contestId int64 0 1.01k | index stringclasses 40
values | name stringlengths 2 54 | type stringclasses 2
values | rating int64 0 3.4k | tags listlengths 0 7 | title stringclasses 393
values | time-limit stringclasses 7
values | memory-limit stringclasses 6
values | problem-description stringlengths 0 2.97k | input-specification stringlengths 4 1.87k | output-specification stringlengths 4 1.12k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 3.5k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 1
value | testset stringclasses 9
values | passedTestCount int64 1 402 | timeConsumedMillis int64 15 8.06k | memoryConsumedBytes int64 0 514M | code stringlengths 11 61.4k | prompt stringlengths 297 7.35k | response stringlengths 25 61.4k | score float64 2.82 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,670,928,740 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 65 | 62 | 0 |
a = input()
n = int(a.split()[0])
t = int(a.split()[1])
k1 = '1' + (n - 1) * '0'
k2 = '1' + (n) * '0'
k1 = int(k1)
k2 = int(k2)
i = k1 - (k1 % t) + t
if (i < k2):
print(i)
else:
print("-1")
| Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
a = input()
n = int(a.split()[0])
t = int(a.split()[1])
k1 = '1' + (n - 1) * '0'
k2 = '1' + (n) * '0'
k1 = int(k1)
k2 = int(k2)
i = k1 - (k1 % t) + t
if (i < k2):
print(i)
else:
print("-1")
``` | 3 | |
224 | B | Array | PROGRAMMING | 1,500 | [
"bitmasks",
"implementation",
"two pointers"
] | null | null | You've got an array *a*, consisting of *n* integers: *a*1,<=*a*2,<=...,<=*a**n*. Your task is to find a minimal by inclusion segment [*l*,<=*r*] (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) such, that among numbers *a**l*,<= *a**l*<=+<=1,<= ...,<= *a**r* there are exactly *k* distinct numbers.
Segment [*l*,<=*r*] (1<=≤<=*l*<=≤<=*r*<=≤... | The first line contains two space-separated integers: *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=105). The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* — elements of the array *a* (1<=≤<=*a**i*<=≤<=105). | Print a space-separated pair of integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) such, that the segment [*l*,<=*r*] is the answer to the problem. If the sought segment does not exist, print "-1 -1" without the quotes. If there are multiple correct answers, print any of them. | [
"4 2\n1 2 2 3\n",
"8 3\n1 1 2 2 3 3 4 5\n",
"7 4\n4 7 7 4 7 4 7\n"
] | [
"1 2\n",
"2 5\n",
"-1 -1\n"
] | In the first sample among numbers *a*<sub class="lower-index">1</sub> and *a*<sub class="lower-index">2</sub> there are exactly two distinct numbers.
In the second sample segment [2, 5] is a minimal by inclusion segment with three distinct numbers, but it is not minimal in length among such segments.
In the third sam... | 1,000 | [
{
"input": "4 2\n1 2 2 3",
"output": "1 2"
},
{
"input": "8 3\n1 1 2 2 3 3 4 5",
"output": "2 5"
},
{
"input": "7 4\n4 7 7 4 7 4 7",
"output": "-1 -1"
},
{
"input": "5 1\n1 7 2 3 2",
"output": "1 1"
},
{
"input": "1 2\n666",
"output": "-1 -1"
},
{
"inp... | 1,662,002,299 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 342 | 12,492,800 | from sys import stdin
from collections import defaultdict
n, k = [int(x) for x in stdin.readline().split()]
a = [int(x) for x in stdin.readline().split()]
unique = defaultdict(int)
l = 0
ans_l = ans_r = -2
for r in range(n):
unique[a[r]] += 1
while len(unique) == k and l < r:
ans_l, ans_... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got an array *a*, consisting of *n* integers: *a*1,<=*a*2,<=...,<=*a**n*. Your task is to find a minimal by inclusion segment [*l*,<=*r*] (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) such, that among numbers *a**l*,<= *a**l*<=+<=1,<= ...,<... | ```python
from sys import stdin
from collections import defaultdict
n, k = [int(x) for x in stdin.readline().split()]
a = [int(x) for x in stdin.readline().split()]
unique = defaultdict(int)
l = 0
ans_l = ans_r = -2
for r in range(n):
unique[a[r]] += 1
while len(unique) == k and l < r:
a... | 3 | |
918 | B | Radio Station | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | As the guys fried the radio station facilities, the school principal gave them tasks as a punishment. Dustin's task was to add comments to nginx configuration for school's website. The school has *n* servers. Each server has a name and an ip (names aren't necessarily unique, but ips are). Dustin knows the ip and name o... | The first line of input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000).
The next *n* lines contain the names and ips of the servers. Each line contains a string name, name of the server and a string ip, ip of the server, separated by space (1<=≤<=|*name*|<=≤<=10, *name* only consists of English lowercase... | Print *m* lines, the commands in the configuration file after Dustin did his task. | [
"2 2\nmain 192.168.0.2\nreplica 192.168.0.1\nblock 192.168.0.1;\nproxy 192.168.0.2;\n",
"3 5\ngoogle 8.8.8.8\ncodeforces 212.193.33.27\nserver 138.197.64.57\nredirect 138.197.64.57;\nblock 8.8.8.8;\ncf 212.193.33.27;\nunblock 8.8.8.8;\ncheck 138.197.64.57;\n"
] | [
"block 192.168.0.1; #replica\nproxy 192.168.0.2; #main\n",
"redirect 138.197.64.57; #server\nblock 8.8.8.8; #google\ncf 212.193.33.27; #codeforces\nunblock 8.8.8.8; #google\ncheck 138.197.64.57; #server\n"
] | none | 1,000 | [
{
"input": "2 2\nmain 192.168.0.2\nreplica 192.168.0.1\nblock 192.168.0.1;\nproxy 192.168.0.2;",
"output": "block 192.168.0.1; #replica\nproxy 192.168.0.2; #main"
},
{
"input": "3 5\ngoogle 8.8.8.8\ncodeforces 212.193.33.27\nserver 138.197.64.57\nredirect 138.197.64.57;\nblock 8.8.8.8;\ncf 212.193.3... | 1,660,973,672 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 28 | 140 | 6,144,000 | N,M = map(int,input().split())
servers = {}
for n in range(N):
name,ip = input().split()
servers[ip] = name
for m in range(M):
name,ip = input().split()
for key,value in servers.items():
if ip[:-1] == key:
print(name,ip,"#"+serv... | Title: Radio Station
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As the guys fried the radio station facilities, the school principal gave them tasks as a punishment. Dustin's task was to add comments to nginx configuration for school's website. The school has *n* servers. Each server ... | ```python
N,M = map(int,input().split())
servers = {}
for n in range(N):
name,ip = input().split()
servers[ip] = name
for m in range(M):
name,ip = input().split()
for key,value in servers.items():
if ip[:-1] == key:
print(name,i... | 3 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,669,123,757 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | import math
a,b = (map (int ,input().split()))
c = a * b
d = math.floor(c//2)
print(d) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
import math
a,b = (map (int ,input().split()))
c = a * b
d = math.floor(c//2)
print(d)
``` | 3.977 |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirem... | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems wi... | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,641,199,755 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 41 | 109 | 1,536,000 | I=lambda:list(map(int,input().split()))
n,m=I();a=I();b=I()
i=j=0
while(i<n and j<m):
i+=1*(a[i]<=b[j]);j+=1
print(n-i)
| Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
T... | ```python
I=lambda:list(map(int,input().split()))
n,m=I();a=I();b=I()
i=j=0
while(i<n and j<m):
i+=1*(a[i]<=b[j]);j+=1
print(n-i)
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. ... | The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants | Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"1 3 2 1 2 1\n",
"1 1 1 1 1 99\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | 0 | [
{
"input": "1 3 2 1 2 1",
"output": "YES"
},
{
"input": "1 1 1 1 1 99",
"output": "NO"
},
{
"input": "1000 1000 1000 1000 1000 1000",
"output": "YES"
},
{
"input": "0 0 0 0 0 0",
"output": "YES"
},
{
"input": "633 609 369 704 573 416",
"output": "NO"
},
{
... | 1,564,244,163 | 2,147,483,647 | PyPy 3 | OK | TESTS | 53 | 218 | 14,848,000 | class CodeforcesTask890ASolution:
def __init__(self):
self.result = ''
self.scores = []
def read_input(self):
self.scores = [int(x) for x in input().split(" ")]
def process_task(self):
result = False
perms = [([5,2,1],[0,4,3]),
([1,3,0],[5,4,2]),
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exac... | ```python
class CodeforcesTask890ASolution:
def __init__(self):
self.result = ''
self.scores = []
def read_input(self):
self.scores = [int(x) for x in input().split(" ")]
def process_task(self):
result = False
perms = [([5,2,1],[0,4,3]),
([1,3,0],... | 3 | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,694,975,278 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | import sys
# sys.stdin = open("input.txt", "r")
# sys.stdout = open("output.txt", "w")
# sys.stderr = open("error.txt", "w")
# # your remaining code
t = int(input())
mn = 0
isum = 0
for i in range(t) :
a , b = map(int,input().split())
isum -= a
isum += b
if isum > mn :
mn = isum
print(mn)
... | Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
import sys
# sys.stdin = open("input.txt", "r")
# sys.stdout = open("output.txt", "w")
# sys.stderr = open("error.txt", "w")
# # your remaining code
t = int(input())
mn = 0
isum = 0
for i in range(t) :
a , b = map(int,input().split())
isum -= a
isum += b
if isum > mn :
mn = isum
p... | 3 | |
793 | A | Oleg and shares | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Oleg the bank client checks share prices every day. There are *n* share prices he is interested in. Today he observed that each second exactly one of these prices decreases by *k* rubles (note that each second exactly one price changes, but at different seconds different prices can change). Prices can become negative. ... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*k*<=≤<=109) — the number of share prices, and the amount of rubles some price decreases each second.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the initial prices. | Print the only line containing the minimum number of seconds needed for prices to become equal, of «-1» if it is impossible. | [
"3 3\n12 9 15\n",
"2 2\n10 9\n",
"4 1\n1 1000000000 1000000000 1000000000\n"
] | [
"3",
"-1",
"2999999997"
] | Consider the first example.
Suppose the third price decreases in the first second and become equal 12 rubles, then the first price decreases and becomes equal 9 rubles, and in the third second the third price decreases again and becomes equal 9 rubles. In this case all prices become equal 9 rubles in 3 seconds.
Ther... | 500 | [
{
"input": "3 3\n12 9 15",
"output": "3"
},
{
"input": "2 2\n10 9",
"output": "-1"
},
{
"input": "4 1\n1 1000000000 1000000000 1000000000",
"output": "2999999997"
},
{
"input": "1 11\n123",
"output": "0"
},
{
"input": "20 6\n38 86 86 50 98 62 32 2 14 62 98 50 2 50... | 1,639,895,317 | 2,147,483,647 | PyPy 3 | OK | TESTS | 88 | 171 | 10,956,800 | n,k=list(map(int,input().split()))
a=list(map(int,input().split()))
a.sort()
x=min(a)
ans=0
c=True
for i in a:
if (i-x)%k!=0:
c=False
break
else:
ans=ans+(i-x)//k
if c==False:
print(-1)
else:
print(ans) | Title: Oleg and shares
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Oleg the bank client checks share prices every day. There are *n* share prices he is interested in. Today he observed that each second exactly one of these prices decreases by *k* rubles (note that each second exactly o... | ```python
n,k=list(map(int,input().split()))
a=list(map(int,input().split()))
a.sort()
x=min(a)
ans=0
c=True
for i in a:
if (i-x)%k!=0:
c=False
break
else:
ans=ans+(i-x)//k
if c==False:
print(-1)
else:
print(ans)
``` | 3 | |
435 | A | Queue on Bus Stop | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | It's that time of the year when the Russians flood their countryside summer cottages (dachas) and the bus stop has a lot of people. People rarely go to the dacha on their own, it's usually a group, so the people stand in queue by groups.
The bus stop queue has *n* groups of people. The *i*-th group from the beginning ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). The next line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*m*). | Print a single integer — the number of buses that is needed to transport all *n* groups to the dacha countryside. | [
"4 3\n2 3 2 1\n",
"3 4\n1 2 1\n"
] | [
"3\n",
"1\n"
] | none | 500 | [
{
"input": "4 3\n2 3 2 1",
"output": "3"
},
{
"input": "3 4\n1 2 1",
"output": "1"
},
{
"input": "1 5\n4",
"output": "1"
},
{
"input": "5 1\n1 1 1 1 1",
"output": "5"
},
{
"input": "6 4\n1 3 2 3 4 1",
"output": "5"
},
{
"input": "6 8\n6 1 1 1 4 5",
... | 1,612,872,122 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 62 | 0 | n, m = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
c = 1
temp = 0
for i in a:
if temp+i<=m:
temp += i
else:
temp = i
c += 1
print(c)
| Title: Queue on Bus Stop
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's that time of the year when the Russians flood their countryside summer cottages (dachas) and the bus stop has a lot of people. People rarely go to the dacha on their own, it's usually a group, so the people stand... | ```python
n, m = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
c = 1
temp = 0
for i in a:
if temp+i<=m:
temp += i
else:
temp = i
c += 1
print(c)
``` | 3 | |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactl... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,604,789,872 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 218 | 307,200 | n, m = input().split()
n = int(n)
m = int(m)
dec = {}
lis = []
for i in range(int(m)):
a, b = input().split()
a = int(a)
b = int(b)
pr = (a, b)
lis.append(pr)
lis.sort(key=lambda x: x[1], reverse=True)
max_count = 0
for i in range(len(lis)):
if lis[i][0] <= n:
n = n-lis[i]... | Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* mat... | ```python
n, m = input().split()
n = int(n)
m = int(m)
dec = {}
lis = []
for i in range(int(m)):
a, b = input().split()
a = int(a)
b = int(b)
pr = (a, b)
lis.append(pr)
lis.sort(key=lambda x: x[1], reverse=True)
max_count = 0
for i in range(len(lis)):
if lis[i][0] <= n:
n ... | 3 |
148 | A | Insomnia cure | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | «One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entertained herself at best she could. Tonight she imagined that all dragons were here to steal her, and ... | Input data contains integer numbers *k*,<=*l*,<=*m*,<=*n* and *d*, each number in a separate line (1<=≤<=*k*,<=*l*,<=*m*,<=*n*<=≤<=10, 1<=≤<=*d*<=≤<=105). | Output the number of damaged dragons. | [
"1\n2\n3\n4\n12\n",
"2\n3\n4\n5\n24\n"
] | [
"12\n",
"17\n"
] | In the first case every first dragon got punched with a frying pan. Some of the dragons suffered from other reasons as well, but the pan alone would be enough.
In the second case dragons 1, 7, 11, 13, 17, 19 and 23 escaped unharmed. | 1,000 | [
{
"input": "1\n2\n3\n4\n12",
"output": "12"
},
{
"input": "2\n3\n4\n5\n24",
"output": "17"
},
{
"input": "1\n1\n1\n1\n100000",
"output": "100000"
},
{
"input": "10\n9\n8\n7\n6",
"output": "0"
},
{
"input": "8\n4\n4\n3\n65437",
"output": "32718"
},
{
"i... | 1,694,837,550 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | q=int(input())
w=int(input())
e=int(input())
r=int(input())
t=int(input())
y=0
for dragon in range(1,t+1):
if dragon %q == 0 or dragon % w ==0 or dragon % e ==0 or dragon % r == 0:
y+=1
print(y)
| Title: Insomnia cure
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
«One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entert... | ```python
q=int(input())
w=int(input())
e=int(input())
r=int(input())
t=int(input())
y=0
for dragon in range(1,t+1):
if dragon %q == 0 or dragon % w ==0 or dragon % e ==0 or dragon % r == 0:
y+=1
print(y)
``` | 3 | |
78 | A | Haiku | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Haiku | 2 | 256 | Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syll... | The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The *i*-th line contains the *i*-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailin... | Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes). | [
"on codeforces \nbeta round is running\n a rustling of keys \n",
"how many gallons\nof edo s rain did you drink\n cuckoo\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "on codeforces \nbeta round is running\n a rustling of keys ",
"output": "YES"
},
{
"input": "how many gallons\nof edo s rain did you drink\n cuckoo",
"output": "NO"
},
{
"input": " hatsu shigure\n saru mo komino wo\nhoshige nari",
... | 1,641,724,106 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 124 | 0 | def is_haiku(l1, l2, l3):
vowel = ['a', 'e', 'i', 'o', 'u']
lines = [l1, l2, l3]
vowel_count = [0, 0, 0]
for index in range(len(lines)):
for char in lines[index]:
if char in vowel:
vowel_count[index] += 1
return vowel_count == [5, 7, 5]
print("Y... | Title: Haiku
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase... | ```python
def is_haiku(l1, l2, l3):
vowel = ['a', 'e', 'i', 'o', 'u']
lines = [l1, l2, l3]
vowel_count = [0, 0, 0]
for index in range(len(lines)):
for char in lines[index]:
if char in vowel:
vowel_count[index] += 1
return vowel_count == [5, 7, 5]
... | 3.969 |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,386,609,083 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 124 | 0 | n=int(input())
d=list(map(int,input().split()))
for i in range(len(d)):
d[i]=d[i]%2
print(d.index(int(d.count(1)==1))+1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
d=list(map(int,input().split()))
for i in range(len(d)):
d[i]=d[i]%2
print(d.index(int(d.count(1)==1))+1)
``` | 3.969 |
474 | A | Keyboard | PROGRAMMING | 900 | [
"implementation"
] | null | null | Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately. He accidentally moved both his hands with one position to the left or to the right. That mean... | First line of the input contains one letter describing direction of shifting ('L' or 'R' respectively for left or right).
Second line contains a sequence of characters written by Mole. The size of this sequence will be no more than 100. Sequence contains only symbols that appear on Mole's keyboard. It doesn't contain ... | Print a line that contains the original message. | [
"R\ns;;upimrrfod;pbr\n"
] | [
"allyouneedislove\n"
] | none | 500 | [
{
"input": "R\ns;;upimrrfod;pbr",
"output": "allyouneedislove"
},
{
"input": "R\nwertyuiop;lkjhgfdsxcvbnm,.",
"output": "qwertyuiolkjhgfdsazxcvbnm,"
},
{
"input": "L\nzxcvbnm,kjhgfdsaqwertyuio",
"output": "xcvbnm,.lkjhgfdswertyuiop"
},
{
"input": "R\nbubbuduppudup",
"outp... | 1,678,078,486 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 46 | 0 | letters = [
['q', 'w', 'e', 'r', 't', 'y', 'u', 'i', 'o', 'p'],
['a', 's', 'd', 'f', 'g', 'h', 'j', 'k', 'l', ';'],
['z', 'x', 'c', 'v', 'b', 'n', 'm', ',', '.', '/']
]
d = input()
s = input()
new_s = []
for l in s:
if l in letters[0]:
i = [0, letters[0].index(l)]
elif l in letters[1]:
... | Title: Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately.... | ```python
letters = [
['q', 'w', 'e', 'r', 't', 'y', 'u', 'i', 'o', 'p'],
['a', 's', 'd', 'f', 'g', 'h', 'j', 'k', 'l', ';'],
['z', 'x', 'c', 'v', 'b', 'n', 'm', ',', '.', '/']
]
d = input()
s = input()
new_s = []
for l in s:
if l in letters[0]:
i = [0, letters[0].index(l)]
elif l in lett... | 3 | |
688 | B | Lovely Palindromes | PROGRAMMING | 1,000 | [
"constructive algorithms",
"math"
] | null | null | Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is trying to love them too, but only very special and gifted people can understand the beauty behind palindro... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=10100<=000). | Print the *n*-th even-length palindrome number. | [
"1\n",
"10\n"
] | [
"11\n",
"1001\n"
] | The first 10 even-length palindrome numbers are 11, 22, 33, ... , 88, 99 and 1001. | 1,000 | [
{
"input": "1",
"output": "11"
},
{
"input": "10",
"output": "1001"
},
{
"input": "11",
"output": "1111"
},
{
"input": "12",
"output": "1221"
},
{
"input": "100",
"output": "100001"
},
{
"input": "1321",
"output": "13211231"
},
{
"input": "... | 1,592,125,090 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 109 | 1,126,400 | n=input()
s1=list(n)
s1.reverse()
n1=''.join(s1)
print(n+n1) | Title: Lovely Palindromes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is tr... | ```python
n=input()
s1=list(n)
s1.reverse()
n1=''.join(s1)
print(n+n1)
``` | 3 | |
440 | A | Forgotten Episode | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus adores TV series. Right now he is ready to finish watching a season of a popular sitcom "Graph Theory". In total, the season has *n* episodes, numbered with integers from 1 to *n*.
Polycarpus watches episodes not one by one but in a random order. He has already watched all the episodes except for one. Which... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100000) — the number of episodes in a season. Assume that the episodes are numbered by integers from 1 to *n*.
The second line contains *n*<=-<=1 integer *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the numbers of episodes that Polycarpus has watch... | Print the number of the episode that Polycarpus hasn't watched. | [
"10\n3 8 10 1 7 9 6 5 2\n"
] | [
"4\n"
] | none | 500 | [
{
"input": "10\n3 8 10 1 7 9 6 5 2",
"output": "4"
},
{
"input": "5\n4 3 2 1",
"output": "5"
},
{
"input": "2\n1",
"output": "2"
},
{
"input": "2\n2",
"output": "1"
},
{
"input": "3\n1 2",
"output": "3"
},
{
"input": "3\n1 3",
"output": "2"
},
... | 1,595,916,830 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 156 | 15,360,000 | missed = [i + 1 for i in range(int(input()))]
for i in map(int, input().split()):
missed[i - 1] = 0
print(sum(missed))
| Title: Forgotten Episode
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus adores TV series. Right now he is ready to finish watching a season of a popular sitcom "Graph Theory". In total, the season has *n* episodes, numbered with integers from 1 to *n*.
Polycarpus watches episo... | ```python
missed = [i + 1 for i in range(int(input()))]
for i in map(int, input().split()):
missed[i - 1] = 0
print(sum(missed))
``` | 3 | |
257 | C | View Angle | PROGRAMMING | 1,800 | [
"brute force",
"geometry",
"math"
] | null | null | Flatland has recently introduced a new type of an eye check for the driver's licence. The check goes like that: there is a plane with mannequins standing on it. You should tell the value of the minimum angle with the vertex at the origin of coordinates and with all mannequins standing inside or on the boarder of this a... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of mannequins.
Next *n* lines contain two space-separated integers each: *x**i*,<=*y**i* (|*x**i*|,<=|*y**i*|<=≤<=1000) — the coordinates of the *i*-th mannequin. It is guaranteed that the origin of the coordinates has no mannequin. It is gu... | Print a single real number — the value of the sought angle in degrees. The answer will be considered valid if the relative or absolute error doesn't exceed 10<=-<=6. | [
"2\n2 0\n0 2\n",
"3\n2 0\n0 2\n-2 2\n",
"4\n2 0\n0 2\n-2 0\n0 -2\n",
"2\n2 1\n1 2\n"
] | [
"90.0000000000\n",
"135.0000000000\n",
"270.0000000000\n",
"36.8698976458\n"
] | Solution for the first sample test is shown below:
Solution for the second sample test is shown below:
Solution for the third sample test is shown below:
Solution for the fourth sample test is shown below: | 1,500 | [
{
"input": "2\n2 0\n0 2",
"output": "90.0000000000"
},
{
"input": "3\n2 0\n0 2\n-2 2",
"output": "135.0000000000"
},
{
"input": "4\n2 0\n0 2\n-2 0\n0 -2",
"output": "270.0000000000"
},
{
"input": "2\n2 1\n1 2",
"output": "36.8698976458"
},
{
"input": "1\n1 1",
... | 1,621,263,643 | 1,783 | Python 3 | OK | TESTS | 56 | 1,028 | 10,649,600 | import math
def angle(x, y):
a = (x**2+y**2)**0.5
x1, y1 = x/a, y/a
my_angle = math.asin(y1)
my_angle = 180*my_angle/math.pi
if x < 0:
my_angle = 180-my_angle
if my_angle < 0:
my_angle = 360+my_angle
return my_angle
def process(M):
angles = []
f... | Title: View Angle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Flatland has recently introduced a new type of an eye check for the driver's licence. The check goes like that: there is a plane with mannequins standing on it. You should tell the value of the minimum angle with the vertex ... | ```python
import math
def angle(x, y):
a = (x**2+y**2)**0.5
x1, y1 = x/a, y/a
my_angle = math.asin(y1)
my_angle = 180*my_angle/math.pi
if x < 0:
my_angle = 180-my_angle
if my_angle < 0:
my_angle = 360+my_angle
return my_angle
def process(M):
angles =... | 3 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,695,645,761 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 124 | 0 | length, breadth = [int(x) for x in input().split()]
area = length * breadth
max_dominoes = area // 2
print(max_dominoes) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
length, breadth = [int(x) for x in input().split()]
area = length * breadth
max_dominoes = area // 2
print(max_dominoes)
``` | 3.969 |
327 | A | Flipping Game | PROGRAMMING | 1,200 | [
"brute force",
"dp",
"implementation"
] | null | null | Iahub got bored, so he invented a game to be played on paper.
He writes *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Each of those integers can be either 0 or 1. He's allowed to do exactly one move: he chooses two indices *i* and *j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) and flips all values *a**k* for which their positions are in... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100). In the second line of the input there are *n* integers: *a*1,<=*a*2,<=...,<=*a**n*. It is guaranteed that each of those *n* values is either 0 or 1. | Print an integer — the maximal number of 1s that can be obtained after exactly one move. | [
"5\n1 0 0 1 0\n",
"4\n1 0 0 1\n"
] | [
"4\n",
"4\n"
] | In the first case, flip the segment from 2 to 5 (*i* = 2, *j* = 5). That flip changes the sequence, it becomes: [1 1 1 0 1]. So, it contains four ones. There is no way to make the whole sequence equal to [1 1 1 1 1].
In the second case, flipping only the second and the third element (*i* = 2, *j* = 3) will turn all nu... | 500 | [
{
"input": "5\n1 0 0 1 0",
"output": "4"
},
{
"input": "4\n1 0 0 1",
"output": "4"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "8\n1 0 0 0 1 0 0 0",
"output": "7"
},
{
"input": "18\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 ... | 1,695,272,594 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 21 | 124 | 0 | n = int(input())
l = [int(x) for x in input().split()]
s=c=0
m = -100000000
for i in l:
if i==0:
s+=1
else:
c+=1
s-=1
if s>m:
m=s
if s<0:
s=0
print(m+c) | Title: Flipping Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub got bored, so he invented a game to be played on paper.
He writes *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Each of those integers can be either 0 or 1. He's allowed to do exactly one move: he chooses two indices *... | ```python
n = int(input())
l = [int(x) for x in input().split()]
s=c=0
m = -100000000
for i in l:
if i==0:
s+=1
else:
c+=1
s-=1
if s>m:
m=s
if s<0:
s=0
print(m+c)
``` | 3 | |
129 | A | Cookies | PROGRAMMING | 900 | [
"implementation"
] | null | null | Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wan... | The first line contains the only integer *n* (1<=≤<=*n*<=≤<=100) — the number of cookie bags Anna and Maria have. The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100) — the number of cookies in the *i*-th bag. | Print in the only line the only number — the sought number of ways. If there are no such ways print 0. | [
"1\n1\n",
"10\n1 2 2 3 4 4 4 2 2 2\n",
"11\n2 2 2 2 2 2 2 2 2 2 99\n"
] | [
"1\n",
"8\n",
"1\n"
] | In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, t... | 500 | [
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 2 2 3 4 4 4 2 2 2",
"output": "8"
},
{
"input": "11\n2 2 2 2 2 2 2 2 2 2 99",
"output": "1"
},
{
"input": "2\n1 1",
"output": "0"
},
{
"input": "2\n2 2",
"output": "2"
},
{
"input": "2\n1 2",
"o... | 1,588,924,930 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 248 | 6,656,000 | integer = int
string = str
length = len
def main():
n=int(input())
l=list(map(integer,input().split()))
add=0
odd=0
even=0
for i in l:
add+=i
if i%2:
odd+=1
else:
even+=1
if add%2:
print(odd)
else:
prin... | Title: Cookies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't wan... | ```python
integer = int
string = str
length = len
def main():
n=int(input())
l=list(map(integer,input().split()))
add=0
odd=0
even=0
for i in l:
add+=i
if i%2:
odd+=1
else:
even+=1
if add%2:
print(odd)
else:
... | 3 | |
276 | A | Lunch Rush | PROGRAMMING | 900 | [
"implementation"
] | null | null | Having written another programming contest, three Rabbits decided to grab some lunch. The coach gave the team exactly *k* time units for the lunch break.
The Rabbits have a list of *n* restaurants to lunch in: the *i*-th restaurant is characterized by two integers *f**i* and *t**i*. Value *t**i* shows the time the Rab... | The first line contains two space-separated integers — *n* (1<=≤<=*n*<=≤<=104) and *k* (1<=≤<=*k*<=≤<=109) — the number of restaurants in the Rabbits' list and the time the coach has given them to lunch, correspondingly. Each of the next *n* lines contains two space-separated integers — *f**i* (1<=≤<=*f**i*<=≤<=109) an... | In a single line print a single integer — the maximum joy value that the Rabbits will get from the lunch. | [
"2 5\n3 3\n4 5\n",
"4 6\n5 8\n3 6\n2 3\n2 2\n",
"1 5\n1 7\n"
] | [
"4\n",
"3\n",
"-1\n"
] | none | 500 | [
{
"input": "2 5\n3 3\n4 5",
"output": "4"
},
{
"input": "4 6\n5 8\n3 6\n2 3\n2 2",
"output": "3"
},
{
"input": "1 5\n1 7",
"output": "-1"
},
{
"input": "4 9\n10 13\n4 18\n13 3\n10 6",
"output": "13"
},
{
"input": "1 1\n1 1000000000",
"output": "-999999998"
}... | 1,643,950,525 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 122 | 409,600 | n,k = map(int, input().split())
l = []
m = []
o = []
s = 0
for i in range(n):
f,t = map(int, input().split())
l.append(f)
m.append(t)
if m[i]>k:
s = l[i]-(m[i]-k)
o.append(s)
i = i + 1
else:
s = l[i]
o.append(s)
i = i + 1
print(max(o)) | Title: Lunch Rush
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Having written another programming contest, three Rabbits decided to grab some lunch. The coach gave the team exactly *k* time units for the lunch break.
The Rabbits have a list of *n* restaurants to lunch in: the *i*-th re... | ```python
n,k = map(int, input().split())
l = []
m = []
o = []
s = 0
for i in range(n):
f,t = map(int, input().split())
l.append(f)
m.append(t)
if m[i]>k:
s = l[i]-(m[i]-k)
o.append(s)
i = i + 1
else:
s = l[i]
o.append(s)
i = i + 1
pri... | 3 | |
876 | B | Divisiblity of Differences | PROGRAMMING | 1,300 | [
"implementation",
"math",
"number theory"
] | null | null | You are given a multiset of *n* integers. You should select exactly *k* of them in a such way that the difference between any two of them is divisible by *m*, or tell that it is impossible.
Numbers can be repeated in the original multiset and in the multiset of selected numbers, but number of occurrences of any number... | First line contains three integers *n*, *k* and *m* (2<=≤<=*k*<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=100<=000) — number of integers in the multiset, number of integers you should select and the required divisor of any pair of selected integers.
Second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=... | If it is not possible to select *k* numbers in the desired way, output «No» (without the quotes).
Otherwise, in the first line of output print «Yes» (without the quotes). In the second line print *k* integers *b*1,<=*b*2,<=...,<=*b**k* — the selected numbers. If there are multiple possible solutions, print any of them... | [
"3 2 3\n1 8 4\n",
"3 3 3\n1 8 4\n",
"4 3 5\n2 7 7 7\n"
] | [
"Yes\n1 4 ",
"No",
"Yes\n2 7 7 "
] | none | 1,000 | [
{
"input": "3 2 3\n1 8 4",
"output": "Yes\n1 4 "
},
{
"input": "3 3 3\n1 8 4",
"output": "No"
},
{
"input": "4 3 5\n2 7 7 7",
"output": "Yes\n2 7 7 "
},
{
"input": "9 9 5\n389149775 833127990 969340400 364457730 48649145 316121525 640054660 924273385 973207825",
"output":... | 1,508,152,603 | 703 | Python 3 | OK | TESTS | 63 | 218 | 13,926,400 | n,k,m = map(int, input().split())
a = list(map(int, input().split()))
d = {}
for i in range(n):
r = a[i]%m
if r not in d:
d[r] = 0
d[r]+=1
ans_r=None
for key in d:
if d[key] >= k:
ans_r=key
break
if ans_r is None:
print('No')
else:
ans = []
for ... | Title: Divisiblity of Differences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a multiset of *n* integers. You should select exactly *k* of them in a such way that the difference between any two of them is divisible by *m*, or tell that it is impossible.
Numbers can be re... | ```python
n,k,m = map(int, input().split())
a = list(map(int, input().split()))
d = {}
for i in range(n):
r = a[i]%m
if r not in d:
d[r] = 0
d[r]+=1
ans_r=None
for key in d:
if d[key] >= k:
ans_r=key
break
if ans_r is None:
print('No')
else:
ans = []... | 3 | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,662,892,203 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 46 | 0 | l = [int(l) for l in input().split()]
n = l[0]; m = l[1]
p = ''
for i in range(n):
x = [str(x) for x in input().split()]
for j in x:
if j == 'C' or j == 'M' or j == 'Y':
p = "#Color"
print(p)
break
if p != '': break
if p == '':
print("#Black&W... | Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
l = [int(l) for l in input().split()]
n = l[0]; m = l[1]
p = ''
for i in range(n):
x = [str(x) for x in input().split()]
for j in x:
if j == 'C' or j == 'M' or j == 'Y':
p = "#Color"
print(p)
break
if p != '': break
if p == '':
print... | 3 | |
61 | D | Eternal Victory | PROGRAMMING | 1,800 | [
"dfs and similar",
"graphs",
"greedy",
"shortest paths",
"trees"
] | D. Eternal Victory | 2 | 256 | Valerian was captured by Shapur. The victory was such a great one that Shapur decided to carve a scene of Valerian's defeat on a mountain. So he had to find the best place to make his victory eternal!
He decided to visit all *n* cities of Persia to find the best available mountain, but after the recent war he was too ... | First line contains a single natural number *n* (1<=≤<=*n*<=≤<=105) — the amount of cities.
Next *n*<=-<=1 lines contain 3 integer numbers each *x**i*, *y**i* and *w**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*,<=0<=≤<=*w**i*<=≤<=2<=×<=104). *x**i* and *y**i* are two ends of a road and *w**i* is the length of that road. | A single integer number, the minimal length of Shapur's travel.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d). | [
"3\n1 2 3\n2 3 4\n",
"3\n1 2 3\n1 3 3\n"
] | [
"7\n",
"9\n"
] | none | 2,000 | [
{
"input": "3\n1 2 3\n2 3 4",
"output": "7"
},
{
"input": "3\n1 2 3\n1 3 3",
"output": "9"
},
{
"input": "5\n5 3 60\n4 3 63\n2 1 97\n3 1 14",
"output": "371"
},
{
"input": "3\n2 1 63\n3 1 78",
"output": "204"
},
{
"input": "13\n8 2 58\n2 1 49\n13 10 41\n11 9 67\n6... | 1,619,556,298 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 655 | 18,432,000 | n = int(input())
matrix = [[] * n for i in range(n)]
conn = dict()
def dfs(el, el2):
suma = 0
for element in matrix[el]:
if element[0] != el2:
suma = max(suma, element[1]+dfs(element[0],el))
return suma
suma=0
for i in range(n-1):
line = input()
line = line.spli... | Title: Eternal Victory
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Valerian was captured by Shapur. The victory was such a great one that Shapur decided to carve a scene of Valerian's defeat on a mountain. So he had to find the best place to make his victory eternal!
He decided to visit a... | ```python
n = int(input())
matrix = [[] * n for i in range(n)]
conn = dict()
def dfs(el, el2):
suma = 0
for element in matrix[el]:
if element[0] != el2:
suma = max(suma, element[1]+dfs(element[0],el))
return suma
suma=0
for i in range(n-1):
line = input()
line =... | 3.801918 |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,692,717,212 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | string = input()
summ1 = sum(i.isupper() for i in string)
summ2 = sum(k.islower() for k in string)
if summ2 >= summ1:
print(string.lower())
elif summ1 > summ2:
print(string.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
string = input()
summ1 = sum(i.isupper() for i in string)
summ2 = sum(k.islower() for k in string)
if summ2 >= summ1:
print(string.lower())
elif summ1 > summ2:
print(string.upper())
``` | 3.977 |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,696,290,875 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 186 | 1,024,000 | # LUOGU_RID: 127188383
a=input()
if '0' in a:
e=a.index('0')
a=a+'0'
a=a[:e]+a[e+1:][:-1]
else:
a=a[1:]
print(a) | Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
# LUOGU_RID: 127188383
a=input()
if '0' in a:
e=a.index('0')
a=a+'0'
a=a[:e]+a[e+1:][:-1]
else:
a=a[1:]
print(a)
``` | 3 | |
1,005 | B | Delete from the Left | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't choose a string if it is empty.
For example:
- by applying a move to the string "where", the result is ... | The first line of the input contains $s$. In the second line of the input contains $t$. Both strings consist only of lowercase Latin letters. The number of letters in each string is between 1 and $2\cdot10^5$, inclusive. | Output the fewest number of moves required. It is possible that, in the end, both strings will be equal to the empty string, and so, are equal to each other. In this case, the answer is obviously the sum of the lengths of the given strings. | [
"test\nwest\n",
"codeforces\nyes\n",
"test\nyes\n",
"b\nab\n"
] | [
"2\n",
"9\n",
"7\n",
"1\n"
] | In the first example, you should apply the move once to the first string and apply the move once to the second string. As a result, both strings will be equal to "est".
In the second example, the move should be applied to the string "codeforces" $8$ times. As a result, the string becomes "codeforces" $\to$ "es". The m... | 0 | [
{
"input": "test\nwest",
"output": "2"
},
{
"input": "codeforces\nyes",
"output": "9"
},
{
"input": "test\nyes",
"output": "7"
},
{
"input": "b\nab",
"output": "1"
},
{
"input": "z\nz",
"output": "0"
},
{
"input": "abacabadabacaba\nabacabadacaba",
... | 1,640,258,213 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 28 | 155 | 2,355,200 | import sys
input = sys.stdin.readline
def main():
S = input()
T = input()
ls = len(S)
lt = len(T)
S = S[::-1]
T = T[::-1]
for i in range(min(ls, lt)):
if S[i] != T[i]:
break
else:
i += 1
print(ls + lt - i * 2)
for _ in range(1):
... | Title: Delete from the Left
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't ... | ```python
import sys
input = sys.stdin.readline
def main():
S = input()
T = input()
ls = len(S)
lt = len(T)
S = S[::-1]
T = T[::-1]
for i in range(min(ls, lt)):
if S[i] != T[i]:
break
else:
i += 1
print(ls + lt - i * 2)
for _ in rang... | 3 | |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The produ... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second... | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,591,970,933 | 2,147,483,647 | PyPy 3 | OK | TESTS | 20 | 280 | 0 | #A. Array
n = int(input())
a,b,c =[],[],[]
l = list(map(int,input().split()))
for i in l:
if i<0:
a.append(i)
elif i>0:
b.append(i)
else:
c.append(i)
if len(b)==0 and len(a)>2:
b.append(a.pop())
b.append(a.pop())
if len(a)%2==0:
c.append(a.pop())
pr... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. T... | ```python
#A. Array
n = int(input())
a,b,c =[],[],[]
l = list(map(int,input().split()))
for i in l:
if i<0:
a.append(i)
elif i>0:
b.append(i)
else:
c.append(i)
if len(b)==0 and len(a)>2:
b.append(a.pop())
b.append(a.pop())
if len(a)%2==0:
c.append(a.pop(... | 3 | |
534 | C | Polycarpus' Dice | PROGRAMMING | 1,600 | [
"math"
] | null | null | Polycarp has *n* dice *d*1,<=*d*2,<=...,<=*d**n*. The *i*-th dice shows numbers from 1 to *d**i*. Polycarp rolled all the dice and the sum of numbers they showed is *A*. Agrippina didn't see which dice showed what number, she knows only the sum *A* and the values *d*1,<=*d*2,<=...,<=*d**n*. However, she finds it enough... | The first line contains two integers *n*,<=*A* (1<=≤<=*n*<=≤<=2·105,<=*n*<=≤<=*A*<=≤<=*s*) — the number of dice and the sum of shown values where *s*<==<=*d*1<=+<=*d*2<=+<=...<=+<=*d**n*.
The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (1<=≤<=*d**i*<=≤<=106), where *d**i* is the maximum value that the... | Print *n* integers *b*1,<=*b*2,<=...,<=*b**n*, where *b**i* is the number of values for which it is guaranteed that the *i*-th dice couldn't show them. | [
"2 8\n4 4\n",
"1 3\n5\n",
"2 3\n2 3\n"
] | [
"3 3 ",
"4 ",
"0 1 "
] | In the first sample from the statement *A* equal to 8 could be obtained in the only case when both the first and the second dice show 4. Correspondingly, both dice couldn't show values 1, 2 or 3.
In the second sample from the statement *A* equal to 3 could be obtained when the single dice shows 3. Correspondingly, it ... | 1,500 | [
{
"input": "2 8\n4 4",
"output": "3 3 "
},
{
"input": "1 3\n5",
"output": "4 "
},
{
"input": "2 3\n2 3",
"output": "0 1 "
},
{
"input": "1 1\n3",
"output": "2 "
},
{
"input": "1 2\n3",
"output": "2 "
},
{
"input": "2 2\n2 3",
"output": "1 2 "
},
... | 1,542,744,352 | 2,147,483,647 | PyPy 3 | OK | TESTS | 99 | 358 | 20,889,600 | n, A = map(int, input().split())
d = [int(x) for x in input().split()]
s = sum(d)
print(' '.join([str(x - min(x, A - n + 1) + max(1, A - s + x) - 1) for x in d])) | Title: Polycarpus' Dice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has *n* dice *d*1,<=*d*2,<=...,<=*d**n*. The *i*-th dice shows numbers from 1 to *d**i*. Polycarp rolled all the dice and the sum of numbers they showed is *A*. Agrippina didn't see which dice showed what numb... | ```python
n, A = map(int, input().split())
d = [int(x) for x in input().split()]
s = sum(d)
print(' '.join([str(x - min(x, A - n + 1) + max(1, A - s + x) - 1) for x in d]))
``` | 3 | |
432 | D | Prefixes and Suffixes | PROGRAMMING | 2,000 | [
"dp",
"string suffix structures",
"strings",
"two pointers"
] | null | null | You have a string *s*<==<=*s*1*s*2...*s*|*s*|, where |*s*| is the length of string *s*, and *s**i* its *i*-th character.
Let's introduce several definitions:
- A substring *s*[*i*..*j*] (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|) of string *s* is string *s**i**s**i*<=+<=1...*s**j*. - The prefix of string *s* of length *l* (1<=≤... | The single line contains a sequence of characters *s*1*s*2...*s*|*s*| (1<=≤<=|*s*|<=≤<=105) — string *s*. The string only consists of uppercase English letters. | In the first line, print integer *k* (0<=≤<=*k*<=≤<=|*s*|) — the number of prefixes that match a suffix of string *s*. Next print *k* lines, in each line print two integers *l**i* *c**i*. Numbers *l**i* *c**i* mean that the prefix of the length *l**i* matches the suffix of length *l**i* and occurs in string *s* as a su... | [
"ABACABA\n",
"AAA\n"
] | [
"3\n1 4\n3 2\n7 1\n",
"3\n1 3\n2 2\n3 1\n"
] | none | 2,000 | [
{
"input": "ABACABA",
"output": "3\n1 4\n3 2\n7 1"
},
{
"input": "AAA",
"output": "3\n1 3\n2 2\n3 1"
},
{
"input": "A",
"output": "1\n1 1"
},
{
"input": "AAAAAAAAAAAAAAAAXAAAAAAAAAAAAAAAAAAAAAAA",
"output": "17\n1 39\n2 37\n3 35\n4 33\n5 31\n6 29\n7 27\n8 25\n9 23\n10 21\... | 1,692,412,537 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 389 | 64,204,800 | from sys import stdin
from collections import defaultdict,Counter
def line(): return stdin.readline().strip()
def rd(converter): return converter(line())
def rl(converter, delimeter = None): return list(map(converter, line().split(delimeter)))
def rls(num_lines, converter): return [rd(converter) for i in range(num_lin... | Title: Prefixes and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a string *s*<==<=*s*1*s*2...*s*|*s*|, where |*s*| is the length of string *s*, and *s**i* its *i*-th character.
Let's introduce several definitions:
- A substring *s*[*i*..*j*] (1<=≤<=*i*<=≤<=*j*<=≤<=... | ```python
from sys import stdin
from collections import defaultdict,Counter
def line(): return stdin.readline().strip()
def rd(converter): return converter(line())
def rl(converter, delimeter = None): return list(map(converter, line().split(delimeter)))
def rls(num_lines, converter): return [rd(converter) for i in ran... | 3 | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,690,545,539 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 154 | 0 | s = str(input())
t = str(input())
w = len(s)
y = ''.join(reversed(s))
flag = True
for i in range(w):
if t[i] != y[i]:
flag = False
break
if flag:
print("YES")
else:
print("NO")
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
s = str(input())
t = str(input())
w = len(s)
y = ''.join(reversed(s))
flag = True
for i in range(w):
if t[i] != y[i]:
flag = False
break
if flag:
print("YES")
else:
print("NO")
``` | 3.9615 |
844 | A | Diversity | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"strings"
] | null | null | Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it is allowed to change characters only to lowercase Latin letters too. | First line of input contains string *s*, consisting only of lowercase Latin letters (1<=≤<=|*s*|<=≤<=1000, |*s*| denotes the length of *s*).
Second line of input contains integer *k* (1<=≤<=*k*<=≤<=26). | Print single line with a minimum number of necessary changes, or the word «impossible» (without quotes) if it is impossible. | [
"yandex\n6\n",
"yahoo\n5\n",
"google\n7\n"
] | [
"0\n",
"1\n",
"impossible\n"
] | In the first test case string contains 6 different letters, so we don't need to change anything.
In the second test case string contains 4 different letters: {'*a*', '*h*', '*o*', '*y*'}. To get 5 different letters it is necessary to change one occurrence of '*o*' to some letter, which doesn't occur in the string, for... | 500 | [
{
"input": "yandex\n6",
"output": "0"
},
{
"input": "yahoo\n5",
"output": "1"
},
{
"input": "google\n7",
"output": "impossible"
},
{
"input": "a\n1",
"output": "0"
},
{
"input": "z\n2",
"output": "impossible"
},
{
"input": "fwgfrwgkuwghfiruhewgirueguhe... | 1,626,774,601 | 2,147,483,647 | PyPy 3 | OK | TESTS | 41 | 93 | 20,172,800 | s=input()
n=int(input())
if(n<=len(s)):
print(max(0,n-len(set(s))))
else:
print('impossible') | Title: Diversity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it... | ```python
s=input()
n=int(input())
if(n<=len(s)):
print(max(0,n-len(set(s))))
else:
print('impossible')
``` | 3 | |
672 | B | Different is Good | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation",
"strings"
] | null | null | A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are different, he wants all substrings of his string *s* to be distinct. Substring is a string formed by some... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the length of the string *s*.
The second line contains the string *s* of length *n* consisting of only lowercase English letters. | If it's impossible to change the string *s* such that all its substring are distinct print -1. Otherwise print the minimum required number of changes. | [
"2\naa\n",
"4\nkoko\n",
"5\nmurat\n"
] | [
"1\n",
"2\n",
"0\n"
] | In the first sample one of the possible solutions is to change the first character to 'b'.
In the second sample, one may change the first character to 'a' and second character to 'b', so the string becomes "abko". | 1,000 | [
{
"input": "2\naa",
"output": "1"
},
{
"input": "4\nkoko",
"output": "2"
},
{
"input": "5\nmurat",
"output": "0"
},
{
"input": "6\nacbead",
"output": "1"
},
{
"input": "7\ncdaadad",
"output": "4"
},
{
"input": "25\npeoaicnbisdocqofsqdpgobpn",
"outp... | 1,679,149,201 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 93 | 2,764,800 | import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n = int(input())
s = list(input().rstrip())
cnt = [0] * 26
for i in s:
cnt[i - 97] += 1
ans = 0
for i in cnt:
ans += max(i - 1, 0)
if n > 26:
ans = -1
print(ans) | Title: Different is Good
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are di... | ```python
import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n = int(input())
s = list(input().rstrip())
cnt = [0] * 26
for i in s:
cnt[i - 97] += 1
ans = 0
for i in cnt:
ans += max(i - 1, 0)
if n > 26:
ans = -1
print(ans)
``` | 3 | |
740 | B | Alyona and flowers | PROGRAMMING | 1,200 | [
"constructive algorithms"
] | null | null | Little Alyona is celebrating Happy Birthday! Her mother has an array of *n* flowers. Each flower has some mood, the mood of *i*-th flower is *a**i*. The mood can be positive, zero or negative.
Let's define a subarray as a segment of consecutive flowers. The mother suggested some set of subarrays. Alyona wants to choos... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of flowers and the number of subarrays suggested by the mother.
The second line contains the flowers moods — *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=100<=≤<=*a**i*<=≤<=100).
The next *m* lines contain the description of the ... | Print single integer — the maximum possible value added to the Alyona's happiness. | [
"5 4\n1 -2 1 3 -4\n1 2\n4 5\n3 4\n1 4\n",
"4 3\n1 2 3 4\n1 3\n2 4\n1 1\n",
"2 2\n-1 -2\n1 1\n1 2\n"
] | [
"7\n",
"16\n",
"0\n"
] | The first example is the situation described in the statements.
In the second example Alyona should choose all subarrays.
The third example has answer 0 because Alyona can choose none of the subarrays. | 1,000 | [
{
"input": "5 4\n1 -2 1 3 -4\n1 2\n4 5\n3 4\n1 4",
"output": "7"
},
{
"input": "4 3\n1 2 3 4\n1 3\n2 4\n1 1",
"output": "16"
},
{
"input": "2 2\n-1 -2\n1 1\n1 2",
"output": "0"
},
{
"input": "5 6\n1 1 1 -1 0\n2 4\n1 3\n4 5\n1 5\n1 4\n4 5",
"output": "8"
},
{
"inpu... | 1,479,921,957 | 3,057 | Python 3 | OK | TESTS | 53 | 62 | 0 | n,m=map(int,input().split())
d=input().split()
d=[int(x) for x in d]
c=0
for i in range(m):
l=input().split()
l=[int(x) for x in l]
k=0
for j in range(l[0]-1,l[1]):
k+=d[j]
if k>0:
c+=k
print(c)
| Title: Alyona and flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Alyona is celebrating Happy Birthday! Her mother has an array of *n* flowers. Each flower has some mood, the mood of *i*-th flower is *a**i*. The mood can be positive, zero or negative.
Let's define a subarra... | ```python
n,m=map(int,input().split())
d=input().split()
d=[int(x) for x in d]
c=0
for i in range(m):
l=input().split()
l=[int(x) for x in l]
k=0
for j in range(l[0]-1,l[1]):
k+=d[j]
if k>0:
c+=k
print(c)
``` | 3 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,691,606,894 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | import math
N, M, A = input().split()
n = int(N)
m = int(M)
a = int(A)
print(math.ceil(m/a)*math.ceil(n/a)) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
import math
N, M, A = input().split()
n = int(N)
m = int(M)
a = int(A)
print(math.ceil(m/a)*math.ceil(n/a))
``` | 3.977 |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,659,529,746 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 124 | 0 | from math import sqrt
x, y, z = map(int, input().split())
a = sqrt (int((x * y) / z))
b = sqrt (int((x * z) / y))
c = sqrt (int((y * z) / x))
print(int((a + b + c) * 4)) | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
from math import sqrt
x, y, z = map(int, input().split())
a = sqrt (int((x * y) / z))
b = sqrt (int((x * z) / y))
c = sqrt (int((y * z) / x))
print(int((a + b + c) * 4))
``` | 3 | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,667,992,558 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 46 | 0 | n = input().split()
n[0] = int(n[0])
n[1] = int(n[1])
m = input().split()
for i in range(0, n[0]):
m[i] = int(m[i])
m.sort()
s = 0
for j in range(0, n[0]):
p = 5 - m[j]
if p >= n[1]:
s = s + 1
c = s//3
print(c) | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
n = input().split()
n[0] = int(n[0])
n[1] = int(n[1])
m = input().split()
for i in range(0, n[0]):
m[i] = int(m[i])
m.sort()
s = 0
for j in range(0, n[0]):
p = 5 - m[j]
if p >= n[1]:
s = s + 1
c = s//3
print(c)
``` | 3 | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,655,703,089 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 46 | 0 | n=int(input())
if n%2!=0:
print(0)
elif n<6:
print(0)
else:
c=0
n=n//2
c=n-1
print(c//2) | Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
n=int(input())
if n%2!=0:
print(0)
elif n<6:
print(0)
else:
c=0
n=n//2
c=n-1
print(c//2)
``` | 3 | |
34 | A | Reconnaissance 2 | PROGRAMMING | 800 | [
"implementation"
] | A. Reconnaissance 2 | 2 | 256 | *n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a ... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). The soldier heights are given in clockwise or counterclockwise direction. | Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle. | [
"5\n10 12 13 15 10\n",
"4\n10 20 30 40\n"
] | [
"5 1\n",
"1 2\n"
] | none | 500 | [
{
"input": "5\n10 12 13 15 10",
"output": "5 1"
},
{
"input": "4\n10 20 30 40",
"output": "1 2"
},
{
"input": "6\n744 359 230 586 944 442",
"output": "2 3"
},
{
"input": "5\n826 747 849 687 437",
"output": "1 2"
},
{
"input": "5\n999 999 993 969 999",
"output"... | 1,632,896,859 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 124 | 6,963,200 | a=input();a,b,c=list(map(int,input().split())),1000,0;a.append(a[0])
for i in range(len(a)-1):
if abs(a[i]-a[i+1])<b:
b,c=abs(a[i]-a[i+1]),i
if c-len(a)+2:
print(c+1,c+2)
else:
print(c+1,1) | Title: Reconnaissance 2
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
*n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So... | ```python
a=input();a,b,c=list(map(int,input().split())),1000,0;a.append(a[0])
for i in range(len(a)-1):
if abs(a[i]-a[i+1])<b:
b,c=abs(a[i]-a[i+1]),i
if c-len(a)+2:
print(c+1,c+2)
else:
print(c+1,1)
``` | 3.95603 |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,642,310,047 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | if __name__ == "__main__":
r, c = input().strip().split()
r = int(r)
c = int(c)
count = 0
cake = []
for i in range(r):
temp = [char for char in input().strip()]
if 'S' not in temp:
count += c
r -= 1
else:
cake.append(temp)
for i in ... | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
if __name__ == "__main__":
r, c = input().strip().split()
r = int(r)
c = int(c)
count = 0
cake = []
for i in range(r):
temp = [char for char in input().strip()]
if 'S' not in temp:
count += c
r -= 1
else:
cake.append(temp)
... | 3 | |
770 | B | Maximize Sum of Digits | PROGRAMMING | 1,300 | [
"*special",
"implementation",
"math"
] | null | null | Anton has the integer *x*. He is interested what positive integer, which doesn't exceed *x*, has the maximum sum of digits.
Your task is to help Anton and to find the integer that interests him. If there are several such integers, determine the biggest of them. | The first line contains the positive integer *x* (1<=≤<=*x*<=≤<=1018) — the integer which Anton has. | Print the positive integer which doesn't exceed *x* and has the maximum sum of digits. If there are several such integers, print the biggest of them. Printed integer must not contain leading zeros. | [
"100\n",
"48\n",
"521\n"
] | [
"99\n",
"48\n",
"499\n"
] | none | 1,000 | [
{
"input": "100",
"output": "99"
},
{
"input": "48",
"output": "48"
},
{
"input": "521",
"output": "499"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "3"
},
{
"input": "39188",
"output":... | 1,658,183,045 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 278 | 62 | 0 | import sys
input = sys.stdin.readline
x = input()[:-1]
n = len(x)
d = [int(x)]
for i in range(1, n+1):
d.append(int(str(int(x[:i])-1) + '9'*(n-i)))
d.sort(reverse=True)
for i in range(len(d)):
if d[i] <= int(x):
c = sum([int(a) for a in str(d[i])])
d[i] = [c, d[i]]
c = max(i fo... | Title: Maximize Sum of Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton has the integer *x*. He is interested what positive integer, which doesn't exceed *x*, has the maximum sum of digits.
Your task is to help Anton and to find the integer that interests him. If there are sev... | ```python
import sys
input = sys.stdin.readline
x = input()[:-1]
n = len(x)
d = [int(x)]
for i in range(1, n+1):
d.append(int(str(int(x[:i])-1) + '9'*(n-i)))
d.sort(reverse=True)
for i in range(len(d)):
if d[i] <= int(x):
c = sum([int(a) for a in str(d[i])])
d[i] = [c, d[i]]
c ... | 3 | |
496 | A | Minimum Difficulty | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Mike is trying rock climbing but he is awful at it.
There are *n* holds on the wall, *i*-th hold is at height *a**i* off the ground. Besides, let the sequence *a**i* increase, that is, *a**i*<=<<=*a**i*<=+<=1 for all *i* from 1 to *n*<=-<=1; we will call such sequence a track. Mike thinks that the track *a*1, ...,... | The first line contains a single integer *n* (3<=≤<=*n*<=≤<=100) — the number of holds.
The next line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=1000), where *a**i* is the height where the hold number *i* hangs. The sequence *a**i* is increasing (i.e. each element except for the first one is strict... | Print a single number — the minimum difficulty of the track after removing a single hold. | [
"3\n1 4 6\n",
"5\n1 2 3 4 5\n",
"5\n1 2 3 7 8\n"
] | [
"5\n",
"2\n",
"4\n"
] | In the first sample you can remove only the second hold, then the sequence looks like (1, 6), the maximum difference of the neighboring elements equals 5.
In the second test after removing every hold the difficulty equals 2.
In the third test you can obtain sequences (1, 3, 7, 8), (1, 2, 7, 8), (1, 2, 3, 8), for whic... | 500 | [
{
"input": "3\n1 4 6",
"output": "5"
},
{
"input": "5\n1 2 3 4 5",
"output": "2"
},
{
"input": "5\n1 2 3 7 8",
"output": "4"
},
{
"input": "3\n1 500 1000",
"output": "999"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "2"
},
{
"input": "10\n1 4 9... | 1,418,834,497 | 697 | Python 3 | OK | TESTS | 19 | 61 | 0 | n, a = int(input()), list(map(int, input().split()))
ans = 20000
for i in range(1, n - 1):
b = a[:i] + a[i + 1:]
ans = min(ans, max(b[j + 1] - b[j] for j in range(n - 2)))
print(ans)
| Title: Minimum Difficulty
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mike is trying rock climbing but he is awful at it.
There are *n* holds on the wall, *i*-th hold is at height *a**i* off the ground. Besides, let the sequence *a**i* increase, that is, *a**i*<=<<=*a**i*<=+<=1 fo... | ```python
n, a = int(input()), list(map(int, input().split()))
ans = 20000
for i in range(1, n - 1):
b = a[:i] + a[i + 1:]
ans = min(ans, max(b[j + 1] - b[j] for j in range(n - 2)))
print(ans)
``` | 3 | |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't rem... | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given... | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you staye... | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,587,021,440 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 124 | 0 | n=int(input())
a=input()
if (a[0]=='S' and a[-1]=='F'):
print('YES')
else:
print('NO') | Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Franci... | ```python
n=int(input())
a=input()
if (a[0]=='S' and a[-1]=='F'):
print('YES')
else:
print('NO')
``` | 3 | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,666,158,989 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 49 | 62 | 1,740,800 | a=[*map(int,input().split())]
b=input()
x=0
for i in b:
x+=a[int(i)-1]
print(x) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
a=[*map(int,input().split())]
b=input()
x=0
for i in b:
x+=a[int(i)-1]
print(x)
``` | 3 | |
27 | A | Next Test | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | A. Next Test | 2 | 256 | «Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the next test will have, the system suggests the default value of the index. It is calculated ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=3000) — the amount of previously added tests. The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3000) — indexes of these tests. | Output the required default value for the next test index. | [
"3\n1 7 2\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "1\n1",
"output": "2"
},
{
"input": "2\n2 1",
"output": "3"
},
{
"input": "3\n3 4 1",
"output": "2"
},
{
"input": "4\n6 4 3 5",
"output": "1"
},
{
"input": "5\n3 2 1 7 4",
"output": "5"
},
{
"input": "6\n4 1 2 5 3 7",
"output": "6"
},
... | 1,596,001,638 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 280 | 21,504,000 | n = int(input())
a = list(map(int,input().split()))
a.sort()
ans, f = 0, 0
if a[0]>1:
print(1)
else:
for i in range(1,n):
if a[i]!=(a[i-1]+1):
ans = a[i-1]+1
f = 1
break
if f==1:
print(ans)
else:
print(a[-1]+1) | Title: Next Test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
«Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the... | ```python
n = int(input())
a = list(map(int,input().split()))
a.sort()
ans, f = 0, 0
if a[0]>1:
print(1)
else:
for i in range(1,n):
if a[i]!=(a[i-1]+1):
ans = a[i-1]+1
f = 1
break
if f==1:
print(ans)
else:
print(a[-1]+1)
``` | 3.889946 |
0 | none | none | none | 0 | [
"none"
] | null | null | It is a balmy spring afternoon, and Farmer John's *n* cows are ruminating about link-cut cacti in their stalls. The cows, labeled 1 through *n*, are arranged so that the *i*-th cow occupies the *i*-th stall from the left. However, Elsie, after realizing that she will forever live in the shadows beyond Bessie's limeligh... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100<=000) — the number of cows and the length of Farmer John's nap, respectively. | Output a single integer, the maximum messiness that the Mischievous Mess Makers can achieve by performing no more than *k* swaps. | [
"5 2\n",
"1 10\n"
] | [
"10\n",
"0\n"
] | In the first sample, the Mischievous Mess Makers can swap the cows in the stalls 1 and 5 during the first minute, then the cows in stalls 2 and 4 during the second minute. This reverses the arrangement of cows, giving us a total messiness of 10.
In the second sample, there is only one cow, so the maximum possible mess... | 0 | [
{
"input": "5 2",
"output": "10"
},
{
"input": "1 10",
"output": "0"
},
{
"input": "100000 2",
"output": "399990"
},
{
"input": "1 1",
"output": "0"
},
{
"input": "8 3",
"output": "27"
},
{
"input": "7 1",
"output": "11"
},
{
"input": "1000... | 1,464,935,891 | 2,147,483,647 | Python 3 | OK | TESTS | 92 | 62 | 4,812,800 | n,k = [int(i) for i in input().split()]
if n == 1:
print(0)
elif k>=(n//2):
print(((n*(n-1))//2))
else:
print(2*(n-k)*k-k)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is a balmy spring afternoon, and Farmer John's *n* cows are ruminating about link-cut cacti in their stalls. The cows, labeled 1 through *n*, are arranged so that the *i*-th cow occupies the *i*-th stall from the left. However,... | ```python
n,k = [int(i) for i in input().split()]
if n == 1:
print(0)
elif k>=(n//2):
print(((n*(n-1))//2))
else:
print(2*(n-k)*k-k)
``` | 3 | |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,625,865,735 | 2,147,483,647 | PyPy 3 | OK | TESTS | 96 | 1,045 | 11,673,600 | import sys
input = sys.stdin.readline
def I(): return input().strip()
def II(): return int(input().strip())
def LI(): return [*map(int, input().strip().split())]
import copy
import re
import string, math, time, functools, random, fractions
from heapq import heappush, heappop, heapify
from bis... | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
import sys
input = sys.stdin.readline
def I(): return input().strip()
def II(): return int(input().strip())
def LI(): return [*map(int, input().strip().split())]
import copy
import re
import string, math, time, functools, random, fractions
from heapq import heappush, heappop, heapify... | 3 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,662,201,018 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | n,m,a=map(int,input().split())
if n%a!=0: p=(n//a)+1
else: p=n//a
if m%a!=0: l=(m//a)+1
else: l=m//a
print(p*l) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
n,m,a=map(int,input().split())
if n%a!=0: p=(n//a)+1
else: p=n//a
if m%a!=0: l=(m//a)+1
else: l=m//a
print(p*l)
``` | 3.977 |
545 | D | Queue | PROGRAMMING | 1,300 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces. | Print a single number — the maximum number of not disappointed people in the queue. | [
"5\n15 2 1 5 3\n"
] | [
"4\n"
] | Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5. | 1,750 | [
{
"input": "5\n15 2 1 5 3",
"output": "4"
},
{
"input": "15\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "2"
},
{
"input": "10\n13 2 5 55 21 34 1 8 1 3",
"output": "6"
},
{
"input": "10\n8 256 16 1 2 1 64 4 128 32",
"output": "10"
},
{
"input": "10\n10000 40000 1000... | 1,698,139,424 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 109 | 13,619,200 | input()
l = list(map(int, input().split()))
l.sort()
sums = 0
cnt = 0
for i in l:
if i >= sums:
cnt += 1
sums += i
print(cnt) | Title: Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time... | ```python
input()
l = list(map(int, input().split()))
l.sort()
sums = 0
cnt = 0
for i in l:
if i >= sums:
cnt += 1
sums += i
print(cnt)
``` | 3 | |
47 | B | Coins | PROGRAMMING | 1,200 | [
"implementation"
] | B. Coins | 2 | 256 | One day Vasya came across three Berland coins. They didn't have any numbers that's why Vasya didn't understand how their denominations differ. He supposed that if one coin is heavier than the other one, then it should be worth more. Vasya weighed all the three pairs of coins on pan balance scales and told you the resul... | The input data contains the results of all the weighting, one result on each line. It is guaranteed that every coin pair was weighted exactly once. Vasya labelled the coins with letters «A», «B» and «C». Each result is a line that appears as (letter)(> or < sign)(letter). For example, if coin "A" proved lighter t... | It the results are contradictory, print Impossible. Otherwise, print without spaces the rearrangement of letters «A», «B» and «C» which represent the coins in the increasing order of their weights. | [
"A>B\nC<B\nA>C\n",
"A<B\nB>C\nC>A\n"
] | [
"CBA",
"ACB"
] | none | 1,000 | [
{
"input": "A>B\nC<B\nA>C",
"output": "CBA"
},
{
"input": "A<B\nB>C\nC>A",
"output": "ACB"
},
{
"input": "A<C\nB<A\nB>C",
"output": "Impossible"
},
{
"input": "A<B\nA<C\nB>C",
"output": "ACB"
},
{
"input": "B>A\nC<B\nC>A",
"output": "ACB"
},
{
"input":... | 1,688,764,732 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 62 | 0 | my_dict = {'A' : 0, 'B' : 0, 'C' : 0}
for _ in range(3):
a = input()
if a[1] == '>':
my_dict[a[0]] += 1
else:
my_dict[a[2]] += 1
ans = set()
res = ['', '', '']
for key, value in my_dict.items():
if value in ans:
print("Impossible")
break
else:
... | Title: Coins
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya came across three Berland coins. They didn't have any numbers that's why Vasya didn't understand how their denominations differ. He supposed that if one coin is heavier than the other one, then it should be worth more. ... | ```python
my_dict = {'A' : 0, 'B' : 0, 'C' : 0}
for _ in range(3):
a = input()
if a[1] == '>':
my_dict[a[0]] += 1
else:
my_dict[a[2]] += 1
ans = set()
res = ['', '', '']
for key, value in my_dict.items():
if value in ans:
print("Impossible")
break
else:... | 3.9845 |
165 | B | Burning Midnight Oil | PROGRAMMING | 1,500 | [
"binary search",
"implementation"
] | null | null | One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of code, drinks a cup of tea, then he writes as much as lines, drinks another cup of tea, then he writes lin... | The input consists of two integers *n* and *k*, separated by spaces — the size of the program in lines and the productivity reduction coefficient, 1<=≤<=*n*<=≤<=109, 2<=≤<=*k*<=≤<=10. | Print the only integer — the minimum value of *v* that lets Vasya write the program in one night. | [
"7 2\n",
"59 9\n"
] | [
"4\n",
"54\n"
] | In the first sample the answer is *v* = 4. Vasya writes the code in the following portions: first 4 lines, then 2, then 1, and then Vasya falls asleep. Thus, he manages to write 4 + 2 + 1 = 7 lines in a night and complete the task.
In the second sample the answer is *v* = 54. Vasya writes the code in the following por... | 1,000 | [
{
"input": "7 2",
"output": "4"
},
{
"input": "59 9",
"output": "54"
},
{
"input": "1 9",
"output": "1"
},
{
"input": "11 2",
"output": "7"
},
{
"input": "747 2",
"output": "376"
},
{
"input": "6578 2",
"output": "3293"
},
{
"input": "37212... | 1,635,573,357 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 56 | 218 | 34,611,200 | from collections import defaultdict, Counter
from queue import PriorityQueue, Queue
import math
def getLines(n, k) :
ans = 0
p = 1
while p <= n :
ans += n // p
p *= k
return ans
n, k= map(int, input().split())
l, h = 1, n
while l <= h :
mid = (l + h) // 2
x ... | Title: Burning Midnight Oil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of c... | ```python
from collections import defaultdict, Counter
from queue import PriorityQueue, Queue
import math
def getLines(n, k) :
ans = 0
p = 1
while p <= n :
ans += n // p
p *= k
return ans
n, k= map(int, input().split())
l, h = 1, n
while l <= h :
mid = (l + h) //... | 3 | |
203 | C | Photographer | PROGRAMMING | 1,400 | [
"greedy",
"sortings"
] | null | null | Valera's lifelong ambition was to be a photographer, so he bought a new camera. Every day he got more and more clients asking for photos, and one day Valera needed a program that would determine the maximum number of people he can serve.
The camera's memory is *d* megabytes. Valera's camera can take photos of high and... | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*d*<=≤<=109) — the number of clients and the camera memory size, correspondingly. The second line contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=104) — the size of one low quality photo and of one high quality photo, correspondingly. ... | On the first line print the answer to the problem — the maximum number of clients that Valera can successfully serve. Print on the second line the numbers of the client in any order. All numbers must be distinct. If there are multiple answers, print any of them. The clients are numbered starting with 1 in the order in ... | [
"3 10\n2 3\n1 4\n2 1\n1 0\n",
"3 6\n6 6\n1 1\n1 0\n1 0\n"
] | [
"2\n3 2 ",
"1\n2 "
] | none | 1,500 | [
{
"input": "3 10\n2 3\n1 4\n2 1\n1 0",
"output": "2\n3 2 "
},
{
"input": "3 6\n6 6\n1 1\n1 0\n1 0",
"output": "1\n2 "
},
{
"input": "4 5\n6 8\n1 2\n3 0\n10 2\n0 4",
"output": "0"
},
{
"input": "4 10\n6 6\n1 2\n2 2\n0 0\n0 0",
"output": "2\n3 4 "
},
{
"input": "10 ... | 1,650,456,015 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 654 | 28,160,000 | import sys
input = sys.stdin.readline
class Order:
def __init__(self, n, cost):
self.number = n
self.cost = cost
n, storage = map(int, input().split())
a, b = map(int, input().split())
orders = []
for i in range(n):
x, y = map(int, input().split())
orders.append(Order(... | Title: Photographer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera's lifelong ambition was to be a photographer, so he bought a new camera. Every day he got more and more clients asking for photos, and one day Valera needed a program that would determine the maximum number of peopl... | ```python
import sys
input = sys.stdin.readline
class Order:
def __init__(self, n, cost):
self.number = n
self.cost = cost
n, storage = map(int, input().split())
a, b = map(int, input().split())
orders = []
for i in range(n):
x, y = map(int, input().split())
orders.app... | 3 | |
981 | A | Antipalindrome | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" are not.
A substring $s[l \ldots r]$ ($1<=\leq<=l<=\leq<=r<=\leq<=|s|$) of a string $s<==<=s_{1}s_{2}... | The first line contains a non-empty string $s$ with length at most $50$ characters, containing lowercase English letters only. | If there is such a substring in $s$ that is not a palindrome, print the maximum length of such a substring. Otherwise print $0$.
Note that there can be multiple longest substrings that are not palindromes, but their length is unique. | [
"mew\n",
"wuffuw\n",
"qqqqqqqq\n"
] | [
"3\n",
"5\n",
"0\n"
] | "mew" is not a palindrome, so the longest substring of it that is not a palindrome, is the string "mew" itself. Thus, the answer for the first example is $3$.
The string "uffuw" is one of the longest non-palindrome substrings (of length $5$) of the string "wuffuw", so the answer for the second example is $5$.
All sub... | 500 | [
{
"input": "mew",
"output": "3"
},
{
"input": "wuffuw",
"output": "5"
},
{
"input": "qqqqqqqq",
"output": "0"
},
{
"input": "ijvji",
"output": "4"
},
{
"input": "iiiiiii",
"output": "0"
},
{
"input": "wobervhvvkihcuyjtmqhaaigvvgiaahqmtjyuchikvvhvrebow"... | 1,695,332,417 | 2,147,483,647 | Python 3 | OK | TESTS | 133 | 46 | 0 | def verificaPalindromo(s):
if len(s) >= 1:
if s[0] == s[-1]:
return verificaPalindromo(s[1:-1])
else:
return False
else:
return True
def antipalindromo(s):
if (verificaPalindromo(s)):
if len(s) == 1:
print(0)
else:
ant... | Title: Antipalindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" ar... | ```python
def verificaPalindromo(s):
if len(s) >= 1:
if s[0] == s[-1]:
return verificaPalindromo(s[1:-1])
else:
return False
else:
return True
def antipalindromo(s):
if (verificaPalindromo(s)):
if len(s) == 1:
print(0)
else:
... | 3 | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,694,600,834 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 46 | 0 | s=input()
up=s.upper()
f=0
z=0
ans=""
if s==up:
z=1
print(s.lower())
else:
if s[0]==s[0].lower():
for i in range(1,len(s)):
if s[i]!=s[i].upper():
f=1
if f==0:
ans+=s[0].upper()
for i in range(1,len(s)):
ans+... | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
s=input()
up=s.upper()
f=0
z=0
ans=""
if s==up:
z=1
print(s.lower())
else:
if s[0]==s[0].lower():
for i in range(1,len(s)):
if s[i]!=s[i].upper():
f=1
if f==0:
ans+=s[0].upper()
for i in range(1,len(s)):
... | 3 | |
794 | A | Bank Robbery | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and steal some money from the safes. There are many safes arranged in a line, where the *i*-th safe f... | The first line of input contains three space-separated integers, *a*, *b* and *c* (1<=≤<=*b*<=<<=*a*<=<<=*c*<=≤<=109), denoting the positions of Oleg, the first security guard and the second security guard, respectively.
The next line of input contains a single integer *n* (1<=≤<=*n*<=≤<=105), denoting the numbe... | Output a single integer: the maximum number of banknotes Oleg can take. | [
"5 3 7\n8\n4 7 5 5 3 6 2 8\n",
"6 5 7\n5\n1 5 7 92 3\n"
] | [
"4\n",
"0\n"
] | In the first example Oleg can take the banknotes in positions 4, 5, 6 (note that there are 2 banknotes at position 5). Oleg can't take the banknotes in safes 7 and 8 because he can't run into the second security guard. Similarly, Oleg cannot take the banknotes at positions 3 and 2 because he can't run into the first se... | 500 | [
{
"input": "5 3 7\n8\n4 7 5 5 3 6 2 8",
"output": "4"
},
{
"input": "6 5 7\n5\n1 5 7 92 3",
"output": "0"
},
{
"input": "3 2 4\n1\n3",
"output": "1"
},
{
"input": "5 3 8\n12\n8 3 4 5 7 6 8 3 5 4 7 6",
"output": "8"
},
{
"input": "7 3 10\n5\n3 3 3 3 3",
"output... | 1,585,562,989 | 2,147,483,647 | PyPy 3 | OK | TESTS | 46 | 249 | 10,752,000 | n,m,o = map(int,input().split())
a = int(input())
b = sorted(list(map(int,input().split())))
z =0
for i in b:
if i>m and i<o:
z+=1
print(z) | Title: Bank Robbery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and... | ```python
n,m,o = map(int,input().split())
a = int(input())
b = sorted(list(map(int,input().split())))
z =0
for i in b:
if i>m and i<o:
z+=1
print(z)
``` | 3 | |
767 | A | Snacktower | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should b... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*. | Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty. | [
"3\n3 1 2\n",
"5\n4 5 1 2 3\n"
] | [
"3\n \n2 1",
"5 4\n \n \n3 2 1\n"
] | In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right aft... | 500 | [
{
"input": "3\n3 1 2",
"output": "3 \n\n2 1 "
},
{
"input": "5\n4 5 1 2 3",
"output": "5 4 \n\n\n3 2 1 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "10\n5 1 6 2 8 3 4 10 9 7",
"output": "10 \n9 8 \n7 6 5 4 3 2 1... | 1,628,259,119 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 1,903 | 14,438,400 | import bisect
t = int(input())
s=list()
arr=list(map(int,input().split()))
for i in arr :
if i == t :
print(t,end=" ")
t-=1
else :
bisect.insort(s, i)
while len(s)>0 and t == s[-1] :
print(t,end=" ")
s.pop()
t-=1
print()
| Title: Snacktower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents sh... | ```python
import bisect
t = int(input())
s=list()
arr=list(map(int,input().split()))
for i in arr :
if i == t :
print(t,end=" ")
t-=1
else :
bisect.insort(s, i)
while len(s)>0 and t == s[-1] :
print(t,end=" ")
s.pop()
t-=1
print()
... | 3 | |
172 | B | Pseudorandom Sequence Period | PROGRAMMING | 1,200 | [
"*special",
"implementation",
"number theory"
] | null | null | Polycarpus has recently got interested in sequences of pseudorandom numbers. He learned that many programming languages generate such sequences in a similar way: (for *i*<=≥<=1). Here *a*, *b*, *m* are constants, fixed for the given realization of the pseudorandom numbers generator, *r*0 is the so-called *randseed* (t... | The single line of the input contains four integers *a*, *b*, *m* and *r*0 (1<=≤<=*m*<=≤<=105,<=0<=≤<=*a*,<=*b*<=≤<=1000,<=0<=≤<=*r*0<=<<=*m*), separated by single spaces. | Print a single integer — the period of the sequence. | [
"2 6 12 11\n",
"2 3 5 1\n",
"3 6 81 9\n"
] | [
"2\n",
"4\n",
"1\n"
] | The first sample is described above.
In the second sample the sequence is (starting from the first element): 0, 3, 4, 1, 0, 3, 4, 1, 0, ...
In the third sample the sequence is (starting from the first element): 33, 24, 78, 78, 78, 78, ... | 1,000 | [
{
"input": "2 6 12 11",
"output": "2"
},
{
"input": "2 3 5 1",
"output": "4"
},
{
"input": "3 6 81 9",
"output": "1"
},
{
"input": "10 11 12 3",
"output": "3"
},
{
"input": "4 4 5 4",
"output": "2"
},
{
"input": "0 1 6 5",
"output": "1"
},
{
... | 1,676,479,317 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 56 | 186 | 10,342,400 | a , b , m , r = map(int,input().split())
cache = {r : 0}
index = 1
flag = True
while flag :
n = (a * r + b) % m
if n in cache.keys() :
print(index - cache[n])
flag = False
exit()
else:
cache[n] = index
index += 1
r = n | Title: Pseudorandom Sequence Period
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has recently got interested in sequences of pseudorandom numbers. He learned that many programming languages generate such sequences in a similar way: (for *i*<=≥<=1). Here *a*, *b*, *m* are con... | ```python
a , b , m , r = map(int,input().split())
cache = {r : 0}
index = 1
flag = True
while flag :
n = (a * r + b) % m
if n in cache.keys() :
print(index - cache[n])
flag = False
exit()
else:
cache[n] = index
index += 1
r = n
``` | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,665,138,608 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | s=input()
x=0
y=0
for i in s:
if i.islower():
y+=1
else:
x+=1
if(x>y):
for i in s:
print(i.upper(),end="")
else:
for i in s:
print(i.lower(),end="") | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s=input()
x=0
y=0
for i in s:
if i.islower():
y+=1
else:
x+=1
if(x>y):
for i in s:
print(i.upper(),end="")
else:
for i in s:
print(i.lower(),end="")
``` | 3.977 |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirem... | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems wi... | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,597,299,303 | 2,147,483,647 | PyPy 3 | OK | TESTS | 41 | 156 | 2,048,000 | n, m = [int(i) for i in input().split()]
a = [int(i) for i in input().split()]
b = [int(i) for i in input().split()]
a.sort()
b.sort()
i = 0
j = 0
while i < n and j < m:
if a[i] <= b[j]:
i += 1
j += 1
else:
j += 1
if i == n:
print(0)
else:
print(n - i)
| Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
T... | ```python
n, m = [int(i) for i in input().split()]
a = [int(i) for i in input().split()]
b = [int(i) for i in input().split()]
a.sort()
b.sort()
i = 0
j = 0
while i < n and j < m:
if a[i] <= b[j]:
i += 1
j += 1
else:
j += 1
if i == n:
print(0)
else:
print(n - i)... | 3 | |
770 | A | New Password | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should cons... | The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists. | Print any password which satisfies all conditions given by Innokentiy. | [
"4 3\n",
"6 6\n",
"5 2\n"
] | [
"java\n",
"python\n",
"phphp\n"
] | In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letter... | 500 | [
{
"input": "4 3",
"output": "abca"
},
{
"input": "6 6",
"output": "abcdef"
},
{
"input": "5 2",
"output": "ababa"
},
{
"input": "3 2",
"output": "aba"
},
{
"input": "10 2",
"output": "ababababab"
},
{
"input": "26 13",
"output": "abcdefghijklmabcde... | 1,603,885,797 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 109 | 0 | m="abcdefghijklmnopqrstuvwxyz"
n,k = map(int, input().split())
z= m[:k]
# print(z)
# print(n//k)
z=z*(n//k)
print(z+z[:n-len(z)]) | Title: New Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the foll... | ```python
m="abcdefghijklmnopqrstuvwxyz"
n,k = map(int, input().split())
z= m[:k]
# print(z)
# print(n//k)
z=z*(n//k)
print(z+z[:n-len(z)])
``` | 3 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,589,823,239 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 340 | 0 |
s = input()
t = 0
p = ""
while t<len(s):
if s[t]==".":
t+=1
p+="0"
elif s[t] == "-" and s[t+1] == ".":
p+="1"
t+=2
elif s[t] == '-' and s[t+1] == "-":
t +=2
p+="2"
print(p) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
s = input()
t = 0
p = ""
while t<len(s):
if s[t]==".":
t+=1
p+="0"
elif s[t] == "-" and s[t+1] == ".":
p+="1"
t+=2
elif s[t] == '-' and s[t+1] == "-":
t +=2
p+="2"
print(p)
``` | 3.915 |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirem... | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems wi... | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,599,927,458 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 109 | 614,400 | read=lambda:map(int,input().split())
n,m=read()
a=list(read())
b=list(read())
i,j=0,0
while(i<n and j<m):
if(a[i]<=b[j]):
i+=1
j+=1
print(n-i)
| Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
T... | ```python
read=lambda:map(int,input().split())
n,m=read()
a=list(read())
b=list(read())
i,j=0,0
while(i<n and j<m):
if(a[i]<=b[j]):
i+=1
j+=1
print(n-i)
``` | 3 | |
26 | A | Almost Prime | PROGRAMMING | 900 | [
"number theory"
] | A. Almost Prime | 2 | 256 | A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive. | Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000). | Output the amount of almost prime numbers between 1 and *n*, inclusive. | [
"10\n",
"21\n"
] | [
"2\n",
"8\n"
] | none | 500 | [
{
"input": "10",
"output": "2"
},
{
"input": "21",
"output": "8"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "8",
"output": "1"
},
... | 1,597,156,358 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 218 | 6,963,200 | def sieve():
prime = [1] * 3005
prime[0] = prime[1] = 0
almostprime = [0]*3005
for i in range(2, 3001) :
if prime[i] :
j = 2*i
while(j < 3001):
prime[j] = 0
almostprime[j] += 1
j += i
return almostprime
... | Title: Almost Prime
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, in... | ```python
def sieve():
prime = [1] * 3005
prime[0] = prime[1] = 0
almostprime = [0]*3005
for i in range(2, 3001) :
if prime[i] :
j = 2*i
while(j < 3001):
prime[j] = 0
almostprime[j] += 1
j += i
return almost... | 3.93253 |
467 | A | George and Accommodation | PROGRAMMING | 800 | [
"implementation"
] | null | null | George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want to live in the same room. The dormitory has *n* rooms in total. At the moment the *i*-th room has *p**i* peopl... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of rooms.
The *i*-th of the next *n* lines contains two integers *p**i* and *q**i* (0<=≤<=*p**i*<=≤<=*q**i*<=≤<=100) — the number of people who already live in the *i*-th room and the room's capacity. | Print a single integer — the number of rooms where George and Alex can move in. | [
"3\n1 1\n2 2\n3 3\n",
"3\n1 10\n0 10\n10 10\n"
] | [
"0\n",
"2\n"
] | none | 500 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "0"
},
{
"input": "3\n1 10\n0 10\n10 10",
"output": "2"
},
{
"input": "2\n36 67\n61 69",
"output": "2"
},
{
"input": "3\n21 71\n10 88\n43 62",
"output": "3"
},
{
"input": "3\n1 2\n2 3\n3 4",
"output": "0"
},
{
"... | 1,694,276,199 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 46 | 0 | c = 0
for s in [*open(0)][1:]:
c += eval(s.replace(' ', '-'))<-1
print(c) | Title: George and Accommodation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want ... | ```python
c = 0
for s in [*open(0)][1:]:
c += eval(s.replace(' ', '-'))<-1
print(c)
``` | 3 | |
112 | A | Petya and Strings | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Petya and Strings | 2 | 256 | Little Petya loves presents. His mum bought him two strings of the same size for his birthday. The strings consist of uppercase and lowercase Latin letters. Now Petya wants to compare those two strings lexicographically. The letters' case does not matter, that is an uppercase letter is considered equivalent to the corr... | Each of the first two lines contains a bought string. The strings' lengths range from 1 to 100 inclusive. It is guaranteed that the strings are of the same length and also consist of uppercase and lowercase Latin letters. | If the first string is less than the second one, print "-1". If the second string is less than the first one, print "1". If the strings are equal, print "0". Note that the letters' case is not taken into consideration when the strings are compared. | [
"aaaa\naaaA\n",
"abs\nAbz\n",
"abcdefg\nAbCdEfF\n"
] | [
"0\n",
"-1\n",
"1\n"
] | If you want more formal information about the lexicographical order (also known as the "dictionary order" or "alphabetical order"), you can visit the following site:
- http://en.wikipedia.org/wiki/Lexicographical_order | 500 | [
{
"input": "aaaa\naaaA",
"output": "0"
},
{
"input": "abs\nAbz",
"output": "-1"
},
{
"input": "abcdefg\nAbCdEfF",
"output": "1"
},
{
"input": "asadasdasd\nasdwasdawd",
"output": "-1"
},
{
"input": "aslkjlkasdd\nasdlkjdajwi",
"output": "1"
},
{
"input":... | 1,695,259,265 | 2,147,483,647 | Python 3 | OK | TESTS | 53 | 92 | 0 | m=input().upper()
n=input().upper()
if m<n:
print(-1)
elif m>n:
print(1)
else:
print(0) | Title: Petya and Strings
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya loves presents. His mum bought him two strings of the same size for his birthday. The strings consist of uppercase and lowercase Latin letters. Now Petya wants to compare those two strings lexicographically. ... | ```python
m=input().upper()
n=input().upper()
if m<n:
print(-1)
elif m>n:
print(1)
else:
print(0)
``` | 3.977 |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,653,550,240 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 31 | 0 | n = int(input())
count = 0
a = list(map(int, input().split()))
for i in range(len(a)):
maximum = max(a)
count += maximum - a[i]
print(count) | Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
n = int(input())
count = 0
a = list(map(int, input().split()))
for i in range(len(a)):
maximum = max(a)
count += maximum - a[i]
print(count)
``` | 3 | |
411 | A | Password Check | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | You have probably registered on Internet sites many times. And each time you should enter your invented password. Usually the registration form automatically checks the password's crypt resistance. If the user's password isn't complex enough, a message is displayed. Today your task is to implement such an automatic che... | The first line contains a non-empty sequence of characters (at most 100 characters). Each character is either a large English letter, or a small English letter, or a digit, or one of characters: "!", "?", ".", ",", "_". | If the password is complex enough, print message "Correct" (without the quotes), otherwise print message "Too weak" (without the quotes). | [
"abacaba\n",
"X12345\n",
"CONTEST_is_STARTED!!11\n"
] | [
"Too weak\n",
"Too weak\n",
"Correct\n"
] | none | 0 | [
{
"input": "abacaba",
"output": "Too weak"
},
{
"input": "X12345",
"output": "Too weak"
},
{
"input": "CONTEST_is_STARTED!!11",
"output": "Correct"
},
{
"input": "1zA__",
"output": "Correct"
},
{
"input": "1zA_",
"output": "Too weak"
},
{
"input": "zA_... | 1,642,836,278 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 62 | 0 | n=input()
res=False
res1=False
res2= False
if(len(n)<5):
print("Too weak")
quit()
else:
for i in range(len(n)):
if(n[i].isupper()):
res=True
elif(n[i].islower()):
res1=True
elif(n[i].isdigit()):
res2=True
if(res==True and res1==Tr... | Title: Password Check
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have probably registered on Internet sites many times. And each time you should enter your invented password. Usually the registration form automatically checks the password's crypt resistance. If the user's password... | ```python
n=input()
res=False
res1=False
res2= False
if(len(n)<5):
print("Too weak")
quit()
else:
for i in range(len(n)):
if(n[i].isupper()):
res=True
elif(n[i].islower()):
res1=True
elif(n[i].isdigit()):
res2=True
if(res==True an... | 3 | |
186 | A | Comparing Strings | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Mish... | The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that co... | Print "YES", if the dwarves belong to the same race. Otherwise, print "NO". | [
"ab\nba\n",
"aa\nab\n"
] | [
"YES\n",
"NO\n"
] | - First example: you can simply swap two letters in string "ab". So we get "ba". - Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b". | 500 | [
{
"input": "ab\nba",
"output": "YES"
},
{
"input": "aa\nab",
"output": "NO"
},
{
"input": "a\nza",
"output": "NO"
},
{
"input": "vvea\nvvae",
"output": "YES"
},
{
"input": "rtfabanpc\natfabrnpc",
"output": "YES"
},
{
"input": "mt\ntm",
"output": "Y... | 1,619,001,660 | 2,147,483,647 | Python 3 | OK | TESTS | 53 | 154 | 3,174,400 | a = list(input())
b = list(input())
answer = "YES"
if len(a) != len(b):
answer = "NO"
else:
indexes = []
for i in range(len(a)):
if a[i] != b[i]:
indexes.append(i)
if len(indexes) != 2:
answer = "NO"
else:
temp = a[indexes[0]]
a[indexes[0]]... | Title: Comparing Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome ... | ```python
a = list(input())
b = list(input())
answer = "YES"
if len(a) != len(b):
answer = "NO"
else:
indexes = []
for i in range(len(a)):
if a[i] != b[i]:
indexes.append(i)
if len(indexes) != 2:
answer = "NO"
else:
temp = a[indexes[0]]
a[i... | 3 | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,659,824,502 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 92 | 0 | def main():
T=input().split(' ')
K=Prime(int(T[0]))
if K==int(T[1]):
print('YES')
else:
print('NO')
def Prime(n):
n+=1
while(not(Premier(n))):
n+=1
return n
def Premier(n):
for i in range(2,n//2+1):
if n%i==0:
return False
r... | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
def main():
T=input().split(' ')
K=Prime(int(T[0]))
if K==int(T[1]):
print('YES')
else:
print('NO')
def Prime(n):
n+=1
while(not(Premier(n))):
n+=1
return n
def Premier(n):
for i in range(2,n//2+1):
if n%i==0:
return Fa... | 3.977 |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
I... | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**... | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,604,389,383 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 109 | 0 | n,m=map(int,input().split());bulbs=[]
for i in range (n):
bulb=[int(x) for x in input().split()]
for k in range (0,bulb[0]):
bulbs.append(bulb[k+1])
for j in range (0,m):
if j+1 not in bulbs:
print("NO")
break
else:print("YES")
| Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is... | ```python
n,m=map(int,input().split());bulbs=[]
for i in range (n):
bulb=[int(x) for x in input().split()]
for k in range (0,bulb[0]):
bulbs.append(bulb[k+1])
for j in range (0,m):
if j+1 not in bulbs:
print("NO")
break
else:print("YES")
``` | 3 | |
962 | A | Equator | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Polycarp has created his own training plan to prepare for the programming contests. He will train for $n$ days, all days are numbered from $1$ to $n$, beginning from the first.
On the $i$-th day Polycarp will necessarily solve $a_i$ problems. One evening Polycarp plans to celebrate the equator. He will celebrate it on... | The first line contains a single integer $n$ ($1 \le n \le 200\,000$) — the number of days to prepare for the programming contests.
The second line contains a sequence $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 10\,000$), where $a_i$ equals to the number of problems, which Polycarp will solve on the $i$-th day. | Print the index of the day when Polycarp will celebrate the equator. | [
"4\n1 3 2 1\n",
"6\n2 2 2 2 2 2\n"
] | [
"2\n",
"3\n"
] | In the first example Polycarp will celebrate the equator on the evening of the second day, because up to this day (inclusive) he will solve $4$ out of $7$ scheduled problems on four days of the training.
In the second example Polycarp will celebrate the equator on the evening of the third day, because up to this day (... | 0 | [
{
"input": "4\n1 3 2 1",
"output": "2"
},
{
"input": "6\n2 2 2 2 2 2",
"output": "3"
},
{
"input": "1\n10000",
"output": "1"
},
{
"input": "3\n2 1 1",
"output": "1"
},
{
"input": "2\n1 3",
"output": "2"
},
{
"input": "4\n2 1 1 3",
"output": "3"
}... | 1,603,460,145 | 2,147,483,647 | Python 3 | OK | TESTS | 106 | 171 | 13,516,800 | def h(i): return (i >> 1) + (i & 1)
input()
a = [int(i) for i in input().split()]
t, c = h(sum(a)), 0
for i, ai in enumerate(a):
c += ai
if c >= t:
print(i+1)
break
| Title: Equator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has created his own training plan to prepare for the programming contests. He will train for $n$ days, all days are numbered from $1$ to $n$, beginning from the first.
On the $i$-th day Polycarp will necessarily solve... | ```python
def h(i): return (i >> 1) + (i & 1)
input()
a = [int(i) for i in input().split()]
t, c = h(sum(a)), 0
for i, ai in enumerate(a):
c += ai
if c >= t:
print(i+1)
break
``` | 3 | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,681,725,001 | 2,147,483,647 | PyPy 3 | OK | TESTS | 102 | 170 | 0 | n1 = input()
n2 = input()
l = []
for i in range(len(n1)):
if n1[i]!=n2[i]:
l.append('1')
else:
l.append('0')
res = "".join(l)
print(res) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
n1 = input()
n2 = input()
l = []
for i in range(len(n1)):
if n1[i]!=n2[i]:
l.append('1')
else:
l.append('0')
res = "".join(l)
print(res)
``` | 3.9575 |
994 | A | Fingerprints | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are locked in a room with a door that has a keypad with 10 keys corresponding to digits from 0 to 9. To escape from the room, you need to enter a correct code. You also have a sequence of digits.
Some keys on the keypad have fingerprints. You believe the correct code is the longest not necessarily contiguous subse... | The first line contains two integers $n$ and $m$ ($1 \le n, m \le 10$) representing the number of digits in the sequence you have and the number of keys on the keypad that have fingerprints.
The next line contains $n$ distinct space-separated integers $x_1, x_2, \ldots, x_n$ ($0 \le x_i \le 9$) representing the sequen... | In a single line print a space-separated sequence of integers representing the code. If the resulting sequence is empty, both printing nothing and printing a single line break is acceptable. | [
"7 3\n3 5 7 1 6 2 8\n1 2 7\n",
"4 4\n3 4 1 0\n0 1 7 9\n"
] | [
"7 1 2\n",
"1 0\n"
] | In the first example, the only digits with fingerprints are $1$, $2$ and $7$. All three of them appear in the sequence you know, $7$ first, then $1$ and then $2$. Therefore the output is 7 1 2. Note that the order is important, and shall be the same as the order in the original sequence.
In the second example digits $... | 500 | [
{
"input": "7 3\n3 5 7 1 6 2 8\n1 2 7",
"output": "7 1 2"
},
{
"input": "4 4\n3 4 1 0\n0 1 7 9",
"output": "1 0"
},
{
"input": "9 4\n9 8 7 6 5 4 3 2 1\n2 4 6 8",
"output": "8 6 4 2"
},
{
"input": "10 5\n3 7 1 2 4 6 9 0 5 8\n4 3 0 7 9",
"output": "3 7 4 9 0"
},
{
"... | 1,616,760,292 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 62 | 0 | n,m = map(int, input().split(' '))
seq = list(map(int, input().split(' ')))
fin = list(map(int, input().split(' ')))
code=[]
for i in seq:
if i in fin:
code.append(i)
for i in code:
print(i, end=" ") | Title: Fingerprints
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are locked in a room with a door that has a keypad with 10 keys corresponding to digits from 0 to 9. To escape from the room, you need to enter a correct code. You also have a sequence of digits.
Some keys on the keyp... | ```python
n,m = map(int, input().split(' '))
seq = list(map(int, input().split(' ')))
fin = list(map(int, input().split(' ')))
code=[]
for i in seq:
if i in fin:
code.append(i)
for i in code:
print(i, end=" ")
``` | 3 | |
604 | B | More Cowbell | PROGRAMMING | 1,400 | [
"binary search",
"greedy"
] | null | null | Kevin Sun wants to move his precious collection of *n* cowbells from Naperthrill to Exeter, where there is actually grass instead of corn. Before moving, he must pack his cowbells into *k* boxes of a fixed size. In order to keep his collection safe during transportation, he won't place more than two cowbells into a sin... | The first line of the input contains two space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=2·*k*<=≤<=100<=000), denoting the number of cowbells and the number of boxes, respectively.
The next line contains *n* space-separated integers *s*1,<=*s*2,<=...,<=*s**n* (1<=≤<=*s*1<=≤<=*s*2<=≤<=...<=≤<=*s**n*<=≤<=1<=000<=000... | Print a single integer, the smallest *s* for which it is possible for Kevin to put all of his cowbells into *k* boxes of size *s*. | [
"2 1\n2 5\n",
"4 3\n2 3 5 9\n",
"3 2\n3 5 7\n"
] | [
"7\n",
"9\n",
"8\n"
] | In the first sample, Kevin must pack his two cowbells into the same box.
In the second sample, Kevin can pack together the following sets of cowbells: {2, 3}, {5} and {9}.
In the third sample, the optimal solution is {3, 5} and {7}. | 1,000 | [
{
"input": "2 1\n2 5",
"output": "7"
},
{
"input": "4 3\n2 3 5 9",
"output": "9"
},
{
"input": "3 2\n3 5 7",
"output": "8"
},
{
"input": "20 11\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "2"
},
{
"input": "10 10\n3 15 31 61 63 63 68 94 98 100",
"outp... | 1,637,203,669 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 108 | 7,372,800 | n, k = map(int, input().split())
s = list(map(int, input().split()))
maxim = s[-1]
twoBells = n - k
for i in range(twoBells):
maxim = max(maxim, s[i] + s[2*twoBells-i-1])
print(maxim)
| Title: More Cowbell
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kevin Sun wants to move his precious collection of *n* cowbells from Naperthrill to Exeter, where there is actually grass instead of corn. Before moving, he must pack his cowbells into *k* boxes of a fixed size. In order t... | ```python
n, k = map(int, input().split())
s = list(map(int, input().split()))
maxim = s[-1]
twoBells = n - k
for i in range(twoBells):
maxim = max(maxim, s[i] + s[2*twoBells-i-1])
print(maxim)
``` | 3 | |
604 | A | Uncowed Forces | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Kevin Sun has just finished competing in Codeforces Round #334! The round was 120 minutes long and featured five problems with maximum point values of 500, 1000, 1500, 2000, and 2500, respectively. Despite the challenging tasks, Kevin was uncowed and bulldozed through all of them, distinguishing himself from the herd a... | The first line of the input contains five space-separated integers *m*1, *m*2, *m*3, *m*4, *m*5, where *m**i* (0<=≤<=*m**i*<=≤<=119) is the time of Kevin's last submission for problem *i*. His last submission is always correct and gets accepted.
The second line contains five space-separated integers *w*1, *w*2, *w*3, ... | Print a single integer, the value of Kevin's final score. | [
"20 40 60 80 100\n0 1 2 3 4\n1 0\n",
"119 119 119 119 119\n0 0 0 0 0\n10 0\n"
] | [
"4900\n",
"4930\n"
] | In the second sample, Kevin takes 119 minutes on all of the problems. Therefore, he gets <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/42158dc2bc78cd21fa679530ae9ef8b9ea298d15.png" style="max-width: 100.0%;max-height: 100.0%;"/> of the points on each problem. So his score from solving pro... | 500 | [
{
"input": "20 40 60 80 100\n0 1 2 3 4\n1 0",
"output": "4900"
},
{
"input": "119 119 119 119 119\n0 0 0 0 0\n10 0",
"output": "4930"
},
{
"input": "3 6 13 38 60\n6 10 10 3 8\n9 9",
"output": "5088"
},
{
"input": "21 44 11 68 75\n6 2 4 8 4\n2 8",
"output": "4522"
},
{... | 1,503,994,160 | 1,160 | Python 3 | OK | TESTS | 57 | 62 | 0 | import sys
m = list(map(int,input().split()))
w = list(map(int,input().split()))
hs,hu = map(int,input().split())
point = [500,1000,1500,2000,2500]
res = 0
for i in range(5):
res += max(0.3*point[i],((1- (m[i]/250) )*point[i] - 50*w[i]))
res += hs*100 - hu*50
print(int(res)) | Title: Uncowed Forces
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kevin Sun has just finished competing in Codeforces Round #334! The round was 120 minutes long and featured five problems with maximum point values of 500, 1000, 1500, 2000, and 2500, respectively. Despite the challengin... | ```python
import sys
m = list(map(int,input().split()))
w = list(map(int,input().split()))
hs,hu = map(int,input().split())
point = [500,1000,1500,2000,2500]
res = 0
for i in range(5):
res += max(0.3*point[i],((1- (m[i]/250) )*point[i] - 50*w[i]))
res += hs*100 - hu*50
print(int(res))
``` | 3 | |
478 | B | Random Teams | PROGRAMMING | 1,300 | [
"combinatorics",
"constructive algorithms",
"greedy",
"math"
] | null | null | *n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is to write a program that will find the minimum and the maximum number of pairs of friends that coul... | The only line of input contains two integers *n* and *m*, separated by a single space (1<=≤<=*m*<=≤<=*n*<=≤<=109) — the number of participants and the number of teams respectively. | The only line of the output should contain two integers *k**min* and *k**max* — the minimum possible number of pairs of friends and the maximum possible number of pairs of friends respectively. | [
"5 1\n",
"3 2\n",
"6 3\n"
] | [
"10 10\n",
"1 1\n",
"3 6\n"
] | In the first sample all the participants get into one team, so there will be exactly ten pairs of friends.
In the second sample at any possible arrangement one team will always have two participants and the other team will always have one participant. Thus, the number of pairs of friends will always be equal to one.
... | 1,000 | [
{
"input": "5 1",
"output": "10 10"
},
{
"input": "3 2",
"output": "1 1"
},
{
"input": "6 3",
"output": "3 6"
},
{
"input": "5 3",
"output": "2 3"
},
{
"input": "10 2",
"output": "20 36"
},
{
"input": "10 6",
"output": "4 10"
},
{
"input": ... | 1,694,535,922 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 46 | 0 | n,m=map(int,input().split())
max=((n-m+1)*(n-m))//2
remainder=(n-m)%m
q=(n-m)//m
min= (((q+1)*(q))//2)*(m-remainder)
min += (((q+2)*(q+1))//2)*(remainder)
print(min, max) | Title: Random Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is ... | ```python
n,m=map(int,input().split())
max=((n-m+1)*(n-m))//2
remainder=(n-m)%m
q=(n-m)//m
min= (((q+1)*(q))//2)*(m-remainder)
min += (((q+2)*(q+1))//2)*(remainder)
print(min, max)
``` | 3 | |
180 | F | Mathematical Analysis Rocks! | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | Students of group 199 have written their lectures dismally. Now an exam on Mathematical Analysis is approaching and something has to be done asap (that is, quickly). Let's number the students of the group from 1 to *n*. Each student *i* (1<=≤<=*i*<=≤<=*n*) has a best friend *p*[*i*] (1<=≤<=*p*[*i*]<=≤<=*n*). In fact, e... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of students in the group. The second line contains sequence of different integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*). The third line contains the sequence of different integers *b*1,<=*b*2,<=...,<=*b**n* (1<=≤<=*b**i*<=≤<=*n*). | Print sequence *n* of different integers *p*[1],<=*p*[2],<=...,<=*p*[*n*] (1<=≤<=*p*[*i*]<=≤<=*n*). It is guaranteed that the solution exists and that it is unique. | [
"4\n2 1 4 3\n3 4 2 1\n",
"5\n5 2 3 1 4\n1 3 2 4 5\n",
"2\n1 2\n2 1\n"
] | [
"4 3 1 2 ",
"4 3 2 5 1 ",
"2 1 "
] | none | 0 | [
{
"input": "4\n2 1 4 3\n3 4 2 1",
"output": "4 3 1 2 "
},
{
"input": "5\n5 2 3 1 4\n1 3 2 4 5",
"output": "4 3 2 5 1 "
},
{
"input": "2\n1 2\n2 1",
"output": "2 1 "
},
{
"input": "1\n1\n1",
"output": "1 "
},
{
"input": "2\n1 2\n1 2",
"output": "1 2 "
},
{
... | 1,698,245,647 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 342 | 17,612,800 | n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
d = [0] * n
for i in range(n):
a[i] -= 1
b[i] -= 1
d[a[i]] = i
for i in range(n):
print(d[b[i]] + 1, end=" ")# 1698245647.4107454 | Title: Mathematical Analysis Rocks!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Students of group 199 have written their lectures dismally. Now an exam on Mathematical Analysis is approaching and something has to be done asap (that is, quickly). Let's number the students of the group f... | ```python
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
d = [0] * n
for i in range(n):
a[i] -= 1
b[i] -= 1
d[a[i]] = i
for i in range(n):
print(d[b[i]] + 1, end=" ")# 1698245647.4107454
``` | 3 | |
931 | A | Friends Meeting | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation",
"math"
] | null | null | Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes acco... | The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend.
The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend.
It is guaranteed that *a*<=≠<=*b*. | Print the minimum possible total tiredness if the friends meet in the same point. | [
"3\n4\n",
"101\n99\n",
"5\n10\n"
] | [
"1\n",
"2\n",
"9\n"
] | In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1.
In the second example the first friend should move by one to the left, an... | 500 | [
{
"input": "3\n4",
"output": "1"
},
{
"input": "101\n99",
"output": "2"
},
{
"input": "5\n10",
"output": "9"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "1\n1000",
"output": "250000"
},
{
"input": "999\n1000",
"output": "1"
},
{
"inpu... | 1,636,603,226 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 46 | 4,505,600 | def friendsMeeting(a, b):
diff = abs(a - b)
if diff == 1:
return 1
xa = diff // 2
xb = diff - xa
return doSum(xa) + doSum(xb)
def doSum(n):
return n * (n + 1) // 2
a, b = int(input()), int(input())
print(friendsMeeting(a, b)) | Title: Friends Meeting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in... | ```python
def friendsMeeting(a, b):
diff = abs(a - b)
if diff == 1:
return 1
xa = diff // 2
xb = diff - xa
return doSum(xa) + doSum(xb)
def doSum(n):
return n * (n + 1) // 2
a, b = int(input()), int(input())
print(friendsMeeting(a, b))
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | A positive integer is called a 2-3-integer, if it is equal to 2*x*·3*y* for some non-negative integers *x* and *y*. In other words, these integers are such integers that only have 2 and 3 among their prime divisors. For example, integers 1, 6, 9, 16 and 108 — are 2-3 integers, while 5, 10, 21 and 120 are not.
Print th... | The only line contains two integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=2·109). | Print a single integer the number of 2-3-integers on the segment [*l*,<=*r*]. | [
"1 10\n",
"100 200\n",
"1 2000000000\n"
] | [
"7\n",
"5\n",
"326\n"
] | In the first example the 2-3-integers are 1, 2, 3, 4, 6, 8 and 9.
In the second example the 2-3-integers are 108, 128, 144, 162 and 192. | 0 | [
{
"input": "1 10",
"output": "7"
},
{
"input": "100 200",
"output": "5"
},
{
"input": "1 2000000000",
"output": "326"
},
{
"input": "1088391168 1934917632",
"output": "17"
},
{
"input": "1088391167 1934917632",
"output": "17"
},
{
"input": "1088391169 ... | 1,521,305,846 | 4,946 | Python 3 | OK | TESTS | 53 | 109 | 7,065,600 | def main():
a, b = map(int, input().split());
count=0;
for two_fact in range(0,40):
for three_fact in range(0,40):
if(a<=(2**two_fact)*(3**three_fact) and b>=(2**two_fact)*(3**three_fact)):
count+=1;
print(count);
main();
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A positive integer is called a 2-3-integer, if it is equal to 2*x*·3*y* for some non-negative integers *x* and *y*. In other words, these integers are such integers that only have 2 and 3 among their prime divisors. For example, i... | ```python
def main():
a, b = map(int, input().split());
count=0;
for two_fact in range(0,40):
for three_fact in range(0,40):
if(a<=(2**two_fact)*(3**three_fact) and b>=(2**two_fact)*(3**three_fact)):
count+=1;
print(count);
main();
``` | 3 | |
716 | A | Crazy Computer | PROGRAMMING | 800 | [
"implementation"
] | null | null | ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *b*, then if *b*<=-<=*a*<=≤<=*c*, just the new word is appended to other words on the screen. If *b*<... | The first line contains two integers *n* and *c* (1<=≤<=*n*<=≤<=100<=000,<=1<=≤<=*c*<=≤<=109) — the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=...<=<<=*t**n*<=≤<=109), where *t**i* denote... | Print a single positive integer, the number of words that remain on the screen after all *n* words was typed, in other words, at the second *t**n*. | [
"6 5\n1 3 8 14 19 20\n",
"6 1\n1 3 5 7 9 10\n"
] | [
"3",
"2"
] | The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be... | 500 | [
{
"input": "6 5\n1 3 8 14 19 20",
"output": "3"
},
{
"input": "6 1\n1 3 5 7 9 10",
"output": "2"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
"input": "5 5\n1 7 12 13 14",
"output": "4"
},
{
"input": "2 1000000000\n1 1000000000",
"output": "2"
},
{
... | 1,666,374,600 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 109 | 8,396,800 | n, c = map(int, input().split())
t = list(map(int, input().split()))
counter = 1
for i in range(n - 1):
if t[i + 1] - t[i] > c:
counter = 1
else:
counter += 1
print(counter)
| Title: Crazy Computer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *... | ```python
n, c = map(int, input().split())
t = list(map(int, input().split()))
counter = 1
for i in range(n - 1):
if t[i + 1] - t[i] > c:
counter = 1
else:
counter += 1
print(counter)
``` | 3 | |
722 | B | Verse Pattern | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | You are given a text consisting of *n* lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowel... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the text.
The second line contains integers *p*1,<=...,<=*p**n* (0<=≤<=*p**i*<=≤<=100) — the verse pattern.
Next *n* lines contain the text itself. Text consists of lowercase English letters and spaces. It's guarant... | If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes). | [
"3\n2 2 3\nintel\ncode\nch allenge\n",
"4\n1 2 3 1\na\nbcdefghi\njklmnopqrstu\nvwxyz\n",
"4\n13 11 15 15\nto be or not to be that is the question\nwhether tis nobler in the mind to suffer\nthe slings and arrows of outrageous fortune\nor to take arms against a sea of troubles\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample, one can split words into syllables in the following way:
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one. | 500 | [
{
"input": "3\n2 2 3\nintel\ncode\nch allenge",
"output": "YES"
},
{
"input": "4\n1 2 3 1\na\nbcdefghi\njklmnopqrstu\nvwxyz",
"output": "NO"
},
{
"input": "4\n13 11 15 15\nto be or not to be that is the question\nwhether tis nobler in the mind to suffer\nthe slings and arrows of outrageo... | 1,563,468,609 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 124 | 0 | n=int(input())
lst = list(map(int,input().split(' ')))
ok = True
for _ in range(n):
st = input()
p_ = lst[_]
a = st.count('a')
a+= st.count('e')
a+= st.count('i')
a+= st.count('o')
a+= st.count('u')
a+= st.count('y')
if p_!=a:
ok=False
if ok:
print('YES')
else:
print('NO') | Title: Verse Pattern
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text consisting of *n* lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary num... | ```python
n=int(input())
lst = list(map(int,input().split(' ')))
ok = True
for _ in range(n):
st = input()
p_ = lst[_]
a = st.count('a')
a+= st.count('e')
a+= st.count('i')
a+= st.count('o')
a+= st.count('u')
a+= st.count('y')
if p_!=a:
ok=False
if ok:
print('YES')
else:
print('NO') ... | 3 | |
399 | A | Pages | PROGRAMMING | 0 | [
"implementation"
] | null | null | User ainta is making a web site. This time he is going to make a navigation of the pages. In his site, there are *n* pages numbered by integers from 1 to *n*. Assume that somebody is on the *p*-th page now. The navigation will look like this:
When someone clicks the button "<<" he is redirected to page 1, and wh... | The first and the only line contains three integers *n*, *p*, *k* (3<=≤<=*n*<=≤<=100; 1<=≤<=*p*<=≤<=*n*; 1<=≤<=*k*<=≤<=*n*) | Print the proper navigation. Follow the format of the output from the test samples. | [
"17 5 2\n",
"6 5 2\n",
"6 1 2\n",
"6 2 2\n",
"9 6 3\n",
"10 6 3\n",
"8 5 4\n"
] | [
"<< 3 4 (5) 6 7 >> ",
"<< 3 4 (5) 6 ",
"(1) 2 3 >> ",
"1 (2) 3 4 >>",
"<< 3 4 5 (6) 7 8 9",
"<< 3 4 5 (6) 7 8 9 >>",
"1 2 3 4 (5) 6 7 8 "
] | none | 500 | [
{
"input": "17 5 2",
"output": "<< 3 4 (5) 6 7 >> "
},
{
"input": "6 5 2",
"output": "<< 3 4 (5) 6 "
},
{
"input": "6 1 2",
"output": "(1) 2 3 >> "
},
{
"input": "6 2 2",
"output": "1 (2) 3 4 >> "
},
{
"input": "9 6 3",
"output": "<< 3 4 5 (6) 7 8 9 "
},
{... | 1,541,076,644 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 109 | 0 | n, p, k = map(int, input().split())
if p - k > 1:
print('<<', end=' ')
for i in range(max(1, p - k), p):
print(i, end=' ')
print('(', p, ')', sep='', end='')
for i in range(p + 1, min(n, p + k) + 1):
print(' ' + str(i), end='')
if p + k < n:
print(' >>', end='') | Title: Pages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
User ainta is making a web site. This time he is going to make a navigation of the pages. In his site, there are *n* pages numbered by integers from 1 to *n*. Assume that somebody is on the *p*-th page now. The navigation will lo... | ```python
n, p, k = map(int, input().split())
if p - k > 1:
print('<<', end=' ')
for i in range(max(1, p - k), p):
print(i, end=' ')
print('(', p, ')', sep='', end='')
for i in range(p + 1, min(n, p + k) + 1):
print(' ' + str(i), end='')
if p + k < n:
print(' >>', end='')
``` | 3 | |
557 | A | Ilya and Diplomas | PROGRAMMING | 1,100 | [
"greedy",
"implementation",
"math"
] | null | null | Soon a school Olympiad in Informatics will be held in Berland, *n* schoolchildren will participate there.
At a meeting of the jury of the Olympiad it was decided that each of the *n* participants, depending on the results, will get a diploma of the first, second or third degree. Thus, each student will receive exactly... | The first line of the input contains a single integer *n* (3<=≤<=*n*<=≤<=3·106) — the number of schoolchildren who will participate in the Olympiad.
The next line of the input contains two integers *min*1 and *max*1 (1<=≤<=*min*1<=≤<=*max*1<=≤<=106) — the minimum and maximum limits on the number of diplomas of the fir... | In the first line of the output print three numbers, showing how many diplomas of the first, second and third degree will be given to students in the optimal variant of distributing diplomas.
The optimal variant of distributing diplomas is the one that maximizes the number of students who receive diplomas of the first... | [
"6\n1 5\n2 6\n3 7\n",
"10\n1 2\n1 3\n1 5\n",
"6\n1 3\n2 2\n2 2\n"
] | [
"1 2 3 \n",
"2 3 5 \n",
"2 2 2 \n"
] | none | 500 | [
{
"input": "6\n1 5\n2 6\n3 7",
"output": "1 2 3 "
},
{
"input": "10\n1 2\n1 3\n1 5",
"output": "2 3 5 "
},
{
"input": "6\n1 3\n2 2\n2 2",
"output": "2 2 2 "
},
{
"input": "55\n1 1000000\n40 50\n10 200",
"output": "5 40 10 "
},
{
"input": "3\n1 1\n1 1\n1 1",
"o... | 1,456,096,070 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 77 | 0 | n = int(input())
minis, maxis = [], []
for i in range(3):
s = list(map(int, input().split()))
minis.append(s[0])
maxis.append(s[1])
left = n
diploms = [0 for i in range(3)]
for i in range(3):
diploms[i] = minis[i]
left -= minis[i]
for i in range(3):
d = min(left, maxis[i] - minis[i])
diplo... | Title: Ilya and Diplomas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Soon a school Olympiad in Informatics will be held in Berland, *n* schoolchildren will participate there.
At a meeting of the jury of the Olympiad it was decided that each of the *n* participants, depending on the re... | ```python
n = int(input())
minis, maxis = [], []
for i in range(3):
s = list(map(int, input().split()))
minis.append(s[0])
maxis.append(s[1])
left = n
diploms = [0 for i in range(3)]
for i in range(3):
diploms[i] = minis[i]
left -= minis[i]
for i in range(3):
d = min(left, maxis[i] - minis[i])... | 3 | |
275 | A | Lights Out | PROGRAMMING | 900 | [
"implementation"
] | null | null | Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be sw... | The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed. | Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0". | [
"1 0 0\n0 0 0\n0 0 1\n",
"1 0 1\n8 8 8\n2 0 3\n"
] | [
"001\n010\n100\n",
"010\n011\n100\n"
] | none | 500 | [
{
"input": "1 0 0\n0 0 0\n0 0 1",
"output": "001\n010\n100"
},
{
"input": "1 0 1\n8 8 8\n2 0 3",
"output": "010\n011\n100"
},
{
"input": "13 85 77\n25 50 45\n65 79 9",
"output": "000\n010\n000"
},
{
"input": "96 95 5\n8 84 74\n67 31 61",
"output": "011\n011\n101"
},
{... | 1,671,594,632 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 33 | 62 | 0 | inp = []
for i in range(3):
row = input().split()
inp.append(row)
ans = [[1,1,1],
[1,1,1],
[1,1,1]]
for i in range(3):
for j in range(3):
if int(inp[i][j]) % 2 == 1:
if (i - 1) >= 0:
ans[i - 1][j] = 1 - ans[i - 1][j]
if (j - 1... | Title: Lights Out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the ... | ```python
inp = []
for i in range(3):
row = input().split()
inp.append(row)
ans = [[1,1,1],
[1,1,1],
[1,1,1]]
for i in range(3):
for j in range(3):
if int(inp[i][j]) % 2 == 1:
if (i - 1) >= 0:
ans[i - 1][j] = 1 - ans[i - 1][j]
... | 3 | |
938 | A | Word Correction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird and it needs to be replaced. So the word corrector works in such a way: as long as there are two consec... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of letters in word *s* before the correction.
The second line contains a string *s* consisting of exactly *n* lowercase Latin letters — the word before the correction. | Output the word *s* after the correction. | [
"5\nweird\n",
"4\nword\n",
"5\naaeaa\n"
] | [
"werd\n",
"word\n",
"a\n"
] | Explanations of the examples:
1. There is only one replace: weird <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> werd;1. No replace needed since there are no two consecutive vowels;1. aaeaa <i... | 0 | [
{
"input": "5\nweird",
"output": "werd"
},
{
"input": "4\nword",
"output": "word"
},
{
"input": "5\naaeaa",
"output": "a"
},
{
"input": "100\naaaaabbbbboyoyoyoyoyacadabbbbbiuiufgiuiuaahjabbbklboyoyoyoyoyaaaaabbbbbiuiuiuiuiuaaaaabbbbbeyiyuyzyw",
"output": "abbbbbocadabbbbb... | 1,563,008,646 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 140 | 0 | g = ['a', 'e', 'i', 'o', 'u', 'y']
n = int(input())
s = input()
ans = ''
i, j = 0, 0
while i < n:
ans += s[i]
if s[i] in g:
j = i + 1
while j < n:
if s[j] in g:
j += 1
else:
break
i = j - 1
i += 1
print(ans)... | Title: Word Correction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird an... | ```python
g = ['a', 'e', 'i', 'o', 'u', 'y']
n = int(input())
s = input()
ans = ''
i, j = 0, 0
while i < n:
ans += s[i]
if s[i] in g:
j = i + 1
while j < n:
if s[j] in g:
j += 1
else:
break
i = j - 1
i += 1
... | 3 | |
263 | A | Beautiful Matrix | PROGRAMMING | 800 | [
"implementation"
] | null | null | You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix:
1.... | The input consists of five lines, each line contains five integers: the *j*-th integer in the *i*-th line of the input represents the element of the matrix that is located on the intersection of the *i*-th row and the *j*-th column. It is guaranteed that the matrix consists of 24 zeroes and a single number one. | Print a single integer — the minimum number of moves needed to make the matrix beautiful. | [
"0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n",
"0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n"
] | [
"3\n",
"1\n"
] | none | 500 | [
{
"input": "0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 1 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "0"
},
{
"input": "0 0 0 0 0... | 1,697,739,762 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 |
matrix = [list(map(int, input().split())) for _ in range(5)]
output = 0
for i, row in enumerate(matrix):
# Acum, 'i' este indicele rândului și 'row' este rândul însuși
# ... restul codului tău ...
if i == 0 or i == 4:
if row[0] == 1 or row[-1] == 1:
output = 4
bre... | Title: Beautiful Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to ri... | ```python
matrix = [list(map(int, input().split())) for _ in range(5)]
output = 0
for i, row in enumerate(matrix):
# Acum, 'i' este indicele rândului și 'row' este rândul însuși
# ... restul codului tău ...
if i == 0 or i == 4:
if row[0] == 1 or row[-1] == 1:
output = 4
... | 3 | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,629,731,971 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 218 | 20,172,800 | s = input()
i=0
while True:
if s[i]=="1":
if i+1<len(s):
if s[i]+s[i+1]=="14":
if i+2<len(s):
if s[i]+s[i+1]+s[i+2]=="144":
i+=3
else:
i+=2
else:
... | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
s = input()
i=0
while True:
if s[i]=="1":
if i+1<len(s):
if s[i]+s[i+1]=="14":
if i+2<len(s):
if s[i]+s[i+1]+s[i+2]=="144":
i+=3
else:
i+=2
else:
... | 3 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,632,664,387 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 6,963,200 | # -*- coding: utf-8 -*-
"""
Created on Sun Sep 26 21:39:24 2021
@author: cheeh
"""
s=list(input())
y=[]
k=0
while k<len(s):
if s[k]=='.':
y.append('0')
k+=1
elif s[k]=='-':
if k!=(len(s)-1):
if s[k+1]=='-':
y.append('2')
k+=... | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
# -*- coding: utf-8 -*-
"""
Created on Sun Sep 26 21:39:24 2021
@author: cheeh
"""
s=list(input())
y=[]
k=0
while k<len(s):
if s[k]=='.':
y.append('0')
k+=1
elif s[k]=='-':
if k!=(len(s)-1):
if s[k+1]=='-':
y.append('2')
... | 3.95603 |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,529,411,747 | 2,147,483,647 | Python 3 | OK | TESTS | 114 | 124 | 102,400 | n, k = map(int, input().split())
from collections import Counter
s = Counter(list(input()))
for i in s:
if s[i]/k > 1:
print('NO')
exit()
print ('YES') | Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same colo... | ```python
n, k = map(int, input().split())
from collections import Counter
s = Counter(list(input()))
for i in s:
if s[i]/k > 1:
print('NO')
exit()
print ('YES')
``` | 3 | |
136 | A | Presents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift.... | Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*. | [
"4\n2 3 4 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"4 1 2 3\n",
"1 3 2\n",
"1 2\n"
] | none | 500 | [
{
"input": "4\n2 3 4 1",
"output": "4 1 2 3"
},
{
"input": "3\n1 3 2",
"output": "1 3 2"
},
{
"input": "2\n1 2",
"output": "1 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 3 2 6 4 5 7 9 8 10",
"output": "1 3 2 5 6 4 7 9 8 10"
},
{
"input"... | 1,699,097,359 | 2,147,483,647 | Python 3 | OK | TESTS | 101 | 92 | 0 |
x=int(input())
liss=list(map(int,input().split()))
akrem=[]
for i in range(x):
for j in range (x):
if i+1==liss[j]:
akrem.append(j+1)
break
else:
continue
print(" ".join(map(str, akrem))) | Title: Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on t... | ```python
x=int(input())
liss=list(map(int,input().split()))
akrem=[]
for i in range(x):
for j in range (x):
if i+1==liss[j]:
akrem.append(j+1)
break
else:
continue
print(" ".join(map(str, akrem)))
``` | 3 | |
27 | E | Number With The Given Amount Of Divisors | PROGRAMMING | 2,000 | [
"brute force",
"dp",
"number theory"
] | E. Number With The Given Amount Of Divisors | 2 | 256 | Given the number *n*, find the smallest positive integer which has exactly *n* divisors. It is guaranteed that for the given *n* the answer will not exceed 1018. | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=1000). | Output the smallest positive integer with exactly *n* divisors. | [
"4\n",
"6\n"
] | [
"6\n",
"12\n"
] | none | 2,500 | [
{
"input": "1",
"output": "1"
},
{
"input": "7",
"output": "64"
},
{
"input": "8",
"output": "24"
},
{
"input": "9",
"output": "36"
},
{
"input": "10",
"output": "48"
},
{
"input": "15",
"output": "144"
},
{
"input": "20",
"output": "24... | 1,626,015,356 | 2,147,483,647 | Python 3 | OK | TESTS | 22 | 124 | 6,963,200 | import math
p = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43]
def solve(n, pos):
ans = [1, 10 ** 18][n > 1] # si n>1 ans = 10**18 sino ans =1 dado que solo se necesita 1 divisor y solo 1 cumple tener un unico divisor
for exp in range(2, n + 1):
if n % exp == 0: # analizamos los posibles ... | Title: Number With The Given Amount Of Divisors
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Given the number *n*, find the smallest positive integer which has exactly *n* divisors. It is guaranteed that for the given *n* the answer will not exceed 1018.
Input Specification:
The first line... | ```python
import math
p = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43]
def solve(n, pos):
ans = [1, 10 ** 18][n > 1] # si n>1 ans = 10**18 sino ans =1 dado que solo se necesita 1 divisor y solo 1 cumple tener un unico divisor
for exp in range(2, n + 1):
if n % exp == 0: # analizamos los... | 3.95603 |
727 | C | Guess the Array | PROGRAMMING | 1,400 | [
"constructive algorithms",
"interactive",
"math"
] | null | null | This is an interactive problem. You should use flush operation after each printed line. For example, in C++ you should use fflush(stdout), in Java you should use System.out.flush(), and in Pascal — flush(output).
In this problem you should guess an array *a* which is unknown for you. The only information you have init... | none | none | [
"5\n \n9\n \n7\n \n9\n \n11\n \n6\n "
] | [
"? 1 5\n \n? 2 3\n \n? 4 1\n \n? 5 2\n \n? 3 4\n \n! 4 6 1 5 5"
] | The format of a test to make a hack is:
- The first line contains an integer number *n* (3 ≤ *n* ≤ 5000) — the length of the array.- The second line contains *n* numbers *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub> (1 ≤ *a*<sub class="lower-inde... | 1,500 | [
{
"input": "5\n4 6 1 5 5",
"output": "5 out of 5"
},
{
"input": "3\n1 1 1",
"output": "3 out of 3"
},
{
"input": "4\n100 1 100 1",
"output": "4 out of 4"
},
{
"input": "10\n9 5 10 7 4 4 8 5 10 5",
"output": "10 out of 10"
},
{
"input": "3\n1 1 1",
"output": "3... | 1,659,702,700 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 327 | 9,318,400 | n = int(input())
d = [0] * n
print('?', 1, 2)
a = int(input())
print('?', 2, 3)
b = int(input())
print('?', 1, 3)
c = int(input())
x = (a+b+c)//2
d[0] = x-b
d[1] = x-c
d[2] = x-a
for i in range(3, n):
print('?', 1, i+1)
x = int(input())
d[i] = x-d[0]
print('!', *d) | Title: Guess the Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This is an interactive problem. You should use flush operation after each printed line. For example, in C++ you should use fflush(stdout), in Java you should use System.out.flush(), and in Pascal — flush(output).
In th... | ```python
n = int(input())
d = [0] * n
print('?', 1, 2)
a = int(input())
print('?', 2, 3)
b = int(input())
print('?', 1, 3)
c = int(input())
x = (a+b+c)//2
d[0] = x-b
d[1] = x-c
d[2] = x-a
for i in range(3, n):
print('?', 1, i+1)
x = int(input())
d[i] = x-d[0]
print('!', *d)
``` | 3 | |
168 | A | Wizards and Demonstration | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Some country is populated by wizards. They want to organize a demonstration.
There are *n* people living in the city, *x* of them are the wizards who will surely go to the demonstration. Other city people (*n*<=-<=*x* people) do not support the wizards and aren't going to go to the demonstration. We know that the city... | The first line contains three space-separated integers, *n*, *x*, *y* (1<=≤<=*n*,<=*x*,<=*y*<=≤<=104,<=*x*<=≤<=*n*) — the number of citizens in the city, the number of wizards and the percentage the administration needs, correspondingly.
Please note that *y* can exceed 100 percent, that is, the administration wants to... | Print a single integer — the answer to the problem, the minimum number of clones to create, so that the demonstration involved no less than *y* percent of *n* (the real total city population). | [
"10 1 14\n",
"20 10 50\n",
"1000 352 146\n"
] | [
"1\n",
"0\n",
"1108\n"
] | In the first sample it is necessary that at least 14% of 10 people came to the demonstration. As the number of people should be integer, then at least two people should come. There is only one wizard living in the city and he is going to come. That isn't enough, so he needs to create one clone.
In the second sample 1... | 500 | [
{
"input": "10 1 14",
"output": "1"
},
{
"input": "20 10 50",
"output": "0"
},
{
"input": "1000 352 146",
"output": "1108"
},
{
"input": "68 65 20",
"output": "0"
},
{
"input": "78 28 27",
"output": "0"
},
{
"input": "78 73 58",
"output": "0"
},
... | 1,368,565,429 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 93 | 102,400 | from math import ceil
n,x,y=map(int,input().split())
ans=max(0,ceil(y*n/100.0-x))
print(ans) | Title: Wizards and Demonstration
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some country is populated by wizards. They want to organize a demonstration.
There are *n* people living in the city, *x* of them are the wizards who will surely go to the demonstration. Other city people (*n... | ```python
from math import ceil
n,x,y=map(int,input().split())
ans=max(0,ceil(y*n/100.0-x))
print(ans)
``` | 3 | |
219 | A | k-String | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string... | The first input line contains integer *k* (1<=≤<=*k*<=≤<=1000). The second line contains *s*, all characters in *s* are lowercase English letters. The string length *s* satisfies the inequality 1<=≤<=|*s*|<=≤<=1000, where |*s*| is the length of string *s*. | Rearrange the letters in string *s* in such a way that the result is a *k*-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "-1" (without quotes). | [
"2\naazz\n",
"3\nabcabcabz\n"
] | [
"azaz\n",
"-1\n"
] | none | 500 | [
{
"input": "2\naazz",
"output": "azaz"
},
{
"input": "3\nabcabcabz",
"output": "-1"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "2\nabba",
"output": "abab"
},
{
"input": "2\naaab",
"output": "-1"
},
{
"input": "7\nabacaba",
"output": "-1"
}... | 1,695,150,627 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 42 | 124 | 0 | k = int(input())
s = input()
result = ""
betuk = [0]*26
for letter in s:
betuk[ord(letter)-97] += 1
for i in range(26):
if betuk[i] % k != 0:
result = "-1"
break
else:
result += chr(i+97)*(betuk[i] // k)
if result == "-1":
print(result)
else:
print(result*k) | Title: k-String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a ... | ```python
k = int(input())
s = input()
result = ""
betuk = [0]*26
for letter in s:
betuk[ord(letter)-97] += 1
for i in range(26):
if betuk[i] % k != 0:
result = "-1"
break
else:
result += chr(i+97)*(betuk[i] // k)
if result == "-1":
print(result)
else:
print(result*k)
``` | 3 | |
527 | A | Playing with Paper | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | One day Vasya was sitting on a not so interesting Maths lesson and making an origami from a rectangular *a* mm <=×<= *b* mm sheet of paper (*a*<=><=*b*). Usually the first step in making an origami is making a square piece of paper from the rectangular sheet by folding the sheet along the bisector of the right angle... | The first line of the input contains two integers *a*, *b* (1<=≤<=*b*<=<<=*a*<=≤<=1012) — the sizes of the original sheet of paper. | Print a single integer — the number of ships that Vasya will make. | [
"2 1\n",
"10 7\n",
"1000000000000 1\n"
] | [
"2\n",
"6\n",
"1000000000000\n"
] | Pictures to the first and second sample test. | 500 | [
{
"input": "2 1",
"output": "2"
},
{
"input": "10 7",
"output": "6"
},
{
"input": "1000000000000 1",
"output": "1000000000000"
},
{
"input": "3 1",
"output": "3"
},
{
"input": "4 1",
"output": "4"
},
{
"input": "3 2",
"output": "3"
},
{
"in... | 1,434,615,578 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 187 | 3,788,800 | #!/usr/bin/env python
# paper.py - Codeforces 572A Paper quiz
#
# Copyright (C) 2015 Sergey
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
# http://www.apache.org/licenses/LICENSE-2.0
#
... | Title: Playing with Paper
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya was sitting on a not so interesting Maths lesson and making an origami from a rectangular *a* mm <=×<= *b* mm sheet of paper (*a*<=><=*b*). Usually the first step in making an origami is making a squ... | ```python
#!/usr/bin/env python
# paper.py - Codeforces 572A Paper quiz
#
# Copyright (C) 2015 Sergey
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
# http://www.apache.org/licenses/LICE... | 3 | |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,660,149,338 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 0 | a = int(input())
b = [int(i) for i in input().split()]
m = max(b)
counter = 0
for i in b:
counter += m - i
print(counter)
| Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
a = int(input())
b = [int(i) for i in input().split()]
m = max(b)
counter = 0
for i in b:
counter += m - i
print(counter)
``` | 3 | |
50 | B | Choosing Symbol Pairs | PROGRAMMING | 1,500 | [
"strings"
] | B. Choosing Symbol Pairs | 2 | 256 | There is a given string *S* consisting of *N* symbols. Your task is to find the number of ordered pairs of integers *i* and *j* such that
1. 1<=≤<=*i*,<=*j*<=≤<=*N*
2. *S*[*i*]<==<=*S*[*j*], that is the *i*-th symbol of string *S* is equal to the *j*-th. | The single input line contains *S*, consisting of lowercase Latin letters and digits. It is guaranteed that string *S* in not empty and its length does not exceed 105. | Print a single number which represents the number of pairs *i* and *j* with the needed property. Pairs (*x*,<=*y*) and (*y*,<=*x*) should be considered different, i.e. the ordered pairs count. | [
"great10\n",
"aaaaaaaaaa\n"
] | [
"7\n",
"100\n"
] | none | 1,000 | [
{
"input": "great10",
"output": "7"
},
{
"input": "aaaaaaaaaa",
"output": "100"
},
{
"input": "great10",
"output": "7"
},
{
"input": "aaaaaaaaaa",
"output": "100"
},
{
"input": "aabb",
"output": "8"
},
{
"input": "w",
"output": "1"
},
{
"in... | 1,615,548,932 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 154 | 307,200 | S=input()
cnt={}
for each in S:
cnt[each]=cnt.get(each,0)+1
ls=cnt.values()
s=0
for i in ls:
s+=int(i)**2
print(s)
| Title: Choosing Symbol Pairs
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a given string *S* consisting of *N* symbols. Your task is to find the number of ordered pairs of integers *i* and *j* such that
1. 1<=≤<=*i*,<=*j*<=≤<=*N*
2. *S*[*i*]<==<=*S*[*j*], that is the *i*-th symbo... | ```python
S=input()
cnt={}
for each in S:
cnt[each]=cnt.get(each,0)+1
ls=cnt.values()
s=0
for i in ls:
s+=int(i)**2
print(s)
``` | 3.960928 |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,622,578,695 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 310 | 0 | l=input()
a=len(l)
f=""
i=0
while i<a:
if l[i]=="-":
if l[i+1]==".":
f+="1"
i+=2
elif l[i+1]=="-":
f+="2"
i+=2
elif l[i]==".":
f+="0"
i+=1
print(f) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
l=input()
a=len(l)
f=""
i=0
while i<a:
if l[i]=="-":
if l[i+1]==".":
f+="1"
i+=2
elif l[i+1]=="-":
f+="2"
i+=2
elif l[i]==".":
f+="0"
i+=1
print(f)
``` | 3.9225 |
612 | B | HDD is Outdated Technology | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | HDD hard drives group data by sectors. All files are split to fragments and each of them are written in some sector of hard drive. Note the fragments can be written in sectors in arbitrary order.
One of the problems of HDD hard drives is the following: the magnetic head should move from one sector to another to read s... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of fragments.
The second line contains *n* different integers *f**i* (1<=≤<=*f**i*<=≤<=*n*) — the number of the fragment written in the *i*-th sector. | Print the only integer — the number of time units needed to read the file. | [
"3\n3 1 2\n",
"5\n1 3 5 4 2\n"
] | [
"3\n",
"10\n"
] | In the second example the head moves in the following way:
- 1->2 means movement from the sector 1 to the sector 5, i.e. it takes 4 time units - 2->3 means movement from the sector 5 to the sector 2, i.e. it takes 3 time units - 3->4 means movement from the sector 2 to the sector 4, i.e. it takes 2 time un... | 0 | [
{
"input": "3\n3 1 2",
"output": "3"
},
{
"input": "5\n1 3 5 4 2",
"output": "10"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "10\n8 2 10 3 4 6 1 7 9 5",
"output": "40"
... | 1,525,171,069 | 2,147,483,647 | Python 3 | OK | TESTS | 24 | 358 | 21,606,400 | n = int(input())
a = [0] * n
i = 1
c = 0
for item in input().split():
a[int(item) - 1] = i
i += 1
for i in range(n - 1):
c += abs(a[i] - a[i + 1])
print(c)
| Title: HDD is Outdated Technology
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HDD hard drives group data by sectors. All files are split to fragments and each of them are written in some sector of hard drive. Note the fragments can be written in sectors in arbitrary order.
One of the ... | ```python
n = int(input())
a = [0] * n
i = 1
c = 0
for item in input().split():
a[int(item) - 1] = i
i += 1
for i in range(n - 1):
c += abs(a[i] - a[i + 1])
print(c)
``` | 3 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,593,974,719 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 109 | 6,758,400 | import math
n = int(input())
name = {1 : 'Sheldon', 2 : 'Leonard', 3 : 'Penny', 4 : 'Rajesh', 5 : 'Howard'}
sum, i, l = 0, 0, [0]
while sum < n:
sum += 5 * 2 ** i
l.append(sum)
i += 1
p = math.ceil((n - l[i - 1]) / 2 ** (i - 1))
print(name[p]) | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
import math
n = int(input())
name = {1 : 'Sheldon', 2 : 'Leonard', 3 : 'Penny', 4 : 'Rajesh', 5 : 'Howard'}
sum, i, l = 0, 0, [0]
while sum < n:
sum += 5 * 2 ** i
l.append(sum)
i += 1
p = math.ceil((n - l[i - 1]) / 2 ** (i - 1))
print(name[p])
``` | 3.932911 |
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