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8
volunteer
Yes!
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volunteer
Make sure to include both at once though to represent both angles adding to 90 degrees
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student
Is this right?
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volunteer
Double check your work on solving for x, because those add to 50 instead of 90
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volunteer
That's the best way to check if you're right
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student
I need to check my answers pls
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student
hello!
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volunteer
Hi
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volunteer
What do you need?
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student
I need to check my answer
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volunteer
okay
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volunteer
How did you come up with the bottom equation
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volunteer
1/7 x - 6/7
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student
first I found the slope by doing (-2--8/-1--2) and then I put it into point slope form to find the y intercept
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volunteer
what is the problem asking for you to do
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student
I uploaded it
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volunteer
Okay i see it
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volunteer
So the first equation is right
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volunteer
x+1 is correct
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volunteer
but the next equation is not
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student
why?
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volunteer
The equation you wrote, 1/7 x - 6/7, what kind of equation is that?
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volunteer
Linear, quadratic, etc.
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student
linear
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volunteer
And when looking at the graph
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volunteer
Does the part before 1 look like a line
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student
I'm not too sure what that function would be x^3?
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volunteer
that's super close
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student
cube root x?
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volunteer
Yep
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student
but what would you put under it?
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student
like under the cube root
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volunteer
just x
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student
ooh ok and would the rule beside it stay the same or is that also wrong
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volunteer
The rule is right :)
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student
yay!
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student
do u have time to check more of my answers?
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volunteer
Yeah
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volunteer
Okay numbers 45, 47, and 49 all look good
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student
yay!
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volunteer
Did you get 83 for number 51?
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student
yes
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volunteer
Okay that's right
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student
yay!
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student
also how would u graph step functions? like for F(x)= step functions thingy -x, would it be like a -x slope but instead of line it would be points and to the left side the small line would go left and towards the right side the lil line would go right?
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volunteer
Yes it would look like that
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student
ooh ok I get it
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volunteer
It looks kind of like stairs
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volunteer
Hence the name "step function"
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student
got it
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volunteer
or atleast that's how I like to think about it
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student
ok I think that's pretty much it for now ty sm!
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volunteer
Okay no problem
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student
I don't know how to get this into hyperbole form
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student
hello!
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volunteer
Hi!
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student
I'm confused on what u would do, divide by 16? but that would not work bcz you have to have 1 on the right side so I'm confused on what to do
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volunteer
Ah, I see why you're confused! you can't divide by 16, but the first term can be divided by 1/16, since dividing by 1/16 is the same as multiplying by 16!
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student
so u would have (x+5)/1/16 - (y-3) =1?
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student
with added exponents that just takes too long to typw
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volunteer
close yeah! You'd just divide the y-3 by 1 to get it in the correct form
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student
ok I get it!
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volunteer
Great job!
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student
I have another question, do u have time?
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volunteer
Yeah, what's up?
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student
I'm confused on 27
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student
I got to the part of y/3 - x/4 =1 , but I don't know how to make it squared
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volunteer
Okay, so a simpler way to do that is to just square both sides and then move the x term over!
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student
ohhh that was so simple ty!
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volunteer
Of course!
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student
that's it for now Charlie and have a great day!
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[ { "pii_type": "PERSON", "surrogate": "Charlie", "start": 18, "end": 25 } ]
volunteer
You too! :)
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volunteer
Hi!
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student
Hii
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volunteer
How are you? What help do you need?
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student
I’m alright I think and I’m kinda struggling with my homework atm..
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volunteer
ok! i can try to help out! i dont have much time but i can help you with the problems you need help with!!
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volunteer
whats the first question you need help with?
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student
(-2)to the power of 2 - (3)(-4)(2)
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volunteer
ok so first you should solve 2 - (3)(-4)(2)
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volunteer
because that is in your exponent
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volunteer
what do you get?
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student
4 - (3)(-4)2) ?
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volunteer
no 2
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student
My bad
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volunteer
because -2 is the base
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student
Oh
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volunteer
oh its ok!
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volunteer
youre doing good!
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student
2+24?
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volunteer
yes!
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volunteer
now you do (-2)^26
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student
-52?
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volunteer
no, i think you have to use a calculater and put (-2) to the power of 26
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student
Alright mbb
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volunteer
oh no! you did really good!
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volunteer
hey im sorry i have to go but please text if you have any problems and ill try to respond right away!
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volunteer
Good job today!!
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student
I need help with like 18 math problems im not sure about how to do
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volunteer
No problem, can you show me them?
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