Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	domain and range okay.	18,871	26	[]
volunteer	so for the domain first we would have to factor and simplify the function	18,871	27	[]
volunteer	as you can see the problem factored and got 3x+1/x+3	18,871	28	[]
student	ohhhh okay so how would i get the 5/3	18,871	29	[]
volunteer	to find the range you would need to solve for x	18,871	30	[]
volunteer	so you see how you have the function	18,871	31	[]
student	okay	18,871	32	[]
student	now HERE is where i really struggle at tbh	18,871	33	[]
volunteer	okay which one do you need help with specifically?	18,871	34	[]
student	how would i know what to right when it says approaching from the left or right if its looks like the same thing	18,871	35	[]
student	write*	18,871	36	[]
student	for example 1	18,871	37	[]
volunteer	so when you are approaching the limit from the right side it literally means from the right side	18,871	38	[]
volunteer	for example for part D	18,871	39	[]
volunteer	it says find the limit as x approaches 2 from the right	18,871	40	[]
volunteer	you would look at the x value 2	18,871	41	[]
volunteer	and see what y value it approaches from the right side	18,871	42	[]
volunteer	you can see its a value of 1	18,871	43	[]
volunteer	does that make sense?	18,871	44	[]
student	ohhhh okay so what about part L	18,871	45	[]
student	like how did we get that answer	18,871	46	[]
volunteer	L would be 1	18,871	47	[]
volunteer	because 1 is your limit	18,871	48	[]
volunteer	oh wait	18,871	49	[]
volunteer	you are talking about part L	18,871	50	[]
volunteer	sorry i misunderstood	18,871	51	[]
student	ur good!!!	18,871	52	[]
volunteer	okay so for part L	18,871	53	[]
volunteer	in order for the limit to exist we have to make sure that both sides (aka limit as x approaches 5 form the left and limit as x approaches 5 from the right) are the same	18,871	54	[]
volunteer	that way the limit as x approaches 5 can exist	18,871	55	[]
volunteer	so if you look on the left and right side of 5 do they both approach the same value?	18,871	56	[]
student	oh Okay i see so i would look at the arrow going down right?	18,871	57	[]
volunteer	yes you would!	18,871	58	[]
student	okay i think im getting the hang of it	18,871	59	[]
volunteer	yup!	18,871	60	[]
student	OKAY NOW THISSSSS	18,871	61	[]
student	is crazy	18,871	62	[]
volunteer	ah finding the limit numerically	18,871	63	[]
student	i would just use the calculator for this though right ???	18,871	64	[]
volunteer	yes you would	18,871	65	[]
volunteer	but do you understand what the values mean?	18,871	66	[]
student	tbh no..	18,871	67	[]
volunteer	okay lets go over it	18,871	68	[]
student	okay	18,871	69	[]
volunteer	so the question is asking to find the limit as x approaches 3 of that function	18,871	70	[]
volunteer	and if you notice when you plug in 3 you get undefined	18,871	71	[]
volunteer	so plugging in 3 would not work	18,871	72	[]
student	yes	18,871	73	[]
volunteer	we could estimate the limit using values super close to 3	18,871	74	[]
student	ohhhh okay	18,871	75	[]
student	i see	18,871	76	[]
volunteer	so you use numbers super close to 3 and plug it in	18,871	77	[]
student	thats the whole point correct	18,871	78	[]
student	to find which one is closet	18,871	79	[]
volunteer	from the right and left side if they approach the same value the limtit would be that value	18,871	80	[]
volunteer	yes	18,871	81	[]
volunteer	you have to make sure that the f(x) is approaching the same number	18,871	82	[]
student	wait huh?	18,871	83	[]
volunteer	at x = 2.999 and x = 3.001	18,871	84	[]
student	f(x) is approashing what	18,871	85	[]
volunteer	f(x) is the value you get after plugging in those super close numbers	18,871	86	[]
volunteer	f(x) is the limit	18,871	87	[]
student	ohhh ookkk	18,871	88	[]
volunteer	at 2.999 and at 3.001 those values are approaching the same limit	18,871	89	[]
volunteer	so thats why it works	18,871	90	[]
student	Okay i see now	18,871	91	[]
student	wait can i go check 1.1 really quick to see if i need help understanding to	18,871	92	[]
volunteer	yes!	18,871	93	[]
student	okay the only question I have about this problem is how would i put this into the calcukator	18,871	94	[]
volunteer	ok so for this one its asking for average velpcioty from 2 seconds to 8 seconds	18,871	95	[]
volunteer	do you recall the average velocity formula?	18,871	96	[]
student	distance/time ?	18,871	97	[]
student	sum like det	18,871	98	[]
volunteer	right	18,871	99	[]
volunteer	its the change in displacement/time	18,871	100	[]
student	okk	18,871	101	[]
volunteer	so that means we to find d(8) - (d(2))/ (8-2)	18,871	102	[]
volunteer	sorry (d(8) - d(2))/(8-2)	18,871	103	[]
volunteer	do get d(8) you would plug 8 into the distance equation	18,871	104	[]
volunteer	and same for 2	18,871	105	[]
student	okayyy i remember that part	18,871	106	[]
student	so thats all im findning	18,871	107	[]
student	right or	18,871	108	[]
volunteer	yes and you put it all together into the average velocity formula	18,871	109	[]
volunteer	and remember your units	18,871	110	[]
student	okkkkk thats smart!	18,871	111	[]
student	okay wait so how would i even start by making a sketch for a problem based on limits n stuff	18,871	112	[]
student	because I rmb we did it in class but i dnt know about a problem pretaining to it	18,871	113	[]
volunteer	interesting is this still on limits? or is this for derivatives	18,871	114	[]
student	limits i think	18,871	115	[]
student	tbh im not sure	18,871	116	[]
volunteer	oh wait sorry i misread that v means vehicles not velocity in this context	18,871	117	[]
student	ok	18,871	118	[]
volunteer	just give me a second to figure out this problem	18,871	119	[]
student	no problem, take ur time	18,871	120	[]
volunteer	okay!	18,871	121	[]
volunteer	so you need help with part b right?	18,871	122	[]
student	yes	18,871	123	[]
volunteer	okay so for this we are just graphing the time vs the number of vehicles	18,871	124	[]
volunteer	so at each time there would be some number of vehicles	18,871	125	[]

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