Instruction stringlengths 45 106 | input_code stringlengths 1 13.7k | output_code stringlengths 1 13.7k |
|---|---|---|
Generate an equivalent C version of this Julia code. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Port the provided Julia code into C# while preserving the original functionality. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Generate an equivalent C# version of this Julia code. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Ensure the translated C++ code behaves exactly like the original Julia snippet. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Generate a C++ translation of this Julia snippet without changing its computational steps. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Maintain the same structure and functionality when rewriting this code in Java. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Write a version of this Julia function in Java with identical behavior. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Ensure the translated Python code behaves exactly like the original Julia snippet. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Translate this program into VB but keep the logic exactly as in Julia. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Produce a language-to-language conversion: from Julia to VB, same semantics. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Please provide an equivalent version of this Julia code in Go. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Rewrite this program in Go while keeping its functionality equivalent to the Julia version. | println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Produce a functionally identical C code for the snippet given in Lua. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Generate a C translation of this Lua snippet without changing its computational steps. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Please provide an equivalent version of this Lua code in C#. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Change the programming language of this snippet from Lua to C# without modifying what it does. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Change the following Lua code into C++ without altering its purpose. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Maintain the same structure and functionality when rewriting this code in C++. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Convert this Lua block to Java, preserving its control flow and logic. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Can you help me rewrite this code in Java instead of Lua, keeping it the same logically? | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Convert the following code from Lua to Python, ensuring the logic remains intact. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Rewrite the snippet below in Python so it works the same as the original Lua code. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Translate the given Lua code snippet into VB without altering its behavior. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Generate a VB translation of this Lua snippet without changing its computational steps. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Translate this program into Go but keep the logic exactly as in Lua. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Maintain the same structure and functionality when rewriting this code in Go. | function isMunchausen (n)
local sum, nStr, digit = 0, tostring(n)
for pos = 1, #nStr do
digit = tonumber(nStr:sub(pos, pos))
sum = sum + digit ^ digit
end
return sum == n
end
local function isMunchausen (n)
local sum, digit, acc = 0, 0, n
while acc > 0 do
digit = acc % 10.0
sum = sum + digit ^ digit
acc = acc // 10
end
return sum == n
end
for i = 1, 5000 do
if isMunchausen(i) then print(i) end
end
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Convert this Mathematica snippet to C and keep its semantics consistent. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Convert the following code from Mathematica to C, ensuring the logic remains intact. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Write a version of this Mathematica function in C# with identical behavior. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Preserve the algorithm and functionality while converting the code from Mathematica to C#. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Convert the following code from Mathematica to C++, ensuring the logic remains intact. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Port the provided Mathematica code into C++ while preserving the original functionality. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Generate a Java translation of this Mathematica snippet without changing its computational steps. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Preserve the algorithm and functionality while converting the code from Mathematica to Java. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Convert this Mathematica block to Python, preserving its control flow and logic. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Maintain the same structure and functionality when rewriting this code in Python. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Change the following Mathematica code into VB without altering its purpose. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Translate the given Mathematica code snippet into VB without altering its behavior. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Change the programming language of this snippet from Mathematica to Go without modifying what it does. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Produce a functionally identical Go code for the snippet given in Mathematica. | Off[Power::indet];
Select[Range[5000], Total[IntegerDigits[#]^IntegerDigits[#]] == # &]
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Convert this Nim block to C, preserving its control flow and logic. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Port the following code from Nim to C with equivalent syntax and logic. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Can you help me rewrite this code in C# instead of Nim, keeping it the same logically? | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Write the same code in C# as shown below in Nim. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Write a version of this Nim function in C++ with identical behavior. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Port the following code from Nim to C++ with equivalent syntax and logic. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Convert the following code from Nim to Java, ensuring the logic remains intact. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Produce a functionally identical Java code for the snippet given in Nim. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Translate this program into Python but keep the logic exactly as in Nim. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Write a version of this Nim function in Python with identical behavior. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Transform the following Nim implementation into VB, maintaining the same output and logic. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Port the following code from Nim to VB with equivalent syntax and logic. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Rewrite this program in Go while keeping its functionality equivalent to the Nim version. | import math
for i in 1..<5000:
var sum: int64 = 0
var number = i
while number > 0:
var digit = number mod 10
sum += digit ^ digit
number = number div 10
if sum == i:
echo i
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Port the following code from OCaml to C with equivalent syntax and logic. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Please provide an equivalent version of this OCaml code in C. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Please provide an equivalent version of this OCaml code in C#. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Rewrite this program in C# while keeping its functionality equivalent to the OCaml version. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Write the same code in C++ as shown below in OCaml. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Rewrite this program in C++ while keeping its functionality equivalent to the OCaml version. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Write the same code in Java as shown below in OCaml. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Write the same algorithm in Java as shown in this OCaml implementation. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Translate this program into Python but keep the logic exactly as in OCaml. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Keep all operations the same but rewrite the snippet in Python. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Produce a language-to-language conversion: from OCaml to VB, same semantics. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Generate an equivalent Go version of this OCaml code. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Please provide an equivalent version of this OCaml code in Go. | let is_munchausen n =
let pwr = [|1; 1; 4; 27; 256; 3125; 46656; 823543; 16777216; 387420489|] in
let rec aux x = if x < 10 then pwr.(x) else aux (x / 10) + pwr.(x mod 10) in
n = aux n
let () =
Seq.(ints 1 |> take 5000 |> filter is_munchausen |> iter (Printf.printf " %u"))
|> print_newline
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Convert this Pascal block to C, preserving its control flow and logic. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Convert this Pascal block to C, preserving its control flow and logic. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Port the following code from Pascal to C# with equivalent syntax and logic. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Convert this Pascal block to C#, preserving its control flow and logic. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Preserve the algorithm and functionality while converting the code from Pascal to C++. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Produce a functionally identical C++ code for the snippet given in Pascal. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Translate the given Pascal code snippet into Java without altering its behavior. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Maintain the same structure and functionality when rewriting this code in Java. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Generate an equivalent Python version of this Pascal code. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Port the following code from Pascal to Python with equivalent syntax and logic. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Convert the following code from Pascal to VB, ensuring the logic remains intact. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Convert this Pascal snippet to VB and keep its semantics consistent. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Maintain the same structure and functionality when rewriting this code in Go. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Port the following code from Pascal to Go with equivalent syntax and logic. |
uses
sysutils;
type
tdigit = byte;
const
base = 10;
maxDigits = base-1;
var
DgtPotDgt : array[0..base-1] of NativeUint;
cnt: NativeUint;
function CheckSameDigits(n1,n2:NativeUInt):boolean;
var
dgtCnt : array[0..Base-1] of NativeInt;
i : NativeUInt;
Begin
fillchar(dgtCnt,SizeOf(dgtCnt),#0);
repeat
i := n1;n1 := n1 div base;i := i-n1*base;inc(dgtCnt[i]);
i := n2;n2 := n2 div base;i := i-n2*base;dec(dgtCnt[i]);
until (n1=0) AND (n2= 0 );
result := true;
For i := 0 to Base-1 do
result := result AND (dgtCnt[i]=0);
end;
procedure Munch(number,DgtPowSum,minDigit:NativeUInt;digits:NativeInt);
var
i: NativeUint;
begin
inc(cnt);
number := number*base;
IF digits > 1 then
Begin
For i := minDigit to base-1 do
Munch(number+i,DgtPowSum+DgtPotDgt[i],i,digits-1);
end
else
For i := minDigit to base-1 do
IF (number+i)<= (DgtPowSum+DgtPotDgt[i]) then
IF CheckSameDigits(number+i,DgtPowSum+DgtPotDgt[i]) then
iF number+i>0 then
writeln(Format('%*d %.*d',
[maxDigits,DgtPowSum+DgtPotDgt[i],maxDigits,number+i]));
end;
procedure InitDgtPotDgt;
var
i,k,dgtpow: NativeUint;
Begin
DgtPotDgt[0]:= 0;
For i := 1 to Base-1 do
Begin
dgtpow := i;
For k := 2 to i do
dgtpow := dgtpow*i;
DgtPotDgt[i] := dgtpow;
end;
end;
begin
cnt := 0;
InitDgtPotDgt;
Munch(0,0,0,maxDigits);
writeln('Check Count ',cnt);
end.
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Translate the given Perl code snippet into C without altering its behavior. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Generate an equivalent C version of this Perl code. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Ensure the translated C# code behaves exactly like the original Perl snippet. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Rewrite this program in C# while keeping its functionality equivalent to the Perl version. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Translate this program into C++ but keep the logic exactly as in Perl. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Produce a language-to-language conversion: from Perl to C++, same semantics. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Generate an equivalent Java version of this Perl code. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Keep all operations the same but rewrite the snippet in Java. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| public class Main {
public static void main(String[] args) {
for(int i = 0 ; i <= 5000 ; i++ ){
int val = String.valueOf(i).chars().map(x -> (int) Math.pow( x-48 ,x-48)).sum();
if( i == val){
System.out.println( i + " (munchausen)");
}
}
}
}
|
Convert this Perl snippet to Python and keep its semantics consistent. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Produce a language-to-language conversion: from Perl to Python, same semantics. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| for i in range(5000):
if i == sum(int(x) ** int(x) for x in str(i)):
print(i)
|
Produce a functionally identical VB code for the snippet given in Perl. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Produce a functionally identical VB code for the snippet given in Perl. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| Option Explicit
Sub Main_Munchausen_numbers()
Dim i&
For i = 1 To 5000
If IsMunchausen(i) Then Debug.Print i & " is a munchausen number."
Next i
End Sub
Function IsMunchausen(Number As Long) As Boolean
Dim Digits, i As Byte, Tot As Long
Digits = Split(StrConv(Number, vbUnicode), Chr(0))
For i = 0 To UBound(Digits) - 1
Tot = (Digits(i) ^ Digits(i)) + Tot
Next i
IsMunchausen = (Tot = Number)
End Function
|
Preserve the algorithm and functionality while converting the code from Perl to Go. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Convert the following code from Perl to Go, ensuring the logic remains intact. | use List::Util "sum";
for my $n (1..5000) {
print "$n\n" if $n == sum( map { $_**$_ } split(//,$n) );
}
| package main
import(
"fmt"
"math"
)
var powers [10]int
func isMunchausen(n int) bool {
if n < 0 { return false }
n64 := int64(n)
nn := n64
var sum int64 = 0
for nn > 0 {
sum += int64(powers[nn % 10])
if sum > n64 { return false }
nn /= 10
}
return sum == n64
}
func main() {
for i := 1; i <= 9; i++ {
d := float64(i)
powers[i] = int(math.Pow(d, d))
}
fmt.Println("The Munchausen numbers between 0 and 500 million are:")
for i := 0; i <= 500000000; i++ {
if isMunchausen(i) { fmt.Printf("%d ", i) }
}
fmt.Println()
}
|
Write the same algorithm in C as shown in this COBOL implementation. | IDENTIFICATION DIVISION.
PROGRAM-ID. MUNCHAUSEN.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 VARIABLES.
03 CANDIDATE PIC 9(4).
03 DIGITS PIC 9 OCCURS 4 TIMES, REDEFINES CANDIDATE.
03 DIGIT PIC 9.
03 POWER-SUM PIC 9(5).
01 OUTPUT-LINE.
03 OUT-NUM PIC ZZZ9.
PROCEDURE DIVISION.
BEGIN.
PERFORM MUNCHAUSEN-TEST VARYING CANDIDATE FROM 1 BY 1
UNTIL CANDIDATE IS GREATER THAN 6000.
STOP RUN.
MUNCHAUSEN-TEST.
MOVE ZERO TO POWER-SUM.
MOVE 1 TO DIGIT.
INSPECT CANDIDATE TALLYING DIGIT FOR LEADING '0'.
PERFORM ADD-DIGIT-POWER VARYING DIGIT FROM DIGIT BY 1
UNTIL DIGIT IS GREATER THAN 4.
IF POWER-SUM IS EQUAL TO CANDIDATE,
MOVE CANDIDATE TO OUT-NUM,
DISPLAY OUTPUT-LINE.
ADD-DIGIT-POWER.
COMPUTE POWER-SUM =
POWER-SUM + DIGITS(DIGIT) ** DIGITS(DIGIT)
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Generate an equivalent C version of this COBOL code. | IDENTIFICATION DIVISION.
PROGRAM-ID. MUNCHAUSEN.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 VARIABLES.
03 CANDIDATE PIC 9(4).
03 DIGITS PIC 9 OCCURS 4 TIMES, REDEFINES CANDIDATE.
03 DIGIT PIC 9.
03 POWER-SUM PIC 9(5).
01 OUTPUT-LINE.
03 OUT-NUM PIC ZZZ9.
PROCEDURE DIVISION.
BEGIN.
PERFORM MUNCHAUSEN-TEST VARYING CANDIDATE FROM 1 BY 1
UNTIL CANDIDATE IS GREATER THAN 6000.
STOP RUN.
MUNCHAUSEN-TEST.
MOVE ZERO TO POWER-SUM.
MOVE 1 TO DIGIT.
INSPECT CANDIDATE TALLYING DIGIT FOR LEADING '0'.
PERFORM ADD-DIGIT-POWER VARYING DIGIT FROM DIGIT BY 1
UNTIL DIGIT IS GREATER THAN 4.
IF POWER-SUM IS EQUAL TO CANDIDATE,
MOVE CANDIDATE TO OUT-NUM,
DISPLAY OUTPUT-LINE.
ADD-DIGIT-POWER.
COMPUTE POWER-SUM =
POWER-SUM + DIGITS(DIGIT) ** DIGITS(DIGIT)
| #include <stdio.h>
#include <math.h>
int main() {
for (int i = 1; i < 5000; i++) {
int sum = 0;
for (int number = i; number > 0; number /= 10) {
int digit = number % 10;
sum += pow(digit, digit);
}
if (sum == i) {
printf("%i\n", i);
}
}
return 0;
}
|
Generate a C# translation of this COBOL snippet without changing its computational steps. | IDENTIFICATION DIVISION.
PROGRAM-ID. MUNCHAUSEN.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 VARIABLES.
03 CANDIDATE PIC 9(4).
03 DIGITS PIC 9 OCCURS 4 TIMES, REDEFINES CANDIDATE.
03 DIGIT PIC 9.
03 POWER-SUM PIC 9(5).
01 OUTPUT-LINE.
03 OUT-NUM PIC ZZZ9.
PROCEDURE DIVISION.
BEGIN.
PERFORM MUNCHAUSEN-TEST VARYING CANDIDATE FROM 1 BY 1
UNTIL CANDIDATE IS GREATER THAN 6000.
STOP RUN.
MUNCHAUSEN-TEST.
MOVE ZERO TO POWER-SUM.
MOVE 1 TO DIGIT.
INSPECT CANDIDATE TALLYING DIGIT FOR LEADING '0'.
PERFORM ADD-DIGIT-POWER VARYING DIGIT FROM DIGIT BY 1
UNTIL DIGIT IS GREATER THAN 4.
IF POWER-SUM IS EQUAL TO CANDIDATE,
MOVE CANDIDATE TO OUT-NUM,
DISPLAY OUTPUT-LINE.
ADD-DIGIT-POWER.
COMPUTE POWER-SUM =
POWER-SUM + DIGITS(DIGIT) ** DIGITS(DIGIT)
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Can you help me rewrite this code in C# instead of COBOL, keeping it the same logically? | IDENTIFICATION DIVISION.
PROGRAM-ID. MUNCHAUSEN.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 VARIABLES.
03 CANDIDATE PIC 9(4).
03 DIGITS PIC 9 OCCURS 4 TIMES, REDEFINES CANDIDATE.
03 DIGIT PIC 9.
03 POWER-SUM PIC 9(5).
01 OUTPUT-LINE.
03 OUT-NUM PIC ZZZ9.
PROCEDURE DIVISION.
BEGIN.
PERFORM MUNCHAUSEN-TEST VARYING CANDIDATE FROM 1 BY 1
UNTIL CANDIDATE IS GREATER THAN 6000.
STOP RUN.
MUNCHAUSEN-TEST.
MOVE ZERO TO POWER-SUM.
MOVE 1 TO DIGIT.
INSPECT CANDIDATE TALLYING DIGIT FOR LEADING '0'.
PERFORM ADD-DIGIT-POWER VARYING DIGIT FROM DIGIT BY 1
UNTIL DIGIT IS GREATER THAN 4.
IF POWER-SUM IS EQUAL TO CANDIDATE,
MOVE CANDIDATE TO OUT-NUM,
DISPLAY OUTPUT-LINE.
ADD-DIGIT-POWER.
COMPUTE POWER-SUM =
POWER-SUM + DIGITS(DIGIT) ** DIGITS(DIGIT)
| Func<char, int> toInt = c => c-'0';
foreach (var i in Enumerable.Range(1,5000)
.Where(n => n == n.ToString()
.Sum(x => Math.Pow(toInt(x), toInt(x)))))
Console.WriteLine(i);
|
Maintain the same structure and functionality when rewriting this code in C++. | IDENTIFICATION DIVISION.
PROGRAM-ID. MUNCHAUSEN.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 VARIABLES.
03 CANDIDATE PIC 9(4).
03 DIGITS PIC 9 OCCURS 4 TIMES, REDEFINES CANDIDATE.
03 DIGIT PIC 9.
03 POWER-SUM PIC 9(5).
01 OUTPUT-LINE.
03 OUT-NUM PIC ZZZ9.
PROCEDURE DIVISION.
BEGIN.
PERFORM MUNCHAUSEN-TEST VARYING CANDIDATE FROM 1 BY 1
UNTIL CANDIDATE IS GREATER THAN 6000.
STOP RUN.
MUNCHAUSEN-TEST.
MOVE ZERO TO POWER-SUM.
MOVE 1 TO DIGIT.
INSPECT CANDIDATE TALLYING DIGIT FOR LEADING '0'.
PERFORM ADD-DIGIT-POWER VARYING DIGIT FROM DIGIT BY 1
UNTIL DIGIT IS GREATER THAN 4.
IF POWER-SUM IS EQUAL TO CANDIDATE,
MOVE CANDIDATE TO OUT-NUM,
DISPLAY OUTPUT-LINE.
ADD-DIGIT-POWER.
COMPUTE POWER-SUM =
POWER-SUM + DIGITS(DIGIT) ** DIGITS(DIGIT)
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
Convert this COBOL block to C++, preserving its control flow and logic. | IDENTIFICATION DIVISION.
PROGRAM-ID. MUNCHAUSEN.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 VARIABLES.
03 CANDIDATE PIC 9(4).
03 DIGITS PIC 9 OCCURS 4 TIMES, REDEFINES CANDIDATE.
03 DIGIT PIC 9.
03 POWER-SUM PIC 9(5).
01 OUTPUT-LINE.
03 OUT-NUM PIC ZZZ9.
PROCEDURE DIVISION.
BEGIN.
PERFORM MUNCHAUSEN-TEST VARYING CANDIDATE FROM 1 BY 1
UNTIL CANDIDATE IS GREATER THAN 6000.
STOP RUN.
MUNCHAUSEN-TEST.
MOVE ZERO TO POWER-SUM.
MOVE 1 TO DIGIT.
INSPECT CANDIDATE TALLYING DIGIT FOR LEADING '0'.
PERFORM ADD-DIGIT-POWER VARYING DIGIT FROM DIGIT BY 1
UNTIL DIGIT IS GREATER THAN 4.
IF POWER-SUM IS EQUAL TO CANDIDATE,
MOVE CANDIDATE TO OUT-NUM,
DISPLAY OUTPUT-LINE.
ADD-DIGIT-POWER.
COMPUTE POWER-SUM =
POWER-SUM + DIGITS(DIGIT) ** DIGITS(DIGIT)
| #include <math.h>
#include <iostream>
unsigned pwr[10];
unsigned munch( unsigned i ) {
unsigned sum = 0;
while( i ) {
sum += pwr[(i % 10)];
i /= 10;
}
return sum;
}
int main( int argc, char* argv[] ) {
for( int i = 0; i < 10; i++ )
pwr[i] = (unsigned)pow( (float)i, (float)i );
std::cout << "Munchausen Numbers\n==================\n";
for( unsigned i = 1; i < 5000; i++ )
if( i == munch( i ) ) std::cout << i << "\n";
return 0;
}
|
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