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Change the programming language of this snippet from Rust to Python without modifying what it does.
use std::env; fn main() { let mut args = env::args().skip(1).flat_map(|num| num.parse()); let rows = args.next().expect("Expected number of rows as first argument"); let cols = args.next().expect("Expected number of columns as second argument"); assert_ne!(rows, 0, "rows were zero"); assert_ne!(cols, 0, "cols were zero"); let mut v = vec![vec![0; cols]; rows]; v[0][0] = 1; println!("{}", v[0][0]); }
width = int(raw_input("Width of myarray: ")) height = int(raw_input("Height of Array: ")) myarray = [[0] * width for i in range(height)] myarray[0][0] = 3.5 print (myarray[0][0])
Port the following code from Rust to VB with equivalent syntax and logic.
use std::env; fn main() { let mut args = env::args().skip(1).flat_map(|num| num.parse()); let rows = args.next().expect("Expected number of rows as first argument"); let cols = args.next().expect("Expected number of columns as second argument"); assert_ne!(rows, 0, "rows were zero"); assert_ne!(cols, 0, "cols were zero"); let mut v = vec![vec![0; cols]; rows]; v[0][0] = 1; println!("{}", v[0][0]); }
Module Program Sub Main() Console.WriteLine("Enter two space-delimited integers:") Dim input = Console.ReadLine().Split() Dim rows = Integer.Parse(input(0)) Dim cols = Integer.Parse(input(1)) Dim arr(rows - 1, cols - 1) As Integer arr(0, 0) = 2 Console.WriteLine(arr(0, 0)) End Sub End Module
Translate the given Go code snippet into Rust without altering its behavior.
package main import "fmt" func main() { var row, col int fmt.Print("enter rows cols: ") fmt.Scan(&row, &col) a := make([][]int, row) for i := range a { a[i] = make([]int, col) } fmt.Println("a[0][0] =", a[0][0]) a[row-1][col-1] = 7 fmt.Printf("a[%d][%d] = %d\n", row-1, col-1, a[row-1][col-1]) a = nil }
use std::env; fn main() { let mut args = env::args().skip(1).flat_map(|num| num.parse()); let rows = args.next().expect("Expected number of rows as first argument"); let cols = args.next().expect("Expected number of columns as second argument"); assert_ne!(rows, 0, "rows were zero"); assert_ne!(cols, 0, "cols were zero"); let mut v = vec![vec![0; cols]; rows]; v[0][0] = 1; println!("{}", v[0][0]); }
Change the programming language of this snippet from Ada to C# without modifying what it does.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Generate an equivalent C# version of this Ada code.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Write the same algorithm in C as shown in this Ada implementation.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Produce a functionally identical C code for the snippet given in Ada.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Can you help me rewrite this code in C++ instead of Ada, keeping it the same logically?
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Translate the given Ada code snippet into C++ without altering its behavior.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Preserve the algorithm and functionality while converting the code from Ada to Go.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Write a version of this Ada function in Go with identical behavior.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Rewrite this program in Java while keeping its functionality equivalent to the Ada version.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Port the following code from Ada to Java with equivalent syntax and logic.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Can you help me rewrite this code in Python instead of Ada, keeping it the same logically?
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Please provide an equivalent version of this Ada code in Python.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Change the programming language of this snippet from Ada to VB without modifying what it does.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Maintain the same structure and functionality when rewriting this code in VB.
with Ada.Text_IO; procedure Munchausen is function Is_Munchausen (M : in Natural) return Boolean is Table : constant array (Character range '0' .. '9') of Natural := (0**0, 1**1, 2**2, 3**3, 4**4, 5**5, 6**6, 7**7, 8**8, 9**9); Image : constant String := M'Image; Sum : Natural := 0; begin for I in Image'First + 1 .. Image'Last loop Sum := Sum + Table (Image (I)); end loop; return Image = Sum'Image; end Is_Munchausen; begin for M in 1 .. 5_000 loop if Is_Munchausen (M) then Ada.Text_IO.Put (M'Image); end if; end loop; Ada.Text_IO.New_Line; end Munchausen;
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Transform the following Arturo implementation into C, maintaining the same output and logic.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Produce a functionally identical C code for the snippet given in Arturo.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Write a version of this Arturo function in C# with identical behavior.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Write a version of this Arturo function in C# with identical behavior.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Convert this Arturo block to C++, preserving its control flow and logic.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Produce a language-to-language conversion: from Arturo to C++, same semantics.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Port the provided Arturo code into Java while preserving the original functionality.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Port the following code from Arturo to Java with equivalent syntax and logic.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Convert this Arturo block to Python, preserving its control flow and logic.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Generate an equivalent Python version of this Arturo code.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Rewrite this program in VB while keeping its functionality equivalent to the Arturo version.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Generate a VB translation of this Arturo snippet without changing its computational steps.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Port the provided Arturo code into Go while preserving the original functionality.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Translate this program into Go but keep the logic exactly as in Arturo.
munchausen?: function [n][ n = sum map split to :string n 'digit [ d: to :integer digit d^d ] ] loop 1..5000 'x [ if munchausen? x -> print x ]
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Port the following code from AutoHotKey to C with equivalent syntax and logic.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Write a version of this AutoHotKey function in C with identical behavior.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Rewrite this program in C# while keeping its functionality equivalent to the AutoHotKey version.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Generate a C# translation of this AutoHotKey snippet without changing its computational steps.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Generate a C++ translation of this AutoHotKey snippet without changing its computational steps.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Transform the following AutoHotKey implementation into C++, maintaining the same output and logic.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Can you help me rewrite this code in Java instead of AutoHotKey, keeping it the same logically?
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Convert this AutoHotKey block to Java, preserving its control flow and logic.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Write a version of this AutoHotKey function in Python with identical behavior.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Change the following AutoHotKey code into Python without altering its purpose.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Rewrite the snippet below in VB so it works the same as the original AutoHotKey code.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Generate an equivalent VB version of this AutoHotKey code.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Ensure the translated Go code behaves exactly like the original AutoHotKey snippet.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Change the following AutoHotKey code into Go without altering its purpose.
Loop, 5000 { Loop, Parse, A_Index var += A_LoopField**A_LoopField if (var = A_Index) num .= var "`n" var := 0 } Msgbox, %num%
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Convert the following code from AWK to C, ensuring the logic remains intact.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Convert this AWK snippet to C and keep its semantics consistent.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Write a version of this AWK function in C# with identical behavior.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Convert this AWK snippet to C# and keep its semantics consistent.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Preserve the algorithm and functionality while converting the code from AWK to C++.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Change the following AWK code into C++ without altering its purpose.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Write a version of this AWK function in Java with identical behavior.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Write the same code in Java as shown below in AWK.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Write the same code in Python as shown below in AWK.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Please provide an equivalent version of this AWK code in Python.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Transform the following AWK implementation into VB, maintaining the same output and logic.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Port the provided AWK code into VB while preserving the original functionality.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Maintain the same structure and functionality when rewriting this code in Go.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Transform the following AWK implementation into Go, maintaining the same output and logic.
BEGIN { for (i=1; i<=5000; i++) { sum = 0 for (j=1; j<=length(i); j++) { digit = substr(i,j,1) sum += digit ^ digit } if (i == sum) { printf("%d\n",i) } } exit(0) }
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Ensure the translated C code behaves exactly like the original BBC_Basic snippet.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Port the following code from BBC_Basic to C with equivalent syntax and logic.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Maintain the same structure and functionality when rewriting this code in C#.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Write the same algorithm in C# as shown in this BBC_Basic implementation.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Write a version of this BBC_Basic function in C++ with identical behavior.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Convert this BBC_Basic block to C++, preserving its control flow and logic.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Rewrite the snippet below in Java so it works the same as the original BBC_Basic code.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Write a version of this BBC_Basic function in Java with identical behavior.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Write the same code in Python as shown below in BBC_Basic.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Change the programming language of this snippet from BBC_Basic to Python without modifying what it does.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Change the following BBC_Basic code into VB without altering its purpose.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Change the following BBC_Basic code into VB without altering its purpose.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Produce a language-to-language conversion: from BBC_Basic to Go, same semantics.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Port the provided BBC_Basic code into Go while preserving the original functionality.
FOR i% = 0 TO 5 FOR j% = 0 TO 5 FOR k% = 0 TO 5 FOR l% = 0 TO 5 m% = FNexp(i%) + FNexp(j%) + FNexp(k%) + FNexp(l%) n% = 1000 * i% + 100 * j% + 10 * k% + l% IF m% = n% AND m% > 0 THEN PRINT m% NEXT NEXT NEXT NEXT END : DEF FNexp(x%) IF x% = 0 THEN = 0 ELSE = x% ^ x%
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Translate the given Common_Lisp code snippet into C without altering its behavior.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Generate a C translation of this Common_Lisp snippet without changing its computational steps.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Preserve the algorithm and functionality while converting the code from Common_Lisp to C#.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Transform the following Common_Lisp implementation into C#, maintaining the same output and logic.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Produce a functionally identical C++ code for the snippet given in Common_Lisp.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Convert the following code from Common_Lisp to C++, ensuring the logic remains intact.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Generate an equivalent Java version of this Common_Lisp code.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Maintain the same structure and functionality when rewriting this code in Java.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Translate this program into Python but keep the logic exactly as in Common_Lisp.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Maintain the same structure and functionality when rewriting this code in Python.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Rewrite the snippet below in VB so it works the same as the original Common_Lisp code.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Port the following code from Common_Lisp to VB with equivalent syntax and logic.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Transform the following Common_Lisp implementation into Go, maintaining the same output and logic.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Produce a functionally identical Go code for the snippet given in Common_Lisp.
(ns async-example.core (:require [clojure.math.numeric-tower :as math]) (:use [criterium.core]) (:gen-class)) (defn get-digits [n] " Convert number of a list of digits (e.g. 545 -> ((5), (4), (5)) " (map #(Integer/valueOf (str %)) (String/valueOf n))) (defn sum-power [digits] " Convert digits such as abc... to a^a + b^b + c^c ..." (let [digits-pwr (fn [n] (apply + (map #(math/expt % %) digits)))] (digits-pwr digits))) (defn find-numbers [max-range] " Filters for Munchausen numbers " (->> (range 1 (inc max-range)) (filter #(= (sum-power (get-digits %)) %)))) (println (find-numbers 5000))
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Can you help me rewrite this code in C instead of D, keeping it the same logically?
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Port the provided D code into C while preserving the original functionality.
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Can you help me rewrite this code in C# instead of D, keeping it the same logically?
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Port the following code from D to C# with equivalent syntax and logic.
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Rewrite the snippet below in C++ so it works the same as the original D code.
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Transform the following D implementation into C++, maintaining the same output and logic.
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Maintain the same structure and functionality when rewriting this code in Java.
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Please provide an equivalent version of this D code in Java.
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Produce a functionally identical Python code for the snippet given in D.
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Port the following code from D to Python with equivalent syntax and logic.
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Write a version of this D function in VB with identical behavior.
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Can you help me rewrite this code in VB instead of D, keeping it the same logically?
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Convert this D snippet to Go and keep its semantics consistent.
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }