role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
student | im confused on how to do this one | 18,362 | 2 | [] |
volunteer | This one is interesting | 18,362 | 3 | [] |
volunteer | Do you know the formula for average rate of change? | 18,362 | 4 | [] |
student | y=x?? | 18,362 | 5 | [] |
student | or is it f(b)-f(a)/b-a | 18,362 | 6 | [] |
volunteer | The second one | 18,362 | 7 | [] |
volunteer | The first one you listed I believe is the slope intercept form of a linear equation | 18,362 | 8 | [] |
student | ohh okay!! | 18,362 | 9 | [] |
student | so how would I go about plugging the equation into the formula? | 18,362 | 10 | [] |
volunteer | So this is a trick question but theres some reasoning behind it | 18,362 | 11 | [] |
volunteer | The f(20)-f(10) / 10 is actually a rate of change formula since 10 can be rewritten as 20-10 | 18,362 | 12 | [] |
volunteer | and f(20)-f(10) / 20-10 matches f(b)-f(a) / b-a | 18,362 | 13 | [] |
volunteer | So the question is effectively asking for the rate of change of f | 18,362 | 14 | [] |
student | by plugging that into the calculator I got an error, did I do it wrong?? | 18,362 | 15 | [] |
volunteer | The question doesn't need a calculator since the answer is already in the question | 18,362 | 16 | [] |
student | and the answer is the last one correct?? | 18,362 | 17 | [] |
volunteer | Well | 18,362 | 18 | [] |
volunteer | The slope (or rate of change) of a linear function is the same across the entire function | 18,362 | 19 | [] |
volunteer | So if the slope of f is 12/5 for one interval its 12/5 for all other intervals | 18,362 | 20 | [] |
volunteer | And f(20) - f(10) / 20-10 is the rate of change of f across the interval [10, 20] | 18,362 | 21 | [] |
volunteer | uh | 18,362 | 22 | [] |
volunteer | The question is asking for the rate of change, not the interval | 18,362 | 23 | [] |
volunteer | And the rate of change across the entire function is 12/5 | 18,362 | 24 | [] |
student | this may be silly but would you mind solving an example problem similar to this one for reference | 18,362 | 25 | [] |
student | I wasn't sure that was the correct answer, but the way I read the message made it sound like that it was obviously simple lol | 18,362 | 26 | [] |
volunteer | Alright sure | 18,362 | 27 | [] |
volunteer | So lets say the rate of change of a linear function a is 4 across the interval [0, 1] | 18,362 | 28 | [] |
volunteer | And you have to calculate the rate of change of function a across a different interval | 18,362 | 29 | [] |
volunteer | regardless of what that interval is the rate of change will always be 4 | 18,362 | 30 | [] |
volunteer | so basically f(b)) - f(a) / b-a = 4 no matter what | 18,362 | 31 | [] |
volunteer | as long as youre solving for something in that form for a function the answer will always be the rate of change | 18,362 | 32 | [] |
volunteer | so in this case since f(20) - f(10) / 20-10 is the right form for rate of change | 18,362 | 33 | [] |
volunteer | it will equal 12/5 since thats what the rate of change is for the entire function | 18,362 | 34 | [] |
volunteer | if that makes sense | 18,362 | 35 | [] |
student | okay yes that makes sense | 18,362 | 36 | [] |
student | so the entire thing equals 12/5 | 18,362 | 37 | [] |
volunteer | Yes its 12/5 | 18,362 | 38 | [] |
volunteer | Do you need help with this one? | 18,362 | 39 | [] |
student | yes please :) | 18,362 | 40 | [] |
volunteer | Casey | 18,362 | 41 | [
{
"pii_type": "PERSON",
"surrogate": "Casey",
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volunteer | Could you try zooming into the question my eyesight is horrendous | 18,362 | 42 | [] |
student | oh lawd yes I can | 18,362 | 43 | [] |
student | tell me if I need to move it | 18,362 | 44 | [] |
volunteer | Ok so this question is asking for if the rate of change is staying constant across the range of values | 18,362 | 45 | [] |
volunteer | Are you allowed to use a calculator for this question? | 18,362 | 46 | [] |
student | yes | 18,362 | 47 | [] |
volunteer | Graphing or scientific? | 18,362 | 48 | [] |
student | im not sure | 18,362 | 49 | [] |
student | I assume graphing | 18,362 | 50 | [] |
student | ?? | 18,362 | 51 | [] |
volunteer | Basically what you have to do here is use the equation for rate of change | 18,362 | 52 | [] |
volunteer | for two pairs at a time | 18,362 | 53 | [] |
volunteer | Each pair is a number of servings and the total cost for that number of servings | 18,362 | 54 | [] |
student | how would I put it into the calculator | 18,362 | 55 | [] |
volunteer | What model of calculator is it | 18,362 | 56 | [] |
volunteer | If its not a ti84 I genuinely have no idea how to use it | 18,362 | 57 | [] |
student | im using the gauth calculator | 18,362 | 58 | [] |
student | I dont have one of my own | 18,362 | 59 | [] |
student | other than at school | 18,362 | 60 | [] |
volunteer | Oh | 18,362 | 61 | [] |
student | yep... | 18,362 | 62 | [] |
volunteer | Unfortunate | 18,362 | 63 | [] |
volunteer | Theres a method you can use with the ti84 to cheese these types of questions | 18,362 | 64 | [] |
student | if you were to set it up how would it look though | 18,362 | 65 | [] |
student | like would you set it up as a fraction | 18,362 | 66 | [] |
volunteer | To do it properly you basically have to calculate f(x2)-f(x1)/x2-x1 | 18,362 | 67 | [] |
volunteer | and then another calculation | 18,362 | 68 | [] |
volunteer | and so on | 18,362 | 69 | [] |
volunteer | because that calculates the rate of change between each pair | 18,362 | 70 | [] |
volunteer | Im gonna do it myself just to make sure | 18,362 | 71 | [] |
student | do you have the right type of calculator | 18,362 | 72 | [] |
volunteer | Any calculator works | 18,362 | 73 | [] |
volunteer | If we do it the proper way that I described | 18,362 | 74 | [] |
volunteer | The fast method only works with the ti84 so we won't be using that | 18,362 | 75 | [] |
student | the answer to the first calculation is 4.65 correct?? | 18,362 | 76 | [] |
volunteer | For the rate of change between the first two pairs yes thats correct | 18,362 | 77 | [] |
volunteer | Now you have to calculate the rate of change between (5, 33.24) and (9, 49.81) | 18,362 | 78 | [] |
volunteer | so f(9)-f(5)/9-5 | 18,362 | 79 | [] |
volunteer | and then after that you have to do the rate of change between (9, 49.81) and (11, 57.96) | 18,362 | 80 | [] |
volunteer | its a long process | 18,362 | 81 | [] |
student | would the answer be 4.075 | 18,362 | 82 | [] |
volunteer | Well the question is asking for if the rate of change is increasing, decreasing, or staying the same | 18,362 | 83 | [] |
volunteer | So you have to compare the rates of change between the points | 18,362 | 84 | [] |
volunteer | So if the rate of change is changing from 4.65 to 4.075 then that means its decreasing | 18,362 | 85 | [] |
student | okay so the rate of change is decreasing while the number of servings is increasing | 18,362 | 86 | [] |
volunteer | As the number of servings increase, the rate of change decreases yes | 18,362 | 87 | [] |
student | what's the difference between quadratic and linear | 18,362 | 88 | [] |
volunteer | Theres multiple differences | 18,362 | 89 | [] |
volunteer | Linear equations are mostly in the form y = mx + b | 18,362 | 90 | [] |
volunteer | but quadratic equations are in the form y = ax^2 + bx + c | 18,362 | 91 | [] |
student | how could I tell which one it is by just looking at h | 18,362 | 92 | [] |
volunteer | By looking at differences | 18,362 | 93 | [] |
volunteer | Basically find the difference between each value of h | 18,362 | 94 | [] |
volunteer | so between 18 and -12 | 18,362 | 95 | [] |
volunteer | and then -12 and -29 | 18,362 | 96 | [] |
volunteer | and -29 and -33 and so on | 18,362 | 97 | [] |
student | are they all supposed to follow a pattern | 18,362 | 98 | [] |
volunteer | Yes | 18,362 | 99 | [] |
volunteer | if they are all equal the function is linear | 18,362 | 100 | [] |
volunteer | If the differences of the differences are equal then the function is quadratic | 18,362 | 101 | [] |
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