Instruction stringlengths 45 106 | input_code stringlengths 1 13.7k | output_code stringlengths 1 13.7k |
|---|---|---|
Change the programming language of this snippet from Nim to C++ without modifying what it does. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i... | #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Produce a language-to-language conversion: from Nim to Java, same semantics. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i... | public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Convert this Nim block to Java, preserving its control flow and logic. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i... | public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Please provide an equivalent version of this Nim code in Python. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i... | >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Write the same algorithm in Python as shown in this Nim implementation. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i... | >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Convert the following code from Nim to VB, ensuring the logic remains intact. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i... | Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Change the programming language of this snippet from Nim to VB without modifying what it does. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i... | Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Produce a language-to-language conversion: from Nim to Go, same semantics. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i... | package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Rewrite this program in Go while keeping its functionality equivalent to the Nim version. |
proc multifact(n, deg: int): int =
result = (if n <= deg: n else: n * multifact(n - deg, deg))
proc multifactI(n, deg: int): int =
result = n
var n = n
while n >= deg + 1:
result *= n - deg
n -= deg
for i in 1..5:
stdout.write "Degree ", i, ": "
for j in 1..10:
stdout.write multifactI(j, i... | package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Convert this OCaml snippet to C and keep its semantics consistent. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Rewrite this program in C while keeping its functionality equivalent to the OCaml version. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Port the provided OCaml code into C# while preserving the original functionality. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Please provide an equivalent version of this OCaml code in C#. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Preserve the algorithm and functionality while converting the code from OCaml to C++. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Write the same code in C++ as shown below in OCaml. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Rewrite the snippet below in Java so it works the same as the original OCaml code. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Can you help me rewrite this code in Java instead of OCaml, keeping it the same logically? | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Generate an equivalent Python version of this OCaml code. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Produce a language-to-language conversion: from OCaml to Python, same semantics. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Port the following code from OCaml to VB with equivalent syntax and logic. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Please provide an equivalent version of this OCaml code in VB. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Translate this program into Go but keep the logic exactly as in OCaml. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Transform the following OCaml implementation into Go, maintaining the same output and logic. | let multi_fac d n =
let rec loop a x = if x < 2 then a else loop (a * x) (x - d) in
loop n (n - d)
let () =
for i = 1 to 5 do
Seq.(ints 1 |> take 10 |> map (multi_fac i) |> map string_of_int)
|> List.of_seq |> String.concat " " |> print_endline
done
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Write a version of this Perl function in C with identical behavior. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Port the provided Perl code into C while preserving the original functionality. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Keep all operations the same but rewrite the snippet in C#. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Can you help me rewrite this code in C# instead of Perl, keeping it the same logically? | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Write the same algorithm in C++ as shown in this Perl implementation. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Maintain the same structure and functionality when rewriting this code in C++. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Convert the following code from Perl to Java, ensuring the logic remains intact. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Rewrite this program in Java while keeping its functionality equivalent to the Perl version. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Preserve the algorithm and functionality while converting the code from Perl to Python. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Convert this Perl block to Python, preserving its control flow and logic. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Rewrite this program in VB while keeping its functionality equivalent to the Perl version. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Can you help me rewrite this code in VB instead of Perl, keeping it the same logically? | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Keep all operations the same but rewrite the snippet in Go. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Produce a functionally identical Go code for the snippet given in Perl. | {
my @cache;
use bigint;
sub mfact {
my ($s, $n) = @_;
return 1 if $n <= 0;
$cache[$s][$n] //= $n * mfact($s, $n - $s);
}
}
for my $s (1 .. 10) {
print "step=$s: ";
print join(" ", map(mfact($s, $_), 1 .. 10)), "\n";
}
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Convert this Racket snippet to C and keep its semantics consistent. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... |
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Port the provided Racket code into C while preserving the original functionality. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... |
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Translate the given Racket code snippet into C# without altering its behavior. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Write the same code in C# as shown below in Racket. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Port the following code from Racket to C++ with equivalent syntax and logic. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Change the following Racket code into C++ without altering its purpose. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Change the programming language of this snippet from Racket to Java without modifying what it does. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Ensure the translated Java code behaves exactly like the original Racket snippet. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Translate the given Racket code snippet into Python without altering its behavior. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Transform the following Racket implementation into Python, maintaining the same output and logic. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Generate an equivalent VB version of this Racket code. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Write a version of this Racket function in VB with identical behavior. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Please provide an equivalent version of this Racket code in Go. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Write the same algorithm in Go as shown in this Racket implementation. | #lang racket
(define (multi-factorial-fn m)
(lambda (n)
(let inner ((acc 1) (n n))
(if (<= n m) (* acc n)
(inner (* acc n) (- n m))))))
(for*/list ([m (in-range 1 (add1 5))] [mf-m (in-value (multi-factorial-fn m))])
(for/list ([n (in-range 1 (add1 10))])
(mf-m n)))
(define (multi-factorial... | package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Rewrite this program in C while keeping its functionality equivalent to the REXX version. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... |
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Write a version of this REXX function in C with identical behavior. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... |
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Translate this program into C# but keep the logic exactly as in REXX. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Write the same code in C# as shown below in REXX. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Maintain the same structure and functionality when rewriting this code in C++. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Convert this REXX snippet to C++ and keep its semantics consistent. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Port the provided REXX code into Java while preserving the original functionality. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Translate the given REXX code snippet into Java without altering its behavior. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Write the same code in Python as shown below in REXX. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Translate this program into Python but keep the logic exactly as in REXX. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Produce a language-to-language conversion: from REXX to VB, same semantics. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Translate this program into VB but keep the logic exactly as in REXX. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Write the same algorithm in Go as shown in this REXX implementation. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Rewrite this program in Go while keeping its functionality equivalent to the REXX version. |
numeric digits 1000
parse arg num deg .
if num=='' | num=="," then num=15
if deg=='' | deg=="," then deg=10
say '═══showing multiple factorials (1 ──►' deg") for numbers 1 ──►" num
say
do d=1 for deg ... | package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Please provide an equivalent version of this Ruby code in C. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Ensure the translated C code behaves exactly like the original Ruby snippet. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Generate an equivalent C# version of this Ruby code. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Generate an equivalent C# version of this Ruby code. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Generate a C++ translation of this Ruby snippet without changing its computational steps. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Convert the following code from Ruby to C++, ensuring the logic remains intact. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Can you help me rewrite this code in Java instead of Ruby, keeping it the same logically? | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Preserve the algorithm and functionality while converting the code from Ruby to Java. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Transform the following Ruby implementation into Python, maintaining the same output and logic. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Keep all operations the same but rewrite the snippet in Python. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Write the same code in VB as shown below in Ruby. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Ensure the translated VB code behaves exactly like the original Ruby snippet. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Maintain the same structure and functionality when rewriting this code in Go. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Maintain the same structure and functionality when rewriting this code in Go. | def multifact(n, d)
n.step(to: 1, by: -d).product
end
(1..5).each {|d| puts "Degree
| package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Write the same code in C as shown below in Scala. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... |
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Maintain the same structure and functionality when rewriting this code in C. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... |
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Write the same algorithm in C# as shown in this Scala implementation. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Write the same algorithm in C# as shown in this Scala implementation. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Translate the given Scala code snippet into C++ without altering its behavior. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Keep all operations the same but rewrite the snippet in C++. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Maintain the same structure and functionality when rewriting this code in Java. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Ensure the translated Java code behaves exactly like the original Scala snippet. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
Convert the following code from Scala to Python, ensuring the logic remains intact. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Please provide an equivalent version of this Scala code in Python. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | >>> from functools import reduce
>>> from operator import mul
>>> def mfac(n, m): return reduce(mul, range(n, 0, -m))
>>> for m in range(1, 11): print("%2i: %r" % (m, [mfac(n, m) for n in range(1, 11)]))
1: [1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
2: [1, 2, 3, 8, 15, 48, 105, 384, 945, 3840]
3: [1, 2,... |
Please provide an equivalent version of this Scala code in VB. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Translate the given Scala code snippet into VB without altering its behavior. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | Function multifactorial(n,d)
If n = 0 Then
multifactorial = 1
Else
For i = n To 1 Step -d
If i = n Then
multifactorial = n
Else
multifactorial = multifactorial * i
End If
Next
End If
End Function
For j = 1 To 5
WScript.StdOut.Write "Degree " & j & ": "
For k = 1 To 10
If k = 10 Then
WS... |
Write the same algorithm in Go as shown in this Scala implementation. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Produce a functionally identical Go code for the snippet given in Scala. | fun multifactorial(n: Long, d: Int) : Long {
val r = n % d
return (1..n).filter { it % d == r } .reduce { i, p -> i * p }
}
fun main(args: Array<String>) {
val m = 5
val r = 1..10L
for (d in 1..m) {
print("%${m}s:".format( "!".repeat(d)))
r.forEach { print(" " + multifactorial(it, d... | package main
import "fmt"
func multiFactorial(n, k int) int {
r := 1
for ; n > 1; n -= k {
r *= n
}
return r
}
func main() {
for k := 1; k <= 5; k++ {
fmt.Print("degree ", k, ":")
for n := 1; n <= 10; n++ {
fmt.Print(" ", multiFactorial(n, k))
}
... |
Change the programming language of this snippet from Swift to C without modifying what it does. | func multiFactorial(_ n: Int, k: Int) -> Int {
return stride(from: n, to: 0, by: -k).reduce(1, *)
}
let multis = (1...5).map({degree in
(1...10).map({member in
multiFactorial(member, k: degree)
})
})
for (i, degree) in multis.enumerated() {
print("Degree \(i + 1): \(degree)")
}
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Transform the following Swift implementation into C, maintaining the same output and logic. | func multiFactorial(_ n: Int, k: Int) -> Int {
return stride(from: n, to: 0, by: -k).reduce(1, *)
}
let multis = (1...5).map({degree in
(1...10).map({member in
multiFactorial(member, k: degree)
})
})
for (i, degree) in multis.enumerated() {
print("Degree \(i + 1): \(degree)")
}
|
#include <stdio.h>
#define HIGHEST_DEGREE 5
#define LARGEST_NUMBER 10
int multifact(int n, int deg){
return n <= deg ? n : n * multifact(n - deg, deg);
}
int multifact_i(int n, int deg){
int result = n;
while (n >= deg + 1){
result *= (n - deg);
n -= deg;
}
return result;
}
int main(vo... |
Write the same algorithm in C# as shown in this Swift implementation. | func multiFactorial(_ n: Int, k: Int) -> Int {
return stride(from: n, to: 0, by: -k).reduce(1, *)
}
let multis = (1...5).map({degree in
(1...10).map({member in
multiFactorial(member, k: degree)
})
})
for (i, degree) in multis.enumerated() {
print("Degree \(i + 1): \(degree)")
}
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Change the following Swift code into C# without altering its purpose. | func multiFactorial(_ n: Int, k: Int) -> Int {
return stride(from: n, to: 0, by: -k).reduce(1, *)
}
let multis = (1...5).map({degree in
(1...10).map({member in
multiFactorial(member, k: degree)
})
})
for (i, degree) in multis.enumerated() {
print("Degree \(i + 1): \(degree)")
}
| namespace RosettaCode.Multifactorial
{
using System;
using System.Linq;
internal static class Program
{
private static void Main()
{
Console.WriteLine(string.Join(Environment.NewLine,
Enumerable.Range(1, 5)
... |
Can you help me rewrite this code in C++ instead of Swift, keeping it the same logically? | func multiFactorial(_ n: Int, k: Int) -> Int {
return stride(from: n, to: 0, by: -k).reduce(1, *)
}
let multis = (1...5).map({degree in
(1...10).map({member in
multiFactorial(member, k: degree)
})
})
for (i, degree) in multis.enumerated() {
print("Degree \(i + 1): \(degree)")
}
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Convert this Swift block to C++, preserving its control flow and logic. | func multiFactorial(_ n: Int, k: Int) -> Int {
return stride(from: n, to: 0, by: -k).reduce(1, *)
}
let multis = (1...5).map({degree in
(1...10).map({member in
multiFactorial(member, k: degree)
})
})
for (i, degree) in multis.enumerated() {
print("Degree \(i + 1): \(degree)")
}
| #include <algorithm>
#include <iostream>
#include <iterator>
int main(void) {
for (int g = 1; g < 10; g++) {
int v[11], n=0;
generate_n(std::ostream_iterator<int>(std::cout, " "), 10, [&]{n++; return v[n]=(g<n)? v[n-g]*n : n;});
std::cout << std::endl;
}
return 0;
}
|
Can you help me rewrite this code in Java instead of Swift, keeping it the same logically? | func multiFactorial(_ n: Int, k: Int) -> Int {
return stride(from: n, to: 0, by: -k).reduce(1, *)
}
let multis = (1...5).map({degree in
(1...10).map({member in
multiFactorial(member, k: degree)
})
})
for (i, degree) in multis.enumerated() {
print("Degree \(i + 1): \(degree)")
}
| public class MultiFact {
private static long multiFact(long n, int deg){
long ans = 1;
for(long i = n; i > 0; i -= deg){
ans *= i;
}
return ans;
}
public static void main(String[] args){
for(int deg = 1; deg <= 5; deg++){
System.out.print("degree " + deg + ":");
for(long n = 1; n <= 10; n++){
... |
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