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values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
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value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
899 | C | Dividing the numbers | PROGRAMMING | 1,300 | [
"constructive algorithms",
"graphs",
"math"
] | null | null | Petya has *n* integers: 1,<=2,<=3,<=...,<=*n*. He wants to split these integers in two non-empty groups in such a way that the absolute difference of sums of integers in each group is as small as possible.
Help Petya to split the integers. Each of *n* integers should be exactly in one group. | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=60<=000) — the number of integers Petya has. | Print the smallest possible absolute difference in the first line.
In the second line print the size of the first group, followed by the integers in that group. You can print these integers in arbitrary order. If there are multiple answers, print any of them. | [
"4\n",
"2\n"
] | [
"0\n2 1 4 \n",
"1\n1 1 \n"
] | In the first example you have to put integers 1 and 4 in the first group, and 2 and 3 in the second. This way the sum in each group is 5, and the absolute difference is 0.
In the second example there are only two integers, and since both groups should be non-empty, you have to put one integer in the first group and on... | 1,500 | [
{
"input": "4",
"output": "0\n2 1 4 "
},
{
"input": "2",
"output": "1\n1 1 "
},
{
"input": "3",
"output": "0\n1\n3 "
},
{
"input": "5",
"output": "1\n3\n1 2 5 "
},
{
"input": "59998",
"output": "1\n29999 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 4... | 1,672,526,056 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | # Function to calculate sum of first n numbers.
def calculate_sum(n):
return (n * (n + 1)) // 2
# Taking input
n = int(input())
sum_n = calculate_sum(n)
# if n is even and n%4 != 0 then first group will
# have one number less if numbers are distributed
# equally.
if(n % 2 == 0 and n % 4 != 0):
... | Title: Dividing the numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya has *n* integers: 1,<=2,<=3,<=...,<=*n*. He wants to split these integers in two non-empty groups in such a way that the absolute difference of sums of integers in each group is as small as possible.
Help P... | ```python
# Function to calculate sum of first n numbers.
def calculate_sum(n):
return (n * (n + 1)) // 2
# Taking input
n = int(input())
sum_n = calculate_sum(n)
# if n is even and n%4 != 0 then first group will
# have one number less if numbers are distributed
# equally.
if(n % 2 == 0 and n % 4 !... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
313 | B | Ilya and Queries | PROGRAMMING | 1,100 | [
"dp",
"implementation"
] | null | null | Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting only of characters "." and "#" and *m* queries. Each query is described by a pair of integers *l**i*,<... | The first line contains string *s* of length *n* (2<=≤<=*n*<=≤<=105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. Each of the next *m* lines contains the description of the corresponding query. The *i*-t... | Print *m* integers — the answers to the queries in the order in which they are given in the input. | [
"......\n4\n3 4\n2 3\n1 6\n2 6\n",
"#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4\n"
] | [
"1\n1\n5\n4\n",
"1\n1\n2\n2\n0\n"
] | none | 1,000 | [
{
"input": "......\n4\n3 4\n2 3\n1 6\n2 6",
"output": "1\n1\n5\n4"
},
{
"input": "#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4",
"output": "1\n1\n2\n2\n0"
},
{
"input": ".#...#..\n6\n1 5\n2 3\n6 7\n2 4\n2 5\n1 3",
"output": "2\n0\n0\n1\n2\n0"
},
{
"input": "#.#.#..\n5\n3 4\n4 5\n5 7\n5... | 1,696,311,633 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 2,000 | 102,400 | s = str(input())
m = int(input())
for i in range(m):
l,r = map(int,input().split())
l2 = s[l-1:r]
c = 0
for j in range(len(l2)-1):
if l2[j] == l2[j+1]:
c += 1
print(c) | Title: Ilya and Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting ... | ```python
s = str(input())
m = int(input())
for i in range(m):
l,r = map(int,input().split())
l2 = s[l-1:r]
c = 0
for j in range(len(l2)-1):
if l2[j] == l2[j+1]:
c += 1
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
609 | B | The Best Gift | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation"
] | null | null | Emily's birthday is next week and Jack has decided to buy a present for her. He knows she loves books so he goes to the local bookshop, where there are *n* books on sale from one of *m* genres.
In the bookshop, Jack decides to buy two books of different genres.
Based on the genre of books on sale in the shop, find th... | The first line contains two positive integers *n* and *m* (2<=≤<=*n*<=≤<=2·105,<=2<=≤<=*m*<=≤<=10) — the number of books in the bookstore and the number of genres.
The second line contains a sequence *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (1<=≤<=*a**i*<=≤<=*m*) equals the genre of the *i*-th book.
It is guaranteed ... | Print the only integer — the number of ways in which Jack can choose books.
It is guaranteed that the answer doesn't exceed the value 2·109. | [
"4 3\n2 1 3 1\n",
"7 4\n4 2 3 1 2 4 3\n"
] | [
"5\n",
"18\n"
] | The answer to the first test sample equals 5 as Sasha can choose:
1. the first and second books, 1. the first and third books, 1. the first and fourth books, 1. the second and third books, 1. the third and fourth books. | 0 | [
{
"input": "4 3\n2 1 3 1",
"output": "5"
},
{
"input": "7 4\n4 2 3 1 2 4 3",
"output": "18"
},
{
"input": "2 2\n1 2",
"output": "1"
},
{
"input": "3 2\n1 2 2",
"output": "2"
},
{
"input": "10 10\n1 2 3 4 5 6 7 8 9 10",
"output": "45"
},
{
"input": "9 2... | 1,511,422,756 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 140 | 3,891,200 | n,m=[int(x) for x in input().split()]
s=[int(x) for x in input().split()]
#print (choose_book(s))
def fast_choose_book(list_of_books,m):
counts={}
num_options=0
for book in list_of_books:
if book in counts:
counts[book]+=1
else:
counts[book]=1
for i i... | Title: The Best Gift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Emily's birthday is next week and Jack has decided to buy a present for her. He knows she loves books so he goes to the local bookshop, where there are *n* books on sale from one of *m* genres.
In the bookshop, Jack deci... | ```python
n,m=[int(x) for x in input().split()]
s=[int(x) for x in input().split()]
#print (choose_book(s))
def fast_choose_book(list_of_books,m):
counts={}
num_options=0
for book in list_of_books:
if book in counts:
counts[book]+=1
else:
counts[book]=1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
501 | A | Contest | PROGRAMMING | 900 | [
"implementation"
] | null | null | Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved the problem that costs *b* points. Besides, Misha submitted the problem *c* minutes after the ... | The first line contains four integers *a*, *b*, *c*, *d* (250<=≤<=*a*,<=*b*<=≤<=3500, 0<=≤<=*c*,<=*d*<=≤<=180).
It is guaranteed that numbers *a* and *b* are divisible by 250 (just like on any real Codeforces round). | Output on a single line:
"Misha" (without the quotes), if Misha got more points than Vasya.
"Vasya" (without the quotes), if Vasya got more points than Misha.
"Tie" (without the quotes), if both of them got the same number of points. | [
"500 1000 20 30\n",
"1000 1000 1 1\n",
"1500 1000 176 177\n"
] | [
"Vasya\n",
"Tie\n",
"Misha\n"
] | none | 500 | [
{
"input": "500 1000 20 30",
"output": "Vasya"
},
{
"input": "1000 1000 1 1",
"output": "Tie"
},
{
"input": "1500 1000 176 177",
"output": "Misha"
},
{
"input": "1500 1000 74 177",
"output": "Misha"
},
{
"input": "750 2500 175 178",
"output": "Vasya"
},
{
... | 1,668,015,915 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 46 | 0 | # Wadea #
m1,v1,tm1,tv1 = input().split()
m1,v1,tm1,tv1 = int(m1),int(v1),int(tm1),int(tv1)
m = int(m1-((m1/250)*tm1))
v = int(v1-((v1/250)*tv1))
if m > v:
print("Misha")
elif m < v:
print("Vasya")
else:
print("Tie")
| Title: Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved t... | ```python
# Wadea #
m1,v1,tm1,tv1 = input().split()
m1,v1,tm1,tv1 = int(m1),int(v1),int(tm1),int(tv1)
m = int(m1-((m1/250)*tm1))
v = int(v1-((v1/250)*tv1))
if m > v:
print("Misha")
elif m < v:
print("Vasya")
else:
print("Tie")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
459 | B | Pashmak and Flowers | PROGRAMMING | 1,300 | [
"combinatorics",
"implementation",
"sortings"
] | null | null | Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have the two most beautiful flowers necessarily. She wants to have those pairs of flowers that their beauty diff... | The first line of the input contains *n* (2<=≤<=*n*<=≤<=2·105). In the next line there are *n* space-separated integers *b*1, *b*2, ..., *b**n* (1<=≤<=*b**i*<=≤<=109). | The only line of output should contain two integers. The maximum beauty difference and the number of ways this may happen, respectively. | [
"2\n1 2\n",
"3\n1 4 5\n",
"5\n3 1 2 3 1\n"
] | [
"1 1",
"4 1",
"2 4"
] | In the third sample the maximum beauty difference is 2 and there are 4 ways to do this:
1. choosing the first and the second flowers; 1. choosing the first and the fifth flowers; 1. choosing the fourth and the second flowers; 1. choosing the fourth and the fifth flowers. | 500 | [
{
"input": "2\n1 2",
"output": "1 1"
},
{
"input": "3\n1 4 5",
"output": "4 1"
},
{
"input": "5\n3 1 2 3 1",
"output": "2 4"
},
{
"input": "2\n1 1",
"output": "0 1"
},
{
"input": "3\n1 1 1",
"output": "0 3"
},
{
"input": "4\n1 1 1 1",
"output": "0 ... | 1,695,045,644 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 124 | 19,660,800 | k=int(input())
l=list(map(int,input().split()))
l.sort()
m=(l[k-1]-l[0])
count=0
for i in range(k//2):
if max(l[k-1-i]-l[i],l[i]-l[k-1-i]>=m):
count+=1
print(m,count**2) | Title: Pashmak and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have th... | ```python
k=int(input())
l=list(map(int,input().split()))
l.sort()
m=(l[k-1]-l[0])
count=0
for i in range(k//2):
if max(l[k-1-i]-l[i],l[i]-l[k-1-i]>=m):
count+=1
print(m,count**2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and ... | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,512,550,583 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 11,776,000 | n=int(input())
line=input()
list1=[int(i)for i in line.split()]
number=len(list1)
s=0
if len(list1)!=1:
for i in list1:
s+=i
for q in range(number):
for i in list1:
s+=i
list1.remove(min(list1))
if len(list1)==1:
break
print(s)
| Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all... | ```python
n=int(input())
line=input()
list1=[int(i)for i in line.split()]
number=len(list1)
s=0
if len(list1)!=1:
for i in list1:
s+=i
for q in range(number):
for i in list1:
s+=i
list1.remove(min(list1))
if len(list1)==1:
break
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
688 | A | Opponents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of them all. That means if one day at least one of Arya's opponents is absent at the school, then Ar... | The first line of the input contains two integers *n* and *d* (1<=≤<=*n*,<=*d*<=≤<=100) — the number of opponents and the number of days, respectively.
The *i*-th of the following *d* lines contains a string of length *n* consisting of characters '0' and '1'. The *j*-th character of this string is '0' if the *j*-th op... | Print the only integer — the maximum number of consecutive days that Arya will beat all present opponents. | [
"2 2\n10\n00\n",
"4 1\n0100\n",
"4 5\n1101\n1111\n0110\n1011\n1111\n"
] | [
"2\n",
"1\n",
"2\n"
] | In the first and the second samples, Arya will beat all present opponents each of the *d* days.
In the third sample, Arya will beat his opponents on days 1, 3 and 4 and his opponents will beat him on days 2 and 5. Thus, the maximum number of consecutive winning days is 2, which happens on days 3 and 4. | 500 | [
{
"input": "2 2\n10\n00",
"output": "2"
},
{
"input": "4 1\n0100",
"output": "1"
},
{
"input": "4 5\n1101\n1111\n0110\n1011\n1111",
"output": "2"
},
{
"input": "3 2\n110\n110",
"output": "2"
},
{
"input": "10 6\n1111111111\n0100110101\n1111111111\n0000011010\n1111... | 1,623,436,209 | 2,147,483,647 | PyPy 3 | OK | TESTS | 56 | 109 | 307,200 | from sys import stdin, stdout
def istr(): return input()
def inum(): return int(stdin.readline())
def imul(): return map(int, stdin.readline().split())
def ilst(): return list(map(int, stdin.readline().split()))
def splt(): return list(stdin.readline().strip())
def emat(row): return [splt() for i in range(row)]
... | Title: Opponents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of th... | ```python
from sys import stdin, stdout
def istr(): return input()
def inum(): return int(stdin.readline())
def imul(): return map(int, stdin.readline().split())
def ilst(): return list(map(int, stdin.readline().split()))
def splt(): return list(stdin.readline().strip())
def emat(row): return [splt() for i in ran... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is close... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the co... | Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days. | [
"4\n1 3 2 0\n",
"7\n1 3 3 2 1 2 3\n",
"2\n2 2\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya ca... | 0 | [
{
"input": "4\n1 3 2 0",
"output": "2"
},
{
"input": "7\n1 3 3 2 1 2 3",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "10\n0 0 1 1 0 0 0 0 1 0",
"output": "8"
},
{
"input": "100\n3 2 3 3 3 2 3 1 ... | 1,692,040,335 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | def logicalOpp(b1, b2):
if b1 == False and b2 == True: return True
else: return False
days = {
0: {'gym': False, 'contest': False},
1: {'gym': False, 'contest': True},
2: {'gym': True, 'contest': False},
3: {'gym': True, 'contest': True}
}
vasyaState = {'... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet... | ```python
def logicalOpp(b1, b2):
if b1 == False and b2 == True: return True
else: return False
days = {
0: {'gym': False, 'contest': False},
1: {'gym': False, 'contest': True},
2: {'gym': True, 'contest': False},
3: {'gym': True, 'contest': True}
}
vasya... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
554 | A | Kyoya and Photobooks | PROGRAMMING | 900 | [
"brute force",
"math",
"strings"
] | null | null | Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the pho... | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters. | Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make. | [
"a\n",
"hi\n"
] | [
"51\n",
"76\n"
] | In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | 250 | [
{
"input": "a",
"output": "51"
},
{
"input": "hi",
"output": "76"
},
{
"input": "y",
"output": "51"
},
{
"input": "kgan",
"output": "126"
},
{
"input": "zoabkyuvus",
"output": "276"
},
{
"input": "spyemhyznjieyhhbk",
"output": "451"
},
{
"i... | 1,586,807,813 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 109 | 0 | s=len(input())
print(26*(s+1) - s) | Title: Kyoya and Photobooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos b... | ```python
s=len(input())
print(26*(s+1) - s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
436 | A | Feed with Candy | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | The hero of the Cut the Rope game is a little monster named Om Nom. He loves candies. And what a coincidence! He also is the hero of today's problem.
One day, Om Nom visited his friend Evan. Evan has *n* candies of two types (fruit drops and caramel drops), the *i*-th candy hangs at the height of *h**i* centimeters ab... | The first line contains two integers, *n* and *x* (1<=≤<=*n*,<=*x*<=≤<=2000) — the number of sweets Evan has and the initial height of Om Nom's jump.
Each of the following *n* lines contains three integers *t**i*,<=*h**i*,<=*m**i* (0<=≤<=*t**i*<=≤<=1; 1<=≤<=*h**i*,<=*m**i*<=≤<=2000) — the type, height and the mass of... | Print a single integer — the maximum number of candies Om Nom can eat. | [
"5 3\n0 2 4\n1 3 1\n0 8 3\n0 20 10\n1 5 5\n"
] | [
"4\n"
] | One of the possible ways to eat 4 candies is to eat them in the order: 1, 5, 3, 2. Let's assume the following scenario:
1. Initially, the height of Om Nom's jump equals 3. He can reach candies 1 and 2. Let's assume that he eats candy 1. As the mass of this candy equals 4, the height of his jump will rise to 3 + 4 = 7... | 1,000 | [
{
"input": "5 3\n0 2 4\n1 3 1\n0 8 3\n0 20 10\n1 5 5",
"output": "4"
},
{
"input": "5 2\n1 15 2\n1 11 2\n0 17 2\n0 16 1\n1 18 2",
"output": "0"
},
{
"input": "6 2\n1 17 3\n1 6 1\n0 4 2\n1 10 1\n1 7 3\n1 5 1",
"output": "0"
},
{
"input": "7 2\n1 14 1\n1 9 2\n0 6 3\n0 20 2\n0 4... | 1,594,496,795 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 124 | 20,172,800 | n,height=map(int,input().split())
caramel=[];frut=[]
for i in range(n):
x,y,z = map(int,input().split())
if x==0:
caramel.append([y,z])
else:
frut.append([y,z])
caramel.sort();frut.sort()
l=min(len(caramel),len(frut))
ans=a=0;f1=f2=1
while a<l :
if f1 and caramel[a][0]<=heigh... | Title: Feed with Candy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The hero of the Cut the Rope game is a little monster named Om Nom. He loves candies. And what a coincidence! He also is the hero of today's problem.
One day, Om Nom visited his friend Evan. Evan has *n* candies of two... | ```python
n,height=map(int,input().split())
caramel=[];frut=[]
for i in range(n):
x,y,z = map(int,input().split())
if x==0:
caramel.append([y,z])
else:
frut.append([y,z])
caramel.sort();frut.sort()
l=min(len(caramel),len(frut))
ans=a=0;f1=f2=1
while a<l :
if f1 and caramel[a]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
588 | A | Duff and Meat | PROGRAMMING | 900 | [
"greedy"
] | null | null | Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her from there. In *i*-th day, they sell meat for *p**i* dollars per kilogram. Malek knows all numbers ... | The first line of input contains integer *n* (1<=≤<=*n*<=≤<=105), the number of days.
In the next *n* lines, *i*-th line contains two integers *a**i* and *p**i* (1<=≤<=*a**i*,<=*p**i*<=≤<=100), the amount of meat Duff needs and the cost of meat in that day. | Print the minimum money needed to keep Duff happy for *n* days, in one line. | [
"3\n1 3\n2 2\n3 1\n",
"3\n1 3\n2 1\n3 2\n"
] | [
"10\n",
"8\n"
] | In the first sample case: An optimal way would be to buy 1 kg on the first day, 2 kg on the second day and 3 kg on the third day.
In the second sample case: An optimal way would be to buy 1 kg on the first day and 5 kg (needed meat for the second and third day) on the second day. | 750 | [
{
"input": "3\n1 3\n2 2\n3 1",
"output": "10"
},
{
"input": "3\n1 3\n2 1\n3 2",
"output": "8"
},
{
"input": "1\n39 52",
"output": "2028"
},
{
"input": "2\n25 56\n94 17",
"output": "2998"
},
{
"input": "5\n39 21\n95 89\n73 90\n9 55\n85 32",
"output": "6321"
}... | 1,628,102,980 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 93 | 20,172,800 | import sys
from os import path
if(path.exists('input.txt')):
sys.stdin = open("input.txt","r")
sys.stdout = open("output.txt","w")
n = int(input())
a = []
p = []
for i in range(n):
x, y =map(int,input().split())
a.append(x)
p.append(y)
money=0
ai=0
pmin=p.index(min(p))
for j in rang... | Title: Duff and Meat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her ... | ```python
import sys
from os import path
if(path.exists('input.txt')):
sys.stdin = open("input.txt","r")
sys.stdout = open("output.txt","w")
n = int(input())
a = []
p = []
for i in range(n):
x, y =map(int,input().split())
a.append(x)
p.append(y)
money=0
ai=0
pmin=p.index(min(p))
for... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
768 | A | Oath of the Night's Watch | PROGRAMMING | 900 | [
"constructive algorithms",
"sortings"
] | null | null | "Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am the sword in the darkness. I am the watcher on the walls. I am the shield that guards the realms of men. I ple... | First line consists of a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of stewards with Jon Snow.
Second line consists of *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) representing the values assigned to the stewards. | Output a single integer representing the number of stewards which Jon will feed. | [
"2\n1 5\n",
"3\n1 2 5\n"
] | [
"0",
"1"
] | In the first sample, Jon Snow cannot support steward with strength 1 because there is no steward with strength less than 1 and he cannot support steward with strength 5 because there is no steward with strength greater than 5.
In the second sample, Jon Snow can support steward with strength 2 because there are steward... | 500 | [
{
"input": "2\n1 5",
"output": "0"
},
{
"input": "3\n1 2 5",
"output": "1"
},
{
"input": "4\n1 2 3 4",
"output": "2"
},
{
"input": "8\n7 8 9 4 5 6 1 2",
"output": "6"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n100",
"output": "0"
},
... | 1,678,451,077 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 2,000 | 7,884,800 | input()
a=list(map(int,input().split()))
count=0
for i in a:
if i> min(a) and i<max(a):
count+=1
print(count)
| Title: Oath of the Night's Watch
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am... | ```python
input()
a=list(map(int,input().split()))
count=0
for i in a:
if i> min(a) and i<max(a):
count+=1
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
724 | A | Checking the Calendar | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | You are given names of two days of the week.
Please, determine whether it is possible that during some non-leap year the first day of some month was equal to the first day of the week you are given, while the first day of the next month was equal to the second day of the week you are given. Both months should belong t... | The input consists of two lines, each of them containing the name of exactly one day of the week. It's guaranteed that each string in the input is from the set "monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday". | Print "YES" (without quotes) if such situation is possible during some non-leap year. Otherwise, print "NO" (without quotes). | [
"monday\ntuesday\n",
"sunday\nsunday\n",
"saturday\ntuesday\n"
] | [
"NO\n",
"YES\n",
"YES\n"
] | In the second sample, one can consider February 1 and March 1 of year 2015. Both these days were Sundays.
In the third sample, one can consider July 1 and August 1 of year 2017. First of these two days is Saturday, while the second one is Tuesday. | 500 | [
{
"input": "monday\ntuesday",
"output": "NO"
},
{
"input": "sunday\nsunday",
"output": "YES"
},
{
"input": "saturday\ntuesday",
"output": "YES"
},
{
"input": "tuesday\nthursday",
"output": "YES"
},
{
"input": "friday\nwednesday",
"output": "NO"
},
{
"i... | 1,681,562,632 | 232 | PyPy 3-64 | OK | TESTS | 68 | 77 | 0 | d = ['monday', 'tuesday', 'wednesday', 'thursday', 'friday', 'saturday', 'sunday']
a, b = input(), input()
x, y = d.index(a), d.index(b)
if (y - x) % 7 in {0, 2, 3}:
print('YES')
else:
print('NO')
| Title: Checking the Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given names of two days of the week.
Please, determine whether it is possible that during some non-leap year the first day of some month was equal to the first day of the week you are given, while the fir... | ```python
d = ['monday', 'tuesday', 'wednesday', 'thursday', 'friday', 'saturday', 'sunday']
a, b = input(), input()
x, y = d.index(a), d.index(b)
if (y - x) % 7 in {0, 2, 3}:
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
832 | A | Sasha and Sticks | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with whom he shares a desk. The rules are simple. Sasha draws *n* sticks in a row. After that the players t... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1018, *k*<=≤<=*n*) — the number of sticks drawn by Sasha and the number *k* — the number of sticks to be crossed out on each turn. | If Sasha wins, print "YES" (without quotes), otherwise print "NO" (without quotes).
You can print each letter in arbitrary case (upper of lower). | [
"1 1\n",
"10 4\n"
] | [
"YES\n",
"NO\n"
] | In the first example Sasha crosses out 1 stick, and then there are no sticks. So Lena can't make a move, and Sasha wins.
In the second example Sasha crosses out 4 sticks, then Lena crosses out 4 sticks, and after that there are only 2 sticks left. Sasha can't make a move. The players make equal number of moves, so Sas... | 500 | [
{
"input": "1 1",
"output": "YES"
},
{
"input": "10 4",
"output": "NO"
},
{
"input": "251656215122324104 164397544865601257",
"output": "YES"
},
{
"input": "963577813436662285 206326039287271924",
"output": "NO"
},
{
"input": "1000000000000000000 1",
"output":... | 1,593,858,092 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 41 | 109 | 0 | n,k=map(int,input().split())
w=int(n/k)%2
if(w):
print('YES')
else:
print('NO') | Title: Sasha and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with ... | ```python
n,k=map(int,input().split())
w=int(n/k)%2
if(w):
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,663,547,213 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 62 | 0 | l=['a','e','i','o','u','y']
s=input().split()
if s[-1][-2].lower() in l:
print('YES')
else:
print('NO') | Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
l=['a','e','i','o','u','y']
s=input().split()
if s[-1][-2].lower() in l:
print('YES')
else:
print('NO')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
665 | D | Simple Subset | PROGRAMMING | 1,800 | [
"constructive algorithms",
"greedy",
"number theory"
] | null | null | A tuple of positive integers {*x*1,<=*x*2,<=...,<=*x**k*} is called simple if for all pairs of positive integers (*i*,<=<=*j*) (1<=<=≤<=*i*<=<=<<=<=*j*<=≤<=*k*), *x**i*<=<=+<=<=*x**j* is a prime.
You are given an array *a* with *n* positive integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n* (not necessary distinct). You wan... | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of integers in the array *a*.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=106) — the elements of the array *a*. | On the first line print integer *m* — the maximum possible size of simple subset of *a*.
On the second line print *m* integers *b**l* — the elements of the simple subset of the array *a* with the maximum size.
If there is more than one solution you can print any of them. You can print the elements of the subset in an... | [
"2\n2 3\n",
"2\n2 2\n",
"3\n2 1 1\n",
"2\n83 14\n"
] | [
"2\n3 2\n",
"1\n2\n",
"3\n1 1 2\n",
"2\n14 83\n"
] | none | 0 | [
{
"input": "2\n2 3",
"output": "2\n3 2"
},
{
"input": "2\n2 2",
"output": "1\n2"
},
{
"input": "3\n2 1 1",
"output": "3\n1 1 2"
},
{
"input": "2\n83 14",
"output": "2\n14 83"
},
{
"input": "10\n10 10 1 2 3 3 1 2 1 5",
"output": "4\n1 1 10 1"
},
{
"inpu... | 1,689,647,860 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1689647860.8473675")# 1689647860.8473878 | Title: Simple Subset
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tuple of positive integers {*x*1,<=*x*2,<=...,<=*x**k*} is called simple if for all pairs of positive integers (*i*,<=<=*j*) (1<=<=≤<=*i*<=<=<<=<=*j*<=≤<=*k*), *x**i*<=<=+<=<=*x**j* is a prime.
You are given an arra... | ```python
print("_RANDOM_GUESS_1689647860.8473675")# 1689647860.8473878
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
367 | B | Sereja ans Anagrams | PROGRAMMING | 1,900 | [
"binary search",
"data structures"
] | null | null | Sereja has two sequences *a* and *b* and number *p*. Sequence *a* consists of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Similarly, sequence *b* consists of *m* integers *b*1,<=*b*2,<=...,<=*b**m*. As usual, Sereja studies the sequences he has. Today he wants to find the number of positions *q* (*q*<=+<=(*m*<=-<=1)·*p*<=... | The first line contains three integers *n*, *m* and *p* (1<=≤<=*n*,<=*m*<=≤<=2·105,<=1<=≤<=*p*<=≤<=2·105). The next line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109). The next line contains *m* integers *b*1, *b*2, ..., *b**m* (1<=≤<=*b**i*<=≤<=109). | In the first line print the number of valid *q*s. In the second line, print the valid values in the increasing order. | [
"5 3 1\n1 2 3 2 1\n1 2 3\n",
"6 3 2\n1 3 2 2 3 1\n1 2 3\n"
] | [
"2\n1 3\n",
"2\n1 2\n"
] | none | 1,000 | [
{
"input": "5 3 1\n1 2 3 2 1\n1 2 3",
"output": "2\n1 3"
},
{
"input": "6 3 2\n1 3 2 2 3 1\n1 2 3",
"output": "2\n1 2"
},
{
"input": "68 16 3\n5 3 4 3 3 3 2 2 2 3 2 4 2 2 2 2 4 3 5 1 1 2 2 2 3 1 5 1 2 2 1 5 1 5 3 2 3 5 2 1 1 4 2 3 4 3 4 3 3 1 3 4 1 5 2 5 3 4 4 1 4 5 5 1 1 2 2 2\n5 4 4 3 ... | 1,677,258,071 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | n = int(input())
x = list(map(int, input().split()))
q = int(input())
x.sort()
for _ in range(q):
qm = int(input())
l = 0
r = n+1
ans = 0
while r>l+1:
m = int((r-l)/2+l)
if x[m-1] > qm:
r = m
else:
ans = m
l = m
print(an... | Title: Sereja ans Anagrams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has two sequences *a* and *b* and number *p*. Sequence *a* consists of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Similarly, sequence *b* consists of *m* integers *b*1,<=*b*2,<=...,<=*b**m*. As usual, Sereja st... | ```python
n = int(input())
x = list(map(int, input().split()))
q = int(input())
x.sort()
for _ in range(q):
qm = int(input())
l = 0
r = n+1
ans = 0
while r>l+1:
m = int((r-l)/2+l)
if x[m-1] > qm:
r = m
else:
ans = m
l = m
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
835 | A | Key races | PROGRAMMING | 800 | [
"math"
] | null | null | Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t*1 milliseconds. The second participant types one character in *v*2 milliseconds and has ping *... | The first line contains five integers *s*, *v*1, *v*2, *t*1, *t*2 (1<=≤<=*s*,<=*v*1,<=*v*2,<=*t*1,<=*t*2<=≤<=1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and th... | If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship". | [
"5 1 2 1 2\n",
"3 3 1 1 1\n",
"4 5 3 1 5\n"
] | [
"First\n",
"Second\n",
"Friendship\n"
] | In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, ... | 500 | [
{
"input": "5 1 2 1 2",
"output": "First"
},
{
"input": "3 3 1 1 1",
"output": "Second"
},
{
"input": "4 5 3 1 5",
"output": "Friendship"
},
{
"input": "1000 1000 1000 1000 1000",
"output": "Friendship"
},
{
"input": "1 1 1 1 1",
"output": "Friendship"
},
... | 1,586,080,472 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 109 | 0 | s,v1,v2,t1,t2 = list(map(int,input().split()))
a1 = (v1*s) + (2*t1)
a2 = (v2*s) + (2*t2)
if a1 > a2:
print('Second')
elif a1 < a2:
print('First')
elif a1 == a2:
print('Friendship') | Title: Key races
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t... | ```python
s,v1,v2,t1,t2 = list(map(int,input().split()))
a1 = (v1*s) + (2*t1)
a2 = (v2*s) + (2*t2)
if a1 > a2:
print('Second')
elif a1 < a2:
print('First')
elif a1 == a2:
print('Friendship')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
656 | A | Da Vinci Powers | PROGRAMMING | 1,900 | [
"*special"
] | null | null | The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output a single integer. | The input contains a single integer *a* (0<=≤<=*a*<=≤<=35). | Output a single integer. | [
"3\n",
"10\n"
] | [
"8\n",
"1024\n"
] | none | 0 | [
{
"input": "3",
"output": "8"
},
{
"input": "10",
"output": "1024"
},
{
"input": "35",
"output": "33940307968"
},
{
"input": "0",
"output": "1"
},
{
"input": "1",
"output": "2"
},
{
"input": "2",
"output": "4"
},
{
"input": "4",
"output... | 1,683,624,982 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | def it(): return int(input())
def pr(a): return print(a)
def li(): return list(map(int, input().split()))
def ls(): return [str(i) for i in input()]
def no(): return print('NO')
def yes(): return print('YES')
def ap(a, b):return a.append(b)
n = it()
print(2**n)
| Title: Da Vinci Powers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output a single integer.
Input Specification:
The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output Specification:
Output a single integer.
De... | ```python
def it(): return int(input())
def pr(a): return print(a)
def li(): return list(map(int, input().split()))
def ls(): return [str(i) for i in input()]
def no(): return print('NO')
def yes(): return print('YES')
def ap(a, b):return a.append(b)
n = it()
print(2**n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
35 | A | Shell Game | PROGRAMMING | 1,000 | [
"implementation"
] | A. Shell Game | 2 | 64 | Today the «Z» city residents enjoy a shell game competition. The residents are gathered on the main square to watch the breath-taking performance. The performer puts 3 non-transparent cups upside down in a row. Then he openly puts a small ball under one of the cups and starts to shuffle the cups around very quickly so ... | The first input line contains an integer from 1 to 3 — index of the cup which covers the ball before the shuffles. The following three lines describe the shuffles. Each description of a shuffle contains two distinct integers from 1 to 3 — indexes of the cups which the performer shuffled this time. The cups are numbered... | In the first line output an integer from 1 to 3 — index of the cup which will have the ball after all the shuffles. | [
"1\n1 2\n2 1\n2 1\n",
"1\n2 1\n3 1\n1 3\n"
] | [
"2\n",
"2\n"
] | none | 500 | [
{
"input": "1\n1 2\n2 1\n2 1",
"output": "2"
},
{
"input": "1\n2 1\n3 1\n1 3",
"output": "2"
},
{
"input": "3\n3 1\n2 1\n1 2",
"output": "1"
},
{
"input": "1\n1 3\n1 2\n2 3",
"output": "2"
},
{
"input": "3\n3 2\n3 1\n3 1",
"output": "2"
},
{
"input": "... | 1,685,048,802 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | import sys
sys.stdin=open("input.txt","r")
idx = int(input())
for _ in range(3):
cup_1, cup_2 = list(map(int, input().split()))
if idx != cup_1 and idx != cup_2: continue
idx = cup_1 if idx == cup_2 else cup_1
print(idx) | Title: Shell Game
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Today the «Z» city residents enjoy a shell game competition. The residents are gathered on the main square to watch the breath-taking performance. The performer puts 3 non-transparent cups upside down in a row. Then he openly put... | ```python
import sys
sys.stdin=open("input.txt","r")
idx = int(input())
for _ in range(3):
cup_1, cup_2 = list(map(int, input().split()))
if idx != cup_1 and idx != cup_2: continue
idx = cup_1 if idx == cup_2 else cup_1
print(idx)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
371 | A | K-Periodic Array | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"math"
] | null | null | This task will exclusively concentrate only on the arrays where all elements equal 1 and/or 2.
Array *a* is *k*-period if its length is divisible by *k* and there is such array *b* of length *k*, that *a* is represented by array *b* written exactly times consecutively. In other words, array *a* is *k*-periodic, if it... | The first line of the input contains a pair of integers *n*, *k* (1<=≤<=*k*<=≤<=*n*<=≤<=100), where *n* is the length of the array and the value *n* is divisible by *k*. The second line contains the sequence of elements of the given array *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2), *a**i* is the *i*-th element of ... | Print the minimum number of array elements we need to change to make the array *k*-periodic. If the array already is *k*-periodic, then print 0. | [
"6 2\n2 1 2 2 2 1\n",
"8 4\n1 1 2 1 1 1 2 1\n",
"9 3\n2 1 1 1 2 1 1 1 2\n"
] | [
"1\n",
"0\n",
"3\n"
] | In the first sample it is enough to change the fourth element from 2 to 1, then the array changes to [2, 1, 2, 1, 2, 1].
In the second sample, the given array already is 4-periodic.
In the third sample it is enough to replace each occurrence of number two by number one. In this case the array will look as [1, 1, 1, 1... | 500 | [
{
"input": "6 2\n2 1 2 2 2 1",
"output": "1"
},
{
"input": "8 4\n1 1 2 1 1 1 2 1",
"output": "0"
},
{
"input": "9 3\n2 1 1 1 2 1 1 1 2",
"output": "3"
},
{
"input": "1 1\n2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "0"
},
{
"input": "2 2\n2 2... | 1,594,285,709 | 2,147,483,647 | PyPy 3 | OK | TESTS | 24 | 140 | 20,172,800 | n,k=map(int,input().split())
a=list(map(int,input().split()))
c=0
z=n//k
for i in range(k):
a1=a[i::k]
r1=a1.count(1)
r2=a1.count(2)
c=c+min(r1,r2)
print(c) | Title: K-Periodic Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This task will exclusively concentrate only on the arrays where all elements equal 1 and/or 2.
Array *a* is *k*-period if its length is divisible by *k* and there is such array *b* of length *k*, that *a* is represent... | ```python
n,k=map(int,input().split())
a=list(map(int,input().split()))
c=0
z=n//k
for i in range(k):
a1=a[i::k]
r1=a1.count(1)
r2=a1.count(2)
c=c+min(r1,r2)
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
762 | B | USB vs. PS/2 | PROGRAMMING | 1,400 | [
"greedy",
"implementation",
"sortings",
"two pointers"
] | null | null | Due to the increase in the number of students of Berland State University it was decided to equip a new computer room. You were given the task of buying mouses, and you have to spend as little as possible. After all, the country is in crisis!
The computers bought for the room were different. Some of them had only USB ... | The first line contains three integers *a*, *b* and *c* (0<=≤<=*a*,<=*b*,<=*c*<=≤<=105) — the number of computers that only have USB ports, the number of computers, that only have PS/2 ports, and the number of computers, that have both options, respectively.
The next line contains one integer *m* (0<=≤<=*m*<=≤<=3·105... | Output two integers separated by space — the number of equipped computers and the total cost of the mouses you will buy. | [
"2 1 1\n4\n5 USB\n6 PS/2\n3 PS/2\n7 PS/2\n"
] | [
"3 14\n"
] | In the first example you can buy the first three mouses. This way you will equip one of the computers that has only a USB port with a USB mouse, and the two PS/2 mouses you will plug into the computer with PS/2 port and the computer with both ports. | 0 | [
{
"input": "2 1 1\n4\n5 USB\n6 PS/2\n3 PS/2\n7 PS/2",
"output": "3 14"
},
{
"input": "1 4 4\n12\n36949214 USB\n683538043 USB\n595594834 PS/2\n24951774 PS/2\n131512123 USB\n327575645 USB\n30947411 USB\n916758386 PS/2\n474310330 USB\n350512489 USB\n281054887 USB\n875326145 USB",
"output": "8 23453... | 1,660,785,625 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 5 | 93 | 2,048,000 | def solve(g,p,q,v):
tmp1=0
tmp2=0
v1=[0]
v2=[0]
v3=[0]
for i in v:
a,b=i[0],i[1]
if b=="USB":
v1.append(a)
tmp1+=1
else:
v2.append(a)
tmp2+=1
v1.sort()
v2.sort()
mxx=min(tmp1,g)+min(tmp2,p)+min(q,... | Title: USB vs. PS/2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Due to the increase in the number of students of Berland State University it was decided to equip a new computer room. You were given the task of buying mouses, and you have to spend as little as possible. After all, the c... | ```python
def solve(g,p,q,v):
tmp1=0
tmp2=0
v1=[0]
v2=[0]
v3=[0]
for i in v:
a,b=i[0],i[1]
if b=="USB":
v1.append(a)
tmp1+=1
else:
v2.append(a)
tmp2+=1
v1.sort()
v2.sort()
mxx=min(tmp1,g)+min(tmp2... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
719 | B | Anatoly and Cockroaches | PROGRAMMING | 1,400 | [
"greedy"
] | null | null | Anatoly lives in the university dorm as many other students do. As you know, cockroaches are also living there together with students. Cockroaches might be of two colors: black and red. There are *n* cockroaches living in Anatoly's room.
Anatoly just made all his cockroaches to form a single line. As he is a perfectio... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of cockroaches.
The second line contains a string of length *n*, consisting of characters 'b' and 'r' that denote black cockroach and red cockroach respectively. | Print one integer — the minimum number of moves Anatoly has to perform in order to make the colors of cockroaches in the line to alternate. | [
"5\nrbbrr\n",
"5\nbbbbb\n",
"3\nrbr\n"
] | [
"1\n",
"2\n",
"0\n"
] | In the first sample, Anatoly has to swap third and fourth cockroaches. He needs 1 turn to do this.
In the second sample, the optimum answer is to paint the second and the fourth cockroaches red. This requires 2 turns.
In the third sample, the colors of cockroaches in the line are alternating already, thus the answer ... | 1,000 | [
{
"input": "5\nrbbrr",
"output": "1"
},
{
"input": "5\nbbbbb",
"output": "2"
},
{
"input": "3\nrbr",
"output": "0"
},
{
"input": "13\nrbbbrbrrbrrbb",
"output": "3"
},
{
"input": "18\nrrrrrrrrrrrrrrrrrb",
"output": "8"
},
{
"input": "100\nbrbbbrrrbbrbrb... | 1,671,962,556 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 46 | 62 | 1,843,200 | n = int(input())
s = input()
orcnt = 0
ercnt = 0
obcnt = 0
ebcnt = 0
for i in range(n):
if i%2==0:
if s[i] == 'r':
ercnt += 1
else:
ebcnt += 1
else:
if s[i] == 'r':
orcnt += 1
else:
obcnt += 1
if orcnt+ercnt > obcnt+ebcnt:
print(min(orcnt,ercnt))
else:
print(min(obcnt,ebcnt)) | Title: Anatoly and Cockroaches
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anatoly lives in the university dorm as many other students do. As you know, cockroaches are also living there together with students. Cockroaches might be of two colors: black and red. There are *n* cockroaches... | ```python
n = int(input())
s = input()
orcnt = 0
ercnt = 0
obcnt = 0
ebcnt = 0
for i in range(n):
if i%2==0:
if s[i] == 'r':
ercnt += 1
else:
ebcnt += 1
else:
if s[i] == 'r':
orcnt += 1
else:
obcnt += 1
if orcnt+ercnt > obcnt+ebcnt:
print(min(orcnt,ercnt))
else:
print(min(obcnt,ebcnt))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
788 | A | Functions again | PROGRAMMING | 1,600 | [
"dp",
"two pointers"
] | null | null | Something happened in Uzhlyandia again... There are riots on the streets... Famous Uzhlyandian superheroes Shean the Sheep and Stas the Giraffe were called in order to save the situation. Upon the arriving, they found that citizens are worried about maximum values of the Main Uzhlyandian Function *f*, which is defined ... | The first line contains single integer *n* (2<=≤<=*n*<=≤<=105) — the size of the array *a*.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (-109<=≤<=*a**i*<=≤<=109) — the array elements. | Print the only integer — the maximum value of *f*. | [
"5\n1 4 2 3 1\n",
"4\n1 5 4 7\n"
] | [
"3",
"6"
] | In the first sample case, the optimal value of *f* is reached on intervals [1, 2] and [2, 5].
In the second case maximal value of *f* is reachable only on the whole array. | 500 | [
{
"input": "5\n1 4 2 3 1",
"output": "3"
},
{
"input": "4\n1 5 4 7",
"output": "6"
},
{
"input": "8\n16 14 12 10 8 100 50 0",
"output": "92"
},
{
"input": "2\n1 1",
"output": "0"
},
{
"input": "50\n-5 -9 0 44 -10 37 34 -49 11 -22 -26 44 8 -13 23 -46 34 12 -24 2 -4... | 1,527,061,048 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 78 | 0 | import math
n=int(input())
a=list(map(int,input().split()))
b=[]
dp1=[]
dp2=[]
c=[]
d=[]
for i in range(n-1):
b.append(abs((a[i+1]-a[i])))
for j in range(n-1):
if(j%2):
c.append(b[j])
d.append(-1*b[j])
else:
c.append(-1*b[j])
d.append(b[j])
... | Title: Functions again
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Something happened in Uzhlyandia again... There are riots on the streets... Famous Uzhlyandian superheroes Shean the Sheep and Stas the Giraffe were called in order to save the situation. Upon the arriving, they found t... | ```python
import math
n=int(input())
a=list(map(int,input().split()))
b=[]
dp1=[]
dp2=[]
c=[]
d=[]
for i in range(n-1):
b.append(abs((a[i+1]-a[i])))
for j in range(n-1):
if(j%2):
c.append(b[j])
d.append(-1*b[j])
else:
c.append(-1*b[j])
d.append... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
799 | A | Carrot Cakes | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In some game by Playrix it takes *t* minutes for an oven to bake *k* carrot cakes, all cakes are ready at the same moment *t* minutes after they started baking. Arkady needs at least *n* cakes to complete a task, but he currently don't have any. However, he has infinitely many ingredients and one oven. Moreover, Arkady... | The only line contains four integers *n*, *t*, *k*, *d* (1<=≤<=*n*,<=*t*,<=*k*,<=*d*<=≤<=1<=000) — the number of cakes needed, the time needed for one oven to bake *k* cakes, the number of cakes baked at the same time, the time needed to build the second oven. | If it is reasonable to build the second oven, print "YES". Otherwise print "NO". | [
"8 6 4 5\n",
"8 6 4 6\n",
"10 3 11 4\n",
"4 2 1 4\n"
] | [
"YES\n",
"NO\n",
"NO\n",
"YES\n"
] | In the first example it is possible to get 8 cakes in 12 minutes using one oven. The second oven can be built in 5 minutes, so after 6 minutes the first oven bakes 4 cakes, the second oven bakes 4 more ovens after 11 minutes. Thus, it is reasonable to build the second oven.
In the second example it doesn't matter whe... | 500 | [
{
"input": "8 6 4 5",
"output": "YES"
},
{
"input": "8 6 4 6",
"output": "NO"
},
{
"input": "10 3 11 4",
"output": "NO"
},
{
"input": "4 2 1 4",
"output": "YES"
},
{
"input": "28 17 16 26",
"output": "NO"
},
{
"input": "60 69 9 438",
"output": "NO"... | 1,698,875,302 | 2,147,483,647 | Python 3 | OK | TESTS | 93 | 46 | 0 | # https://codeforces.com/contest/799/problem/A
num_of_cake,time_for_oven,cake_in_oven,second_oven = map(int,input().split())
batch = (num_of_cake+cake_in_oven-1)//cake_in_oven
oven1 = 0
oven2 = second_oven
for i in range(batch):
if(oven1<=oven2):
oven1+=time_for_oven
else:
oven2+=time_f... | Title: Carrot Cakes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In some game by Playrix it takes *t* minutes for an oven to bake *k* carrot cakes, all cakes are ready at the same moment *t* minutes after they started baking. Arkady needs at least *n* cakes to complete a task, but he cu... | ```python
# https://codeforces.com/contest/799/problem/A
num_of_cake,time_for_oven,cake_in_oven,second_oven = map(int,input().split())
batch = (num_of_cake+cake_in_oven-1)//cake_in_oven
oven1 = 0
oven2 = second_oven
for i in range(batch):
if(oven1<=oven2):
oven1+=time_for_oven
else:
ove... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
614 | A | Link/Cut Tree | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agre... | The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109). | Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes). | [
"1 10 2\n",
"2 4 5\n"
] | [
"1 2 4 8 ",
"-1"
] | Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | 500 | [
{
"input": "1 10 2",
"output": "1 2 4 8 "
},
{
"input": "2 4 5",
"output": "-1"
},
{
"input": "18102 43332383920 28554",
"output": "28554 815330916 "
},
{
"input": "19562 31702689720 17701",
"output": "313325401 "
},
{
"input": "11729 55221128400 313",
"output... | 1,565,893,457 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 2,000 | 0 | def is_power(x, y):
pow = 1
while(pow < x):
pow = pow * y
if(pow == x): return True
else: return False
l, r, k = list(map(int, input().split()))
powers = []
for i in range(l, r):
if(is_power(i, k)): powers.append(i)
if(powers == []): print('-1')
else:
print(" ".join(map(str, powers))) | Title: Link/Cut Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand ... | ```python
def is_power(x, y):
pow = 1
while(pow < x):
pow = pow * y
if(pow == x): return True
else: return False
l, r, k = list(map(int, input().split()))
powers = []
for i in range(l, r):
if(is_power(i, k)): powers.append(i)
if(powers == []): print('-1')
else:
print(" ".join(map(str, powers)))
`... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
707 | C | Pythagorean Triples | PROGRAMMING | 1,500 | [
"math",
"number theory"
] | null | null | Katya studies in a fifth grade. Recently her class studied right triangles and the Pythagorean theorem. It appeared, that there are triples of positive integers such that you can construct a right triangle with segments of lengths corresponding to triple. Such triples are called Pythagorean triples.
For example, tripl... | The only line of the input contains single integer *n* (1<=≤<=*n*<=≤<=109) — the length of some side of a right triangle. | Print two integers *m* and *k* (1<=≤<=*m*,<=*k*<=≤<=1018), such that *n*, *m* and *k* form a Pythagorean triple, in the only line.
In case if there is no any Pythagorean triple containing integer *n*, print <=-<=1 in the only line. If there are many answers, print any of them. | [
"3\n",
"6\n",
"1\n",
"17\n",
"67\n"
] | [
"4 5",
"8 10",
"-1",
"144 145",
"2244 2245"
] | Illustration for the first sample. | 1,500 | [
{
"input": "3",
"output": "4 5"
},
{
"input": "6",
"output": "8 10"
},
{
"input": "1",
"output": "-1"
},
{
"input": "17",
"output": "144 145"
},
{
"input": "67",
"output": "2244 2245"
},
{
"input": "10",
"output": "24 26"
},
{
"input": "14"... | 1,658,781,288 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | from math import *
def findTriple(a):
x = 1
while True:
leg = sqrt(abs(a**2 - x**2))
print(a, x, leg)
if (ceil(leg) == x):
return -1
if (floor(leg) == leg and leg != 0):
return (str(int(leg)) + " " + str(x))
x += 1
side = int(input()... | Title: Pythagorean Triples
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Katya studies in a fifth grade. Recently her class studied right triangles and the Pythagorean theorem. It appeared, that there are triples of positive integers such that you can construct a right triangle with segm... | ```python
from math import *
def findTriple(a):
x = 1
while True:
leg = sqrt(abs(a**2 - x**2))
print(a, x, leg)
if (ceil(leg) == x):
return -1
if (floor(leg) == leg and leg != 0):
return (str(int(leg)) + " " + str(x))
x += 1
side = i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
262 | A | Roma and Lucky Numbers | PROGRAMMING | 800 | [
"implementation"
] | null | null | Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Roma's got *n* positive integer... | The first line contains two integers *n*, *k* (1<=≤<=*n*,<=*k*<=≤<=100). The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the numbers that Roma has.
The numbers in the lines are separated by single spaces. | In a single line print a single integer — the answer to the problem. | [
"3 4\n1 2 4\n",
"3 2\n447 44 77\n"
] | [
"3\n",
"2\n"
] | In the first sample all numbers contain at most four lucky digits, so the answer is 3.
In the second sample number 447 doesn't fit in, as it contains more than two lucky digits. All other numbers are fine, so the answer is 2. | 500 | [
{
"input": "3 4\n1 2 4",
"output": "3"
},
{
"input": "3 2\n447 44 77",
"output": "2"
},
{
"input": "2 2\n507978501 180480073",
"output": "2"
},
{
"input": "9 6\n655243746 167613748 1470546 57644035 176077477 56984809 44677 215706823 369042089",
"output": "9"
},
{
... | 1,573,600,529 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 218 | 0 | a, b = map(int,input().split())
c = list(map(int, input().split()))
counter = 0
for i in c:
x = str(i)
if x.count('4') + x.count('7') <= b:
counter += 1
print(counter) | Title: Roma and Lucky Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits... | ```python
a, b = map(int,input().split())
c = list(map(int, input().split()))
counter = 0
for i in c:
x = str(i)
if x.count('4') + x.count('7') <= b:
counter += 1
print(counter)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
27 | A | Next Test | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | A. Next Test | 2 | 256 | «Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the next test will have, the system suggests the default value of the index. It is calculated ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=3000) — the amount of previously added tests. The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3000) — indexes of these tests. | Output the required default value for the next test index. | [
"3\n1 7 2\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "1\n1",
"output": "2"
},
{
"input": "2\n2 1",
"output": "3"
},
{
"input": "3\n3 4 1",
"output": "2"
},
{
"input": "4\n6 4 3 5",
"output": "1"
},
{
"input": "5\n3 2 1 7 4",
"output": "5"
},
{
"input": "6\n4 1 2 5 3 7",
"output": "6"
},
... | 1,635,564,221 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 122 | 4,505,600 | i = int(input())
a = map(int, input().split())
a = sorted(a)
ans = 1
for j in range(i):
if ans == a[j]:
ans = ans + 1
print(ans)
| Title: Next Test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
«Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the... | ```python
i = int(input())
a = map(int, input().split())
a = sorted(a)
ans = 1
for j in range(i):
if ans == a[j]:
ans = ans + 1
print(ans)
``` | 3.961108 | MatrixStudio/Codeforces-Python-Submissions |
560 | A | Currency System in Geraldion | PROGRAMMING | 1,000 | [
"implementation",
"sortings"
] | null | null | A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of ea... | The first line contains number *n* (1<=≤<=*n*<=≤<=1000) — the number of values of the banknotes that used in Geraldion.
The second line contains *n* distinct space-separated numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the values of the banknotes. | Print a single line — the minimum unfortunate sum. If there are no unfortunate sums, print <=-<=1. | [
"5\n1 2 3 4 5\n"
] | [
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "-1"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "10\n371054 506438 397130 1 766759 208409 769264 549213 641270 771837",
"output": "-1"
},
{
"input": "10\n635370 154890 909382 220996 276501 716105 538714 140162 171960 271264",
"o... | 1,692,548,106 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 31 | 0 | n=int(input())
arr=[int(i) for i in input().split()]
arr.sort()
if arr[0]==1:
print(-1)
else :
print(1)
| Title: Currency System in Geraldion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cann... | ```python
n=int(input())
arr=[int(i) for i in input().split()]
arr.sort()
if arr[0]==1:
print(-1)
else :
print(1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
545 | D | Queue | PROGRAMMING | 1,300 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces. | Print a single number — the maximum number of not disappointed people in the queue. | [
"5\n15 2 1 5 3\n"
] | [
"4\n"
] | Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5. | 1,750 | [
{
"input": "5\n15 2 1 5 3",
"output": "4"
},
{
"input": "15\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "2"
},
{
"input": "10\n13 2 5 55 21 34 1 8 1 3",
"output": "6"
},
{
"input": "10\n8 256 16 1 2 1 64 4 128 32",
"output": "10"
},
{
"input": "10\n10000 40000 1000... | 1,695,826,168 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n = int(input())
people = list(map(int, input().split()))
people.sort()
count = 0
time = 0
for a in people:
if a >= time:
count+=1
time += a
print(count) | Title: Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time... | ```python
n = int(input())
people = list(map(int, input().split()))
people.sort()
count = 0
time = 0
for a in people:
if a >= time:
count+=1
time += a
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,693,762,630 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 45 | 124 | 1,331,200 | a, b = map(int, input().split())
check_a, check_b = 0, 0
check_flag = True
for i in range(1, a + 1):
if a % i == 0:
check_a += 1
for i in range(1, b + 1):
if b % i == 0:
check_b += 1
for i in range(a+1, b):
check_numb = 0
for j in range(1, i+1):
if i % j == 0:
... | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
a, b = map(int, input().split())
check_a, check_b = 0, 0
check_flag = True
for i in range(1, a + 1):
if a % i == 0:
check_a += 1
for i in range(1, b + 1):
if b % i == 0:
check_b += 1
for i in range(a+1, b):
check_numb = 0
for j in range(1, i+1):
if i %... | 3.96652 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,677,925,018 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | text = input()
uppercase = 0
lowercase = 0
for detail in text:
if detail.isupper():
uppercase = uppercase + 1
elif detail.islower():
lowercase = lowercase + 1
if uppercase > lowercase:
print(text.upper())
else:
print(text.lower())
quit() | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
text = input()
uppercase = 0
lowercase = 0
for detail in text:
if detail.isupper():
uppercase = uppercase + 1
elif detail.islower():
lowercase = lowercase + 1
if uppercase > lowercase:
print(text.upper())
else:
print(text.lower())
quit()
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
124 | A | The number of positions | PROGRAMMING | 1,000 | [
"math"
] | null | null | Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy. | The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=<<=*n*<=≤<=100). | Print the single number — the number of the sought positions. | [
"3 1 1\n",
"5 2 3\n"
] | [
"2\n",
"3\n"
] | The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1).
In the second sample they are 3, 4 and 5. | 500 | [
{
"input": "3 1 1",
"output": "2"
},
{
"input": "5 2 3",
"output": "3"
},
{
"input": "5 4 0",
"output": "1"
},
{
"input": "6 5 5",
"output": "1"
},
{
"input": "9 4 3",
"output": "4"
},
{
"input": "11 4 6",
"output": "7"
},
{
"input": "13 8 ... | 1,630,986,614 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 6,758,400 | n,a,b=list(map(int,input().split()))
print((a+1)-(n-b-1-1)) | Title: The number of positions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind h... | ```python
n,a,b=list(map(int,input().split()))
print((a+1)-(n-b-1-1))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
343 | B | Alternating Current | PROGRAMMING | 1,600 | [
"data structures",
"greedy",
"implementation"
] | null | null | Mad scientist Mike has just finished constructing a new device to search for extraterrestrial intelligence! He was in such a hurry to launch it for the first time that he plugged in the power wires without giving it a proper glance and started experimenting right away. After a while Mike observed that the wires ended u... | The single line of the input contains a sequence of characters "+" and "-" of length *n* (1<=≤<=*n*<=≤<=100000). The *i*-th (1<=≤<=*i*<=≤<=*n*) position of the sequence contains the character "+", if on the *i*-th step from the wall the "plus" wire runs above the "minus" wire, and the character "-" otherwise. | Print either "Yes" (without the quotes) if the wires can be untangled or "No" (without the quotes) if the wires cannot be untangled. | [
"-++-\n",
"+-\n",
"++\n",
"-\n"
] | [
"Yes\n",
"No\n",
"Yes\n",
"No\n"
] | The first testcase corresponds to the picture in the statement. To untangle the wires, one can first move the "plus" wire lower, thus eliminating the two crosses in the middle, and then draw it under the "minus" wire, eliminating also the remaining two crosses.
In the second testcase the "plus" wire makes one full rev... | 1,000 | [
{
"input": "-++-",
"output": "Yes"
},
{
"input": "+-",
"output": "No"
},
{
"input": "++",
"output": "Yes"
},
{
"input": "-",
"output": "No"
},
{
"input": "+-+-",
"output": "No"
},
{
"input": "-+-",
"output": "No"
},
{
"input": "-++-+--+",
... | 1,605,127,496 | 2,147,483,647 | Python 3 | OK | TESTS | 62 | 310 | 2,048,000 | S=list(input())
charge=[]
top=-1
no_of_notes=0
for i in S:
c=i
if top==-1:
charge.append(c)
top+=1
no_of_notes+=1
else:
if c==charge[top]:
no_of_notes-=1
charge.pop()
top-=1
else:
no_of_notes+=1
... | Title: Alternating Current
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike has just finished constructing a new device to search for extraterrestrial intelligence! He was in such a hurry to launch it for the first time that he plugged in the power wires without giving it... | ```python
S=list(input())
charge=[]
top=-1
no_of_notes=0
for i in S:
c=i
if top==-1:
charge.append(c)
top+=1
no_of_notes+=1
else:
if c==charge[top]:
no_of_notes-=1
charge.pop()
top-=1
else:
no_of_notes+=1... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,688,523,381 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 62 | 0 | n=0
x=list(input())
for i in x:
if i == i.upper():
n+=1
y=len(x)-n
if y>=n:
x=list(map(str.lower,x))
print(*x,sep='')
else:
x=list(map(str.upper,x))
print(*x,sep='') | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
n=0
x=list(input())
for i in x:
if i == i.upper():
n+=1
y=len(x)-n
if y>=n:
x=list(map(str.lower,x))
print(*x,sep='')
else:
x=list(map(str.upper,x))
print(*x,sep='')
``` | 3.9845 | MatrixStudio/Codeforces-Python-Submissions |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single s... | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,667,674,637 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | ans = 0
n = int(input()) + 1
tot = sum(list(map(int, input().split()))) - 1
act = tot % n
for i in range(1, 6):
ans += (((act + i) % n) != 0)
print(ans) | Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the... | ```python
ans = 0
n = int(input()) + 1
tot = sum(list(map(int, input().split()))) - 1
act = tot % n
for i in range(1, 6):
ans += (((act + i) % n) != 0)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
63 | A | Sinking Ship | PROGRAMMING | 900 | [
"implementation",
"sortings",
"strings"
] | A. Sinking Ship | 2 | 256 | The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to *n*) and await further instructions. However, one should evacuate the crew properly, in a stri... | The first line contains an integer *n*, which is the number of people in the crew (1<=≤<=*n*<=≤<=100). Then follow *n* lines. The *i*-th of those lines contains two words — the name of the crew member who is *i*-th in line, and his status on the ship. The words are separated by exactly one space. There are no other spa... | Print *n* lines. The *i*-th of them should contain the name of the crew member who must be the *i*-th one to leave the ship. | [
"6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman\n"
] | [
"Teddy\nAlice\nBob\nJulia\nCharlie\nJack\n"
] | none | 500 | [
{
"input": "6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman",
"output": "Teddy\nAlice\nBob\nJulia\nCharlie\nJack"
},
{
"input": "1\nA captain",
"output": "A"
},
{
"input": "1\nAbcdefjhij captain",
"output": "Abcdefjhij"
},
{
"input": "5\nA captain... | 1,543,351,487 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 186 | 0 | def rename(s):
return "women" if s == "woman" or s== "child" else s
def classify(d):
s,r=input().split()
if not d.get(rename(r)):
d[rename(r)]=[s,]
else:
d[rename(r)].append(s)
return d
n=int(input())
d={}
for i in range(n):
d=classify(d)
for i in ["rat","women","man... | Title: Sinking Ship
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to ... | ```python
def rename(s):
return "women" if s == "woman" or s== "child" else s
def classify(d):
s,r=input().split()
if not d.get(rename(r)):
d[rename(r)]=[s,]
else:
d[rename(r)].append(s)
return d
n=int(input())
d={}
for i in range(n):
d=classify(d)
for i in ["rat","w... | 0 | MatrixStudio/Codeforces-Python-Submissions |
845 | A | Chess Tourney | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by BerMobile. Obviously, organizers should guarantee the win for the team of BerOil.
Thus, organizer... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100).
The second line contains 2·*n* integers *a*1,<=*a*2,<=... *a*2*n* (1<=≤<=*a**i*<=≤<=1000). | If it's possible to divide all 2·*n* players into two teams with *n* people each so that the player from the first team in every pair wins regardless of the results of the drawing, then print "YES". Otherwise print "NO". | [
"2\n1 3 2 4\n",
"1\n3 3\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "2\n1 3 2 4",
"output": "YES"
},
{
"input": "1\n3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 2 2 3 3 3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 1 2 2 2 2 2",
"output": "YES"
},
{
"input": "10\n1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000... | 1,588,392,885 | 2,147,483,647 | PyPy 3 | OK | TESTS | 88 | 155 | 0 | a=int(input())
t= list(map(int,input().split()))
t.sort()
if t[a]>t[a-1]:
print('YES')
else:
print('NO')
| Title: Chess Tourney
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by... | ```python
a=int(input())
t= list(map(int,input().split()))
t.sort()
if t[a]>t[a-1]:
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
742 | A | Arpa’s hard exam and Mehrdad’s naive cheat | PROGRAMMING | 1,000 | [
"implementation",
"math",
"number theory"
] | null | null | There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one question, given *n*, print the last digit of 1378*n*.
Mehrdad has become quite confused and wants you to help him. Please help, al... | The single line of input contains one integer *n* (0<=<=≤<=<=*n*<=<=≤<=<=109). | Print single integer — the last digit of 1378*n*. | [
"1\n",
"2\n"
] | [
"8",
"4"
] | In the first example, last digit of 1378<sup class="upper-index">1</sup> = 1378 is 8.
In the second example, last digit of 1378<sup class="upper-index">2</sup> = 1378·1378 = 1898884 is 4. | 500 | [
{
"input": "1",
"output": "8"
},
{
"input": "2",
"output": "4"
},
{
"input": "1000",
"output": "6"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "6"
},
{
"input": "1000000000",
"output": "6"
},
{
"input": "5",
"output": ... | 1,663,674,012 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 62 | 0 | def solve():
n = int(input())
if n == 0 :
print(1)
return
a = [6,8,4,2]
print(a[n%4])
#for i in range(int(input())):
solve() | Title: Arpa’s hard exam and Mehrdad’s naive cheat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one ques... | ```python
def solve():
n = int(input())
if n == 0 :
print(1)
return
a = [6,8,4,2]
print(a[n%4])
#for i in range(int(input())):
solve()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
991 | D | Bishwock | PROGRAMMING | 1,500 | [
"dp",
"greedy"
] | null | null | Bishwock is a chess figure that consists of three squares resembling an "L-bar". This figure can be rotated by 90, 180 and 270 degrees so it can have four possible states:
Bishwocks don't attack any squares and can even occupy on the adjacent squares as long as they don't occupy the same square.
Vasya has a board wi... | The input contains two nonempty strings that describe Vasya's board. Those strings contain only symbols "0" (zero) that denote the empty squares and symbols "X" (uppercase English letter) that denote the squares occupied by pawns. Strings are nonempty and are of the same length that does not exceed $100$. | Output a single integer — the maximum amount of bishwocks that can be placed onto the given board. | [
"00\n00\n",
"00X00X0XXX0\n0XXX0X00X00\n",
"0X0X0\n0X0X0\n",
"0XXX0\n00000\n"
] | [
"1",
"4",
"0",
"2"
] | none | 1,500 | [
{
"input": "00\n00",
"output": "1"
},
{
"input": "00X00X0XXX0\n0XXX0X00X00",
"output": "4"
},
{
"input": "0X0X0\n0X0X0",
"output": "0"
},
{
"input": "0XXX0\n00000",
"output": "2"
},
{
"input": "0\n0",
"output": "0"
},
{
"input": "0\nX",
"output": "... | 1,549,630,153 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 307,200 | sa = input()
sb = input()
a = []
b = []
k = 0
for i in range(0, len(sa) - 1) :
a.append(sa[i])
for i in range(0, len(sb) - 1) :
b.append(sb[i])
for i in range(0, len(sa) - 2) :
if a[i] == '0' and a[i + 1] == '0' :
if b[i] == '0' :
k += 1
a[i] = a[i + 1] = 'X'
... | Title: Bishwock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bishwock is a chess figure that consists of three squares resembling an "L-bar". This figure can be rotated by 90, 180 and 270 degrees so it can have four possible states:
Bishwocks don't attack any squares and can even occup... | ```python
sa = input()
sb = input()
a = []
b = []
k = 0
for i in range(0, len(sa) - 1) :
a.append(sa[i])
for i in range(0, len(sb) - 1) :
b.append(sb[i])
for i in range(0, len(sa) - 2) :
if a[i] == '0' and a[i + 1] == '0' :
if b[i] == '0' :
k += 1
a[i] = a[i + 1]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
462 | B | Appleman and Card Game | PROGRAMMING | 1,300 | [
"greedy"
] | null | null | Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally, for each Toastman's card *i* you should calculate how much Toastman's cards have the letter equal to lette... | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The next line contains *n* uppercase letters without spaces — the *i*-th letter describes the *i*-th card of the Appleman. | Print a single integer – the answer to the problem. | [
"15 10\nDZFDFZDFDDDDDDF\n",
"6 4\nYJSNPI\n"
] | [
"82\n",
"4\n"
] | In the first test example Toastman can choose nine cards with letter D and one additional card with any letter. For each card with D he will get 9 coins and for the additional card he will get 1 coin. | 1,000 | [
{
"input": "15 10\nDZFDFZDFDDDDDDF",
"output": "82"
},
{
"input": "6 4\nYJSNPI",
"output": "4"
},
{
"input": "5 3\nAOWBY",
"output": "3"
},
{
"input": "1 1\nV",
"output": "1"
},
{
"input": "2 1\nWT",
"output": "1"
},
{
"input": "2 2\nBL",
"output":... | 1,592,200,987 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 307,200 | n,k=map(int,input().split())
s=input()
output,i,temp=0,0,[]
for ch in "ABCDEFGHIJKLMNOPQRSTUVWXYZ":
temp.append(s.count(ch))
temp.sort(reverse=True)
print(temp)
while(k>0):
if(temp[i]<=k):
output+=(temp[i]**2)
k-=temp[i]
else:
output+=(k**2)
k=0
i+=1
print(... | Title: Appleman and Card Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally... | ```python
n,k=map(int,input().split())
s=input()
output,i,temp=0,0,[]
for ch in "ABCDEFGHIJKLMNOPQRSTUVWXYZ":
temp.append(s.count(ch))
temp.sort(reverse=True)
print(temp)
while(k>0):
if(temp[i]<=k):
output+=(temp[i]**2)
k-=temp[i]
else:
output+=(k**2)
k=0
i+... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
888 | B | Buggy Robot | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the cell (*x*,<=*y*) to (*x*,<=*y*<=+<=1); - D — move from (*x*,<=*y*) to (*x*,<=*y*<=-<=1); - L — mo... | The first line contains one number *n* — the length of sequence of commands entered by Ivan (1<=≤<=*n*<=≤<=100).
The second line contains the sequence itself — a string consisting of *n* characters. Each character can be U, D, L or R. | Print the maximum possible number of commands from the sequence the robot could perform to end up in the starting cell. | [
"4\nLDUR\n",
"5\nRRRUU\n",
"6\nLLRRRR\n"
] | [
"4\n",
"0\n",
"4\n"
] | none | 0 | [
{
"input": "4\nLDUR",
"output": "4"
},
{
"input": "5\nRRRUU",
"output": "0"
},
{
"input": "6\nLLRRRR",
"output": "4"
},
{
"input": "88\nLLUUULRDRRURDDLURRLRDRLLRULRUUDDLLLLRRDDURDURRLDURRLDRRRUULDDLRRRDDRRLUULLURDURUDDDDDLDR",
"output": "76"
},
{
"input": "89\nLDL... | 1,679,045,917 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 77 | 0 | input()
i=input()
C=lambda c:i.count(c)
print(min(C('U'),C('D'))*2+min(C('L'),C('R'))*2) | Title: Buggy Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the ce... | ```python
input()
i=input()
C=lambda c:i.count(c)
print(min(C('U'),C('D'))*2+min(C('L'),C('R'))*2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th... | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd pl... | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,627,403,579 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 216 | 20,172,800 | n, m = map(int, input().split(" "))
ls = list(map(int, input().split(" ")))
ls.sort(reverse=True)
# MIN
count = n
_min_ = 0
i = m-1
while count>0:
_min_ += (ls[i]*(ls[i]+1)//2 - max(0,ls[i]-count)*(max(0,ls[i]-count)+1)//2)
count -= ls[i]
i -= 1
if i==-1:
i = m-1
# MAX
_max_ = ... | Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen pl... | ```python
n, m = map(int, input().split(" "))
ls = list(map(int, input().split(" ")))
ls.sort(reverse=True)
# MIN
count = n
_min_ = 0
i = m-1
while count>0:
_min_ += (ls[i]*(ls[i]+1)//2 - max(0,ls[i]-count)*(max(0,ls[i]-count)+1)//2)
count -= ls[i]
i -= 1
if i==-1:
i = m-1
# MAX... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | An atom of element X can exist in *n* distinct states with energies *E*1<=<<=*E*2<=<<=...<=<<=*E**n*. Arkady wants to build a laser on this element, using a three-level scheme. Here is a simplified description of the scheme.
Three distinct states *i*, *j* and *k* are selected, where *i*<=<<=*j*<=<<=*k*... | The first line contains two integers *n* and *U* (3<=≤<=*n*<=≤<=105, 1<=≤<=*U*<=≤<=109) — the number of states and the maximum possible difference between *E**k* and *E**i*.
The second line contains a sequence of integers *E*1,<=*E*2,<=...,<=*E**n* (1<=≤<=*E*1<=<<=*E*2...<=<<=*E**n*<=≤<=109). It is guaranteed th... | If it is not possible to choose three states that satisfy all constraints, print -1.
Otherwise, print one real number η — the maximum possible energy conversion efficiency. Your answer is considered correct its absolute or relative error does not exceed 10<=-<=9.
Formally, let your answer be *a*, and the jury's answe... | [
"4 4\n1 3 5 7\n",
"10 8\n10 13 15 16 17 19 20 22 24 25\n",
"3 1\n2 5 10\n"
] | [
"0.5\n",
"0.875\n",
"-1\n"
] | In the first example choose states 1, 2 and 3, so that the energy conversion efficiency becomes equal to <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/147ae7a830722917b0aa37d064df8eb74cfefb97.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second example choose states 4, 5 a... | 0 | [
{
"input": "4 4\n1 3 5 7",
"output": "0.5"
},
{
"input": "10 8\n10 13 15 16 17 19 20 22 24 25",
"output": "0.875"
},
{
"input": "3 1\n2 5 10",
"output": "-1"
},
{
"input": "5 3\n4 6 8 9 10",
"output": "0.5"
},
{
"input": "10 128\n110 121 140 158 174 188 251 271 27... | 1,521,908,507 | 2,807 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 10 | 1,000 | 14,848,000 | n, u = map(int, input().split())
e = [int(x) for x in input().split()]
mx = -1
for i in range(n - 2):
l = i + 1
r = n
while r - l > 1:
mid = (r + l) // 2
if e[mid] > e[i] + u:
r = mid
else:
l = mid
if l > i + 1:
mx = max(mx, (e[l] - e[i + 1]) / (e[l] - e[i]))
print(mx) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An atom of element X can exist in *n* distinct states with energies *E*1<=<<=*E*2<=<<=...<=<<=*E**n*. Arkady wants to build a laser on this element, using a three-level scheme. Here is a simplified description of the sche... | ```python
n, u = map(int, input().split())
e = [int(x) for x in input().split()]
mx = -1
for i in range(n - 2):
l = i + 1
r = n
while r - l > 1:
mid = (r + l) // 2
if e[mid] > e[i] + u:
r = mid
else:
l = mid
if l > i + 1:
mx = max(mx, (e[l] - e[i + 1]) / (e[l] - e[i]))
print(mx)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
625 | A | Guest From the Past | PROGRAMMING | 1,700 | [
"implementation",
"math"
] | null | null | Kolya Gerasimov loves kefir very much. He lives in year 1984 and knows all the details of buying this delicious drink. One day, as you probably know, he found himself in year 2084, and buying kefir there is much more complicated.
Kolya is hungry, so he went to the nearest milk shop. In 2084 you may buy kefir in a plas... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1018) — the number of rubles Kolya has at the beginning.
Then follow three lines containing integers *a*, *b* and *c* (1<=≤<=*a*<=≤<=1018, 1<=≤<=*c*<=<<=*b*<=≤<=1018) — the cost of one plastic liter bottle, the cost of one glass liter bottle and t... | Print the only integer — maximum number of liters of kefir, that Kolya can drink. | [
"10\n11\n9\n8\n",
"10\n5\n6\n1\n"
] | [
"2\n",
"2\n"
] | In the first sample, Kolya can buy one glass bottle, then return it and buy one more glass bottle. Thus he will drink 2 liters of kefir.
In the second sample, Kolya can buy two plastic bottle and get two liters of kefir, or he can buy one liter glass bottle, then return it and buy one plastic bottle. In both cases he ... | 750 | [
{
"input": "10\n11\n9\n8",
"output": "2"
},
{
"input": "10\n5\n6\n1",
"output": "2"
},
{
"input": "2\n2\n2\n1",
"output": "1"
},
{
"input": "10\n3\n3\n1",
"output": "4"
},
{
"input": "10\n1\n2\n1",
"output": "10"
},
{
"input": "10\n2\n3\n1",
"outpu... | 1,507,494,447 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 10 | 61 | 0 | n = int(input())
a = int(input())
b = int(input())
c = int(input())
if a <= b-c:
print(int(n/a))
else:
result = int((n-c)/(b-c))
result += int(c/a)
print(result) | Title: Guest From the Past
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya Gerasimov loves kefir very much. He lives in year 1984 and knows all the details of buying this delicious drink. One day, as you probably know, he found himself in year 2084, and buying kefir there is much mor... | ```python
n = int(input())
a = int(input())
b = int(input())
c = int(input())
if a <= b-c:
print(int(n/a))
else:
result = int((n-c)/(b-c))
result += int(c/a)
print(result)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
765 | D | Artsem and Saunders | PROGRAMMING | 1,700 | [
"constructive algorithms",
"dsu",
"math"
] | null | null | Artsem has a friend Saunders from University of Chicago. Saunders presented him with the following problem.
Let [*n*] denote the set {1,<=...,<=*n*}. We will also write *f*:<=[*x*]<=→<=[*y*] when a function *f* is defined in integer points 1, ..., *x*, and all its values are integers from 1 to *y*.
Now then, you are ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* space-separated integers — values *f*(1),<=...,<=*f*(*n*) (1<=≤<=*f*(*i*)<=≤<=*n*). | If there is no answer, print one integer -1.
Otherwise, on the first line print the number *m* (1<=≤<=*m*<=≤<=106). On the second line print *n* numbers *g*(1),<=...,<=*g*(*n*). On the third line print *m* numbers *h*(1),<=...,<=*h*(*m*).
If there are several correct answers, you may output any of them. It is guarant... | [
"3\n1 2 3\n",
"3\n2 2 2\n",
"2\n2 1\n"
] | [
"3\n1 2 3\n1 2 3\n",
"1\n1 1 1\n2\n",
"-1\n"
] | none | 2,000 | [
{
"input": "3\n1 2 3",
"output": "3\n1 2 3\n1 2 3"
},
{
"input": "3\n2 2 2",
"output": "1\n1 1 1\n2"
},
{
"input": "2\n2 1",
"output": "-1"
},
{
"input": "1\n1",
"output": "1\n1\n1"
},
{
"input": "2\n2 1",
"output": "-1"
},
{
"input": "2\n2 2",
"ou... | 1,487,065,112 | 5,612 | Python 3 | OK | TESTS | 43 | 265 | 22,323,200 | n = int(input())
line = list(map(int, input().split()))
h = []
sets = set()
mm = dict()
out = False
for i in range(len(line)):
element = line[i]
if line[element - 1] != element:
print(-1)
out = True
break
else:
if element not in sets:
h += [element]
... | Title: Artsem and Saunders
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Artsem has a friend Saunders from University of Chicago. Saunders presented him with the following problem.
Let [*n*] denote the set {1,<=...,<=*n*}. We will also write *f*:<=[*x*]<=→<=[*y*] when a function *f* is ... | ```python
n = int(input())
line = list(map(int, input().split()))
h = []
sets = set()
mm = dict()
out = False
for i in range(len(line)):
element = line[i]
if line[element - 1] != element:
print(-1)
out = True
break
else:
if element not in sets:
h += ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
660 | A | Co-prime Array | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | You are given an array of *n* elements, you must make it a co-prime array in as few moves as possible.
In each move you can insert any positive integral number you want not greater than 109 in any place in the array.
An array is co-prime if any two adjacent numbers of it are co-prime.
In the number theory, two integ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the given array.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*. | Print integer *k* on the first line — the least number of elements needed to add to the array *a* to make it co-prime.
The second line should contain *n*<=+<=*k* integers *a**j* — the elements of the array *a* after adding *k* elements to it. Note that the new array should be co-prime, so any two adjacent values shoul... | [
"3\n2 7 28\n"
] | [
"1\n2 7 9 28\n"
] | none | 0 | [
{
"input": "3\n2 7 28",
"output": "1\n2 7 1 28"
},
{
"input": "1\n1",
"output": "0\n1"
},
{
"input": "1\n548",
"output": "0\n548"
},
{
"input": "1\n963837006",
"output": "0\n963837006"
},
{
"input": "10\n1 1 1 1 1 1 1 1 1 1",
"output": "0\n1 1 1 1 1 1 1 1 1 1"... | 1,545,249,779 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 109 | 0 | def gcd(x, y):
while y != 0:
(x, y) = (y, x % y)
return x
n=int(input())
Ar=[int(x) for x in input().split()]
cnt=0
A=[]
for i in range(n-1):
if (gcd(Ar[i],Ar[i+1]))>1:
cnt+=1
if Ar[i]%2==0 and Ar[i+1]%2==0:
m=Ar[i]+1
if gcd(Ar[i],Ar[i+1])!=1:
... | Title: Co-prime Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array of *n* elements, you must make it a co-prime array in as few moves as possible.
In each move you can insert any positive integral number you want not greater than 109 in any place in the array.
A... | ```python
def gcd(x, y):
while y != 0:
(x, y) = (y, x % y)
return x
n=int(input())
Ar=[int(x) for x in input().split()]
cnt=0
A=[]
for i in range(n-1):
if (gcd(Ar[i],Ar[i+1]))>1:
cnt+=1
if Ar[i]%2==0 and Ar[i+1]%2==0:
m=Ar[i]+1
if gcd(Ar[i],Ar[i+1... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,672,435,888 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 46 | 0 | # -*- coding: utf-8 -*-
"""
Created on Fri Dec 30 22:28:44 2022
@author: R I B
"""
import sys
from math import *
L = []
for i in sys.stdin:
L.append(i)
K= [line.rstrip('\n') for line in L if line]
ch=list(K[0])
ch1=list(K[1])
ch2=''
for i in range(len(ch)):
ch2+=str(int(ch[i]!=ch1[i]))
pri... | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
# -*- coding: utf-8 -*-
"""
Created on Fri Dec 30 22:28:44 2022
@author: R I B
"""
import sys
from math import *
L = []
for i in sys.stdin:
L.append(i)
K= [line.rstrip('\n') for line in L if line]
ch=list(K[0])
ch1=list(K[1])
ch2=''
for i in range(len(ch)):
ch2+=str(int(ch[i]!=ch1... | 3.9885 | MatrixStudio/Codeforces-Python-Submissions |
931 | B | World Cup | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | The last stage of Football World Cup is played using the play-off system.
There are *n* teams left in this stage, they are enumerated from 1 to *n*. Several rounds are held, in each round the remaining teams are sorted in the order of their ids, then the first in this order plays with the second, the third — with the ... | The only line contains three integers *n*, *a* and *b* (2<=≤<=*n*<=≤<=256, 1<=≤<=*a*,<=*b*<=≤<=*n*) — the total number of teams, and the ids of the teams that Arkady is interested in.
It is guaranteed that *n* is such that in each round an even number of team advance, and that *a* and *b* are not equal. | In the only line print "Final!" (without quotes), if teams *a* and *b* can meet in the Final.
Otherwise, print a single integer — the number of the round in which teams *a* and *b* can meet. The round are enumerated from 1. | [
"4 1 2\n",
"8 2 6\n",
"8 7 5\n"
] | [
"1\n",
"Final!\n",
"2\n"
] | In the first example teams 1 and 2 meet in the first round.
In the second example teams 2 and 6 can only meet in the third round, which is the Final, if they win all their opponents in earlier rounds.
In the third example the teams with ids 7 and 5 can meet in the second round, if they win their opponents in the firs... | 1,000 | [
{
"input": "4 1 2",
"output": "1"
},
{
"input": "8 2 6",
"output": "Final!"
},
{
"input": "8 7 5",
"output": "2"
},
{
"input": "128 30 98",
"output": "Final!"
},
{
"input": "256 128 256",
"output": "Final!"
},
{
"input": "256 2 127",
"output": "7"
... | 1,565,534,824 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 124 | 0 | import math
def rec(a,b,count):
if a//2 == b//2:
return count
else:
return rec(a//2,b//2,count+1)
n,a,b = input().split()
res = rec(int(a)-1,int(b)-1,1)
if res==math.log2(int(n)):
print("Final!")
else:
print(res) | Title: World Cup
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The last stage of Football World Cup is played using the play-off system.
There are *n* teams left in this stage, they are enumerated from 1 to *n*. Several rounds are held, in each round the remaining teams are sorted in th... | ```python
import math
def rec(a,b,count):
if a//2 == b//2:
return count
else:
return rec(a//2,b//2,count+1)
n,a,b = input().split()
res = rec(int(a)-1,int(b)-1,1)
if res==math.log2(int(n)):
print("Final!")
else:
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
614 | A | Link/Cut Tree | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agre... | The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109). | Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes). | [
"1 10 2\n",
"2 4 5\n"
] | [
"1 2 4 8 ",
"-1"
] | Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | 500 | [
{
"input": "1 10 2",
"output": "1 2 4 8 "
},
{
"input": "2 4 5",
"output": "-1"
},
{
"input": "18102 43332383920 28554",
"output": "28554 815330916 "
},
{
"input": "19562 31702689720 17701",
"output": "313325401 "
},
{
"input": "11729 55221128400 313",
"output... | 1,561,835,693 | 2,147,483,647 | PyPy 3 | OK | TESTS | 44 | 140 | 0 | l, r, k = [int(x) for x in input().split(' ')]
kek = True
x = 1
ans = ""
while True:
if l <= x <= r:
ans += str(x) + " "
kek = False
x *= k
if x > r: break
if kek:
print(-1)
else:
print(ans) | Title: Link/Cut Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand ... | ```python
l, r, k = [int(x) for x in input().split(' ')]
kek = True
x = 1
ans = ""
while True:
if l <= x <= r:
ans += str(x) + " "
kek = False
x *= k
if x > r: break
if kek:
print(-1)
else:
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,690,723,531 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 62 | 1,945,600 | def max_teams(n, k, participation_counts):
eligible_students = sum(1 for count in participation_counts if count + k <= 5)
return eligible_students // 3
n, k = map(int, input().split())
participation_counts = list(map(int, input().split()))
result = max_teams(n, k, participation_counts)
print(result)
| Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
def max_teams(n, k, participation_counts):
eligible_students = sum(1 for count in participation_counts if count + k <= 5)
return eligible_students // 3
n, k = map(int, input().split())
participation_counts = list(map(int, input().split()))
result = max_teams(n, k, participation_counts)
print... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,637,081,998 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | yakko, wakko=map(int,input().split())
if yakko<wakko:
i=wakko
if yakko>=wakko:
i=yakko
if i==1:
print("1")
elif i==2:
print("5/6")
elif i==3:
print("2/3")
elif i==4 :
print("1/2")
elif i==5 :
print("1/3")
elif i==6 :
print("1/6")
| Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
yakko, wakko=map(int,input().split())
if yakko<wakko:
i=wakko
if yakko>=wakko:
i=yakko
if i==1:
print("1")
elif i==2:
print("5/6")
elif i==3:
print("2/3")
elif i==4 :
print("1/2")
elif i==5 :
print("1/3")
elif i==6 :
print("1/6")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
236 | A | Boy or Girl | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
Bu... | The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters. | If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes). | [
"wjmzbmr\n",
"xiaodao\n",
"sevenkplus\n"
] | [
"CHAT WITH HER!\n",
"IGNORE HIM!\n",
"CHAT WITH HER!\n"
] | For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | 500 | [
{
"input": "wjmzbmr",
"output": "CHAT WITH HER!"
},
{
"input": "xiaodao",
"output": "IGNORE HIM!"
},
{
"input": "sevenkplus",
"output": "CHAT WITH HER!"
},
{
"input": "pezu",
"output": "CHAT WITH HER!"
},
{
"input": "wnemlgppy",
"output": "CHAT WITH HER!"
},... | 1,696,494,302 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 92 | 0 | name=input()
dist_letter=''.join(set(name))
ans=''
if(len(dist_letter)%2==0):
ans='CHAT WITH HER!'
else:
ans='IGNORE HIM!'
print(ans)
| Title: Boy or Girl
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he though... | ```python
name=input()
dist_letter=''.join(set(name))
ans=''
if(len(dist_letter)%2==0):
ans='CHAT WITH HER!'
else:
ans='IGNORE HIM!'
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
278 | B | New Problem | PROGRAMMING | 1,500 | [
"brute force",
"strings"
] | null | null | Coming up with a new problem isn't as easy as many people think. Sometimes it is hard enough to name it. We'll consider a title original if it doesn't occur as a substring in any titles of recent Codeforces problems.
You've got the titles of *n* last problems — the strings, consisting of lowercase English letters. Yo... | The first line contains integer *n* (1<=≤<=*n*<=≤<=30) — the number of titles you've got to consider. Then follow *n* problem titles, one per line. Each title only consists of lowercase English letters (specifically, it doesn't contain any spaces) and has the length from 1 to 20, inclusive. | Print a string, consisting of lowercase English letters — the lexicographically minimum shortest original title. | [
"5\nthreehorses\ngoodsubstrings\nsecret\nprimematrix\nbeautifulyear\n",
"4\naa\nbdefghijklmn\nopqrstuvwxyz\nc\n"
] | [
"j\n",
"ab\n"
] | In the first sample the first 9 letters of the English alphabet (a, b, c, d, e, f, g, h, i) occur in the problem titles, so the answer is letter j.
In the second sample the titles contain 26 English letters, so the shortest original title cannot have length 1. Title aa occurs as a substring in the first title. | 1,000 | [
{
"input": "5\nthreehorses\ngoodsubstrings\nsecret\nprimematrix\nbeautifulyear",
"output": "j"
},
{
"input": "4\naa\nbdefghijklmn\nopqrstuvwxyz\nc",
"output": "ab"
},
{
"input": "1\na",
"output": "b"
},
{
"input": "1\nb",
"output": "a"
},
{
"input": "1\nz",
"o... | 1,666,905,505 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 0 | n = int(input())
arr = []
for _ in range(n):
arr.append(input())
def new_title_brute_force():
obj = {}
for s in arr:
for i in range(len(s)):
for j in range(i + 1, len(s) + 1):
sub_s = s[i:j]
obj[sub_s] = True
word_arr = sorted([k for k i... | Title: New Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Coming up with a new problem isn't as easy as many people think. Sometimes it is hard enough to name it. We'll consider a title original if it doesn't occur as a substring in any titles of recent Codeforces problems.
You'... | ```python
n = int(input())
arr = []
for _ in range(n):
arr.append(input())
def new_title_brute_force():
obj = {}
for s in arr:
for i in range(len(s)):
for j in range(i + 1, len(s) + 1):
sub_s = s[i:j]
obj[sub_s] = True
word_arr = sorted(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,689,153,506 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | s=input()
a=s[0]
b=s[1:]
a=a.upper()
b=b.lower()
print(a+b,sep=" ") | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
s=input()
a=s[0]
b=s[1:]
a=a.upper()
b=b.lower()
print(a+b,sep=" ")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
155 | A | I_love_\%username\% | PROGRAMMING | 800 | [
"brute force"
] | null | null | Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For e... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed ... | Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests. | [
"5\n100 50 200 150 200\n",
"10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n"
] | [
"2\n",
"4\n"
] | In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing. | 500 | [
{
"input": "5\n100 50 200 150 200",
"output": "2"
},
{
"input": "10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242",
"output": "4"
},
{
"input": "1\n6",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "5\n100 36 53 7 81",
"output": "2"
... | 1,675,578,075 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | n=int(input())
if len(set(input()).lower())==26:
print("YES")
else:
print("NO") | Title: I_love_\%username\%
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the re... | ```python
n=int(input())
if len(set(input()).lower())==26:
print("YES")
else:
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
118 | A | String Task | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:
- deletes all the vowels, - inserts a character "." before each consonant, - replaces ... | The first line represents input string of Petya's program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive. | Print the resulting string. It is guaranteed that this string is not empty. | [
"tour\n",
"Codeforces\n",
"aBAcAba\n"
] | [
".t.r\n",
".c.d.f.r.c.s\n",
".b.c.b\n"
] | none | 500 | [
{
"input": "tour",
"output": ".t.r"
},
{
"input": "Codeforces",
"output": ".c.d.f.r.c.s"
},
{
"input": "aBAcAba",
"output": ".b.c.b"
},
{
"input": "obn",
"output": ".b.n"
},
{
"input": "wpwl",
"output": ".w.p.w.l"
},
{
"input": "ggdvq",
"output": "... | 1,694,096,863 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | [print(end='.'+c)for c in input().lower()if~-(c in'aeiouy')] | Title: String Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters... | ```python
[print(end='.'+c)for c in input().lower()if~-(c in'aeiouy')]
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,593,753,297 | 2,147,483,647 | PyPy 3 | OK | TESTS | 31 | 310 | 0 | n = int(input())
A = list(map(int, input().split()))
A = list(set(A))
A.sort()
if len(A) == 1:
print('NO')
else:
print(A[1])
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
n = int(input())
A = list(map(int, input().split()))
A = list(set(A))
A.sort()
if len(A) == 1:
print('NO')
else:
print(A[1])
``` | 3.9225 | MatrixStudio/Codeforces-Python-Submissions |
911 | B | Two Cakes | PROGRAMMING | 1,200 | [
"binary search",
"brute force",
"implementation"
] | null | null | It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into *a* pieces, and the second one — into *b* pieces.
Ivan knows that there will be *n* people at the celebration (including himself), so Ivan has set ... | The first line contains three integers *n*, *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100, 2<=≤<=*n*<=≤<=*a*<=+<=*b*) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively. | Print the maximum possible number *x* such that Ivan can distribute the cake in such a way that each plate will contain at least *x* pieces of cake. | [
"5 2 3\n",
"4 7 10\n"
] | [
"1\n",
"3\n"
] | In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3. | 0 | [
{
"input": "5 2 3",
"output": "1"
},
{
"input": "4 7 10",
"output": "3"
},
{
"input": "100 100 100",
"output": "2"
},
{
"input": "10 100 3",
"output": "3"
},
{
"input": "2 9 29",
"output": "9"
},
{
"input": "4 6 10",
"output": "3"
},
{
"inp... | 1,587,652,485 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 0 | a,b,c=map(int,input().split())
print(min(b,c)//(a//2)) | Title: Two Cakes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into *a* pieces, and the second one — into *b* pieces.
Iv... | ```python
a,b,c=map(int,input().split())
print(min(b,c)//(a//2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,676,609,583 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | x=input()
l=len(x)
i=0
lis=[]
while i<l:
if x[i]=='-':
if x[i+1]=='.':
lis.append(1)
else:
lis.append(2)
i=i+2
elif x[i]=='.':
lis.append(0)
i=i+1
print(lis)
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
x=input()
l=len(x)
i=0
lis=[]
while i<l:
if x[i]=='-':
if x[i+1]=='.':
lis.append(1)
else:
lis.append(2)
i=i+2
elif x[i]=='.':
lis.append(0)
i=i+1
print(lis)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
2 | B | The least round way | PROGRAMMING | 2,000 | [
"dp",
"math"
] | B. The least round way | 2 | 64 | There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down from the current cell; - the way ends in the bottom right cell.
Moreover, if we multiply together all... | The first line contains an integer number *n* (2<=≤<=*n*<=≤<=1000), *n* is the size of the matrix. Then follow *n* lines containing the matrix elements (non-negative integer numbers not exceeding 109). | In the first line print the least number of trailing zeros. In the second line print the correspondent way itself. | [
"3\n1 2 3\n4 5 6\n7 8 9\n"
] | [
"0\nDDRR\n"
] | none | 0 | [
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "0\nDDRR"
},
{
"input": "2\n7 6\n3 8",
"output": "0\nDR"
},
{
"input": "3\n4 10 5\n10 9 4\n6 5 3",
"output": "1\nDRRD"
},
{
"input": "4\n1 1 9 9\n3 4 7 3\n7 9 1 7\n1 7 1 5",
"output": "0\nDDDRRR"
},
{
"input": "5\n8 3... | 1,644,277,011 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 46 | 204,800 | n = int(input())
matrix = []
paths = []
def count_zeros(num):
count = 0
num = str(num)
start = len(num) - 1
while num[start] == '0':
start -= 1
count += 1
return count
def best(val1, val2):
val1_zeros = count_zeros(val1)
val2_zeros = count_zeros(val2)
if... | Title: The least round way
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down fro... | ```python
n = int(input())
matrix = []
paths = []
def count_zeros(num):
count = 0
num = str(num)
start = len(num) - 1
while num[start] == '0':
start -= 1
count += 1
return count
def best(val1, val2):
val1_zeros = count_zeros(val1)
val2_zeros = count_zeros(val... | 0 | MatrixStudio/Codeforces-Python-Submissions |
365 | A | Good Number | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*). | The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the number of *k*-good numbers in *a*. | [
"10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n",
"2 1\n1\n10\n"
] | [
"10\n",
"1\n"
] | none | 500 | [
{
"input": "10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560",
"output": "10"
},
{
"input": "2 1\n1\n10",
"output": "1"
},
{
"input": "1 0\n1000000000",
"output": "1"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
... | 1,641,895,996 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n,k=map(int,input().split()))
c=0
for i in range(n):
a=int(input())
if a in k:
c+=1
else:
c=0
print(c) | Title: Good Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number eve... | ```python
n,k=map(int,input().split()))
c=0
for i in range(n):
a=int(input())
if a in k:
c+=1
else:
c=0
print(c)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
169 | A | Chores | PROGRAMMING | 800 | [
"sortings"
] | null | null | Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of the *i*-th chore equals *h**i*.
As Petya is older, he wants to take the chores with complexit... | The first input line contains three integers *n*,<=*a* and *b* (2<=≤<=*n*<=≤<=2000; *a*,<=*b*<=≥<=1; *a*<=+<=*b*<==<=*n*) — the total number of chores, the number of Petya's chores and the number of Vasya's chores.
The next line contains a sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=109), *h**i* ... | Print the required number of ways to choose an integer value of *x*. If there are no such ways, print 0. | [
"5 2 3\n6 2 3 100 1\n",
"7 3 4\n1 1 9 1 1 1 1\n"
] | [
"3\n",
"0\n"
] | In the first sample the possible values of *x* are 3, 4 or 5.
In the second sample it is impossible to find such *x*, that Petya got 3 chores and Vasya got 4. | 500 | [
{
"input": "5 2 3\n6 2 3 100 1",
"output": "3"
},
{
"input": "7 3 4\n1 1 9 1 1 1 1",
"output": "0"
},
{
"input": "2 1 1\n10 2",
"output": "8"
},
{
"input": "2 1 1\n7 7",
"output": "0"
},
{
"input": "2 1 1\n1 1000000000",
"output": "999999999"
},
{
"inp... | 1,654,351,303 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("k") | Title: Chores
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of th... | ```python
print("k")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
56 | A | Bar | PROGRAMMING | 1,000 | [
"implementation"
] | A. Bar | 2 | 256 | According to Berland laws it is only allowed to sell alcohol to people not younger than 18 years. Vasya's job is to monitor the law's enforcement. Tonight he entered a bar and saw *n* people sitting there. For every one of them Vasya happened to determine either the age or the drink the person is having. Vasya can chec... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) which is the number of the bar's clients. Then follow *n* lines, each describing one visitor. A line either contains his age (an integer from 0 to 1000) or his drink (a string of capital Latin letters from 1 to 100 in length). It is guaranteed that the input da... | Print a single number which is the number of people Vasya should check to guarantee the law enforcement. | [
"5\n18\nVODKA\nCOKE\n19\n17\n"
] | [
"2\n"
] | In the sample test the second and fifth clients should be checked. | 500 | [
{
"input": "5\n18\nVODKA\nCOKE\n19\n17",
"output": "2"
},
{
"input": "2\n2\nGIN",
"output": "2"
},
{
"input": "3\nWHISKEY\n3\nGIN",
"output": "3"
},
{
"input": "4\n813\nIORBQITQXMPTFAEMEQDQIKFGKGOTNKTOSZCBRPXJLUKVLVHJYNRUJXK\nRUM\nRHVRWGODYWWTYZFLFYKCVUFFRTQDINKNWPKFHZBFWBHWI... | 1,641,773,144 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 28 | 218 | 0 | alcohol = ["ABSINTH", "BEER", "BRANDY", "CHAMPAGNE", "GIN", "RUM", "SAKE", "TEQUILA", "VODKA", "WHISKEY", "WINE"]
ans = 0
for _ in range(int(input())):
inp = input()
if inp.isnumeric():
if int(inp) < 18:
ans += 1
elif inp in alcohol:
ans += 1
print(ans)
| Title: Bar
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
According to Berland laws it is only allowed to sell alcohol to people not younger than 18 years. Vasya's job is to monitor the law's enforcement. Tonight he entered a bar and saw *n* people sitting there. For every one of them Vasya h... | ```python
alcohol = ["ABSINTH", "BEER", "BRANDY", "CHAMPAGNE", "GIN", "RUM", "SAKE", "TEQUILA", "VODKA", "WHISKEY", "WINE"]
ans = 0
for _ in range(int(input())):
inp = input()
if inp.isnumeric():
if int(inp) < 18:
ans += 1
elif inp in alcohol:
ans += 1
print(ans)
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,448,824,930 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 154 | 307,200 | s = input()
f_10 = s.find('10')
if f_10 >= 0:
print(s[:f_10 + 1] + s[f_10 + 2:])
else:
print(s[:-1]) | Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
s = input()
f_10 = s.find('10')
if f_10 >= 0:
print(s[:f_10 + 1] + s[f_10 + 2:])
else:
print(s[:-1])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
774 | C | Maximum Number | PROGRAMMING | 1,200 | [
"*special",
"constructive algorithms",
"greedy",
"implementation"
] | null | null | Stepan has the newest electronic device with a display. Different digits can be shown on it. Each digit is shown on a seven-section indicator like it is shown on the picture below.
So, for example, to show the digit 3 on the display, 5 sections must be highlighted; and for the digit 6, 6 sections must be highlighted. ... | The first line contains the integer *n* (2<=≤<=*n*<=≤<=100<=000) — the maximum number of sections which can be highlighted on the display. | Print the maximum integer which can be shown on the display of Stepan's newest device. | [
"2\n",
"3\n"
] | [
"1\n",
"7\n"
] | none | 0 | [
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "7"
},
{
"input": "4",
"output": "11"
},
{
"input": "5",
"output": "71"
},
{
"input": "6",
"output": "111"
},
{
"input": "85651",
"output": "711111111111111111111111111111111111111111111111... | 1,491,408,222 | 1,722 | Python 3 | OK | TESTS | 21 | 218 | 6,348,800 | from math import *
n=int(input())
if n % 2 != 0:
n -= 3;
print (7, end = "")
i = 0
while i < n:
i += 2
print (1, end = "") | Title: Maximum Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Stepan has the newest electronic device with a display. Different digits can be shown on it. Each digit is shown on a seven-section indicator like it is shown on the picture below.
So, for example, to show the digit 3 o... | ```python
from math import *
n=int(input())
if n % 2 != 0:
n -= 3;
print (7, end = "")
i = 0
while i < n:
i += 2
print (1, end = "")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
322 | A | Ciel and Dancing | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. Besides, there is a special rule:
- either the boy in the dancing pair must dance for the first time ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of boys and girls in the dancing room. | In the first line print *k* — the number of songs during which they can dance. Then in the following *k* lines, print the indexes of boys and girls dancing during songs chronologically. You can assume that the boys are indexed from 1 to *n*, and the girls are indexed from 1 to *m*. | [
"2 1\n",
"2 2\n"
] | [
"2\n1 1\n2 1\n",
"3\n1 1\n1 2\n2 2\n"
] | In test case 1, there are 2 boys and 1 girl. We can have 2 dances: the 1st boy and 1st girl (during the first song), the 2nd boy and 1st girl (during the second song).
And in test case 2, we have 2 boys with 2 girls, the answer is 3. | 500 | [
{
"input": "2 1",
"output": "2\n1 1\n2 1"
},
{
"input": "2 2",
"output": "3\n1 1\n1 2\n2 2"
},
{
"input": "1 1",
"output": "1\n1 1"
},
{
"input": "2 3",
"output": "4\n1 1\n1 2\n1 3\n2 3"
},
{
"input": "4 4",
"output": "7\n1 1\n1 2\n1 3\n1 4\n4 4\n3 4\n2 4"
}... | 1,613,751,728 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 154 | 0 | n , m = list(map(int,input().split()))
if(n>1 and m>1):
print(m+n-1)
for i in range(n):
print(i+1 , 1)
for i in range(1,m):
print(1,m+1)
elif(n>1):
print(n)
for i in range(n):
print(i+1,1)
else:
print(m)
for i in range(m):
print(1+1,i) ... | Title: Ciel and Dancing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. B... | ```python
n , m = list(map(int,input().split()))
if(n>1 and m>1):
print(m+n-1)
for i in range(n):
print(i+1 , 1)
for i in range(1,m):
print(1,m+1)
elif(n>1):
print(n)
for i in range(n):
print(i+1,1)
else:
print(m)
for i in range(m):
print... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
235 | A | LCM Challenge | PROGRAMMING | 1,600 | [
"number theory"
] | null | null | Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive integers (they don't have to be distinct) which are not greater than *n*. Can you help me to find ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the *n* mentioned in the statement. | Print a single integer — the maximum possible LCM of three not necessarily distinct positive integers that are not greater than *n*. | [
"9\n",
"7\n"
] | [
"504\n",
"210\n"
] | The least common multiple of some positive integers is the least positive integer which is multiple for each of them.
The result may become very large, 32-bit integer won't be enough. So using 64-bit integers is recommended.
For the last example, we can chose numbers 7, 6, 5 and the LCM of them is 7·6·5 = 210. It is ... | 500 | [
{
"input": "9",
"output": "504"
},
{
"input": "7",
"output": "210"
},
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "60"
},
{
"input": "33",
"output": "32736"
},
{
"input": "21",
"output": ... | 1,590,997,109 | 2,147,483,647 | PyPy 3 | OK | TESTS | 87 | 310 | 0 | import sys
import math as mt
input=sys.stdin.buffer.readline
def lcm(a,b):
return (a*b)//(mt.gcd(a,b))
#t=int(input())
t=1
for __ in range(t):
# s=input()
n=int(input())
if n%2!=0:
ans=(n)*(n-1)*(n-2)
else:
if n%3==0:
ans=(n-1)*(n-2)*(n-3)
else:
... | Title: LCM Challenge
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive... | ```python
import sys
import math as mt
input=sys.stdin.buffer.readline
def lcm(a,b):
return (a*b)//(mt.gcd(a,b))
#t=int(input())
t=1
for __ in range(t):
# s=input()
n=int(input())
if n%2!=0:
ans=(n)*(n-1)*(n-2)
else:
if n%3==0:
ans=(n-1)*(n-2)*(n-3)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Oleg writes down the history of the days he lived. For each day he decides if it was good or bad. Oleg calls a non-empty sequence of days a zebra, if it starts with a bad day, ends with a bad day, and good and bad days are alternating in it. Let us denote bad days as 0 and good days as 1. Then, for example, sequences o... | In the only line of input data there is a non-empty string *s* consisting of characters 0 and 1, which describes the history of Oleg's life. Its length (denoted as |*s*|) does not exceed 200<=000 characters. | If there is a way to divide history into zebra subsequences, in the first line of output you should print an integer *k* (1<=≤<=*k*<=≤<=|*s*|), the resulting number of subsequences. In the *i*-th of following *k* lines first print the integer *l**i* (1<=≤<=*l**i*<=≤<=|*s*|), which is the length of the *i*-th subsequenc... | [
"0010100\n",
"111\n"
] | [
"3\n3 1 3 4\n3 2 5 6\n1 7\n",
"-1\n"
] | none | 0 | [
{
"input": "0010100",
"output": "3\n1 1\n5 2 3 4 5 6\n1 7"
},
{
"input": "111",
"output": "-1"
},
{
"input": "0",
"output": "1\n1 1"
},
{
"input": "1",
"output": "-1"
},
{
"input": "0101010101",
"output": "-1"
},
{
"input": "010100001",
"output": "... | 1,522,067,751 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 1,000 | 23,244,800 | life_log = input()
result = list()
life_length = len(life_log)
def possible():
ones = 0
zeros = 0
for k in life_log:
if int(k) == 1:
zeros -= 1
ones += 1
else:
if ones > 0:
ones -= 1
zeros += 1
if zeros < 0:
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Oleg writes down the history of the days he lived. For each day he decides if it was good or bad. Oleg calls a non-empty sequence of days a zebra, if it starts with a bad day, ends with a bad day, and good and bad days are alterna... | ```python
life_log = input()
result = list()
life_length = len(life_log)
def possible():
ones = 0
zeros = 0
for k in life_log:
if int(k) == 1:
zeros -= 1
ones += 1
else:
if ones > 0:
ones -= 1
zeros += 1
if zeros < 0:... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
688 | B | Lovely Palindromes | PROGRAMMING | 1,000 | [
"constructive algorithms",
"math"
] | null | null | Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is trying to love them too, but only very special and gifted people can understand the beauty behind palindro... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=10100<=000). | Print the *n*-th even-length palindrome number. | [
"1\n",
"10\n"
] | [
"11\n",
"1001\n"
] | The first 10 even-length palindrome numbers are 11, 22, 33, ... , 88, 99 and 1001. | 1,000 | [
{
"input": "1",
"output": "11"
},
{
"input": "10",
"output": "1001"
},
{
"input": "11",
"output": "1111"
},
{
"input": "12",
"output": "1221"
},
{
"input": "100",
"output": "100001"
},
{
"input": "1321",
"output": "13211231"
},
{
"input": "... | 1,646,925,821 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 77 | 3,379,200 | l = []
for i in range(int(input())):
pos, steps = list(map(int, input().split(" ")))
for i in range(1, steps+1):
if steps % 4 == 0:
print(pos)
break
if pos % 2 == 0: pos -= i
else: pos += i
l.append(pos)
print(l) | Title: Lovely Palindromes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is tr... | ```python
l = []
for i in range(int(input())):
pos, steps = list(map(int, input().split(" ")))
for i in range(1, steps+1):
if steps % 4 == 0:
print(pos)
break
if pos % 2 == 0: pos -= i
else: pos += i
l.append(pos)
print(l)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into two halves of the same size *a*1 and *a*2, and string *b* into two halves of the same size ... | The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200<=000 and consists of lowercase English letters. The strings have the same length. | Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. | [
"aaba\nabaa\n",
"aabb\nabab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you should split the first string into strings "aa" and "ba", the second one — into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equival... | 0 | [
{
"input": "aaba\nabaa",
"output": "YES"
},
{
"input": "aabb\nabab",
"output": "NO"
},
{
"input": "a\na",
"output": "YES"
},
{
"input": "a\nb",
"output": "NO"
},
{
"input": "ab\nab",
"output": "YES"
},
{
"input": "ab\nba",
"output": "YES"
},
{
... | 1,604,893,374 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 108 | 307,200 | def equal_string(a, b, length):
if a[:length] == b[:length]:
return True
elif length % 2 == 0:
halfLength = int(length / 2)
if equal_string(a, b[halfLength:], halfLength) and equal_string(a[halfLength:], b, halfLength):
return True
if equal_string(a, b, halfLen... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into t... | ```python
def equal_string(a, b, length):
if a[:length] == b[:length]:
return True
elif length % 2 == 0:
halfLength = int(length / 2)
if equal_string(a, b[halfLength:], halfLength) and equal_string(a[halfLength:], b, halfLength):
return True
if equal_string(a, ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
44 | H | Phone Number | PROGRAMMING | 1,700 | [
"dp"
] | H. Phone Number | 2 | 256 | Alas, finding one's true love is not easy. Masha has been unsuccessful in that yet. Her friend Dasha told Masha about a way to determine the phone number of one's Prince Charming through arithmancy.
The phone number is divined like that. First one needs to write down one's own phone numbers. For example, let's suppos... | The first line contains nonempty sequence consisting of digits from 0 to 9 — Masha's phone number. The sequence length does not exceed 50. | Output the single number — the number of phone numbers Masha will dial. | [
"12345\n",
"09\n"
] | [
"48\n",
"15\n"
] | none | 0 | [
{
"input": "12345",
"output": "48"
},
{
"input": "09",
"output": "15"
},
{
"input": "3",
"output": "9"
},
{
"input": "55",
"output": "14"
},
{
"input": "737",
"output": "23"
},
{
"input": "21583",
"output": "55"
},
{
"input": "33408349",
... | 1,658,322,486 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 122 | 0 | if __name__ == '__main__':
s = input()
dp = [1] * 10
mk = 1
for i in s[1:]:
new_dp = [0] * 10
for j in range(10):
n = j + int(i)
new_dp[n // 2] += dp[j]
if n % 2 != 0:
new_dp[n // 2 + 1] += dp[j]
dp = new_dp
for ... | Title: Phone Number
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Alas, finding one's true love is not easy. Masha has been unsuccessful in that yet. Her friend Dasha told Masha about a way to determine the phone number of one's Prince Charming through arithmancy.
The phone number is divin... | ```python
if __name__ == '__main__':
s = input()
dp = [1] * 10
mk = 1
for i in s[1:]:
new_dp = [0] * 10
for j in range(10):
n = j + int(i)
new_dp[n // 2] += dp[j]
if n % 2 != 0:
new_dp[n // 2 + 1] += dp[j]
dp = new_dp... | 3.9695 | MatrixStudio/Codeforces-Python-Submissions |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,695,650,158 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 61 | 102,400 | #m = 1 5 3 2
#w = 11221
m=list(map(int,input().split()))
w=input()
c=0
for i in w:
c+=m[int(i)-1]
print(c)
| Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
#m = 1 5 3 2
#w = 11221
m=list(map(int,input().split()))
w=input()
c=0
for i in w:
c+=m[int(i)-1]
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
205 | A | Little Elephant and Rozdil | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elephant doesn't like to spend much time on travelling, so for his journey he will choose a town that needs minimum ti... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of cities. The next line contains *n* integers, separated by single spaces: the *i*-th integer represents the time needed to go from town Rozdil to the *i*-th town. The time values are positive integers, not exceeding 109.
You can consider t... | Print the answer on a single line — the number of the town the Little Elephant will go to. If there are multiple cities with minimum travel time, print "Still Rozdil" (without the quotes). | [
"2\n7 4\n",
"7\n7 4 47 100 4 9 12\n"
] | [
"2\n",
"Still Rozdil\n"
] | In the first sample there are only two cities where the Little Elephant can go. The travel time for the first town equals 7, to the second one — 4. The town which is closest to Rodzil (the only one) is the second one, so the answer is 2.
In the second sample the closest cities are cities two and five, the travelling t... | 500 | [
{
"input": "2\n7 4",
"output": "2"
},
{
"input": "7\n7 4 47 100 4 9 12",
"output": "Still Rozdil"
},
{
"input": "1\n47",
"output": "1"
},
{
"input": "2\n1000000000 1000000000",
"output": "Still Rozdil"
},
{
"input": "7\n7 6 5 4 3 2 1",
"output": "7"
},
{
... | 1,666,711,449 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<stdio.h>
int main()
{
int n;
int a[100010];
long long min;
int i,d;
int m,q,e;
while(~scanf("%d",&n))
{
e=0;
scanf("%d",&d);
min=d;
for(i=1;i<n;i++)
{
scanf("%d",&a[i]);
if(a[i]<min)
{
min=a[... | Title: Little Elephant and Rozdil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elepha... | ```python
#include<stdio.h>
int main()
{
int n;
int a[100010];
long long min;
int i,d;
int m,q,e;
while(~scanf("%d",&n))
{
e=0;
scanf("%d",&d);
min=d;
for(i=1;i<n;i++)
{
scanf("%d",&a[i]);
if(a[i]<min)
{
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
467 | B | Fedor and New Game | PROGRAMMING | 1,100 | [
"bitmasks",
"brute force",
"constructive algorithms",
"implementation"
] | null | null | After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».
The game has (*m*<=+<=1) players and *n* types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (*m*<=+<=1). Types of soldiers are numbered from 0 to *n... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*k*<=≤<=*n*<=≤<=20; 1<=≤<=*m*<=≤<=1000).
The *i*-th of the next (*m*<=+<=1) lines contains a single integer *x**i* (1<=≤<=*x**i*<=≤<=2*n*<=-<=1), that describes the *i*-th player's army. We remind you that Fedor is the (*m*<=+<=1)-th player. | Print a single integer — the number of Fedor's potential friends. | [
"7 3 1\n8\n5\n111\n17\n",
"3 3 3\n1\n2\n3\n4\n"
] | [
"0\n",
"3\n"
] | none | 1,000 | [
{
"input": "7 3 1\n8\n5\n111\n17",
"output": "0"
},
{
"input": "3 3 3\n1\n2\n3\n4",
"output": "3"
},
{
"input": "4 2 2\n5\n6\n7",
"output": "2"
},
{
"input": "4 7 4\n9\n10\n5\n12\n4\n12\n7\n10",
"output": "7"
},
{
"input": "2 7 2\n1\n1\n1\n1\n1\n1\n1\n1",
"out... | 1,700,137,382 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | import heapq
from math import gcd,lcm,comb
from collections import Counter
# Shortcut for input
def I(): return int(input())
def MI(): return map(int, input().split())
def MS(): return map(str, input().split())
def LI(): return list(map(int, input().split()))
def LI(): return list(map(int, input().split()))
de... | Title: Fedor and New Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».
The game has (*m*<=+<=1) players and *n* types of soldiers in total. Play... | ```python
import heapq
from math import gcd,lcm,comb
from collections import Counter
# Shortcut for input
def I(): return int(input())
def MI(): return map(int, input().split())
def MS(): return map(str, input().split())
def LI(): return list(map(int, input().split()))
def LI(): return list(map(int, input().spl... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
767 | A | Snacktower | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should b... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*. | Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty. | [
"3\n3 1 2\n",
"5\n4 5 1 2 3\n"
] | [
"3\n \n2 1",
"5 4\n \n \n3 2 1\n"
] | In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right aft... | 500 | [
{
"input": "3\n3 1 2",
"output": "3 \n\n2 1 "
},
{
"input": "5\n4 5 1 2 3",
"output": "5 4 \n\n\n3 2 1 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "10\n5 1 6 2 8 3 4 10 9 7",
"output": "10 \n9 8 \n7 6 5 4 3 2 1... | 1,638,642,949 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | n=int(input())
s=[int(x) for x in input().split()]
stack=[]
i=0
for q in range (n):
if s[i]==max(s):
stack.append(s[i])
s1=s[:i]
s2=str(s1)[1:-1]
stack.append(s2)
s = s[i+1:]
print(*stack)
stack=[]
i = 0
else:
print(*stack)
i+=1
| Title: Snacktower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents sh... | ```python
n=int(input())
s=[int(x) for x in input().split()]
stack=[]
i=0
for q in range (n):
if s[i]==max(s):
stack.append(s[i])
s1=s[:i]
s2=str(s1)[1:-1]
stack.append(s2)
s = s[i+1:]
print(*stack)
stack=[]
i = 0
else:
print(*stack)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
2 | B | The least round way | PROGRAMMING | 2,000 | [
"dp",
"math"
] | B. The least round way | 2 | 64 | There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down from the current cell; - the way ends in the bottom right cell.
Moreover, if we multiply together all... | The first line contains an integer number *n* (2<=≤<=*n*<=≤<=1000), *n* is the size of the matrix. Then follow *n* lines containing the matrix elements (non-negative integer numbers not exceeding 109). | In the first line print the least number of trailing zeros. In the second line print the correspondent way itself. | [
"3\n1 2 3\n4 5 6\n7 8 9\n"
] | [
"0\nDDRR\n"
] | none | 0 | [
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "0\nDDRR"
},
{
"input": "2\n7 6\n3 8",
"output": "0\nDR"
},
{
"input": "3\n4 10 5\n10 9 4\n6 5 3",
"output": "1\nDRRD"
},
{
"input": "4\n1 1 9 9\n3 4 7 3\n7 9 1 7\n1 7 1 5",
"output": "0\nDDDRRR"
},
{
"input": "5\n8 3... | 1,540,670,300 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 171 | 819,200 | import queue
d = int(input())
graph = [[a for a in map(int, input().split())] for _ in range(d)]
# print(graph)
q = queue.PriorityQueue()
q.put((0, ((0, 0), "")))
while True:
cur = q.get()
x = cur[1][0][1]
y = cur[1][0][0]
di = cur[1][1]
o = cur[0]
if (x == d-1) and (y == d-1... | Title: The least round way
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down fro... | ```python
import queue
d = int(input())
graph = [[a for a in map(int, input().split())] for _ in range(d)]
# print(graph)
q = queue.PriorityQueue()
q.put((0, ((0, 0), "")))
while True:
cur = q.get()
x = cur[1][0][1]
y = cur[1][0][0]
di = cur[1][1]
o = cur[0]
if (x == d-1) and... | 0 | MatrixStudio/Codeforces-Python-Submissions |
959 | A | Mahmoud and Ehab and the even-odd game | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a* and subtract it from *n* such that:
- 1<=≤<=*a*<=≤<=*n*. - If it's Mahmoud's turn, *a* has to be even, but if it's Ehab'... | The only line contains an integer *n* (1<=≤<=*n*<=≤<=109), the number at the beginning of the game. | Output "Mahmoud" (without quotes) if Mahmoud wins and "Ehab" (without quotes) otherwise. | [
"1\n",
"2\n"
] | [
"Ehab",
"Mahmoud"
] | In the first sample, Mahmoud can't choose any integer *a* initially because there is no positive even integer less than or equal to 1 so Ehab wins.
In the second sample, Mahmoud has to choose *a* = 2 and subtract it from *n*. It's Ehab's turn and *n* = 0. There is no positive odd integer less than or equal to 0 so Mah... | 500 | [
{
"input": "1",
"output": "Ehab"
},
{
"input": "2",
"output": "Mahmoud"
},
{
"input": "10000",
"output": "Mahmoud"
},
{
"input": "33333",
"output": "Ehab"
},
{
"input": "5",
"output": "Ehab"
},
{
"input": "1000000000",
"output": "Mahmoud"
},
{
... | 1,690,022,338 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | for _ in range(int(input()):
n=int(input())
if n%2==0: print("Mahmoud")
else: print("Ehab")
| Title: Mahmoud and Ehab and the even-odd game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a*... | ```python
for _ in range(int(input()):
n=int(input())
if n%2==0: print("Mahmoud")
else: print("Ehab")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
459 | B | Pashmak and Flowers | PROGRAMMING | 1,300 | [
"combinatorics",
"implementation",
"sortings"
] | null | null | Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have the two most beautiful flowers necessarily. She wants to have those pairs of flowers that their beauty diff... | The first line of the input contains *n* (2<=≤<=*n*<=≤<=2·105). In the next line there are *n* space-separated integers *b*1, *b*2, ..., *b**n* (1<=≤<=*b**i*<=≤<=109). | The only line of output should contain two integers. The maximum beauty difference and the number of ways this may happen, respectively. | [
"2\n1 2\n",
"3\n1 4 5\n",
"5\n3 1 2 3 1\n"
] | [
"1 1",
"4 1",
"2 4"
] | In the third sample the maximum beauty difference is 2 and there are 4 ways to do this:
1. choosing the first and the second flowers; 1. choosing the first and the fifth flowers; 1. choosing the fourth and the second flowers; 1. choosing the fourth and the fifth flowers. | 500 | [
{
"input": "2\n1 2",
"output": "1 1"
},
{
"input": "3\n1 4 5",
"output": "4 1"
},
{
"input": "5\n3 1 2 3 1",
"output": "2 4"
},
{
"input": "2\n1 1",
"output": "0 1"
},
{
"input": "3\n1 1 1",
"output": "0 3"
},
{
"input": "4\n1 1 1 1",
"output": "0 ... | 1,660,500,457 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 124 | 17,100,800 | import math
n=int(input())
b=[int(i) for i in input().split()]
maxi=max(b)
mini=min(b)
if mini!=maxi:
print(maxi-mini, b.count(maxi)*b.count(mini))
else:
print(maxi-mini, (b.count(maxi)//2)*math.ceil(b.count(mini)/2)) | Title: Pashmak and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have th... | ```python
import math
n=int(input())
b=[int(i) for i in input().split()]
maxi=max(b)
mini=min(b)
if mini!=maxi:
print(maxi-mini, b.count(maxi)*b.count(mini))
else:
print(maxi-mini, (b.count(maxi)//2)*math.ceil(b.count(mini)/2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
835 | B | The number on the board | PROGRAMMING | 1,100 | [
"greedy"
] | null | null | Some natural number was written on the board. Its sum of digits was not less than *k*. But you were distracted a bit, and someone changed this number to *n*, replacing some digits with others. It's known that the length of the number didn't change.
You have to find the minimum number of digits in which these two numbe... | The first line contains integer *k* (1<=≤<=*k*<=≤<=109).
The second line contains integer *n* (1<=≤<=*n*<=<<=10100000).
There are no leading zeros in *n*. It's guaranteed that this situation is possible. | Print the minimum number of digits in which the initial number and *n* can differ. | [
"3\n11\n",
"3\n99\n"
] | [
"1\n",
"0\n"
] | In the first example, the initial number could be 12.
In the second example the sum of the digits of *n* is not less than *k*. The initial number could be equal to *n*. | 750 | [
{
"input": "3\n11",
"output": "1"
},
{
"input": "3\n99",
"output": "0"
},
{
"input": "10\n5205602270",
"output": "0"
},
{
"input": "70\n3326631213",
"output": "6"
},
{
"input": "200\n100000001000000000000000000001000000000000000100000100000000000000000000000000000... | 1,615,023,028 | 2,147,483,647 | PyPy 3 | OK | TESTS | 48 | 108 | 3,993,600 | import sys
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def minput(): return map(int, input().split())
def listinput(): return list(map(int, input()))
k=iinput()
n=listinput()
n.sort()
i=0
s=sum(n)
while s<k:
s+=9-n[i]
i+=1
print(i) | Title: The number on the board
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some natural number was written on the board. Its sum of digits was not less than *k*. But you were distracted a bit, and someone changed this number to *n*, replacing some digits with others. It's known that th... | ```python
import sys
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def minput(): return map(int, input().split())
def listinput(): return list(map(int, input()))
k=iinput()
n=listinput()
n.sort()
i=0
s=sum(n)
while s<k:
s+=9-n[i]
i+=1
print(i)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
761 | A | Dasha and Stairs | PROGRAMMING | 1,000 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | On her way to programming school tiger Dasha faced her first test — a huge staircase!
The steps were numbered from one to infinity. As we know, tigers are very fond of all striped things, it is possible that it has something to do with their color. So on some interval of her way she calculated two values — the number ... | In the only line you are given two integers *a*, *b* (0<=≤<=*a*,<=*b*<=≤<=100) — the number of even and odd steps, accordingly. | In the only line print "YES", if the interval of steps described above exists, and "NO" otherwise. | [
"2 3\n",
"3 1\n"
] | [
"YES\n",
"NO\n"
] | In the first example one of suitable intervals is from 1 to 5. The interval contains two even steps — 2 and 4, and three odd: 1, 3 and 5. | 500 | [
{
"input": "2 3",
"output": "YES"
},
{
"input": "3 1",
"output": "NO"
},
{
"input": "5 4",
"output": "YES"
},
{
"input": "9 9",
"output": "YES"
},
{
"input": "85 95",
"output": "NO"
},
{
"input": "0 1",
"output": "YES"
},
{
"input": "89 25"... | 1,582,047,016 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 11 | 93 | 0 | a,b=map(int,input().split())
if a-b==-1 or a-b==1 or a==b:
print("YES")
else:
print("NO")
| Title: Dasha and Stairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On her way to programming school tiger Dasha faced her first test — a huge staircase!
The steps were numbered from one to infinity. As we know, tigers are very fond of all striped things, it is possible that it has so... | ```python
a,b=map(int,input().split())
if a-b==-1 or a-b==1 or a==b:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,674,565,577 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | x = int(input())
if (x%2==0):
print(x//x)
else:
print(x//2) | Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
x = int(input())
if (x%2==0):
print(x//x)
else:
print(x//2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
689 | C | Mike and Chocolate Thieves | PROGRAMMING | 1,700 | [
"binary search",
"combinatorics",
"math"
] | null | null | Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly *k* times more than the previous... | The single line of input contains the integer *m* (1<=≤<=*m*<=≤<=1015) — the number of ways the thieves might steal the chocolates, as rumours say. | Print the only integer *n* — the maximum amount of chocolates that thieves' bags can carry. If there are more than one *n* satisfying the rumors, print the smallest one.
If there is no such *n* for a false-rumoured *m*, print <=-<=1. | [
"1\n",
"8\n",
"10\n"
] | [
"8\n",
"54\n",
"-1\n"
] | In the first sample case the smallest *n* that leads to exactly one way of stealing chocolates is *n* = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest *n* that leads to exactly 8 ways is *n* = 54 with the po... | 1,500 | [
{
"input": "1",
"output": "8"
},
{
"input": "8",
"output": "54"
},
{
"input": "10",
"output": "-1"
},
{
"input": "27",
"output": "152"
},
{
"input": "28206",
"output": "139840"
},
{
"input": "32",
"output": "184"
},
{
"input": "115",
"o... | 1,608,428,607 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | t = [k ** 3 for k in range(2, 100000)]
s = m = int(input())
a, b = 1, 9 * m
while a < b:
c = (a + b) // 2
d = sum(int(c / k) for k in t)
if d < m: a = c + 1
else: s, b = d, c
print(a if s == m else -1)
| Title: Mike and Chocolate Thieves
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thi... | ```python
t = [k ** 3 for k in range(2, 100000)]
s = m = int(input())
a, b = 1, 9 * m
while a < b:
c = (a + b) // 2
d = sum(int(c / k) for k in t)
if d < m: a = c + 1
else: s, b = d, c
print(a if s == m else -1)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
23 | B | Party | PROGRAMMING | 1,600 | [
"constructive algorithms",
"graphs",
"math"
] | B. Party | 2 | 256 | *n* people came to a party. Then those, who had no friends among people at the party, left. Then those, who had exactly 1 friend among those who stayed, left as well. Then those, who had exactly 2,<=3,<=...,<=*n*<=-<=1 friends among those who stayed by the moment of their leaving, did the same.
What is the maximum amo... | The first input line contains one number *t* — amount of tests (1<=≤<=*t*<=≤<=105). Each of the following *t* lines contains one integer number *n* (1<=≤<=*n*<=≤<=105). | For each test output in a separate line one number — the maximum amount of people that could stay in the end. | [
"1\n3\n"
] | [
"1\n"
] | none | 0 | [
{
"input": "1\n3",
"output": "1"
}
] | 1,573,982,369 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 1,870 | 0 | t=int(input())
for i in range(0,t):
n=int(input())
print(n//2)
| Title: Party
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
*n* people came to a party. Then those, who had no friends among people at the party, left. Then those, who had exactly 1 friend among those who stayed, left as well. Then those, who had exactly 2,<=3,<=...,<=*n*<=-<=1 friends among ... | ```python
t=int(input())
for i in range(0,t):
n=int(input())
print(n//2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
296 | A | Yaroslav and Permutations | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) — the array elements. | In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise. | [
"1\n1\n",
"3\n1 1 2\n",
"4\n7 7 7 7\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs. | 500 | [
{
"input": "1\n1",
"output": "YES"
},
{
"input": "3\n1 1 2",
"output": "YES"
},
{
"input": "4\n7 7 7 7",
"output": "NO"
},
{
"input": "4\n479 170 465 146",
"output": "YES"
},
{
"input": "5\n996 437 605 996 293",
"output": "YES"
},
{
"input": "6\n727 53... | 1,675,708,317 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n = input()
x = [int(i) for i in input().split()]
if len(x) == 1 :
print("YES")
maxx = 0
sett = set(x)
for i in sett :
if x.count(i) > maxx :
maxx = x.count(i)
e = i
if maxx > len(x)/2 +1 :
print("NO")
else :
print("YES") | Title: Yaroslav and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would... | ```python
n = input()
x = [int(i) for i in input().split()]
if len(x) == 1 :
print("YES")
maxx = 0
sett = set(x)
for i in sett :
if x.count(i) > maxx :
maxx = x.count(i)
e = i
if maxx > len(x)/2 +1 :
print("NO")
else :
print("YES")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
1,008 | A | Romaji | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant... | The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters. | Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"sumimasen\n",
"ninja\n",
"codeforces\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | 500 | [
{
"input": "sumimasen",
"output": "YES"
},
{
"input": "ninja",
"output": "YES"
},
{
"input": "codeforces",
"output": "NO"
},
{
"input": "auuaoonntanonnuewannnnpuuinniwoonennyolonnnvienonpoujinndinunnenannmuveoiuuhikucuziuhunnnmunzancenen",
"output": "YES"
},
{
"in... | 1,672,860,856 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | string = input()
l = len(string)
n = "n"
vowel = ['a', 'i', 'o', 'u','e']
for i in range(l):
if string[i] in vowel or string[i] in n:
continue
else:
if i = l-1:
print("NO")
exit(0)
else:
if string[i+1] not in vowel:
print("NO")
print("YES... | Title: Romaji
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after eve... | ```python
string = input()
l = len(string)
n = "n"
vowel = ['a', 'i', 'o', 'u','e']
for i in range(l):
if string[i] in vowel or string[i] in n:
continue
else:
if i = l-1:
print("NO")
exit(0)
else:
if string[i+1] not in vowel:
print("NO")
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
835 | B | The number on the board | PROGRAMMING | 1,100 | [
"greedy"
] | null | null | Some natural number was written on the board. Its sum of digits was not less than *k*. But you were distracted a bit, and someone changed this number to *n*, replacing some digits with others. It's known that the length of the number didn't change.
You have to find the minimum number of digits in which these two numbe... | The first line contains integer *k* (1<=≤<=*k*<=≤<=109).
The second line contains integer *n* (1<=≤<=*n*<=<<=10100000).
There are no leading zeros in *n*. It's guaranteed that this situation is possible. | Print the minimum number of digits in which the initial number and *n* can differ. | [
"3\n11\n",
"3\n99\n"
] | [
"1\n",
"0\n"
] | In the first example, the initial number could be 12.
In the second example the sum of the digits of *n* is not less than *k*. The initial number could be equal to *n*. | 750 | [
{
"input": "3\n11",
"output": "1"
},
{
"input": "3\n99",
"output": "0"
},
{
"input": "10\n5205602270",
"output": "0"
},
{
"input": "70\n3326631213",
"output": "6"
},
{
"input": "200\n100000001000000000000000000001000000000000000100000100000000000000000000000000000... | 1,587,471,096 | 2,147,483,647 | PyPy 3 | OK | TESTS | 48 | 170 | 5,836,800 | n=int(input())
t=list(input())
g=[int(i) for i in t]
p=sum(g)
g.sort()
if p >= n:
print(0)
else:
for k in range(len(g)):
p= (p+9)-g[k]
if p>=n:
print(k+1)
break
| Title: The number on the board
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some natural number was written on the board. Its sum of digits was not less than *k*. But you were distracted a bit, and someone changed this number to *n*, replacing some digits with others. It's known that th... | ```python
n=int(input())
t=list(input())
g=[int(i) for i in t]
p=sum(g)
g.sort()
if p >= n:
print(0)
else:
for k in range(len(g)):
p= (p+9)-g[k]
if p>=n:
print(k+1)
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
703 | A | Mishka and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they started playing the game.
Rules of the game are very simple: at first number of rounds *n* is defined.... | The first line of the input contains single integer *n* *n* (1<=≤<=*n*<=≤<=100) — the number of game rounds.
The next *n* lines contains rounds description. *i*-th of them contains pair of integers *m**i* and *c**i* (1<=≤<=*m**i*,<=<=*c**i*<=≤<=6) — values on dice upper face after Mishka's and Chris' throws in *i*-th ... | If Mishka is the winner of the game, print "Mishka" (without quotes) in the only line.
If Chris is the winner of the game, print "Chris" (without quotes) in the only line.
If the result of the game is draw, print "Friendship is magic!^^" (without quotes) in the only line. | [
"3\n3 5\n2 1\n4 2\n",
"2\n6 1\n1 6\n",
"3\n1 5\n3 3\n2 2\n"
] | [
"Mishka",
"Friendship is magic!^^",
"Chris"
] | In the first sample case Mishka loses the first round, but wins second and third rounds and thus she is the winner of the game.
In the second sample case Mishka wins the first round, Chris wins the second round, and the game ends with draw with score 1:1.
In the third sample case Chris wins the first round, but there... | 500 | [
{
"input": "3\n3 5\n2 1\n4 2",
"output": "Mishka"
},
{
"input": "2\n6 1\n1 6",
"output": "Friendship is magic!^^"
},
{
"input": "3\n1 5\n3 3\n2 2",
"output": "Chris"
},
{
"input": "6\n4 1\n4 2\n5 3\n5 1\n5 3\n4 1",
"output": "Mishka"
},
{
"input": "8\n2 4\n1 4\n1 ... | 1,667,467,438 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | # Wadea #
s = int(input())
Mishka = 0
Chris = 0
for i in range(s):
s1 = input().split()
m = int(s1[0])
c = (s1[-1])
if m > c:
Mishka += 1
elif m < c:
Chris += 1
elif m == c:
Mishka += 0
Chris += 0
if Mishka > Chris:
print("Mishka")
elif Mish... | Title: Mishka and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they st... | ```python
# Wadea #
s = int(input())
Mishka = 0
Chris = 0
for i in range(s):
s1 = input().split()
m = int(s1[0])
c = (s1[-1])
if m > c:
Mishka += 1
elif m < c:
Chris += 1
elif m == c:
Mishka += 0
Chris += 0
if Mishka > Chris:
print("Mishka")
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
208 | A | Dubstep | PROGRAMMING | 900 | [
"strings"
] | null | null | Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain nu... | The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the son... | Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space. | [
"WUBWUBABCWUB\n",
"WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n"
] | [
"ABC ",
"WE ARE THE CHAMPIONS MY FRIEND "
] | In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE... | 500 | [
{
"input": "WUBWUBABCWUB",
"output": "ABC "
},
{
"input": "WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB",
"output": "WE ARE THE CHAMPIONS MY FRIEND "
},
{
"input": "WUBWUBWUBSR",
"output": "SR "
},
{
"input": "RWUBWUBWUBLWUB",
"output": "R L "
},
{
"input": "... | 1,697,567,127 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | # Not Completed
n = str(input())
wordList = list(n.split("WUB"))
ans = ""
for i in wordList:
if i != "":
ans += i + " "
print(ans)
| Title: Dubstep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consist... | ```python
# Not Completed
n = str(input())
wordList = list(n.split("WUB"))
ans = ""
for i in wordList:
if i != "":
ans += i + " "
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,633,019,963 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n = int(input())
a = [int(i) for i in input().split()]
m = min(a)
k = m
flag = False
for i in a:
if i > m:
k = min(k, i)
flag = True
if flag:
print(k)
else:
print('NO')
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
n = int(input())
a = [int(i) for i in input().split()]
m = min(a)
k = m
flag = False
for i in a:
if i > m:
k = min(k, i)
flag = True
if flag:
print(k)
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
287 | B | Pipeline | PROGRAMMING | 1,700 | [
"binary search",
"math"
] | null | null | Vova, the Ultimate Thule new shaman, wants to build a pipeline. As there are exactly *n* houses in Ultimate Thule, Vova wants the city to have exactly *n* pipes, each such pipe should be connected to the water supply. A pipe can be connected to the water supply if there's water flowing out of it. Initially Vova has onl... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=1018, 2<=≤<=*k*<=≤<=109).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | Print a single integer — the minimum number of splitters needed to build the pipeline. If it is impossible to build a pipeline with the given splitters, print -1. | [
"4 3\n",
"5 5\n",
"8 4\n"
] | [
"2\n",
"1\n",
"-1\n"
] | none | 1,500 | [
{
"input": "4 3",
"output": "2"
},
{
"input": "5 5",
"output": "1"
},
{
"input": "8 4",
"output": "-1"
},
{
"input": "1000000000000000000 1000000000",
"output": "-1"
},
{
"input": "499999998500000001 1000000000",
"output": "999955279"
},
{
"input": "49... | 1,689,160,370 | 2,147,483,647 | Python 3 | OK | TESTS | 22 | 46 | 0 | def sum(n):
return (n * (n+1)) // 2
def sum_range(s, e):
if s <= 1:
return sum(e)
return sum(e) - sum(s-1)
def splitter(k, n):
start = 1
end = k
while start < end:
md = (start + end) // 2
s = sum_range(md, k)
if s == n:
return k - md +... | Title: Pipeline
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vova, the Ultimate Thule new shaman, wants to build a pipeline. As there are exactly *n* houses in Ultimate Thule, Vova wants the city to have exactly *n* pipes, each such pipe should be connected to the water supply. A pipe c... | ```python
def sum(n):
return (n * (n+1)) // 2
def sum_range(s, e):
if s <= 1:
return sum(e)
return sum(e) - sum(s-1)
def splitter(k, n):
start = 1
end = k
while start < end:
md = (start + end) // 2
s = sum_range(md, k)
if s == n:
retur... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
987 | A | Infinity Gauntlet | PROGRAMMING | 800 | [
"implementation"
] | null | null | You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the Soul Gem of orange color, - the Reality Gem of red color, - the Mind Gem of yellow color.
Using colors... | In the first line of input there is one integer $n$ ($0 \le n \le 6$) — the number of Gems in Infinity Gauntlet.
In next $n$ lines there are colors of Gems you saw. Words used for colors are: purple, green, blue, orange, red, yellow. It is guaranteed that all the colors are distinct. All colors are given in lowercase ... | In the first line output one integer $m$ ($0 \le m \le 6$) — the number of absent Gems.
Then in $m$ lines print the names of absent Gems, each on its own line. Words used for names are: Power, Time, Space, Soul, Reality, Mind. Names can be printed in any order. Keep the first letter uppercase, others lowercase. | [
"4\nred\npurple\nyellow\norange\n",
"0\n"
] | [
"2\nSpace\nTime\n",
"6\nTime\nMind\nSoul\nPower\nReality\nSpace\n"
] | In the first sample Thanos already has Reality, Power, Mind and Soul Gems, so he needs two more: Time and Space.
In the second sample Thanos doesn't have any Gems, so he needs all six. | 500 | [
{
"input": "4\nred\npurple\nyellow\norange",
"output": "2\nSpace\nTime"
},
{
"input": "0",
"output": "6\nMind\nSpace\nPower\nTime\nReality\nSoul"
},
{
"input": "6\npurple\nblue\nyellow\nred\ngreen\norange",
"output": "0"
},
{
"input": "1\npurple",
"output": "5\nTime\nReal... | 1,615,403,147 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 307,200 | """"the Power Gem of purple color,
the Time Gem of green color,
the Space Gem of blue color,
the Soul Gem of orange color,
the Reality Gem of red color,
the Mind Gem of yellow color.
"""
col = ["p", "g", "b,", "o", "r", "y"]
gem = ["Power", "Time", "Space", "Soul", "Reality", "Mind"]
cases = int(input())
x ... | Title: Infinity Gauntlet
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the So... | ```python
""""the Power Gem of purple color,
the Time Gem of green color,
the Space Gem of blue color,
the Soul Gem of orange color,
the Reality Gem of red color,
the Mind Gem of yellow color.
"""
col = ["p", "g", "b,", "o", "r", "y"]
gem = ["Power", "Time", "Space", "Soul", "Reality", "Mind"]
cases = int(in... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another c... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follo... | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,696,339,110 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 405 | 13,926,400 | n = int(input())
nums = list(map(int,input().split()))
counter = 0
while counter < len(nums):
if counter == 0 or counter == len(nums) - 1:
if counter == 0:
print(abs(nums[counter] - nums[counter+1]), abs(nums[counter] - nums[-1]))
else:
print(abs(nums[counter] - num... | Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love... | ```python
n = int(input())
nums = list(map(int,input().split()))
counter = 0
while counter < len(nums):
if counter == 0 or counter == len(nums) - 1:
if counter == 0:
print(abs(nums[counter] - nums[counter+1]), abs(nums[counter] - nums[-1]))
else:
print(abs(nums[coun... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
895 | A | Pizza Separation | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | Students Vasya and Petya are studying at the BSU (Byteland State University). At one of the breaks they decided to order a pizza. In this problem pizza is a circle of some radius. The pizza was delivered already cut into *n* pieces. The *i*-th piece is a sector of angle equal to *a**i*. Vasya and Petya want to divide a... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=360) — the number of pieces into which the delivered pizza was cut.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=360) — the angles of the sectors into which the pizza was cut. The sum of all *a**i* is 360. | Print one integer — the minimal difference between angles of sectors that will go to Vasya and Petya. | [
"4\n90 90 90 90\n",
"3\n100 100 160\n",
"1\n360\n",
"4\n170 30 150 10\n"
] | [
"0\n",
"40\n",
"360\n",
"0\n"
] | In first sample Vasya can take 1 and 2 pieces, Petya can take 3 and 4 pieces. Then the answer is |(90 + 90) - (90 + 90)| = 0.
In third sample there is only one piece of pizza that can be taken by only one from Vasya and Petya. So the answer is |360 - 0| = 360.
In fourth sample Vasya can take 1 and 4 pieces, then Pety... | 500 | [
{
"input": "4\n90 90 90 90",
"output": "0"
},
{
"input": "3\n100 100 160",
"output": "40"
},
{
"input": "1\n360",
"output": "360"
},
{
"input": "4\n170 30 150 10",
"output": "0"
},
{
"input": "5\n10 10 10 10 320",
"output": "280"
},
{
"input": "8\n45 4... | 1,511,986,097 | 2,147,483,647 | Python 3 | OK | TESTS | 93 | 187 | 7,065,600 | n = int(input())
a = list(map(int, input().split()))
sectorSize = [sum(a[l:r]) for l in range(n) for r in range(l + 1, n)]
differenceBetweenSectorAndRest = [360] + [2*abs(180 - sectorSize[i]) for i in range(len(sectorSize))]
print(min(differenceBetweenSectorAndRest))
| Title: Pizza Separation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Students Vasya and Petya are studying at the BSU (Byteland State University). At one of the breaks they decided to order a pizza. In this problem pizza is a circle of some radius. The pizza was delivered already cut in... | ```python
n = int(input())
a = list(map(int, input().split()))
sectorSize = [sum(a[l:r]) for l in range(n) for r in range(l + 1, n)]
differenceBetweenSectorAndRest = [360] + [2*abs(180 - sectorSize[i]) for i in range(len(sectorSize))]
print(min(differenceBetweenSectorAndRest))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a*... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,698,409,511 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 30 | 0 | def getMax(s):
return max([ i for i in s])
n = int(input())
l = [i for i in input().split()]
s = ""
for i in l:s+=i
maxSum = 0
m = None
subs = [s]
while subs!=[]:
newSubs = []
for i in range(len(subs)):
if len(subs)==0:continue
m = getMax(subs[i])
t = subs[i].split(m)
... | Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make ... | ```python
def getMax(s):
return max([ i for i in s])
n = int(input())
l = [i for i in input().split()]
s = ""
for i in l:s+=i
maxSum = 0
m = None
subs = [s]
while subs!=[]:
newSubs = []
for i in range(len(subs)):
if len(subs)==0:continue
m = getMax(subs[i])
t = subs[i].... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
275 | B | Convex Shape | PROGRAMMING | 1,700 | [
"constructive algorithms",
"implementation"
] | null | null | Consider an *n*<=×<=*m* grid. Initially all the cells of the grid are colored white. Lenny has painted some of the cells (at least one) black. We call a painted grid convex if one can walk from any black cell to any another black cell using a path of side-adjacent black cells changing his direction at most once during ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the size of the grid. Each of the next *n* lines contains *m* characters "B" or "W". Character "B" denotes a black cell of the grid and "W" denotes a white cell of the grid.
It's guaranteed that the grid has at least one black cel... | On the only line of the output print "YES" if the grid is convex, otherwise print "NO". Do not print quotes. | [
"3 4\nWWBW\nBWWW\nWWWB\n",
"3 1\nB\nB\nW\n"
] | [
"NO\n",
"YES\n"
] | none | 1,000 | [
{
"input": "3 4\nWWBW\nBWWW\nWWWB",
"output": "NO"
},
{
"input": "3 1\nB\nB\nW",
"output": "YES"
},
{
"input": "1 1\nB",
"output": "YES"
},
{
"input": "1 2\nBB",
"output": "YES"
},
{
"input": "2 1\nB\nB",
"output": "YES"
},
{
"input": "1 2\nBW",
"o... | 1,634,544,127 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 10 | 122 | 512,000 | def isConsecutiveRow(s):
if s[0]=="B":
c=1
e=0
start.append(0)
else:
c=0
for j in range(1,len(s)):
if s[j]=="B":
c+=1
if c==1:
start.append(j)
elif c>1 and s[j-1]!="B":
return False
... | Title: Convex Shape
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider an *n*<=×<=*m* grid. Initially all the cells of the grid are colored white. Lenny has painted some of the cells (at least one) black. We call a painted grid convex if one can walk from any black cell to any anothe... | ```python
def isConsecutiveRow(s):
if s[0]=="B":
c=1
e=0
start.append(0)
else:
c=0
for j in range(1,len(s)):
if s[j]=="B":
c+=1
if c==1:
start.append(j)
elif c>1 and s[j-1]!="B":
return F... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | There is a rectangular grid of *n* rows of *m* initially-white cells each.
Arkady performed a certain number (possibly zero) of operations on it. In the *i*-th operation, a non-empty subset of rows *R**i* and a non-empty subset of columns *C**i* are chosen. For each row *r* in *R**i* and each column *c* in *C**i*, the... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the number of rows and columns of the grid, respectively.
Each of the following *n* lines contains a string of *m* characters, each being either '.' (denoting a white cell) or '#' (denoting a black cell), representing the desir... | If the given grid can be achieved by any valid sequence of operations, output "Yes"; otherwise output "No" (both without quotes).
You can print each character in any case (upper or lower). | [
"5 8\n.#.#..#.\n.....#..\n.#.#..#.\n#.#....#\n.....#..\n",
"5 5\n..#..\n..#..\n#####\n..#..\n..#..\n",
"5 9\n........#\n#........\n..##.#...\n.......#.\n....#.#.#\n"
] | [
"Yes\n",
"No\n",
"No\n"
] | For the first example, the desired setup can be produced by 3 operations, as is shown below.
For the second example, the desired setup cannot be produced, since in order to colour the center row, the third row and all columns must be selected in one operation, but after that no column can be selected again, hence it w... | 0 | [
{
"input": "5 8\n.#.#..#.\n.....#..\n.#.#..#.\n#.#....#\n.....#..",
"output": "Yes"
},
{
"input": "5 5\n..#..\n..#..\n#####\n..#..\n..#..",
"output": "No"
},
{
"input": "5 9\n........#\n#........\n..##.#...\n.......#.\n....#.#.#",
"output": "No"
},
{
"input": "1 1\n#",
"o... | 1,522,494,391 | 2,147,483,647 | PyPy 3 | OK | TESTS | 50 | 171 | 22,732,800 | import functools
import sys
def with_args(deco):
@functools.wraps(deco)
def wrapper(*args,**kwargs):
def res(func):
return deco(func,*args,**kwargs)
return res
return wrapper
@with_args
def deco(func,str = "я бесполезен"):
@functools.wraps(func)
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a rectangular grid of *n* rows of *m* initially-white cells each.
Arkady performed a certain number (possibly zero) of operations on it. In the *i*-th operation, a non-empty subset of rows *R**i* and a non-empty subset o... | ```python
import functools
import sys
def with_args(deco):
@functools.wraps(deco)
def wrapper(*args,**kwargs):
def res(func):
return deco(func,*args,**kwargs)
return res
return wrapper
@with_args
def deco(func,str = "я бесполезен"):
@functools.wraps(f... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
362 | B | Petya and Staircases | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | Little boy Petya loves stairs very much. But he is bored from simple going up and down them — he loves jumping over several stairs at a time. As he stands on some stair, he can either jump to the next one or jump over one or two stairs at a time. But some stairs are too dirty and Petya doesn't want to step on them.
No... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=109, 0<=≤<=*m*<=≤<=3000) — the number of stairs in the staircase and the number of dirty stairs, correspondingly. The second line contains *m* different space-separated integers *d*1,<=*d*2,<=...,<=*d**m* (1<=≤<=*d**i*<=≤<=*n*) — the numbers of the dirty s... | Print "YES" if Petya can reach stair number *n*, stepping only on the clean stairs. Otherwise print "NO". | [
"10 5\n2 4 8 3 6\n",
"10 5\n2 4 5 7 9\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "10 5\n2 4 8 3 6",
"output": "NO"
},
{
"input": "10 5\n2 4 5 7 9",
"output": "YES"
},
{
"input": "10 9\n2 3 4 5 6 7 8 9 10",
"output": "NO"
},
{
"input": "5 2\n4 5",
"output": "NO"
},
{
"input": "123 13\n36 73 111 2 92 5 47 55 48 113 7 78 37",
"outp... | 1,428,747,390 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 7 | 46 | 307,200 | # coding: utf-8
n, m = [int(i) for i in input().split()]
if m:
d = [int(i) for i in input().split()]
if n in d:
print('NO')
exit()
d.sort()
i = 0
while i < m-2:
if d[i+2]-d[i+1]==1:
if d[i+1]-d[i]==1:
print('NO')
break
else:
i += 1
else:
i ... | Title: Petya and Staircases
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little boy Petya loves stairs very much. But he is bored from simple going up and down them — he loves jumping over several stairs at a time. As he stands on some stair, he can either jump to the next one or jump o... | ```python
# coding: utf-8
n, m = [int(i) for i in input().split()]
if m:
d = [int(i) for i in input().split()]
if n in d:
print('NO')
exit()
d.sort()
i = 0
while i < m-2:
if d[i+2]-d[i+1]==1:
if d[i+1]-d[i]==1:
print('NO')
break
else:
i += 1
else:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
485 | A | Factory | PROGRAMMING | 1,400 | [
"implementation",
"math",
"matrices"
] | null | null | One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the factory has to produce (remainder after dividing *x* by *m*) more details. Unfortunately, no cu... | The first line contains two integers *a* and *m* (1<=≤<=*a*,<=*m*<=≤<=105). | Print "Yes" (without quotes) if the production will eventually stop, otherwise print "No". | [
"1 5\n",
"3 6\n"
] | [
"No\n",
"Yes\n"
] | none | 1,000 | [
{
"input": "1 5",
"output": "No"
},
{
"input": "3 6",
"output": "Yes"
},
{
"input": "1 8",
"output": "Yes"
},
{
"input": "2 3",
"output": "No"
},
{
"input": "3 24",
"output": "Yes"
},
{
"input": "1 1",
"output": "Yes"
},
{
"input": "100000 ... | 1,633,365,507 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 1,000 | 21,401,600 | import math
import sys
input = sys.stdin.readline
a,m = map(int,input().split())
if a == m:
print("Yes")
exit()
visited = set()
flag = 0
while True:
if a in visited:
break
visited.add(a)
while a < m:
a = a+a
if a == m:
flag = 1
... | Title: Factory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the fac... | ```python
import math
import sys
input = sys.stdin.readline
a,m = map(int,input().split())
if a == m:
print("Yes")
exit()
visited = set()
flag = 0
while True:
if a in visited:
break
visited.add(a)
while a < m:
a = a+a
if a == m:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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