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Rewrite this program in Python while keeping its functionality equivalent to the Erlang version.
-module(haversine). -export([main/0]). main() -> haversine(36.12, -86.67, 33.94, -118.40). haversine(Lat1, Long1, Lat2, Long2) -> V = math:pi()/180, R = 6372.8, Diff_Lat = (Lat2 - Lat1)*V , Diff_Long = (Long2 - Long1)*V, NLat = Lat1*V, NLong = Lat2*V, A = math:sin(Diff_Lat/2) * math:sin(Diff_Lat/2) + math:sin(Diff_Long/2) * math:sin(Diff_Long/2) * math:cos(NLat) * math:cos(NLong), C = 2 * math:asin(math:sqrt(A)), R*C.
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Generate a Python translation of this Erlang snippet without changing its computational steps.
-module(haversine). -export([main/0]). main() -> haversine(36.12, -86.67, 33.94, -118.40). haversine(Lat1, Long1, Lat2, Long2) -> V = math:pi()/180, R = 6372.8, Diff_Lat = (Lat2 - Lat1)*V , Diff_Long = (Long2 - Long1)*V, NLat = Lat1*V, NLong = Lat2*V, A = math:sin(Diff_Lat/2) * math:sin(Diff_Lat/2) + math:sin(Diff_Long/2) * math:sin(Diff_Long/2) * math:cos(NLat) * math:cos(NLong), C = 2 * math:asin(math:sqrt(A)), R*C.
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Port the provided Erlang code into VB while preserving the original functionality.
-module(haversine). -export([main/0]). main() -> haversine(36.12, -86.67, 33.94, -118.40). haversine(Lat1, Long1, Lat2, Long2) -> V = math:pi()/180, R = 6372.8, Diff_Lat = (Lat2 - Lat1)*V , Diff_Long = (Long2 - Long1)*V, NLat = Lat1*V, NLong = Lat2*V, A = math:sin(Diff_Lat/2) * math:sin(Diff_Lat/2) + math:sin(Diff_Long/2) * math:sin(Diff_Long/2) * math:cos(NLat) * math:cos(NLong), C = 2 * math:asin(math:sqrt(A)), R*C.
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Ensure the translated VB code behaves exactly like the original Erlang snippet.
-module(haversine). -export([main/0]). main() -> haversine(36.12, -86.67, 33.94, -118.40). haversine(Lat1, Long1, Lat2, Long2) -> V = math:pi()/180, R = 6372.8, Diff_Lat = (Lat2 - Lat1)*V , Diff_Long = (Long2 - Long1)*V, NLat = Lat1*V, NLong = Lat2*V, A = math:sin(Diff_Lat/2) * math:sin(Diff_Lat/2) + math:sin(Diff_Long/2) * math:sin(Diff_Long/2) * math:cos(NLat) * math:cos(NLong), C = 2 * math:asin(math:sqrt(A)), R*C.
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Ensure the translated Go code behaves exactly like the original Erlang snippet.
-module(haversine). -export([main/0]). main() -> haversine(36.12, -86.67, 33.94, -118.40). haversine(Lat1, Long1, Lat2, Long2) -> V = math:pi()/180, R = 6372.8, Diff_Lat = (Lat2 - Lat1)*V , Diff_Long = (Long2 - Long1)*V, NLat = Lat1*V, NLong = Lat2*V, A = math:sin(Diff_Lat/2) * math:sin(Diff_Lat/2) + math:sin(Diff_Long/2) * math:sin(Diff_Long/2) * math:cos(NLat) * math:cos(NLong), C = 2 * math:asin(math:sqrt(A)), R*C.
package main import ( "fmt" "math" ) func haversine(θ float64) float64 { return .5 * (1 - math.Cos(θ)) } type pos struct { φ float64 ψ float64 } func degPos(lat, lon float64) pos { return pos{lat * math.Pi / 180, lon * math.Pi / 180} } const rEarth = 6372.8 func hsDist(p1, p2 pos) float64 { return 2 * rEarth * math.Asin(math.Sqrt(haversine(p2.φ-p1.φ)+ math.Cos(p1.φ)*math.Cos(p2.φ)*haversine(p2.ψ-p1.ψ))) } func main() { fmt.Println(hsDist(degPos(36.12, -86.67), degPos(33.94, -118.40))) }
Change the programming language of this snippet from F# to C without modifying what it does.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Keep all operations the same but rewrite the snippet in C.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Rewrite the snippet below in C# so it works the same as the original F# code.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Translate this program into C# but keep the logic exactly as in F#.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Convert this F# block to C++, preserving its control flow and logic.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Port the provided F# code into C++ while preserving the original functionality.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Transform the following F# implementation into Java, maintaining the same output and logic.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Please provide an equivalent version of this F# code in Java.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Generate an equivalent Python version of this F# code.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Ensure the translated Python code behaves exactly like the original F# snippet.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Generate a VB translation of this F# snippet without changing its computational steps.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Produce a functionally identical VB code for the snippet given in F#.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Convert the following code from F# to Go, ensuring the logic remains intact.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
package main import ( "fmt" "math" ) func haversine(θ float64) float64 { return .5 * (1 - math.Cos(θ)) } type pos struct { φ float64 ψ float64 } func degPos(lat, lon float64) pos { return pos{lat * math.Pi / 180, lon * math.Pi / 180} } const rEarth = 6372.8 func hsDist(p1, p2 pos) float64 { return 2 * rEarth * math.Asin(math.Sqrt(haversine(p2.φ-p1.φ)+ math.Cos(p1.φ)*math.Cos(p2.φ)*haversine(p2.ψ-p1.ψ))) } func main() { fmt.Println(hsDist(degPos(36.12, -86.67), degPos(33.94, -118.40))) }
Convert this F# block to Go, preserving its control flow and logic.
open System [<Measure>] type deg [<Measure>] type rad [<Measure>] type km let haversine (θ: float<rad>) = 0.5 * (1.0 - Math.Cos(θ/1.0<rad>)) let radPerDeg = (Math.PI / 180.0) * 1.0<rad/deg> type pos(latitude: float<deg>, longitude: float<deg>) = member this.φ = latitude * radPerDeg member this.ψ = longitude * radPerDeg let rEarth = 6372.8<km> let hsDist (p1: pos) (p2: pos) = 2.0 * rEarth * Math.Asin(Math.Sqrt(haversine(p2.φ - p1.φ)+ Math.Cos(p1.φ/1.0<rad>)*Math.Cos(p2.φ/1.0<rad>)*haversine(p2.ψ - p1.ψ))) [<EntryPoint>] let main argv = printfn "%A" (hsDist (pos(36.12<deg>, -86.67<deg>)) (pos(33.94<deg>, -118.40<deg>))) 0
package main import ( "fmt" "math" ) func haversine(θ float64) float64 { return .5 * (1 - math.Cos(θ)) } type pos struct { φ float64 ψ float64 } func degPos(lat, lon float64) pos { return pos{lat * math.Pi / 180, lon * math.Pi / 180} } const rEarth = 6372.8 func hsDist(p1, p2 pos) float64 { return 2 * rEarth * math.Asin(math.Sqrt(haversine(p2.φ-p1.φ)+ math.Cos(p1.φ)*math.Cos(p2.φ)*haversine(p2.ψ-p1.ψ))) } func main() { fmt.Println(hsDist(degPos(36.12, -86.67), degPos(33.94, -118.40))) }
Can you help me rewrite this code in C instead of Factor, keeping it the same logically?
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Can you help me rewrite this code in C instead of Factor, keeping it the same logically?
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Ensure the translated C# code behaves exactly like the original Factor snippet.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Convert the following code from Factor to C#, ensuring the logic remains intact.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Preserve the algorithm and functionality while converting the code from Factor to C++.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Rewrite the snippet below in C++ so it works the same as the original Factor code.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Translate the given Factor code snippet into Java without altering its behavior.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Convert the following code from Factor to Java, ensuring the logic remains intact.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Translate the given Factor code snippet into Python without altering its behavior.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Rewrite the snippet below in Python so it works the same as the original Factor code.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Rewrite this program in VB while keeping its functionality equivalent to the Factor version.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Convert this Factor snippet to VB and keep its semantics consistent.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Keep all operations the same but rewrite the snippet in Go.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
package main import ( "fmt" "math" ) func haversine(θ float64) float64 { return .5 * (1 - math.Cos(θ)) } type pos struct { φ float64 ψ float64 } func degPos(lat, lon float64) pos { return pos{lat * math.Pi / 180, lon * math.Pi / 180} } const rEarth = 6372.8 func hsDist(p1, p2 pos) float64 { return 2 * rEarth * math.Asin(math.Sqrt(haversine(p2.φ-p1.φ)+ math.Cos(p1.φ)*math.Cos(p2.φ)*haversine(p2.ψ-p1.ψ))) } func main() { fmt.Println(hsDist(degPos(36.12, -86.67), degPos(33.94, -118.40))) }
Write a version of this Factor function in Go with identical behavior.
USING: arrays kernel math math.constants math.functions math.vectors sequences ; : haversin ( x -- y ) cos 1 swap - 2 / ; : haversininv ( y -- x ) 2 * 1 swap - acos ; : haversineDist ( as bs -- d ) [ [ 180 / pi * ] map ] bi@ [ [ swap - haversin ] 2map ] [ [ first cos ] bi@ * 1 swap 2array ] 2bi v. haversininv R_earth * ;
package main import ( "fmt" "math" ) func haversine(θ float64) float64 { return .5 * (1 - math.Cos(θ)) } type pos struct { φ float64 ψ float64 } func degPos(lat, lon float64) pos { return pos{lat * math.Pi / 180, lon * math.Pi / 180} } const rEarth = 6372.8 func hsDist(p1, p2 pos) float64 { return 2 * rEarth * math.Asin(math.Sqrt(haversine(p2.φ-p1.φ)+ math.Cos(p1.φ)*math.Cos(p2.φ)*haversine(p2.ψ-p1.ψ))) } func main() { fmt.Println(hsDist(degPos(36.12, -86.67), degPos(33.94, -118.40))) }
Port the provided Forth code into C while preserving the original functionality.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Ensure the translated C code behaves exactly like the original Forth snippet.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Ensure the translated C# code behaves exactly like the original Forth snippet.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Can you help me rewrite this code in C# instead of Forth, keeping it the same logically?
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Please provide an equivalent version of this Forth code in C++.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Generate an equivalent C++ version of this Forth code.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Please provide an equivalent version of this Forth code in Java.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Keep all operations the same but rewrite the snippet in Java.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Convert this Forth snippet to Python and keep its semantics consistent.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Keep all operations the same but rewrite the snippet in Python.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Generate a VB translation of this Forth snippet without changing its computational steps.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Translate this program into VB but keep the logic exactly as in Forth.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Rewrite the snippet below in Go so it works the same as the original Forth code.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
package main import ( "fmt" "math" ) func haversine(θ float64) float64 { return .5 * (1 - math.Cos(θ)) } type pos struct { φ float64 ψ float64 } func degPos(lat, lon float64) pos { return pos{lat * math.Pi / 180, lon * math.Pi / 180} } const rEarth = 6372.8 func hsDist(p1, p2 pos) float64 { return 2 * rEarth * math.Asin(math.Sqrt(haversine(p2.φ-p1.φ)+ math.Cos(p1.φ)*math.Cos(p2.φ)*haversine(p2.ψ-p1.ψ))) } func main() { fmt.Println(hsDist(degPos(36.12, -86.67), degPos(33.94, -118.40))) }
Generate an equivalent Go version of this Forth code.
: s>f s>d d>f ; : deg>rad 174532925199433e-16 f* ; : difference f- deg>rad 2 s>f f/ fsin fdup f* ; : haversine frot difference frot frot fover fover fswap difference fswap deg>rad fcos frot deg>rad fcos f* frot f* f+ fsqrt fasin 127456 s>f f* 10 s>f f/ ; 36.12e -86.67e 33.94e -118.40e haversine cr f.
package main import ( "fmt" "math" ) func haversine(θ float64) float64 { return .5 * (1 - math.Cos(θ)) } type pos struct { φ float64 ψ float64 } func degPos(lat, lon float64) pos { return pos{lat * math.Pi / 180, lon * math.Pi / 180} } const rEarth = 6372.8 func hsDist(p1, p2 pos) float64 { return 2 * rEarth * math.Asin(math.Sqrt(haversine(p2.φ-p1.φ)+ math.Cos(p1.φ)*math.Cos(p2.φ)*haversine(p2.ψ-p1.ψ))) } func main() { fmt.Println(hsDist(degPos(36.12, -86.67), degPos(33.94, -118.40))) }
Translate this program into C# but keep the logic exactly as in Fortran.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Write a version of this Fortran function in C# with identical behavior.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Rewrite this program in C++ while keeping its functionality equivalent to the Fortran version.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Maintain the same structure and functionality when rewriting this code in C++.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Translate the given Fortran code snippet into C without altering its behavior.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Can you help me rewrite this code in C instead of Fortran, keeping it the same logically?
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Write a version of this Fortran function in Java with identical behavior.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Translate this program into Java but keep the logic exactly as in Fortran.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Ensure the translated Python code behaves exactly like the original Fortran snippet.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Transform the following Fortran implementation into Python, maintaining the same output and logic.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Write the same code in VB as shown below in Fortran.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Transform the following Fortran implementation into VB, maintaining the same output and logic.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Produce a functionally identical PHP code for the snippet given in Fortran.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
class POI { private $latitude; private $longitude; public function __construct($latitude, $longitude) { $this->latitude = deg2rad($latitude); $this->longitude = deg2rad($longitude); } public function getLatitude() { return $this->latitude; } public function getLongitude() { return $this->longitude; } public function getDistanceInMetersTo(POI $other) { $radiusOfEarth = 6371; // Earth's radius in kilometers. $diffLatitude = $other->getLatitude() - $this->latitude; $diffLongitude = $other->getLongitude() - $this->longitude; $a = sin($diffLatitude / 2) ** 2 + cos($this->latitude) * cos($other->getLatitude()) * sin($diffLongitude / 2) ** 2; $c = 2 * asin(sqrt($a)); $distance = $radiusOfEarth * $c; return $distance; } }
Convert the following code from Fortran to PHP, ensuring the logic remains intact.
program example implicit none real :: d d = haversine(36.12,-86.67,33.94,-118.40) print '(A,F9.4,A)', 'distance: ',d,' km' contains function to_radian(degree) result(rad) real,intent(in) :: degree real, parameter :: deg_to_rad = atan(1.0)/45 real :: rad rad = degree*deg_to_rad end function to_radian function haversine(deglat1,deglon1,deglat2,deglon2) result (dist) real,intent(in) :: deglat1,deglon1,deglat2,deglon2 real :: a,c,dist,dlat,dlon,lat1,lat2 real,parameter :: radius = 6372.8 dlat = to_radian(deglat2-deglat1) dlon = to_radian(deglon2-deglon1) lat1 = to_radian(deglat1) lat2 = to_radian(deglat2) a = (sin(dlat/2))**2 + cos(lat1)*cos(lat2)*(sin(dlon/2))**2 c = 2*asin(sqrt(a)) dist = radius*c end function haversine end program example
class POI { private $latitude; private $longitude; public function __construct($latitude, $longitude) { $this->latitude = deg2rad($latitude); $this->longitude = deg2rad($longitude); } public function getLatitude() { return $this->latitude; } public function getLongitude() { return $this->longitude; } public function getDistanceInMetersTo(POI $other) { $radiusOfEarth = 6371; // Earth's radius in kilometers. $diffLatitude = $other->getLatitude() - $this->latitude; $diffLongitude = $other->getLongitude() - $this->longitude; $a = sin($diffLatitude / 2) ** 2 + cos($this->latitude) * cos($other->getLatitude()) * sin($diffLongitude / 2) ** 2; $c = 2 * asin(sqrt($a)); $distance = $radiusOfEarth * $c; return $distance; } }
Change the following Groovy code into C without altering its purpose.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Preserve the algorithm and functionality while converting the code from Groovy to C.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Rewrite this program in C# while keeping its functionality equivalent to the Groovy version.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Write the same algorithm in C# as shown in this Groovy implementation.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Generate a C++ translation of this Groovy snippet without changing its computational steps.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Transform the following Groovy implementation into C++, maintaining the same output and logic.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Preserve the algorithm and functionality while converting the code from Groovy to Java.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Transform the following Groovy implementation into Java, maintaining the same output and logic.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Convert this Groovy block to Python, preserving its control flow and logic.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Write a version of this Groovy function in Python with identical behavior.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Generate a VB translation of this Groovy snippet without changing its computational steps.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Rewrite this program in VB while keeping its functionality equivalent to the Groovy version.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Keep all operations the same but rewrite the snippet in Go.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
package main import ( "fmt" "math" ) func haversine(θ float64) float64 { return .5 * (1 - math.Cos(θ)) } type pos struct { φ float64 ψ float64 } func degPos(lat, lon float64) pos { return pos{lat * math.Pi / 180, lon * math.Pi / 180} } const rEarth = 6372.8 func hsDist(p1, p2 pos) float64 { return 2 * rEarth * math.Asin(math.Sqrt(haversine(p2.φ-p1.φ)+ math.Cos(p1.φ)*math.Cos(p2.φ)*haversine(p2.ψ-p1.ψ))) } func main() { fmt.Println(hsDist(degPos(36.12, -86.67), degPos(33.94, -118.40))) }
Transform the following Groovy implementation into Go, maintaining the same output and logic.
def haversine(lat1, lon1, lat2, lon2) { def R = 6372.8 def dLat = Math.toRadians(lat2 - lat1) def dLon = Math.toRadians(lon2 - lon1) lat1 = Math.toRadians(lat1) lat2 = Math.toRadians(lat2) def a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2) * Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2) def c = 2 * Math.asin(Math.sqrt(a)) R * c } haversine(36.12, -86.67, 33.94, -118.40) > 2887.25995060711
package main import ( "fmt" "math" ) func haversine(θ float64) float64 { return .5 * (1 - math.Cos(θ)) } type pos struct { φ float64 ψ float64 } func degPos(lat, lon float64) pos { return pos{lat * math.Pi / 180, lon * math.Pi / 180} } const rEarth = 6372.8 func hsDist(p1, p2 pos) float64 { return 2 * rEarth * math.Asin(math.Sqrt(haversine(p2.φ-p1.φ)+ math.Cos(p1.φ)*math.Cos(p2.φ)*haversine(p2.ψ-p1.ψ))) } func main() { fmt.Println(hsDist(degPos(36.12, -86.67), degPos(33.94, -118.40))) }
Rewrite the snippet below in C so it works the same as the original Haskell code.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Translate this program into C but keep the logic exactly as in Haskell.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Preserve the algorithm and functionality while converting the code from Haskell to C#.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Rewrite this program in C# while keeping its functionality equivalent to the Haskell version.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Ensure the translated C++ code behaves exactly like the original Haskell snippet.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Change the following Haskell code into C++ without altering its purpose.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Produce a language-to-language conversion: from Haskell to Java, same semantics.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Convert the following code from Haskell to Java, ensuring the logic remains intact.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Produce a language-to-language conversion: from Haskell to Python, same semantics.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Rewrite the snippet below in Python so it works the same as the original Haskell code.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Keep all operations the same but rewrite the snippet in VB.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Produce a language-to-language conversion: from Haskell to VB, same semantics.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub
Transform the following Haskell implementation into Go, maintaining the same output and logic.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
package main import ( "fmt" "math" ) func haversine(θ float64) float64 { return .5 * (1 - math.Cos(θ)) } type pos struct { φ float64 ψ float64 } func degPos(lat, lon float64) pos { return pos{lat * math.Pi / 180, lon * math.Pi / 180} } const rEarth = 6372.8 func hsDist(p1, p2 pos) float64 { return 2 * rEarth * math.Asin(math.Sqrt(haversine(p2.φ-p1.φ)+ math.Cos(p1.φ)*math.Cos(p2.φ)*haversine(p2.ψ-p1.ψ))) } func main() { fmt.Println(hsDist(degPos(36.12, -86.67), degPos(33.94, -118.40))) }
Translate the given Haskell code snippet into Go without altering its behavior.
import Control.Monad (join) import Data.Bifunctor (bimap) import Text.Printf (printf) haversine :: Float -> Float haversine = (^ 2) . sin . (/ 2) greatCircleDistance :: (Float, Float) -> (Float, Float) -> Float greatCircleDistance = distDeg 6371 where distDeg radius p1 p2 = distRad radius (deg2rad p1) (deg2rad p2) distRad radius (lat1, lng1) (lat2, lng2) = (2 * radius) * asin ( min 1.0 ( sqrt $ haversine (lat2 - lat1) + ( (cos lat1 * cos lat2) * haversine (lng2 - lng1) ) ) ) deg2rad = join bimap ((/ 180) . (pi *)) main :: IO () main = printf "The distance between BNA and LAX is about %0.f km.\n" (greatCircleDistance bna lax) where bna = (36.12, -86.67) lax = (33.94, -118.40)
package main import ( "fmt" "math" ) func haversine(θ float64) float64 { return .5 * (1 - math.Cos(θ)) } type pos struct { φ float64 ψ float64 } func degPos(lat, lon float64) pos { return pos{lat * math.Pi / 180, lon * math.Pi / 180} } const rEarth = 6372.8 func hsDist(p1, p2 pos) float64 { return 2 * rEarth * math.Asin(math.Sqrt(haversine(p2.φ-p1.φ)+ math.Cos(p1.φ)*math.Cos(p2.φ)*haversine(p2.ψ-p1.ψ))) } func main() { fmt.Println(hsDist(degPos(36.12, -86.67), degPos(33.94, -118.40))) }
Produce a language-to-language conversion: from Icon to C, same semantics.
link printf procedure main() printf("BNA to LAX is %d km (%d miles)\n", d := gcdistance([36.12, -86.67],[33.94, -118.40]),d*3280/5280) end procedure gcdistance(a,b) a[2] -:= b[2] every (x := a|b)[i := 1 to 2] := dtor(x[i]) dz := sin(a[1]) - sin(b[1]) dx := cos(a[2]) * cos(a[1]) - cos(b[1]) dy := sin(a[2]) * cos(a[1]) return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * 6371 end
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Translate the given Icon code snippet into C without altering its behavior.
link printf procedure main() printf("BNA to LAX is %d km (%d miles)\n", d := gcdistance([36.12, -86.67],[33.94, -118.40]),d*3280/5280) end procedure gcdistance(a,b) a[2] -:= b[2] every (x := a|b)[i := 1 to 2] := dtor(x[i]) dz := sin(a[1]) - sin(b[1]) dx := cos(a[2]) * cos(a[1]) - cos(b[1]) dy := sin(a[2]) * cos(a[1]) return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * 6371 end
#include <stdio.h> #include <stdlib.h> #include <math.h> #define R 6371 #define TO_RAD (3.1415926536 / 180) double dist(double th1, double ph1, double th2, double ph2) { double dx, dy, dz; ph1 -= ph2; ph1 *= TO_RAD, th1 *= TO_RAD, th2 *= TO_RAD; dz = sin(th1) - sin(th2); dx = cos(ph1) * cos(th1) - cos(th2); dy = sin(ph1) * cos(th1); return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * R; } int main() { double d = dist(36.12, -86.67, 33.94, -118.4); printf("dist: %.1f km (%.1f mi.)\n", d, d / 1.609344); return 0; }
Please provide an equivalent version of this Icon code in C#.
link printf procedure main() printf("BNA to LAX is %d km (%d miles)\n", d := gcdistance([36.12, -86.67],[33.94, -118.40]),d*3280/5280) end procedure gcdistance(a,b) a[2] -:= b[2] every (x := a|b)[i := 1 to 2] := dtor(x[i]) dz := sin(a[1]) - sin(b[1]) dx := cos(a[2]) * cos(a[1]) - cos(b[1]) dy := sin(a[2]) * cos(a[1]) return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * 6371 end
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Port the provided Icon code into C# while preserving the original functionality.
link printf procedure main() printf("BNA to LAX is %d km (%d miles)\n", d := gcdistance([36.12, -86.67],[33.94, -118.40]),d*3280/5280) end procedure gcdistance(a,b) a[2] -:= b[2] every (x := a|b)[i := 1 to 2] := dtor(x[i]) dz := sin(a[1]) - sin(b[1]) dx := cos(a[2]) * cos(a[1]) - cos(b[1]) dy := sin(a[2]) * cos(a[1]) return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * 6371 end
public static class Haversine { public static double calculate(double lat1, double lon1, double lat2, double lon2) { var R = 6372.8; var dLat = toRadians(lat2 - lat1); var dLon = toRadians(lon2 - lon1); lat1 = toRadians(lat1); lat2 = toRadians(lat2); var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2); var c = 2 * Math.Asin(Math.Sqrt(a)); return R * 2 * Math.Asin(Math.Sqrt(a)); } public static double toRadians(double angle) { return Math.PI * angle / 180.0; } } void Main() { Console.WriteLine(String.Format("The distance between coordinates {0},{1} and {2},{3} is: {4}", 36.12, -86.67, 33.94, -118.40, Haversine.calculate(36.12, -86.67, 33.94, -118.40))); }
Convert this Icon block to C++, preserving its control flow and logic.
link printf procedure main() printf("BNA to LAX is %d km (%d miles)\n", d := gcdistance([36.12, -86.67],[33.94, -118.40]),d*3280/5280) end procedure gcdistance(a,b) a[2] -:= b[2] every (x := a|b)[i := 1 to 2] := dtor(x[i]) dz := sin(a[1]) - sin(b[1]) dx := cos(a[2]) * cos(a[1]) - cos(b[1]) dy := sin(a[2]) * cos(a[1]) return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * 6371 end
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Maintain the same structure and functionality when rewriting this code in C++.
link printf procedure main() printf("BNA to LAX is %d km (%d miles)\n", d := gcdistance([36.12, -86.67],[33.94, -118.40]),d*3280/5280) end procedure gcdistance(a,b) a[2] -:= b[2] every (x := a|b)[i := 1 to 2] := dtor(x[i]) dz := sin(a[1]) - sin(b[1]) dx := cos(a[2]) * cos(a[1]) - cos(b[1]) dy := sin(a[2]) * cos(a[1]) return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * 6371 end
#define _USE_MATH_DEFINES #include <math.h> #include <iostream> const static double EarthRadiusKm = 6372.8; inline double DegreeToRadian(double angle) { return M_PI * angle / 180.0; } class Coordinate { public: Coordinate(double latitude ,double longitude):myLatitude(latitude), myLongitude(longitude) {} double Latitude() const { return myLatitude; } double Longitude() const { return myLongitude; } private: double myLatitude; double myLongitude; }; double HaversineDistance(const Coordinate& p1, const Coordinate& p2) { double latRad1 = DegreeToRadian(p1.Latitude()); double latRad2 = DegreeToRadian(p2.Latitude()); double lonRad1 = DegreeToRadian(p1.Longitude()); double lonRad2 = DegreeToRadian(p2.Longitude()); double diffLa = latRad2 - latRad1; double doffLo = lonRad2 - lonRad1; double computation = asin(sqrt(sin(diffLa / 2) * sin(diffLa / 2) + cos(latRad1) * cos(latRad2) * sin(doffLo / 2) * sin(doffLo / 2))); return 2 * EarthRadiusKm * computation; } int main() { Coordinate c1(36.12, -86.67); Coordinate c2(33.94, -118.4); std::cout << "Distance = " << HaversineDistance(c1, c2) << std::endl; return 0; }
Rewrite the snippet below in Java so it works the same as the original Icon code.
link printf procedure main() printf("BNA to LAX is %d km (%d miles)\n", d := gcdistance([36.12, -86.67],[33.94, -118.40]),d*3280/5280) end procedure gcdistance(a,b) a[2] -:= b[2] every (x := a|b)[i := 1 to 2] := dtor(x[i]) dz := sin(a[1]) - sin(b[1]) dx := cos(a[2]) * cos(a[1]) - cos(b[1]) dy := sin(a[2]) * cos(a[1]) return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * 6371 end
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Port the provided Icon code into Java while preserving the original functionality.
link printf procedure main() printf("BNA to LAX is %d km (%d miles)\n", d := gcdistance([36.12, -86.67],[33.94, -118.40]),d*3280/5280) end procedure gcdistance(a,b) a[2] -:= b[2] every (x := a|b)[i := 1 to 2] := dtor(x[i]) dz := sin(a[1]) - sin(b[1]) dx := cos(a[2]) * cos(a[1]) - cos(b[1]) dy := sin(a[2]) * cos(a[1]) return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * 6371 end
public class Haversine { public static final double R = 6372.8; public static double haversine(double lat1, double lon1, double lat2, double lon2) { lat1 = Math.toRadians(lat1); lat2 = Math.toRadians(lat2); double dLat = lat2 - lat1; double dLon = Math.toRadians(lon2 - lon1); double a = Math.pow(Math.sin(dLat / 2), 2) + Math.pow(Math.sin(dLon / 2), 2) * Math.cos(lat1) * Math.cos(lat2); double c = 2 * Math.asin(Math.sqrt(a)); return R * c; } public static void main(String[] args) { System.out.println(haversine(36.12, -86.67, 33.94, -118.40)); } }
Preserve the algorithm and functionality while converting the code from Icon to Python.
link printf procedure main() printf("BNA to LAX is %d km (%d miles)\n", d := gcdistance([36.12, -86.67],[33.94, -118.40]),d*3280/5280) end procedure gcdistance(a,b) a[2] -:= b[2] every (x := a|b)[i := 1 to 2] := dtor(x[i]) dz := sin(a[1]) - sin(b[1]) dx := cos(a[2]) * cos(a[1]) - cos(b[1]) dy := sin(a[2]) * cos(a[1]) return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * 6371 end
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Write the same algorithm in Python as shown in this Icon implementation.
link printf procedure main() printf("BNA to LAX is %d km (%d miles)\n", d := gcdistance([36.12, -86.67],[33.94, -118.40]),d*3280/5280) end procedure gcdistance(a,b) a[2] -:= b[2] every (x := a|b)[i := 1 to 2] := dtor(x[i]) dz := sin(a[1]) - sin(b[1]) dx := cos(a[2]) * cos(a[1]) - cos(b[1]) dy := sin(a[2]) * cos(a[1]) return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * 6371 end
from math import radians, sin, cos, sqrt, asin def haversine(lat1, lon1, lat2, lon2): R = 6372.8 dLat = radians(lat2 - lat1) dLon = radians(lon2 - lon1) lat1 = radians(lat1) lat2 = radians(lat2) a = sin(dLat / 2)**2 + cos(lat1) * cos(lat2) * sin(dLon / 2)**2 c = 2 * asin(sqrt(a)) return R * c >>> haversine(36.12, -86.67, 33.94, -118.40) 2887.2599506071106 >>>
Rewrite this program in VB while keeping its functionality equivalent to the Icon version.
link printf procedure main() printf("BNA to LAX is %d km (%d miles)\n", d := gcdistance([36.12, -86.67],[33.94, -118.40]),d*3280/5280) end procedure gcdistance(a,b) a[2] -:= b[2] every (x := a|b)[i := 1 to 2] := dtor(x[i]) dz := sin(a[1]) - sin(b[1]) dx := cos(a[2]) * cos(a[1]) - cos(b[1]) dy := sin(a[2]) * cos(a[1]) return asin(sqrt(dx * dx + dy * dy + dz * dz) / 2) * 2 * 6371 end
Const MER = 6371 Public DEG_TO_RAD As Double Function haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double lat1 = lat1 * DEG_TO_RAD lat2 = lat2 * DEG_TO_RAD long1 = long1 * DEG_TO_RAD long2 = long2 * DEG_TO_RAD haversine = MER * WorksheetFunction.Acos(Sin(lat1) * Sin(lat2) + Cos(lat1) * Cos(lat2) * Cos(long2 - long1)) End Function Public Sub main() DEG_TO_RAD = WorksheetFunction.Pi / 180 d = haversine(36.12, -86.67, 33.94, -118.4) Debug.Print "Distance is "; Format(d, "#.######"); " km ("; Format(d / 1.609344, "#.######"); " miles)." End Sub