to(5)
[2, 3]
>>> count_up_to(11)
[2, 3, 5, 7]
>>> count... | return [] | result = []
for number in range(2, n):
is_prime = True
for divisor in range(2, number):
if number % divisor == 0:
is_prime = False
break
if is_prime:
result.append(number)
return result
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Implement the function f that takes n as a parameter,
// and returns an array array list of size n, such that the value of the elem... | } | |
//Write a function that accepts an array of strings as a parameter,
// deletes the strings that have odd lengths from it,
// and returns the resulted array with a sorted order,
// The array is always an array of strings and never an array of numbers,
// and it may contain duplicates.
// The order of the array should be... | } | else if(a.length > b.length){
return 1;
}
else{
if(a < b){
return -1;
}
else if(a > b){
return 1;
}
else{
return 0;
}
}
});
}
var a = ["aa", "a", "aaa"]... |
//prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> prime_fib(1)
// 2
// >>> prime_fib(2)
// 3
// >>> prime_fib(3)
// 5
// >>> prime_fib(4)
// 13
// >>> prime_fib(5)
// 89
function prime_fib(n){
function isPrime(number){
if(number <= 3){
return number > 1;
... | num--; | }
return b;
}
var res = 0;
var fibNum = 0;
while(res < n){
if(isPrime(fib(fibNum))){
res++;
}
fibNum++;
}
return fib(fibNum - 1);
} |
//This function takes an array l and returns an array l' such that
// l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
// to the values of the corresponding indicies of l, but sorted.
// >>> sort_third([1, 2, 3])
// [1, 2, 3]
//... | } | }
y.sort();
k=0;
for(let i=0;i<l.length;i++){
if(i%3==0){
x[i]=y[k];
k=k+1;
}
}
return x;
} |
//Given an array of numbers, return whether or not they are sorted
// in ascending order. If array has more than 1 duplicate of the same
// number, return false. Assume no negative numbers and only integers.
// Examples
// >>> is_sorted([5])
// true
// >>> is_sorted([1, 2, 3, 4, 5])
// true
// >>> is_sorted([1, 3, 2, 4... | if (last == null){ | last = x;
} else if (x < last){
return false;
} else if (x == last){
if (dupe_found){
return false;
} else {
dupe_found = true;
}
} else {
last = x;
dupe_found = false;
}
... |
//Given array of numbers (of at least two elements), apply a linear transform to that array,
// such that the smallest number will become 0 and the largest will become 1
// >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
// [0.0, 0.25, 0.5, 0.75, 1.0]
function rescale_to_unit(numbers){
var min = Math.min.apply(Math, n... | var sub = max - min; | var unit = [];
for (var i = 0; i < numbers.length; i++) {
unit.push((numbers[i] - min) / sub);
}
return unit;
}
|
from typing import List
def search(lst: List[int]) -> int:
"""
You are given a non-empty list of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times i... | return maxValue | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | num -= 40; | }
while (num >= 10) {
res += "x";
num -= 10;
}
if (num >= 9) {
res += "ix";
num -= 9;
}
if (num >= 5) {
res += "v";
num -= 5;
}
if (num >= 4) {
res += "iv";
num... |
//Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous ... | odd_numbers.push(1) | return odd_numbers
}
}
|
//Given a string representing a space separated lowercase letters, return an object
// of the letter with the most repetition and containing the corresponding count.
// If several letters have the same occurrence, return all of them.
// Example:
// >>> histogram("a b c")
// {"a": 1, "b": 1, "c": 1}
// >>> histogram("a ... | } | return result;
}
|
from typing import Union
def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]:
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values ... | return a | elif a < b:
return b
else:
return None
elif isinstance(a, float) and isinstance(b, int):
if a > b:
return a
elif a < b:
return b
else:
return None
elif isinstance(a, str) and isinstance(b, int):
a_tmp = a... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of numbers, return whether or not they are sorted
// in ascending order. If array list has more than 1 du... | } | }
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes two positive numbers x and y and returns the
// biggest even integer number that is in the range [x, y] inclusi... | return chosen; | }
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of integers nums, find the minimum sum of any non-empty sub-array array list
// of nums.
// Example
... | long prevMinSum = Long.MAX_VALUE; | for (int i = 0; i < nums.size(); i++) {
long currSum = nums.get(i);
if (currSum < prevMinSum) {
prevMinSum = currSum;
}
if (currSum < minSum) {
minSum = currSum;
}
for (int j = i + 1; j < nums.size(); j++) {
... |
def fib4(n: int) -> int:
"""The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-... | return 0 | else:
return fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4)
|
//In this problem, you will implement a function that takes two arrays of numbers,
// and determines whether it is possible to perform an exchange of elements
// between them to make lst1 an array of only even numbers.
// There is no limit on the number of exchanged elements between lst1 and lst2.
// If it is possible ... | } | |
//In this problem, you will implement a function that takes two arrays of numbers,
// and determines whether it is possible to perform an exchange of elements
// between them to make lst1 an array of only even numbers.
// There is no limit on the number of exchanged elements between lst1 and lst2.
// If it is possible ... | if(lst1[num1] % 2 !== 0){ | exchange = false;
if(num2 < lst2.length){
while(num2 < lst2.length && exchange == false){
if(lst2[num2] % 2 == 0){
lst1[num1] = lst2[num2];
exchange = true;
}
num2++;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Checks if given string is a palindrome
// >>> isPalindrome((""))
// (true)
// >>> isPalindrome(("aba"))
// (true)
/... | boolean isPalindrome = true; | int left = 0;
int right = text.length() - 1;
while (left < right) {
if (text.charAt(left) != text.charAt(right)) {
isPalindrome = false;
break;
}
left++;
right--;
}
return isPalindrome;
}
} |
//You're a hungry rabbit, and you already have eaten a certain number of carrots,
// but now you need to eat more carrots to complete the day's meals.
// you should return an array of [ total number of eaten carrots after your meals,
// the number of carrots left after your meals ]
// if there are not enough remaining ... | else return [number + need, remaining - need]; | }
|
from typing import List, Optional
def prod_signs(arr: List[int]) -> Optional[int]:
"""
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty a... | sign_arr.append(-1) | else:
sign_arr.append(0)
return sum(map(abs, arr)) * product(sign_arr) |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
// For each of the group... | for (char c : paren.toCharArray()) { | if (c == '(') {
current_depth += 1;
max_depth = Math.max(max_depth, current_depth);
} else if (c == ')') {
current_depth -= 1;
}
}
result.add(max_depth);
}
return result;
... |
//You are given a string s.
// if s[i] is a letter, reverse its case from lower to upper or vise versa,
// otherwise keep it as it is.
// If the string contains no letters, reverse the string.
// The function should return the resulted string.
// Examples
// >>> solve("1234")
// "4321"
// >>> solve("ab")
// "AB"
// >>... | }); | return swapped.join('');
}
return s.split('').reverse().join('');
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Filter an input array list of strings only for ones that start with a given prefix.
// >>> filterByPrefix((new ArrayList<String>(Ar... | } | } |
//There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
// Uranus, Neptune.
// Write a function that takes two planet names as strings planet1 and planet2.
// The function should return an array containing all planets whose orbit... | 'Saturn':6, | 'Uranus':7,
'Neptune':8
}
if(!planets[planet1] || !planets[planet2]){
return [];
}
var keys = Object.keys(planets);
var position1 = keys.indexOf(planet1);
var position2 = keys.indexOf(planet2);
if(position1 > position2){
var temp = position1;
position1... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupit... | } | |
//Circular shift the digits of the integer x, shift the digits right by shift
// and return the result as a string.
// If shift > number of digits, return digits reversed.
// >>> circular_shift(12, 1)
// "21"
// >>> circular_shift(12, 2)
// "12"
function circular_shift(x, shift){
var str = x.toString();
var len = str... | res += str[i]; | }
}else{
res = str.substring(len-shift) + str.substring(0, len-shift);
}
return res;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that takes an array array list of numbers as input and returns
// the number of elements in the array array list ... | digits.add(n % 10); | n /= 10;
}
Collections.reverse(digits);
return digits.stream().mapToLong(i -> i).toArray();
}
}
helper h = new helper();
return nums.stream().filter(x -> x > 10).filter(x -> {
long firstDigit = h.getFirst... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of integers nums, find the minimum sum of any non-empty sub-array array list
// of nums.
// Example
... | for (int j = i + 1; j < nums.size(); j++) { | currSum += nums.get(j);
if (currSum < prevMinSum) {
prevMinSum = currSum;
}
if (currSum < minSum) {
minSum = currSum;
}
}
}
return minSum;
}
} |
//Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> is_equal_to_sum_even(4)
// false
// >>> is_equal_to_sum_even(6)
// false
// >>> is_equal_to_sum_even(8)
// true
function is_equal_to_sum_even(n){
let m =0;
for(let i=2;i<n;i+=2){
for(let ... | return true; | }
else{
return false;
}
} |
def file_name_check(file_name: str) -> str:
"""Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There shoul... | e_count = 0 | for i in file_name:
if i.isdigit():
s_count += 1
if i == '.':
e_count += 1
if s_count > 3 or e_count != 1:
return 'No'
s_name = file_name.split('.')[0]
e_name = file_name.split('.')[1]
if not s_name or not e_name or not s_name[0].isalpha():
ret... |
//Complete the function that takes two integers and returns
// the product of their unit digits.
// Assume the input is always valid.
// Examples:
// >>> multiply(148, 412)
// 16
// >>> multiply(19, 28)
// 72
// >>> multiply(2020, 1851)
// 0
// >>> multiply(14, -15)
// 20
function multiply(a, b){
| let aStr = a.toString() | let bStr = b.toString()
return parseInt(aStr[aStr.length - 1]) * parseInt(bStr[bStr.length - 1])
}
|
//Your task is to write a function that returns true if a number x is a simple
// power of n and false in other cases.
// x is a simple power of n if n**int=x
// For example:
// >>> is_simple_power(1, 4)
// true
// >>> is_simple_power(2, 2)
// true
// >>> is_simple_power(8, 2)
// true
// >>> is_simple_power(3, 2)
// fa... | return false; | }
return is_simple_power(x/n, n);
}
|
//Given array of integers, return array in strange order.
// Strange sorting, is when you start with the minimum value,
// then maximum of the remaining integers, then minimum and so on.
// Examples:
// >>> strange_sort_list([1, 2, 3, 4])
// [1, 4, 2, 3]
// >>> strange_sort_list([5, 5, 5, 5])
// [5, 5, 5, 5]
// >>> str... | } | else{
output.push(Math.max.apply(null, tmp));
}
tmp.splice(tmp.indexOf(output[i]), 1);
}
return output;
} |
from typing import List
def maximum(arr: List[int], k: int) -> List[int]:
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
Example 1:
>>> maximum([-3, -4, 5], 3)
[-4, -3, 5]
Example 2:
>>> maximum([4, -... | max_num = max(arr) | arr.remove(max_num)
return [max_num] + get_max(arr, k - 1)
return sorted(get_max(arr, k))
|
def starts_one_ends(n: int) -> int:
"""
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
"""
count = 0
for i in range(10**(n-1), 10**n):
if i // 10**(n-1) == 1 or i % 10 == 1:
count += 1 | return count | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of integers, sort the integers that are between 1 and 9 inclusive,
// reverse the resulting array array l... | res.add(a[i.intValue() - 1]); | }
return res;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that accepts an array array list of strings as a parameter,
// deletes the strings that have odd lengths from it,
... | return s1.compareTo(s2); | }
return s1.length() - s2.length();
}
});
return result;
}
} |
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | } | else if (key == key.toLowerCase()){
case_type = 0;
}
else{
return false;
}
}
else if (case_type == 1){
if (key != key.toUpperCase()){
return false;
... |
def get_max_triples(n: int) -> int:
"""
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multipl... | k = j + 1 | return count
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | res += "cd"; | num -= 400;
}
while (num >= 100) {
res += "c";
num -= 100;
}
if (num >= 90) {
res += "xc";
num -= 90;
}
if (num >= 50) {
res += "l";
num -= 50;
}
if (num >= 40) {
... |
//It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algorithm for grading.
// The only problem is, she has lost the code she used for grading.
// She has given you an array of GPAs for some students and you have to write
// a function that ca... | grades_array.push("D+"); | }
else if (grades[i] > 0.7){
grades_array.push("D");
}
else if (grades[i] > 0.0){
grades_array.push("D-");
}
else if (grades[i] == 0.0){
grades_array.push("E");
}
}
return grades_array;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of integers nums, find the minimum sum of any non-empty sub-array array list
// of nums.
// Example
... | prevMinSum = currSum; | }
if (currSum < minSum) {
minSum = currSum;
}
for (int j = i + 1; j < nums.size(); j++) {
currSum += nums.get(j);
if (currSum < prevMinSum) {
prevMinSum = currSum;
}
if (cu... |
//Complete the function that takes two integers and returns
// the product of their unit digits.
// Assume the input is always valid.
// Examples:
// >>> multiply(148, 412)
// 16
// >>> multiply(19, 28)
// 72
// >>> multiply(2020, 1851)
// 0
// >>> multiply(14, -15)
// 20
function multiply(a, b){
let aStr = a.toSt... | } | |
//Given two arrays operator, and operand. The first array has basic algebra operations, and
// the second array is an array of integers. Use the two given arrays to build the algebric
// expression and return the evaluation of this expression.
// The basic algebra operations:
// Addition ( + )
// Subtraction ( - )
... | operand[count] = Math.floor(operand[count] / operand[count + 1]); | operand.splice(count + 1, 1);
operator.splice(count, 1);
count = 0;
do_again = true;
break;
case '**':
operand[count] = Math.pow(operand[count], operand[count + 1]);
operand.splice(count + 1, 1);
operator.splice(count, 1);
count = 0;
... |
//It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algorithm for grading.
// The only problem is, she has lost the code she used for grading.
// She has given you an array of GPAs for some students and you have to write
// a function that ca... | else if (grades[i] > 2.0){ | grades_array.push("C+");
}
else if (grades[i] > 1.7){
grades_array.push("C");
}
else if (grades[i] > 1.3){
grades_array.push("C-");
}
else if (grades[i] > 1.0){
grades_array.push("D+");
}
else if (grades[i] >... |
def x_or_y(n: int, x: int, y: int) -> int:
"""A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
>>> x_or_y(7, 34, 12)
34
>>> x_or_y(15, 8, 5)
5
"""
if n < 2:
return y | for i in range(2, n): | if n % i == 0:
return y
return x
|
//You are given an array of two strings, both strings consist of open
// parentheses '(' or close parentheses ')' only.
// Your job is to check if it is possible to concatenate the two strings in
// some order, that the resulting string will be good.
// A string S is considered to be good if and only if all parentheses... | if (is_good(str2 + str1)){ | return 'Yes';
}
return 'No';
} |
//You are given a string s.
// Your task is to check if the string is hapjs or not.
// A string is hapjs if its length is at least 3 and every 3 consecutive letters are distinct
// For example:
// >>> is_happy(a)
// false
// >>> is_happy(aa)
// false
// >>> is_happy(abcd)
// true
// >>> is_happy(aabb)
// false
// >>> i... | if(s[i]===s[i-1] || s[i]===s[i-2]){ | happy = false;
}
}
return happy;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into s... | } else if (c == ')') { | open_paren--;
temp.append(c);
if (open_paren == 0) {
output.add(temp.toString());
}
}
}
return output;
}
} |
//You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Y... | } | let length = end - start;
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97];
return primes.includes(length) ? "YES" : "NO";
}
|
from typing import Union
def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]:
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values ... | return b | else:
return None
elif isinstance(a, str) and isinstance(b, float):
a_tmp = a.replace(',', '.')
if float(a_tmp) > b:
return a
elif float(a_tmp) < b:
return b |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function vowels_count which takes a string representing
// a word as input and returns the number of vowels in the string.
... | } | } |
//You are given a string s.
// Your task is to check if the string is hapjs or not.
// A string is hapjs if its length is at least 3 and every 3 consecutive letters are distinct
// For example:
// >>> is_happy(a)
// false
// >>> is_happy(aa)
// false
// >>> is_happy(abcd)
// true
// >>> is_happy(aabb)
// false
// >>> i... | for(let i=2; i<s.length; i++){ | if(s[i]===s[i-1] || s[i]===s[i-2]){
happy = false;
}
}
return happy;
} |
//Input is a space-delimited string of numberals from 'zero' to 'nine'.
// Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
// Return the string with numbers sorted from smallest to largest
// >>> sort_numbers("three one five")
// "one three five"
function sort_number... | } |
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