contestId int64 0 1.01k | index stringclasses 40
values | name stringlengths 2 54 | type stringclasses 2
values | rating int64 0 3.4k | tags listlengths 0 7 | title stringclasses 393
values | time-limit stringclasses 7
values | memory-limit stringclasses 6
values | problem-description stringlengths 0 2.97k | input-specification stringlengths 4 1.87k | output-specification stringlengths 4 1.12k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 3.5k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 1
value | testset stringclasses 9
values | passedTestCount int64 1 402 | timeConsumedMillis int64 15 8.06k | memoryConsumedBytes int64 0 514M | code stringlengths 11 61.4k | prompt stringlengths 297 7.35k | response stringlengths 25 61.4k | score float64 2.82 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
16 | A | Flag | PROGRAMMING | 800 | [
"implementation"
] | A. Flag | 2 | 64 | According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of the same colour, and the colours of adjacent horizontal rows should be different. Be... | The first line of the input contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), *n* — the amount of rows, *m* — the amount of columns on the flag of Berland. Then there follows the description of the flag: each of the following *n* lines contain *m* characters. Each character is a digit between 0 and 9, and stands ... | Output YES, if the flag meets the new ISO standard, and NO otherwise. | [
"3 3\n000\n111\n222\n",
"3 3\n000\n000\n111\n",
"3 3\n000\n111\n002\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 0 | [
{
"input": "3 3\n000\n111\n222",
"output": "YES"
},
{
"input": "3 3\n000\n000\n111",
"output": "NO"
},
{
"input": "3 3\n000\n111\n002",
"output": "NO"
},
{
"input": "10 10\n2222222222\n5555555555\n0000000000\n4444444444\n1111111111\n3333333393\n3333333333\n5555555555\n0000000... | 1,676,631,743 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 154 | 1,331,200 | # https://codeforces.com/problemset/problem/16/A
def func_sol(raw_data):
data = raw_data.split('\n')[:-1]
n, m = map(int, data[0].split(' '))
lines = data[1:]
for line in lines:
for c in line:
if c != line[0]:
return "NO\n"
for i in range(len(lines) - 1... | Title: Flag
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of... | ```python
# https://codeforces.com/problemset/problem/16/A
def func_sol(raw_data):
data = raw_data.split('\n')[:-1]
n, m = map(int, data[0].split(' '))
lines = data[1:]
for line in lines:
for c in line:
if c != line[0]:
return "NO\n"
for i in range(len(... | 3.951582 |
716 | A | Crazy Computer | PROGRAMMING | 800 | [
"implementation"
] | null | null | ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *b*, then if *b*<=-<=*a*<=≤<=*c*, just the new word is appended to other words on the screen. If *b*<... | The first line contains two integers *n* and *c* (1<=≤<=*n*<=≤<=100<=000,<=1<=≤<=*c*<=≤<=109) — the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=...<=<<=*t**n*<=≤<=109), where *t**i* denote... | Print a single positive integer, the number of words that remain on the screen after all *n* words was typed, in other words, at the second *t**n*. | [
"6 5\n1 3 8 14 19 20\n",
"6 1\n1 3 5 7 9 10\n"
] | [
"3",
"2"
] | The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be... | 500 | [
{
"input": "6 5\n1 3 8 14 19 20",
"output": "3"
},
{
"input": "6 1\n1 3 5 7 9 10",
"output": "2"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
"input": "5 5\n1 7 12 13 14",
"output": "4"
},
{
"input": "2 1000000000\n1 1000000000",
"output": "2"
},
{
... | 1,644,891,996 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 124 | 7,884,800 | n,c = map(int,input().split())
a = list(map(int, input().split()))
s = 0
for i in range(1,n):
if (a[i]-a[i-1])>c:
s = 0
else:
s = s + 1
print(s+1) | Title: Crazy Computer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *... | ```python
n,c = map(int,input().split())
a = list(map(int, input().split()))
s = 0
for i in range(1,n):
if (a[i]-a[i-1])>c:
s = 0
else:
s = s + 1
print(s+1)
``` | 3 | |
453 | A | Little Pony and Expected Maximum | PROGRAMMING | 1,600 | [
"probabilities"
] | null | null | Twilight Sparkle was playing Ludo with her friends Rainbow Dash, Apple Jack and Flutter Shy. But she kept losing. Having returned to the castle, Twilight Sparkle became interested in the dice that were used in the game.
The dice has *m* faces: the first face of the dice contains a dot, the second one contains two dots... | A single line contains two integers *m* and *n* (1<=≤<=*m*,<=*n*<=≤<=105). | Output a single real number corresponding to the expected maximum. The answer will be considered correct if its relative or absolute error doesn't exceed 10<=<=-<=4. | [
"6 1\n",
"6 3\n",
"2 2\n"
] | [
"3.500000000000\n",
"4.958333333333\n",
"1.750000000000\n"
] | Consider the third test example. If you've made two tosses:
1. You can get 1 in the first toss, and 2 in the second. Maximum equals to 2. 1. You can get 1 in the first toss, and 1 in the second. Maximum equals to 1. 1. You can get 2 in the first toss, and 1 in the second. Maximum equals to 2. 1. You can get 2 in t... | 500 | [
{
"input": "6 1",
"output": "3.500000000000"
},
{
"input": "6 3",
"output": "4.958333333333"
},
{
"input": "2 2",
"output": "1.750000000000"
},
{
"input": "5 4",
"output": "4.433600000000"
},
{
"input": "5 8",
"output": "4.814773760000"
},
{
"input": "... | 1,638,275,101 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 93 | 0 | m,n=list(map(int,input().split()))
q=0
for i in range(1,m):
q+=(i/m)**n
print(m-q)
| Title: Little Pony and Expected Maximum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Twilight Sparkle was playing Ludo with her friends Rainbow Dash, Apple Jack and Flutter Shy. But she kept losing. Having returned to the castle, Twilight Sparkle became interested in the dice that were ... | ```python
m,n=list(map(int,input().split()))
q=0
for i in range(1,m):
q+=(i/m)**n
print(m-q)
``` | 3 | |
165 | A | Supercentral Point | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the given set (*x*,<=*y*):
- point (*x*',<=*y*') is (*x*,<=*y*)'s right neighbor, if *x*'<=><=*x* and *y*'... | The first input line contains the only integer *n* (1<=≤<=*n*<=≤<=200) — the number of points in the given set. Next *n* lines contain the coordinates of the points written as "*x* *y*" (without the quotes) (|*x*|,<=|*y*|<=≤<=1000), all coordinates are integers. The numbers in the line are separated by exactly one spac... | Print the only number — the number of supercentral points of the given set. | [
"8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3\n",
"5\n0 0\n0 1\n1 0\n0 -1\n-1 0\n"
] | [
"2\n",
"1\n"
] | In the first sample the supercentral points are only points (1, 1) and (1, 2).
In the second sample there is one supercental point — point (0, 0). | 500 | [
{
"input": "8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3",
"output": "2"
},
{
"input": "5\n0 0\n0 1\n1 0\n0 -1\n-1 0",
"output": "1"
},
{
"input": "9\n-565 -752\n-184 723\n-184 -752\n-184 1\n950 723\n-565 723\n950 -752\n950 1\n-565 1",
"output": "1"
},
{
"input": "25\n-651 897\n... | 1,684,229,259 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 92 | 0 | #Keshika Patwari
#Indian Institute Of Technology, Jodhpur
# 2022
import sys
input=sys.stdin.readline
def exe():
lx=[]
ly=[]
for i in al:
dx[i]=[]
for i in range(len(al)):
dx[al[i]]+=[bl[i]]
for i in dx:
if(len(dx[i])>=3):
a=dx[i]
a.sort... | Title: Supercentral Point
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the give... | ```python
#Keshika Patwari
#Indian Institute Of Technology, Jodhpur
# 2022
import sys
input=sys.stdin.readline
def exe():
lx=[]
ly=[]
for i in al:
dx[i]=[]
for i in range(len(al)):
dx[al[i]]+=[bl[i]]
for i in dx:
if(len(dx[i])>=3):
a=dx[i]
... | 3 | |
92 | A | Chips | PROGRAMMING | 800 | [
"implementation",
"math"
] | A. Chips | 2 | 256 | There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus number 1 sits to the left of the walrus number *n*.
The presenter has *m* chips. The pre... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=50, 1<=≤<=*m*<=≤<=104) — the number of walruses and the number of chips correspondingly. | Print the number of chips the presenter ended up with. | [
"4 11\n",
"17 107\n",
"3 8\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first sample the presenter gives one chip to the walrus number 1, two chips to the walrus number 2, three chips to the walrus number 3, four chips to the walrus number 4, then again one chip to the walrus number 1. After that the presenter runs out of chips. He can't give anything to the walrus number 2 and the ... | 500 | [
{
"input": "4 11",
"output": "0"
},
{
"input": "17 107",
"output": "2"
},
{
"input": "3 8",
"output": "1"
},
{
"input": "46 7262",
"output": "35"
},
{
"input": "32 6864",
"output": "0"
},
{
"input": "36 6218",
"output": "14"
},
{
"input": "... | 1,690,711,483 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | A,B = map(int, input().split())
temp = A * (A + 1) // 2
for i in range(100000000):
if temp <= B:
B -= temp
elif temp > B:
break
if B == 0:
print(0)
else:
for i in range(1, A + 1):
if B >= i:
B -= i
elif B < i:
print(B)
br... | Title: Chips
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus nu... | ```python
A,B = map(int, input().split())
temp = A * (A + 1) // 2
for i in range(100000000):
if temp <= B:
B -= temp
elif temp > B:
break
if B == 0:
print(0)
else:
for i in range(1, A + 1):
if B >= i:
B -= i
elif B < i:
print(B)
... | 3.977 |
744 | A | Hongcow Builds A Nation | PROGRAMMING | 1,500 | [
"dfs and similar",
"graphs"
] | null | null | Hongcow is ruler of the world. As ruler of the world, he wants to make it easier for people to travel by road within their own countries.
The world can be modeled as an undirected graph with *n* nodes and *m* edges. *k* of the nodes are home to the governments of the *k* countries that make up the world.
There is at ... | The first line of input will contain three integers *n*, *m* and *k* (1<=≤<=*n*<=≤<=1<=000, 0<=≤<=*m*<=≤<=100<=000, 1<=≤<=*k*<=≤<=*n*) — the number of vertices and edges in the graph, and the number of vertices that are homes of the government.
The next line of input will contain *k* integers *c*1,<=*c*2,<=...,<=*c**... | Output a single integer, the maximum number of edges Hongcow can add to the graph while keeping it stable. | [
"4 1 2\n1 3\n1 2\n",
"3 3 1\n2\n1 2\n1 3\n2 3\n"
] | [
"2\n",
"0\n"
] | For the first sample test, the graph looks like this:
For the second sample test, the graph looks like this: | 500 | [
{
"input": "4 1 2\n1 3\n1 2",
"output": "2"
},
{
"input": "3 3 1\n2\n1 2\n1 3\n2 3",
"output": "0"
},
{
"input": "10 3 2\n1 10\n1 2\n1 3\n4 5",
"output": "33"
},
{
"input": "1 0 1\n1",
"output": "0"
},
{
"input": "1000 0 1\n72",
"output": "499500"
},
{
... | 1,620,413,385 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 342 | 9,420,800 | def functionAux(ind):
if not C[ind]:
C[ind]=True
aux[0]+=1
for i in B[ind]:
if not C[i]:functionAux(i)
listOne,listTwo,listThree=list(map(int, input().split()))
A=list(map(int, input().split()))
A=[i-1 for i in A]
B=[list([]) for i in range(listOne)]
C=[False for i in ran... | Title: Hongcow Builds A Nation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hongcow is ruler of the world. As ruler of the world, he wants to make it easier for people to travel by road within their own countries.
The world can be modeled as an undirected graph with *n* nodes and *m* e... | ```python
def functionAux(ind):
if not C[ind]:
C[ind]=True
aux[0]+=1
for i in B[ind]:
if not C[i]:functionAux(i)
listOne,listTwo,listThree=list(map(int, input().split()))
A=list(map(int, input().split()))
A=[i-1 for i in A]
B=[list([]) for i in range(listOne)]
C=[False fo... | 3 | |
208 | A | Dubstep | PROGRAMMING | 900 | [
"strings"
] | null | null | Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain nu... | The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the son... | Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space. | [
"WUBWUBABCWUB\n",
"WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n"
] | [
"ABC ",
"WE ARE THE CHAMPIONS MY FRIEND "
] | In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE... | 500 | [
{
"input": "WUBWUBABCWUB",
"output": "ABC "
},
{
"input": "WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB",
"output": "WE ARE THE CHAMPIONS MY FRIEND "
},
{
"input": "WUBWUBWUBSR",
"output": "SR "
},
{
"input": "RWUBWUBWUBLWUB",
"output": "R L "
},
{
"input": "... | 1,674,575,455 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | txt = input()
txtsplit = txt.split("WUB")
txtnew = ''
for i in txtsplit:
if i == '':
continue
txtnew += (i + ' ')
print(txtnew) | Title: Dubstep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consist... | ```python
txt = input()
txtsplit = txt.split("WUB")
txtnew = ''
for i in txtsplit:
if i == '':
continue
txtnew += (i + ' ')
print(txtnew)
``` | 3 | |
369 | A | Valera and Plates | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Valera is a lazy student. He has *m* clean bowls and *k* clean plates.
Valera has made an eating plan for the next *n* days. As Valera is lazy, he will eat exactly one dish per day. At that, in order to eat a dish, he needs exactly one clean plate or bowl. We know that Valera can cook only two types of dishes. He can... | The first line of the input contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=1000) — the number of the planned days, the number of clean bowls and the number of clean plates.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2). If *a**i* equals one, then on day *i* Val... | Print a single integer — the minimum number of times Valera will need to wash a plate/bowl. | [
"3 1 1\n1 2 1\n",
"4 3 1\n1 1 1 1\n",
"3 1 2\n2 2 2\n",
"8 2 2\n1 2 1 2 1 2 1 2\n"
] | [
"1\n",
"1\n",
"0\n",
"4\n"
] | In the first sample Valera will wash a bowl only on the third day, so the answer is one.
In the second sample, Valera will have the first type of the dish during all four days, and since there are only three bowls, he will wash a bowl exactly once.
In the third sample, Valera will have the second type of dish for all... | 500 | [
{
"input": "3 1 1\n1 2 1",
"output": "1"
},
{
"input": "4 3 1\n1 1 1 1",
"output": "1"
},
{
"input": "3 1 2\n2 2 2",
"output": "0"
},
{
"input": "8 2 2\n1 2 1 2 1 2 1 2",
"output": "4"
},
{
"input": "2 100 100\n2 2",
"output": "0"
},
{
"input": "1 1 1\... | 1,594,385,626 | 2,147,483,647 | PyPy 3 | OK | TESTS | 63 | 155 | 20,172,800 | l1 = [int(x) for x in input().split()]
l2 = [int(x) for x in input().split()]
bowls = l1[1]
plates = l1[2]
first = l2.count(1)
second = l2.count(2)
bfirst = max(0,first-bowls)
bowls = max(0,bowls-first)
bsecond = max(0,second-plates-bowls)
print(bfirst+bsecond)
| Title: Valera and Plates
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a lazy student. He has *m* clean bowls and *k* clean plates.
Valera has made an eating plan for the next *n* days. As Valera is lazy, he will eat exactly one dish per day. At that, in order to eat a dish, ... | ```python
l1 = [int(x) for x in input().split()]
l2 = [int(x) for x in input().split()]
bowls = l1[1]
plates = l1[2]
first = l2.count(1)
second = l2.count(2)
bfirst = max(0,first-bowls)
bowls = max(0,bowls-first)
bsecond = max(0,second-plates-bowls)
print(bfirst+bsecond)
``` | 3 | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,696,511,113 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 62 | 1,740,800 | def solve():
n, k = map(int, input().split())
l = [int(i) for i in input().split()]
ans = 0
for i in l:
ans += i+k <= 5
print(ans//3)
# t = int(input())
t = 1
while t:
solve()
t -= 1
| Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
def solve():
n, k = map(int, input().split())
l = [int(i) for i in input().split()]
ans = 0
for i in l:
ans += i+k <= 5
print(ans//3)
# t = int(input())
t = 1
while t:
solve()
t -= 1
``` | 3 | |
705 | A | Hulk | PROGRAMMING | 800 | [
"implementation"
] | null | null | Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, se... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate. | Print Dr.Banner's feeling in one line. | [
"1\n",
"2\n",
"3\n"
] | [
"I hate it\n",
"I hate that I love it\n",
"I hate that I love that I hate it\n"
] | none | 500 | [
{
"input": "1",
"output": "I hate it"
},
{
"input": "2",
"output": "I hate that I love it"
},
{
"input": "3",
"output": "I hate that I love that I hate it"
},
{
"input": "4",
"output": "I hate that I love that I hate that I love it"
},
{
"input": "5",
"output"... | 1,700,228,474 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 31 | 0 | n=int(input(""))
s=""
if n==1:
s+="I hate it"
else:
for i in range(n):
i=i+1
if i+1 > n:
if n%2 == 0:
s += "I love it"
else:
s += "I hate it"
else:
if i%2 == 0:
s += "I love that "
... | Title: Hulk
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and... | ```python
n=int(input(""))
s=""
if n==1:
s+="I hate it"
else:
for i in range(n):
i=i+1
if i+1 > n:
if n%2 == 0:
s += "I love it"
else:
s += "I hate it"
else:
if i%2 == 0:
s += "I love that "... | 3 | |
614 | B | Gena's Code | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | It's the year 4527 and the tanks game that we all know and love still exists. There also exists Great Gena's code, written in 2016. The problem this code solves is: given the number of tanks that go into the battle from each country, find their product. If it is turns to be too large, then the servers might have not en... | The first line of the input contains the number of countries *n* (1<=≤<=*n*<=≤<=100<=000). The second line contains *n* non-negative integers *a**i* without leading zeroes — the number of tanks of the *i*-th country.
It is guaranteed that the second line contains at least *n*<=-<=1 beautiful numbers and the total leng... | Print a single number without leading zeroes — the product of the number of tanks presented by each country. | [
"3\n5 10 1\n",
"4\n1 1 10 11\n",
"5\n0 3 1 100 1\n"
] | [
"50",
"110",
"0"
] | In sample 1 numbers 10 and 1 are beautiful, number 5 is not not.
In sample 2 number 11 is not beautiful (contains two '1's), all others are beautiful.
In sample 3 number 3 is not beautiful, all others are beautiful. | 1,000 | [
{
"input": "3\n5 10 1",
"output": "50"
},
{
"input": "4\n1 1 10 11",
"output": "110"
},
{
"input": "5\n0 3 1 100 1",
"output": "0"
},
{
"input": "40\n10 100 10 1 10 10 100 10 10 100 10 100 100 10 1824868942 100 100 1 10 100 100 10 100 100 10 100 10 1 10 100 100 100 10 1 10 1 ... | 1,685,963,495 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 62 | 8,294,400 | # https://codeforces.com/contest/614
import sys
input = lambda: sys.stdin.readline().rstrip() # faster!
n = int(input())
a = list(input().split())
f, z = "1", 0
for x in a:
if x == "0":
print(0)
exit()
else:
i = len(x) - 1
while i >= 0 and x[i] == "0":
... | Title: Gena's Code
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's the year 4527 and the tanks game that we all know and love still exists. There also exists Great Gena's code, written in 2016. The problem this code solves is: given the number of tanks that go into the battle from eac... | ```python
# https://codeforces.com/contest/614
import sys
input = lambda: sys.stdin.readline().rstrip() # faster!
n = int(input())
a = list(input().split())
f, z = "1", 0
for x in a:
if x == "0":
print(0)
exit()
else:
i = len(x) - 1
while i >= 0 and x[i] == "... | 3 | |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. E... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match di... | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,598,454,435 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 218 | 0 | d = {}
for _ in range(int(input())):
a = input()
if(a not in d):
d[a] = 1
else:
d[a] +=1
print(max(d,key=d.get)) | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process... | ```python
d = {}
for _ in range(int(input())):
a = input()
if(a not in d):
d[a] = 1
else:
d[a] +=1
print(max(d,key=d.get))
``` | 3.9455 |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,651,751,889 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | a=input()
ans=''
x=0
while x<len(a):
if a[x]=='.':
ans+='0'
x+=1
elif a[x:x+2]=='-.':
ans+='1'
x+=2
else:
ans+='2'
x+=2
print(ans) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
a=input()
ans=''
x=0
while x<len(a):
if a[x]=='.':
ans+='0'
x+=1
elif a[x:x+2]=='-.':
ans+='1'
x+=2
else:
ans+='2'
x+=2
print(ans)
``` | 3.977 |
197 | B | Limit | PROGRAMMING | 1,400 | [
"math"
] | null | null | You are given two polynomials:
- *P*(*x*)<==<=*a*0·*x**n*<=+<=*a*1·*x**n*<=-<=1<=+<=...<=+<=*a**n*<=-<=1·*x*<=+<=*a**n* and - *Q*(*x*)<==<=*b*0·*x**m*<=+<=*b*1·*x**m*<=-<=1<=+<=...<=+<=*b**m*<=-<=1·*x*<=+<=*b**m*.
Calculate limit . | The first line contains two space-separated integers *n* and *m* (0<=≤<=*n*,<=*m*<=≤<=100) — degrees of polynomials *P*(*x*) and *Q*(*x*) correspondingly.
The second line contains *n*<=+<=1 space-separated integers — the factors of polynomial *P*(*x*): *a*0, *a*1, ..., *a**n*<=-<=1, *a**n* (<=-<=100<=≤<=*a**i*<=≤<=100... | If the limit equals <=+<=∞, print "Infinity" (without quotes). If the limit equals <=-<=∞, print "-Infinity" (without the quotes).
If the value of the limit equals zero, print "0/1" (without the quotes).
Otherwise, print an irreducible fraction — the value of limit , in the format "p/q" (without the quotes), where *p... | [
"2 1\n1 1 1\n2 5\n",
"1 0\n-1 3\n2\n",
"0 1\n1\n1 0\n",
"2 2\n2 1 6\n4 5 -7\n",
"1 1\n9 0\n-5 2\n"
] | [
"Infinity\n",
"-Infinity\n",
"0/1\n",
"1/2\n",
"-9/5\n"
] | Let's consider all samples:
1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c28febca257452afdfcbd6984ba8623911f9bdbc.png" style="max-width: 100.0%;max-height: 100.0%;"/> 1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1e55ecd04e54a45e5e0092ec9a5c1ea03bb... | 500 | [
{
"input": "2 1\n1 1 1\n2 5",
"output": "Infinity"
},
{
"input": "1 0\n-1 3\n2",
"output": "-Infinity"
},
{
"input": "0 1\n1\n1 0",
"output": "0/1"
},
{
"input": "2 2\n2 1 6\n4 5 -7",
"output": "1/2"
},
{
"input": "1 1\n9 0\n-5 2",
"output": "-9/5"
},
{
... | 1,565,769,563 | 2,147,483,647 | PyPy 3 | OK | TESTS | 80 | 654 | 7,372,800 | from fractions import Fraction
class CodeforcesTask197BSolution:
def __init__(self):
self.result = ''
self.n_m = []
self.p_x = []
self.q_x = []
def read_input(self):
self.n_m = [int(x) for x in input().split(" ")]
self.p_x = [int(x) for x in input().split(" ")]... | Title: Limit
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two polynomials:
- *P*(*x*)<==<=*a*0·*x**n*<=+<=*a*1·*x**n*<=-<=1<=+<=...<=+<=*a**n*<=-<=1·*x*<=+<=*a**n* and - *Q*(*x*)<==<=*b*0·*x**m*<=+<=*b*1·*x**m*<=-<=1<=+<=...<=+<=*b**m*<=-<=1·*x*<=+<=*b**m*.
Calculate l... | ```python
from fractions import Fraction
class CodeforcesTask197BSolution:
def __init__(self):
self.result = ''
self.n_m = []
self.p_x = []
self.q_x = []
def read_input(self):
self.n_m = [int(x) for x in input().split(" ")]
self.p_x = [int(x) for x in input().s... | 3 | |
985 | C | Liebig's Barrels | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | You have *m*<==<=*n*·*k* wooden staves. The *i*-th stave has length *a**i*. You have to assemble *n* barrels consisting of *k* staves each, you can use any *k* staves to construct a barrel. Each stave must belong to exactly one barrel.
Let volume *v**j* of barrel *j* be equal to the length of the minimal stave in it.
... | The first line contains three space-separated integers *n*, *k* and *l* (1<=≤<=*n*,<=*k*<=≤<=105, 1<=≤<=*n*·*k*<=≤<=105, 0<=≤<=*l*<=≤<=109).
The second line contains *m*<==<=*n*·*k* space-separated integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=109) — lengths of staves. | Print single integer — maximal total sum of the volumes of barrels or 0 if it's impossible to construct exactly *n* barrels satisfying the condition |*v**x*<=-<=*v**y*|<=≤<=*l* for any 1<=≤<=*x*<=≤<=*n* and 1<=≤<=*y*<=≤<=*n*. | [
"4 2 1\n2 2 1 2 3 2 2 3\n",
"2 1 0\n10 10\n",
"1 2 1\n5 2\n",
"3 2 1\n1 2 3 4 5 6\n"
] | [
"7\n",
"20\n",
"2\n",
"0\n"
] | In the first example you can form the following barrels: [1, 2], [2, 2], [2, 3], [2, 3].
In the second example you can form the following barrels: [10], [10].
In the third example you can form the following barrels: [2, 5].
In the fourth example difference between volumes of barrels in any partition is at least 2 so... | 0 | [
{
"input": "4 2 1\n2 2 1 2 3 2 2 3",
"output": "7"
},
{
"input": "2 1 0\n10 10",
"output": "20"
},
{
"input": "1 2 1\n5 2",
"output": "2"
},
{
"input": "3 2 1\n1 2 3 4 5 6",
"output": "0"
},
{
"input": "10 3 189\n267 697 667 4 52 128 85 616 142 344 413 660 962 194... | 1,527,000,972 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 218 | 8,089,600 | [n,k,l] = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
import bisect
s = 0
a = sorted(a)
b = bisect.bisect_right(a,a[0]+l)
a1 = a[:b]
tot = n * k
av = tot - b
if b >= n:
for i in range(b-1,b-n-1,-1):
m = a1.pop()
for j in range(0,k-1):
if av > 0:
... | Title: Liebig's Barrels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *m*<==<=*n*·*k* wooden staves. The *i*-th stave has length *a**i*. You have to assemble *n* barrels consisting of *k* staves each, you can use any *k* staves to construct a barrel. Each stave must belong to ex... | ```python
[n,k,l] = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
import bisect
s = 0
a = sorted(a)
b = bisect.bisect_right(a,a[0]+l)
a1 = a[:b]
tot = n * k
av = tot - b
if b >= n:
for i in range(b-1,b-n-1,-1):
m = a1.pop()
for j in range(0,k-1):
if... | 3 | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,693,119,848 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 46 | 0 | firstline = [int(n) for n in input().split()]
NOP = firstline[0]
Time = firstline[1]
remainder_time = 240 - Time
counter = 0
time , all_time = 0, 0
for i in range(1, NOP+1):
time = i*5
if time+all_time <= remainder_time:
all_time+=time
counter+=1
print(counter) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
firstline = [int(n) for n in input().split()]
NOP = firstline[0]
Time = firstline[1]
remainder_time = 240 - Time
counter = 0
time , all_time = 0, 0
for i in range(1, NOP+1):
time = i*5
if time+all_time <= remainder_time:
all_time+=time
counter+=1
print(counter)
``` | 3 | |
298 | A | Snow Footprints | PROGRAMMING | 1,300 | [
"greedy",
"implementation"
] | null | null | There is a straight snowy road, divided into *n* blocks. The blocks are numbered from 1 to *n* from left to right. If one moves from the *i*-th block to the (*i*<=+<=1)-th block, he will leave a right footprint on the *i*-th block. Similarly, if one moves from the *i*-th block to the (*i*<=-<=1)-th block, he will leave... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=1000).
The second line contains the description of the road — the string that consists of *n* characters. Each character will be either "." (a block without footprint), or "L" (a block with a left footprint), "R" (a block with a right footprint).
It's gu... | Print two space-separated integers — the values of *s* and *t*. If there are several possible solutions you can print any of them. | [
"9\n..RRLL...\n",
"11\n.RRRLLLLL..\n"
] | [
"3 4\n",
"7 5\n"
] | The first test sample is the one in the picture. | 500 | [
{
"input": "11\n.RRRLLLLL..",
"output": "7 5"
},
{
"input": "4\n.RL.",
"output": "3 2"
},
{
"input": "3\n.L.",
"output": "2 1"
},
{
"input": "3\n.R.",
"output": "2 3"
}
] | 1,443,248,346 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 122 | 0 |
n = int(input())
s = input()
ans = ""
if 'L' in s and not 'R' in s:
ans = str(s.index('L')+1)+" "+str(s.index('L')-1+1)
elif 'R' in s and not 'L' in s:
st = s.index('R')
en = st+1
while s[en]=='R':
en+=1
ans = str(st+1)+" "+str(en+1)
else:
st = s.index('R')
en = st+1... | Title: Snow Footprints
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a straight snowy road, divided into *n* blocks. The blocks are numbered from 1 to *n* from left to right. If one moves from the *i*-th block to the (*i*<=+<=1)-th block, he will leave a right footprint on the *... | ```python
n = int(input())
s = input()
ans = ""
if 'L' in s and not 'R' in s:
ans = str(s.index('L')+1)+" "+str(s.index('L')-1+1)
elif 'R' in s and not 'L' in s:
st = s.index('R')
en = st+1
while s[en]=='R':
en+=1
ans = str(st+1)+" "+str(en+1)
else:
st = s.index('R')
... | 3 | |
513 | A | Game | PROGRAMMING | 800 | [
"constructive algorithms",
"math"
] | null | null | Two players play a simple game. Each player is provided with a box with balls. First player's box contains exactly *n*1 balls and second player's box contains exactly *n*2 balls. In one move first player can take from 1 to *k*1 balls from his box and throw them away. Similarly, the second player can take from 1 to *k*2... | The first line contains four integers *n*1,<=*n*2,<=*k*1,<=*k*2. All numbers in the input are from 1 to 50.
This problem doesn't have subproblems. You will get 3 points for the correct submission. | Output "First" if the first player wins and "Second" otherwise. | [
"2 2 1 2\n",
"2 1 1 1\n"
] | [
"Second\n",
"First\n"
] | Consider the first sample test. Each player has a box with 2 balls. The first player draws a single ball from his box in one move and the second player can either take 1 or 2 balls from his box in one move. No matter how the first player acts, the second player can always win if he plays wisely. | 3 | [
{
"input": "2 2 1 2",
"output": "Second"
},
{
"input": "2 1 1 1",
"output": "First"
},
{
"input": "5 7 4 1",
"output": "Second"
},
{
"input": "5 7 1 4",
"output": "Second"
},
{
"input": "5 7 10 10",
"output": "Second"
},
{
"input": "5 7 1 10",
"out... | 1,577,535,844 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 109 | 307,200 | def solve(n1, n2, k1, k2):
if n1 > n2:
return "First"
else:
return "Second"
def main():
n1, n2, k1, k2 = list(map(int, input().split()))
print(solve(n1, n2, k1, k2))
main()
| Title: Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two players play a simple game. Each player is provided with a box with balls. First player's box contains exactly *n*1 balls and second player's box contains exactly *n*2 balls. In one move first player can take from 1 to *k*1 ba... | ```python
def solve(n1, n2, k1, k2):
if n1 > n2:
return "First"
else:
return "Second"
def main():
n1, n2, k1, k2 = list(map(int, input().split()))
print(solve(n1, n2, k1, k2))
main()
``` | 3 | |
794 | A | Bank Robbery | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and steal some money from the safes. There are many safes arranged in a line, where the *i*-th safe f... | The first line of input contains three space-separated integers, *a*, *b* and *c* (1<=≤<=*b*<=<<=*a*<=<<=*c*<=≤<=109), denoting the positions of Oleg, the first security guard and the second security guard, respectively.
The next line of input contains a single integer *n* (1<=≤<=*n*<=≤<=105), denoting the numbe... | Output a single integer: the maximum number of banknotes Oleg can take. | [
"5 3 7\n8\n4 7 5 5 3 6 2 8\n",
"6 5 7\n5\n1 5 7 92 3\n"
] | [
"4\n",
"0\n"
] | In the first example Oleg can take the banknotes in positions 4, 5, 6 (note that there are 2 banknotes at position 5). Oleg can't take the banknotes in safes 7 and 8 because he can't run into the second security guard. Similarly, Oleg cannot take the banknotes at positions 3 and 2 because he can't run into the first se... | 500 | [
{
"input": "5 3 7\n8\n4 7 5 5 3 6 2 8",
"output": "4"
},
{
"input": "6 5 7\n5\n1 5 7 92 3",
"output": "0"
},
{
"input": "3 2 4\n1\n3",
"output": "1"
},
{
"input": "5 3 8\n12\n8 3 4 5 7 6 8 3 5 4 7 6",
"output": "8"
},
{
"input": "7 3 10\n5\n3 3 3 3 3",
"output... | 1,571,512,499 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 156 | 8,396,800 | a, b, c = map(int, input().split())
input()
all_cells = map(int, input().split())
cells = [x for x in all_cells if b < x < c]
print(len(cells)) | Title: Bank Robbery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and... | ```python
a, b, c = map(int, input().split())
input()
all_cells = map(int, input().split())
cells = [x for x in all_cells if b < x < c]
print(len(cells))
``` | 3 | |
94 | A | Restoring Password | PROGRAMMING | 900 | [
"implementation",
"strings"
] | A. Restoring Password | 2 | 256 | Igor K. always used to trust his favorite Kashpirovsky Antivirus. That is why he didn't hesitate to download the link one of his groupmates sent him via QIP Infinium. The link was said to contain "some real funny stuff about swine influenza". The antivirus had no objections and Igor K. run the flash application he had ... | The input data contains 11 lines. The first line represents the binary code 80 characters in length. That is the code written in Igor K.'s ISQ account's info. Next 10 lines contain pairwise distinct binary codes 10 characters in length, corresponding to numbers 0, 1, ..., 9. | Print one line containing 8 characters — The password to Igor K.'s ISQ account. It is guaranteed that the solution exists. | [
"01001100100101100000010110001001011001000101100110010110100001011010100101101100\n0100110000\n0100110010\n0101100000\n0101100010\n0101100100\n0101100110\n0101101000\n0101101010\n0101101100\n0101101110\n",
"10101101111001000010100100011010101101110010110111011000100011011110010110001000\n1001000010\n1101111001\n1... | [
"12345678\n",
"30234919\n"
] | none | 500 | [
{
"input": "01001100100101100000010110001001011001000101100110010110100001011010100101101100\n0100110000\n0100110010\n0101100000\n0101100010\n0101100100\n0101100110\n0101101000\n0101101010\n0101101100\n0101101110",
"output": "12345678"
},
{
"input": "1010110111100100001010010001101010110111001011011... | 1,406,679,800 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 124 | 0 | p = input()
num = {}
for i in range(10):
num[input()] = i
out = ''
for i in range(0,len(p),10):
part = p[i:i+10]
out += str(num[part])
print(out)
| Title: Restoring Password
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Igor K. always used to trust his favorite Kashpirovsky Antivirus. That is why he didn't hesitate to download the link one of his groupmates sent him via QIP Infinium. The link was said to contain "some real funny stuff a... | ```python
p = input()
num = {}
for i in range(10):
num[input()] = i
out = ''
for i in range(0,len(p),10):
part = p[i:i+10]
out += str(num[part])
print(out)
``` | 3.969 |
946 | A | Partition | PROGRAMMING | 800 | [
"greedy"
] | null | null | You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of elements belonging to *b*, and *C* be the sum of elements belonging to *c* (if some of these sequenc... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (<=-<=100<=≤<=*a**i*<=≤<=100) — the elements of sequence *a*. | Print the maximum possible value of *B*<=-<=*C*, where *B* is the sum of elements of sequence *b*, and *C* is the sum of elements of sequence *c*. | [
"3\n1 -2 0\n",
"6\n16 23 16 15 42 8\n"
] | [
"3\n",
"120\n"
] | In the first example we may choose *b* = {1, 0}, *c* = { - 2}. Then *B* = 1, *C* = - 2, *B* - *C* = 3.
In the second example we choose *b* = {16, 23, 16, 15, 42, 8}, *c* = {} (an empty sequence). Then *B* = 120, *C* = 0, *B* - *C* = 120. | 0 | [
{
"input": "3\n1 -2 0",
"output": "3"
},
{
"input": "6\n16 23 16 15 42 8",
"output": "120"
},
{
"input": "1\n-1",
"output": "1"
},
{
"input": "100\n-100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -10... | 1,578,050,659 | 2,147,483,647 | Python 3 | OK | TESTS | 72 | 124 | 0 | if __name__ == '__main__':
# n, a, b = map(int, input().split())
n = int(input())
arrs = map(int, input().split())
b = []
c = []
for num in arrs:
if num >= 0:
b.append(num)
else:
c.append(num)
print(sum(b) - sum(c))
| Title: Partition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of eleme... | ```python
if __name__ == '__main__':
# n, a, b = map(int, input().split())
n = int(input())
arrs = map(int, input().split())
b = []
c = []
for num in arrs:
if num >= 0:
b.append(num)
else:
c.append(num)
print(sum(b) - sum(c))
... | 3 | |
340 | A | The Wall | PROGRAMMING | 1,200 | [
"math"
] | null | null | Iahub and his friend Floyd have started painting a wall. Iahub is painting the wall red and Floyd is painting it pink. You can consider the wall being made of a very large number of bricks, numbered 1, 2, 3 and so on.
Iahub has the following scheme of painting: he skips *x*<=-<=1 consecutive bricks, then he paints th... | The input will have a single line containing four integers in this order: *x*, *y*, *a*, *b*. (1<=≤<=*x*,<=*y*<=≤<=1000, 1<=≤<=*a*,<=*b*<=≤<=2·109, *a*<=≤<=*b*). | Output a single integer — the number of bricks numbered no less than *a* and no greater than *b* that are painted both red and pink. | [
"2 3 6 18\n"
] | [
"3"
] | Let's look at the bricks from *a* to *b* (*a* = 6, *b* = 18). The bricks colored in red are numbered 6, 8, 10, 12, 14, 16, 18. The bricks colored in pink are numbered 6, 9, 12, 15, 18. The bricks colored in both red and pink are numbered with 6, 12 and 18. | 500 | [
{
"input": "2 3 6 18",
"output": "3"
},
{
"input": "4 6 20 201",
"output": "15"
},
{
"input": "15 27 100 10000",
"output": "74"
},
{
"input": "105 60 3456 78910",
"output": "179"
},
{
"input": "1 1 1000 100000",
"output": "99001"
},
{
"input": "3 2 5 5... | 1,520,522,438 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 124 | 5,632,000 | def gcd(a,b):
while b:
a,b=b,a%b
return a
x,y,a,b=map(int,input().split())
k=(x*y)//gcd(x,y)
m=int(a%k==0)
print((b//k)-(a//k)+m) | Title: The Wall
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub and his friend Floyd have started painting a wall. Iahub is painting the wall red and Floyd is painting it pink. You can consider the wall being made of a very large number of bricks, numbered 1, 2, 3 and so on.
Iahub ... | ```python
def gcd(a,b):
while b:
a,b=b,a%b
return a
x,y,a,b=map(int,input().split())
k=(x*y)//gcd(x,y)
m=int(a%k==0)
print((b//k)-(a//k)+m)
``` | 3 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,685,167,878 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 0 | target = int(input())
multiplier = 1
index = 0
q = ["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"]
while target > 0:
index = 0
for i in range(5):
target -= multiplier
if target <= 0:
break
index += 1
multiplier *= 2
print(q[index])
| Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
target = int(input())
multiplier = 1
index = 0
q = ["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"]
while target > 0:
index = 0
for i in range(5):
target -= multiplier
if target <= 0:
break
index += 1
multiplier *= 2
print(q[index])
... | 3.977 |
959 | A | Mahmoud and Ehab and the even-odd game | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a* and subtract it from *n* such that:
- 1<=≤<=*a*<=≤<=*n*. - If it's Mahmoud's turn, *a* has to be even, but if it's Ehab'... | The only line contains an integer *n* (1<=≤<=*n*<=≤<=109), the number at the beginning of the game. | Output "Mahmoud" (without quotes) if Mahmoud wins and "Ehab" (without quotes) otherwise. | [
"1\n",
"2\n"
] | [
"Ehab",
"Mahmoud"
] | In the first sample, Mahmoud can't choose any integer *a* initially because there is no positive even integer less than or equal to 1 so Ehab wins.
In the second sample, Mahmoud has to choose *a* = 2 and subtract it from *n*. It's Ehab's turn and *n* = 0. There is no positive odd integer less than or equal to 0 so Mah... | 500 | [
{
"input": "1",
"output": "Ehab"
},
{
"input": "2",
"output": "Mahmoud"
},
{
"input": "10000",
"output": "Mahmoud"
},
{
"input": "33333",
"output": "Ehab"
},
{
"input": "5",
"output": "Ehab"
},
{
"input": "1000000000",
"output": "Mahmoud"
},
{
... | 1,631,613,761 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 62 | 7,065,600 | #!/usr/bin/env python
import sys, math, itertools
if __name__ == '__main__':
wtf = sys.stdin.read()
wtf = wtf.strip().split('\n')
n = int(wtf[0])
ans = ["Mahmoud", "Ehab"]
ct = 0
while n > 0:
if ct == 0:
if n % 2 == 0:
print(ans[ct])
break
else:
if n - 2 > 0:
n -= 2
... | Title: Mahmoud and Ehab and the even-odd game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a*... | ```python
#!/usr/bin/env python
import sys, math, itertools
if __name__ == '__main__':
wtf = sys.stdin.read()
wtf = wtf.strip().split('\n')
n = int(wtf[0])
ans = ["Mahmoud", "Ehab"]
ct = 0
while n > 0:
if ct == 0:
if n % 2 == 0:
print(ans[ct])
break
else:
if n - 2 > 0:
n ... | 3 | |
278 | A | Circle Line | PROGRAMMING | 800 | [
"implementation"
] | null | null | The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations:
- *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd and the 3-rd station;...- *d**n*<=-<=1 is the distance between the *n*<=-<=1-th and the *n*-th ... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — the number of stations on the circle line. The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (1<=≤<=*d**i*<=≤<=100) — the distances between pairs of neighboring stations. The third line contains two integers *s* and *t* (1<=≤<=*s*,<=*t*<=≤<=*n*) —... | Print a single number — the length of the shortest path between stations number *s* and *t*. | [
"4\n2 3 4 9\n1 3\n",
"4\n5 8 2 100\n4 1\n",
"3\n1 1 1\n3 1\n",
"3\n31 41 59\n1 1\n"
] | [
"5\n",
"15\n",
"1\n",
"0\n"
] | In the first sample the length of path 1 → 2 → 3 equals 5, the length of path 1 → 4 → 3 equals 13.
In the second sample the length of path 4 → 1 is 100, the length of path 4 → 3 → 2 → 1 is 15.
In the third sample the length of path 3 → 1 is 1, the length of path 3 → 2 → 1 is 2.
In the fourth sample the numbers of st... | 500 | [
{
"input": "4\n2 3 4 9\n1 3",
"output": "5"
},
{
"input": "4\n5 8 2 100\n4 1",
"output": "15"
},
{
"input": "3\n1 1 1\n3 1",
"output": "1"
},
{
"input": "3\n31 41 59\n1 1",
"output": "0"
},
{
"input": "5\n16 13 10 30 15\n4 2",
"output": "23"
},
{
"inpu... | 1,496,867,069 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 124 | 0 | x = int(input())
y = list(map(int, input().split()))
a, b = sorted(list(map(int, input().split())))
ab = sum(y[a-1:b-1])
ba = sum(y) - ab
if ab < ba:
print(ab)
else:
print(ba) | Title: Circle Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations:
- *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd... | ```python
x = int(input())
y = list(map(int, input().split()))
a, b = sorted(list(map(int, input().split())))
ab = sum(y[a-1:b-1])
ba = sum(y) - ab
if ab < ba:
print(ab)
else:
print(ba)
``` | 3 | |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
I... | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**... | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,604,312,145 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 109 | 614,400 | n , m = map(int,input().split())
b1 = []
for i in range (n):
a = input().split()
for j in a[1:]:
b1.append(j)
b2 = list(set(b1))
if m == len(b2):
print('YES')
else:
print('NO') | Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is... | ```python
n , m = map(int,input().split())
b1 = []
for i in range (n):
a = input().split()
for j in a[1:]:
b1.append(j)
b2 = list(set(b1))
if m == len(b2):
print('YES')
else:
print('NO')
``` | 3 | |
75 | A | Life Without Zeros | PROGRAMMING | 1,000 | [
"implementation"
] | A. Life Without Zeros | 2 | 256 | Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c*... | The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. | The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. | [
"101\n102\n",
"105\n106\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "101\n102",
"output": "YES"
},
{
"input": "105\n106",
"output": "NO"
},
{
"input": "544\n397",
"output": "YES"
},
{
"input": "822\n280",
"output": "NO"
},
{
"input": "101\n413",
"output": "NO"
},
{
"input": "309\n139",
"output": "NO"
}... | 1,663,485,859 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 92 | 0 | n=int(input())
k=int(input())
p=n+k
a=b=c=''
n=str(n)
for i in n:
if i!='0':
a+=i
k=str(k)
for i in k:
if i!='0':
b+=i
q=str(p)
for i in q:
if i!='0':
c+=i
if int(a)+int(b)==int(c):
print('YES')
else:
print('NO') | Title: Life Without Zeros
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assu... | ```python
n=int(input())
k=int(input())
p=n+k
a=b=c=''
n=str(n)
for i in n:
if i!='0':
a+=i
k=str(k)
for i in k:
if i!='0':
b+=i
q=str(p)
for i in q:
if i!='0':
c+=i
if int(a)+int(b)==int(c):
print('YES')
else:
print('NO')
``` | 3.977 |
294 | C | Shaass and Lights | PROGRAMMING | 1,900 | [
"combinatorics",
"number theory"
] | null | null | There are *n* lights aligned in a row. These lights are numbered 1 to *n* from left to right. Initially some of the lights are switched on. Shaass wants to switch all the lights on. At each step he can switch a light on (this light should be switched off at that moment) if there's at least one adjacent light which is a... | The first line of the input contains two integers *n* and *m* where *n* is the number of lights in the sequence and *m* is the number of lights which are initially switched on, (1<=≤<=*n*<=≤<=1000,<=1<=≤<=*m*<=≤<=*n*). The second line contains *m* distinct integers, each between 1 to *n* inclusive, denoting the indices... | In the only line of the output print the number of different possible ways to switch on all the lights modulo 1000000007 (109<=+<=7). | [
"3 1\n1\n",
"4 2\n1 4\n",
"11 2\n4 8\n"
] | [
"1\n",
"2\n",
"6720\n"
] | none | 1,500 | [
{
"input": "3 1\n1",
"output": "1"
},
{
"input": "4 2\n1 4",
"output": "2"
},
{
"input": "11 2\n4 8",
"output": "6720"
},
{
"input": "4 2\n1 3",
"output": "2"
},
{
"input": "4 4\n1 2 3 4",
"output": "1"
},
{
"input": "4 2\n1 3",
"output": "2"
},
... | 1,603,178,099 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 140 | 1,638,400 | M= 1000000007
f = [1]*2000
for i in range(1,2000):
f[i]=f[i-1]*i%M
n,m = map(int,input().split())
a = sorted(map(int,input().split()))
b = []
for i in range (1,m):
x=a[i]-a[i-1]-1
if(x>0):
b.append(x)
count = pow(2,sum(b)-len(b),M)*f[n-m]%M
b = [a[0]-1]+b+[n-a[-1]]
for i in b:
count =... | Title: Shaass and Lights
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* lights aligned in a row. These lights are numbered 1 to *n* from left to right. Initially some of the lights are switched on. Shaass wants to switch all the lights on. At each step he can switch a light ... | ```python
M= 1000000007
f = [1]*2000
for i in range(1,2000):
f[i]=f[i-1]*i%M
n,m = map(int,input().split())
a = sorted(map(int,input().split()))
b = []
for i in range (1,m):
x=a[i]-a[i-1]-1
if(x>0):
b.append(x)
count = pow(2,sum(b)-len(b),M)*f[n-m]%M
b = [a[0]-1]+b+[n-a[-1]]
for i in b:... | 3 | |
544 | A | Set of Strings | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | You are given a string *q*. A sequence of *k* strings *s*1,<=*s*2,<=...,<=*s**k* is called beautiful, if the concatenation of these strings is string *q* (formally, *s*1<=+<=*s*2<=+<=...<=+<=*s**k*<==<=*q*) and the first characters of these strings are distinct.
Find any beautiful sequence of strings or determine that... | The first line contains a positive integer *k* (1<=≤<=*k*<=≤<=26) — the number of strings that should be in a beautiful sequence.
The second line contains string *q*, consisting of lowercase Latin letters. The length of the string is within range from 1 to 100, inclusive. | If such sequence doesn't exist, then print in a single line "NO" (without the quotes). Otherwise, print in the first line "YES" (without the quotes) and in the next *k* lines print the beautiful sequence of strings *s*1,<=*s*2,<=...,<=*s**k*.
If there are multiple possible answers, print any of them. | [
"1\nabca\n",
"2\naaacas\n",
"4\nabc\n"
] | [
"YES\nabca\n",
"YES\naaa\ncas\n",
"NO\n"
] | In the second sample there are two possible answers: {"*aaaca*", "*s*"} and {"*aaa*", "*cas*"}. | 500 | [
{
"input": "1\nabca",
"output": "YES\nabca"
},
{
"input": "2\naaacas",
"output": "YES\naaa\ncas"
},
{
"input": "4\nabc",
"output": "NO"
},
{
"input": "3\nnddkhkhkdndknndkhrnhddkrdhrnrrnkkdnnndndrdhnknknhnrnnkrrdhrkhkrkhnkhkhhrhdnrndnknrrhdrdrkhdrkkhkrnkk",
"output": "YES\... | 1,618,139,215 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 93 | 0 | n = int(input())
s = input()
arr = set(list(s))
if len(arr) < n:
print("NO")
else:
ans = []
d = {}
for i in s:
if i in d:
ans[-1] += i
else:
d[i] = 1
ans.append(i)
print("YES")
for i in ans[:n-1]:
print(i)
... | Title: Set of Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *q*. A sequence of *k* strings *s*1,<=*s*2,<=...,<=*s**k* is called beautiful, if the concatenation of these strings is string *q* (formally, *s*1<=+<=*s*2<=+<=...<=+<=*s**k*<==<=*q*) and the first... | ```python
n = int(input())
s = input()
arr = set(list(s))
if len(arr) < n:
print("NO")
else:
ans = []
d = {}
for i in s:
if i in d:
ans[-1] += i
else:
d[i] = 1
ans.append(i)
print("YES")
for i in ans[:n-1]:
p... | 3 | |
439 | B | Devu, the Dumb Guy | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Devu is a dumb guy, his learning curve is very slow. You are supposed to teach him *n* subjects, the *i**th* subject has *c**i* chapters. When you teach him, you are supposed to teach all the chapters of a subject continuously.
Let us say that his initial per chapter learning power of a subject is *x* hours. In other ... | The first line will contain two space separated integers *n*, *x* (1<=≤<=*n*,<=*x*<=≤<=105). The next line will contain *n* space separated integers: *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=105). | Output a single integer representing the answer to the problem. | [
"2 3\n4 1\n",
"4 2\n5 1 2 1\n",
"3 3\n1 1 1\n"
] | [
"11\n",
"10\n",
"6\n"
] | Look at the first example. Consider the order of subjects: 1, 2. When you teach Devu the first subject, it will take him 3 hours per chapter, so it will take 12 hours to teach first subject. After teaching first subject, his per chapter learning time will be 2 hours. Now teaching him second subject will take 2 × 1 = 2 ... | 1,000 | [
{
"input": "2 3\n4 1",
"output": "11"
},
{
"input": "4 2\n5 1 2 1",
"output": "10"
},
{
"input": "3 3\n1 1 1",
"output": "6"
},
{
"input": "20 4\n1 1 3 5 5 1 3 4 2 5 2 4 3 1 3 3 3 3 4 3",
"output": "65"
},
{
"input": "20 10\n6 6 1 2 6 4 5 3 6 5 4 5 6 5 4 6 6 2 3 3... | 1,559,319,141 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 187 | 7,372,800 | n,x = [int(i) for i in input().split()]
arr = sorted([int(i) for i in input().split()])
ans = 0
for i in arr:
if x>1:
ans+=i*x
x-=1
else:
ans+=i
print(ans) | Title: Devu, the Dumb Guy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a dumb guy, his learning curve is very slow. You are supposed to teach him *n* subjects, the *i**th* subject has *c**i* chapters. When you teach him, you are supposed to teach all the chapters of a subject co... | ```python
n,x = [int(i) for i in input().split()]
arr = sorted([int(i) for i in input().split()])
ans = 0
for i in arr:
if x>1:
ans+=i*x
x-=1
else:
ans+=i
print(ans)
``` | 3 | |
658 | A | Bear and Reverse Radewoosh | PROGRAMMING | 800 | [
"implementation"
] | null | null | Limak and Radewoosh are going to compete against each other in the upcoming algorithmic contest. They are equally skilled but they won't solve problems in the same order.
There will be *n* problems. The *i*-th problem has initial score *p**i* and it takes exactly *t**i* minutes to solve it. Problems are sorted by diff... | The first line contains two integers *n* and *c* (1<=≤<=*n*<=≤<=50,<=1<=≤<=*c*<=≤<=1000) — the number of problems and the constant representing the speed of loosing points.
The second line contains *n* integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=1000,<=*p**i*<=<<=*p**i*<=+<=1) — initial scores.
The third... | Print "Limak" (without quotes) if Limak will get more points in total. Print "Radewoosh" (without quotes) if Radewoosh will get more points in total. Print "Tie" (without quotes) if Limak and Radewoosh will get the same total number of points. | [
"3 2\n50 85 250\n10 15 25\n",
"3 6\n50 85 250\n10 15 25\n",
"8 1\n10 20 30 40 50 60 70 80\n8 10 58 63 71 72 75 76\n"
] | [
"Limak\n",
"Radewoosh\n",
"Tie\n"
] | In the first sample, there are 3 problems. Limak solves them as follows:
1. Limak spends 10 minutes on the 1-st problem and he gets 50 - *c*·10 = 50 - 2·10 = 30 points. 1. Limak spends 15 minutes on the 2-nd problem so he submits it 10 + 15 = 25 minutes after the start of the contest. For the 2-nd problem he gets 85... | 500 | [
{
"input": "3 2\n50 85 250\n10 15 25",
"output": "Limak"
},
{
"input": "3 6\n50 85 250\n10 15 25",
"output": "Radewoosh"
},
{
"input": "8 1\n10 20 30 40 50 60 70 80\n8 10 58 63 71 72 75 76",
"output": "Tie"
},
{
"input": "4 1\n3 5 6 9\n1 2 4 8",
"output": "Limak"
},
{... | 1,566,913,202 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 109 | 0 | # import sys
# sys.stdin=open("input.in","r")
# sys.stdout=open("output.out","w")
a,b=map(int,input().split())
i=list(map(int,input().split()))
j=list(map(int,input().split()))
Limak,Radewoosh,d,e=0,0,0,0
for x in range(a):
d+=j[x]
Limak+=max(0,(i[x]-d*b))
e+=j[a-1-x]
Radewoosh+=max(0,(i[a-1-x]-e*b))
... | Title: Bear and Reverse Radewoosh
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak and Radewoosh are going to compete against each other in the upcoming algorithmic contest. They are equally skilled but they won't solve problems in the same order.
There will be *n* problems. The *i*-... | ```python
# import sys
# sys.stdin=open("input.in","r")
# sys.stdout=open("output.out","w")
a,b=map(int,input().split())
i=list(map(int,input().split()))
j=list(map(int,input().split()))
Limak,Radewoosh,d,e=0,0,0,0
for x in range(a):
d+=j[x]
Limak+=max(0,(i[x]-d*b))
e+=j[a-1-x]
Radewoosh+=max(0,(i[a-1-... | 3 | |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,666,328,140 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 96 | 451 | 2,252,800 | n,k=map(int,input().split())
def divisors(n):
lower,upper=[],[]
i=1
while i*i<=n:
if n%i==0:
lower.append(i)
if i!=n//i:
upper.append(n//i)
i+=1
return lower+upper[::-1]
d=divisors(n)
if len(d)>=k:
print(d[k-1])
else:
print(-1) | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
n,k=map(int,input().split())
def divisors(n):
lower,upper=[],[]
i=1
while i*i<=n:
if n%i==0:
lower.append(i)
if i!=n//i:
upper.append(n//i)
i+=1
return lower+upper[::-1]
d=divisors(n)
if len(d)>=k:
print(d[k-1])
else:
print(-1)
``` | 3 | |
520 | A | Pangram | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
You are given a string consisting of lowercase and uppercase Latin letters. Check whether thi... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of characters in the string.
The second line contains the string. The string consists only of uppercase and lowercase Latin letters. | Output "YES", if the string is a pangram and "NO" otherwise. | [
"12\ntoosmallword\n",
"35\nTheQuickBrownFoxJumpsOverTheLazyDog\n"
] | [
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "12\ntoosmallword",
"output": "NO"
},
{
"input": "35\nTheQuickBrownFoxJumpsOverTheLazyDog",
"output": "YES"
},
{
"input": "1\na",
"output": "NO"
},
{
"input": "26\nqwertyuiopasdfghjklzxcvbnm",
"output": "YES"
},
{
"input": "26\nABCDEFGHIJKLMNOPQRSTUVWXY... | 1,696,589,196 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 46 | 0 | n = int(input())
print(('NO', 'YES')[len({x for x in input().lower()}) == 26])
| Title: Pangram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
... | ```python
n = int(input())
print(('NO', 'YES')[len({x for x in input().lower()}) == 26])
``` | 3 | |
56 | A | Bar | PROGRAMMING | 1,000 | [
"implementation"
] | A. Bar | 2 | 256 | According to Berland laws it is only allowed to sell alcohol to people not younger than 18 years. Vasya's job is to monitor the law's enforcement. Tonight he entered a bar and saw *n* people sitting there. For every one of them Vasya happened to determine either the age or the drink the person is having. Vasya can chec... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) which is the number of the bar's clients. Then follow *n* lines, each describing one visitor. A line either contains his age (an integer from 0 to 1000) or his drink (a string of capital Latin letters from 1 to 100 in length). It is guaranteed that the input da... | Print a single number which is the number of people Vasya should check to guarantee the law enforcement. | [
"5\n18\nVODKA\nCOKE\n19\n17\n"
] | [
"2\n"
] | In the sample test the second and fifth clients should be checked. | 500 | [
{
"input": "5\n18\nVODKA\nCOKE\n19\n17",
"output": "2"
},
{
"input": "2\n2\nGIN",
"output": "2"
},
{
"input": "3\nWHISKEY\n3\nGIN",
"output": "3"
},
{
"input": "4\n813\nIORBQITQXMPTFAEMEQDQIKFGKGOTNKTOSZCBRPXJLUKVLVHJYNRUJXK\nRUM\nRHVRWGODYWWTYZFLFYKCVUFFRTQDINKNWPKFHZBFWBHWI... | 1,544,429,792 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 216 | 0 | alc = ['ABSINTH', 'BEER', 'BRANDY', 'CHAMPAGNE', 'GIN', 'RUM', 'SAKE', 'TEQUILA', 'VODKA', 'WHISKEY', 'WINE']
numb = []
for i in range(1001):
numb.append(str(i))
n = int(input())
ans = []
count = 0
for i in range(n):
z = input()
if z in alc:
count+=1
if z in numb:
if int(z)<18:
... | Title: Bar
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
According to Berland laws it is only allowed to sell alcohol to people not younger than 18 years. Vasya's job is to monitor the law's enforcement. Tonight he entered a bar and saw *n* people sitting there. For every one of them Vasya h... | ```python
alc = ['ABSINTH', 'BEER', 'BRANDY', 'CHAMPAGNE', 'GIN', 'RUM', 'SAKE', 'TEQUILA', 'VODKA', 'WHISKEY', 'WINE']
numb = []
for i in range(1001):
numb.append(str(i))
n = int(input())
ans = []
count = 0
for i in range(n):
z = input()
if z in alc:
count+=1
if z in numb:
if int(z... | 3.946 |
465 | A | inc ARG | PROGRAMMING | 900 | [
"implementation"
] | null | null | Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of *n* bits. These bits are numbered from 1 to *n*. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of bits in the cell.
The second line contains a string consisting of *n* characters — the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significan... | Print a single integer — the number of bits in the cell which change their state after we add 1 to the cell. | [
"4\n1100\n",
"4\n1111\n"
] | [
"3\n",
"4\n"
] | In the first sample the cell ends up with value 0010, in the second sample — with 0000. | 500 | [
{
"input": "4\n1100",
"output": "3"
},
{
"input": "4\n1111",
"output": "4"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "1"
},
{
"input": "2\n01",
"output": "1"
},
{
"input": "2\n1... | 1,586,939,779 | 2,147,483,647 | PyPy 3 | OK | TESTS | 29 | 155 | 0 | t=int(input())
s=input()
l=int(s[::-1],2)+1
h=bin(l)[::-1]
w=h[:-2]
p=0
q=len(w)
for k in range(t):
if k<= q-1:
if w[k]!= s[k]:
p+=1
else:
pass
if k< t-1:
print(p+ t-q)
else:
print(p)
| Title: inc ARG
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of *n* bits. These bits are numbered from 1 to *n*. An integer is stored in the cell in the following way: the lea... | ```python
t=int(input())
s=input()
l=int(s[::-1],2)+1
h=bin(l)[::-1]
w=h[:-2]
p=0
q=len(w)
for k in range(t):
if k<= q-1:
if w[k]!= s[k]:
p+=1
else:
pass
if k< t-1:
print(p+ t-q)
else:
print(p)
``` | 3 | |
366 | B | Dima and To-do List | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | You helped Dima to have a great weekend, but it's time to work. Naturally, Dima, as all other men who have girlfriends, does everything wrong.
Inna and Dima are now in one room. Inna tells Dima off for everything he does in her presence. After Inna tells him off for something, she goes to another room, walks there in ... | The first line of the input contains two integers *n*,<=*k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103), where *a**i* is the power Inna tells Dima off with if she is present in the room while he is doing the *i*-th task.
It is guaranteed that *n*... | In a single line print the number of the task Dima should start with to get told off with as little power as possible. If there are multiple solutions, print the one with the minimum number of the first task to do. | [
"6 2\n3 2 1 6 5 4\n",
"10 5\n1 3 5 7 9 9 4 1 8 5\n"
] | [
"1\n",
"3\n"
] | Explanation of the first example.
If Dima starts from the first task, Inna tells him off with power 3, then Dima can do one more task (as *k* = 2), then Inna tells him off for the third task with power 1, then she tells him off for the fifth task with power 5. Thus, Dima gets told off with total power 3 + 1 + 5 = 9. I... | 1,000 | [
{
"input": "6 2\n3 2 1 6 5 4",
"output": "1"
},
{
"input": "10 5\n1 3 5 7 9 9 4 1 8 5",
"output": "3"
},
{
"input": "20 4\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "1"
},
{
"input": "10 10\n8 4 5 7 6 9 2 2 3 5",
"output": "7"
},
{
"input": "50 10\n1 2 3... | 1,690,638,526 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 77 | 13,414,400 | def main():
n, k = map(int, input().split())
a = [0] * k
l=list(map(int,input().split()))
for i in range(n):
a[i % k] += l[i]
m = 0
for i in range(1, k):
if a[i] < a[m]:
m = i
print(m + 1)
if __name__ == "__main__":
main()
| Title: Dima and To-do List
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You helped Dima to have a great weekend, but it's time to work. Naturally, Dima, as all other men who have girlfriends, does everything wrong.
Inna and Dima are now in one room. Inna tells Dima off for everything h... | ```python
def main():
n, k = map(int, input().split())
a = [0] * k
l=list(map(int,input().split()))
for i in range(n):
a[i % k] += l[i]
m = 0
for i in range(1, k):
if a[i] < a[m]:
m = i
print(m + 1)
if __name__ == "__main__":
main()
``` | 3 | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,636,648,206 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 62 | 4,300,800 | first_number = input()
second_number = input()
result_number = ""
for i in range(len(first_number)):
if(first_number[i] != second_number[i]):
result_number+="1"
elif(first_number[i] == second_number[i]):
result_number+="0"
print(result_number)
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
first_number = input()
second_number = input()
result_number = ""
for i in range(len(first_number)):
if(first_number[i] != second_number[i]):
result_number+="1"
elif(first_number[i] == second_number[i]):
result_number+="0"
print(result_number)
``` | 3.976489 |
611 | A | New Year and Days | PROGRAMMING | 900 | [
"implementation"
] | null | null | Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming year 2016.
Limak wants to prove how responsible a bear he is. He is going to regularly save candies for ... | The only line of the input is in one of the following two formats:
- "*x* of week" where *x* (1<=≤<=*x*<=≤<=7) denotes the day of the week. The 1-st day is Monday and the 7-th one is Sunday. - "*x* of month" where *x* (1<=≤<=*x*<=≤<=31) denotes the day of the month. | Print one integer — the number of candies Limak will save in the year 2016. | [
"4 of week\n",
"30 of month\n"
] | [
"52\n",
"11\n"
] | Polar bears use the Gregorian calendar. It is the most common calendar and you likely use it too. You can read about it on Wikipedia if you want to – [https://en.wikipedia.org/wiki/Gregorian_calendar](https://en.wikipedia.org/wiki/Gregorian_calendar). The week starts with Monday.
In the first sample Limak wants to sav... | 500 | [
{
"input": "4 of week",
"output": "52"
},
{
"input": "30 of month",
"output": "11"
},
{
"input": "17 of month",
"output": "12"
},
{
"input": "31 of month",
"output": "7"
},
{
"input": "6 of week",
"output": "53"
},
{
"input": "1 of week",
"output":... | 1,520,869,028 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 77 | 6,348,800 | l=[0,52,52,52,52,53,53,52]
m=[31,29,31,30,31,30,31,31,30,31,30,31]
a,b,c=map(str,input().split())
if c=='week':
print(l[int(a)])
if c=='month':
count=0
for i in range(len(m)):
if int(a) in range(1,m[i]+1):
count+=1
print(count)
| Title: New Year and Days
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming ye... | ```python
l=[0,52,52,52,52,53,53,52]
m=[31,29,31,30,31,30,31,31,30,31,30,31]
a,b,c=map(str,input().split())
if c=='week':
print(l[int(a)])
if c=='month':
count=0
for i in range(len(m)):
if int(a) in range(1,m[i]+1):
count+=1
print(count)
``` | 3 | |
452 | A | Eevee | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"strings"
] | null | null | You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight different pokemons: Vaporeon, Jolteon, Flareon, Espeon, Umbreon, Leafeon, Glaceon, and Syl... | First line contains an integer *n* (6<=≤<=*n*<=≤<=8) – the length of the string.
Next line contains a string consisting of *n* characters, each of which is either a lower case english letter (indicating a known letter) or a dot character (indicating an empty cell in the crossword). | Print a name of the pokemon that Eevee can evolve into that matches the pattern in the input. Use lower case letters only to print the name (in particular, do not capitalize the first letter). | [
"7\nj......\n",
"7\n...feon\n",
"7\n.l.r.o.\n"
] | [
"jolteon\n",
"leafeon\n",
"flareon\n"
] | Here's a set of names in a form you can paste into your solution:
["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
{"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"} | 500 | [
{
"input": "7\n...feon",
"output": "leafeon"
},
{
"input": "7\n.l.r.o.",
"output": "flareon"
},
{
"input": "6\n.s..o.",
"output": "espeon"
},
{
"input": "7\nglaceon",
"output": "glaceon"
},
{
"input": "8\n.a.o.e.n",
"output": "vaporeon"
},
{
"input": "... | 1,438,678,877 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 62 | 0 | a = ["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
n = input()
s = input()
res = ""
for k in a:
if len(k) == len(s):
cnt = 0
for i in range(len(s)):
if (k[i] == s[i]) or (s[i] == '.'):
cnt+=1
if cnt == len(s):
... | Title: Eevee
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight... | ```python
a = ["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
n = input()
s = input()
res = ""
for k in a:
if len(k) == len(s):
cnt = 0
for i in range(len(s)):
if (k[i] == s[i]) or (s[i] == '.'):
cnt+=1
if cnt == ... | 3 | |
414 | B | Mashmokh and ACM | PROGRAMMING | 1,400 | [
"combinatorics",
"dp",
"number theory"
] | null | null | Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced prog... | The first line of input contains two space-separated integers *n*,<=*k* (1<=≤<=*n*,<=*k*<=≤<=2000). | Output a single integer — the number of good sequences of length *k* modulo 1000000007 (109<=+<=7). | [
"3 2\n",
"6 4\n",
"2 1\n"
] | [
"5\n",
"39\n",
"2\n"
] | In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3]. | 1,000 | [
{
"input": "3 2",
"output": "5"
},
{
"input": "6 4",
"output": "39"
},
{
"input": "2 1",
"output": "2"
},
{
"input": "1478 194",
"output": "312087753"
},
{
"input": "1415 562",
"output": "953558593"
},
{
"input": "1266 844",
"output": "735042656"
... | 1,628,088,947 | 2,147,483,647 | PyPy 3 | OK | TESTS | 65 | 967 | 29,593,600 | n,k=map(int,input().split())# se reciben los datos n y k
lista=[] # se nombra la lista donde se guardaran en cada posicion el numero de combinaciones al ubicar en la primera posicion de la secuemcia el numero n
for i in range(n+1): # inicialmente se guarda 1 que es el nunmero que genera al ubicar cadan en la primera... | Title: Mashmokh and ACM
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join h... | ```python
n,k=map(int,input().split())# se reciben los datos n y k
lista=[] # se nombra la lista donde se guardaran en cada posicion el numero de combinaciones al ubicar en la primera posicion de la secuemcia el numero n
for i in range(n+1): # inicialmente se guarda 1 que es el nunmero que genera al ubicar cadan en ... | 3 | |
583 | B | Robot's Task | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The computers are equipped with a security system, so to crack the *i*-th of them, the robot needs to colle... | The first line contains number *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*n*), separated by a space. It is guaranteed that there exists a way for robot to collect all pieces of the information. | Print a single number — the minimum number of changes in direction that the robot will have to make in order to collect all *n* parts of information. | [
"3\n0 2 0\n",
"5\n4 2 3 0 1\n",
"7\n0 3 1 0 5 2 6\n"
] | [
"1\n",
"3\n",
"2\n"
] | In the first sample you can assemble all the pieces of information in the optimal manner by assembling first the piece of information in the first computer, then in the third one, then change direction and move to the second one, and then, having 2 pieces of information, collect the last piece.
In the second sample to... | 1,000 | [
{
"input": "3\n0 2 0",
"output": "1"
},
{
"input": "5\n4 2 3 0 1",
"output": "3"
},
{
"input": "7\n0 3 1 0 5 2 6",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n0 1",
"output": "0"
},
{
"input": "10\n0 0 0 0 0 0 0 0 0 0",
"out... | 1,590,215,416 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 280 | 307,200 | n=int(input())
a=list(map(int,input().split()))
info=0; i=0; di=0
while 1:
for i in range(n):
if a[i]==-69: continue
if a[i]<=info:
info+=1
a[i]=-69
if info==n: break
a.reverse()
di+=1
print(di) | Title: Robot's Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The compu... | ```python
n=int(input())
a=list(map(int,input().split()))
info=0; i=0; di=0
while 1:
for i in range(n):
if a[i]==-69: continue
if a[i]<=info:
info+=1
a[i]=-69
if info==n: break
a.reverse()
di+=1
print(di)
``` | 3 | |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. E... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match di... | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,511,090,494 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 124 | 5,529,600 | n = int(input())
i = 1
team = []
while i <= n:
team.append(input())
i += 1
print(max(set(team),key = team.count)) | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process... | ```python
n = int(input())
i = 1
team = []
while i <= n:
team.append(input())
i += 1
print(max(set(team),key = team.count))
``` | 3.9587 |
620 | A | Professor GukiZ's Robot | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of them) by one (decrease or increase). So the robot can move in one of the 8 directions. Find the minimal numbe... | The first line contains two integers *x*1,<=*y*1 (<=-<=109<=≤<=*x*1,<=*y*1<=≤<=109) — the start position of the robot.
The second line contains two integers *x*2,<=*y*2 (<=-<=109<=≤<=*x*2,<=*y*2<=≤<=109) — the finish position of the robot. | Print the only integer *d* — the minimal number of steps to get the finish position. | [
"0 0\n4 5\n",
"3 4\n6 1\n"
] | [
"5\n",
"3\n"
] | In the first example robot should increase both of its coordinates by one four times, so it will be in position (4, 4). After that robot should simply increase its *y* coordinate and get the finish position.
In the second example robot should simultaneously increase *x* coordinate and decrease *y* coordinate by one th... | 0 | [
{
"input": "0 0\n4 5",
"output": "5"
},
{
"input": "3 4\n6 1",
"output": "3"
},
{
"input": "0 0\n4 6",
"output": "6"
},
{
"input": "1 1\n-3 -5",
"output": "6"
},
{
"input": "-1 -1\n-10 100",
"output": "101"
},
{
"input": "1 -1\n100 -100",
"output":... | 1,620,991,295 | 2,147,483,647 | Python 3 | OK | TESTS | 75 | 77 | 6,758,400 | x1,y1=input().split()
x2,y2=input().split()
x1=int(x1)
y1=int(y1)
x2=int(x2)
y2=int(y2)
print(max(abs(y2-y1),abs(x2-x1))) | Title: Professor GukiZ's Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of ... | ```python
x1,y1=input().split()
x2,y2=input().split()
x1=int(x1)
y1=int(y1)
x2=int(x2)
y2=int(y2)
print(max(abs(y2-y1),abs(x2-x1)))
``` | 3 | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,675,449,489 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 46 | 4,300,800 | a, b = map(int, input().split())
n = min(a, b)
m = (max(a, b) - n) // 2
print(n, m) | Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
a, b = map(int, input().split())
n = min(a, b)
m = (max(a, b) - n) // 2
print(n, m)
``` | 3 | |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution.... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second numbe... | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't ta... | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,697,699,029 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | probs = []
nprobs = int(input())
for i in range(nprobs):
assurance = input()
probs.append(assurance)
n = 0
for j in probs:
if j.count("1") >= 2:
n += 1
print(n) | Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decid... | ```python
probs = []
nprobs = int(input())
for i in range(nprobs):
assurance = input()
probs.append(assurance)
n = 0
for j in probs:
if j.count("1") >= 2:
n += 1
print(n)
``` | 3 | |
810 | A | Straight <<A>> | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
In school, where Noora is studying, teachers are putting down marks to the online class register, wh... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100) denoting the number of marks, received by Noora and the value of highest possible mark.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*k*) denoting marks received by Noora before Leha's hack. | Print a single integer — minimal number of additional marks, that Leha has to add in order to change Noora's final mark to *k*. | [
"2 10\n8 9\n",
"3 5\n4 4 4\n"
] | [
"4",
"3"
] | Consider the first example testcase.
Maximal mark is 10, Noora received two marks — 8 and 9, so current final mark is 9. To fix it, Leha can add marks [10, 10, 10, 10] (4 marks in total) to the registry, achieving Noora having average mark equal to <img align="middle" class="tex-formula" src="https://espresso.codeforc... | 500 | [
{
"input": "2 10\n8 9",
"output": "4"
},
{
"input": "3 5\n4 4 4",
"output": "3"
},
{
"input": "3 10\n10 8 9",
"output": "3"
},
{
"input": "2 23\n21 23",
"output": "2"
},
{
"input": "5 10\n5 10 10 9 10",
"output": "7"
},
{
"input": "12 50\n18 10 26 22 2... | 1,604,367,277 | 2,147,483,647 | Python 3 | OK | TESTS | 106 | 109 | 307,200 | n, k = map(int, input().split())
a = [int(i)for i in input().split()]
a = sum(a)
x = 0
i = 0
while k-a/(n+x) > 0.5:
i+=1
a+=k*i
x+=i
if k-a/(n+x) <= 0.5:
a-=k*i
x-=i
break
while k-a/(n+x) > 0.5:
a+=k
x+=1
print(x) | Title: Straight <<A>>
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
... | ```python
n, k = map(int, input().split())
a = [int(i)for i in input().split()]
a = sum(a)
x = 0
i = 0
while k-a/(n+x) > 0.5:
i+=1
a+=k*i
x+=i
if k-a/(n+x) <= 0.5:
a-=k*i
x-=i
break
while k-a/(n+x) > 0.5:
a+=k
x+=1
print(x)
``` | 3 | |
106 | B | Choosing Laptop | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | B. Choosing Laptop | 2 | 256 | Vasya is choosing a laptop. The shop has *n* laptops to all tastes.
Vasya is interested in the following properties: processor speed, ram and hdd. Vasya is a programmer and not a gamer which is why he is not interested in all other properties.
If all three properties of a laptop are strictly less than those propertie... | The first line contains number *n* (1<=≤<=*n*<=≤<=100).
Then follow *n* lines. Each describes a laptop as *speed* *ram* *hdd* *cost*. Besides,
- *speed*, *ram*, *hdd* and *cost* are integers - 1000<=≤<=*speed*<=≤<=4200 is the processor's speed in megahertz - 256<=≤<=*ram*<=≤<=4096 the RAM volume in megabytes - 1... | Print a single number — the number of a laptop Vasya will choose. The laptops are numbered with positive integers from 1 to *n* in the order in which they are given in the input data. | [
"5\n2100 512 150 200\n2000 2048 240 350\n2300 1024 200 320\n2500 2048 80 300\n2000 512 180 150\n"
] | [
"4"
] | In the third sample Vasya considers the first and fifth laptops outdated as all of their properties cannot match those of the third laptop. The fourth one is the cheapest among the laptops that are left. Thus, Vasya chooses the fourth laptop. | 1,000 | [
{
"input": "5\n2100 512 150 200\n2000 2048 240 350\n2300 1024 200 320\n2500 2048 80 300\n2000 512 180 150",
"output": "4"
},
{
"input": "2\n1500 500 50 755\n1600 600 80 700",
"output": "2"
},
{
"input": "2\n1500 512 50 567\n1600 400 70 789",
"output": "1"
},
{
"input": "4\n10... | 1,636,217,466 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 122 | 4,505,600 | def compare(l1, l2):
for i in range(3):
if l1[i]>=l2[i]:
return False
return True
n = int(input())
laptop = []
outdated = [False]*n
for i in range(n):
laptop.append(list(map(int, input().split())))
for i in range(n):
for j in range(n):
if compare(laptop[i], ... | Title: Choosing Laptop
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is choosing a laptop. The shop has *n* laptops to all tastes.
Vasya is interested in the following properties: processor speed, ram and hdd. Vasya is a programmer and not a gamer which is why he is not interested in ... | ```python
def compare(l1, l2):
for i in range(3):
if l1[i]>=l2[i]:
return False
return True
n = int(input())
laptop = []
outdated = [False]*n
for i in range(n):
laptop.append(list(map(int, input().split())))
for i in range(n):
for j in range(n):
if compare(l... | 3.961108 |
141 | A | Amusing Joke | PROGRAMMING | 800 | [
"implementation",
"sortings",
"strings"
] | null | null | So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name and the host's name in honor of this event. Then the hung the letters above the main entrance. O... | The input file consists of three lines: the first line contains the guest's name, the second line contains the name of the residence host and the third line contains letters in a pile that were found at the door in the morning. All lines are not empty and contain only uppercase Latin letters. The length of each line do... | Print "YES" without the quotes, if the letters in the pile could be permuted to make the names of the "New Year and Christmas Men". Otherwise, print "NO" without the quotes. | [
"SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS\n",
"PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI\n",
"BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | In the first sample the letters written in the last line can be used to write the names and there won't be any extra letters left.
In the second sample letter "P" is missing from the pile and there's an extra letter "L".
In the third sample there's an extra letter "L". | 500 | [
{
"input": "SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS",
"output": "YES"
},
{
"input": "PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI",
"output": "NO"
},
{
"input": "BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER",
"output": "NO"
},
{
"input": "B\nA\nAB",
"output": ... | 1,691,585,138 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 92 | 0 | def main():
alpha_length = 26
first = [0] * alpha_length
second = [0] * alpha_length
line = input().strip()
for char in line:
first[ord(char) - ord('A')] += 1
line = input().strip()
for char in line:
first[ord(char) - ord('A')] += 1
line = input().strip()
... | Title: Amusing Joke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's nam... | ```python
def main():
alpha_length = 26
first = [0] * alpha_length
second = [0] * alpha_length
line = input().strip()
for char in line:
first[ord(char) - ord('A')] += 1
line = input().strip()
for char in line:
first[ord(char) - ord('A')] += 1
line = input(... | 3 | |
877 | B | Nikita and string | PROGRAMMING | 1,500 | [
"brute force",
"dp"
] | null | null | One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st and the 3-rd one contain only letters "a" and the 2-nd contains only letters "b".
Nikita wants to make... | The first line contains a non-empty string of length not greater than 5<=000 containing only lowercase English letters "a" and "b". | Print a single integer — the maximum possible size of beautiful string Nikita can get. | [
"abba\n",
"bab\n"
] | [
"4",
"2"
] | It the first sample the string is already beautiful.
In the second sample he needs to delete one of "b" to make it beautiful. | 1,000 | [
{
"input": "abba",
"output": "4"
},
{
"input": "bab",
"output": "2"
},
{
"input": "bbabbbaabbbb",
"output": "9"
},
{
"input": "bbabbbbbaaba",
"output": "10"
},
{
"input": "bbabbbababaa",
"output": "9"
},
{
"input": "aabbaababbab",
"output": "8"
}... | 1,604,178,349 | 1,549 | PyPy 3 | OK | TESTS | 46 | 170 | 2,355,200 | s = input()
n = len(s)
dp = []
dp.append((0, 0, 0))
for i in range(n):
if s[i] == 'a':
dp.append((dp[-1][0] + 1, dp[-1][1], max(dp[-1][1:]) + 1))
elif s[i] == 'b':
dp.append((dp[-1][0], max(dp[-1][1], dp[-1][0]) + 1, dp[-1][-1]))
print(max(dp[-1])) | Title: Nikita and string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st ... | ```python
s = input()
n = len(s)
dp = []
dp.append((0, 0, 0))
for i in range(n):
if s[i] == 'a':
dp.append((dp[-1][0] + 1, dp[-1][1], max(dp[-1][1:]) + 1))
elif s[i] == 'b':
dp.append((dp[-1][0], max(dp[-1][1], dp[-1][0]) + 1, dp[-1][-1]))
print(max(dp[-1]))
``` | 3 | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,698,396,637 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 61 | 0 | x = int(input())
i = 1
while x//2 > 0:
if x % 2 == 1: i += 1
x = x // 2
print(i) | Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
x = int(input())
i = 1
while x//2 > 0:
if x % 2 == 1: i += 1
x = x // 2
print(i)
``` | 3 | |
230 | B | T-primes | PROGRAMMING | 1,300 | [
"binary search",
"implementation",
"math",
"number theory"
] | null | null | We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an array of *n* positive integers. For each of them determine whether it is Т-prime or not. | The first line contains a single positive integer, *n* (1<=≤<=*n*<=≤<=105), showing how many numbers are in the array. The next line contains *n* space-separated integers *x**i* (1<=≤<=*x**i*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout st... | Print *n* lines: the *i*-th line should contain "YES" (without the quotes), if number *x**i* is Т-prime, and "NO" (without the quotes), if it isn't. | [
"3\n4 5 6\n"
] | [
"YES\nNO\nNO\n"
] | The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO". | 500 | [
{
"input": "3\n4 5 6",
"output": "YES\nNO\nNO"
},
{
"input": "2\n48 49",
"output": "NO\nYES"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "NO\nYES\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO"
},
{
"input": "1\n36",
"output": "NO"
},
{
"input": "1\n999966000289",
"... | 1,697,542,610 | 2,147,483,647 | Python 3 | OK | TESTS | 68 | 1,560 | 22,323,200 | import math
n1 = 1000005
pa = [1]*(n1+1)
pa[0]= pa[1]= 0
for i in range(2, int(math.sqrt(n1)+1)):
if pa[i] == 1:
j =i
while i*j <= n1:
pa[i*j] = 0
j+=1
n = int(input())
arr = list(map(int, input().split()))
for i in range(n):
s = int(math.sqrt(arr[i]))
... | Title: T-primes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an ar... | ```python
import math
n1 = 1000005
pa = [1]*(n1+1)
pa[0]= pa[1]= 0
for i in range(2, int(math.sqrt(n1)+1)):
if pa[i] == 1:
j =i
while i*j <= n1:
pa[i*j] = 0
j+=1
n = int(input())
arr = list(map(int, input().split()))
for i in range(n):
s = int(math.sqrt(arr... | 3 | |
281 | A | Word Capitalization | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged. | A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103. | Output the given word after capitalization. | [
"ApPLe\n",
"konjac\n"
] | [
"ApPLe\n",
"Konjac\n"
] | none | 500 | [
{
"input": "ApPLe",
"output": "ApPLe"
},
{
"input": "konjac",
"output": "Konjac"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "A"
},
{
"input": "z",
"output": "Z"
},
{
"input": "ABACABA",
"output": "ABACABA"
},
{
"input": "... | 1,696,104,366 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 92 | 0 | word = input()
if word[0] >= 'a':
print(chr(ord(word[0]) - 32) + word[1:])
else:
print(word)
| Title: Word Capitalization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input... | ```python
word = input()
if word[0] >= 'a':
print(chr(ord(word[0]) - 32) + word[1:])
else:
print(word)
``` | 3 | |
888 | B | Buggy Robot | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the cell (*x*,<=*y*) to (*x*,<=*y*<=+<=1); - D — move from (*x*,<=*y*) to (*x*,<=*y*<=-<=1); - L — mo... | The first line contains one number *n* — the length of sequence of commands entered by Ivan (1<=≤<=*n*<=≤<=100).
The second line contains the sequence itself — a string consisting of *n* characters. Each character can be U, D, L or R. | Print the maximum possible number of commands from the sequence the robot could perform to end up in the starting cell. | [
"4\nLDUR\n",
"5\nRRRUU\n",
"6\nLLRRRR\n"
] | [
"4\n",
"0\n",
"4\n"
] | none | 0 | [
{
"input": "4\nLDUR",
"output": "4"
},
{
"input": "5\nRRRUU",
"output": "0"
},
{
"input": "6\nLLRRRR",
"output": "4"
},
{
"input": "88\nLLUUULRDRRURDDLURRLRDRLLRULRUUDDLLLLRRDDURDURRLDURRLDRRRUULDDLRRRDDRRLUULLURDURUDDDDDLDR",
"output": "76"
},
{
"input": "89\nLDL... | 1,604,055,830 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 108 | 0 |
n = int(input())
a = list(input())
x = y = 0
count = {}
for c in a:
if c not in count:
count[c] = 0
count[c] += 1
print(2*(min(count.get('L', 0), count.get('R', 0)) + min(count.get('U', 0), count.get('D', 0))))
| Title: Buggy Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the ce... | ```python
n = int(input())
a = list(input())
x = y = 0
count = {}
for c in a:
if c not in count:
count[c] = 0
count[c] += 1
print(2*(min(count.get('L', 0), count.get('R', 0)) + min(count.get('U', 0), count.get('D', 0))))
``` | 3 | |
176 | B | Word Cut | PROGRAMMING | 1,700 | [
"dp"
] | null | null | Let's consider one interesting word game. In this game you should transform one word into another through special operations.
Let's say we have word *w*, let's split this word into two non-empty parts *x* and *y* so, that *w*<==<=*xy*. A split operation is transforming word *w*<==<=*xy* into word *u*<==<=*yx*. For ex... | The first line contains a non-empty word *start*, the second line contains a non-empty word *end*. The words consist of lowercase Latin letters. The number of letters in word *start* equals the number of letters in word *end* and is at least 2 and doesn't exceed 1000 letters.
The third line contains integer *k* (0<=≤<... | Print a single number — the answer to the problem. As this number can be rather large, print it modulo 1000000007 (109<=+<=7). | [
"ab\nab\n2\n",
"ababab\nababab\n1\n",
"ab\nba\n2\n"
] | [
"1\n",
"2\n",
"0\n"
] | The sought way in the first sample is:
ab → a|b → ba → b|a → ab
In the second sample the two sought ways are:
- ababab → abab|ab → ababab - ababab → ab|abab → ababab | 1,000 | [
{
"input": "ab\nab\n2",
"output": "1"
},
{
"input": "ababab\nababab\n1",
"output": "2"
},
{
"input": "ab\nba\n2",
"output": "0"
},
{
"input": "aaa\naaa\n0",
"output": "1"
},
{
"input": "hi\nhi\n1",
"output": "0"
},
{
"input": "abcd\ncbad\n5",
"outp... | 1,687,496,487 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 90 | 810 | 2,662,400 | import sys
input = lambda:sys.stdin.readline().strip()
M = lambda:map(int,input().split())
from collections import deque
inf = float('inf')
mod = 10**9+7
a = input()
a += a
b = input()
n = len(b)
k = int(input())
bo = [0]*n
for i in range(n):
if a[i:i+n] == b:
bo[i] = 1
res = [0]*n
res[0] = ... | Title: Word Cut
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider one interesting word game. In this game you should transform one word into another through special operations.
Let's say we have word *w*, let's split this word into two non-empty parts *x* and *y* so, that *w... | ```python
import sys
input = lambda:sys.stdin.readline().strip()
M = lambda:map(int,input().split())
from collections import deque
inf = float('inf')
mod = 10**9+7
a = input()
a += a
b = input()
n = len(b)
k = int(input())
bo = [0]*n
for i in range(n):
if a[i:i+n] == b:
bo[i] = 1
res = [0]*n
... | 3 | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*... | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,699,720,612 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 93 | 512,000 | n = int(input())
str = input().strip()
a = str.count("A")
d = str.count("D")
if (a>d):
print("Anton")
elif(d>a):
print("Danik")
else:
print("Friendship") | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, w... | ```python
n = int(input())
str = input().strip()
a = str.count("A")
d = str.count("D")
if (a>d):
print("Anton")
elif(d>a):
print("Danik")
else:
print("Friendship")
``` | 3 | |
16 | A | Flag | PROGRAMMING | 800 | [
"implementation"
] | A. Flag | 2 | 64 | According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of the same colour, and the colours of adjacent horizontal rows should be different. Be... | The first line of the input contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), *n* — the amount of rows, *m* — the amount of columns on the flag of Berland. Then there follows the description of the flag: each of the following *n* lines contain *m* characters. Each character is a digit between 0 and 9, and stands ... | Output YES, if the flag meets the new ISO standard, and NO otherwise. | [
"3 3\n000\n111\n222\n",
"3 3\n000\n000\n111\n",
"3 3\n000\n111\n002\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 0 | [
{
"input": "3 3\n000\n111\n222",
"output": "YES"
},
{
"input": "3 3\n000\n000\n111",
"output": "NO"
},
{
"input": "3 3\n000\n111\n002",
"output": "NO"
},
{
"input": "10 10\n2222222222\n5555555555\n0000000000\n4444444444\n1111111111\n3333333393\n3333333333\n5555555555\n0000000... | 1,643,724,781 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | def solve():
n, m = map(int,input().split())
arr = [set(input()) for x in range(n)]
curr = '#'
for x in arr:
if len(x) != 1 or x == curr:
return 'NO'
curr = x
return 'YES'
print(solve())
| Title: Flag
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of... | ```python
def solve():
n, m = map(int,input().split())
arr = [set(input()) for x in range(n)]
curr = '#'
for x in arr:
if len(x) != 1 or x == curr:
return 'NO'
curr = x
return 'YES'
print(solve())
``` | 3.977 |
142 | B | Help General | PROGRAMMING | 1,800 | [
"constructive algorithms",
"greedy",
"implementation"
] | null | null | Once upon a time in the Kingdom of Far Far Away lived Sir Lancelot, the chief Royal General. He was very proud of his men and he liked to invite the King to come and watch drill exercises which demonstrated the fighting techniques and tactics of the squad he was in charge of. But time went by and one day Sir Lancelot h... | The single line contains space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) that represent the size of the drill exercise field. | Print the desired maximum number of warriors. | [
"2 4\n",
"3 4\n"
] | [
"4",
"6"
] | In the first sample test Sir Lancelot can place his 4 soldiers on the 2 × 4 court as follows (the soldiers' locations are marked with gray circles on the scheme):
In the second sample test he can place 6 soldiers on the 3 × 4 site in the following manner: | 1,000 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 4",
"output": "6"
},
{
"input": "4 4",
"output": "8"
},
{
"input": "4 3",
"output": "6"
},
{
"input": "4 2",
"output": "4"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "3 5",
"output"... | 1,514,028,752 | 2,147,483,647 | PyPy 3 | OK | TESTS | 103 | 218 | 23,142,400 | n, m = sorted(map(int, input().split()))
k = 4 * (m >> 2)
print(m if n == 1 else k + 2 * min(2, m - k) if n == 2 else (m * n + 1 >> 1)) | Title: Help General
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once upon a time in the Kingdom of Far Far Away lived Sir Lancelot, the chief Royal General. He was very proud of his men and he liked to invite the King to come and watch drill exercises which demonstrated the fighting te... | ```python
n, m = sorted(map(int, input().split()))
k = 4 * (m >> 2)
print(m if n == 1 else k + 2 * min(2, m - k) if n == 2 else (m * n + 1 >> 1))
``` | 3 | |
851 | A | Arpa and a research in Mexican wave | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Arpa is researching the Mexican wave.
There are *n* spectators in the stadium, labeled from 1 to *n*. They start the Mexican wave at time 0.
- At time 1, the first spectator stands. - At time 2, the second spectator stands. - ... - At time *k*, the *k*-th spectator stands. - At time *k*<=+<=1, the (*k*<=+<=1)-t... | The first line contains three integers *n*, *k*, *t* (1<=≤<=*n*<=≤<=109, 1<=≤<=*k*<=≤<=*n*, 1<=≤<=*t*<=<<=*n*<=+<=*k*). | Print single integer: how many spectators are standing at time *t*. | [
"10 5 3\n",
"10 5 7\n",
"10 5 12\n"
] | [
"3\n",
"5\n",
"3\n"
] | In the following a sitting spectator is represented as -, a standing spectator is represented as ^.
- At *t* = 0 ---------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spe... | 500 | [
{
"input": "10 5 3",
"output": "3"
},
{
"input": "10 5 7",
"output": "5"
},
{
"input": "10 5 12",
"output": "3"
},
{
"input": "840585600 770678331 788528791",
"output": "770678331"
},
{
"input": "25462281 23343504 8024619",
"output": "8024619"
},
{
"in... | 1,585,719,888 | 2,147,483,647 | PyPy 3 | OK | TESTS | 166 | 140 | 0 | #-------------Program--------------
#----Kuzlyaev-Nikita-Codeforces----
#-------------Training-------------
#----------------------------------
n,k,t=map(int,input().split())
if t<=k:print(t)
elif t>=n:print(n+k-t)
else:
print(k) | Title: Arpa and a research in Mexican wave
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arpa is researching the Mexican wave.
There are *n* spectators in the stadium, labeled from 1 to *n*. They start the Mexican wave at time 0.
- At time 1, the first spectator stands. - At time 2,... | ```python
#-------------Program--------------
#----Kuzlyaev-Nikita-Codeforces----
#-------------Training-------------
#----------------------------------
n,k,t=map(int,input().split())
if t<=k:print(t)
elif t>=n:print(n+k-t)
else:
print(k)
``` | 3 | |
299 | B | Ksusha the Squirrel | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to the end of the road, that is, get to sector *n*. Unfortunately, there are some rocks on the road. We know ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=3·105,<=1<=≤<=*k*<=≤<=3·105). The next line contains *n* characters — the description of the road: the *i*-th character equals ".", if the *i*-th sector contains no rocks. Otherwise, it equals "#".
It is guaranteed that the first and the last characters e... | Print "YES" (without the quotes) if Ksusha can reach the end of the road, otherwise print "NO" (without the quotes). | [
"2 1\n..\n",
"5 2\n.#.#.\n",
"7 3\n.#.###.\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 1,000 | [
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "5 2\n.#.#.",
"output": "YES"
},
{
"input": "7 3\n.#.###.",
"output": "NO"
},
{
"input": "2 200\n..",
"output": "YES"
},
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "2 2\n..",
"output": "Y... | 1,660,297,965 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 218 | 819,200 | n, m = map(int, input(). split())
s = input()
ans = 'YES'
d = 0
for i in range(n):
if s[i] == '#':
d += 1
else:
if d >= m:
ans = 'NO'
break
d = 0
print(ans)
| Title: Ksusha the Squirrel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to t... | ```python
n, m = map(int, input(). split())
s = input()
ans = 'YES'
d = 0
for i in range(n):
if s[i] == '#':
d += 1
else:
if d >= m:
ans = 'NO'
break
d = 0
print(ans)
``` | 3 | |
928 | A | Login Verification | PROGRAMMING | 1,200 | [
"*special",
"strings"
] | null | null | When registering in a social network, users are allowed to create their own convenient login to make it easier to share contacts, print it on business cards, etc.
Login is an arbitrary sequence of lower and uppercase latin letters, digits and underline symbols («_»). However, in order to decrease the number of frauds ... | The first line contains a non-empty string *s* consisting of lower and uppercase latin letters, digits and underline symbols («_») with length not exceeding 50 — the login itself.
The second line contains a single integer *n* (1<=≤<=*n*<=≤<=1<=000) — the number of existing logins.
The next *n* lines describe the exi... | Print «Yes» (without quotes), if user can register via this login, i.e. none of the existing logins is similar with it.
Otherwise print «No» (without quotes). | [
"1_wat\n2\n2_wat\nwat_1\n",
"000\n3\n00\nooA\noOo\n",
"_i_\n3\n__i_\n_1_\nI\n",
"La0\n3\n2a0\nLa1\n1a0\n",
"abc\n1\naBc\n",
"0Lil\n2\nLIL0\n0Ril\n"
] | [
"Yes\n",
"No\n",
"No\n",
"No\n",
"No\n",
"Yes\n"
] | In the second sample case the user wants to create a login consisting of three zeros. It's impossible due to collision with the third among the existing.
In the third sample case the new login is similar with the second one. | 500 | [
{
"input": "1_wat\n2\n2_wat\nwat_1",
"output": "Yes"
},
{
"input": "000\n3\n00\nooA\noOo",
"output": "No"
},
{
"input": "_i_\n3\n__i_\n_1_\nI",
"output": "No"
},
{
"input": "La0\n3\n2a0\nLa1\n1a0",
"output": "No"
},
{
"input": "abc\n1\naBc",
"output": "No"
}... | 1,519,489,781 | 3,281 | Python 3 | OK | TESTS | 73 | 77 | 5,632,000 | def checkEquals( a , b):
if a == b :
return True
if a == b.upper() or b == a.upper():
return True
if (a == '0' or a == 'O' or a == 'o') and (b == '0' or b == 'O' or b == 'o') :
return True
if (a == '1' or a == 'i' or a == 'I' or a == 'l' or a == 'L') and (b == '1' or b... | Title: Login Verification
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When registering in a social network, users are allowed to create their own convenient login to make it easier to share contacts, print it on business cards, etc.
Login is an arbitrary sequence of lower and uppercas... | ```python
def checkEquals( a , b):
if a == b :
return True
if a == b.upper() or b == a.upper():
return True
if (a == '0' or a == 'O' or a == 'o') and (b == '0' or b == 'O' or b == 'o') :
return True
if (a == '1' or a == 'i' or a == 'I' or a == 'l' or a == 'L') and (b =... | 3 | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,695,898,708 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 124 | 0 | import sys
n = int(sys.stdin.readline().strip())
h_count = {}
g_count = {}
for _ in range(n):
h, g = list(map(int, sys.stdin.readline().strip().split()))
h_count[h] = h_count.get(h, 0) + 1
g_count[g] = g_count.get(g, 0) + 1
ans = 0
for h, h_num in h_count.items():
if h in g_count:
... | Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
import sys
n = int(sys.stdin.readline().strip())
h_count = {}
g_count = {}
for _ in range(n):
h, g = list(map(int, sys.stdin.readline().strip().split()))
h_count[h] = h_count.get(h, 0) + 1
g_count[g] = g_count.get(g, 0) + 1
ans = 0
for h, h_num in h_count.items():
if h in g_c... | 3 | |
165 | A | Supercentral Point | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the given set (*x*,<=*y*):
- point (*x*',<=*y*') is (*x*,<=*y*)'s right neighbor, if *x*'<=><=*x* and *y*'... | The first input line contains the only integer *n* (1<=≤<=*n*<=≤<=200) — the number of points in the given set. Next *n* lines contain the coordinates of the points written as "*x* *y*" (without the quotes) (|*x*|,<=|*y*|<=≤<=1000), all coordinates are integers. The numbers in the line are separated by exactly one spac... | Print the only number — the number of supercentral points of the given set. | [
"8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3\n",
"5\n0 0\n0 1\n1 0\n0 -1\n-1 0\n"
] | [
"2\n",
"1\n"
] | In the first sample the supercentral points are only points (1, 1) and (1, 2).
In the second sample there is one supercental point — point (0, 0). | 500 | [
{
"input": "8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3",
"output": "2"
},
{
"input": "5\n0 0\n0 1\n1 0\n0 -1\n-1 0",
"output": "1"
},
{
"input": "9\n-565 -752\n-184 723\n-184 -752\n-184 1\n950 723\n-565 723\n950 -752\n950 1\n-565 1",
"output": "1"
},
{
"input": "25\n-651 897\n... | 1,589,200,134 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 248 | 7,065,600 | import sys
import collections
import math
import itertools as it
def readArray(type= int):
line = input()
return [type(x) for x in line.split()]
def solve():
n = int(input())
points = []
for x in range(n):
points.append(readArray())
xfreq = collections.defaultdict(lis... | Title: Supercentral Point
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the give... | ```python
import sys
import collections
import math
import itertools as it
def readArray(type= int):
line = input()
return [type(x) for x in line.split()]
def solve():
n = int(input())
points = []
for x in range(n):
points.append(readArray())
xfreq = collections.defau... | 3 | |
887 | A | Div. 64 | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some digits in such a way, that remaining number is a representation of some positive integer, divisi... | In the only line given a non-empty binary string *s* with length up to 100. | Print «yes» (without quotes) if it's possible to remove digits required way and «no» otherwise. | [
"100010001\n",
"100\n"
] | [
"yes",
"no"
] | In the first test case, you can get string 1 000 000 after removing two ones which is a representation of number 64 in the binary numerical system.
You can read more about binary numeral system representation here: [https://en.wikipedia.org/wiki/Binary_system](https://en.wikipedia.org/wiki/Binary_system) | 500 | [
{
"input": "100010001",
"output": "yes"
},
{
"input": "100",
"output": "no"
},
{
"input": "0000001000000",
"output": "yes"
},
{
"input": "1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111",
"output": "no"
},
{
"in... | 1,510,915,337 | 2,147,483,647 | Python 3 | OK | TESTS | 98 | 62 | 102,400 | n = input()
if '1' in n and n[n.index('1'):].count('0') >= 6:
print('yes')
else:
print('no')
| Title: Div. 64
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some dig... | ```python
n = input()
if '1' in n and n[n.index('1'):].count('0') >= 6:
print('yes')
else:
print('no')
``` | 3 | |
982 | B | Bus of Characters | PROGRAMMING | 1,300 | [
"data structures",
"greedy",
"implementation"
] | null | null | In the Bus of Characters there are $n$ rows of seat, each having $2$ seats. The width of both seats in the $i$-th row is $w_i$ centimeters. All integers $w_i$ are distinct.
Initially the bus is empty. On each of $2n$ stops one passenger enters the bus. There are two types of passengers:
- an introvert always choose... | The first line contains a single integer $n$ ($1 \le n \le 200\,000$) — the number of rows in the bus.
The second line contains the sequence of integers $w_1, w_2, \dots, w_n$ ($1 \le w_i \le 10^{9}$), where $w_i$ is the width of each of the seats in the $i$-th row. It is guaranteed that all $w_i$ are distinct.
The t... | Print $2n$ integers — the rows the passengers will take. The order of passengers should be the same as in input. | [
"2\n3 1\n0011\n",
"6\n10 8 9 11 13 5\n010010011101\n"
] | [
"2 1 1 2 \n",
"6 6 2 3 3 1 4 4 1 2 5 5 \n"
] | In the first example the first passenger (introvert) chooses the row $2$, because it has the seats with smallest width. The second passenger (introvert) chooses the row $1$, because it is the only empty row now. The third passenger (extrovert) chooses the row $1$, because it has exactly one occupied seat and the seat w... | 1,000 | [
{
"input": "2\n3 1\n0011",
"output": "2 1 1 2 "
},
{
"input": "6\n10 8 9 11 13 5\n010010011101",
"output": "6 6 2 3 3 1 4 4 1 2 5 5 "
},
{
"input": "1\n1\n01",
"output": "1 1 "
},
{
"input": "1\n1000000\n01",
"output": "1 1 "
},
{
"input": "2\n1 1000000\n0011",
... | 1,624,894,334 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 1,185 | 30,720,000 | n=int(input())
i=iter(sorted(zip(map(int,input().split()),range(1,n+1))))
s,o=[],[]
for c in input():
if c=='0':
x=next(i)[1];o+=[x];s+=[x]
else:o.append(s.pop())
print(*o)
| Title: Bus of Characters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the Bus of Characters there are $n$ rows of seat, each having $2$ seats. The width of both seats in the $i$-th row is $w_i$ centimeters. All integers $w_i$ are distinct.
Initially the bus is empty. On each of $2n$... | ```python
n=int(input())
i=iter(sorted(zip(map(int,input().split()),range(1,n+1))))
s,o=[],[]
for c in input():
if c=='0':
x=next(i)[1];o+=[x];s+=[x]
else:o.append(s.pop())
print(*o)
``` | 3 | |
483 | A | Counterexample | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"math",
"number theory"
] | null | null | Your friend has recently learned about coprime numbers. A pair of numbers {*a*,<=*b*} is called coprime if the maximum number that divides both *a* and *b* is equal to one.
Your friend often comes up with different statements. He has recently supposed that if the pair (*a*,<=*b*) is coprime and the pair (*b*,<=*c*) i... | The single line contains two positive space-separated integers *l*, *r* (1<=≤<=*l*<=≤<=*r*<=≤<=1018; *r*<=-<=*l*<=≤<=50). | Print three positive space-separated integers *a*, *b*, *c* — three distinct numbers (*a*,<=*b*,<=*c*) that form the counterexample. If there are several solutions, you are allowed to print any of them. The numbers must be printed in ascending order.
If the counterexample does not exist, print the single number -1. | [
"2 4\n",
"10 11\n",
"900000000000000009 900000000000000029\n"
] | [
"2 3 4\n",
"-1\n",
"900000000000000009 900000000000000010 900000000000000021\n"
] | In the first sample pair (2, 4) is not coprime and pairs (2, 3) and (3, 4) are.
In the second sample you cannot form a group of three distinct integers, so the answer is -1.
In the third sample it is easy to see that numbers 900000000000000009 and 900000000000000021 are divisible by three. | 500 | [
{
"input": "2 4",
"output": "2 3 4"
},
{
"input": "10 11",
"output": "-1"
},
{
"input": "900000000000000009 900000000000000029",
"output": "900000000000000009 900000000000000010 900000000000000021"
},
{
"input": "640097987171091791 640097987171091835",
"output": "64009798... | 1,624,281,464 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 62 | 0 | a, c = map(int, input().split(" "))
if a & 1 == 0:
if a+1 >= c:
print(-1)
else:
print(a, a+1, a+2)
else:
if a+2 >= c:
print(-1)
else:
print(a+1, a+2, a+3)
| Title: Counterexample
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend has recently learned about coprime numbers. A pair of numbers {*a*,<=*b*} is called coprime if the maximum number that divides both *a* and *b* is equal to one.
Your friend often comes up with different st... | ```python
a, c = map(int, input().split(" "))
if a & 1 == 0:
if a+1 >= c:
print(-1)
else:
print(a, a+1, a+2)
else:
if a+2 >= c:
print(-1)
else:
print(a+1, a+2, a+3)
``` | 3 | |
864 | B | Polycarp and Letters | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"strings"
] | null | null | Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string *s* consisting only of lowercase and uppercase Latin letters.
Let *A* be a set of positions in the string. Let's call it pretty if following conditions are met:
- letters on positions from *A* in the string are all distinct and lowerc... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=200) — length of string *s*.
The second line contains a string *s* consisting of lowercase and uppercase Latin letters. | Print maximum number of elements in pretty set of positions for string *s*. | [
"11\naaaaBaabAbA\n",
"12\nzACaAbbaazzC\n",
"3\nABC\n"
] | [
"2\n",
"3\n",
"0\n"
] | In the first example the desired positions might be 6 and 8 or 7 and 8. Positions 6 and 7 contain letters 'a', position 8 contains letter 'b'. The pair of positions 1 and 8 is not suitable because there is an uppercase letter 'B' between these position.
In the second example desired positions can be 7, 8 and 11. There... | 1,000 | [
{
"input": "11\naaaaBaabAbA",
"output": "2"
},
{
"input": "12\nzACaAbbaazzC",
"output": "3"
},
{
"input": "3\nABC",
"output": "0"
},
{
"input": "1\na",
"output": "1"
},
{
"input": "2\naz",
"output": "2"
},
{
"input": "200\nXbTJZqcbpYuZQEoUrbxlPXAPCtVLr... | 1,521,486,387 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 93 | 7,065,600 | IL = lambda: list(map(int, input().split()))
IS = lambda: input().split()
I = lambda: int(input())
S = lambda: input()
n = I()
s = S()
for l in "QWERTYUIOPASDFGHJKLZXCVBNM":
s = s.replace(l, '#')
print(max([len(set(i)) for i in s.split('#')])) | Title: Polycarp and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string *s* consisting only of lowercase and uppercase Latin letters.
Let *A* be a set of positions in the string. Let's call it pretty if... | ```python
IL = lambda: list(map(int, input().split()))
IS = lambda: input().split()
I = lambda: int(input())
S = lambda: input()
n = I()
s = S()
for l in "QWERTYUIOPASDFGHJKLZXCVBNM":
s = s.replace(l, '#')
print(max([len(set(i)) for i in s.split('#')]))
``` | 3 | |
1,011 | B | Planning The Expedition | PROGRAMMING | 1,200 | [
"binary search",
"brute force",
"implementation"
] | null | null | Natasha is planning an expedition to Mars for $n$ people. One of the important tasks is to provide food for each participant.
The warehouse has $m$ daily food packages. Each package has some food type $a_i$.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat t... | The first line contains two integers $n$ and $m$ ($1 \le n \le 100$, $1 \le m \le 100$) — the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers $a_1, a_2, \dots, a_m$ ($1 \le a_i \le 100$), where $a_i$ is the type of $i$-th food pac... | Print the single integer — the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0. | [
"4 10\n1 5 2 1 1 1 2 5 7 2\n",
"100 1\n1\n",
"2 5\n5 4 3 2 1\n",
"3 9\n42 42 42 42 42 42 42 42 42\n"
] | [
"2\n",
"0\n",
"1\n",
"3\n"
] | In the first example, Natasha can assign type $1$ food to the first participant, the same type $1$ to the second, type $5$ to the third and type $2$ to the fourth. In this case, the expedition can last for $2$ days, since each participant can get two food packages of his food type (there will be used $4$ packages of ty... | 1,000 | [
{
"input": "4 10\n1 5 2 1 1 1 2 5 7 2",
"output": "2"
},
{
"input": "100 1\n1",
"output": "0"
},
{
"input": "2 5\n5 4 3 2 1",
"output": "1"
},
{
"input": "3 9\n42 42 42 42 42 42 42 42 42",
"output": "3"
},
{
"input": "1 1\n100",
"output": "1"
},
{
"inp... | 1,696,055,970 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 46 | 0 | # LUOGU_RID: 126684742
a,b=map(int,input().split());b=input().split();c={}
for i in b:
if i in c:c[i]+=1
else:c[i]=1
b=1
while 1:
if sum(c[j]//b for j in c)<a:print(b-1);break
b+=1 | Title: Planning The Expedition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Natasha is planning an expedition to Mars for $n$ people. One of the important tasks is to provide food for each participant.
The warehouse has $m$ daily food packages. Each package has some food type $a_i$.
E... | ```python
# LUOGU_RID: 126684742
a,b=map(int,input().split());b=input().split();c={}
for i in b:
if i in c:c[i]+=1
else:c[i]=1
b=1
while 1:
if sum(c[j]//b for j in c)<a:print(b-1);break
b+=1
``` | 3 | |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make ... | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,696,009,912 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 |
import math
n = int(input())
print(int(math.ceil(n/5))) | Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2... | ```python
import math
n = int(input())
print(int(math.ceil(n/5)))
``` | 3 | |
1,011 | A | Stages | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | null | null | Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — concatenation of letters, which correspond to the stages.
There are $n$ stages available. The ro... | The first line of input contains two integers — $n$ and $k$ ($1 \le k \le n \le 50$) – the number of available stages and the number of stages to use in the rocket.
The second line contains string $s$, which consists of exactly $n$ lowercase Latin letters. Each letter defines a new stage, which can be used to build th... | Print a single integer — the minimal total weight of the rocket or -1, if it is impossible to build the rocket at all. | [
"5 3\nxyabd\n",
"7 4\nproblem\n",
"2 2\nab\n",
"12 1\nabaabbaaabbb\n"
] | [
"29",
"34",
"-1",
"1"
] | In the first example, the following rockets satisfy the condition:
- "adx" (weight is $1+4+24=29$);- "ady" (weight is $1+4+25=30$);- "bdx" (weight is $2+4+24=30$);- "bdy" (weight is $2+4+25=31$).
Rocket "adx" has the minimal weight, so the answer is $29$.
In the second example, target rocket is "belo". Its weight ... | 500 | [
{
"input": "5 3\nxyabd",
"output": "29"
},
{
"input": "7 4\nproblem",
"output": "34"
},
{
"input": "2 2\nab",
"output": "-1"
},
{
"input": "12 1\nabaabbaaabbb",
"output": "1"
},
{
"input": "50 13\nqwertyuiopasdfghjklzxcvbnmaaaaaaaaaaaaaaaaaaaaaaaa",
"output": ... | 1,564,940,744 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 124 | 0 | n,k=map(int,input().split())
s=list(map(ord,sorted(input())))
last=0
total=0
i=0
while i<n:
if s[i]>last+1:
total += s[i]-96
last = s[i]
k -= 1
if k==0:
break
i+=1
if i<n:
print(total)
else:
print(-1)
| Title: Stages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — conca... | ```python
n,k=map(int,input().split())
s=list(map(ord,sorted(input())))
last=0
total=0
i=0
while i<n:
if s[i]>last+1:
total += s[i]-96
last = s[i]
k -= 1
if k==0:
break
i+=1
if i<n:
print(total)
else:
print(-1)
``` | 3 | |
858 | A | k-rounding | PROGRAMMING | 1,100 | [
"brute force",
"math",
"number theory"
] | null | null | For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000. 30000 is the minimum integer such that it ends with 4 or more zeros and is divisible by 375.
W... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=8). | Print the *k*-rounding of *n*. | [
"375 4\n",
"10000 1\n",
"38101 0\n",
"123456789 8\n"
] | [
"30000\n",
"10000\n",
"38101\n",
"12345678900000000\n"
] | none | 750 | [
{
"input": "375 4",
"output": "30000"
},
{
"input": "10000 1",
"output": "10000"
},
{
"input": "38101 0",
"output": "38101"
},
{
"input": "123456789 8",
"output": "12345678900000000"
},
{
"input": "1 0",
"output": "1"
},
{
"input": "2 0",
"output":... | 1,615,269,152 | 2,147,483,647 | Python 3 | OK | TESTS | 96 | 62 | 0 | import math
a,b=input().split()
a=int(a)
b=int(b)
ab=1
for i in range(b):
ab=ab*10
print((ab//math.gcd(ab,a))*a)
| Title: k-rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000.... | ```python
import math
a,b=input().split()
a=int(a)
b=int(b)
ab=1
for i in range(b):
ab=ab*10
print((ab//math.gcd(ab,a))*a)
``` | 3 | |
215 | A | Bicycle Chain | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Vasya's bicycle chain drive consists of two parts: *n* stars are attached to the pedal axle, *m* stars are attached to the rear wheel axle. The chain helps to rotate the rear wheel by transmitting the pedal rotation.
We know that the *i*-th star on the pedal axle has *a**i* (0<=<<=*a*1<=<<=*a*2<=<<=...<=<<... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stars on the bicycle's pedal axle. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104) in the order of strict increasing.
The third input line contains integer *m* (1<=≤<=*m*<=≤<=50) — the number of stars o... | Print the number of "integer" gears with the maximum ratio among all "integer" gears. | [
"2\n4 5\n3\n12 13 15\n",
"4\n1 2 3 4\n5\n10 11 12 13 14\n"
] | [
"2\n",
"1\n"
] | In the first sample the maximum "integer" gear ratio equals 3. There are two gears that have such gear ratio. For one of them *a*<sub class="lower-index">1</sub> = 4, *b*<sub class="lower-index">1</sub> = 12, and for the other *a*<sub class="lower-index">2</sub> = 5, *b*<sub class="lower-index">3</sub> = 15. | 500 | [
{
"input": "2\n4 5\n3\n12 13 15",
"output": "2"
},
{
"input": "4\n1 2 3 4\n5\n10 11 12 13 14",
"output": "1"
},
{
"input": "1\n1\n1\n1",
"output": "1"
},
{
"input": "2\n1 2\n1\n1",
"output": "1"
},
{
"input": "1\n1\n2\n1 2",
"output": "1"
},
{
"input":... | 1,660,669,330 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 57 | 154 | 1,536,000 | import math
n=int(input())
l1=[int(i) for i in input().split()]
m=int(input())
l2=[int(j) for j in input().split()]
l3=[]
for x in range(m):
for y in range(n):
k=l2[x]/l1[y]
if k-math.floor(k)==0:
l3.append(k)
a=max(l3)
print(l3.count(a)) | Title: Bicycle Chain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya's bicycle chain drive consists of two parts: *n* stars are attached to the pedal axle, *m* stars are attached to the rear wheel axle. The chain helps to rotate the rear wheel by transmitting the pedal rotation.
We ... | ```python
import math
n=int(input())
l1=[int(i) for i in input().split()]
m=int(input())
l2=[int(j) for j in input().split()]
l3=[]
for x in range(m):
for y in range(n):
k=l2[x]/l1[y]
if k-math.floor(k)==0:
l3.append(k)
a=max(l3)
print(l3.count(a))
``` | 3 | |
747 | A | Display Size | PROGRAMMING | 800 | [
"brute force",
"math"
] | null | null | A big company decided to launch a new series of rectangular displays, and decided that the display must have exactly *n* pixels.
Your task is to determine the size of the rectangular display — the number of lines (rows) of pixels *a* and the number of columns of pixels *b*, so that:
- there are exactly *n* pixels o... | The first line contains the positive integer *n* (1<=≤<=*n*<=≤<=106) — the number of pixels display should have. | Print two integers — the number of rows and columns on the display. | [
"8\n",
"64\n",
"5\n",
"999999\n"
] | [
"2 4\n",
"8 8\n",
"1 5\n",
"999 1001\n"
] | In the first example the minimum possible difference equals 2, so on the display should be 2 rows of 4 pixels.
In the second example the minimum possible difference equals 0, so on the display should be 8 rows of 8 pixels.
In the third example the minimum possible difference equals 4, so on the display should be 1 ro... | 500 | [
{
"input": "8",
"output": "2 4"
},
{
"input": "64",
"output": "8 8"
},
{
"input": "5",
"output": "1 5"
},
{
"input": "999999",
"output": "999 1001"
},
{
"input": "716539",
"output": "97 7387"
},
{
"input": "1",
"output": "1 1"
},
{
"input":... | 1,591,420,623 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 155 | 0 | from math import*
#n,k=map(int, input().split())
n=int(input())
#l=list(map(int, input().split()))
#s=input()
k=int(pow(n,1/2))
for i in range(k,0,-1):
if n%i==0:
print(i,n//i)
break | Title: Display Size
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A big company decided to launch a new series of rectangular displays, and decided that the display must have exactly *n* pixels.
Your task is to determine the size of the rectangular display — the number of lines (rows) ... | ```python
from math import*
#n,k=map(int, input().split())
n=int(input())
#l=list(map(int, input().split()))
#s=input()
k=int(pow(n,1/2))
for i in range(k,0,-1):
if n%i==0:
print(i,n//i)
break
``` | 3 | |
39 | J | Spelling Check | PROGRAMMING | 1,500 | [
"hashing",
"implementation",
"strings"
] | J. Spelling Check | 2 | 256 | Petya has noticed that when he types using a keyboard, he often presses extra buttons and adds extra letters to the words. Of course, the spell-checking system underlines the words for him and he has to click every word and choose the right variant. Petya got fed up with correcting his mistakes himself, that’s why he d... | The input data contains two strings, consisting of lower-case Latin letters. The length of each string is from 1 to 106 symbols inclusive, the first string contains exactly 1 symbol more than the second one. | In the first line output the number of positions of the symbols in the first string, after the deleting of which the first string becomes identical to the second one. In the second line output space-separated positions of these symbols in increasing order. The positions are numbered starting from 1. If it is impossible... | [
"abdrakadabra\nabrakadabra\n",
"aa\na\n",
"competition\ncodeforces\n"
] | [
"1\n3\n",
"2\n1 2\n",
"0\n"
] | none | 0 | [
{
"input": "abdrakadabra\nabrakadabra",
"output": "1\n3 "
},
{
"input": "aa\na",
"output": "2\n1 2 "
},
{
"input": "competition\ncodeforces",
"output": "0"
},
{
"input": "ab\na",
"output": "1\n2 "
},
{
"input": "bb\nb",
"output": "2\n1 2 "
},
{
"input"... | 1,553,170,560 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 1,716 | 48,742,400 | s, t = input(), input()
n = j = len(t)
for i in range(n):
if s[i] != t[i]:
j = i
break
for i in range(j + 1, n + 1):
if s[i] != t[i - 1]:
print(0)
break
else:
i = j
while i > 0 and s[i - 1] == s[j]:
i -= 1
print(j - i + 1)
print(*r... | Title: Spelling Check
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya has noticed that when he types using a keyboard, he often presses extra buttons and adds extra letters to the words. Of course, the spell-checking system underlines the words for him and he has to click every word and ... | ```python
s, t = input(), input()
n = j = len(t)
for i in range(n):
if s[i] != t[i]:
j = i
break
for i in range(j + 1, n + 1):
if s[i] != t[i - 1]:
print(0)
break
else:
i = j
while i > 0 and s[i - 1] == s[j]:
i -= 1
print(j - i + 1)
... | 3.48021 |
236 | A | Boy or Girl | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
Bu... | The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters. | If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes). | [
"wjmzbmr\n",
"xiaodao\n",
"sevenkplus\n"
] | [
"CHAT WITH HER!\n",
"IGNORE HIM!\n",
"CHAT WITH HER!\n"
] | For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | 500 | [
{
"input": "wjmzbmr",
"output": "CHAT WITH HER!"
},
{
"input": "xiaodao",
"output": "IGNORE HIM!"
},
{
"input": "sevenkplus",
"output": "CHAT WITH HER!"
},
{
"input": "pezu",
"output": "CHAT WITH HER!"
},
{
"input": "wnemlgppy",
"output": "CHAT WITH HER!"
},... | 1,697,154,509 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 85 | 124 | 0 | name = input()
nameSet = set()
for char in name:
nameSet.add(char)
if len(nameSet) % 2 == 0:
print('CHAT WITH HER!')
else:
print('IGNORE HIM!')
| Title: Boy or Girl
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he though... | ```python
name = input()
nameSet = set()
for char in name:
nameSet.add(char)
if len(nameSet) % 2 == 0:
print('CHAT WITH HER!')
else:
print('IGNORE HIM!')
``` | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,648,455,004 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 62 | 0 | s = input()
upper = ''
lower = ''
for i in s:
if i.isupper():
upper += i
else:
lower += i
if len(upper) > len(lower):
print(s.upper())
else:
print(s.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s = input()
upper = ''
lower = ''
for i in s:
if i.isupper():
upper += i
else:
lower += i
if len(upper) > len(lower):
print(s.upper())
else:
print(s.lower())
``` | 3.9845 |
761 | A | Dasha and Stairs | PROGRAMMING | 1,000 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | On her way to programming school tiger Dasha faced her first test — a huge staircase!
The steps were numbered from one to infinity. As we know, tigers are very fond of all striped things, it is possible that it has something to do with their color. So on some interval of her way she calculated two values — the number ... | In the only line you are given two integers *a*, *b* (0<=≤<=*a*,<=*b*<=≤<=100) — the number of even and odd steps, accordingly. | In the only line print "YES", if the interval of steps described above exists, and "NO" otherwise. | [
"2 3\n",
"3 1\n"
] | [
"YES\n",
"NO\n"
] | In the first example one of suitable intervals is from 1 to 5. The interval contains two even steps — 2 and 4, and three odd: 1, 3 and 5. | 500 | [
{
"input": "2 3",
"output": "YES"
},
{
"input": "3 1",
"output": "NO"
},
{
"input": "5 4",
"output": "YES"
},
{
"input": "9 9",
"output": "YES"
},
{
"input": "85 95",
"output": "NO"
},
{
"input": "0 1",
"output": "YES"
},
{
"input": "89 25"... | 1,485,890,957 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 93 | 4,608,000 | n,m = map(int,input().split())
if (n+m)> 0 and abs(n-m)<= 1 :
print("YES")
else :
print("NO") | Title: Dasha and Stairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On her way to programming school tiger Dasha faced her first test — a huge staircase!
The steps were numbered from one to infinity. As we know, tigers are very fond of all striped things, it is possible that it has so... | ```python
n,m = map(int,input().split())
if (n+m)> 0 and abs(n-m)<= 1 :
print("YES")
else :
print("NO")
``` | 3 | |
31 | A | Worms Evolution | PROGRAMMING | 1,200 | [
"implementation"
] | A. Worms Evolution | 2 | 256 | Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his theory, professor needs to find 3 different forms that the length of the first form is equal to ... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of worm's forms. The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=1000) — lengths of worms of each form. | Output 3 distinct integers *i* *j* *k* (1<=≤<=*i*,<=*j*,<=*k*<=≤<=*n*) — such indexes of worm's forms that *a**i*<==<=*a**j*<=+<=*a**k*. If there is no such triple, output -1. If there are several solutions, output any of them. It possible that *a**j*<==<=*a**k*. | [
"5\n1 2 3 5 7\n",
"5\n1 8 1 5 1\n"
] | [
"3 2 1\n",
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 5 7",
"output": "3 2 1"
},
{
"input": "5\n1 8 1 5 1",
"output": "-1"
},
{
"input": "4\n303 872 764 401",
"output": "-1"
},
{
"input": "6\n86 402 133 524 405 610",
"output": "6 4 1"
},
{
"input": "8\n217 779 418 895 996 473 3 22",
"output":... | 1,693,408,561 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 372 | 0 | n=int(input())
arr=[int(i) for i in input().split()]
ansi=-1
ansj=-1
ansk=-1
for i in range(n):
for j in range(n):
for k in range(n):
if arr[i]== arr[j]+ arr[k]and j!=k:
ansi= i
ansj= j
ansk= k
if ansi==-1:
print(-1)
else:
print(ansi+1,ansj... | Title: Worms Evolution
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his... | ```python
n=int(input())
arr=[int(i) for i in input().split()]
ansi=-1
ansj=-1
ansk=-1
for i in range(n):
for j in range(n):
for k in range(n):
if arr[i]== arr[j]+ arr[k]and j!=k:
ansi= i
ansj= j
ansk= k
if ansi==-1:
print(-1)
else:
print(a... | 3.907 |
837 | C | Two Seals | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | One very important person has a piece of paper in the form of a rectangle *a*<=×<=*b*.
Also, he has *n* seals. Each seal leaves an impression on the paper in the form of a rectangle of the size *x**i*<=×<=*y**i*. Each impression must be parallel to the sides of the piece of paper (but seal can be rotated by 90 degrees... | The first line contains three integer numbers *n*, *a* and *b* (1<=≤<=*n*,<=*a*,<=*b*<=≤<=100).
Each of the next *n* lines contain two numbers *x**i*, *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=100). | Print the largest total area that can be occupied by two seals. If you can not select two seals, print 0. | [
"2 2 2\n1 2\n2 1\n",
"4 10 9\n2 3\n1 1\n5 10\n9 11\n",
"3 10 10\n6 6\n7 7\n20 5\n"
] | [
"4\n",
"56\n",
"0\n"
] | In the first example you can rotate the second seal by 90 degrees. Then put impression of it right under the impression of the first seal. This will occupy all the piece of paper.
In the second example you can't choose the last seal because it doesn't fit. By choosing the first and the third seals you occupy the large... | 0 | [
{
"input": "2 2 2\n1 2\n2 1",
"output": "4"
},
{
"input": "4 10 9\n2 3\n1 1\n5 10\n9 11",
"output": "56"
},
{
"input": "3 10 10\n6 6\n7 7\n20 5",
"output": "0"
},
{
"input": "2 1 1\n1 1\n1 1",
"output": "0"
},
{
"input": "2 1 2\n1 1\n1 1",
"output": "2"
},
... | 1,501,777,149 | 3,849 | Python 3 | OK | TESTS | 51 | 93 | 4,915,200 | def main():
n, a, b = [int(t) for t in input().split()]
points = []
for _ in range(n):
point = [int(t) for t in input().split()]
points.append(point)
largest_area = 0
for i, (x1, y1) in enumerate(points):
for j, (x2, y2) in enumerate(points):
if i == j:
... | Title: Two Seals
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One very important person has a piece of paper in the form of a rectangle *a*<=×<=*b*.
Also, he has *n* seals. Each seal leaves an impression on the paper in the form of a rectangle of the size *x**i*<=×<=*y**i*. Each impres... | ```python
def main():
n, a, b = [int(t) for t in input().split()]
points = []
for _ in range(n):
point = [int(t) for t in input().split()]
points.append(point)
largest_area = 0
for i, (x1, y1) in enumerate(points):
for j, (x2, y2) in enumerate(points):
if i == j... | 3 | |
900 | B | Position in Fraction | PROGRAMMING | 1,300 | [
"math",
"number theory"
] | null | null | You have a fraction . You need to find the first occurrence of digit *c* into decimal notation of the fraction after decimal point. | The first contains three single positive integers *a*, *b*, *c* (1<=≤<=*a*<=<<=*b*<=≤<=105, 0<=≤<=*c*<=≤<=9). | Print position of the first occurrence of digit *c* into the fraction. Positions are numbered from 1 after decimal point. It there is no such position, print -1. | [
"1 2 0\n",
"2 3 7\n"
] | [
"2",
"-1"
] | The fraction in the first example has the following decimal notation: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/896357459a466614a0542f34c9cfb0cef1afc9ed.png" style="max-width: 100.0%;max-height: 100.0%;"/>. The first zero stands on second position.
The fraction in the second example ... | 1,000 | [
{
"input": "1 2 0",
"output": "2"
},
{
"input": "2 3 7",
"output": "-1"
},
{
"input": "1 100000 1",
"output": "5"
},
{
"input": "1 7 7",
"output": "6"
},
{
"input": "99999 100000 8",
"output": "-1"
},
{
"input": "44102 73848 2",
"output": "132"
}... | 1,572,700,064 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 124 | 0 | a,b,c=map(int,input().split())
a%=b
k=0
for i in range(1,b+1):
a*=10
if int(a/b)==c:
print(i)
k+=1
break
a%=b
if k==0:
print(-1)
| Title: Position in Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a fraction . You need to find the first occurrence of digit *c* into decimal notation of the fraction after decimal point.
Input Specification:
The first contains three single positive integers *a*, *b*, ... | ```python
a,b,c=map(int,input().split())
a%=b
k=0
for i in range(1,b+1):
a*=10
if int(a/b)==c:
print(i)
k+=1
break
a%=b
if k==0:
print(-1)
``` | 3 | |
618 | C | Constellation | PROGRAMMING | 1,600 | [
"geometry",
"implementation"
] | null | null | Cat Noku has obtained a map of the night sky. On this map, he found a constellation with *n* stars numbered from 1 to *n*. For each *i*, the *i*-th star is located at coordinates (*x**i*,<=*y**i*). No two stars are located at the same position.
In the evening Noku is going to take a look at the night sky. He would lik... | The first line of the input contains a single integer *n* (3<=≤<=*n*<=≤<=100<=000).
Each of the next *n* lines contains two integers *x**i* and *y**i* (<=-<=109<=≤<=*x**i*,<=*y**i*<=≤<=109).
It is guaranteed that no two stars lie at the same point, and there does not exist a line such that all stars lie on that line. | Print three distinct integers on a single line — the indices of the three points that form a triangle that satisfies the conditions stated in the problem.
If there are multiple possible answers, you may print any of them. | [
"3\n0 1\n1 0\n1 1\n",
"5\n0 0\n0 2\n2 0\n2 2\n1 1\n"
] | [
"1 2 3\n",
"1 3 5\n"
] | In the first sample, we can print the three indices in any order.
In the second sample, we have the following picture.
Note that the triangle formed by starts 1, 4 and 3 doesn't satisfy the conditions stated in the problem, as point 5 is not strictly outside of this triangle (it lies on it's border). | 1,500 | [
{
"input": "3\n0 1\n1 0\n1 1",
"output": "1 2 3"
},
{
"input": "5\n0 0\n0 2\n2 0\n2 2\n1 1",
"output": "1 3 5"
},
{
"input": "3\n819934317 939682125\n487662889 8614219\n-557136619 382982369",
"output": "1 3 2"
},
{
"input": "10\n25280705 121178189\n219147240 -570920213\n-8298... | 1,454,133,412 | 2,147,483,647 | Python 3 | OK | TESTS | 98 | 748 | 13,004,800 | n = int(input())
points = [list(map(int, input().split(' ')))+[i+1] for i in range(n)]
points.sort()
i, j, k = 0, 1, 2
while True:
if points[i][0] == points[j][0] and points[j][0] == points[k][0]:
k += 1
elif points[i][0] != points[j][0] and points[i][0] != points[k][0] and\
(points[j][1]-point... | Title: Constellation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Cat Noku has obtained a map of the night sky. On this map, he found a constellation with *n* stars numbered from 1 to *n*. For each *i*, the *i*-th star is located at coordinates (*x**i*,<=*y**i*). No two stars are locate... | ```python
n = int(input())
points = [list(map(int, input().split(' ')))+[i+1] for i in range(n)]
points.sort()
i, j, k = 0, 1, 2
while True:
if points[i][0] == points[j][0] and points[j][0] == points[k][0]:
k += 1
elif points[i][0] != points[j][0] and points[i][0] != points[k][0] and\
(points[j... | 3 | |
688 | B | Lovely Palindromes | PROGRAMMING | 1,000 | [
"constructive algorithms",
"math"
] | null | null | Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is trying to love them too, but only very special and gifted people can understand the beauty behind palindro... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=10100<=000). | Print the *n*-th even-length palindrome number. | [
"1\n",
"10\n"
] | [
"11\n",
"1001\n"
] | The first 10 even-length palindrome numbers are 11, 22, 33, ... , 88, 99 and 1001. | 1,000 | [
{
"input": "1",
"output": "11"
},
{
"input": "10",
"output": "1001"
},
{
"input": "11",
"output": "1111"
},
{
"input": "12",
"output": "1221"
},
{
"input": "100",
"output": "100001"
},
{
"input": "1321",
"output": "13211231"
},
{
"input": "... | 1,610,494,577 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 921,600 | n = str(input())
res = n
for j in range(len(n) - 1, -1, -1):
res += n[j]
print(res) | Title: Lovely Palindromes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is tr... | ```python
n = str(input())
res = n
for j in range(len(n) - 1, -1, -1):
res += n[j]
print(res)
``` | 3 | |
47 | A | Triangular numbers | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Triangular numbers | 2 | 256 | A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is the number of dots in a triangle with *n* dots on a side. . You can learn more about these numbers fr... | The first line contains the single number *n* (1<=≤<=*n*<=≤<=500) — the given integer. | If the given integer is a triangular number output YES, otherwise output NO. | [
"1\n",
"2\n",
"3\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "1",
"output": "YES"
},
{
"input": "2",
"output": "NO"
},
{
"input": "3",
"output": "YES"
},
{
"input": "4",
"output": "NO"
},
{
"input": "5",
"output": "NO"
},
{
"input": "6",
"output": "YES"
},
{
"input": "7",
"output": "NO... | 1,603,055,334 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 218 | 0 | n=int(input())
sol="NO"
# n(n+1)/2=tn
for i in range(n+1):
if int(i*(i+1)/2)==n:
sol="YES"
break
print(sol) | Title: Triangular numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is t... | ```python
n=int(input())
sol="NO"
# n(n+1)/2=tn
for i in range(n+1):
if int(i*(i+1)/2)==n:
sol="YES"
break
print(sol)
``` | 3.9455 |
965 | A | Paper Airplanes | PROGRAMMING | 800 | [
"math"
] | null | null | To make a paper airplane, one has to use a rectangular piece of paper. From a sheet of standard size you can make $s$ airplanes.
A group of $k$ people decided to make $n$ airplanes each. They are going to buy several packs of paper, each of them containing $p$ sheets, and then distribute the sheets between the people.... | The only line contains four integers $k$, $n$, $s$, $p$ ($1 \le k, n, s, p \le 10^4$) — the number of people, the number of airplanes each should make, the number of airplanes that can be made using one sheet and the number of sheets in one pack, respectively. | Print a single integer — the minimum number of packs they should buy. | [
"5 3 2 3\n",
"5 3 100 1\n"
] | [
"4\n",
"5\n"
] | In the first sample they have to buy $4$ packs of paper: there will be $12$ sheets in total, and giving $2$ sheets to each person is enough to suit everyone's needs.
In the second sample they have to buy a pack for each person as they can't share sheets. | 500 | [
{
"input": "5 3 2 3",
"output": "4"
},
{
"input": "5 3 100 1",
"output": "5"
},
{
"input": "10000 10000 1 1",
"output": "100000000"
},
{
"input": "1 1 10000 10000",
"output": "1"
},
{
"input": "300 300 21 23",
"output": "196"
},
{
"input": "300 2 37 51... | 1,668,142,673 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 18 | 62 | 0 | from math import ceil
k,n,s,p = map(float,input().split())
print(ceil((ceil(n/s)*k)/p)) | Title: Paper Airplanes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
To make a paper airplane, one has to use a rectangular piece of paper. From a sheet of standard size you can make $s$ airplanes.
A group of $k$ people decided to make $n$ airplanes each. They are going to buy several p... | ```python
from math import ceil
k,n,s,p = map(float,input().split())
print(ceil((ceil(n/s)*k)/p))
``` | 3 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,605,528,890 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 186 | 0 | # n=int(input())
# s1=0
# s2=0
# s3=0
# for _ in range(n):
# x,y,z=(map(int,input().split()))
# s1=s1+x
# s2=s2+y
# s3=s3+z
#
# if s1==0 and s2==0 and s3==0:
# print("YES")
# else:
# print("NO")
# l=[]
# for i in range(5):
# arr=list(map(int,input().split()))
# l.appen... | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
# n=int(input())
# s1=0
# s2=0
# s3=0
# for _ in range(n):
# x,y,z=(map(int,input().split()))
# s1=s1+x
# s2=s2+y
# s3=s3+z
#
# if s1==0 and s2==0 and s3==0:
# print("YES")
# else:
# print("NO")
# l=[]
# for i in range(5):
# arr=list(map(int,input().split()))
# ... | 3.9535 |
450 | B | Jzzhu and Sequences | PROGRAMMING | 1,300 | [
"implementation",
"math"
] | null | null | Jzzhu has invented a kind of sequences, they meet the following property:
You are given *x* and *y*, please calculate *f**n* modulo 1000000007 (109<=+<=7). | The first line contains two integers *x* and *y* (|*x*|,<=|*y*|<=≤<=109). The second line contains a single integer *n* (1<=≤<=*n*<=≤<=2·109). | Output a single integer representing *f**n* modulo 1000000007 (109<=+<=7). | [
"2 3\n3\n",
"0 -1\n2\n"
] | [
"1\n",
"1000000006\n"
] | In the first sample, *f*<sub class="lower-index">2</sub> = *f*<sub class="lower-index">1</sub> + *f*<sub class="lower-index">3</sub>, 3 = 2 + *f*<sub class="lower-index">3</sub>, *f*<sub class="lower-index">3</sub> = 1.
In the second sample, *f*<sub class="lower-index">2</sub> = - 1; - 1 modulo (10<sup class="upper-... | 1,000 | [
{
"input": "2 3\n3",
"output": "1"
},
{
"input": "0 -1\n2",
"output": "1000000006"
},
{
"input": "-9 -11\n12345",
"output": "1000000005"
},
{
"input": "0 0\n1000000000",
"output": "0"
},
{
"input": "-1000000000 1000000000\n2000000000",
"output": "1000000000"
... | 1,636,009,231 | 2,147,483,647 | Python 3 | OK | TESTS | 74 | 62 | 4,505,600 | a, b = map(int, input().split())
n = int(input())
if(n%6==1):
val = a
elif(n%6==2):
val = b
elif(n%6==3):
val = b-a
elif(n%6==4):
val = -a
elif(n%6==5):
val = -b
else:
val = a-b
if(val<0):
val += 1000000007
print(val%1000000007)
| Title: Jzzhu and Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jzzhu has invented a kind of sequences, they meet the following property:
You are given *x* and *y*, please calculate *f**n* modulo 1000000007 (109<=+<=7).
Input Specification:
The first line contains two integers... | ```python
a, b = map(int, input().split())
n = int(input())
if(n%6==1):
val = a
elif(n%6==2):
val = b
elif(n%6==3):
val = b-a
elif(n%6==4):
val = -a
elif(n%6==5):
val = -b
else:
val = a-b
if(val<0):
val += 1000000007
print(val%1000000007)
``` | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,636,989,744 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 122 | 0 | n=input()
c=0
d=0
for x in n:
if x.isupper():
c+=1
else:
d+=1
if c>d:
print(n.upper())
else:
print(n.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
n=input()
c=0
d=0
for x in n:
if x.isupper():
c+=1
else:
d+=1
if c>d:
print(n.upper())
else:
print(n.lower())
``` | 3.9695 |
266 | B | Queue at the School | PROGRAMMING | 800 | [
"constructive algorithms",
"graph matchings",
"implementation",
"shortest paths"
] | null | null | During the break the schoolchildren, boys and girls, formed a queue of *n* people in the canteen. Initially the children stood in the order they entered the canteen. However, after a while the boys started feeling awkward for standing in front of the girls in the queue and they started letting the girls move forward ea... | The first line contains two integers *n* and *t* (1<=≤<=*n*,<=*t*<=≤<=50), which represent the number of children in the queue and the time after which the queue will transform into the arrangement you need to find.
The next line contains string *s*, which represents the schoolchildren's initial arrangement. If the *... | Print string *a*, which describes the arrangement after *t* seconds. If the *i*-th position has a boy after the needed time, then the *i*-th character *a* must equal "B", otherwise it must equal "G". | [
"5 1\nBGGBG\n",
"5 2\nBGGBG\n",
"4 1\nGGGB\n"
] | [
"GBGGB\n",
"GGBGB\n",
"GGGB\n"
] | none | 500 | [
{
"input": "5 1\nBGGBG",
"output": "GBGGB"
},
{
"input": "5 2\nBGGBG",
"output": "GGBGB"
},
{
"input": "4 1\nGGGB",
"output": "GGGB"
},
{
"input": "2 1\nBB",
"output": "BB"
},
{
"input": "2 1\nBG",
"output": "GB"
},
{
"input": "6 2\nBBGBBG",
"outpu... | 1,695,130,781 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 62 | 0 | s=input().split()
n=int(s[0])
t=int(s[1])
q=input()
for i in range(t):
q=q.replace('BG','GB',n)
print(q) | Title: Queue at the School
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During the break the schoolchildren, boys and girls, formed a queue of *n* people in the canteen. Initially the children stood in the order they entered the canteen. However, after a while the boys started feeling a... | ```python
s=input().split()
n=int(s[0])
t=int(s[1])
q=input()
for i in range(t):
q=q.replace('BG','GB',n)
print(q)
``` | 3 | |
237 | C | Primes on Interval | PROGRAMMING | 1,600 | [
"binary search",
"number theory",
"two pointers"
] | null | null | You've decided to carry out a survey in the theory of prime numbers. Let us remind you that a prime number is a positive integer that has exactly two distinct positive integer divisors.
Consider positive integers *a*, *a*<=+<=1, ..., *b* (*a*<=≤<=*b*). You want to find the minimum integer *l* (1<=≤<=*l*<=≤<=*b*<=-<=*a... | A single line contains three space-separated integers *a*,<=*b*,<=*k* (1<=≤<=*a*,<=*b*,<=*k*<=≤<=106; *a*<=≤<=*b*). | In a single line print a single integer — the required minimum *l*. If there's no solution, print -1. | [
"2 4 2\n",
"6 13 1\n",
"1 4 3\n"
] | [
"3\n",
"4\n",
"-1\n"
] | none | 1,500 | [
{
"input": "2 4 2",
"output": "3"
},
{
"input": "6 13 1",
"output": "4"
},
{
"input": "1 4 3",
"output": "-1"
},
{
"input": "5 8 2",
"output": "4"
},
{
"input": "8 10 3",
"output": "-1"
},
{
"input": "1 5 2",
"output": "3"
},
{
"input": "6 ... | 1,613,461,554 | 2,147,483,647 | PyPy 3 | OK | TESTS | 55 | 171 | 9,523,200 | from sys import stdin,stdout
nmbr = lambda: int(stdin.readline())
lst = lambda: list(map(int,stdin.readline().split()))
N=10**6+6
primes=[1]*N
p=2
while p*p<=N:
if primes[p]:
for j in range(p*p,N,p):
primes[j]=0
p+=1
primes[1]=primes[0]=0
def fn(x):
for i in range(n-x+1):
... | Title: Primes on Interval
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've decided to carry out a survey in the theory of prime numbers. Let us remind you that a prime number is a positive integer that has exactly two distinct positive integer divisors.
Consider positive integers *a... | ```python
from sys import stdin,stdout
nmbr = lambda: int(stdin.readline())
lst = lambda: list(map(int,stdin.readline().split()))
N=10**6+6
primes=[1]*N
p=2
while p*p<=N:
if primes[p]:
for j in range(p*p,N,p):
primes[j]=0
p+=1
primes[1]=primes[0]=0
def fn(x):
for i in range(... | 3 | |
835 | B | The number on the board | PROGRAMMING | 1,100 | [
"greedy"
] | null | null | Some natural number was written on the board. Its sum of digits was not less than *k*. But you were distracted a bit, and someone changed this number to *n*, replacing some digits with others. It's known that the length of the number didn't change.
You have to find the minimum number of digits in which these two numbe... | The first line contains integer *k* (1<=≤<=*k*<=≤<=109).
The second line contains integer *n* (1<=≤<=*n*<=<<=10100000).
There are no leading zeros in *n*. It's guaranteed that this situation is possible. | Print the minimum number of digits in which the initial number and *n* can differ. | [
"3\n11\n",
"3\n99\n"
] | [
"1\n",
"0\n"
] | In the first example, the initial number could be 12.
In the second example the sum of the digits of *n* is not less than *k*. The initial number could be equal to *n*. | 750 | [
{
"input": "3\n11",
"output": "1"
},
{
"input": "3\n99",
"output": "0"
},
{
"input": "10\n5205602270",
"output": "0"
},
{
"input": "70\n3326631213",
"output": "6"
},
{
"input": "200\n100000001000000000000000000001000000000000000100000100000000000000000000000000000... | 1,601,023,283 | 2,147,483,647 | PyPy 3 | OK | TESTS | 48 | 171 | 4,710,400 | k = int(input())
n = list(input())
n.sort()
sum=0
for i in n:
sum+=int(i)
m=0
if k>sum:
j=0
while sum<k:
sum+=9-int(n[j])
j+=1
m+=1
print(m) | Title: The number on the board
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some natural number was written on the board. Its sum of digits was not less than *k*. But you were distracted a bit, and someone changed this number to *n*, replacing some digits with others. It's known that th... | ```python
k = int(input())
n = list(input())
n.sort()
sum=0
for i in n:
sum+=int(i)
m=0
if k>sum:
j=0
while sum<k:
sum+=9-int(n[j])
j+=1
m+=1
print(m)
``` | 3 | |
47 | B | Coins | PROGRAMMING | 1,200 | [
"implementation"
] | B. Coins | 2 | 256 | One day Vasya came across three Berland coins. They didn't have any numbers that's why Vasya didn't understand how their denominations differ. He supposed that if one coin is heavier than the other one, then it should be worth more. Vasya weighed all the three pairs of coins on pan balance scales and told you the resul... | The input data contains the results of all the weighting, one result on each line. It is guaranteed that every coin pair was weighted exactly once. Vasya labelled the coins with letters «A», «B» and «C». Each result is a line that appears as (letter)(> or < sign)(letter). For example, if coin "A" proved lighter t... | It the results are contradictory, print Impossible. Otherwise, print without spaces the rearrangement of letters «A», «B» and «C» which represent the coins in the increasing order of their weights. | [
"A>B\nC<B\nA>C\n",
"A<B\nB>C\nC>A\n"
] | [
"CBA",
"ACB"
] | none | 1,000 | [
{
"input": "A>B\nC<B\nA>C",
"output": "CBA"
},
{
"input": "A<B\nB>C\nC>A",
"output": "ACB"
},
{
"input": "A<C\nB<A\nB>C",
"output": "Impossible"
},
{
"input": "A<B\nA<C\nB>C",
"output": "ACB"
},
{
"input": "B>A\nC<B\nC>A",
"output": "ACB"
},
{
"input":... | 1,587,801,545 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 218 | 307,200 | d = {"A": 1 , "B" : 1 , "C" : 1}
for _ in range(3):
q = input()
a = q[0]
e= q[1]
b = q[2]
if(q[1]=="<"):
d[a] -=1
d[b]+= 1
else:
d[a] +=1
d[b] -= 1
s = ""
for i in d:
if d[i] == -1:
s+=i
break
for i in d:
if d[i] == 1... | Title: Coins
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya came across three Berland coins. They didn't have any numbers that's why Vasya didn't understand how their denominations differ. He supposed that if one coin is heavier than the other one, then it should be worth more. ... | ```python
d = {"A": 1 , "B" : 1 , "C" : 1}
for _ in range(3):
q = input()
a = q[0]
e= q[1]
b = q[2]
if(q[1]=="<"):
d[a] -=1
d[b]+= 1
else:
d[a] +=1
d[b] -= 1
s = ""
for i in d:
if d[i] == -1:
s+=i
break
for i in d:
if... | 3.944928 |
682 | A | Alyona and Numbers | PROGRAMMING | 1,100 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers from 1 to *m*. Now the girl wants to count how many pairs of integers she can choose, one from the first... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1<=000<=000). | Print the only integer — the number of pairs of integers (*x*,<=*y*) such that 1<=≤<=*x*<=≤<=*n*, 1<=≤<=*y*<=≤<=*m* and (*x*<=+<=*y*) is divisible by 5. | [
"6 12\n",
"11 14\n",
"1 5\n",
"3 8\n",
"5 7\n",
"21 21\n"
] | [
"14\n",
"31\n",
"1\n",
"5\n",
"7\n",
"88\n"
] | Following pairs are suitable in the first sample case:
- for *x* = 1 fits *y* equal to 4 or 9; - for *x* = 2 fits *y* equal to 3 or 8; - for *x* = 3 fits *y* equal to 2, 7 or 12; - for *x* = 4 fits *y* equal to 1, 6 or 11; - for *x* = 5 fits *y* equal to 5 or 10; - for *x* = 6 fits *y* equal to 4 or 9.
Only th... | 500 | [
{
"input": "6 12",
"output": "14"
},
{
"input": "11 14",
"output": "31"
},
{
"input": "1 5",
"output": "1"
},
{
"input": "3 8",
"output": "5"
},
{
"input": "5 7",
"output": "7"
},
{
"input": "21 21",
"output": "88"
},
{
"input": "10 15",
... | 1,612,118,404 | 2,147,483,647 | Python 3 | OK | TESTS | 128 | 733 | 0 | n,m = map(int,input().split())
gr = n if n>m else m
sm = n+m-gr
save=0
st=0
for i in range(1,sm+1):
gr+=1
temp=gr//5
if i%5==0:
st+=1
temp-=1*st
save+=temp
print(save) | Title: Alyona and Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers ... | ```python
n,m = map(int,input().split())
gr = n if n>m else m
sm = n+m-gr
save=0
st=0
for i in range(1,sm+1):
gr+=1
temp=gr//5
if i%5==0:
st+=1
temp-=1*st
save+=temp
print(save)
``` | 3 | |
749 | A | Bachgold Problem | PROGRAMMING | 800 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer *k* is called prime if it is greater than 1 and has exactly two positive integer ... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000). | The first line of the output contains a single integer *k* — maximum possible number of primes in representation.
The second line should contain *k* primes with their sum equal to *n*. You can print them in any order. If there are several optimal solution, print any of them. | [
"5\n",
"6\n"
] | [
"2\n2 3\n",
"3\n2 2 2\n"
] | none | 500 | [
{
"input": "5",
"output": "2\n2 3"
},
{
"input": "6",
"output": "3\n2 2 2"
},
{
"input": "2",
"output": "1\n2"
},
{
"input": "3",
"output": "1\n3"
},
{
"input": "99999",
"output": "49999\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,685,041,672 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 41 | 62 | 2,150,400 | def baghold(num):
arr = []
if num % 2 == 0:
print(num // 2)
arr = ['2' for i in range(num // 2)]
print(' '.join(arr))
else:
print(num // 2)
arr = ['2' for i in range(num // 2 -1)]
arr.append('3')
print(' '.join(arr))
baghold(int(input()))
... | Title: Bachgold Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
... | ```python
def baghold(num):
arr = []
if num % 2 == 0:
print(num // 2)
arr = ['2' for i in range(num // 2)]
print(' '.join(arr))
else:
print(num // 2)
arr = ['2' for i in range(num // 2 -1)]
arr.append('3')
print(' '.join(arr))
baghold(int(in... | 3 | |
248 | A | Cupboards | PROGRAMMING | 800 | [
"implementation"
] | null | null | One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any longer, so he decided to get some food in the house.
Karlsson's gaze immediately fell on *n* woode... | The first input line contains a single integer *n* — the number of cupboards in the kitchen (2<=≤<=*n*<=≤<=104). Then follow *n* lines, each containing two integers *l**i* and *r**i* (0<=≤<=*l**i*,<=*r**i*<=≤<=1). Number *l**i* equals one, if the left door of the *i*-th cupboard is opened, otherwise number *l**i* equal... | In the only output line print a single integer *t* — the minimum number of seconds Karlsson needs to change the doors of all cupboards to the position he needs. | [
"5\n0 1\n1 0\n0 1\n1 1\n0 1\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "5\n0 1\n1 0\n0 1\n1 1\n0 1",
"output": "3"
},
{
"input": "2\n0 0\n0 0",
"output": "0"
},
{
"input": "3\n0 1\n1 1\n1 1",
"output": "1"
},
{
"input": "8\n0 1\n1 0\n0 1\n1 1\n0 1\n1 0\n0 1\n1 0",
"output": "7"
},
{
"input": "8\n1 0\n1 0\n1 0\n0 1\n0 1\n1 ... | 1,651,236,794 | 2,147,483,647 | PyPy 3 | OK | TESTS | 57 | 436 | 4,812,800 | import sys
from collections import Counter, defaultdict, deque
from heapq import heapify, heappush, heappop
from functools import lru_cache
from math import floor, ceil, sqrt, gcd
from string import ascii_lowercase
from math import gcd
from bisect import bisect_left, bisect, bisect_right
def read():
re... | Title: Cupboards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any long... | ```python
import sys
from collections import Counter, defaultdict, deque
from heapq import heapify, heappush, heappop
from functools import lru_cache
from math import floor, ceil, sqrt, gcd
from string import ascii_lowercase
from math import gcd
from bisect import bisect_left, bisect, bisect_right
def read(... | 3 | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,677,055,251 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 124 | 0 | n=int(input())
i=0
list1=[]
list2=[]
while i<n:
h,a=(map(int, input().split()))
list1.append(h)
list2.append(a)
i+=1
u=0
count1=0
while u<n:
count1+=list2.count(list1[u])
u+=1
print(count1) | Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
n=int(input())
i=0
list1=[]
list2=[]
while i<n:
h,a=(map(int, input().split()))
list1.append(h)
list2.append(a)
i+=1
u=0
count1=0
while u<n:
count1+=list2.count(list1[u])
u+=1
print(count1)
``` | 3 | |
427 | A | Police Recruits | PROGRAMMING | 800 | [
"implementation"
] | null | null | The police department of your city has just started its journey. Initially, they don’t have any manpower. So, they started hiring new recruits in groups.
Meanwhile, crimes keeps occurring within the city. One member of the police force can investigate only one crime during his/her lifetime.
If there is no police offi... | The first line of input will contain an integer *n* (1<=≤<=*n*<=≤<=105), the number of events. The next line will contain *n* space-separated integers.
If the integer is -1 then it means a crime has occurred. Otherwise, the integer will be positive, the number of officers recruited together at that time. No more than ... | Print a single integer, the number of crimes which will go untreated. | [
"3\n-1 -1 1\n",
"8\n1 -1 1 -1 -1 1 1 1\n",
"11\n-1 -1 2 -1 -1 -1 -1 -1 -1 -1 -1\n"
] | [
"2\n",
"1\n",
"8\n"
] | Lets consider the second example:
1. Firstly one person is hired. 1. Then crime appears, the last hired person will investigate this crime. 1. One more person is hired. 1. One more crime appears, the last hired person will investigate this crime. 1. Crime appears. There is no free policeman at the time, so this c... | 500 | [
{
"input": "3\n-1 -1 1",
"output": "2"
},
{
"input": "8\n1 -1 1 -1 -1 1 1 1",
"output": "1"
},
{
"input": "11\n-1 -1 2 -1 -1 -1 -1 -1 -1 -1 -1",
"output": "8"
},
{
"input": "7\n-1 -1 1 1 -1 -1 1",
"output": "2"
},
{
"input": "21\n-1 -1 -1 -1 -1 3 2 -1 6 -1 -1 2 1 ... | 1,699,804,756 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 62 | 10,547,200 | n = int(input())
n2 = list(map(int, input().split()))
lose = 0
menti = 0
for i in range(len(n2)):
if n2[i] < 0 and menti == 0:
lose += 1
elif n2[i] < 0 and menti != 0:
menti -= 1
elif n2[i] > 0:
menti += n2[i]
print(lose) | Title: Police Recruits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The police department of your city has just started its journey. Initially, they don’t have any manpower. So, they started hiring new recruits in groups.
Meanwhile, crimes keeps occurring within the city. One member of... | ```python
n = int(input())
n2 = list(map(int, input().split()))
lose = 0
menti = 0
for i in range(len(n2)):
if n2[i] < 0 and menti == 0:
lose += 1
elif n2[i] < 0 and menti != 0:
menti -= 1
elif n2[i] > 0:
menti += n2[i]
print(lose)
``` | 3 | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,685,117,766 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 46 | 0 | num1, num2 = map(int, input().split())
if num1 >= num2:
num1 -= num2
num1 //= 2
print(num2, num1)
else:
num2 -= num1
num2 //= 2
print(num1, num2)
| Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
num1, num2 = map(int, input().split())
if num1 >= num2:
num1 -= num2
num1 //= 2
print(num2, num1)
else:
num2 -= num1
num2 //= 2
print(num1, num2)
``` | 3 | |
808 | B | Average Sleep Time | PROGRAMMING | 1,300 | [
"data structures",
"implementation",
"math"
] | null | null | It's been almost a week since Polycarp couldn't get rid of insomnia. And as you may already know, one week in Berland lasts *k* days!
When Polycarp went to a doctor with his problem, the doctor asked him about his sleeping schedule (more specifically, the average amount of hours of sleep per week). Luckily, Polycarp k... | The first line contains two integer numbers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=2·105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105). | Output average sleeping time over all weeks.
The answer is considered to be correct if its absolute or relative error does not exceed 10<=-<=6. In particular, it is enough to output real number with at least 6 digits after the decimal point. | [
"3 2\n3 4 7\n",
"1 1\n10\n",
"8 2\n1 2 4 100000 123 456 789 1\n"
] | [
"9.0000000000\n",
"10.0000000000\n",
"28964.2857142857\n"
] | In the third example there are *n* - *k* + 1 = 7 weeks, so the answer is sums of all weeks divided by 7. | 0 | [
{
"input": "3 2\n3 4 7",
"output": "9.0000000000"
},
{
"input": "1 1\n10",
"output": "10.0000000000"
},
{
"input": "8 2\n1 2 4 100000 123 456 789 1",
"output": "28964.2857142857"
},
{
"input": "1 1\n1",
"output": "1.0000000000"
},
{
"input": "1 1\n100000",
"ou... | 1,505,991,823 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 233 | 14,233,600 | f = lambda: map(int, input().split())
n, k = f()
t = list(f())
h = s = sum(t[:k])
for i in range(n - k):
s += t[k + i] - t[i]
h += s
print(h / (n - k + 1)) | Title: Average Sleep Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's been almost a week since Polycarp couldn't get rid of insomnia. And as you may already know, one week in Berland lasts *k* days!
When Polycarp went to a doctor with his problem, the doctor asked him about his s... | ```python
f = lambda: map(int, input().split())
n, k = f()
t = list(f())
h = s = sum(t[:k])
for i in range(n - k):
s += t[k + i] - t[i]
h += s
print(h / (n - k + 1))
``` | 3 | |
139 | A | Petr and Book | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. S... | The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book.
The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and... | Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. | [
"100\n15 20 20 15 10 30 45\n",
"2\n1 0 0 0 0 0 0\n"
] | [
"6\n",
"1\n"
] | Note to the first sample:
By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else).
Note to the second... | 500 | [
{
"input": "100\n15 20 20 15 10 30 45",
"output": "6"
},
{
"input": "2\n1 0 0 0 0 0 0",
"output": "1"
},
{
"input": "100\n100 200 100 200 300 400 500",
"output": "1"
},
{
"input": "3\n1 1 1 1 1 1 1",
"output": "3"
},
{
"input": "1\n1 1 1 1 1 1 1",
"output": "1... | 1,695,379,595 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 49 | 124 | 1,536,000 | n = int(input())
d = list(map(int, input().split()))
s = 0; ns=1
while ns:
for i in range(1,8):
s = s+d[i-1]
if s >= n:
print(i)
ns = 0
break;
| Title: Petr and Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight s... | ```python
n = int(input())
d = list(map(int, input().split()))
s = 0; ns=1
while ns:
for i in range(1,8):
s = s+d[i-1]
if s >= n:
print(i)
ns = 0
break;
``` | 3 | |
780 | A | Andryusha and Socks | PROGRAMMING | 800 | [
"implementation"
] | null | null | Andryusha is an orderly boy and likes to keep things in their place.
Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbered from 1 to *n*. Andryusha wants to put paired socks together and put them in the wardrobe. He takes the ... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=105) — the number of sock pairs.
The second line contains 2*n* integers *x*1,<=*x*2,<=...,<=*x*2*n* (1<=≤<=*x**i*<=≤<=*n*), which describe the order in which Andryusha took the socks from the bag. More precisely, *x**i* means that the *i*-th sock Andryusha ... | Print single integer — the maximum number of socks that were on the table at the same time. | [
"1\n1 1\n",
"3\n2 1 1 3 2 3\n"
] | [
"1\n",
"2\n"
] | In the first example Andryusha took a sock from the first pair and put it on the table. Then he took the next sock which is from the first pair as well, so he immediately puts both socks to the wardrobe. Thus, at most one sock was on the table at the same time.
In the second example Andryusha behaved as follows:
- ... | 500 | [
{
"input": "1\n1 1",
"output": "1"
},
{
"input": "3\n2 1 1 3 2 3",
"output": "2"
},
{
"input": "5\n5 1 3 2 4 3 1 2 4 5",
"output": "5"
},
{
"input": "10\n4 2 6 3 4 8 7 1 1 5 2 10 6 8 3 5 10 9 9 7",
"output": "6"
},
{
"input": "50\n30 47 31 38 37 50 36 43 9 23 2 2 ... | 1,596,800,747 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 249 | 20,992,000 | a=int(input())
b=list(map(int, input().split()))
cnt=0
x=set()
y=[]
for i in b:
x^={i}
if len(x)>cnt:
cnt=len(x)
print(cnt) | Title: Andryusha and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andryusha is an orderly boy and likes to keep things in their place.
Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbere... | ```python
a=int(input())
b=list(map(int, input().split()))
cnt=0
x=set()
y=[]
for i in b:
x^={i}
if len(x)>cnt:
cnt=len(x)
print(cnt)
``` | 3 | |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the st... | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The... | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,685,454,887 | 2,147,483,647 | Python 3 | OK | TESTS | 72 | 46 | 0 | n,p,q=map(int,input().split())
s=str(input())
mi=min(p,q)
mx=max(p,q)
for i in range(0,n//mi+1):
nimi=n-i*mi
if 0==nimi%mx:
print(nimi//mx+i)
for j in range(0,i):
print(s[j*mi:(j+1)*mi])
s=s[i*mi:]
for j in range(0,nimi//mx):
print(s[j*mx:(j+1)*mx])
... | Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "H... | ```python
n,p,q=map(int,input().split())
s=str(input())
mi=min(p,q)
mx=max(p,q)
for i in range(0,n//mi+1):
nimi=n-i*mi
if 0==nimi%mx:
print(nimi//mx+i)
for j in range(0,i):
print(s[j*mi:(j+1)*mi])
s=s[i*mi:]
for j in range(0,nimi//mx):
print(s[j*mx:(j+1)*m... | 3 |
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