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values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
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value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
246 | D | Colorful Graph | PROGRAMMING | 1,600 | [
"brute force",
"dfs and similar",
"graphs"
] | null | null | You've got an undirected graph, consisting of *n* vertices and *m* edges. We will consider the graph's vertices numbered with integers from 1 to *n*. Each vertex of the graph has a color. The color of the *i*-th vertex is an integer *c**i*.
Let's consider all vertices of the graph, that are painted some color *k*. Let... | The first line contains two space-separated integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of vertices end edges of the graph, correspondingly. The second line contains a sequence of integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=105) — the colors of the graph vertices. The numbers on the line are sep... | Print the number of the color which has the set of neighbours with the maximum cardinality. It there are multiple optimal colors, print the color with the minimum number. Please note, that you want to find such color, that the graph has at least one vertex with such color. | [
"6 6\n1 1 2 3 5 8\n1 2\n3 2\n1 4\n4 3\n4 5\n4 6\n",
"5 6\n4 2 5 2 4\n1 2\n2 3\n3 1\n5 3\n5 4\n3 4\n"
] | [
"3\n",
"2\n"
] | none | 2,000 | [
{
"input": "6 6\n1 1 2 3 5 8\n1 2\n3 2\n1 4\n4 3\n4 5\n4 6",
"output": "3"
},
{
"input": "5 6\n4 2 5 2 4\n1 2\n2 3\n3 1\n5 3\n5 4\n3 4",
"output": "2"
},
{
"input": "3 1\n13 13 4\n1 2",
"output": "4"
},
{
"input": "2 1\n500 300\n1 2",
"output": "300"
},
{
"input":... | 1,603,860,580 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 216 | 614,400 | #Binary_Search
def Binary_Search_With_Index(color,colors,start,end):
midle=int(end-(end-start)/2)
if color==colors[midle]:
return midle
if color<colors[midle]:
return Binary_Search_With_Index(color,colors,start,midle-1)
return Binary_Search_With_Index(color,colors,midle+1,end)
def ... | Title: Colorful Graph
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got an undirected graph, consisting of *n* vertices and *m* edges. We will consider the graph's vertices numbered with integers from 1 to *n*. Each vertex of the graph has a color. The color of the *i*-th vertex i... | ```python
#Binary_Search
def Binary_Search_With_Index(color,colors,start,end):
midle=int(end-(end-start)/2)
if color==colors[midle]:
return midle
if color<colors[midle]:
return Binary_Search_With_Index(color,colors,start,midle-1)
return Binary_Search_With_Index(color,colors,midle+1,end)... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
631 | A | Interview | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function *f*(*x*,<=*l*,<=*r*) as a bitwise OR of integers *x... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the length of the arrays.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=109).
The third line contains *n* integers *b**i* (0<=≤<=*b**i*<=≤<=109). | Print a single integer — the maximum value of sum *f*(*a*,<=*l*,<=*r*)<=+<=*f*(*b*,<=*l*,<=*r*) among all possible 1<=≤<=*l*<=≤<=*r*<=≤<=*n*. | [
"5\n1 2 4 3 2\n2 3 3 12 1\n",
"10\n13 2 7 11 8 4 9 8 5 1\n5 7 18 9 2 3 0 11 8 6\n"
] | [
"22",
"46"
] | Bitwise OR of two non-negative integers *a* and *b* is the number *c* = *a* *OR* *b*, such that each of its digits in binary notation is 1 if and only if at least one of *a* or *b* have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is *l* = 2 and *r* = 4, because *... | 500 | [
{
"input": "5\n1 2 4 3 2\n2 3 3 12 1",
"output": "22"
},
{
"input": "10\n13 2 7 11 8 4 9 8 5 1\n5 7 18 9 2 3 0 11 8 6",
"output": "46"
},
{
"input": "25\n12 30 38 109 81 124 80 33 38 48 29 78 96 48 96 27 80 77 102 65 80 113 31 118 35\n25 64 95 13 12 6 111 80 85 16 61 119 23 65 73 65 20 9... | 1,660,204,446 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 46 | 0 | l = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
m = 0
n = 0
for i in a:
m |= i
for i in b:
n |= i
print(m+n) | Title: Interview
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of... | ```python
l = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
m = 0
n = 0
for i in a:
m |= i
for i in b:
n |= i
print(m+n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
492 | B | Vanya and Lanterns | PROGRAMMING | 1,200 | [
"binary search",
"implementation",
"math",
"sortings"
] | null | null | Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the point *l*. Then the *i*-th lantern is at the point *a**i*. The lantern lights all points of the street that... | The first line contains two integers *n*, *l* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*l*<=≤<=109) — the number of lanterns and the length of the street respectively.
The next line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=*l*). Multiple lanterns can be located at the same point. The lanterns may be located at the ends of th... | Print the minimum light radius *d*, needed to light the whole street. The answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=9. | [
"7 15\n15 5 3 7 9 14 0\n",
"2 5\n2 5\n"
] | [
"2.5000000000\n",
"2.0000000000\n"
] | Consider the second sample. At *d* = 2 the first lantern will light the segment [0, 4] of the street, and the second lantern will light segment [3, 5]. Thus, the whole street will be lit. | 1,000 | [
{
"input": "7 15\n15 5 3 7 9 14 0",
"output": "2.5000000000"
},
{
"input": "2 5\n2 5",
"output": "2.0000000000"
},
{
"input": "46 615683844\n431749087 271781274 274974690 324606253 480870261 401650581 13285442 478090364 266585394 425024433 588791449 492057200 391293435 563090494 317950 1... | 1,688,970,268 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | n = int(input())
l = int(input())
aList= []
for i in range(n):
aList.append(int(input()))
aList.sort()
firstPoint = 0
diffArray = []
for index, item in enumerate(aList[1:]):
diffArray.append((item - aList[index])/2)
minDistance = max(diffArray)
startDistance = aList[0]
endDistance = l - aList[-1]... | Title: Vanya and Lanterns
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the poi... | ```python
n = int(input())
l = int(input())
aList= []
for i in range(n):
aList.append(int(input()))
aList.sort()
firstPoint = 0
diffArray = []
for index, item in enumerate(aList[1:]):
diffArray.append((item - aList[index])/2)
minDistance = max(diffArray)
startDistance = aList[0]
endDistance = l -... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
729 | A | Interview with Oleg | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a filler word ogo in Oleg's speech. All words that can be obtained from ogo by adding go several times to the... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the interview.
The second line contains the string *s* of length *n*, consisting of lowercase English letters. | Print the interview text after the replacement of each of the fillers with "***". It is allowed for the substring "***" to have several consecutive occurences. | [
"7\naogogob\n",
"13\nogogmgogogogo\n",
"9\nogoogoogo\n"
] | [
"a***b\n",
"***gmg***\n",
"*********\n"
] | The first sample contains one filler word ogogo, so the interview for printing is "a***b".
The second sample contains two fillers ogo and ogogogo. Thus, the interview is transformed to "***gmg***". | 500 | [
{
"input": "7\naogogob",
"output": "a***b"
},
{
"input": "13\nogogmgogogogo",
"output": "***gmg***"
},
{
"input": "9\nogoogoogo",
"output": "*********"
},
{
"input": "32\nabcdefogoghijklmnogoopqrstuvwxyz",
"output": "abcdef***ghijklmn***opqrstuvwxyz"
},
{
"input":... | 1,505,247,506 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 77 | 512,000 | import re
n = int(input())
a = input()
print(re.sub("ogo(go)*", "***", a))
| Title: Interview with Oleg
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a fi... | ```python
import re
n = int(input())
a = input()
print(re.sub("ogo(go)*", "***", a))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,659,614,876 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 46 | 0 | t, etalon = [], ['h', 'e', 'l', 'l', 'o']
[t.append(i) for i in input() if t != etalon and i == etalon[len(t)]]
print('YES' if t == etalon else 'NO') | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
t, etalon = [], ['h', 'e', 'l', 'l', 'o']
[t.append(i) for i in input() if t != etalon and i == etalon[len(t)]]
print('YES' if t == etalon else 'NO')
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
701 | C | They Are Everywhere | PROGRAMMING | 1,500 | [
"binary search",
"strings",
"two pointers"
] | null | null | Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each flat. Also, each flat is connected with the flat to the left and the flat to the right. Flat number 1 is ... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of flats in the house.
The second line contains the row *s* with the length *n*, it consists of uppercase and lowercase letters of English alphabet, the *i*-th letter equals the type of Pokemon, which is in the flat number *i*. | Print the minimum number of flats which Sergei B. should visit in order to catch Pokemons of all types which there are in the house. | [
"3\nAaA\n",
"7\nbcAAcbc\n",
"6\naaBCCe\n"
] | [
"2\n",
"3\n",
"5\n"
] | In the first test Sergei B. can begin, for example, from the flat number 1 and end in the flat number 2.
In the second test Sergei B. can begin, for example, from the flat number 4 and end in the flat number 6.
In the third test Sergei B. must begin from the flat number 2 and end in the flat number 6. | 1,000 | [
{
"input": "3\nAaA",
"output": "2"
},
{
"input": "7\nbcAAcbc",
"output": "3"
},
{
"input": "6\naaBCCe",
"output": "5"
},
{
"input": "1\nA",
"output": "1"
},
{
"input": "1\ng",
"output": "1"
},
{
"input": "52\nabcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQ... | 1,630,896,653 | 2,147,483,647 | Python 3 | OK | TESTS | 80 | 530 | 12,185,600 | n = int(input())
palabra = input()
tipos = []
mapa = []
contador = 0
for i in range(n):
if palabra[i] not in tipos:
tipos.append(palabra[i])
if i>0:
mapa.append([palabra[i-1],contador])
contador=1
elif palabra[i]==palabra[i-1] and i>0:
contador=contador+1
elif i>0:
mapa.append([palabra[i... | Title: They Are Everywhere
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each ... | ```python
n = int(input())
palabra = input()
tipos = []
mapa = []
contador = 0
for i in range(n):
if palabra[i] not in tipos:
tipos.append(palabra[i])
if i>0:
mapa.append([palabra[i-1],contador])
contador=1
elif palabra[i]==palabra[i-1] and i>0:
contador=contador+1
elif i>0:
mapa.append(... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
137 | B | Permutation | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | "Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is cal... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*). | Print the only number — the minimum number of changes needed to get the permutation. | [
"3\n3 1 2\n",
"2\n2 2\n",
"5\n5 3 3 3 1\n"
] | [
"0\n",
"1\n",
"2\n"
] | The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with... | 1,000 | [
{
"input": "3\n3 1 2",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "2"
},
{
"input": "5\n6 6 6 6 6",
"output": "5"
},
{
"input": "10\n1 1 2 2 8 8 7 7 9 9",
"output": "5"
},
{
"input": "8\n9 8 7 6 5 4 3 2"... | 1,527,969,024 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 124 | 7,065,600 | n=int(input())
a=list(input().split())
b=[]
for i in range(n):
b.append(int(a[i]))
b=sorted(b)
k=0
for i in range(n-1):
if b[i]==b[i+1]:
k=k+1
print(k) | Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task ... | ```python
n=int(input())
a=list(input().split())
b=[]
for i in range(n):
b.append(int(a[i]))
b=sorted(b)
k=0
for i in range(n-1):
if b[i]==b[i+1]:
k=k+1
print(k)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,625,560,887 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 216 | 0 | import sys
import os
import math
from io import IOBase, BytesIO
mod=int(1e9+7)
# for modulus factorial
#fact=[1]
#for i in range(1,100001):
# fact.append((fact[-1]*i)%mod)
#ifact=[0]*100001
#ifact[100000]=pow(fact[100000],mod-2,mod)
#for i in range(100000,0,-1):
# ifact[i-1]=(i*ifact[i])%mod
#... | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
import sys
import os
import math
from io import IOBase, BytesIO
mod=int(1e9+7)
# for modulus factorial
#fact=[1]
#for i in range(1,100001):
# fact.append((fact[-1]*i)%mod)
#ifact=[0]*100001
#ifact[100000]=pow(fact[100000],mod-2,mod)
#for i in range(100000,0,-1):
# ifact[i-1]=(i*ifact[... | 3.946 | MatrixStudio/Codeforces-Python-Submissions |
914 | B | Conan and Agasa play a Card Game | PROGRAMMING | 1,200 | [
"games",
"greedy",
"implementation"
] | null | null | Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has *n* cards, and the *i*-th card has a number *a**i* written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he remov... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of cards Conan has.
The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105), where *a**i* is the number on the *i*-th card. | If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes). | [
"3\n4 5 7\n",
"2\n1 1\n"
] | [
"Conan\n",
"Agasa\n"
] | In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it... | 1,000 | [
{
"input": "3\n4 5 7",
"output": "Conan"
},
{
"input": "2\n1 1",
"output": "Agasa"
},
{
"input": "10\n38282 53699 38282 38282 38282 38282 38282 38282 38282 38282",
"output": "Conan"
},
{
"input": "10\n50165 50165 50165 50165 50165 50165 50165 50165 50165 50165",
"output":... | 1,543,768,538 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 10 | 140 | 7,065,600 | cards = int(input())
lst = [int(x) for x in input().split(" ")]
num = lst.count(max(lst))
if num % 2 == 1:
print("Conan")
else:
print("Agasa") | Title: Conan and Agasa play a Card Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has *n* cards, and the *i*-th card has a number *a**i* written on it.... | ```python
cards = int(input())
lst = [int(x) for x in input().split(" ")]
num = lst.count(max(lst))
if num % 2 == 1:
print("Conan")
else:
print("Agasa")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
439 | A | Devu, the Singer and Churu, the Joker | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* s... | The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100). | If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event. | [
"3 30\n2 2 1\n",
"3 20\n2 1 1\n"
] | [
"5\n",
"-1\n"
] | Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Ch... | 500 | [
{
"input": "3 30\n2 2 1",
"output": "5"
},
{
"input": "3 20\n2 1 1",
"output": "-1"
},
{
"input": "50 10000\n5 4 10 9 9 6 7 7 7 3 3 7 7 4 7 4 10 10 1 7 10 3 1 4 5 7 2 10 10 10 2 3 4 7 6 1 8 4 7 3 8 8 4 10 1 1 9 2 6 1",
"output": "1943"
},
{
"input": "50 10000\n4 7 15 9 11 12 ... | 1,608,625,741 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 109 | 0 | n , d = input().split()
n = int(n) #no of songs
d = int(d) #max time of the show
l = list(map(int,input().split()))
s = 0
count = 0
for i in l[:-1]:
s += i + 10
count +=2
s += l[-1]
if s > d:
print(-1)
else:
rem = d - s
rem = rem//5
print(rem+count) | Title: Devu, the Singer and Churu, the Joker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invit... | ```python
n , d = input().split()
n = int(n) #no of songs
d = int(d) #max time of the show
l = list(map(int,input().split()))
s = 0
count = 0
for i in l[:-1]:
s += i + 10
count +=2
s += l[-1]
if s > d:
print(-1)
else:
rem = d - s
rem = rem//5
print(rem+count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
171 | B | Star | PROGRAMMING | 1,300 | [
"*special",
"combinatorics"
] | null | null | The input contains a single integer *a* (1<=≤<=*a*<=≤<=18257). | Print a single integer *output* (1<=≤<=*output*<=≤<=2·109). | [
"2\n"
] | [
"13"
] | none | 0 | [
{
"input": "2",
"output": "13"
},
{
"input": "1",
"output": "1"
},
{
"input": "3",
"output": "37"
},
{
"input": "4",
"output": "73"
},
{
"input": "5",
"output": "121"
},
{
"input": "6",
"output": "181"
},
{
"input": "7",
"output": "253"... | 1,680,360,198 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 124 | 1,331,200 | n = int(input())
s = 1
for i in range(1, n):
s+=12*i
print(s) | Title: Star
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Input Specification:
The input contains a single integer *a* (1<=≤<=*a*<=≤<=18257).
Output Specification:
Print a single integer *output* (1<=≤<=*output*<=≤<=2·109).
Demo Input:
['2\n']
Demo Output:
['13']
Note:
none | ```python
n = int(input())
s = 1
for i in range(1, n):
s+=12*i
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | ||
863 | B | Kayaking | PROGRAMMING | 1,500 | [
"brute force",
"greedy",
"sortings"
] | null | null | Vadim is really keen on travelling. Recently he heard about kayaking activity near his town and became very excited about it, so he joined a party of kayakers.
Now the party is ready to start its journey, but firstly they have to choose kayaks. There are 2·*n* people in the group (including Vadim), and they have exact... | The first line contains one number *n* (2<=≤<=*n*<=≤<=50).
The second line contains 2·*n* integer numbers *w*1, *w*2, ..., *w*2*n*, where *w**i* is weight of person *i* (1<=≤<=*w**i*<=≤<=1000). | Print minimum possible total instability. | [
"2\n1 2 3 4\n",
"4\n1 3 4 6 3 4 100 200\n"
] | [
"1\n",
"5\n"
] | none | 0 | [
{
"input": "2\n1 2 3 4",
"output": "1"
},
{
"input": "4\n1 3 4 6 3 4 100 200",
"output": "5"
},
{
"input": "3\n305 139 205 406 530 206",
"output": "102"
},
{
"input": "3\n610 750 778 6 361 407",
"output": "74"
},
{
"input": "5\n97 166 126 164 154 98 221 7 51 47",
... | 1,617,045,738 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 61 | 307,200 | N=int(input())
N*=2
W=[]
W=input().split()
for i in range(len(W)):
W[i]=int(W[i])
W.sort()
instab=1
for i in range(0,N):
for j in range(i+1,N):
a=[]
for z in range(N):
if z!=i and z!=j:
a.append(W[z])
total=0
for k in range(0,N-2,2):
tota... | Title: Kayaking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vadim is really keen on travelling. Recently he heard about kayaking activity near his town and became very excited about it, so he joined a party of kayakers.
Now the party is ready to start its journey, but firstly they hav... | ```python
N=int(input())
N*=2
W=[]
W=input().split()
for i in range(len(W)):
W[i]=int(W[i])
W.sort()
instab=1
for i in range(0,N):
for j in range(i+1,N):
a=[]
for z in range(N):
if z!=i and z!=j:
a.append(W[z])
total=0
for k in range(0,N-2,2):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th... | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd pl... | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,675,966,833 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 280 | 0 | n, m = input().split()
n, m = int(n), int(m)
a = list(map(int, input().split()))
a.sort()
max_income = 0
n_to_min = n
min_price = 0
for plane in a:
if plane >= n_to_min:
min_price += (plane * (plane + 1)) // 2 - (((plane - n_to_min) * (plane - n_to_min + 1)) // 2)
break
else:
... | Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen pl... | ```python
n, m = input().split()
n, m = int(n), int(m)
a = list(map(int, input().split()))
a.sort()
max_income = 0
n_to_min = n
min_price = 0
for plane in a:
if plane >= n_to_min:
min_price += (plane * (plane + 1)) // 2 - (((plane - n_to_min) * (plane - n_to_min + 1)) // 2)
break
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
124 | A | The number of positions | PROGRAMMING | 1,000 | [
"math"
] | null | null | Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy. | The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=<<=*n*<=≤<=100). | Print the single number — the number of the sought positions. | [
"3 1 1\n",
"5 2 3\n"
] | [
"2\n",
"3\n"
] | The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1).
In the second sample they are 3, 4 and 5. | 500 | [
{
"input": "3 1 1",
"output": "2"
},
{
"input": "5 2 3",
"output": "3"
},
{
"input": "5 4 0",
"output": "1"
},
{
"input": "6 5 5",
"output": "1"
},
{
"input": "9 4 3",
"output": "4"
},
{
"input": "11 4 6",
"output": "7"
},
{
"input": "13 8 ... | 1,657,794,166 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 122 | 0 | n, a, b = map(int, input(). split())
if a > b and b != 0:
print(n - a - 1)
else:
print(n - a)
| Title: The number of positions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind h... | ```python
n, a, b = map(int, input(). split())
if a > b and b != 0:
print(n - a - 1)
else:
print(n - a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
830 | A | Office Keys | PROGRAMMING | 1,800 | [
"binary search",
"brute force",
"dp",
"greedy",
"sortings"
] | null | null | There are *n* people and *k* keys on a straight line. Every person wants to get to the office which is located on the line as well. To do that, he needs to reach some point with a key, take the key and then go to the office. Once a key is taken by somebody, it couldn't be taken by anybody else.
You are to determine th... | The first line contains three integers *n*, *k* and *p* (1<=≤<=*n*<=≤<=1<=000, *n*<=≤<=*k*<=≤<=2<=000, 1<=≤<=*p*<=≤<=109) — the number of people, the number of keys and the office location.
The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — positions in which people are ... | Print the minimum time (in seconds) needed for all *n* to reach the office with keys. | [
"2 4 50\n20 100\n60 10 40 80\n",
"1 2 10\n11\n15 7\n"
] | [
"50\n",
"7\n"
] | In the first example the person located at point 20 should take the key located at point 40 and go with it to the office located at point 50. He spends 30 seconds. The person located at point 100 can take the key located at point 80 and go to the office with it. He spends 50 seconds. Thus, after 50 seconds everybody is... | 500 | [
{
"input": "2 4 50\n20 100\n60 10 40 80",
"output": "50"
},
{
"input": "1 2 10\n11\n15 7",
"output": "7"
},
{
"input": "2 5 15\n10 4\n29 23 21 22 26",
"output": "23"
},
{
"input": "3 10 1500\n106 160 129\n1333 1532 1181 1091 1656 1698 1291 1741 1242 1163",
"output": "1394... | 1,621,407,311 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 187 | 29,081,600 | from sys import stdin,stdout
from itertools import accumulate
nmbr = lambda: int(input())
lst = lambda: list(map(int, input().split()))
PI=float('inf')
for _ in range(1):#nmbr()):
na,nb,o=lst()
a=sorted(lst())
b=sorted(lst())
dp=[[PI for _ in range(nb+1)] for _ in range(na+1)]
# print(a)
... | Title: Office Keys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* people and *k* keys on a straight line. Every person wants to get to the office which is located on the line as well. To do that, he needs to reach some point with a key, take the key and then go to the office... | ```python
from sys import stdin,stdout
from itertools import accumulate
nmbr = lambda: int(input())
lst = lambda: list(map(int, input().split()))
PI=float('inf')
for _ in range(1):#nmbr()):
na,nb,o=lst()
a=sorted(lst())
b=sorted(lst())
dp=[[PI for _ in range(nb+1)] for _ in range(na+1)]
# ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
586 | A | Alena's Schedule | PROGRAMMING | 900 | [
"implementation"
] | null | null | Alena has successfully passed the entrance exams to the university and is now looking forward to start studying.
One two-hour lesson at the Russian university is traditionally called a pair, it lasts for two academic hours (an academic hour is equal to 45 minutes).
The University works in such a way that every day it... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of lessons at the university.
The second line contains *n* numbers *a**i* (0<=≤<=*a**i*<=≤<=1). Number *a**i* equals 0, if Alena doesn't have the *i*-th pairs, otherwise it is equal to 1. Numbers *a*1,<=*a*2,<=...,<=*a**n* ar... | Print a single number — the number of pairs during which Alena stays at the university. | [
"5\n0 1 0 1 1\n",
"7\n1 0 1 0 0 1 0\n",
"1\n0\n"
] | [
"4\n",
"4\n",
"0\n"
] | In the first sample Alena stays at the university from the second to the fifth pair, inclusive, during the third pair she will be it the university waiting for the next pair.
In the last sample Alena doesn't have a single pair, so she spends all the time at home. | 500 | [
{
"input": "5\n0 1 0 1 1",
"output": "4"
},
{
"input": "7\n1 0 1 0 0 1 0",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n0 0",
"output": "0"
},
{
"input": "2\n0 1",
"output": "1"
},
{
... | 1,592,825,052 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 108 | 307,200 | n = int(input())
a = list(map(int, input().split()))
p= 0
i= 0
t= 0
c= 0
while i<n and a[i]== 0:
i+=1
for j in range(i, n):
if a[j]== 0:
t+=1
if a[j]==1:
c+=1
if t==1:
c+=1
t= 0
print(c) | Title: Alena's Schedule
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alena has successfully passed the entrance exams to the university and is now looking forward to start studying.
One two-hour lesson at the Russian university is traditionally called a pair, it lasts for two academic ... | ```python
n = int(input())
a = list(map(int, input().split()))
p= 0
i= 0
t= 0
c= 0
while i<n and a[i]== 0:
i+=1
for j in range(i, n):
if a[j]== 0:
t+=1
if a[j]==1:
c+=1
if t==1:
c+=1
t= 0
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
920 | A | Water The Garden | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | It is winter now, and Max decided it's about time he watered the garden.
The garden can be represented as *n* consecutive garden beds, numbered from 1 to *n*. *k* beds contain water taps (*i*-th tap is located in the bed *x**i*), which, if turned on, start delivering water to neighbouring beds. If the tap on the bed *... | The first line contains one integer *t* — the number of test cases to solve (1<=≤<=*t*<=≤<=200).
Then *t* test cases follow. The first line of each test case contains two integers *n* and *k* (1<=≤<=*n*<=≤<=200, 1<=≤<=*k*<=≤<=*n*) — the number of garden beds and water taps, respectively.
Next line contains *k* intege... | For each test case print one integer — the minimum number of seconds that have to pass after Max turns on some of the water taps, until the whole garden is watered. | [
"3\n5 1\n3\n3 3\n1 2 3\n4 1\n1\n"
] | [
"3\n1\n4\n"
] | The first example consists of 3 tests:
1. There are 5 garden beds, and a water tap in the bed 3. If we turn it on, then after 1 second passes, only bed 3 will be watered; after 2 seconds pass, beds [1, 3] will be watered, and after 3 seconds pass, everything will be watered. 1. There are 3 garden beds, and there is ... | 0 | [
{
"input": "3\n5 1\n3\n3 3\n1 2 3\n4 1\n1",
"output": "3\n1\n4"
},
{
"input": "26\n1 1\n1\n2 1\n2\n2 1\n1\n2 2\n1 2\n3 1\n3\n3 1\n2\n3 2\n2 3\n3 1\n1\n3 2\n1 3\n3 2\n1 2\n3 3\n1 2 3\n4 1\n4\n4 1\n3\n4 2\n3 4\n4 1\n2\n4 2\n2 4\n4 2\n2 3\n4 3\n2 3 4\n4 1\n1\n4 2\n1 4\n4 2\n1 3\n4 3\n1 3 4\n4 2\n1 2\n4... | 1,517,587,753 | 5,653 | Python 3 | OK | TESTS | 21 | 62 | 5,632,000 | for i in range(int(input())):
n, k = [int(x) for x in input().split()]
valves = [int(x) for x in input().split()]
gr = [False] * n
for i in valves:
gr[i - 1] = True
time = 1
while gr.count(True) != n:
for i in valves:
if i - 1 - time >= 0:
gr... | Title: Water The Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is winter now, and Max decided it's about time he watered the garden.
The garden can be represented as *n* consecutive garden beds, numbered from 1 to *n*. *k* beds contain water taps (*i*-th tap is located in the ... | ```python
for i in range(int(input())):
n, k = [int(x) for x in input().split()]
valves = [int(x) for x in input().split()]
gr = [False] * n
for i in valves:
gr[i - 1] = True
time = 1
while gr.count(True) != n:
for i in valves:
if i - 1 - time >= 0:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
466 | A | Cheap Travel | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Ann has recently started commuting by subway. We know that a one ride subway ticket costs *a* rubles. Besides, Ann found out that she can buy a special ticket for *m* rides (she can buy it several times). It costs *b* rubles. Ann did the math; she will need to use subway *n* times. Help Ann, tell her what is the minimu... | The single line contains four space-separated integers *n*, *m*, *a*, *b* (1<=≤<=*n*,<=*m*,<=*a*,<=*b*<=≤<=1000) — the number of rides Ann has planned, the number of rides covered by the *m* ride ticket, the price of a one ride ticket and the price of an *m* ride ticket. | Print a single integer — the minimum sum in rubles that Ann will need to spend. | [
"6 2 1 2\n",
"5 2 2 3\n"
] | [
"6\n",
"8\n"
] | In the first sample one of the optimal solutions is: each time buy a one ride ticket. There are other optimal solutions. For example, buy three *m* ride tickets. | 500 | [
{
"input": "6 2 1 2",
"output": "6"
},
{
"input": "5 2 2 3",
"output": "8"
},
{
"input": "10 3 5 1",
"output": "4"
},
{
"input": "1000 1 1000 1000",
"output": "1000000"
},
{
"input": "1000 3 1000 1000",
"output": "334000"
},
{
"input": "1 1 1 1",
"... | 1,692,043,144 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 14 | 93 | 0 | # -*- coding: utf-8 -*-
"""
Created on Mon Aug 14 12:56:36 2023
@author: pc
"""
n, m, a, b = map(int, input().split())
if n % m == 0:
print((n // m) * b)
else:
print(min((n // m) * b + (n % m) * a, (n // m) * b + b))
| Title: Cheap Travel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ann has recently started commuting by subway. We know that a one ride subway ticket costs *a* rubles. Besides, Ann found out that she can buy a special ticket for *m* rides (she can buy it several times). It costs *b* rubl... | ```python
# -*- coding: utf-8 -*-
"""
Created on Mon Aug 14 12:56:36 2023
@author: pc
"""
n, m, a, b = map(int, input().split())
if n % m == 0:
print((n // m) * b)
else:
print(min((n // m) * b + (n % m) * a, (n // m) * b + b))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
205 | A | Little Elephant and Rozdil | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elephant doesn't like to spend much time on travelling, so for his journey he will choose a town that needs minimum ti... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of cities. The next line contains *n* integers, separated by single spaces: the *i*-th integer represents the time needed to go from town Rozdil to the *i*-th town. The time values are positive integers, not exceeding 109.
You can consider t... | Print the answer on a single line — the number of the town the Little Elephant will go to. If there are multiple cities with minimum travel time, print "Still Rozdil" (without the quotes). | [
"2\n7 4\n",
"7\n7 4 47 100 4 9 12\n"
] | [
"2\n",
"Still Rozdil\n"
] | In the first sample there are only two cities where the Little Elephant can go. The travel time for the first town equals 7, to the second one — 4. The town which is closest to Rodzil (the only one) is the second one, so the answer is 2.
In the second sample the closest cities are cities two and five, the travelling t... | 500 | [
{
"input": "2\n7 4",
"output": "2"
},
{
"input": "7\n7 4 47 100 4 9 12",
"output": "Still Rozdil"
},
{
"input": "1\n47",
"output": "1"
},
{
"input": "2\n1000000000 1000000000",
"output": "Still Rozdil"
},
{
"input": "7\n7 6 5 4 3 2 1",
"output": "7"
},
{
... | 1,681,774,015 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 154 | 0 | n = int(input())
a = [int(x) for x in input().split()]
s = 100000
i = -1
d = False
for x in range(n):
if a[x] < s:
s = a[x]
i = x
d = False
elif a[x] == s:
d = True
if d:
print('Still Rozdil')
else:
print(i+1) | Title: Little Elephant and Rozdil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elepha... | ```python
n = int(input())
a = [int(x) for x in input().split()]
s = 100000
i = -1
d = False
for x in range(n):
if a[x] < s:
s = a[x]
i = x
d = False
elif a[x] == s:
d = True
if d:
print('Still Rozdil')
else:
print(i+1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
811 | A | Vladik and Courtesy | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | At regular competition Vladik and Valera won *a* and *b* candies respectively. Vladik offered 1 his candy to Valera. After that Valera gave Vladik 2 his candies, so that no one thought that he was less generous. Vladik for same reason gave 3 candies to Valera in next turn.
More formally, the guys take turns giving eac... | Single line of input data contains two space-separated integers *a*, *b* (1<=≤<=*a*,<=*b*<=≤<=109) — number of Vladik and Valera candies respectively. | Pring a single line "Vladik’’ in case, if Vladik first who can’t give right amount of candy, or "Valera’’ otherwise. | [
"1 1\n",
"7 6\n"
] | [
"Valera\n",
"Vladik\n"
] | Illustration for first test case:
<img class="tex-graphics" src="https://espresso.codeforces.com/ad9b7d0e481208de8e3a585aa1d96b9e1dda4fd7.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Illustration for second test case:
<img class="tex-graphics" src="https://espresso.codeforces.com/9f4836d2ccdffaee5a63898e5d4e... | 500 | [
{
"input": "1 1",
"output": "Valera"
},
{
"input": "7 6",
"output": "Vladik"
},
{
"input": "25 38",
"output": "Vladik"
},
{
"input": "8311 2468",
"output": "Valera"
},
{
"input": "250708 857756",
"output": "Vladik"
},
{
"input": "957985574 24997558",
... | 1,676,458,443 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | a, b = map(int, input().split())
n = 1
ans = ""
while 1:
if n % 2:
if a >= n:
a -= n
else:
ans = "Valadik"
break
else:
if b >= n:
b -= n
else:
ans = "Valera"
break
n += 1
print(ans)
| Title: Vladik and Courtesy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
At regular competition Vladik and Valera won *a* and *b* candies respectively. Vladik offered 1 his candy to Valera. After that Valera gave Vladik 2 his candies, so that no one thought that he was less generous. Vla... | ```python
a, b = map(int, input().split())
n = 1
ans = ""
while 1:
if n % 2:
if a >= n:
a -= n
else:
ans = "Valadik"
break
else:
if b >= n:
b -= n
else:
ans = "Valera"
break
n += 1
print(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
169 | A | Chores | PROGRAMMING | 800 | [
"sortings"
] | null | null | Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of the *i*-th chore equals *h**i*.
As Petya is older, he wants to take the chores with complexit... | The first input line contains three integers *n*,<=*a* and *b* (2<=≤<=*n*<=≤<=2000; *a*,<=*b*<=≥<=1; *a*<=+<=*b*<==<=*n*) — the total number of chores, the number of Petya's chores and the number of Vasya's chores.
The next line contains a sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=109), *h**i* ... | Print the required number of ways to choose an integer value of *x*. If there are no such ways, print 0. | [
"5 2 3\n6 2 3 100 1\n",
"7 3 4\n1 1 9 1 1 1 1\n"
] | [
"3\n",
"0\n"
] | In the first sample the possible values of *x* are 3, 4 or 5.
In the second sample it is impossible to find such *x*, that Petya got 3 chores and Vasya got 4. | 500 | [
{
"input": "5 2 3\n6 2 3 100 1",
"output": "3"
},
{
"input": "7 3 4\n1 1 9 1 1 1 1",
"output": "0"
},
{
"input": "2 1 1\n10 2",
"output": "8"
},
{
"input": "2 1 1\n7 7",
"output": "0"
},
{
"input": "2 1 1\n1 1000000000",
"output": "999999999"
},
{
"inp... | 1,644,168,324 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | n,c,b = list(map(int, input().split()))
a= list(map(int, input().split()))
a.sort()
if c==1 and b==1:
result= a[1]-a[0]
print(result)
elif a[0] == a[1]:
print("0")
else:
result = a[0:b]
print(result[-1])
| Title: Chores
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of th... | ```python
n,c,b = list(map(int, input().split()))
a= list(map(int, input().split()))
a.sort()
if c==1 and b==1:
result= a[1]-a[0]
print(result)
elif a[0] == a[1]:
print("0")
else:
result = a[0:b]
print(result[-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
764 | A | Taymyr is calling you | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long,... | The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104). | Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls. | [
"1 1 10\n",
"1 2 5\n",
"2 3 9\n"
] | [
"10\n",
"2\n",
"1\n"
] | Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute. | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "1 2 5",
"output": "2"
},
{
"input": "2 3 9",
"output": "1"
},
{
"input": "4 8 9",
"output": "1"
},
{
"input": "7 9 2",
"output": "0"
},
{
"input": "10000 10000 10000",
"output": "1"
},
{
"i... | 1,486,123,663 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 4,608,000 | a=input()
a=int(a)
b=input()
b=int(b)
c=input()
c=int(c)
i=0
j=b
ans=0
while j <= c:
while i<j :
i+=a
if i==j : ans+=1
j+=b
print(ans)
| Title: Taymyr is calling you
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists com... | ```python
a=input()
a=int(a)
b=input()
b=int(b)
c=input()
c=int(c)
i=0
j=b
ans=0
while j <= c:
while i<j :
i+=a
if i==j : ans+=1
j+=b
print(ans)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it la... | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on... | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,677,092,666 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 31 | 0 | l=[int(i) for i in input().split()]
n=l[0]
m=l[1]
days=0
temp=1
while(n>=temp):
days+=n//temp
temp=temp*m
print(days) | Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th... | ```python
l=[int(i) for i in input().split()]
n=l[0]
m=l[1]
days=0
temp=1
while(n>=temp):
days+=n//temp
temp=temp*m
print(days)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
766 | B | Mahmoud and a Triangle | PROGRAMMING | 1,000 | [
"constructive algorithms",
"geometry",
"greedy",
"math",
"number theory",
"sortings"
] | null | null | Mahmoud has *n* line segments, the *i*-th of them has length *a**i*. Ehab challenged him to use exactly 3 line segments to form a non-degenerate triangle. Mahmoud doesn't accept challenges unless he is sure he can win, so he asked you to tell him if he should accept the challenge. Given the lengths of the line segments... | The first line contains single integer *n* (3<=≤<=*n*<=≤<=105) — the number of line segments Mahmoud has.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the lengths of line segments Mahmoud has. | In the only line print "YES" if he can choose exactly three line segments and form a non-degenerate triangle with them, and "NO" otherwise. | [
"5\n1 5 3 2 4\n",
"3\n4 1 2\n"
] | [
"YES\n",
"NO\n"
] | For the first example, he can use line segments with lengths 2, 4 and 5 to form a non-degenerate triangle. | 1,000 | [
{
"input": "5\n1 5 3 2 4",
"output": "YES"
},
{
"input": "3\n4 1 2",
"output": "NO"
},
{
"input": "30\n197 75 517 39724 7906061 1153471 3 15166 168284 3019844 272293 316 16 24548 42 118 5792 5 9373 1866366 4886214 24 2206 712886 104005 1363 836 64273 440585 3576",
"output": "NO"
},... | 1,673,120,573 | 2,147,483,647 | Python 3 | OK | TESTS | 87 | 93 | 8,089,600 | length = int(input())
sides = list(map(int, input().split()))
sides.sort()
side1 = 0
side2 = side1+1
side3 = side2+1
ans = "NO"
while side3 < length:
if sides[side1] + sides[side2] > sides[side3]:
ans = "YES"
break
side1 += 1
side2 += 1
side3 += 1
print(ans) | Title: Mahmoud and a Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud has *n* line segments, the *i*-th of them has length *a**i*. Ehab challenged him to use exactly 3 line segments to form a non-degenerate triangle. Mahmoud doesn't accept challenges unless he is sure he ca... | ```python
length = int(input())
sides = list(map(int, input().split()))
sides.sort()
side1 = 0
side2 = side1+1
side3 = side2+1
ans = "NO"
while side3 < length:
if sides[side1] + sides[side2] > sides[side3]:
ans = "YES"
break
side1 += 1
side2 += 1
side3 += 1
print(... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
137 | B | Permutation | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | "Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is cal... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*). | Print the only number — the minimum number of changes needed to get the permutation. | [
"3\n3 1 2\n",
"2\n2 2\n",
"5\n5 3 3 3 1\n"
] | [
"0\n",
"1\n",
"2\n"
] | The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with... | 1,000 | [
{
"input": "3\n3 1 2",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "2"
},
{
"input": "5\n6 6 6 6 6",
"output": "5"
},
{
"input": "10\n1 1 2 2 8 8 7 7 9 9",
"output": "5"
},
{
"input": "8\n9 8 7 6 5 4 3 2"... | 1,610,569,594 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 154 | 819,200 | from collections import Counter
n = int(input())
s = [int(i) for i in input().split()]
c = Counter(s)
ans = 0
for k, v in c.items():
if k <= n:
ans += v - 1
else:
ans += v
print(ans)
| Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task ... | ```python
from collections import Counter
n = int(input())
s = [int(i) for i in input().split()]
c = Counter(s)
ans = 0
for k, v in c.items():
if k <= n:
ans += v - 1
else:
ans += v
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
976 | C | Nested Segments | PROGRAMMING | 1,500 | [
"greedy",
"implementation",
"sortings"
] | null | null | You are given a sequence *a*1,<=*a*2,<=...,<=*a**n* of one-dimensional segments numbered 1 through *n*. Your task is to find two distinct indices *i* and *j* such that segment *a**i* lies within segment *a**j*.
Segment [*l*1,<=*r*1] lies within segment [*l*2,<=*r*2] iff *l*1<=≥<=*l*2 and *r*1<=≤<=*r*2.
Print indices ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of segments.
Each of the next *n* lines contains two integers *l**i* and *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109) — the *i*-th segment. | Print two distinct indices *i* and *j* such that segment *a**i* lies within segment *a**j*. If there are multiple answers, print any of them. If no answer exists, print -1 -1. | [
"5\n1 10\n2 9\n3 9\n2 3\n2 9\n",
"3\n1 5\n2 6\n6 20\n"
] | [
"2 1\n",
"-1 -1\n"
] | In the first example the following pairs are considered correct:
- (2, 1), (3, 1), (4, 1), (5, 1) — not even touching borders; - (3, 2), (4, 2), (3, 5), (4, 5) — touch one border; - (5, 2), (2, 5) — match exactly. | 0 | [
{
"input": "5\n1 10\n2 9\n3 9\n2 3\n2 9",
"output": "2 1"
},
{
"input": "3\n1 5\n2 6\n6 20",
"output": "-1 -1"
},
{
"input": "1\n1 1000000000",
"output": "-1 -1"
},
{
"input": "2\n1 1000000000\n1 1000000000",
"output": "2 1"
},
{
"input": "2\n1 1000000000\n5000000... | 1,563,509,174 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | # 976C.py
# greedy implementation sorting *1500
from operator import itemgetter
class SEG:
def __init__(self, l, r, i):
self.seg = (l, r, i)
def __lt__(self, other):
if self.seg[0] != other.seg[0]:
return self.seg[0] < other.seg[0]
else:
return sel... | Title: Nested Segments
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence *a*1,<=*a*2,<=...,<=*a**n* of one-dimensional segments numbered 1 through *n*. Your task is to find two distinct indices *i* and *j* such that segment *a**i* lies within segment *a**j*.
Segment... | ```python
# 976C.py
# greedy implementation sorting *1500
from operator import itemgetter
class SEG:
def __init__(self, l, r, i):
self.seg = (l, r, i)
def __lt__(self, other):
if self.seg[0] != other.seg[0]:
return self.seg[0] < other.seg[0]
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,674,957,248 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 1,331,200 | inp=input()
x=inp.split()
def pay(num,rest):
n=1
var=True
while var:
if n*num % 10 == rest:
return n
n+=1
print(pay(int(x[0]),int(x[1]))) | Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
inp=input()
x=inp.split()
def pay(num,rest):
n=1
var=True
while var:
if n*num % 10 == rest:
return n
n+=1
print(pay(int(x[0]),int(x[1])))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
401 | A | Vanya and Cards | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each card doesn't exceed *x* in the absolute value.
Natasha doesn't like when Vanya spends a long time p... | The first line contains two integers: *n* (1<=≤<=*n*<=≤<=1000) — the number of found cards and *x* (1<=≤<=*x*<=≤<=1000) — the maximum absolute value of the number on a card. The second line contains *n* space-separated integers — the numbers on found cards. It is guaranteed that the numbers do not exceed *x* in their a... | Print a single number — the answer to the problem. | [
"3 2\n-1 1 2\n",
"2 3\n-2 -2\n"
] | [
"1\n",
"2\n"
] | In the first sample, Vanya needs to find a single card with number -2.
In the second sample, Vanya needs to find two cards with number 2. He can't find a single card with the required number as the numbers on the lost cards do not exceed 3 in their absolute value. | 500 | [
{
"input": "3 2\n-1 1 2",
"output": "1"
},
{
"input": "2 3\n-2 -2",
"output": "2"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
},
{
"input": "2 2\n-1 -1",
"output": "1"
},
{
"input": "15 5\n-2 -1 2 -4 -3 4 -4 -2 -2 2 -2 -1 1 -4 -2",
"output": "4"
},
{
"... | 1,632,390,456 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 77 | 6,963,200 | n,x = map(int,input().split())
a = list(map(int,input().split()))
b = abs(sum(a))
c = b
if c/x == int(c/x):print(c//x)
else:print(c//x+1) | Title: Vanya and Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each... | ```python
n,x = map(int,input().split())
a = list(map(int,input().split()))
b = abs(sum(a))
c = b
if c/x == int(c/x):print(c//x)
else:print(c//x+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,672,309,946 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 93 | 204,800 | m=list(map(int,input().split()))
s=input()
sumc=0
for i in range(len(s)):
if s[i]=='1':
sumc=sumc+m[0]
if s[i]=='2':
sumc=sumc+m[1]
if s[i]=='3':
sumc=sumc+m[2]
if s[i]=='4':
sumc=sumc+m[3]
print(sumc) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
m=list(map(int,input().split()))
s=input()
sumc=0
for i in range(len(s)):
if s[i]=='1':
sumc=sumc+m[0]
if s[i]=='2':
sumc=sumc+m[1]
if s[i]=='3':
sumc=sumc+m[2]
if s[i]=='4':
sumc=sumc+m[3]
print(sumc)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,690,156,021 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 124 | 102,400 | num = input()
count = 0
sum = 0
while len(num) != 1:
for n in num:
sum += int(n)
num = str(sum)
sum = 0
count += 1
print(count)
| Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
num = input()
count = 0
sum = 0
while len(num) != 1:
for n in num:
sum += int(n)
num = str(sum)
sum = 0
count += 1
print(count)
``` | 3.968816 | MatrixStudio/Codeforces-Python-Submissions |
378 | A | Playing with Dice | PROGRAMMING | 800 | [
"brute force"
] | null | null | Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number *a*, the second player wrote number *b*. How many w... | The single line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=6) — the numbers written on the paper by the first and second player, correspondingly. | Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly. | [
"2 5\n",
"2 4\n"
] | [
"3 0 3\n",
"2 1 3\n"
] | The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number *a* is closer to number *x* than number *b*, if |*a* - *x*| < |*b* - *x*|. | 500 | [
{
"input": "2 5",
"output": "3 0 3"
},
{
"input": "2 4",
"output": "2 1 3"
},
{
"input": "5 3",
"output": "2 1 3"
},
{
"input": "1 6",
"output": "3 0 3"
},
{
"input": "5 1",
"output": "3 1 2"
},
{
"input": "6 3",
"output": "2 0 4"
},
{
"inp... | 1,650,566,595 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 46 | 0 | i = [int(i) for i in input().split()]
a = i[0]
b = i[1]
counts = 0
countl = 0
countd = 0
for i in range(1,7):
if abs(i-a) < abs(i-b):
counts += 1
elif(abs(i-a) > abs(i-b)):
countl += 1
else:
countd += 1
print(counts,countd,countl) | Title: Playing with Dice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same diff... | ```python
i = [int(i) for i in input().split()]
a = i[0]
b = i[1]
counts = 0
countl = 0
countd = 0
for i in range(1,7):
if abs(i-a) < abs(i-b):
counts += 1
elif(abs(i-a) > abs(i-b)):
countl += 1
else:
countd += 1
print(counts,countd,countl)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | D | Roads not only in Berland | PROGRAMMING | 1,900 | [
"dsu",
"graphs",
"trees"
] | D. Roads not only in Berland | 2 | 256 | Berland Government decided to improve relations with neighboring countries. First of all, it was decided to build new roads so that from each city of Berland and neighboring countries it became possible to reach all the others. There are *n* cities in Berland and neighboring countries in total and exactly *n*<=-<=1 two... | The first line contains integer *n* (2<=≤<=*n*<=≤<=1000) — amount of cities in Berland and neighboring countries. Next *n*<=-<=1 lines contain the description of roads. Each road is described by two space-separated integers *a**i*, *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*) — pair of cities, which the r... | Output the answer, number *t* — what is the least amount of days needed to rebuild roads so that from each city it became possible to reach all the others. Then output *t* lines — the plan of closure of old roads and building of new ones. Each line should describe one day in the format i j u v — it means that road betw... | [
"2\n1 2\n",
"7\n1 2\n2 3\n3 1\n4 5\n5 6\n6 7\n"
] | [
"0\n",
"1\n3 1 3 7\n"
] | none | 0 | [
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "7\n1 2\n2 3\n3 1\n4 5\n5 6\n6 7",
"output": "1\n3 1 3 7"
},
{
"input": "3\n3 2\n1 2",
"output": "0"
},
{
"input": "3\n3 1\n3 2",
"output": "0"
},
{
"input": "4\n1 4\n3 1\n3 4",
"output": "1\n3 4 2 4"
},
{
... | 1,457,181,516 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 122 | 0 | def way(v):
if vertices[v] == v:
return v
else:
vertices[v] = way(vertices[v])
return vertices[v]
n = int(input())
vertices = [i for i in range(n + 1)]
useless = []
useful = []
for i in range(n - 1):
a, b = map(int, input().split())
a = way(a)
b = way(b)
... | Title: Roads not only in Berland
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Berland Government decided to improve relations with neighboring countries. First of all, it was decided to build new roads so that from each city of Berland and neighboring countries it became possible to reach a... | ```python
def way(v):
if vertices[v] == v:
return v
else:
vertices[v] = way(vertices[v])
return vertices[v]
n = int(input())
vertices = [i for i in range(n + 1)]
useless = []
useful = []
for i in range(n - 1):
a, b = map(int, input().split())
a = way(a)
b = w... | 0 | MatrixStudio/Codeforces-Python-Submissions |
803 | B | Distances to Zero | PROGRAMMING | 1,200 | [
"constructive algorithms"
] | null | null | You are given the array of integer numbers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. For each element find the distance to the nearest zero (to the element which equals to zero). There is at least one zero element in the given array. | The first line contains integer *n* (1<=≤<=*n*<=≤<=2·105) — length of the array *a*. The second line contains integer elements of the array separated by single spaces (<=-<=109<=≤<=*a**i*<=≤<=109). | Print the sequence *d*0,<=*d*1,<=...,<=*d**n*<=-<=1, where *d**i* is the difference of indices between *i* and nearest *j* such that *a**j*<==<=0. It is possible that *i*<==<=*j*. | [
"9\n2 1 0 3 0 0 3 2 4\n",
"5\n0 1 2 3 4\n",
"7\n5 6 0 1 -2 3 4\n"
] | [
"2 1 0 1 0 0 1 2 3 ",
"0 1 2 3 4 ",
"2 1 0 1 2 3 4 "
] | none | 0 | [
{
"input": "9\n2 1 0 3 0 0 3 2 4",
"output": "2 1 0 1 0 0 1 2 3 "
},
{
"input": "5\n0 1 2 3 4",
"output": "0 1 2 3 4 "
},
{
"input": "7\n5 6 0 1 -2 3 4",
"output": "2 1 0 1 2 3 4 "
},
{
"input": "1\n0",
"output": "0 "
},
{
"input": "2\n0 0",
"output": "0 0 "
... | 1,598,455,297 | 2,147,483,647 | Python 3 | OK | TESTS | 164 | 530 | 16,998,400 | n = int(input())
s = [int(i) for i in input().split()]
d = [10**9+7 for i in range(n)]
cnt = 0
for i in range(n):
if s[i]==0:
d[i]=0
cnt = 1
elif cnt:
d[i]=cnt
cnt+=1
cnt = 0
for i in range(n-1,-1,-1):
if s[i]==0:
cnt = 1
elif cnt:
if d[i]>=cnt:
d[i]=cnt
cnt+=1
print(*d) | Title: Distances to Zero
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the array of integer numbers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. For each element find the distance to the nearest zero (to the element which equals to zero). There is at least one zero element in the give... | ```python
n = int(input())
s = [int(i) for i in input().split()]
d = [10**9+7 for i in range(n)]
cnt = 0
for i in range(n):
if s[i]==0:
d[i]=0
cnt = 1
elif cnt:
d[i]=cnt
cnt+=1
cnt = 0
for i in range(n-1,-1,-1):
if s[i]==0:
cnt = 1
elif cnt:
if d[i]>=cnt:
d[i]=cnt
cnt+=1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
409 | F | 000001 | PROGRAMMING | 1,900 | [
"*special"
] | null | null | The input contains a single integer *a* (1<=≤<=*a*<=≤<=64).
Output a single integer. | The input contains a single integer *a* (1<=≤<=*a*<=≤<=64). | Output a single integer. | [
"2\n",
"4\n",
"27\n",
"42\n"
] | [
"1\n",
"2\n",
"5\n",
"6\n"
] | none | 0 | [
{
"input": "2",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "27",
"output": "5"
},
{
"input": "42",
"output": "6"
},
{
"input": "1",
"output": "1"
},
{
"input": "3",
"output": "1"
},
{
"input": "64",
"output": "267"
}... | 1,629,585,511 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 62 | 20,172,800 | def process(a):
return int(a**0.5)
a = int(input()) | Title: 000001
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains a single integer *a* (1<=≤<=*a*<=≤<=64).
Output a single integer.
Input Specification:
The input contains a single integer *a* (1<=≤<=*a*<=≤<=64).
Output Specification:
Output a single integer.
Demo Input:... | ```python
def process(a):
return int(a**0.5)
a = int(input())
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
664 | A | Complicated GCD | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find greatest common divisor *GCD*(*a*,<=*b*), for example, Euclid algorithm.
Formally, find the biggest in... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10100). | Output one integer — greatest common divisor of all integers from *a* to *b* inclusive. | [
"1 2\n",
"61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576\n"
] | [
"1\n",
"61803398874989484820458683436563811772030917980576\n"
] | none | 500 | [
{
"input": "1 2",
"output": "1"
},
{
"input": "61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576",
"output": "61803398874989484820458683436563811772030917980576"
},
{
"input": "1 100",
"output": "1"
},
{
"input": "100 100000... | 1,680,560,371 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 28 | 46 | 0 | def helper(pw,k):
if k == 0:
return pw
return helper(k,pw%k)
pw, k = map(int,input().split())
if pw != k:
print(1)
else:
print(helper(k,pw)) | Title: Complicated GCD
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find gre... | ```python
def helper(pw,k):
if k == 0:
return pw
return helper(k,pw%k)
pw, k = map(int,input().split())
if pw != k:
print(1)
else:
print(helper(k,pw))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
257 | A | Sockets | PROGRAMMING | 1,100 | [
"greedy",
"implementation",
"sortings"
] | null | null | Vasya has got many devices that work on electricity. He's got *n* supply-line filters to plug the devices, the *i*-th supply-line filter has *a**i* sockets.
Overall Vasya has got *m* devices and *k* electrical sockets in his flat, he can plug the devices or supply-line filters directly. Of course, he can plug the supp... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=50) — the number of supply-line filters, the number of devices and the number of sockets that he can plug to directly, correspondingly. The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=50) —... | Print a single number — the minimum number of supply-line filters that is needed to plug all the devices to electricity. If it is impossible to plug all the devices even using all the supply-line filters, print -1. | [
"3 5 3\n3 1 2\n",
"4 7 2\n3 3 2 4\n",
"5 5 1\n1 3 1 2 1\n"
] | [
"1\n",
"2\n",
"-1\n"
] | In the first test case he can plug the first supply-line filter directly to electricity. After he plug it, he get 5 (3 on the supply-line filter and 2 remaining sockets for direct plugging) available sockets to plug. Thus, one filter is enough to plug 5 devices.
One of the optimal ways in the second test sample is to ... | 500 | [
{
"input": "3 5 3\n3 1 2",
"output": "1"
},
{
"input": "4 7 2\n3 3 2 4",
"output": "2"
},
{
"input": "5 5 1\n1 3 1 2 1",
"output": "-1"
},
{
"input": "4 5 8\n3 2 4 3",
"output": "0"
},
{
"input": "5 10 1\n4 3 4 2 4",
"output": "3"
},
{
"input": "7 13 2... | 1,666,248,837 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 92 | 0 | n,m,k= map(int,input().split())
u=[int(s) for s in input().split()]
u=sorted(u)
z=0
f=0
for i in range(n):
z+=u[n-1-i]
if i+1>k:
break
if z+k-1-i>=m:
print(i+1)
f=1
break
if f==0:
print(-1)
| Title: Sockets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got many devices that work on electricity. He's got *n* supply-line filters to plug the devices, the *i*-th supply-line filter has *a**i* sockets.
Overall Vasya has got *m* devices and *k* electrical sockets in his f... | ```python
n,m,k= map(int,input().split())
u=[int(s) for s in input().split()]
u=sorted(u)
z=0
f=0
for i in range(n):
z+=u[n-1-i]
if i+1>k:
break
if z+k-1-i>=m:
print(i+1)
f=1
break
if f==0:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,611,338,794 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 0 | string = input()
count = 0
for x in string:
if x.upper() == x:
count+= 1
if len(string) / 2 < count:
print(string.upper())
else:
print(string.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
string = input()
count = 0
for x in string:
if x.upper() == x:
count+= 1
if len(string) / 2 < count:
print(string.upper())
else:
print(string.lower())
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
359 | C | Prime Number | PROGRAMMING | 1,900 | [
"math",
"number theory"
] | null | null | Simon has a prime number *x* and an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*.
Simon loves fractions very much. Today he wrote out number on a piece of paper. After Simon led all fractions to a common denominator and summed them up, he got a fraction: , where number *t* equals *x**a*1<=+<=*a*2<=+<=...... | The first line contains two positive integers *n* and *x* (1<=≤<=*n*<=≤<=105, 2<=≤<=*x*<=≤<=109) — the size of the array and the prime number.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n*<=≤<=109). | Print a single number — the answer to the problem modulo 1000000007 (109<=+<=7). | [
"2 2\n2 2\n",
"3 3\n1 2 3\n",
"2 2\n29 29\n",
"4 5\n0 0 0 0\n"
] | [
"8\n",
"27\n",
"73741817\n",
"1\n"
] | In the first sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7745f7cc87c6c5f753e3414fad9baa3b1e3fea48.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Thus, the answer to the problem is 8.
In the second sample, <img align="middle" class="tex-formula" src="https://espresso.codef... | 1,500 | [
{
"input": "2 2\n2 2",
"output": "8"
},
{
"input": "3 3\n1 2 3",
"output": "27"
},
{
"input": "2 2\n29 29",
"output": "73741817"
},
{
"input": "4 5\n0 0 0 0",
"output": "1"
},
{
"input": "1 2\n1000000000",
"output": "1"
},
{
"input": "26 2\n0 0 0 0 0 0... | 1,609,571,913 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 1,000 | 11,980,800 | from math import gcd
def primer(n,arr):
s=sum(arr)
up=0
lower=n**s
for i in arr:
up+=n**(s-i)
return (gcd(up,lower))%(10**9+7)
a,b=map(int,input().strip().split())
lst=list(map(int,input().strip().split()))
print(primer(b,lst)) | Title: Prime Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon has a prime number *x* and an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*.
Simon loves fractions very much. Today he wrote out number on a piece of paper. After Simon led all fractions to a common den... | ```python
from math import gcd
def primer(n,arr):
s=sum(arr)
up=0
lower=n**s
for i in arr:
up+=n**(s-i)
return (gcd(up,lower))%(10**9+7)
a,b=map(int,input().strip().split())
lst=list(map(int,input().strip().split()))
print(primer(b,lst))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
898 | A | Rounding | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5 Vasya can round it to 0 or to 10. Both ways are correct.
For given *n* find out to which int... | The first line contains single integer *n* (0<=≤<=*n*<=≤<=109) — number that Vasya has. | Print result of rounding *n*. Pay attention that in some cases answer isn't unique. In that case print any correct answer. | [
"5\n",
"113\n",
"1000000000\n",
"5432359\n"
] | [
"0\n",
"110\n",
"1000000000\n",
"5432360\n"
] | In the first example *n* = 5. Nearest integers, that ends up with zero are 0 and 10. Any of these answers is correct, so you can print 0 or 10. | 500 | [
{
"input": "5",
"output": "0"
},
{
"input": "113",
"output": "110"
},
{
"input": "1000000000",
"output": "1000000000"
},
{
"input": "5432359",
"output": "5432360"
},
{
"input": "999999994",
"output": "999999990"
},
{
"input": "10",
"output": "10"
... | 1,610,386,908 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 307,200 | n = int(input())
if n % 10 == 0:
print(n)
else:
n1 = str(n)
ln = len(n1)
if ln > 1:
m1 = '1' + '0' * (ln - 2)
m = int(m1)
l = n % m
else:
m = 10
l = n % m
if l > 5:
n = n // 10
n = (n + 1) * 10
else:
n = n... | Title: Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5... | ```python
n = int(input())
if n % 10 == 0:
print(n)
else:
n1 = str(n)
ln = len(n1)
if ln > 1:
m1 = '1' + '0' * (ln - 2)
m = int(m1)
l = n % m
else:
m = 10
l = n % m
if l > 5:
n = n // 10
n = (n + 1) * 10
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
667 | B | Coat of Anticubism | PROGRAMMING | 1,100 | [
"constructive algorithms",
"geometry"
] | null | null | As some of you know, cubism is a trend in art, where the problem of constructing volumetrical shape on a plane with a combination of three-dimensional geometric shapes comes to the fore.
A famous sculptor Cicasso, whose self-portrait you can contemplate, hates cubism. He is more impressed by the idea to transmit two-... | The first line contains an integer *n* (3<=≤<=*n*<=≤<=105) — a number of rod-blanks.
The second line contains *n* integers *l**i* (1<=≤<=*l**i*<=≤<=109) — lengths of rods, which Cicasso already has. It is guaranteed that it is impossible to make a polygon with *n* vertices and nonzero area using the rods Cicasso alrea... | Print the only integer *z* — the minimum length of the rod, so that after adding it it can be possible to construct convex polygon with (*n*<=+<=1) vertices and nonzero area from all of the rods. | [
"3\n1 2 1\n",
"5\n20 4 3 2 1\n"
] | [
"1\n",
"11\n"
] | In the first example triangle with sides {1 + 1 = 2, 2, 1} can be formed from a set of lengths {1, 1, 1, 2}.
In the second example you can make a triangle with lengths {20, 11, 4 + 3 + 2 + 1 = 10}. | 1,000 | [
{
"input": "3\n1 2 1",
"output": "1"
},
{
"input": "5\n20 4 3 2 1",
"output": "11"
},
{
"input": "7\n77486105 317474713 89523018 332007362 7897847 949616701 54820086",
"output": "70407571"
},
{
"input": "14\n245638694 2941428 4673577 12468 991349408 44735727 14046308 60637707... | 1,626,889,395 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 109 | 10,240,000 | mas = list(map(int, input().split()))
t = mas[0]
mas = list(map(int, input().split()))
s = 0
for i in mas:
s += i
mas.sort()
print(2 * mas[-1] - s + 1) | Title: Coat of Anticubism
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As some of you know, cubism is a trend in art, where the problem of constructing volumetrical shape on a plane with a combination of three-dimensional geometric shapes comes to the fore.
A famous sculptor Cicasso, ... | ```python
mas = list(map(int, input().split()))
t = mas[0]
mas = list(map(int, input().split()))
s = 0
for i in mas:
s += i
mas.sort()
print(2 * mas[-1] - s + 1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,684,164,165 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 0 | denominations=[100,20,10,5,1]
index=0
result=0
amount=int(input())
for denomination in denominations:
if amount>=denomination:
result+=amount//denomination
amount-=amount//denomination * denomination
print(result)
| Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
denominations=[100,20,10,5,1]
index=0
result=0
amount=int(input())
for denomination in denominations:
if amount>=denomination:
result+=amount//denomination
amount-=amount//denomination * denomination
print(result)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
735 | D | Taxes | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not equal to *n*, of course). For example, if *n*<==<=6 then Funt has to pay 3 burles, while fo... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·109) — the total year income of mr. Funt. | Print one integer — minimum possible number of burles that mr. Funt has to pay as a tax. | [
"4\n",
"27\n"
] | [
"2\n",
"3\n"
] | none | 1,750 | [
{
"input": "4",
"output": "2"
},
{
"input": "27",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "5",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "2000000000",
"output": "2"
},
{
"input": "26",
"output": ... | 1,597,662,005 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 170 | 409,600 | from sys import stdin,stdout
from collections import Counter
from collections import defaultdict
from math import ceil
from bisect import bisect_left
from bisect import bisect_right
import math
ai = lambda: list(map(int, stdin.readline().split()))
ei = lambda: map(int, stdin.readline().split())
ip = lambda:... | Title: Taxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not ... | ```python
from sys import stdin,stdout
from collections import Counter
from collections import defaultdict
from math import ceil
from bisect import bisect_left
from bisect import bisect_right
import math
ai = lambda: list(map(int, stdin.readline().split()))
ei = lambda: map(int, stdin.readline().split())
ip... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
155 | B | Combination | PROGRAMMING | 1,100 | [
"greedy",
"sortings"
] | null | null | Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number *a**i*, and the botto... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards Ilya has.
Each of the next *n* lines contains two non-negative space-separated integers — *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=104) — the numbers, written at the top and the bottom of the *i*-th card correspondingly. | Print the single number — the maximum number of points you can score in one round by the described rules. | [
"2\n1 0\n2 0\n",
"3\n1 0\n2 0\n0 2\n"
] | [
"2\n",
"3\n"
] | In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards. | 1,000 | [
{
"input": "2\n1 0\n2 0",
"output": "2"
},
{
"input": "3\n1 0\n2 0\n0 2",
"output": "3"
},
{
"input": "5\n0 0\n2 0\n2 0\n3 0\n5 1",
"output": "8"
},
{
"input": "7\n9 1\n8 1\n9 0\n9 1\n5 1\n1 1\n0 1",
"output": "41"
},
{
"input": "7\n5 0\n4 0\n3 0\n5 2\n3 0\n4 2\n0... | 1,686,159,370 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 6 | 62 | 0 | zeros = []
score = 0
cards = 1
for _ in range(int(input())):
a, b = list(map(int, input().split(' ')))
if b == 0:
zeros.append(a)
else:
cards -= 1
cards += b
score += a
zeros = sorted(zeros)[::-1]
for i in range(cards):
score += zeros[i]
print(scor... | Title: Combination
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player ... | ```python
zeros = []
score = 0
cards = 1
for _ in range(int(input())):
a, b = list(map(int, input().split(' ')))
if b == 0:
zeros.append(a)
else:
cards -= 1
cards += b
score += a
zeros = sorted(zeros)[::-1]
for i in range(cards):
score += zeros[i]
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
219 | A | k-String | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string... | The first input line contains integer *k* (1<=≤<=*k*<=≤<=1000). The second line contains *s*, all characters in *s* are lowercase English letters. The string length *s* satisfies the inequality 1<=≤<=|*s*|<=≤<=1000, where |*s*| is the length of string *s*. | Rearrange the letters in string *s* in such a way that the result is a *k*-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "-1" (without quotes). | [
"2\naazz\n",
"3\nabcabcabz\n"
] | [
"azaz\n",
"-1\n"
] | none | 500 | [
{
"input": "2\naazz",
"output": "azaz"
},
{
"input": "3\nabcabcabz",
"output": "-1"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "2\nabba",
"output": "abab"
},
{
"input": "2\naaab",
"output": "-1"
},
{
"input": "7\nabacaba",
"output": "-1"
}... | 1,634,848,991 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 4,505,600 | k=int(input())
text=input()
text=sorted(text)
letters=[[] for _ in range(26)]
j=0
while len(text) and j < len(letters):
i=text[0]
while len(text) and i == i:
letters[j].append(text.pop(0))
j+=1
x =0
while x<len(letters) and letters[x]:
x+=1
letters=letters[0:x]
lengths=([len(x) for... | Title: k-String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a ... | ```python
k=int(input())
text=input()
text=sorted(text)
letters=[[] for _ in range(26)]
j=0
while len(text) and j < len(letters):
i=text[0]
while len(text) and i == i:
letters[j].append(text.pop(0))
j+=1
x =0
while x<len(letters) and letters[x]:
x+=1
letters=letters[0:x]
lengths=([... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,603,943,387 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 218 | 0 | # import pandas as pd
# import numpy as np
# import sklearn
# from sklearn import linear_model
# from sklearn.utils import shuffle
# data = pd.read_csv("student-mat.csv", sep=";")
# print(data.head())
# data = data[["G1", "G2", "G3", "studytime", "failures", "absences"]]
string=input()
upper=0
lower=0
f... | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
# import pandas as pd
# import numpy as np
# import sklearn
# from sklearn import linear_model
# from sklearn.utils import shuffle
# data = pd.read_csv("student-mat.csv", sep=";")
# print(data.head())
# data = data[["G1", "G2", "G3", "studytime", "failures", "absences"]]
string=input()
upper=0
... | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
765 | C | Table Tennis Game 2 | PROGRAMMING | 1,200 | [
"math"
] | null | null | Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scores exactly *k* points, the score is reset and a new set begins.
Across all the sets Misha scored *a* poi... | The first line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=109, 0<=≤<=*a*,<=*b*<=≤<=109, *a*<=+<=*b*<=><=0). | If the situation is impossible, print a single number -1. Otherwise, print the maximum possible number of sets. | [
"11 11 5\n",
"11 2 3\n"
] | [
"1\n",
"-1\n"
] | Note that the rules of the game in this problem differ from the real table tennis game, for example, the rule of "balance" (the winning player has to be at least two points ahead to win a set) has no power within the present problem. | 1,250 | [
{
"input": "11 11 5",
"output": "1"
},
{
"input": "11 2 3",
"output": "-1"
},
{
"input": "1 5 9",
"output": "14"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "1 1000000000 1000000000",
"output": "2000000000"
},
{
"input": "2 3 5",
"output": "... | 1,487,063,470 | 3,970 | Python 3 | WRONG_ANSWER | PRETESTS | 1 | 46 | 4,608,000 | # 1 Yotta Byte!
# Codeforces 397
k,a,b=map(int,input().split())
'''
c=a+b
n=c/(2*k)
m=int(n)
t=0
if n-m>0 or a/k-a//k>0 or b/k-b//k>0:
t+=1
if n==0:
print(-1)
else:
print(m+t)
'''
mn=max(a,b)
n=mn/k
m=int(n)
t=0
if n-m>0:
t=1
print(m+t)
| Title: Table Tennis Game 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scor... | ```python
# 1 Yotta Byte!
# Codeforces 397
k,a,b=map(int,input().split())
'''
c=a+b
n=c/(2*k)
m=int(n)
t=0
if n-m>0 or a/k-a//k>0 or b/k-b//k>0:
t+=1
if n==0:
print(-1)
else:
print(m+t)
'''
mn=max(a,b)
n=mn/k
m=int(n)
t=0
if n-m>0:
t=1
print(m+t)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
315 | A | Sereja and Bottles | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th bottle is from brand *a**i*, besides, you can use it to open other bottles of brand *b**i*. You can use... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles. The next *n* lines contain the bottles' description. The *i*-th line contains two integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the description of the *i*-th bottle. | In a single line print a single integer — the answer to the problem. | [
"4\n1 1\n2 2\n3 3\n4 4\n",
"4\n1 2\n2 3\n3 4\n4 1\n"
] | [
"4\n",
"0\n"
] | none | 500 | [
{
"input": "4\n1 1\n2 2\n3 3\n4 4",
"output": "4"
},
{
"input": "4\n1 2\n2 3\n3 4\n4 1",
"output": "0"
},
{
"input": "3\n2 828\n4 392\n4 903",
"output": "3"
},
{
"input": "4\n2 3\n1 772\n3 870\n3 668",
"output": "2"
},
{
"input": "5\n1 4\n6 6\n4 3\n3 4\n4 758",
... | 1,476,152,467 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 248 | 5,120,000 | from collections import defaultdict
def serej(bottles):
#set of bottles that need to be opened
unopened = defaultdict(set)
for i, bottle in enumerate(bottles):
unopened[bottle[0]].add(i+1)
for i, bottle in enumerate(bottles):
if bottle[1] in unopened:
unopened[bottle[1]] ... | Title: Sereja and Bottles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th... | ```python
from collections import defaultdict
def serej(bottles):
#set of bottles that need to be opened
unopened = defaultdict(set)
for i, bottle in enumerate(bottles):
unopened[bottle[0]].add(i+1)
for i, bottle in enumerate(bottles):
if bottle[1] in unopened:
unopened[b... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
577 | A | Multiplication Table | PROGRAMMING | 1,000 | [
"implementation",
"number theory"
] | null | null | Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain num... | The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table. | Print a single number: the number of times *x* occurs in the table. | [
"10 5\n",
"6 12\n",
"5 13\n"
] | [
"2\n",
"4\n",
"0\n"
] | A table for the second sample test is given below. The occurrences of number 12 are marked bold. | 500 | [
{
"input": "10 5",
"output": "2"
},
{
"input": "6 12",
"output": "4"
},
{
"input": "5 13",
"output": "0"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "100000 1",
"output": "1"
},
{
"input": "1 10000000... | 1,657,543,422 | 2,147,483,647 | PyPy 3-64 | MEMORY_LIMIT_EXCEEDED | TESTS | 5 | 265 | 268,390,400 | n,s=map(int,input().split())
ax=[]
for i in range(1,n+1):
t=[i*x for x in range(1,n+1)]
ax.append(t)
cnt=0
for x in ax:
cnt+=x.count(s)
print(cnt) | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
Y... | ```python
n,s=map(int,input().split())
ax=[]
for i in range(1,n+1):
t=[i*x for x in range(1,n+1)]
ax.append(t)
cnt=0
for x in ax:
cnt+=x.count(s)
print(cnt)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,549,300,573 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 248 | 0 | string = str(input())
cu = 0
cl = 0
for items in string:
if items.isupper():
cu = cu + 1
elif items.islower():
cl = cl + 1
if cl>=cu:
string = string.lower()
elif cu>cl:
string = string.upper()
print(string) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
string = str(input())
cu = 0
cl = 0
for items in string:
if items.isupper():
cu = cu + 1
elif items.islower():
cl = cl + 1
if cl>=cu:
string = string.lower()
elif cu>cl:
string = string.upper()
print(string)
``` | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,695,052,382 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 46 | 0 | # s = input().split("+")
# a = list(map(int, s))
# g = len(a)
# for i in range(g - 1):
# for j in range(g - 1 - i):
# if a[j] > a[j + 1]:
# a[j], a[j+ 1] = a[j + 1], a[j]
# print(*a, sep="+")
# t = int(input())
# for i in range(t):
# a = input().split()
# b = list(map(int, a... | Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
# s = input().split("+")
# a = list(map(int, s))
# g = len(a)
# for i in range(g - 1):
# for j in range(g - 1 - i):
# if a[j] > a[j + 1]:
# a[j], a[j+ 1] = a[j + 1], a[j]
# print(*a, sep="+")
# t = int(input())
# for i in range(t):
# a = input().split()
# b = list(... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,687,848,378 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 51 | 434 | 9,728,000 | n=int(input())
r=0
while n>9:
n=sum(map(int,str(n)))
r+=1
print(r) | Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
n=int(input())
r=0
while n>9:
n=sum(map(int,str(n)))
r+=1
print(r)
``` | 3.873996 | MatrixStudio/Codeforces-Python-Submissions |
24 | A | Ring road | PROGRAMMING | 1,400 | [
"graphs"
] | A. Ring road | 2 | 256 | Nowadays the one-way traffic is introduced all over the world in order to improve driving safety and reduce traffic jams. The government of Berland decided to keep up with new trends. Formerly all *n* cities of Berland were connected by *n* two-way roads in the ring, i. e. each city was connected directly to exactly tw... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of cities (and roads) in Berland. Next *n* lines contain description of roads. Each road is described by three integers *a**i*, *b**i*, *c**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*,<=1<=≤<=*c**i*<=≤<=100) — road is directed from city *a**i* t... | Output single integer — the smallest amount of money the government should spend on the redirecting of roads so that from every city you can get to any other. | [
"3\n1 3 1\n1 2 1\n3 2 1\n",
"3\n1 3 1\n1 2 5\n3 2 1\n",
"6\n1 5 4\n5 3 8\n2 4 15\n1 6 16\n2 3 23\n4 6 42\n",
"4\n1 2 9\n2 3 8\n3 4 7\n4 1 5\n"
] | [
"1\n",
"2\n",
"39\n",
"0\n"
] | none | 0 | [
{
"input": "3\n1 3 1\n1 2 1\n3 2 1",
"output": "1"
},
{
"input": "3\n1 3 1\n1 2 5\n3 2 1",
"output": "2"
},
{
"input": "6\n1 5 4\n5 3 8\n2 4 15\n1 6 16\n2 3 23\n4 6 42",
"output": "39"
},
{
"input": "4\n1 2 9\n2 3 8\n3 4 7\n4 1 5",
"output": "0"
},
{
"input": "5\n... | 1,602,467,816 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 248 | 0 | arr = {}
arr2 = {}
cost = 0
cost2 = 0
n = int(input())
for _ in range(n):
a, b, c = list(map(int, input().split()))
cost2 += c
if a in arr:
arr[a].append(b)
else:
arr[a] = [b]
arr2[a, b] = c
#print(arr)
#print(arr2)
count = 0
for k in arr:
if len(arr[k]) > 1:
... | Title: Ring road
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Nowadays the one-way traffic is introduced all over the world in order to improve driving safety and reduce traffic jams. The government of Berland decided to keep up with new trends. Formerly all *n* cities of Berland were conne... | ```python
arr = {}
arr2 = {}
cost = 0
cost2 = 0
n = int(input())
for _ in range(n):
a, b, c = list(map(int, input().split()))
cost2 += c
if a in arr:
arr[a].append(b)
else:
arr[a] = [b]
arr2[a, b] = c
#print(arr)
#print(arr2)
count = 0
for k in arr:
if len(arr[k]... | 0 | MatrixStudio/Codeforces-Python-Submissions |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,625,401,667 | 2,147,483,647 | PyPy 3 | OK | TESTS | 20 | 218 | 2,355,200 | from collections import defaultdict
T=int(input())
mat=[]
d=defaultdict(int)
d1=defaultdict(int)
for _ in range(T):
a=[str(x) for x in input().split()]
mat.append(a)
d[a[0]]+=(int(a[1]))
ans=max(list(d.values()))
ss=set()
for i in d:
if d[i]==ans:
ss.add(i)
for i in mat:
d1[i[0]]+=int... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
from collections import defaultdict
T=int(input())
mat=[]
d=defaultdict(int)
d1=defaultdict(int)
for _ in range(T):
a=[str(x) for x in input().split()]
mat.append(a)
d[a[0]]+=(int(a[1]))
ans=max(list(d.values()))
ss=set()
for i in d:
if d[i]==ans:
ss.add(i)
for i in mat:
d1[... | 3.873452 | MatrixStudio/Codeforces-Python-Submissions |
448 | D | Multiplication Table | PROGRAMMING | 1,800 | [
"binary search",
"brute force"
] | null | null | Bizon the Champion isn't just charming, he also is very smart.
While some of us were learning the multiplication table, Bizon the Champion had fun in his own manner. Bizon the Champion painted an *n*<=×<=*m* multiplication table, where the element on the intersection of the *i*-th row and *j*-th column equals *i*·*j* ... | The single line contains integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=5·105; 1<=≤<=*k*<=≤<=*n*·*m*). | Print the *k*-th largest number in a *n*<=×<=*m* multiplication table. | [
"2 2 2\n",
"2 3 4\n",
"1 10 5\n"
] | [
"2\n",
"3\n",
"5\n"
] | A 2 × 3 multiplication table looks like this: | 2,000 | [
{
"input": "2 2 2",
"output": "2"
},
{
"input": "2 3 4",
"output": "3"
},
{
"input": "1 10 5",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "10 1 7",
"output": "7"
},
{
"input": "10 10 33",
"output": "14"
},
{
"input": "... | 1,620,759,227 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 74,444,800 | #!/usr/bin/env python3
n, m, k = map(int, input().split())
l = 0
r = n * m
best = -1
def check(x):
return sum([min(x - 1, i * m) // i for i in range(1, n + 1)]) < k
while l <= r:
mid = (l + r) // 2
if check(mid):
best = mid
l = mid + 1
else:
r = mid - 1
assert(best != -1)
pr... | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bizon the Champion isn't just charming, he also is very smart.
While some of us were learning the multiplication table, Bizon the Champion had fun in his own manner. Bizon the Champion painted an *n*<=×<=*m* multi... | ```python
#!/usr/bin/env python3
n, m, k = map(int, input().split())
l = 0
r = n * m
best = -1
def check(x):
return sum([min(x - 1, i * m) // i for i in range(1, n + 1)]) < k
while l <= r:
mid = (l + r) // 2
if check(mid):
best = mid
l = mid + 1
else:
r = mid - 1
assert(best... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
570 | A | Elections | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | The country of Byalechinsk is running elections involving *n* candidates. The country consists of *m* cities. We know how many people in each city voted for each candidate.
The electoral system in the country is pretty unusual. At the first stage of elections the votes are counted for each city: it is assumed that in ... | The first line of the input contains two integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of candidates and of cities, respectively.
Each of the next *m* lines contains *n* non-negative integers, the *j*-th number in the *i*-th line *a**ij* (1<=≤<=*j*<=≤<=*n*, 1<=≤<=*i*<=≤<=*m*, 0<=≤<=*a**ij*<=≤<=109) denotes ... | Print a single number — the index of the candidate who won the elections. The candidates are indexed starting from one. | [
"3 3\n1 2 3\n2 3 1\n1 2 1\n",
"3 4\n10 10 3\n5 1 6\n2 2 2\n1 5 7\n"
] | [
"2",
"1"
] | Note to the first sample test. At the first stage city 1 chosen candidate 3, city 2 chosen candidate 2, city 3 chosen candidate 2. The winner is candidate 2, he gained 2 votes.
Note to the second sample test. At the first stage in city 1 candidates 1 and 2 got the same maximum number of votes, but candidate 1 has a sm... | 500 | [
{
"input": "3 3\n1 2 3\n2 3 1\n1 2 1",
"output": "2"
},
{
"input": "3 4\n10 10 3\n5 1 6\n2 2 2\n1 5 7",
"output": "1"
},
{
"input": "1 3\n5\n3\n2",
"output": "1"
},
{
"input": "3 1\n1 2 3",
"output": "3"
},
{
"input": "3 1\n100 100 100",
"output": "1"
},
{... | 1,558,524,829 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 0 | n, m = map(int, input().split())
a = [0] * n
for i in range(m):
b = map(int, input().split())
a[b.index(max(b))]+=1
print(a.index(max(a)) + 1) | Title: Elections
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The country of Byalechinsk is running elections involving *n* candidates. The country consists of *m* cities. We know how many people in each city voted for each candidate.
The electoral system in the country is pretty unusu... | ```python
n, m = map(int, input().split())
a = [0] * n
for i in range(m):
b = map(int, input().split())
a[b.index(max(b))]+=1
print(a.index(max(a)) + 1)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
913 | A | Modular Exponentiation | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" problem. Given integers *n* and *m*, calculate | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=108).
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=108). | Output a single integer — the value of . | [
"4\n42\n",
"1\n58\n",
"98765432\n23456789\n"
] | [
"10\n",
"0\n",
"23456789\n"
] | In the first example, the remainder of division of 42 by 2<sup class="upper-index">4</sup> = 16 is equal to 10.
In the second example, 58 is divisible by 2<sup class="upper-index">1</sup> = 2 without remainder, and the answer is 0. | 500 | [
{
"input": "4\n42",
"output": "10"
},
{
"input": "1\n58",
"output": "0"
},
{
"input": "98765432\n23456789",
"output": "23456789"
},
{
"input": "8\n88127381",
"output": "149"
},
{
"input": "32\n92831989",
"output": "92831989"
},
{
"input": "92831989\n25... | 1,595,418,324 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 155 | 33,177,600 | n= int(input())
m= int(input())
a=2**n
print(m%a) | Title: Modular Exponentiation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" prob... | ```python
n= int(input())
m= int(input())
a=2**n
print(m%a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
165 | C | Another Problem on Strings | PROGRAMMING | 1,600 | [
"binary search",
"brute force",
"dp",
"math",
"strings",
"two pointers"
] | null | null | A string is binary, if it consists only of characters "0" and "1".
String *v* is a substring of string *w* if it has a non-zero length and can be read starting from some position in string *w*. For example, string "010" has six substrings: "0", "1", "0", "01", "10", "010". Two substrings are considered different if th... | The first line contains the single integer *k* (0<=≤<=*k*<=≤<=106). The second line contains a non-empty binary string *s*. The length of *s* does not exceed 106 characters. | Print the single number — the number of substrings of the given string, containing exactly *k* characters "1".
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"1\n1010\n",
"2\n01010\n",
"100\n01010\n"
] | [
"6\n",
"4\n",
"0\n"
] | In the first sample the sought substrings are: "1", "1", "10", "01", "10", "010".
In the second sample the sought substrings are: "101", "0101", "1010", "01010". | 1,500 | [
{
"input": "1\n1010",
"output": "6"
},
{
"input": "2\n01010",
"output": "4"
},
{
"input": "100\n01010",
"output": "0"
},
{
"input": "0\n01010",
"output": "3"
},
{
"input": "0\n0010100011",
"output": "10"
},
{
"input": "0\n10000",
"output": "10"
}... | 1,682,934,816 | 2,147,483,647 | Python 3 | OK | TESTS | 82 | 1,340 | 11,366,400 | m= int(input())
s=input()
n=len(s)
tem=1
y=[]
for i in range (0,n):
if s[i]=='1':
y.append(tem)
tem=1
else:
tem+=1
y.append(tem)
ans=0
if m>0:
if len(y)<m+1:
print(0)
else:
for i in range (0,len(y)-m):
ans+=y[i]*y[i+m]
print(... | Title: Another Problem on Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is binary, if it consists only of characters "0" and "1".
String *v* is a substring of string *w* if it has a non-zero length and can be read starting from some position in string *w*. For example, ... | ```python
m= int(input())
s=input()
n=len(s)
tem=1
y=[]
for i in range (0,n):
if s[i]=='1':
y.append(tem)
tem=1
else:
tem+=1
y.append(tem)
ans=0
if m>0:
if len(y)<m+1:
print(0)
else:
for i in range (0,len(y)-m):
ans+=y[i]*y[i+m]
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
11 | A | Increasing Sequence | PROGRAMMING | 900 | [
"constructive algorithms",
"implementation",
"math"
] | A. Increasing Sequence | 1 | 64 | A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least... | The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106). | Output the minimal number of moves needed to make the sequence increasing. | [
"4 2\n1 3 3 2\n"
] | [
"3\n"
] | none | 0 | [
{
"input": "4 2\n1 3 3 2",
"output": "3"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 1\n2 5",
"output": "0"
},
{
"input": "2 1\n1 2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 7\n10 20",
"output": "0"
},
... | 1,584,756,617 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 10 | 310 | 0 | n,d=tuple(map(int,input().split()))
l=list(map(int,input().split()))
c=0
if l[0]>=l[1]:
while(l[1]<=l[0]):
l[1]+=d
c+=1
for i in range(1,len(l)-1):
if l[i]<=l[i+1]:
continue
else:
q=l[i-1]
while(l[i]<=q):
l[i]+=d
c+=1
if l[len(l)... | Title: Increasing Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*... | ```python
n,d=tuple(map(int,input().split()))
l=list(map(int,input().split()))
c=0
if l[0]>=l[1]:
while(l[1]<=l[0]):
l[1]+=d
c+=1
for i in range(1,len(l)-1):
if l[i]<=l[i+1]:
continue
else:
q=l[i-1]
while(l[i]<=q):
l[i]+=d
c+=1
i... | 0 | MatrixStudio/Codeforces-Python-Submissions |
7 | A | Kalevitch and Chess | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms"
] | A. Kalevitch and Chess | 2 | 64 | A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch decided to put an end to this tradition and to introduce a new attitude to chessboards.
As before, th... | The input file contains 8 lines, each of the lines contains 8 characters. The given matrix describes the client's requirements, W character stands for a white square, and B character — for a square painted black.
It is guaranteed that client's requirments can be fulfilled with a sequence of allowed strokes (vertical/c... | Output the only number — the minimum amount of rows and columns that Kalevitch has to paint on the white chessboard to meet the client's requirements. | [
"WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\n",
"WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\n"
] | [
"3\n",
"1\n"
] | none | 0 | [
{
"input": "WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW",
"output": "3"
},
{
"input": "WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW",
"output": "1"
},
{
"input": "WWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWW... | 1,639,011,290 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 122 | 0 | import sys
row_white = [False] * 8
col_white = [False] * 8
board = []
count = 0
for line in sys.stdin:
chars = list(line[:len(line) - 1])
board.append(chars)
for i in range(len(row_white)):
for j in range(len(col_white)):
if board[i][j] == 'W':
row_white[i] = True
... | Title: Kalevitch and Chess
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch de... | ```python
import sys
row_white = [False] * 8
col_white = [False] * 8
board = []
count = 0
for line in sys.stdin:
chars = list(line[:len(line) - 1])
board.append(chars)
for i in range(len(row_white)):
for j in range(len(col_white)):
if board[i][j] == 'W':
row_white[i] = T... | 3.9695 | MatrixStudio/Codeforces-Python-Submissions |
992 | A | Nastya and an Array | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second we can add an arbitrary (possibly negative) integer to all elements of the array that are not equal to ze... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=105<=≤<=*a**i*<=≤<=105) — the elements of the array. | Print a single integer — the minimum number of seconds needed to make all elements of the array equal to zero. | [
"5\n1 1 1 1 1\n",
"3\n2 0 -1\n",
"4\n5 -6 -5 1\n"
] | [
"1\n",
"2\n",
"4\n"
] | In the first example you can add - 1 to all non-zero elements in one second and make them equal to zero.
In the second example you can add - 2 on the first second, then the array becomes equal to [0, 0, - 3]. On the second second you can add 3 to the third (the only non-zero) element. | 500 | [
{
"input": "5\n1 1 1 1 1",
"output": "1"
},
{
"input": "3\n2 0 -1",
"output": "2"
},
{
"input": "4\n5 -6 -5 1",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n21794 -79194",
"output": "2"
},
{
"input": "3\n-63526 95085 -5239",
... | 1,530,270,838 | 2,147,483,647 | Python 3 | OK | TESTS | 79 | 155 | 9,113,600 | input()
a = {int(i) for i in input().split()}
print(len(a) - 1 if 0 in a else len(a))
| Title: Nastya and an Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second ... | ```python
input()
a = {int(i) for i in input().split()}
print(len(a) - 1 if 0 in a else len(a))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | From beginning till end, this message has been waiting to be conveyed.
For a given unordered multiset of *n* lowercase English letters ("multi" means that a letter may appear more than once), we treat all letters as strings of length 1, and repeat the following operation *n*<=-<=1 times:
- Remove any two elements *s... | The first and only line of input contains a non-negative integer *k* (0<=≤<=*k*<=≤<=100<=000) — the required minimum cost. | Output a non-empty string of no more than 100<=000 lowercase English letters — any multiset satisfying the requirements, concatenated to be a string.
Note that the printed string doesn't need to be the final concatenated string. It only needs to represent an unordered multiset of letters. | [
"12\n",
"3\n"
] | [
"abababab\n",
"codeforces\n"
] | For the multiset {'a', 'b', 'a', 'b', 'a', 'b', 'a', 'b'}, one of the ways to complete the process is as follows:
- {"ab", "a", "b", "a", "b", "a", "b"}, with a cost of 0; - {"aba", "b", "a", "b", "a", "b"}, with a cost of 1; - {"abab", "a", "b", "a", "b"}, with a cost of 1; - {"abab", "ab", "a", "b"}, with a cost... | 0 | [
{
"input": "12",
"output": "abababab"
},
{
"input": "3",
"output": "codeforces"
},
{
"input": "0",
"output": "o"
},
{
"input": "2",
"output": "aabb"
},
{
"input": "5",
"output": "aaabbcc"
},
{
"input": "10",
"output": "aaaaa"
},
{
"input": ... | 1,504,279,691 | 6,791 | Python 3 | WRONG_ANSWER | PRETESTS | 2 | 46 | 0 | from sys import stdin
from math import sqrt
n = int(stdin.readline().rstrip())
N = n * 2
charset = 'abcdefghijklmnopqrstuvwxyz'
sqr = int(sqrt(N)) // 2 + 1
for i in range(1, sqr + 1):
for j in range(1, i + 1):
for k in range(1, 26 + 1):
N_ = N - k * i * (i + 1)
if N_ % (j... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
From beginning till end, this message has been waiting to be conveyed.
For a given unordered multiset of *n* lowercase English letters ("multi" means that a letter may appear more than once), we treat all letters as strings of le... | ```python
from sys import stdin
from math import sqrt
n = int(stdin.readline().rstrip())
N = n * 2
charset = 'abcdefghijklmnopqrstuvwxyz'
sqr = int(sqrt(N)) // 2 + 1
for i in range(1, sqr + 1):
for j in range(1, i + 1):
for k in range(1, 26 + 1):
N_ = N - k * i * (i + 1)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
474 | A | Keyboard | PROGRAMMING | 900 | [
"implementation"
] | null | null | Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately. He accidentally moved both his hands with one position to the left or to the right. That mean... | First line of the input contains one letter describing direction of shifting ('L' or 'R' respectively for left or right).
Second line contains a sequence of characters written by Mole. The size of this sequence will be no more than 100. Sequence contains only symbols that appear on Mole's keyboard. It doesn't contain ... | Print a line that contains the original message. | [
"R\ns;;upimrrfod;pbr\n"
] | [
"allyouneedislove\n"
] | none | 500 | [
{
"input": "R\ns;;upimrrfod;pbr",
"output": "allyouneedislove"
},
{
"input": "R\nwertyuiop;lkjhgfdsxcvbnm,.",
"output": "qwertyuiolkjhgfdsazxcvbnm,"
},
{
"input": "L\nzxcvbnm,kjhgfdsaqwertyuio",
"output": "xcvbnm,.lkjhgfdswertyuiop"
},
{
"input": "R\nbubbuduppudup",
"outp... | 1,691,242,116 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 62 | 0 | keyboard = "qwertyuiopasdfghjkl;zxcvbnm,./"
shift= input()
typing = input()
new = ""
for i in range(len(typing)):
if shift == "R":
new+= keyboard[keyboard.index(typing[i]) - 1]
else:
new+= keyboard[keyboard.index(typing[i]) + 1]
print(new) | Title: Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately.... | ```python
keyboard = "qwertyuiopasdfghjkl;zxcvbnm,./"
shift= input()
typing = input()
new = ""
for i in range(len(typing)):
if shift == "R":
new+= keyboard[keyboard.index(typing[i]) - 1]
else:
new+= keyboard[keyboard.index(typing[i]) + 1]
print(new)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
990 | A | Commentary Boxes | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation should get the same number of the commentary boxes. If any box is left unoccupied then the delegations wil... | The only line contains four integer numbers $n$, $m$, $a$ and $b$ ($1 \le n, m \le 10^{12}$, $1 \le a, b \le 100$), where $n$ is the initial number of the commentary boxes, $m$ is the number of delegations to come, $a$ is the fee to build a box and $b$ is the fee to demolish a box. | Output the minimal amount of burles organizers should pay to satisfy all the delegations (i.e. to make the number of the boxes be divisible by $m$). It is allowed that the final number of the boxes is equal to $0$. | [
"9 7 3 8\n",
"2 7 3 7\n",
"30 6 17 19\n"
] | [
"15\n",
"14\n",
"0\n"
] | In the first example organizers can build $5$ boxes to make the total of $14$ paying $3$ burles for the each of them.
In the second example organizers can demolish $2$ boxes to make the total of $0$ paying $7$ burles for the each of them.
In the third example organizers are already able to distribute all the boxes eq... | 0 | [
{
"input": "9 7 3 8",
"output": "15"
},
{
"input": "2 7 3 7",
"output": "14"
},
{
"input": "30 6 17 19",
"output": "0"
},
{
"input": "500000000001 1000000000000 100 100",
"output": "49999999999900"
},
{
"input": "1000000000000 750000000001 10 100",
"output": "... | 1,528,630,400 | 5,300 | Python 3 | OK | TESTS | 109 | 108 | 0 | a,b,c,d=[int (x) for x in input().split()]
def min(a,b):
if(a>=b):
return b
else:
return a
a=min(a%b*d,(b-a%b)*c)
print(a) | Title: Commentary Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation shou... | ```python
a,b,c,d=[int (x) for x in input().split()]
def min(a,b):
if(a>=b):
return b
else:
return a
a=min(a%b*d,(b-a%b)*c)
print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
811 | A | Vladik and Courtesy | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | At regular competition Vladik and Valera won *a* and *b* candies respectively. Vladik offered 1 his candy to Valera. After that Valera gave Vladik 2 his candies, so that no one thought that he was less generous. Vladik for same reason gave 3 candies to Valera in next turn.
More formally, the guys take turns giving eac... | Single line of input data contains two space-separated integers *a*, *b* (1<=≤<=*a*,<=*b*<=≤<=109) — number of Vladik and Valera candies respectively. | Pring a single line "Vladik’’ in case, if Vladik first who can’t give right amount of candy, or "Valera’’ otherwise. | [
"1 1\n",
"7 6\n"
] | [
"Valera\n",
"Vladik\n"
] | Illustration for first test case:
<img class="tex-graphics" src="https://espresso.codeforces.com/ad9b7d0e481208de8e3a585aa1d96b9e1dda4fd7.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Illustration for second test case:
<img class="tex-graphics" src="https://espresso.codeforces.com/9f4836d2ccdffaee5a63898e5d4e... | 500 | [
{
"input": "1 1",
"output": "Valera"
},
{
"input": "7 6",
"output": "Vladik"
},
{
"input": "25 38",
"output": "Vladik"
},
{
"input": "8311 2468",
"output": "Valera"
},
{
"input": "250708 857756",
"output": "Vladik"
},
{
"input": "957985574 24997558",
... | 1,588,761,388 | 2,147,483,647 | PyPy 3 | OK | TESTS | 42 | 140 | 1,331,200 | n,m = map(int,input().split())
i=1
while(n>=0 and m>=0):
n-=i
i+=1
if(n<0):
print("Vladik")
break
m-=i
i+=1
if(m<0):
print("Valera")
break
| Title: Vladik and Courtesy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
At regular competition Vladik and Valera won *a* and *b* candies respectively. Vladik offered 1 his candy to Valera. After that Valera gave Vladik 2 his candies, so that no one thought that he was less generous. Vla... | ```python
n,m = map(int,input().split())
i=1
while(n>=0 and m>=0):
n-=i
i+=1
if(n<0):
print("Vladik")
break
m-=i
i+=1
if(m<0):
print("Valera")
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
680 | B | Bear and Finding Criminals | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation"
] | null | null | There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city *a*. His job is to catch criminals. It's hard because he doesn't know in which cities criminals are. Though, he... | The first line of the input contains two integers *n* and *a* (1<=≤<=*a*<=≤<=*n*<=≤<=100) — the number of cities and the index of city where Limak lives.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (0<=≤<=*t**i*<=≤<=1). There are *t**i* criminals in the *i*-th city. | Print the number of criminals Limak will catch. | [
"6 3\n1 1 1 0 1 0\n",
"5 2\n0 0 0 1 0\n"
] | [
"3\n",
"1\n"
] | In the first sample, there are six cities and Limak lives in the third one (blue arrow below). Criminals are in cities marked red.
Using the BCD gives Limak the following information:
- There is one criminal at distance 0 from the third city — Limak is sure that this criminal is exactly in the third city. - There i... | 1,000 | [
{
"input": "6 3\n1 1 1 0 1 0",
"output": "3"
},
{
"input": "5 2\n0 0 0 1 0",
"output": "1"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "1 1\n0",
"output": "0"
},
{
"input": "9 3\n1 1 1 1 1 1 1 1 0",
"output": "8"
},
{
"input": "9 5\n1 0 1 0 1 0... | 1,631,509,527 | 2,147,483,647 | PyPy 3 | OK | TESTS | 24 | 108 | 20,172,800 | n,a=map(int,input().split())
arr=list(map(int,input().split()))
ind=a-1
cnt=0
if arr[ind]==1: cnt+=1
for i in range(1,n):
left=ind-i
right=ind+i
if left>=0 or right<n:
if left>=0 and right<n:
if arr[right]==1 and arr[left]==1: cnt+=2
elif left>=0:
if arr[l... | Title: Bear and Finding Criminals
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city... | ```python
n,a=map(int,input().split())
arr=list(map(int,input().split()))
ind=a-1
cnt=0
if arr[ind]==1: cnt+=1
for i in range(1,n):
left=ind-i
right=ind+i
if left>=0 or right<n:
if left>=0 and right<n:
if arr[right]==1 and arr[left]==1: cnt+=2
elif left>=0:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
762 | C | Two strings | PROGRAMMING | 2,100 | [
"binary search",
"hashing",
"strings",
"two pointers"
] | null | null | You are given two strings *a* and *b*. You have to remove the minimum possible number of consecutive (standing one after another) characters from string *b* in such a way that it becomes a subsequence of string *a*. It can happen that you will not need to remove any characters at all, or maybe you will have to remove a... | The first line contains string *a*, and the second line — string *b*. Both of these strings are nonempty and consist of lowercase letters of English alphabet. The length of each string is no bigger than 105 characters. | On the first line output a subsequence of string *a*, obtained from *b* by erasing the minimum number of consecutive characters.
If the answer consists of zero characters, output «-» (a minus sign). | [
"hi\nbob\n",
"abca\naccepted\n",
"abacaba\nabcdcba\n"
] | [
"-\n",
"ac\n",
"abcba\n"
] | In the first example strings *a* and *b* don't share any symbols, so the longest string that you can get is empty.
In the second example ac is a subsequence of *a*, and at the same time you can obtain it by erasing consecutive symbols cepted from string *b*. | 0 | [
{
"input": "hi\nbob",
"output": "-"
},
{
"input": "abca\naccepted",
"output": "ac"
},
{
"input": "abacaba\nabcdcba",
"output": "abcba"
},
{
"input": "lo\neuhaqdhhzlnkmqnakgwzuhurqlpmdm",
"output": "-"
},
{
"input": "aaeojkdyuilpdvyewjfrftkpcobhcumwlaoiocbfdtvjkhgd... | 1,560,201,733 | 2,147,483,647 | Python 3 | OK | TESTS | 99 | 342 | 5,939,200 | a = list(input())
b = list(input())
s = [-1]
i = 0
j = 0
while i < len(a) and j < len(b):
if a[i] == b[j]:
s.append(i)
j += 1
i += 1
e = [10**6]
i = len(a) - 1
j = len(b) - 1
while i >= 0 and j >= 0:
if a[i] == b[j]:
e.append(i)
j -= 1
i -= 1
ans_len = 0
ans = ['-']
i = len(s) - 1
j = 0
while i >= 0 a... | Title: Two strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two strings *a* and *b*. You have to remove the minimum possible number of consecutive (standing one after another) characters from string *b* in such a way that it becomes a subsequence of string *a*. It can ... | ```python
a = list(input())
b = list(input())
s = [-1]
i = 0
j = 0
while i < len(a) and j < len(b):
if a[i] == b[j]:
s.append(i)
j += 1
i += 1
e = [10**6]
i = len(a) - 1
j = len(b) - 1
while i >= 0 and j >= 0:
if a[i] == b[j]:
e.append(i)
j -= 1
i -= 1
ans_len = 0
ans = ['-']
i = len(s) - 1
j = 0
whil... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
192 | B | Walking in the Rain | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In Berland the opposition is going to arrange mass walking on the boulevard. The boulevard consists of *n* tiles that are lain in a row and are numbered from 1 to *n* from right to left. The opposition should start walking on the tile number 1 and the finish on the tile number *n*. During the walk it is allowed to move... | The first line contains integer *n* (1<=≤<=*n*<=≤<=103) — the boulevard's length in tiles.
The second line contains *n* space-separated integers *a**i* — the number of days after which the *i*-th tile gets destroyed (1<=≤<=*a**i*<=≤<=103). | Print a single number — the sought number of days. | [
"4\n10 3 5 10\n",
"5\n10 2 8 3 5\n"
] | [
"5\n",
"5\n"
] | In the first sample the second tile gets destroyed after day three, and the only path left is 1 → 3 → 4. After day five there is a two-tile gap between the first and the last tile, you can't jump over it.
In the second sample path 1 → 3 → 5 is available up to day five, inclusive. On day six the last tile is destroyed ... | 1,000 | [
{
"input": "4\n10 3 5 10",
"output": "5"
},
{
"input": "5\n10 2 8 3 5",
"output": "5"
},
{
"input": "10\n10 3 1 6 7 1 3 3 8 1",
"output": "1"
},
{
"input": "10\n26 72 10 52 2 5 61 2 39 64",
"output": "5"
},
{
"input": "100\n8 2 1 2 8 3 5 8 5 1 9 3 4 1 5 6 4 2 9 10... | 1,535,291,477 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 278 | 0 | n, t = int(input()), list(map(int, input().split()))
print(min(min(max(t[i], t[i + 1]) for i in range(1, n - 2)), t[0], t[n - 1]) if n > 2 else min(t))
# Made By Mostafa_Khaled | Title: Walking in the Rain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland the opposition is going to arrange mass walking on the boulevard. The boulevard consists of *n* tiles that are lain in a row and are numbered from 1 to *n* from right to left. The opposition should start ... | ```python
n, t = int(input()), list(map(int, input().split()))
print(min(min(max(t[i], t[i + 1]) for i in range(1, n - 2)), t[0], t[n - 1]) if n > 2 else min(t))
# Made By Mostafa_Khaled
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,650,372,374 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 233 | 9,728,000 | n, m = map(int, input().split())
a = []
b = []
c = []
res = []
for i in range(m):
s1, s2 = map(str, input().split())
a.append(s1)
b.append(s2)
if len(s2) < len(s1):
c.append(2)
else:
c.append(1)
s = list(input().split())
for el in s:
if c[a.index(... | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
n, m = map(int, input().split())
a = []
b = []
c = []
res = []
for i in range(m):
s1, s2 = map(str, input().split())
a.append(s1)
b.append(s2)
if len(s2) < len(s1):
c.append(2)
else:
c.append(1)
s = list(input().split())
for el in s:
if ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,691,163,658 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n=int(input())
l=list(map(int,input().split(' ')))
a,b,c=[],[],[]
for i,x in enumerate(l):
if(x==1):a.append(i+1)
elif(x==2):b.append(i+1)
else:c.append(i+1)
cc=min(len(a), min(len(b),len(c)))
if(cc>0):
for i in range(cc):
print(a[i],b[i],c[i])
| Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
n=int(input())
l=list(map(int,input().split(' ')))
a,b,c=[],[],[]
for i,x in enumerate(l):
if(x==1):a.append(i+1)
elif(x==2):b.append(i+1)
else:c.append(i+1)
cc=min(len(a), min(len(b),len(c)))
if(cc>0):
for i in range(cc):
print(a[i],b[i],c[i])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
220 | A | Little Elephant and Problem | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | null | null | The Little Elephant has got a problem — somebody has been touching his sorted by non-decreasing array *a* of length *n* and possibly swapped some elements of the array.
The Little Elephant doesn't want to call the police until he understands if he could have accidentally changed the array himself. He thinks that he co... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=105) — the size of array *a*. The next line contains *n* positive integers, separated by single spaces and not exceeding 109, — array *a*.
Note that the elements of the array are not necessarily distinct numbers. | In a single line print "YES" (without the quotes) if the Little Elephant could have accidentally changed the array himself, and "NO" (without the quotes) otherwise. | [
"2\n1 2\n",
"3\n3 2 1\n",
"4\n4 3 2 1\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample the array has already been sorted, so to sort it, we need 0 swap operations, that is not more than 1. Thus, the answer is "YES".
In the second sample we can sort the array if we swap elements 1 and 3, so we need 1 swap operation to sort the array. Thus, the answer is "YES".
In the third sample we ... | 500 | [
{
"input": "2\n1 2",
"output": "YES"
},
{
"input": "3\n3 2 1",
"output": "YES"
},
{
"input": "4\n4 3 2 1",
"output": "NO"
},
{
"input": "3\n1 3 2",
"output": "YES"
},
{
"input": "2\n2 1",
"output": "YES"
},
{
"input": "9\n7 7 8 8 10 10 10 10 1000000000... | 1,501,488,347 | 2,147,483,647 | Python 3 | OK | TESTS | 96 | 156 | 12,800,000 | def list_input():
return list(map(int,input().split()))
def map_input():
return map(int,input().split())
def map_string():
return input().split()
n = int(input())
a = list_input()
b = sorted(a)
cnt = 0
pos = 0
pos2 = 0
for i in range(n):
if b[i] != a[i]:
cnt += 1
... | Title: Little Elephant and Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has got a problem — somebody has been touching his sorted by non-decreasing array *a* of length *n* and possibly swapped some elements of the array.
The Little Elephant doesn't want to c... | ```python
def list_input():
return list(map(int,input().split()))
def map_input():
return map(int,input().split())
def map_string():
return input().split()
n = int(input())
a = list_input()
b = sorted(a)
cnt = 0
pos = 0
pos2 = 0
for i in range(n):
if b[i] != a[i]:
cnt += ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
722 | B | Verse Pattern | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | You are given a text consisting of *n* lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowel... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the text.
The second line contains integers *p*1,<=...,<=*p**n* (0<=≤<=*p**i*<=≤<=100) — the verse pattern.
Next *n* lines contain the text itself. Text consists of lowercase English letters and spaces. It's guarant... | If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes). | [
"3\n2 2 3\nintel\ncode\nch allenge\n",
"4\n1 2 3 1\na\nbcdefghi\njklmnopqrstu\nvwxyz\n",
"4\n13 11 15 15\nto be or not to be that is the question\nwhether tis nobler in the mind to suffer\nthe slings and arrows of outrageous fortune\nor to take arms against a sea of troubles\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample, one can split words into syllables in the following way:
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one. | 500 | [
{
"input": "3\n2 2 3\nintel\ncode\nch allenge",
"output": "YES"
},
{
"input": "4\n1 2 3 1\na\nbcdefghi\njklmnopqrstu\nvwxyz",
"output": "NO"
},
{
"input": "4\n13 11 15 15\nto be or not to be that is the question\nwhether tis nobler in the mind to suffer\nthe slings and arrows of outrageo... | 1,476,346,638 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 4,608,000 | def main():
n = int(input())
ns = (input()).split();
for i in range(n):
s = input()
c = 0
for substr in s:
if substr == 'a':
c += 1
elif substr == 'e':
c += 1
elif substr == 'i':
c += 1
elif substr == 'o':
c += 1
elif substr == 'u':
c += 1
if c != int(ns[i]):
print('... | Title: Verse Pattern
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text consisting of *n* lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary num... | ```python
def main():
n = int(input())
ns = (input()).split();
for i in range(n):
s = input()
c = 0
for substr in s:
if substr == 'a':
c += 1
elif substr == 'e':
c += 1
elif substr == 'i':
c += 1
elif substr == 'o':
c += 1
elif substr == 'u':
c += 1
if c != int(ns[i]):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
189 | A | Cut Ribbon | PROGRAMMING | 1,300 | [
"brute force",
"dp"
] | null | null | Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the number of ribbon pieces should be maximum.
Help Polycarpus and find the number of ribbon piece... | The first line contains four space-separated integers *n*, *a*, *b* and *c* (1<=≤<=*n*,<=*a*,<=*b*,<=*c*<=≤<=4000) — the length of the original ribbon and the acceptable lengths of the ribbon pieces after the cutting, correspondingly. The numbers *a*, *b* and *c* can coincide. | Print a single number — the maximum possible number of ribbon pieces. It is guaranteed that at least one correct ribbon cutting exists. | [
"5 5 3 2\n",
"7 5 5 2\n"
] | [
"2\n",
"2\n"
] | In the first example Polycarpus can cut the ribbon in such way: the first piece has length 2, the second piece has length 3.
In the second example Polycarpus can cut the ribbon in such way: the first piece has length 5, the second piece has length 2. | 500 | [
{
"input": "5 5 3 2",
"output": "2"
},
{
"input": "7 5 5 2",
"output": "2"
},
{
"input": "4 4 4 4",
"output": "1"
},
{
"input": "1 1 1 1",
"output": "1"
},
{
"input": "4000 1 2 3",
"output": "4000"
},
{
"input": "4000 3 4 5",
"output": "1333"
},
... | 1,693,876,692 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 4 | 93 | 6,451,200 | x = [int(i) for i in input().split()]
n,a,b,c = x[0],x[1],x[2],x[3]
def s2(n,a,b):
x = sorted([a,b])
a,b = x[0],x[1]
if n < a:
return -1
if n == a:
return 1
if n < b:
if not n % a:
return n // a
return -1
if n == b:
if not n % a:
return n // a
return 1
c = s2(n-a,a,b)... | Title: Cut Ribbon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the... | ```python
x = [int(i) for i in input().split()]
n,a,b,c = x[0],x[1],x[2],x[3]
def s2(n,a,b):
x = sorted([a,b])
a,b = x[0],x[1]
if n < a:
return -1
if n == a:
return 1
if n < b:
if not n % a:
return n // a
return -1
if n == b:
if not n % a:
return n // a
return 1
c = s... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
440 | A | Forgotten Episode | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus adores TV series. Right now he is ready to finish watching a season of a popular sitcom "Graph Theory". In total, the season has *n* episodes, numbered with integers from 1 to *n*.
Polycarpus watches episodes not one by one but in a random order. He has already watched all the episodes except for one. Which... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100000) — the number of episodes in a season. Assume that the episodes are numbered by integers from 1 to *n*.
The second line contains *n*<=-<=1 integer *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the numbers of episodes that Polycarpus has watch... | Print the number of the episode that Polycarpus hasn't watched. | [
"10\n3 8 10 1 7 9 6 5 2\n"
] | [
"4\n"
] | none | 500 | [
{
"input": "10\n3 8 10 1 7 9 6 5 2",
"output": "4"
},
{
"input": "5\n4 3 2 1",
"output": "5"
},
{
"input": "2\n1",
"output": "2"
},
{
"input": "2\n2",
"output": "1"
},
{
"input": "3\n1 2",
"output": "3"
},
{
"input": "3\n1 3",
"output": "2"
},
... | 1,588,674,321 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 155 | 7,168,000 | n = int(input())
a = list(map(int, input().split()))
x = [0] * (n+1)
for i in a:
x[i] = 1
for i in range(1,n+1):
if x[i] == 0:
print(i)
break | Title: Forgotten Episode
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus adores TV series. Right now he is ready to finish watching a season of a popular sitcom "Graph Theory". In total, the season has *n* episodes, numbered with integers from 1 to *n*.
Polycarpus watches episo... | ```python
n = int(input())
a = list(map(int, input().split()))
x = [0] * (n+1)
for i in a:
x[i] = 1
for i in range(1,n+1):
if x[i] == 0:
print(i)
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,593,316,965 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 310 | 20,172,800 | a,b,n=map(int,input().split())
def gcd(u,v):
while(v):
u,v=v,u%v
return u
#import math
while(1):
n=n-gcd(a,n)
if(n<=0):
print(0)
break
n=n-gcd(b,n)
if(n<=0):
print(1)
break
| Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
a,b,n=map(int,input().split())
def gcd(u,v):
while(v):
u,v=v,u%v
return u
#import math
while(1):
n=n-gcd(a,n)
if(n<=0):
print(0)
break
n=n-gcd(b,n)
if(n<=0):
print(1)
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,580,155,851 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 2,662,400 | x,y,z=input().split(' ')
x=int(x)
y=int(y)
z=int(z)
temp=0
flag=0
for i in range(0,z):
if flag==1:
old_x=x
for i in range(1,10):
temp=(10*x)+i
if(temp%y==0):
x=temp
break
if old_x==x:
x=(10*x)
else:
... | Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
x,y,z=input().split(' ')
x=int(x)
y=int(y)
z=int(z)
temp=0
flag=0
for i in range(0,z):
if flag==1:
old_x=x
for i in range(1,10):
temp=(10*x)+i
if(temp%y==0):
x=temp
break
if old_x==x:
x=(10*x)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,679,989,669 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 92 | 0 | a,b=map(int,input().split())
k=6-max(a,b)+1
if k==2:
print('1/3')
elif k==3:
print('1/2')
elif k==4:
print('2/3')
elif k==6:
print('1/1')
elif k==0:
print('0/1')
else:
print(str(k)+'/6') | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
a,b=map(int,input().split())
k=6-max(a,b)+1
if k==2:
print('1/3')
elif k==3:
print('1/2')
elif k==4:
print('2/3')
elif k==6:
print('1/1')
elif k==0:
print('0/1')
else:
print(str(k)+'/6')
``` | 3.954 | MatrixStudio/Codeforces-Python-Submissions |
216 | C | Hiring Staff | PROGRAMMING | 1,800 | [
"greedy"
] | null | null | A new Berland businessman Vitaly is going to open a household appliances' store. All he's got to do now is to hire the staff.
The store will work seven days a week, but not around the clock. Every day at least *k* people must work in the store.
Berland has a law that determines the order of working days and non-worki... | The first line contains three integers *n*, *m* and *k* (1<=≤<=*m*<=≤<=*n*<=≤<=1000, *n*<=≠<=1, 1<=≤<=*k*<=≤<=1000). | In the first line print a single integer *z* — the minimum required number of employees.
In the second line print *z* positive integers, separated by spaces: the *i*-th integer *a**i* (1<=≤<=*a**i*<=≤<=104) should represent the number of the day, on which Vitaly should hire the *i*-th employee.
If there are multiple ... | [
"4 3 2\n",
"3 3 1\n"
] | [
"4\n1 1 4 5",
"3\n1 3 5"
] | none | 2,000 | [
{
"input": "4 3 2",
"output": "4\n1 1 4 5"
},
{
"input": "3 3 1",
"output": "3\n1 3 5"
},
{
"input": "5 5 3",
"output": "7\n1 1 1 5 6 6 7"
},
{
"input": "7 6 8",
"output": "16\n1 1 1 1 1 1 1 1 7 7 7 7 7 7 7 8"
},
{
"input": "8 3 2",
"output": "4\n1 1 8 9"
},... | 1,652,879,093 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 92 | 4,505,600 | n,m,k = map(int, input().split())
ans = [1]*k + [n] + [n+1]*(k-1)
if n==m or (k==1 and m==(n-1)):
ans.append(n+m-1)
print(len(ans))
print(*ans) | Title: Hiring Staff
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A new Berland businessman Vitaly is going to open a household appliances' store. All he's got to do now is to hire the staff.
The store will work seven days a week, but not around the clock. Every day at least *k* people ... | ```python
n,m,k = map(int, input().split())
ans = [1]*k + [n] + [n+1]*(k-1)
if n==m or (k==1 and m==(n-1)):
ans.append(n+m-1)
print(len(ans))
print(*ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
735 | D | Taxes | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not equal to *n*, of course). For example, if *n*<==<=6 then Funt has to pay 3 burles, while fo... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·109) — the total year income of mr. Funt. | Print one integer — minimum possible number of burles that mr. Funt has to pay as a tax. | [
"4\n",
"27\n"
] | [
"2\n",
"3\n"
] | none | 1,750 | [
{
"input": "4",
"output": "2"
},
{
"input": "27",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "5",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "2000000000",
"output": "2"
},
{
"input": "26",
"output": ... | 1,544,112,247 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 0 | def aval(a):
if n==1:
return 0
elif n==2:
return 1
else:
for i in range(2,n):
if n%i==0:
return 0
return 1
n1=int(input())
n=n1
t=0
while n1!=0:
#print(n,n1,t)
while aval(n)==0:
n-=1
#print(n,n1,t)
if n... | Title: Taxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not ... | ```python
def aval(a):
if n==1:
return 0
elif n==2:
return 1
else:
for i in range(2,n):
if n%i==0:
return 0
return 1
n1=int(input())
n=n1
t=0
while n1!=0:
#print(n,n1,t)
while aval(n)==0:
n-=1
#print(n,n1,t)... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
992 | A | Nastya and an Array | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second we can add an arbitrary (possibly negative) integer to all elements of the array that are not equal to ze... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=105<=≤<=*a**i*<=≤<=105) — the elements of the array. | Print a single integer — the minimum number of seconds needed to make all elements of the array equal to zero. | [
"5\n1 1 1 1 1\n",
"3\n2 0 -1\n",
"4\n5 -6 -5 1\n"
] | [
"1\n",
"2\n",
"4\n"
] | In the first example you can add - 1 to all non-zero elements in one second and make them equal to zero.
In the second example you can add - 2 on the first second, then the array becomes equal to [0, 0, - 3]. On the second second you can add 3 to the third (the only non-zero) element. | 500 | [
{
"input": "5\n1 1 1 1 1",
"output": "1"
},
{
"input": "3\n2 0 -1",
"output": "2"
},
{
"input": "4\n5 -6 -5 1",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n21794 -79194",
"output": "2"
},
{
"input": "3\n-63526 95085 -5239",
... | 1,619,520,304 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | n=int(input())
li = list(map(int,input().split()))
res = []
for i in li:
if i not in res:
res.append(i)
print (len(res))
| Title: Nastya and an Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second ... | ```python
n=int(input())
li = list(map(int,input().split()))
res = []
for i in li:
if i not in res:
res.append(i)
print (len(res))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
763 | B | Timofey and rectangles | PROGRAMMING | 2,100 | [
"constructive algorithms",
"geometry"
] | null | null | One of Timofey's birthday presents is a colourbook in a shape of an infinite plane. On the plane *n* rectangles with sides parallel to coordinate axes are situated. All sides of the rectangles have odd length. Rectangles cannot intersect, but they can touch each other.
Help Timofey to color his rectangles in 4 differe... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=5·105) — the number of rectangles.
*n* lines follow. The *i*-th of these lines contains four integers *x*1, *y*1, *x*2 and *y*2 (<=-<=109<=≤<=*x*1<=<<=*x*2<=≤<=109, <=-<=109<=≤<=*y*1<=<<=*y*2<=≤<=109), that means that points (*x*1,<=*y*1) and (*x*2,<=*y*2... | Print "NO" in the only line if it is impossible to color the rectangles in 4 different colors in such a way that every two rectangles touching each other by side would have different color.
Otherwise, print "YES" in the first line. Then print *n* lines, in the *i*-th of them print single integer *c**i* (1<=≤<=*c**i*<=... | [
"8\n0 0 5 3\n2 -1 5 0\n-3 -4 2 -1\n-1 -1 2 0\n-3 0 0 5\n5 2 10 3\n7 -3 10 2\n4 -2 7 -1\n"
] | [
"YES\n1\n2\n2\n3\n2\n2\n4\n1\n"
] | none | 750 | [
{
"input": "8\n0 0 5 3\n2 -1 5 0\n-3 -4 2 -1\n-1 -1 2 0\n-3 0 0 5\n5 2 10 3\n7 -3 10 2\n4 -2 7 -1",
"output": "YES\n1\n4\n3\n2\n3\n3\n2\n1"
},
{
"input": "1\n0 0 1 1",
"output": "YES\n1"
},
{
"input": "4\n0 0 1 1\n1 0 2 1\n1 1 2 2\n0 1 1 2",
"output": "YES\n1\n3\n4\n2"
},
{
"... | 1,697,180,134 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 1,044 | 12,288,000 | n = int(input())
print("YES")
for i in range(n):
a, b, c, d = map(int, input().split())
a = abs(a)
b = abs(b)
print((a % 2) * 2 + b % 2 + 1) | Title: Timofey and rectangles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One of Timofey's birthday presents is a colourbook in a shape of an infinite plane. On the plane *n* rectangles with sides parallel to coordinate axes are situated. All sides of the rectangles have odd length. Re... | ```python
n = int(input())
print("YES")
for i in range(n):
a, b, c, d = map(int, input().split())
a = abs(a)
b = abs(b)
print((a % 2) * 2 + b % 2 + 1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,687,274,457 | 2,147,483,647 | Python 3 | OK | TESTS | 65 | 46 | 0 | number_of_digits, divisor = map(int, input().split())
inferior_limit = 10 ** (number_of_digits - 1)
upper_limit = 10 ** number_of_digits - 1
rest_of_division_between_first_number_and_divisor = inferior_limit % divisor
number_with_digits_and_divisible = inferior_limit + (divisor - rest_of_division_between_first_numb... | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
number_of_digits, divisor = map(int, input().split())
inferior_limit = 10 ** (number_of_digits - 1)
upper_limit = 10 ** number_of_digits - 1
rest_of_division_between_first_number_and_divisor = inferior_limit % divisor
number_with_digits_and_divisible = inferior_limit + (divisor - rest_of_division_between_... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
281 | A | Word Capitalization | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged. | A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103. | Output the given word after capitalization. | [
"ApPLe\n",
"konjac\n"
] | [
"ApPLe\n",
"Konjac\n"
] | none | 500 | [
{
"input": "ApPLe",
"output": "ApPLe"
},
{
"input": "konjac",
"output": "Konjac"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "A"
},
{
"input": "z",
"output": "Z"
},
{
"input": "ABACABA",
"output": "ABACABA"
},
{
"input": "... | 1,696,368,211 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | n = input()
a = n[0].upper()
for i in range(1,len(n)):
a += n[i]
print(a) | Title: Word Capitalization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input... | ```python
n = input()
a = n[0].upper()
for i in range(1,len(n)):
a += n[i]
print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
546 | A | Soldier and Bananas | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He has *n* dollars. How many dollars does he have to borrow from his friend soldier to buy *w* bananas? | The first line contains three positive integers *k*,<=*n*,<=*w* (1<=<=≤<=<=*k*,<=*w*<=<=≤<=<=1000, 0<=≤<=*n*<=≤<=109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants. | Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn't have to borrow money, output 0. | [
"3 17 4\n"
] | [
"13"
] | none | 500 | [
{
"input": "3 17 4",
"output": "13"
},
{
"input": "1 2 1",
"output": "0"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 5 6",
"output": "16"
},
{
"input": "1 1000000000 1",
"output": "0"
},
{
"input": "1000 0 1000",
"output": "500500000"
}... | 1,694,315,141 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | a,b,c=map(int,input().split())
w=a*(c+1)*c/2
m=int(w-b)
print(m) | Title: Soldier and Bananas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He h... | ```python
a,b,c=map(int,input().split())
w=a*(c+1)*c/2
m=int(w-b)
print(m)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
127 | A | Wasted Time | PROGRAMMING | 900 | [
"geometry"
] | null | null | Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count the time he has wasted signing papers.
Mr. Scrooge's signature can be represented as a polyline ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). Each of the following *n* lines contains the coordinates of the polyline's endpoints. The *i*-th one contains coordinates of the point *A**i* — integers *x**i* and *y**i*, separated by a space.
All points *A**i* are different. Th... | Print one real number — the total time Scrooges wastes on signing the papers in seconds. The absolute or relative error should not exceed 10<=-<=6. | [
"2 1\n0 0\n10 0\n",
"5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0\n",
"6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0\n"
] | [
"0.200000000",
"6.032163204",
"3.000000000"
] | none | 500 | [
{
"input": "2 1\n0 0\n10 0",
"output": "0.200000000"
},
{
"input": "5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0",
"output": "6.032163204"
},
{
"input": "6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0",
"output": "3.000000000"
},
{
"input": "10 95\n-20 -5\n2 -8\n14 13\n10 3\n17 11\n13 -12\n-6 11\n1... | 1,669,199,326 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | import math
k, n = input().split()
k, n = map(int, (k, n))
coor = []
for i in range(k):
coor.append(tuple(input().split()))
ans = 0
for i in range(k - 1):
x = int(coor[i][0]) - int(coor[i + 1][0])
y = int(coor[i][1]) - int(coor[i + 1][1])
ans += math.sqrt(x*x + y*y)
print((ans * n)/50)
... | Title: Wasted Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count ... | ```python
import math
k, n = input().split()
k, n = map(int, (k, n))
coor = []
for i in range(k):
coor.append(tuple(input().split()))
ans = 0
for i in range(k - 1):
x = int(coor[i][0]) - int(coor[i + 1][0])
y = int(coor[i][1]) - int(coor[i + 1][1])
ans += math.sqrt(x*x + y*y)
print((ans * n)/50)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,696,187,874 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 31 | 0 | w = str(input())
if w.isupper() or (w[0].islower() and w[1:].isupper()):q = w.swapcase();print(q)
else:print(w)
| Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
w = str(input())
if w.isupper() or (w[0].islower() and w[1:].isupper()):q = w.swapcase();print(q)
else:print(w)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
898 | A | Rounding | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5 Vasya can round it to 0 or to 10. Both ways are correct.
For given *n* find out to which int... | The first line contains single integer *n* (0<=≤<=*n*<=≤<=109) — number that Vasya has. | Print result of rounding *n*. Pay attention that in some cases answer isn't unique. In that case print any correct answer. | [
"5\n",
"113\n",
"1000000000\n",
"5432359\n"
] | [
"0\n",
"110\n",
"1000000000\n",
"5432360\n"
] | In the first example *n* = 5. Nearest integers, that ends up with zero are 0 and 10. Any of these answers is correct, so you can print 0 or 10. | 500 | [
{
"input": "5",
"output": "0"
},
{
"input": "113",
"output": "110"
},
{
"input": "1000000000",
"output": "1000000000"
},
{
"input": "5432359",
"output": "5432360"
},
{
"input": "999999994",
"output": "999999990"
},
{
"input": "10",
"output": "10"
... | 1,655,758,268 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n=int(input())
r=n%10
if n%10==0:
print (n)
if r>5:
print (n+(10-r))
if r<5:
print (n-r)
if r==5:
print (n+(10-r)) or (n-r) | Title: Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5... | ```python
n=int(input())
r=n%10
if n%10==0:
print (n)
if r>5:
print (n+(10-r))
if r<5:
print (n-r)
if r==5:
print (n+(10-r)) or (n-r)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
909 | A | Generate Login | PROGRAMMING | 1,000 | [
"brute force",
"greedy",
"sortings"
] | null | null | The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the full name. Typically there are multiple possible logins for each person.
You are given the first and ... | The input consists of a single line containing two space-separated strings: the first and the last names. Each character of each string is a lowercase English letter. The length of each string is between 1 and 10, inclusive. | Output a single string — alphabetically earliest possible login formed from these names. The output should be given in lowercase as well. | [
"harry potter\n",
"tom riddle\n"
] | [
"hap\n",
"tomr\n"
] | none | 500 | [
{
"input": "harry potter",
"output": "hap"
},
{
"input": "tom riddle",
"output": "tomr"
},
{
"input": "a qdpinbmcrf",
"output": "aq"
},
{
"input": "wixjzniiub ssdfodfgap",
"output": "wis"
},
{
"input": "z z",
"output": "zz"
},
{
"input": "ertuyivhfg v"... | 1,514,397,005 | 4,505 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 46 | 5,529,600 | inp=input()
n=inp.split()
first=list(n[0])
last=list(n[1])
p1=[ord(x) for x in first]
p2=[ord(x) for x in last]
minindex1=min(p1)
minindex2=ord(last[0])
str1 = ''.join(chr(e) for e in p1[:p1.index(minindex1)+1])
if minindex2<minindex1:
print(n[0]+last[0])
else:
print(str1+last[0])
| Title: Generate Login
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the fu... | ```python
inp=input()
n=inp.split()
first=list(n[0])
last=list(n[1])
p1=[ord(x) for x in first]
p2=[ord(x) for x in last]
minindex1=min(p1)
minindex2=ord(last[0])
str1 = ''.join(chr(e) for e in p1[:p1.index(minindex1)+1])
if minindex2<minindex1:
print(n[0]+last[0])
else:
print(str1+last[0])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
618 | B | Guess the Permutation | PROGRAMMING | 1,100 | [
"constructive algorithms"
] | null | null | Bob has a permutation of integers from 1 to *n*. Denote this permutation as *p*. The *i*-th element of *p* will be denoted as *p**i*. For all pairs of distinct integers *i*,<=*j* between 1 and *n*, he wrote the number *a**i*,<=*j*<==<=*min*(*p**i*,<=*p**j*). He writes *a**i*,<=*i*<==<=0 for all integer *i* from 1 to *n... | The first line of the input will contain a single integer *n* (2<=≤<=*n*<=≤<=50).
The next *n* lines will contain the values of *a**i*,<=*j*. The *j*-th number on the *i*-th line will represent *a**i*,<=*j*. The *i*-th number on the *i*-th line will be 0. It's guaranteed that *a**i*,<=*j*<==<=*a**j*,<=*i* and there is... | Print *n* space separated integers, which represents a permutation that could have generated these values. If there are multiple possible solutions, print any of them. | [
"2\n0 1\n1 0\n",
"5\n0 2 2 1 2\n2 0 4 1 3\n2 4 0 1 3\n1 1 1 0 1\n2 3 3 1 0\n"
] | [
"2 1\n",
"2 5 4 1 3\n"
] | In the first case, the answer can be {1, 2} or {2, 1}.
In the second case, another possible answer is {2, 4, 5, 1, 3}. | 1,000 | [
{
"input": "2\n0 1\n1 0",
"output": "2 1"
},
{
"input": "5\n0 2 2 1 2\n2 0 4 1 3\n2 4 0 1 3\n1 1 1 0 1\n2 3 3 1 0",
"output": "2 5 4 1 3"
},
{
"input": "10\n0 1 5 2 5 3 4 5 5 5\n1 0 1 1 1 1 1 1 1 1\n5 1 0 2 6 3 4 6 6 6\n2 1 2 0 2 2 2 2 2 2\n5 1 6 2 0 3 4 8 8 7\n3 1 3 2 3 0 3 3 3 3\n4 1 4... | 1,699,096,575 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n=int(input())
square=[]
p=[]
for i in range(n):
a=[int(x) for x in input().split()]
square.append(a)
for i in range(n):
lst=square[i]
for a in range(n):
if lst.count(a)==n-a:
p.append(a)
for k in range(n):
if p[k]==n-1:
p[k]=n
break
pri... | Title: Guess the Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bob has a permutation of integers from 1 to *n*. Denote this permutation as *p*. The *i*-th element of *p* will be denoted as *p**i*. For all pairs of distinct integers *i*,<=*j* between 1 and *n*, he wrote the nu... | ```python
n=int(input())
square=[]
p=[]
for i in range(n):
a=[int(x) for x in input().split()]
square.append(a)
for i in range(n):
lst=square[i]
for a in range(n):
if lst.count(a)==n-a:
p.append(a)
for k in range(n):
if p[k]==n-1:
p[k]=n
br... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is close... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the co... | Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days. | [
"4\n1 3 2 0\n",
"7\n1 3 3 2 1 2 3\n",
"2\n2 2\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya ca... | 0 | [
{
"input": "4\n1 3 2 0",
"output": "2"
},
{
"input": "7\n1 3 3 2 1 2 3",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "10\n0 0 1 1 0 0 0 0 1 0",
"output": "8"
},
{
"input": "100\n3 2 3 3 3 2 3 1 ... | 1,509,117,023 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 87 | 1,000 | 0 | n = int(input())
days = input().strip().split()
def assignJob(days, i, lastJob):
sleepyDays = 0
if i == len(days):
return 0
job = days[i]
if job == '0':
sleepyDays = 1 + assignJob(days, i+1, "s")
elif job == '1':
if lastJob == 'c':
sleepyDays = 1 + as... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet... | ```python
n = int(input())
days = input().strip().split()
def assignJob(days, i, lastJob):
sleepyDays = 0
if i == len(days):
return 0
job = days[i]
if job == '0':
sleepyDays = 1 + assignJob(days, i+1, "s")
elif job == '1':
if lastJob == 'c':
sleepyDay... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
328 | A | IQ Test | PROGRAMMING | 1,800 | [
"implementation"
] | null | null | Petya is preparing for IQ test and he has noticed that there many problems like: you are given a sequence, find the next number. Now Petya can solve only problems with arithmetic or geometric progressions.
Arithmetic progression is a sequence *a*1, *a*1<=+<=*d*, *a*1<=+<=2*d*, ..., *a*1<=+<=(*n*<=-<=1)*d*, where *a*1 ... | The first line contains exactly four integer numbers between 1 and 1000, inclusively. | Print the required number. If the given sequence is arithmetic progression, print the next progression element. Similarly, if the given sequence is geometric progression, print the next progression element.
Print 42 if the given sequence is not an arithmetic or geometric progression. | [
"836 624 412 200\n",
"1 334 667 1000\n"
] | [
"-12\n",
"1333\n"
] | This problem contains very weak pretests! | 500 | [
{
"input": "836 624 412 200",
"output": "-12"
},
{
"input": "1 334 667 1000",
"output": "1333"
},
{
"input": "501 451 400 350",
"output": "42"
},
{
"input": "836 624 412 200",
"output": "-12"
},
{
"input": "1 334 667 1000",
"output": "1333"
},
{
"input... | 1,681,067,537 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | x = list(map(float,input().split()))
geo = 0
if x[0]<x[1]:
geo+=1
d = x[0]-x[1]
else:
d = x[1]-x[0]
if geo==1:
ans = int(x[0]-4*d)
print(int(ans) if ans==int(ans) else 42)
else:
ans = int(x[0]+4*d)
print(int(ans) if ans==int(ans) else 42) | Title: IQ Test
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya is preparing for IQ test and he has noticed that there many problems like: you are given a sequence, find the next number. Now Petya can solve only problems with arithmetic or geometric progressions.
Arithmetic progressi... | ```python
x = list(map(float,input().split()))
geo = 0
if x[0]<x[1]:
geo+=1
d = x[0]-x[1]
else:
d = x[1]-x[0]
if geo==1:
ans = int(x[0]-4*d)
print(int(ans) if ans==int(ans) else 42)
else:
ans = int(x[0]+4*d)
print(int(ans) if ans==int(ans) else 42)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,623,471,603 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 9 | 186 | 0 | import sys
#from math import gcd
#from bisect import bisect_left, bisect_right
read_line = lambda: sys.stdin.readline().strip()
read_intmap = lambda: map(int, read_line().split())
def testCase():
n = int(input())
players = dict()
for ind in range(1, n + 1):
name, score = read_line().split()
... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
import sys
#from math import gcd
#from bisect import bisect_left, bisect_right
read_line = lambda: sys.stdin.readline().strip()
read_intmap = lambda: map(int, read_line().split())
def testCase():
n = int(input())
players = dict()
for ind in range(1, n + 1):
name, score = read_line().... | 0 | MatrixStudio/Codeforces-Python-Submissions |
510 | A | Fox And Snake | PROGRAMMING | 800 | [
"implementation"
] | null | null | Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*-th cell of *r*-th row as (*r*,<=*c*). The tail of the snake is located at (1,<=1), then it's body ... | The only line contains two integers: *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=50).
*n* is an odd number. | Output *n* lines. Each line should contain a string consisting of *m* characters. Do not output spaces. | [
"3 3\n",
"3 4\n",
"5 3\n",
"9 9\n"
] | [
"###\n..#\n###\n",
"####\n...#\n####\n",
"###\n..#\n###\n#..\n###\n",
"#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#########\n"
] | none | 500 | [
{
"input": "3 3",
"output": "###\n..#\n###"
},
{
"input": "3 4",
"output": "####\n...#\n####"
},
{
"input": "5 3",
"output": "###\n..#\n###\n#..\n###"
},
{
"input": "9 9",
"output": "#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#... | 1,683,485,487 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | n = int(input())
m = int(input())
flag = 1
for i in range(n):
if i % 2 != 0:
x = '#' * m
else:
if flag == 1:
x = '.' * (m - 1) + '#'
flag = 0
else:
x = '#' + '.' * (m - 1)
flag = 1
print(x)
| Title: Fox And Snake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*... | ```python
n = int(input())
m = int(input())
flag = 1
for i in range(n):
if i % 2 != 0:
x = '#' * m
else:
if flag == 1:
x = '.' * (m - 1) + '#'
flag = 0
else:
x = '#' + '.' * (m - 1)
flag = 1
print(x)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
20 | C | Dijkstra? | PROGRAMMING | 1,900 | [
"graphs",
"shortest paths"
] | C. Dijkstra? | 1 | 64 | You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*. | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105), where *n* is the number of vertices and *m* is the number of edges. Following *m* lines contain one edge each in form *a**i*, *b**i* and *w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=1<=≤<=*w**i*<=≤<=106), where *a**i*,<=*b**i* are edge... | Write the only integer -1 in case of no path. Write the shortest path in opposite case. If there are many solutions, print any of them. | [
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n",
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n"
] | [
"1 4 3 5 ",
"1 4 3 5 "
] | none | 1,500 | [
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "2 1\n1 2 1",
"output": "1 2 "
},
{
"input": "3 1\n1 2 1",
"output": "-1"
},
{
"input... | 1,675,105,156 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 342 | 30,310,400 | import heapq
import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
def dijkstra(s):
dist = [inf] * (n + 1)
dist[s] = 0
visit = [0] * (n + 1)
parent = [-1] * (n + 1)
p = []
heapq.heappush(p, (dist[s], s))
while p:
d, u = heapq.heappop(p)
... | Title: Dijkstra?
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*.
Input Specification:
The first line contains two integers *n* a... | ```python
import heapq
import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
def dijkstra(s):
dist = [inf] * (n + 1)
dist[s] = 0
visit = [0] * (n + 1)
parent = [-1] * (n + 1)
p = []
heapq.heappush(p, (dist[s], s))
while p:
d, u = heapq.heappop(p... | 3.60317 | MatrixStudio/Codeforces-Python-Submissions |
171 | B | Star | PROGRAMMING | 1,300 | [
"*special",
"combinatorics"
] | null | null | The input contains a single integer *a* (1<=≤<=*a*<=≤<=18257). | Print a single integer *output* (1<=≤<=*output*<=≤<=2·109). | [
"2\n"
] | [
"13"
] | none | 0 | [
{
"input": "2",
"output": "13"
},
{
"input": "1",
"output": "1"
},
{
"input": "3",
"output": "37"
},
{
"input": "4",
"output": "73"
},
{
"input": "5",
"output": "121"
},
{
"input": "6",
"output": "181"
},
{
"input": "7",
"output": "253"... | 1,616,783,696 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 216 | 0 | n = int(input())
print(6*n*(n-1) + 1)
| Title: Star
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Input Specification:
The input contains a single integer *a* (1<=≤<=*a*<=≤<=18257).
Output Specification:
Print a single integer *output* (1<=≤<=*output*<=≤<=2·109).
Demo Input:
['2\n']
Demo Output:
['13']
Note:
none | ```python
n = int(input())
print(6*n*(n-1) + 1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | ||
485 | B | Valuable Resources | PROGRAMMING | 1,300 | [
"brute force",
"greedy"
] | null | null | Many computer strategy games require building cities, recruiting army, conquering tribes, collecting resources. Sometimes it leads to interesting problems.
Let's suppose that your task is to build a square city. The world map uses the Cartesian coordinates. The sides of the city should be parallel to coordinate axes.... | The first line of the input contains number *n* — the number of mines on the map (2<=≤<=*n*<=≤<=1000). Each of the next *n* lines contains a pair of integers *x**i* and *y**i* — the coordinates of the corresponding mine (<=-<=109<=≤<=*x**i*,<=*y**i*<=≤<=109). All points are pairwise distinct. | Print the minimum area of the city that can cover all the mines with valuable resources. | [
"2\n0 0\n2 2\n",
"2\n0 0\n0 3\n"
] | [
"4\n",
"9\n"
] | none | 500 | [
{
"input": "2\n0 0\n2 2",
"output": "4"
},
{
"input": "2\n0 0\n0 3",
"output": "9"
},
{
"input": "2\n0 1\n1 0",
"output": "1"
},
{
"input": "3\n2 2\n1 1\n3 3",
"output": "4"
},
{
"input": "3\n3 1\n1 3\n2 2",
"output": "4"
},
{
"input": "3\n0 1\n1 0\n2 ... | 1,415,844,013 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 62 | 0 | a = int(input(""))
XlistOfCoordinates = []
YlistOfCoordinates = []
for value in range(a):
y = input("").split(" ")
XlistOfCoordinates.append(int(y[0]))
YlistOfCoordinates.append(int(y[1]))
print(max(max(XlistOfCoordinates)-min(XlistOfCoordinates),max(YlistOfCoordinates)-min(YlistOfCoordinates))**2)
| Title: Valuable Resources
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Many computer strategy games require building cities, recruiting army, conquering tribes, collecting resources. Sometimes it leads to interesting problems.
Let's suppose that your task is to build a square city. Th... | ```python
a = int(input(""))
XlistOfCoordinates = []
YlistOfCoordinates = []
for value in range(a):
y = input("").split(" ")
XlistOfCoordinates.append(int(y[0]))
YlistOfCoordinates.append(int(y[1]))
print(max(max(XlistOfCoordinates)-min(XlistOfCoordinates),max(YlistOfCoordinates)-min(YlistOfCoordinat... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
474 | B | Worms | PROGRAMMING | 1,200 | [
"binary search",
"implementation"
] | null | null | It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers: worms in first pile are labeled with numbers 1 to *a*1, worms in second pile are labeled w... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), the number of piles.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103, *a*1<=+<=*a*2<=+<=...<=+<=*a**n*<=≤<=106), where *a**i* is the number of worms in the *i*-th pile.
The third line contains single integer *m* (... | Print *m* lines to the standard output. The *i*-th line should contain an integer, representing the number of the pile where the worm labeled with the number *q**i* is. | [
"5\n2 7 3 4 9\n3\n1 25 11\n"
] | [
"1\n5\n3\n"
] | For the sample input:
- The worms with labels from [1, 2] are in the first pile. - The worms with labels from [3, 9] are in the second pile. - The worms with labels from [10, 12] are in the third pile. - The worms with labels from [13, 16] are in the fourth pile. - The worms with labels from [17, 25] are in the f... | 1,000 | [
{
"input": "5\n2 7 3 4 9\n3\n1 25 11",
"output": "1\n5\n3"
}
] | 1,675,188,920 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 8,908,800 | n = int(input())
a = input().split(maxsplit=n)
b = list(map(int, a))
m = int(input())
a = input().split(maxsplit=m)
q = list(map(int, a))
sum = b[0]
for i in range(1, n):
sum = sum + b[i]
b[i] = sum
def binary_search(list1, n):
low = 0
high = len(list1) - 1
i = 0
while low <= h... | Title: Worms
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers:... | ```python
n = int(input())
a = input().split(maxsplit=n)
b = list(map(int, a))
m = int(input())
a = input().split(maxsplit=m)
q = list(map(int, a))
sum = b[0]
for i in range(1, n):
sum = sum + b[i]
b[i] = sum
def binary_search(list1, n):
low = 0
high = len(list1) - 1
i = 0
whil... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
242 | B | Big Segment | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all oth... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of segments. Next *n* lines contain the descriptions of the segments. The *i*-th line contains two space-separated integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109) — the borders of the *i*-th segment.
It is guaranteed that no two segments c... | Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input. | [
"3\n1 1\n2 2\n3 3\n",
"6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10\n"
] | [
"-1\n",
"3\n"
] | none | 1,000 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "-1"
},
{
"input": "6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10",
"output": "3"
},
{
"input": "4\n1 5\n2 2\n2 4\n2 5",
"output": "1"
},
{
"input": "5\n3 3\n1 3\n2 2\n2 3\n1 2",
"output": "2"
},
{
"input": "7\n7 7\n8 8\n3 7\n1 6\n1 ... | 1,638,592,062 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 216 | 0 | # condition = a ≤ c ≤ d ≤ b
# [a, b]
# [c, d]
n = int(input())
if n == 1:
x,y = map(int,input().split())
print(1)
else:
forx = []
fory = []
f= False
count = 1
for i in range(n):
x,y= map(int,input().split())
forx.append(x)
fory.append(y)
count =... | Title: Big Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments ... | ```python
# condition = a ≤ c ≤ d ≤ b
# [a, b]
# [c, d]
n = int(input())
if n == 1:
x,y = map(int,input().split())
print(1)
else:
forx = []
fory = []
f= False
count = 1
for i in range(n):
x,y= map(int,input().split())
forx.append(x)
fory.append(y)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
595 | A | Vitaly and Night | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vitaly sees a building of *n* floors and 2·*m* windows on each floor. On each floor there are *m* flats num... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of floors in the house and the number of flats on each floor respectively.
Next *n* lines describe the floors from top to bottom and contain 2·*m* characters each. If the *i*-th window of the given floor has lights on,... | Print a single integer — the number of flats that have lights on in at least one window, that is, the flats where, according to Vitaly, people aren't sleeping. | [
"2 2\n0 0 0 1\n1 0 1 1\n",
"1 3\n1 1 0 1 0 0\n"
] | [
"3\n",
"2\n"
] | In the first test case the house has two floors, two flats on each floor. That is, in total there are 4 flats. The light isn't on only on the second floor in the left flat. That is, in both rooms of the flat the light is off.
In the second test case the house has one floor and the first floor has three flats. The ligh... | 500 | [
{
"input": "2 2\n0 0 0 1\n1 0 1 1",
"output": "3"
},
{
"input": "1 3\n1 1 0 1 0 0",
"output": "2"
},
{
"input": "3 3\n1 1 1 1 1 1\n1 1 0 1 1 0\n1 0 0 0 1 1",
"output": "8"
},
{
"input": "1 5\n1 0 1 1 1 0 1 1 1 1",
"output": "5"
},
{
"input": "1 100\n1 1 1 1 1 1 1 ... | 1,549,900,476 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 124 | 0 | a=lambda:map(int,input().split())
n,m=a()
s=0
for __ in range(n):
l=list(a())
s+=sum([l[i*2]+l[i*2+1]>0 for i in range(m)])
#s+=1
print(s) | Title: Vitaly and Night
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vital... | ```python
a=lambda:map(int,input().split())
n,m=a()
s=0
for __ in range(n):
l=list(a())
s+=sum([l[i*2]+l[i*2+1]>0 for i in range(m)])
#s+=1
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
611 | A | New Year and Days | PROGRAMMING | 900 | [
"implementation"
] | null | null | Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming year 2016.
Limak wants to prove how responsible a bear he is. He is going to regularly save candies for ... | The only line of the input is in one of the following two formats:
- "*x* of week" where *x* (1<=≤<=*x*<=≤<=7) denotes the day of the week. The 1-st day is Monday and the 7-th one is Sunday. - "*x* of month" where *x* (1<=≤<=*x*<=≤<=31) denotes the day of the month. | Print one integer — the number of candies Limak will save in the year 2016. | [
"4 of week\n",
"30 of month\n"
] | [
"52\n",
"11\n"
] | Polar bears use the Gregorian calendar. It is the most common calendar and you likely use it too. You can read about it on Wikipedia if you want to – [https://en.wikipedia.org/wiki/Gregorian_calendar](https://en.wikipedia.org/wiki/Gregorian_calendar). The week starts with Monday.
In the first sample Limak wants to sav... | 500 | [
{
"input": "4 of week",
"output": "52"
},
{
"input": "30 of month",
"output": "11"
},
{
"input": "17 of month",
"output": "12"
},
{
"input": "31 of month",
"output": "7"
},
{
"input": "6 of week",
"output": "53"
},
{
"input": "1 of week",
"output":... | 1,678,049,707 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | s = input()
if len(s) == 9:
if int(s[0]) == 4:
print(52)
else:
print(53)
else:
s = s.split()
if int(s[0]) < 30:
print(12)
elif int(s[0]) == 30:
print(11)
else:
print(7)
| Title: New Year and Days
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming ye... | ```python
s = input()
if len(s) == 9:
if int(s[0]) == 4:
print(52)
else:
print(53)
else:
s = s.split()
if int(s[0]) < 30:
print(12)
elif int(s[0]) == 30:
print(11)
else:
print(7)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
733 | A | Grasshopper And the String | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of ... | The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100. | Print single integer *a* — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels. | [
"ABABBBACFEYUKOTT\n",
"AAA\n"
] | [
"4",
"1"
] | none | 500 | [
{
"input": "ABABBBACFEYUKOTT",
"output": "4"
},
{
"input": "AAA",
"output": "1"
},
{
"input": "A",
"output": "1"
},
{
"input": "B",
"output": "2"
},
{
"input": "AEYUIOAEIYAEOUIYOEIUYEAOIUEOEAYOEIUYAEOUIYEOIKLMJNHGTRWSDZXCVBNMHGFDSXVWRTPPPLKMNBXIUOIUOIUOIUOOIU",
... | 1,607,838,753 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 0 | s=input().lower()
m=0
count=0
for c in s:
if c in ["a","e","i","o","u","y"]:
m=max(m,count)
count=0
else:
count+=1
print(m+1) | Title: Grasshopper And the String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far en... | ```python
s=input().lower()
m=0
count=0
for c in s:
if c in ["a","e","i","o","u","y"]:
m=max(m,count)
count=0
else:
count+=1
print(m+1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
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