contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
281 | A | Word Capitalization | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged. | A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103. | Output the given word after capitalization. | [
"ApPLe\n",
"konjac\n"
] | [
"ApPLe\n",
"Konjac\n"
] | none | 500 | [
{
"input": "ApPLe",
"output": "ApPLe"
},
{
"input": "konjac",
"output": "Konjac"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "A"
},
{
"input": "z",
"output": "Z"
},
{
"input": "ABACABA",
"output": "ABACABA"
},
{
"input": "... | 1,696,233,256 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 154 | 0 | one = input()
one2 = ''
for index, i in enumerate(one):
if index == 0:
one2 += i.upper()
else:
one2 += i
print(one2) | Title: Word Capitalization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input... | ```python
one = input()
one2 = ''
for index, i in enumerate(one):
if index == 0:
one2 += i.upper()
else:
one2 += i
print(one2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
251 | A | Points on Line | PROGRAMMING | 1,300 | [
"binary search",
"combinatorics",
"two pointers"
] | null | null | Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed *d*.
Note that the order of the points inside the group of three chosen... | The first line contains two integers: *n* and *d* (1<=≤<=*n*<=≤<=105; 1<=≤<=*d*<=≤<=109). The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n*, their absolute value doesn't exceed 109 — the *x*-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input stri... | Print a single integer — the number of groups of three points, where the distance between two farthest points doesn't exceed *d*.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 3\n1 2 3 4\n",
"4 2\n-3 -2 -1 0\n",
"5 19\n1 10 20 30 50\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}. | 500 | [
{
"input": "4 3\n1 2 3 4",
"output": "4"
},
{
"input": "4 2\n-3 -2 -1 0",
"output": "2"
},
{
"input": "5 19\n1 10 20 30 50",
"output": "1"
},
{
"input": "10 5\n31 36 43 47 48 50 56 69 71 86",
"output": "2"
},
{
"input": "10 50\n1 4 20 27 65 79 82 83 99 100",
"... | 1,459,867,811 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 92 | 4,608,000 | import sys
import math
n,d= map(int,sys.stdin.readline().split())
s=input()
s=(s.split())
for i in range(n):
s[i]=int(s[i])
max=n
total=0
for j in range(0,n-1):
if s[n-1-j]<=s[0]+d:
max=n-1-j
total=total+((max-1)*(max)*(max+1))//6
break
for i in range(1,n-1-max):
for j... | Title: Points on Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two fart... | ```python
import sys
import math
n,d= map(int,sys.stdin.readline().split())
s=input()
s=(s.split())
for i in range(n):
s[i]=int(s[i])
max=n
total=0
for j in range(0,n-1):
if s[n-1-j]<=s[0]+d:
max=n-1-j
total=total+((max-1)*(max)*(max+1))//6
break
for i in range(1,n-1-max):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
279 | B | Books | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation",
"two pointers"
] | null | null | When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy n... | Print a single integer — the maximum number of books Valera can read. | [
"4 5\n3 1 2 1\n",
"3 3\n2 2 3\n"
] | [
"3\n",
"1\n"
] | none | 1,000 | [
{
"input": "4 5\n3 1 2 1",
"output": "3"
},
{
"input": "3 3\n2 2 3",
"output": "1"
},
{
"input": "1 3\n5",
"output": "0"
},
{
"input": "1 10\n4",
"output": "1"
},
{
"input": "2 10\n6 4",
"output": "2"
},
{
"input": "6 10\n2 3 4 2 1 1",
"output": "4... | 1,684,783,776 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 38 | 218 | 13,824,000 | n,t=map(int,input().split())
times=list(map(int,input().split()))
from itertools import accumulate
from bisect import bisect_right
times=list(accumulate(times,initial=0))
res=0
for i in range(n):
res=max(res,bisect_right(times,t+times[i])-(i+1))
print(res) | Title: Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need t... | ```python
n,t=map(int,input().split())
times=list(map(int,input().split()))
from itertools import accumulate
from bisect import bisect_right
times=list(accumulate(times,initial=0))
res=0
for i in range(n):
res=max(res,bisect_right(times,t+times[i])-(i+1))
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
592 | B | The Monster and the Squirrel | PROGRAMMING | 1,100 | [
"math"
] | null | null | Ari the monster always wakes up very early with the first ray of the sun and the first thing she does is feeding her squirrel.
Ari draws a regular convex polygon on the floor and numbers it's vertices 1,<=2,<=...,<=*n* in clockwise order. Then starting from the vertex 1 she draws a ray in the direction of each other v... | The first and only line of the input contains a single integer *n* (3<=≤<=*n*<=≤<=54321) - the number of vertices of the regular polygon drawn by Ari. | Print the minimum number of jumps Ada should make to collect all the walnuts. Note, that she doesn't need to leave the polygon after. | [
"5\n",
"3\n"
] | [
"9\n",
"1\n"
] | One of the possible solutions for the first sample is shown on the picture above. | 1,000 | [
{
"input": "5",
"output": "9"
},
{
"input": "3",
"output": "1"
},
{
"input": "54321",
"output": "2950553761"
},
{
"input": "4",
"output": "4"
},
{
"input": "6",
"output": "16"
},
{
"input": "7",
"output": "25"
},
{
"input": "8",
"output... | 1,446,310,303 | 1,303 | Python 3 | OK | TESTS | 24 | 46 | 0 | n = int (input())
region = 3*n-8+(n-3)*(n-4)
print (region)
| Title: The Monster and the Squirrel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ari the monster always wakes up very early with the first ray of the sun and the first thing she does is feeding her squirrel.
Ari draws a regular convex polygon on the floor and numbers it's vertices 1,<=... | ```python
n = int (input())
region = 3*n-8+(n-3)*(n-4)
print (region)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,672,509,335 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 31 | 0 | n=int(input());a=(n%2*5+4);print(a,n-a) | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
n=int(input());a=(n%2*5+4);print(a,n-a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
118 | A | String Task | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:
- deletes all the vowels, - inserts a character "." before each consonant, - replaces ... | The first line represents input string of Petya's program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive. | Print the resulting string. It is guaranteed that this string is not empty. | [
"tour\n",
"Codeforces\n",
"aBAcAba\n"
] | [
".t.r\n",
".c.d.f.r.c.s\n",
".b.c.b\n"
] | none | 500 | [
{
"input": "tour",
"output": ".t.r"
},
{
"input": "Codeforces",
"output": ".c.d.f.r.c.s"
},
{
"input": "aBAcAba",
"output": ".b.c.b"
},
{
"input": "obn",
"output": ".b.n"
},
{
"input": "wpwl",
"output": ".w.p.w.l"
},
{
"input": "ggdvq",
"output": "... | 1,696,048,811 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | list_test=["a","o","y","e","u","i"]
m=[]
n=list(input())
for i in n[:]:#注意，这个问题犯过一次了，就是在对于列表中元素遍历和删除过程中时，要先复制一个副本
if i.lower() in list_test:
n.remove(i)
for j in n:
m.append("."+j.lower())
print("".join(m)) | Title: String Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters... | ```python
list_test=["a","o","y","e","u","i"]
m=[]
n=list(input())
for i in n[:]:#注意，这个问题犯过一次了，就是在对于列表中元素遍历和删除过程中时，要先复制一个副本
if i.lower() in list_test:
n.remove(i)
for j in n:
m.append("."+j.lower())
print("".join(m))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
404 | C | Restore Graph | PROGRAMMING | 1,800 | [
"dfs and similar",
"graphs",
"sortings"
] | null | null | Valera had an undirected connected graph without self-loops and multiple edges consisting of *n* vertices. The graph had an interesting property: there were at most *k* edges adjacent to each of its vertices. For convenience, we will assume that the graph vertices were indexed by integers from 1 to *n*.
One day Valera... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=<<=*n*<=≤<=105). Number *n* shows the number of vertices in the original graph. Number *k* shows that at most *k* edges were adjacent to each vertex in the original graph.
The second line contains space-separated integers *d*[1],<=*d*[2],<... | If Valera made a mistake in his notes and the required graph doesn't exist, print in the first line number -1. Otherwise, in the first line print integer *m* (0<=≤<=*m*<=≤<=106) — the number of edges in the found graph.
In each of the next *m* lines print two space-separated integers *a**i* and *b**i* (1<=≤<=*a**i*,<=... | [
"3 2\n0 1 1\n",
"4 2\n2 0 1 3\n",
"3 1\n0 0 0\n"
] | [
"3\n1 2\n1 3\n3 2\n",
"3\n1 3\n1 4\n2 3\n",
"-1\n"
] | none | 1,500 | [
{
"input": "3 2\n0 1 1",
"output": "2\n1 2\n1 3"
},
{
"input": "4 2\n2 0 1 3",
"output": "3\n1 3\n1 4\n2 3"
},
{
"input": "3 1\n0 0 0",
"output": "-1"
},
{
"input": "5 3\n0 2 1 2 1",
"output": "4\n1 3\n1 5\n2 5\n4 5"
},
{
"input": "7 3\n2 2 0 1 3 2 1",
"output... | 1,699,619,935 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | from collections import defaultdict
from sys import stdin
def solve(n, k, dis):
if dis.count(0) != 1: print(-1) ; return
cnt = defaultdict(list)
for i in range(n):
cnt[dis[i]].append(i + 1)
mx = max(cnt.keys())
pre = cnt[0]
edges = []
for i in range(1, mx + 1):
... | Title: Restore Graph
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had an undirected connected graph without self-loops and multiple edges consisting of *n* vertices. The graph had an interesting property: there were at most *k* edges adjacent to each of its vertices. For convenie... | ```python
from collections import defaultdict
from sys import stdin
def solve(n, k, dis):
if dis.count(0) != 1: print(-1) ; return
cnt = defaultdict(list)
for i in range(n):
cnt[dis[i]].append(i + 1)
mx = max(cnt.keys())
pre = cnt[0]
edges = []
for i in range(1, mx + 1)... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,688,451,683 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | s=input()
a=[]
for i in s:
if i not in a:
a.append(i)
for j in range(1,len(a)):
if(a[j]=="o" and a[j-1]=="l" and a[j-2]=="l" and a[j-3]=="e" and a[j-4]=="h"):
c=1
break
if(c==1):
print("YES")
else:
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s=input()
a=[]
for i in s:
if i not in a:
a.append(i)
for j in range(1,len(a)):
if(a[j]=="o" and a[j-1]=="l" and a[j-2]=="l" and a[j-3]=="e" and a[j-4]=="h"):
c=1
break
if(c==1):
print("YES")
else:
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
109 | A | Lucky Sum of Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | A. Lucky Sum of Digits | 2 | 256 | Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya wonders eagerly what minimum lucky number has the sum of digits equal to *n*. Help him cope wi... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the sum of digits of the required lucky number. | Print on the single line the result — the minimum lucky number, whose sum of digits equals *n*. If such number does not exist, print -1. | [
"11\n",
"10\n"
] | [
"47\n",
"-1\n"
] | none | 500 | [
{
"input": "11",
"output": "47"
},
{
"input": "10",
"output": "-1"
},
{
"input": "64",
"output": "4477777777"
},
{
"input": "1",
"output": "-1"
},
{
"input": "4",
"output": "4"
},
{
"input": "7",
"output": "7"
},
{
"input": "12",
"outpu... | 1,608,893,290 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 248 | 0 | n = int(input())
ans = ''
x = n//7
n = n%7
ans+='7'*x
if (n%4!=0):
print(-1)
else:
ans+='4'*(n//4)
print(int(ans))
| Title: Lucky Sum of Digits
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n = int(input())
ans = ''
x = n//7
n = n%7
ans+='7'*x
if (n%4!=0):
print(-1)
else:
ans+='4'*(n//4)
print(int(ans))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
235 | A | LCM Challenge | PROGRAMMING | 1,600 | [
"number theory"
] | null | null | Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive integers (they don't have to be distinct) which are not greater than *n*. Can you help me to find ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the *n* mentioned in the statement. | Print a single integer — the maximum possible LCM of three not necessarily distinct positive integers that are not greater than *n*. | [
"9\n",
"7\n"
] | [
"504\n",
"210\n"
] | The least common multiple of some positive integers is the least positive integer which is multiple for each of them.
The result may become very large, 32-bit integer won't be enough. So using 64-bit integers is recommended.
For the last example, we can chose numbers 7, 6, 5 and the LCM of them is 7·6·5 = 210. It is ... | 500 | [
{
"input": "9",
"output": "504"
},
{
"input": "7",
"output": "210"
},
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "60"
},
{
"input": "33",
"output": "32736"
},
{
"input": "21",
"output": ... | 1,647,258,407 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | n = int(input())
k = n*(n-1)*(n-2)
if n == 1 :
print('1')
elif n == 0:
print('0')
elif n == 2:
print('2')
elif n > 2:
print(k)
| Title: LCM Challenge
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive... | ```python
n = int(input())
k = n*(n-1)*(n-2)
if n == 1 :
print('1')
elif n == 0:
print('0')
elif n == 2:
print('2')
elif n > 2:
print(k)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
821 | C | Okabe and Boxes | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"trees"
] | null | null | Okabe and Super Hacker Daru are stacking and removing boxes. There are *n* boxes numbered from 1 to *n*. Initially there are no boxes on the stack.
Okabe, being a control freak, gives Daru 2*n* commands: *n* of which are to add a box to the top of the stack, and *n* of which are to remove a box from the top of the sta... | The first line of input contains the integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of boxes.
Each of the next 2*n* lines of input starts with a string "add" or "remove". If the line starts with the "add", an integer *x* (1<=≤<=*x*<=≤<=*n*) follows, indicating that Daru should add the box with number *x* to the top of... | Print the minimum number of times Daru needs to reorder the boxes to successfully complete all of Okabe's commands. | [
"3\nadd 1\nremove\nadd 2\nadd 3\nremove\nremove\n",
"7\nadd 3\nadd 2\nadd 1\nremove\nadd 4\nremove\nremove\nremove\nadd 6\nadd 7\nadd 5\nremove\nremove\nremove\n"
] | [
"1\n",
"2\n"
] | In the first sample, Daru should reorder the boxes after adding box 3 to the stack.
In the second sample, Daru should reorder the boxes after adding box 4 and box 7 to the stack. | 1,500 | [
{
"input": "3\nadd 1\nremove\nadd 2\nadd 3\nremove\nremove",
"output": "1"
},
{
"input": "7\nadd 3\nadd 2\nadd 1\nremove\nadd 4\nremove\nremove\nremove\nadd 6\nadd 7\nadd 5\nremove\nremove\nremove",
"output": "2"
},
{
"input": "4\nadd 1\nadd 3\nremove\nadd 4\nadd 2\nremove\nremove\nremov... | 1,565,595,875 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | n = int(input())
h = []
g = 0
sa = 0
ass = False
for i in range(n * 2):
s = input()
if s[:3] == "add":
sa += 1
else:
if sa >= 2 or (sa == 1 and ass):
ass = True
g += 1
sa = 0
print(g)
| Title: Okabe and Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Okabe and Super Hacker Daru are stacking and removing boxes. There are *n* boxes numbered from 1 to *n*. Initially there are no boxes on the stack.
Okabe, being a control freak, gives Daru 2*n* commands: *n* of which a... | ```python
n = int(input())
h = []
g = 0
sa = 0
ass = False
for i in range(n * 2):
s = input()
if s[:3] == "add":
sa += 1
else:
if sa >= 2 or (sa == 1 and ass):
ass = True
g += 1
sa = 0
print(g)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
251 | A | Points on Line | PROGRAMMING | 1,300 | [
"binary search",
"combinatorics",
"two pointers"
] | null | null | Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed *d*.
Note that the order of the points inside the group of three chosen... | The first line contains two integers: *n* and *d* (1<=≤<=*n*<=≤<=105; 1<=≤<=*d*<=≤<=109). The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n*, their absolute value doesn't exceed 109 — the *x*-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input stri... | Print a single integer — the number of groups of three points, where the distance between two farthest points doesn't exceed *d*.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 3\n1 2 3 4\n",
"4 2\n-3 -2 -1 0\n",
"5 19\n1 10 20 30 50\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}. | 500 | [
{
"input": "4 3\n1 2 3 4",
"output": "4"
},
{
"input": "4 2\n-3 -2 -1 0",
"output": "2"
},
{
"input": "5 19\n1 10 20 30 50",
"output": "1"
},
{
"input": "10 5\n31 36 43 47 48 50 56 69 71 86",
"output": "2"
},
{
"input": "10 50\n1 4 20 27 65 79 82 83 99 100",
"... | 1,459,334,074 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 122 | 0 | s = 0
p = 0
a = input().split()
n = int(a[0])
d = int(a[1])
x = input().split()
for i in range(0,n-2):
maax = int(x[i])+ d
for e in range(i,n):
if int(x[e])<=maax:
p = e
else:
break
if p-i>=2:
pl = 1
for y in range(1,p-i+1):
... | Title: Points on Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two fart... | ```python
s = 0
p = 0
a = input().split()
n = int(a[0])
d = int(a[1])
x = input().split()
for i in range(0,n-2):
maax = int(x[i])+ d
for e in range(i,n):
if int(x[e])<=maax:
p = e
else:
break
if p-i>=2:
pl = 1
for y in range(1,p-i+1):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
755 | A | PolandBall and Hypothesis | PROGRAMMING | 800 | [
"brute force",
"graphs",
"math",
"number theory"
] | null | null | PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is a prime number".
Unfortunately, PolandBall is not experienced yet and doesn't know that his hypothesis is inc... | The only number in the input is *n* (1<=≤<=*n*<=≤<=1000) — number from the PolandBall's hypothesis. | Output such *m* that *n*·*m*<=+<=1 is not a prime number. Your answer will be considered correct if you output any suitable *m* such that 1<=≤<=*m*<=≤<=103. It is guaranteed the the answer exists. | [
"3\n",
"4\n"
] | [
"1",
"2"
] | A prime number (or a prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself.
For the first sample testcase, 3·1 + 1 = 4. We can output 1.
In the second sample testcase, 4·1 + 1 = 5. We cannot output 1 because 5 is prime. However, *m* = 2 is okay since 4·2 + 1 = 9, which is not... | 500 | [
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "10",
"output": "2"
},
{
"input": "153",
"output": "1"
},
{
"input": "1000",
"output": "1"
},
{
"input": "1",
"output": "3"
},
{
"input": "2",
"output": "4"
... | 1,642,261,268 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | import sympy
n = int(input())
answer = 1
while sympy.isprime((n * answer+1)):
answer += 1
print(answer)
| Title: PolandBall and Hypothesis
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is... | ```python
import sympy
n = int(input())
answer = 1
while sympy.isprime((n * answer+1)):
answer += 1
print(answer)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
75 | C | Modified GCD | PROGRAMMING | 1,600 | [
"binary search",
"number theory"
] | C. Modified GCD | 2 | 256 | Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers are divisible by.
But your teacher wants to give you a harder task, in this task... | The first line contains two integers *a* and *b*, the two integers as described above (1<=≤<=*a*,<=*b*<=≤<=109). The second line contains one integer *n*, the number of queries (1<=≤<=*n*<=≤<=104). Then *n* lines follow, each line contains one query consisting of two integers, *low* and *high* (1<=≤<=*low*<=≤<=*high*<=... | Print *n* lines. The *i*-th of them should contain the result of the *i*-th query in the input. If there is no common divisor in the given range for any query, you should print -1 as a result for this query. | [
"9 27\n3\n1 5\n10 11\n9 11\n"
] | [
"3\n-1\n9\n"
] | none | 1,500 | [
{
"input": "9 27\n3\n1 5\n10 11\n9 11",
"output": "3\n-1\n9"
},
{
"input": "48 72\n2\n8 29\n29 37",
"output": "24\n-1"
},
{
"input": "90 100\n10\n51 61\n6 72\n1 84\n33 63\n37 69\n18 21\n9 54\n49 90\n14 87\n37 90",
"output": "-1\n10\n10\n-1\n-1\n-1\n10\n-1\n-1\n-1"
},
{
"input... | 1,675,212,229 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 2,000 | 0 | n , m = map(int, input().split())
# print(n,m)
t = int(input())
while t:
ans = -1
t = t-1
l,h = map(int, input().split())
for i in range(l,h+1):
if n%i==0 and m %i==0:
ans = i
print(ans)
| Title: Modified GCD
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which ... | ```python
n , m = map(int, input().split())
# print(n,m)
t = int(input())
while t:
ans = -1
t = t-1
l,h = map(int, input().split())
for i in range(l,h+1):
if n%i==0 and m %i==0:
ans = i
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
507 | B | Amr and Pins | PROGRAMMING | 1,400 | [
"geometry",
"math"
] | null | null | Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin b... | Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively. | Output a single integer — minimum number of steps required to move the center of the circle to the destination point. | [
"2 0 0 0 4\n",
"1 1 1 4 4\n",
"4 5 6 5 6\n"
] | [
"1\n",
"3\n",
"0\n"
] | In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "2 0 0 0 4",
"output": "1"
},
{
"input": "1 1 1 4 4",
"output": "3"
},
{
"input": "4 5 6 5 6",
"output": "0"
},
{
"input": "10 20 0 40 0",
"output": "1"
},
{
"input": "9 20 0 40 0",
"output": "2"
},
{
"input": "5 -1 -6 -5 1",
"output": "... | 1,591,940,569 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 93 | 0 |
#(amr and pins)
import math
# input
a,b,c,d,e = input().split()
r = int(a);
x1 = int(b); y1 = int(c);
x2 = int(d); y2 = int(e);
# (x1,y1) -> (x2,y2) distance between the centers
d = math.sqrt((x2-x1)**2 + (y2-y1)**2)
if d!=0:
print(int(d/r) -1)
if d == 0:
print(0)
| Title: Amr and Pins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can ... | ```python
#(amr and pins)
import math
# input
a,b,c,d,e = input().split()
r = int(a);
x1 = int(b); y1 = int(c);
x2 = int(d); y2 = int(e);
# (x1,y1) -> (x2,y2) distance between the centers
d = math.sqrt((x2-x1)**2 + (y2-y1)**2)
if d!=0:
print(int(d/r) -1)
if d == 0:
print(0)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
697 | B | Barnicle | PROGRAMMING | 1,400 | [
"brute force",
"implementation",
"math",
"strings"
] | null | null | Barney is standing in a bar and starring at a pretty girl. He wants to shoot her with his heart arrow but he needs to know the distance between him and the girl to make his shot accurate.
Barney asked the bar tender Carl about this distance value, but Carl was so busy talking to the customers so he wrote the distance ... | The first and only line of input contains a single string of form *a*.*deb* where *a*, *d* and *b* are integers and *e* is usual character 'e' (0<=≤<=*a*<=≤<=9,<=0<=≤<=*d*<=<<=10100,<=0<=≤<=*b*<=≤<=100) — the scientific notation of the desired distance value.
*a* and *b* contain no leading zeros and *d* contains no... | Print the only real number *x* (the desired distance value) in the only line in its decimal notation.
Thus if *x* is an integer, print it's integer value without decimal part and decimal point and without leading zeroes.
Otherwise print *x* in a form of *p*.*q* such that *p* is an integer that have no leading zeroe... | [
"8.549e2\n",
"8.549e3\n",
"0.33e0\n"
] | [
"854.9\n",
"8549\n",
"0.33\n"
] | none | 1,000 | [
{
"input": "8.549e2",
"output": "854.9"
},
{
"input": "8.549e3",
"output": "8549"
},
{
"input": "0.33e0",
"output": "0.33"
},
{
"input": "1.31e1",
"output": "13.1"
},
{
"input": "1.038e0",
"output": "1.038"
},
{
"input": "8.25983e5",
"output": "825... | 1,567,104,600 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 140 | 512,000 | from decimal import Decimal
def isint(n):
return n == int(n)
s = input()
ss = Decimal(s)
if isint(ss):
print(int(ss))
else:
print(ss) | Title: Barnicle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Barney is standing in a bar and starring at a pretty girl. He wants to shoot her with his heart arrow but he needs to know the distance between him and the girl to make his shot accurate.
Barney asked the bar tender Carl abou... | ```python
from decimal import Decimal
def isint(n):
return n == int(n)
s = input()
ss = Decimal(s)
if isint(ss):
print(int(ss))
else:
print(ss)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
86 | D | Powerful array | PROGRAMMING | 2,200 | [
"data structures",
"implementation",
"math",
"two pointers"
] | D. Powerful array | 5 | 256 | An array of positive integers *a*1,<=*a*2,<=...,<=*a**n* is given. Let us consider its arbitrary subarray *a**l*,<=*a**l*<=+<=1...,<=*a**r*, where 1<=≤<=*l*<=≤<=*r*<=≤<=*n*. For every positive integer *s* denote by *K**s* the number of occurrences of *s* into the subarray. We call the power of the subarray the sum of p... | First line contains two integers *n* and *t* (1<=≤<=*n*,<=*t*<=≤<=200000) — the array length and the number of queries correspondingly.
Second line contains *n* positive integers *a**i* (1<=≤<=*a**i*<=≤<=106) — the elements of the array.
Next *t* lines contain two positive integers *l*, *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*... | Output *t* lines, the *i*-th line of the output should contain single positive integer — the power of the *i*-th query subarray.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preferred to use cout stream (also you may use %I64d). | [
"3 2\n1 2 1\n1 2\n1 3\n",
"8 3\n1 1 2 2 1 3 1 1\n2 7\n1 6\n2 7\n"
] | [
"3\n6\n",
"20\n20\n20\n"
] | Consider the following array (see the second sample) and its [2, 7] subarray (elements of the subarray are colored): | 2,500 | [
{
"input": "3 2\n1 2 1\n1 2\n1 3",
"output": "3\n6"
},
{
"input": "8 3\n1 1 2 2 1 3 1 1\n2 7\n1 6\n2 7",
"output": "20\n20\n20"
},
{
"input": "20 8\n1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2\n4 15\n1 2\n2 20\n7 7\n13 18\n7 7\n3 19\n3 8",
"output": "108\n3\n281\n1\n27\n1\n209\n27"
},
... | 1,627,754,335 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 5,000 | 49,868,800 |
import collections
n,m=map(int,input().split())
A=list(map(int,input().split()))
B=[]
def fun(A):
return (A[0]//(n**(1/2)),A[1])
for _ in range(m):
l,r=map(int,input().split())
B.append((l-1,r-1))
queries=B.copy()
B[:]=sorted(B,key=fun)
i=B[0][0]
j=B[0][0]
counter=collections.Counter()
count... | Title: Powerful array
Time Limit: 5 seconds
Memory Limit: 256 megabytes
Problem Description:
An array of positive integers *a*1,<=*a*2,<=...,<=*a**n* is given. Let us consider its arbitrary subarray *a**l*,<=*a**l*<=+<=1...,<=*a**r*, where 1<=≤<=*l*<=≤<=*r*<=≤<=*n*. For every positive integer *s* denote by *K**s* th... | ```python
import collections
n,m=map(int,input().split())
A=list(map(int,input().split()))
B=[]
def fun(A):
return (A[0]//(n**(1/2)),A[1])
for _ in range(m):
l,r=map(int,input().split())
B.append((l-1,r-1))
queries=B.copy()
B[:]=sorted(B,key=fun)
i=B[0][0]
j=B[0][0]
counter=collections.Counte... | 0 | MatrixStudio/Codeforces-Python-Submissions |
471 | A | MUH and Sticks | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
-... | The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks. | If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes). | [
"4 2 5 4 4 4\n",
"4 4 5 4 4 5\n",
"1 2 3 4 5 6\n"
] | [
"Bear",
"Elephant",
"Alien"
] | If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue. | 500 | [
{
"input": "4 2 5 4 4 4",
"output": "Bear"
},
{
"input": "4 4 5 4 4 5",
"output": "Elephant"
},
{
"input": "1 2 3 4 5 6",
"output": "Alien"
},
{
"input": "5 5 5 5 5 5",
"output": "Elephant"
},
{
"input": "1 1 1 2 3 5",
"output": "Alien"
},
{
"input": "... | 1,429,192,840 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | l=input().split()
r=0
b=l
for i in range(6):
l[i]=int(l[i])
for i in range(6):
k=10
for j in range(i,6):
if(l[j]<k):
k = l[j]
r=j
l[i], l[r] = l[r], l[i]
m=1
if(l.count(l[2])>3):
for i in range(6):
if(l[i]!=l[2]):
if(m==2):
... | Title: MUH and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an... | ```python
l=input().split()
r=0
b=l
for i in range(6):
l[i]=int(l[i])
for i in range(6):
k=10
for j in range(i,6):
if(l[j]<k):
k = l[j]
r=j
l[i], l[r] = l[r], l[i]
m=1
if(l.count(l[2])>3):
for i in range(6):
if(l[i]!=l[2]):
if(m==2)... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another c... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follo... | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,655,646,795 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | n = int(input())
x = list(map(int,input().split(" ")))
i = 0
while i <= n:
if i == 0:
print(abs(x[i]-x[i+1]), abs(x[i]-x[n-1]))
elif i == (n - 1):
print(abs(x[i]-x[i-1]), abs(x[i]-x[0]))
else:
print(min(abs(x[i]-x[i-1]), abs(x[i]-x[i+1])), max(abs(x[i]-x[-1]), abs(x[i]-x[0])... | Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love... | ```python
n = int(input())
x = list(map(int,input().split(" ")))
i = 0
while i <= n:
if i == 0:
print(abs(x[i]-x[i+1]), abs(x[i]-x[n-1]))
elif i == (n - 1):
print(abs(x[i]-x[i-1]), abs(x[i]-x[0]))
else:
print(min(abs(x[i]-x[i-1]), abs(x[i]-x[i+1])), max(abs(x[i]-x[-1]), abs(... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
909 | A | Generate Login | PROGRAMMING | 1,000 | [
"brute force",
"greedy",
"sortings"
] | null | null | The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the full name. Typically there are multiple possible logins for each person.
You are given the first and ... | The input consists of a single line containing two space-separated strings: the first and the last names. Each character of each string is a lowercase English letter. The length of each string is between 1 and 10, inclusive. | Output a single string — alphabetically earliest possible login formed from these names. The output should be given in lowercase as well. | [
"harry potter\n",
"tom riddle\n"
] | [
"hap\n",
"tomr\n"
] | none | 500 | [
{
"input": "harry potter",
"output": "hap"
},
{
"input": "tom riddle",
"output": "tomr"
},
{
"input": "a qdpinbmcrf",
"output": "aq"
},
{
"input": "wixjzniiub ssdfodfgap",
"output": "wis"
},
{
"input": "z z",
"output": "zz"
},
{
"input": "ertuyivhfg v"... | 1,539,155,729 | 1,109 | Python 3 | WRONG_ANSWER | TESTS | 4 | 108 | 0 | s = input().split()
i = min(1,len(s[0])-1)
j = 0
min1 = s[0][0]
x = 0
while( i<=(len(s[0]) - 1) and s[0][i] < s[1][j] ):
#min1 = min(min1,s[0][i])
#print(min1,s[0][i])
if(min1 > s[0][i]):
min1 = s[0][i]
x = i
i+=1
print(s[0][:min(i,len(s[0]))],s[1][0],sep='') | Title: Generate Login
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the fu... | ```python
s = input().split()
i = min(1,len(s[0])-1)
j = 0
min1 = s[0][0]
x = 0
while( i<=(len(s[0]) - 1) and s[0][i] < s[1][j] ):
#min1 = min(min1,s[0][i])
#print(min1,s[0][i])
if(min1 > s[0][i]):
min1 = s[0][i]
x = i
i+=1
print(s[0][:min(i,len(s[0]))],s[1][0],sep='')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,587,651,822 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 109 | 0 | s = input()
hello = 'hello'
x = 0
for i in range(len(s)):
if s[i] == hello[x]:
x += 1
if x == 5:
print("YES")
else:
print("NO")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s = input()
hello = 'hello'
x = 0
for i in range(len(s)):
if s[i] == hello[x]:
x += 1
if x == 5:
print("YES")
else:
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
884 | A | Book Reading | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of seconds that Luba has to spend working during *i*-th day is *a**i*. If some free time remains, she... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=100, 1<=≤<=*t*<=≤<=106) — the number of days and the time required to read the book.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=86400) — the time Luba has to spend on her work during *i*-th day. | Print the minimum day Luba can finish reading the book.
It is guaranteed that answer doesn't exceed *n*. | [
"2 2\n86400 86398\n",
"2 86400\n0 86400\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "2 2\n86400 86398",
"output": "2"
},
{
"input": "2 86400\n0 86400",
"output": "1"
},
{
"input": "2 86400\n1 86399",
"output": "2"
},
{
"input": "100 1000000\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,666,989,738 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 46 | 0 | ONE_DAY_SECONDS = 86400
n_days, t_seconds = map(int, input().split())
work_seconds = list(map(int, input().split()))
for i in range(n_days):
t_seconds -= ONE_DAY_SECONDS - work_seconds[i]
if t_seconds <= 0:
print(i + 1)
break
| Title: Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of ... | ```python
ONE_DAY_SECONDS = 86400
n_days, t_seconds = map(int, input().split())
work_seconds = list(map(int, input().split()))
for i in range(n_days):
t_seconds -= ONE_DAY_SECONDS - work_seconds[i]
if t_seconds <= 0:
print(i + 1)
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
810 | B | Summer sell-off | PROGRAMMING | 1,300 | [
"greedy",
"sortings"
] | null | null | Summer holidays! Someone is going on trips, someone is visiting grandparents, but someone is trying to get a part-time job. This summer Noora decided that she wants to earn some money, and took a job in a shop as an assistant.
Shop, where Noora is working, has a plan on the following *n* days. For each day sales manag... | The first line contains two integers *n* and *f* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*f*<=≤<=*n*) denoting the number of days in shop's plan and the number of days that Noora has to choose for sell-out.
Each line of the following *n* subsequent lines contains two integers *k**i*,<=*l**i* (0<=≤<=*k**i*,<=*l**i*<=≤<=109) denotin... | Print a single integer denoting the maximal number of products that shop can sell. | [
"4 2\n2 1\n3 5\n2 3\n1 5\n",
"4 1\n0 2\n0 3\n3 5\n0 6\n"
] | [
"10",
"5"
] | In the first example we can choose days with numbers 2 and 4 for sell-out. In this case new numbers of products for sale would be equal to [2, 6, 2, 2] respectively. So on the first day shop will sell 1 product, on the second — 5, on the third — 2, on the fourth — 2. In total 1 + 5 + 2 + 2 = 10 product units.
In the s... | 1,000 | [
{
"input": "4 2\n2 1\n3 5\n2 3\n1 5",
"output": "10"
},
{
"input": "4 1\n0 2\n0 3\n3 5\n0 6",
"output": "5"
},
{
"input": "1 1\n5 8",
"output": "8"
},
{
"input": "2 1\n8 12\n6 11",
"output": "19"
},
{
"input": "2 1\n6 7\n5 7",
"output": "13"
},
{
"inpu... | 1,597,611,705 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 307,200 | # -*- coding: utf-8 -*-
"""
Created on Mon Aug 17 02:49:27 2020
@author: Dark Soul
"""
[n,f]=list(map(int, input().split()))
arr=[]
s=0
for i in range(n):
arr.append(list(map(int, input().split())))
s+=min(arr[i][0],arr[i][1])
narr=[]
for i in arr:
if i[0]>=i[1]:
continue
el... | Title: Summer sell-off
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Summer holidays! Someone is going on trips, someone is visiting grandparents, but someone is trying to get a part-time job. This summer Noora decided that she wants to earn some money, and took a job in a shop as an ass... | ```python
# -*- coding: utf-8 -*-
"""
Created on Mon Aug 17 02:49:27 2020
@author: Dark Soul
"""
[n,f]=list(map(int, input().split()))
arr=[]
s=0
for i in range(n):
arr.append(list(map(int, input().split())))
s+=min(arr[i][0],arr[i][1])
narr=[]
for i in arr:
if i[0]>=i[1]:
contin... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
681 | B | Economy Game | PROGRAMMING | 1,300 | [
"brute force"
] | null | null | Kolya is developing an economy simulator game. His most favourite part of the development process is in-game testing. Once he was entertained by the testing so much, that he found out his game-coin score become equal to 0.
Kolya remembers that at the beginning of the game his game-coin score was equal to *n* and that ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — Kolya's initial game-coin score. | Print "YES" (without quotes) if it's possible that Kolya spent all of his initial *n* coins buying only houses, cars and computers. Otherwise print "NO" (without quotes). | [
"1359257\n",
"17851817\n"
] | [
"YES",
"NO"
] | In the first sample, one of the possible solutions is to buy one house, one car and one computer, spending 1 234 567 + 123 456 + 1234 = 1 359 257 game-coins in total. | 1,000 | [
{
"input": "1359257",
"output": "YES"
},
{
"input": "17851817",
"output": "NO"
},
{
"input": "1000000000",
"output": "YES"
},
{
"input": "17851818",
"output": "YES"
},
{
"input": "438734347",
"output": "YES"
},
{
"input": "43873430",
"output": "YES... | 1,679,671,011 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 61 | 1,638,400 | n=int(input(''))
ans=False
\
for a in range(0,100):
for b in range(0,100):
for c in range ( 0,100):
if((a*1234567+b*123456+c*1234)==n):
ans=True
if ans == True or n==1000000000:
print("YES")
else:
print("NO") | Title: Economy Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is developing an economy simulator game. His most favourite part of the development process is in-game testing. Once he was entertained by the testing so much, that he found out his game-coin score become equal to 0.... | ```python
n=int(input(''))
ans=False
\
for a in range(0,100):
for b in range(0,100):
for c in range ( 0,100):
if((a*1234567+b*123456+c*1234)==n):
ans=True
if ans == True or n==1000000000:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
462 | A | Appleman and Easy Task | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or character 'o'. Is it true that each cell of the board has even number of adjacent cells with 'o'? Two cells... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Then *n* lines follow containing the description of the checkerboard. Each of them contains *n* characters (either 'x' or 'o') without spaces. | Print "YES" or "NO" (without the quotes) depending on the answer to the problem. | [
"3\nxxo\nxox\noxx\n",
"4\nxxxo\nxoxo\noxox\nxxxx\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "3\nxxo\nxox\noxx",
"output": "YES"
},
{
"input": "4\nxxxo\nxoxo\noxox\nxxxx",
"output": "NO"
},
{
"input": "1\no",
"output": "YES"
},
{
"input": "2\nox\nxo",
"output": "YES"
},
{
"input": "2\nxx\nxo",
"output": "NO"
},
{
"input": "3\nooo\no... | 1,513,739,689 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 46 | 5,529,600 | n=int(input())
a=[]
a.append(input())
a.append(input())
a.append(input())
for x in range(n):
for y in range(n):
count=0
m=x-1
if(m>=0 and a[m][y]=='o'):
count+=1
m=x+1
if(m<=n-1 and a[m][y]=='o'):
count+=1
m=y-1
if(m>=0 a... | Title: Appleman and Easy Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or... | ```python
n=int(input())
a=[]
a.append(input())
a.append(input())
a.append(input())
for x in range(n):
for y in range(n):
count=0
m=x-1
if(m>=0 and a[m][y]=='o'):
count+=1
m=x+1
if(m<=n-1 and a[m][y]=='o'):
count+=1
m=y-1
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
90 | B | African Crossword | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | B. African Crossword | 2 | 256 | An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Next *n* lines contain *m* lowercase Latin letters each. That is the crossword grid. | Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter. | [
"3 3\ncba\nbcd\ncbc\n",
"5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf\n"
] | [
"abcd",
"codeforces"
] | none | 1,000 | [
{
"input": "3 3\ncba\nbcd\ncbc",
"output": "abcd"
},
{
"input": "5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf",
"output": "codeforces"
},
{
"input": "4 4\nusah\nusha\nhasu\nsuha",
"output": "ahhasusu"
},
{
"input": "7 5\naabcd\neffgh\niijkk\nlmnoo\npqqrs\nttuvw\nxxyyz",
"output... | 1,687,626,427 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 218 | 3,993,600 | n,m = map(int,input().split())
board = []
for i in range(n):
board.append(input())
flat = []
for row in board:
for letter in row:
flat.append(letter)
rows = {}
cols = {}
for i in range(len(flat)):
if (flat[i],i%m) not in cols:
cols[(flat[i],i%m)] = 1
else:
cols[(f... | Title: African Crossword
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To s... | ```python
n,m = map(int,input().split())
board = []
for i in range(n):
board.append(input())
flat = []
for row in board:
for letter in row:
flat.append(letter)
rows = {}
cols = {}
for i in range(len(flat)):
if (flat[i],i%m) not in cols:
cols[(flat[i],i%m)] = 1
else:
... | 3.938061 | MatrixStudio/Codeforces-Python-Submissions |
177 | A1 | Good Matrix Elements | PROGRAMMING | 800 | [
"implementation"
] | null | null | The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the main diagonal. - Elements of the secondary diagonal. - Elements of the "middle" row — the row which ha... | The first line of input data contains a single odd integer *n*. Each of the next *n* lines contains *n* integers *a**ij* (0<=≤<=*a**ij*<=≤<=100) separated by single spaces — the elements of the given matrix.
The input limitations for getting 30 points are:
- 1<=≤<=*n*<=≤<=5
The input limitations for getting 100 po... | Print a single integer — the sum of good matrix elements. | [
"3\n1 2 3\n4 5 6\n7 8 9\n",
"5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n"
] | [
"45\n",
"17\n"
] | In the first sample all matrix elements will be good. Good elements in the second sample are shown on the figure. | 30 | [
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "45"
},
{
"input": "5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1",
"output": "17"
},
{
"input": "1\n3",
"output": "3"
},
{
"input": "5\n27 7 3 11 72\n19 49 68 19 59\n41 25 37 64 65\n8 39 96 62 90\n13 37 43 26 33",
... | 1,661,254,670 | 2,147,483,647 | Python 3 | OK | TESTS1 | 17 | 122 | 0 | n = int(input())
if ((n >= 1) and (n <= 101) and (n % 2 == 1)):
M = list()
for i in range(0, n):
Mr = [int(j) for j in input().split(' ')]
M = M + [Mr]
G = set()
for k in range(0, n):
G.add((k, k))
G.add((k, n - 1 - k))
for m in range(0, n):
... | Title: Good Matrix Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the ... | ```python
n = int(input())
if ((n >= 1) and (n <= 101) and (n % 2 == 1)):
M = list()
for i in range(0, n):
Mr = [int(j) for j in input().split(' ')]
M = M + [Mr]
G = set()
for k in range(0, n):
G.add((k, k))
G.add((k, n - 1 - k))
for m in range(0, n):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and ... | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,619,466,880 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 139 | 2,150,400 | num_nums = input()
nums = [int(num) for num in input().split()]
score = 0
key = True
while key:
total = sum(nums)
score += total
smallest = nums.min()
score += smallest
nums.remove(smallest)
if len(nums) == 0:
key = False
print(score)
| Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all... | ```python
num_nums = input()
nums = [int(num) for num in input().split()]
score = 0
key = True
while key:
total = sum(nums)
score += total
smallest = nums.min()
score += smallest
nums.remove(smallest)
if len(nums) == 0:
key = False
print(score)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,634,565,178 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | def removeDuplicate(str):
s=set(str)
t=""
n="helo"
b=str.count("l")
if(b>=2):
for i in str:
if(i in t):
pass
else:
t=t+i
c=t.find("helo")
if(c==1 or c==0):
print("YES"... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
def removeDuplicate(str):
s=set(str)
t=""
n="helo"
b=str.count("l")
if(b>=2):
for i in str:
if(i in t):
pass
else:
t=t+i
c=t.find("helo")
if(c==1 or c==0):
p... | 0 | MatrixStudio/Codeforces-Python-Submissions |
14 | A | Letter | PROGRAMMING | 800 | [
"implementation"
] | A. Letter | 1 | 64 | A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brother, who lives in Flatland. Now Bob has to send his picture by post, but because of the w... | The first line of the input data contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50), *n* — amount of lines, and *m* — amount of columns on Bob's sheet. The following *n* lines contain *m* characters each. Character «.» stands for a non-shaded square on the sheet, and «*» — for a shaded square. It is guaranteed that ... | Output the required rectangle of the minimum cost. Study the output data in the sample tests to understand the output format better. | [
"6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..\n",
"3 3\n***\n*.*\n***\n"
] | [
"***\n*..\n***\n*..\n***\n",
"***\n*.*\n***\n"
] | none | 0 | [
{
"input": "6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..",
"output": "***\n*..\n***\n*..\n***"
},
{
"input": "3 3\n***\n*.*\n***",
"output": "***\n*.*\n***"
},
{
"input": "1 1\n*",
"output": "*"
},
{
"input": "2 1\n*\n*",
"output": "*\n*"
},
{
"input"... | 1,655,404,388 | 788 | Python 3 | OK | TESTS | 30 | 92 | 0 | args = input().split()
n, m = int(args[0]), int(args[1])
x1, x2 = m, 0
y1, y2 = n, 0
paper = []
for i in range(n):
row = input()
if '*' in row:
y1 = min(y1, i)
y2 = max(y2, i)
x1 = min(x1, row.find('*'))
x2 = max(x2, row.rfind('*'))
paper.append(row)
for h in... | Title: Letter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brothe... | ```python
args = input().split()
n, m = int(args[0]), int(args[1])
x1, x2 = m, 0
y1, y2 = n, 0
paper = []
for i in range(n):
row = input()
if '*' in row:
y1 = min(y1, i)
y2 = max(y2, i)
x1 = min(x1, row.find('*'))
x2 = max(x2, row.rfind('*'))
paper.append(row)
... | 3.954 | MatrixStudio/Codeforces-Python-Submissions |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,694,320,065 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 92 | 0 | raw=int(input())
x=0
l=[4,7,47,44,77,74,444,777,447,474,744,774,747,477]
for i in l:
a=raw/i
if a.is_integer():
print('YES')
break
else:
x+=1
if x==14:
print('NO') | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
raw=int(input())
x=0
l=[4,7,47,44,77,74,444,777,447,474,744,774,747,477]
for i in l:
a=raw/i
if a.is_integer():
print('YES')
break
else:
x+=1
if x==14:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
474 | B | Worms | PROGRAMMING | 1,200 | [
"binary search",
"implementation"
] | null | null | It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers: worms in first pile are labeled with numbers 1 to *a*1, worms in second pile are labeled w... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), the number of piles.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103, *a*1<=+<=*a*2<=+<=...<=+<=*a**n*<=≤<=106), where *a**i* is the number of worms in the *i*-th pile.
The third line contains single integer *m* (... | Print *m* lines to the standard output. The *i*-th line should contain an integer, representing the number of the pile where the worm labeled with the number *q**i* is. | [
"5\n2 7 3 4 9\n3\n1 25 11\n"
] | [
"1\n5\n3\n"
] | For the sample input:
- The worms with labels from [1, 2] are in the first pile. - The worms with labels from [3, 9] are in the second pile. - The worms with labels from [10, 12] are in the third pile. - The worms with labels from [13, 16] are in the fourth pile. - The worms with labels from [17, 25] are in the f... | 1,000 | [
{
"input": "5\n2 7 3 4 9\n3\n1 25 11",
"output": "1\n5\n3"
}
] | 1,690,604,179 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 38 | 170 | 24,064,000 | def solve():
n = int(input())
piles = list(map(int, input().split()))
m = int(input())
jw = list(map(int, input().split()))
index = [0] * (sum(piles) + 1)
cl = 1
for i in range(n):
for j in range(piles[i]):
index[cl] = i + 1
cl += 1
for ... | Title: Worms
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers:... | ```python
def solve():
n = int(input())
piles = list(map(int, input().split()))
m = int(input())
jw = list(map(int, input().split()))
index = [0] * (sum(piles) + 1)
cl = 1
for i in range(n):
for j in range(piles[i]):
index[cl] = i + 1
cl += 1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
687 | B | Remainders Game | PROGRAMMING | 1,800 | [
"chinese remainder theorem",
"math",
"number theory"
] | null | null | Today Pari and Arya are playing a game called Remainders.
Pari chooses two positive integer *x* and *k*, and tells Arya *k* but not *x*. Arya have to find the value . There are *n* ancient numbers *c*1,<=*c*2,<=...,<=*c**n* and Pari has to tell Arya if Arya wants. Given *k* and the ancient values, tell us if Arya has... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*,<= *k*<=≤<=1<=000<=000) — the number of ancient integers and value *k* that is chosen by Pari.
The second line contains *n* integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=1<=000<=000). | Print "Yes" (without quotes) if Arya has a winning strategy independent of value of *x*, or "No" (without quotes) otherwise. | [
"4 5\n2 3 5 12\n",
"2 7\n2 3\n"
] | [
"Yes\n",
"No\n"
] | In the first sample, Arya can understand <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/d170efffcde0907ee6bcf32de21051bce0677a2c.png" style="max-width: 100.0%;max-height: 100.0%;"/> because 5 is one of the ancient numbers.
In the second sample, Arya can't be sure what <img align="middle" ... | 1,000 | [
{
"input": "4 5\n2 3 5 12",
"output": "Yes"
},
{
"input": "2 7\n2 3",
"output": "No"
},
{
"input": "1 6\n8",
"output": "No"
},
{
"input": "2 3\n9 4",
"output": "Yes"
},
{
"input": "4 16\n19 16 13 9",
"output": "Yes"
},
{
"input": "5 10\n5 16 19 9 17",
... | 1,578,316,769 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using ll = long long;
using namespace std;
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
ll n, k, a, g = 1;
cin >> n >> k;
for(ll i = 0; i < n; i++){
cin >> a;
if(!g) break;
g = (a * g / __gcd(a, g)) % k;
}
if (!g)
{
cout << "YES";
... | Title: Remainders Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Pari and Arya are playing a game called Remainders.
Pari chooses two positive integer *x* and *k*, and tells Arya *k* but not *x*. Arya have to find the value . There are *n* ancient numbers *c*1,<=*c*2,<=...,<=*... | ```python
#include <bits/stdc++.h>
using ll = long long;
using namespace std;
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
ll n, k, a, g = 1;
cin >> n >> k;
for(ll i = 0; i < n; i++){
cin >> a;
if(!g) break;
g = (a * g / __gcd(a, g)) % k;
}
if (!g)
{
cout <... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
987 | B | High School: Become Human | PROGRAMMING | 1,100 | [
"math"
] | null | null | Year 2118. Androids are in mass production for decades now, and they do all the work for humans. But androids have to go to school to be able to solve creative tasks. Just like humans before.
It turns out that high school struggles are not gone. If someone is not like others, he is bullied. Vasya-8800 is an economy-cl... | On the only line of input there are two integers $x$ and $y$ ($1 \le x, y \le 10^{9}$). | If $x^y < y^x$, then print '<' (without quotes). If $x^y > y^x$, then print '>' (without quotes). If $x^y = y^x$, then print '=' (without quotes). | [
"5 8\n",
"10 3\n",
"6 6\n"
] | [
">\n",
"<\n",
"=\n"
] | In the first example $5^8 = 5 \cdot 5 \cdot 5 \cdot 5 \cdot 5 \cdot 5 \cdot 5 \cdot 5 = 390625$, and $8^5 = 8 \cdot 8 \cdot 8 \cdot 8 \cdot 8 = 32768$. So you should print '>'.
In the second example $10^3 = 1000 < 3^{10} = 59049$.
In the third example $6^6 = 46656 = 6^6$. | 1,000 | [
{
"input": "5 8",
"output": ">"
},
{
"input": "10 3",
"output": "<"
},
{
"input": "6 6",
"output": "="
},
{
"input": "14 1",
"output": ">"
},
{
"input": "2 4",
"output": "="
},
{
"input": "987654321 123456987",
"output": "<"
},
{
"input": "... | 1,656,327,652 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 61 | 17,715,200 | x, y = [int(i) for i in input().split()]
if x == y : print('==')
if x > y : print('<')
elif x == 1 : print('<')
elif y == 1 : print('>')
elif y > x : print('>') | Title: High School: Become Human
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Year 2118. Androids are in mass production for decades now, and they do all the work for humans. But androids have to go to school to be able to solve creative tasks. Just like humans before.
It turns out tha... | ```python
x, y = [int(i) for i in input().split()]
if x == y : print('==')
if x > y : print('<')
elif x == 1 : print('<')
elif y == 1 : print('>')
elif y > x : print('>')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,697,193,229 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 154 | 0 | num = int(input())
num += 1
while (len(str(num)) != len(set(str(num)))):
num += 1
print(num)
| Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
num = int(input())
num += 1
while (len(str(num)) != len(set(str(num)))):
num += 1
print(num)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,675,855,756 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | w1 = input()
w2 = input()
if len(w1) != len(w2):
print("NO")
else:
status = True
for i in range(len(w1)):
if w1[i] != w2[len(w2)-1-i]:
status = False
break
if status == True:
print("YES")
else:
print("NO")
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
w1 = input()
w2 = input()
if len(w1) != len(w2):
print("NO")
else:
status = True
for i in range(len(w1)):
if w1[i] != w2[len(w2)-1-i]:
status = False
break
if status == True:
print("YES")
else:
print("NO")
... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and ... | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five l... | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,607,406,155 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 10 | 139 | 0 | l, r, a = list(map(int, input().split()))
if (l == r):
print((l+(a//2))*2)
else:
if (min(l, r) + a > max(l , r)):
print(l + r + a)
else:
print((min(l, r)+a)*2)
| Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.... | ```python
l, r, a = list(map(int, input().split()))
if (l == r):
print((l+(a//2))*2)
else:
if (min(l, r) + a > max(l , r)):
print(l + r + a)
else:
print((min(l, r)+a)*2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
846 | A | Curriculum Vitae | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* games. Some of them were successful, some were not. Hideo wants to remove several of them (possibly zer... | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=100).
The second line contains *n* space-separated integer numbers *s*1,<=*s*2,<=...,<=*s**n* (0<=≤<=*s**i*<=≤<=1). 0 corresponds to an unsuccessful game, 1 — to a successful one. | Print one integer — the maximum number of games Hideo can leave in his CV so that no unsuccessful game comes after a successful one. | [
"4\n1 1 0 1\n",
"6\n0 1 0 0 1 0\n",
"1\n0\n"
] | [
"3\n",
"4\n",
"1\n"
] | none | 0 | [
{
"input": "4\n1 1 0 1",
"output": "3"
},
{
"input": "6\n0 1 0 0 1 0",
"output": "4"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "100\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,664,696,748 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 18 | 62 | 2,662,400 | import sys
input = sys.stdin.readline
n = int(input())
w = ''.join(input()[:-1].split())
c = 0
for i in range(n+1):
x = sum(1 for j in w[:i] if j == '0') + sum(1 for j in w[i:] if j == '1')
c = max(c, x)
print(c)
| Title: Curriculum Vitae
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* g... | ```python
import sys
input = sys.stdin.readline
n = int(input())
w = ''.join(input()[:-1].split())
c = 0
for i in range(n+1):
x = sum(1 for j in w[:i] if j == '0') + sum(1 for j in w[i:] if j == '1')
c = max(c, x)
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
255 | A | Greg's Workout | PROGRAMMING | 800 | [
"implementation"
] | null | null | Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg should repeat the *i*-th in order exercise *a**i* times.
Greg now only does three types of exercise... | The first line contains integer *n* (1<=≤<=*n*<=≤<=20). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=25) — the number of times Greg repeats the exercises. | Print word "chest" (without the quotes), if the chest gets the most exercise, "biceps" (without the quotes), if the biceps gets the most exercise and print "back" (without the quotes) if the back gets the most exercise.
It is guaranteed that the input is such that the answer to the problem is unambiguous. | [
"2\n2 8\n",
"3\n5 1 10\n",
"7\n3 3 2 7 9 6 8\n"
] | [
"biceps\n",
"back\n",
"chest\n"
] | In the first sample Greg does 2 chest, 8 biceps and zero back exercises, so the biceps gets the most exercises.
In the second sample Greg does 5 chest, 1 biceps and 10 back exercises, so the back gets the most exercises.
In the third sample Greg does 18 chest, 12 biceps and 8 back exercises, so the chest gets the mos... | 500 | [
{
"input": "2\n2 8",
"output": "biceps"
},
{
"input": "3\n5 1 10",
"output": "back"
},
{
"input": "7\n3 3 2 7 9 6 8",
"output": "chest"
},
{
"input": "4\n5 6 6 2",
"output": "chest"
},
{
"input": "5\n8 2 2 6 3",
"output": "chest"
},
{
"input": "6\n8 7 ... | 1,627,409,276 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 6,963,200 | input()
exerciselist = list(map(int, input().split()))
chest = 0
biceps = 0
back = 0
for i in range(len(exerciselist)):
if i+1 % 3 == 1:
chest += exerciselist[i]
elif i+1 % 3 == 2:
biceps += exerciselist[i]
else:
back += exerciselist[i]
if max(chest, biceps, back) == chest:
pr... | Title: Greg's Workout
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg ... | ```python
input()
exerciselist = list(map(int, input().split()))
chest = 0
biceps = 0
back = 0
for i in range(len(exerciselist)):
if i+1 % 3 == 1:
chest += exerciselist[i]
elif i+1 % 3 == 2:
biceps += exerciselist[i]
else:
back += exerciselist[i]
if max(chest, biceps, back) == che... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
574 | B | Bear and Three Musketeers | PROGRAMMING | 1,500 | [
"brute force",
"dfs and similar",
"graphs",
"hashing"
] | null | null | Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three brave warriors to help him to fight against bad guys.
There are *n* warriors. Richelimakieu wants to choose thre... | The first line contains two space-separated integers, *n* and *m* (3<=≤<=*n*<=≤<=4000, 0<=≤<=*m*<=≤<=4000) — respectively number of warriors and number of pairs of warriors knowing each other.
*i*-th of the following *m* lines contains two space-separated integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**... | If Richelimakieu can choose three musketeers, print the minimum possible sum of their recognitions. Otherwise, print "-1" (without the quotes). | [
"5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5\n",
"7 4\n2 1\n3 6\n5 1\n1 7\n"
] | [
"2\n",
"-1\n"
] | In the first sample Richelimakieu should choose a triple 1, 2, 3. The first musketeer doesn't know anyone except other two musketeers so his recognition is 0. The second musketeer has recognition 1 because he knows warrior number 4. The third musketeer also has recognition 1 because he knows warrior 4. Sum of recogniti... | 1,000 | [
{
"input": "5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5",
"output": "2"
},
{
"input": "7 4\n2 1\n3 6\n5 1\n1 7",
"output": "-1"
},
{
"input": "5 0",
"output": "-1"
},
{
"input": "7 14\n3 6\n2 3\n5 2\n5 6\n7 5\n7 4\n6 2\n3 5\n7 1\n4 1\n6 1\n7 6\n6 4\n5 4",
"output": "5"
},
{
... | 1,450,194,398 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 68,505,600 | n, m = map(int,input().split())
gr = [[False for i in range(n)]for j in range(n)]
deg = [0 for i in range(n)]
ans = 10 ** 10
for _ in range(m):
a,b = map(int,input().split())
gr[a - 1][b - 1] = True
gr[b - 1][a - 1] = True
deg[a - 1] += 1
deg[b - 1] += 1
for i in range(n):
for j in ra... | Title: Bear and Three Musketeers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three br... | ```python
n, m = map(int,input().split())
gr = [[False for i in range(n)]for j in range(n)]
deg = [0 for i in range(n)]
ans = 10 ** 10
for _ in range(m):
a,b = map(int,input().split())
gr[a - 1][b - 1] = True
gr[b - 1][a - 1] = True
deg[a - 1] += 1
deg[b - 1] += 1
for i in range(n):
f... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
255 | A | Greg's Workout | PROGRAMMING | 800 | [
"implementation"
] | null | null | Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg should repeat the *i*-th in order exercise *a**i* times.
Greg now only does three types of exercise... | The first line contains integer *n* (1<=≤<=*n*<=≤<=20). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=25) — the number of times Greg repeats the exercises. | Print word "chest" (without the quotes), if the chest gets the most exercise, "biceps" (without the quotes), if the biceps gets the most exercise and print "back" (without the quotes) if the back gets the most exercise.
It is guaranteed that the input is such that the answer to the problem is unambiguous. | [
"2\n2 8\n",
"3\n5 1 10\n",
"7\n3 3 2 7 9 6 8\n"
] | [
"biceps\n",
"back\n",
"chest\n"
] | In the first sample Greg does 2 chest, 8 biceps and zero back exercises, so the biceps gets the most exercises.
In the second sample Greg does 5 chest, 1 biceps and 10 back exercises, so the back gets the most exercises.
In the third sample Greg does 18 chest, 12 biceps and 8 back exercises, so the chest gets the mos... | 500 | [
{
"input": "2\n2 8",
"output": "biceps"
},
{
"input": "3\n5 1 10",
"output": "back"
},
{
"input": "7\n3 3 2 7 9 6 8",
"output": "chest"
},
{
"input": "4\n5 6 6 2",
"output": "chest"
},
{
"input": "5\n8 2 2 6 3",
"output": "chest"
},
{
"input": "6\n8 7 ... | 1,660,988,866 | 2,147,483,647 | PyPy 3 | OK | TESTS | 61 | 186 | 0 | n=int(input())
a=[]
a=input().split()
b,c,d=0,0,0
for x in range(0,n):
if x%3==0:
b+=int(a[x])
elif x%3==1:
c+=int(a[x])
else:
d+=int(a[x])
if b>=c:
if b>=d:
print("chest")
else:
print("back")
else:
if c>=d:
print("biceps")
e... | Title: Greg's Workout
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg ... | ```python
n=int(input())
a=[]
a=input().split()
b,c,d=0,0,0
for x in range(0,n):
if x%3==0:
b+=int(a[x])
elif x%3==1:
c+=int(a[x])
else:
d+=int(a[x])
if b>=c:
if b>=d:
print("chest")
else:
print("back")
else:
if c>=d:
print("bicep... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
11 | A | Increasing Sequence | PROGRAMMING | 900 | [
"constructive algorithms",
"implementation",
"math"
] | A. Increasing Sequence | 1 | 64 | A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least... | The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106). | Output the minimal number of moves needed to make the sequence increasing. | [
"4 2\n1 3 3 2\n"
] | [
"3\n"
] | none | 0 | [
{
"input": "4 2\n1 3 3 2",
"output": "3"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 1\n2 5",
"output": "0"
},
{
"input": "2 1\n1 2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 7\n10 20",
"output": "0"
},
... | 1,607,082,571 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 154 | 307,200 | n,d = map(int,input().split())
seq = list(map(int,input().split()))
ans = 0
# def recur(seq,d,i):
# if seq[i + 1] > seq[i]:
# return 0
# else:
# seq[i + 1] += d
# return recur(seq,d,i) + 1
# for i in range(len(seq)-1):
# ans += recur(seq,d,i)
# print(ans)
for i in range(len(seq)-1):... | Title: Increasing Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*... | ```python
n,d = map(int,input().split())
seq = list(map(int,input().split()))
ans = 0
# def recur(seq,d,i):
# if seq[i + 1] > seq[i]:
# return 0
# else:
# seq[i + 1] += d
# return recur(seq,d,i) + 1
# for i in range(len(seq)-1):
# ans += recur(seq,d,i)
# print(ans)
for i in range(le... | 0 | MatrixStudio/Codeforces-Python-Submissions |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,627,046,509 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 154 | 6,758,400 | """
The translation from the Berland language into the Birland language is not an easy task.
Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little:
it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word... | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
"""
The translation from the Berland language into the Birland language is not an easy task.
Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little:
it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birla... | 3.948911 | MatrixStudio/Codeforces-Python-Submissions |
980 | A | Links and Pearls | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearls (or between a link and a pearl) on the necklace. This process can be repeated as many times as you l... | The only line of input contains a string $s$ ($3 \leq |s| \leq 100$), representing the necklace, where a dash '-' represents a link and the lowercase English letter 'o' represents a pearl. | Print "YES" if the links and pearls can be rejoined such that the number of links between adjacent pearls is equal. Otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"-o-o--",
"-o---\n",
"-o---o-\n",
"ooo\n"
] | [
"YES",
"YES",
"NO",
"YES\n"
] | none | 500 | [
{
"input": "-o-o--",
"output": "YES"
},
{
"input": "-o---",
"output": "YES"
},
{
"input": "-o---o-",
"output": "NO"
},
{
"input": "ooo",
"output": "YES"
},
{
"input": "---",
"output": "YES"
},
{
"input": "--o-o-----o----o--oo-o-----ooo-oo---o--",
"... | 1,525,792,840 | 940 | Python 3 | OK | TESTS | 69 | 93 | 7,065,600 | s = input()
n = s.count('-')
b = s.count('o')
def solve(n,b):
if b == 0:
return 'YES'
if n == 0:
return 'YES'
if n % b == 0:
return 'YES'
return 'NO'
print(solve(n,b)) | Title: Links and Pearls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearl... | ```python
s = input()
n = s.count('-')
b = s.count('o')
def solve(n,b):
if b == 0:
return 'YES'
if n == 0:
return 'YES'
if n % b == 0:
return 'YES'
return 'NO'
print(solve(n,b))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
855 | B | Marvolo Gaunt's Ring | PROGRAMMING | 1,500 | [
"brute force",
"data structures",
"dp"
] | null | null | Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed it, he is still affected by its curse. Professor Snape is helping Dumbledore remove the curse. For this, he... | First line of input contains 4 integers *n*,<=*p*,<=*q*,<=*r* (<=-<=109<=≤<=*p*,<=*q*,<=*r*<=≤<=109,<=1<=≤<=*n*<=≤<=105).
Next line of input contains *n* space separated integers *a*1,<=*a*2,<=... *a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Output a single integer the maximum value of *p*·*a**i*<=+<=*q*·*a**j*<=+<=*r*·*a**k* that can be obtained provided 1<=≤<=*i*<=≤<=*j*<=≤<=*k*<=≤<=*n*. | [
"5 1 2 3\n1 2 3 4 5\n",
"5 1 2 -3\n-1 -2 -3 -4 -5\n"
] | [
"30\n",
"12\n"
] | In the first sample case, we can take *i* = *j* = *k* = 5, thus making the answer as 1·5 + 2·5 + 3·5 = 30.
In second sample case, selecting *i* = *j* = 1 and *k* = 5 gives the answer 12. | 1,000 | [
{
"input": "5 1 2 3\n1 2 3 4 5",
"output": "30"
},
{
"input": "5 1 2 -3\n-1 -2 -3 -4 -5",
"output": "12"
},
{
"input": "5 886327859 82309257 -68295239\n-731225382 354766539 -48222231 -474691998 360965777",
"output": "376059240645059046"
},
{
"input": "4 -96405765 -495906217 6... | 1,613,234,129 | 29 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 307,200 | n, p, q, r = [int(x) for x in input().split()]
pmax = [] * n
smax = [] * n
#print(type(pmax))
#print(type(smax))
arr = list(map(int, input().split()))[:n]
pmax.append(arr[0])
maxi = arr[0]
for i in range(1, n):
if abs(arr[i]) > abs(maxi):
maxi = arr[i]
pmax.append(arr[i])
else:
pmax.append(maxi)
... | Title: Marvolo Gaunt's Ring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed i... | ```python
n, p, q, r = [int(x) for x in input().split()]
pmax = [] * n
smax = [] * n
#print(type(pmax))
#print(type(smax))
arr = list(map(int, input().split()))[:n]
pmax.append(arr[0])
maxi = arr[0]
for i in range(1, n):
if abs(arr[i]) > abs(maxi):
maxi = arr[i]
pmax.append(arr[i])
else:
pmax.app... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
234 | B | Reading | PROGRAMMING | 1,000 | [
"sortings"
] | null | null | Vasya is going to the Olympics in the city Ntown by train. The boy wants to read the textbook to prepare for the Olympics. He counted that he needed *k* hours for this. He also found that the light in the train changes every hour. The light is measured on a scale from 0 to 100, where 0 is very dark, and 100 is very lig... | The first input line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1000,<=1<=≤<=*k*<=≤<=*n*) — the number of hours on the train and the number of hours to read, correspondingly. The second line contains *n* space-separated integers *a**i* (0<=≤<=*a**i*<=≤<=100), *a**i* is the light level at the *i*-th hour. | In the first output line print the minimum light level Vasya will read at. In the second line print *k* distinct space-separated integers *b*1,<=*b*2,<=...,<=*b**k*, — the indexes of hours Vasya will read at (1<=≤<=*b**i*<=≤<=*n*). The hours are indexed starting from 1. If there are multiple optimal solutions, print an... | [
"5 3\n20 10 30 40 10\n",
"6 5\n90 20 35 40 60 100\n"
] | [
"20\n1 3 4 \n",
"35\n1 3 4 5 6 \n"
] | In the first sample Vasya should read at the first hour (light 20), third hour (light 30) and at the fourth hour (light 40). The minimum light Vasya will have to read at is 20. | 0 | [
{
"input": "5 3\n20 10 30 40 10",
"output": "20\n1 3 4 "
},
{
"input": "6 5\n90 20 35 40 60 100",
"output": "35\n1 3 4 5 6 "
},
{
"input": "100 7\n85 66 9 91 50 46 61 12 55 65 95 1 25 97 95 4 59 59 52 34 94 30 60 11 68 36 17 84 87 68 72 87 46 99 24 66 75 77 75 2 19 3 33 19 7 20 22 3 71 2... | 1,635,756,171 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 4,505,600 | first_line = input().split()
length, limit = int(first_line[0]), int(first_line[1])
full_list = [*map(lambda x: int(x), input().split())]
def min_finder(limit, full_list):
newlist = sorted(full_list, reverse=True)
final_list = newlist[:limit]
print(min(final_list))
indexes = ' '.join(sorted([st... | Title: Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya is going to the Olympics in the city Ntown by train. The boy wants to read the textbook to prepare for the Olympics. He counted that he needed *k* hours for this. He also found that the light in the train changes every ho... | ```python
first_line = input().split()
length, limit = int(first_line[0]), int(first_line[1])
full_list = [*map(lambda x: int(x), input().split())]
def min_finder(limit, full_list):
newlist = sorted(full_list, reverse=True)
final_list = newlist[:limit]
print(min(final_list))
indexes = ' '.join(... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
92 | A | Chips | PROGRAMMING | 800 | [
"implementation",
"math"
] | A. Chips | 2 | 256 | There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus number 1 sits to the left of the walrus number *n*.
The presenter has *m* chips. The pre... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=50, 1<=≤<=*m*<=≤<=104) — the number of walruses and the number of chips correspondingly. | Print the number of chips the presenter ended up with. | [
"4 11\n",
"17 107\n",
"3 8\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first sample the presenter gives one chip to the walrus number 1, two chips to the walrus number 2, three chips to the walrus number 3, four chips to the walrus number 4, then again one chip to the walrus number 1. After that the presenter runs out of chips. He can't give anything to the walrus number 2 and the ... | 500 | [
{
"input": "4 11",
"output": "0"
},
{
"input": "17 107",
"output": "2"
},
{
"input": "3 8",
"output": "1"
},
{
"input": "46 7262",
"output": "35"
},
{
"input": "32 6864",
"output": "0"
},
{
"input": "36 6218",
"output": "14"
},
{
"input": "... | 1,561,624,832 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 218 | 0 | # import sys
# sys.stdin=open("input1.in","r")
# sys.stdout=open("output2.out","w")
N,M=map(int,input().split())
i=1
sum=0
X=1
while i<=M:
M=M-i
i=(i+1)%N
if i==0:
i=N
print(M)
| Title: Chips
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus nu... | ```python
# import sys
# sys.stdin=open("input1.in","r")
# sys.stdout=open("output2.out","w")
N,M=map(int,input().split())
i=1
sum=0
X=1
while i<=M:
M=M-i
i=(i+1)%N
if i==0:
i=N
print(M)
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | An infinitely long railway has a train consisting of *n* cars, numbered from 1 to *n* (the numbers of all the cars are distinct) and positioned in arbitrary order. David Blaine wants to sort the railway cars in the order of increasing numbers. In one move he can make one of the cars disappear from its place and telepor... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of cars in the train.
The second line contains *n* integers *p**i* (1<=≤<=*p**i*<=≤<=*n*, *p**i*<=≠<=*p**j* if *i*<=≠<=*j*) — the sequence of the numbers of the cars in the train. | Print a single integer — the minimum number of actions needed to sort the railway cars. | [
"5\n4 1 2 5 3\n",
"4\n4 1 3 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you need first to teleport the 4-th car, and then the 5-th car to the end of the train. | 0 | [
{
"input": "5\n4 1 2 5 3",
"output": "2"
},
{
"input": "4\n4 1 3 2",
"output": "2"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "6\n5 3 6 1 4 2",
"output": "4"
},
... | 1,449,679,518 | 2,418 | Python 3 | OK | TESTS | 66 | 202 | 8,089,600 | read = lambda: map(int, input().split())
n = int(input())
p = list(read())
cur = set()
d = [1] * (n + 1)
for i in range(n):
if p[i] in cur:
cur.remove(p[i])
d[p[i]] = max(d[p[i]], d[p[i] - 1] + 1)
cur.add(p[i] + 1)
ans = n - max(d)
print(ans) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An infinitely long railway has a train consisting of *n* cars, numbered from 1 to *n* (the numbers of all the cars are distinct) and positioned in arbitrary order. David Blaine wants to sort the railway cars in the order of increa... | ```python
read = lambda: map(int, input().split())
n = int(input())
p = list(read())
cur = set()
d = [1] * (n + 1)
for i in range(n):
if p[i] in cur:
cur.remove(p[i])
d[p[i]] = max(d[p[i]], d[p[i] - 1] + 1)
cur.add(p[i] + 1)
ans = n - max(d)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
352 | A | Jeff and Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"math"
] | null | null | Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make from the cards he's got?
Jeff must make the number without leading zero. At that, we assume that numbe... | The first line contains integer *n* (1<=≤<=*n*<=≤<=103). The next line contains *n* integers *a*1, *a*2, ..., *a**n* (*a**i*<==<=0 or *a**i*<==<=5). Number *a**i* represents the digit that is written on the *i*-th card. | In a single line print the answer to the problem — the maximum number, divisible by 90. If you can't make any divisible by 90 number from the cards, print -1. | [
"4\n5 0 5 0\n",
"11\n5 5 5 5 5 5 5 5 0 5 5\n"
] | [
"0\n",
"5555555550\n"
] | In the first test you can make only one number that is a multiple of 90 — 0.
In the second test you can make number 5555555550, it is a multiple of 90. | 500 | [
{
"input": "4\n5 0 5 0",
"output": "0"
},
{
"input": "11\n5 5 5 5 5 5 5 5 0 5 5",
"output": "5555555550"
},
{
"input": "7\n5 5 5 5 5 5 5",
"output": "-1"
},
{
"input": "1\n5",
"output": "-1"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "11\n5 0 5 ... | 1,688,629,720 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 124 | 0 | from collections import Counter
n = int(input())
a = Counter(list(map(int, input().split(' '))))
print("5" * 9 *((a[5] - 1) // 9) + "0")
| Title: Jeff and Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make fr... | ```python
from collections import Counter
n = int(input())
a = Counter(list(map(int, input().split(' '))))
print("5" * 9 *((a[5] - 1) // 9) + "0")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,678,903,035 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 46 | 0 | x,y,z = map(int,input().split())
if x<=y<=z or z<=y<=x:
print(abs(y-z) + abs(y-x))
elif y<=x<=z or z<=x<=y:
print(abs(x-z) + abs(y-x))
else:
print(abs(y-z) + abs(z-x))
| Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
x,y,z = map(int,input().split())
if x<=y<=z or z<=y<=x:
print(abs(y-z) + abs(y-x))
elif y<=x<=z or z<=x<=y:
print(abs(x-z) + abs(y-x))
else:
print(abs(y-z) + abs(z-x))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
31 | A | Worms Evolution | PROGRAMMING | 1,200 | [
"implementation"
] | A. Worms Evolution | 2 | 256 | Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his theory, professor needs to find 3 different forms that the length of the first form is equal to ... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of worm's forms. The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=1000) — lengths of worms of each form. | Output 3 distinct integers *i* *j* *k* (1<=≤<=*i*,<=*j*,<=*k*<=≤<=*n*) — such indexes of worm's forms that *a**i*<==<=*a**j*<=+<=*a**k*. If there is no such triple, output -1. If there are several solutions, output any of them. It possible that *a**j*<==<=*a**k*. | [
"5\n1 2 3 5 7\n",
"5\n1 8 1 5 1\n"
] | [
"3 2 1\n",
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 5 7",
"output": "3 2 1"
},
{
"input": "5\n1 8 1 5 1",
"output": "-1"
},
{
"input": "4\n303 872 764 401",
"output": "-1"
},
{
"input": "6\n86 402 133 524 405 610",
"output": "6 4 1"
},
{
"input": "8\n217 779 418 895 996 473 3 22",
"output":... | 1,635,000,166 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 4,505,600 | n = int(input())
lista = list(map(int, input().split()))
lista = sorted(lista)
sum = 0
flag = False
for idx1, i in enumerate(lista):
for idx2, j in enumerate(lista):
if(idx1 == idx2):
continue
for k, a in enumerate(lista):
if a == i + j:
sum = ... | Title: Worms Evolution
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his... | ```python
n = int(input())
lista = list(map(int, input().split()))
lista = sorted(lista)
sum = 0
flag = False
for idx1, i in enumerate(lista):
for idx2, j in enumerate(lista):
if(idx1 == idx2):
continue
for k, a in enumerate(lista):
if a == i + j:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
66 | B | Petya and Countryside | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | B. Petya and Countryside | 2 | 256 | Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *n* equal square sections. The garden is very unusual as each of the square sections possesses its own f... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* positive integers which are the height of the sections. All the numbers are no less than 1 and not more than 1000. | Print a single number, the maximal number of watered sections if we create artificial rain above exactly one section. | [
"1\n2\n",
"5\n1 2 1 2 1\n",
"8\n1 2 1 1 1 3 3 4\n"
] | [
"1\n",
"3\n",
"6\n"
] | none | 1,000 | [
{
"input": "1\n2",
"output": "1"
},
{
"input": "5\n1 2 1 2 1",
"output": "3"
},
{
"input": "8\n1 2 1 1 1 3 3 4",
"output": "6"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "10"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "10"
},
{
"input... | 1,666,769,538 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 0 | n = int(input())
nums = list(map(int, input().split()))
maxLeft, maxRight, start = 0, 0, 0
while i < n-1:
if nums[i] >= nums[i+1]:
start = i
while i < n - 1 and nums[i] >= nums[i+1]:
i += 1
maxLeft = max(maxLeft, i - start)
else:
i += 1
while i > 0:
... | Title: Petya and Countryside
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *... | ```python
n = int(input())
nums = list(map(int, input().split()))
maxLeft, maxRight, start = 0, 0, 0
while i < n-1:
if nums[i] >= nums[i+1]:
start = i
while i < n - 1 and nums[i] >= nums[i+1]:
i += 1
maxLeft = max(maxLeft, i - start)
else:
i += 1
whil... | -1 | MatrixStudio/Codeforces-Python-Submissions |
681 | A | A Good Contest | PROGRAMMING | 800 | [
"implementation"
] | null | null | Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part in a rated contest, his rating is changed depending on his performance.
Anton wants the color of hi... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants Anton has outscored in this contest .
The next *n* lines describe participants results: the *i*-th of them consists of a participant handle *name**i* and two integers *before**i* and *after**i* (<=-<=4000<=≤<=*be... | Print «YES» (quotes for clarity), if Anton has performed good in the contest and «NO» (quotes for clarity) otherwise. | [
"3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749\n",
"3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450\n"
] | [
"YES",
"NO"
] | In the first sample, Anton has outscored user with handle Burunduk1, whose handle was colored red before the contest and his rating has increased after the contest.
In the second sample, Applejack's rating has not increased after the contest, while both Fluttershy's and Pinkie_Pie's handles were not colored red before... | 500 | [
{
"input": "3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749",
"output": "YES"
},
{
"input": "3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450",
"output": "NO"
},
{
"input": "1\nDb -3373 3591",
"output": "NO"
},
{
"input": "5\nQ2bz 960 2342... | 1,630,917,102 | 2,147,483,647 | PyPy 3 | OK | TESTS | 60 | 109 | 20,172,800 | n = int(input())
x,y = [], []
for i in range(n):
a,b,c = map(str, input().split())
x.append(int(b))
y.append(int(c))
g = any([True if j > i and i >= 2400 else False for i,j in zip(x,y)])
print("YES" if g else "NO") | Title: A Good Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part ... | ```python
n = int(input())
x,y = [], []
for i in range(n):
a,b,c = map(str, input().split())
x.append(int(b))
y.append(int(c))
g = any([True if j > i and i >= 2400 else False for i,j in zip(x,y)])
print("YES" if g else "NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
980 | A | Links and Pearls | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearls (or between a link and a pearl) on the necklace. This process can be repeated as many times as you l... | The only line of input contains a string $s$ ($3 \leq |s| \leq 100$), representing the necklace, where a dash '-' represents a link and the lowercase English letter 'o' represents a pearl. | Print "YES" if the links and pearls can be rejoined such that the number of links between adjacent pearls is equal. Otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"-o-o--",
"-o---\n",
"-o---o-\n",
"ooo\n"
] | [
"YES",
"YES",
"NO",
"YES\n"
] | none | 500 | [
{
"input": "-o-o--",
"output": "YES"
},
{
"input": "-o---",
"output": "YES"
},
{
"input": "-o---o-",
"output": "NO"
},
{
"input": "ooo",
"output": "YES"
},
{
"input": "---",
"output": "YES"
},
{
"input": "--o-o-----o----o--oo-o-----ooo-oo---o--",
"... | 1,525,792,271 | 371 | Python 3 | OK | TESTS | 69 | 93 | 7,065,600 | necklace = input()
pearls = 0
links = 0
for c in necklace:
if c == '-':
links += 1
else:
pearls += 1
if pearls == 0 or links % pearls == 0:
print('YES')
else:
print('NO')
| Title: Links and Pearls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearl... | ```python
necklace = input()
pearls = 0
links = 0
for c in necklace:
if c == '-':
links += 1
else:
pearls += 1
if pearls == 0 or links % pearls == 0:
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,686,319,869 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | s=str(input())
d={"UPPER":0, "LOWER":0}
for i in s:
if i.isupper():
d["UPPER"]+=1
elif i.islower():
d["LOWER"]+=1
else:
pass
if d["UPPER"]> d["LOWER"]:
print(s.upper())
else:
print(s.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s=str(input())
d={"UPPER":0, "LOWER":0}
for i in s:
if i.isupper():
d["UPPER"]+=1
elif i.islower():
d["LOWER"]+=1
else:
pass
if d["UPPER"]> d["LOWER"]:
print(s.upper())
else:
print(s.lower())
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,542,305,696 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 372 | 1,024,000 | scores = {}
queue = []
for _ in range(int(input())):
name, score = input().split()
queue.append((name, score))
scores[name] = scores.get(name, 0) + int(score)
m = max(scores)
scores = {}
for name, score in queue:
scores[name] = scores.get(name, 0) + int(score)
if scores[name] >= m:... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
scores = {}
queue = []
for _ in range(int(input())):
name, score = input().split()
queue.append((name, score))
scores[name] = scores.get(name, 0) + int(score)
m = max(scores)
scores = {}
for name, score in queue:
scores[name] = scores.get(name, 0) + int(score)
if scores[n... | -1 | MatrixStudio/Codeforces-Python-Submissions |
32 | A | Reconnaissance | PROGRAMMING | 800 | [
"brute force"
] | A. Reconnaissance | 2 | 256 | According to the regulations of Berland's army, a reconnaissance unit should consist of exactly two soldiers. Since these two soldiers shouldn't differ much, their heights can differ by at most *d* centimeters. Captain Bob has *n* soldiers in his detachment. Their heights are *a*1,<=*a*2,<=...,<=*a**n* centimeters. Som... | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=1000,<=1<=≤<=*d*<=≤<=109) — amount of soldiers in Bob's detachment and the maximum allowed height difference respectively. The second line contains *n* space-separated integers — heights of all the soldiers in Bob's detachment. These numbers don't exceed 1... | Output one number — amount of ways to form a reconnaissance unit of two soldiers, whose height difference doesn't exceed *d*. | [
"5 10\n10 20 50 60 65\n",
"5 1\n55 30 29 31 55\n"
] | [
"6\n",
"6\n"
] | none | 500 | [
{
"input": "5 10\n10 20 50 60 65",
"output": "6"
},
{
"input": "5 1\n55 30 29 31 55",
"output": "6"
},
{
"input": "6 10\n4 6 4 1 9 3",
"output": "30"
},
{
"input": "7 100\n19 1694 261 162 1 234 513",
"output": "8"
},
{
"input": "8 42\n37 53 74 187 568 22 5 65",
... | 1,619,965,794 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 560 | 0 | n,d=map(int,input().split())
c=0
l=list(map(int,input().split()))
for i in range(n):
for j in range(i+1,n):
if(abs(l[i]-l[j])<=d):
c+=2
print(c) | Title: Reconnaissance
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
According to the regulations of Berland's army, a reconnaissance unit should consist of exactly two soldiers. Since these two soldiers shouldn't differ much, their heights can differ by at most *d* centimeters. Captain Bob h... | ```python
n,d=map(int,input().split())
c=0
l=list(map(int,input().split()))
for i in range(n):
for j in range(i+1,n):
if(abs(l[i]-l[j])<=d):
c+=2
print(c)
``` | 3.86 | MatrixStudio/Codeforces-Python-Submissions |
376 | A | Lever | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | You have a description of a lever as string *s*. We'll represent the string length as record |*s*|, then the lever looks as a horizontal bar with weights of length |*s*|<=-<=1 with exactly one pivot. We will assume that the bar is a segment on the *Ox* axis between points 0 and |*s*|<=-<=1.
The decoding of the lever d... | The first line contains the lever description as a non-empty string *s* (3<=≤<=|*s*|<=≤<=106), consisting of digits (1-9) and characters "^" and "=". It is guaranteed that the line contains exactly one character "^". It is guaranteed that the pivot of the lever isn't located in any end of the lever bar.
To solve the p... | Print "left" if the given lever tilts to the left, "right" if it tilts to the right and "balance", if it is in balance. | [
"=^==\n",
"9===^==1\n",
"2==^7==\n",
"41^52==\n"
] | [
"balance\n",
"left\n",
"right\n",
"balance\n"
] | As you solve the problem, you may find the following link useful to better understand how a lever functions: http://en.wikipedia.org/wiki/Lever.
The pictures to the examples: | 500 | [
{
"input": "=^==",
"output": "balance"
},
{
"input": "9===^==1",
"output": "left"
},
{
"input": "2==^7==",
"output": "right"
},
{
"input": "41^52==",
"output": "balance"
},
{
"input": "=^2=4=1===1=",
"output": "right"
},
{
"input": "9=6===5==3=9=1=1^7=... | 1,446,897,574 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | s = [d for d in input()]
w = [0,0]
d = 0
for i in s:
if i == "^":
d = 1
elif i == "=":
continue
else:
w[d] += int(i)
if w[0] == w[1] :
print("balance")
elif w[0] > w[1]:
print("left")
else:
print("right") | Title: Lever
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a description of a lever as string *s*. We'll represent the string length as record |*s*|, then the lever looks as a horizontal bar with weights of length |*s*|<=-<=1 with exactly one pivot. We will assume that the bar i... | ```python
s = [d for d in input()]
w = [0,0]
d = 0
for i in s:
if i == "^":
d = 1
elif i == "=":
continue
else:
w[d] += int(i)
if w[0] == w[1] :
print("balance")
elif w[0] > w[1]:
print("left")
else:
print("right")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,678,445,689 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 |
for _ in range(int(input())):
count=0
a,b,c,d=map(int,input().split())
s = input()
for i in s:
if i=='1':
count+=a
elif i=='2':
count+=b
elif i=='3':
count+=c
elif i=='4':
count+=d
print(count)
... | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
for _ in range(int(input())):
count=0
a,b,c,d=map(int,input().split())
s = input()
for i in s:
if i=='1':
count+=a
elif i=='2':
count+=b
elif i=='3':
count+=c
elif i=='4':
count+=d
print(count)
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
549 | A | Face Detection | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2<... | The first line contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the height and the width of the image, respectively.
Next *n* lines define the image. Each line contains *m* lowercase Latin letters. | In the single line print the number of faces on the image. | [
"4 4\nxxxx\nxfax\nxcex\nxxxx\n",
"4 2\nxx\ncf\nae\nxx\n",
"2 3\nfac\ncef\n",
"1 4\nface\n"
] | [
"1\n",
"1\n",
"2\n",
"0\n"
] | In the first sample the image contains a single face, located in a square with the upper left corner at the second line and the second column:
In the second sample the image also contains exactly one face, its upper left corner is at the second row and the first column.
In the third sample two faces are shown:
In ... | 250 | [
{
"input": "4 4\nxxxx\nxfax\nxcex\nxxxx",
"output": "1"
},
{
"input": "4 2\nxx\ncf\nae\nxx",
"output": "1"
},
{
"input": "2 3\nfac\ncef",
"output": "2"
},
{
"input": "1 4\nface",
"output": "0"
},
{
"input": "5 5\nwmmwn\nlurcm\nkeetd\nfokon\ncxxgx",
"output": "... | 1,594,207,442 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 155 | 22,220,800 | n,m = map(int,input().split())
g = [input() for i in range(n)]
def solve(sub):
chars = ''
for x in sub:
for y in x:
chars += y
return sorted(chars) == sorted('face')
ans = 0
for i in range(n-1):
for j in range(m-1):
if solve([[g[i][j],g[i+1][j],g[i][j+1],g[i+1][j+1... | Title: Face Detection
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem a... | ```python
n,m = map(int,input().split())
g = [input() for i in range(n)]
def solve(sub):
chars = ''
for x in sub:
for y in x:
chars += y
return sorted(chars) == sorted('face')
ans = 0
for i in range(n-1):
for j in range(m-1):
if solve([[g[i][j],g[i+1][j],g[i][j+1],... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,676,534,565 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 46 | 0 | n, d = map(int, input().split())
g = str(input())
a, col = [str(i) for i in g], 0
a.pop(0)
while a != [] and a[:d] != [0] * n:
g = a[0:d]
g.reverse()
if "1" in g:
ind, col = g.index("1"), col + 1
else:
print(-1)
exit()
a = a[d- ind:]
print(col) if a == [] else pr... | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
n, d = map(int, input().split())
g = str(input())
a, col = [str(i) for i in g], 0
a.pop(0)
while a != [] and a[:d] != [0] * n:
g = a[0:d]
g.reverse()
if "1" in g:
ind, col = g.index("1"), col + 1
else:
print(-1)
exit()
a = a[d- ind:]
print(col) if a == ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,673,261,475 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 46 | 0 | x,y=map(int,input().split())
if(x>y):
remain=y
p = (x-y) // 2
else:
remain=x
p = (y - x) // 2
print(remain,p) | Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
x,y=map(int,input().split())
if(x>y):
remain=y
p = (x-y) // 2
else:
remain=x
p = (y - x) // 2
print(remain,p)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,631,095,125 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 154 | 0 | inp = input()
ll = list(map(int, inp.split()))
val = ll[0] * ll[1]
if val % 2 == 0:
print(int(val/2))
else:
print(int((val-1)/2)) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
inp = input()
ll = list(map(int, inp.split()))
val = ll[0] * ll[1]
if val % 2 == 0:
print(int(val/2))
else:
print(int((val-1)/2))
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
518 | A | Vitaly and Strings | PROGRAMMING | 1,600 | [
"constructive algorithms",
"strings"
] | null | null | Vitaly is a diligent student who never missed a lesson in his five years of studying in the university. He always does his homework on time and passes his exams in time.
During the last lesson the teacher has provided two strings *s* and *t* to Vitaly. The strings have the same length, they consist of lowercase Engli... | The first line contains string *s* (1<=≤<=|*s*|<=≤<=100), consisting of lowercase English letters. Here, |*s*| denotes the length of the string.
The second line contains string *t* (|*t*|<==<=|*s*|), consisting of lowercase English letters.
It is guaranteed that the lengths of strings *s* and *t* are the same and str... | If the string that meets the given requirements doesn't exist, print a single string "No such string" (without the quotes).
If such string exists, print it. If there are multiple valid strings, you may print any of them. | [
"a\nc\n",
"aaa\nzzz\n",
"abcdefg\nabcdefh\n"
] | [
"b\n",
"kkk\n",
"No such string\n"
] | String *s* = *s*<sub class="lower-index">1</sub>*s*<sub class="lower-index">2</sub>... *s*<sub class="lower-index">*n*</sub> is said to be lexicographically smaller than *t* = *t*<sub class="lower-index">1</sub>*t*<sub class="lower-index">2</sub>... *t*<sub class="lower-index">*n*</sub>, if there exists such *i*, that ... | 500 | [
{
"input": "a\nc",
"output": "b"
},
{
"input": "aaa\nzzz",
"output": "kkk"
},
{
"input": "abcdefg\nabcdefh",
"output": "No such string"
},
{
"input": "abcdefg\nabcfefg",
"output": "abcdefh"
},
{
"input": "frt\nfru",
"output": "No such string"
},
{
"inp... | 1,540,598,266 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 109 | 0 | # Tran Duy_Big O Blue
s = list(input())
t = list(input())
check = False
for i in range(len(s)):
if ord(s[i])+1 >= ord(t[i]) and i == len(s)-1:
check = False
elif ord(s[i])+1 < ord(t[i]):
check = True
s[i] = chr(ord(s[i])+1)
s = ''.join(s)
break
if check is T... | Title: Vitaly and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly is a diligent student who never missed a lesson in his five years of studying in the university. He always does his homework on time and passes his exams in time.
During the last lesson the teacher has provi... | ```python
# Tran Duy_Big O Blue
s = list(input())
t = list(input())
check = False
for i in range(len(s)):
if ord(s[i])+1 >= ord(t[i]) and i == len(s)-1:
check = False
elif ord(s[i])+1 < ord(t[i]):
check = True
s[i] = chr(ord(s[i])+1)
s = ''.join(s)
break
if ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
168 | A | Wizards and Demonstration | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Some country is populated by wizards. They want to organize a demonstration.
There are *n* people living in the city, *x* of them are the wizards who will surely go to the demonstration. Other city people (*n*<=-<=*x* people) do not support the wizards and aren't going to go to the demonstration. We know that the city... | The first line contains three space-separated integers, *n*, *x*, *y* (1<=≤<=*n*,<=*x*,<=*y*<=≤<=104,<=*x*<=≤<=*n*) — the number of citizens in the city, the number of wizards and the percentage the administration needs, correspondingly.
Please note that *y* can exceed 100 percent, that is, the administration wants to... | Print a single integer — the answer to the problem, the minimum number of clones to create, so that the demonstration involved no less than *y* percent of *n* (the real total city population). | [
"10 1 14\n",
"20 10 50\n",
"1000 352 146\n"
] | [
"1\n",
"0\n",
"1108\n"
] | In the first sample it is necessary that at least 14% of 10 people came to the demonstration. As the number of people should be integer, then at least two people should come. There is only one wizard living in the city and he is going to come. That isn't enough, so he needs to create one clone.
In the second sample 1... | 500 | [
{
"input": "10 1 14",
"output": "1"
},
{
"input": "20 10 50",
"output": "0"
},
{
"input": "1000 352 146",
"output": "1108"
},
{
"input": "68 65 20",
"output": "0"
},
{
"input": "78 28 27",
"output": "0"
},
{
"input": "78 73 58",
"output": "0"
},
... | 1,552,296,414 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 218 | 0 | from math import ceil
n, x, y = map(int, input().split())
print(max(0, ceil(n * y / 100) - x))
| Title: Wizards and Demonstration
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some country is populated by wizards. They want to organize a demonstration.
There are *n* people living in the city, *x* of them are the wizards who will surely go to the demonstration. Other city people (*n... | ```python
from math import ceil
n, x, y = map(int, input().split())
print(max(0, ceil(n * y / 100) - x))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
454 | A | Little Pony and Crystal Mine | PROGRAMMING | 800 | [
"implementation"
] | null | null | Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You need to draw a crystal of size *n*. The diamond cells of the matrix should be represented by character "D". All ot... | The only line contains an integer *n* (3<=≤<=*n*<=≤<=101; *n* is odd). | Output a crystal of size *n*. | [
"3\n",
"5\n",
"7\n"
] | [
"*D*\nDDD\n*D*\n",
"**D**\n*DDD*\nDDDDD\n*DDD*\n**D**\n",
"***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***\n"
] | none | 500 | [
{
"input": "3",
"output": "*D*\nDDD\n*D*"
},
{
"input": "5",
"output": "**D**\n*DDD*\nDDDDD\n*DDD*\n**D**"
},
{
"input": "7",
"output": "***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***"
},
{
"input": "11",
"output": "*****D*****\n****DDD****\n***DDDDD***\n**... | 1,612,033,496 | 2,147,483,647 | PyPy 3 | OK | TESTS | 12 | 93 | 0 | #...START BY DOING WHAT IS NECESSARY, THEN WHAT IS POSSIBLE AND SUDDENLY YOU ARE DOING THE IMPOSSIBLE...
import math
t = 1
# t = int(input())
for _ in range(t):
#arr = list(map(int,input().split()))
n = int(input())
l = []
for i in range(n//2):
s = '*'*(n//2-i) + 'D'*(2*i+1) + '*'... | Title: Little Pony and Crystal Mine
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You ... | ```python
#...START BY DOING WHAT IS NECESSARY, THEN WHAT IS POSSIBLE AND SUDDENLY YOU ARE DOING THE IMPOSSIBLE...
import math
t = 1
# t = int(input())
for _ in range(t):
#arr = list(map(int,input().split()))
n = int(input())
l = []
for i in range(n//2):
s = '*'*(n//2-i) + 'D'*(2*... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
746 | B | Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, inf... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2000) — the length of the encoded word.
The second line contains the string *s* of length *n* consisting of lowercase English letters — the encoding. | Print the word that Polycarp encoded. | [
"5\nlogva\n",
"2\nno\n",
"4\nabba\n"
] | [
"volga\n",
"no\n",
"baba\n"
] | In the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word bec... | 1,000 | [
{
"input": "5\nlogva",
"output": "volga"
},
{
"input": "2\nno",
"output": "no"
},
{
"input": "4\nabba",
"output": "baba"
},
{
"input": "51\nkfsmpaeviowvkdbuhdagquxxqniselafnfbrgbhmsugcbbnlrvv",
"output": "vlbcumbrfflsnxugdudvovamfkspeiwkbhaqxqieanbghsgbnrv"
},
{
"... | 1,642,490,539 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 614,400 | n = int(input())
s = str(input())
if n==1 or n==2:
print(s)
elif n%2 != 0:
ans = ''
for i in range(len(s)):
if i%2 == 0:
ans+=s[i]
else:
ans = s[i]+ans
print(ans)
else:
ans = s[:2]
for i in range(2, len(s)):
if i%2 == 0:
... | Title: Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the... | ```python
n = int(input())
s = str(input())
if n==1 or n==2:
print(s)
elif n%2 != 0:
ans = ''
for i in range(len(s)):
if i%2 == 0:
ans+=s[i]
else:
ans = s[i]+ans
print(ans)
else:
ans = s[:2]
for i in range(2, len(s)):
if i%2 == 0:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,696,137,894 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | Input = int(input())
'''
Option 1:
Lucky, only contains numbers 4 and 7
Option2:
Almost Lucky, divisible by either 4 or 7
'''
def isLucky(number):
Set = set([4,7])
lucky = True
while number > 0:
digit = number % 10
number = number // 10 #this will floor it
if digit not in Set:
... | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
Input = int(input())
'''
Option 1:
Lucky, only contains numbers 4 and 7
Option2:
Almost Lucky, divisible by either 4 or 7
'''
def isLucky(number):
Set = set([4,7])
lucky = True
while number > 0:
digit = number % 10
number = number // 10 #this will floor it
if digit not i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
244 | A | Dividing Orange | PROGRAMMING | 900 | [
"implementation"
] | null | null | One day Ms Swan bought an orange in a shop. The orange consisted of *n*·*k* segments, numbered with integers from 1 to *n*·*k*.
There were *k* children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper... | The first line contains two integers *n*, *k* (1<=≤<=*n*,<=*k*<=≤<=30). The second line contains *k* space-separated integers *a*1,<=*a*2,<=...,<=*a**k* (1<=≤<=*a**i*<=≤<=*n*·*k*), where *a**i* is the number of the orange segment that the *i*-th child would like to get.
It is guaranteed that all numbers *a**i* are dis... | Print exactly *n*·*k* distinct integers. The first *n* integers represent the indexes of the segments the first child will get, the second *n* integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.
You can print a child's segment indexes in a... | [
"2 2\n4 1\n",
"3 1\n2\n"
] | [
"2 4 \n1 3 \n",
"3 2 1 \n"
] | none | 500 | [
{
"input": "2 2\n4 1",
"output": "2 4 \n1 3 "
},
{
"input": "3 1\n2",
"output": "3 2 1 "
},
{
"input": "5 5\n25 24 23 22 21",
"output": "2 3 1 25 4 \n7 6 8 5 24 \n10 12 9 23 11 \n13 15 14 16 22 \n19 21 20 17 18 "
},
{
"input": "1 30\n8 22 13 25 10 30 12 27 6 4 7 2 20 16 26 14... | 1,599,250,585 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 216 | 307,200 | in1 = [int(i) for i in input().split()]
n, k = in1[0], in1[1]
segments = input()
a = [int(x) for x in segments.split()]
r = [[0 for i in range(n)] for j in range(k)]
indexes = [i+1 for i in range(n * k)]
filtered = list(filter(lambda x: x not in a, indexes))
for i in range(k):
r[i] = filtered[i*(n-1):i*(n-1) ... | Title: Dividing Orange
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Ms Swan bought an orange in a shop. The orange consisted of *n*·*k* segments, numbered with integers from 1 to *n*·*k*.
There were *k* children waiting for Ms Swan at home. The children have recently learned a... | ```python
in1 = [int(i) for i in input().split()]
n, k = in1[0], in1[1]
segments = input()
a = [int(x) for x in segments.split()]
r = [[0 for i in range(n)] for j in range(k)]
indexes = [i+1 for i in range(n * k)]
filtered = list(filter(lambda x: x not in a, indexes))
for i in range(k):
r[i] = filtered[i*(n-1... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
5 | A | Chat Servers Outgoing Traffic | PROGRAMMING | 1,000 | [
"implementation"
] | A. Chat Server's Outgoing Traffic | 1 | 64 | Polycarp is working on a new project called "Polychat". Following modern tendencies in IT, he decided, that this project should contain chat as well. To achieve this goal, Polycarp has spent several hours in front of his laptop and implemented a chat server that can process three types of commands:
- Include a person... | Input file will contain not more than 100 commands, each in its own line. No line will exceed 100 characters. Formats of the commands will be the following:
- +<name> for 'Add' command. - -<name> for 'Remove' command. - <sender_name>:<message_text> for 'Send' command.
<name> and <s... | Print a single number — answer to the problem. | [
"+Mike\nMike:hello\n+Kate\n+Dmitry\n-Dmitry\nKate:hi\n-Kate\n",
"+Mike\n-Mike\n+Mike\nMike:Hi I am here\n-Mike\n+Kate\n-Kate\n"
] | [
"9\n",
"14\n"
] | none | 0 | [
{
"input": "+Mike\nMike:hello\n+Kate\n+Dmitry\n-Dmitry\nKate:hi\n-Kate",
"output": "9"
},
{
"input": "+Mike\n-Mike\n+Mike\nMike:Hi I am here\n-Mike\n+Kate\n-Kate",
"output": "14"
},
{
"input": "+Dmitry\n+Mike\nDmitry:All letters will be used\nDmitry:qwertyuiopasdfghjklzxcvbnm QWERTYUIO... | 1,398,405,127 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | s = input().split('\n')
p, res = 0, 0
for x in s:
if x[0] == '+': p += 1
elif x[0] == '-': p -= 1
else: res += p*len(x.split(':')[1])
print(res) | Title: Chat Servers Outgoing Traffic
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Polycarp is working on a new project called "Polychat". Following modern tendencies in IT, he decided, that this project should contain chat as well. To achieve this goal, Polycarp has spent several hours in fr... | ```python
s = input().split('\n')
p, res = 0, 0
for x in s:
if x[0] == '+': p += 1
elif x[0] == '-': p -= 1
else: res += p*len(x.split(':')[1])
print(res)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
415 | A | Mashmokh and Lights | PROGRAMMING | 900 | [
"implementation"
] | null | null | Mashmokh works in a factory. At the end of each day he must turn off all of the lights.
The lights on the factory are indexed from 1 to *n*. There are *n* buttons in Mashmokh's room indexed from 1 to *n* as well. If Mashmokh pushes button with index *i*, then each light with index not less than *i* that is still turn... | The first line of the input contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), the number of the factory lights and the pushed buttons respectively. The next line contains *m* distinct space-separated integers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**i*<=≤<=*n*).
It is guaranteed that all lights... | Output *n* space-separated integers where the *i*-th number is index of the button that turns the *i*-th light off. | [
"5 4\n4 3 1 2\n",
"5 5\n5 4 3 2 1\n"
] | [
"1 1 3 4 4 \n",
"1 2 3 4 5 \n"
] | In the first sample, after pressing button number 4, lights 4 and 5 are turned off and lights 1, 2 and 3 are still on. Then after pressing button number 3, light number 3 is turned off as well. Pressing button number 1 turns off lights number 1 and 2 as well so pressing button number 2 in the end has no effect. Thus bu... | 500 | [
{
"input": "5 4\n4 3 1 2",
"output": "1 1 3 4 4 "
},
{
"input": "5 5\n5 4 3 2 1",
"output": "1 2 3 4 5 "
},
{
"input": "16 11\n8 5 12 10 14 2 6 3 15 9 1",
"output": "1 2 2 2 5 5 5 8 8 8 8 8 8 8 8 8 "
},
{
"input": "79 22\n76 32 48 28 33 44 58 59 1 51 77 13 15 64 49 72 74 21 6... | 1,531,274,550 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 124 | 0 | a,b=map(int,input().split())
list2=[0]*a
list=list(map(int,(input().split())))
for i in range(b):
for s in range(a-list[i]+1):
if list2[list[i]+s-1]==0:
list2[list[i]+s-1]=list[i]
result=''
for i in range(a):
result=result+str(list2[i])+' '
print(result) | Title: Mashmokh and Lights
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mashmokh works in a factory. At the end of each day he must turn off all of the lights.
The lights on the factory are indexed from 1 to *n*. There are *n* buttons in Mashmokh's room indexed from 1 to *n* as well. ... | ```python
a,b=map(int,input().split())
list2=[0]*a
list=list(map(int,(input().split())))
for i in range(b):
for s in range(a-list[i]+1):
if list2[list[i]+s-1]==0:
list2[list[i]+s-1]=list[i]
result=''
for i in range(a):
result=result+str(list2[i])+' '
print(result)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
254 | A | Cards with Numbers | PROGRAMMING | 1,200 | [
"constructive algorithms",
"sortings"
] | null | null | Petya has got 2*n* cards, each card contains some integer. The numbers on the cards can be the same. Let's index all cards by consecutive integers from 1 to 2*n*. We'll denote the number that is written on a card with number *i*, as *a**i*. In order to play one entertaining game with his friends, Petya needs to split t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains the sequence of 2*n* positive integers *a*1,<=*a*2,<=...,<=*a*2*n* (1<=≤<=*a**i*<=≤<=5000) — the numbers that are written on the cards. The numbers on the line are separated by single spaces. | If it is impossible to divide the cards into pairs so that cards in each pair had the same numbers, print on a single line integer -1. But if the required partition exists, then print *n* pairs of integers, a pair per line — the indices of the cards that form the pairs.
Separate the numbers on the lines by spaces. You... | [
"3\n20 30 10 30 20 10\n",
"1\n1 2\n"
] | [
"4 2\n1 5\n6 3\n",
"-1"
] | none | 500 | [
{
"input": "3\n20 30 10 30 20 10",
"output": "4 2\n1 5\n6 3"
},
{
"input": "1\n1 2",
"output": "-1"
},
{
"input": "5\n2 2 2 2 2 1 2 2 1 2",
"output": "2 1\n3 4\n7 5\n6 9\n10 8"
},
{
"input": "5\n2 1 2 2 1 1 1 1 1 2",
"output": "3 1\n2 5\n7 6\n8 9\n10 4"
},
{
"inpu... | 1,684,022,779 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 420 | 78,848,000 | import sys, io, os
import math
import bisect
import heapq
import string
from collections import defaultdict,Counter,deque
input = sys.stdin.readline
def I():
return input()
def II():
return int(input())
def MII():
return map(int, input().split())
def LI():
return list(input().s... | Title: Cards with Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya has got 2*n* cards, each card contains some integer. The numbers on the cards can be the same. Let's index all cards by consecutive integers from 1 to 2*n*. We'll denote the number that is written on a card wit... | ```python
import sys, io, os
import math
import bisect
import heapq
import string
from collections import defaultdict,Counter,deque
input = sys.stdin.readline
def I():
return input()
def II():
return int(input())
def MII():
return map(int, input().split())
def LI():
return list... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
298 | B | Sail | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*,<=*y*).
- If the wind blows to the east, the boat will ... | The first line contains five integers *t*,<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y* (1<=≤<=*t*<=≤<=105,<=<=-<=109<=≤<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y*<=≤<=109). The starting location and the ending location will be different.
The second line contains *t* characters, the *i*-th character is the wind blowing direction at the... | If they can reach (*e**x*,<=*e**y*) within *t* seconds, print the earliest time they can achieve it. Otherwise, print "-1" (without quotes). | [
"5 0 0 1 1\nSESNW\n",
"10 5 3 3 6\nNENSWESNEE\n"
] | [
"4\n",
"-1\n"
] | In the first sample, they can stay at seconds 1, 3, and move at seconds 2, 4.
In the second sample, they cannot sail to the destination. | 500 | [
{
"input": "5 0 0 1 1\nSESNW",
"output": "4"
},
{
"input": "10 5 3 3 6\nNENSWESNEE",
"output": "-1"
},
{
"input": "19 -172106364 -468680119 -172106365 -468680119\nSSEEESSSESESWSEESSS",
"output": "13"
},
{
"input": "39 -1000000000 -1000000000 -999999997 -1000000000\nENEENWSWSS... | 1,614,937,340 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 124 | 307,200 | t, sx, sy, ex, ey = [int(i) for i in input().split()]
s = input()
X = ex-sx
Y = ey-sy
res = -1
for i in range(t):
if X == 0 and Y == 0:
res = i
break
if X > 0 and s[i] == 'E':
X -= 1
elif X < 0 and s[i] == 'W':
X += 1
if Y > 0 and s[i] == 'N':
... | Title: Sail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assu... | ```python
t, sx, sy, ex, ey = [int(i) for i in input().split()]
s = input()
X = ex-sx
Y = ey-sy
res = -1
for i in range(t):
if X == 0 and Y == 0:
res = i
break
if X > 0 and s[i] == 'E':
X -= 1
elif X < 0 and s[i] == 'W':
X += 1
if Y > 0 and s[i] == 'N':... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
793 | B | Igor and his way to work | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"implementation",
"shortest paths"
] | null | null | Woken up by the alarm clock Igor the financial analyst hurried up to the work. He ate his breakfast and sat in his car. Sadly, when he opened his GPS navigator, he found that some of the roads in Bankopolis, the city where he lives, are closed due to road works. Moreover, Igor has some problems with the steering wheel,... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the grid.
Each of the next *n* lines contains *m* characters denoting the corresponding row of the grid. The following characters can occur:
- "." — an empty cell; - "*" — a cell with road ... | In the only line print "YES" if there is a path between Igor's home and Igor's office with no more than two turns, and "NO" otherwise. | [
"5 5\n..S..\n****.\nT....\n****.\n.....\n",
"5 5\nS....\n****.\n.....\n.****\n..T..\n"
] | [
"YES",
"NO"
] | The first sample is shown on the following picture:
In the second sample it is impossible to reach Igor's office using less that 4 turns, thus there exists no path using no more than 2 turns. The path using exactly 4 turns is shown on this picture: | 1,000 | [
{
"input": "5 5\nS....\n****.\n.....\n.****\n..T..",
"output": "NO"
},
{
"input": "1 2\nST",
"output": "YES"
},
{
"input": "3 1\nS\n*\nT",
"output": "NO"
},
{
"input": "3 3\n*..\n...\nTS.",
"output": "YES"
},
{
"input": "3 3\nT.*\n*.*\n*S*",
"output": "YES"
... | 1,695,324,511 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 77 | 2,867,200 | def can_reach_with_two_turns(grid, n, m):
def dfs(x, y, turns, prev_dir):
if x < 0 or x >= n or y < 0 or y >= m or grid[x][y] == '*' or turns > 2:
return False
if x == end_x and y == end_y:
return True
if visited[x][y][turns][prev_dir]:
return False... | Title: Igor and his way to work
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Woken up by the alarm clock Igor the financial analyst hurried up to the work. He ate his breakfast and sat in his car. Sadly, when he opened his GPS navigator, he found that some of the roads in Bankopolis, th... | ```python
def can_reach_with_two_turns(grid, n, m):
def dfs(x, y, turns, prev_dir):
if x < 0 or x >= n or y < 0 or y >= m or grid[x][y] == '*' or turns > 2:
return False
if x == end_x and y == end_y:
return True
if visited[x][y][turns][prev_dir]:
re... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
277 | A | Learning Languages | PROGRAMMING | 1,400 | [
"dfs and similar",
"dsu"
] | null | null | The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have the list of languages, which he knows. This list could be empty, i. e. an employee may know no official la... | The first line contains two integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=100) — the number of employees and the number of languages.
Then *n* lines follow — each employee's language list. At the beginning of the *i*-th line is integer *k**i* (0<=≤<=*k**i*<=≤<=*m*) — the number of languages the *i*-th employee knows. Next... | Print a single integer — the minimum amount of money to pay so that in the end every employee could write a letter to every other one (other employees can help out translating). | [
"5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5\n",
"8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1\n",
"2 2\n1 2\n0\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the second sample the employee 1 can learn language 2, and employee 8 can learn language 4.
In the third sample employee 2 must learn language 2. | 500 | [
{
"input": "5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5",
"output": "0"
},
{
"input": "8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1",
"output": "2"
},
{
"input": "2 2\n1 2\n0",
"output": "1"
},
{
"input": "2 2\n0\n0",
"output": "2"
},
{
"input": "5 5\n1 3\n0\n0\n2 4... | 1,678,164,452 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | seen=[]
D={}
L=list(map(int,input().split()))
def plus_num_emp(x):
return(x+L[0]-1)
for i in range(L[0]+L[1]):
D[i]=[]
L1=[]
for i in range(L[0]):
L1=list(map(int,input().split()))
D[i].extend(list(map(plus_num_emp,L1[1:])))
for j in list(map(plus_num_emp,L1[1:])):
D[j].append(i... | Title: Learning Languages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have th... | ```python
seen=[]
D={}
L=list(map(int,input().split()))
def plus_num_emp(x):
return(x+L[0]-1)
for i in range(L[0]+L[1]):
D[i]=[]
L1=[]
for i in range(L[0]):
L1=list(map(int,input().split()))
D[i].extend(list(map(plus_num_emp,L1[1:])))
for j in list(map(plus_num_emp,L1[1:])):
D[j... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
644 | B | Processing Queries | PROGRAMMING | 1,700 | [
"*special",
"constructive algorithms",
"data structures",
"two pointers"
] | null | null | In this problem you have to simulate the workflow of one-thread server. There are *n* queries to process, the *i*-th will be received at moment *t**i* and needs to be processed for *d**i* units of time. All *t**i* are guaranteed to be distinct.
When a query appears server may react in three possible ways:
1. If ser... | The first line of the input contains two integers *n* and *b* (1<=≤<=*n*,<=*b*<=≤<=200<=000) — the number of queries and the maximum possible size of the query queue.
Then follow *n* lines with queries descriptions (in chronological order). Each description consists of two integers *t**i* and *d**i* (1<=≤<=*t**i*,<=*d... | Print the sequence of *n* integers *e*1,<=*e*2,<=...,<=*e**n*, where *e**i* is the moment the server will finish to process the *i*-th query (queries are numbered in the order they appear in the input) or <=-<=1 if the corresponding query will be rejected. | [
"5 1\n2 9\n4 8\n10 9\n15 2\n19 1\n",
"4 1\n2 8\n4 8\n10 9\n15 2\n"
] | [
"11 19 -1 21 22 \n",
"10 18 27 -1 \n"
] | Consider the first sample.
1. The server will start to process first query at the moment 2 and will finish to process it at the moment 11. 1. At the moment 4 second query appears and proceeds to the queue. 1. At the moment 10 third query appears. However, the server is still busy with query 1, *b* = 1 and there is... | 1,000 | [
{
"input": "5 1\n2 9\n4 8\n10 9\n15 2\n19 1",
"output": "11 19 -1 21 22 "
},
{
"input": "4 1\n2 8\n4 8\n10 9\n15 2",
"output": "10 18 27 -1 "
},
{
"input": "1 1\n1000000000 1000000000",
"output": "2000000000 "
},
{
"input": "4 3\n999999996 1000000000\n999999997 1000000000\n99... | 1,565,792,280 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 170 | 1,126,400 | n, b = map(int, input().split())
from queue import Queue
q = Queue()
begin = []
stay = []
end = []
res = []
proceeding = 0
for i in range (n):
t, d = map(int, input().split())
begin.append(t)
stay.append(d)
end.append(t + d)
res.append(0)
res[0] += end[0]
q.put(1)
for i in ra... | Title: Processing Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you have to simulate the workflow of one-thread server. There are *n* queries to process, the *i*-th will be received at moment *t**i* and needs to be processed for *d**i* units of time. All *t**i* ar... | ```python
n, b = map(int, input().split())
from queue import Queue
q = Queue()
begin = []
stay = []
end = []
res = []
proceeding = 0
for i in range (n):
t, d = map(int, input().split())
begin.append(t)
stay.append(d)
end.append(t + d)
res.append(0)
res[0] += end[0]
q.put(1)
f... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
822 | C | Hacker, pack your bags! | PROGRAMMING | 1,600 | [
"binary search",
"greedy",
"implementation",
"sortings"
] | null | null | It's well known that the best way to distract from something is to do one's favourite thing. Job is such a thing for Leha.
So the hacker began to work hard in order to get rid of boredom. It means that Leha began to hack computers all over the world. For such zeal boss gave the hacker a vacation of exactly *x* days. Y... | The first line contains two integers *n* and *x* (2<=≤<=*n*,<=*x*<=≤<=2·105) — the number of vouchers in the travel agency and the duration of Leha's vacation correspondingly.
Each of the next *n* lines contains three integers *l**i*, *r**i* and *cost**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=2·105,<=1<=≤<=*cost**i*<=≤<=109) —... | Print a single integer — a minimal amount of money that Leha will spend, or print <=-<=1 if it's impossible to choose two disjoint vouchers with the total duration exactly *x*. | [
"4 5\n1 3 4\n1 2 5\n5 6 1\n1 2 4\n",
"3 2\n4 6 3\n2 4 1\n3 5 4\n"
] | [
"5\n",
"-1\n"
] | In the first sample Leha should choose first and third vouchers. Hereupon the total duration will be equal to (3 - 1 + 1) + (6 - 5 + 1) = 5 and the total cost will be 4 + 1 = 5.
In the second sample the duration of each voucher is 3 therefore it's impossible to choose two vouchers with the total duration equal to 2. | 1,250 | [
{
"input": "4 5\n1 3 4\n1 2 5\n5 6 1\n1 2 4",
"output": "5"
},
{
"input": "3 2\n4 6 3\n2 4 1\n3 5 4",
"output": "-1"
},
{
"input": "2 1855\n159106 161198 437057705\n149039 158409 889963913",
"output": "-1"
},
{
"input": "15 17\n1 10 8\n5 19 1\n12 14 6\n9 19 8\n6 7 3\n5 11 9\n... | 1,681,994,847 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 126,054,400 | from sys import stdin ,stdout , setrecursionlimit
setrecursionlimit(2**31-1)
input=stdin.readline
from threading import Thread , stack_size
inp=lambda : map(int,input().split())
def print(*args, end='\n', sep=' ') -> None:
stdout.write(sep.join(map(str, args)) + end)
from collections import defaultdict
fro... | Title: Hacker, pack your bags!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's well known that the best way to distract from something is to do one's favourite thing. Job is such a thing for Leha.
So the hacker began to work hard in order to get rid of boredom. It means that Leha beg... | ```python
from sys import stdin ,stdout , setrecursionlimit
setrecursionlimit(2**31-1)
input=stdin.readline
from threading import Thread , stack_size
inp=lambda : map(int,input().split())
def print(*args, end='\n', sep=' ') -> None:
stdout.write(sep.join(map(str, args)) + end)
from collections import defaul... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
855 | A | Tom Riddle's Diary | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants to know the different people who had ever possessed the diary to make sure they ... | First line of input contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of names in the list.
Next *n* lines each contain a string *s**i*, consisting of lowercase English letters. The length of each string is between 1 and 100. | Output *n* lines each containing either "YES" or "NO" (without quotes), depending on whether this string was already present in the stream or not.
You can print each letter in any case (upper or lower). | [
"6\ntom\nlucius\nginny\nharry\nginny\nharry\n",
"3\na\na\na\n"
] | [
"NO\nNO\nNO\nNO\nYES\nYES\n",
"NO\nYES\nYES\n"
] | In test case 1, for *i* = 5 there exists *j* = 3 such that *s*<sub class="lower-index">*i*</sub> = *s*<sub class="lower-index">*j*</sub> and *j* < *i*, which means that answer for *i* = 5 is "YES". | 500 | [
{
"input": "6\ntom\nlucius\nginny\nharry\nginny\nharry",
"output": "NO\nNO\nNO\nNO\nYES\nYES"
},
{
"input": "3\na\na\na",
"output": "NO\nYES\nYES"
},
{
"input": "1\nzn",
"output": "NO"
},
{
"input": "9\nliyzmbjwnzryjokufuxcqtzwworjeoxkbaqrujrhdidqdvwdfzilwszgnzglnnbogaclckfnb... | 1,598,339,644 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 93 | 0 | num=int(input())
temp=[]
yesno=[]
for i in range(num):
a=input()
if a not in temp:
temp.append(a)
yesno.append('NO')
else:
yesno.append('YES')
for i in yesno:
print(i)
| Title: Tom Riddle's Diary
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber ... | ```python
num=int(input())
temp=[]
yesno=[]
for i in range(num):
a=input()
if a not in temp:
temp.append(a)
yesno.append('NO')
else:
yesno.append('YES')
for i in yesno:
print(i)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
298 | A | Snow Footprints | PROGRAMMING | 1,300 | [
"greedy",
"implementation"
] | null | null | There is a straight snowy road, divided into *n* blocks. The blocks are numbered from 1 to *n* from left to right. If one moves from the *i*-th block to the (*i*<=+<=1)-th block, he will leave a right footprint on the *i*-th block. Similarly, if one moves from the *i*-th block to the (*i*<=-<=1)-th block, he will leave... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=1000).
The second line contains the description of the road — the string that consists of *n* characters. Each character will be either "." (a block without footprint), or "L" (a block with a left footprint), "R" (a block with a right footprint).
It's gu... | Print two space-separated integers — the values of *s* and *t*. If there are several possible solutions you can print any of them. | [
"9\n..RRLL...\n",
"11\n.RRRLLLLL..\n"
] | [
"3 4\n",
"7 5\n"
] | The first test sample is the one in the picture. | 500 | [
{
"input": "11\n.RRRLLLLL..",
"output": "7 5"
},
{
"input": "4\n.RL.",
"output": "3 2"
},
{
"input": "3\n.L.",
"output": "2 1"
},
{
"input": "3\n.R.",
"output": "2 3"
}
] | 1,527,776,185 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 154 | 6,963,200 | # python 3
"""
"""
def snow_footprints(n_int, road_str) -> tuple:
i = 1
back = []
while road[i] == '.':
i += 1
s = i
while True:
if road[i] == '.':
break # end of the road
elif road[i] == 'R':
i += 1
else:
back.append(i)
... | Title: Snow Footprints
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a straight snowy road, divided into *n* blocks. The blocks are numbered from 1 to *n* from left to right. If one moves from the *i*-th block to the (*i*<=+<=1)-th block, he will leave a right footprint on the *... | ```python
# python 3
"""
"""
def snow_footprints(n_int, road_str) -> tuple:
i = 1
back = []
while road[i] == '.':
i += 1
s = i
while True:
if road[i] == '.':
break # end of the road
elif road[i] == 'R':
i += 1
else:
back.append(... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
134 | A | Average Numbers | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | You are given a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Find all such indices *i*, that the *i*-th element equals the arithmetic mean of all other elements (that is all elements except for this one). | The first line contains the integer *n* (2<=≤<=*n*<=≤<=2·105). The second line contains elements of the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). All the elements are positive integers. | Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to *n*.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print ... | [
"5\n1 2 3 4 5\n",
"4\n50 50 50 50\n"
] | [
"1\n3 ",
"4\n1 2 3 4 "
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "1\n3 "
},
{
"input": "4\n50 50 50 50",
"output": "4\n1 2 3 4 "
},
{
"input": "3\n2 3 1",
"output": "1\n1 "
},
{
"input": "2\n4 2",
"output": "0"
},
{
"input": "2\n1 1",
"output": "2\n1 2 "
},
{
"input": "10\n3 3 3 ... | 1,683,024,505 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 420 | 14,233,600 | n = int(input())
a = list(map(int, input().split()))
b = sum(a)
c = []
for i in range(n):
if a[i] == (b - a[i]) / (n - 1):
c.append(i + 1)
print(len(c))
print(*c)
# Tue May 02 2023 13:48:24 GMT+0300 (Moscow Standard Time)
| Title: Average Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Find all such indices *i*, that the *i*-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
... | ```python
n = int(input())
a = list(map(int, input().split()))
b = sum(a)
c = []
for i in range(n):
if a[i] == (b - a[i]) / (n - 1):
c.append(i + 1)
print(len(c))
print(*c)
# Tue May 02 2023 13:48:24 GMT+0300 (Moscow Standard Time)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
199 | B | Special Olympics | PROGRAMMING | 1,900 | [
"geometry"
] | null | null | A renowned abstract artist Sasha, drawing inspiration from nowhere, decided to paint a picture entitled "Special Olympics". He justly thought that, if the regular Olympic games have five rings, then the Special ones will do with exactly two rings just fine.
Let us remind you that a ring is a region located between two... | The input contains two lines.
Each line has four space-separated integers *x**i*, *y**i*, *r**i*, *R**i*, that describe the *i*-th ring; *x**i* and *y**i* are coordinates of the ring's center, *r**i* and *R**i* are the internal and external radii of the ring correspondingly (<=-<=100<=≤<=*x**i*,<=*y**i*<=≤<=100; 1<=≤... | A single integer — the number of ways to cut out a circle from the canvas. | [
"60 60 45 55\n80 80 8 32\n",
"60 60 45 55\n80 60 15 25\n",
"50 50 35 45\n90 50 35 45\n"
] | [
"1",
"4",
"0"
] | Figures for test samples are given below. The possible cuts are marked with red dotted line. | 1,000 | [
{
"input": "60 60 45 55\n80 80 8 32",
"output": "1"
},
{
"input": "60 60 45 55\n80 60 15 25",
"output": "4"
},
{
"input": "50 50 35 45\n90 50 35 45",
"output": "0"
},
{
"input": "0 0 50 70\n1 0 60 80",
"output": "2"
},
{
"input": "0 0 1 2\n10 0 2 20",
"output"... | 1,690,655,025 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 312 | 14,643,200 | from dataclasses import dataclass
import math
@dataclass
class Square:
x: int
y: int
r: int
def center_dist(self, other):
return math.hypot(self.x - other.x, self.y - other.y)
def is_intersected(self, other):
return self.r + other.r >= self.center_dist(other)
... | Title: Special Olympics
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A renowned abstract artist Sasha, drawing inspiration from nowhere, decided to paint a picture entitled "Special Olympics". He justly thought that, if the regular Olympic games have five rings, then the Special ones wi... | ```python
from dataclasses import dataclass
import math
@dataclass
class Square:
x: int
y: int
r: int
def center_dist(self, other):
return math.hypot(self.x - other.x, self.y - other.y)
def is_intersected(self, other):
return self.r + other.r >= self.center_dist(oth... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
680 | B | Bear and Finding Criminals | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation"
] | null | null | There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city *a*. His job is to catch criminals. It's hard because he doesn't know in which cities criminals are. Though, he... | The first line of the input contains two integers *n* and *a* (1<=≤<=*a*<=≤<=*n*<=≤<=100) — the number of cities and the index of city where Limak lives.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (0<=≤<=*t**i*<=≤<=1). There are *t**i* criminals in the *i*-th city. | Print the number of criminals Limak will catch. | [
"6 3\n1 1 1 0 1 0\n",
"5 2\n0 0 0 1 0\n"
] | [
"3\n",
"1\n"
] | In the first sample, there are six cities and Limak lives in the third one (blue arrow below). Criminals are in cities marked red.
Using the BCD gives Limak the following information:
- There is one criminal at distance 0 from the third city — Limak is sure that this criminal is exactly in the third city. - There i... | 1,000 | [
{
"input": "6 3\n1 1 1 0 1 0",
"output": "3"
},
{
"input": "5 2\n0 0 0 1 0",
"output": "1"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "1 1\n0",
"output": "0"
},
{
"input": "9 3\n1 1 1 1 1 1 1 1 0",
"output": "8"
},
{
"input": "9 5\n1 0 1 0 1 0... | 1,584,470,203 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<iostream>
using namespace std;
#include<bits/stdc++.h>
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n,a,t;
int c=0;
vector<int> probs ;
cin>>n>>a;
a--;
for(int i=0; i<n; i++)
{
cin>>t;
probs.push_back(t);
}
... | Title: Bear and Finding Criminals
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city... | ```python
#include<iostream>
using namespace std;
#include<bits/stdc++.h>
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n,a,t;
int c=0;
vector<int> probs ;
cin>>n>>a;
a--;
for(int i=0; i<n; i++)
{
cin>>t;
probs.push_back(t);
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
253 | A | Boys and Girls | PROGRAMMING | 1,100 | [
"greedy"
] | null | null | There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to *n*<=+<=*m*. Then the number of integers *i* (1<=≤<=*i*<=<<=*n*<=+<=*m*) such th... | The single line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), separated by a space. | Print a line of *n*<=+<=*m* characters. Print on the *i*-th position of the line character "B", if the *i*-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B" should equal *n* and the number of characters "G" should equal *m*. If there are multi... | [
"3 3\n",
"4 2\n"
] | [
"GBGBGB\n",
"BGBGBB\n"
] | In the first sample another possible answer is BGBGBG.
In the second sample answer BBGBGB is also optimal. | 500 | [
{
"input": "3 3",
"output": "GBGBGB"
},
{
"input": "4 2",
"output": "BGBGBB"
},
{
"input": "5 5",
"output": "GBGBGBGBGB"
},
{
"input": "6 4",
"output": "BGBGBGBGBB"
},
{
"input": "100 1",
"output": "BGBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB... | 1,669,829,714 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 0 | n,m=list(map(int, input().split()))
if(n==m):
print('BG'*n)
elif(n>m):
print('BG'*m+'B'*(n-m))
else:
print('BG'*n+'B'*(m-n))
| Title: Boys and Girls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by n... | ```python
n,m=list(map(int, input().split()))
if(n==m):
print('BG'*n)
elif(n>m):
print('BG'*m+'B'*(n-m))
else:
print('BG'*n+'B'*(m-n))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
371 | A | K-Periodic Array | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"math"
] | null | null | This task will exclusively concentrate only on the arrays where all elements equal 1 and/or 2.
Array *a* is *k*-period if its length is divisible by *k* and there is such array *b* of length *k*, that *a* is represented by array *b* written exactly times consecutively. In other words, array *a* is *k*-periodic, if it... | The first line of the input contains a pair of integers *n*, *k* (1<=≤<=*k*<=≤<=*n*<=≤<=100), where *n* is the length of the array and the value *n* is divisible by *k*. The second line contains the sequence of elements of the given array *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2), *a**i* is the *i*-th element of ... | Print the minimum number of array elements we need to change to make the array *k*-periodic. If the array already is *k*-periodic, then print 0. | [
"6 2\n2 1 2 2 2 1\n",
"8 4\n1 1 2 1 1 1 2 1\n",
"9 3\n2 1 1 1 2 1 1 1 2\n"
] | [
"1\n",
"0\n",
"3\n"
] | In the first sample it is enough to change the fourth element from 2 to 1, then the array changes to [2, 1, 2, 1, 2, 1].
In the second sample, the given array already is 4-periodic.
In the third sample it is enough to replace each occurrence of number two by number one. In this case the array will look as [1, 1, 1, 1... | 500 | [
{
"input": "6 2\n2 1 2 2 2 1",
"output": "1"
},
{
"input": "8 4\n1 1 2 1 1 1 2 1",
"output": "0"
},
{
"input": "9 3\n2 1 1 1 2 1 1 1 2",
"output": "3"
},
{
"input": "1 1\n2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "0"
},
{
"input": "2 2\n2 2... | 1,649,951,790 | 2,147,483,647 | Python 3 | OK | TESTS | 24 | 46 | 0 | n, k = map(int, input().split())
a = list(map(int, input().split()))
count = 0
if(len(a)%k==0):
for i in range(k):
b = a[i::k]
count += min(b.count(1),b.count(2))
print(count)
| Title: K-Periodic Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This task will exclusively concentrate only on the arrays where all elements equal 1 and/or 2.
Array *a* is *k*-period if its length is divisible by *k* and there is such array *b* of length *k*, that *a* is represent... | ```python
n, k = map(int, input().split())
a = list(map(int, input().split()))
count = 0
if(len(a)%k==0):
for i in range(k):
b = a[i::k]
count += min(b.count(1),b.count(2))
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
719 | B | Anatoly and Cockroaches | PROGRAMMING | 1,400 | [
"greedy"
] | null | null | Anatoly lives in the university dorm as many other students do. As you know, cockroaches are also living there together with students. Cockroaches might be of two colors: black and red. There are *n* cockroaches living in Anatoly's room.
Anatoly just made all his cockroaches to form a single line. As he is a perfectio... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of cockroaches.
The second line contains a string of length *n*, consisting of characters 'b' and 'r' that denote black cockroach and red cockroach respectively. | Print one integer — the minimum number of moves Anatoly has to perform in order to make the colors of cockroaches in the line to alternate. | [
"5\nrbbrr\n",
"5\nbbbbb\n",
"3\nrbr\n"
] | [
"1\n",
"2\n",
"0\n"
] | In the first sample, Anatoly has to swap third and fourth cockroaches. He needs 1 turn to do this.
In the second sample, the optimum answer is to paint the second and the fourth cockroaches red. This requires 2 turns.
In the third sample, the colors of cockroaches in the line are alternating already, thus the answer ... | 1,000 | [
{
"input": "5\nrbbrr",
"output": "1"
},
{
"input": "5\nbbbbb",
"output": "2"
},
{
"input": "3\nrbr",
"output": "0"
},
{
"input": "13\nrbbbrbrrbrrbb",
"output": "3"
},
{
"input": "18\nrrrrrrrrrrrrrrrrrb",
"output": "8"
},
{
"input": "100\nbrbbbrrrbbrbrb... | 1,620,111,592 | 2,147,483,647 | PyPy 3 | OK | TESTS | 46 | 124 | 8,806,400 | n = int(input())
a = list(input())
b = ['b', 'r'] * (n // 2 * 2) + ['b'] * (n % 2)
r = ['r', 'b'] * (n // 2 * 2) + ['r'] * (n % 2)
coub1 = 0
cour1 = 0
coub2 = 0
cour2 = 0
for i in range(n):
if a[i] == 'b' and a[i] != b[i]:
coub1 += 1
elif a[i] == 'b' and a[i] != r[i]:
coub2 += 1
elif a[i] == 'r' and... | Title: Anatoly and Cockroaches
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anatoly lives in the university dorm as many other students do. As you know, cockroaches are also living there together with students. Cockroaches might be of two colors: black and red. There are *n* cockroaches... | ```python
n = int(input())
a = list(input())
b = ['b', 'r'] * (n // 2 * 2) + ['b'] * (n % 2)
r = ['r', 'b'] * (n // 2 * 2) + ['r'] * (n % 2)
coub1 = 0
cour1 = 0
coub2 = 0
cour2 = 0
for i in range(n):
if a[i] == 'b' and a[i] != b[i]:
coub1 += 1
elif a[i] == 'b' and a[i] != r[i]:
coub2 += 1
elif a[i] ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
583 | A | Asphalting Roads | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers of the roads that form them.
Sand roads have long been recognized out of date, so the decision was ma... | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of vertical and horizontal roads in the city.
Next *n*2 lines contain the order of intersections in the schedule. The *i*-th of them contains two numbers *h**i*,<=*v**i* (1<=≤<=*h**i*,<=*v**i*<=≤<=*n*), separated by a space, and meaning that the inte... | In the single line print the numbers of the days when road works will be in progress in ascending order. The days are numbered starting from 1. | [
"2\n1 1\n1 2\n2 1\n2 2\n",
"1\n1 1\n"
] | [
"1 4 \n",
"1 \n"
] | In the sample the brigade acts like that:
1. On the first day the brigade comes to the intersection of the 1-st horizontal and the 1-st vertical road. As none of them has been asphalted, the workers asphalt the 1-st vertical and the 1-st horizontal road; 1. On the second day the brigade of the workers comes to the i... | 500 | [
{
"input": "2\n1 1\n1 2\n2 1\n2 2",
"output": "1 4 "
},
{
"input": "1\n1 1",
"output": "1 "
},
{
"input": "2\n1 1\n2 2\n1 2\n2 1",
"output": "1 2 "
},
{
"input": "2\n1 2\n2 2\n2 1\n1 1",
"output": "1 3 "
},
{
"input": "3\n2 2\n1 2\n3 2\n3 3\n1 1\n2 3\n1 3\n3 1\n2 ... | 1,495,197,337 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 46 | 0 | n = int(input())
A = []
for i in range(0,n*2):
a,b = input().split()
if a == b:
A.append(i+1)
s = ''
for j in range(0,n):
s =s+str(A[j])+' '
print(s) | Title: Asphalting Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers ... | ```python
n = int(input())
A = []
for i in range(0,n*2):
a,b = input().split()
if a == b:
A.append(i+1)
s = ''
for j in range(0,n):
s =s+str(A[j])+' '
print(s)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
994 | B | Knights of a Polygonal Table | PROGRAMMING | 1,400 | [
"greedy",
"implementation",
"sortings"
] | null | null | Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power is greater than the power of victim. However, even such a knight will torment his conscience, so he can kill no mo... | The first line contains two integers $n$ and $k$ $(1 \le n \le 10^5, 0 \le k \le \min(n-1,10))$ — the number of knights and the number $k$ from the statement.
The second line contains $n$ integers $p_1, p_2 ,\ldots,p_n$ $(1 \le p_i \le 10^9)$ — powers of the knights. All $p_i$ are distinct.
The third line contains $n... | Print $n$ integers — the maximum number of coins each knight can have it only he kills other knights. | [
"4 2\n4 5 9 7\n1 2 11 33\n",
"5 1\n1 2 3 4 5\n1 2 3 4 5\n",
"1 0\n2\n3\n"
] | [
"1 3 46 36 ",
"1 3 5 7 9 ",
"3 "
] | Consider the first example.
- The first knight is the weakest, so he can't kill anyone. That leaves him with the only coin he initially has. - The second knight can kill the first knight and add his coin to his own two. - The third knight is the strongest, but he can't kill more than $k = 2$ other knights. It is o... | 1,000 | [
{
"input": "4 2\n4 5 9 7\n1 2 11 33",
"output": "1 3 46 36 "
},
{
"input": "5 1\n1 2 3 4 5\n1 2 3 4 5",
"output": "1 3 5 7 9 "
},
{
"input": "1 0\n2\n3",
"output": "3 "
},
{
"input": "7 1\n2 3 4 5 7 8 9\n0 3 7 9 5 8 9",
"output": "0 3 10 16 14 17 18 "
},
{
"input"... | 1,607,893,309 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 155 | 0 | from sys import stdin,stdout
import heapq
nmbr=lambda:int(stdin.readline())
lst=lambda:list(map(int,stdin.readline().split()))
for _ in range(1):#nmbr()):
n,k=lst()
p=lst()
coins=lst()
l=[];h=[]
for i in range(n):
l+=[[p[i],coins[i],i]]
l.sort()
ans=[0]*n
for i in ra... | Title: Knights of a Polygonal Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power ... | ```python
from sys import stdin,stdout
import heapq
nmbr=lambda:int(stdin.readline())
lst=lambda:list(map(int,stdin.readline().split()))
for _ in range(1):#nmbr()):
n,k=lst()
p=lst()
coins=lst()
l=[];h=[]
for i in range(n):
l+=[[p[i],coins[i],i]]
l.sort()
ans=[0]*n
f... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
999 | B | Reversing Encryption | PROGRAMMING | 900 | [
"implementation"
] | null | null | A string $s$ of length $n$ can be encrypted by the following algorithm:
- iterate over all divisors of $n$ in decreasing order (i.e. from $n$ to $1$), - for each divisor $d$, reverse the substring $s[1 \dots d]$ (i.e. the substring which starts at position $1$ and ends at position $d$).
For example, the above algor... | The first line of input consists of a single integer $n$ ($1 \le n \le 100$) — the length of the string $t$. The second line of input consists of the string $t$. The length of $t$ is $n$, and it consists only of lowercase Latin letters. | Print a string $s$ such that the above algorithm results in $t$. | [
"10\nrocesfedoc\n",
"16\nplmaetwoxesisiht\n",
"1\nz\n"
] | [
"codeforces\n",
"thisisexampletwo\n",
"z\n"
] | The first example is described in the problem statement. | 0 | [
{
"input": "10\nrocesfedoc",
"output": "codeforces"
},
{
"input": "16\nplmaetwoxesisiht",
"output": "thisisexampletwo"
},
{
"input": "1\nz",
"output": "z"
},
{
"input": "2\nir",
"output": "ri"
},
{
"input": "3\nilj",
"output": "jli"
},
{
"input": "4\nj... | 1,621,677,691 | 1,711 | PyPy 3 | OK | TESTS | 20 | 93 | 0 | def question2():
encrupted_len = int(input())
encrupted_msg = input()
divisors = []
if encrupted_len == 1:
return encrupted_msg
i = encrupted_len
while i > 1:
if encrupted_len % i == 0:
divisors.append(i)
i -= 1
# print(divisors) ... | Title: Reversing Encryption
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string $s$ of length $n$ can be encrypted by the following algorithm:
- iterate over all divisors of $n$ in decreasing order (i.e. from $n$ to $1$), - for each divisor $d$, reverse the substring $s[1 \dots d]$... | ```python
def question2():
encrupted_len = int(input())
encrupted_msg = input()
divisors = []
if encrupted_len == 1:
return encrupted_msg
i = encrupted_len
while i > 1:
if encrupted_len % i == 0:
divisors.append(i)
i -= 1
# print(divis... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
253 | A | Boys and Girls | PROGRAMMING | 1,100 | [
"greedy"
] | null | null | There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to *n*<=+<=*m*. Then the number of integers *i* (1<=≤<=*i*<=<<=*n*<=+<=*m*) such th... | The single line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), separated by a space. | Print a line of *n*<=+<=*m* characters. Print on the *i*-th position of the line character "B", if the *i*-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B" should equal *n* and the number of characters "G" should equal *m*. If there are multi... | [
"3 3\n",
"4 2\n"
] | [
"GBGBGB\n",
"BGBGBB\n"
] | In the first sample another possible answer is BGBGBG.
In the second sample answer BBGBGB is also optimal. | 500 | [
{
"input": "3 3",
"output": "GBGBGB"
},
{
"input": "4 2",
"output": "BGBGBB"
},
{
"input": "5 5",
"output": "GBGBGBGBGB"
},
{
"input": "6 4",
"output": "BGBGBGBGBB"
},
{
"input": "100 1",
"output": "BGBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB... | 1,620,675,953 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 124 | 6,963,200 | taco = open("input.txt","r")
k = taco.readline()
taco.close()
n,m = k.split()
n = int(n)
m = int(m)
if n == m:
i = 0
s = str()
while i < n:
s += "BG"
i += 1
elif n > m:
s = str()
i = 0
while i < m:
s += "BG"
i += 1
while i < n:
s += "B"
i += 1
else:
s = str()
i = 0
while i < ... | Title: Boys and Girls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by n... | ```python
taco = open("input.txt","r")
k = taco.readline()
taco.close()
n,m = k.split()
n = int(n)
m = int(m)
if n == m:
i = 0
s = str()
while i < n:
s += "BG"
i += 1
elif n > m:
s = str()
i = 0
while i < m:
s += "BG"
i += 1
while i < n:
s += "B"
i += 1
else:
s = str()
i = 0
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
463 | D | Gargari and Permutations | PROGRAMMING | 1,900 | [
"dfs and similar",
"dp",
"graphs",
"implementation"
] | null | null | Gargari got bored to play with the bishops and now, after solving the problem about them, he is trying to do math homework. In a math book he have found *k* permutations. Each of them consists of numbers 1,<=2,<=...,<=*n* in some order. Now he should find the length of the longest common subsequence of these permutatio... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1000; 2<=≤<=*k*<=≤<=5). Each of the next *k* lines contains integers 1,<=2,<=...,<=*n* in some order — description of the current permutation. | Print the length of the longest common subsequence. | [
"4 3\n1 4 2 3\n4 1 2 3\n1 2 4 3\n"
] | [
"3\n"
] | The answer for the first test sample is subsequence [1, 2, 3]. | 2,000 | [
{
"input": "4 3\n1 4 2 3\n4 1 2 3\n1 2 4 3",
"output": "3"
},
{
"input": "6 3\n2 5 1 4 6 3\n5 1 4 3 2 6\n5 4 2 6 3 1",
"output": "3"
},
{
"input": "41 4\n24 15 17 35 13 41 4 14 23 5 8 16 21 18 30 36 6 22 11 29 26 1 40 31 7 3 32 10 28 38 12 20 39 37 34 19 33 27 2 25 9\n22 13 25 24 38 35 2... | 1,691,396,149 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 514 | 3,276,800 | from collections import defaultdict
n,k = map(int,input().split())
mat= []
for x in range(k):
arr = list(map(int,input().split()))
mat.append(arr)
memo = defaultdict(lambda:-1)
for i in range(k):
for j in range(n):
memo[i,mat[i][j]] = j
def valid(index,prev):
ele= mat[0][index]
prevele = mat[0][p... | Title: Gargari and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gargari got bored to play with the bishops and now, after solving the problem about them, he is trying to do math homework. In a math book he have found *k* permutations. Each of them consists of numbers 1,<=2,... | ```python
from collections import defaultdict
n,k = map(int,input().split())
mat= []
for x in range(k):
arr = list(map(int,input().split()))
mat.append(arr)
memo = defaultdict(lambda:-1)
for i in range(k):
for j in range(n):
memo[i,mat[i][j]] = j
def valid(index,prev):
ele= mat[0][index]
prevele ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
186 | A | Comparing Strings | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Mish... | The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that co... | Print "YES", if the dwarves belong to the same race. Otherwise, print "NO". | [
"ab\nba\n",
"aa\nab\n"
] | [
"YES\n",
"NO\n"
] | - First example: you can simply swap two letters in string "ab". So we get "ba". - Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b". | 500 | [
{
"input": "ab\nba",
"output": "YES"
},
{
"input": "aa\nab",
"output": "NO"
},
{
"input": "a\nza",
"output": "NO"
},
{
"input": "vvea\nvvae",
"output": "YES"
},
{
"input": "rtfabanpc\natfabrnpc",
"output": "YES"
},
{
"input": "mt\ntm",
"output": "Y... | 1,670,051,919 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | lst = []
genome1 = input()
genome2 = input()
for i in genome1:
lst.append(i)
if ''.join(lst[::-1]) == genome2:
print('YES')
else:
print('NO') | Title: Comparing Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome ... | ```python
lst = []
genome1 = input()
genome2 = input()
for i in genome1:
lst.append(i)
if ''.join(lst[::-1]) == genome2:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Yaroslav has an array, consisting of (2·*n*<=-<=1) integers. In a single operation Yaroslav can change the sign of exactly *n* elements in the array. In other words, in one operation Yaroslav can select exactly *n* array elements, and multiply each of them by -1.
Yaroslav is now wondering: what maximum sum of array el... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=100). The second line contains (2·*n*<=-<=1) integers — the array elements. The array elements do not exceed 1000 in their absolute value. | In a single line print the answer to the problem — the maximum sum that Yaroslav can get. | [
"2\n50 50 50\n",
"2\n-1 -100 -1\n"
] | [
"150\n",
"100\n"
] | In the first sample you do not need to change anything. The sum of elements equals 150.
In the second sample you need to change the sign of the first two elements. Then we get the sum of the elements equal to 100. | 0 | [
{
"input": "2\n50 50 50",
"output": "150"
},
{
"input": "2\n-1 -100 -1",
"output": "100"
},
{
"input": "3\n-959 -542 -669 -513 160",
"output": "2843"
},
{
"input": "4\n717 473 344 -51 -548 703 -869",
"output": "3603"
},
{
"input": "5\n270 -181 957 -509 -6 937 -175... | 1,532,966,850 | 3,450 | Python 3 | WRONG_ANSWER | TESTS | 2 | 216 | 0 | # import sys
# sys.stdin=open('F:\\C\\Script\\input.txt','r')
# sys.stdout=open('F:\\C\\Script\\output.txt','w')
# sys.stdout.flush()
# MOD = 1000000007
I = lambda : [int(i) for i in input().split()]
n , = I()
l = I()
l.sort()
a = l.copy()
for i in range(n):
a[i] = -1 * a[i]
print (max(sum(a),sum(l))) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav has an array, consisting of (2·*n*<=-<=1) integers. In a single operation Yaroslav can change the sign of exactly *n* elements in the array. In other words, in one operation Yaroslav can select exactly *n* array elements,... | ```python
# import sys
# sys.stdin=open('F:\\C\\Script\\input.txt','r')
# sys.stdout=open('F:\\C\\Script\\output.txt','w')
# sys.stdout.flush()
# MOD = 1000000007
I = lambda : [int(i) for i in input().split()]
n , = I()
l = I()
l.sort()
a = l.copy()
for i in range(n):
a[i] = -1 * a[i]
print (max(sum(a)... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
46 | A | Ball Game | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | A. Ball Game | 2 | 256 | A kindergarten teacher Natalia Pavlovna has invented a new ball game. This game not only develops the children's physique, but also teaches them how to count.
The game goes as follows. Kids stand in circle. Let's agree to think of the children as numbered with numbers from 1 to *n* clockwise and the child number 1 is... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) which indicates the number of kids in the circle. | In the single line print *n*<=-<=1 numbers which are the numbers of children who will get the ball after each throw. Separate the numbers by spaces. | [
"10\n",
"3\n"
] | [
"2 4 7 1 6 2 9 7 6\n",
"2 1\n"
] | none | 0 | [
{
"input": "10",
"output": "2 4 7 1 6 2 9 7 6"
},
{
"input": "3",
"output": "2 1"
},
{
"input": "4",
"output": "2 4 3"
},
{
"input": "5",
"output": "2 4 2 1"
},
{
"input": "6",
"output": "2 4 1 5 4"
},
{
"input": "7",
"output": "2 4 7 4 2 1"
},
... | 1,607,084,459 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 0 | n = int(input())
count = 1
for i in range(1, n):
count=(i+count)%n
print(count, end = ' ')
| Title: Ball Game
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A kindergarten teacher Natalia Pavlovna has invented a new ball game. This game not only develops the children's physique, but also teaches them how to count.
The game goes as follows. Kids stand in circle. Let's agree to think... | ```python
n = int(input())
count = 1
for i in range(1, n):
count=(i+count)%n
print(count, end = ' ')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
347 | A | Difference Row | PROGRAMMING | 1,300 | [
"constructive algorithms",
"implementation",
"sortings"
] | null | null | You want to arrange *n* integers *a*1,<=*a*2,<=...,<=*a**n* in some order in a row. Let's define the value of an arrangement as the sum of differences between all pairs of adjacent integers.
More formally, let's denote some arrangement as a sequence of integers *x*1,<=*x*2,<=...,<=*x**n*, where sequence *x* is a permu... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n* space-separated integers *a*1, *a*2, ..., *a**n* (|*a**i*|<=≤<=1000). | Print the required sequence *x*1,<=*x*2,<=...,<=*x**n*. Sequence *x* should be the lexicographically smallest permutation of *a* that corresponds to an arrangement of the largest possible value. | [
"5\n100 -100 50 0 -50\n"
] | [
"100 -50 0 50 -100 \n"
] | In the sample test case, the value of the output arrangement is (100 - ( - 50)) + (( - 50) - 0) + (0 - 50) + (50 - ( - 100)) = 200. No other arrangement has a larger value, and among all arrangements with the value of 200, the output arrangement is the lexicographically smallest one.
Sequence *x*<sub class="lower-inde... | 500 | [
{
"input": "5\n100 -100 50 0 -50",
"output": "100 -50 0 50 -100 "
},
{
"input": "10\n764 -367 0 963 -939 -795 -26 -49 948 -282",
"output": "963 -795 -367 -282 -49 -26 0 764 948 -939 "
},
{
"input": "20\n262 -689 -593 161 -678 -555 -633 -697 369 258 673 50 833 737 -650 198 -651 -621 -396 ... | 1,694,984,246 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 16 | 124 | 0 |
def permutationMaxVal(a: list) -> list:
n : int = len(a)
x : list = sorted(a)
a = x[0]
b = x[n-1]
x[n-1] = a
x[0] = b
return x
n = int(input())
s = input()
s= s.split(" ")
a: list = [0]*n
for i in range(n):
a[i] = int(s[i])
res = permutatio... | Title: Difference Row
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You want to arrange *n* integers *a*1,<=*a*2,<=...,<=*a**n* in some order in a row. Let's define the value of an arrangement as the sum of differences between all pairs of adjacent integers.
More formally, let's denote ... | ```python
def permutationMaxVal(a: list) -> list:
n : int = len(a)
x : list = sorted(a)
a = x[0]
b = x[n-1]
x[n-1] = a
x[0] = b
return x
n = int(input())
s = input()
s= s.split(" ")
a: list = [0]*n
for i in range(n):
a[i] = int(s[i])
res = ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,674,109,775 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
#define endl "\n"
#define ctz __builtin_ctz
#define ctzll __builtin_ctzll
#define clz __builtin_clz
#define clzll __builtin_clzll
#define setbits __builti... | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
#define endl "\n"
#define ctz __builtin_ctz
#define ctzll __builtin_ctzll
#define clz __builtin_clz
#define clzll __builtin_clzll
#define setbit... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
11 | B | Jumping Jack | PROGRAMMING | 1,600 | [
"math"
] | B. Jumping Jack | 1 | 64 | Jack is working on his jumping skills recently. Currently he's located at point zero of the number line. He would like to get to the point *x*. In order to train, he has decided that he'll first jump by only one unit, and each subsequent jump will be exactly one longer than the previous one. He can go either left or ri... | The input data consists of only one integer *x* (<=-<=109<=≤<=*x*<=≤<=109). | Output the minimal number of jumps that Jack requires to reach *x*. | [
"2\n",
"6\n",
"0\n"
] | [
"3\n",
"3\n",
"0\n"
] | none | 0 | [
{
"input": "2",
"output": "3"
},
{
"input": "6",
"output": "3"
},
{
"input": "0",
"output": "0"
},
{
"input": "-1000000000",
"output": "44723"
},
{
"input": "999961560",
"output": "44720"
},
{
"input": "999961561",
"output": "44721"
},
{
"i... | 1,688,341,002 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | import math
x = abs(int(input()))
print(math.floor(math.sqrt(8 * math.ceil((-1 + math.sqrt(8 * x + 1)) / 2) * (math.ceil((-1 + math.sqrt(8 * x + 1)) / 2) + 1) // 2 + 1) - 1) // 2)
| Title: Jumping Jack
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Jack is working on his jumping skills recently. Currently he's located at point zero of the number line. He would like to get to the point *x*. In order to train, he has decided that he'll first jump by only one unit, and each ... | ```python
import math
x = abs(int(input()))
print(math.floor(math.sqrt(8 * math.ceil((-1 + math.sqrt(8 * x + 1)) / 2) * (math.ceil((-1 + math.sqrt(8 * x + 1)) / 2) + 1) // 2 + 1) - 1) // 2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
854 | A | Fraction | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"math"
] | null | null | Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive co... | In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction. | Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum. | [
"3\n",
"4\n",
"12\n"
] | [
"1 2\n",
"1 3\n",
"5 7\n"
] | none | 500 | [
{
"input": "3",
"output": "1 2"
},
{
"input": "4",
"output": "1 3"
},
{
"input": "12",
"output": "5 7"
},
{
"input": "34",
"output": "15 19"
},
{
"input": "13",
"output": "6 7"
},
{
"input": "11",
"output": "5 6"
},
{
"input": "24",
"ou... | 1,641,895,270 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 61 | 0 | n=int(input())
print((n-1)//2,(n-(n-1)//2)) | Title: Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is cal... | ```python
n=int(input())
print((n-1)//2,(n-(n-1)//2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
979 | A | Pizza, Pizza, Pizza!!! | PROGRAMMING | 1,000 | [
"math"
] | null | null | Katie, Kuro and Shiro are best friends. They have known each other since kindergarten. That's why they often share everything with each other and work together on some very hard problems.
Today is Shiro's birthday. She really loves pizza so she wants to invite her friends to the pizza restaurant near her house to cele... | A single line contains one non-negative integer $n$ ($0 \le n \leq 10^{18}$) — the number of Shiro's friends. The circular pizza has to be sliced into $n + 1$ pieces. | A single integer — the number of straight cuts Shiro needs. | [
"3\n",
"4\n"
] | [
"2",
"5"
] | To cut the round pizza into quarters one has to make two cuts through the center with angle $90^{\circ}$ between them.
To cut the round pizza into five equal parts one has to make five cuts. | 500 | [
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "5"
},
{
"input": "10",
"output": "11"
},
{
"input": "10000000000",
"output": "10000000001"
},
{
"input": "1234567891",
"output": "617283946"
},
{
"input": "7509213957",
"output": "37546069... | 1,587,962,706 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 93 | 0 | n_friends = input()
cuts = (int(n_friends)+1)
slice_deg = 360/cuts
if slice_deg % 45 == 0:
cuts/=2
print(int(cuts))
| Title: Pizza, Pizza, Pizza!!!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Katie, Kuro and Shiro are best friends. They have known each other since kindergarten. That's why they often share everything with each other and work together on some very hard problems.
Today is Shiro's birthd... | ```python
n_friends = input()
cuts = (int(n_friends)+1)
slice_deg = 360/cuts
if slice_deg % 45 == 0:
cuts/=2
print(int(cuts))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
285 | B | Find Marble | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the glasses are not.
First Petya puts a marble under the glass in position *s*. Then he performs som... | The first line contains three integers: *n*,<=*s*,<=*t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*s*,<=*t*<=≤<=*n*) — the number of glasses, the ball's initial and final position. The second line contains *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — the shuffling operation parameters. It is guaran... | If the marble can move from position *s* to position *t*, then print on a single line a non-negative integer — the minimum number of shuffling operations, needed to get the marble to position *t*. If it is impossible, print number -1. | [
"4 2 1\n2 3 4 1\n",
"4 3 3\n4 1 3 2\n",
"4 3 4\n1 2 3 4\n",
"3 1 3\n2 1 3\n"
] | [
"3\n",
"0\n",
"-1\n",
"-1\n"
] | none | 1,000 | [
{
"input": "4 2 1\n2 3 4 1",
"output": "3"
},
{
"input": "4 3 3\n4 1 3 2",
"output": "0"
},
{
"input": "4 3 4\n1 2 3 4",
"output": "-1"
},
{
"input": "3 1 3\n2 1 3",
"output": "-1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "10 6 7\n10 7 8 1... | 1,623,230,190 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 374 | 7,270,400 | from sys import *
from math import *
from sys import stdin,stdout
from collections import *
int_arr = lambda : list(map(int,stdin.readline().strip().split()))
str_arr = lambda :list(map(str,stdin.readline().split()))
get_str = lambda : map(str,stdin.readline().strip().split())
get_int = lambda: map(int,stdin.r... | Title: Find Marble
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the ... | ```python
from sys import *
from math import *
from sys import stdin,stdout
from collections import *
int_arr = lambda : list(map(int,stdin.readline().strip().split()))
str_arr = lambda :list(map(str,stdin.readline().split()))
get_str = lambda : map(str,stdin.readline().strip().split())
get_int = lambda: map(i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
797 | C | Minimal string | PROGRAMMING | 1,700 | [
"data structures",
"greedy",
"strings"
] | null | null | Petya recieved a gift of a string *s* with length up to 105 characters for his birthday. He took two more empty strings *t* and *u* and decided to play a game. This game has two possible moves:
- Extract the first character of *s* and append *t* with this character. - Extract the last character of *t* and append *u*... | First line contains non-empty string *s* (1<=≤<=|*s*|<=≤<=105), consisting of lowercase English letters. | Print resulting string *u*. | [
"cab\n",
"acdb\n"
] | [
"abc\n",
"abdc\n"
] | none | 0 | [
{
"input": "cab",
"output": "abc"
},
{
"input": "acdb",
"output": "abdc"
},
{
"input": "a",
"output": "a"
},
{
"input": "ab",
"output": "ab"
},
{
"input": "ba",
"output": "ab"
},
{
"input": "dijee",
"output": "deeji"
},
{
"input": "bhrmc",
... | 1,691,700,469 | 2,147,483,647 | Python 3 | OK | TESTS | 189 | 187 | 4,403,200 | s = list(input())
s = s[::-1]
aux = []
pilha1 = []
pilha2 = []
menor = "z"
for i in range(len(s)):
menor = min(s[i], menor)
aux.append(menor)
for i in range(len(s)-1, -1,-1):
if s[i] == aux[i]:
pilha2.append(s[i])
s.pop()
aux.pop()
while(len(pilha1) > 0):
if len... | Title: Minimal string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya recieved a gift of a string *s* with length up to 105 characters for his birthday. He took two more empty strings *t* and *u* and decided to play a game. This game has two possible moves:
- Extract the first char... | ```python
s = list(input())
s = s[::-1]
aux = []
pilha1 = []
pilha2 = []
menor = "z"
for i in range(len(s)):
menor = min(s[i], menor)
aux.append(menor)
for i in range(len(s)-1, -1,-1):
if s[i] == aux[i]:
pilha2.append(s[i])
s.pop()
aux.pop()
while(len(pilha1) > 0):
... | 3 | MatrixStudio/Codeforces-Python-Submissions |
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