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Can you help me rewrite this code in Go instead of D, keeping it the same logically?
import std.stdio; void main() { for (int i=1; i<5000; i++) { int sum = 0; for (int number=i; number>0; number/=10) { int digit = number % 10; sum += digit ^^ digit; } if (sum == i) { writeln(i); } } }
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Convert this Elixir block to C, preserving its control flow and logic.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Write the same algorithm in C as shown in this Elixir implementation.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Translate this program into C# but keep the logic exactly as in Elixir.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Port the provided Elixir code into C# while preserving the original functionality.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Generate a C++ translation of this Elixir snippet without changing its computational steps.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Change the following Elixir code into Java without altering its purpose.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Change the programming language of this snippet from Elixir to Java without modifying what it does.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Please provide an equivalent version of this Elixir code in Python.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Maintain the same structure and functionality when rewriting this code in Python.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Translate this program into VB but keep the logic exactly as in Elixir.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Rewrite the snippet below in VB so it works the same as the original Elixir code.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Convert this Elixir block to Go, preserving its control flow and logic.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Generate an equivalent Go version of this Elixir code.
defmodule Munchausen do @pow for i <- 0..9, into: %{}, do: {i, :math.pow(i,i) |> round} def number?(n) do n == Integer.digits(n) |> Enum.reduce(0, fn d,acc -> @pow[d] + acc end) end end Enum.each(1..5000, fn i -> if Munchausen.number?(i), do: IO.puts i end)
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Change the following F# code into C without altering its purpose.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Write a version of this F# function in C with identical behavior.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Write the same code in C# as shown below in F#.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Generate a C# translation of this F# snippet without changing its computational steps.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Translate this program into C++ but keep the logic exactly as in F#.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Produce a language-to-language conversion: from F# to C++, same semantics.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Convert this F# snippet to Java and keep its semantics consistent.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Change the following F# code into Java without altering its purpose.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Please provide an equivalent version of this F# code in Python.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Generate an equivalent Python version of this F# code.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Write the same algorithm in VB as shown in this F# implementation.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Translate the given F# code snippet into VB without altering its behavior.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Convert this F# block to Go, preserving its control flow and logic.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Rewrite this program in Go while keeping its functionality equivalent to the F# version.
let toFloat x = x |> int |> fun n -> n - 48 |> float let power x = toFloat x ** toFloat x |> int let isMunchausen n = n = (string n |> Seq.map char |> Seq.map power |> Seq.sum) printfn "%A" ([1..5000] |> List.filter isMunchausen)
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Write the same code in C as shown below in Factor.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Convert this Factor snippet to C and keep its semantics consistent.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Produce a language-to-language conversion: from Factor to C#, same semantics.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Transform the following Factor implementation into C#, maintaining the same output and logic.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Translate this program into C++ but keep the logic exactly as in Factor.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Convert this Factor snippet to C++ and keep its semantics consistent.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Can you help me rewrite this code in Java instead of Factor, keeping it the same logically?
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Please provide an equivalent version of this Factor code in Java.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Translate the given Factor code snippet into Python without altering its behavior.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Ensure the translated Python code behaves exactly like the original Factor snippet.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Change the programming language of this snippet from Factor to VB without modifying what it does.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Convert this Factor snippet to VB and keep its semantics consistent.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Generate a Go translation of this Factor snippet without changing its computational steps.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Write the same algorithm in Go as shown in this Factor implementation.
USING: kernel math.functions math.ranges math.text.utils prettyprint sequences ; : munchausen? ( n -- ? ) dup 1 digit-groups dup [ ^ ] 2map sum = ; 5000 [1,b] [ munchausen? ] filter .
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Port the provided Forth code into C while preserving the original functionality.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Write the same code in C as shown below in Forth.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Generate a C# translation of this Forth snippet without changing its computational steps.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Ensure the translated C# code behaves exactly like the original Forth snippet.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Port the provided Forth code into C++ while preserving the original functionality.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Can you help me rewrite this code in C++ instead of Forth, keeping it the same logically?
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Convert this Forth snippet to Java and keep its semantics consistent.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Write a version of this Forth function in Java with identical behavior.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Write the same code in Python as shown below in Forth.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Port the following code from Forth to Python with equivalent syntax and logic.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Transform the following Forth implementation into VB, maintaining the same output and logic.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Produce a functionally identical VB code for the snippet given in Forth.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Rewrite this program in Go while keeping its functionality equivalent to the Forth version.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Translate the given Forth code snippet into Go without altering its behavior.
: dig.num dup 0 swap begin swap 1 + swap dup 10 >= while 10 / repeat drop ; : to.self dup 1 = if drop 1 else dup 0 <= if drop 0 else dup 1 do dup loop dup 1 do * loop then then ; : ten.to dup 0 <= if drop 1 else dup 1 = if drop 10 else 10 swap 1 do 10 * loop then then ; : zero.divmod dup 0 = if drop 0 else /mod then ; : split.div dup 10 < if dup 0 else dig.num swap dup rot dup 1 - ten.to swap 1 do dup rot swap zero.divmod swap rot 10 / loop drop then ; : add.pow to.self depth 2 do swap to.self + loop ; : check.num split.div add.pow ; : munch.num 1 + page 1 do i check.num = if i . cr then loop ;
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Change the programming language of this snippet from Fortran to C# without modifying what it does.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Change the following Fortran code into C# without altering its purpose.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Change the following Fortran code into C++ without altering its purpose.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Change the programming language of this snippet from Fortran to C++ without modifying what it does.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Change the following Fortran code into C without altering its purpose.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Produce a language-to-language conversion: from Fortran to C, same semantics.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Port the provided Fortran code into Go while preserving the original functionality.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Can you help me rewrite this code in Java instead of Fortran, keeping it the same logically?
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Rewrite this program in Java while keeping its functionality equivalent to the Fortran version.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Maintain the same structure and functionality when rewriting this code in Python.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Maintain the same structure and functionality when rewriting this code in Python.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Convert the following code from Fortran to VB, ensuring the logic remains intact.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Please provide an equivalent version of this Fortran code in VB.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Change the following Fortran code into PHP without altering its purpose.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
<?php $pwr = array_fill(0, 10, 0); function isMunchhausen($n) { global $pwr; $sm = 0; $temp = $n; while ($temp) { $sm= $sm + $pwr[($temp % 10)]; $temp = (int)($temp / 10); } return $sm == $n; } for ($i = 0; $i < 10; $i++) { $pwr[$i] = pow((float)($i), (float)($i)); } for ($i = 1; $i < 5000 + 1; $i++) { if (isMunchhausen($i)) { echo $i . PHP_EOL; } }
Write a version of this Fortran function in PHP with identical behavior.
C MUNCHAUSEN NUMBERS - FORTRAN IV DO 2 I=1,5000 IS=0 II=I DO 1 J=1,4 ID=10**(4-J) N=II/ID IR=MOD(II,ID) IF(N.NE.0) IS=IS+N**N 1 II=IR 2 IF(IS.EQ.I) WRITE(*,*) I END
<?php $pwr = array_fill(0, 10, 0); function isMunchhausen($n) { global $pwr; $sm = 0; $temp = $n; while ($temp) { $sm= $sm + $pwr[($temp % 10)]; $temp = (int)($temp / 10); } return $sm == $n; } for ($i = 0; $i < 10; $i++) { $pwr[$i] = pow((float)($i), (float)($i)); } for ($i = 1; $i < 5000 + 1; $i++) { if (isMunchhausen($i)) { echo $i . PHP_EOL; } }
Convert the following code from Haskell to C, ensuring the logic remains intact.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Preserve the algorithm and functionality while converting the code from Haskell to C.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Keep all operations the same but rewrite the snippet in C#.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Write the same algorithm in C# as shown in this Haskell implementation.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Write the same code in C++ as shown below in Haskell.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Port the provided Haskell code into C++ while preserving the original functionality.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Write the same code in Java as shown below in Haskell.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Can you help me rewrite this code in Java instead of Haskell, keeping it the same logically?
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Can you help me rewrite this code in Python instead of Haskell, keeping it the same logically?
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Keep all operations the same but rewrite the snippet in Python.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Ensure the translated VB code behaves exactly like the original Haskell snippet.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Maintain the same structure and functionality when rewriting this code in VB.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Change the following Haskell code into Go without altering its purpose.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Maintain the same structure and functionality when rewriting this code in Go.
import Control.Monad (join) import Data.List (unfoldr) isMunchausen :: Integer -> Bool isMunchausen = (==) <*> (sum . map (join (^)) . unfoldr digit) digit 0 = Nothing digit n = Just (r, q) where (q, r) = n `divMod` 10 main :: IO () main = print $ filter isMunchausen [1 .. 5000]
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Produce a functionally identical C code for the snippet given in J.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Port the provided J code into C while preserving the original functionality.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }
Maintain the same structure and functionality when rewriting this code in C#.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Change the programming language of this snippet from J to C# without modifying what it does.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
Func<char, int> toInt = c => c-'0'; foreach (var i in Enumerable.Range(1,5000) .Where(n => n == n.ToString() .Sum(x => Math.Pow(toInt(x), toInt(x))))) Console.WriteLine(i);
Write the same algorithm in C++ as shown in this J implementation.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Convert the following code from J to C++, ensuring the logic remains intact.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
#include <math.h> #include <iostream> unsigned pwr[10]; unsigned munch( unsigned i ) { unsigned sum = 0; while( i ) { sum += pwr[(i % 10)]; i /= 10; } return sum; } int main( int argc, char* argv[] ) { for( int i = 0; i < 10; i++ ) pwr[i] = (unsigned)pow( (float)i, (float)i ); std::cout << "Munchausen Numbers\n==================\n"; for( unsigned i = 1; i < 5000; i++ ) if( i == munch( i ) ) std::cout << i << "\n"; return 0; }
Write a version of this J function in Java with identical behavior.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Translate the given J code snippet into Java without altering its behavior.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
public class Main { public static void main(String[] args) { for(int i = 0 ; i <= 5000 ; i++ ){ int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum(); if( i == val){ System.out.println( i + " (munchausen)"); } } } }
Can you help me rewrite this code in Python instead of J, keeping it the same logically?
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Write a version of this J function in Python with identical behavior.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
for i in range(5000): if i == sum(int(x) ** int(x) for x in str(i)): print(i)
Port the following code from J to VB with equivalent syntax and logic.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Generate an equivalent VB version of this J code.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
Option Explicit Sub Main_Munchausen_numbers() Dim i& For i = 1 To 5000 If IsMunchausen(i) Then Debug.Print i & " is a munchausen number." Next i End Sub Function IsMunchausen(Number As Long) As Boolean Dim Digits, i As Byte, Tot As Long Digits = Split(StrConv(Number, vbUnicode), Chr(0)) For i = 0 To UBound(Digits) - 1 Tot = (Digits(i) ^ Digits(i)) + Tot Next i IsMunchausen = (Tot = Number) End Function
Rewrite this program in Go while keeping its functionality equivalent to the J version.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Generate an equivalent Go version of this J code.
munch=: +/@(^~@(10&#.inv)) (#~ ] = munch"0) 1+i.5000 1 3435
package main import( "fmt" "math" ) var powers [10]int func isMunchausen(n int) bool { if n < 0 { return false } n64 := int64(n) nn := n64 var sum int64 = 0 for nn > 0 { sum += int64(powers[nn % 10]) if sum > n64 { return false } nn /= 10 } return sum == n64 } func main() { for i := 1; i <= 9; i++ { d := float64(i) powers[i] = int(math.Pow(d, d)) } fmt.Println("The Munchausen numbers between 0 and 500 million are:") for i := 0; i <= 500000000; i++ { if isMunchausen(i) { fmt.Printf("%d ", i) } } fmt.Println() }
Convert this Julia snippet to C and keep its semantics consistent.
println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
#include <stdio.h> #include <math.h> int main() { for (int i = 1; i < 5000; i++) { int sum = 0; for (int number = i; number > 0; number /= 10) { int digit = number % 10; sum += pow(digit, digit); } if (sum == i) { printf("%i\n", i); } } return 0; }